There are 10 points on the plane, any three points are not on a straight line, connect these points two by two, get 120 triangles with these points as vertices, if one line is removed, how many triangles are left.
平面上有10个点，任意三个点不在一条直线上，将这些点两两相连，得到以这些点为顶点的三角形120个，若去掉一条线，则还剩下多少个三角形．
<gadget id="calculator">120 - 8</gadget>
<output>112</output>

<result>112</result>