When a natural number is divided by 7, 8, and 9, the remainder is 3, 5, and 7 respectively, and the sum of the three quotients obtained is 758. What is this number?
一个自然数除以7、8、9后分别余3、5、7，而所得的三个商的和是758，这个数是多少．
<result>2_005</result>