If 4 cubes with side lengths of 2 decimeters are put together to form a cuboid, what is the minimum reduction in the surface area of the cuboid from the sum of the surface areas of the 4 cubes?
将4个棱长为2分米的正方体拼成一个长方体，长方体的表面积比4个正方体表面积的和减少最少是多少平方分米．
<gadget id="calculator">2 * 2 * 6 * 4</gadget>
<output>96</output>

<gadget id="calculator">8 * 2 * 4</gadget>
<output>64</output>

<gadget id="calculator">2 * 2 * 2</gadget>
<output>8</output>

<gadget id="calculator">64 + 8</gadget>
<output>72</output>

<gadget id="calculator">96 - 72</gadget>
<output>24</output>

<result>24</result>