For a pile of chemical fertilizers, the first time to carry away (2/5) of the total weight, the second time to carry away the remaining (5/9) less than 10 tons, the third time to carry away the remaining 74 tons, and the third time to carry away all of them. How many tons is this pile of fertilizer?
一堆化肥，第一次运走全部重量的(2/5)，第二次运走余下的(5/9)少10吨，第三次运走剩下的74吨，三次全部运完，这堆化肥共有多少吨？
<gadget id="calculator">74 - 10</gadget>
<output>64</output>

<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>

<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>

<gadget id="calculator">5 / 9</gadget>
<output>5/9 = around 0.555556</output>

<gadget id="calculator">(3/5) * (5/9)</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">1 - (2/5) - (1/3)</gadget>
<output>4/15 = around 0.266667</output>

<gadget id="calculator">64 / (4/15)</gadget>
<output>240</output>

<result>240</result>