Both numbers A and B contain only prime factors 3 and 2, and their greatest common divisor is 36. It is known that A has 12 divisors, and B has 9 divisors. So what is the minimum value of A+B?
A、B两数都只含有质因数3和2，他们的最大公约数为36，已知A有12个约数，B有9个约数．那么A+B的最小值是多少．
<gadget id="calculator">2 * 3</gadget>
<output>6</output>

<gadget id="calculator">6 ** 2</gadget>
<output>36</output>

<gadget id="calculator">36 * 2</gadget>
<output>72</output>

<gadget id="calculator">36 + 72</gadget>
<output>108</output>

<result>108</result>