There are two integers A and B, the sum of the digits of A is 8, and the sum of the digits of B is 7, when the two numbers are added, one carry is made, then what is the sum of the digits of A+B?
有A、B两个整数，A的各位数字之和是8，B的各位数字之和为7，两数相加时进位一次，那么A+B的各位数字之和是多少．
<gadget id="calculator">8 + 7</gadget>
<output>15</output>

<gadget id="calculator">15 - 9</gadget>
<output>6</output>

<result>6</result>