passenger in the car found an acquaintance walking in the opposite direction of the car, and after 10 seconds, the passenger got out of the car and chased the acquaintance. If he walks twice as fast as his acquaintance, and the car travels five times faster than him. How many seconds before he can catch up to the acquaintance?
汽车上的一个乘客发现一个熟人沿汽车行驶的相反方向走去，10秒钟后，这个乘客下车追赶熟人．如果他行走的速度是他熟人行走速度的2倍，汽车速度是他行走速度的5倍．几秒钟后，他才能追上熟人？
<result>110</result>