There is a three-digit number, the ones digit is twice that of the hundreds digit, and the tens digit is 1 greater than the hundreds digit. 2 times the original number is less than 49, find the original number.
有一个三位数，个位数字为百位数字的2倍，十位数字比百位数字大1，若将此数个位与百位顺序对调(个位变百位)所得的新数比原数的2倍少49，求原数．
<result>346</result>