Today there are 10 prime numbers: 17, 23, 31, 41, 53, 67, 79, 83, 101, 103. If they are divided into two groups with five numbers in each group, and the sum of the five numbers in each group is equal, then arrange the numbers in the group containing 101 from small to large, what is the second number?
今有10个质数：17，23，31，41，53，67，79，83，101，103．如果将它们分成两组，每组五个数，并且每组的五个数之和相等，那么把含有101的这组数从小到大排列，第二个数应是多少．
<result>31</result>