The sequence of numbers 1, 2, 3, 4, 5, 6, ... is eliminated. The principle of elimination is: all numbers that can be written as the sum of 3 composite numbers are retained; all numbers that cannot be written as the sum of 3 composite numbers are eliminated. What is the 2004th number in this column after elimination?
对数列1、2、3、4、5、6、…进行淘汰，淘汰的原则是：凡能写成3个合数的和的数保留；凡不能写成3个合数的和的数淘汰．淘汰后这列数中第2004个数是多少．
<gadget id="calculator">2_004 + 13</gadget>
<output>2_017</output>

<result>2_017</result>