There are two integers A and B, the sum of the digits of A is 49, the sum of the digits of B is 52, and the two numbers are carried three times when adding the two numbers, then what is the sum of the digits of (A+B).
有A、B两个整数，A的各位数字之和为49，B的各位数字之和为52，两数相加时进位三次，那么(A+B)的各位数字之和是多少．
<gadget id="calculator">49 + 52</gadget>
<output>101</output>

<gadget id="calculator">9 * 3</gadget>
<output>27</output>

<gadget id="calculator">101 - 27</gadget>
<output>74</output>

<result>74</result>