An insect (regardless of length) starts from one end of a 3 cm long rubber band and crawls at a speed of 1 cm per second. After each second the insect crawls, the rubber band will be stretched evenly by 1 cm. Ask: How many insects are there? Can you just reach the other end of the eraser in seconds? How many
一只昆虫(不计长度)从长为3厘米的橡皮筋一端开始，以每秒1厘米的速度爬行，昆虫每爬行1秒后，橡皮筋都会被均匀的拉伸了1厘米，问：昆虫多少秒后刚好可以达到橡皮的另一端？多少
<gadget id="calculator">3 - 1</gadget>
<output>2</output>

<gadget id="calculator">4 / 3</gadget>
<output>4/3 = around 1.333333</output>

<gadget id="calculator">2 * (4/3)</gadget>
<output>8/3 = around 2.666667</output>

<gadget id="calculator">(8/3) - 1</gadget>
<output>5/3 = around 1.666667</output>

<gadget id="calculator">5 / 4</gadget>
<output>5/4 = around 1.25</output>

<gadget id="calculator">(5/3) * (5/4)</gadget>
<output>25/12 = around 2.083333</output>

<gadget id="calculator">(25/12) - 1</gadget>
<output>13/12 = around 1.083333</output>

<gadget id="calculator">6 / 5</gadget>
<output>6/5 = around 1.2</output>

<gadget id="calculator">(13/12) * (6/5)</gadget>
<output>13/10 = around 1.3</output>

<gadget id="calculator">(13/10) - 1</gadget>
<output>3/10 = around 0.3</output>

<gadget id="calculator">7 / 6</gadget>
<output>7/6 = around 1.166667</output>

<gadget id="calculator">(3/10) * (7/6)</gadget>
<output>7/20 = around 0.35</output>

<gadget id="calculator">4 + (7/20)</gadget>
<output>87/20 = around 4.35</output>

<result>87/20 = around 4.35</result>