Randomly select 3 of the 4 integers, find their average, and then calculate the sum of the average and the remaining 1 number, so that you can get 4 numbers: 4, 6, 5 (1/3) and 4(2/3), what is the sum of the originally given 4 integers?
从4个整数中任意选出3个，求出它们的平均值，然后再求这个平均值和余下1个数的和，这样可以得到4个数：4、6、5(1/3)和4(2/3)，则原来给定的4个整数的和为多少．
<result>10</result>