The elder brother and younger sister went to school at the same time from A to a school 540 meters away. The elder brother walked 60 meters per minute, and the younger sister walked 48 meters per minute. When the elder brother arrived at the school, he found that he had forgotten to take a pencil, so he returned home immediately to get it. On the way, he met his younger sister. ． How many minutes did it take from the beginning of school to the time when the two met again?
哥哥和妹妹同时从甲到相距540米远的学校上学，哥哥每分钟走60米，妹妹每分钟走48米，哥哥到达学校后发现忘了拿铅笔，立即返回家去取，在途中遇到妹妹．从开始上学到两人再相遇共有多少分钟？
<gadget id="calculator">540 * 2</gadget>
<output>1_080</output>

<gadget id="calculator">60 + 48</gadget>
<output>108</output>

<gadget id="calculator">1_080 / 108</gadget>
<output>10</output>

<result>10</result>