Rule of product: $$3\times 4\times 3\times 2=72$$; therefore we can choose D. 
How many different four-digit odd numbers can be made by using digits $$1$$, $$2$$, $$3$$, $$4$$, and $$5$$ (without digits be repeated)? 
Options:
[A] $$24$$ 
[B] $$36$$ 
[C] $$48$$ 
[D] $$72$$ 