A spectral gap precludes low-dimensional embeddings
  We prove that there is a universal constant $C>0$ with the following property. Suppose that $n\in \mathbb{N}$ and that $\mathsf{A}=(a_{ij})\in M_n(\mathbb{R})$ is a symmetric stochastic matrix. Denote the second-largest eigenvalue of $\mathsf{A}$ by $\lambda_2(\mathsf{A})$. Then for $\mathrm{\it any}$ finite-dimensional normed space $(X,\|\cdot\|)$ we have $$ \forall\, x_1,\ldots,x_n\in X,\qquad \mathrm{dim}(X)\ge \frac12 \exp\left(C\frac{1-\lambda_2(\mathsf{A})}{\sqrt{n}}\bigg(\frac{\sum_{i=1}^n\sum_{j=1}^n\|x_i-x_j\|^2}{\sum_{i=1}^n\sum_{j=1}^na_{ij}\|x_i-x_j\|^2}\bigg)^{\frac12}\right). $$ This implies that if an $n$-vertex $O(1)$-expander embeds with average distortion $D\ge 1$ into $X$, then necessarily $\mathrm{dim}(X)\gtrsim n^{c/D}$ for some universal constant $c>0$, thus improving over the previously best-known estimate $\mathrm{dim}(X)\gtrsim (\log n)^2/D^2$ of Linial, London and Rabinovich, strengthening a theorem of Matou\v{s}ek, and answering a question of Andoni, Nikolov, Razenshteyn and Waingarten. 
Assaf Naor
math.MG cs.DS math.CO math.FA