Container A contains 11 liters of pure alcohol, and container B contains 15 liters of water. For the first time, part of the pure alcohol in container A is poured into container B to mix the alcohol and water. For the second time, part of the mixture in container B is poured into container A. In this way, the pure alcohol content in container A is 62.5%, and the alcohol content in container B is 40%. Then, how many liters of the mixed solution is poured from container B into container A for the second time?
甲容器有纯酒精11升，乙容器有水15升，第一次将甲容器中的一部分纯酒精倒入乙容器，使酒精与水混合．第二次将乙容器中一部分混合液倒入甲容器．这样甲容器中纯酒精含量为62.5%，乙容器中酒精含量为40%，那么，第二次从乙容器倒入甲容器的混合液多少升？
<gadget id="calculator">25 / 3</gadget>
<output>25/3 = around 8.333333</output>

<result>25/3 = around 8.333333</result>