We use the property that the digits of a number must sum to a multiple of $9$ if it is divisible by $9$. This means $2+0+1+8+U$ must be divisible by $9$. The only possible value for U then must be $7$. Since we are looking for the remainder when divided by $8$, we can ignore the thousands. The remainder when $187$ is divided by $8$ is $(\rm B)$ $3$. 
The $5$-digit number $\overline{2018U}$ is divisible by $9$. What is the remainder when this number is divided by $8$? 
a. $$1$$ 
b. $$3$$ 
c. $$5$$ 
d. $$6$$ 
e. $$7$$ 