The spectrum of chiral operators should be consistent with the Kaluza-Klein reduction of the 11-dimensional supergravity on M 1 , 1 , $^{1}$/$_{Z}$$_{k}$ . Chiral operators in the quiver gauge theory Fig.1, with k = 1 were studied in Ref. [18]. For pure-scalar operators, we have a simple task of classifying holomorphic expressions of the nine complex scalar fields, up to the F-term condition, One can start with the simplest gauge singlet operators, There are three SU (3) indices, but the F-term condition forces total symmetrization of l,m,n , so these dimension 2 operators are in 10 of SU (3). In order to construct SU (2) multiplets, we should consider the monopole operators. For simplicity let us consider the abelian case with CS level k = 1. Then there exists a dual photon field e ia which carries charge (1 , 1 , − 2) but does not change the conformal dimension of the entire composite oper- ator. One can easily verify there are two more neutral operators, and if we continue to use the matrix notation, they are X lmn 0 ,X lmn ± thus give ( 10 , 3 ) of SU (3) × SU (2), and has R-charge 2. With generic values of the CS level k , X lmn ± fields are not neutral anymore and SU (2) is broken to U (1). The above spectrum of chiral operators is consistent with the Kaluza-Klein analysis [4, 5]. As N = 2 supergravity in four dimensions, there exist hypermultiplets - the ones appearing in Eq.(6.14) of Ref. [5] - which are totally symmetric rank-3 n representation of SU (3) and spin- n in SU (2). Through the AdS/CFT prescription, they have conformal dimension 2 n . In the duality proposal of Fig. 1, the dual operators are constructed with 3 n -th order monomials of the scalar fields, and taking the trace. For the membrane action, we will use the form developed and utilized by Bozhilov [19]. Since we will consider classical solutions which in our ansatz do not couple to the background III. THE MEMBRANE ACTION 5 X lmn + = Tr( e − $^{ia}$Xl $_{12}$X m $_{23}$X n $_{23}$) , X lmn − = Tr( e + $^{ia}$Xl $_{12}$X m $_{31}$X n $_{31}$) . (7) X lmn 0 = Tr( X l $_{12}$X m $_{23}$X n $_{31}$) . (6) ϵ$_{lmn}$X m $_{23}$X n 31 = 0 , ϵ$_{lmn}$X m $_{31}$X n 12 = 0 , ϵ$_{lmn}$X m $_{12}$X n 23 = 0 . (5)