There is a series of very interesting numbers, the first number in this series is 8, each subsequent number is 3 greater than the previous number, and the last number is 41. So, what is the sum of this series of numbers.
有一串非常有趣的数，这串数的第一个数是8，以后每个数都比前一个数大3，最后一个数是41．那么，这串数连加之和是多少．
<gadget id="calculator">8 + 41</gadget>
<output>49</output>

<gadget id="calculator">41 - 8</gadget>
<output>33</output>

<gadget id="calculator">33 / 3</gadget>
<output>11</output>

<gadget id="calculator">11 + 1</gadget>
<output>12</output>

<gadget id="calculator">12 / 2</gadget>
<output>6</output>

<gadget id="calculator">49 * 6</gadget>
<output>294</output>

<result>294</result>