A cuboid container, the bottom surface is a square with a side length of 50 cm, and a cuboid iron block with a height of 1 meter and a side length of 10 cm stands upright in the container. At this time, the water depth in the container is 40 cm. If the iron block is lifted up slightly by 24 cm, how many centimeters is the length of the part of the iron block exposed to the water that is wetted by water?
一个长方体容器，底面是一个边长50厘米的正方形，容器中直立着一个高1米、底面是边长10厘米的正方形的长方体铁块，这时容器中的水深40厘米．如果把铁块轻轻上提24厘米，那么，露出水面的铁块上被水浸湿的部分长多少厘米？
<gadget id="calculator">50 * 50</gadget>
<output>2_500</output>

<gadget id="calculator">24 / 2_500</gadget>
<output>6/625 = around 0.0096</output>

<gadget id="calculator">10 * 10 * (6/625)</gadget>
<output>24/25 = around 0.96</output>

<gadget id="calculator">24 + (24/25)</gadget>
<output>624/25 = around 24.96</output>

<result>624/25 = around 24.96</result>