Two people, A and B, set off from A and B at the same time, and walk toward each other, and they meet after (5/2) minutes; when they meet, A travels (1/4) longer than B, so how many minutes should A be ahead of B? Arrive at the starting point of the other party.
甲乙二人从A，B两地同时出发，相向而行，经(5/2)分钟二人相遇；相遇时甲比乙多行(1/4)的路，那么甲比乙应提前多少分钟到达对方的出发地．
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>

<gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>

<gadget id="calculator">(5/4) / 2 / (5/2)</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>

<gadget id="calculator">(3/4) / 2 / (5/2)</gadget>
<output>3/20 = around 0.15</output>

<gadget id="calculator">(5/4) / 2 / (3/20)</gadget>
<output>25/6 = around 4.166667</output>

<gadget id="calculator">(3/4) / 2 / (1/4)</gadget>
<output>3/2 = around 1.5</output>

<gadget id="calculator">(25/6) - (3/2)</gadget>
<output>8/3 = around 2.666667</output>

<result>8/3 = around 2.666667</result>