A mathematics competition originally scheduled 10 first prizes and 20 second prizes. First, the last 4 people in the first prize are adjusted to the second prize, so that the average score of the first prize is increased by 3 points, and the average score of the second prize is increased by 2 points. Then the average score of the original first prize is higher than the average score of the second prize.
某此数学竞赛原定一等奖10人，二等奖20人．先将一等奖中最后4人调整为二等奖，这样得一等奖的平均分提高了3分，得二等奖的平均分提高了2分．则原一等奖平均分比二等奖平均分高多少分．
<gadget id="calculator">20 + 4</gadget>
<output>24</output>

<gadget id="calculator">24 * 2</gadget>
<output>48</output>

<gadget id="calculator">10 - 4</gadget>
<output>6</output>

<gadget id="calculator">6 * 3</gadget>
<output>18</output>

<gadget id="calculator">48 + 18</gadget>
<output>66</output>

<gadget id="calculator">66 / 4</gadget>
<output>33/2 = around 16.5</output>

<result>33/2 = around 16.5</result>