Two trains, passenger and freight, are running towards each other from stations A and B respectively. It is known that the ratio of the speed of the freight train to the speed of the passenger train is 5:6. After the encounter, the speed of the passenger train will decrease by 20%, and the speed of the freight train will increase by 20%. In this way, when the truck arrives at place A, the bus is still 10 kilometers away from place B, so how many kilometers are there between places A and B?
客、货两车分别从甲乙两站同时相向而行，已知货车的速度与客车的速度比是5：6，相遇后，客车的速度减少20%，货车的速度增加20%．这样，当货车到达甲地时，客车离乙地还有10千米，那么甲乙两地相距多少千米？
<gadget id="calculator">5 / 11</gadget>
<output>5/11 = around 0.454545</output>

<gadget id="calculator">6 / 11</gadget>
<output>6/11 = around 0.545455</output>

<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">5 * (1/5)</gadget>
<output>1</output>

<gadget id="calculator">5 + 1</gadget>
<output>6</output>

<gadget id="calculator">6 * (1/5)</gadget>
<output>6/5 = around 1.2</output>

<gadget id="calculator">6 - (6/5)</gadget>
<output>24/5 = around 4.8</output>

<gadget id="calculator">6 / (24/5)</gadget>
<output>5/4 = around 1.25</output>

<gadget id="calculator">1 / (5/4)</gadget>
<output>4/5 = around 0.8</output>

<gadget id="calculator">(6/11) * (4/5)</gadget>
<output>24/55 = around 0.436364</output>

<gadget id="calculator">(5/11) - (24/55)</gadget>
<output>1/55 = around 0.018182</output>

<gadget id="calculator">10 / (1/55)</gadget>
<output>550</output>

<result>550</result>