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# Two boats are heading towards each other at constant speeds

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01 May 2012, 20:29
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Two boats are heading towards each other at constant speeds of 5 miles/hr and 20 miles/hr respectively. They begin at a distance 20 miles from each other. How far are they (in miles) one minute before they collide ?

A. 1/12
B. 5/12
C. 1/6
D. 1/3
E. 1/5
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01 May 2012, 21:52
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gmihir wrote:
Two boats are heading towards each other at constant speeds of 5 miles/hr and 20 miles/hr respectively. They begin at a distance 20 miles from each other. How far are they (in miles) one minute before they collide ?

A. 1/12
B. 5/12
C. 1/6
D. 1/3
E. 1/5

The question asks: how far apart will they be 1 minute=1/60 hours before they collide?

Since the combined rate of the boats is 5+20=25 mph then 1/60 hours before they collide they'll be rate*time=distance --> 25*1/60=5/12 miles apart.

Similar question to practice: 12-easy-pieces-or-not-126366.html#p1033924

Hope it helps.
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02 May 2012, 21:34
Thanks Bunnel for the great link - awesome questions!!

For this one (two boats heading towards each other) - i calculated the time they would collide with each other (48th min) and then "tried" calculating from there on, taking eons to solve - how can the problem be solved with this apporach ? is 25*1/60 the only way to solve such problems ?
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03 May 2012, 11:23
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gmihir wrote:
Thanks Bunnel for the great link - awesome questions!!

For this one (two boats heading towards each other) - i calculated the time they would collide with each other (48th min) and then "tried" calculating from there on, taking eons to solve - how can the problem be solved with this apporach ? is 25*1/60 the only way to solve such problems ?

It's not the only way but for sure the shortest way to solve this problem.
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03 May 2012, 18:47
I first calculated the time at which they collide, assuming they started at the same time. but i did not even need it.

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04 May 2012, 19:44
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gmihir wrote:
Thanks Bunnel for the great link - awesome questions!!

For this one (two boats heading towards each other) - i calculated the time they would collide with each other (48th min) and then "tried" calculating from there on, taking eons to solve - how can the problem be solved with this apporach ? is 25*1/60 the only way to solve such problems ?

Bunuel has already given you a great and most direct approach for this question. But if you did go the round about way, you could have solved it in this way:

Since their combined speed is 20 + 5 = 25 miles/hr, they cover 20 miles in $$\frac{20}{25}$$ hrs i.e. $$\frac{20}{25} * 60$$ mins = 48 mins

Now, in 48 mins, they cover 20 miles. So in 1 min, they must have covered 20/48 = 5/12 miles
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Director Joined: 24 Aug 2009 Posts: 507 Schools: Harvard, Columbia, Stern, Booth, LSB, Followers: 17 Kudos [?]: 676 [1] , given: 276 Re: Two boats are heading towards each other at constant speeds [#permalink] ### Show Tags 25 Aug 2012, 10:53 1 This post received KUDOS Hi Bunuel, Your explanation is always the best. I have a slightly different Logic to solve this question. Hope you will like the logic The question asks: How much distance will both travel in 1 minute? Since the combined rate of the boats is 5+20=25 mph = 25/60 mile/min = 5/12 mile/min Hence Answer: B. _________________ If you like my Question/Explanation or the contribution, Kindly appreciate by pressing KUDOS. Kudos always maximizes GMATCLUB worth -Game Theory If you have any question regarding my post, kindly pm me or else I won't be able to reply GMAT Club Legend Joined: 09 Sep 2013 Posts: 13460 Followers: 575 Kudos [?]: 163 [0], given: 0 Re: Two boats are heading towards each other at constant speeds [#permalink] ### Show Tags 06 Nov 2013, 14:47 Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________ Senior Manager Joined: 13 May 2013 Posts: 472 Followers: 3 Kudos [?]: 160 [0], given: 134 Re: Two boats are heading towards each other at constant speeds [#permalink] ### Show Tags 06 Nov 2013, 18:21 Two boats are heading towards each other at constant speeds of 5 miles/hr and 20 miles/hr respectively. They begin at a distance 20 miles from each other. How far are they (in miles) one minute before they collide? I probably did this a bit backwards but here is how I figured it out... The boats travel at a combined rate of 25 miles/hour. If they need to cover 20 miles, it will take them 20/ (5/12) or roughly 48 minutes to reach one another. Either way, one minute before they collide, they will be 5/12ths of a mile away from one another, the distance they travel combined every minute. In this way, it is almost a trick question. ANSWER B. 5/12 Manager Joined: 03 Apr 2013 Posts: 117 Followers: 4 Kudos [?]: 18 [0], given: 526 Re: Two boats are heading towards each other at constant speeds [#permalink] ### Show Tags 19 Nov 2013, 12:07 Just form this simple equation :- 20 - (20/25 -1/60)X25 _________________ Spread some love..Like = +1 Kudos Manager Joined: 26 Sep 2013 Posts: 221 Concentration: Finance, Economics GMAT 1: 670 Q39 V41 GMAT 2: 730 Q49 V41 Followers: 4 Kudos [?]: 139 [0], given: 40 Re: Two boats are heading towards each other at constant speeds [#permalink] ### Show Tags 19 Nov 2013, 17:38 Bunuel wrote: gmihir wrote: Two boats are heading towards each other at constant speeds of 5 miles/hr and 20 miles/hr respectively. They begin at a distance 20 miles from each other. How far are they (in miles) one minute before they collide ? A. 1/12 B. 5/12 C. 1/6 D. 1/3 E. 1/5 The question asks: how far apart will they be 1 minute=1/60 hours before they collide? Since the combined rate of the boats is 5+20=25 mph then 1/60 hours before they collide they'll be rate*time=distance --> 25*1/60=5/12 miles apart. Answer: B. Similar question to practice: 12-easy-pieces-or-not-126366.html#p1033924 Hope it helps. Can you tell me why my method didn't work: I figured that 5*T+20*T=20 (since they'll have traveled 20 miles combined when they collide). so 25T=20, thus T=4/5. So if they collide at the 48 minute mark, then the distance they travel in 44 minutes combined, subtracted from 20 should give you the answer. so 5*(47/60)+20*(47/60)=D 235/60+940/60=D 1175/60=D 19 $$\frac{35}{60}$$=D So if they had traveled 19 35/60 miles in 44 minutes combined, then one minute before they collide they should be 25/60 miles apart. EDIT: Just edited my work. I had a glaring error. My method did work. I keep doing this. I don't know what's happening to me. I'm starting to become concerned. I make errors in calculations on roughtly 80% of the problems I do. I read the questions, and by the second line of the question my mind is already wandering and I don't see or remember anything after the first few words of the question. UGH. Just today I've done ~100 problems, and I made errors in simple addition, or just didn't remember a constraint (answer must be positive or something) on 89 of them. I feel like my brain is dying or something. Manager Joined: 22 Jul 2014 Posts: 129 Location: India Concentration: General Management, Finance GMAT 1: 590 Q V GMAT 2: 670 Q48 V34 WE: Engineering (Energy and Utilities) Followers: 0 Kudos [?]: 222 [0], given: 197 Re: Two boats are heading towards each other at constant speeds [#permalink] ### Show Tags 18 Sep 2014, 05:12 Sorry I don't get it The question states that we must find out the distance 1 min from the time of collision. So if they collided at the 48th minute, question asks us to find the distance of the 2 boats from each other in the 47th minute right? Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 7125 Location: Pune, India Followers: 2137 Kudos [?]: 13664 [1] , given: 222 Re: Two boats are heading towards each other at constant speeds [#permalink] ### Show Tags 18 Sep 2014, 20:55 1 This post received KUDOS Expert's post 1 This post was BOOKMARKED alphonsa wrote: Sorry I don't get it The question states that we must find out the distance 1 min from the time of collision. So if they collided at the 48th minute, question asks us to find the distance of the 2 boats from each other in the 47th minute right? Yes, there are two ways we can find the distance between the boats in the 47th minute: One way is we find the distance traveled by the boats in 47 mins and then subtract that out of the total distance. Another way is to find the distance they will cover in the last 1 min. That must be the distance between them in the 47th minute. Because at the end of the 48th minute, the boats meet - i.e. there is no distance between them. Knowing their speed, we know the distance traveled by them in 1 min and hence know the distance between them 1 min before they meet. The solutions above use this approach to get the answer. _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

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Re: Two boats are heading towards each other at constant speeds [#permalink]

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25 Oct 2014, 00:48
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what is the problem with my solution

after calculating the time of collision i.e 4/5=48 mins.

since we need to calculate the distance b/w them in 47 mins,cant we do like this ..

boat 1
48 mins=4miles
47 mins=(4/48) *47

similarly for boat 2
47 mins=(16/48)*47

then subtracting the distance of boat 2 from boat 1..

kindly correct me on this.

thank you
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25 Oct 2014, 00:49
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what is the problem with my solution

after calculating the time of collision i.e 4/5=48 mins.

since we need to calculate the distance b/w them in 47 mins,cant we do like this ..

boat 1
48 mins=4miles
47 mins=(4/48) *47

similarly for boat 2
47 mins=(16/48)*47

then subtracting the distance of boat 2 from boat 1..

kindly correct me on this.

thank you
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25 Oct 2014, 04:53
shreygupta3192 wrote:
what is the problem with my solution

after calculating the time of collision i.e 4/5=48 mins.

since we need to calculate the distance b/w them in 47 mins,cant we do like this ..

boat 1
48 mins=4miles
47 mins=(4/48) *47

similarly for boat 2
47 mins=(16/48)*47

then subtracting the distance of boat 2 from boat 1..

kindly correct me on this.

thank you

It should be 20 - ((16/48)*47 + (4/48) *47).
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30 Oct 2014, 10:49
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thank you for the valuable reply but why are we subtracting the total from 20 and not subtracting them by each other(as per my solution), as that will give us how far are they from each other..
confused.
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31 Oct 2014, 05:34
shreygupta3192 wrote:
thank you for the valuable reply but why are we subtracting the total from 20 and not subtracting them by each other(as per my solution), as that will give us how far are they from each other..
confused.

In 47 minutes boat 1 covers (16/48)*47 = 47/3 miles and boat 2 covers (4/48) *47 = 47/12 miles. Together in 47 minutes they cover 47/3 + 47/12 = 235/12 miles. Therefore after 47 minutes, so 1 minute before they meet, they will be 20 - 235/12 = 5/12 miles apart.

Hope it's clear.

P.S. 30-second approach to deal with this problem is given here: two-boats-are-heading-towards-each-other-at-constant-speeds-131737.html#p1080945
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06 Nov 2014, 00:19
okay now its clear.
a very stupid mistake from my side.
Thanx Bunuel.
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Re: Two boats are heading towards each other at constant speeds [#permalink]

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30 Jan 2015, 05:51
One question,

I thought that when 2 objects are moving towards each other we subtract the rates, as they cover this distance. When they more away from each other we add the rates because they create the distance. In this case, why did we add the rates?
Re: Two boats are heading towards each other at constant speeds   [#permalink] 30 Jan 2015, 05:51

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# Two boats are heading towards each other at constant speeds

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01 May 2012, 20:29
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Two boats are heading towards each other at constant speeds of 5 miles/hr and 20 miles/hr respectively. They begin at a distance 20 miles from each other. How far are they (in miles) one minute before they collide ?

A. 1/12
B. 5/12
C. 1/6
D. 1/3
E. 1/5
[Reveal] Spoiler: OA
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01 May 2012, 21:52
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gmihir wrote:
Two boats are heading towards each other at constant speeds of 5 miles/hr and 20 miles/hr respectively. They begin at a distance 20 miles from each other. How far are they (in miles) one minute before they collide ?

A. 1/12
B. 5/12
C. 1/6
D. 1/3
E. 1/5

The question asks: how far apart will they be 1 minute=1/60 hours before they collide?

Since the combined rate of the boats is 5+20=25 mph then 1/60 hours before they collide they'll be rate*time=distance --> 25*1/60=5/12 miles apart.

Similar question to practice: 12-easy-pieces-or-not-126366.html#p1033924

Hope it helps.
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02 May 2012, 21:34
Thanks Bunnel for the great link - awesome questions!!

For this one (two boats heading towards each other) - i calculated the time they would collide with each other (48th min) and then "tried" calculating from there on, taking eons to solve - how can the problem be solved with this apporach ? is 25*1/60 the only way to solve such problems ?
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Re: Two boats are heading towards each other at constant speeds [#permalink]

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03 May 2012, 11:23
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gmihir wrote:
Thanks Bunnel for the great link - awesome questions!!

For this one (two boats heading towards each other) - i calculated the time they would collide with each other (48th min) and then "tried" calculating from there on, taking eons to solve - how can the problem be solved with this apporach ? is 25*1/60 the only way to solve such problems ?

It's not the only way but for sure the shortest way to solve this problem.
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03 May 2012, 18:47
I first calculated the time at which they collide, assuming they started at the same time. but i did not even need it.

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04 May 2012, 19:44
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gmihir wrote:
Thanks Bunnel for the great link - awesome questions!!

For this one (two boats heading towards each other) - i calculated the time they would collide with each other (48th min) and then "tried" calculating from there on, taking eons to solve - how can the problem be solved with this apporach ? is 25*1/60 the only way to solve such problems ?

Bunuel has already given you a great and most direct approach for this question. But if you did go the round about way, you could have solved it in this way:

Since their combined speed is 20 + 5 = 25 miles/hr, they cover 20 miles in $$\frac{20}{25}$$ hrs i.e. $$\frac{20}{25} * 60$$ mins = 48 mins

Now, in 48 mins, they cover 20 miles. So in 1 min, they must have covered 20/48 = 5/12 miles
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Director Joined: 24 Aug 2009 Posts: 507 Schools: Harvard, Columbia, Stern, Booth, LSB, Followers: 17 Kudos [?]: 676 [1] , given: 276 Re: Two boats are heading towards each other at constant speeds [#permalink] ### Show Tags 25 Aug 2012, 10:53 1 This post received KUDOS Hi Bunuel, Your explanation is always the best. I have a slightly different Logic to solve this question. Hope you will like the logic The question asks: How much distance will both travel in 1 minute? Since the combined rate of the boats is 5+20=25 mph = 25/60 mile/min = 5/12 mile/min Hence Answer: B. _________________ If you like my Question/Explanation or the contribution, Kindly appreciate by pressing KUDOS. Kudos always maximizes GMATCLUB worth -Game Theory If you have any question regarding my post, kindly pm me or else I won't be able to reply GMAT Club Legend Joined: 09 Sep 2013 Posts: 13460 Followers: 575 Kudos [?]: 163 [0], given: 0 Re: Two boats are heading towards each other at constant speeds [#permalink] ### Show Tags 06 Nov 2013, 14:47 Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________ Senior Manager Joined: 13 May 2013 Posts: 472 Followers: 3 Kudos [?]: 160 [0], given: 134 Re: Two boats are heading towards each other at constant speeds [#permalink] ### Show Tags 06 Nov 2013, 18:21 Two boats are heading towards each other at constant speeds of 5 miles/hr and 20 miles/hr respectively. They begin at a distance 20 miles from each other. How far are they (in miles) one minute before they collide? I probably did this a bit backwards but here is how I figured it out... The boats travel at a combined rate of 25 miles/hour. If they need to cover 20 miles, it will take them 20/ (5/12) or roughly 48 minutes to reach one another. Either way, one minute before they collide, they will be 5/12ths of a mile away from one another, the distance they travel combined every minute. In this way, it is almost a trick question. ANSWER B. 5/12 Manager Joined: 03 Apr 2013 Posts: 117 Followers: 4 Kudos [?]: 18 [0], given: 526 Re: Two boats are heading towards each other at constant speeds [#permalink] ### Show Tags 19 Nov 2013, 12:07 Just form this simple equation :- 20 - (20/25 -1/60)X25 _________________ Spread some love..Like = +1 Kudos Manager Joined: 26 Sep 2013 Posts: 221 Concentration: Finance, Economics GMAT 1: 670 Q39 V41 GMAT 2: 730 Q49 V41 Followers: 4 Kudos [?]: 139 [0], given: 40 Re: Two boats are heading towards each other at constant speeds [#permalink] ### Show Tags 19 Nov 2013, 17:38 Bunuel wrote: gmihir wrote: Two boats are heading towards each other at constant speeds of 5 miles/hr and 20 miles/hr respectively. They begin at a distance 20 miles from each other. How far are they (in miles) one minute before they collide ? A. 1/12 B. 5/12 C. 1/6 D. 1/3 E. 1/5 The question asks: how far apart will they be 1 minute=1/60 hours before they collide? Since the combined rate of the boats is 5+20=25 mph then 1/60 hours before they collide they'll be rate*time=distance --> 25*1/60=5/12 miles apart. Answer: B. Similar question to practice: 12-easy-pieces-or-not-126366.html#p1033924 Hope it helps. Can you tell me why my method didn't work: I figured that 5*T+20*T=20 (since they'll have traveled 20 miles combined when they collide). so 25T=20, thus T=4/5. So if they collide at the 48 minute mark, then the distance they travel in 44 minutes combined, subtracted from 20 should give you the answer. so 5*(47/60)+20*(47/60)=D 235/60+940/60=D 1175/60=D 19 $$\frac{35}{60}$$=D So if they had traveled 19 35/60 miles in 44 minutes combined, then one minute before they collide they should be 25/60 miles apart. EDIT: Just edited my work. I had a glaring error. My method did work. I keep doing this. I don't know what's happening to me. I'm starting to become concerned. I make errors in calculations on roughtly 80% of the problems I do. I read the questions, and by the second line of the question my mind is already wandering and I don't see or remember anything after the first few words of the question. UGH. Just today I've done ~100 problems, and I made errors in simple addition, or just didn't remember a constraint (answer must be positive or something) on 89 of them. I feel like my brain is dying or something. Manager Joined: 22 Jul 2014 Posts: 129 Location: India Concentration: General Management, Finance GMAT 1: 590 Q V GMAT 2: 670 Q48 V34 WE: Engineering (Energy and Utilities) Followers: 0 Kudos [?]: 222 [0], given: 197 Re: Two boats are heading towards each other at constant speeds [#permalink] ### Show Tags 18 Sep 2014, 05:12 Sorry I don't get it The question states that we must find out the distance 1 min from the time of collision. So if they collided at the 48th minute, question asks us to find the distance of the 2 boats from each other in the 47th minute right? Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 7125 Location: Pune, India Followers: 2137 Kudos [?]: 13664 [1] , given: 222 Re: Two boats are heading towards each other at constant speeds [#permalink] ### Show Tags 18 Sep 2014, 20:55 1 This post received KUDOS Expert's post 1 This post was BOOKMARKED alphonsa wrote: Sorry I don't get it The question states that we must find out the distance 1 min from the time of collision. So if they collided at the 48th minute, question asks us to find the distance of the 2 boats from each other in the 47th minute right? Yes, there are two ways we can find the distance between the boats in the 47th minute: One way is we find the distance traveled by the boats in 47 mins and then subtract that out of the total distance. Another way is to find the distance they will cover in the last 1 min. That must be the distance between them in the 47th minute. Because at the end of the 48th minute, the boats meet - i.e. there is no distance between them. Knowing their speed, we know the distance traveled by them in 1 min and hence know the distance between them 1 min before they meet. The solutions above use this approach to get the answer. _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

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Re: Two boats are heading towards each other at constant speeds [#permalink]

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25 Oct 2014, 00:48
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what is the problem with my solution

after calculating the time of collision i.e 4/5=48 mins.

since we need to calculate the distance b/w them in 47 mins,cant we do like this ..

boat 1
48 mins=4miles
47 mins=(4/48) *47

similarly for boat 2
47 mins=(16/48)*47

then subtracting the distance of boat 2 from boat 1..

kindly correct me on this.

thank you
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Re: Two boats are heading towards each other at constant speeds [#permalink]

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25 Oct 2014, 00:49
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what is the problem with my solution

after calculating the time of collision i.e 4/5=48 mins.

since we need to calculate the distance b/w them in 47 mins,cant we do like this ..

boat 1
48 mins=4miles
47 mins=(4/48) *47

similarly for boat 2
47 mins=(16/48)*47

then subtracting the distance of boat 2 from boat 1..

kindly correct me on this.

thank you
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Re: Two boats are heading towards each other at constant speeds [#permalink]

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25 Oct 2014, 04:53
shreygupta3192 wrote:
what is the problem with my solution

after calculating the time of collision i.e 4/5=48 mins.

since we need to calculate the distance b/w them in 47 mins,cant we do like this ..

boat 1
48 mins=4miles
47 mins=(4/48) *47

similarly for boat 2
47 mins=(16/48)*47

then subtracting the distance of boat 2 from boat 1..

kindly correct me on this.

thank you

It should be 20 - ((16/48)*47 + (4/48) *47).
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Re: Two boats are heading towards each other at constant speeds [#permalink]

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30 Oct 2014, 10:49
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thank you for the valuable reply but why are we subtracting the total from 20 and not subtracting them by each other(as per my solution), as that will give us how far are they from each other..
confused.
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Re: Two boats are heading towards each other at constant speeds [#permalink]

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31 Oct 2014, 05:34
shreygupta3192 wrote:
thank you for the valuable reply but why are we subtracting the total from 20 and not subtracting them by each other(as per my solution), as that will give us how far are they from each other..
confused.

In 47 minutes boat 1 covers (16/48)*47 = 47/3 miles and boat 2 covers (4/48) *47 = 47/12 miles. Together in 47 minutes they cover 47/3 + 47/12 = 235/12 miles. Therefore after 47 minutes, so 1 minute before they meet, they will be 20 - 235/12 = 5/12 miles apart.

Hope it's clear.

P.S. 30-second approach to deal with this problem is given here: two-boats-are-heading-towards-each-other-at-constant-speeds-131737.html#p1080945
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Re: Two boats are heading towards each other at constant speeds [#permalink]

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06 Nov 2014, 00:19
okay now its clear.
a very stupid mistake from my side.
Thanx Bunuel.
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Re: Two boats are heading towards each other at constant speeds [#permalink]

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30 Jan 2015, 05:51
One question,

I thought that when 2 objects are moving towards each other we subtract the rates, as they cover this distance. When they more away from each other we add the rates because they create the distance. In this case, why did we add the rates?
Re: Two boats are heading towards each other at constant speeds   [#permalink] 30 Jan 2015, 05:51

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The two boats on a lake shown above are heading directly toward each other at constant speeds. The faster boat is 200 meters from the shore and the slower boat is 100 meters from the shore. The faster boat is traveling at 20 meters per second and the slower boat is traveling at 10 meters per second. How far, in meters, are the two boats from each other 2 seconds after they begin traveling toward each other?

(A) 50
(B) 60
(C) 70
(D) 80
(E) 90

Let's approach this step-by-step:

1) **Initial Distance Between the Boats:**
   - The faster boat is 200 meters from the shore.
   - The slower boat is 100 meters from the shore.
   - The total initial distance between the two boats is \(200 + 100 = 300\) meters.

2) **Speeds of the Boats:**
   - The faster boat is traveling at 20 meters per second.
   - The slower boat is traveling at 10 meters per second.

3) **Combined Speed:**
   - Since the boats are moving