The sum of 8 different non-zero natural numbers is 56. If the largest number and the smallest number are removed, the sum of the remaining numbers is 44. Question: Among the remaining numbers, what is the smallest number?
8个互不相同的非零自然数的总和是56，如果去掉最大的数及最小的数，那么剩下的数的总和是44．问：剩下的数中，最小的数是多少？
<result>4</result>