x.øi5ss="partText">If you treat an electron as a classical spherical object with radius 1.80×10−17 m, what angular speed omega is necessary to produce a spin angular momentum of magnitude \sqrt {{3}/{4}}\,\hbar? Use h = 6.63×10−34 J \cdot s for Planck's constant, recalling that \hbar = {h}/{2\pi}, and 9.11×10−31 kg for the mass of an electron.
Express your answer in radians per second to three significant figures.
omega =
{\rm rad/s}

Part B
Use the equation v=r \omega relating velocity to radius and angular velocity together with the result of Part A to calculate the speed v of a point at the electron's equator.
Express your answer in meters per second to three significant figures.
v =
{\rm m/s}ãv øi58m