Students from classes A and B went to visit the airport 24 kilometers away from the school, but there was only one car, and students from one class could only take one class at a time. In order to arrive at the airport as soon as possible, the two classes agreed that class A would take the car first, and class B The class walks first and starts at the same time. The students in class A get off the bus somewhere on the way and walk to the airport, and the car returns immediately to pick up the students in class B who are walking on the way. If students in Class A and Class B walk at the same speed, 5 km/h, the speed of the car is 35 km/h. I would like to ask: How many kilometers away from the airport should the car return to pick up the students in class B so that the students in the two classes can arrive at the airport at the same time?
甲、乙两班学生到离校24千米的飞机场参观，但只有一辆汽车，一次只能乘坐一个班的学生，为了尽快到达飞机场，两个班商定，由甲班先坐车，乙班先步行，同时出发，甲班学生在途中某地下车后步行去飞机场，汽车则立即返回接在途中步行的乙班学生．如果甲、乙两班学生步行速度相同，都为5千米/时，汽车的速度为35千米/时．请问：汽车应在距飞机场多少千米处返回接乙班学生，才能使两班学生同时到达飞机场？
<gadget id="calculator">35 - 5</gadget>
<output>30</output>

<gadget id="calculator">30 / 2</gadget>
<output>15</output>

<gadget id="calculator">5 + 5 + 15</gadget>
<output>25</output>

<gadget id="calculator">24 / 25</gadget>
<output>24/25 = around 0.96</output>

<gadget id="calculator">(24/25) * 5</gadget>
<output>24/5 = around 4.8</output>

<result>24/5 = around 4.8</result>