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I'm loading a jqGrid on my page. The grid has a Delete button for each row. I'm trying to use the jquery UI dialog confirmation on my Delete button.

Here's my javascript code:

<script type="text/javascript">

    $(document).ready(function () {

            url: '/MyController/MyFunction/',
            datatype: 'json',
            mtype: 'POST',
            colNames: ['', 'Name', ''],
            colModel: [
                { name: 'Edit', index: 'Edit', width: 40, align: 'left', sortable: false },
                { name: 'Name', index: 'Name', width: 120, align: 'left' },
                { name: 'Delete', index: 'Delete', width: 50, align: 'left', sortable: false }],
            pager: $('#pager'),
            rowNum: 10,
            rowList: [10, 20, 50],
            sortname: 'Name',
            sortorder: "asc",
            viewrecords: true,
            width: 700

            autoOpen: false,
            modal: true,
            buttons: {
                "Delete": function () {
                    window.location.href = $(this).attr("href"); ;
                Cancel: function () {

        $("a.confirm").click(function () {



I'm passing in data from my controller to the grid. I have the class "confirm" added to the Delete link for each row.

If I click on my Delete button, nothing happens. The link has the correct class, and all my javascript is loading correctly. I placed an alert at the end of my document.ready function to make sure there were no errors.

But if I comment out my jqGrid and add a link onto my page with the class "confirm", the click event will fire.

Has anyone ever run into this?

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1 Answer

up vote 3 down vote accepted

The main problem which you have is that you try to make 'click' binding with $("a.confirm").click(...) before the elements "a.confirm" are loaded.

You should either place the binding code inside of loadComplete or gridComplete event handler or use jQuery.live

$("a.confirm").live('click', function() {

instead of $("a.confirm").click(...).

One more general remark. The best practice working with jqGrid is dividing data from the HTML markup. I suppose that you place HTML fragment with <a class="confirm">...</a> inside of JSON data returned from the server. jqGrid supports another ways to archive the same results. You can 1) use showlink formatter; 2) use custom formatter which allow create any HTML fragment for the grid cell based on the row of data (see rowObject parameter) returned from the server 3) use unobtrusive JavaScript (see my answer with the code example) 4) any mix from both (see another answer with the code example). The way 3 seems me mostly close to what you do.

In any way having clear separation of JSON data from HTML markup is good not only because of design reason. It allows additionally reduce the size of data send from server. (see this answer for more information)

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thanks, helped a lot! –  volocuga Mar 10 '13 at 21:09
@volocuga: You are welcome! The answer is relatively old. Currently I will recommend to use custom formatter and beforeSelectRow or onCellSelect instead of any additional binding of click event handler. See the answer, another one for code examples. The old answer was the first for me when I saw the advantages on usage one common event handler to handle click event of multiple elements inside of grid. –  Oleg Mar 10 '13 at 21:53
Awesome! I'll try, thanks! –  volocuga Mar 11 '13 at 10:31
@volocuga: You are welcome! –  Oleg Mar 11 '13 at 10:33
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