Processing a batch of parts, if two workers A and B with the same work efficiency cooperate to complete it in 6 hours, if the efficiency of worker A increases by 20%, and the efficiency of B remains the same, how many hours will it take for the two workers to cooperate?
加工一批零件，如果由工作效率相同的甲、乙两工人合作要6小时完成，如果甲工人效率提高20%，乙效率不变，问两人合作要几小时完成？
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>

<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>

<gadget id="calculator">(6/5) * (1/12)</gadget>
<output>1/10 = around 0.1</output>

<gadget id="calculator">(1/12) + (1/10)</gadget>
<output>11/60 = around 0.183333</output>

<gadget id="calculator">1 / (11/60)</gadget>
<output>60/11 = around 5.454545</output>

<result>60/11 = around 5.454545</result>