# When divided by 30, 36, & 80 gives a remainder 11 in each case is :

A number between 1000 and 2000 which when divided by 30, 36, & 80 gives a remainder 11 in each case is

1. 1641
2. 1712
3. 1523
4. 1451
Anurag Mishra Professor Asked on 29th December 2015 in

Explanation:-
The factors of 30 = 2 x 3 x 5
The factors of 36 = 2 x 2 x 3 x 3
The factors of 80 = 2 x 2 x 2 x 2 x 5

Then, the L C M of 30, 36, 80 = 2 x 2 x 2 x 2 x 3 x 3 x 5
= 720

The second multiple of 720 = 720 x 2 = 1440 which is between 1, 000 and 2, 000.
Gives remainder = 11
Then, the number = 1440 + 11
= 1451

Then, a number between 1, 000  and 2, 000 which when divided by 30, 36  & 80 gives a remainder 11 in each case is 1451.

Hence, the correct answer is option (4) 1451.

Monis Rasool Professor Answered on 29th December 2015.
The text contains a mathematical question and its answer, along with an explanation of how the answer was derived.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
# When divided by 30, 36, & 80 gives a remainder 11 in each case is :

A number between 1000 and 2000 which when divided by 30, 36, & 80 gives a remainder 11 in each case is

1. 1641
2. 1712
3. 1523
4. 1451
Anurag Mishra Professor Asked on 29th December 2015 in

Explanation:-
The factors of 30 = 2 x 3 x 5
The factors of 36 = 2 x 2 x 3 x 3
The factors of 80 = 2 x 2 x 2 x 2 x 5

Then, the L C M of 30, 36, 80 = 2 x 2 x 2 x 2 x 3 x 3 x 5
= 720

The second multiple of 720 = 720 x 2 = 1440 which is between 1, 000 and 2, 000.
Gives remainder = 11
Then, the number = 1440 + 11
= 1451

Then, a number between 1, 000  and 2, 000 which when divided by 30, 36  & 80 gives a remainder 11 in each case is 1451.

Hence, the correct answer is option (4) 1451.

Monis Rasool Professor Answered on 29th December 2015.
user
The text contains a mathematical question and its answer, along with an explanation of how the answer was derived.

TYPE: SINGLE_QUESTION_WITH_ANSWER