$$36={{2}^{2}}\times {{3}^{2}}$$, so the number of its factors would be $$\left( 2+1 \right)\times \left( 2+1 \right)=9$$, Among them, there are $$\left( 2+1 \right)\times 1=3$$ factors which has $${{2}^{2}}$$ as its factors. 
How many positive factors of $$36$$ are also multiples of $$4$$ ? 
a) $$2$$ 
b) $$3$$ 
c) $$4$$ 
d) $$5$$ 
e) $$6$$ 