(1/24)=(1/(A))+(1/(B)), where A and B represent two different natural numbers, what is the smallest sum of A and B?
(1/24)=(1/(A))+(1/(B))，其中A、B表示两个不同的自然数，则A、B的和最小是多少．
<gadget id="calculator">60 + 40</gadget>
<output>100</output>

<result>100</result>