There is a container whose bottom surface is square, and the side length measured from the inside is 14 cm. There is a part of water in the container, and the water depth is 8 cm. When a solid iron cone is erected behind the container, the water level in the container rises (1/ 4). At this time, the depth of water is exactly half of the height of the cone, and the volume ratio of the submerged part of the cone to the part above the water is 7:1. Find the area of the bottom of the cone.
有一个容器，它的底面是正方形，从里面量边长是14厘米，容器里装着部分水，水深8厘米，把一个实心铁圆锥直立在容后，容器里的水面比原来上升了(1/4)．这时水深正好是圆锥高的一半，圆锥在水下部分和水上部分体积比是7：1，求圆锥的底面积．
<gadget id="calculator">14 ** 2</gadget>
<output>196</output>

<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">8 * (1/4)</gadget>
<output>2</output>

<gadget id="calculator">196 * 2</gadget>
<output>392</output>

<gadget id="calculator">7 + 1</gadget>
<output>8</output>

<gadget id="calculator">7 / 8</gadget>
<output>7/8 = around 0.875</output>

<gadget id="calculator">392 / (7/8)</gadget>
<output>448</output>

<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>

<gadget id="calculator">8 + 2</gadget>
<output>10</output>

<gadget id="calculator">10 * 2</gadget>
<output>20</output>

<gadget id="calculator">448 / (1/3) / 20</gadget>
<output>336/5 = around 67.2</output>

<result>336/5 = around 67.2</result>