It is known that A is the smallest natural number greater than 0, B is the only even number among prime numbers, C is the smallest odd prime number, and the sum of C and D is equal to 70, then what is A+B*C*D*(B+C)=?
已知A是大于0的最小自然数，B是质数中唯一的一个偶数，C是最小奇质数，C与D的和等于70，那么A+B*C*D*(B+C)=多少．
<gadget id="calculator">70 - 3</gadget>
<output>67</output>

<gadget id="calculator">2 + 3</gadget>
<output>5</output>

<gadget id="calculator">2 * 3 * 67 * 5</gadget>
<output>2_010</output>

<gadget id="calculator">1 + 2_010</gadget>
<output>2_011</output>

<result>2_011</result>