There is a cube with "1" written on one face, "2" written on two faces, and "3" written on three faces. What is the probability that the number facing up is an odd number after the cube is thrown up?
有一个正方体，它的1个面上写着"1"，2个面上写着"2"，3个面上写着"3"．抛起这个正方体，落下后，朝上的数是奇数的可能性是多少
<gadget id="calculator">1 + 3</gadget>
<output>4</output>

<gadget id="calculator">4 / 6</gadget>
<output>2/3 = around 0.666667</output>

<result>2/3 = around 0.666667</result>