

Ramona Fricosu's attorney says she may have forgotten the password







Source: Wired

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RE: Is this actually necessary?
By bug77 on 2/7/2012 3:45:55 PM , Rating: 3
Yes, but they could use the Amazon cloud and divide that by 10!

RE: Is this actually necessary?
By Lifted on 2/7/2012 5:31:47 PM , Rating: 2
Wouldn't that be a lot less?

RE: Is this actually necessary?
By SlyNine on 2/7/2012 10:13:59 PM , Rating: 2
I don't think an Amazon cloud can do 2^56. In fact according to Toms Hardware, in regards to cracking WPA, said

"Each GPU cluster instance is armed with a 10 Gb Ethernet link, restricting bidirectional traffic between the master and nodes to 1.25 GB/s. This is what bottlenecks the cracking speed. Remember that a single ASCII character consumes one byte. So, as you start cracking longer passwords, the master server has to send more data to the clients. Worse still, the clients have to send the processed PMK/PTK back to the master server. As the network grows, the number of passwords each additional node processes goes down, resulting in diminishing returns. "

So having 4 Tesla GPUs is faster than renting an Amazon virtual computer.

Now lets say they have 100 570s, 2 of them can do 1.5billion passwords a second ( again according to tomshardware), so 1500000000x50=75 billion. So 75 billion Tries per second is about the Max amount of computer power they can through at it.

I believe to reach the Max security on AES 128 you need 32 characters. 64 for AES 256. But lets use 128 for example. You have 94 characters in a full ASCII character set. So you take 94 possibilities in every character of a passphrase. So if you have 2 characters in your password that's 94x94 or 94^2, If you use the full strength that's 94^32= 1.38067454 × 10^63 or 13 with 63 zeros behind it. That number looks like this 130000000000000000000000000000000000000000000000000 00000000000000 + possible combinations. So lets take 130000000000000000000000000000000000000000000000000 00000000000000/ 75000000000 Which takes you 1.84089939 X 10^52 Seconds to complete. That number looks like that
1800000000000000000000000000000000000000000000000 00000 So lets divide that by 60 and than by 60 again to get us to hours, and than by 24 to get to days, and than by 365 to get to years, than lets Divide by 10 again figureing they will find the phrases after trying 1/10 the possibilities. That number is 5.83745367 × 10^43 or 58000000000000000000000000000000000 years.

So it would take 58000000000000000000000000000000000 years to complete, now if you want to divide that by a million, or billion, you will still get a number that's to big to worry about.

No you are not brute forcing AES 128 with conventonal means. Not in our lifetimes anyways. Probably not with in the lifetime of the universe.

RE: Is this actually necessary?
By SlyNine on 2/7/2012 10:21:56 PM , Rating: 2
I screwed up, it should be 1.3 with 64 zeros behind it. But since the calculations were done using the scientific numbers the calculations are still correct. Just knock off a zero on each one of the non scientific numbers.

RE: Is this actually necessary?
By SlyNine on 2/7/2012 10:23:37 PM , Rating: 2
LOL oops again. But if you don't understand what I mean elementary algebra will show you.

