# In Young's double slit experiment, the fringe width is found to be 0.4 mm. If the whole apparatus is immersed in water of refractive index $$\dfrac{4}{3}$$, without disturbing the geometrical arrangement, the new fringe width will be

1. 0.30 mm
2. 0.40 mm
3. 0.53 mm
4. 450 microns

Option 1 : 0.30 mm
Free
CT 1: हिन्दी (आदिकाल)
6912
10 Questions 40 Marks 10 Mins

## Detailed Solution

Concept:

Young’s Double Slit Experiment:

If a monochromatic light falls on two narrow slits which are very close to each other act as a coherent source superpose each other and an interference pattern is observed on the screen.

Property:

• The central fringe is always bright as ϕ = 0°
• If one slit is illuminated with red light and the other with green no pattern is observed.
• All the fringes are of equal width β = λ D/d
• Angular fringe width θ = λ /d
• If the whole thing is submerged in water then βw = ¾ βa
• Position of nth bright fringe from central maxima n = nλ d/D
• Position of nth dark fringe from central maxima n = (2n-1)λ d/D

Calculation:

Fringe width in air (βa) = 0.4 mm

We know that when submerged in water

If the whole thing is submerged in water then:

βw = ¾ βa

βw = ¾ β= ¾ (0.4) = 0.3 mm
The passage contains a physics question related to Young's double slit experiment, specifically asking about the change in fringe width when the apparatus is immersed in water. The correct answer is provided as 0.30 mm.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
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- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
# In Young's double slit experiment, the fringe width is found to be 0.4 mm. If the whole apparatus is immersed in water of refractive index $$\dfrac{4}{3}$$, without disturbing the geometrical arrangement, the new fringe width will be

1. 0.30 mm
2. 0.40 mm
3. 0.53 mm
4. 450 microns

Option 1 : 0.30 mm
Free
CT 1: हिन्दी (आदिकाल)
6912
10 Questions 40 Marks 10 Mins

## Detailed Solution

Concept:

Young’s Double Slit Experiment:

If a monochromatic light falls on two narrow slits which are very close to each other act as a coherent source superpose each other and an interference pattern is observed on the screen.

Property:

• The central fringe is always bright as ϕ = 0°
• If one slit is illuminated with red light and the other with green no pattern is observed.
• All the fringes are of equal width β = λ D/d
• Angular fringe width θ = λ /d
• If the whole thing is submerged in water then βw = ¾ βa
• Position of nth bright fringe from central maxima n = nλ d/D
• Position of nth dark fringe from central maxima n = (2n-1)λ d/D

Calculation:

Fringe width in air (βa) = 0.4 mm

We know that when submerged in water

If the whole thing is submerged in water then:

βw = ¾ βa

βw = ¾ β= ¾ (0.4) = 0.3 mm
user
The passage contains a physics question related to Young's double slit experiment, specifically asking about the change in fringe width when the apparatus is immersed in water. The correct answer is provided as 0.30 mm.

TYPE: SINGLE_QUESTION_WITH_ANSWER