A batch of parts, after A and B work together for 4 days, A will finish it alone in 6 days. If A makes more (1/80) of this batch of parts than B every day, and A can complete 60 parts per day, what is the total number of parts in this batch?
一批零件，甲乙合做4天后，再由甲单独做6天完成．如果甲比乙每天多做这批零件的(1/80)，而甲每天可完成零件60个，这批零件的总数是多少个？
<gadget id="calculator">6 * 60</gadget>
<output>360</output>

<gadget id="calculator">4 * 60</gadget>
<output>240</output>

<gadget id="calculator">60 * 4</gadget>
<output>240</output>

<gadget id="calculator">360 + 240 + 240</gadget>
<output>840</output>

<gadget id="calculator">1 / 80</gadget>
<output>1/80 = around 0.0125</output>

<gadget id="calculator">(1/80) * 4</gadget>
<output>1/20 = around 0.05</output>

<gadget id="calculator">(1/20) + 1</gadget>
<output>21/20 = around 1.05</output>

<gadget id="calculator">840 / (21/20)</gadget>
<output>800</output>

<result>800</result>