SELECT count(*) FROM branch WHERE membership_amount  >  (SELECT avg(membership_amount) FROM branch)
How many branches where have more than average number of memberships are there?
SELECT count ( * ) FROM branch WHERE membership_amount > ( SELECT avg ( membership_amount ) FROM branch )
select count ( * ) from branch where membership_amount > ( select avg ( membership_amount ) from branch )
How many branches where have more than average number of memberships are there ?