Perform the following operation on a natural number greater than 0: if it is even, divide by 2, if it is odd, add 1, and so on until the operation stops at 1, then how many numbers become 1 after 9 operations.
对一个大于0的自然数作如下操作：如果是偶数则除以2，如果是奇数则加1，如此进行直到1时操作停止，那么经过9次操作变为1的数有多少个．
<gadget id="calculator">5 + 8</gadget>
<output>13</output>

<gadget id="calculator">13 + 8</gadget>
<output>21</output>

<gadget id="calculator">21 + 13</gadget>
<output>34</output>

<result>34</result>