It is known that the first number in a series of numbers is 2, starting from the second number, each number is equal to the difference between 2 minus the reciprocal of the previous number, what is the 2011th number?
已知一列数中第一个数是2，从第二个数开始，每一个数都等于2减去前一个数的倒数的差，则第2011个数是多少．
<gadget id="calculator">2_011 + 1</gadget>
<output>2_012</output>

<gadget id="calculator">2_012 / 2_011</gadget>
<output>2_012/2_011 = around 1.000497</output>

<result>2_012/2_011 = around 1.000497</result>