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1 CONTRIBUTIONS TO ZERO SUM PROBLEMS S. D. ADHIKARI, Y. G. CHEN, J. B. FRIEDLANDER, S. V. KONYAGIN AND F. PAPPALARDI Abstract. A prototype of zero sum theorems, the well known theorem of Erdős, Ginzburg and Ziv says that for any positive integer n, any sequence a 1, a 2,, a 2n 1 of 2n 1 integers has a subsequence of n elements whose sum is 0 modulo n. Appropriate generalizations of the question, especially that for (Z/pZ) d, generated a lot of research and still have challenging open questions. Here we propose a new generalization of the Erdős Ginzburg Ziv Theorem and prove it in some basic cases. 1. Introduction The famous Erdős-Ginzburg-Ziv Theorem [5] states that, given any sequence of 2n 1 integers, there are n of them that add up to a multiple of n. Furthermore a sequence of 2n 2 integers does not always enjoy this property (consider for example the sequence of n 1 zeros and n 1 ones). Therefore we have that, if E(n) is the least integer t such that any sequence of t integers contains n integers that add up to a multiple of n, then E(n) = 2n 1. A number of different proofs of this result are presented in the book [1]. Various generalizations and variations of the above property have been considered in the past (see for example [6, 2]). Here we consider a different one that (at least to our knowledge) is new. If n is a positive integer, we will identify Z/nZ with the set of the integers {0,..., n 1}. Let n N and assume A Z/nZ. We consider the function E A (n) defined as the least t N such that for all sequences (x 1,..., x t ) Z t there exist indices j 1,..., j n N, 1 j 1 < < j n t, and Date: September 25, Mathematics Subject Classification. 11B50. 1
2 2 S. D. ADHIKARI AND OTHERS (ϑ 1,, ϑ n ) A n with n ϑ i x ji 0 (mod n). i=1 To avoid trivial cases, we will always assume that A does not contain 0 and it is non empty. It is clear that E {1} (n) = E(n) and that E A (n) E(n) = 2n 1. Further, if we consider the sequence with n 1 zeros and one 1, we deduce that E A (n) n + 1. We propose the problem of enumerating E A (n). Here we consider the case A = {1, n 1} = {1, 1}. We denote E A = E ± in this case, which is perhaps the most basic one aside from the classical Erdős, Ginzburg, Ziv problem. It is easy to see that (1.1) E ± (n) n + log n, where here and throughout the paper log will mean the base 2 logarithm. Indeed, consider the sequence of integers: n 1 times { }} { ( 0, 0,..., 0, 1, 2,..., 2 r ) where r is defined by 2 r+1 n < 2 r+2. Any combination with signs of n integers of the sequence gives rise to a number whose absolute value is 2 r+1 1 and is not zero by the uniqueness of the binary expansion. Furthermore the sequence has n + r = n + log n 1 elements. We will prove that Theorem 1.1. For any positive integer n, we have E ± (n) = n + log n. We will illustrate a number of different approaches to the problem. Whereas the approach of Section 2 leads to the solution in the even case in Theorem 2.2, the approach in Sections 4 and 5 will lead to that in the odd case in Theorem 5.1. In Section 3, we give a number of results for odd prime modulus, which imply Theorem 1.1 in this particular case. Although not really needed due to the other results presented, this argument, which uses the Cauchy-Davenport inequality, seems to us of independent interest. In the concluding Section 6 we make a few remarks about the problem for other sets A.
3 CONTRIBUTIONS TO ZERO SUM PROBLEMS 3 2. A conditional result and the even case It turns out to be easier to deal with sequences where one or more of the elements is in the zero class. We have Theorem 2.1. Let n N. Assume that N n + log n is an integer. Given any sequence (x 1,..., x N ) Z N with at least one multiple of n, there exist m = N log n indices {j 1,..., j m } [N] and signs ε 1,..., ε m {1, 1} such that ε 1 x j1 + + ε m x jm 0 (mod n). Here, and throughout the paper, [N] will denote the set {1,..., N}. We will make use more than once of the following: Lemma 2.1. Let n N and (y 1,..., y s ) be a sequence of integers with s > log n. Then there exists a nonempty J [s] and ε j {±1} for each j J such that ε j y j 0 (modn). j J Proof of Lemma 2.1. This is an application of the pigeonhole principle. Consider the sequence of 2 s > n integers ( ) y j j I I [s] that cannot contain distinct integers modulo n. Therefore, there are J 1, J 2 [s] with J 1 J 2 such that y j y j (mod n). j J 1 j J 2 Set J = J 1 J 2 \ J 1 J 2 and { ε j = 1 if j J 1, ε j = 1 if j J 2. It is clear that J is non empty and it has the required property. Proof of Theorem 2.1. Let us reorder the sequence in such a way that, modulo n, x 1 = 0, x 2 = x 3, x 4 = x 5,..., x 2t = x 2t+1 and x 2t+2,..., x N are all distinct. Hence N 2t 1 n and 2t + 1 N n log n.
4 4 S. D. ADHIKARI AND OTHERS Let B = {r 1,..., r l } {2t + 2, 2t + 3,..., N} be maximal with respect to the properties that there exist ε 1,..., ε l { 1, 1} with l ε j x rj 0 (mod n). Now we claim that l + 2t + 1 m. Indeed, if this were not the case then the set C = {2t + 2,..., N} \ {r 1,, r l } would contain N 2t 1 l > log n elements. Hence by Lemma 2.1 there would exist a non empty B C and ε j {±1} for each j B such that j B ε j x j 0 (mod n). So we would find that B B still verifies the property above and we would contradict the maximality of B. Hence we write l + 2t + 1 = m + r and distinguish the two cases: If r = 2r is even then we choose the sequence (x 1, x 2(r +1), x 2r +3,..., x 2t, x 2t+1, x r1,..., x rl ) which has m elements and t l x 1 + (x 2j x 2j+1 ) + ε j x rj j=r +1 0 (mod n). If r = 2r + 1 is odd then we leave out x 1 and consider the sequence (x 2(r +1), x 2r +3,..., x 2t, x 2t+1, x r1,..., x rl ) which has m elements and also verifies the thesis. When the modulus n is even it turns out to be possible to modify the above ideas so as to obtain this case of Theorem 1.1 without any hypothesis. For this we shall use the following Lemma 2.2. Let n N and (y 1,..., y s ) be a sequence of integers with s > log n + 1. Then there exists a nonempty J [s] with J even and ε j {±1} for each j J such that ε j y j 0 (modn). j J
5 CONTRIBUTIONS TO ZERO SUM PROBLEMS 5 Proof. Just as in the proof of Lemma 2.1 above, we apply pigeonhole on the 2 s 1 > n integers ( ) y j j I. I [s] I even The following Theorem takes care of the case n is even in Theorem 1.1. Theorem 2.2. Let n N be even. Consider the integer N = n + log n. Then, given any sequence (x 1,..., x N ) Z N, there exist n indices {j 1,..., j n } [N] and signs ε 1,..., ε n {1, 1} such that ε 1 x j1 + + ε n x jn 0 (mod n). Proof. Let us reorder the sequence in such a way that, modulo n, x 1 = x 2, x 3 = x 4,..., x 2t 1 = x 2t and x 2t+1,..., x N are all distinct. Hence N 2t n and 2t N n = log n. Let B = {r 1,..., r l } {2t + 1, 2t + 2,..., N}, with l = B even, be maximal with respect to the properties that there exist ε 1,..., ε l { 1, 1} with l ε j x rj 0 (mod n). Now we claim that l + 2t n. Indeed, if this were not the case then we have l + 2t n 2 since the numbers l + 2t and n are both even, and the set C = {2t + 1,..., N} \ {r 1,, r l } would contain N 2t l log n + 2 > log n + 1 elements. Hence by Lemma 2.2 there would exist a non empty B C with B even and ε j {±1} for each j B such that j B ε j x j 0 (mod n). So we would find that B B still verifies the property above and we would contradict the maximality of B. Since both l and n are even, from l + 2t = n + r, we see that r is even. If r = 2r then we choose the sequence (x 2r +1, x 2r +2,..., x 2t, x r1,..., x rl )
6 6 S. D. ADHIKARI AND OTHERS which has n elements and t l (x 2j x 2j 1 ) + ε j x rj j=r +1 0 (mod n). 3. The case n = p with p an odd prime and the Cauchy Davenport inequality We will state and prove a couple of results that have their own interest. Lemma 3.1. Let p be an odd prime. If N p 1 is an integer and (x 1,..., x N ) Z N is any sequence of integers not divisible by p, then for every b Z there exist signs ε 1,..., ε N {1, 1} such that ε 1 x ε N x N b (mod p). The above is a direct consequence of the famous Lemma 3.2 (Cauchy Davenport inequality). Let A and B be two nonempty subsets of Z/pZ. Then where A + B min{p, A + B 1} A + B = {x Z/pZ x a + b (mod p), a A, b B} and K denotes the cardinality of the subset K of Z/pZ. This was first proved by Cauchy [3] in 1813 and later rediscovered by Davenport [4] in By iterating the Cauchy Davenport inequality we immediately obtain: Lemma 3.3. Let A 1, A 2,... A h be non-empty subsets of Z/pZ. Then h A 1 + A A h min{p, A i h + 1}. i=1 By choosing A i = {x i, x i }, we deduce that {x 1, x 1 } + {x 2, x 2 } + + {x N, x N } p which immediately implies Lemma 3.1. The statements of Lemma 3.1 and Theorem 2.1 imply the result of Theorem 1.1 when the modulus p is an odd prime since the first statement deals with the case when none of the elements of the sequence are 0 modulo p and the second statement deals with the case when the sequence contains an element which is 0 modulo p.
7 CONTRIBUTIONS TO ZERO SUM PROBLEMS 7 4. Complete sequences of integers We are not aware whether the notion in the following definition has already appeared in the literature. However, it appears natural in this context. Definition. Let x = (x 1,..., x N ) Z N. We say the sequence x is complete with respect to a positive integer m if for every positive d m we have (4.1) {j [N] x j 0 (mod d)} d 1. A complete sequence of integers with respect to a prime p is a sequence that contains p 1 elements which are not divisible by p. Let us collect some properties of complete sequences: Lemma 4.1. If (x 1,..., x N ) Z N is complete with respect to m and N m then there is j 0 N, 1 j 0 N, such that is complete with respect to m. (x 1,..., x j0 1, x j0 +1,..., x N ) Z N 1 Proof. Let d 1, d 2,..., d s be the divisors d of m that satisfy {j [N] x j 0 (mod d )} = d 1. Assume also that m d 1 > d 2 > > d s, set D k = lcm[d 1,..., d k ] and U k = {j [N] x j 0 (mod d k )}. Our goal is to show that U 1... U s < m so that we can choose j 0 [N] \ U 1... U s and the sequence (x 1,..., x j0 1, x j0 +1,..., x N ) will still verify the hypothesis of completeness. Note that U 1... U k = {j [N] x j 0 (mod D k )} and that U 1... U k = U 1... U k 1 if D k = D k 1. Thus U 1... U s = U 1 U k. D k >D k 1 Now, for those k participating in this formula we have D k > D k 1 and so D k = [D k 1, d k ] 2D k 1. This implies, for these k > 1, that D k D k 1 D k 1 d k 1 > d k 1,
8 8 S. D. ADHIKARI AND OTHERS while D 1 > d 1 1. We deduce that U 1... U s U 1 + U k D k >D k 1 = d (d k 1) D k >D k 1 s < D 1 + (D k D k 1 ) This completes the proof. k=2 = D s m. Lemma 4.2. If (x 1,..., x N ) Z N is complete with respect to m then there exist indices {j 1,..., j m 1 } [N] such that the sequence (x j1,..., x jm 1 ) Z m 1 is complete with respect to m. Proof. From the definition of complete sequence in (4.1) we deduce that N m 1. By applying Lemma 4.1 several times we can eliminate elements from the sequence until we arrive at exactly m 1 elements. Theorem 4.1. If (x 1,..., x N ) Z N is complete with respect to m, then for every integer b there is a choice of coefficients ς 1,..., ς N {0, 1} such that N ς j x j b (mod m). Proof. We prove the theorem by induction on m. The case m = 1 is clear. Now we assume that k 2 and the theorem is true for m < k. Suppose that the sequence x 1, x 2,, x N of N integers is complete with respect to k. Without loss of generality, we may assume that k x 1. For any integer a, let a be the residue class of a mod k. For any set A of integers, let A = {a a A}. Let A 1 = {0, x 1 } and i 1 = 1. Then A 1 = 2. Now, if possible, we choose an index i 2 i 1 such that A 1 + {0, x i2 } A 1. If such an i 2 exists, then let A 2 = A 1 + {0, x i2 }. We continue this procedure and suppose that the procedure stops at A t. Noting that we have A 1 A 2 A t,
9 CONTRIBUTIONS TO ZERO SUM PROBLEMS 9 (4.2) A t A t t + 1. To complete the proof, it is enough to prove that A t k. By (4.2), we may assume that t k 2. Without loss of generality, we may assume that i j = j (j = 1, 2,, t). Since {j x j 0 (mod k)} k 1, we have N k 1. Also, rearranging the remaining elements if necessary, we can assume that k x t+1. By the assumption on A t, for all t + 1 j N, we have (4.3) A t + {0, x j } = A t. Let H be the subgroup of Z k generated by x t+1. By (4.3), we have A t + H = A t. Thus, A t is the union of some cosets of H. Let (4.4) A t = s i=1 (b i + H), where b i b j / H for all i j. Then A t = s H. Let k 1 = (x t+1, k). Then, since k x t+1 we have k 1 < k and the sequence x 1, x 2,, x N is complete with respect to the positive integer k 1. By the induction hypothesis, we see that, for every integer b, there is a choice of coefficients ζ 1,, ζ N {0, 1} such that N (4.5) ζ j x j b (mod k 1 ). By (4.3) we have N { ζ j x j (mod k) ζ i = 0, 1, i = 1, 2, N} = A t. Thus, by k 1 k, k 1 x t+1 and (4.4), we have N { ζ j x j (mod k 1 ) ζ i = 0, 1} = {b 1 (mod k 1 ),, b s (mod k 1 )}. Hence, by (4.5) we have s k 1. Noting that it follows that H x t+1 0 (mod k), H 0 (mod k k 1 ).
10 10 S. D. ADHIKARI AND OTHERS Since H 1 we have H k/k 1. Therefore This completes the proof. A t = s H k. The above theorem deals with linear combinations of the x j having coefficients 0 and 1 whereas we are really interested in combinations with coefficients ±1. The following result allows us to move from one to the other, but only in the case where the modulus is odd. Corollary 4.1. If m is odd and (x 1,..., x N ) is complete with respect to m, then for every integer b Z there is a choice of coefficients ε 1,, ε N {±1} such that N ε j x j b (mod m). Proof. Given any integer b Z, Theorem 4.1 implies that there exist ς 1,..., ς N {0, 1} such that b 2 + x x N 2 N ς j x j (mod m), which is meaningful since m is odd. Consider the identity ς 1 x ς N x N = x x N + 1 N (2ς j 1)x j. 2 2 Since ε j = 2ς j 1 {±1}, we obtain the claim. 5. Proof of Theorem 1.1 in the case n is odd The result in the n is odd case is a direct consequence of (1.1) and the following statement: Theorem 5.1. Assume that m N is odd. If N m + log m and x = (x 1,..., x N ) Z N, then there exists I 0 = {j 1,..., j t } [N] with I 0 = t = N log m and some choice of coefficients ε 1,..., ε t {±1}, so that t ε i x ji 0 (mod m). i=1 Proof. If x is complete with respect to m, then, by Lemma 4.2, there are m 1 indices j 1,..., j m 1 [N] such that (x j1,..., x jm 1 ) is still complete with respect to m.
11 CONTRIBUTIONS TO ZERO SUM PROBLEMS 11 Choose arbitrarily indices j m,..., j t [N] \ {j 1,..., j m 1 }. Then (x j1,..., x jt ) is also complete with respect to m, and the assertion follows from Corollary 4.1. Next suppose that x is not complete with respect to m. Then there exists a divisor d of m such that {j [N] : x j 0 (mod d)} < d 1. Let D be the maximal divisor of m possessing this property. We claim that if f m is such that D f then (5.1) {j [N] x j 0 (mod D), x j 0 (mod f)} f D 1. Indeed, the claim is trivial if f = D. If f > D and (5.1) does not hold then {j [N] x j 0 (mod f)} = {j [N] x j 0 (mod D)} + {j [N] x j 0 (mod D), x j 0 (mod f)} < D + f/d 2 f 1. This would contradict the maximality of D. Denote I 1 = {j [N] x j 0 (mod D)}, I 2 = {j [N] x j 0 (mod D)}. Let I 3 be a maximal subset of I 1 such that for some choice of coefficients ε j {±1}, j I 3, we have j I 3 ε jx j 0 (mod D). By Lemma 2.1 we know that (5.2) I 1 I 3 log D. Let k = t I 3. By (5.2) we have On the other hand, Therefore k N I 1 = I 2. k m I 3 m I 1 > m D + 1 m/d. (5.3) I 2 k m D.
12 12 S. D. ADHIKARI AND OTHERS Now set ( xj ) x =. D j I 2 By (5.1), x is complete with respect to m. D Lemma 4.2 implies that there exists I = {j 1,..., j m/d 1 } I 2, such that ( xj ) ( xj1 = D j I D,..., x ) j m/d 1 D is complete with respect to m. D By (5.3), we can choose a set I 1 such that I I 1 I 2 and I 1 = k. Clearly ) j I 1 ( xj D j I 1 is also complete with respect to m. D Therefore, Corollary 4.1 implies that we can choose coefficients ε {±1}, j I 1, such that ε x j j D 1 ( ε D jx j mod m ). D j I 3 To complete the proof of Theorem 5.1, it suffices to set j and choose ε j = and this concludes the proof. I 0 = I 3 I 1 { ε j if j I 1, ε j if j I 3, 6. Concluding Remarks An interesting choice for the set A is that of A = (Z/nZ), namely, A = {a : (a, n) = 1}. It is easy to see that E A (n) n + Ω(n) where as usual Ω(n) denotes the number of prime factors of n, multiplicity included. Indeed, write n = p 1, p s as product of s = Ω(n) not necessarily distinct primes. Consider the sequence consisting of n 1 zeros and {1, p 1, p 1 p 2,..., p 1 p 2 p s 1 }, giving the lower bound. Perhaps, one can show that equality holds so that E A (n) = n + Ω(n). An easier case is A = (Z/nZ) \ {0}. As mentioned in the introduction, we always have E A (n) n + 1 and, for this particular choice of A (the maximal A, since we always exclude 0), this lower bound is achieved. Theorem 6.1. Let A = (Z/nZ) \ {0}. Then E A (n) = n + 1.
13 CONTRIBUTIONS TO ZERO SUM PROBLEMS 13 Proof. We can assume that n > 2. We have the following observations. Fact 1. If r 2 and (x j, n) = 1 for j = 1,..., r then there are coefficients ϑ j A such that r ϑ j x j 0 (mod n). Indeed, without loss of generality, we can consider x j = 1 for j = 1,..., r. If r is even we take ϑ j = ( 1) j, otherwise we replace ϑ 2 by 2. Fact 2. If (x j, n) > 1 then there is ϑ j A such that ϑ j x j 0 (mod n). Let (x 1,..., x t ) Z t where t n + 1. By re-ordering we can assume that (x j, n) = 1 for j = 1,..., r and (x j, n) > 1 for j > r. If r 2, we take i j = j for j = 1,..., n and use Fact 1 and Fact 2 while if r 1, we take i j = r + j for j = 1,..., n and use Fact 2. It might be interesting to characterize any other sets A for which E A (n) = n + 1 or even those for which E A (n) = n + j for specific small values of j. Acknowledgement. Part of this project was realised when the first, the third and the fourth authors were visiting the Dipartimento di Matematica of the Università Roma Tre in the years 2002 and The second author was supported by the National Natural Science Foundation of China, Grant No The third author was supported in part by NSERC and by a Killam Research Fellowship. The last two authors were supported in part by G.N.S.A.G.A. of INDAM and by the INTAS grant References 1. S. D. Adhikari, Aspects of combinatorics and combinatorial number theory, Narosa, New Delhi, Y. Caro, Zero-sum problems A survey, Discrete Math. 152, (1996). 3. A. L. Cauchy, Recherches sur les nombres, J. Ecôle Polytech. 9 (1813), H. Davenport, On the addition of residue classes, J. London Math. Soc. 22 (1947), P. Erdős, A. Ginzburg and A. Ziv, Theorem in the additive number theory, Bull. Res. Council Israel 10 F (1961), R. Thangadurai, Non-canonical extensions of Erdős-Ginzburg-Ziv Theorem, Integers 2 (2002), #A (Adhikari) Harish-Chandra Research Institute, (Former Mehta Research Institute ) Chhatnag Road, Jhusi, Allahabad , INDIA. address:
14 14 S. D. ADHIKARI AND OTHERS (Chen) Department of Mathematics, Nanjing Normal University, Nanjing , P. R. China address: (Friedlander) Department of Mathematics, University of Toronto, ON, M5S 3G3, CANADA address: (Konyagin) Department of Mechanics and Mathematics, Moscow State University, Vorobjovy Gory, , Moscow, Russia address: (Pappalardi) Dipartimento di Matematica, Università degli Studi Roma Tre, Largo S. L. Murialdo, 1, I Roma, Italia address:
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Gent Treadly was initially fronted by Vince Welnick of the Grateful Dead, and jam royalty (members of Phish, moe., the Dead) regularly pop up onstage at GT shows. Charles Neville of the Neville Brothers makes an appearance, with support from Sean Schulich's Groovin' Donald Byrd Tribute.
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California Employment Law
Have California Employment Law Questions? Ask a Lawyer.
Perhaps you misinterpreted my sitution i am the owner of the buinesss
i am the owner of auto repair shop i had a former tech who was paid to install parts to vehicle
parts were not intalled to vehicle due to this damage was occured to the vehicle resulting in $5000 dollars
employee that was paid for installing these parts is now a former employee due i have any rights to property left at my business
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Congressman Brian Bilbray (CA-50), Chairman of the House Immigration Reform Caucs, released the following statement today in response to President Obama's speech in El Paso, TX:
"The President provided plenty of good examples for success stories of legal immigrants in his campaign speech today. But exploiting their success stories as justification for amnesty to an estimated 11-20 million illegal immigrants who have violated our nation's laws and cut in line is completely irresponsible. While the crime rate and number of illegal crossings along the border is down, the federal government has still not done enough to address the source of the problem -- employers who use illegal labor.
The President mentioned holding employers accountable for hiring illegal workers but he has yet to join me in the call for nationwide implementation of the E-Verify system. I call on President Obama to join with members of the House Immigration Reform Caucus to implement a nationwide E-Verify program to hold employers accountable." -- Rep Brian Bilbray (CA-50), Chairman of the House Immigration Reform Caucus
Source: http://bilbray.house.gov/2011/05/congressman-brian-bilbrays-statement-on-president-obamas-immigration-reform-speech.shtml


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Please can we arrange for me to live inside a flower market?
There is nothing I love more than being in London on a sunny Sunday. Why? Because I love Columbia Road Flower Market (so much). When I was last in town I spent an unusually warm day lazing about the market. It was so crowded but I loved every minute. I wore a double printed look from Aubin & Wills which I love. It's super soft and silky. Perfect for feeling easy and breezy but looking a bit put together.
p.s. yes, posing with a potted flower plant was essential (although highly cliche).
Wearing: Everard skirt and Willington vest with white Converse. Props: flowers and yellow SIGG bottle.
Massive thanks to the Cat for keeping me company and taking my outfit shot.


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Professor; Ph.D., Graduate Faculty, New School for Social Research; 1982.
Ancient Greek philosophy (especially Plato and Aristotle); recent continental European philosophy (especially Levinas and Derrida), psychoanalytic theory.
Jason Fisette
Lecturer; Ph.D., New School for Social Research, 2015.
Early modern philosophy, ethics, Hume.
Professor; Ph.D., Boston University, 1973.
Metaphysics, epistemology, philosophical logic, philosophy of religion.
Assistant Professor; Ph.D., Duke University, 2014.
Philosophy of Science, History & Philosophy of Biology, Philosophy of Astrobiology
Assistant Professor, Ph.D., McMaster University, 2009.
Social and political philosophy, ethics (theoretical and applied), American Pragmatism, Philosophy of Law, history of ehtics and political philosophy, philosophy of art/aesthetics.
Assistant Professor, Ph.D., Emory University, 2013.
Social and Political Philosophy, Philosophy of Law, Feminist Philosophy, Applied Ethics
Associate Professor, Chair; Ph.D., University of Pittsburgh, 1993.
Aesthetics; ethics; Philosophy of Mind; Hume.
Assistant Professor, Ph.D., City University of New York, 2011.
Philosophy of Cognitive Science & Neuroscience, Philosophy of Mind, Philosophy of Psychology
Emeritus Faculty
Professor; Ph.D., Princeton University, 1969.
History and philosophy of science; science, technology, society; scientific methodology; epistemology; philosophy of mind (cognitive aspects).
Emeritus Associate Professor; Ph.D., University of Chicago, 1969.
Ethics, philosophy of religion, Plato, Wittgenstein.
Frank Lucash
Emeritus Associate Professor; Ph.D., Southern Illinois University, 1970.
History of philosophy (especially the rationalists), metaphysics, philosophy of mind (especially the emotions).
Piotr Hoffman
Emeritus Professor; Ph.D., University of Paris, Sorbonne, 1970.
History of philosophy; continental philosophy (especially Descartes, Hobbes, Rousseau, Kant, Hegel, Marx, Nietzsche, Heidegger, and Sartre).
M.A., University of Nevada, Reno, 1997.
M.A., University of Nevada, Reno, 2012
Ph.D., University of Tennessee, 1978.
M.A., University of Nevada, Reno, 2003.
M.A., University of Nevada, Reno, 2011.
M.A. University of Nevada, Reno, 2012
M.A., University of Nevada, Reno, 2012
M.A. University of Nevada, Reno, 2007
Ph.D., State University of New York at Buffalo, 1972.
M.A., University of Nevada, Reno, 1997.
Teaching Assistants
Christopher Stancil, Jones Center 103C


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Here are our highlights from August's PLOS Computational Biology The Role of Cell Volume in the Dynamics of Seizure, Spreading Depression, and Anoxic Depolarization Cell volume changes are ubiquitous in normal and pathological activity of
Launching the PLOS Genetics Research Prize 2015
What did you do when you turned 10? Throw a party? Have a sleepover? Eat chocolate cake? We would love to do all these things with our readers, authors and editors (especially the chocolate cake),
Understanding Images: Plants Limit Crossovers
Authors: Javier Varas and Mónica Pradillo from Universidad Complutense de Madrid, Madrid, Spain. Competing interests: Javier Varas and Mónica Pradillo are authors of the work discussed in this blog. In the July issue of PLOS
Microbiome Evolution, Molecular Recognition and Interaction Webs: the PLOS Comp Biol July Issue
Here are our highlights from July's PLOS Computational Biology Neutral Models of Microbiome Evolution There has been an explosion of research on host-associated microbial communities (i.e.,microbiomes) and how they correlate with host health, disease, phenotype,
What's your favourite PLOS Genetics issue image?
PLOS Genetics is celebrating its ten year anniversary in July. Over the last decade, we have seen some eye-catching issue images and we would like to know which one is your favourite. The winning image
J. Andrew Bangham (1947 – 2014): Enterprising scientist who broke new ground in computational biology and image analysis
Andrew Bangham, former Professor in Computer Science at the University of East Anglia, Norwich, was a pioneering researcher with the rare ability to integrate diverse disciplines: from computer science and electrophysiology to plant development and
Calling All Bloggers for ISMB/ECCB 2015
ISMB/ECCB 2015 in Dublin, Ireland, is fast approaching and we invite you to be involved in the live coverage of the event. In previous years, ISMB has been way ahead of the social media
Heading to Dublin for ISMB/ECCB 2015? Swing by Booth 1 and say hello to PLOS! Many of the journal's academic editors will be in attendance, and PLOS Computational Biology staff Gary Beardmore and Bethany Coates
PLOS Genetics editors – David Kwiatkowski and Peter McKinnon
The first post in our PLOS Genetics' editors series introduces David Kwiatkowski, Brigham and Women's Hospital and Harvard Medical School, USA and Peter McKinnon, St Jude Children's Research Hospital, USA, who are Section Editors for
Understanding images: microRNAs contribute to hair loss and follicle regression
In a piece reflecting on this month's PLOS Genetics issue image, author Zhengquan Yu discusses the research behind Yuan et al. Author: Zhengquan Yu, State Key Laboratories for Agrobiotechnology, College of Biological Sciences, China Agricultural


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San Francisco Chronicle/Bloomberg, February 17, 2011
Drugmakers led by Merck & Co. and Novartis AG boosted investments in mobile phone applications and educational websites by 78% to get patients to take their drugs, eat right and exercise, an Ernst & Young report found. Pharmaceutical companies initiated 97 projects last year focused on using information technologies to improve patient health, according to the report by the consulting firm, which relied on analyst reports and press releases to reach its tally. That compares with 124 projects started in the four previous years combined. About 41% of the projects were smart-phone applications, an increase from 11% since 2006.


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- 40 Cabo 2005 Express
- Vessel Name: KarenB
- Vessel Length: 40 feet
- Vessel Builder: Cabo
- Vessel Model: Express
- Vessel Year: 2005
- Vessel Type: Express Fish
- Vessel Price: $ Contact for Price
- Vessel Location: KeyLargo, FL
- For additional details please scroll down
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40 Cabo Express 2005 Details:
The owner's plans have changed and now is your chance to own the nicest 40' Cabo on the market. She has only 1,000 hours on her reliable 700 HP CATS and was just painted at American Custom Yachts.
Seriously for sale, so please call!
Other interesting yachts for sale


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DHPE Message Regarding the President's 2015 Proposed Budget on Chronic Disease Prevention and Health Promotion
DHPE remains concerned that funding for chronic disease prevention and health promotion and public health in general remains too low...Indeed, the proposed funding for many discretionary health programs remains below FY 2010, even without adjusting for inflation. We have learned that there is little opportunity for growth in the President's budget, necessitating flat funding, deep cuts, and in some cases, elimination. Yes, elimination…once again the Preventive Health and Health Services (PHHS) Block Grant has been eliminated from the President's Budget! The PHHS Block Grant is one of DHPE's three funding priorities and as such gives states the flexibility to deal with those gaps in services and infrastructure that states' so desperately need. Significant progress in chronic disease prevention and health promotion, programs for the most vulnerable and public health jobs could be lost if the PHHS Block Grant funding is not restored.
It should be noted that the appropriations process is started with the release of the President's budget and becomes the starting place for action not the endpoint for the appropriations process. What follows is the beginning of the conversation.
What follows is from the HHS BUDGET BRIEF…
The President's 2015 Proposed Budget includes $1.1 billion for chronic disease prevention and health promotion activities, $110 million below FY 2014.
CDC will continue the anticipated Partnerships to Improve Community Health program created in FY 2014, at the same funding level of $80 million. This program reaches Americans where they live, work, and play to reduce the burden of chronic diseases.
In FY 2015, CDC will also continue to fund the State Public Health Approaches to Chronic Disease Prevention program, which supports states to implement cross-cutting strategies to promote health and prevent and control chronic diseases and their risk factors. The coordinated approach is comprised of the Diabetes, Heart Disease and Stroke Prevention, School Health, and Nutrition, Physical Activity, and Obesity state programs. Coordinating these efforts into a single effort encourages states to implement a cohesive set of evidence and practice-based interventions that address four inter-related chronic diseases and risk factors and allows for increased efficiencies. These interventions are implemented in multiple settings, such as child care, schools, communities, healthcare, and work sites.
In addition, the Budget eliminates the REACH program and the Preventive Health and Health Services Block Grant; other CDC activities address the goals of these programs through the State Public Health Approaches to Chronic Disease Prevention program and the community chronic disease prevention grant program.
GOOD to KNOW…CDC's Congressional Justification and related documents, including the 2014 Operating Plan, will be posted on March 7th at www.cdc.gov/budget. Today, you can access a summary of CDC's request at www.hhs.gov/budget#brief and look for the CDC chapter. DHPE looks forward to talking to you about the FY15 budget request throughout this appropriations cycle.
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We used to love Steve Jackson's Fighting Fantasy books, which were basically papery versions of videogames – turn to page 67 to cast a spell of smiting, turn to page 108 to wet your breeches and run away, that sort of thing. Well, kids don't know what a book is these days, but they can still play those classic adventures thanks to Sorcery!, an iOS update complete with beautiful illustrations, atmospheric sound effects and proper full-on interaction.
Your mystical quest sees you hunting down a mystical crown in a perilous land filled with wild beasties and bandits. At first the whole point of tracking down this royal headgear is unclear, but the backstory is gradually revealed as you push ahead. We'd have preferred a bit more information to begin with, to raise the stakes and get us involved in the mission, but to be fair the plots of the Fighting Fantasy books were always fluffy. It's all about the exploration and bloody limb-rendering battles...
Swords and spells
All of the necessary skills are set up in a brief tutorial that takes place in your home town, before you set off on your crown hike. Fighting is one of the more valuable lessons, and proves to be well handled with a simplified mini-game feel, instead of heaps of stats and dice rolls. The fight is played out via text, with clues given as to what your enemy will do next. You can choose to either defend, which minimises the impact of even strong attacks, or you can have a go to try and knock off some of their stamina. The strength of your blow can be altered via a sliding scale, and if you attack at the same time as your enemy, the one with the most forceful blow will win out. Use too much strength early on, however, and you'll have none left to finish off your foe. There's an element of luck to battles, of course, but you'll also have to employ careful tactics to emerge unscathed.
You're also handed a spell book filled with 40+ powers, which can get you out of many a tight scrape. From cushioning a fall to turning yourself huge, there's a great variety of spells that all prove useful at some point, and can give you a killer advantage in a fight.
It's a big, bad world
When you set off into the world, your journey is relayed via short chunks of text, which are well written and atmospheric – helped by the excellent sound effects and occasional bout of dramatic music. Stalk through a forest and you'll hear insects and birds, while slipping inside a cavern surrounds you with the sinister sound of dripping water. You progress through the realm by dragging a path across a beautifully rendered map, with colourful flags denoting a location you can explore.
At regular points you have to make a choice which affects the adventure. For instance, if you happen across a blind ogre, do you try to convince him you're a friend, charge in with your sword drawn, or run screaming with your pantaloons filled with excrement? Take the riskier approach and you're more likely to be hurt or killed, but the rewards can be great. You can also choose different paths to your destination, which affects a sizeable chunk of what happens and adds greatly to the game's replayability.
If you do fall in battle or make a duff decision, you can restart at a nearby checkpoint or even rewind the adventure to an earlier point to try something different. It's the equivalent of keeping your thumb stuck at the previous page, like we all used to with the books. Of course, the ability to jump back to absolutely any point means you're free to take as many risks as you like, with no real consequences, which lessens the tension of battles and critical decisions somewhat.
The verdict
Sorcery! is a beautifully crafted and excellent refresh of the classic Fighting Fantasy books, brought up to date for a whole new generation to enjoy. The simple but fun combat and game-changing decisions make it a truly involving and addictive game, despite the bog-standard plot and tension-killing checkpoints.


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THE BELLUSCI brothers will be out to make up for missing out on individual glory when they team up in their quest for doubles glory.
Elmo and Alfonso are in to the last four of the Blackburn, Darwen and District Games Federation pairs competition.
The pair, who both play for Hollins Grove, take on Jonny Hannon and Mark Slatter in the semi final to be held tonight at Mill Hill Working Men's Club.
Both men fell to the talents of Ricky Hardman in the singles tournament.
Elmo was beaten in the semi finals by the Ewood man before Alfonso lost 3-2 in the final – having led 2-0 at one stage thanks to two breaks of 60.
But Hardman showed real steel to fight back to level before winning the decisive fifth frame.
The winners of tonight's semi final will play Lee Whittle and Frank Jex Jnr who beat Steve Woods and Mick Clarke in an all-Audley clash.
The final wil be played on May 29 at Mill Hill WMC.


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Ferrari 250 GTO
Bugatti Royale Coupé Napoléon (photo courtesy of Aurélien Boffy)
Shelby Cobra 427
When discussing killings made in the market, the classic story seems to be that hypothetical person who invested $10,000 and bought 5,000 shares of Apple stock in 1985 for $2.00 a share, and held it for nearly 30 years, and watched that initial investment balloon to $6 million today. Some people have done nearly as well in the classic car world. Here are some of our favorite killings in the classic car market:
The 17th annual Amelia Island Concours d'Elegance takes place on Sunday, March 11. Special classes this year include a tribute to the 50th anniversary of both the Ferrari GTO and Shelby Cobra. More
The biggest and most obvious differentiator between cars and traditional investments is that cars can actually be driven and enjoyed, while a stock portfolio, for example, cannot. It is with that simple fact that we at Hagerty Price Guide assembled this short list. More
There's been a lot of discussion among collector car enthusiasts about the recent 2008-09 hiccup. But lost is the fact that over the course of the last decade, … More
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The British Ministry of Defense has investigated 14 chemical weapons factories and storage sites across the United Kingdom for contamination, according to an official briefing seen by The Guardian.
Since World War I, tens of thousands of tons of mustard gas and other lethal chemicals have been manufactured, stored, burned and dumped at various sites throughout England, Scotland and Wales, the news organization reports.
Though a four-year investigation dubbed Project Cleansweep deemed that the materials did not pose a danger to public health or the environment, one expert tells The Guardian there is no scientific proof that all traces of the chemicals are gone.
"The more problematic areas are where physical destruction took place," Alastair Hay, professor of environmental toxicology at the University of Leeds and government adviser, tells the news organization.
"Incineration is a well-recognized method of disposal, but you need to insure all is burned. We have no details of these procedures."
The Ministry of Defense launched Project Cleansweep in 2007. Initially, it included 46 sites but those were whittled down to 14.
A briefing on the project has been released in response to freedom of information requests.
Doug is an unrepentant news junkie who loves breaking news and has been known to watch C-SPAN even on vacation. He has covered a wide range of domestic and international news stories, from prison riots in Oklahoma to the Moscow coup against Mikhail Gorbachev. Doug previously served as foreign editor at USA TODAY. More about Doug
Michael Winter has been a daily contributor to On Deadline since its debut in January 2006. His journalism career began in the prehistoric Ink Era, and he was an early adapter at the dawn of the Digital Age. His varied experience includes editing at the San Jose Mercury News and The Philadelphia Inquirer.
Also: Follow On Deadline on Twitter


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All Star Laundry & Dry Cleaning
Sarasota, FL 34239
About All Star Laundry & Dry Cleaning
Welcome to the All Star Commercial Laundry
Our goal at All Star is to provide you the customer with the finest in laundry services in the Sarasota, Bradenton and Siesta Keys, Florida area. From Coin ...
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Promote your business through our innovative Marketplace system! It's free to sign up!


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2200 Airport Industrial Dr, Ball Ground, GA 30107Request info Add to list
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- Available Spaces
|Space Type
|Industrial Space
|For lease: $0.46/sqft
|5,200 sqft
Excellent Modern Multi-Tenant Facility Skylights Brick and Block Construction Fully Sprinklered Frontage on Airport Industrial DriveView Details
|Industrial Space
|For lease: Negotiable
|15,600 sqft
Building Details:
2200 Airport Industrial Dr is an industrial property for lease in Ball Ground, GA. The property currently has 2 industrial spaces for lease and is marketed by NAI Brannen Goddard and Wilson, Hull & Neal Real Estate.
Excellent modern multi-tenant facility; skylights; brick and block construction; fully sprinklered; dock canopies; frontage on Airport Industrial Drive.
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UK Hoops at Ole Miss -- Post-Game Notes
Feb. 1, 2009
2008-09 UK Hoops Post-Game Notes
Kentucky at Ole Miss
Sunday, Feb. 1, 2009
Oxford, Miss. (C.M. "Tad" Smith Coliseum)
Attendance – 1,328
FINAL SCORE: – Ole Miss 69, Kentucky 60
Team Records and Series Notes
- The Wildcats fall to 12-10 overall, 2-5 in the SEC while Ole Miss improves to 14-8, 3-4 in conference play.
- This marked UK's 16th game on Super Bowl Sunday. The Cats now own a 5-12 record when playing on Super Bowl Sunday.
- The Rebels now lead the series 20-10, including an 11-4 advantage when the game is played in Oxford.
- Coach Mitchell is now 1-1 all-time vs. the Rebels.
- UK returns to Memorial Coliseum for a two-game home stand vs. South Carolina (Feb. 5) and Vanderbilt (Feb. 8).
Team Game Notes
- UK used its seventh different starting lineup this season. It consisted of Victoria Dunlap, Eleia Roddy, Carly Ormerod, Amani Franklin and Carly Morrow.
- Thirteen of UK's 22 games have been decided by 10 points or less this season, including six of seven SEC games. The Cats hold a 6-7 record overall and are 2-4 in SEC close games.
- Only one Wildcat scored in double-digits led by Amani Franklin's season high-tying 20 points.
-- UK is now 1-3 this season when only one player scores in double-figures.
- Ole Miss outrebounded Kentucky, 40-35. It marked just the sixth time this season UK has lost the rebounding battle.
- UK attempted just eight free throws (4-of-8) today, a season low.
- The Cats hit a season high-tying 8-of-18 attempts from the three-point line. UK has now hit a three-pointer in 174 consecutive games. The Cats also hit eight vs. Arkansas and Tennessee.
- UK shot 42.9 percent from the field (24-of-56), its highest shooting percentage since hitting .455 percent against Tennessee in the SEC opener on Jan. 8.
- Kentucky held the Rebels to 40.0 percent (24-of-60) shooting from the field. The Cats have held all 22 opponents to 50.0 percent shooting or less this season.
- The scored was knotted 27 apiece at the half. UK is now 10-2 overall, 2-2 in the SEC when tied for leading at the half.
Individual Game Notes
- Junior Amani Franklin tied her season high and was one point away from tying her career high with 20 points while hitting four three-pointers. She also tied her career high in blocks with two and finished with three steals and three assists.
-- This was her third career and second 20-plus point performance this season. She also had 20 points vs. UC Santa Barbara.
- Sophomore Victoria Dunlap narrowly missed a double-double with nine points and 11 rebounds. She has pulled down double-figure rebounds for the ninth time this season, including fifth straight.
- Senior center Eleia Roddy also narrowly missed a double-double, finishing with eight points and eight rebounds. She played just 18 minutes due to foul trouble.
- Sophomore Carly Morrow hit one three-pointer in the game and has now hit at least one three-pointer in 17-of-22 games this season.


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|Half Baths
|Property type
|Minimum Stay
'Best of the Best' is what you'll find with this beautifully furnished MIRADA MODEL. Highly upgraded with granite counters throughout, 18' tile on most floors & decorator colors. The master bedroom has a queen bed & full bath, the den has 1/2 bath and queen sofabed. This unit is in beautiful condition having been completely redecorated and furnished in the last year. This condo is fully equipped with EVERYTHING but your choice of groceries. There is also an assigned covered parking space. The LaSolana complex boasts it's own clubhouse, lending library, theatre, heated pool/spa, hair salon, pool-side BBQ, organized activities and a resource room with computers As a lessee of this unit you have complete access to the Sun City Grand recreational facilities for a small fee.
The LaSolana Complex is the best kept secret in Arizona. This is Resort style living at its' best with a totally care free feel and the friendliest people you can find. Picture yourself on the lanai overlooking the complex greenery, having a glass of cabernet and appetizer with your loved one and looking at the mountain views or watching the beautiful sunset. In the morning you can have your coffee in the cute nook or back on the lanai while you contemplate the possibilities of any number of fun activities that you can choose from. Let your imagination run wild. We also have a sun City West patio home for rent.
Keywords: golf, tennis, active adults, age restricted, resort, sunsets, mountain views, activities
pickleball, bocce ball, craft learning centers, recreation buildings
We require a pet fee of $250-500 based the breed and size. We do not allow cats. Our unit is a non-smoking unit
Rent rates: April 2014-$1650;June-Sept 2014-$1250;May, Oct, Nov 2014-$1350;Dec 2014-$1650;Jan-March 2015-$1975
We require a $1000 reservation fee which becomes a part of the rent. Full amount of rent is due and payable 3 months in advance of the first day of occupancy. Upon taking possession a $700 fee is payable. This fee consists of a $500 damage deposit and is refundable. The remainder is a $200 cleaning fee of which $100 is refundable if the property is left in a state of reasonable cleanliness.


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Hard not to love this. Comedian Pete Holmes has an answer to the question nobody asked.
What would it sound like if Ray Romano could sing duets with himself? Now, in this parody commercial, Holmes teamed up with the real Romano so we can hear a voice that is familiar for sounding... less than musical. Check it out!


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After the official biz we get right into our FALL TV REPORT CARDS (6:44)! 23 shows! Basically, for us, these are the shows that failed this season - and the shows that made the grade. Certain shows get spoiled a bit but we've marked those off! We start with shows that FLUNKED! Listen to find out why! • Heroes Reborn (7:29) • The Player (11:00) • Limitless (13:15) • Benders (14:04) • Once Upon A Time (Spoilerish 18:16)Passed But Yet To Be GRADED:Listen to find out what we graded these! • Into the Badlands (24:44) • Grimm (Spoilers! 26:49) • Blin
More from


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ED Magedson – Founder
Ripoff Report
MVI Marketing /Mini Vacations Inc.410 Ware Blvd. Tampa, Florida United States of America
Does your business have a bad reputation?
Fix it the right way.
Corporate Advocacy Program™
This report was posted on Ripoff Report on 05/07/2003 05:36 AM and is a permanent record located here: http://www.ripoffreport.com/reports/mvi-marketing-mini-vacations-inc/tampa-florida-33619/mini-vacations-mvi-marketing-ripoff-tampa-florida-55979. The posting time indicated is Arizona local time. Arizona does not observe daylight savings so the post time may be Mountain or Pacific depending on the time of year.
Ripoff Report has an exclusive license to this report. It may not be copied without the written permission of Ripoff Report. READ: Foreign websites steal our content
Click Here to read other Ripoff Reports on MVI Marketing /Mini Vacations Inc.
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SUBMITTED: Wednesday, February 15, 2006POSTED: Wednesday, February 15, 2006
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HBO and Funko have teamed up to make this Game of Thrones Comic-Con Exclusive Pop! Television Ned Stark Figurine and, while it looks pretty normal at first glance, the exclusive part of this figure is what makes it amazing (and potentially upsetting but still) awesome.
Check it out after the break.
It's available for pre-order now in the HBO store online.
Product Page ($19)


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Each month, Rated People connects over 50,000 homeowners with quality tradesmen - simply enter your job details in the form above to get started.
We'll match your job to the relevant tradesmen in your area - those interested will pay to see your contact details and call you to quote.
As each tradesman expresses interest in quoting on your job, we'll send you their profile and ratings to help you choose the right one for you.
After the work is complete, return to the site and rate your tradesman based on their quality of work, reliability and value for money.
Tree Surgeon
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Steven by Steve Madden 'Puffy' Boot
Absolutely love these boots! I first saw them in Cosmopolitan. They come in red or black and have a 3 inch wedge heel. They are $138.95 and available at Nordstrom.
These jeans make The Husband sit up and take notice. My backside never looked so good. They're hot!!!
off to the wedding!Tags: hot, wedding dress, sun dressAdded 8 Years Ago from Nordstrom
I think this is a really cool and great dress!Its like art on a dress but all designer...Tags: dresses, hot, sexy, sweater dress, designer dress, chic dress, colorful dress, Nordstrom dress, art dressAdded 8 Years Ago from Nordstrom
Great jeans that look good on any body!! The perfect slim fitting dark jean that almost every girl needs!
Comfort and warmth now costs $140. Remember when UGG was a brand bought by poor people? :-)Tags: fashion, winter, gifts, shoes, Clothes, accessories, style, boots, womens shoesAdded 9 Years Ago from Neiman Marcus Online
Get your tough girl on, while being stylish at the same time. This feels like an item from Gwen Stefani's famous clothing line.
This cute little number is made of soft crinkled lambskin, cropped at the waist and sleeve and trimmed with ruffles. A feminine take on the leather coat.
These are basic black pumps with a bit of added glitz to the heel...now the boys will have even more reason to watch us walk away!
Starter chain bracelet. Perfect for adding on charms.Added 9 Years Ago from Juicy Couture
The other iconic sneaker is the Converse All Star. I think one of the greatest things about the All Star is that it can be used for so many styles. Wear it plain and be old school, or trick it out and be punk. The sky is the limi... The other iconic sneaker is the Converse All Star. I think one of the greatest things about the All Star is that it can be used for so many styles. Wear it plain and be old school, or trick it out and be punk. The sky is the limit when it comes to All Stars.
An exposed zipper secures the side of a heavier-weight wool skirt with an oversized plaid pattern. High-waisted style has a form-fitting silhouette finished with an inverted back pleat for ease of movement.
This boot is HOT! A pump and a boot in one! I already have the perfect outfit and jewelry to match!
I love, love love love love love love love love love this bag. If I were a bag I would be this bag. I am going to end up in jail if I ever see anyone with this bag on the street.
Fun pair of shorts to put on over a bikini after being on the beach and heading off home, back to hotel, to a cafe, for a walk or just to chill out in around the house - terry fabric is great over wet bikini's !!
Sweet, stylish and sexy!! Perfect for a night out during Valentine's Day.Tags: fashion, pink, trench coats, gift ideas, hot, women, Valentines, mommy, pink satin trench coatAdded 10 Years Ago from Nordstrom
These are some hot shoes!!!Tags: shoes, pumps, womens shoes, hot, spring, Steve Madden, black shoes, ladies shoes, steve madden pumpsAdded 10 Years Ago from Nordstrom
The Street Style #1 Look is all about the white, cotton trapeze dress. This one from BCBG is cute and perfect for a rainy or sunny summer day stroll with your daughter. Empire waist and cascading layers of eyelet lace.


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PLOS Medicine publishes research and commentary of general interest with clear implications for patient care, public policy or clinical research agendas.
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Stanford Prevention Research Center, Department of Medicine and Department of Health Research and Policy, Stanford University School of Medicine, Stanford, California, United States of America
Center for Health Policy and Center for Primary Care and Outcomes Research, Stanford University School of Medicine, Stanford, California, United States of America,
Veterans Affairs Palo Alto Health Care System, Stanford, California, United States of America
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Add a new page
Whether you intend to add a new category, guide or article, MindTouch allows you to easily add new pages to your site. This article guides you through the steps of creating new pages in your MindTouch site using our default page templates. You can also create your own custom page templates, although we recommend that you become familiar with the existing default page templates first.
How to add a new page
Step 1: Choose your new page template
- On the MindTouch toolbar, click New.
- Select one of the following page default templates or choose one of your own templates:
A Blank page is simply a page with no preset text or formatting. If you create a new page using the Blank page option and save without adding any content, MindTouch will redirect anonymous users from your blank page to the homepage to ensure your end users don't encounter a blank page.
The templates that should exist under the current page will appear automatically. To view the whole list of templates, select the "Show all […] available templates" checkbox.
- Depending on whether you want to create the page live or as a draft, select either the Create live or Create draft radio button. (You will be able to publish the draft to your live site later.)
- Click Create.
Step 2: Add content to your new page
- Title your page.
- Replace any instructional text with your content.
Do not remove the DekiScript codes at the top of the page or the "Tags recommended by the template..." line at the end of the page. Both determine how the page behaves.
The MindTouch editor is typical of other document creation applications you've used in the past. Use the editor to bold, italicize or edit your text as you would normally perform in a document creation application.
Step 3: Configure new page settings
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- Hover over the Add page summary field to display the page summary icon.
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The page summary is not only the first paragraph that is displayed on your page, it also is the description that is displayed in MindTouch and Google search results, so make sure to include valuable key words.
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- Apply appropriate Tags to your article. Press Enter after entering each tag.
Tags determine which articles MindTouch recommends at the bottom of your page, so keep tags consistent. The more tags related articles have in common, the more likely they will be recommended together.
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Find a copy online
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|Early works
Maps Early works to 1800
|Material Type:
|Internet resource
|Document Type:
|Map, Internet Resource
|All Authors / Contributors:
César-François Cassini; J Andriveau-Goujon; Société de la carte de France.; Dépôt de la guerre (France)
|OCLC Number:
|Relief shown by hachures.
Title from sheets no. 1 and no. 6.
Publication taken over by Dépôt de la guerre in 1793.
Publication information and dates from Pelletier's Cartes des Cassini, 2002.
Engravers named on some sheets: C. Aldring, Aubin, J.A. Aveline, Beauvais, Bourgoin, R. Brunet, N. Chalmandrier, Chambon, Desbruslins, B. Desfontaines, Dupain-Triel fils, Durand, Foin, Le Roy le ainé, Le Roy le jeune, J. Séguin.
Sheet no. 160 was never published, but its projected coverage was included in some states of sheet 131.
Most sheets include both a sheet number in the upper right or middle margin and a number in the upper left indicating the order of publication, e.g. no. 3, feuille 11.
LC scanned copy is LC copy 2 from the Hauslab-Liechtenstein collection. This is a complete set, hand colored, on uncut sheets of heavy paper.
LC copy includes 2 different states of sheets 5, 6, 41, 43, 77, 78, 109 (feuille 68), 110, 113, 141 (feuille 73), 142, 161, and 162.
LC copy includes 2 copies of sheets 10 and 78 (1 copy of 1 state, 2 copies of the other).
LC copy includes some sheets mounted in sections on cloth backing.
LC copy imperfect: lacking sheets 1, 7, 8, 24-28, 60-64, 93-98, 102-105, 125-130, 167, 170-72.
|175 maps on 182 sheets ; sheets 65 x 95 cm or smaller.
|Cartographic Mathematical Data:
|Scale [1:86,400].
|Series Title:
|[Hauslab-Liechtenstein collection], HL 30-1-175
|levée par ordre du roy.
User-contributed reviews


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A Tesco supermarket in upmarket Highgate was today named as one of Britain's filthiest food shops.
The shop in Swain's Lane is one of just 14 in the country to have been given a "zero" rating by inspectors.
It was closed for a day in April after officers discovered a mouse infestation.
Staff had to thoroughly clean the building and put in pest control measures to prevent further infestation, before reopening.
Four other stores in the capital also received the lowest rating: Fine Foods in Harlesden, Sira Cash & Carry in Southall, Abbey Wood Afro Caribbean Cash & Carry in Willesden and Cheam Food Centre in Sutton.
The businesses were among 11,440 shops tested across England, Wales and Northern Ireland by local authority inspectors to protect customers from food poisoning.
A Tesco spokesman said today: "We take the hygiene standards in our stores very seriously and receive the best possible food hygiene ratings in the vast majority of our stores.
"Earlier this year, we voluntarily closed our Swain's Lane Express store for two days to deal with a pest issue. We cooperated fully with the local authority officers and the store conditions have now vastly improved."
The zero rating means a shop fell dramatically short of hygiene guidelines and that 'urgent improvement is necessary'.
It also means they could have a history of rodent infestations, filthy conditions or inadequate safety measures.
The data, which is regularly updated on the agency's website, reflects the standards of food hygiene found on the date of inspection or visit by the relevant local authority.
All the scores listed on the FSA's website reflect the standard, graded from zero to five, awarded during the most recent inspection and improvements may have been made since then.
Some of the businesses given a zero rating include:
Fine Foods, Harlesden, London
Sira Cash & Carry, Southall, London
Tesco Express, Swain's Lane, Highgate, London
Abbey Wood Afro Caribbean Cash & Carry, Willesden, London
Cheam Food Centre, Sutton, London
Yours Supermarket, Leicester
Spar, Millstone Lane, Leicester
Co-op, Evington Road, Leicester
Pound Box, Preston
Iqbal Cash & Carry, Rochdale
Pak Supermarket, Birmingham
Poundland, Corporation Street, Birmingham
Beer Bank, Walsall, West Midlands
Aberavon Supermarket, Port Talbot, South Wales
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- Britain
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Out of stock
Thomas Ruff has had an ongoing fascination with astronomy. His attempt at photographing the night sky failed due to the lack of detail captured in the pictures taken. Ruff's equipment could not render the detail he wanted as well as air and light pollution added to the difficulties of capturing the beautiful constellations. Ruff's solution was to take observation shots from the European Southern Observatory (ESO) based in the Andes in Chile.
Ruff talked briefly about STERNE in a 1993 interview with Philip Pocock:
Pocock: Why stars? Do they mean something extra special to you?
Ruff: When I was eighteen I had to decide whether to become an astronomer or a photographer. I also wanted to move the so-called künstlerische Fotografie boundary. Do you know Flusser?
Pocock: No.
Ruff: He defines isolated categories for photography that sometimes cross over. For example, if medical photography is used in a journalistic way, or with the Stars, a scientific archive isn't used for scientific research but for my idea of what stars look like. It's also a homage to Karl Bloßfeldt. In the twenties he took photographs of plants to explain to his students architectural archetypes. So he was a researcher but the way he represented his intention with the help of photography made him an artist. I like these crossovers.
Publisher specialising in limited edition Photo and Art Books.
We view the book as the final step in an artists process, and encourage the artist to engage in the conception, design and feel of the book.
Having worked on the book closely with the artist we feel it is only right we also keep a close relationship with bookshops.
Occasionally our books can be bought with special editions.
We're happy to take submissions - but please don't mail us anything you expect us to return - alternatively just send us an email.
Send us an email if you would like to visit us in London.


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I Am The Movement
Our friends at 'The Got Your Back Movement' are liquidating their remaining merchandise and are giving ALL proceeds to Poetice International's ongoing work.
Don't pass up this amazing opportunity to get a couple new shirts for a great price. They won't last long!
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