Ways of selecting group = 6C2 * 4C2 * 2C2 / 3! = 15
Three groups can select three subjects in 6 ways
Therefore total combinations = 15*6 = 90
Six students are equally divided into 3 groups, then, the three groups were assigned to three different topics. How many different arrangements are possible?
Options:
(a) 30
(b) 60
(c) 90
(d) 180
(e) 540