# (solved)Question 10 SSC-CGL 2020 March 4 Shift 1

In triangle ABC, ∠C = 68°, ∠B = 32°. The external angle bisectors of ∠B and ∠C meet at point O. Find ∠BOC.
(Rev. 18-Jun-2024)

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### Question 10SSC-CGL 2020 Mar 4 Shift 1

In triangle ABC, ∠C = 68°, ∠B = 32°. The external angle bisectors of ∠B and ∠C meet at point O. Find ∠BOC.

### Solution inBrief

∠A = 180 - (32 + 68) = 80. By a theorem in geometry, ∠BOC = 90 - (∠A/2). So ∠BOC = 90 - 80/2 = 50 degree answer!

### Solution in Detail

BO is angle bisector, therefore,

$\displaystyle \angle {OBC} = \frac{180 - 32}{2} = 74\degree$

Similarly, we can deduce that

$\displaystyle \angle {BCO} = \frac{180 - 68}{2} = 56\degree$

From $\displaystyle \Delta OBC$ we get

$\displaystyle x + 74 + 56 = 180$

$\displaystyle \therefore x = 50 \degree\:\underline{Ans}$

This Blog Post/Article "(solved)Question 10 SSC-CGL 2020 March 4 Shift 1" by Parveen is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
The text passage contains a mathematical question related to geometry, specifically about finding the measure of an angle in a triangle. The passage also provides a detailed solution to the problem.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
# (solved)Question 10 SSC-CGL 2020 March 4 Shift 1

In triangle ABC, ∠C = 68°, ∠B = 32°. The external angle bisectors of ∠B and ∠C meet at point O. Find ∠BOC.
(Rev. 18-Jun-2024)

## Categories | About Hoven's Blog

,

### Question 10SSC-CGL 2020 Mar 4 Shift 1

In triangle ABC, ∠C = 68°, ∠B = 32°. The external angle bisectors of ∠B and ∠C meet at point O. Find ∠BOC.

### Solution inBrief

∠A = 180 - (32 + 68) = 80. By a theorem in geometry, ∠BOC = 90 - (∠A/2). So ∠BOC = 90 - 80/2 = 50 degree answer!

### Solution in Detail

BO is angle bisector, therefore,

$\displaystyle \angle {OBC} = \frac{180 - 32}{2} = 74\degree$

Similarly, we can deduce that

$\displaystyle \angle {BCO} = \frac{180 - 68}{2} = 56\degree$

From $\displaystyle \Delta OBC$ we get

$\displaystyle x + 74 + 56 = 180$

$\displaystyle \therefore x = 50 \degree\:\underline{Ans}$

This Blog Post/Article "(solved)Question 10 SSC-CGL 2020 March 4 Shift 1" by Parveen is licensed under a Creative Commons Attribution-NonCommercial-ShareAlike 4.0 International License.
user
The text passage contains a mathematical question related to geometry, specifically about finding the measure of an angle in a triangle. The passage also provides a detailed solution to the problem.

TYPE: SINGLE_QUESTION_WITH_ANSWER