$$A$$能被$$5$$整除，个位就是$$0$$或$$5$$，$$A$$加$$1$$得$$B$$ 是$$8$$的倍数，个位不能是$$1$$，故只能是$$6$$，$$B$$再加$$1$$得$$C$$ 是$$9$$的倍数，个位数字是$$7$$，$$C$$的个位只能由$$3\times 9=27$$得来．  假设$$C=3\times 9=27$$，则$$B=26$$，$$26$$不能被$$8$$整除；故排除；  假设$$C=13\times 9=127$$，则$$B=126$$，$$126$$不能被$$8$$整除；故排除；  假设$$C=23\times 9=207$$，则$$B=206$$，$$206$$不能被$$8$$整除；故排除；  假设$$C=33\times 9=297$$，则$$B=296$$，$$296\div 8=37$$，且$$295\div 5=59$$；因此，最小$$A=295$$，$$B=296$$，$$C=297$$，三个数的和为：$$295+296+297=888$$．  故选$$888$$． 
$$A$$, $$B$$ and $$C$$ are three consecutive numbers that are divisible by $$5$$, $$8$$ and $$9$$ respectively. The smallest possible sum of these three numbers is ．  $$A$$、$$B$$、$$C$$是三个连续数，分别可被$$5$$、$$8$$及$$9$$整除．此三个数最小的和是~\uline{~~~~~~~~~~}~． 

  * $$555$$ 
  * $$666$$ 
  * $$777$$ 
  * $$888$$ 
  * $$999$$ 