Both A and B are two-digit numbers. The tens digit of A is reversed with the ones digit to obtain C, and the tens digit and ones digit of B are reversed to obtain D. The product of C and D is equal to the product of A and B, and The numbers of A and B are all even numbers, and the numbers cannot be exactly the same (such as 24 and 42), what is the maximum sum of A and B?
甲、乙都是两位数，将甲的十位数与个位数对调得丙，将乙的十位数与个位数对调得丁，丙和丁的乘积等于甲和乙的乘积，而甲乙两数的数字全为偶数，并且数字不能完全相同(如24和42)，则甲、乙两数之和最大是多少．
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>

<gadget id="calculator">4 * 3 * 7</gadget>
<output>84</output>

<gadget id="calculator">24 + 84</gadget>
<output>108</output>

<result>108</result>