a, b and c are natural numbers with two digits, the ones digit of a and b are 7 and 5 respectively, and the tens digit of c is 1. If they satisfy the equation ab+c=2005, then a+b+c=how much.
a，b和c都是二位的自然数，a，b的个位分别是7与5，c的十位是1．如果它们满足等式ab+c=2005，则a+b+c=多少．
<gadget id="calculator">57 + 35 + 10</gadget>
<output>102</output>

<result>102</result>