Two people, A and B, start from A and B at the same time and walk towards each other. They meet at C, and they make an appointment: After meeting, they continue to move forward, and when they arrive at B and A, they turn back immediately and wait at C on a first-come-first-served basis. ． As a result, B waited at C for 14 minutes before A arrived. If A walks 60 meters per minute and B walks 80 meters per minute, what is the distance between A and B in meters?
甲、乙二人分别从A、B两地同时出发相向而行，于C处相遇，两人相约：相遇后彼此继续前行，分别到达B和A后立即折返，在C处先到先等．结果乙在C处等了14分钟，甲才到达．已知甲每分钟行走60米，乙每分钟行走80米，则A、B两地相距多少米．
<gadget id="calculator">14 * 80</gadget>
<output>1_120</output>

<gadget id="calculator">11 / 7</gadget>
<output>11/7 = around 1.571429</output>

<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>

<gadget id="calculator">(11/7) * (1/60) * 80</gadget>
<output>44/21 = around 2.095238</output>

<gadget id="calculator">10 / 7</gadget>
<output>10/7 = around 1.428571</output>

<gadget id="calculator">(44/21) - (10/7)</gadget>
<output>2/3 = around 0.666667</output>

<gadget id="calculator">1_120 / (2/3)</gadget>
<output>1_680</output>

<result>1_680</result>