One-digit number: $9-1=8$  Two-digit number: $8\times9=72$  Three-digit number: $8\times9\times9=648$  So, there are $8+72+648=728$ numbers that meet the requirements. 
How many whole numbers between $$1$$ and $$1000$$ do not contain the digit $$1$$? ($2009$ AMC $8$ Problems, Question \#$22$) 
A. $$512$$ 
B. $$648$$ 
C. $$720$$ 
D. $$728$$ 
E. $$800$$ 