In a cylindrical container with a bottom area of 34 square centimeters, put a cylindrical object and a conical object with the same bottom and height, the water surface rises by 10 cm, (1/5) of the cylinder is exposed to the water surface, and the cone is completely submerged , what is the volume of the cone in cubic centimeters?
在一个底面积为34平方厘米的圆柱形容器中，放入等底等高的一根圆柱形物体和一个圆锥形物体，水面上升10厘米，圆柱有(1/5)露出水面，圆锥完全浸没，圆锥的体积是多少立方厘米？
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">3 * (1/5)</gadget>
<output>3/5 = around 0.6</output>

<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>

<gadget id="calculator">3 + (2/5)</gadget>
<output>17/5 = around 3.4</output>

<gadget id="calculator">10 / (17/5)</gadget>
<output>50/17 = around 2.941176</output>

<gadget id="calculator">34 * (50/17)</gadget>
<output>100</output>

<result>100</result>