Given that two positive integers x and y satisfy x=3y+2, do the following operations: x-7, y-15. After several times, there are still 53 left in x and 7 in y. Find the minimum value of x.
已知两个正整数x和y满足x=3y+2，作如下操作：x-7，y-15．各经若干次后x还剩下53，y还剩下7，求x的最小值．
<gadget id="calculator">7 * 15</gadget>
<output>105</output>

<gadget id="calculator">105 + 53</gadget>
<output>158</output>

<result>158</result>