Two snails crawl opposite ends of a bamboo pole. The second snail climbs (1/5) meter first, and then the first snail starts to climb out. The speed of the first snail is (1/4) faster than that of the second snail. When they meet B has done 20% more than A, what is the total length of this bamboo pole?
两只蜗牛从一根竹竿的两端相对爬行，乙蜗牛先爬了(1/5)米，甲蜗牛才开始爬出，甲蜗牛的速度比乙蜗牛的速度快(1/4)，相遇时乙比甲多行了20%，这根竹竿的全长是多少米？
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>

<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>

<gadget id="calculator">(1/5) - (4/5)</gadget>
<output>-3/5 = around -0.6</output>

<gadget id="calculator">1 + (-3/5)</gadget>
<output>2/5 = around 0.4</output>

<gadget id="calculator">(1/5) / (2/5)</gadget>
<output>1/2 = around 0.5</output>

<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>

<gadget id="calculator">(1/2) * (6/5)</gadget>
<output>3/5 = around 0.6</output>

<gadget id="calculator">(1/2) + (3/5)</gadget>
<output>11/10 = around 1.1</output>

<result>11/10 = around 1.1</result>