How many numbers can be selected from the 12 natural numbers from 1 to 12, so that each number among the selected numbers is not a multiple of another number?
从l至12这12个自然数中最多能选出几个数，使得在选出的数中，每一个数都不是另一个数的倍数？
<gadget id="calculator">12 - 7</gadget>
<output>5</output>

<gadget id="calculator">5 + 1</gadget>
<output>6</output>

<gadget id="calculator">11 - 6</gadget>
<output>5</output>

<result>6</result>