Between the two numbers 1 and 2, write 3 for the first time to get 1, 3, 2. For the second time, write 4, 5 between 1, 3 and 3, 2 respectively, and get 1, 4, 3, 5, 2. Every time thereafter, between the two adjacent numbers that have already been written, write the sum of these two adjacent numbers. This process has been repeated 6 times in total, so what is the sum of all the numbers?
在1，2两数之间，第一次写上3，得到1,3,2．第二次在1，3之间和3，2之间分别写上4，5，得到1,4,3,5,2．以后每一次都在已写上的两个相邻数之间，再写上这两个相邻数之和．这样的过程总共重复了6次，那么所有数的和是多少．
<gadget id="calculator">7 * 3</gadget>
<output>21</output>

<gadget id="calculator">1 + 21</gadget>
<output>22</output>

<gadget id="calculator">1 + 22</gadget>
<output>23</output>

<gadget id="calculator">23 / 2</gadget>
<output>23/2 = around 11.5</output>

<gadget id="calculator">8 * (23/2)</gadget>
<output>92</output>

<gadget id="calculator">2 + 21</gadget>
<output>23</output>

<gadget id="calculator">1 + 23</gadget>
<output>24</output>

<gadget id="calculator">24 / 2</gadget>
<output>12</output>

<gadget id="calculator">8 * 12</gadget>
<output>96</output>

<gadget id="calculator">92 + 96 + 3</gadget>
<output>191</output>

<result>191</result>