Two people, A and B, set off from AB at the same time and walk toward each other. A's speed is B's (4/5) when they start. After the first meeting, A's speed increases by 25%, and B's speed increases by 20. %, so that when B arrives at A, A is still 15 kilometers away from B, how many kilometers is the distance between AB and AB?
甲、乙两人分别从AB两地同时出发相向而行，出发时甲的速度是乙的(4/5)，第一次相遇后，甲的速度提高了25%，乙的速度提高了20%，这样当乙到达A地时，甲离B地还有15千米，求AB两地相距多少千米？
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">4 * (1/4)</gadget>
<output>1</output>

<gadget id="calculator">4 + 1</gadget>
<output>5</output>

<gadget id="calculator">4 + 5</gadget>
<output>9</output>

<gadget id="calculator">5 / 9</gadget>
<output>5/9 = around 0.555556</output>

<gadget id="calculator">4 / 9</gadget>
<output>4/9 = around 0.444444</output>

<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">5 * (1/5)</gadget>
<output>1</output>

<gadget id="calculator">5 + 1</gadget>
<output>6</output>

<gadget id="calculator">5 / 6</gadget>
<output>5/6 = around 0.833333</output>

<gadget id="calculator">(4/9) * (5/6)</gadget>
<output>10/27 = around 0.37037</output>

<gadget id="calculator">(5/9) - (10/27)</gadget>
<output>5/27 = around 0.185185</output>

<gadget id="calculator">15 / (5/27)</gadget>
<output>81</output>

<result>81</result>