There is a K-digit number N, and after adding a 1 to each of its two ends, it becomes a K+2-digit number M. If M is 99 times N, find the value of N when K is the smallest.
有一个K位数N，在它的两头各添上一个1以后就变成一个K+2位的数M．若M是N的99倍，求当K最小时，N的值．
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