A certain city held a mathematics competition, with a number of first, second and third prizes. The number of people who won the first and second prizes accounted for (1/3) of the total number of winners, the number of people who won the first and third prizes accounted for (7/9) of the total number of winners, and the number of people who won the first prize accounted for a few percent of the total number of winners. How much?
某市举办数学竞赛，设一、二、三等奖若干名．获一、二等奖的人数占获奖总人数的(1/3)，获一、三等奖的人数占获奖总人数的(7/9)，获一等奖的人数占获奖总人数的几分之几？
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">7 / 9</gadget>
<output>7/9 = around 0.777778</output>

<gadget id="calculator">(7/9) - 1</gadget>
<output>-2/9 = around -0.222222</output>

<gadget id="calculator">(1/3) + (-2/9)</gadget>
<output>1/9 = around 0.111111</output>

<result>1/9 = around 0.111111</result>