There is a three-digit number, the number in the tens place is equal to the sum of the number in the ones place and the number in the hundreds place, the number in the tens place minus the number in the ones place is 2, the number in the hundreds place and the number in the ones place After the numbers on the digits are reversed, the resulting three-digit number is 99% larger than the original three-digit number. Find the original three-digit number.
有一个三位数，它的十位上的数字等于个位上的数字与百位上的数字的和，十位上的数减去个位上的数等于2，百位上的数字与个位上的数字对调后，所得的三位数比原来的三位数大99．求原来的三位数．
<result>253</result>