There are 10 chess players in a single round-robin match (that is, every two players play one game), and it is stipulated that 2 points are awarded for a win, 1 point for a tie, and 0 points for a loss. After the game, it is found that the scores of each player are different, and the score of the second place is the sum of the scores of the last five players (4/5). What is the score of the second player?
有10名象棋选手进行单循环赛(即每两名选手比赛一场)，规定获胜得2分，平局各得1分，负得0分．比赛结束后，发现每名选手的得分各不相同，且第二名的得分是最后五名选手的得分和的(4/5)．则第二名选手的得分是多少．
<gadget id="calculator">10 * 2</gadget>
<output>20</output>

<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>

<gadget id="calculator">20 * (4/5)</gadget>
<output>16</output>

<result>16</result>