After adding $3$ toys, the number of toys should be divisible by $9$, and it also should be divisible by $2, 3, $ and $4$. Thus, the answer is $B$. 
Betty has more than $90$ toys. All her toys can be divided evenly between $2$, $3$, or $4$ children. However, they cannot be divided evenly between $9$ children because $3$ more toys would be needed. How many toys does she have at least? 

$$87$$ 
$$96$$ 
$$132$$ 
$$135$$ 