If the smallest of three consecutive natural numbers is a multiple of 9, the middle number is a multiple of 8, and the largest is a multiple of 7, what is the smallest sum of these three numbers?
三个连续自然数中最小的数是9的倍数，中间的数是8的倍数，最大的数是7的倍数，则这三个数的和最小是多少．
<gadget id="calculator">7 * 8 * 9</gadget>
<output>504</output>

<gadget id="calculator">504 - 9</gadget>
<output>495</output>

<gadget id="calculator">504 - 8</gadget>
<output>496</output>

<gadget id="calculator">504 - 7</gadget>
<output>497</output>

<gadget id="calculator">495 + 496 + 497</gadget>
<output>1_488</output>

<result>1_488</result>