Rearranging, we find $x+y=2x, -x=y, \frac xy = -1$. 
Suppose that $x$ and $y$ are nonzero real numbers such that $\frac{x+y}{x}=2$, what is the value of $\frac{x}{y}$? 

(1) $$\frac{1}{3}$$ 
(2) $$-1$$ 
(3) $$1$$ 
(4) $$3$$ 