A and B take turns to take candies. A takes one first, then B takes two next, A takes three more, and B takes four again...Continuing in this way, the person who takes candy for the nth time takes n If the remaining sugar is less than n sugars when taking the nth sugar, take all the remaining sugar. It is known that A got a total of 125 candies in the end, may I ask: How many candies did B get in total?
甲、乙两人轮流拿糖，甲先拿一颗，则乙接着拿二颗，甲再拿三颗，乙再拿四颗…依此方式继续下去，第n次取糖的人再取n颗糖，如果第n次取糖时所剩的糖少于n颗糖则拿光所剩的糖．已知甲最后总共拿到125颗糖，请问：乙总共拿到多少颗糖？
<gadget id="calculator">2 + 22</gadget>
<output>24</output>

<gadget id="calculator">11 / 2</gadget>
<output>11/2 = around 5.5</output>

<gadget id="calculator">24 * (11/2)</gadget>
<output>132</output>

<result>132</result>