There are $3$ $C$s in total now with other $4$ letters remaining.  There are $\_4P\_4$ ways for us to arrange the $4$ letters\textquotesingle{} positions.  So the answer is $\_4P\_4\times \_5C\_3 =240$. 
In how many ways can the letters in $CPCCKBY$ be rearranged so that two or more $C$s do not appear together? 
Options:
a. $$240$$ 
b. $$180$$ 
c. $$64$$ 
d. $$96$$ 
e. $$140$$ 