There are 5 red, yellow, and blue balls in the pocket. At least how many balls must be drawn so that the sum of the balls of any two colors is greater than the number of balls of the third color.
口袋中有红、黄、蓝三种颜色的小球各5个，至少要摸出多少个球，才能使任意两种颜色的球数之和大于第三种颜色的球数．
<gadget id="calculator">5 + 1 + 5</gadget>
<output>11</output>

<result>11</result>