If the natural number n makes no carry phenomenon occur when doing continuous addition n+(n+1)+(n+2), then n is called a "continuous number". For example, 12+13+14 does not produce carry phenomenon, so 12 It is a continuous number, but 13+14+15 produces a carry phenomenon, so 12 is a continuous number, how many consecutive numbers do not exceed 200?
若自然数n使得作连式加法n+(n+1)+(n+2)时均不产生进位现象，便称n为"连绵数"，如因为12+13+14不产生进位现象，所以12是连绵数，但13+14+15产生进位现象，所以12是连绵数，则不超过200的连绵数有多少个．
<gadget id="calculator">3 * 4 * 2</gadget>
<output>24</output>

<result>24</result>