Choose 3 different numbers from the 8 numbers of 1, 2, 3, ... 7, 8, so that the sum can be divisible by 4 and the product can be divisible by 6, then how many different selection methods are there (selected 3 Different order of number is regarded as the same kind)
从1，2，3，…7，8这8个数中选取3个不同的数，使其和能被4整除而其乘积能被6整除，那么不同的选法共有多少种(选取的3个数次序不同视为同一种)
<gadget id="calculator">2 + 2 + 6 + 2</gadget>
<output>12</output>

<result>12</result>