There are three consecutive even numbers with two digits, the sum of their single digits is divisible by 7, what is the smallest sum of these three numbers
有三个两位的连续偶数，它们的个位数字的和能被7整除，这三个数的和最小是多少
<gadget id="calculator">0 + 2 + 4</gadget>
<output>6</output>

<gadget id="calculator">4 + 6 + 8</gadget>
<output>18</output>

<gadget id="calculator">16 + 18 + 20</gadget>
<output>54</output>

<result>54</result>