There are four taxis A, B, C, and D that need to be repaired. If a worker repairs the four vehicles, the time is 3 hours, 6 hours, 4 hours and 2 hours respectively. It is known that each car loses 100 yuan when it is parked for 1 hour. Now two maintenance workers with the same work efficiency are working independently. To minimize the economic loss, how much is the minimum loss?
有A、B、C、D四辆出租车需要维修．如果有一名工人维修这四辆车的时间分别为3小时，6小时，4小时和2小时．已知每辆车停开1小时损失100元．现在由两名工效相同的维修工人各自单独工作，要使经济损失减少到最低程度，最少损失多少元？
<gadget id="calculator">3 - 2</gadget>
<output>1</output>

<gadget id="calculator">4 - 1</gadget>
<output>3</output>

<gadget id="calculator">6 - 3</gadget>
<output>3</output>

<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>

<gadget id="calculator">3 + 2 + 2 + 4 + 3 + 3 + (3/2)</gadget>
<output>37/2 = around 18.5</output>

<gadget id="calculator">100 * (37/2)</gadget>
<output>1_850</output>

<result>1_850</result>