It is known that (1/5) can be expressed as the sum and difference of two unit fractions (1/5)=(1/(A))+(1/(B))=(1/(C)) -(1/(D))(A≠B), then A+B+C+D=how much.
已知(1/5)可以表示为两个单位分数的和与差的形式即(1/5)=(1/(A))+(1/(B))=(1/(C))-(1/(D))(A≠B)，则A+B+C+D=多少．
<gadget id="calculator">30 + 6 + 4 + 20</gadget>
<output>60</output>

<result>60</result>