The distance between A and B is 60 kilometers. Both A and B set off from A at the same time by bicycle. A is 4 kilometers slower than B per hour. When B arrives at B, he turns back immediately and meets B at a distance of 12 kilometers. A meet, then what is the speed of A.
A、B两城相距60千米，甲、乙两人都骑自行车从A城同时出发，甲比乙每小时慢4千米，乙到B城当即折返，于距B城12千米处与甲相遇，那么甲的速度是多少．
<gadget id="calculator">60 * 4</gadget>
<output>240</output>

<gadget id="calculator">12 * 4</gadget>
<output>48</output>

<gadget id="calculator">240 - 48</gadget>
<output>192</output>

<gadget id="calculator">12 - 60</gadget>
<output>-48</output>

<gadget id="calculator">12 + 60 + (-48)</gadget>
<output>24</output>

<gadget id="calculator">192 / 24</gadget>
<output>8</output>

<result>8</result>