There are six positive integers lined up, their average is 4.5, the average of the first four numbers is 4, and the average of the last three numbers is (19/3), what is the smallest continuous product of these six numbers ?
有六个正整数排成一列，它们的平均数是4.5，前4个数的平均数是4，后三个数的平均数是(19/3)，这六个数的连乘积最小是多少？
<gadget id="calculator">4 * 4</gadget>
<output>16</output>

<gadget id="calculator">19 / 3</gadget>
<output>19/3 = around 6.333333</output>

<gadget id="calculator">(19/3) * 3</gadget>
<output>19</output>

<gadget id="calculator">4.5 * 6</gadget>
<output>27</output>

<gadget id="calculator">19 - 27</gadget>
<output>-8</output>

<gadget id="calculator">16 + (-8)</gadget>
<output>8</output>

<gadget id="calculator">16 - 8</gadget>
<output>8</output>

<gadget id="calculator">1 * 1 * 6 * 8 * 1 * 10</gadget>
<output>480</output>

<result>480</result>