132/11 = 12 lanterns  12 lanterns + 1 = 13 lanterns  13 x 2 = 26 lanterns. 
A city council decided to put lanterns on both sides of a river. The distance between any two neighbouring lanterns on each side must be $11$ metres. The length of the river is $132$ metres. The distance between the first and the last lantern on each side must be also $132$ metres. How many lanterns will there be in total? 

(A) $$12$$ 
(B) $$13$$ 
(C) $$24$$ 
(D) $$26$$ 
(E) None of the above 