The sum of six non-zero consecutive natural numbers is 33, if two more non-zero natural numbers are added to make them eight consecutive natural numbers, then their sum is 52, then among these eight numbers, the two in the middle position What is the product of the numbers
六个非零连续自然数的和是33，如果再增加两个非零自然数，使它们成为八个连续的自然数，这时它们的和是52，那么这八个数中，处于中间位置的两个数的乘积是多少
<gadget id="calculator">6 * 7</gadget>
<output>42</output>

<result>42</result>