Now define two operations "⊕" and "*". For any two integers, a⊕b=a+b-1, a*b=a*b-1, then the result of 6⊕8*(3⊕5) how many.
现定义两种运算"⊕""*"，对于任意两个整数，a⊕b=a+b-1，a*b=a*b-1，则6⊕8*(3⊕5)的结果是多少．
<gadget id="calculator">8 - 1</gadget>
<output>7</output>

<gadget id="calculator">6 + 7</gadget>
<output>13</output>

<gadget id="calculator">13 * 7</gadget>
<output>91</output>

<gadget id="calculator">91 - 1</gadget>
<output>90</output>

<result>90</result>