What is the sum of the 49 remainders obtained by dividing the formula 1*2*3*4*5*6*...*1000-6 by 3, 5, 7, 9,..., 99 respectively.
式子1*2*3*4*5*6*…*1000-6分别除以3、5、7、9、…、99得到的49个余数的和是多少．
<result>2_213</result>