Factor the polynomial as $\left(x^{2}-5\right)\left(x^{2}-2\right)$. Since this expression is negative, one term must be negative and the other positive. Also, the first term is obviously smaller than the second, so $x^{2}-5\textless0\textless x^{2}-2$. Solving this inequality, we find $2\textless x^{2}\textless5$. There are exactly $2$ integers $x$ that satisfy this inequality, $\pm 2$. Thus our answer is $(\mathbf{A}) 2$. 
For how many integers $x$ is the number $x^{4}-7x^{2}+10$ negative? (  2014 AMC 10B Problems, Question \#20) 
A. $$2$$ 
B. $$4$$ 
C. $$6$$ 
D. $$12$$ 
E. $$24$$ 