It is known that A and B are 300 meters apart. A and B start from A and B respectively at the same time. Walk towards each other and meet at a distance of 140 meters from point A; if B travels more than 1 meter per second, the place where the two meet is 180 meters away from point B. So what is the original speed of B in meters per second?
已知A，B两地相距300米．甲乙两人同时分别从A，B两地出发．相向而行，在距A地140米处相遇；如果乙每秒多行1米，则两人相遇处距B地180米．那么乙原来的速度是每秒多少米．
<gadget id="calculator">300 - 180</gadget>
<output>120</output>

<gadget id="calculator">180 * 7</gadget>
<output>1_260</output>

<gadget id="calculator">180 * 8</gadget>
<output>1_440</output>

<gadget id="calculator">300 * 8</gadget>
<output>2_400</output>

<gadget id="calculator">1_440 - 2_400</gadget>
<output>-960</output>

<gadget id="calculator">1_260 + (-960)</gadget>
<output>300</output>

<gadget id="calculator">120 / 300</gadget>
<output>2/5 = around 0.4</output>

<gadget id="calculator">(2/5) * 8</gadget>
<output>16/5 = around 3.2</output>

<result>16/5 = around 3.2</result>