The first number is 7 less than the third number, the third number is twice the second number, and the average of the three numbers is 2011, what is the first number?
第一个数比第三个数少7，第三个数是第二个数的2倍，三个数的平均数是2011，则第一个数是多少．
<gadget id="calculator">2_011 * 3</gadget>
<output>6_033</output>

<gadget id="calculator">7 + 6_033</gadget>
<output>6_040</output>

<gadget id="calculator">1 + 2 + 2</gadget>
<output>5</output>

<gadget id="calculator">6_040 / 5</gadget>
<output>1_208</output>

<gadget id="calculator">1_208 * 2</gadget>
<output>2_416</output>

<gadget id="calculator">2_416 - 7</gadget>
<output>2_409</output>

<result>2_409</result>