For any natural number Χ, y, it is stipulated that f(Χ)=2Χ-1, g(y)=y/2+1, then f10-g10=what
对于任意自然数Χ、y，规定f(Χ)=2Χ-1，g(y)=y/2+1，则f10-g10=多少
<gadget id="calculator">2 * 10</gadget>
<output>20</output>

<gadget id="calculator">20 - 1</gadget>
<output>19</output>

<gadget id="calculator">10 / 2</gadget>
<output>5</output>

<gadget id="calculator">5 + 1</gadget>
<output>6</output>

<gadget id="calculator">19 - 6</gadget>
<output>13</output>

<result>13</result>