A, B, and C are three consecutive even numbers, and the sum of their reciprocals is (37/120), then what is the sum of A, B, and C?
A、B、C是三个连续偶数，它们的倒数和是(37/120)，则A、B、C的和是多少．
<gadget id="calculator">2 * 2 * 2</gadget>
<output>8</output>

<gadget id="calculator">5 * 2</gadget>
<output>10</output>

<gadget id="calculator">6 * 2</gadget>
<output>12</output>

<gadget id="calculator">8 + 10 + 12</gadget>
<output>30</output>

<result>30</result>