An ordinary dice has 6 faces, with 1, 2, 3, 4, 5, and 6 written on them. When the dice is rolled, the probability of either side is (1/6). Suppose you throw a certain dice 9 times in a row, and each time the result is that one point is up, then after the tenth throw, what is the probability that the number of points on the face up is exactly odd?
一只普通的骰子有6个面，分别写有1、2、3、4、5、6．掷出这枚骰子，它的任何一面朝上的概率都是(1/6)．假设你将某一个骰子连续投掷了9次，每次的结果都是l点朝上，那么第十次投掷后，朝上的面上的点数恰好是奇数的概率是多少？
<gadget id="calculator">3 / 6</gadget>
<output>1/2 = around 0.5</output>

<result>1/2 = around 0.5</result>