If a metal cone with a bottom radius of 10cm and a height of 9cm is fully immersed in a cylindrical tank with an inner bottom radius of 20cm (the water does not overflow), how many centimeters will the water level in the tank rise?
将一个底面半径是10cm，高为9cm的金属圆锥全部浸没在内底面半径是20cm的圆柱形水槽中(水未溢出)，水槽中的水面会升高多少厘米？
<gadget id="calculator">10 ** 2</gadget>
<output>100</output>

<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">3.14 * 20 * 20</gadget>
<output>1_256</output>

<gadget id="calculator">(1/3) / 1_256</gadget>
<output>1/3_768 = around 0.000265</output>

<gadget id="calculator">3.14 * 100 * 9 * (1/3_768)</gadget>
<output>0.75</output>

<result>0.75</result>