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Jersey Jewel B785
- No Pets Allowed
- WiFi
- Fireplace
- No Smoking
- Bed & Bath Linens
- Pillows & Blankets
- Coffee Maker
- Toaster
- Blender
- Dishes, Utensils, & Cookware
- Dishwasher
- Microwave
- Iron & Ironing Board
- Stereo with CD Player
- Telephone
- TV & DVD Player
- Central Heat & Air Conditioning
- Washer & Dryer
- Outdoor Furniture
- Outdoor Shower
- Grill
- Beach Chairs (5 per home)
Home Details
|Jersey Jewel
|Wild Duck Dunes
|Check in Day:
|Check-in Office:
|Distance to Beach:
|View Map
|5 (1K, 2Q, 2T, 1Duo, 1Tr)
|Master Bedrooms:
|3 Full 2 Half
|Parking for 4
This comfortable, well-maintained Duck vacation home is close to the beach and offers deck access from every room!
Main House
|Level 1
|BR (Q); half bath.
|Level 2
|MBR (K); two BRs (2T, Duo/Tr); full bath; den; covered deck.
|Level 3
|MBR (Q) with whirlpool; half bath; kitchen with breakfast bar; great room; open decks.
|Multiple TVs.
Ratings & Reviews
- Elaan 9/4/2016
- Stephen 8/21/2016
- Gregory 7/3/2016
- Jonathan 6/5/2016
Questions & Answers
Is there a community pool?
Sharon, guests of B785 do not have access to a community pool.
- Answered by Twiddy on 3/13/2017
does all the rooms have flat screen tvs
Brittney, the TV in the great room is a flat screen.
- Answered by Twiddy on 7/21/2016
Is there a beach wagon available to carry things down to the beach?
Ellen, items such as beach carts are not standard amenities for our homes. If you would like to rent beach equipment for your stay, Just for the Beach, Moneysworth, and Ocean Atlantic Rentals all provide this service. For contact information, please visit www.twiddy.com/activities/services.aspx.
- Answered by Twiddy on 7/11/2016
Is there a trundle in the room with the bunk beds? Because in the description it says "Duo/Tr". And I'm not sure if the Tr is just supposed to be T for Twin. Or if it means trundle.
Autumn, there is a trundle in the room with the Duo.
- Answered by Twiddy on 7/4/2016
Are there any pictures of what the bedroom on level 1 looks like?
Mike22, all available photos are currently provided on the website. Unfortunately, we do not have an available photo of this room. Please let us know if you have specific questions about the Level 1 BR (D) we may answer for you.
- Answered by Twiddy on 2/14/2015
Is there an enclosed, outside shower?
Yes Amanda, outdoor showers are standard amenities in all of our Twiddy homes!
- Answered by Twiddy on 7/1/2014
Is there a washer and dryer?
Hi Agee! A washer and dryer is a standard amenity in every Twiddy vacation home. You can find a list of all Twiddy standard amenities here, www.twiddy.com/abbreviations-definitions.aspx#stfurneq
- Answered by Twiddy on 7/20/2013
Are there bikes and beach chairs available at this house?
Hello J, every Twiddy home provides 5 beach chairs. Bikes are not a standard amenity. If you would like to rent additional beach equipment or bikes, Just for the Beach, Moneysworth, and Ocean Atlantic Rentals all provide this service. For contact information, please visit www.twiddy.com/activities/services.aspx.
- Answered by Twiddy on 6/13/2013


text:
Google Map
Though the police called it a rumour, eyewitness account, as per the report, suggests that at least 10 women were sexually assaulted.
NH1 atravellersdiary
The report said 30-odd goons were involved in attacking the commuters going towards the National Capital Region (NCR).
The victims were provided clothes and blankets by villagers of Hassanpur and Kurad.
The women were united with their families at Amrik Sukhdev Dhaba, according to an eyewitness. And instead of investigating the matter, district officials, persuaded the families to take the women home.

subset: commoncrawl


text:
October 3, 2011
I'm a little late with my entry today! Gomen ne~?!
Today's manga review is going to be on another sports manga. this is a feel good manga about an underdog story and so on~ blah blah blah! haha, its not as old as the real classic manga like Slamdunk, but its been released for a while and yes indeed…it is complete!
The manga is called Eyeshield 21!
The hero of this story is a boy called Sena Kobayakawa, he is physically weak, and always get picked on and never accomplished anything in his life. His friend taught him how to run, hence running is his only form of escape from being bullied, and over the years he became extremely agile and fast. His talent was scouted by Deimon high school's (the high school Sena attends) American Football club captain Yoichi Hiruma. He is the devil itself as he blackmailed Sena into joining the American football team. At first Sena was extremely afraid of the sport, he didn't want to be found out playing such a dangerous sport especially by Mamori Anezaki, who is Sena's Senior in highschool. She is very protective and very parental like over Sena as they've been friends since childhood and she knows Sena always get picked on. So to hide his identity from Mamori he wore an Eyeshield on the Football Helmet hence the manga name 'Eyeshield 21′.
This manga has incredible humour, and terrific shonen art. It has a right balance of excitement with the story and the art. Some of the concept the author made up is quite ridiculous but thats what make this manga fun and awesome to read! As you progress over the story, it gets more and more exciting especially when Deimon high school competes with other schools in the tournaments!! It is definately worth the read!!
Written by Riichiro Inagaki
Illustrated by Yusuke Murata
Genre: Shonen, Sports, Comedy
Released Date: 2002~2009
Volumes: 37 (complete)
Story: 08/10
Art: 10/10
Over all: 9/10
See ya'll NEXT WEEK!!! PEACE OUT!
FAT JENGA! sign off. . .


text:
Ray LaMontagne, one of the most distinct and recognizable voices in music, announced his first North American tour in support of his new album Gossip In The Grain due out October 14 on RCA Records.
The six week tour starts September 30 in Indianapolis. October 14 is the new release date for the album as LaMontagne, struck by inspiration, went back into the studio last week to record additional material. The new album can be pre-ordered at www.raylamontagne.com.
Recorded with returning producer, Ethan Johns in Box, England, and touching upon a range of styles and musical settings- spanning pastoral folk, railroad blues, front porch country, and plangent balladry – Gossip In The Grain proves to be his most creative and emotionally expansive collection to date.
Whereas LaMontagne's two previous albums, Trouble and Till The Sun Turns Black, were largely solo affairs, with Johns serving as multi-tasking instrumentalist, Gossip In The Grain sees him joined by members of his touring band, bassist Jennifer Condos and guitarist Eric Heywood (with Johns largely handling drum duties). Along with his band members, LaMontagne is also joined on two tracks – "A Falling Through" and "I Still Care For You" – by singer/songwriter Leona Naess.
Naess will be the opener for the entire tour and is touring in support of her new album Thirteens out September 23 on Verve Forecast.
Below are the dates for Ray LaMontagne with Leona Naess:
Sept 30 Murat Theatre Indianapolis, IN
Oct 1 Chicago Theatre Chicago, IL
Oct 3 Union Theatre Madison, WI
Oct 4 State Theatre Minneapolis, MN
Oct 6 Royal Oak Music Theatre Royal Oak, MI
Oct 7 Queen Elizabeth Theatre Toronto, ON
Oct 9 Opera House Boston, MA
Oct 10 Opera House Boston, MA
Oct 11 Radio City Music Hall New York, NY
Oct 13 Keswick Theatre Philadelphia, PA
Oct 14 The Strathmore Music Center Washington, DC
Oct 16 Meymandi Concert Hall Raleigh, NC
Oct 17 Bijou Theatre
Oct 18 The Tabernacle Atlanta, GA
Oct 19 Ryman Auditorium Nashville, TN
Oct 21 Uptown Theatre Kansas City, MO
Oct 23 Verizon Wireless Theatre Houston, TX
Oct 24 Majestic Theatre Dallas, TX
Oct 25 Paramount Theatre Austin, TX
Oct 27 Macky Auditorium Boulder, CO
Oct 28 Murray Theatre Salt Lake City, UT
Oct 30 Wiltern Theatre Los Angeles, CA
Nov 1 Spreckels Theatre San Diego, CA
Nov 3 Paramount Theatre Oakland, CA
Nov 5 Arlene Schnitzer Concert Hall Portland, OR
Nov 6 McDonald Theatre Eugene, OR
Nov 8 Vogue Theatre Vancouver, BC
Nov 9 Marion Oliver McCaw Hall Seattle, WA


text:
Studying Hebraic Roots?
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Patterns of Exile and Redemption in the Torah
This Teaching set explains how the events in Genesis and Exodus foreshadow the course of Biblical and modern history. The events associated with Adam and Eve, Noah, Abraham and Isaac foreshadows the exile of the nation of Israel into the nations and their redemption through the Messiah. The conflict between Jacob and Esau foreshadows the events of the tribulation or Jacob's trouble. Joseph's separation from his brothers foreshadow the split of the house of Jacob into Northern Kingdom and Southern Kingdom and there eventual reunification. The judgments upon Egypt foreshadows the judgment upon the nations during the tribulation period. The two signs of Moses foreshadow the death and resurrection of the Messiah The events of the historical Egyptian exodus foreshadows the tribulation, judgment of the nations, and the redemption of Ephraim and Judah.


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|Publication number
|Publication type
|Application number
|Publication date
|Jul 19, 2005
|Filing date
|Oct 24, 2000
|Priority date
|Oct 24, 2000
|Fee status
|Publication number
|Barry L. Spletzer, George S. Davidson, Daniel J. Zimmerer, Lisa C. Marron
|Original Assignee
|Sandia Corporation
|Export Citation
|BiBTeX, EndNote, RefMan
|Patent Citations (4), Non-Patent Citations (2), Referenced by (10), Classifications (12), Legal Events (7)
|External Links: USPTO, USPTO Assignment, Espacenet
This invention was made with Government support under Contract DE-AC04-94AL85000 awarded by the U.S. Department of Energy. The Government has certain rights in the invention.
This invention relates to the field of displays using multiple projectors to provide enhanced resolution.
Conventional displays can be characterized by their resolution. Generally, higher resolution means higher display system cost. In many display applications, however, higher resolution is needed for only portions of the overall image. For example, in display of a sporting event, only a limited region (e.g., the pitcher and batter in a baseball game) benefits from high resolution at any given time. As another example, in a display of a computer image, only the portion currently being inspected needs to be displayed in high resolution. In both examples, low resolution display of the surrounding context can aid understanding of the portion displayed at high resolution. Also, the portion that benefits from high resolution display can change with time (the batter hits the ball and begins running the bases in the baseball game example). A conventional display with sufficient resolution for the high resolution portion can be more expensive; a conventional display at lower cost can be incapable of the high resolution needed for some portions of the image.
Accordingly, there is a need for a display method and apparatus that can display portions of an image at a higher resolution and the rest at lower resolution, without incurring the cost associated with displaying the entire image at the higher resolution.
The accompanying drawings, which are incorporated into and form part of the specification, illustrate embodiments of the invention and, together with the description, server to explain the principles of the invention.
The present invention provides a method and apparatus for displaying two portions of an image at two resolutions. For example, the invention can display an entire image at a first resolution, and a subset of the image at a second, higher resolution. Two inexpensive, low resolution displays can be used to produce a large image with high resolution only where needed.
The first and second portions of the image can be any portions of the image, including the entire image. For example, the first portion can be an entire image to be displayed, and the second portion can be a subset of the entire image that requires display in higher resolution. The first portion can be, for example, a display of a camera image while the second portion is a subset of the camera image deserving specific attention (e.g., where motion occurs, or where detailed features are present). The first and second portions can change with time. In the entire image/subset example, the entire image can change with time, as with a panning camera or an animated computer display. The subset can also change with time, both in content (as the image itself changes) and in relation to the entire image (as the subset deserving attention moves relative to the image). Motion of the second portion relative to the entire image can follow, as examples, a viewer's eye movements, motion of a pointing device, and motion of an onscreen object (such as a ball in a sporting event).
The display medium can be of any form compatible with the video sources. As examples, rear projection displays, screens, and suitable wall surfaces can each server as a display medium.
Those skilled in the art know a variety of suitable video sources suitable for use in various settings. Any combination of display technology that would be capable of displaying 2 different resolutions on the same screen may be used. Examples of suitable image display sources include rear projection systems, cathode ray tube (CRT), LCD, Digital Light Projectors (DLP), and plasma displays. The first video source can be operated in a conventional method to display a larger, lower resolution image. The mounting and alignment of the two video sources depends on the type of display sources, optical properties (such as focal length and depth of focus), image steering apparatus, and the geometry of the system.
In the example implementation described below, the two projectors were rigidly mounted to a base to reduce the degrees of freedom of the system. The main projector was set approximately perpendicular to the display screen to limit distortion of the main image. However, this is not necessary. The transform (TL) compensates for linear distortion in overall transform. If the projection surface (screen) is planar, then homogeneous transforms can be used. Otherwise, more complex transforms can be required.
The second projector was mounted so that the focal range would coincide with the display screen after reflection from the mirror, and such that the optical axis of the lens intersects the mirror coordinate system at the origin. The angles between the projects are arbitrary, and were chosen to restrict the overall size of the apparatus.
The second video source can be any of a variety of video sources as discussed above. The second video source can be mounted so that its display corresponds to only a subset of the region covered by the display of the first video source. If the second portion of the image is mobile with respect to the first portion, then the second video source must be able to adjust the placement of its display relative to the display of the first video source.
A conventional video source can be combined with an image steerer to provide the second video source. The image steerer directs the output of the conventional video source to the appropriate portion of the display medium. As examples, an image steerer can comprise a movable mirror, a controllable optical transmitter, or a micro-electromechanical device. A conventional video source can also be mounted mobile with respect to the display medium, allowing the output to be directed to the appropriate portion of the display medium by movement of the video source.
The second portion of the image travels a different path to the display medium than does the first portion. Accordingly, the display of the second portion can be adjusted to achieve proper registration between the two portions. In the discussion below, it is assumed that the second portion is directed toward the display medium by a gimbal-mounted mirror, controlled by computer commands to stepper motors, as shown in FIG. 2. Those skilled in the art will appreciate similar image transformations suitable for other mechanisms directing the second portion to the display medium.
The output of the second video source can undergo significant distortions depending on the location on the display medium to which it is projected. These distortions can include skew, rotation, and anisotropic stretching. The second portion can be transformed before reaching the second video source so that, after all the distortion, the display on the display medium is properly registered. The transformation can be complex, but, since ray tracing from the object plane of the second video source to the display medium involves classical projection, rotation, and reflection, the transformation can be expressed as a single homogeneous transform. Development of such transforms is discussed below.
Homogeneous transforms can provide a powerful mathematical tool for converting between coordinate systems and determining the projection of images. A homogeneous transform comprises a 4�4 matrix that operates on a four element homogeneous coordinate vector. The first three elements of the homogeneous coordinate vector are the usual x, y, and z components used to describe a three-dimensional point. The fourth component (d) allows projection information to be carried along with the three-dimensional point. For a point in actual space this fourth component is always equal to 1. The usefulness of this fourth component and its physical meaning will become more clear later.
Homogeneous transforms are true matrices. Accordingly, they are amenable to various matrix operations; for example, several simple transforms can be multiplied together to produce a more complex transform. A homogeneous transform can be understood by examining some of the basic components that can contribute to the transform. The first of these is translation of the coordinate system origin. An origin translation transform has the form shown in Equation 1.
The transform of Equation 1 converts a general point in the s coordinate system to the b coordinate system. Examining the operation shown in Equation 1. the general point in the vector t is simply added to the point expressed in the s system. This constitutes a translation transform where the vector t is defined as the vector from the origin of the b system to the s system. Rather than writing on all the elements explicitly, this translation homogeneous transform can be defined as in Equation 2.
In addition to translation, rotation between two coordinate systems can be defined by the homogeneous transform of Equation 3, where C is a point expressed in the c coordinate system and B is the identical point expressed in the b coordinate system
All of the elements of this rotation vector are made up of dot products between the unit vectors of the b and c coordinate systems. The notation used here for this rotational homogeneous transform is shown in Equation 4a.
The rotational transform and origin translation transform can be combined to perform a complete coordinate system transform as in Equation 4b.
C(b,c)=O(b,c)R(b,c) Equation 4b
In addition to rotation and translation scaling may be accomplished by a homogeneous transform. Simple isotropic scaling is done by multiplying each of the three components by a fixed scale factor f. The scaling transform is defined as in Equation 5.
The next basic transform is a projection transform which uses the bottom row of the homogeneous transform. Before presenting the form of this transform, some explanation of the fourth element (d) of a homogeneous coordinate can be useful.
As mentioned before, a point in space can be represented by the usual xyz coordinates and a d value of 1. The definition of homogeneous coordinates states that any four element coordinate can be converted into a point in space by dividing all four elements by the value of d. By defining this as a valid operation on a homogeneous coordinate the ratios between the first three elements are invariant. This means that a homogeneous coordinate describes a line passing through the origin from which the point is measured and through the actual point in space. This property makes homogeneous coordinates very useful for calculating projections. If the origin of the coordinate system is moved to the observation point or perspective point then the homogeneous coordinate of a point defines a line that passes through the point in space and through the observation point. By definition, this line is the projection of the actual point through the observation point.
Using the projection transform, the homogeneous representation with respect to the origin can be produced for any point. By adjusting the fourth coordinate, any point along the line passing through the original point and the origin can be represented. Specifically, consider the value of the fourth coordinate required to represent the point where the line intersects a plane. The plane is completely defined by the vector N that connects the origin to the image plane and is normal to the image plane.
Similar triangles lead to Equation 6.
The vector C can be scaled to represent Cp as in Equation 7.
By the definition of homogeneous coordinates, the fourth coordinate (d) can be divided into the homogeneous representation to create a point in space. Therefore, to convert the point C to the point Cp, only the value of d need be modified. The value of d required to perform the conversion is given by Equation 8.
The vector M can be completely determined from the projection plane definition N as in Equation 9.
The bottom row of the homogeneous transformation can be used to produce this value. The first three components of the bottom row operate on the vector to produce a dot product. The fourth component must be 0 so that the proper value of d is obtained. This results in a transform of Equation 10, which is the complete projection transform.
The final basic transform is the zoom transform, which consists of the identity matrix with a zoom value in the lower right element. The zoom value is a multiplier of the input d value of the homogeneous coordinate. Since the d value can be divided into the homogeneous coordinate to produce a point in space the zoom factor is the isotropic scaling of the distance from the origin to the input point. After the transform, the distance to the point is 1/z times the distance to the original point. The zoom transform as defined as in Equation 11.
One more transform is needed to completely analyze the system. This is the transform resulting from reflection in a mirror. The nature this transform will be determined here based on a vector analysis of reflection. The position of the mirror can be completely described by the normal vector (n) to the mirror. In general this normal vector will be known and the resulting transform is desired. Unlike previous transforms which expressed a given point in a second coordinate system, the mirror transform takes a point in the original coordinate system and expresses location of the reflected image of that point in the original system (virtual point).
The development of a transform to handle mirror reflection requires the determination of the relationship between the incident coordinate system and the reflected coordinate system. To simplify this determination, place the origin of both coordinate systems coincident on the mirror. The z-axis (k) of the incident system points towards the mirror. The required rotation to produce the reflected system must be determined. The notation for the reflected system will be to add a prime (′) to the notation of the incident system. The law of reflection gives Equation 12.
{circumflex over (k)}′={circumflex over (k)}−(2{circumflex over (k)}�{circumflex over (n)}){circumflex over (n)}={circumflex over (k)}−2n z {circumflex over (n)} Equation 12
The equation of the mirror plane is given in Equation 13, where A is any vector lying in the mirror plane.
A�{circumflex over (n)}=0 Equation 13
To determine the direction of the reflected x-axis, consider the projection of a ray parallel to the z-axis but displaced one unit in the x direction. The intersection of this ray and of the z-axis with the mirror creates two points, which define the projection of the x-axis onto the mirror. The vector representing this projection can be determined by noting the equation of the incoming ray, given in Equation 14.
x=1, y=0 Equation 14
Solving for the z coordinate of the intersection of the ray with the mirror plane yields Equation 15.
The projection of the x-axis onto the mirror (im) has the above x, y, and z components as in Equation 16.
This vector, when viewed from the k′direction, constitutes the x′-axis. The im vector can be projected into the plane perpendicular to the k′direction by subtracting the component of the vector parallel to k′. This results in the expression for i′in Equation 17.
�′=ī m−(ī m �{circumflex over (k)}′){circumflex over (k)}′ Equation 17
Equation 17 shows i′ as a unit vector. This is true because an object is not foreshortened by reflection So that the magnitude of the reflected vector is the same as the incoming vector as long as the view direction relative to the vector remains the same. Combining this expression with the above relationships gives Equation 18.
Evaluating some useful subexpressions gives Equation 19.
�{circumflex over (k)}′=�[{circumflex over (k)}−(2{circumflex over (k)}�{circumflex over (n)}) {circumflex over (n)}]=−(2{circumflex over (k)}�{circumflex over (n)})(�{circumflex over (n)})
{circumflex over (k)}�{circumflex over (k)}′={circumflex over (k)}�[{circumflex over (k)}−(2{circumflex over (k)}�{circumflex over (n)}) {circumflex over (n)}]=1−2({circumflex over (k)}�{circumflex over (n)}) 2 Equation 19
Combining yields Equation 20.
Since all the indicated dot products with the mirror normal have one of the original unit vectors as a component, they can be replaced by the components of the mirror normal unit vector as in Equations 21 and 22.
From this, the homogeneous transformation matrix of a mirror can be developed. This matrix consists solely of rotation with the origin of both systems located coincident on the mirror surface as shown in Equation 23.
The notation and description of each of the required contributing transforms is summarized in Table 1.
TABLE 1 Transform Symbol Description Origin translation O(b, c) Translates coordinates from origin of c system to origin of b system Coordinate rotation R(b, c) Converts coordinates from c system to b system provided that the system origins are coincident Coordinate conversion C(b, c) Convert coordinates from c system to b system accounting for both rotation and translation Isotropic scaling S(f) Isotropically scales coordinate values by factor f Projection P(N) Projects points from three-dimensional space onto an image plane where N is the vector from the coordinate system origin to the image plane and normal to the image line Zoom Z(z) Scales three-dimensional points so the resulting point lies along the original line connecting the origin with the point but at a fraction 1/z from the origin Mirror reflection M(n) Determines the image of the original point has seen in a mirror based on the unit normal n to the mirror
Before tackling the more difficult problem of two projectors and a mirror, consider the problem of producing a projection of an object onto an image plane. This requires that all rays from the object to the image plane pass through the pinhole or observation point. The intersection of such a ray with the image lane is the projected image of the original point.
In the figure, the points in the object are originally expressed in the S coordinate system. The homogeneous coordinate representation of the general vector S is given in Equation 24.
The 1 for the fourth element means that the actual values of the vector S are used here. First, construct a simple rotation and translation transform to convert from the S coordinate system to the C coordinate system with the origin at the pinhole. This transform is in Equation 25.
C=C(c,s)S Equation 25
In this transform, c and s refer to the appropriate unit vectors of the two coordinate systems and s0 is the vector from the origin of c to the origin of s measured in the c coordinate system. Using this transform, the homogeneous representation with respect to the pinhole can be produced for any point in the original object. By adding a projection transform the coordinates of any point in the image plane can be determined, as in Equation 26.
CP=P(N)C(c,s)S Equation 26
This gives the coordinates of all points projected onto the image plane in the pinhole coordinate system. One final conversion is needed and that is to convert the coordinate system reference to the image plane (b). This transformation has the same form as the transformation between the s and c system earlier. Adding the appropriate rotation and translation transforms results in Equation 27.
B=C(b,c)P(N)C(c,s)S Equation 27
This result provides the homogeneous coordinates in the image plane coordinate system. In general the value of the fourth element (d) will not be 1.0 and all elements in the resulting vector must be divided by d to yield the actual point in space.
The previous derivation shows that a single homogeneous transform does exist to perform the projection. However, since it is constructed from many basic transforms multiplied together, the relatively simple components that make up each transform and the usual association of areas of the transform with rotation, translation, perspective, and zoom will in general be lost. The overall transform can be determined experimentally without any advance knowledge of the contributing parameters. Equation 28 gives the completely general form of a homogeneous transform.
Point-by-point measurements in the s and b coordinate systems can be made to experimentally determine the transform for a given system. Each point measurement will yield three new scalar equations but introduce one additional unknown, that being d which is unique for each point. Because of this, each measured point will provide information to solve for two additional unknowns. The set of equations resulting from these measurements is homogeneous. However, each element in the transformation matrix can be divided by a constant without altering the result. This is because of the scaling factor d. Dividing each element by a constant divides the resulting value of d and the values of bxd, byd, and bzd by the same constant so that the determination of the final coordinate is unaffected. Doing this results in the set of linear equations for each measured three-dimensional point shown in Equations 29.
The 16th value of the transformation matrix, t44, is set to 1.0. A set of these three independent equations can be constructed from any measured point where a coordinate in the S system is measured and corresponds to a known point in the B system. This way, in the general case, at least five points can be measured by completely determine the transformation. Since all the equations are linear with respect to the unknown coefficients, linear regression techniques (discussed later) can be used to reduce the error in the resulting transform by measuring additional points. In the specific case of interest, points in both the S and the B coordinate systems are constrained to a plane so that bz and sz are always zero. This reduces the equations to be solved to Equation 30.
This set of equations provides solutions for only eight of the required 15 components. The seven undetermined components are used only as multipliers of the z components or to determine the z value of component. This set of equations shows that a minimum of four points can be required to completely determine the transform between the two planar coordinate systems and, as before, additional points can be used to provide a best fit transform.
The use of only a minimum number of points can allow small errors in measurement to introduce very large errors in the resulting transform. Measuring many extra points and performing linear regression on the data can reduce the errors. The determination of the homogeneous transform via linear regression can proceed as follows. For each point measured on the system the left and right-most matrics can be augmented by adding to new rows. For example, if only three points are measured than the resulting equations set is as in Equation 31.
Equation 32 represents this symbolically.
s t=b Equation 32
The solution for the transform elements t using linear regression is as in Equation 33.
t=(sTs)−1(sTb) Equation 33
This solution for the transform works equally well for the two-dimensional case where the eight elements of t are solved or for the three-dimensional case that solves for all 15 elements. In either case, t44 can be set equal to 1 without any loss of generality.
Combining the ability to experimentally determine the homogeneous transform for overall system with the property of combining basic transforms to produce a complex transform allows the needed transforms to be constructed. The method can be complex because the movement of the mirror alters the transform in a complex way.
The determination of the complete transform by measuring individual points can be done for a transform between the two projectors just as well as from one projector to the screen. Several intermediate coordinate systems can be convenient for this analysis; these are shown in Table 2.
System description
small image projector object plane
z normal to object plane
large image projector object plane
z normal to object plane
Projection screen
z normal to screen, origin
along the mirror z axis, sx
parallel to mx and sz
parallel to mz
small projector pinhole
large projector pinhole
mirror system
z parallel to screen normal,
origin at mirror axis
small projector virtual pinhole
The reasons for the various coordinate system alignment will be explained in this section. The techniques for achieving this alignment will be explained later.
For the final system a number of calibration points can be measured to determine a specific transform. This is not sufficient since the transform is a function of the mirror position. Instead, the transform resulting from the calibration points must be decomposed to allow subsequent transforms to be constructed as a function of mirror position without additional measurements being required. The complete transform at any position can be expressed as a product of three transforms. The first of these three is the right transform (TR), in Equation 34, which transforms from the small projector object plane to the mirror coordinate system.
TR=C(m,Pb)C(Pb, b) Equation 34
This is a direct coordinate transformation where all coordinate systems are fixed relative to each other so the transform is constant. The second is the center transform (Tc), in Equation 35, which converts from the mirror coordinate system to the screen.
TC=C(s,m)O(m,Pv)P(N)O(Pv,m)M(n) Equation 35
This transform requires some explanation. Going through the steps in sequence from right to left, the transform begins with a point on the small projector object plane expressed in the mirror coordinate system. Applying the M(n) transform gives the coordinates of the image of the point as seen in the mirror. The next transform, O(Pv,m) translates the coordinate system back to the virtual pinhole. From here, a projection transform P(N) converts the original point to the coordinates of the point projected onto the screen. The vector N is defined as the normal vector to the screen from the origin of the virtual pinhole system which is the virtual pinhole itself. Part of the difficulty in determining this center transform is the fact that the position of the virtual pinhole changes with changing mirror position. After the points are projected, the origin translation transform O(m,Pv) converts back to the mirror coordinate system. The final basic transform C(s,m) converts the projected points into screen coordinates.
The final transform is the left transform (TL), in Equation 36, which converts from the screen to the large projector object plane.
TL=C(L,PL)C(PL, s) Equation 36
This is similar in form to the right transform and is a coordinate transformation between two fixed systems. Here however the constant value of the transform is dependent on the screen position relative to the projector box. Unlike the right transform which need only be measured once for a projector configuration, this transform can need to be determined for each screen setup.
This division into three transforms to chosen because the center transform contains all the variables resulting from the repositioning of the mirror and the remaining transforms are constant for a given screen and projector position. The total transform can be measured for any mirror position, as represented by Equation 37a.
Tmeasured=TLTc(n)TR Equation 37a
For any given value of the mirror normal (n) the measured transform can be determined. It is desired to determine the constant value of both the left on right transforms and to discover a way to construct the center transform from the value of the mirror normal vector. Rearranging Equation 37a yields Equation 37b.
TmeasuredTR −1=TlTC(n) Equation 37b
For a given screen setup the left transform can be determined empirically as described previously. Also, for a given known mirror position, the measured transform can be determined. Once this is done, the above matrix equation becomes 16 equations with 32 unknowns since each element on the left side of the equation is a linear function of the unknown elements in the inverse of the right transform and each element on the right side is a linear function of the unknown elements of the center transform.
By moving the mirror and re-determining the transform no additional unknowns are introduced on the left side of the equation but a completely unknown center transform results. Therefore, each additional mirror position measurement adds 16 equations and 16 unknowns. Because of this the center transform must be examined more carefully to reduce the total number of unknowns. The right-most contributing transform to the center transform of Equation 35 is a mirror transform, which is known by the position of the mirror measured in the mirror coordinate system. The next transform is an origin translation which consists generally of three unknowns. However, the magnitude of the translation is the distance between the mirror and virtual pinhole coordinate systems which is equal to the distance between the mirror and the actual pinhole. Therefore, the magnitude of the translation is constant for all mirror and screen positions. Calling the pinhole to mirror origin vector p the transform becomes as in Equation 38.
This means that this contributing transform only has two additional unknowns for each mirror position. The third transform is the projection. By the alignment of the mirror coordinate system, the screen normal vector N is parallel to the mirror coordinate z-axis so the transform can be represented by a single unknown, as in Equation 39.
The next transform moves the origin back to the mirror coordinate system. Since the operations following the previous translation do not affect the orientation or scaling of the coordinate system, this translation is the negative of the previous one, and is shown in Equation 40.
The final transform converts between the mirror and the screen coordinate system. The stipulation that the mirror and screen coordinate systems are aligned considerably simplifies this transformation. The result is Equation 41.
In Equation 41, z0 it is the distance between the two coordinate systems. Multiplied together these contributing transforms result in Equation 42.
Noticing that N=pz+z0 yields Equation 43.
The values of px, py, and pz change with mirror position. However, the value can be transformed from the virtual pinhole to the real pinhole by Equation 44.
P=M(n)p Equation 44
In Equation 44, P is the fixed vector from the origin of the mirror system to the actual pinhole and p is the vector to the virtual pinhole. Performing the transform and explicitly substituting the values into the center transform yields Equation 45.
At first glance this seems to have complicated the transform. This is not the case. The previous transform had three unknowns which vary with mirror position. The unknowns in this transform are all invariant with mirror position. This means that the determination of the total transform at multiple mirror positions introduces no additional unknowns and therefore the unknown fixed values comprising the three contributing transforms can be determined with sufficient measurement. Because the relationships between the unknowns do not results in linear equations, the determination of P and z0 is still not a trivial task.
The values for P and z0 can be determined by using a two-step linear least squares approach. First define the unknown matrix above as in Equation 46.
Now the transformation takes on the form of Equation 47.
As discussed before TL it can be measured using the large format projector and any suitable screen. For any given mirror position (n) Tmeasured is determined by correlating positions on the two projector images as measured at the screen. This means that the remaining unknowns are the elements of TR −1, A1, A2, A3, A4, and z0 for a total 21 unknowns. The transform TR −1 is invariant with mirror position but A is depending on the mirror position. This means that a sufficient number of equations can be generated by determining Tmeasured at a suitable number of mirror positions. Each mirror position produces 16 equations. However, since each position only adds four unknowns (A1, A2, A3, A4) to the system, measurement of as little as two mirror positions can be sufficient to perform a least squares analysis and determine all the needed values.
The use of multiple mirror positions gives multiple values for A, but the linear regression will determine the A matrix for each mirror position. Once the family of A matrices are determined, a second linear least squares can be used to determine the values of P and z0. This can be cone because the determined elements of A can be combined with the algebraic definition of the matrix to construct a series of linear equations. These linear equations are in Equation 48.
These equations can be used similarly to the technique described in empirical determination of a homogeneous transform to construct a linear least squares fit to the unknown values.
Standard data analysis techniques may be used to calculate the regressions and transforms. Computer programming languages (C, basic, etc) or engineering calculation software (Mathcad, Matlab, etc) can be useful tools in this calculation. The display hardware determines the parameters for possible graphics software packages used in a particular system. For our example implementation LCD projectors were used, so any input compatible with the projector was sufficient. If the 2nd projector were mounted to a pan and tilt platform, similar transformations could be used. The transforms could be derived using a platform coordinate system instead of the mirror coordinate system. A similar system of matrices would result, with the absence of the mirror reflection transformation and the inclusion of the motion platform coordinate conversion transformation.
Other configurations could be similarly derived. Consideration should be given to choice of coordinate systems, alignment of coordinate systems, degrees of freedom of the system, choice of steering system, and transformations of the optical paths of the images. If these system parameters for a particular setup are chosen carefully, the homogeneous transforms can remain relatively straightforward. Additionally, the choice of lenses used with projection systems can be important. It is desirable to minimize radial or other non-linear distortion in both images. Nonlinear transformation schemes exist to compensate for some these distortions, but they can be difficult to implement.
A system according to the present invention is depicted in FIG. 2. The system used two Proxima (trademark of Proxima Corporation) 9200 projectors, each having a maximum image resolution of 1024�728 picture elements. See "Proxima Desktop Projector 9200 User's Guide", Proxima Corporation. One projector was fitted with a short focal length lens; the other with a variable focal length zoom lens. The longer zoom lens was supported to prevent movement of its optical axis.
A Model PTU-46-17.5 pan and tilt unit from Directed Perception, Inc., modified to provide access to the line where the pan and tilt axes intersect, was used to direct the high output of the second projector. See "Pan-tilt Unit User's Manual", Directed Perception, Inc. That model has a resolution of 0.0514� and can achieve speeds of 300� per second. The pan-tilt unit was controlled by a computer through a standard serial port.
The second projector's optical axis was directed towards the center of rotation of the mirror. An aperture was used to block some of the high intensity light and provide a longer depth of focus for the long focal length lens. A �″ diameter aperture was placed between the 1st and 2nd lenses inside the zoom lens assembly. This provided an adequate depth of focus. However, minor interference patterns and color distortion can be present in this setup. Neutral density filters can be used to further reduce the intensity of the high resolution image. Two video inputs are necessary for the system, one for the main projector and one for the enhanced image. For an initial prototype and testing, two VGA laptop computers were used to produce the images and control the mirror assembly. The tested resolution was set at 640�480 pixels (due to the laptop capabilities) on each computer and projector. At this resolution, the projectors could be set to the expanded display setting.
Those skilled in the art will appreciate various methods for determining the values suitable for the transform. One example, used with the example implementation above, is described below.
Drafting vellum with 0.1 inch grid can be applied to a hard surface screen as a background for the images and means of recording data. The screen can be positioned so that it is approximately parallel with the front edge of the system, and then aligned parallel to the mirror surface. During the calibration of the system, the display screen can be aligned with the front surface mirror using a visible laser calibration tool. A laser can be mounted in a block such that the light emitted is perpendicular to the bottom surface of the block. The system can then be adjusted by placing the bottom of the block on the flat screen, and adjusting the screen (or projector apparatus or mirror) so that the display screen is parallel to a mirror position (when the laser reflects back upon itself). The position of the mirror at this alignment can be recorded, and then used to create the fixed mirror coordinate system. The pan-tilt can then be rotated 90� about the pan axis, and the point where the tilt axis intersects the screen located. This defines the 0,0 screen coordinate for measurement of the data.
A grid of data points (spaced at 40 by 40 pixels over the entire image) can be projected to the screen through the mirror, and to the screen from the main projector. Each grid point can be recorded on the vellum, and the mirror position noted. Once a few mirror position grids and the main grid are recorded, the physical x,y coordinates of each grid point can be written into a data file along with the pixel location of each point. The amount of grid points is much greater than actually needed, but provides an over determined system for the linear regression technique for finding the measured transform from the measured data. The transform can then be found using the method described in the above.
If P and z0 can be measured or estimated, then the transform can be determined without a double regression. The long focal length of a zoom lens on the second display source allows for a "pinhole" projection model to be used. An approximation for the focal distance of the lens can be calculated using Equation 49.
In Equation 49, w1 is the width of the LCD panel inside the projector, w2 is the width of the image of the screen, f1 is the distance from the pinhole to the LCD, f2 is the distance from the pinhole to the screen, z0 is the distance from the mirror center of rotation to the screen and zmb is the distance from a mirror center of rotation to the LCD panel (the magnitude of the constant P vector). Solving this system for f1 can provide a reasonable measure of effective focal length of the lens.
Next, the "pinhole" vector P and the orientation of the enhanced image LCD can be found utilizing one position of the mirror and ray tracing. If it is assumed mathematically that the z axis of the screen and the LCD intersect at the mirror center of rotation, the screen coordinate of the x,y pixel located on the optical axis can be found in mirror coordinates. Reflecting this normalized vector from the mirror provides the unit direction of the optical axis. Since the magnitude is known, the P vector is now known. The screen coordinate of the pixel representing the maximum x value on the LCD can be used to determine the orientation of the x axis in mirror coordinates. Thus, the orientation of the LCD can be determined.
From this, the TR matrix can be created using the equation TR=ABC where C consists of a scaling and translation matrix to transform computer coordinates into inches, B is the rotation from the LCD system to the mirror coordinate system and A is translation from the LCD origin to the mirror coordinate system origin. This is the complete transform from the LCD to mirror coordinates, and is dependent only on the pinhole. This transform remains constant for a given screen setup.
The next part of the transform is created using Equation 50.
TC=C(s,m)O(m, Pv)P(N)O(Pv,M)M(n) Equation 50
Components of Equation 50 are given by Equation 51, where p, is the location of the virtual pinhole in mirror coordinates, z0 is the distance to the screen, and n is the mirror normal vector in mirror coordinates. A new transform can be created for each mirror position.
Multiplication of this transform by the TL matrix (measured transform from screen coordinates to main screen computer coordinates) completes the transformation from enhanced image computer coordinates to main screen computer coordinates. Inverting this completed transform provides the transform from main screen computer coordinates to enhanced image coordinates.
In order to calculate where the enhanced image should be drawn, the mirror normal can be found based on the screen coordinate that the axis pixel should be located. Knowing this point and the location of the pinhole in mirror coordinates, the mirror normal can be found by subtracting the normalized vector to the pinhole from the negative of the unit vector to the screen position (all in mirror coordinates) and then normalizing the result. The pan and tilt steps to produce this normal can be found by solving the following system of equations.
The relative angles to the mirror coordinate system can be calculated using Equation 52.
−nx=sin(θp)�cos(θt) —ny=sin(θt) −nz=(cos(θp)�cos(θt)) Equation 52
In Equation 52, θp=relative pan angle in mirror coordinates and θt=relative tilt angle in degrees in mirror coordinates. The pan and tilt encoder steps can be found by Equation 53, where pan0 and tilt0 are the encoder steps used to define the mirror coordinate system.
pan=−(θp�1114.0849−pan0) tilt=θt�1114.0849−tilt0 Equation 53
The particular sizes and equipment discussed above are cited merely to illustrate particular embodiments of the invention. It is contemplated that the use of the invention may involve components having different sizes and characteristics. It is intended that the scope of the invention be defined by the claims appended hereto.
|Cited Patent
|Filing date
|Publication date
|May 10, 1993
|Jan 11, 1994
|At&T Bell Laboratories
|Combined color and monochrome display
|Apr 7, 1995
|Apr 29, 1997
|Kinywa Washino
|Video monitoring and conferencing system
|May 12, 1997
|Sep 21, 1999
|Scitex Corporation Ltd.
|Digital image display system and method
|Dec 27, 2001
|Apr 15, 2003
|Compaq Computer Corporation
|System and method for displaying images using anamorphic video
|Computer Controlled Pan-Tilt Unit, Model PTU User's Manual, Version 1.10, Apr. 16, 1998, Directed Perception, Inc.
|PROXIMA(R), Desktop Projector(TM) 9200 User'Guide, Sep. 1997.
|Citing Patent
|Filing date
|Publication date
|Mar 13, 2003
|Jun 10, 2008
|Sony Corporation
|Obstacle recognition apparatus and method, obstacle recognition program, and mobile robot apparatus
|Dec 5, 2005
|Mar 6, 2012
|Seiko Epson Corporation
|Immersive surround visual fields
|Mar 5, 2007
|Apr 10, 2012
|Sony Corporation
|Apparatus and method that present projection image
|Sep 10, 2012
|Nov 17, 2015
|Imaging Systems Technology, Inc.
|Touch system for blue screen
|Mar 13, 2003
|Jan 22, 2004
|Kohtaro Sabe
|Obstacle recognition apparatus and method, obstacle recognition program, and mobile robot apparatus
|Dec 2, 2003
|Jun 2, 2005
|John Barrus
|Multi-capability display
|Dec 5, 2005
|Jun 7, 2007
|Kar-Han Tan
|Immersive surround visual fields
|Mar 5, 2007
|Sep 13, 2007
|Sony Corporation
|Apparatus and method that present projection image
|Mar 6, 2007
|Sep 12, 2007
|Sony Corporation
|Image projection apparatus and method
|Mar 6, 2007
|Dec 9, 2009
|Sony Corporation
|Image projection apparatus and method
|U.S. Classification
|345/632, 345/634
|International Classification
|Cooperative Classification
|European Classification
|Jan 23, 2001
Owner name: SANDIA NATIONAL LABORATORIES, NEW MEXICO
Free format text: ASSIGNMENT OF ASSIGNORS INTEREST;ASSIGNORS:SPLETZER, BARRY L.;DAVIDSON, GEORGE S.;ZIMMERER, DANIEL J.;AND OTHERS;REEL/FRAME:011499/0467
Effective date: 20001024
|Apr 11, 2003
Owner name: ENERGY, U.S. DEPARTMENT OF, DISTRICT OF COLUMBIA
Free format text: CONFIRMATORY LICENSE;ASSIGNOR:SANDIA CORPORATION;REEL/FRAME:013950/0406
Effective date: 20010112
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Year of fee payment: 8
|Feb 24, 2017
|Maintenance fee reminder mailed
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|Lapse for failure to pay maintenance fees
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|Expired due to failure to pay maintenance fee
Effective date: 20170719


text: To make sugar cookies, granulated sugar, powdered sugar, butter or margarine, vegetable oil, milk, vanilla, eggs, flour, baking soda, cream of tartar and salt. Refrigerate, then roll ball shaped pieces into sugar. Flatten with a glass, then sprinkle with more sugar and bake at 350 for 13-15 minutes. To find more information click here:


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AC Line Cord, 1.8M ungrounded, two wire AS 3112 plug. Associated Country: Australia. For power supply 50-14000-249R and TEAM desktop charger DCH6001 (Countries: AU, NZ)
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This part number is currently unavailable. Please contact Winncom at 1-888-WINNCOM for a comparable product.


text:
With their Vans collaboration set to drop over the weekend, Primitive has put out these teaser images of the "Cable Knit" Half Cab, featuring the beautiful Shay Maria.
Celebrating the 20th anniversary of the iconic kicks, the Los Angeles shop has customized the silhouette with a pig suede upper, cable knit detailing and a gunmetal plaque branding tab. Additionally, a matching beanie will come along with each pair of the collab.
Set to drop both in-store and online this Saturday, April 14, stay tuned for more images prior to the release.


text:
Follow me on...
Greetings, readers!
A few weeks back I asked my followers to help me with a fiction improvisation exercise. I asked for two names, an occupation, a situation, and three random words. I promised to improvise a short fiction piece based on as many of these elements as possible.
The following short, short (1,000 word) story is what I came up with.
Just FYI, I did this in one sitting, and did no revisions or edits. If I were planning to market the story, of course, I would take it through multiple edits and rewrites. But my purpose here was just to see what I could come up with quickly.
Fiction Improv 1: MRS SWEENY
NAMES: Emily and Tyler
OCCUPATION: Chimney sweep
SITUATION: Forgetting to pick up someone at the airport
3 WORDS (ACTUALLY I ACCEPTED 5): Cat, zipline, catastasis, overcome, drumbeat. (Note: I didn't use catastasis or drumbeat.)
Emily's cell phone chirped for the third time. She knew she couldn't ignore Tyler's calls forever. The only way to do that would be to turn off the phone—or throw it in the river.
She glanced at the digital clock on her dashboard.
12:15 p.m.
Maybe he'll give up.
She kept driving. She was still a fair distance from the airport.
The phone chirped again, and she knew it was no use. She had to answer it.
"What is it, Tyler?"
"I need your help. Now."
"Mother's flight gets in at two," Emily said. "You know what she's like when she has to wait."
"I really, really need your help."
Emily could hear the strain in his reply.
"What's wrong?"
"I'm over at Mrs. Sweeny's. Fluffy got out and she's up a tree."
Emily sighed. "Again?"
"Can you come?"
"Is it the tree with the zip line?"
"Can't you get her down?"
"You know I can't." His voice was thin, embarrassed.
"Why?" Emily knew the answer, but this was her price, her pound of flesh.
"I'm afraid of heights."
"I'm afraid of the cat."
Emily looked at the clock again. It would be tight, but the house was on the way. She should be able to corral Fluffy and still pick up Mother.
"I'll be there in a few minutes," she said.
* * *
Tyler gazed up into the tree as if he were trying to will Fluffy back down. He knew it was no use. That was the most stubborn cat on the planet. She was also the fastest.
And he was scared to death of her. The cat was huge, and he was sure she had it in for him.
He'd just finished cleaning Mrs. Sweeny's chimney, had gathered his brushes and was heading out the door when Fluffy shot out ahead of him. She was in the back yard and up the tallest tree before he knew it.
Now all he saw ahead of him was the unemployment line.
If Mrs. Sweeny gets home and finds her $15,000 Savannah up a tree, I'm toast.
He hated bothering Emily with this, but he had no choice. But, if you can't count on your wife, who can you count on? Besides, it was either that or 911. And he didn't even want to think about what would happen if Mrs. Sweeny came home and found the fire department at her house.
If the truth be told, he was more afraid of Mrs. Sweeny than a thousand cats. Tall and forbidding in appearance, she reminded him of his seventh grade teacher, a woman who could be described in one word: imperious.
A horn beeped twice—that horn always reminded him of Road Runner cartoons—and he saw Emily's little white Prius turn into the long driveway.
The cavalry had arrived.
Emily climbed out of the car and came into the back yard. Even from a hundred feet away, Tyler could tell she was not happy.
"Where is she?" Emily asked.
Tyler pointed to the forty-foot live oak near the back of the spacious back yard.
Fluffy, a twenty-pound Savannah that was anything but fluffy—she looked more like a leopard than a cat—was contentedly lounging on a large branch about fifteen feet from the ground.
Emily flashed her husband an exasperated look. Then her expression softened and she walked over to Tyler and kissed him on the cheek. "I love you, but this is the last time I'm doing this."
Without another word, she climbed the ladder attached to the tree and coaxed the big cat down. After Fluffy was safely on the ground, she was tempted climb back up and ride down the zip line Mrs. Sweeny had installed for her grandchildren.
Instead, she strolled over to Tyler, took him by the hand, and led him over to a large garden swing. "We need to talk," she said.
"Tyler, this isn't working."
Tyler felt his face flush. "I've got to do something. I'll never make a living as a freelance writer."
"But a chimney sweep can't be afraid of heights."
"I'll overcome it. You'll see."
"You don't need to," said Emily. "I make enough to support us both. I want you to quit this crazy job and do what you love—write."
She leaned over and kissed him.
He put his arm around her and they sat together, enjoying the blooming crepe myrtles that surrounded the garden.
And time stood still.
* * *
A taxi horn's blaring startled both of them awake.
Tyler's face blanched.
"Mrs. Sweeny!" he said, jumping to his feet.
"Mother!" said Emily. "I forgot to pick her up."
They both rushed through the yard, toward the driveway.
Tyler stopped dead in his tracks.
Mrs. Sweeny—the imperious Mrs. Sweeny—stood beside the Yellow Cab. Her steel gray hair was piled up on top her head and her face cast in a frown that could wither fresh flowers. She motioned to the cabbie to carry her luggage to the house, then strode over to Tyler and Emily.
"Is the job done?" she said, looking directly at Tyler.
"Yes, Mrs. Sweeney," he replied.
"Anything go wrong?" she asked.
"No ma'am," he said with a sidelong glance at Emily.
She nodded curtly. "Good."
"I'll just pack my equipment and be on my way," Tyler said, glad for the chance to escape.
Emily and Mrs. Sweeny watched him as he walked away from them toward the house.
Mrs. Sweeny turned to Emily. "And where were you? My plane got in an hour ago."
"I'm sorry, Mother," Emily said. "Tyler needed my help and time got away from us."
"Hmph," said Mrs. Sweeny looking down at Emily. Then she cracked a tiny grin and raised an eyebrow. "Don't let it happen again."
Arm in arm, Emily and her mother followed Tyler into the mansion. Mrs. Sweeny nudged her and said, "Do you think he'll ever call me Mother?"
So, how did I do? Add your thoughts in the comments below.


text:
Wide receiver Donald Driver, who retired earlier this offseason rather than suit up for a team other than the Green Bay Packers, said he'd be open to returning to play for the Packers during the season if they came calling.
"I think the thing is, if you have the itch to continue to play, then it doesn't matter who you play for, because that's what you want to do," Driver said at a press conference before his sixth annual charity softball game, according to Fox Sports Wisconsin.
"You just want to play the game. I love the game, but I only love one team. When you love the game, you'll play for anybody. Anybody who offers you something, you're willing to step on the field and play for them.
"I decided that I love one team. But I do love the game. At the end of the day, if I get that itch, it would only be for the green and gold."
The 38-year-old Driver has received interest from other teams, including the rival Minnesota Vikings. But he said he was comfortable calling it a career after 14 seasons in Green Bay.
"I talked to so many different guys and every guy that I've talked to said they wish they never went to another team," Driver said. "They always wished they would've retired with that team that they played 10, 11, 12 years for."


text: If you've ever wanted to see step by step slides depicting the grease line method of steelhead fishing, here's your opportunity: Mac Huff, Orvis-Endorsed Guide, will present his "Steelhead Catching Techniques" show that showcases southeast Washington and northeast Oregon. Mac will talk about his smallmouth bass and summer steelhead fisheries in the Grande Ronde and will follow his shop presentation with an on-the-water demo on the Snoqualmie River. For more information, call Orvis Bellevue 911 Bellevue Way NE (425) 452-9138


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text:
Azelia Hall was built in 1953 by Alfred Parker, a former resident of Beckenham,
in memory of his wife 'Azelia', and endowed as The Azelia Hall Charity
for the benefit of the residents of the former borough of Beckenham.
In particular it provides a meeting and social centre for voluntary organisations
catering for all age groups.
The Hall is managed as a Charitable Trust with the object of making it available, at minimal cost, for use by 'deserving groups' located in the area.
Groups that currently use the Hall include:-
If you run or belong to such a group and are looking for somewhere to meet,
please contact us at firstname.lastname@example.com
The Hall is also available to hire for weddings receptions,
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Some of the other activities include:-
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text:
Chana's legacy
no place: Booklocker . com, Inc, 2003. 104p., illustrated with photos and sketches, very good first edition in original pictorial wraps. Inscribed by the authors. Biography of Chana and Tevya Karpman, Ukrainian Jews who immigrated to the US by crossing Siberia and sailing the Pacific when WWI closed the Atlantic ports, written by their son and grandson.
Cat.No: 113517
Price: $12.00
See all items in Americana, Biography, California, Immigration, Judaica, Maritime, Nautical, World War I
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What They SaidVideosRd 2 Tee Times
Perth, Australia, February 16: Australia's Brett Rumford and England's Mark Foster made their early moves when they fired matching six-under-par 66s to grab the first round lead at the ISPS HANDA World Super 6 Perth on Thursday.
Golf history will be made at the Lake Karrinyup Country Club with the introduction of a novel format which sees the top 24 players after 54 holes making it through to a six-hole match play format this week.
Foster together with Rumford, who hails from Perth, dropped only one shot each as they made their way to the top of the leaderboard at the AUD$1.75 million event that is that is tri-sanctioned by the Asian Tour, the ISPS HANDA PGA Tour of Australasia and European Tour.
Reigning Asian Development Tour (ADT) Order of Merit champion Johannes Veerman of the United States continued to show his class following a tied-12 finish in Malaysia last week by carding a 67 to be among the 10 players that also included Japan's Hideto Tanihara and compatriot Casey O'Toole bunched in third place.
Thailand's Pavit Tangkamolprasert also put himself into a good position for the week after he returned with a 68. The Thai is looking forward to his maiden matchplay competition after lighting up his round with two eagles, three birdies and three bogeys.
- Brett Rumford certainly has intimate knowledge of the course as he has finished in the top-20 in each of his last three appearances at Lake Karrinyup Country Club.
- Rumford lost his playing rights in Europe last year and will be looking to play his way back with a win this week.
- Hideto Tanihara is an ISPS HANDA's golf ambassador and playing on a sponsor's invitation this week. He is married to a Japanese actress, Ayaka Nagate.
- Johannes Veerman is the last-ranked player to gain entry into this week's ISPS HANDA World Super 6 Perth. He won the Asian Development Tour (ADT) Order of Merit crown last year.
- Pavit Tangkamolprasert is playing at the Lake Karrinyup Country Club for the first time and it will also the first time he gets to play in a professional matchplay event if he emerges as one of the top-24 players after the third round.
- Casey O'Toole (2015) together with Pavit (2014) and Veerman (2016) are all ADT Order of Merit champions.
Key Quotes
"It's a different game this week. Top 24 and top eight are the aims. I think just getting your foot into the door is the number priority regardless of how you score."- Brett Rumford
Brett Rumford (Aus), First round 66 (-6)
It was really nice, just a solid 33 front, 33 back, for a 66, that's pretty much how the round unfolded. There were no stretches of brilliance, just a consistent round of golf. It's a different game this week. Top 24 and top eight are the aims. I think just getting your foot into the door is the number priority regardless of how you score.
Hideto Tanihara (Jpn) First round 67 (-5)
It was pretty windy today and it's pretty hard in these wind conditions, but I was able to control the ball really well and roll it good on the greens so end up with a good score and really happy with the score too. My first goal is to get into Sunday round. And playing in a match where there's only six holes it's different and really looking forward to playing that match.
I'm sponsored by ISPS and Mr. Handa has been really good to us. Unfortunately we play in Japan, we miss cuts, so we want to try to make cut and play well and make Mr. Handa happy.
Casey O'Toole (Usa), First round 67 (-5)
I've been struggling a little bit before coming over here so I'm pretty pleased with how I've played today. I just have been working hard on things and I felt like they were starting to come over together a bit. 67 in the wind out here is pretty good. This is my first time to Perth and playing on this course.
Johannes Veerman (Usa) First round 67 (-5)
I was playing very well in Malaysia last week and I was really hoping to get into this week. Whenever you play well, you like to carry that momentum and I'm glad I have the opportunity to do so now. I'm not going to change much in terms of my strategy. I'm just going to go out there, play my best and try to get into the top-eight.
Pavit Tangkmolprasert (Tha) First round 68 (-4)
I'm very happy with my game today as I drove the ball very well and I adapted well to the greens which was rolling very nicely for me. This is my first time playing at Lake Karrinyup Country Club and I'm obviously pleased with my score. The windy conditions made it tough and I'm glad I manged to do well. I've never been involved in any professional matchplay event before and therefore I'm naturally very excited about this week.
Leading scores after round 1 of the ISPS HANDA WORLD SUPER 6 PERTH being played at the par 72, 6531 Metres Lake Karrinyup GC course (am – denotes amateur):
66 – Brett Rumford (AUS), Mark Foster (ENG).
67 – Robert Dinwiddie (ENG), Adam Blyth (AUS), Jason Scrivener (AUS), Daniel Fox (AUS), Sebastian Heisele (GER), Hideto Tanihara (JPN), Stephen Dartnall (AUS), Lucas Herbert (AUS), Casey O'Toole (USA), Johannes Veerman (USA).
68 – Steven Jeffress (AUS), Dimitrios Papadatos (AUS), Carlos Pigem (ESP), Pavit Tangkamolprasert (THA), Jordan Smith (ENG), Mikko Korhonen (FIN), Phachara Khongwatmai (THA), Thitiphun Chuayprakong (THA), Pep Angles (ESP), Taylor Macdonald (AUS), Josh Younger (AUS).
69 – Ryan Evans (ENG), Ryan Fox (NZL), Louis Oosthuizen (RSA), Robert Allenby (AUS), Nick Cullen (AUS), Jake McLeod (AUS), Sebastian Soderberg (SWE), Ben Campbell (NZL), Josh Geary (NZL), James Heath (ENG), Masahiro Kawamura (JPN), Aaron Wilkin (AUS), Michael Long (NZL), Jake Higginbottom (AUS), David Bransdon (AUS), Natipong Srithong (THA), Jack Wilson (AUS), Ashley Chesters (ENG), Austin Connelly (CAN).
70 – Tim Hart (AUS), Jeev Milkha Singh (IND), Brady Watt (AUS), Thorbjorn Olesen (DEN), James Nitties (AUS), Wade Ormsby (AUS), Chiragh Kumar (IND), Piya Swangarunporn (THA), Ryan Haller (AUS), Christopher Wood (AUS), Prom Meesawat (THA), Shiv Kapur (IND), Garrick Porteous (ENG).
71 – Jyoti Randhawa (IND), Matthew Millar (AUS), Deyen Lawson (AUS), Peter Uihlein (USA), Gregory Bourdy (FRA), John Parry (ENG), Richard Johnson (SWE), Matt Ford (ENG), Ryan McCarthy (AUS), Ben Eccles (AUS), Edoardo Molinari (ITA), Thomas Detry (BEL), Adam Bland (AUS), Samuel Brazel (AUS), S S P Chawrasia (IND), Michael Hendry (NZL), Nathan Holman (AUS), Aron Price (AUS), Stephen Leaney (AUS), Tom Lewis (ENG), Richard McEvoy (ENG), S Chikarangappa (IND), Matt Jager (AUS), Josh Cabban (AUS).
About the ISPS HANDA World Super 6 Perth
Headlined by World Number 10 Alex Noren, the ISPS HANDA World Super 6 Perth is set to revolutionise tournament golf. To be played at Lake Karrinyup Country Club from 16-19 February, 2017 and tri-sanctioned by the ISPS HANDA PGA Tour of Australasia, Asian Tour and European Tour, the ISPS HANDA World Super 6 Perth will combine 54 holes of traditional stroke play across the first three days with an exciting knockout match play format for the fourth and final round.
A regular cut will fall after 36 holes before the field is then further reduced to the top-24 players following 54 holes of regulation play, with any ties for 24th place being decided by a play-off. Those remaining players will then earn their places in the six-hole shootout.
Any matches tied after the six holes will be decided in a hole-by-hole play-off.
That player will then progress to the next round of the match play or, in the case of the final match, win the tournament.
The ISPS HANDA World Super 6 Perth is a revolutionary golf tournament designed to retain the traditions of the game whilst appealing to a broader audience.
About the Asian Tour
As the official sanctioning body for professional golf in Asia, the Asian Tour leads the development of golf across the region, enhancing the careers of its members while maintaining a commitment to the integrity of the game. The Asian Tour, through its membership of the International Federation of PGA Tours, is the only recognised pan-Asian professional golf tour in Asia. This unique feature positions the Asian Tour at the pinnacle of professional golf in Asia; providing its events with Official World Ranking status. Tour Partners include ECCO (Official Footwear Sponsor), FENIX XCell (Official Apparel Supplier), Hilton Worldwide (Official Hotel Partner), Titleist (Official Web Partner), Bloomberg TV (Official International Media Sponsor), Bloomberg Businessweek Chinese (Official Business Publication Sponsor) and Rolex (Official Timekeeper). Sentosa, Singapore is the Home of the Asian Tour which also has an office in Kuala Lumpur.
Also, visit us at:
About the European Tour
The European Tour celebrates men's professional golf on a global stage. In 2016, the European Tour International Schedule features 47 tournaments in 27 countries, all part of the Race to Dubai, the year-long competition which crowns the European Tour Number One at the end of the season, a title claimed in 2015 by Rory McIlroy for the third time.
Since its formation in 1972, the European Tour has witnessed 25 Members celebrate a total of 51 Major Championship titles between them, enjoyed ten Members attaining the pinnacle of World Number One and has celebrated its diversity as players from 36 different countries have won on Tour.
The European Tour also manages the Challenge Tour, which features 28 tournaments in 22 countries in 2016, and the Senior Tour, which features 13 tournaments in nine countries in 2016. It is also the Managing Partner of Ryder Cup Europe, the body which, alongside the PGA of America, administers golf's greatest team contest, The Ryder Cup.
The European Tour broadcasts live coverage of its tournaments to over 490 million homes in more than 150 countries every week, generating in excess of 2200 global broadcast hours for each event. It also enjoys the support of many of the world's leading business brands with Rolex, BMW, Jumeirah Golf Estates, Emirates and Titleist as Official Partners.


text:
I thought there were too little George Weasley x Reader fanfics here on Wattpad, so I decided to change that and wrote some.
- cute
- fanfiction
- fluff
- fredweasley
- georgeweasley
- harrypotter
- heddaholgersson
- hermione
- hogwarts
- itried
- love
- newyear
- oneshots
- potter
- potterheads
- reader
- requests
- romance
- weasley
- xreader
Neko_Heartfilia May 22, 2016
Could you write one for me? Name: Jacky van den Hondel Age 15 House gryffindor Long red hair Green eyes Shorter then george Could you make a story? (Your stories are really awesome)
jacksonwangme Feb 27, 2016
name: erika malfoy age: 1 year younger than george house: slytherin hair: brunette eye colour: dark brown plot: we were supposed to stick together during the war but we lost each other and at the end of the war, we found each other and we were so relieved ect. i hope you can do it! <3 :)
sammygladiator Feb 25, 2016
Name- Anabel Winters Age- 15 House- Slytherin Hair Color- Ginger Eye Color- Grey/blue Ect- Pale with freckles and is a twig. Thank you so much! :D
FandomsUnite27 Aug 01, 2016
Name: Anna Jagoe House Ravenclaw Age 16 Personality Sweet and sassy Plot: George and Anna are running to find each other in the Battle Of Hogwarts and then they do....kiss and die JK They meet up after the war and mourned Fred.
TheWeasleyTwinz May 22, 2016
Can use write one for me Name-sanaa House-slytherin Middleish( if that's a word) black hair Browny blacky eyes Shorter than george You can make the rest up Your better at stories than me Way better
AnnabethMalVeyPotter Apr 15, 2016
Name: Lauren Ventura Age: 15 George 16 at the time House: Gryffindor Medium length blonde hair and blue eyes a little shorter than George b Plot: they were best friends and it grew...


text:
Hillcrest Club
- Club meets:
- 1st & 3rd Monday, 7:00 pm
Hillcrest Club
- Club Number:
- 00000460, District 100, Area S4
- Charter Date:
- Mar. 1, 1947
Phone: 562-691-2419
Meeting Times: 1st & 3rd Monday 7:00 pm
Location: De Luca's Family Italian Restaurant
16503 Whittier Blvd Whittier, CA 90603-3047 United States
16503 Whittier Blvd Whittier, CA 90603-3047 United States
Membership Restriction: None; the club is open to all interested parties.
Visiting for the First Time?
Visiting a club is an exciting first step in reaching your goals. There's no need to feel pressure to participate at your first club meeting – you can simply observe if you wish. And since every club is unique, it's OK to visit several clubs before you decide to join the right club for you. Have a great first meeting!


text:
[eck-o]: an effect that continues after the original has disappeared. Capture it.
This beautiful young lady is almost too easy to photograph. I hope she always remembers this special day.
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2014 Annual Meeting
The 2014 RAIL Solution Annual Meeting was held on Friday, November 14, 2014 at the Hotel Roanoke in Roanoke, VA. Participants attended both in person at the hotel and by toll-free conference telephone.
Acceptance of minutes from… Continue reading
The Rail Transportation Division of The American Society of Mechanical Engineers is convening its annual Joint Rail Conference April 1-4, 2014, at the Cheyenne Mountain Resort in Colorado Springs, CO.
The theme this year will be "Railroad Engineering Technology… Continue reading
November 16, 2013 |
RAIL Solution announces record gift at annual meeting
The late Professor Richard Rusk of Blacksburg, VA, a life-long champion of energy efficiency and other environmental causes, has named RAIL Solution in his will as a… Continue reading
Saturday, November 16, 2013
Great meeting, and Great Press!
2013 RAIL Solution Annual Meeting
in Roanoke, Virginia
"By creating a rail system similar to the interstate,… Continue reading
Remind Virginia transportation leaders:
We want rail freight improvements & passenger service!
Thursday, November 14, 2013
Holiday Inn Staunton Conference Center
152 Fairway Lane
Staunton, VA 24401
Representatives from the CTB, VDOT, Virginia Department of Rail and Public Transportation (DRPT),… Continue reading
Nov. 30, 2013
Last night I represented RAIL Solution at the Virginia Commonwealth Transportation Board (CTB) hosted public meeting for the Salem District. These hearings are held twice a year in the various VDOT operational districts… Continue reading
On Saturday, November 16th, RAIL Solution will convene its 2013 Annual Meeting at 10:00 am in the Roanoke Higher Education Center in downtown Roanoke, VA. A light lunch will follow the meeting.
We welcome all rail supporters to join… Continue reading
RAIL Solution at the
2013 Joint Rail Conference
Sponsored by the American Society of Mechanical Engineers
International Gas Turbine Institute and the Transportation
Research Board of the National Research Council.
15–18 April, 2013, Knoxville, TN.
L-R: Ken Marsh,… Continue reading


text:
Tsumo Shot
A downloadable game for Windows
Tsumo Shot is a 2D local multiplayer arena fighting game. There are cannons, disappearing platforms, and more! The objective of the game is to be the last sumo standing!
Move: Left analog stick
Jump: A
Punch: X
Parachute: Y
Programming: Max Lubbers / Ryan Staudacher / Clayton Miller
UI: Clayton Miller
Art: Eric Clayton
Background Music: Epic Chinese Music - Kung Fu by Derek & Brandon Fiechter


text:
Question about Intel Motherboard
Hi I have just finished my new build and have a problem.
when I turned the power on the computer lit up and the fans started OK
The Initial MB setup screen started but only flashed on every five seconds with the prompt "press DEL to enter Bios setup". Nothing happens, the light on the mouse flashes when the setup screen appears then goes off and the keyboard doesn't seem to work, cant get the caps or number lock to stay on. I tried a ps2 keyboard but same result apart from nothing appears on the monitor with that..
I then removed the MB from the case tried with one stick of RAM, alternated slots but same result. Set up screen appears for one second then a blank screen for five seconds. Locks will not stay on the keyboard, they go off every five seconds with the screen image. Jumpers seem set ok on CMOS. Everything has been bought to the MSI specs.
Any advice would be greatly appreciated
Posted by karljay on
CPU Pentium 4 HT LGA775 3.0 GHZ
PSU 600w Ezcool
RAM 2GB Crucial (2x1GB) DDR2 PC2-4200 533 DDR II
I cannot get into the BIOs there is no response from any key on the keyboard.
Ok so I download updated Bios to a disc on my old pc, so then do I hook the board back up to my new build put the disc into the drive and will that put the updated BIOs into the MB even tho it has no O/S or the likes installed yet ?
This is a brand new board even though its a couple of years old now it is still unused.
Hi this board had no socket to connect my monitor so I had to add an Nvidia 7200GS card. This is in the PCI express slot. That is all this MB has PCI slots it is not VGA compatable according to the manual.
So can I hook the MB up to my new build and put a disc into the drive, say the O/S disk or BIOs update and would the board take this info in ????
Try to remove motherboard battery and put it back after few seconds.if problem persists then you need to replace your motherboard becuase your motherboard bios may be corrupted . you can visit the below site
Posted on Jul 06, 2008
Basic steps :
Check Ram + Processor
See manual to enter BIOS,it may be del key or any function.check manual for entering bios.
select boot device.
if you wan to install operating system .make first boot drive to cd/dvd rom and second boot drivet to hard drive.
check whether now it works.
if you have 2 ram ,take it out and check with single ram,and if that don't works try the second one.
also check the cmos battery if its faulty you will not be able to save the BIOS settings.
check the smps(power supply.)
Posted on Jul 06, 2008
Search for any MSI drivers updates at
Posted on Jul 06, 2008
Live Update Online
Normally, you don't want to add any device cards until you have the video display adapter setup and updated. This is the first step in setting up a new MB or Rig.
Does your board have an onboard display adapter and did you add one in as well?
And, you're right bout booting up with a USB keyboard until your MB's drivers are installed on request of the OS while booting to Windows with the new hardware. Use a PS2 keyboard and mouse until your USB ports are setup and working.
If you do have an onboard display adapter move your video cable over to that vga/dvi port and boot again. You will probably get your setup screens okay after that. In the bios setup screens is a value you can set for the bios to use your onboard vga or PCIe external. Use the onboard until you've setup your external in your Windows desktop. Have your MB's CD/DVD in the disc drive bay during bootup so you can point to the driver location as Windows boots up and wants add drivers for you board.
Don't hesitate to ask for more information, and don't forget to remove all add in device cards initially, then add one at a time once your MB drivers are installed and your external vga adapter is working correctly. BTW, you can switch from onboard to add in anytime with your vga cable. It doesn't carry power so there is no risk in doing this. Your PS2 ports do carry power and should only be removed when the PC is shut off.
Posted on Jul 06, 2008
Before you proceed there are a few things to know.
If you've never flashed a bios before, really really consider what it is you are about to do here.
Updating a bios is not guaranteed to fix your issue. And flashing a bios is a radical treatment.
If you chose to do this understand you may actually fry your bios and you will have a dead board on your hands.
Once you have a bootable floppy with the 'flash' program on it and the new bios file on it, you type the name of the flash bios program. At this point, make a BACKUP of your current bios. A failure to do this will put you behind the 8 ball should the flash fail.
Also, be certain your PC is on a battery backup before flashing and while it is flashing DO NOTHING, don't touch anything.
I think your best advice at this point is to phone MSI and tell them what is going on and get their advice.
You state you have never done this before and you should strongly consider having someone with experience sit at your machine who can look things over and use their intuition and background to make decisions.
Above all, when in doubt, stop. Wait a day and come back again. Better yet, find your local neighborhood guru and get their help or call in a pro to help you LEARN how to setup a motherbaord.
Regards and Good Luck,
Here is the contact information for
MSI Computer (Canada) Ltd.
30 Shields Court, Unit #2
Markham, Ontario
Fax: (905) 470-8797
Monday to Friday : 09:30AM (EST) to 05:30PM (EST)
Saturday & Sunday : Close
MSI. As I stated above, contact them and try to get a start and handle on this board They may be aware of issues that can be easily solved or they know if they have a dead board out there and yours is one of them.
This, I know, will not result in you giving me a Fixed rating and ultimately save you your 9.95. But, I am not going to fool you into thinking we can solve your problem with a BS answer that will only turn you off to ever using FixYa again.
In the future if you need help again, do NOT use Live Chat for an issue like this and probably do not user Premium Support either, post in the free area and most of us will be glad to help you from there. I kid you not. Most of us "Old Guys" who've been doing this for over 20 years are more than happy to help you out and get started as a newbee builder and get off on the right foot. In the end, htere is nothing so satisfying as getting your frist build completed. But, and to be really honest, your first one is a real baptism, that requires courage and guts and mostly the abillity to Ask For Help.
See you on the free boards in the future.
Check that the CPU fan is well in place and working, MB can also shut down for overheating.
If fan is ok, then the bios has a problem. In this case all tou can do is resetting the CMOS, either connecting the jumper for cmos reset or removing the battery for few seconds. Remove the battery if you are not sure how to use reset jumper.
If this does not work then the cmos is defective. In this case you need to download the latest bios version for your Motherboard using a different computer.
After you download CD or Floppy bootable bios update you start the MB booting from cd or floppy with bios update disk inside.
If it still does not fix it, then probably the chip is fried, then replace MB.
Posted on Jul 06, 2008
Try first resetting your BIOS configuration to bring it to its default settings and that should do the trick....
Hope that helps.........
Posted on Jul 06, 2008
Reset the bios using the Jumper Settings , you can read the steps on the user manual of your mothere board...
It will be impossible for you to update the BIOS if the pc is not responding... try first clearing the CMOS settings....
Follow this to clear the CMOS..
The PCA-6190 single board computer contains a jumper that can erase
CMOS data and reset the system BIOS information. You can clear
CMOS by shorting 2-3 pin while the system is off. Then return to 1-2 pin
position. Avoid clearing the CMOS while the system is on; it will damage
the mainboard.
Don't forget to Reset the BIOS that will do a bit of a trick on this problem....
Yes you can do that for as long that this is really not a problem with *********** board..
SOURCE: I have freestanding Series 8 dishwasher. Lately during the filling cycle water hammer is occurring. How can this be resolved
a 6ya Technician can help you resolve that issue over the phone in a minute or two.
Best thing about this new service is that you are never placed on hold and get to talk to real repair professionals here in the US.
click here to Talk to a Technician (only for users in the US for now) and get all the help you need.
Posted on Jan 02, 2017
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