# Determine the Equation Of Sinusodial Function

• Oct 19th 2009, 03:39 PM
mmhaaz
Determine the Equation Of Sinusodial Function
Could someone please explain how I would find the ht of sine and cosine on this graph? I don't understand what the difference is. Also how would I find the period? Is it the same for cosine and sine? Thank-you to anyone that could help!! Not in radian form please...
• Oct 20th 2009, 06:15 AM
Finding a sine and cosine function for a given graph
Hello mmhaaz
Quote:

Originally Posted by mmhaaz
Could someone please explain how I would find the ht of sine and cosine on this graph? I don't understand what the difference is. Also how would I find the period? Is it the same for cosine and sine? Thank-you to anyone that could help!! Not in radian form please...

First: the difference between the graphs of sine and cosine: there is none, except a 'phase shift' of $\displaystyle 90^o$. In other words, if you shift the cosine graph $\displaystyle 90^o$ to the right, you get the sine graph. See the attached diagram.

Note in particular the 'starting' values; i.e. the values when $\displaystyle x = 0$:

• $\displaystyle \cos 0^o=1$
• $\displaystyle \sin0^o=0$

Then, the particular questions relating to the graph you've attached.

The scale on the vertical axis isn't very clear, but it looks as if one square = one unit.

So, on that assumption, the graph has a maximum value of $\displaystyle 1$ and a minimum value of $\displaystyle -5$. The sinusoidal axis is the horizontal line that divides the graph exactly in half. So this is the line $\displaystyle y = -2$ (which I think is what you got).

Then, the amplitude is the vertical distance from the sinusoidal axis to one of the peaks or troughs. So that's $\displaystyle 3$ (again, I think you got that).

From these two facts, we can deduce that the equation of the graph will be of the form:
$\displaystyle y=-2+3\sin$(something) or $\displaystyle y = -2+3\cos$(something)
The question then refers to the 'starting point', based on a sine and then a cosine graph. I assume that means the point which corresponds to the point where $\displaystyle x = 0$ on the graphs of the basic graphs (the ones in my diagram).

So, for sine, this is the point that corresponds to $\displaystyle (0,0)$ on the basic graph - in other words one of the points where the graph crosses the sinusoidal axis and is moving upwards in a direction from left to right. There's more than one such point, but the obvious one is $\displaystyle (30, -2)$. (Can you see that another one will be $\displaystyle (210,-2)$?)

For the cosine function, the starting point will be the point corresponding to $\displaystyle (0,1)$ on the basic graph. So we're looking for a peak (maximum) value: the obvious one here is $\displaystyle (75,1)$.

The period is the horizontal distance between two consecutive corresponding points on the graph. We said above that two possible starting points for the sine graph are $\displaystyle (30,-2)$ and $\displaystyle (210,-2)$. So the period is the distance between these two points. That's $\displaystyle 180^o$.

Divide by $\displaystyle 360^o$ for the next answer: $\displaystyle \frac{180}{360}=\frac12$.

If we divide $\displaystyle x$ by this fraction ($\displaystyle \tfrac12$) we get $\displaystyle 2x$, which gives us the coefficient of $\displaystyle x$ in the functions we're looking for. (A complete period for $\displaystyle y = \sin x$ is when $\displaystyle x$ goes from $\displaystyle 0^o$ to $\displaystyle 360^o$; so if we want a period of $\displaystyle 180^o$, we shall need values of $\displaystyle 2x$, because they will go from $\displaystyle 0^o$ to $\displaystyle 360^o$ when $\displaystyle x$ goes from $\displaystyle 0^o$ to $\displaystyle 180^o$.)

The 'starting points' that we've worked out above tell us the angle that has to be added or subtracted from $\displaystyle x$ to give the correct starting value - the phase-shift.

So, for the sine function we want to start at $\displaystyle x = 30$, so the function is
$\displaystyle y=-2+3\sin(2[x-30])$
And for the cosine function, we want to start at $\displaystyle x = 75$, so the function is
$\displaystyle y=-2+3\cos(2[x-75])$
The text passage contains a student's query about determining the equation of a sinusoidal function from a graph, including questions about the height (amplitude) and period of sine and cosine functions. The response provides a detailed explanation and answers to the student's questions.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
# Determine the Equation Of Sinusodial Function

• Oct 19th 2009, 03:39 PM
mmhaaz
Determine the Equation Of Sinusodial Function
Could someone please explain how I would find the ht of sine and cosine on this graph? I don't understand what the difference is. Also how would I find the period? Is it the same for cosine and sine? Thank-you to anyone that could help!! Not in radian form please...
• Oct 20th 2009, 06:15 AM
Finding a sine and cosine function for a given graph
Hello mmhaaz
Quote:

Originally Posted by mmhaaz
Could someone please explain how I would find the ht of sine and cosine on this graph? I don't understand what the difference is. Also how would I find the period? Is it the same for cosine and sine? Thank-you to anyone that could help!! Not in radian form please...

First: the difference between the graphs of sine and cosine: there is none, except a 'phase shift' of $\displaystyle 90^o$. In other words, if you shift the cosine graph $\displaystyle 90^o$ to the right, you get the sine graph. See the attached diagram.

Note in particular the 'starting' values; i.e. the values when $\displaystyle x = 0$:

• $\displaystyle \cos 0^o=1$
• $\displaystyle \sin0^o=0$

Then, the particular questions relating to the graph you've attached.

The scale on the vertical axis isn't very clear, but it looks as if one square = one unit.

So, on that assumption, the graph has a maximum value of $\displaystyle 1$ and a minimum value of $\displaystyle -5$. The sinusoidal axis is the horizontal line that divides the graph exactly in half. So this is the line $\displaystyle y = -2$ (which I think is what you got).

Then, the amplitude is the vertical distance from the sinusoidal axis to one of the peaks or troughs. So that's $\displaystyle 3$ (again, I think you got that).

From these two facts, we can deduce that the equation of the graph will be of the form:
$\displaystyle y=-2+3\sin$(something) or $\displaystyle y = -2+3\cos$(something)
The question then refers to the 'starting point', based on a sine and then a cosine graph. I assume that means the point which corresponds to the point where $\displaystyle x = 0$ on the graphs of the basic graphs (the ones in my diagram).

So, for sine, this is the point that corresponds to $\displaystyle (0,0)$ on the basic graph - in other words one of the points where the graph crosses the sinusoidal axis and is moving upwards in a direction from left to right. There's more than one such point, but the obvious one is $\displaystyle (30, -2)$. (Can you see that another one will be $\displaystyle (210,-2)$?)

For the cosine function, the starting point will be the point corresponding to $\displaystyle (0,1)$ on the basic graph. So we're looking for a peak (maximum) value: the obvious one here is $\displaystyle (75,1)$.

The period is the horizontal distance between two consecutive corresponding points on the graph. We said above that two possible starting points for the sine graph are $\displaystyle (30,-2)$ and $\displaystyle (210,-2)$. So the period is the distance between these two points. That's $\displaystyle 180^o$.

Divide by $\displaystyle 360^o$ for the next answer: $\displaystyle \frac{180}{360}=\frac12$.

If we divide $\displaystyle x$ by this fraction ($\displaystyle \tfrac12$) we get $\displaystyle 2x$, which gives us the coefficient of $\displaystyle x$ in the functions we're looking for. (A complete period for $\displaystyle y = \sin x$ is when $\displaystyle x$ goes from $\displaystyle 0^o$ to $\displaystyle 360^o$; so if we want a period of $\displaystyle 180^o$, we shall need values of $\displaystyle 2x$, because they will go from $\displaystyle 0^o$ to $\displaystyle 360^o$ when $\displaystyle x$ goes from $\displaystyle 0^o$ to $\displaystyle 180^o$.)

The 'starting points' that we've worked out above tell us the angle that has to be added or subtracted from $\displaystyle x$ to give the correct starting value - the phase-shift.

So, for the sine function we want to start at $\displaystyle x = 30$, so the function is
$\displaystyle y=-2+3\sin(2[x-30])$
And for the cosine function, we want to start at $\displaystyle x = 75$, so the function is
$\displaystyle y=-2+3\cos(2[x-75])$
user
The text passage contains a student's query about determining the equation of a sinusoidal function from a graph, including questions about the height (amplitude) and period of sine and cosine functions. The response provides a detailed explanation and answers to the student's questions.

TYPE: SINGLE_QUESTION_WITH_ANSWER