Find the smallest integer that can be divisible by 5, 10 when divided by 715, 140 when divided by 247, 245 when divided by 391, and 109 when divided by 187. To explain the process of answering.
求能被5整除，被715除余10，被247除余140，被391除余245，被187除余109的最小整数．要说出解答过程．
<gadget id="calculator">715 * 14</gadget>
<output>10_010</output>

<gadget id="calculator">10_010 + 10</gadget>
<output>10_020</output>

<result>10_020</result>