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#### Online Quiz (WorksheetABCD)

Questions Per Quiz = 2 4 6 8 10

### Math Word Problems - GED, PSAT, SAT, ACT, GRE Preparation6.4 Coins Word Problems - 2

 Example: Tim has 11 coins in his pocket that have a total value of \$1. If these coins consists of nickels and dimes only, how many of each kind are there? Solution: Let 'n' be the number of nickels and 'd' be the number of dimes. The word problem can be translated into equation n+d=11 There are 5 cents in a nickel and 'n' nickels equals an amount of 5n. There are 10 cents in a dime and 'd' dimes equals to an amount of 10d. The total value is \$1 or 100 cents. Another equation that can be written as 5n+10d=100 Solve these two equations for n and d to find the number of nickels n and dimes d n+d=11 implies n = 11 - d 5n+10d=100 substituting n = 11 - d in the equation 5n+10d=100 5(11 - d)+10d=100 55 - 5d + 10d = 100 55 + 5d = 100 5d = 100 - 55 5d = 45 d = 9 n = 11 - d = 11 - 9 = 2 Tim has 9 dimes and 2 nickels Verification: substitute value of n and d in the equation n + d = 11 which is 9 + 2 = 11 or substitute value of n and d in the equation 5n+10d=100 which is 5n+10d= 5x2 + 10x9 = 10 + 90 = 100 Example: Kim has 10 coins that total \$2.10. The coins are nickels and quarters only. How many of each kind are there? Solution: Let 'n' be the number of nickels and 'q' be the number of quarters. The word problem can be translated into this equation as n+q=10 Another equation that can be written is 5n+25q=210 Solve these two equations for n and q n+q=10 implies that n = 10 - q 5n+25q=210 5(10 - q)+25q=210 50 - 5q + 25q = 210 50 + 20q = 210 20q = 160 q = 8 n = 10 - q = 10 - 8 = 2 There are 8 quarters and 2 nickles Example: Lilly has 21 coins that total \$4.50. The coins are dimes and quarters only. How many of each kind are there? Solution: Let 'd' be the number of dimes and 'q' be the number of quarters. The word problem can be translated into this equation d+q=21 Another equation that can be written is 10d+25q=450 Solve these two equations for d and q d+q=21 10d+25q=450 d+q=21 implies d = 21 - q substituting in the equation 2 we have 10d+25q=450 10(21 - q)+25q=450 210 - 10q + 25q = 450 210 + 15q = 450 15q = 240 q = 16 d = 21 - q = 21 - 16 = 5 Directions: Solve the following word problems.
 Q 1: Ron has 38 coins that total \$6.70. The coins are nickels and quarters only. How many of each kind are there?q = 24 and n = 10q = 21 and n = 14q = 24 and n = 14 Q 2: Kelly has 16 coins that total \$3.20. The coins are nickels and quarters only. How many of each kind are there? q = 12 and n = 4q = 12 and n = 6q = 10 and n = 6 Q 3: Peter has 31 coins in his pocket that have a total value of \$2.80. If these coins consists of nickels and dimes only, how many of each kind are there? d = 25 and n = 6d = 20 and n = 6d = 21 and n = 8 Q 4: Kim has 15 coins that total \$2.35. The coins are nickels and quarters only. How many of each kind are there?q = 5 and n = 10q = 8 and n = 7q = 10 and n = 5 Q 5: Dan has 22 coins that total \$2.50. The coins are dimes and quarters only. How many of each kind are there?d = 2 and q = 20d = 18 and q = 4d = 20 and q = 2 Q 6: Eric has 29 coins that total \$6.50. The coins are dimes and quarters only. How many of each kind are there?q = 24 and d = 5q = 22 and d = 7q = 24 and d = 8 Q 7: Dan has 8 coins that total \$1.70. The coins are dimes and quarters only. How many of each kind are there?q = 6 and d = 2q = 2 and d = 6q = 3 and d = 3 Q 8: Mary has 20 coins in his pocket that have a total value of \$1.75. If these coins consists of nickels and dimes only, how many of each kind are there? d = 12 and n = 8d = 16 and n = 6d = 15 and n = 5 Question 9: This question is available to subscribers only! Question 10: This question is available to subscribers only!
The text passage contains multiple math word problems, each asking to determine the number of different types of coins (nickels, dimes, quarters) that add up to a specific total value. Each problem is structured similarly, providing the total number of coins and the total value, and requiring the reader to solve a system of equations to find the number of each type of coin.
multiple_questions
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
Email us to get an instant 20% discount on highly effective K-12 Math & English kwizNET Programs!

#### Online Quiz (WorksheetABCD)

Questions Per Quiz = 2 4 6 8 10

### Math Word Problems - GED, PSAT, SAT, ACT, GRE Preparation6.4 Coins Word Problems - 2

 Example: Tim has 11 coins in his pocket that have a total value of \$1. If these coins consists of nickels and dimes only, how many of each kind are there? Solution: Let 'n' be the number of nickels and 'd' be the number of dimes. The word problem can be translated into equation n+d=11 There are 5 cents in a nickel and 'n' nickels equals an amount of 5n. There are 10 cents in a dime and 'd' dimes equals to an amount of 10d. The total value is \$1 or 100 cents. Another equation that can be written as 5n+10d=100 Solve these two equations for n and d to find the number of nickels n and dimes d n+d=11 implies n = 11 - d 5n+10d=100 substituting n = 11 - d in the equation 5n+10d=100 5(11 - d)+10d=100 55 - 5d + 10d = 100 55 + 5d = 100 5d = 100 - 55 5d = 45 d = 9 n = 11 - d = 11 - 9 = 2 Tim has 9 dimes and 2 nickels Verification: substitute value of n and d in the equation n + d = 11 which is 9 + 2 = 11 or substitute value of n and d in the equation 5n+10d=100 which is 5n+10d= 5x2 + 10x9 = 10 + 90 = 100 Example: Kim has 10 coins that total \$2.10. The coins are nickels and quarters only. How many of each kind are there? Solution: Let 'n' be the number of nickels and 'q' be the number of quarters. The word problem can be translated into this equation as n+q=10 Another equation that can be written is 5n+25q=210 Solve these two equations for n and q n+q=10 implies that n = 10 - q 5n+25q=210 5(10 - q)+25q=210 50 - 5q + 25q = 210 50 + 20q = 210 20q = 160 q = 8 n = 10 - q = 10 - 8 = 2 There are 8 quarters and 2 nickles Example: Lilly has 21 coins that total \$4.50. The coins are dimes and quarters only. How many of each kind are there? Solution: Let 'd' be the number of dimes and 'q' be the number of quarters. The word problem can be translated into this equation d+q=21 Another equation that can be written is 10d+25q=450 Solve these two equations for d and q d+q=21 10d+25q=450 d+q=21 implies d = 21 - q substituting in the equation 2 we have 10d+25q=450 10(21 - q)+25q=450 210 - 10q + 25q = 450 210 + 15q = 450 15q = 240 q = 16 d = 21 - q = 21 - 16 = 5 Directions: Solve the following word problems.
 Q 1: Ron has 38 coins that total \$6.70. The coins are nickels and quarters only. How many of each kind are there?q = 24 and n = 10q = 21 and n = 14q = 24 and n = 14 Q 2: Kelly has 16 coins that total \$3.20. The coins are nickels and quarters only. How many of each kind are there? q = 12 and n = 4q = 12 and n = 6q = 10 and n = 6 Q 3: Peter has 31 coins in his pocket that have a total value of \$2.80. If these coins consists of nickels and dimes only, how many of each kind are there? d = 25 and n = 6d = 20 and n = 6d = 21 and n = 8 Q 4: Kim has 15 coins that total \$2.35. The coins are nickels and quarters only. How many of each kind are there?q = 5 and n = 10q = 8 and n = 7q = 10 and n = 5 Q 5: Dan has 22 coins that total \$2.50. The coins are dimes and quarters only. How many of each kind are there?d = 2 and q = 20d = 18 and q = 4d = 20 and q = 2 Q 6: Eric has 29 coins that total \$6.50. The coins are dimes and quarters only. How many of each kind are there?q = 24 and d = 5q = 22 and d = 7q = 24 and d = 8 Q 7: Dan has 8 coins that total \$1.70. The coins are dimes and quarters only. How many of each kind are there?q = 6 and d = 2q = 2 and d = 6q = 3 and d = 3 Q 8: Mary has 20 coins in his pocket that have a total value of \$1.75. If these coins consists of nickels and dimes only, how many of each kind are there? d = 12 and n = 8d = 16 and n = 6d = 15 and n = 5 Question 9: This question is available to subscribers only! Question 10: This question is available to subscribers only!
user
The text passage contains multiple math word problems, each asking to determine the number of different types of coins (nickels, dimes, quarters) that add up to a specific total value. Each problem is structured similarly, providing the total number of coins and the total value, and requiring the reader to solve a system of equations to find the number of each type of coin.

TYPE: MULTIPLE_QUESTIONS