Given that x and y are unequal natural numbers, when (1/18)=(1/(x))+(1/(y)), what is the minimum value of x+y?
已知x、y是互不相等的自然数，当(1/18)=(1/(x))+(1/(y))时，x+y的最小值是多少．
<gadget id="calculator">30 + 45</gadget>
<output>75</output>

<result>75</result>