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Effective stack 80% max buy-in. Villain (UTG) bets 3xBB, Hero (Big Blind) calls with 5d 4d. Flop 6d 7d Ac.Action: Hero checks, Villain bets 3/4 pot. Hero goes all-in. Is it all-in good move considering that in most cases Vilain will throw best hand and if he does't throw hero will win in more then 50% cases at showdown. Also villain will throw his hand if he's on flush or straight draw.
Shoving with a straight+flush draw is a pretty standard play for NLHE in my book. You typically have enough equity to be even money against your opponent's calling range. That means you could call their shove and see a profit due to the dead money in the pot.
Almost any time that you could call and be even money, a shove is better, and the more money in the pot at the time of your shove, the better it is. You profit from every time your opponent folds in these spots - much more than you do if you both stay in the hand.
I made a mock hand-history to illustrate the situation.
$1 NL (6 max) - Holdem - 6 players
Pre Flop: Hero on BB has 5⋄ 4⋄
Flop: ($7, 2 players) 7⋄ 6⋄ A♣
Assuming all your outs are good and clean, then you have 9 diamonds (2⋄3⋄, 8⋄9⋄T⋄J⋄Q⋄K⋄A⋄) and 6 outs to a straight (3♣3♥3♠, 8♣8♥8♠).
Depending on your opponents range this very often equates to over 50% equity. Thus, you're likely to be the favourite to win the hand at this stage. All-in is OK but it may not be best!
There are a few things to consider when making a decision about the best play. Especially:
As I've laid out in the mock hand-history, you'd be shoving/paying $77 to win $89.25 total (your bet of $77 + current pot of $12.25).
I've tried to consider the range that your opponent would likely call with. I came up with
Obviously, your opponents UTG range is wider than this and he will fold a significant amount of the time to make a shove profitable, in addition to your strong equity.
I suppose it comes down to this, considering the other hands in your opponents range, Is it more profitable to give the opponent an opportunity to bluff some hands he might otherwise fold, by hero raising a smaller amount? I'd say yes. The only way to make this judgement is to know villains UTG range more clearly, which you don't mention. Calculating X and Y depend on this analysis of possible hand combinations.
It's difficult to come to a clear best answer but, when is it anytime in poker! I hope this gives you some ideas on making better decisions. :)
Adding the graph of dependance, X=% opponent folds to shove and f(x)=profit.
As you can see, more opponent folds, more profit you make. But even if he calls 100% of the time (x=0), you will be in profit of 0.971$
If it is your strategy to be playing these marginal hands in the first place. you probably need to have a more subtle strategy for letting their value come forth when you hit a gin draw like this. betting more of your stack than would be mathematically valid for a flush draw, even with the guarantee that everyone calls you all in when you make it, puts other people off of their draws as well. Betting about a third of your stack still will have many of the hands that originally called you all in, raising you all in, but you just call those anyway, really what you're looking to do is give the people who have your draws crushed and would have called you all in as many opportunities to put dead money into the pot and fold on the turn as often as possible. The hand that comes to mind specifically is Adxd.
This is just my intuition for this hand
Given the fact that you said "effective stack 80 % max buy-in", I'll assume this is a cash game we're talking about, not a tournament.
If villain has about the same stack as you, I think the all-in move is not a mistake. Even if he has an Ace or if he hits a set on the flop, you say he will still fold. In the worst case (a.k.a if he calls and wins), you will still be winning in the long run.


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I've been searching for an approximation that will allow me to solve for $p$ in $\frac{\log(p-1)}{\log p}$. Since it is so "obviously" $1 - \frac1{(\text{something})}$ for larger $p$ I thought it would be simple, but I have run into infinities with the substitutions I have tried so far. For my purposes I need an approximation with the following properties:
- It is invertible so I can have a simple function for $p$
- It is guaranteed smaller than the true expression
Since I am working with integers I was thinking that an expansion "around infinity" would work well, though I could probably use an expansion around $p=2$ if it converged to $1$ for larger numbers. I've considered either creating a series for the whole expression, or creating a series for the numerator only using a substitution which would give powers of $\log$, then I could divide through by the denominator.
So is there an obvious effective substitution that I am missing?

subset: commoncrawl


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Familial cold autoinflammatory syndrome
Other Names for this Disease
- Familial polymorphous cold eruption
- Familial cold urticaria
See Disclaimer regarding information on this site. Some links on this page may take you to organizations outside of the National Institutes of Health.
periodic fever syndrome. Signs and symptoms may include include an itchy or burning rash; fever; and joint pain which are triggered by exposure to cold temperatures. It is inherited in an autosomal dominant manner and can be caused by mutations in the NLRP3 or NLRP12 genes. Management of this condition involves avoiding exposure to cold temperatures and treatment with specific types of medications.[1][2]Familial cold autoinflammatory syndrome is a type of
Last updated: 10/30/2013
- Simon A, Van Der Meer S, Drenth J. Familial autoinflammatory syndromes. In: Harris et al.,. Harris: Kelley's Textbook of Rheumatology, 7th ed. Philadelphia, PA: Saunders; 2005;
- Familial cold autoinflammatory syndrome. Genetics Home Reference. September 2008; http://ghr.nlm.nih.gov/condition/familial-cold-autoinflammatory-syndrome. Accessed 10/28/2013.
GARD Video TutorialsLearn how to find information on treatment, research, specialists, and more.
Your Questions AnsweredView questions about this condition answered by GARD Information Specialists. You can also submit a new question.
Basic Information
- The Cleveland Clinic provides an overview of the different types of periodic fever syndromes.
- DermNet NZ is an online resource about skin diseases developed by the New Zealand Dermatological Society Incorporated. DermNet NZ provides information about this condition.
- Genetics Home Reference (GHR) contains information on Familial cold autoinflammatory syndrome. This website is maintained by the National Library of Medicine.
In Depth Information
- Medscape Reference provides information on this topic. You may need to register to view the medical textbook, but registration is free.
- The Monarch Initiative brings together data about this condition from humans and other species to help physicians and biomedical researchers. Monarch's tools are designed to make it easier to compare the signs and symptoms (phenotypes) of different diseases and discover common features. This initiative is a collaboration between several academic institutions across the world and is funded by the National Institutes of Health. Visit the website to explore the biology of this condition.
- Online Mendelian Inheritance in Man (OMIM) is a catalog of human genes and genetic disorders. Each entry has a summary of related medical articles. It is meant for health care professionals and researchers. OMIM is maintained by Johns Hopkins University School of Medicine.
- Orphanet is a European reference portal for information on rare diseases and orphan drugs. Access to this database is free of charge.
- PubMed is a searchable database of medical literature and lists journal articles that discuss Familial cold autoinflammatory syndrome. Click on the link to view a sample search on this topic.
Selected Full-Text Journal Articles
- Leigh D Church, Sinisa Savic, and Michael F McDermott; Long term management of patients with cryopyrin-associated periodic syndromes (CAPS): focus on rilonacept (IL-1 Trap), Biologics. 2008 December; 2(4): 733–742.
Other Names for this Disease
- Familial polymorphous cold eruption
- Familial cold urticaria
See Disclaimer regarding information on this site. Some links on this page may take you to organizations outside of the National Institutes of Health.


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You're the kind of fan that has a compulsory need to flaunt your Rangers passion everywhere you go. You can't stop yourself, and you wouldn't want to even if you could! You're absolutely fanatical, and these Texas slogan magnets will keep your passion on display! This 12" x 12" sheet features three Texas magnets in full team-colors, including two Rangers logos and a large "Claw Antler" magnet. Because they're removable and reusable, you can stick them to your car, fridge or locker - or to someone else's! With these magnets, the Rangers will go wherever you go so that you'll leave no one in doubt about who rules the diamond!
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I have a non-georeferenced vector layer that I need to be georeferenced. With raster layers the task is easy and straightforward, but I have no idea what should I do with my vector layer. I have a few control points with known coordinates which should provide some basis to transformation. So, let's say I know points with id-s of 1, 2 and 3 should have the coordinates of x1,y1 ; x2,y2 ; x3,y3. There might be some rotation and scale transformation in addition to simple shifting. Any ideas?
To georeference a vector layer, try the qgsAffine plugin. More info here: Where to find qgsaffine in the menu?
Given the fact that you have some points of control, you should be able to use an Affine transformation to shift your vector data. Have a look at this recipe. The process is a two part process:
If you put your control points into a CSV file (old_x,old_y,new_x,new_y), you can just about cut'n paste the R commands from the link to solve the coefficients part.
see my answer in this thread: Snapping two polygons together and give the free openjump a try. its affine transformation is much more userfriendly than qgis affine plugin
Following-on from my comments on Rayner's answer, GRASS v.transform, which can be run from the Sextante toolbox, can be used to calculate transformation parameters and apply them to a vector layer to perform an affine transformation. A text file containing control points is required, in the format shown here.
It's very easy to use and works well.
With the release of GDAL 1.10 this is now possible.
It is done by performing a basic transformation in ogr2ogr and supplying the control points in the -gcp tag. http://www.gdal.org/ogr2ogr.html
For a guide please see: http://gisforthought.com/georeferencing-vector-data-using-qgis-and-ogr2ogr/
I recommend the Vector Bender plugin for QGIS. I tried it and it works fine and is user friendly. Depending on amount of pair of points that you define, you can either do:
You find a short video here and I advice you to read the Vector Bender help once you installed the plugin.
I just had to do that, and ended up doing this :
The following script computes the affine transformation matrix using the saved GCPs :
You can use the spatial adjustment method in ARC GIS. Once you add into arc Map, you need to make it editable than after spatial adjustment option is enable.And you also import your control point Spatial Adjustment->Link->Open Link.......
For more details please refer Spatial Adjustment section of ESRI help


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I'm 25 (born 1987). When I was young (must have been very young) I saw a show or movie that was an anime, but the kind that has a mature drawing style, smaller eyes, more serious, and the character that I remember had long blue hair, they were soldiers, but it was very futuristic, and they were hiding in a forest from these robots/mech things.
I also then remember a scene where they were sneaking into this quarry or something and the bad soldiers, had these bug heads (or helmets)
Does any one know? this is killing me!!!


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Chicken Wraps with Creamy Olive Dressing RecipeChicken Wraps with Creamy Olive Dressing
Sandwich wraps are a great option when you need a quick lunch. Unfortunately, with extra large tortillas and heavy sauces, the wraps you pick up at fast food restaurants and delis are loaded with calories, fat, and sodium. When you have leftover chicken on hand, this healthier version takes only 15 minutes to prepare. You can use your favorite variety of wrap, and the chicken can easily be swapped with cooked chickpeas for a vegetarian version.
Yield: 2 wraps
Preparation time: 15 minutes
- 2 tbsp finely chopped black olives
- ¼ cup plain, non-fat Greek yogurt
- 1 tbsp crumbled Feta cheese
- ¼ tsp dried oregano
- ¼ tsp garlic powder
- 1/8 tsp ground black pepper
- 2 8-inch whole wheat flour tortillas
- 4 oz. cooked, shredded chicken breast
- 1 cup shredded lettuce
- ¼ cup chopped tomato
- In a small dish, stir together the olives, yogurt, and Feta cheese. Stir in the oregano, garlic powder, and black pepper.
- Spread half of the dressing on one of the tortillas. Spread the dressing thin so that it reaches very close to the edge.
- Working at the end of the tortilla that is closest to you, sprinkle 2 ounces of cooked chicken over the dressing, and make sure to pile it towards the bottom third of the tortilla. Top the chicken with shredded lettuce and tomatoes.
- Working from the end closest to you, roll the tortilla up over the toppings, tucking it under tightly. Roll away from you as you continue to tuck in the sides and the fillings. Once completely rolled up, cut in half before serving. Repeat with the second wrap.
Nutrition information for one wrap: Calories 254; Total Fat 5.9 g; Saturated Fat 1.5 g; Trans Fat 0 g; Cholesterol 50 mg; Sodium 276 mg; Carbohydrate 27.7 g; Fiber 4.1 g; Sugar 2.8 g; Protein 24.7 g


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In Piskunov's Calulus (P375 & P385) & Hardy's Integration of Functions of a Single Variable (P48) mention is made of Chebyshev's theorem on the integration of binomial differentials however no proof for the general case is offered. I'm wondering if anybody has a proof of this theorem in general & hopefully a few references in English that discuss this theorem. My suspicions are that this theorem can be proven using methods of differential algebra (whether it actually is in the literature or not is another story) though I'm really hoping for something along the lines Chebyshev himself would have followed (along the strands thread out in Hardy's book), thanks for your time...
Two other books are: MR0617377 J. Davenport, On the integration of algebraic functions, and J. F. Ritt, Integration in Finite Terms. Liouville's Theory of Elementary Methods.
Third. The idea is simple. In all cases, except those 3 when the integral is known, the Riemann surface of the integrand is completely ramified over 3 points. Such surfaces are of positive genus. Of course this is not a proof but just a hint, one needs to study the monodromy group.
However it is really interesting how Chebyshev proved it: they say Chebyshev did not use even complex numbers, not speaking of the monodromy group:-)


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Houston Landmarks
3 of 10
Williams Water Wall
This horseshoe-shaped urban waterfall, designed by award-winning architect Phillip Johnson, pumps 78,500 gallons of water every three hours. The Water Wall is 64 feet tall, representing the adjacent 64-story Williams (formerly Transco) Tower. The surrounding park was added as an amenity to the fountain and has been a popular tourist spot since its inception.
Fun Fact: Architect Phillip Johnson won the prestigious Pritzker Prize for designing the Water Wall.
Photo source: Carol M. Highsmith
Next: The Orange Show
Provided by Infoplease—an authoritative, comprehensive reference website that offers an encyclopedia, a dictionary, an atlas, and several almanacs. Visit Infoplease.com to find more resources endorsed by teachers and librarians.


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Shreveport Service Center
Denise is proud to serve Caddo Parish as Membership Specialist. She counts herself blessed to meet so many wonderful volunteers, community leaders and girls during her recruitment efforts. She has been on staff since 2011. She was a Girl Scout Brownie and Junior as a girl. Her fondest memories are of camping and troop meetings. Before joining the staff she was a Parent Volunteer for her daughter's troop for three years. Denise is involved with Salvation Army, Goodwill Industries and Red River National Wildlife Refuge. She has been married for 24 years and has two children.


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December 4, 2007
I went to an orthopedic ankle doctor/surgeon at the University of Minnesota today whom I have seen once before (1.5 years ago for the same problem). He actually referred me to the doctor who performed my ankle surgery a year ago. My appointment was at the Riverside Orthopedic Clinic and I have to say the place was hectic and an unorganized mess. Despite that I had called them multiple times before my scheduled appointment to make sure that they had received my records, there were no records to be found today. More than one woman who works there assured me the records had been faxed and received (note to self: next time write down the woman's name who says such things). So, despite having to wait extra long because the doctor was running behind, I had to wait an additional amount of time while the nurse got my records re-faxed over to the clinic. What is the point of me even calling to assure that my IMPORTANT records and information are there in time for my appointment if I'm not being told the truth anyway and they are NOT THERE? Frustrating.
Even more frustrating was that the doctor basically told me he can't think of anything else to do to help me. He does not want to fuse the bones of my ankle joint together (this is permanent, of course) because contrary to my pain and swelling, the MRI scans show a "normal" joint. This is good. But he also didn't think I should have another synovectomy procedure done on it, since it didn't seem to help much in the first place. He suggested the only thing to do is to live with my ankles the way they are and to monitor the pain by using pain medications. I do NOT want to do this, of course. I can't handle heavy pain meds and anyway, I want this problem FIXED! I don't want to just mask the problem with drugs. I sat there trying to hold back tears of worry and frustration and asked what else can we do? The only other thing he suggested was to get another MRI scan done and then see if that shows anything different and to go from there. So, not a lot to hope for, but I agreed. I'm having yet another MRI scan tomorrow afternoon at CDI (I think I've had 5 now on these ankles?). I'm trying to not have a panic attack about this and to take it step by step, but I admit it's really hard sometimes to "keep it together." I do believe in medical miracles (all miracles really), and I still have hope that things can and will improve. It sucks though. It really does.
I waited for the nurse to come back into the room to give me the MRI scheduling info. As I waited, I stood by the open door and noticed a man sitting in a room across from mine. He had grayish hair and his body was slumped over as he held his face in his hands, crying. I was taken aback to see such a display of emotion from anyone, especially a man (it's not often you see a man crying in an examining room). Tears immediately pricked my own eyes and I looked at him again and noticed that he was missing a leg. In its place was a robotic-looking prosthetic that reached all the way to his hip. He must have just gotten some bad news, I guessed.
The nurse returned and I walked out of the examining area thinking about this poor man sitting there alone and crying. For a second I said to myself, things could be worse, you could be like him. But that's no comfort, of course. Why can't we both be well and whole? Why all of this pain and suffering in the world? It's so unfair.
I wish I would have offered him a hug or something.
4 Responses to "Pain"
April 16, 2008 at 11:00 pm
I agree with not fusing an ankle. My mom has RA too and she has not had any success with fusing bones/joints that are meant to move. She had her toes all fused and eventually they all came apart because she walked on her feet and loosened the fusion up.
Sorry that is of no help to your suffering ankle. My mom uses athletic tape to tape her ankles and wrists, it works better than fabric braces – but if socks hurt that won't work either.
September 18, 2008 at 2:52 pm
With regard to that brace, were any of the braces constructed from an actual cast of your ankle?
This makes a huge difference, and my patients have experienced great relief from these braces.


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Ongoing: Microfabrication at Berkeley - Video
Ongoing: Berkeley Sensor & Actuator Center – Select Research Project Posters
4:30: Plans for the Marvell Nanofabrication Laboratory – Slide Show, Q/A
The UC Berkeley Microfabrication Laboratory is a shared cleanroom facility that is used for research in semi-conductor devices and technology, micro-electromechanical devices and systems (MEMS), bioMEMS, optoelectronics, superconductive devices, and nanoelectronics. The laboratory is a recharge operation maintained by a full-time professional staff, that offers specialized tools, process modules, and integrated processes to academic and industrial researchers. The Microlab presently has over 400 active members; more than half of this membership originates in departments other than EECS.
The Berkeley Sensor & Actuator Center (BSAC) is the National Science Foundation Industry/University Cooperative Research Center for Microsensors and Microactuators. With more than 100 researchers, BSAC is the largest single set of Microlab members. BSAC researchers use the Microlab and their own research facilities to conduct industry-relevant, interdisciplinary research on micro- and nano-scale sensors, moving mechanical elements, microfluidics, materials, and processes that take advantage of progress made in integrated-circuit, bio, and polymer technologies. BSAC research projects stimulate cross disciplinary research and attract Microlab members from Bioeng, Chemistry, Chemical Eng, Materials Science and Eng, Mechanical Eng, and Physics.
During 2009, the Berkeley Microlab will migrate to the Marvell Nanofabrication Laboratory in the New Sutardja-Dai Hall (CITRIS Building). Construction is scheduled for completion in February 2009. The Marvell Lab will replace and significantly expand the capabilities of the present Microlab.
To learn more about BEARS 2009 and register: http://www.eecs.berkeley.edu/IPRO/BEARS/


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In $D_4\times\mathbb Z_2$, find normal subgroups $H$ of orders $2$,$4$, and $8$. For each $H$ describe $G/H$.
I know what makes a subgroup normal, but I don't know how to find one. And what would it mean to describe G/H? I could think of is maybe the left cosets and isomorphic subgroups?


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STEUBENVILLE -- City Council will consider a new $10,000 retirement or resignation program to allow city employees more time to consider their options.
Council failed to pass emergency legislation last week to offer a $10,000 retirement or resignation program to city employees because three council members voted against the measure.
The council also prepared for their final regular meeting of the year with a list of end of the year legislation to be considered at next week's session.
Second Ward Councilman Rick Perkins introduced an ordinance to declare buildings located at 1409 State St., 711 N. Seventh St., 235 N. Eighth St., 312 Mears Ave. and 523 Maxwell Ave. to be unsafe structures and ordering their demolition.
Perkins also proposed an ordinance from the Planning Committee authorizing the advertisement for a request for qualifications for professional services under the Ohio Community Housing Improvement Program.
Nine ordinances were introduced from the council Finance Committee including a revenue tax budget for 2012 and a temporary revenue tax budget for 2013.
Other legislation introduced by Sixth Ward Councilman and Finance Committee Chairman David Lalich included a measure to make final appropriations for expenditures this year.
Lalich also introduced an ordinance authorizing the finance director to repay $147,183 from the American Recovery and Reinvestment Act federal grant fund to the street fund..
And an ordinance authorizing the approval without a purchase order over $3,000 over several bills.
Legislation adopting the indirect cost allocation plan for the city was also introduced.
Read the Wednesday edition of the Herald-Star for all the details from the City Council meeting.


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I took a landscape photo in portrait orientation. Now, when I rotate the picture into correct orientation, it looks smaller than the original sideways image. I want to maintain its original height and width.
Based on Anisha's verification, The question can be summarised as:
A number of "solutions" are provided below.
4:3 ratio picture
Any other screen and image ratio can be assumed.
"Took a landscape photo vertically" is assumed to mean that the camera was held in portrait orientation to take the photo / long axis vertical / 4 tall, 3 wide.
When the photos were presented to you they presumably were in landscape mode, long acis hozizontal, so that the photo was "on its side". The photo could be fitted to fill a 4:3 display (4 wide, 3 high.)
Now the fun begins.
As the image height fits the screen height it's area as a % of screen area is 56.25% of screen area.
You cannot make the image taller without some of it being above screen dimensions.
The image looks small because it IS small compared to available screen size. It is only 56.25% as large area wise as an image that fits the screen "properly".
Note that if you print this image and display it in portrait mode, as it was taken, then it will be as large as a landscape image printed full size on the same size paper - it is only a screen problem.
There are various things you can do about this depending on how serious you are.
Anisha confirms that the problem being addressed above is indeed the problem that they want solved.
Anish - If Drewbenn described you problem exactly then my answer tells you a number of ways to "solve" it. None are ideal, but arguably the best one is to realise that this is an effect that is unavoidable with a minitor of a fixed size, and that taking pictures in landscape mode is necessary if you want to view them fully filling the sceen. The coices are to fit the heightm abd have empty area either side, or to fill the width, nand then crop top and/or bottom.
This isn't an answer, just an attempt to clarify the question, and I need the space that an "answer" provides. Is this what you're seeing? If not, you may need to share the exact list of steps that you're taking (run program X. Go to File menu, select Open, browse to the image I want, select OK. Go to Edit menu, select Rotate.....) to get a useful answer.
Here I'm looking at my image "normally" in my image viewer. The image viewer is displaying a 3:2 aspect ratio image in a window set up for a landscape image; you can see that the picture takes up the full height of the viewing area but not the full width, although it almost fills the width of the canvas. In the status bar, you can see that the image is scaled to 23% of its original size (if I was viewing it at full size, that number would be 100%).
Okay, now I went to Image | Rotate Clockwise, and the image has been rotated. My image viewer program hasn't resized itself, and is now trying to fit the image, with a 2:3 aspect ratio, inside the same landscape canvas. The image still takes up the full height in the canvas, but only a small fraction of the width. If you look at the status bar, you see that the image is now scaled to only 15% of its original size:
The image resolution hasn't changed (just been reversed from 3504x2336 to 2336x3504, as you can see in the status bar in each screenshot). The only thing that has changed is the amount of room that the image viewer has available to fit the picture onto the screen, so the image viewer has rescaled the image to fit in the provided canvas.
Some pictures like this (taken with a medium format camera):
have a square form factor, and will by definition have the same scale if rotated. What you can do is to crop your picture to a square (of course you will lose parts of the image) or even to a landscape format. But for portrait pictures the first option may be more appropriate (or maybe less inappropriate).
But since your screen is wider than tall, landscape format will always appear bigger.
I just discovered that if you crop the image in photoshop you can include all the areas you want... then save as a jpg transport the picture to your desktop. Then just drag and drop your picture in to your document. This will keep edge image areas that were annoyingly cropped out before. Hope that helps.
Pauline Neal


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(Gluten-Free, Gout-Friendly)
1 cup frozen, pitted sweet cherries
1 cup skim milk
1/2 cup light vanilla yogurt
Freezing fruit before blending lets you skip ice cubes. Put ingredients in blender. Puree until almost smooth. Pour into two glasses.
Each serving contains about 133 calories, 6 g protein, 0 g fat, 25 g carbohydrates, 2 g fiber, and 95 mg sodium.
Reviewed Date: 03-25-2013


text:
Region Chops Sandy Debris Down to Size
The immense task of leveling the mountains of debris left behind by Sandy is coming into focus two months after the historic superstorm ravaged the East Coast.
In the end, the federal government estimates that 16 million cubic yards of debris piled up around New York and New Jersey—enough to fill the Empire State Building 16 times over—though more than half has yet to arrive at landfills.
Tons of refuse including sodden furniture, uprooted trees and smashed houses amassed at collection points in New York and New Jersey, where it formed towering monuments to the scale of the storm's destruction.
For weeks, one trash heap had filled about a quarter of the parking lot of Jacob Riis Park in the Rockaways. By last week, it was all but gone, as Army Corps of Engineers contractors carted away 177,183 cubic yards of debris dumped at the park by city sanitation crews.
"It was a long haul," said Jimmy McGovern, a deputy chief of the city's sanitation department who is overseeing the cleanup of the Rockaways. "Now we're coming toward the end of it. We're seeing the fruits of our labor."
Mounds of debris made the Rockaways look like a "war zone" in the days after the storm, but they're now mostly gone, said Finbarr McDowell, 40 years old, of Rockaway Park.
However, he pointed to remaining work, including the removal of several burnt-out buildings and a lot full of demolition debris on Rockaway Beach Boulevard, near his apartment. "The cleanup is going to take time, you know?" he said. "It's tough. You can't blame anybody."
Even as some cleanup projects are wrapping up, others are just starting. Last week, Gov. Andrew Cuomo said the Army Corps of Engineers would begin overseeing removal of debris from Fire Island, the community of mostly summer homes off the South Shore of Long Island.
Cleanup on Fire Island presents a challenge because the infrastructure there is made up almost entirely of boardwalks and narrow dirt roads, the governor's office said. The Federal Emergency Management Agency has approved $30 million for the project.
All in all, workers have cleared away about 4.2 million of the six million cubic yards of Sandy debris in New York state, estimated Mike Byrne, the FEMA coordinator overseeing the state's recovery. That includes about 90% of debris in New York City, he said.
The Army Corps of Engineers has overseen the cleanup of more than 330,000 cubic yards of garbage from sites primarily in the Rockaways, Staten Island and Red Hook, said Patrick Moes, an Army Corps of Engineers spokesman.
That refuse made its way to landfills in 10,813 truckloads, Mr. Moes said
In New Jersey, FEMA says the storm created about 10 million cubic yards of debris and three million has been picked up, according to Darrell Habisch, a spokesman for the agency's New Jersey office.
"We had 1.2 miles of boardwalk destroyed, all four pavilions up on the boardwalk destroyed, and then we had flooding in approximately 1,400 houses or properties, so that meant 1,400 pairs of washers and dryers, 1,400 furnaces," said Matt Doherty, the mayor of the seaside borough of Belmar.
The municipality worked to truck garbage out of neighborhoods and move it to the Belmar Marina as quickly as possible, Mr. Doherty said, because "the emotional and psychological effect of seeing debris just remain there day after day can be a detriment to the community."
As of last week, workers had trucked almost all of it—about 7,250 tons—from the marina to a landfill in Ocean County, Mr. Doherty said.
On Long Island, a company called Insurance Auto Auctions is storing about 15,000 storm-damaged cars from across the island on a pair of airplane runways in Riverhead Town, said Sean Walter, the town supervisor.
The site will gradually clear out as the vehicles are auctioned off, he said. "They are moving off the property at a greater clip now," he said.
In Long Beach, an oceanfront city on Long Island, almost every front yard was littered with ruined furniture and drywall in the days after the storm.
The city's public works department spent six weeks cleaning up the mess, and last week, front stoops and yards were visible once again, said Gordon Tepper, the city's spokesman.
Long Beach has received $24 million from FEMA for debris removal, but is hoping for more, because the city's total storm recovery bill is estimated to be $250 million, Mr. Tepper said.
Still standing is what local officials call Mount Sandy, a mound made from much of the sand that once filled the city's streets and parking lots after the storm. It towers over an oceanfront parking lot and rivals nearby six-story apartment buildings in height. The city is using excavators and dump trucks to chip away at the pile, hoping to get the sand back on the beach by summer.
This month, Long Beach will begin tearing down its entire 2-mile boardwalk, Mr. Tepper said. He said the hope is for that to be replaced by summer as well.


text:
4 Dec 2012 4:38 AM #1
[2.1] Sheets / ActionSheets / Picker flying of the screen
Since some 2.1 preview version, can't remember exactly which, sheets that are supposed to slide in from the bottom fly off the screen on Chrome, iOS and Android.
This has something to do with the show animation, turning it off fixes it.
I wasn't able to reproduce this in the kitchensink nor isolate it yet. In the isolated test I did the other day it worked.
Still thought I file a bug, maybe somebody else can provide more info.
4 Dec 2012 7:24 AM #2
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Just tried this on a couple different devices and could not reproduce. Would need to repro it to find the bug:
var actionSheet = Ext.create('Ext.ActionSheet', { items : [ { text : 'Delete draft', ui : 'decline' }, { text : 'Save draft' }, { text : 'Cancel', ui : 'confirm' } ] }); Ext.Viewport.add(actionSheet); actionSheet.show();Mitchell Simoens @LikelyMitch
Sencha Inc, Senior Software Engineer
Check out my GitHub, lots of nice things for Ext JS 4 and Sencha Touch 2
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13 Apr 2013 9:11 AM #3
This is happening with all of my ActionSheets, Pickers, selectfields. Was working in 188.8.131.52, broken in 2.1.1. Sometimes they fly off the top of the screen and then come back, sometimes they disappear entirely and just leave a blank screen which breaks the app entirely. A quick search of the forums shows that this has been buggy for a year.
Couple of easy ways to reproduce. Take the bottom-docked tab panel example, add a card layout to one of the tabs, add a FormPanel to one of the cards, add a selectfield to the form. Works ok the very first time you click on the selectfield, but then cancel it and try to select it again and it breaks from that point on.
On another card, add a button or link or something that opens a Picker. Same behavior.
Also on the same bottom tab panel, add a Container to the Viewport with a toolbar docked to the top, with a button in the toolbar that creates an ActionSheet. Show it and hide it a few times. Same behavior.
If I add a hide listener that destroys the ActionSheet after a brief timeout, that works, but I need my form elements and Pickers to exist.


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What does the power button on the Apple Wireless Keyboard do? When it is paired to a MacBook in clamshell mode, does pushing the power button put the MacBook to sleep, wake it up, or have some other effect? Is the power button strictly limited to turning on and off the keyboard itself?
The power button only powers ON/OFF the keyboard, it doesn't power off the computer.
To power off your computer using the keyboard, you might want to use any of the following:
⌃ Control + ⏏ Eject : Show shutdown dialog
⌥ Option + ⌘ Command + ⏏ Eject : Put the computer to sleep
⌃ Control + ⌘ Command + ⏏ Eject : Quit all applications (after giving you a chance to save changes to open documents), then restart the computer.
⌃ Control + ⌥ Option + ⌘ Command + ⏏ Eject : Quit all applications (after giving you a chance to save changes to open documents), then shut down the computer.
⇧ Shift + ⌃ Control + ⏏ Eject : Sleep the display, but not the computer. (thanks to VxJasonxV)
Yep. The wireless keyboard software detects inactivity and will go in sleep mode where it reduces power consumption, however it's probably better to turn it off if you know you won't be using it for a while. You must press that button for a few seconds. The light will show, then it will disappear while you are still holding the button. Then you know it is off.
When you turn it off that way it should display a notification on the OS X desktop, that the bluetooth device was turned off.
I'm not using one anymore. When I did, I would often forget to switch off the keyboard.
Now that I think of it it would be nice if there was an option for the computer to tell the keyboard to power off. That way when you shut down your Mac it would power off. I don't remember seeing such an option :(


text:
6 Bizarre Incidents that Prove God Hates Sports
Whether we like to admit it or not, a whole bunch of us only watch car races in hopes of seeing a spectacular crash. Likewise, we follow other sports like reality television, never happier than when some big star goes apeshit on national TV. In other words, many people only become sports fans when things go horribly wrong.
This article is for them.
#6. The Baseball Game that was Called on Account of Bees
Ahh, bees. Mother Nature's way of telling us "I love you guys, but seriously -- screw you sideways for Chernobyl and plastic bags."
Bees are a big problem for backyard barbecues and honey thieves, but as far as we can tell, they've never substantially altered the course of a professional baseball game. That all changed on March 25, 2005. After five innings, the Colorado Rockies and the Arizona Diamondbacks were forced off the field by hundreds of angry bees.
Via MLB
Sergio Santos exhales bees onto the field, Green Mile style.
Darren Oliver, pitcher for the Rockies, was the first player targeted. The swarm apparently smelled his coconut hair gel and decided his head was the perfect place for a giant bee feast/orgy. The Diamondbacks tried to take the field in the sixth, but "by then the bees had spread over the entire field." The shortstop was chased into the far end of center field and, after a brief discussion, the humans elected to flee Tucson stadium.
Via ESPN
Darren Oliver runs from a bee, screaming like a 12-year-old girl.
This sounds like the sinister prelude to a bloody worldwide invasion, but so far the bees have held back their awful wrath, and incredibly, no one in the crowd of 8,029 reported any stings. The Invasion of Tucson was simply a show of force from the Mother Hive. People of Arizona: You live or die at the pleasure of the All-Queen!
Via Science Daily
#5. Zeus Hates Soccer
When someone mentions the "dangers of soccer," getting hit in the face with a ball, or possibly getting gouged with some cleats comes to mind. But it isn't a contact sport like football or rugby or sex-jousting, so there really isn't much to worry about. Unless, of course, you've pissed off Zeus, which at some point soccer apparently has.
What we're trying to say is that soccer games seem to be absolute magnets for lightning. Even when it's not storming.
They're making evil in there.
On May 3, 2009, a bolt of lightning struck a soccer field in southern Germany and wounded 26 teenagers. One even died on scene, but was later resuscitated and is now (presumably) some manner of supernatural crime-fighter. More recently, this April, a lightning bolt injured seven more young soccer players.
With sick, extreme fisheye-lens wrath.
The details vary in each strike. In Germany, the players reported no stormy weather or warning whatsoever. Meanwhile, at a soccer game in Michigan, 10 players were struck by lightning as they huddled underneath the same tree for cover. Which we're fairly certain is the exact opposite of what you're supposed to do in a lightning storm, second only to perhaps climbing said tree and waving a 9-iron in the air.
Lightning, preying on trees -- and everything else within 100 yards of it.
But both of these disasters pale in comparison to a 1998 soccer game between two Congolese teams. They were tied in a thrilling (well, as far as soccer goes) 1-1 game when a storm began to brew overhead. Suddenly, a bolt of lightning streaked out of the sky and hit the visiting team -- killing all 11 players instantly. The home team was left unharmed, leading to immediate suspicions of witchcraft.
We actually don't have a convincing argument to counter that claim.
#4. Head-On Collision Ends a Doubles Match
Professional tennis seems like it gets a raw deal in America. You've got athletes serving up balls at more than 130 miles-per-hour directly at each other, yet it seems like we only give celebrity status to about one player per generation. We're honestly astounded that human beings exist with the reflexes and visual acuity to actually play this game. Which just makes it all that much more hilarious when something goes ridiculously wrong.
Via Sports Shooter
Nope, we're not above laughing at that.
This is precisely what happened during a Toronto doubles match involving the Aussie Mark Philippoussis and his partner, Croation pro Goran Ivanisevic, who already had a history of unlikely game-ending injuries. For example, Ivanisevic once broke multiple fingers after accidentally closing a door on his hand.
The trouble started when both men went after the same shot. Ivanisevic tried to head it over the net, while Philippoussis attempted to play it with his racquet.
Via AutoBlog.com
Known in the sports world as an "oh shit" moment.
The Aussie and the Croat were so focused on making the play that they both missed it entirely. Philippoussis and Ivanisevic collided head-to-head in mid-air, Three Stooges-style. Ivanisevic ended up requiring stitches, while his partner staggered away with a concussion. The two never partnered again, which is probably better off for everyone who doesn't make a living as a comedy writer.
Via TheSharkGuys.com
Not that we're complaining -- look at it!
Ivanisevic's battle with spatial awareness came to a head in 2003, when he was forced to withdraw from a tournament after stepping on a seashell at the beach and injuring his foot. For subsequent matches, we assume Ivanisevic was issued a football helmet, thick mittens and galoshes.


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The functions $\tanh x$ and $\arctan x$ have a similar graph. Is there a formula to transform $\tanh x$ to $\arctan x$?
The two functions resemble each other on the real line, but they're not the only sigmoidal functions around. There are functions as simple as $\dfrac{x}{\sqrt{1+x^2}}$ and as complicated as $\dfrac2{\sqrt \pi}\int_0^x e^{-t^2}\mathrm dt$ that also have the s-shape.
Also, the resemblance ends when we look at their behavior for complex arguments:
The former possesses branch cuts, while the latter exhibits periodicity on the imaginary axis.
On the other hand, a look at the Maclaurin series for $\tan\tanh\,z$ and $\mathrm{artanh}\arctan\,z$ gives a clue as to why there is some resemblance between $\arctan$ and $\tanh$:
$$\begin{align*} \tan\tanh\,z&=z-\frac{z^5}{15}+\frac{z^7}{45}-\frac{z^9}{2835}-\frac{13 z^{11}}{4725}+\cdots\\ \mathrm{artanh}\arctan\,z&=z+\frac{z^5}{15}-\frac{z^7}{45}+\frac{64 z^9}{2835}-\frac{71 z^{11}}{4725}+\cdots \end{align*}$$
There is no formula that "transforms $\tanh x$ to $\arctan x$" even though the graphs of the two functions look apparently similar: Both functions are odd, are defined on all of ${\mathbb R}$, and for $x>0$ are monotonically increasing to some finite limit. But that's where the similarities end: In particular
$${\pi\over2}-\arctan(x)\sim{1\over x}\ ,\qquad 1-\tanh(x)\sim 2e^{-2x}$$
when $x\to\infty$. This shows that the asymptotic behavior of the two functions is completely different.
As indicated in other answers, $\tan$ and $\tanh$ are related to the function $\exp$ whereas $\arctan$ and ${\rm artanh}$ are related to the function $\log$, whereby the transition from trigonometric functions to hyperbolic ones lives in the complex domain.
There is the identity $\arcsin(\tanh x) = \arctan(\sinh x)$, if that's what you're looking for. See Gudermannian function on Wikipedia.
They are only similar around the origin because their Taylor series agree up to fourth order, that is,
$\tanh(x) = x -x^3/3 + 2x^5/15 + O(x^7)$
$\arctan(x) = x - x^3/3 + x^5/5 + O(x^7)$
I don't believe there is any deeper reason why these look alike since one is an inverse trigonometric function while the other is a hyperbolic function (not an inverse).
If you define $f(t) = \arctan(\text{arctanh}(t))$, you'll have $f(\tanh(x)) = \arctan(x)$. $f$ is analytic in $|t|<1$, with Maclaurin series $f(t) = t + \frac{t^5}{15} + \frac{t^7}{45} + \frac{64}{2835} t^9 + \frac{71}{4725} x^{11}+ \ldots$
If we let $f$ and $g$ be defined by
$$\begin{align} f&:\mathbb{C}\to\mathbb{C}\\ &z\mapsto -i\tanh(z)\\ g&:\mathbb{R}\to\mathbb{C}\\ &:x\mapsto i\arctan(x) \end{align}$$
Then $f$ and $g$ are semi-inverses, in the sense that $f\circ g=$ is the identity map.
Another way to say the same thing: If we consider multiplication by $i$ as a function represented by $\mu_i$, then $$\mu_i^{-1}\circ\tanh\circ \mu_i\circ\arctan=\mathrm{id}_{\mathbb{R}}$$
So there is this relationship between the functions, along with all the others mentioned in other answers.


text:
Is it possible to pre-choose a private RSA key, then obtain a public key from it?
Yes, in general the private key is generated at the same time as the public key in RSA, first the $p$, $q$ primes, then $n = pq$, then the public exponent $e$ and finally the private exponent $d$.
If the private key is given as $(p, q, d$) then you can recover the public key easily. As long as you know the public exponent and $n$, you have the public key (and this means that if you cannot guess $e$, you need $d$ and the factorization of $n$, this is an instance of the RSA problem).
However, as @fgrieu points out, if the private key is stored as $(n, d)$ and $e$ is not conventionally chosen and unknown, then the public key is lost and cannot be obtained from the private key.
The opposite (private key from public key) is meant to be infeasible though.


text:
Taunton Swaim Scores CGS Hornet Victory
By Ben Deatherage
(Photo Courtesy of Madman Photography)
It was all smiles for Taunton Swaim and his car owner, or should I truck owner, Randy Kuhl in victory lane on Friday August 23rd. Swaim would win his first race of the year at the Cottage Grove Speedway in the Hornet division.
The main event started out with Veneta's Joe Maricle as the car to beat. Maricle took full advantage from his inside pole position start in the Ram Jack Foundation Repair #11 entry. Maricle built a decent lead in the early goings but just before the halfway mark Matt Cordell of Springfield would put the pressure on.
Cordell, in his Cartwright Automotive & Welding/Secure Transportation #51 entry, would catch and actually pass Maricle several times but Maricle would get the position right back. A caution on lap ten would give Maricle a little bit of a break from holding back Cordell and company off for the much desired lead.
Shortly after the ensuing restart Matt Cordell would get caught up in an incident that would end his night as he made heavy contact on the front stretch wall. Maricle would stay in the lead but on the ensuing restart Taunton Swaim would come into the picture as a potential contender.
A few laps after the restart Swaim would pass Maricle for the lead but Swaim was not out of the woods just yet. As several laps remained it gave Cottage Grove's Chris Pierce an opportunity to reel in Swaim and potentially make a late race pass. Pierce, in the Material Fabrication/Meineke Car Care #28, ran out of laps though and the win would go to Swaim. Swaim became the eighth different point race winner after he put the Big Dog Recycling/A-1 Auto Supply #17 in the winner's circle.
Chris Pierce would finish a respectable second followed by Joe Maricle in third. The balance of the top five would consist of the Rapid Delivery/Big Dog Recycling #48 entry of Mike Swaim from Dexter in fourth and K.C. Scott from Springfield driving the Dalton Carpet/T.L. Morgan Motors #30. Matt Cordell was fastest in qualifying and won both the heat race and trophy dash.
The Cottage Grove Speedway will be back in action on Saturday night August 24th. Classes competing include Late Models, Northwest Extreme Sprints, Street Stocks, and Hornets. For more information www.cottagegrovespeedway.com.
Race Summary:
Friday August 23rd, 2013
Cottage Grove Speedway
Cottage Grove, Oregon
A Feature: 1. 17-Taunton Swaim[4]; 2. 28-Chris Pierce[5]; 3. 11-Joe Maricle[1]; 4. 48-Mike Swaim[2]; 5. 30-K.C. Scott[8]; 6. 34-Mike Simmons[3]; 7. 51-Matt Cordell[6]; 8. 89-Jim Simmons[7]
Dash: 1. 51-Matt Cordell; 2. 28-Chris Pierce; 3. 11-Joe Maricle; 4. 17-Taunton Swaim
Heat 1: 1. 51-Matt Cordell[4]; 2. 28-Chris Pierce[2]; 3. 17-Taunton Swaim[3]; 4. 34-Mike Simmons[6]; 5. 48-Mike Swaim[5]; 6. 11-Joe Maricle[1]; 7. 89-Jim Simmons[7]; 8. 30-K.C. Scott[8]
Qualifying: 1. 51-Matt Cordell; 2. 17-Taunton Swaim; 3. 28-Chris Pierce; 4. 11-Joe Maricle; 5. 48-Mike Swaim; 6. 34-Mike Simmons; 7. 89-Jim Simmons; 8. 30-K.C. Scott
Driven by MyRacePassTM
Cottage Grove Speedway | All rights reserved


text:
MCGREGOR (November 2, 2012)--The 5th annual Central Texas Family Fair sponsored by SpaceX is going on now through Saturday.
Rides, arts & crafts, face painting, live entertainment, food and giveaways will set the scene from 6 p.m. until 10 p.m. each night.
The event is free but barbeque plates are being sold to raise money for local charities and a scholarship fund for students.
Gloryland Church and other local organizations are helping to provide the fun on the grounds of Weston Inn and Suites on W. McGregor Drive.
For more information, call (254) 486-2999.


text:
Hi guys, first of all I want to introduce myself to the Dueling Blades community. My name is Adi, and I'm the community manager for Dueling Blades. I'm here to help you guys enjoy Dueling Blades by answering your questions and taking your feedbacks.
We are preparing to launch the official version of Dueling Blades in Kongregate soon. Characters created on the Beta version will no longer be available and you will have to create a new character. For every Kongregate kreds you've spent in the beta version, you will get the same exact amount reimbursed in Diamonds.
We've worked very hard in adding new features and balancing the difficulty. It is now easier to progress through the main quest. Navigating through the menu is now easier due to a revamped UI. There are several new rare armors for each class, and we've also added a slot machine. We apologize for the inconvenience and we truly appreciate your continuing support of Dueling Blades. We hope you enjoy the game.


text:
Slow Hostel
Slow Hostel is the best budget accomodation in Joao Pessoa, we don't extra charge you when you arrive. Breakfast, wi-fi, a fully equipped kitchen for self-catering as well as all the linen are FREE.
Set in a large, charming and beach-side house, in the best neighbourhood in Joao Pessoa - Manaira, we are proud to tell you that Slow Hostel is the perfect place to feel at home while on a trip.
We offer 5 big and comfortable rooms. You can chose among a couple room, a family room, a female or male room or/and a mixed room and you have the option for air-conditioner.
We are within walking distance from an abundance of day and night activities (10' to 15'), cafe's, touristic spots (15'), fantastic price&delicious restaurants and places to visit, staying at Slow Hostel is really fun and convenient.
Guests with bookings are 24h welcome, Our reception is there to make your journey the most enjoyable experience, from finding out what is happening in Joao Pessoa to booking day excursions, adventure activities and overland trips. Our professionalism and local knowledge ensures you the holiday of a lifetime!
We look forward to seeing you in Joao Pessoa soon! Please don't hesitate to contact us for any travel questions.
Don't waste your time, come to enjoy the life with Slow Hostel.
If you have to cancel your booking, you must do it at least 48hrs before arrival.
Check in: 14:00
Check out: 12:00
If you book between December 15th and March 15th you will be charged 50% in advance in order to secure your booking (non refundable) - for special evenements too (conference, concerts...)
You also may be contacted by the property requesting the CVV code of the credit card used for this booking or asked for a deposit.
This also applies if your booking is during a national holiday, New Year`s eve or Carnival and special dater (conferences, concerts...)
Availability & RatesTo view availability and prices please select dates and click 'Update Dates'
Hostel Facilities & Policies
- Age Restriction
- Air Conditioning
- Airport Transfers
- Bicycle hire
- Board Games
- Free Breakfast
- Cable TV
- Café
- Common Room
- Credit Cards Not Accepted
- Currency Exchange
- DVDs
- Free City Maps
- Free WiFi
- Hair Dryers
- Hot Showers
- Internet Access
- Self-Catering Facilities
- Laundry Facilities
- Linen Included
- Security Lockers
- Outdoor Terrace
- Parking
- Tours/Travel Desk
- Towels For Hire
- Washing Machine
Cancellation PolicyThis property has a 7 day cancellation policy. Failure to cancel within this time will result in a cancellation charge equal to the first night of your stay.
Must-Read Hostel InfoThis property has specific Terms & Conditions.
Please note that guests under 18 years of age must stay in a private room with an adult and are not allowed to stay in the dormitory
we will contact you for the CVC code (your booking only be valid after a payment of 50% non refundable).
Extra deposit depending on the length of your stay or size of your group we may ask you to confirm your booking with a further payment directly to the hostel. If required, the payment conditions are a 50% deposit due to SLOW Hostel in addition to the 10% deposit paid to HostelWorld. Expenses with deposits and transfers are sender responsability and are not refundable or deductible from total amount to be transferred to secure bookings. The 50% deposit must be made within one week of the HostelWorld booking for it to be valid.
DirectionsShow MapHide Map
From airport: Take the only bus which goes to Joao Pessoa bus station (Rodoviaria) at the bus stop just beside the airport bulding.
From Bus Station (Rodoviaria): Take the bus 513 or 510, when it arrives to the ocean road, on Manaira Beach, ask the driver to stop the second bus stop (before Quadras de Manaíra point),you should go through the street in face of the bus stop and turn first left. The third house is our hostel!!
Located Near
The best hostel location in Joao Pessoa.
Just cross the street and you arrive to a clean and beatiful beach! You have a bus stop to the centre or to the beaches at 100m. You have the best regional restaurant 50m. Walk 3 or 4 blocks and you arrive to the mall.
A lot of culture and leisure activities 10' to 15' minutes walking!!
For sure this is the place to stay!!


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Rated 5 out of 5 by 1goodwife Ran a bit small; purchased larger size. Overall, this is a great looking and feeling coat. May 14, 2014
Rated 2 out of 5 by Parisian fabric too shiny Not dressy enough to pass as jacket for going to restaurant. The styling (cuffs on sleeves) and front zipper detract. But the main problem is the shininess of the fabric. With the cotton content and microfiber, a jacket can be made that is not shiny. Some twelve years ago or so, Travelsmith sold one that was great. July 4, 2014
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text:
Assume $G$ is a finite group and $H$ a subgroup. Is it true that the number of irreducible representations of $G$ is always larger than (or equal to) the number of irreducible representations of $H$?
Is the number of irreducible representations of G always bigger (or equal) to the number of irreducible representations of H, with H a subgroup of G?
Here is a simple example. As mentionned by Gjergji, this is a question about the number of conjugacy classes. Take $G=\frak A_4$, which has $3$ classes (the identity, the double transpositions and the $4$-cycles). Now take $H$ the subgroup spanned by a $4$-cycle. Because $|H|=4$ and $H$ is abelian, it has $4$ classes.
Edit. This is incorrect: $H$ is not a subgroup of $\frak A_4$, because a $4$-cycle is an odd permutation. I apologize. Note that I an accepted answer can not be deleted.
The number of irreducible representations equals the number of conjugacy classes, and the number of conjugacy classes in a subgroup may be more than in the whole group.
No, an easy example is when $G= {\bf Z}/2{\bf Z} \ltimes ({\bf Z}/p{\bf Z})^2$ where the action is by switching the factors and $H = ({\bf Z}/p{\bf Z})^2$.
$G$ has $2p$ 1dimrepresentations and $(p^2-p)/2$ 2dim representations which for big $p$ is smaller than the number of representations for $H$ which is $p^2$.
Dihedral groups also give examples. More generally, for a subgroup $H$ of a finite group $G$, the sum of the $p$-th power of dimensions of representations of $H$ is at most that for $G$, provided $p\geq 1$ (here $p$ is not a prime, but one should think of $L^p$-norms, including the limit as $p$ goes to infinity, which corresponds to the maximal dimension.)
This monotony property fails for any $p$ in the interval $[0,1[$ (again, dihedral groups give examples).
In many cases, the result is rather in the opposite direction. Let $k(G)$ denote the number of conjugacy classes of a finite group $G$. Now take $G$ to be be a semdirect product of the form $VM$, where $V$ is an elementary Abelian $p$-group and $M$ is a group of linear transformations of order prime to $p$ of $V$. Then $k(G) \leq |V|$, and it is rare for equality to be achieved ( see Gluck, David; Magaard, Kay; Riese, Udo; Schmid, Peter The solution of the $k(GV)$-problem. J. Algebra 279 (2004), no. 2, 694–719). The precise conditions under which equality is achieved have not been characterized to date as far as I know), so taking $H = V$ usually leads to $k(G) < k(H)$ (and always to $k(G) \leq k(H)$) for this choice of $H$. For an explicit example, if $V$ is elementary Abelian of order $p^n$ for some odd prime $p$, and $M$ is cyclic of order $(p^n -1)/2$, acting as the square of a Singer cycle on $V$, then $G = VM$ has $2 + (p^n - 1)/2$ conjugacy classes, so this is less that $p^n$ unless $p^n = 3.$ While the result of Gluck,Magaard,Riese and Schmid and some of its prerequisites rely on the classification of finite simple groups, many cases can be proved without the classification, for example, the case where $G$ is solvable.


text:
BOSTON — Bruins winger Daniel Paille skated Friday morning before the team's optional morning skate, his first time on the ice since being knocked out of last Saturday's win over the Sabres.
Paille skated along with injured defenseman Adam McQuaid.
Several players were absent from the optional morning skate. Both forward Chris Kelly and defenseman Matt Bartkowski did not skate, and neither has practiced all week. Kelly has a back injury.
Coach Claude Julien said there were "no updates" to offer on the status of his injured players.
Justin Florek and Jordan Caron are expected to plug into the forward lineup for Game 1 against the Red Wings if Paille and Kelly are unavailable. Andrej Meszaros would be the next man up on defense if Bartkowski can't play.
Also missing from Friday's skate were goalie Tuukka Rask, defenseman Zdeno Chara and forwards Jarome Iginla, David Krejci and Milan Lucic.
Follow @DanCagen


text:
Since upgrading to 12.04, I've been having issues with my speakers:
They seem to be making an odd hissing noise (sort of like static) and they sound really tinny.
Is anyone else having these problems or is it just me and is there any way to fix it?
This is a new problem that I've never had until I upgraded yesterday.


text:
I want to create a feature, once the feature is activated by the administrator a number of lists, items and workflows will be created.
What would be the best approach to implementing this?
The only way i have currently came across is using SPFeatureReceiver and creating the objects on the FeatureActivated function.
Any other suggestions?


text:
An interdisciplinary degree in the history of ideas
The College of Letters and Science Master's in Liberal Studies is designed for college graduates interested in an interdisciplinary master's degree. In the liberal arts tradition, the MLS emphasizes breadth of learning across disciplines, critical thinking, clear communication, and integration of knowledge. While strengthening each student's general education is the primary goal of the program, the degree also expands professional and career opportunities.Hallmarks of the program include:
- interdisciplinary areas of study
- outstanding faculty
- individualized advising
- flexible timetable for meeting graduation requirements
- scheduled coursework during late afternoons, evenings, or weekends.
The only degree of its kind in the state of Wisconsin, the MLS is based in the College of Letters and Science prestigious Center for 21st Century Studies and features small seminars led by distinguished graduate faculty.
Kristie Hamilton, Associate Professor of English, is Director of the Masters in Liberal Studies Program. For a biographical sketch of Professor Hamilton, please visit her biography page.


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14 Feb 2012 8:31 AM #1
Panel and tpl with store?
I have a panel in Designer 2 which i need to fill with some columns/rows, just like a html table.
I see that the Panel has the 'tpl' attribute, but i don't see how i can add a store to it. My store has JSON data, and i want to display this data as html inside that panel.
How can i do this..?? What would be a good way??
14 Feb 2012 12:43 PM #2
There are a couple of different solutions for what you are looking for.
If you already have the data in a Store then the one that you probably want is to put an Ext.view.View into your Panel and use a layout of fit. This will stretch the view to 100% width and height of the panel it is in.
Bind the View to the store of your choosing. Then configure a tpl for the View. Every record will be passed in a loop to the template in a tpl for="." loop.Aaron Conran
15 Feb 2012 5:18 AM #3
I couldn't find the Ext.view.View, but i did find Ext.dataview.DataView. I guess that's the one you mean. I can tell it what store to load and i can change its 'tpl' property. So its working for me. Thanks.
15 Feb 2012 6:25 AM #4
Guess it didn't work after all
I added the store to the dataview and added the following in the itemTpl property:
<tpl for="."> <div style="width:100px; height:80px; background:#CCC;"> {Name} </div> </tpl>
Any idea what the problem could be? Perhaps a bug?
15 Feb 2012 8:07 AM #5
Make sure you have store configured correctly (See Store/Proxy/Reader docs).
Check the record count after data load.Bharat Nagwani
Sencha Designer Development Team
16 Feb 2012 4:48 AM #6


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Given a root hash
root = H(plaintext)
and two (or more) derived hashes
h1 = H(salt1 + root)
h2 = H(salt2 + root)
would the knowledge of h1 and h2 alone increase the chances of finding the root hash or even the plaintext? I'm using SHA256.
Given a root hash
and two (or more) derived hashes
would the knowledge of h1 and h2 alone increase the chances of finding the root hash or even the plaintext? I'm using SHA256.
To the best of our knowledge, SHA256 does not leak any additional information from related hashes.
On the other hand, the state of "our knowledge" might not be that comprehensive; this security property of SHA256 cannot be derived from the base security assumptions of a hash function (preimage resistance, second preimage resistance and collision resistance), and as far as I know, no one has studied it. While it may be (and likely is) secure, no one has really studied it, and so there there might be a semiobvious leakage that no one happened to find yet.
Now, there is an obvious variation on this which has been studied: HMAC. HMAC is a Message Authentication Code, that is, it has a security assumption that if you give someone (who doesn't know the key) a large number of MAC outputs based on known texts, they still cannot derive the key, or any information about MAC outputs for texts they haven't seen. That is precisely the security assumption that you are looking for; and so HMAC has been analyzed against the exact problem you're looking for. HMAC uses a hash function (for example, SHA256) as an underlying primitive, and it does have a small additional cost over the underlying hash; if you can do some precomputation, this additional cost is just one more hash compression evaluation.
As for how you would use HMAC; well, HMAC has two inputs, a "key" and a "message". You would make your "root" the key and the "salt" the message, and use the output of the MAC as your derived hash.
Given just h1 and h2, if the salts are of any significant length then it will be impossible to uniquely determine "root" even if the hash function is very weak so long as it performs enough "compression". If both salts are known as well as h1 and h2 then the value of root is impractical to determine as long as the hash function is secure.
Recovery of root or plaintext given the above construction given only the derived values would constitute as serious break of the security of SHA256. However, you may not have considered all the relevant threats and the system as a whole may be vulnerable to a length-extension attack. It's worth using the HMAC construction mentioned in poncho's answer rather than trying to do it yourself.
The answer depends on assumptions on
If an adversary can enumerate the possible
Presuming root contains enough entropy to make a brute force search infeasible given only $h1$ and $salt1$, the (presumed) preimage resistance of SHA256 means that finding root would still be infeasible even if the attacker also knows the value $h2$ and $salt2$.
Update: First order preimage resistance is usually defined as, for a random value $h$, it is hard to find a message $m$ such that $h = H(m)$. Given the debate this definition has caused in the comment field of another answer, one might argue that this definition is too imprecise and doesn't fully capture the intuitive notion of preimage resistance. Other definitions are of course possible:
Let $n$ be the output length of the hash function $h$ and let $N$ be the maximum input length. Let $r:\{0,1\}^N\mapsto\{0,1\}^N$ be a random function that maps any valid input to another valid input. This function is unknown to adversary but a parameter of the game. Let $BitSelect:\{0,1\}^N\mapsto\{0,1\}$ be such that $BitSelect(m)$ selects a single bit from $m$ based on the value of $h(m)$. Let $f_r:\{0,1\}^N\mapsto\{0,1\}^n\times\{0,1\}$ be such that $f_r(x) = h(r(x)),BitSelect(r(x))$. Define first order preimage resistance such that $h$ is first order preimage restistant if and only if an adversary has less than $2^{-(n-1)}$ advantage distinguishing $f_r$ from the corresponding random function.
Arguably, this definition captures the intuitive notion that first order preimage resistance is about the inability to derive a hash input you didn't get to choose from a hash output you didn't get to choose. Also, if $h$ is not preimage resistant in the common sense, then $f_r$ as defined above will not be IND-CPA.


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Reviewer: Courtney Bui, MD
Abramson Cancer Center of the University of Pennsylvania
Last Modified: December 24, 2006
Birgisson H, Pahlman L, Gunnarsson U, Glimelius B. Journal of Clinical Oncology 23:8697-8705, 2005.
Radiation therapy and/or chemotherapy combined with surgery typically comprise the standard treatment for early to intermediate stage rectal cancer. Pre-operative treatment is often better tolerated than post-operative treatment, and thus is preferred at some centers. The Swedish Rectal Cancer Trial was designed to evaluate the benefit of pre-operative radiation therapy utilizing 5 Gy x 5 to 25 Gy, followed by resection 1 week later. The benefit of radiation therapy has been demonstrated in several trials, including this one, but the therapy is not without risk. This article presents the long-term toxicity data of the previously published Swedish Rectal Cancer Trial.


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"Speak Up"by Ty N., 9th Grade
York Co. School of Technology, York PA
"My artwork demonstrates how creativity begins. My motive for illustrating it was because I know that when you are an adolescent you have more things coming to you mentally. So, I thought when you're young and you're taut to execute creative itdeas it can help you in the future."


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I want to set up a GTD workflow based around my gmail account.
Although I have some other possible sources of tasks and projects coming "in", most things I need to do come "in" through my gmail inbox. My intent is to take the inbox as a starting point, and use gmail to manage my entire GTD system. For example, without ever taking things out of gmail, trash can be trashed, reference material can be labelled and archived, and open loops can be tracked in many ways...if only I knew an efficient way to track them.
In order to make this work, here are some questions that need to be solved:
- What labels do I need to indicate actions (context, resources required, and priority)?
- What non-action labels do I need (eg, wait for reply, incubate)?
- Can projects (actions and support material) also be tracked within gmail, or do I need a separate system for them?
Finally, once these buckets are established, how can I make sure every bucket is flowing smoothly?


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Why do some Jews (Sephardic, Hasidic, et al.) place the kiddush cup into the hands of another?
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Sefer Ben Ish Hai Year 2 Bereshit Ot 29(Quoting from the English Edition published by Ahavat Shalom):
According to the Sha'ar HaKavvanot 71a and the Siddur HaRaShaSh the cup is actually supposed to be held upon the tips of the five fingers of the right hand(the is actually derived from the Zohar Hakdma daf 2a). So the cup is briefly actully passed to the left hand.
So the simple reason is because the Ari and the Ben Ish Hai says so. The longer reason is that it is representative of drawing down kedusha from the upper worlds in ours. As elaborated in much more detail in the sources cited.
I don't know about all the above Kabbalah discussions, but the Tur and Shulchan Aruch in OC 183 say:
Sounds to me like someone is passing it off.
The Taz (OC 183 sk 2) says that the acceptance with two hands is to show how excited one is to receive it, as if he was reaching out and grabbing for it.
My understanding -- don't recall where I heard this -- is that the Kabbalistic preference is to hold the (preferably flat-bottomed) kiddush cup in a cupped, palm-facing-the-ceiling hand. (And if your hand is in this position, it's much easier if someone else places the cup into it.) That hand shape indicates you're a recepticle, prepared to receive "shefa" -- an outpouring of Heavenly influence and blessing -- from Above.
For more on the notion of "shefa" in a not-particularly-Kabbalistic source, try Malbim's commentary to II Kings Chapter 4 (where they keep pouring and pouring and pouring the oil). His comments there are permeated (not punctuated) with treatment of the concept.
This is far out of left field, but I wonder what type of cup was used in the times of the Mishnah, Gemara, Geonim, or early Rishonim. The reason I wonder is that a couple of years ago a British gentleman found a very interesting cup dating to ancient Persia. If you notice, the cup was ornately molded (or sculpted, but I doubt that) with the face of what is believed to be an ancient
Now, I'm speculating here, but it would not shock me if it was common practice among the noble classes to have these types of cups for formal/ritual occasions. Indeed, here is another cup from the same period:
Now, I would imagine, especially given the shape of the second cup above, it was common to hold the cup from underneath so as not to cover the face of the deity on the cup - in fact, the shape of the second cup may have even been designed assuming that it would be held that way and that the molding would not interfere with holding the cup. Assuming all my above speculation is correct (or close), it might follow, then, that this was universally seen as the most "proper" way to make a toast or to declare loyalty or admiration to one's king or god, and that this method was used by Jews as well (which would explain why I have heard so many times that one's fingers should be positioned vertically so that they resemble the points of a crown at the bottom of the cup).
Again, this is just speculation, so take it for what it's worth (if anything at all).
To close the loop on my train of thought here, I was taught (by a non-Hasidic Ashkenazi rabbi/mentor) that, for Zimun over a Kos, someone should take the full cup in two hands and place it into the open and waiting palm of the person who will call the Zimun (who will then close his fingers around the base of the cup as described above).


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Night Owl Bamboo Wall Clock
The adorable original design is laser cut from natural and amber bamboo. Each piece is precisely inlayed at various depths giving our inspiring design unexpected dimension, creativity, and clever ingenuity. Beautiful details such as the wood grain on the log, veins in the leaves and numbers on the clock face are all lightly engraved into the wood.
The design is super cute, the pieces fit together perfectly and the engineering is brilliant. The best part is the amazing glass-like silk finish! All wood parts go through a multi-step process of sanding and clear coat sealing. It is made using only the greenest formulated, ultra-low formaldehyde, eco-friendly finishing system of products to enhance and protect the natural beauty of the wood. The gorgeous satin clear top coat provides a very durable, hand-rubbed, smooth-to-the-touch finish that protects your piece from moisture and ultraviolet exposure as well.
Mr. Night Owl Wall Clock measures 10.5" x 10.5 x 1". It comes with a silent motor (no ticking sound!) and a free battery. The box motor is totally encased in wood making this clock a decorator's delight!
Made in USA.


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In the Atiyah-Singer paper mentioned above, they introduced on p.557 a concept called $H$-structure which is used to describe the Chern character of special elements of $K(TX)$. It is roughly the following: Take a principal $H$-bundle $P$, so that $P \times_H V \cong TX$ for some $V$ and use this to construct a map from $K_G(V)$ to $K(TX)$.
On p. 559, Remark 2, they describe how this concept can be generalised to $H$-structures with an action of a group $G$. For the special case that $G$ acts trivially on the manifold $X$, they state that
"the action of $G$ on the principal $H$-bundle $P$ is given by some homomorphism $\rho:G \to$ Centre($H$)"
I actually do not believe this is true (or I misunderstood what kind of actions are considered here). In my opinion we only have fibre-preserving left action of $G$ on $P$, which can be given by any map $G \to H$ (we assume that the base space $X$ is connected).
Can somebody familiar with the paper give me argument for (or against) it?
PS: Any source where the case of Remark 2 is calculated in special cases would also be helpful.


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FROM THE BBB -- The latest Scam Alert from the Better Business Bureau, deals with the fictitious "P. Less Sinclair Corporation"
The Better Business Bureau is warning consumers of a scam "mystery shopper" scheme that uses a faked Kansas return address. Consumers throughout the U.S. are receiving letters in the mail from P. Less Sinclair Corporation, which claims to be located at 2403 S. Main, Fort Scott Kansas. That address in Fort Scott is actually Peerless Corporation, located there since 1952. Peerless manufactures doors and windows.
They have NO association with P. Less Sinclair Corporation.
Consumers are receiving a sizeable check, usually between $1300.00 and $1400.00, along with a letter instructing them to deposit the check and go to a website. At the website they are supposed to enter the supplied ID and Password to get their first shopping assignment. As usual consumers are to wire money from Western Union to Spain, then scan the receipt and upload it to the website to complete the assignment.
Consumers should know that this is not a valid work at home opportunity. Eventually the check from "P. Less Sinclair Corporation" will bounce and the consumer is left with the responsibility for paying back the bank. Contact the BBB at 1-800-856-2417 or www.kansasplains.bbb.org if this scammer contacts you.
The Better Business Bureau has years of experience with victims of such scams. There are several signs that have been identified as indicators of a work-at-home scam.
A legitimate work-at-home opportunity will not:
• Offer you regular salaried employment.
• Promise you huge profits and big part-time earnings.
• Use personal testimonials without identifying the person so that you could check with them.
• Require money for instructions or merchandise before telling you how the plan operates.
• Assure you of guaranteed markets and a huge demand for your handiwork.
• Tell you that no experience is necessary.
• Take your money and give you little or nothing in return except heartbreak and grief.
The Better Business Bureau advises that you utilize the following tips to become a more savvy consumer:
1. Know who you're dealing with. Do business only with companies that clearly provide their name, street address and phone number.
2. Protect your personal information. Share credit card or other personal information only when buying from a company you know and trust.
3. Take your time. Resist the urge to "act now". Most any offer that's good today will be good tomorrow, too.
4. Rate the risks. Every potentially high-profit investment is a high-risk investment. That means you could lose your investment – all of it.
5. Read the small print. Get all promises in writing and read all paperwork before making any payments or signing any contracts. Pay special attention to the small print.
6. "Free" means free. Throw out any offer that says you have to pay to get a free gift. Period.
7. Report fraud. If you think you've been a victim of fraud, report it. It's one way to get even with a scam artist who has cheated you. Report your complaint to the BBB.


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5 Mind Blowing Things Crowds Do Better Than Experts
#2. The Crowd Beats the Experts ... Over and Over Again
Now, we don't want to give the impression that all of these crowdsourcing tasks are about farming out manual labor grunt work. If you do it right, you can get better decisions on complex issues by asking a crowd than you can by asking a few experts.
However, simple questions like "Where should we eat?" will take hours to argue out.
Some of the best examples of this involve cases where the crowd didn't know they were being asked a question at all. Back in 1986, when the Space Shuttle Challenger exploded shortly after takeoff, the stock market immediately reacted by selling the stocks of the four main contractors that were involved in building the spacecraft. But experts noticed something odd in the buying and selling habits of all of those millions of traders. Three of the contractors' stock saw only minor losses, ending the day with an average loss of 3 percent. Yet the fourth company, an outfit called Morton Thiokol, had their stock end down by a whopping 12 percent.
It was clear that the investors blamed them (or their components) for the accident, even though the news coverage had in no way fingered them as the culprit. The press did have some rumors about what caused the accident, but no one was implicating Thiokol above any of the other companies. It took a Washington blue ribbon commission six months to figure out that, sure enough, Morton Thiokol was responsible. It took the faceless mass of investors one day.
Our methods of prediction involve a financial paper, a bear and wild flailing. We're all millionaires.
Experiments have been done on this from several angles, and the results are always remarkable. You remember the game show "Who Wants to be a Millionaire?" (you saw it if you were watching TV in the same room as your grandmother). It was a quiz show where if you got stuck on a question, you had three options for help. You could eliminate two of the four possible answers, raising your odds to 50/50, you could phone an expert or you could ask the audience to vote on the right answer.
This gives us a unique opportunity to study who has the better scores, the "experts" or the audience. So James Surowiecki, author of the book The Wisdom of Crowds, actually ran the numbers. The results? While the experts got the answer right about 65 percent of the time, which is a respectable score, the audience -- made up of random dumbasses who waited in line to watch a game show -- managed to get the correct answer a shocking 91 percent of the time.
If these questions were posed over the Internet, half the audience would answer "FIRST" and the other half would call them fags.
And it doesn't just work for trivia questions, either. One researcher asked a group of 56 people how many jelly beans were in a jar. And while some people guessed way too low, and some guessed way too high, they all averaged out and guessed 871, only 21 beans higher than the actual amount.
Well, we guess this proves that millions of people can't be wrong and Twilight is the best book of our generation.
This is why you can't dismiss "prediction markets" like Intrade, where the crowd basically bets money on outcomes for everything from elections to geopolitical events. Huge corporations now use such prediction markets to make decisions, including Google, which details the predictions in this blog post. They know what they're doing, right?
#1. Using the Crowd to Solve ... Everything
Some groups just aren't satisfied with using you and thousands of strangers to tackle one or two issues. Some groups want to solve it all.
Take Zooniverse, for example. Any scientific project with a crowdsourcing goal can open up shop on their site and gain access to the half million people they have registered as members. They currently have about 10 major active projects with goals that range from having volunteers read through actual 100-year-old ship logs from the royal English Navy to creating a online map of the galaxies.
Here we're discovering a planet, soon to be named Bonaas9000.
But what about all that time you spend away from your computer, selfishly living your life instead of helping out the cause? Is there a way you can pitch in without, you know, actually doing anything?
Actually, yes. The World Community Grid is looking to take advantage of all that downtime your computer has by putting it to work on something meaningful. Through a simple download, whenever your computer starts to go into idle or sleep mode, they will borrow your computer's processing power to try to save the world.
Finally, a use for our Cheetos 2 a.m. crash time.
They currently have more than half a million PCs forming one huge distributed computing hive mind super computer, tackling aspects of the human genome, HIV, muscular dystrophy, cancer and clean energy. Users are automatically opted in to all of these projects, but you can choose to opt out of ones you find disagreeable.
For more on crowds getting it done (or not), check out The 25 Most Nonsensical Protest Signs and The 8 Most Ridiculously Badass Protesters Ever Photographed.