There are two groups of numbers A and B, each group is arranged according to a certain rule, and each group has 26 numbers, the first few numbers in group A are arranged like this: 1, 6, 11, 16, 21, ... ; The last few numbers in group B are arranged like this: ..., 110, 115, 120, 125, 130. Then, what is the sum of all the numbers in the two sets of numbers A and B?
有A、B两组数，每组都按一定规律排列着，并且每组各有26个数，A组数中前几个数是这样排列的：1、6、11、16、21、…；B组数中最后几个数是这样排列的：…、110、115、120、125、130．那么，A、B两组数中所有数的和是多少．
<gadget id="calculator">26 * 1</gadget>
<output>26</output>

<gadget id="calculator">26 - 1</gadget>
<output>25</output>

<gadget id="calculator">26 * 25</gadget>
<output>650</output>

<gadget id="calculator">650 / 2</gadget>
<output>325</output>

<gadget id="calculator">325 * 5</gadget>
<output>1_625</output>

<gadget id="calculator">26 * 130</gadget>
<output>3_380</output>

<gadget id="calculator">3_380 - 1_625</gadget>
<output>1_755</output>

<gadget id="calculator">26 + 1_625 + 1_755</gadget>
<output>3_406</output>

<result>3_406</result>