There are $7$ out of $36$ outcomes are perfect squares: $1+3$, $2+2$, $3+1$, $3+6$, $4+5$, $5+4$, $6+3$. 
A fair $6-$sided die is rolled twice. What is the probability that the sum of the two rolls\textquotesingle{} outcomes is a perfect square? 
Options:
A) $\dfrac{1}{27}$ 
B) $\dfrac{7}{9}$ 
C) $\dfrac{7}{36}$ 
D) $\dfrac{1}{9}$ 
E) $\dfrac{5}{18}$ 