For a project, A works alone for 3 days first, and then cooperates with B for 6 days. Only in this way can half of the whole project be completed. It is known that A’s work efficiency is (4/3) times that of B. How many days will it take for B to do this job alone?
一项工程，甲先单独做3天，然后与乙合作6天，这样才完成全工程的一半，已知甲的工效是乙的(4/3)倍．这件工作乙单独做，需要多少天才能完成？
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>

<gadget id="calculator">4 / 3</gadget>
<output>4/3 = around 1.333333</output>

<gadget id="calculator">3 * (4/3)</gadget>
<output>4</output>

<gadget id="calculator">6 * (4/3)</gadget>
<output>8</output>

<gadget id="calculator">4 + 8 + 6</gadget>
<output>18</output>

<gadget id="calculator">(1/2) / 18</gadget>
<output>1/36 = around 0.027778</output>

<gadget id="calculator">1 / (1/36)</gadget>
<output>36</output>

<result>36</result>