# A 1 6 6 ms 2 121416 412 pm hw09s31 2 page 15 of 22

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a (1) = -6 -6 m/s 2
12/14/16, 4(12 PM hw09S3.1-2 Page 15 of 22 19. 2/2 points | Previous Answers SCalcET7 3.2.004. Differentiate. g' ( x ) = \$\$5 ex (2 x +12 x ) Solution or Explanation Click to View Solution 20. 2/2 points | Previous Answers SCalcET7 3.2.014. Differentiate. y' = \$\$ 2 x 3 27 x 2 15( x 3+ x 6)2 Solution or Explanation Click to View Solution g ( x ) = 5 e x x y = x + 9 x 3 + x 6
12/14/16, 4(12 PM hw09S3.1-2 Page 16 of 22 21. 2/2 points | Previous Answers SCalcET7 3.2.018. Differentiate. (Assume k is a constant.) y' = \$\$ 1+ kec ( c + kec )2 Solution or Explanation Click to View Solution 22. 2/2 points | Previous Answers SCalcET7 3.2.021. Differentiate. Solution or Explanation Click to View Solution y = 1 c + ke c f ( t ) = 4 t 4 + t f ' ( t ) = \$\$16+2 t (4+ t )2
12/14/16, 4(12 PM hw09S3.1-2 Page 17 of 22 23. 2/2 points | Previous Answers SCalcET7 3.2.025. Differentiate. Solution or Explanation Click to View Solution 24. 2/2 points | Previous Answers SCalcET7 3.2.028. Find f ' ( x ) and f '' ( x f ( x ) = x 7/2 e f ' ( x ) = \$\$ exx (72)+ ex 72 x (52) f '' ( x ) = \$\$ exx (72)+ ex 7 x (52)+ ex 354 x (32) ). Solution or Explanation Click to View Solution f ( y ) = y y + d y f ' ( y ) = \$\$2 dy 1( y + dy )2 x
12/14/16, 4(12 PM hw09S3.1-2 25. 2/2 points | Previous Answers SCalcET7 3.2.031. Find an equation of the tangent line to the given curve at the specified point. y = , (1, 0) 2 1 x 2 + x + 1 y = \$\$23( x 1) x x . . 2 2 2
Page 18 of 22 (b) Illustrate part (a) by graphing the curve and tangent line on the same screen.
26. 2/2 points | Previous Answers SCalcET7 3.2.035. (a) The curve is called a witch of Maria Agnesi . Find an equation of the tangent line to this curve at the point y = 2
12/14/16, 4(12 PM hw09S3.1-2 Page 19 of 22 Solution or Explanation (a) So the slope of the tangent line at the point is and its equation is (b) 27. 2/2 points | Previous Answers SCalcET7 3.2.046. If find -9/2 -4.5 Solution or Explanation Click to View Solution y = f ( x ) = f ' ( x ) = = . 1 1 + x 2 (1 + x 2 )(0) 1(2 x ) (1 + x 2 ) 2 2 x (1 + x 2 ) 2 1 , 1 2 f ' ( 1 ) = = 2 2 2 1 2 y = ( x ( 1 )) or y = x + 1. 1 2 1 2 1 2 h (2) = 8 and h' (2) = 5 , d dx h ( x ) x x = 2.
12/14/16, 4(12 PM hw09S3.1-2
The text passage appears to be a series of calculus problems and solutions, likely from a homework assignment or study guide. Each problem is numbered and includes a differentiation or tangent line question, followed by a student's answer and a "Click to View Solution" note.
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TYPE: <one of the following values>
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- MULTIPLE_QUESTIONS_WITH_ANSWERS
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# A 1 6 6 ms 2 121416 412 pm hw09s31 2 page 15 of 22

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• 100% (16) 16 out of 16 people found this document helpful

This preview shows page 14 - 21 out of 22 pages.

a (1) = -6 -6 m/s 2
12/14/16, 4(12 PM hw09S3.1-2 Page 15 of 22 19. 2/2 points | Previous Answers SCalcET7 3.2.004. Differentiate. g' ( x ) = \$\$5 ex (2 x +12 x ) Solution or Explanation Click to View Solution 20. 2/2 points | Previous Answers SCalcET7 3.2.014. Differentiate. y' = \$\$ 2 x 3 27 x 2 15( x 3+ x 6)2 Solution or Explanation Click to View Solution g ( x ) = 5 e x x y = x + 9 x 3 + x 6
12/14/16, 4(12 PM hw09S3.1-2 Page 16 of 22 21. 2/2 points | Previous Answers SCalcET7 3.2.018. Differentiate. (Assume k is a constant.) y' = \$\$ 1+ kec ( c + kec )2 Solution or Explanation Click to View Solution 22. 2/2 points | Previous Answers SCalcET7 3.2.021. Differentiate. Solution or Explanation Click to View Solution y = 1 c + ke c f ( t ) = 4 t 4 + t f ' ( t ) = \$\$16+2 t (4+ t )2
12/14/16, 4(12 PM hw09S3.1-2 Page 17 of 22 23. 2/2 points | Previous Answers SCalcET7 3.2.025. Differentiate. Solution or Explanation Click to View Solution 24. 2/2 points | Previous Answers SCalcET7 3.2.028. Find f ' ( x ) and f '' ( x f ( x ) = x 7/2 e f ' ( x ) = \$\$ exx (72)+ ex 72 x (52) f '' ( x ) = \$\$ exx (72)+ ex 7 x (52)+ ex 354 x (32) ). Solution or Explanation Click to View Solution f ( y ) = y y + d y f ' ( y ) = \$\$2 dy 1( y + dy )2 x
12/14/16, 4(12 PM hw09S3.1-2 25. 2/2 points | Previous Answers SCalcET7 3.2.031. Find an equation of the tangent line to the given curve at the specified point. y = , (1, 0) 2 1 x 2 + x + 1 y = \$\$23( x 1) x x . . 2 2 2
Page 18 of 22 (b) Illustrate part (a) by graphing the curve and tangent line on the same screen.
26. 2/2 points | Previous Answers SCalcET7 3.2.035. (a) The curve is called a witch of Maria Agnesi . Find an equation of the tangent line to this curve at the point y = 2
12/14/16, 4(12 PM hw09S3.1-2 Page 19 of 22 Solution or Explanation (a) So the slope of the tangent line at the point is and its equation is (b) 27. 2/2 points | Previous Answers SCalcET7 3.2.046. If find -9/2 -4.5 Solution or Explanation Click to View Solution y = f ( x ) = f ' ( x ) = = . 1 1 + x 2 (1 + x 2 )(0) 1(2 x ) (1 + x 2 ) 2 2 x (1 + x 2 ) 2 1 , 1 2 f ' ( 1 ) = = 2 2 2 1 2 y = ( x ( 1 )) or y = x + 1. 1 2 1 2 1 2 h (2) = 8 and h' (2) = 5 , d dx h ( x ) x x = 2.
12/14/16, 4(12 PM hw09S3.1-2
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The text passage appears to be a series of calculus problems and solutions, likely from a homework assignment or study guide. Each problem is numbered and includes a differentiation or tangent line question, followed by a student's answer and a "Click to View Solution" note.

TYPE: MULTIPLE_QUESTIONS_WITH_ANSWERS