There are three stations A, B, and C in sequence along the route, and the distance from A to B is the same as the distance from B to C. Both A and B start from station A to station C at the same time. A has kept the speed constant. B’s starting speed is 120 meters per minute. A arrives at station B 5 minutes earlier than B. After passing station B, the speed becomes 180 meters per minute. As a result, he arrives at station C 5 minutes earlier than A. , what is the speed of A?
沿途顺次有3个站点A、B、C，A到B的距离与B到C的距离相同．甲、乙两人同时从A站出发前往C站．甲一直保持速度不变，乙开始的速度是每分钟120米，甲比乙早到B站5分钟，乙过了B站之后速度变为180米每分钟，结果比甲早到C站5分钟，则甲的速度是多少？
<gadget id="calculator">180 * 10</gadget>
<output>1_800</output>

<gadget id="calculator">120 * 5</gadget>
<output>600</output>

<gadget id="calculator">1_800 + 600</gadget>
<output>2_400</output>

<gadget id="calculator">180 - 120</gadget>
<output>60</output>

<gadget id="calculator">2_400 / 60</gadget>
<output>40</output>

<gadget id="calculator">40 + 5</gadget>
<output>45</output>

<gadget id="calculator">120 * 45</gadget>
<output>5_400</output>

<gadget id="calculator">5_400 / 40</gadget>
<output>135</output>

<result>135</result>