There are five numbers A, B, C, D, E, A is 80, B is 9 less than the average of the five numbers, C is 89, D is 4 more than the average of the five numbers, E is 2 more than D, How much is E?
有A、B、C、D、E五个数，A是80，B比五个数的平均数少9，C是89，D比五个数的平均数多4，E比D多2，求E是多少？
<gadget id="calculator">80 / 5</gadget>
<output>16</output>

<gadget id="calculator">89 / 5</gadget>
<output>89/5 = around 17.8</output>

<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>

<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>

<gadget id="calculator">9 / 5</gadget>
<output>9/5 = around 1.8</output>

<gadget id="calculator">(2/5) - (9/5)</gadget>
<output>-7/5 = around -1.4</output>

<gadget id="calculator">16 + (89/5) + (4/5) + (4/5) + (-7/5)</gadget>
<output>34</output>

<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">1 - (1/5) - (1/5) - (1/5)</gadget>
<output>2/5 = around 0.4</output>

<gadget id="calculator">34 / (2/5)</gadget>
<output>85</output>

<gadget id="calculator">85 + 4 + 2</gadget>
<output>91</output>

<result>91</result>