The ones digit of a multi-digit number is 8, and the ones are shifted to the first digit of the number, and the order of other digits remains unchanged, and a new multi-digit number is obtained, which is 8 times the original number, and the original number is the smallest How much should be.
一个多位数的个位是8，将个位移到这个数的首位，其他数字次序不变的往后退一位，得到一个新的多位数，它是原数的8倍，则原数最小应是多少．
<gadget id="calculator">8 * 10</gadget>
<output>80</output>

<gadget id="calculator">80 * 1_000_000_000_000</gadget>
<output>80_000_000_000_000</output>

<gadget id="calculator">80_000_000_000_000 - 640</gadget>
<output>79_999_999_999_360</output>

<gadget id="calculator">79_999_999_999_360 / 79</gadget>
<output>1_012_658_227_840</output>

<gadget id="calculator">1_012_658_227_840 + 8</gadget>
<output>1_012_658_227_848</output>

<result>1_012_658_227_848</result>