Three masters and apprentices work together to process a batch of parts in 5 days. Among them, the work completed by apprentice A belongs to apprentice B (1/2), and the work completed by apprentice B belongs to the master (1/2). If apprentice A alone does 2 Two days later, how many days will it take for apprentice B and the master to complete the remaining work?
师徒三人合作加工一批零件5天可以完成，其中徒弟甲完成的工作是徒弟乙的(1/2)，徒弟乙完成的工作是师傅的(1/2)，如果徒弟甲一人做2天后，徒弟乙和师傅合作余下的工作，还要几天完成？
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">2 / 1</gadget>
<output>2</output>

<gadget id="calculator">1 + 2 + 4</gadget>
<output>7</output>

<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>

<gadget id="calculator">(1/5) * (1/7) * 2</gadget>
<output>2/35 = around 0.057143</output>

<gadget id="calculator">1 - (2/35)</gadget>
<output>33/35 = around 0.942857</output>

<gadget id="calculator">2 + 4</gadget>
<output>6</output>

<gadget id="calculator">6 / 7</gadget>
<output>6/7 = around 0.857143</output>

<gadget id="calculator">(1/5) * (6/7)</gadget>
<output>6/35 = around 0.171429</output>

<gadget id="calculator">(33/35) / (6/35)</gadget>
<output>11/2 = around 5.5</output>

<result>11/2 = around 5.5</result>