$$f(x)$$的对称轴为$$x=\frac{ \pi }{2}$$，  易得$$0\textless{}\alpha \textless{}\frac{ \pi }{6}\textless{}\frac{ \pi }{4}\textless{}\beta \textless{}\frac{ \pi }{3}\textless{}\frac{ \pi }{2}\textless{}\gamma \textless{}\frac{2 \pi }{3}\textless{}\frac{3 \pi }{4}\textless{}\delta \textless{}\frac{5 \pi }{6}$$．  故选$$\text{B}$$． 
设$$f(x)={{x}^{2}}- \pi x$$，$$\alpha =\arcsin \frac{1}{3}$$，$$\beta =\arctan \frac{5}{4}$$，$$\gamma =\arccos \left( -\frac{1}{3} \right)$$，$$\delta =\text{arc}\cot \left( -\frac{5}{4} \right)$$，则（~ ~ ）．

[1] $$f\left( \alpha \right)\textgreater f\left( \beta \right)\textgreater f\left( \delta \right)\textgreater f\left( \gamma \right)$$ 
[2] $$f\left( \alpha \right)\textgreater f\left( \delta \right)\textgreater f\left( \beta \right)\textgreater f\left( \gamma \right)$$ 
[3] $$f\left( \delta \right)\textgreater f\left( \alpha \right)\textgreater f\left( \beta \right)\textgreater f\left( \gamma \right)$$ 
[4] $$f\left( \delta \right)\textgreater f\left( \alpha \right)\textgreater f\left( \gamma \right)\textgreater f\left( \beta \right)$$ 