For a pile of coal, all (2/7) was transported in the morning, and 6 tons more than the remaining (1/3) was transported in the afternoon, and finally 14 tons were left untransported. How many tons are there in total in this pile of coal?
一堆煤，上午运走了全部的(2/7)，下午运的比余下的(1/3)还多6吨，最后还剩14吨没有运，这堆煤共有多少吨？
<gadget id="calculator">14 + 6</gadget>
<output>20</output>

<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>

<gadget id="calculator">20 / (2/3)</gadget>
<output>30</output>

<gadget id="calculator">2 / 7</gadget>
<output>2/7 = around 0.285714</output>

<gadget id="calculator">1 - (2/7)</gadget>
<output>5/7 = around 0.714286</output>

<gadget id="calculator">30 / (5/7)</gadget>
<output>42</output>

<result>42</result>