Two cars A and B are traveling towards each other on a road parallel to the railway. A train with a length of 180 meters is moving in the same direction as car A at a speed of 60 km/h. It takes 5 minutes for the train to catch up with car A and meet car B. If the train takes 30 seconds from catching up to passing car A, and 6 seconds from meeting B to leaving. How many minutes after car B meets the train, will it meet car A?
甲、乙两辆汽车在与铁路并行的道路上相向而行．一列长180米的火车以60千米/小时的速度与甲车同向前进，火车从追上甲车到遇上乙车，相隔5分钟．若火车从追上到超过甲车用时30秒，从与乙车相遇到离开用时6秒．求乙车遇到火车后再过多少分钟与甲车相遇？
<gadget id="calculator">180 / 30</gadget>
<output>6</output>

<gadget id="calculator">16.67 - 6</gadget>
<output>10.67</output>

<gadget id="calculator">16.67 - 10.67</gadget>
<output>6</output>

<gadget id="calculator">180 / 6</gadget>
<output>30</output>

<gadget id="calculator">30 - 16.67</gadget>
<output>13.33</output>

<gadget id="calculator">10.67 + 13.33</gadget>
<output>24</output>

<gadget id="calculator">6 / 24 / 60</gadget>
<output>1/240 = around 0.004167</output>

<gadget id="calculator">5 * 60 * (1/240)</gadget>
<output>5/4 = around 1.25</output>

<result>5/4 = around 1.25</result>