Both a and b are positive integers, a≠b, and (90a+102b) is exactly a perfect square number, so what is the minimum value of (a+b)?
a、b均为正整数，a≠b，且(90a+102b)正好是一个完全平方数，那么，(a+b)的最小值为多少？
<gadget id="calculator">11 + 3</gadget>
<output>14</output>

<result>14</result>