There are 8 unequal integers arranged in a row from small to large. It is known that the first 3 integers are 2, 7, and 14 respectively. The average of these 8 numbers is 25. So, what is the last integer at least?
有8个互不相等的整数由小到大排成一行，已知前面3个整数分别为2、7、14，这8个数的平均数是25，那么，最后一个整数至少为几？
<result>38</result>