# An alloy contains the copper and aluminum in the ratio of 7 : 4

## d) 14.4 kg

Solution -

Copper and Aluminum in the ratio = 7 : 4

Let,

Copper and Aluminum be 7x and 4x respectively in the weapons.

Aluminum in the weapon = 12 kg (given)

4x = 12

x = 3

Therefore,

Copper in the Weapon = 7x

Copper in the weapon = 7*3

Copper in the weapon = 21 kg

Total Alloy in the weapon = 12 + 21

Total Alloy in the weapon = 33 kg

12% of the alloy got destroyed.

Now,

Total alloy in the weapon = (100% - 12%)

Total alloy in the weapon = 88%

But,

Total alloy in the weapon = 33kg

88%  = 33kg

1% = (33/88)

1% = (3/8)

100% = [(3/8)*100]

100% = 300/8

100% = 37.5

Therefore,

Weight of the alloy required is 37.5

Hence,

The correct option is (c) 37.5

Thank You
The passage contains a mathematical word problem involving ratios and percentages, and it provides a detailed solution leading to the final answer.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
# An alloy contains the copper and aluminum in the ratio of 7 : 4

## d) 14.4 kg

Solution -

Copper and Aluminum in the ratio = 7 : 4

Let,

Copper and Aluminum be 7x and 4x respectively in the weapons.

Aluminum in the weapon = 12 kg (given)

4x = 12

x = 3

Therefore,

Copper in the Weapon = 7x

Copper in the weapon = 7*3

Copper in the weapon = 21 kg

Total Alloy in the weapon = 12 + 21

Total Alloy in the weapon = 33 kg

12% of the alloy got destroyed.

Now,

Total alloy in the weapon = (100% - 12%)

Total alloy in the weapon = 88%

But,

Total alloy in the weapon = 33kg

88%  = 33kg

1% = (33/88)

1% = (3/8)

100% = [(3/8)*100]

100% = 300/8

100% = 37.5

Therefore,

Weight of the alloy required is 37.5

Hence,

The correct option is (c) 37.5

Thank You
user
The passage contains a mathematical word problem involving ratios and percentages, and it provides a detailed solution leading to the final answer.

TYPE: SINGLE_QUESTION_WITH_ANSWER