A 48 cm long iron wire is made into a cuboid frame (the loss at the joint is not counted), and the ratio of length, width, and height is 3:2:1. What is the area of the smallest surface of the cuboid frame in square centimeters?
把一根长是48厘米的铁丝做成一个长方体框架(接头处损耗不计)，已经长、宽、高的比为3：2：1，这个长方体框架最小的一个面的面积是多少平方厘米．
<gadget id="calculator">48 / 4</gadget>
<output>12</output>

<gadget id="calculator">3 + 2 + 1</gadget>
<output>6</output>

<gadget id="calculator">3 / 6</gadget>
<output>1/2 = around 0.5</output>

<gadget id="calculator">12 * (1/2)</gadget>
<output>6</output>

<gadget id="calculator">2 / 6</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">12 * (1/3)</gadget>
<output>4</output>

<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>

<gadget id="calculator">4 * 12 * (1/6)</gadget>
<output>8</output>

<result>8</result>