There is a three-digit number, and the numbers on each digit are three consecutive natural numbers arranged from small to large. The quotient obtained by dividing the three-digit number by 6 is compared with the result obtained by exchanging the positions of the ones and tens digits of the three-digit number. The new three-digit number is less than 389. Find the original three-digit number.
有一个三位数，各数位上的数是从小到大排列的三个连续自然数，这个三位数除以6所得的商，比这个三位数的个位数字与十位数字调换位置所得的新三位数少389．求出原来的三位数．
<gadget id="calculator">389 - 9</gadget>
<output>380</output>

<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>

<gadget id="calculator">1 - (1/6)</gadget>
<output>5/6 = around 0.833333</output>

<gadget id="calculator">380 / (5/6)</gadget>
<output>456</output>

<result>456</result>