After converting the fractions a(3/5), b(3/4), and c(5/9) into the simplest improper fractions, the numerators are exactly the same, so what is the minimum value of a+b+c?
将带分数a(3/5)、b(3/4)、c(5/9)化成最简假分数后，分子恰好相同，那么a+b+c最小值为多少．
<gadget id="calculator">4 + 5 + 2</gadget>
<output>11</output>

<result>11</result>