There are $200$ multiples of $3$ and there are $120$ multiples of of $5$. There are also $40$ multiples of $15$. By the Inclusion Exclusion Principle, there are $200+120-40=280$ numbers which are multiples of $3$ or $5$. 
Among the natural numbers from $1$ to $600$, how many numbers are multiples of $3$ or $5$? 

- $$260$$ 
- $$280$$ 
- $$300$$ 
- $$320$$ 