in Eq. (27), has the relation as below: That is, The jamming capacity C$_{J}$ can be obtained as: and Finally, with Eq. (21)–(23), the capacity C$_{J}$ can be calculated: Since T$_{J}$ ∼ ( φ − φ$_{c}$ ) and p ∼ ( φ − φ$_{c}$ ) 1 . $^{5}$, we obtain C$_{J}$ ∼ ( φ − φ$_{c}$ ) − $^{1}$. d E$_{J}$ = T$_{J}$ d S = T$_{J}$ ∂S ∂ ln( φ − φ$_{c}$ ) d ln( φ − φ$_{c}$ ) + T$_{J}$ ∂S ∂ ln p d ln p = ( − X cos θ c$_{2}$ )( − c$_{2}$ X )d ln( φ − φ$_{c}$ ) + A sin θ c$_{1}$ c$_{1}$ A d ln p = cos θ d ln( φ − φ$_{c}$ ) + sin θ d ln p = (cos θ + sin θ tan θ )d ln( φ − φ$_{c}$ ) = d ln( φ − φ$_{c}$ ) cos θ . (28) d E$_{J}$ = √$_{a}$ 2 + 1d ln( φ − φ$_{c}$ ) , (29) E$_{J}$ $_{= (}$√$_{a}$ 2 + 1) ln( φ − φ$_{c}$ ) . (30) C$_{J}$ = T$_{J}$ ∂S ∂T$_{J}$ = T$_{J}$ ∂S ∂ ln p ∂ ln p ∂T$_{J}$ + T$_{J}$ ∂S ∂ ln( φ − φ$_{c}$ ) ∂ ln( φ − φ$_{c}$ ) ∂T$_{J}$ , (31) C$_{J}$ = T$_{J}$ ( c$_{1}$ A − c$_{2}$ aX ) ∂ ln p ∂T$_{J}$ = T$_{J}$ 1 + a 2 a 2 c$_{1}$ A ∂ ln p ∂T$_{J}$ . (32) 14