## . An express train passes through a station. It enters with an initial velocity of 22.0 m/s and decelerates at a rate of 0.150 m/s2 as it go

Question

. An express train passes through a station. It enters with an initial velocity of 22.0 m/s and decelerates at a rate of 0.150 m/s2 as it goes through. The station is 210 m long. (a) How long is the nose of the train in the station

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8 hours 2021-07-22T04:26:50+00:00 1 Answers 0 views 0

Explanation:

Give it that,

Initial velocity

u = 22m/s

Deceleration a = – 0.15m/s2

Time taken to travel a station long of 210m

Using equation of motion

Let know the final velocity, when it leaves the station

v² = u²+2as

v² = 22²+2×(-0.15)×210

v² = 484—63

v² = 421

v =√421

v = 20.52m/s

Then,

Using equation of motion to find time taken

v = u + at

20.52 = 22 +(-0.15)t

20.52-22 = -0.15t

-0.15t = -1.48

t = -1.48/-0.15

t = 9.88 sec
The text passage describes a physics problem involving an express train decelerating as it passes through a station. The passage includes the initial velocity, deceleration rate, and the length of the station, and asks for the time the nose of the train is in the station.
single_question

the passage contains a single mathematical question but does not provide an answer to it. the question is about determining the time the nose of the train is in the station.
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
## . An express train passes through a station. It enters with an initial velocity of 22.0 m/s and decelerates at a rate of 0.150 m/s2 as it go

Question

. An express train passes through a station. It enters with an initial velocity of 22.0 m/s and decelerates at a rate of 0.150 m/s2 as it goes through. The station is 210 m long. (a) How long is the nose of the train in the station

in progress 0
8 hours 2021-07-22T04:26:50+00:00 1 Answers 0 views 0

Explanation:

Give it that,

Initial velocity

u = 22m/s

Deceleration a = – 0.15m/s2

Time taken to travel a station long of 210m

Using equation of motion

Let know the final velocity, when it leaves the station

v² = u²+2as

v² = 22²+2×(-0.15)×210

v² = 484—63

v² = 421

v =√421

v = 20.52m/s

Then,

Using equation of motion to find time taken

v = u + at

20.52 = 22 +(-0.15)t

20.52-22 = -0.15t

-0.15t = -1.48

t = -1.48/-0.15

t = 9.88 sec
user
The text passage describes a physics problem involving an express train decelerating as it passes through a station. The passage includes the initial velocity, deceleration rate, and the length of the station, and asks for the time the nose of the train is in the station.

TYPE: SINGLE_QUESTION

The passage contains a single mathematical question but does not provide an answer to it. The question is about determining the time the nose of the train is in the station.