It is known that a, b, c, and d are prime numbers, and a*b*c*d is the sum of 77 non-zero consecutive natural numbers. What is the minimum value of a+b+c+d?
已知a、b、c、d是质数，且a*b*c*d是77个非零连续自然数之和．则a+b+c+d的最小值是多少？
<gadget id="calculator">3 + 7 + 11 + 13</gadget>
<output>34</output>

<result>34</result>