The six sides of a dice are written 1, 2, 4, 5, 6, 7 respectively. If the dice is rolled twice, what is the probability that the sum of the two numbers is not less than 10?
一个骰子的六面分别写着1，2，4，5，6，7，掷两次骰子，两次出来的数字相加后不小于10的可能性为多少
<gadget id="calculator">6 * 6</gadget>
<output>36</output>

<gadget id="calculator">13 / 36</gadget>
<output>13/36 = around 0.361111</output>

<result>13/36 = around 0.361111</result>