A, B, and C are all positive integers. It is known that A has 7 divisors, B has 6 divisors, C has 3 divisors, AxB has 24 divisors, and BxC has 10 divisors. What is the minimum value of A+B+C?
A、B、C均为正整数．已知A有7个约数，B有6个约数，C有3个约数，AxB有24个约数，BxC有10个约数．则A+B+C的最小值为多少．
<gadget id="calculator">2 ** 6</gadget>
<output>64</output>

<gadget id="calculator">3 ** 2</gadget>
<output>9</output>

<gadget id="calculator">2 * 9</gadget>
<output>18</output>

<gadget id="calculator">64 + 18 + 9</gadget>
<output>91</output>

<result>91</result>