There are two water pipes, A and B, which respectively fill water into two pools of the same size, A and B, at the same time. After 2+1/3 hours, the sum of the water injected into pools A and B is exactly one pool. At this time, the water injection speed of pipe A increases by 25%, and the water injection speed of pipe B remains unchanged. Then, when pipe A fills pool A, how many hours will it take for pipe B to fill pool B?
有甲、乙两根水管，分别同时给A、B两个大小相同的水池注水，在相同的时间里甲、乙两管注水量之比是7：5．经过2+1/3小时，A，B两池中注入的水之和恰好是一池．这时，甲管注水速度提高25%，乙管的注水速度不变，那么，当甲管注满A池时，乙管再经过多少小时注满B池？
<gadget id="calculator">7 + 5</gadget>
<output>12</output>

<gadget id="calculator">7 / 12</gadget>
<output>7/12 = around 0.583333</output>

<gadget id="calculator">7 / 3</gadget>
<output>7/3 = around 2.333333</output>

<gadget id="calculator">(7/12) / (7/3)</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">5 / 7</gadget>
<output>5/7 = around 0.714286</output>

<gadget id="calculator">(1/4) * (5/7)</gadget>
<output>5/28 = around 0.178571</output>

<gadget id="calculator">1 / (5/28)</gadget>
<output>28/5 = around 5.6</output>

<gadget id="calculator">5 / 12</gadget>
<output>5/12 = around 0.416667</output>

<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>

<gadget id="calculator">(1/4) * (5/4)</gadget>
<output>5/16 = around 0.3125</output>

<gadget id="calculator">(5/12) / (5/16)</gadget>
<output>4/3 = around 1.333333</output>

<gadget id="calculator">(28/5) - (7/3) - (4/3)</gadget>
<output>29/15 = around 1.933333</output>

<result>29/15 = around 1.933333</result>