A road, A has repaired (4/5) kilometers, B has repaired (1/4) kilometers, and C has repaired (3/8) kilometers less than twice the sum of A and B. How many kilometers have C repaired? rice?
一条公路，甲修了(4/5)千米，乙修了(1/4)千米，丙修的比甲、乙两队总和的2倍少(3/8)千米，丙队修了多少千米？
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>

<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">(4/5) + (1/4)</gadget>
<output>21/20 = around 1.05</output>

<gadget id="calculator">(21/20) * 2</gadget>
<output>21/10 = around 2.1</output>

<gadget id="calculator">3 / 8</gadget>
<output>3/8 = around 0.375</output>

<gadget id="calculator">(21/10) - (3/8)</gadget>
<output>69/40 = around 1.725</output>

<result>69/40 = around 1.725</result>