A conical part whose bottom diameter is 6 cm and whose height is 2/3 of the diameter, if it is completely submerged in a cylindrical container with a bottom area of 18.84 cm2, how many centimeters will the water level in the container rise?
一个圆锥形零件，底面直径是6厘米，高是直径的(2/3)，将它完全浸没在一个底面积是18.84平方厘米的圆柱体容器内，容器内的水面会上升多少厘米？
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">6 / 2</gadget>
<output>3</output>

<gadget id="calculator">3 ** 2</gadget>
<output>9</output>

<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>

<gadget id="calculator">6 * (2/3)</gadget>
<output>4</output>

<gadget id="calculator">(1/3) * 3.14 * 9 * 4</gadget>
<output>37.68</output>

<gadget id="calculator">37.68 / 18.84</gadget>
<output>2</output>

<result>2</result>