Container A contains 11 liters of pure alcohol and container B contains 9 liters of water. For the first time, pour part of the pure alcohol in container A into container B, so that the alcohol and water are fully mixed; for the second time, pour part of the mixed solution in container B into container A. In this way, the alcohol content in container A is 62.5%, and the alcohol content in container B is 25%. Then, how many liters of the mixed solution is poured from container B into container A for the second time?
甲容器中有纯酒精11升，乙容器有水9升．第一次将甲容器中的一部分纯酒精倒入乙容器，使酒精与水充分混合；第二次将乙容器中的一部分混合液倒入甲容器．这样，甲容器中酒精含量为62.5%，乙容器中酒精含量为25%，那么，第二次从乙容器中倒入甲容器的混合液是多少升？
<gadget id="calculator">1 + 3</gadget>
<output>4</output>

<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">9 * (1/4)</gadget>
<output>9/4 = around 2.25</output>

<gadget id="calculator">11 - (9/4)</gadget>
<output>35/4 = around 8.75</output>

<gadget id="calculator">(35/4) * 0.625</gadget>
<output>5.46875</output>

<gadget id="calculator">(35/4) - 5.46875</gadget>
<output>3.28125</output>

<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">0.625 - (1/4)</gadget>
<output>0.375</output>

<gadget id="calculator">3.28125 / 0.375</gadget>
<output>8.75</output>

<result>8.75</result>