Out of $$18$$ chocolates there are $$6\times2=12$$ of the flavours that she likes. So the probability of Swee Tuth getting one she doesn\textquotesingle t like is $$\frac{6}{18} =\frac{1}{3}$$. 
There are $$18$$ chocolates in Swee Tuth\textquotesingle s box, $$2$$ each of $$9$$ flavours. She likes only $$6$$ of the flavours. If she picks a chocolate at random, what is the probability of her getting one she doesn\textquotesingle t like? 
[a] $$\frac{2}{9}$$ 
[b] $$\frac{1}{3}$$ 
[c] $$\frac{4}{9}$$ 
[d] $$\frac{1}{2}$$ 
[e] $$\frac{2}{3}$$ 