There are three consecutive natural numbers, the smallest one is divisible by 11, the middle one is divisible by 15 with a remainder of 2, and the largest one is divisible by 17. What is the smallest one?
有三个连续自然数，其中最小的一个能被11整除，中间一个被15除余2，最大一个能被17整除，求最小的一个是多少？
<gadget id="calculator">17 * 114</gadget>
<output>1_938</output>

<gadget id="calculator">1_938 - 2</gadget>
<output>1_936</output>

<result>1_936</result>