There is a column of numbers arranged according to the law of "0, 1, 0, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1, ...," that is, there is 1 between 0 and 0 1, 2 1s, 3 1s, ..., if the sum of the first m numbers is exactly 100, then what is m equal to?
有一列数字按"0，1，0，1，1，0，1，1，1，0，1，1，1，1，…，"的规律排列，即在0与0之间有1个1，2个1，3个1，…，若前m个数字的和恰好是100，则m等于多少．
<gadget id="calculator">13 + 91 + 1 + 9</gadget>
<output>114</output>

<result>114</result>