There are 11 numbers in a string, and the number in the middle is the largest. Counting from the middle number forward, one number is 2 smaller than the other number; counting backward from the middle number, one number is 3 smaller than the other number, the sum of these 11 numbers is 200, so what is the middle number?
一串数有11个数，中间一个数最大．从中间的数往前数，一个数比一个数小2；从中间的数往后数，一个数比一个数小3，这11个数的总和是200，那么中间的数是多少？
<gadget id="calculator">2 + 4 + 6 + 8 + 10 + 3 + 6 + 9 + 12 + 15 + 200</gadget>
<output>275</output>

<gadget id="calculator">275 / 11</gadget>
<output>25</output>

<result>25</result>