The sum of 2004 consecutive natural numbers is a*b*c*d. If a, b, c, and d are all different prime numbers, what is the minimum value of a+b+c+d?
2004个连续自然数的和是a*b*c*d，若a、b、c、d都是不同的质数，则a+b+c+d最小值应是多少．
<gadget id="calculator">2 + 3 + 167 + 2_011</gadget>
<output>2_183</output>

<result>2_183</result>