A group of cyclists are doing pre-competition training on a narrow road, and they are moving forward at a speed of 35 kilometers per hour. Athlete A suddenly leaves the group, drives forward for 10 kilometers at a speed of 45 kilometers per hour, then turns back, drives at the same speed, and rejoins the group. The time period between Athlete A leaving the group and rejoining the group is How many.
一组自行车运动员在一条不宽的道路上作赛前训练，他们以每小时35千米的速度向前行驶．突然运动员甲离开小组，以每小时45千米的速度向前行驶10千米，然后转回来，以同样的速度行驶，重新和小组汇合，运动员甲从离开小组到重新和小组汇合这段时间是多少．
<gadget id="calculator">10 / 45</gadget>
<output>2/9 = around 0.222222</output>

<gadget id="calculator">35 * (2/9)</gadget>
<output>70/9 = around 7.777778</output>

<gadget id="calculator">10 - (70/9)</gadget>
<output>20/9 = around 2.222222</output>

<gadget id="calculator">45 + 35</gadget>
<output>80</output>

<gadget id="calculator">(20/9) / 80</gadget>
<output>1/36 = around 0.027778</output>

<gadget id="calculator">(1/36) + (2/9)</gadget>
<output>1/4 = around 0.25</output>

<result>1/4 = around 0.25</result>