A project alone takes 6 hours, and B alone takes 10 hours. If A, B, A, B... work alternately in the order of 1 hour each time, how long will it take to complete?
一件工程，甲单独做要6小时，乙单独做要10小时，如果按甲、乙、甲、乙…顺序交替工作，每次1小时，那么需要多长时间完成？
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>

<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>

<gadget id="calculator">(1/6) + (1/10) + (1/6) + (1/10) + (1/6) + (1/10)</gadget>
<output>4/5 = around 0.8</output>

<gadget id="calculator">1 - (4/5) - (1/6)</gadget>
<output>1/30 = around 0.033333</output>

<gadget id="calculator">(1/30) / (1/10)</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">6 + 1 + (1/3)</gadget>
<output>22/3 = around 7.333333</output>

<result>22/3 = around 7.333333</result>