An armed police force drove from the station to the earthquake-stricken area of Beichuan for rescue and relief. If they traveled more per hour (1/9) than the original time, they could arrive 20 minutes earlier than the scheduled time. If they first drove 72 kilometers at the original speed, and then Increase the speed (1/3) from the original, and you can arrive 30 minutes earlier than the scheduled time. How many kilometers is this troop traveling?
一支武警部队从驻地乘车赶往北川地震灾区抢险救灾，如果每小时比原来多行(1/9)，就可以比预定时间提前20分钟到达，如果先按原速度行驶72千米，再将速度比原来提高(1/3)，就可以比预定时间提早30分钟到达，这支部队行程是多少千米？
<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>

<gadget id="calculator">1 + (1/9)</gadget>
<output>10/9 = around 1.111111</output>

<gadget id="calculator">1 / (10/9)</gadget>
<output>9/10 = around 0.9</output>

<gadget id="calculator">1 - (9/10)</gadget>
<output>1/10 = around 0.1</output>

<gadget id="calculator">20 / (1/10)</gadget>
<output>200</output>

<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">1 + (1/3)</gadget>
<output>4/3 = around 1.333333</output>

<gadget id="calculator">1 / (4/3)</gadget>
<output>3/4 = around 0.75</output>

<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">200 * (1/4)</gadget>
<output>50</output>

<gadget id="calculator">30 / 50</gadget>
<output>3/5 = around 0.6</output>

<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>

<gadget id="calculator">72 / (2/5)</gadget>
<output>180</output>

<result>180</result>