The specified operation "Ω" satisfies yΩx=5 for any x, y, z, xΩ(yΩz)=(xΩy)+z-5, try to find 2009Ω(1949Ω10).
规定运算"Ω"对任意的x、y、z都满足yΩx=5，xΩ(yΩz)=(xΩy)+z-5，试求2009Ω(1949Ω10)．
<gadget id="calculator">10 - 5</gadget>
<output>5</output>

<gadget id="calculator">5 + 5</gadget>
<output>10</output>

<result>10</result>