Geometry: Common Core (15th Edition)

$x = 34.2$ ft.
Since we have the measure of one angle and the measure of the hypotenuse, we can use the sine ratio to find $x$, which is the side opposite to the angle. The sine ratio is given as follows: sin $A = \frac{opposite}{hypotenuse}$ Let's plug in what we know: sin $20^{\circ} = \frac{x}{100}$ Multiply each side by $100$: sin $20^{\circ}(100) = x$ Multiply to solve: $x = 34.2$ ft.
The passage describes a geometry problem involving the use of the sine ratio to find the length of a side in a right triangle, given an angle and the hypotenuse. The problem and its solution are both provided.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
Geometry: Common Core (15th Edition)

$x = 34.2$ ft.
Since we have the measure of one angle and the measure of the hypotenuse, we can use the sine ratio to find $x$, which is the side opposite to the angle. The sine ratio is given as follows: sin $A = \frac{opposite}{hypotenuse}$ Let's plug in what we know: sin $20^{\circ} = \frac{x}{100}$ Multiply each side by $100$: sin $20^{\circ}(100) = x$ Multiply to solve: $x = 34.2$ ft.
user
The passage describes a geometry problem involving the use of the sine ratio to find the length of a side in a right triangle, given an angle and the hypotenuse. The problem and its solution are both provided.

TYPE: SINGLE_QUESTION_WITH_ANSWER