On weekends, 5 machines in the workshop broke down at the same time, and the repair time from the first machine to the fifth machine was 15, 8, 29, 7, and 10 minutes. Each machine will cause a loss of 5 yuan if it stops production for 1 minute. How to arrange repair sequence to minimize economic losses. How much is the least loss?
双休日，车间内有5台机器同时出了故障，从第一台到第五台的修复时间依次为15、8、29、7、10分钟．每台机器停产1分钟都将造成5元钱的损失．如何安排修复顺序，使经济损失最少．最少损失多少元？
<gadget id="calculator">7 + 8</gadget>
<output>15</output>

<gadget id="calculator">7 + 8 + 10</gadget>
<output>25</output>

<gadget id="calculator">7 + 8 + 10 + 15</gadget>
<output>40</output>

<gadget id="calculator">7 + 8 + 10 + 15 + 29</gadget>
<output>69</output>

<gadget id="calculator">7 + 15 + 25 + 40 + 69</gadget>
<output>156</output>

<gadget id="calculator">156 * 5</gadget>
<output>780</output>

<result>780</result>