Arrange the numbers of all the dates in 2011 in order to form a string: 1234567891011...3031123.... Then the "8" in July 8 is ranked in the number string.
将2011年的所有日期的数字依次排列在一起，组成一个数串：1234567891011…3031123…．则7月8日中的"8"排在数串的第多少位．
<gadget id="calculator">31 + 28 + 31 + 30 + 31 + 30</gadget>
<output>181</output>

<gadget id="calculator">2 * 181</gadget>
<output>362</output>

<gadget id="calculator">6 * 9</gadget>
<output>54</output>

<gadget id="calculator">362 - 54</gadget>
<output>308</output>

<gadget id="calculator">308 + 8</gadget>
<output>316</output>

<result>316</result>