For a two-digit number, the number in the tens place is the number in the ones place (2/3), and the number obtained by exchanging the numbers in each place is 18 larger than the original number. What is the original two-digit number?
一个两位数，十位上的数是个位上数的(2/3)，把它各数位上的数字互换所得到的数比原数大18，原来两位数是多少．
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>

<gadget id="calculator">10 * (2/3)</gadget>
<output>20/3 = around 6.666667</output>

<gadget id="calculator">(2/3) - (20/3) - 1</gadget>
<output>-7</output>

<gadget id="calculator">10 + (-7)</gadget>
<output>3</output>

<gadget id="calculator">18 / 3</gadget>
<output>6</output>

<gadget id="calculator">6 * (2/3) * 10</gadget>
<output>40</output>

<gadget id="calculator">40 + 6</gadget>
<output>46</output>

<result>46</result>