An oil refinery refines (7/8) tons of oil on the first day, refines (1/6) more tons of oil on the second day than the first day, and refines less (1/12) than the sum of the first and second days on the third day tons, how many tons were refined on the third day?
一个炼油厂，第一天炼油(7/8)吨，第二天比第一天多炼油(1/6)吨，第三天比第一、二两天炼油的总和少(1/12)吨，第三天炼多少吨？
<gadget id="calculator">7 / 8</gadget>
<output>7/8 = around 0.875</output>

<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>

<gadget id="calculator">(7/8) + (1/6)</gadget>
<output>25/24 = around 1.041667</output>

<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>

<gadget id="calculator">(25/24) - (1/12)</gadget>
<output>23/24 = around 0.958333</output>

<gadget id="calculator">(7/8) + (23/24)</gadget>
<output>11/6 = around 1.833333</output>

<result>11/6 = around 1.833333</result>