There are four family members in a family whose ages are different. The sum of their ages is 129 years, and the ages of three of them are square numbers. If you go back 15 years, the ages of three of these four people are still square numbers. , the age difference between the oldest and the youngest.
某个家庭有四名家庭成员，他们的年龄各不相同，他们的年龄总和是129岁，而其中有三个人的年龄是平方数，若倒退15年，这四人中仍有三人的年龄是平方数，则年龄最大的与最小的相差多少岁．
<gadget id="calculator">64 - 16</gadget>
<output>48</output>

<result>48</result>