Order does not matter as peaches and baskets are identical. But we need to have different number of peaches in each basket and none of the baskets can be empty.  $$12=1+2+9$$  $$12=1+3+8$$  $$12=1+4+7$$  $$12=1+5+6$$  $$12=2+3+7$$  $$12=2+4+6$$  $$12=3+4+5$$  There are $$7$$ ways she can place the peaches. 
Mother has $$12$$ identical peaches. She wants to place them into $$3$$ identical baskets. How many ways can she place the peaches if the number of peaches in each basket cannot be zero and must be different from one other? 

a. $$4$$ 
b. $$6$$ 
c. $$7$$ 
d. $$12$$ 