Subtract its (1/2) from 2008, then subtract the remaining (1/3) from the first time, then subtract the remaining (1/4) from the second time, and so on, until the 2007 time minus 2006 How many are left until the remaining (1/2008)?
2008减去它的(1/2)，再减去第一次余下的(1/3)，再减去第二次余下的(1/4)，如此下去，一直到第2007次减去2006次余下的(1/2008)为止，则最后剩下多少？
<gadget id="calculator">1 / 2_008</gadget>
<output>1/2_008 = around 0.000498</output>

<gadget id="calculator">2_008 * (1/2_008)</gadget>
<output>1</output>

<result>1</result>