$77=7\times 11$  $132=2\times 2\times 3\times 11$  Because $B$ is the factor both number contains, $B=11$  Thus, $A=7$, $C=12$. 
There are three whole number $A$, $B$, $C$. $A\times B=77$, $B\times C=132$. $A+B+C=$~\uline{~~~~~~~~~~}~. 
Options:
1: $$30$$ 
2: $$31$$ 
3: $$32$$ 
4: $$33$$ 