# Word Problem regarding The Doppler Effect?

Jun 29, 2016

$320 H z$

#### Explanation:

Step 1
The problem describes a sound that is moving toward a stationary observer with an air temperature of ${15}^{\circ} C$. Since the speed of sound increases as the temperature increases, we must determine the speed of the waves at ${15}^{\circ} C$. This can be found with the formula:

$\textcolor{b l u e}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{{v}_{s} = 331 \frac{m}{s} + \left(\frac{0.6 \frac{m}{s}}{{\textcolor{w h i t e}{i}}^{\circ} C}\right) \times \text{temperature}} \textcolor{w h i t e}{\frac{a}{a}} |}}}$

Using the formula, the speed of the sound waves is:

$\textcolor{\mathrm{da} r k \mathmr{and} a n \ge}{{v}_{s}} = 331 \frac{m}{s} + \left(\frac{0.6 \frac{m}{s}}{{\textcolor{w h i t e}{i}}^{\circ} C}\right) \times {15}^{\circ} C$

$= \textcolor{\mathrm{da} r k \mathmr{and} a n \ge}{340 \frac{m}{s}}$

Step 2
Since the Doppler effect results in a change in the perceived frequency between the source and the observer, we can use the Dopper Effect formula for sound. The sign in the denominator will be a subtraction sign since the source is moving toward the observer:

$\textcolor{b l u e}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{{f}_{d} = \left({v}_{s} / \left({v}_{s} - {v}_{o}\right)\right) f} \textcolor{w h i t e}{\frac{a}{a}} |}}}$

$\underline{\text{where:}}$
${f}_{d} =$frequency detected by observer
${v}_{s} =$speed of sound wave
${v}_{o} =$speed of object
$f =$frequency at source

${f}_{d} = \left(\frac{\textcolor{\mathrm{da} r k \mathmr{and} a n \ge}{340 \frac{m}{s}}}{\textcolor{\mathrm{da} r k \mathmr{and} a n \ge}{340 \frac{m}{s}} - 25 \frac{m}{s}}\right) 300.0 H z$

$\approx \textcolor{g r e e n}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{320 H z} \textcolor{w h i t e}{\frac{a}{a}} |}}}$

Since the detected frequency is higher than $300.0 H z$, the frequency at the source, we can conclude that our answer is correct.
The text passage contains a detailed explanation and solution to a physics problem involving the Doppler Effect, including the calculation of the speed of sound at a given temperature and the calculation of the perceived frequency by a stationary observer.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
# Word Problem regarding The Doppler Effect?

Jun 29, 2016

$320 H z$

#### Explanation:

Step 1
The problem describes a sound that is moving toward a stationary observer with an air temperature of ${15}^{\circ} C$. Since the speed of sound increases as the temperature increases, we must determine the speed of the waves at ${15}^{\circ} C$. This can be found with the formula:

$\textcolor{b l u e}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{{v}_{s} = 331 \frac{m}{s} + \left(\frac{0.6 \frac{m}{s}}{{\textcolor{w h i t e}{i}}^{\circ} C}\right) \times \text{temperature}} \textcolor{w h i t e}{\frac{a}{a}} |}}}$

Using the formula, the speed of the sound waves is:

$\textcolor{\mathrm{da} r k \mathmr{and} a n \ge}{{v}_{s}} = 331 \frac{m}{s} + \left(\frac{0.6 \frac{m}{s}}{{\textcolor{w h i t e}{i}}^{\circ} C}\right) \times {15}^{\circ} C$

$= \textcolor{\mathrm{da} r k \mathmr{and} a n \ge}{340 \frac{m}{s}}$

Step 2
Since the Doppler effect results in a change in the perceived frequency between the source and the observer, we can use the Dopper Effect formula for sound. The sign in the denominator will be a subtraction sign since the source is moving toward the observer:

$\textcolor{b l u e}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{{f}_{d} = \left({v}_{s} / \left({v}_{s} - {v}_{o}\right)\right) f} \textcolor{w h i t e}{\frac{a}{a}} |}}}$

$\underline{\text{where:}}$
${f}_{d} =$frequency detected by observer
${v}_{s} =$speed of sound wave
${v}_{o} =$speed of object
$f =$frequency at source

${f}_{d} = \left(\frac{\textcolor{\mathrm{da} r k \mathmr{and} a n \ge}{340 \frac{m}{s}}}{\textcolor{\mathrm{da} r k \mathmr{and} a n \ge}{340 \frac{m}{s}} - 25 \frac{m}{s}}\right) 300.0 H z$

$\approx \textcolor{g r e e n}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} \textcolor{b l a c k}{320 H z} \textcolor{w h i t e}{\frac{a}{a}} |}}}$

Since the detected frequency is higher than $300.0 H z$, the frequency at the source, we can conclude that our answer is correct.
user
The text passage contains a detailed explanation and solution to a physics problem involving the Doppler Effect, including the calculation of the speed of sound at a given temperature and the calculation of the perceived frequency by a stationary observer.

TYPE: SINGLE_QUESTION_WITH_ANSWER