$50 \textbackslash\% \cdot 10=5$ $30 \textbackslash\% \cdot 20=6$ $30 \textbackslash\% \cdot 30=9$ Adding them up gets $5+6+9=20$. The overall percentage correct would be $\frac{20}{60}=\frac{1}{3}=0 . \overline{3} \approx(\mathbf{A}) 33$. 
Patrick gets $50 \textbackslash\%$ on a 10 -problem test, $30 \textbackslash\%$ on a 20 -problem test and $30 \textbackslash\%$ on a 30 -problem test. If the three tests are combined into one 60 problem test, which percent is closest to her overall score? (adapted from 2006 AMC 8, Question \#12) 
A. $$33$$ 
B. $$44$$ 
C. $$55$$ 
D. $$66$$ 
E. $$99$$ 