def split_s3_path(s3_path):
    """
    Splits the complete s3 path to a bucket name and a key name, 
    this is useful in cases where and api requires two seperate entries (bucket and key)


    Arguments:
        s3_path {string} -- An S3 uri path

    Returns:
        bucket {string} - The bucket name
        key {string} - The key name
    """
    
    bucket = s3_path.split("/")[2]    
    key  = '/'.join(s3_path.split("/")[3:])
    
    return bucket, key