If the last 4 digits of the product of 15 consecutive two-digit numbers are all 0, what is the minimum sum of these 15 numbers?
15个连续两位数乘积的末4位都是0，那么这15个数的总和最小是多少．
<gadget id="calculator">11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20 + 21 + 22 + 23 + 24 + 25</gadget>
<output>270</output>

<result>270</result>