Obsever that $3\times27=9^{2}$ and $12\times27=24^{2}$ are both squares. Hence, their product is also a perfect square and the fifth number must be $6$. 
Four numbers are chosen from the set $3$, $6$, $12$, $27$, $48$ so that the product is a perfect square. What is the number that was not chosen? 
Options:
A: $$3$$ 
B: $$6$$ 
C: $$12$$ 
D: $$27$$ 
E: $$48$$ 