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Inductance Calculator
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Its known that inductance (L) is the opposing change in current. Lets take coil wounded by the wire the resisting force that acts in a coil of wire due the current flow leads to the emf.

So the inductance is given by
L = $\frac{\mu N^2 A}{l}$Where $\mu$ is the core material permeability,
N is the no of turns the coil wire has,
A is the core area,
l is the average coil length.

Inductance Calculator is a online tool to calculate any unknown quantity of these inductance (L), core material permeability ($\mu$), no of turns (N), core area (A), average coil length (l) if any four of these are known.

## Steps for Inductance Calculator

Step 1 :

Read the given problem and observe the quantities given

Step 2 :

Use the formula

L = $\frac{N^2 \mu A}{l}$

Substitute the given values in above equation and calculate the unknown quantity.

## Problems on Inductance Calculator

1. ### A inductor coil has 600 turns of copper wire with core area 0.6 m2 and length 70 m with permeability 0.6.Calculate the self-inductance.

Step 1 :

Given: No of turns N = 600 turns,
Area A = 0.6 m2,
Length l = 70 m,
Permeability $\mu$ = 0.6

Step 2 :

Self Inductance is given by
L = $\frac{\mu N^2 A}{l}$
= $\frac{0.6 \times 600^2 \times 0.6 m}{70 m}$
= 1851.4 Henry

Hence the inductance L of the coil is 1851.4 Henry.

2. ### A coiled wire has 320 turns having the diameter of 20 cm and an unstretched length of 29 cm. what is its self inductance?

Step 1 :

Given: No of turns N = 320 turns,
Area A = $\pi$ $\times$ r2 = 314.2 m2,
Length l = 70 m,
Permeability $\mu$ = 0.6

Step 2 :

Self Inductance is given by
L = $\frac{\mu N^2 A}{l}$
= $\frac{0.6 \times 320^2 \times 314.2 m}{70 m}$
= 275777.8 Henry
The text passage provides a detailed explanation of inductance and how to calculate it using a formula. It also includes two example problems with step-by-step solutions.
multiple_questions_with_answers
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
To get the best deal on Tutoring, call 1-855-666-7440 (Toll Free)
Top

Inductance Calculator
Top
Its known that inductance (L) is the opposing change in current. Lets take coil wounded by the wire the resisting force that acts in a coil of wire due the current flow leads to the emf.

So the inductance is given by
L = $\frac{\mu N^2 A}{l}$Where $\mu$ is the core material permeability,
N is the no of turns the coil wire has,
A is the core area,
l is the average coil length.

Inductance Calculator is a online tool to calculate any unknown quantity of these inductance (L), core material permeability ($\mu$), no of turns (N), core area (A), average coil length (l) if any four of these are known.

## Steps for Inductance Calculator

Step 1 :

Read the given problem and observe the quantities given

Step 2 :

Use the formula

L = $\frac{N^2 \mu A}{l}$

Substitute the given values in above equation and calculate the unknown quantity.

## Problems on Inductance Calculator

1. ### A inductor coil has 600 turns of copper wire with core area 0.6 m2 and length 70 m with permeability 0.6.Calculate the self-inductance.

Step 1 :

Given: No of turns N = 600 turns,
Area A = 0.6 m2,
Length l = 70 m,
Permeability $\mu$ = 0.6

Step 2 :

Self Inductance is given by
L = $\frac{\mu N^2 A}{l}$
= $\frac{0.6 \times 600^2 \times 0.6 m}{70 m}$
= 1851.4 Henry

Hence the inductance L of the coil is 1851.4 Henry.

2. ### A coiled wire has 320 turns having the diameter of 20 cm and an unstretched length of 29 cm. what is its self inductance?

Step 1 :

Given: No of turns N = 320 turns,
Area A = $\pi$ $\times$ r2 = 314.2 m2,
Length l = 70 m,
Permeability $\mu$ = 0.6

Step 2 :

Self Inductance is given by
L = $\frac{\mu N^2 A}{l}$
= $\frac{0.6 \times 320^2 \times 314.2 m}{70 m}$
= 275777.8 Henry
user
The text passage provides a detailed explanation of inductance and how to calculate it using a formula. It also includes two example problems with step-by-step solutions.

TYPE: MULTIPLE_QUESTIONS_WITH_ANSWERS