The sum of 8 different natural numbers not equal to zero is 45. If the largest number and the smallest number are removed, the sum of the remaining 6 numbers is 33. Q: What is the smallest number among the remaining numbers?
8个互不相同的不等于零的自然数的和是45，如果去掉最大数和最小数，那么剩下的6个数的和是33，问：剩下的数中最小数是多少？
<result>2</result>