For a two-digit number, the number in the tens place is the number in the ones place (2/3). After the number in the tens place and the number in the ones place are exchanged, the new number is 18 larger than the original number. What is the sum of the ones digit of the two-digit number and the number in the tens digit?
一个两位数，十位上的数字是个位上数字的(2/3)，把十位上的数字与个位上的数字调换后，新数比原数大18．则原来这个两位数个位与十位上数字的和是多少
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>

<gadget id="calculator">(2/3) * 10</gadget>
<output>20/3 = around 6.666667</output>

<gadget id="calculator">(2/3) - (20/3) - 1</gadget>
<output>-7</output>

<gadget id="calculator">10 + (-7)</gadget>
<output>3</output>

<gadget id="calculator">18 / 3</gadget>
<output>6</output>

<gadget id="calculator">6 * (2/3)</gadget>
<output>4</output>

<gadget id="calculator">6 + 4</gadget>
<output>10</output>

<result>10</result>