Known: In △ABC, ∠C=90°, AC=20cm, BC=15cm. Rotate the right-angled triangle once about the axis of side BC. Find the surface area of the resulting solid of revolution.
已知：在△ABC中，∠C=90°，AC=20cm，BC=15cm．以BC边为轴把这个直角三角形旋转一周．求所得的旋转体的表面积．
<result>900</result>