Because $$99$$ is an odd number, one of these two prime numbers must be an even prime number. The only choice is $$2$$. So the other is $$99-2 = 97$$. So, the difference between the two numbers is $$95$$. Therefore, we choose $$\rm C$$ . 
The sum of two prime numbers is $$99$$. What is the difference between the two prime numbers? 

a: $$89$$ 
b: $$92$$ 
c: $$95$$ 
d: $$97$$ 