The sum of 200 consecutive natural numbers is 32300. Take out all the even-numbered numbers (2nd, 4th, ..., 200th) and add them up. What is the sum?
200个连续自然数的和是32300，取出其中所有的第偶数个数(第2个，第4个，…，第200个)，将它们相加，则和是多少．
<gadget id="calculator">32_300 + 100</gadget>
<output>32_400</output>

<gadget id="calculator">32_400 / 2</gadget>
<output>16_200</output>

<result>16_200</result>