Whenever you are asked to find the number of digits, try to bring the number in multiples of 10. This way, we can wasily calculate the umber of 0's through the powers of 10
50^8 × 8^3 × 11^3 = (5^2*2)^8*2^9*11^3 = 5^16*2^17*11^3 = 2*11^3*10^16 = 2662*10^16
Hence we would have 16 trailing 0's and the three digits from 2662
Total digits = 4 + 16 = 20
How many digits are in the number 50^8 × 8^3 × 11^3?
Options:
1. 22
2. 20
3. 19
4. 18
5. 17