There are four natural numbers whose sum is 243. If 8 is added to the first number, 8 is subtracted from the second number, 8 is multiplied by the third number, and 8 is divided by the fourth number, the four numbers obtained are equal. Then, what is the product of the largest number and the smallest number among the original four numbers?
有四个自然数，它们的和是243．如果将第一个数加上8，第二数减去8，第三个数乘以8，第四个数除以8，则得到的四个数相等．那么，原来的四个数中最大数与最小数的乘积是多少．
<gadget id="calculator">243 - 8</gadget>
<output>235</output>

<gadget id="calculator">8 + 235</gadget>
<output>243</output>

<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>

<gadget id="calculator">1 + 1 + (1/8) + 8</gadget>
<output>81/8 = around 10.125</output>

<gadget id="calculator">243 / (81/8) / 8</gadget>
<output>3</output>

<gadget id="calculator">243 / (81/8)</gadget>
<output>24</output>

<gadget id="calculator">3 * 24 * 8</gadget>
<output>576</output>

<result>576</result>