# Solving polynomial equations

#### Everything You Need in One Place

Homework problems? Exam preparation? Trying to grasp a concept or just brushing up the basics? Our extensive help & practice library have got you covered.

#### Learn and Practice With Ease

Our proven video lessons ease you through problems quickly, and you get tonnes of friendly practice on questions that trip students up on tests and finals.

#### Instant and Unlimited Help

Our personalized learning platform enables you to instantly find the exact walkthrough to your specific type of question. Activate unlimited help now!

0/1
##### Intros
###### Lessons
1. What is zero product property?
0/3
##### Examples
###### Lessons
1. Solving the equations:
1. ${4x^2-9=0}$
2. ${3x^2-13x-10=0}$
3. ${(2x-3)^2=1}$
###### Topic Notes
Depending on the degree what terms are included in the polynomial equations, you may simply move terms around to get the answers. Sometimes, you may need to perform factoring in order to solve the equations. Yet, the rule of thumb is always isolating the unknown to one side of the equation.

## What is the zero product property

The zero product property definition tells us that if:

a x b = 0

then either a or b has to equal 0.

Logically, this makes sense. Any number multiplied by 0 gives us 0. No other combinations can give us this. Therefore, one of the two unknown numbers must be 0.

## How to solve polynomials

When we're asked to solve a polynomial, we're actually being asked to find the roots where the function equals 0. You can see how the above zero product property can come in handy! So how do we start solving polynomials? We'll have to do some isolating.

## How to isolate a variable

In order to figure out when a polynomial equals 0, we'll have to isolate the variable that is in the equation so that we can find its value. This is like how we solve two-step linear equations. Let's try it out with a simple polynomial equation. Do you know how to solve for x?

$2x - 1 = 0$

Since we don't know what x is, we'll have to isolate it onto one side to see what it equals. In this case, let's start with moving the 1, and then the 2 that's next to the x.

$2x - 1 = 0$

$2x = 1$

$x = \frac{1}{2}$

When you've got a positive on one side and you've got to move it to the other side of the equal sign, simply reverse the sign to negative. If it's negative and you've got to move it, it'll become positive. Similarly, if you have to multiply on one side and now you're trying to move it to the other side, you'll have to divide it. If you've got a division, it'll become multiplication on the other side of the equal sign.

If you've got a variable on both sides of the equal sign, you'll still have to group it to one side in order to find its value.

## Example problems

Question 1:

1a) Solve the equation:

$4x^{2} - 9 = 0$

Solution:

Since we're dealing with a degree of a polynomial (in this case it's the power of 2), when you move a square to the other side of the equal sign, you'll have a square root. A note is that all positive real numbers has two square roots—one that's positive and one that's negative. Therefore, we'll put a ±sign in front of the square root to indicate we'd like both the negative and positive in our final answer.

$4x^{2} = 9$

$x^{2} = \frac{9}{4}$

$x = \pm \sqrt{\frac{9}{4}}$

$x = \pm \frac{3}{2}$

1b) Solve the equation:

$(2x - 3)^{2} = 1$

Solution:

$2x - 3 = \pm \sqrt{1}$

$2x - 3 = \pm 1$

$2x = \pm 1 + 3$

$x = \frac{3 \pm 1}{2}$

$x = 2, 1$

Question 2

Solving the equation:

$3x^{2} - 13x - 10 = 0$

We have to factor the polynomial before solving for x so that we can get it into a form that looks like we're about to do distributive property on it.

After factoring, we have:

$(3x + 2)(x - 5) = 0$

To solve for x, we can separate $(3x + 2)(x - 5) = 0$ into two equations using the zero product property:

$(3x + 2) = 0$,and $(x - 5) = 0$

Isolate and solve for x

$3x + 2 = 0$

$3x = -2$

$x = \frac{-2}{3}$

$x - 5 = 0$

$x = 5$

So, in this question, $x = \frac{-2}{3}$ and $x = 5$
The text passage contains multiple polynomial equations and their solutions. It explains the zero product property and demonstrates how to solve polynomial equations by isolating the variable and factoring.
multiple_questions_with_answers
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
# Solving polynomial equations

#### Everything You Need in One Place

Homework problems? Exam preparation? Trying to grasp a concept or just brushing up the basics? Our extensive help & practice library have got you covered.

#### Learn and Practice With Ease

Our proven video lessons ease you through problems quickly, and you get tonnes of friendly practice on questions that trip students up on tests and finals.

#### Instant and Unlimited Help

Our personalized learning platform enables you to instantly find the exact walkthrough to your specific type of question. Activate unlimited help now!

0/1
##### Intros
###### Lessons
1. What is zero product property?
0/3
##### Examples
###### Lessons
1. Solving the equations:
1. ${4x^2-9=0}$
2. ${3x^2-13x-10=0}$
3. ${(2x-3)^2=1}$
###### Topic Notes
Depending on the degree what terms are included in the polynomial equations, you may simply move terms around to get the answers. Sometimes, you may need to perform factoring in order to solve the equations. Yet, the rule of thumb is always isolating the unknown to one side of the equation.

## What is the zero product property

The zero product property definition tells us that if:

a x b = 0

then either a or b has to equal 0.

Logically, this makes sense. Any number multiplied by 0 gives us 0. No other combinations can give us this. Therefore, one of the two unknown numbers must be 0.

## How to solve polynomials

When we're asked to solve a polynomial, we're actually being asked to find the roots where the function equals 0. You can see how the above zero product property can come in handy! So how do we start solving polynomials? We'll have to do some isolating.

## How to isolate a variable

In order to figure out when a polynomial equals 0, we'll have to isolate the variable that is in the equation so that we can find its value. This is like how we solve two-step linear equations. Let's try it out with a simple polynomial equation. Do you know how to solve for x?

$2x - 1 = 0$

Since we don't know what x is, we'll have to isolate it onto one side to see what it equals. In this case, let's start with moving the 1, and then the 2 that's next to the x.

$2x - 1 = 0$

$2x = 1$

$x = \frac{1}{2}$

When you've got a positive on one side and you've got to move it to the other side of the equal sign, simply reverse the sign to negative. If it's negative and you've got to move it, it'll become positive. Similarly, if you have to multiply on one side and now you're trying to move it to the other side, you'll have to divide it. If you've got a division, it'll become multiplication on the other side of the equal sign.

If you've got a variable on both sides of the equal sign, you'll still have to group it to one side in order to find its value.

## Example problems

Question 1:

1a) Solve the equation:

$4x^{2} - 9 = 0$

Solution:

Since we're dealing with a degree of a polynomial (in this case it's the power of 2), when you move a square to the other side of the equal sign, you'll have a square root. A note is that all positive real numbers has two square roots—one that's positive and one that's negative. Therefore, we'll put a ±sign in front of the square root to indicate we'd like both the negative and positive in our final answer.

$4x^{2} = 9$

$x^{2} = \frac{9}{4}$

$x = \pm \sqrt{\frac{9}{4}}$

$x = \pm \frac{3}{2}$

1b) Solve the equation:

$(2x - 3)^{2} = 1$

Solution:

$2x - 3 = \pm \sqrt{1}$

$2x - 3 = \pm 1$

$2x = \pm 1 + 3$

$x = \frac{3 \pm 1}{2}$

$x = 2, 1$

Question 2

Solving the equation:

$3x^{2} - 13x - 10 = 0$

We have to factor the polynomial before solving for x so that we can get it into a form that looks like we're about to do distributive property on it.

After factoring, we have:

$(3x + 2)(x - 5) = 0$

To solve for x, we can separate $(3x + 2)(x - 5) = 0$ into two equations using the zero product property:

$(3x + 2) = 0$,and $(x - 5) = 0$

Isolate and solve for x

$3x + 2 = 0$

$3x = -2$

$x = \frac{-2}{3}$

$x - 5 = 0$

$x = 5$

So, in this question, $x = \frac{-2}{3}$ and $x = 5$
user
The text passage contains multiple polynomial equations and their solutions. It explains the zero product property and demonstrates how to solve polynomial equations by isolating the variable and factoring.

TYPE: MULTIPLE_QUESTIONS_WITH_ANSWERS