Two trucks, A and B, have to transport goods from A to B, and B will start after A has driven 48 kilometers. It is known that the speed of car A is 60 kilometers per hour, and the speed of car B is 20% faster than that of car A. How long will it take for car B to catch up with car A? (solution by equation)
甲、乙两辆货车都要从A地向B地运送货物，甲车开出48千米后乙车才出发．已知甲车的速度是每时60千米，乙车的速度比甲车快20%，经过几时乙车可以追上甲车？(用方程解)
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">60 * (1/5)</gadget>
<output>12</output>

<gadget id="calculator">12 - 60</gadget>
<output>-48</output>

<gadget id="calculator">60 + (-48)</gadget>
<output>12</output>

<gadget id="calculator">48 / 12</gadget>
<output>4</output>

<result>4</result>