## Algebra 1

$y^{2}$-16y+64 Using the rule of $a^{2}$-2ab+$b^{2}$= $(a-b)^{2}$ In this case, the a= y and b= 8 as substituting these gives us the original polynomial $a^{2}$-2ab+$b^{2}$ $y^{2}$-2(y)(8)+$8^{2}$ $y^{2}$-16y+64 Thus: $y^{2}$-16y+64 = $(y-8)^{2}$ = (y-8)(y-8)
The text passage provides a step-by-step solution to factor a quadratic polynomial using a specific algebraic identity, but it does not contain a question or an explicit answer to a question.
no_question
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
## Algebra 1

$y^{2}$-16y+64 Using the rule of $a^{2}$-2ab+$b^{2}$= $(a-b)^{2}$ In this case, the a= y and b= 8 as substituting these gives us the original polynomial $a^{2}$-2ab+$b^{2}$ $y^{2}$-2(y)(8)+$8^{2}$ $y^{2}$-16y+64 Thus: $y^{2}$-16y+64 = $(y-8)^{2}$ = (y-8)(y-8)
user
The text passage provides a step-by-step solution to factor a quadratic polynomial using a specific algebraic identity, but it does not contain a question or an explicit answer to a question.

TYPE: NO_QUESTION