If an integer a is divided by 8 natural numbers 2, 3, ..., 9, and the remainder is 1, what is the minimum value of a?
若一个整数a被2，3，…，9这8个自然数除，所得的余数都为1，则a的最小值是多少．
<gadget id="calculator">2 * 2 * 2 * 3 * 3 * 5 * 7</gadget>
<output>2_520</output>

<gadget id="calculator">2_520 + 1</gadget>
<output>2_521</output>

<result>2_521</result>