We can imagine the distance of Jack\textquotesingle s long jump as $1$, and the distance of Mike\textquotesingle s long jump as $2$. The distance that Mike jumps three times is $2$$\times$$3$=$6$.  ~Jack needs to jump $6$$\div$$1=$$6$ times. 
Mike and Jack compete in the long jump. Mike jumps twice as far as Jack once. Mike jumps three times. How many times can jack jump the distance equal to Mike？(adapted from $$2008$$ Math kangaroo Problems, Level $$1-2$$, Question \#$$6$$) 
$$2$$ 
$$6$$ 
$$3$$ 
$$4$$ 
$$5$$ 