Car A and car B go back and forth between places A and B, which are 270 kilometers apart. Car A first starts from point A, and after 12 minutes, car B also starts from point A, and chases after point C, which is 90 kilometers away from point A. On the armored car. Car B returns at the same speed immediately after arriving at point B. Car A rests at point B for 5 minutes and then speeds up to return to point A, and catches up with car B again at point C. In the end, how many minutes earlier did car A arrive at point A than car B?
甲、乙两车往返于相距270千米的A、B两地，甲车先从A地出发，12分钟后，乙车也从A地出发，并在距A地90千米的C地追上甲车．乙车到B地后立即按原速返回，甲车到B地休息5分钟后加快速度向A地返回，在C地又将乙车追上．最后甲车比乙车早多少分钟到达A地？
<gadget id="calculator">270 - 90</gadget>
<output>180</output>

<gadget id="calculator">180 / 90</gadget>
<output>2</output>

<gadget id="calculator">2 * 12</gadget>
<output>24</output>

<gadget id="calculator">24 + 5</gadget>
<output>29</output>

<gadget id="calculator">29 / 180</gadget>
<output>29/180 = around 0.161111</output>

<gadget id="calculator">(29/180) * 90</gadget>
<output>29/2 = around 14.5</output>

<result>29/2 = around 14.5</result>