It is known that the five numbers are 13, 12, 15, 25, 20 in turn, and the multiplication of two adjacent numbers of them gives four numbers, and the multiplication of two adjacent numbers of these four numbers gives three numbers, and the three numbers Multiply every two adjacent numbers to get two numbers, and multiply these two numbers to get a number. May I ask how many 0s can be counted continuously from the ones digit to the left of the last number.
已知五个数依次是13、12、15、25、20，它们每相邻的两个数相乘得四个数，这四个数相邻两个相乘得三个数，这三个数每相邻两个相乘得两个数，这两个数相乘得一个数，请问最后这个数从个位起向左数，可以连续地数到多少个0．
<result>10</result>