FIG. 2: R$_{p,q}$ ( n, n/ 2 , x n 3 / $^{4}$) (blue curves) versus x at z = − 9 and a = 1 so that q = 1 − 9 /n and p = 1 − 0 . 105391 /n − 1 . 50171 /n 3 / 2 for n = 2 $^{6}$, 2$^{8}$, 2$^{10}$, 212 and 2 $^{14}$. The red curve is the asymptote e − 0 . 719718 ( x $^{4}$− 2 x $^{$^{2}$)}$. for p = 1 + y$_{1}$/n + · · · and q = 1 + z/n as before. Note that a = − 2 corresponds to a binomial distribution, so we are usually interested in the case − 2 < a < 0. After expanding the equation we receive as before, from the first term of the left and right hand side, the equation which has the solution y$_{1}$ = 2 w − a where The second equation, which is slightly longer, has the solution 21 ( a + y$_{1}$ ) e y$_{1}$/ 2 = ( a + z ) e z/ 2 (67) w = W ( a + z 2 e ( a + z ) / 2 ) (68) y$_{2}$ = ( a − 2 w + z ) ( a $^{2}$( w + 2) − 2 a w 2 − w z (2 w + z )) 2 ( w + 1) ( a + z ) (69) $^{GLYPH<Minus>}$2.0 $^{GLYPH<Minus>}$1.5 $^{GLYPH<Minus>}$1.0 $^{GLYPH<Minus>}$0.5 0.5 1.0 1.5 2.0 x 0.5 1.0 1.5 2.0 R