There is a strange four-digit number (the first digit is not 0), which is a perfect square number, and the sum of its numbers is also a perfect square number. Dividing this four-digit number by its number and the result is still a perfect square number, and it The divisor of is exactly equal to the sum of its digits, so of course it is also a perfect square number. If the digits of this four-digit number are different from each other, what is the four-digit number?
有一个奇怪的四位数(首位不为0)，它是完全平方数，它的数字和也是完全平方数，用这个四位数除以它的数字和得到的结果还是完全平方数，并且它的约数个数还恰好等于它的数字和，那当然也是完全平方数，如果这个四位数的各位数字互不相同，那么这个四位数是多少？
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>

<gadget id="calculator">17 ** 2</gadget>
<output>289</output>

<gadget id="calculator">9 * 289</gadget>
<output>2_601</output>

<result>2_601</result>