If a square steel ingot with a side length of 4 decimeters is forged into a cylindrical steel ingot with a base area of 16 square decimeters, what is the height of the cylindrical steel ingot?
把一块棱长4分米的正方体钢锭，锻造成一个底面积是16平方分米的圆柱形钢锭，则圆柱形钢锭的高是多少？
<gadget id="calculator">4 / 16</gadget>
<output>1/4 = around 0.25</output>

<gadget id="calculator">4 * 4 * (1/4)</gadget>
<output>4</output>

<result>4</result>