If x, y, z represent different natural numbers, x/y=2, z/x=4, zy=56, how much is x+y+z=?
如果用x、y、z分别表示不同的自然数，x/y=2，z/x=4，z-y=56，求x+y+z=多少．
<gadget id="calculator">4 - 0.5</gadget>
<output>3.5</output>

<gadget id="calculator">56 / 3.5</gadget>
<output>16</output>

<gadget id="calculator">4 * 16</gadget>
<output>64</output>

<gadget id="calculator">16 + 8 + 64</gadget>
<output>88</output>

<result>88</result>