## Precalculus (6th Edition) Blitzer

See figure; solution: $(0,5)$ and $(0,-5)$
Step 1. Graph the given equations $\begin{cases} x^2+y^2=25 \\ 25x^2+y^2=25 \end{cases}$ as shown in the figure. Step 2. We can identify the intersect points as $(0,5)$ and $(0,-5)$ Step 3. Checking the solutions with the first equation, we have $(0)^2+(5)^2=25$ and $(0)^2+(-5)^2=25$ Step 4. Checking the solutions with the second equation, we have $25 (0)^2+(5)^2=25$ and $25 (0)^2+(-5)^2=25$
The text passage describes a precalculus problem involving the graphical solution of a system of equations. It provides the solution points and verifies them by substitution.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
## Precalculus (6th Edition) Blitzer

See figure; solution: $(0,5)$ and $(0,-5)$
Step 1. Graph the given equations $\begin{cases} x^2+y^2=25 \\ 25x^2+y^2=25 \end{cases}$ as shown in the figure. Step 2. We can identify the intersect points as $(0,5)$ and $(0,-5)$ Step 3. Checking the solutions with the first equation, we have $(0)^2+(5)^2=25$ and $(0)^2+(-5)^2=25$ Step 4. Checking the solutions with the second equation, we have $25 (0)^2+(5)^2=25$ and $25 (0)^2+(-5)^2=25$
user
The text passage describes a precalculus problem involving the graphical solution of a system of equations. It provides the solution points and verifies them by substitution.

TYPE: SINGLE_QUESTION_WITH_ANSWER