There is a road from city A to city B, which is divided into three sections. On the first section, the speed of the car is 40 kilometers per hour. On the second segment, the speed of the car is 90 kilometers per hour, and on the third segment, the speed of the car is 50 kilometers per hour. It is known that the length of the first section of the road is exactly twice that of the third section. Now two cars start from A and B at the same time and drive towards each other. After 1 hour and 20 minutes, they are on the second section (1/ 3) meet at the same place, how many kilometers are the distance between A and B?
从A城到B城有一段公路，分成三段，在第一段上，汽车速度是每小时40千米．在第二段上，汽车速度是每小时90千米，在第三段上，汽车速度是每小时50千米．已知第一段公路的长恰好是第三段的2倍，现在有两辆汽车分别从A、B两城同时出发，相向而行，1小时20分后，在第二段的(1/3)处相遇，那么A、B两城相距多少千米？
<gadget id="calculator">4 / 3</gadget>
<output>4/3 = around 1.333333</output>

<gadget id="calculator">2 * (4/3)</gadget>
<output>8/3 = around 2.666667</output>

<gadget id="calculator">(8/3) - (4/3)</gadget>
<output>4/3 = around 1.333333</output>

<gadget id="calculator">2 / 40</gadget>
<output>1/20 = around 0.05</output>

<gadget id="calculator">2 * (1/20)</gadget>
<output>1/10 = around 0.1</output>

<gadget id="calculator">1 / 50</gadget>
<output>1/50 = around 0.02</output>

<gadget id="calculator">(1/10) - (1/50)</gadget>
<output>2/25 = around 0.08</output>

<gadget id="calculator">(4/3) / (2/25) / 40</gadget>
<output>5/12 = around 0.416667</output>

<gadget id="calculator">2 * (5/12)</gadget>
<output>5/6 = around 0.833333</output>

<gadget id="calculator">(4/3) - (5/6)</gadget>
<output>1/2 = around 0.5</output>

<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">90 / (1/3)</gadget>
<output>270</output>

<gadget id="calculator">(1/2) * 270</gadget>
<output>135</output>

<gadget id="calculator">(4/3) / (2/25)</gadget>
<output>50/3 = around 16.666667</output>

<gadget id="calculator">(50/3) * 3</gadget>
<output>50</output>

<gadget id="calculator">135 + 50</gadget>
<output>185</output>

<result>185</result>