$6!=10\times9\times8$, $$6!\times8!=8\times 10!$$. 
For a positive integer $n$, the factorial notation $n!$ repressents the product of the integer from $n$ to $1$, (For example, $6!=6\times5\times4\times3\times2\times1$.) What value of $N$ satisfies the following equation?  $$6!\times8!=8\times N!$$ 

  * $$9$$ 
  * $$10$$ 
  * $$11$$ 
  * $$12$$ 
  * $$13$$ 