Cars A and B travel between places A and B, which are 240 kilometers apart. Car A starts from point A first, and after 12 minutes, car B also starts from point A and catches up with car A at point C, which is 60 kilometers away from point A. Car B returns at the original speed immediately after arriving at point B. Car A speeds up after resting for 15 minutes at point B, returns to point A, and catches up with car B again at point C. In the end, how many minutes earlier does car A arrive at point A than car B?
甲、乙两车往返于相距240千米的A、B两地．甲车先从A地出发，12分钟后，乙车也从A地出发，并在距A地60千米的C地追上甲车．乙车到B地后立即按原速返回，甲车到B地休息15分钟后加快速度，向A地返回，在C地又将乙车追上．最后甲车比乙车早多少分钟到达A地．
<gadget id="calculator">240 - 60</gadget>
<output>180</output>

<gadget id="calculator">180 / 60</gadget>
<output>3</output>

<gadget id="calculator">3 * 12</gadget>
<output>36</output>

<gadget id="calculator">36 + 15</gadget>
<output>51</output>

<gadget id="calculator">51 / 180</gadget>
<output>17/60 = around 0.283333</output>

<gadget id="calculator">(17/60) * 60</gadget>
<output>17</output>

<result>17</result>