Suppose 1, 3, 9, 27, 81, and 243 are 6 given numbers, and from these 6 numbers, either take one at a time, or take several different numbers to sum (each number can only be taken once), A new number can be obtained, so a total of 63 new numbers can be obtained. If they are arranged in order from small to large, it is 1, 3, 4, 9, 10, 12..., then what is the 60th number?
设1、3、9、27、81、243是6个给定的数，从这6个数中每次或者取一个，或者取几个不同的数求和(每个数只能取一次)，可以得到一个新数，这样共得到63个新数．如果把它们按从小到大的顺序依次排列起来就是1、3、4、9、10、12…，那么第60个数是多少．
<gadget id="calculator">9 + 27 + 81 + 243</gadget>
<output>360</output>

<result>360</result>