There are four numbers, choose three of them each time, calculate their average, and add another number, calculate four times in this way, and get the following four numbers respectively: 26, 32, 40, 46 ． So what is the largest number among the original four numbers?
有四个数，每次选取其中三个数，算出它们的平均数，再加上另外的一个数，用这样的方法计算了4次，分别得到以下4个数：26，32，40，46．那么原来四个数中，最大的一个数是多少？
<gadget id="calculator">46 * 3</gadget>
<output>138</output>

<gadget id="calculator">26 + 32 + 40 + 46</gadget>
<output>144</output>

<gadget id="calculator">144 / 2</gadget>
<output>72</output>

<gadget id="calculator">138 - 72</gadget>
<output>66</output>

<gadget id="calculator">66 / 2</gadget>
<output>33</output>

<result>33</result>