Among the five numbers, the average of the four numbers is randomly taken and the remaining one is added. The resulting sums are 74, 80, 98, 116, and 128 respectively. Then how much is the smallest number among the five numbers smaller than the largest number?
五个数中，任取四个数的平均数再加上余下的一个数，所得的和分别是74、80、98、116、128，那么五个数中的最小数比最大数小多少．
<gadget id="calculator">128 * 4</gadget>
<output>512</output>

<gadget id="calculator">74 * 4</gadget>
<output>296</output>

<gadget id="calculator">512 - 296</gadget>
<output>216</output>

<gadget id="calculator">216 / 3</gadget>
<output>72</output>

<result>72</result>