Multiply 1997 by an integer as small as possible but larger than 1, so that 5 consecutive 9s appear in the product. Find this product.
用一个尽可能小但比1大的整数乘以1997，使其乘积中出现5个连续的9．求这个乘积．
<gadget id="calculator">2_003 * 1_997</gadget>
<output>3_999_991</output>

<result>3_999_991</result>