$2^{10}=1024\equiv24($mod$100)$  $\left (2^{10}\right )^{2}=1024^{2}\equiv76($mod$100)$  $\left (2^{10}\right )^{3}\equiv 76\times24\equiv24($mod$100)$  $\left (2^{10}\right )^{4}\equiv76($mod$100)$  $\cdots\cdots$  $$2^{2018201}-8=2\left (2^{2018200}\right )-8 \equiv 2\left (76\right )-8 \equiv 44($$mod$$100)$$. 
What are the last $2$ digits on the right in the expansion of the expression $2^{2018201}- 8$? 
1) $$12$$ 
2) $$22$$ 
3) $$44$$ 
4) $$88$$ 
5) None of the above 