For any natural numbers X and Y, define a new operation @:X@Y=((6XY)/(mX+2Y)), where m is a certain natural number. If 1@2=1, then 2@8=how much.
对于任意的自然数X和Y，定义新运算@：X@Y=((6XY)/(mX+2Y))，其中m是一个确定的自然数．如果1@2=1，则2@8=多少．
<gadget id="calculator">6 * 2 * 8</gadget>
<output>96</output>

<gadget id="calculator">8 * 2</gadget>
<output>16</output>

<gadget id="calculator">2 * 8</gadget>
<output>16</output>

<gadget id="calculator">16 + 16</gadget>
<output>32</output>

<gadget id="calculator">96 / 32</gadget>
<output>3</output>

<result>3</result>