The sum of five consecutive natural numbers is 55, what is the least common multiple of the largest number and the smallest number among these five numbers.
五个连续自然数的和是55，这五个数中最大的数和最小数的最小公倍数是多少．
<gadget id="calculator">55 / 5</gadget>
<output>11</output>

<gadget id="calculator">11 + 2</gadget>
<output>13</output>

<gadget id="calculator">11 - 2</gadget>
<output>9</output>

<gadget id="calculator">13 * 9</gadget>
<output>117</output>

<result>117</result>