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# Polynomial Factorization - Series 2c

FACTORING BINOMIALS USING DIFFERENCE OF TWO SQUARES

Binomials of the general form m^2 - n^2 can be factored into terms

(m - n)*(m + n).

example5:
9x^2 - 64 = (3x)^2 - (8)^2
= (3x-8)*(3x+8)

example6:
4a^3 - 4a = 4a * (a^2 -1)
= 4a * (a^2 - 1^2)
= 4a * (a - 1)(a + 1)

example7:
x^4 - y^4 = (x^2)^2 - (y^2)^2
= (x^2 - y^2) * (x^2 + y^2)
= (x - y)*(x +y) *(x^2 +y^2)

FACTORING BINOMIALS USING SUM AND DIFFERENCE OF TWO CUBES

Binomials of the general form outlined below can be factored as described:

a^3 + b^3 can be factored into (a + b) * (a^2 - ab + b^2)
a^3 - b^3 can be factored into (a - b) * (a^2 + ab + b^2)
The text passage provides examples and explanations for factoring binomials using the difference of two squares and the sum and difference of two cubes. It does not contain any specific questions or answers to mathematical problems.
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    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
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# Polynomial Factorization - Series 2c

FACTORING BINOMIALS USING DIFFERENCE OF TWO SQUARES

Binomials of the general form m^2 - n^2 can be factored into terms

(m - n)*(m + n).

example5:
9x^2 - 64 = (3x)^2 - (8)^2
= (3x-8)*(3x+8)

example6:
4a^3 - 4a = 4a * (a^2 -1)
= 4a * (a^2 - 1^2)
= 4a * (a - 1)(a + 1)

example7:
x^4 - y^4 = (x^2)^2 - (y^2)^2
= (x^2 - y^2) * (x^2 + y^2)
= (x - y)*(x +y) *(x^2 +y^2)

FACTORING BINOMIALS USING SUM AND DIFFERENCE OF TWO CUBES

Binomials of the general form outlined below can be factored as described:

a^3 + b^3 can be factored into (a + b) * (a^2 - ab + b^2)
a^3 - b^3 can be factored into (a - b) * (a^2 + ab + b^2)
user
The text passage provides examples and explanations for factoring binomials using the difference of two squares and the sum and difference of two cubes. It does not contain any specific questions or answers to mathematical problems.

TYPE: NO_QUESTION