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# m15 q29

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Author Message
Senior Manager
Status: Happy to join ROSS!
Joined: 29 Sep 2010
Posts: 279
Concentration: General Management, Strategy
Schools: Ross '14 (M)
Followers: 19

Kudos [?]: 120 [0], given: 48

### Show Tags

05 Dec 2010, 13:11
If in a six-digit integer N , F(k) is the value of the k- th digit, is N divisible by 7 (For example, F(4) is the value of the hundreds digit of N )?

1. F(1)= F(4); F(2) = F(5); F(3)=F(6)
2. F(1)= F(2)= F(3) =.. = F(6)

OA: D
Explanation
Statements (1) and (2) by themselves are sufficient. S1 tells us that the last three digits of are the same as the first three digits: N=abcabc . Note that abc*1000+abc = abc*1001 . As 1001 is divisible by 7, is also divisible by 7.

==
I did not get it. Why do we talk about 1001? and abc*1001 if we only have 6-digit integer N?
And what about Statement 2 - where is not a word about its sufficiency.
Thanks!
VP
Status: There is always something new !!
Affiliations: PMI,QAI Global,eXampleCG
Joined: 08 May 2009
Posts: 1353
Followers: 17

Kudos [?]: 217 [1] , given: 10

Re: m15 q29 [#permalink]

### Show Tags

05 Dec 2010, 20:37
1
KUDOS
Let f(1) = f(4) = A ; f(2) = f(5) = B ; f(3) = f(6) = C then,

A. (10^5 * C ) + ( 10^4 *B) + (10^3 *A ) + ( 10^2 * C ) + (10 * B) + A

Reducing the terms we have

( 10^2 * C ) * [ 10^3 + 1 ] + (10 * B) * [ 10^3 + 1 ] + A * [ 10^3 + 1 ]

Taking [ 10^3 + 1 ] common term outside

[ 10^3 + 1 ] * {(10^2 * C) + (10 * B) + A }

[ 10^3 + 1 ] = 1001 is divisible by 7. Hence A is sufficient.

Let f(1) = f(2) = ...... = f(6) = a ; then

B. (10^5 * a ) +(10^4 * a)+ ( 10^3 * a )+ (10^2 * a )+ (10 * a ) + a

taking a the common term outside ,

(10^5 + 10^4 + 10^3 + 10^2 + 10 + 1 ) a

111111 * a , here 111111 is divisible by 7. Hence B is sufficient. So, OA D.

I believe this helps.
_________________

Visit -- http://www.sustainable-sphere.com/
Promote Green Business,Sustainable Living and Green Earth !!

Re: m15 q29   [#permalink] 05 Dec 2010, 20:37
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Topics:
m19 Q29 2 01 May 2011, 22:53
1 Q29 of M13 1 08 Feb 2010, 09:18
m06, Q 29 2 20 Sep 2009, 16:21
12 M15#18 22 19 Nov 2008, 19:24
6 M15 #3 26 22 Oct 2008, 13:23
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# m15 q29

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Moderator: Bunuel

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.
The provided text does not contain a mathematical question or any calculations. It appears to be a discussion or explanation of a solution to a problem, but the problem itself is not clearly stated within the text.
no_question
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
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Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 24 Aug 2016, 12:02

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
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we will pick new questions that match your level based on your Timer History

Track

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# Events & Promotions

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# m15 q29

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Senior Manager
Status: Happy to join ROSS!
Joined: 29 Sep 2010
Posts: 279
Concentration: General Management, Strategy
Schools: Ross '14 (M)
Followers: 19

Kudos [?]: 120 [0], given: 48

### Show Tags

05 Dec 2010, 13:11
If in a six-digit integer N , F(k) is the value of the k- th digit, is N divisible by 7 (For example, F(4) is the value of the hundreds digit of N )?

1. F(1)= F(4); F(2) = F(5); F(3)=F(6)
2. F(1)= F(2)= F(3) =.. = F(6)

OA: D
Explanation
Statements (1) and (2) by themselves are sufficient. S1 tells us that the last three digits of are the same as the first three digits: N=abcabc . Note that abc*1000+abc = abc*1001 . As 1001 is divisible by 7, is also divisible by 7.

==
I did not get it. Why do we talk about 1001? and abc*1001 if we only have 6-digit integer N?
And what about Statement 2 - where is not a word about its sufficiency.
Thanks!
VP
Status: There is always something new !!
Affiliations: PMI,QAI Global,eXampleCG
Joined: 08 May 2009
Posts: 1353
Followers: 17

Kudos [?]: 217 [1] , given: 10

Re: m15 q29 [#permalink]

### Show Tags

05 Dec 2010, 20:37
1
KUDOS
Let f(1) = f(4) = A ; f(2) = f(5) = B ; f(3) = f(6) = C then,

A. (10^5 * C ) + ( 10^4 *B) + (10^3 *A ) + ( 10^2 * C ) + (10 * B) + A

Reducing the terms we have

( 10^2 * C ) * [ 10^3 + 1 ] + (10 * B) * [ 10^3 + 1 ] + A * [ 10^3 + 1 ]

Taking [ 10^3 + 1 ] common term outside

[ 10^3 + 1 ] * {(10^2 * C) + (10 * B) + A }

[ 10^3 + 1 ] = 1001 is divisible by 7. Hence A is sufficient.

Let f(1) = f(2) = ...... = f(6) = a ; then

B. (10^5 * a ) +(10^4 * a)+ ( 10^3 * a )+ (10^2 * a )+ (10 * a ) + a

taking a the common term outside ,

(10^5 + 10^4 + 10^3 + 10^2 + 10 + 1 ) a

111111 * a , here 111111 is divisible by 7. Hence B is sufficient. So, OA D.

I believe this helps.
_________________

Visit -- http://www.sustainable-sphere.com/
Promote Green Business,Sustainable Living and Green Earth !!

Re: m15 q29   [#permalink] 05 Dec 2010, 20:37
Similar topics Replies Last post
Similar
Topics:
m19 Q29 2 01 May 2011, 22:53
1 Q29 of M13 1 08 Feb 2010, 09:18
m06, Q 29 2 20 Sep 2009, 16:21
12 M15#18 22 19 Nov 2008, 19:24
6 M15 #3 26 22 Oct 2008, 13:23
Display posts from previous: Sort by

# m15 q29

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

Moderator: Bunuel

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.
user
The provided text does not contain a mathematical question or any calculations. It appears to be a discussion or explanation of a solution to a problem, but the problem itself is not clearly stated within the text.

TYPE: NO_QUESTION