A steel mill saved 250,000 kW/h of electricity in the first two months of this year. According to this calculation, how many kilowatts/hours of electricity can be saved in one year (12 months)? (Solve with ratio)
某钢厂今年头2个月节约用电250000千瓦/时．照这样计算，一年(12个月)可节约电多少千瓦/时？(用比例解)
<gadget id="calculator">250_000 / 2</gadget>
<output>125_000</output>

<gadget id="calculator">125_000 * 12</gadget>
<output>1_500_000</output>

<result>1_500_000</result>