# Find any critical numbers of the function.  f(θ) = 6sec θ + 3tan θ, 0 < θ < 2π  f(θ) = 6sec θ + 3tan θ, 0 < θ < 2πθ =? Enter your answers as a comma-separated list.

You need to remember that the function `f(theta)`  has critical values if the equation `f'(theta)=0`  has solutions, hence, you neded to evaluate `f'(theta)`  such that:

`f'(theta) = (6sec theta + 3tan theta)'`

You should remember that `sec theta = 1/cos theta` , hence, you need to use quotient rule to evaluate (sec...

Start your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

You need to remember that the function `f(theta)`  has critical values if the equation `f'(theta)=0`  has solutions, hence, you neded to evaluate `f'(theta)`  such that:

`f'(theta) = (6sec theta + 3tan theta)'`

You should remember that `sec theta = 1/cos theta` , hence, you need to use quotient rule to evaluate (sec theta)' such that:

`(sec theta)' = (1'*cos theta - 1*(cos theta)')/(cos^2 theta)`

`(sec theta)' = -(-sin theta)/(cos^2 theta)=> (sec theta)' = (sin theta)/(cos^2 theta)`

`f'(theta) = 6sin theta/(cos^2 theta) + 3/(cos^2 theta)`

Factoring out `3/(cos^2 theta)`  yields:

`f'(theta) = 3/(cos^2 theta)(2sin theta + 1)`

You need to solve for theta the equation `f'(theta) = 0`  such that:

`3/(cos^2 theta)(2sin theta + 1) = 0`

Since `3/(cos^2 theta)!=0 => 2sin theta + 1 = 0`  such that:

`2sin theta + 1 = 0 => 2sin theta=- 1 => sin theta = -1/2`

You need to remember that the sine function is negative in quadrants 3 and 4, hence, you will have the following solutions to the equation `sin theta = -1/2`  such that:

`sin theta = -1/2 => theta = pi+pi/6 => theta = 7pi/6` (quadrant 3)

`theta = 2pi-pi/6 => theta = 11pi/6`  (quadrant 4)

Hence, evaluating the critical values of the function yields `theta = 7pi/6`  and `theta = 11pi/6` .

Approved by eNotes Editorial Team
The text passage contains a mathematical question about finding the critical numbers of a given function, and it provides a detailed solution to the problem.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
# Find any critical numbers of the function.  f(θ) = 6sec θ + 3tan θ, 0 < θ < 2π  f(θ) = 6sec θ + 3tan θ, 0 < θ < 2πθ =? Enter your answers as a comma-separated list.

You need to remember that the function `f(theta)`  has critical values if the equation `f'(theta)=0`  has solutions, hence, you neded to evaluate `f'(theta)`  such that:

`f'(theta) = (6sec theta + 3tan theta)'`

You should remember that `sec theta = 1/cos theta` , hence, you need to use quotient rule to evaluate (sec...

Start your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

You need to remember that the function `f(theta)`  has critical values if the equation `f'(theta)=0`  has solutions, hence, you neded to evaluate `f'(theta)`  such that:

`f'(theta) = (6sec theta + 3tan theta)'`

You should remember that `sec theta = 1/cos theta` , hence, you need to use quotient rule to evaluate (sec theta)' such that:

`(sec theta)' = (1'*cos theta - 1*(cos theta)')/(cos^2 theta)`

`(sec theta)' = -(-sin theta)/(cos^2 theta)=> (sec theta)' = (sin theta)/(cos^2 theta)`

`f'(theta) = 6sin theta/(cos^2 theta) + 3/(cos^2 theta)`

Factoring out `3/(cos^2 theta)`  yields:

`f'(theta) = 3/(cos^2 theta)(2sin theta + 1)`

You need to solve for theta the equation `f'(theta) = 0`  such that:

`3/(cos^2 theta)(2sin theta + 1) = 0`

Since `3/(cos^2 theta)!=0 => 2sin theta + 1 = 0`  such that:

`2sin theta + 1 = 0 => 2sin theta=- 1 => sin theta = -1/2`

You need to remember that the sine function is negative in quadrants 3 and 4, hence, you will have the following solutions to the equation `sin theta = -1/2`  such that:

`sin theta = -1/2 => theta = pi+pi/6 => theta = 7pi/6` (quadrant 3)

`theta = 2pi-pi/6 => theta = 11pi/6`  (quadrant 4)

Hence, evaluating the critical values of the function yields `theta = 7pi/6`  and `theta = 11pi/6` .

Approved by eNotes Editorial Team
user
The text passage contains a mathematical question about finding the critical numbers of a given function, and it provides a detailed solution to the problem.

TYPE: SINGLE_QUESTION_WITH_ANSWER