The gas cashier went to a building to collect the gas price difference. When he walked out of the building, he calculated that the number of households that had not paid accounted for (1/8) of the number of households that had paid. If 2 households are received less, the number of households that have not paid is exactly 1/6 of the number of households that have paid. How many households are there in this building?
煤气收款员到一幢楼里收煤气差价款，他走出楼时一算，没交款的户数占已交款户数的(1/8)．如果少收2户，则没交款的户数恰好占已交款户数的(1/6)，这幢楼有多少住户？
<gadget id="calculator">1 + 6</gadget>
<output>7</output>

<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>

<gadget id="calculator">1 + 8</gadget>
<output>9</output>

<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>

<gadget id="calculator">(1/7) - (1/9)</gadget>
<output>2/63 = around 0.031746</output>

<gadget id="calculator">2 / (2/63)</gadget>
<output>63</output>

<result>63</result>