$$360={{2}^{3}}\times {{3}^{2}}\times5$$, so the number of its factors would be $$\left( 3+1 \right)\times \left( 2+1 \right)\times\left( 1+1 \right)=24$$. Among them, there are $$2\times 2\times(1+1)=8$$ factors which have $${{2}^{2}}\times 3$$ as its factors. 
How many positive factors of $$360$$ are also multiples of $$12$$? 
Options:
(1) $$4$$ 
(2) $$5$$ 
(3) $$6$$ 
(4) $$7$$ 
(5) $$8$$ 