There is some alcohol solution with 30% alcohol content, and after adding a certain amount of water, it is diluted into a solution with 24% alcohol content. If the same amount of water is added, what will be the alcohol content of the liquid?
有酒精含量为30%的酒精溶液若干，加了一定数量的水后稀释成酒精含量为24%的溶液，如果再加入同样多的水，那么液体酒精含量将变为多少．
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>

<gadget id="calculator">100 * (3/10)</gadget>
<output>30</output>

<gadget id="calculator">24 / 100</gadget>
<output>6/25 = around 0.24</output>

<gadget id="calculator">100 * (6/25)</gadget>
<output>24</output>

<gadget id="calculator">30 - 24</gadget>
<output>6</output>

<gadget id="calculator">6 / (6/25)</gadget>
<output>25</output>

<gadget id="calculator">100 + 25 + 25</gadget>
<output>150</output>

<gadget id="calculator">(3/10) / 150</gadget>
<output>1/500 = around 0.002</output>

<gadget id="calculator">100 * (1/500)</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">100 / 100</gadget>
<output>1</output>

<gadget id="calculator">(1/5) * 1</gadget>
<output>1/5 = around 0.2</output>

<result>1/5 = around 0.2</result>