In the two-digit number 10, 11, ..., 98, 99, add a decimal point between the ones and tens digits of the remainder 2 when divided by 7, and keep the rest of the numbers unchanged. Question: After this change, what is the sum of all the numbers?
在两位数10，11，…，98，99中，将每个被7除余2的数的个位与十位之间添加一个小数点，其余的数不变．问：经过这样改变之后，所有数的和是多少？
<gadget id="calculator">10 + 99</gadget>
<output>109</output>

<gadget id="calculator">109 / 2</gadget>
<output>109/2 = around 54.5</output>

<gadget id="calculator">(109/2) * 90</gadget>
<output>4_905</output>

<gadget id="calculator">7 * 2</gadget>
<output>14</output>

<gadget id="calculator">7 * 13</gadget>
<output>91</output>

<gadget id="calculator">14 + 2 + 91 + 2</gadget>
<output>109</output>

<gadget id="calculator">12 / 2</gadget>
<output>6</output>

<gadget id="calculator">10 / 1</gadget>
<output>10</output>

<gadget id="calculator">9 / 10</gadget>
<output>9/10 = around 0.9</output>

<gadget id="calculator">109 * 6 * (9/10)</gadget>
<output>2_943/5 = around 588.6</output>

<gadget id="calculator">4_905 - (2_943/5)</gadget>
<output>21_582/5 = around 4_316.4</output>

<result>21_582/5 = around 4_316.4</result>