There are a bunch of buildings that need to be removed, and it is the first time to remove (1/2008) of the total amount. The remaining (2/(2008-1)) was removed for the second time, the remaining (3/(2008-3)) was removed for the third time, and the remaining (4/(2008-6)) was removed for the fourth time , the remaining (5/(2008-10)) is transported away for the fifth time, and the transport continues in sequence. After 49 transports, what is the total amount of the remaining waste.
现有一堆建筑需要清运，它第一次运走总量的(1/2008)．第二次运走余下的(2/(2008-1))，第三次运走余下的(3/(2008-3))，第四次运走余下的(4/(2008-6))，第五次运走余下的(5/(2008-10))，依次规律继续运下去，当运走49次后，余下废料是总量的多少．
<gadget id="calculator">2_008 - 48</gadget>
<output>1_960</output>

<gadget id="calculator">49 / 1_960</gadget>
<output>1/40 = around 0.025</output>

<result>1/40 = around 0.025</result>