It is known that a>0, b>0, a+b=3, then what is the minimum value of y=(1/(a))+(9/(b)).
已知a＞0，b＞0，a+b=3，则y=(1/(a))+(9/(b))的最小值是多少．
<gadget id="calculator">16 / 3</gadget>
<output>16/3 = around 5.333333</output>

<result>16/3 = around 5.333333</result>