physics question

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A block of mass M1 sits on a table, with no friction, anda block of mass M2 is suspended by a cord of negligible mass over africtionless pulley. At t=0s the blocks are at rest, and thehanging mass starts descend.
Student X says: "The hanging mass is pulling down on therope, so the tension in the rope is (M2)g. That's the forceon the block on the table, so that block's acceleration isa=F/m=(M2)g/M1."
Student Y says: "That can't be right, because if M2 is biggerthan M1, then M1 will have an acceleration bigger than g!"

I am confused about the overall problem. Just don'tunderstand at all.

Answers (1)

  • Anonymous
    Rating:4 stars

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