Now there are three piles of chess pieces, A, B, and C, with a total of 98 pieces. First divide the chess pieces from pile A to the other two piles, so that the number of chess pieces in the two piles is doubled, and then distribute the chess pieces in pile B in the same way. Finally, the C pile of chess pieces is also distributed in the same way. As a result, the number of chess pieces in pile A is (4/5) the number of moped pieces in pile C, and the number of chess pieces in pile B is 1 (7/15) of the number of chess pieces in pile C. What is the original maximum pile of chess pieces in the three piles? (requires explanation of process)
今有甲、乙、丙三堆棋子共98枚．先从甲堆中分棋子给另外两堆，使两堆棋子数各增加一倍，再把乙堆棋子照这样分配一次．最后把丙堆棋子也这样分配．结果甲堆棋子数是丙堆摸子数的(4/5)，乙堆棋子数是丙堆棋子数的1(7/15)．问三堆中原来最多一堆的棋子是多少？(要求说明过程)
<gadget id="calculator">26 / 49</gadget>
<output>26/49 = around 0.530612</output>

<gadget id="calculator">98 * (26/49)</gadget>
<output>52</output>

<result>52</result>