There is a two-digit number, the number in the tens place is twice the number in the ones place, if you exchange the number in the tens place with the number in the ones place, you will get another two-digit number, and compare this two-digit number with the original Add two digits, and the sum is 132, what is the original two digits?
有一个两位数，十位上的数是个位上的数的2倍，如果把十位上的数与个位上的数交换，就得到另外一个两位数，把这个两位数与原两位数相加，和是132，原来的两位数是多少．
<result>84</result>