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The difference between malloc and calloc are: 1. malloc() allocates byte of memory, whereas calloc()allocates block of memory. y Calloc(m, n) is essentially equivalent to p = m*malloc(n); memset(p, 0, m * n); The zero fill is all-bits-zero, and does not therefore guarantee useful null pointer values (see section 5 of this list) or floating-point zero values. Free is properly used to free the memory allocated by calloc. y Malloc(s); returns a pointer for enough storage for an object of s bytes. Calloc(n,s); returns a pointer for enough contiguous storage for n objects, each of s bytes. The storage is all initialized to zeros. y Simply, malloc takes a single argument and allocates bytes of memory as per the argument taken during its invocation. Where as calloc takes two aguments, they are the number of variables to be created and the capacity of each vaiable (i.e. the bytes per variable).
Scanf returns number of items successfully read & not 1 or 0.
24. What is an orthogonal base class? Answer: If two base classes have no overlapping methods or data they are said to be independent of, or orthogonal to each other. Orthogonal in the sense means that two classes operate in different dimensions and do not interfere with each other in any way. The same derived class may inherit such classes with no difficulty.
6. What are links and symbolic links in UNIX file system? A link is a second name (not a file) for a file. Links can be used to assign more than one name to a file, but cannot be used to assign a directory more than one name or link filenames on different computers. Symbolic link 'is' a file that only contains the name of another file.Operation on the symbolic link is directed to the file pointed by the it.Both the limitations of links are eliminated in symbolic links. Commands for linking files are: Link ln filename1 filename2 Symbolic link ln -s filename1 filename2
35. What is a smart pointer? Answer: A smart pointer is an object that acts, looks and feels like a normal pointer but offers more functionality. In C++, smart pointers are implemented as template classes that encapsulate a pointer and override standard pointer operators. They have a number of advantages over regular pointers. They are guaranteed to be initialized as either null pointers or pointers to a heap object. Indirection through a null pointer is checked. No delete is ever necessary. Objects are automatically freed when the last pointer to them has gone away. One significant problem with these smart pointers is that unlike regular pointers, they don't respect inheritance. Smart pointers are unattractive for polymorphic code. Given below is an example for the implementation of smart pointers.
template <class X> class smart_pointer { public: smart_pointer(); // makes a null pointer smart_pointer(const X& x) // makes pointer to copy of x X& operator *( ); const X& operator*( ) const; X* operator->() const; smart_pointer(const smart_pointer <X> &); const smart_pointer <X> & operator =(const smart_pointer<X>&); ~smart_pointer(); private: //... }; This class implement a smart pointer to an object of type X. The object itself is located on the heap. Here is how to use it: smart_pointer <employee> p= employee("Harris",1333); Like other overloaded operators, p will behave like a regular pointer, cout<<*p; p->raise_salary(0.5);
22. Name the operators that cannot be overloaded. Answer: ³ sizeof ´ ³
. ³ ³ * ³ ³ -> ³ ³ :: ³ ³ ?: ³
*j. void *k. Incomplete types are otherwise called uninitialized pointers.j. names[3]=names[4]. char names[5][20]={"pascal".Theory 11. } Answer: Compiler error: Cannot increment a void pointer ."perl"}. j=k=&a.k). 12. int i=strlen(a). What is a dangling pointer? Answer: A dangling pointer arises when you use the address of an object after its lifetime is over. // NULL is not counted by strlen function // char a[]="12345\0"."ada". k++. hence i=5 // ****175) main() { int a=10. j++. So it cannot be modified. Array names are pointer constants. Example: int *i=0x400 // i points to address 400 *i=0. What is an incomplete type? Answer: Incomplete types refers to pointers in which there is non availability of the implementation of the referenced location or it points to some location whose value is not available for modification."fortran". //set the value of memory location pointed by i. This may occur in situations like returning addresses of the automatic variables from a function or using the address of the memory block after it is freed."cobol". printf("\n %u %u ".
a). DIM(arr. printf(³The dimension of the array is %d´. } Answer: 10 Explanation: The size of integer array of 10 elements is 10 * sizeof(int). } Answer: HELL%@!~@!@???@~~! Explanation: The character array has the memory just enough to hold the string ³HELL´ and doesnt have enough space to store the terminating null character. } main() { int arr[10].Explanation: Void pointers are generic pointers and they can be used only when the type is not known and as an intermediate address storage type. printf("%s". 145) int DIM(int array[]) { return sizeof(array)/sizeof(int ). } . KEY RULE:Don¶t use expressions that have side-effects in assert statements. So it prints the HELL correctly and continues to print garbage values till it accidentally comes across a NULL character. type) sizeof(array)/sizeof(type) main() { int arr[10]. DIM(arr)). int)). assert(val++ != 0). No pointer arithmetic can be done on it and you cannot apply indirection operator (*) on void pointers. main() { char a[4]="HELL". printf(³The dimension of the array is %d´. 144) #define DIM( array. The macro expands to sizeof(arr)/sizeof(int) => 10 * sizeof(int) / sizeof(int) => 10.
i. The return statement becomes. j). } Answer: 41 Explanation: The boolean expression needs to be evaluated only till the truth value of the expression is not known. char* const a.j=7. j is not equal to zero itself means that the expression¶s truth value is 1. when any of the operands become false. Similarly when && operator is involved in an expression. . -Differentiate the above declarations. Answer: 1.Answer: 1 Explanation: Arrays cannot be passed to functions as arguments and only the pointers can be passed. the whole expression¶s truth value becomes false and hence the remaining expression will not be evaluated. 'const' applies to 'a' rather than to the value of a (constant pointer to char ) *a='F' : legal a="Hi" : illegal 3. const char *a. char const *a. So the remaining expression is not evaluated and so the value of i remains the same. printf("%d %d". VVVVVIIIIIMMMMPPP 136) 1. sizeof(int *)/ sizeof(int) that happens to be equal in this case. 138) main() { int i=4. So the argument is equivalent to int * array (this is one of the very few places where [] and * usage are equivalent). Same as 1. 'const' applies to char * rather than 'a' ( pointer to a constant char ) *a='F' : illegal a="Hi" : legal 2. Because it is followed by || and true || (anything) => true where (anything) will not be evaluated. 3. j = j || i++ && printf("YOU CAN"). 2.
// 123) main() { char *p = ³ayqm´. ***120). now it is ³b´.e.false && (anything) => false where (anything) will not be evaluated. } else j = j. printf(³%c´.++*(p++)). So the question can be written as: if(i. //// ³++*(p++)´ is same as ³++*p++´ (Q125) } Answer: b Here * first point to value at address of p i.j)?i:j:j. // //printf("%d". j?(i.j) { if(i. // j = i..j) j = i. else j = j.e. What is the output for the following program main() { .printf("%d")) here if add 1 space in inner printf(" %d") then outer will print 2 else 1«.// //Printf will return how many characters does it print. The Ternary operator ( ? : ) is equivalent for if-then-else statement. a then outer (++) will increment that value i.
. Answer Definition.. // the expression i+++j is treated as (i++ + j) structure point is globally declared x & y are initialized as zeroes 79) main() { char *p.%p". printf("%p... return 0. int *q. x is a pointer to array of(size 10) integers.0002..h> int main() { extern int a. } Answer 1 ***115) Is the following statement a declaration/definition. printf("%d\n".. p=q=r=0.0004 Explanation: ++ operator when applied topointers increments address according to their corresponding data-types . } Answer: 0001. Apply clock-wise rule to find the meaning of this definition chk out // #include<stdio.. ((arr2D==* arr2D)&&(* arr2D == arr2D[0])) ). Find what does it mean? int (*x)[10]. long *r.p. a). r++.int arr2D[3][3].%p. printf("%d\n".q. q++. } int a=20.r). p++..
printf("%d..%d. Since this information is enough to determine the truth value of the boolean expression. ptr[1]=bbb.int b = 20. Q85** 86) main() { int i =0.char y =10.j=0.. if(a. ptr[2]() is in effect of writing ccc(). ptr[0]=aaa. So the statement following the if statement is not executed. Similarly ptr[1] and ptr[2] for bbb and ccc respectively. } Answer: hello Explanation: .i++. } bbb(){ printf("hello"). # include<stdio. The values of i and j remain unchanged and get printed. ptr[2]().char x =1. } main() { int (*ptr[3])(). } Answer: 0. **89) main(){ int a= 0.h> aaa() { printf("hi").j).b.0 Explanation: The value of i is 0. } Answer: bye Explanation: ptr is array of pointers to functions of return type int. ptr[2]=ccc. since ptr[2] points to ccc.ptr[0] is assigned to address of the function aaa.j).x.y) printf("hello"). } ccc(){ printf("bye").i. if(i && j++) printf("%d...%d".
***90) main(){ unsigned int i. float b.i--) printf("c aptitude"). 92) What are the following notations of defining functions known as? i. ****95) func(a.float b) { /* some code */ } ii. int abc(a. { . for(i=1. p++. Since it is a non zero value if becomes true so. it points to '%d\n' and 300 is printed.b. ANSI C notation ii. Kernighan & Ritche notation **** ****93) main() { char *p. The unsigned equivalent of -2 is a huge value so condition becomes false and control comes out of the loop. signed is promoted to unsigned value.i>-2. } Answer: 300 Explanation: The pointer points to % since it is incremented twice and again decremented by 2. Since the both types doesn't match. p="%d\n".The comma operator has associativity from left to right. "hello" will be printed.300). } Explanation: i is an unsigned integer. Only the rightmost value is returned and the other values are evaluated and ignored. It is compared with a signed value. { /* some code*/ } Answer: i. p++. Thus the value of last variable y is returned to check in if. printf(p-2.b) int a.b) int a. int abc(int a.
//pointer to function declaration int val1. and since main() is recursively called.return( a= (a==b) ). printf("%u ". } Answer: The value if process is 0 ! Explanation: The function 'process' has 3 parameters . printf("%u \n". integers.val2) int (*pf) ().6)). This function returns the result of the operation performed by the function 'func'.process(func.++giveit). printf("The value of process is %d !\n ". } main() { int process(). 0 will be printed every time the control is returned. if(--i){ main(). the following substitutions for formal parameters take place: func for pf. a pointer to another function 2 and 3. The function func has two integer parameters.3. { return((*pf) (val1. } } Answer: 0000 Explanation: The variable "I" is declared as static. } Answer: 0 65535 . hence memory for I will be allocated for only once. printf("%d ". The formal parameters are substituted as 3 for a and 6 for b. 3 for val1 and 6 for val2.val2.func(). The function main() will be called recursively unless I becomes equal to 0. since 3 is not equal to 6. } process(pf. int gotit.val2)). therefore the function returns 0 which in turn is returned by the function 'process'.gotit=--giveit).i). as it encounters the statement. When this function is invoked from main. ****96) void main() { static int i=5. 99) void main() { unsigned giveit=-1.1. a==b returns 0. so the value of static I ie.val1..
g=10.fmod(f.(int*)*v). int *i=&integer. www.ittestpapers. printf("%d\n". We cannot apply indirection on type void*. Passing generic pointers to functions and returning such pointers. j. k=k++. v=i. 1. leading to an infinite loop.>=0 will always be true. 2. Used when the exact pointer type will be known at a later point of time. 103) void main() { static int i=i++. } Answer: i=1j=1k=1 104) main() { unsigned int i=10. As a intermediate pointer type.i). } Answer: 10 9 8 7 6 5 4 3 2 1 0 65535 65534«. Explanation: Void pointer is a generic pointer type. printf("%f\n".>=0) printf("%u ". printf("%lf\n". k). printf("%d".101) void main() { void *v. So the expression i-.g)). Explanation: Since i is an unsigned integer it can never become negative. while(i-. Void pointers are normally used for. j=j++. } Answer: Compiler Error. ***113) main() { float f=5. 3.com 48 printf("%lf\n". int integer=2.++k).k=50}.j=20. printf(³i = %d j = %d k = %d´.f<<2). . enum{i=10. i..f%g). No pointer arithmetic can be done on it.
i++). The condition in the for loop fails and so comes out of the for loop.} Answer: Line no 5: Error: Lvalue required Line no 6: Cannot apply leftshift to float Line no 7: Cannot apply mod to float Explanation: Enumeration constants cannot be modified. } Answer: 10 11 12 13 12 11 10 13 Explanation: Pascal argument passing mechanism forces the arguments to be called from left to right. What is the output of the program given below main() { signed char i=0.i). printf(" %d\n". THe initial value of the i is set to 0. Bit-wise operators and % operators cannot be applied on float values. The inner loop executes to increment the value from 0 to 127 (the positive range of char) and then it rotates to the negative value of -128.int k) { printf(³%d %d %d´.i++. printf(" %d". } void cdecl f(int i. i=10. j.i++).i>=0. printf("%d\n".i. f(i++.int j.i++. f(i++. It prints the current value of i that is -128. cdecl is the normal C argument passing mechanism where the arguments are passed from right to left.int k) { printf(³%d %d %d´. fmod() is to find the modulus values for floats as % operator is for ints.i++) . } main() { int i=10. ///////////////////////////////////////// 112). k). } Answer -128 Explanation Notice the semicolon at the end of the for loop. for(.int j. k).i).i). j.i. . *****111) void pascal f(int i. so you cannot apply ++.
exception.error =1.com 52 Answer 1 Explanation The three usages of name errors can be distinguishable by the compiler at any instance. } Answer: Behavior is implementation dependent. error.com 50 unsigned char i=0.i++) .i>=0. (dot) or -> (arrow) operator preceded by the variable .i++) . So the i++ can never yield negative value and i>=0 never becomes false so that it can come out of the for loop.i).}error. for(. Typedef struct error{int warning. //////////////////////////////////////// ***117) typedef struct error{int warning. 114) main() { char i=0. so valid (they are in different namespaces). error. for(.g1. On the other hand if it considers char to be unsigned by default. Rule: You can write programs that have implementation dependent behavior. main() { error g1. printf("%d\n". } Answer infinite loop Explanation The difference between the previous question and this one is that the char is declared to be unsigned. This error can be used only by preceding the error by struct kayword as in: struct error someError. printf("%d\n".}error. error. But dont write programs that depend on such behavior. exception. exception. If the implementation treats the char to be signed by default the program will print ±128 and terminate. typedef struct error{int warning.i). it goes to infinite loop.ittestpapers. g1.error). This can be used only after . } www.ittestpapers.113) main() { www. printf("%d". Explanation: The detail if the char is signed/unsigned by default is implementation dependent.}error.i>=0.
This can be used to define variables without using the preceding struct keyword as in: error g1. It reduces the readability of the code.thing). exception.error). typedef struct error{int warning. } Answer 00 Explanation This code is to show that preprocessor expressions are not the same as the ordinary expressions. The name something is not already known to the compiler making the declaration int some = 0. ***** 121) void main() { if(~0 == (unsigned int)-1) printf(³You can answer this if you know how values are represented in . In real programming don¶t use such overloading of names. #endif main() { int thing = 0. printf("%d". some . ***119) #if something == 0 int some=0. Note This code is given here to just explain the concept behind. If a name is not known the preprocessor treats it to be equal to zero. error. #endif main() { int thing = 0. printf("%d %d\n". effectively removed from the source code. Since the compiler can perfectly distinguish between these three usages. it is perfectly legal and valid.name as in : g1.}error.com 53 Explanation: This is a very simple example for conditional compilation. some . } Answer: Compiler error : undefined symbol some www.thing).ittestpapers. Possible doesn¶t mean that we should use it! ***118) #ifdef something int some=0. printf("%d %d\n".g1.error =1.
Since str1 doesn¶t have null termination. for (.) printf(³%d´.65). } Answer: A 130) main() { while (strcmp(³some´.str2)) printf(³Strings are not equal\n´). } Answer You can answer this if you know how values are represented in memory Explanation ~ (tilde operator or bit-wise negation operator) operates on 0 to produce all ones to fill the space for an integer. Explanation: If a string constant is initialized explicitly with characters. So str1 and str2 are not the same. char str2[] = {µs¶. printf(p.¶m¶. ±1 is represented in unsigned value as all 1¶s and so both are equal 128) main() { char p[ ]="%d\n". it treats whatever the values that are in the following positions as part of the string until it randomly reaches a µ\0¶.i). } . µ\0¶ is not appended automatically to the string. } Answer: No output ////strcmp returns 0 if strings are equal 131) main() { char str1[] = {µs¶. p[1] = 'c'.i++=0.memory´).¶m¶. while (strcmp(str1.¶\0¶}.´some\0´)) printf(³Strings are not equal\n´). } Answer: ³Strings are not equal´ ³Strings are not equal´ «.¶e¶.¶o¶. hence the result. ***132) main() { int i = 3.¶o¶.¶e¶}.
. char a[ ]="GOOD". strlen(p) = 4 sizeof(a) = 5. sizeof(*p). } Answer: garbage-value 0 Explanation: The memory space allocated by malloc is uninitialized. printf("\n sizeof(p) = %d.*cptr). sizeof(a). sizeof(p).*mptr). printf(³%d´. strlen(a) = 4 Explanation: sizeof(p) => sizeof(char*) => 2 sizeof(*p) => sizeof(char) => 1 Similarly. Here the sizeof(a) where a is the character array and the size of the array is 5 because the space necessary for the terminating NULL character should also be taken into account. printf("\n sizeof(a) = %d. *cptr. int *cptr = (int*) calloc (sizeof(int). strlen(a) = %d".com 59 int *mptr.Answer: Compiler Error: Lvalue required.ittestpapers. sizeof(a) => size of the character array => 5 When sizeof operator is applied to an array it returns the sizeof the array and it is not the same as the sizeof the pointer variable. ***Q141 *** 143) main() { char *p="GOOD". sizeof(*p) = 1. } Answer: sizeof(p) = 2. whereas calloc returns the allocated memory space initialized to zeros. strlen(p)). strlen(p) = %d". ****133) void main() { www. mptr = (int*) malloc (sizeof(int)). Explanation: As we know that increment operators return rvalues and hence it cannot appear on the left hand side of an assignment operation. printf(³%d´.1). strlen(a)). sizeof(*p) = %d.
} } Answer: 1111 2424 3737 4242 www. } void swap(int *a.*(*(i+p)+j). static *p[]={a.y).&y). *a ^= *b.j<3. } Answer: x=8 y=10 Explanation: Using ^ like this is a way to swap two variables without using a temporary variable and that too in a single statement.***146) main() { static int a[3][3]={1.9}.3.*(*(p+i)+j).7.j.5. *(*(j+p)+i). This convention is historically due to pre-ANSI style (referred to as Kernighan and Ritchie style) style of function declaration. printf("x=%d y=%d". means that swap is a function that may take any number of arguments (not no arguments) and returns nothing.i++) { for(j=0.x. So this doesn¶t issue a compiler error by the call swap(&x. void swap(). the swap function will be defined as follows. Another swapping logic using µ ^ ¶operator **** 147) main() { void swap().j++) printf("%d\t%d\t%d\t%d\n". *b ^= *a.4.2.i<3.y=8. int *b) { *a ^= *b.8. int x=10.ittestpapers.6.&y).a+1.*(*(p+j)+i)). for(i=0. Inside main().a+2}. int i. In that style.com 65 5555 6868 7373 8686 9999 Explanation: *(*(p+i)+j) is equivalent to p[i][j]. swap(&x. void swap() . that has two arguments.
It is stored in memory (small-endian) as: 00101100 00000001. printf("%d". *((char*)iPtr+1) ). } Answer: 21 Explanation: The integer value 257 can be represented in binary as. int *iPtr = &i. printf("%d %d". *++ptr=2. *b ^= *a. so the individual bytes are taken by casting it to char * and get printed. } Answer: 11 Explanation: The integer value 257 is stored in the memory as. } where the arguments follow the (). So naturally the declaration for swap will look like. Result of the expression *++ptr = 2 makes the memory representation as: 00101100 00000010. void swap() which means the swap can take any number of arguments.int *a. printf("%d %d". *((char*)iPtr). Smallendian means that the lower order bytes are stored in the higher memory addresses and the higher order bytes are stored in lower addresses. *a ^= *b. So the integer corresponding to it is 00000010 00101100 => 556. The integer value 258 is stored in memory as: 00000001 00000010. *((char*)iPtr). Remember that the INTEL machines are µsmall-endian¶ machines. } Answer: 556 Explanation: The integer value 300 in binary notation is: 00000001 00101100. int *b { *a ^= *b. char *ptr = &i. *** ****150) main() { int i=300. . 00000001 00000001. 149) main() { int i = 258. int *iPtr = &i. 00000001 00000001. ***** 148) main() { int i = 257. *((char*)iPtr+1) ).i).
struct date { int day.year). &student.****154) main() { struct date. }.rollno.dob.com 70 int i=0. int foo(int *arr[]) and 2. stud. }stud. .day. ****156) Is there any difference between the two declarations. int arr[]) { int *p=0. } Answer: Compiler Error: Undefined structure date Explanation: Only declaration of struct date is available inside the structure definition of µstudent¶ but to have a variable of type struct date the definition of the structure is required. &student. So there is no difference between the two declarations. } Answer & Explanation: If the body of the loop never executes p is assigned no address.dob.ittestpapers. www. *p = 0. 1.year. scanf("%s%d%d%d". So p remains NULL where *p =0 may result in problem (may rise to runtime error ³NULL pointer assignment´ and terminate the program).month. The numbers that are allowed inside the [] is just for more readability. int foo(int *arr[2]) Answer: No Explanation: Functions can only pass pointers and not arrays. &student. *****157) What is the subtle error in the following code segment? void fun(int n. struct date dob.dob. struct student { char name[30]. while(i++<n) p = &arr[i].month.
This type of pointer in which the non-availability of the implementation of the referenced location is known as 'incomplete type'. // µself-referencing¶ // } Answer: No Explanation: Is it not legal for a structure to contain a member that is of the same type as in this case. The check s != NULL is for error/exception handling and for that assert shouldn¶t be used. assert(s != NULL). When fgets is used with stdin .****158) What is wrong with the following code? int *foo() { int *s = malloc(sizeof(int)100). sizeof(inputString). //struct a *b. ***168) char inputString[100] = {0}. return s. fp) Answer & Explanation: The second one is better because gets(inputString) doesn't know the size of the string passed and so. } Answer & Explanation: assert macro should be used for debugging and finding out bugs. ***160) void main() { int *i = 0x400. 162) Is the following code legal? struct a { int x. struct a b. // set the value of memory location pointed by i. Because this will cause the structure declaration to be recursive without end. // i points to the address 400 *i = 0. A plain if and the corresponding remedy statement has to be given. if a very big input (here. } Answer: Undefined behavior Explanation: The second statement results in undefined behavior because it points to some location whose value may not be available for modification. To get string input from the keyboard which one of the following is better? 1) gets(inputString) 2) fgets(inputString. more than 100 chars) the charactes will be written past the input string.
// put braces to force the intention will solve the problem. so this doesn¶t lead to dangling pointers. 179) char *someFun1() { char temp[ ] = ³string". the compiler treats the operator sequence / and * as /* which happens to be the starting of comment. // give space explicity separating / and * //or int k = *ip/(*jp). but by the ³maximum munch´ rule. } int main() { puts(someFun()).performs the same operation as gets but is safe. return temp. j=2.k). ***170) void main() { int i=10. *jp = &j. To force what is intended by the programmer. int *ip= &i. printf(³%d´. } Answer: Compiler Error: ³Unexpected end of file in comment started in line 5´. Explanation: The programmer intended to divide two integers. 178) char *someFun() { char *temp = ³string constant". } Answer: string constant Explanation: The program suffers no problem and gives the output correctly because the character constants are stored in code/data area and not allocated in stack. int k = *ip/ *jp. . return temp. int k = *ip/*jp.
} Answer: Garbage values. µt¶. This is created dynamically as the function is called. . } int main() { puts(someFun1()).¶i¶.¶n¶.¶r¶. In someFun1() temp is a character array and so the space for it is allocated in heap and is initialized with character string ³string´. so is also deleted dynamically on exiting the function so the string data is not available in the calling function main() leading to print some garbage values. return temp.} char *someFun2() { char temp[ ] = {µs¶. Explanation: Both the functions suffer from the problem of dangling pointers.¶g¶}. puts(someFun2()). The function someFun2() also suffers from the same problem but the problem can be easily identified in this case.

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Tanzania start-up Dunia Designs is turning plastic waste collected from the streets of Arusha into stylish sofas, desks, seats and cushions that are going down a storm with businesses, schools and property developers.
Permalink http://p.dw.com/p/2TfFc
Milan's Salone del Mobile is the world's top event in the design calendar. While some criticize the participation of big brands such as Google and Instagram, the fair remains a celebration of the "optimism" of design.
Thousands of skulls and bones from the colonial era are still stored away in German archives. In Africa, the calls for their return are getting louder. But that's proving to be difficult. Daniel Pelz reports from Berlin.
From making paper out of elephant dung to building homes with used cardboard, eco@africa has featured a range of inventive recycling ideas. Here are our top five innovations doing their bit for the environment.
African masks have a history almost as long as the continent to which they belong, but an artist in Ghana has given them a whole new twist by making them out of waste. Meet the inimitable Ed Franklin Gavua.
Send us your stories, photos and videos and we will showcase them on our website where they can inspire others to do their bit too.
Meet a man who's doing his bit for the environment by digging holes in urban India. It might sound unlikely, but it's helping to prevent both flooding and drought. Welcome to the world of the recharge well.
This week, eco@africa takes a look at extreme weather around the world. We meet South Africans dealing with drought, Germans coming to terms with flooding, and an international team searching for rain in Burkina Faso.
'If we destroy the planet, we destroy ourselves' — Dr. Joseph Mukabana, Director of the Office for Africa and Least Developed Countries at the World Meteorological Organization, in an interview with DW.
On this week's eco@africa, we visit Zimbabwe, where textile waste is being turned into stationery, check out efforts to save Manta rays, and meet kids in South Africa who are learning about nature through photography.
The half-hour radio show and podcast Living Planet makes the environment matter to you.
This Earth Day, activists are calling for an end to plastic pollution. DW has been following the impacts of disposable plastic and efforts to do away with it — by everyone from artists to policymakers.
When humans get loud, the impacts are far-reaching for fish, mammals, birds, insects and even plants. The effects are similar, and similarly bad.
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This is a preliminary programme for the Seedbeds of Transformation conference.
Side Events
Global Sustainable Development Report Consultations of multi-stakeholders in Africa
Port Elizabeth, South Africa, 12 May 2018
The Global Sustainable Development Report (GSDR) was mandated by the United Nations Member States for the follow-up of the 2030 Agenda for Sustainable Development at the High-Level Political Forum, with a first report due at the end of 2019. An independent group of fifteen scientists (IGS) is currently drafting the report, which will provide guidance on the state of global sustainable development and transformative pathways. The report will help address the implementation of the 2030 Agenda by highlighting emerging trends and acting as a science-policy interface. Transformative pathways to achieve the 2030 Agenda will be a central question addressed by the report, along with Sustainable Development Goals (SDGs) interactions towards policy coherence. Since these pathways are regional and country specific, the GSDR opened a consultation process across regions to reach out to local experts for their contribution and views on the report content.
Within this context, the IGS is convening this multi-stakeholders consultation workshop in Africa on the 12th of May (by invitation only), as a side event to the Seedbeds of Transformation conference taking place in Port Elizabeth, South Africa.
With the support of the French National Research Institute for Sustainable Development (IRD), the Centre for Development and Environment (CDE) – University of Bern, and Future-Earth, this consultation process aims to gather high-level African scientists, governments across the continent, development experts, African stakeholders from civil society and the private sector for their contributions and views on the GSDR content.
An ice-breaking event will be held on the 11th evening at the Alliance Française of Port Elizabeth, South Africa.


text:
|By PR Newswire
Article Rating:
|December 10, 2012 02:32 AM EST
TEL AVIV, Israel, December 10, 2012 /PRNewswire/ --
Elbit Imaging Ltd. (NASDAQ: EMITF) (the "Company") announced today that it has scheduled its 2012 annual shareholders meeting to take place Monday, December 31, 2012 at 11:00 a.m. (Israel time), at the offices of the Company, located at 2 Weitzman Street, Tel Aviv, Israel. The record date for the meeting is December 17, 2012.
Proxy statements describing the proposals on the agenda and proxy cards for use by shareholders that cannot attend the meeting in person will be sent by mail, on or about December 20, 2012, to the Company's shareholders of record and to shareholders that hold shares registered with the American Stock Transfer & Trust Company. The Company will also furnish the proxy statement to the Securities and Exchange Commission on Form 6-K.
The agenda of the meeting is as follows:
- To re-elect the following members of the Company's Board of Directors: Mordechay Zisser, Shimon Yitzhaki, David Rubner, Moshe Lion and Shmuel Peretz;
- To re-appoint Brightman Almagor Zohar & Co., a member of Deloitte, as the Company's independent auditors until the next annual general meeting of shareholders; and
- To discuss the Company's financial statements for the year ended December 31, 2011.
Items 1 and 2 require the approval of a simple majority of the shares voted on the matter.
Item 3 will not require a vote of the shareholders.
About Elbit Imaging Ltd.
Elbit Imaging Ltd. operates in the following principal fields of business: (i) Commercial and Entertainment Centers - Initiation, construction and sale of shopping and entertainment centers and other mixed-use real property projects, predominantly in the retail sector, located in Central and Eastern Europe and in India; (ii) U.S. Real Property - Investment in commercial real property in the United States; (iii) Hotels - Hotel operation and management, primarily in major European cities; (iv) Medical Industries - (a) research and development, production and marketing of magnetic resonance imaging guided focused ultrasound treatment equipment and (b) development of stem cell population expansion technologies and stem cell therapy products for transplantation and regenerative medicine; (v) Residential Projects - Initiation, construction and sale of residential projects and other mixed-use real property projects, predominately residential, located primarily in India and in Eastern Europe; (vi) Fashion Apparel - Distribution and marketing of fashion apparel and accessories in Israel; and (vii) Other Activity - Venture capital investments.
Any forward-looking statements in our releases include statements regarding the intent, belief or current expectations of Elbit Imaging Ltd. and our management about our business, financial condition, results of operations, and its relationship with its employees and the condition of our properties. Words such as "believe," "expect," "intend," "estimate" and similar expressions are intended to identify forward-looking statements but are not the exclusive means of identifying such statements. Actual results may differ materially from those projected, expressed or implied in the forward-looking statements as a result of various factors including, without limitation, the factors set forth in our filings with the Securities and Exchange Commission including, without limitation, Item 3.D of our annual report on Form 20-F for the fiscal year ended December 31, 2011, under the caption "Risk Factors". Any forward-looking statements contained in our releases speak only as of the date of such release, and we caution existing and prospective investors not to place undue reliance on such statements. Such forward-looking statements do not purport to be predictions of future events or circumstances, and therefore, there can be no assurance that any forward-looking statement contained our releases will prove to be accurate. We undertake no obligation to update or revise any forward-looking statements.
For Further Information:
Company Contact:
Shimon Yitzhaki
Chairman of the Board of Directors
Tel: +972-3-608-6048
[email protected]
Investor Contact:
Mor Dagan
Investor Relations
Tel: +972-3-516-7620
[email protected]
SOURCE Elbit Imaging Ltd.
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164047 Brownsville Road, South-west Oxford (twp), ON, N4G 4G8Listing ID# 110838
164047 Brownsville Road, South-west Oxford (twp), ON, N4G 4G8Listing ID# 110838
$ 424,900
164047 Brownsville Road
South-west Oxford (twp), ON N4G 4G8
- Listing ID 110838
- Building Type: House
- Building Style: 2 Level (split)
- Bedrooms: 4
- Bathrooms: 1
- Land Size: 0.3460 acres
- Space: 0
- Status: For Sale/Active
- Days on Market: 52
- Tax Year: 2017
- Age of Building (yrs): 53
- Basements: Separate Entrance,Walk-Up
- Drive: Front Yard,Private Triple+ Wide
- Garage: 1.0
- Garage Spaces: 1.0
- Garage Type: Attached
- Heating: Baseboard,Forced Air-Gas,Hot Water-Gas
- Kitchens: 1
- Rooms: 13
- Exterior: Brick,Vinyl Siding
Travel time
Property Description
Great family home on the edge of Tillsonburg with 3 bedrms and 2 baths.Nice size kitchen and eating area with solid oak kitchen cupboards (custom made) Hardwood floors in the livingrm. Main floor laundry with access to the back yard. Come to the 2nd. level and the children can enjoy these xlarge bedrms with lots of closet and storage space.Come to the basement and enjoy your rec. room, extra room which could be converted into a kitchen area and lots of storage space. 3 piece bathrm and bedrm. Walk out from the basement to the garage.Enjoy your large deck over looking your completely fenced in back yard with a field behind. 2 storey shop measuring 16 X 14 ft. on each level with hydro, insulated panels, concrete floor and steel roof. Triple wide concrete drive with stamped concrete walkway to the house. Sprinkler system in front of the house. Don't worry about no hydro this home has a wired in generator. Don't just drive by call today and let us show you this Great Home close to Town.
Listing courtesy of ROYAL LEPAGE R.E.WOOD REALTY, BROKERAGE
Points of interest and Comparables
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Vanity Lights. Friday , February 23rd , 2018 - 15:34:14 PM
The best reproductions will be made meticulously, first with a pattern on cardboard which indicates numbers for each section of the glass and the color that will be used. The glass for the vanity lights is then traced over the pattern, cut and cleaned, and joined together with copper foil. Once the vanity lights pattern is soldered together and cleaned again, its a completed and quality reproduction.
If your bathroom is starting to feel drab every time you step in, then it might be time for you to change your bathroom vanity light to make it more welcoming for you and your guests. Add ambiance and elegance in your bathroom by putting stylish, warm light with just the perfect brightness to illuminate your bathroom while youre grooming. The right lighting is essential in a bathroom especially for the ladies in the home when putting that tricky eyeliner.
Tiffany vanity lights reproductions are distinguishable first by their style. The stained glass will be in many colors or sometimes just a few, but it will be in certain patterns that were common themes in the work of this company. Flowers, foliage, tree branches and shrubs, spiders and their spiderwebs, dragonflies, butterflies, and almost anything from nature along those lines appeared in the original lamps. Tiffany vanity lights reproductions hold true to his vision and try to mimic his work as closely as possible.
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Question about 2wire (1000-100052-000) 802.11g/b Wireless Adapter
For the past year I have been using a wireless networking adapter but lately its been nothing but a hassle. I have sbc yahoo dsl (now AT@T) and I also have an xbox 360 right by my computer so I was wondering (step by step I'm a little computer illiterate) on how to get internet connection using a modem. I have a 2wire homportal downstairs for my other computer.I would like to be able to plug the ethernet cable directly in the xbox 360 when i want but then also be able to take it out when im done and use the computer. It would be helpful if you suggested where to get the modem,what model to use, ect. Also do I need to get anything from AT@T to allow me to use it. Once again I already use internet downstairs via 2wire homeportal. Also, do I need any filter to go in my phone line. Thanks in advance for help.
Posted by blfall on
Also do I need to buy an ethernet cable or will it come with the modem. Thx again.
I assume when you say you want a modem, it's because you want a wired connection to the internet. Your HomePortal already has an integrated ADSL modem, and it will not be possible for you to add another one to your line.
If you want a wired connection to the internet, you can either run ethernet cable from the HomePortal downstairs, or you can use a wireless bridge like the SMC EZ Connect g. (There are several brands of adapters that are marketed especially for gaming consoles, but they function similarly to the non-gaming bridges.) The instructions included with the equipment will tell you how to enter the necessary security information for your network.
Also, if you'd like to avoid switching the cable connection every time you move between the X-box and the computer, you can run the wireless bridge into a small network switch, and then plug both items into that. (This would also work with the cable from downstairs if you choose that route.) This gives the added advantage of allowing simultaneous access by both machines.
Posted on Jan 09, 2008
SOURCE: I have freestanding Series 8 dishwasher. Lately during the filling cycle water hammer is occurring. How can this be resolved
A 6ya expert can help you resolve that issue over the phone in a minute or two.
Best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.
The service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).
click here to download the app (for users in the US for now) and get all the help you need.
Good luck!
Posted on Jan 02, 2017
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text: Taxi drivers to donate £2,750 to Nottingham hospital children's ward tomorrow 19 December 2017 Big-hearted Nottingham hackney taxi drivers are donating £2,750 to the children's ward at the city's Queen's Medical Centre (QMC) tomorrow (Wednesday 20 December). More than 500 licensed hackney carriage drivers – who are represented in a branch of Unite, the country's largest union – have come together for the first time to donate money to the hospital's Big Appeal for highly specialised diagnostic equipment that accurately identifies illness and disease at an earlier stage. Unite branch secretary Kaleem Ashraf said: "Our drivers are local people and we are proud to serve our city. This time of year is about giving, doing our bit and showing that Nottingham is together. It's a new initiative from the branch. "Hackney cabs are a vital part of the city's economy both day and night - keeping the city moving 24/7. Now Nottingham's hackney carriage drivers in association with Unite have decided they would like to give a little back to their local community. "The cabbies are committed to making further contributions to other local charities in the future, while working closely in conjunction with the city council, as to the best way to direct any fund raising." Unite branch chairman Basheer Latif: "We all love Nottingham, and we all want what's best for this city. "Nottingham remains an inclusive place where all types of people and businesses can continue to prosper in the years to come. It is always nice to put something back and especially at this special time of year. "Not everyone will be fortunate enough to spend time at home with their family and this is just something we wanted to do to make life a little easier for others." Nottingham currently has 411 hackney cabs and over 500 drivers in the city. The cheque will be presented at the QMC tomorrow at 14:30. ENDS Notes to editors: For more information please contact Unite senior communications officer Shaun Noble on 020 3371 2060 or 07768 693940. Unite press office is on: 020 3371 2065. Email: firstname.lastname@example.com Unite is Britain and Ireland's largest trade union with over 1.4 million members working across all sectors of the economy. The general secretary is Len McCluskey. You may also be interested in... 'Tips' protest at TGI Fridays in London todayThis action is about much more than a change in tip policy. It's about standing up to an employer that thinks it can get away with bulldozing through changes unchallenged. Chorus of discontent over pay and bullying engulfs Royal Opera HousePerformances at the world-renowned Covent Garden venue, whose history can be traced back to 1732, will be disrupted this summer if the security guards vote for strikes. TGI Fridays hit with first ever strike ballots over tips and minimum wage abusesA protest will be held outside the TGI Fridays' Covent Garden branch to mark the launch of the first ever strike ballots to hit the company since opening its first UK restaurant in 1986. Cherry blossom flowers in long-running Fujitsu disputeThere will be a demonstration outside the Japanese embassy in London tomorrow (Thursday 5 April) in the long-running Fujitsu dispute which includes allegations of victimisation of workers who blew the whistle on unethical and possibly illegal company... Bromley library strike starts tomorrow over 'paltry' pay dealThe strike is the latest to hit the controversial Tory-controlled council which has made outsourcing the lynchpin of its polices


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- CreatorUnknown (Weaver)
- In the Style Of
- Place of origin
- Date of manufacture1960-1969
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- Materials and techniques
- ConditionExcellent.
- Dimensions
H 111 in. x W 63 in. x D 0.07 in.
H 281.94 cm x W 160.02 cm x D 1.78 mm
- Seller locationNew York, NY
- Seller reference numberMT.01
- Reference numberLU86522505972
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- Date: 30 July 2018 - 5 August 2018
- Location: Galway Race Course, Ballybrit
The Galway Races are definitely one of the most noteworthy events in the Irish calendar. Every year people gather from near and far to enjoy an always memorable day of fun, entertainment and racing. This 7-day event will be attended by over 140,000 people and is set to be a day to remember.
Conveniently located just 12 minutes from the event, Maldron Hotel Sandy Road Galway is the perfect spot to relax, enjoy a post-event dinner and wake up refreshed the next day. Our hotel offers free Wi-Fi and complimentary parking to all of our guests, to make your stay as comfortable and convenient as possible.
Galway Races take place from Monday the 30th of July until Sunday the 5th of August this year and is sure to be the best races yet. Tickets are priced from €20.00 per person and are available to book on GalwayRaces.com.
After a busy day at the races, relax in the newly refurbished surrounding of Maldron Hotel Sandy Road Galway which has just recently completed an €8 million refurbishment programme.
We have 3 different packages available for the races which all include breakfast on each morning, one evening meal and tickets to either the Monday or Tuesday of the races. Available is a two-night package or three-night package and a five-night package.
Conveniently located just minutes from the track, make sure to book your stay now and make sure you catch all the action at the 2018 Galway Races!


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- DescriptionBake Life Sweeter with Betty's Original Recipe Scratch Cake Mix. Easy to prepare and contains no preservatives or artificial flavors. Perfect for special occasions and those spontaneous celebrations when only "homemade" will do. (from Betty Crocker)Claims
- No Preservatives
- Nutrition
- Allergens
- Contains Wheat
- Ingredients
Sugar, Enriched Flour Bleached (Wheat Flour, Niacin, Iron, Thiamin Mononitrate, Riboflavin, Folic Acid), Cocoa Processed With Alkali, Corn Starch, Canola Oil, Baking Powder (Baking Soda, Sodium Aluminum Sulfate, Monocalcium Phosphate), Salt.
Betty Crocker Original Recipe Scratch Cake, Chocolate Joy
Like That? You'll Love This.
- $3.99/ea($6.88/lb)
- $5.19/ea
- $2.99/ea($2.99/ct)
- $3.49/ea
- Fresh Halved Strawberriesapprox. 8oz
- $2.49/ea($2.49/lb)
- $5.15/ea($5.85/lb)
- $3.49/ea($8.51/lb)
- Driscoll'sStrawberriesapprox. 16oz$4.99/ea
- $2.29/ea($2.29/lb)
- $4.99/ea($1.66/lb)
- $2.69/ea($5.38/lb)


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how do you change spark plugs in a 1999 dodge caravan
1 Answer
This is the best place I know of that tells how to removed your spark plugs. It has step by step instructions and pictures to help you. Good luck! http://www.autozone.com/az/cds/en_us/0900823d/80/1a/37/65/0900823d801a3765/repairInfoPages.htm
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- Well trained staff, though many are unfriendly.
- Beautiful private beach
- Average water sports (skiing 3 times per week - only 10 mins per time)
- Nice comfortable, though not "luxury" villas.
- Brilliant restaurant, lovely setting (Food did get boring after a while)
- Okay pool area
- Small beach, which fills up very quickly.
- Villas were clean and nice - but do not come here for a luxury getaway.
- Some unfriendly staff (don't get me wrong - some of the staff are very friendly)
- Value for money was lacking.
- Water sports were below par.
- Lack of pool lounger (or a sufficient number of loungers) in the pool area.
- The outside of the villas looms old, and dated.
This hotel is perfect if you are looking for a basic, comfortable family getaway, but for a bit more you could stay at the beautiful La Cannonier or Club Med which have a HUGE array of activities and water sports.More
- Free Wifi
- Free Parking