If 6 times of a certain number is subtracted from 1, the difference obtained is 3, then, what is the sum of 9 times of this number plus 4?
某数的6倍减去1，得到的差为3，那么，这个数的9倍加上4，和是多少．
<gadget id="calculator">3 + 1</gadget>
<output>4</output>

<gadget id="calculator">4 / 6</gadget>
<output>2/3 = around 0.666667</output>

<gadget id="calculator">(2/3) * 9</gadget>
<output>6</output>

<gadget id="calculator">6 + 4</gadget>
<output>10</output>

<result>10</result>