import re


def find_url(string):
    """
    Search URL in text.

    Parameters
    ----------
        string: str
            Text selected to apply transformation

    Examples:
    ---------
    ```python
    sentence="I love spending time at https://www.kaggle.com/"
    find_url(sentence)
    ```
    """
    text = re.findall('http[s]?://(?:[a-zA-Z]|[0-9]|[$-_@.&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-F]))+', string)
    return "".join(text)