Rearranging, we find $x+y=2x, x=y, \frac xy = 1$. 
Suppose that $x$ and $y$ are nonzero real numbers such that $\frac{x+y}{x}=2$, what is the value of $\frac{x}{y}$? 
Options:
  - $$\frac{1}{3}$$ 
  - $$-1$$ 
  - $$1$$ 
  - $$3$$ 