There are $4$ ways to choose three from four. Two $B$s with one $O$ can form Bob\textquotesingle s name. Thus, $2$ of the $4$ ways can get Bob\textquotesingle s name. 
Annie has four cards of different colors. She writes letter $B$ on the red card and blue card, and writes letter $O$ on the yellow card and green card. Now Annie puts the four cards in a box. Bob is going to draw three of them from the box randomly. How many different possible results can Bob get? Among them, how many can Bob get his name? 
Options:
[A] $6$; $3$ 
[B] $4$; $3$ 
[C] $6$; $2$ 
[D] $4$; $2$ 
[E] $6$; $1$ 