It is known that the sum of the reciprocals of three consecutive natural numbers is (47/60), what is the sum of these three numbers?
已知三个连续自然数的倒数的和是(47/60)，求这三个数的和是多少？
<gadget id="calculator">3 + 4 + 5</gadget>
<output>12</output>

<result>12</result>