There are $12$ different combinations. The product of two numbers is greater than or equal to $10$ will be $2\times5$ and $2\times6$. Thus, the probability is $\frac 2{12}$ = $\frac 16$. 
Two tiles numbered $1$ and $2$ are turned face down, respectively. One tile is turned up at random, and throw a die to get a number from $1$ to $6$. What is the probability that the product of the numbers on the tile and the die is greater than or equal to $10$? 
  * $\frac {1}{2}$ 
  * $\frac {1}{6}$ 
  * $\frac {1}{3}$ 
  * $\frac {1}{4}$ 
  * $\frac {1}{12}$ 