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# On his birthday, Praet brings two pieces of cakes weighing

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Senior Manager
Joined: 22 Aug 2003
Posts: 257
Location: Bangalore
On his birthday, Praet brings two pieces of cakes weighing [#permalink]

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22 Sep 2003, 04:13
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

On his birthday, Praet brings two pieces of cakes weighing 3/5 lbs & 7/20lbs. He wants to cut them into pieces of equal weights such that weight of each piece is maximum possible. Find the number of maximum guests praet could invite to his house. (assume: Praet will give atleast one cake to every guest).
SVP
Joined: 03 Feb 2003
Posts: 1604

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22 Sep 2003, 04:47
At the first glance: 3/5 and 7/20 are not terminating fractions
3/5=12/20
12/20 and 7/20 can be equally divided among 19 people.

19?
Senior Manager
Joined: 22 Aug 2003
Posts: 257
Location: Bangalore

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22 Sep 2003, 05:03
thats correct.
Now if two pieces are 6/5lbs & 9/10 lbs. What would be your answer?
Senior Manager
Joined: 22 May 2003
Posts: 329
Location: Uruguay

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22 Sep 2003, 17:38
Maybe 7? Each piece weighting 3/10 lbs
Senior Manager
Joined: 22 Aug 2003
Posts: 257
Location: Bangalore

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22 Sep 2003, 23:45
there u go.. yes it would be 7 each weighing 3/10 lbs.
we have to divide weights such that each has maximum possible weight.
21 will give each cake of weight 1/10lbs.
Senior Manager
Joined: 02 Feb 2004
Posts: 344

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21 May 2004, 12:52
can anybody show the workings better?
SVP
Joined: 30 Oct 2003
Posts: 1790
Location: NewJersey USA

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21 May 2004, 14:35
Assume that Praetorian divides 3/5 pound cake into n pieces and 7/20 pound cake into m pieces. m and n pieces have equal weight
Then
weight of each cake piece = (3/5)/n = 3/5n Since each cake piece has same weight
(3/5)/n = (7/20)/m
3/n = 7/4m therefore m = n * 7/12

Now we want minimum pieces because minimum pieces yeild maximum size and we know that m and n are integers
if n = 12 then m = 7
there fore praetorian will invite 7+12 = 19 guests.
I hope I am included
21 May 2004, 14:35
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The text passage describes a scenario where Praet brings two pieces of cake to his birthday party and wants to cut them into pieces of equal weight, with the maximum possible weight for each piece, to determine the number of guests he can invite. The passage then provides a solution for a specific case and asks for an analysis of another case.
single_question_with_answer

the passage contains a mathematical question (how to divide the cakes into pieces of maximum possible equal weight) and provides an answer for one of the cases (19 guests for cakes weighing 3/5 lbs and 7/20 lbs). it also asks for an analysis of another case (6/5 lbs and 9/10 lbs).
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
It is currently 25 Jun 2017, 07:24

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# Events & Promotions

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# On his birthday, Praet brings two pieces of cakes weighing

Author Message
Senior Manager
Joined: 22 Aug 2003
Posts: 257
Location: Bangalore
On his birthday, Praet brings two pieces of cakes weighing [#permalink]

### Show Tags

22 Sep 2003, 04:13
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

On his birthday, Praet brings two pieces of cakes weighing 3/5 lbs & 7/20lbs. He wants to cut them into pieces of equal weights such that weight of each piece is maximum possible. Find the number of maximum guests praet could invite to his house. (assume: Praet will give atleast one cake to every guest).
SVP
Joined: 03 Feb 2003
Posts: 1604

### Show Tags

22 Sep 2003, 04:47
At the first glance: 3/5 and 7/20 are not terminating fractions
3/5=12/20
12/20 and 7/20 can be equally divided among 19 people.

19?
Senior Manager
Joined: 22 Aug 2003
Posts: 257
Location: Bangalore

### Show Tags

22 Sep 2003, 05:03
thats correct.
Now if two pieces are 6/5lbs & 9/10 lbs. What would be your answer?
Senior Manager
Joined: 22 May 2003
Posts: 329
Location: Uruguay

### Show Tags

22 Sep 2003, 17:38
Maybe 7? Each piece weighting 3/10 lbs
Senior Manager
Joined: 22 Aug 2003
Posts: 257
Location: Bangalore

### Show Tags

22 Sep 2003, 23:45
there u go.. yes it would be 7 each weighing 3/10 lbs.
we have to divide weights such that each has maximum possible weight.
21 will give each cake of weight 1/10lbs.
Senior Manager
Joined: 02 Feb 2004
Posts: 344

### Show Tags

21 May 2004, 12:52
can anybody show the workings better?
SVP
Joined: 30 Oct 2003
Posts: 1790
Location: NewJersey USA

### Show Tags

21 May 2004, 14:35
Assume that Praetorian divides 3/5 pound cake into n pieces and 7/20 pound cake into m pieces. m and n pieces have equal weight
Then
weight of each cake piece = (3/5)/n = 3/5n Since each cake piece has same weight
(3/5)/n = (7/20)/m
3/n = 7/4m therefore m = n * 7/12

Now we want minimum pieces because minimum pieces yeild maximum size and we know that m and n are integers
if n = 12 then m = 7
there fore praetorian will invite 7+12 = 19 guests.
I hope I am included
21 May 2004, 14:35
Display posts from previous: Sort by
user
The text passage describes a scenario where Praet brings two pieces of cake to his birthday party and wants to cut them into pieces of equal weight, with the maximum possible weight for each piece, to determine the number of guests he can invite. The passage then provides a solution for a specific case and asks for an analysis of another case.

TYPE: SINGLE_QUESTION_WITH_ANSWER

The passage contains a mathematical question (how to divide the cakes into pieces of maximum possible equal weight) and provides an answer for one of the cases (19 guests for cakes weighing 3/5 lbs and 7/20 lbs). It also asks for an analysis of another case (6/5 lbs and 9/10 lbs).