There are $12$ different combinations. The product of two numbers is greater than $20$ will be $4\times5$ and $4\times6$. Thus, the probability is $\frac 2{12}$ = $\frac 16$. 
Two tiles numbered $3$ and $4$ are turned face down, respectively. One tile is turned up at random, and throw a die to get a number from $1$ to $6$. What is the probability that the product of the numbers on the tile and the die is greater than or equal to $20$? 

1) $\frac {1}{2}$ 
2) $\frac {1}{6}$ 
3) $\frac {1}{3}$ 
4) $\frac {1}{4}$ 
5) $\frac {1}{12}$ 