Suppose (1/37), (1/143), (1/271) are transformed into recurring decimals, and their recurring section lengths are m, n, k respectively (that is, their recurring sections have m, n, k bits respectively ), then m+n+k=how much.
设(1/37)，(1/143)，(1/271)化为循环小数后，它们的循环节长度分别是m，n，k(即它们的循环节分别有m，n，k位)，则m+n+k=多少．
<gadget id="calculator">3 + 6 + 5</gadget>
<output>14</output>

<result>14</result>