In a mathematics competition, there are only three possibilities for each team to score 0 points, 3 points and 5 points for each question. At the end of the game, the sum of the total points of three teams is 32 points. If any one of the teams can reach 32 points, how many different situations are there for the total points of these three teams?
一次数学竞赛中，参赛各队每题的得分只有0分、3分和5分三种可能．比赛结束时，有三个队的总得分之和为32分，若任何一个队的总得分都可能达到32分，那么这三个队的总得分有多少种不同的情况？
<gadget id="calculator">55 * 3</gadget>
<output>165</output>

<gadget id="calculator">5 + 4 + 3 + 2 + 1</gadget>
<output>15</output>

<gadget id="calculator">15 - 9</gadget>
<output>6</output>

<gadget id="calculator">15 * 6</gadget>
<output>90</output>

<gadget id="calculator">165 + 90</gadget>
<output>255</output>

<result>255</result>