A cuboid, when its height is reduced by 2 cm, a cube is obtained. Given that the surface area of the cube is 20 cm2 less than that of the cuboid, what is the surface area of the original cuboid in cm2?
一个长方体，当它的高减少2厘米后，就得到一个正方体．已知正方体的表面积比长方体少20平方厘米，求原长方体的表面积是多少平方厘米？
<gadget id="calculator">20 / 4 / 2</gadget>
<output>5/2 = around 2.5</output>

<gadget id="calculator">(5/2) * (5/2) * 2</gadget>
<output>25/2 = around 12.5</output>

<gadget id="calculator">(5/2) + 2</gadget>
<output>9/2 = around 4.5</output>

<gadget id="calculator">(5/2) * (9/2) * 4</gadget>
<output>45</output>

<gadget id="calculator">(25/2) + 45</gadget>
<output>115/2 = around 57.5</output>

<result>115/2 = around 57.5</result>