There are four consecutive natural numbers, their least common multiple is 60, the product of these four numbers is 120, what is the sum of these four numbers.
有四个连续的自然数，它们的最小公倍数是60，这四个数的乘积是120，这四个数的和是多少．
<gadget id="calculator">2 + 3 + 4 + 5</gadget>
<output>14</output>

<result>14</result>