$$36={{2}^{2}}\times {{3}^{2}}$$, so the number of its factors would be $$\left( 2+1 \right)\times \left( 2+1 \right)=9$$, Among them, there are $$\left( 2+1 \right)\times 1=3$$ factors which has $${{2}^{2}}$$ as its factors. 
How many positive factors of $$36$$ are also multiples of $$4$$ ? 
1. $$2$$ 
2. $$3$$ 
3. $$4$$ 
4. $$5$$ 