There are five non-zero natural numbers that are not equal to each other. If one of the swords is 45 less, and the other four numbers are doubled, then these five numbers are still obtained. What is the sum of these five numbers?
有五个互不相等的非零自然数．如果其中一个剑少45，另外四个数都变成原先的2倍，那么得到的仍然是这五个数．这五个数的总和是多少．
<gadget id="calculator">1 + 2 + 4 + 8 + 16</gadget>
<output>31</output>

<gadget id="calculator">45 / 15</gadget>
<output>3</output>

<gadget id="calculator">31 * 3</gadget>
<output>93</output>

<result>93</result>