Suppose n is a natural number less than 50, what is the sum of all possible values of n that make 4n+5 and 7n+6 have a common divisor greater than 1?
设n是小于50的自然数，那么使得4n+5和7n+6有大于1的公约数的所有n的可能值之和为多少．
<gadget id="calculator">7 + 18 + 29 + 40</gadget>
<output>94</output>

<result>94</result>