Given that x**2+y**2+z**2-2x+4y-6z+14=0, find the value of the algebraic formula x+y+z.
已知x**2+y**2+z**2-2x+4y-6z+14=0，求代数式x+y+z的值．
<gadget id="calculator">1 - 2</gadget>
<output>-1</output>

<gadget id="calculator">(-1) + 3</gadget>
<output>2</output>

<result>2</result>