Remove the two cubes in both ends, and then we can get: $[(3-2)+(4-2)+(5-2)]\times4=24$ 
There is a cuboid with a dimension of $3\times4\times5$. Now paint all the surfaces red and cut it into many $1\times1\times1$ cubes. How many cubes that have two faces painted red are there? 

  * $$24$$ 
  * $$6$$ 
  * $$8$$ 
  * $$11$$ 
  * $$22$$ 