$36\div5=7R1$.  Thus, for the first $35$ boxes, there is a total of $$14\times7=98$$ balls.  Therefore, there are $100-98=2$ balls. 
把$$100$$个球放到$$36$$个盒子里．已知任何连续的$$5$$个盒子中共有$$14$$个球，问最后一个盒子里有多少个球？  Put a total of $100$ balls into $36$ boxes. Given that any consecutive $5$ boxes have a sum of $14$ balls, the last box has~\uline{~~~~~~~~~~}~balls. 
Options:
1) $$1$$ 
2) $$2$$ 
3) $$7$$ 
4) $$8$$ 
5) $$14$$ 