def _looks_like_url(name):
    """
    Function tries to determine if input argument
    looks like URL and not like S3 bucket name.
    :param name - input name
    :return: True, if name looks like URL;
             False otherwise.
    """
    if name.endswith('.com'):
        return True
    if name.find(':') >= 0:
        # Assume it is port number
        return True
    return False