If it is known that there are natural numbers a and b, and there is 2(a**2-b**2)=2002, what is the minimum value of a+b?
如果已知有自然数a和b，而且有2(a**2-b**2)=2002，那么a+b的最小值为多少．
<gadget id="calculator">7 * 11</gadget>
<output>77</output>

<result>77</result>