There is a series of numbers 2, 5, 4, 5, ..., starting from the third number, each number is equal to the remainder of 2 times the previous number and the sum of the previous second number divided by 8. What is the sum of the first 100 numbers?
有一串数字2，5，4，5，…，从第三个数字起，每个数都等于它前面一个数字的2倍与前面第二个数字的和除以8的余数．前100个数字的和是多少．
<gadget id="calculator">2 + 5 + 4 + 5 + 6 + 1 + 0 + 1</gadget>
<output>24</output>

<gadget id="calculator">24 * 12</gadget>
<output>288</output>

<gadget id="calculator">2 + 5 + 4 + 5</gadget>
<output>16</output>

<gadget id="calculator">288 + 16</gadget>
<output>304</output>

<result>304</result>