There are two integers A and B. The sum of the digits of A is 17, and the sum of the digits of B is 11. When the two numbers are added, they are carried twice. What is the sum of the digits of A+B?
有A、B两个整数，A的各位数字之和为17，B的各位数字之和为11，两数相加时进位两次，那么A+B的各位数字之和是多少．
<gadget id="calculator">9 * 2</gadget>
<output>18</output>

<gadget id="calculator">11 - 18</gadget>
<output>-7</output>

<gadget id="calculator">17 + (-7)</gadget>
<output>10</output>

<result>10</result>