For a two-digit number, the sum of the number in the tens place and the number in the ones place is 11. If the number in the tens place and the number in the ones place are reversed, the new number obtained will be 63 greater than the original number. Find the original number two digits of .
一个两位数，十位上的数字与个位上的数字之和为11，如果把十位上的数字与个位上的数字对调，那么得到的新数就比原数大63，求原来的两位数．
<result>29</result>