P(at least one blue) = 1 - P(no blue, so 2 red) = 1- 2/5*1/4 = 9/10.
In a bucket there are 3 blue balls and 2 red balls. What is the probability of drawing at least one blue ball when drawing two consecutive balls randomly?
Options:
9/10
16/20
2/5
3/5
½