Two people, A and B, set off from A and B respectively at the same time, and go in the same direction. A catches up with B 20 minutes after departure; if A's speed becomes 1.5 times the original speed, then 10 minutes after departure, A catches up with B. Then if A's speed doubles, how many minutes after starting to catch up with B?
甲、乙二人分别从A、B两地同时出发，同向而行，出发后20分钟甲追上乙；如果甲的速度变为原来的1.5倍，则出发后10分钟追上乙．那么如果甲的速度变为原来的2倍，出发后多少分钟追上乙．
<gadget id="calculator">20 / 3</gadget>
<output>20/3 = around 6.666667</output>

<result>20/3 = around 6.666667</result>