A and B set off from A and B at the same time and walk towards each other. When they start, their speed ratio is 6:5. After they meet for the first time, A’s speed decreases by 20%, while B’s speed increases. 20%, so that when B arrives at A, A is still 128 meters away from B, then the distance between A and B is: how much.
甲，乙两人分别从A，B两地同时出发，相向而行，出发时他们的速度比是6：5，他们第一次相遇后，甲的速度降低了20%，乙的速度提高了20%，这样当乙到达A地时，甲离B地还有128米，那么A，B两地的距离是：多少．
<gadget id="calculator">6 + 5</gadget>
<output>11</output>

<gadget id="calculator">6 / 11</gadget>
<output>6/11 = around 0.545455</output>

<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>

<gadget id="calculator">6 * (4/5)</gadget>
<output>24/5 = around 4.8</output>

<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>

<gadget id="calculator">5 * (6/5)</gadget>
<output>6</output>

<gadget id="calculator">(24/5) / 6</gadget>
<output>4/5 = around 0.8</output>

<gadget id="calculator">(6/11) * (4/5)</gadget>
<output>24/55 = around 0.436364</output>

<gadget id="calculator">1 - (6/11) - (24/55)</gadget>
<output>1/55 = around 0.018182</output>

<gadget id="calculator">128 / (1/55)</gadget>
<output>7_040</output>

<result>7_040</result>