The sum of the areas is equal to $2 \cdot 1+2 \cdot 4+2 \cdot 9+2 \cdot 16+2 \cdot 25+2 \cdot 36$. This is equal to $2(1+4+9+16+25+36)$, which is equal to $2 \cdot 91$. This is equal to our final answer of (D) 182 . 
Six rectangles each with a common base width of $2$ have lengths of $1,4,9,16,25$, and 36 . What is the sum of the areas of the six rectangles? (2014 AMC 8, Question \#6) 
[a] $$91$$ 
[b] $$93$$ 
[c] $$162$$ 
[d] $$182$$ 
[e] $$202$$ 