Let 1, 3, 9, 27, 81, and 243 be six given numbers, and from these six numbers, either take one at a time, or take several different numbers to sum (each number can only be taken once), A new number can be obtained, so a total of 63 new numbers can be obtained. If they are arranged in order from small to large, it is 1, 3, 4, 9, 12... then what is the 60th number.
设1，3，9，27，81，243是六个给定的数，从这六个数中每次或者取一个，或者取几个不同的数求和(每个数只能取一次)，可以得到一个新数，这样共得到63个新数．如果把它们从小到大依次排列起来是1，3，4，9，12…那么第60个数是多少．
<gadget id="calculator">1 + 3 + 9 + 27 + 81 + 243</gadget>
<output>364</output>

<gadget id="calculator">364 - 4</gadget>
<output>360</output>

<result>360</result>