Among the five persons A, B, C, D, and E, the sum of the average ages of four of them plus the age of the remaining one is 37, 40, 49, 58, and 64 respectively. How much older is the oldest than the youngest.
A，B，C，D，E五个人中，其中任取4个人的平均年龄再加上余下一个人的年龄所得的和分别为37，40，49，58，64，则这五个人中年龄最大的比年龄最小的大多少岁．
<gadget id="calculator">64 * 4</gadget>
<output>256</output>

<gadget id="calculator">37 * 4</gadget>
<output>148</output>

<gadget id="calculator">256 - 148</gadget>
<output>108</output>

<gadget id="calculator">108 / 3</gadget>
<output>36</output>

<result>36</result>