There are 40 consecutive natural numbers, the largest number is 4 times the smallest number, what is the sum of the largest number and the smallest number?
有40个连续的自然数，其中最大的数是最小的数的4倍，那么最大的数与最小的数之和是多少．
<gadget id="calculator">40 - 1</gadget>
<output>39</output>

<gadget id="calculator">4 - 1</gadget>
<output>3</output>

<gadget id="calculator">39 / 3</gadget>
<output>13</output>

<gadget id="calculator">4 + 1</gadget>
<output>5</output>

<gadget id="calculator">13 * 5</gadget>
<output>65</output>

<result>65</result>