At $$6:15$$, hr. hand has moved $$\left(1/4\right)\times 30^{}\circ$$ from $$6$$, so $$\angle =90^{}\circ+30^{}\circ/4=97.5^{}\circ$$. 
The hands of a circular clock form aangle at $$6:15$$ P.M. 
a: $$82.5^{}\circ$$ 
b: $$90^{}\circ$$ 
c: $$97.5^{}\circ$$ 
d: $$270^{}\circ$$ 