FIG. 14: (14a) Contour levels for 95% C.L. plotted against g ′ 1 and M$_{Z}$ ′ at the LHC for selected integrated luminosities and (14b) integrated luminosity required for observation at 3 σ and 5 σ vs. M$_{Z}$ ′ for selected values of g ′ 1 (in which only the allowed combination of masses and couplings are shown), for √$_{s}$ = 14 TeV, for both electrons and muons. The shaded areas and the allowed ( M$_{Z}$ ′ , g ′ $_{1}$) shown are in accordance with eq. (21) (LEP bounds, in black) and table II (Tevatron bounds, in red for electrons and in green for muons). 14 TeV can exclude at 95% C.L. up to a mass of roughly 5 TeV for a value of the coupling 9 g ′ 1 = 0 . 4. For 100 fb − 1 and for the same value of the coupling, the LHC can exclude at 95% C.L. masses up to roughly 6 TeV. For 10 fb − 1 it will be possible to exclude a Z ′ B − L boson for M$_{Z}$ ′ = 600 GeV if the coupling is greater than 1 . 8 · 10 − $^{2}$(9 · 10 − $^{3}$) for muons(electrons), and values of the coupling greater than 1 . 5 · 10 − $^{2}$(6 . 5 · 10 − $^{3}$) for an integrated luminosity of 100 fb − $^{1}$. Figure 14b shows the integrated luminosity that is required to excluded a certain Z ′ B − L boson mass for fixed values of the coupling. As previously noticed, electrons and muons set the same limits for g ′ 1 ≥ 0 . 1, a smaller value than for √$_{s}$ = 10 TeV due to the improved resolutions. An integrated luminosity of 10 fb − 1 is required to exclude a Z ′ B − L mass up to 3 . 8 TeV for g ′ 1 = 0 . 2, instead 40 fb − 1 reduces this to g ′ 1 = 0 . 1. For an integrated luminosity of 10 9 This is the biggest allowed value for the consistency of the model up to a scale Q = 10 15 GeV, from a Renormalisation Group (RG) analysis of the gauge sector of the model [8, 23]. 28 1 2 3 4 10 −3 10 −2 10 −1 95% C.L. LHC, s=14 TeV L = 100 fb −1 −1  , e L = 10 fb −1 L = 10 fb$^{−1}$, e L = 1 fb −1 L = 1 fb$^{−1}$, e L = 100 pb −1 M$_{Z’}$ (TeV) g’ 1 $^{−1}$, e (a) 1 2 3 4 10 10 −1 1 10 10 2 g’$_{1}$=0.2, e g’$_{1}$=0.2, g’ g’ M$_{Z’}$ (TeV) −2 g’ =0.025, =0.025, e =0.05,  1 1 95% C.L. 1 g’$_{1}$=0.1, e g’$_{1}$=0.1, g’ −1 1 ) =0.05, e Int.Lum. (fb (b)