# algebra 11

posted by .

(K+1)x+2y=6; M=k-2

• algebra 11 -

Apparently you mean that M is the slope. Most folks use lower-case letters.

In any case, we have

2y = -(k+1)x + 6
y = -(k+1)/2 x + 3
The slope is -(k+1)/2

-(k+1)/2 = k-2
-(k+1) = 2k - 2
-k-1 = 2k-2
3k = 1
k = 1/3

• algebra 11 -

oops
-(k+1) = 2k - 4
-k-1 = 2k-4
3k=3
k=1

• algebra 11 -

Steve, You made another mistake in that second edit.

Once you reach -k-1=2k-4.

You need to subtract 2k from the right side.
That gets you -3k-1=-4.

You add 1 to get rid of that negative one which gets -3k=-3. Solve for k=1

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The text passage provided is a series of posts from a forum or discussion board, where a user is asking for help with an algebra problem and another user (Steve) is providing a solution. The problem is to find the value of k given the slope of a line and an equation.
no_question

the passage does not contain a direct question from the user asking for a solution, but rather a series of posts where the user is presenting a problem and another user is solving it. therefore, it does not fit the criteria for a question and answer format as described in the options. however, if we consider the problem presented as an implicit question, it would be a single_question_with_answer, but since the user did not explicitly ask a question, the most accurate classification is no_question.
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
# algebra 11

posted by .

(K+1)x+2y=6; M=k-2

• algebra 11 -

Apparently you mean that M is the slope. Most folks use lower-case letters.

In any case, we have

2y = -(k+1)x + 6
y = -(k+1)/2 x + 3
The slope is -(k+1)/2

-(k+1)/2 = k-2
-(k+1) = 2k - 2
-k-1 = 2k-2
3k = 1
k = 1/3

• algebra 11 -

oops
-(k+1) = 2k - 4
-k-1 = 2k-4
3k=3
k=1

• algebra 11 -

Steve, You made another mistake in that second edit.

Once you reach -k-1=2k-4.

You need to subtract 2k from the right side.
That gets you -3k-1=-4.

You add 1 to get rid of that negative one which gets -3k=-3. Solve for k=1

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More Similar Questions
user
The text passage provided is a series of posts from a forum or discussion board, where a user is asking for help with an algebra problem and another user (Steve) is providing a solution. The problem is to find the value of k given the slope of a line and an equation.

TYPE: NO_QUESTION

The passage does not contain a direct question from the user asking for a solution, but rather a series of posts where the user is presenting a problem and another user is solving it. Therefore, it does not fit the criteria for a question and answer format as described in the options. However, if we consider the problem presented as an implicit question, it would be a SINGLE_QUESTION_WITH_ANSWER, but since the user did not explicitly ask a question, the most accurate classification is NO_QUESTION.