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# Calc03_7 - 3.7 Implicit Differentiation Niagara Falls NY...

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3.7 Implicit Differentiation Niagara Falls, NY & Canada Greg Kelly, Hanford High School, Richland, Washington Photo by Vickie Kelly, 2003

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Before we start, we are going to load the Calculus Tools flash application software to your calculator. 1. Connect the sending and receiving calculators together. 2. On the sending unit, press , and then . 2nd VAR-LINK 2nd F7 Press to select . F4 Calculus Tools 3. On the receiving unit, press . 2nd VAR-LINK 4. On both units, press (Link). F3 4. On the receiving unit, select (Receive). 2 5. On the sending unit, select (Send). 1
2 2 1 x y + = This is not a function, but it would still be nice to be able to find the slope. 2 2 1 d d d x y dx dx dx + = Do the same thing to both sides. 2 2 0 dy x y dx + = Note use of chain rule. 2 2 dy y x dx = - 2 2 dy x dx y - = dy x dx y = -

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2 2 sin y x y = + 2 2 sin d d d y x y dx dx dx = + This can’t be solved for y . 2 2 cos dy dy x y dx dx = + 2 cos 2 dy dy y x dx dx - = ( 29 2 2 cos dy x y dx = - 2 2 cos dy x dx y = - This technique is called implicit differentiation.
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The text passage appears to be a set of slides or notes on a calculus topic, specifically implicit differentiation, with examples and explanations. It does not contain any explicit mathematical questions or answers in a question-and-answer format.
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- MULTIPLE_QUESTIONS_WITH_ANSWERS
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# Calc03_7 - 3.7 Implicit Differentiation Niagara Falls NY...

This preview shows pages 1–5. Sign up to view the full content.

3.7 Implicit Differentiation Niagara Falls, NY & Canada Greg Kelly, Hanford High School, Richland, Washington Photo by Vickie Kelly, 2003

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Before we start, we are going to load the Calculus Tools flash application software to your calculator. 1. Connect the sending and receiving calculators together. 2. On the sending unit, press , and then . 2nd VAR-LINK 2nd F7 Press to select . F4 Calculus Tools 3. On the receiving unit, press . 2nd VAR-LINK 4. On both units, press (Link). F3 4. On the receiving unit, select (Receive). 2 5. On the sending unit, select (Send). 1
2 2 1 x y + = This is not a function, but it would still be nice to be able to find the slope. 2 2 1 d d d x y dx dx dx + = Do the same thing to both sides. 2 2 0 dy x y dx + = Note use of chain rule. 2 2 dy y x dx = - 2 2 dy x dx y - = dy x dx y = -

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2 2 sin y x y = + 2 2 sin d d d y x y dx dx dx = + This can’t be solved for y . 2 2 cos dy dy x y dx dx = + 2 cos 2 dy dy y x dx dx - = ( 29 2 2 cos dy x y dx = - 2 2 cos dy x dx y = - This technique is called implicit differentiation.
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The text passage appears to be a set of slides or notes on a calculus topic, specifically implicit differentiation, with examples and explanations. It does not contain any explicit mathematical questions or answers in a question-and-answer format.

TYPE: NO_QUESTION