There are four natural numbers 1, a, b, c satisfying the condition a+b+c=2010, and 1<a<b<c, these four natural numbers are summed in pairs to get 6 different numbers, and these 6 The numbers are arranged from small to large, and the difference between the two adjacent items and the last item minus the previous item is exactly the same number, then a=how much.
有四个自然数1，a，b，c满足条件a+b+c=2010，且1＜a＜b＜c，这四个自然数两两求和得出6个不同的数，把这6个数从小到大排列，相邻的两项，后一项减去前一项之差恰好都是同一个数，那么a=多少．
<result>445</result>