The sum of four consecutive natural numbers is 54, then what is the least common multiple of these four numbers (1/10).
四个连续自然数的和等于54，那么这四个数的最小公倍数的(1/10)是多少．
<gadget id="calculator">5_460 / 10 / 1</gadget>
<output>546</output>

<result>546</result>