21 pairs in different events. We determine the rescale of the mixed event denominator by considering the number of pairs of pairs for the case | Δ η | lying be- tween 1.2 and 1.5 plus any value of | Δ φ | for events and mixed events so that the overall ratio of this sample numerator to denominator is 1. By picking this Δ η bin for all | Δ φ | we have around the same pair count as the signal cut with the Δ φ correlation of the bubbles being washed out. For a simpler no- tation let (sign ( | Δ P $^{t}$1 | + | Δ P $^{t}$2 | )) = Δ P $^{t}$1 + Δ P $^{t}$2 which we plot in the range from -4 to +4 since we have an over all p t range 0.8 to 4.0 GeV/c. Thus the In Fig. 18 we show the correlation function of op- posite sign charged-particle-pairs paired and binned by the variable Δ P $^{t}$1 + Δ P $^{t}$2 with a cut | Δ η | less than 0.2 between the vector sums of the two pairs, and with 40 ◦ < | Δ φ | < 48 ◦ . The events are gen- erated by the PBM[6] and are charged particles of 0.8 < p t < 4.0 GeV/c, with | η | < 1, from Au Au collisions at √ s NN = 200 GeV. Since we select pairs maximum magnitude of Δ P t ’s is 3.2 GeV/c which makes Δ P $^{t}$1 + Δ P $^{t}$2 have a range of ± 6.4. However the larger values near these range limits occur very rarely. FIG. 17: Pairs of pairs selected for forming a correlation exhibiting the effect of changes in p t due to the color magnetic field. The largest opening angle θ for plus minus pairs is 16 ◦ or less. This opening angle assures that each pair has a high probability that it arises from a quark anti-quark pair. In this figure we have picked two pairs at this limit ( θ 1 = 16 ◦ and θ 2 = 16 ◦ ). The mid-point for pair 1 and 2 represents the vector sum of pair 1 and 2 which moves toward the harder particle when the momenta differ. These mid-points are chosen to have 40 ◦ < | Δ φ | < 48 ◦ in order for the pairs to be on opposite sides of the bubble. Since we are interested in pairs directly across the bubble we make the Δ η separation be no more than 0.2. The difference in p t for pair 1 is Δ P t 1 = -0.25 GeV/c, while the difference in p t for pair 2 is Δ P t 2 = 0.40 GeV/c. The minus sign for 1 follows from the fact that the plus particle has 1.14 GeV/c and the minus particle has 1.39 GeV/c. The plus sign for 2 follows from the fact that the plus particle has 1.31 GeV/c and the minus particle has 0.91 GeV/c. + - - + $_{1}$ = 16 0 $_{2}$ = 16 0 P$_{t1}$ = -.25 GeV/c P$_{t2}$ = .40 GeV/c  = 0.19  = 45 0 1 2