$49\textbackslash{} \div(1+6)=7$~groups, so the second mover will have the winning strategy. 
There are $49$ matchsticks on the table. Kevin and Michael will take turns to take away the matchsticks from the first matchstick in order. Each person can take $1$ to $6$ matchsticks at a time. The person who takes the last matchstick on the table will win the game. If Kevin plays the game first, does he have the winning strategy? 
  - Yes, he has the winning strategy. 
  - No, he does not have the winning strategy. 