There is a two-digit number, the number in the tens place is twice the number in the ones place. If you subtract 3 from the tens digit and add 3 to the ones digit, you get a two-digit number. Add this two-digit number to the original two-digit number, and the sum is 141. What is the original two-digit number.
有一个两位数，十位上的数字是个位上数字的2倍．如果把十位上的数减3，个位上的数加3，就得到一个两位数，把这个两位数与原来的两位数相加，和是141．原来的两位数是多少．
<result>84</result>