It is known that the radius of the base of an inverted cone is 5, and the height is 10. Place an irregular stone (with a volume of (196/3)π) in the inverted cone and fill it with water. What is the height of the water surface of the inverted cone after the stone is taken out?
己知一个倒立圆锥的底面半径是5，高是10，在倒立圆锥内放置不规则石头(体积为(196/3)π)后注满水，求石头取出后倒立圆锥的水面高度是多少？
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>

<gadget id="calculator">(3/5) * 10</gadget>
<output>6</output>

<result>6</result>