A certain small aircraft can fly up to 1500 kilometers with full fuel, but it is not enough to fly from point A to point B. If 3 such planes are sent from point A, and the fuel supply is realized through the air, one of the planes can fly to point B, and the other two can return to point A safely, then how many kilometers is the farthest distance between points A and B?
某种小型飞机加满油最多能飞行1500千米，但不够从A地飞到B地．如果从A地派3架这样的飞机，通机实现空中供油，可以使其中一架飞机飞到B地，另两架安全返回A地，那么A、B两地最远相距多少千米？
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">1_500 * (1/4)</gadget>
<output>375</output>

<gadget id="calculator">375 + 375 + 1_500</gadget>
<output>2_250</output>

<result>2_250</result>