The natural gas cashier goes to a building to collect the natural gas price difference. When he leaves the building, he calculates that the number of households that have not paid accounts for 1/6 of the number of households that have paid. The number of households accounts for exactly (1/8) of the number of paid households. How many households are there in this building?
天然气收款员到一幢楼收天然气差价款，他出楼时一算，没交款的户数占已交款户数的(1/6)，如果再收2户，则没交款的户数恰好占已交款户数的(1/8)，这幢楼一共有多少户？
<gadget id="calculator">1 + 6</gadget>
<output>7</output>

<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>

<gadget id="calculator">1 + 8</gadget>
<output>9</output>

<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>

<gadget id="calculator">(1/7) - (1/9)</gadget>
<output>2/63 = around 0.031746</output>

<gadget id="calculator">2 / (2/63)</gadget>
<output>63</output>

<result>63</result>