According to regulations, Xiaoming's mathematics comprehensive evaluation score this semester is equal to the sum of half of the average score of the four tests and half of the final exam score. It is known that the scores of the four tests are 90 points, 85 points, 77 points, and 96 points respectively. If Xiaoming wants to achieve a score of no less than 90 in the comprehensive assessment, what is the minimum score he must score in the final exam.
按规定，晓明这学期数学的综合测评成绩等于4次测验平均分的一半与期末考试成绩的一半之和．已知4次测验的成绩分别是90分，85分，77分，96分．若晓明要使综合测评成绩不低于90分，则他在期末考试中至少要考多少分．
<gadget id="calculator">90 + 85 + 77 + 96</gadget>
<output>348</output>

<gadget id="calculator">348 / 4</gadget>
<output>87</output>

<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>

<gadget id="calculator">87 * (1/2)</gadget>
<output>87/2 = around 43.5</output>

<gadget id="calculator">90 - (87/2)</gadget>
<output>93/2 = around 46.5</output>

<gadget id="calculator">(93/2) / (1/2)</gadget>
<output>93</output>

<result>93</result>