Each number in the second sum is $$18$$ greater than the corresponding number in the first sum. Thus the second sum is $$1935 +18 \times9 = 2097$$. 
If the sum of $$9$$ consecutive odd integers is $$1935$$, what is the sum of the next $$9$$ consecutive odd integers? 

[1] $$2015$$ 
[2] $$2017$$ 
[3] $$2097$$ 
[4] $$2099$$ 