There is such a formula: 41+14=55, we call numbers like 41 and 14 reversed ordinal numbers, how many pairs of such reversed ordinal numbers with sums within 100 are there.
有这样一个算式：41+14=55，我们把41和14这样的数叫做倒序数，像这样的和在100以内的倒序数有多少对．
<gadget id="calculator">1 + 1 + 2 + 2 + 3 + 3 + 4</gadget>
<output>16</output>

<result>16</result>