An engineering team repaired a road, and repaired (4/9) kilometers in the first week, (2/9) kilometers in the second week, and (1/6) kilometers less than the sum of the previous two weeks in the third week , How many kilometers did you repair in the third week?
某工程队修一条路，第一周修了(4/9)千米，第二周修了(2/9)千米，第三周修的比前两周的总和少(1/6)千米，第三周修了多少千米？
<gadget id="calculator">4 / 9</gadget>
<output>4/9 = around 0.444444</output>

<gadget id="calculator">2 / 9</gadget>
<output>2/9 = around 0.222222</output>

<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>

<gadget id="calculator">(2/9) - (1/6)</gadget>
<output>1/18 = around 0.055556</output>

<gadget id="calculator">(4/9) + (1/18)</gadget>
<output>1/2 = around 0.5</output>

<result>1/2 = around 0.5</result>