$5 - 9: 9 - 5 + 1 = 5$  $10 - 99: 99 - 10 + 1 = 90$  $100 - 118: 118 - 100 + 1 = 19$  $5\times1 + 90\times2 + 19\times3 = 5 + 180 + 57 = 242$ 
How many digits are there from $5$ to $118$? 
Options:
1) $$114$$ 
2) $$204$$ 
3) $$239$$ 
4) $$242$$ 