and B start from A and B respectively at the same time and walk towards each other. Their speed ratio at the start is 3:2. After meeting for the first time, A's speed increases (1/5), and B's speed Increase (3/10), so that when A arrives at B, B is still 14 kilometers away from A, so how many meters is the distance between A and B?
甲、乙二人分别从A，B两地同时出发，相向而行，出发时他们的速度比是3：2，第一次相遇后，甲的速度提高了(1/5)，乙的速度提高了(3/10)，这样，当甲到达B地时，乙离A地还有14千米，那么A，B两地间距离是多少米？
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>

<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>

<gadget id="calculator">13 / 18</gadget>
<output>13/18 = around 0.722222</output>

<gadget id="calculator">(2/5) * (13/18)</gadget>
<output>13/45 = around 0.288889</output>

<gadget id="calculator">(3/5) - (13/45)</gadget>
<output>14/45 = around 0.311111</output>

<gadget id="calculator">14 / (14/45)</gadget>
<output>45</output>

<result>45</result>