Known 1**2+2**2+3**2+4**2+5**2+6**2+7**2+8**2+9**2+10** 2=385, use it to explore the sum of the areas of 10 different squares whose sides are integers is 1110, what is the minimum perimeter of the largest square.
已知1**2+2**2+3**2+4**2+5**2+6**2+7**2+8**2+9**2+10**2=385，利用它探究边长为整数的10个不同正方形的面积和为1110，则最大正方形的最小周长为多少．
<gadget id="calculator">15 * 4</gadget>
<output>60</output>

<result>60</result>