A three-digit number is said to be "eaten" by another three-digit number if each of its digits does not exceed the corresponding digit of the other three-digit number. It also stipulates that "any number can be eaten by its same number". For example, 241 is "eaten" by 342, and 123 is "eaten" by 123, but neither 240 nor 223 can be "eaten" by each other. Now please design 6 three-digit numbers, none of them can be "eaten" by the other 5, and their hundreds digits are only allowed to take 1, 2; tens digits are only allowed to take 1, 2, 3; The ones digit is only allowed to take 1, 2, 3, 4, so what is the sum of these 6 three-digit numbers.
一个三位数，如果它的每一位数字都不超过另一个三位数对应数位上的数字，那么就称它被另一个三位数"吃掉"．又规定"任何数都可以被它相同的数吃掉"．比如，241被342"吃掉"，123被123"吃掉"，但是240和223互相都不能被"吃掉"．现请你设计出6个三位数，它们中的任何一个都不能被另外5个"吃掉"，并且它们的百位数字只允许取1，2；十位数字只允许取1，2，3；个位数字只允许取1，2，3，4，那么这6个三位数之和是多少．
<gadget id="calculator">114 + 123 + 132 + 213 + 222 + 231</gadget>
<output>1_035</output>

<result>1_035</result>