A series of consecutive natural numbers starting from 5, 5, 6, 7, 8, ..., 17, if one of the numbers is taken away, the average of the remaining numbers is 10.75, so what is the number taken away?
从5开始的一串连续自然数5，6，7，8，…，17，拿走其中一个数，余下的数的平均数是10.75，那么拿走的数是多少．
<gadget id="calculator">5 + 17</gadget>
<output>22</output>

<gadget id="calculator">13 / 2</gadget>
<output>13/2 = around 6.5</output>

<gadget id="calculator">22 * (13/2)</gadget>
<output>143</output>

<gadget id="calculator">10.75 * 12</gadget>
<output>129</output>

<gadget id="calculator">143 - 129</gadget>
<output>14</output>

<result>14</result>