There is a four-digit number, the numbers on each bit are different, and the sum of it and its anti-sequence number (the so-called anti-sequence number is to reverse the order of the original numbers, for example, the anti-sequence number of 1234 is 4321) is a five-digit number Number, and the number arrangement of the five-digit teaching is symmetrical with the numbers in it. What is the maximum number of such four digits.
有-个四位数，各位上的数字各不相同，它和它的反序数(所谓反序数就是将原来的数字顺序倒过来排列，例如1234的反序数为4321)之和为-个五位数，且这个五位教的数字排列是以当中的数字为对称的．这样的四位数最大可以是多少．
<result>9_832</result>