Suppose S=2+4+6+8+...+2N, where N is the smallest natural number that makes S>1000000, then what is the sum of the numbers of N.
设S=2+4+6+8+…+2N，式中N是使S＞1000000的最小自然数，那么N的数字之和是多少．
<gadget id="calculator">1 + 0 + 0 + 0</gadget>
<output>1</output>

<result>1</result>