First, note that $24+1=25$, which motivates us to factor the polynomial as $\left(x^{2}-24\right)\left(x^{2}-1\right)$. Since this expression is negative, one term must be negative and the other positive. Also, the first term is obviously smaller than the second, so $x^{2}-24\textless0\textless x^{2}-1$. Solving this inequality, we find $1\textless x^{2}\textless24$. There are exactly $6$ integers $x$ that satisfy this inequality, $\pm\textbackslash{2,3,4\textbackslash}$. Thus our answer is $(\mathbf{B}) 6$. 
For how many integers $x$ is the number $x^{4}-25 x^{2}+24$ negative? (  2014 AMC 10B Problems, Question \#20) 
* $$3$$ 
* $$6$$ 
* $$12$$ 
* $$14$$ 
* $$16$$ 