There is a series of numbers: 1, 3, 8, 22, 60, 164, 448, ... where the first number is 1, the second number is 3, and from the third number onwards, each number is exactly the first two numbers 2 times the sum. Then in this series of numbers, what is the remainder when the 2000th number is divided by 9?
有一串数：1，3，8，22，60，164，448，…其中第一个数是1，第二个数是3，从第三个数起，每个数恰好是前两个数之和的2倍．那么在这串数中，第2000个数除以9的余数是多少．
<result>3</result>