$$5$$ out of $$6$$ of the $$2016$$ lightbulbs are not defective. Thus $$2016 \times \frac{5}{6} =1680$$ lightbulbs are not defective. 
If $$1$$ out of $$6$$ lightbulbs is defective and there are $$2016$$ lightbulbs, how many of them are not defective? 
Options:
  - $$5$$ 
  - $$336$$ 
  - $$1680$$ 
  - $$2016$$ 