Known: 1-(1/(6+(1/(6+(1/6)))))=(1/(A+(1/(B+(1/(C+(1/(C)))) ))))) Where A, B, and C are all natural numbers greater than 0 and different from each other, then (A+B)/C=how much.
已知：1-(1/(6+(1/(6+(1/6)))))=(1/(A+(1/(B+(1/(C+(1/(C))))))))其中A、B、C都是大于0且互不相同的自然数，则(A+B)/C=多少．
<gadget id="calculator">1 + 5</gadget>
<output>6</output>

<gadget id="calculator">6 / 6</gadget>
<output>1</output>

<result>1</result>