$99\div3=33$  $32+33+34=99$  $32\times33\times34=35904$ 
The sum of three $2-$digit consecutive numbers is the maximum 2-digit number. What is their product? 
Options:
[A] $$99$$ 
[B] $$25900$$ 
[C] $$35904$$ 
[D] $$34589$$ 
[E] $$39804$$ 