There is a rectangle and a square, both of which have a perimeter of 32 cm. If the length and width of the rectangle and the side lengths of the square are all in centimeters, how many square centimeters is the difference between the area of the rectangle with the smallest area and the area of the square?
有一个长方形和一个正方形，它们的周长都是32厘米．如果长方形的长、宽和正方形的边长都是整厘米数，那么面积最小的长方形和这个正方形面积相差多少平方厘米？
<gadget id="calculator">32 / 4</gadget>
<output>8</output>

<gadget id="calculator">8 * 8</gadget>
<output>64</output>

<gadget id="calculator">32 / 2</gadget>
<output>16</output>

<gadget id="calculator">16 - 1</gadget>
<output>15</output>

<gadget id="calculator">15 * 1</gadget>
<output>15</output>

<gadget id="calculator">64 - 15</gadget>
<output>49</output>

<result>49</result>