a, b, c, d are 4 non-zero one-bit natural numbers, how many times is the sum of 24 four-digit numbers composed of them to be (a+b+c+d).
a、b、c、d是4个非零的一位自然数，用它们组成的24个没有重复数字的四位数的和是(a+b+c+d)的多少倍．
<gadget id="calculator">6 * 1_000</gadget>
<output>6_000</output>

<gadget id="calculator">6 * 100</gadget>
<output>600</output>

<gadget id="calculator">6 * 10</gadget>
<output>60</output>

<gadget id="calculator">6_000 + 600 + 60 + 6</gadget>
<output>6_666</output>

<result>6_666</result>