The first three numbers in a column are 1, 7, and 8 in turn, and each subsequent number is the remainder obtained by dividing the sum of the previous three adjacent numbers by 4. What is the sum of the first 2011 numbers in this column?
一列数的前三个依次是1，7，8，以后每个都是它前面相邻三个数之和除以4所得的余数，则这列数中的前2011个数的和是多少．
<gadget id="calculator">0 + 3 + 3 + 2 + 0 + 1 + 3 + 0</gadget>
<output>12</output>

<gadget id="calculator">2_011 - 3</gadget>
<output>2_008</output>

<gadget id="calculator">2_008 / 8</gadget>
<output>251</output>

<gadget id="calculator">12 * 251</gadget>
<output>3_012</output>

<gadget id="calculator">3_012 + 1 + 7 + 8</gadget>
<output>3_028</output>

<result>3_028</result>