College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6



number to be added: $9$ factored form: $(y-3)^2$

Work Step by Step

RECALL: To complete the square of an expression in the form $x^2-bx$, $(\frac{b}{a})^2$ must be added. The factored form of the result is $(x-\frac{b}{2})^2$. Thus, in the given expression add $(\frac{6}{2})^2=3^2=9$ to obtain: $y^2 -6y + 9$ Writing the square in factored form gives: $y^2-6y+9 = (y-3)^2$
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