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= DeMorgan's Theorem

$overline(\XY) = overline(X) + overline(Y)$

$overline(X + Y) = overline(\XY)$


- Simplify $(\AB)'(A' + B)$
  + $(A' + B')(A' + B)$

  + $A' + A'B + B'A'$

  + $A'cancel((B + B'))$

  + $A'$
