From the nine numbers from 1 to 9, two different numbers are taken each time to form a two-digit number, and the sum of the tens and ones digits must be greater than 10. How many such two-digit numbers are there? ?
从1～9这九个数字中，每次取两个不同的数字组成一个两位数，而十位与个位上数字的和都必须比10大，这样的两位数一共有几个？
<gadget id="calculator">16 * 2</gadget>
<output>32</output>

<result>32</result>