For a three-digit number, the tens digit is 0, and the sum of the ones digit and the hundreds digit is 9. If the ones digit and the hundreds digit of this three-digit number are reversed, the new three-digit number obtained is larger than the original one. The three-digit number is greater than 693, find the original three-digit number.
一个三位数，十位上是0，个位和百位上的数字之和是9，如果把这个三位数的个位数与百位数对调，则得到的新三位数比原来的三位数大693，求原来的三位数．
<result>108</result>