There are three engineering teams A, B, and C cooperating in a project. If teams B and C cooperate for 3 days first, then A can complete the project in 1 day (11/40); if A and B cooperate for 3 days first, C can complete the project for 1 more day (37/120); if A and C cooperate for 6 days, and B can complete the project for 2 more days (7/12), then if A works for 2 days first, B then If you work for 3 days and C for another 4 days, how much of the project can be completed?
一项工程有甲、乙、丙三个工程队合作，如果乙、丙两队先合作3天，甲再做1天能完成工程的(11/40)；如果甲、乙先合作3天，丙再做1天，能完成工程的(37/120)；如果甲、丙合作6天，乙再做2天，能完成工程的(7/12)，那么若甲先做2天，乙再做3天，丙再做4天，能完成工程的多少？
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>

<gadget id="calculator">(1/20) * 2</gadget>
<output>1/10 = around 0.1</output>

<gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>

<gadget id="calculator">(1/24) * 3</gadget>
<output>1/8 = around 0.125</output>

<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>

<gadget id="calculator">(1/30) * 4</gadget>
<output>2/15 = around 0.133333</output>

<gadget id="calculator">(1/10) + (1/8) + (2/15)</gadget>
<output>43/120 = around 0.358333</output>

<result>43/120 = around 0.358333</result>