In the equation 1*2*3*...*99*100=12n*M, M and n are both natural numbers. What is the maximum value of n?
在等式1*2*3*…*99*100=12n*M中，M，n都是自然数，n最大可以取几？
<gadget id="calculator">33 + 11 + 3 + 1</gadget>
<output>48</output>

<result>48</result>