There is a two-digit number, the number in the tens place is less than the number in the ones place 3. If the ones and tens digits of these two digits are reversed, the sum of the new two digits obtained and the original number is 121. So what is the original number.
有一个两位数，十位上的数字比个位上的数字少3．如果把这两位数的个位与十位上的数字对调，所得的新两位数与原数和是121．那么原数是多少．
<result>47</result>