# Algebra

posted by .

Solve by using the quadratic formula
x^2=-7x+12

First, put all the terms on one side.

x^2=-7x+12

x^2 + 7x -12 = 0

If the original sign for the 12 were negative, this would lead you to:

x^2 + 7x + 12 = 0

This could factor into:

(x+3)(x+4) = 0

However, as you have formula posted, it cannot be factored.

I hope this helps. Thanks for asking.

x=(-7/2)+(sq97)/(2),(-7/2)-(sq97)/(2)

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single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
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First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
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system
# Algebra

posted by .

Solve by using the quadratic formula
x^2=-7x+12

First, put all the terms on one side.

x^2=-7x+12

x^2 + 7x -12 = 0

If the original sign for the 12 were negative, this would lead you to:

x^2 + 7x + 12 = 0

This could factor into:

(x+3)(x+4) = 0

However, as you have formula posted, it cannot be factored.

I hope this helps. Thanks for asking.

x=(-7/2)+(sq97)/(2),(-7/2)-(sq97)/(2)

## Similar Questions

1. ### Variable

SOLVING EQUATIONS WITH THE VARIABLE ON BOTH SIDES Solve the equation. Then check your solution. 4x-9 = 7x+12 Just remember that one can add, subtract, multiply, divide, etc but whatever is done to one side must be done to the other …

3. ### algebra--distributive

how would you do this prob. negative4-(5y+6) = negative 7y+3 thanks. happy halloween I'm going to assume your problem is this: -4 - (5y + 6) = -7y + 3 If that's the case, distribute the negative over the terms in the parentheses first: …
4. ### algabra

the sum of a the digits in a two digit # is 11. if the digits are reversed, the new # is 45 more than the original #. What is this # !!! i need help AB is the two digit number A+B=11 10B + A= 10A + B - 45 solve. Ok, first. You would …
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