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# If y is an integer and y = |x| + x, is y = 0? (1) x < 0

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SVP
Joined: 21 Jul 2006
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If y is an integer and y = |x| + x, is y = 0? (1) x < 0 [#permalink]

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27 Oct 2008, 10:51
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If y is an integer and y = |x| + x, is y = 0?

(1) x < 0

(2) y < 1

Thanks

Kudos [?]: 1008 [0], given: 1

Director
Joined: 23 May 2008
Posts: 801

Kudos [?]: 83 [0], given: 0

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27 Oct 2008, 11:11
1)if x less than 0 then lxl + x has to be 0 ..suff
2) if y<1 then then lxl + x is less than one, which means -tve numbers since y is an integer so same results as 1)
..suff

D

Kudos [?]: 83 [0], given: 0

SVP
Joined: 29 Aug 2007
Posts: 2472

Kudos [?]: 843 [0], given: 19

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27 Oct 2008, 11:12
tarek99 wrote:
If y is an integer and y = |x| + x, is y = 0?

(1) x < 0
(2) y < 1

Thanks

Did not you get D?
Yeah, it should be D.

St 1 is sufficient - no need to expalin.
St 2 is also sufficient - since Y is an integer and <1, Y must be 0 cuz at any cost Y cannot be -ve.

so D.
_________________

Gmat: http://gmatclub.com/forum/everything-you-need-to-prepare-for-the-gmat-revised-77983.html

GT

Kudos [?]: 843 [0], given: 19

SVP
Joined: 21 Jul 2006
Posts: 1512

Kudos [?]: 1008 [0], given: 1

### Show Tags

27 Oct 2008, 11:33
GMAT TIGER wrote:
tarek99 wrote:
If y is an integer and y = |x| + x, is y = 0?

(1) x < 0
(2) y < 1

Thanks

Did not you get D?
Yeah, it should be D.

St 1 is sufficient - no need to expalin.
St 2 is also sufficient - since Y is an integer and <1, Y must be 0 cuz at any cost Y cannot be -ve.

so D.

OA is D. I got A when I worked on this problem. Stupid mistake

Kudos [?]: 1008 [0], given: 1

Current Student
Joined: 28 Dec 2004
Posts: 3350

Kudos [?]: 319 [0], given: 2

Location: New York City
Schools: Wharton'11 HBS'12

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27 Oct 2008, 13:03
key is Y is an integer..so if y<1 then the only option is that its 0..

Kudos [?]: 319 [0], given: 2

VP
Joined: 30 Jun 2008
Posts: 1034

Kudos [?]: 708 [0], given: 1

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27 Oct 2008, 17:32
tarek99 wrote:
If y is an integer and y = |x| + x, is y = 0?

(1) x < 0

(2) y < 1

Thanks

(1) x < 0. Pick any simple -ve number for x. say x = -2

now y = |-2| + (-2) = 2-2 = 0. Statement 1 is sufficient.

(2) y < 1. y could be 0,-1,-2,-3 .........

but we have an extra info in the stem, y = |x| + x. if y<1 then |x| + x < 1 or |x| + x </= 0............ [</= --- lesser than or equal to]

|x| </= -x .... now this can happen only when x </= 0

so y has to be 0.. Statement 2 is sufficient.

D.
_________________

"You have to find it. No one else can find it for you." - Bjorn Borg

Kudos [?]: 708 [0], given: 1

Re: DS: absolute value   [#permalink] 27 Oct 2008, 17:32
Display posts from previous: Sort by
The given text is a GMAT Club Daily Prep post and a question from a user. The content structure includes a date and time stamp, a brief description of the GMAT Club Daily Prep service, and a math question.
no_question

the text does not contain a mathematical question that requires solving or a word problem. the math question is actually a part of the user's post at the end, but it is not integrated into the main content of the text, which is about the gmat club daily prep service.
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
It is currently 20 Oct 2017, 17:11

### GMAT Club Daily Prep

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# Events & Promotions

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# If y is an integer and y = |x| + x, is y = 0? (1) x < 0

Author Message
SVP
Joined: 21 Jul 2006
Posts: 1512

Kudos [?]: 1008 [0], given: 1

If y is an integer and y = |x| + x, is y = 0? (1) x < 0 [#permalink]

### Show Tags

27 Oct 2008, 10:51
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If y is an integer and y = |x| + x, is y = 0?

(1) x < 0

(2) y < 1

Thanks

Kudos [?]: 1008 [0], given: 1

Director
Joined: 23 May 2008
Posts: 801

Kudos [?]: 83 [0], given: 0

### Show Tags

27 Oct 2008, 11:11
1)if x less than 0 then lxl + x has to be 0 ..suff
2) if y<1 then then lxl + x is less than one, which means -tve numbers since y is an integer so same results as 1)
..suff

D

Kudos [?]: 83 [0], given: 0

SVP
Joined: 29 Aug 2007
Posts: 2472

Kudos [?]: 843 [0], given: 19

### Show Tags

27 Oct 2008, 11:12
tarek99 wrote:
If y is an integer and y = |x| + x, is y = 0?

(1) x < 0
(2) y < 1

Thanks

Did not you get D?
Yeah, it should be D.

St 1 is sufficient - no need to expalin.
St 2 is also sufficient - since Y is an integer and <1, Y must be 0 cuz at any cost Y cannot be -ve.

so D.
_________________

Gmat: http://gmatclub.com/forum/everything-you-need-to-prepare-for-the-gmat-revised-77983.html

GT

Kudos [?]: 843 [0], given: 19

SVP
Joined: 21 Jul 2006
Posts: 1512

Kudos [?]: 1008 [0], given: 1

### Show Tags

27 Oct 2008, 11:33
GMAT TIGER wrote:
tarek99 wrote:
If y is an integer and y = |x| + x, is y = 0?

(1) x < 0
(2) y < 1

Thanks

Did not you get D?
Yeah, it should be D.

St 1 is sufficient - no need to expalin.
St 2 is also sufficient - since Y is an integer and <1, Y must be 0 cuz at any cost Y cannot be -ve.

so D.

OA is D. I got A when I worked on this problem. Stupid mistake

Kudos [?]: 1008 [0], given: 1

Current Student
Joined: 28 Dec 2004
Posts: 3350

Kudos [?]: 319 [0], given: 2

Location: New York City
Schools: Wharton'11 HBS'12

### Show Tags

27 Oct 2008, 13:03
key is Y is an integer..so if y<1 then the only option is that its 0..

Kudos [?]: 319 [0], given: 2

VP
Joined: 30 Jun 2008
Posts: 1034

Kudos [?]: 708 [0], given: 1

### Show Tags

27 Oct 2008, 17:32
tarek99 wrote:
If y is an integer and y = |x| + x, is y = 0?

(1) x < 0

(2) y < 1

Thanks

(1) x < 0. Pick any simple -ve number for x. say x = -2

now y = |-2| + (-2) = 2-2 = 0. Statement 1 is sufficient.

(2) y < 1. y could be 0,-1,-2,-3 .........

but we have an extra info in the stem, y = |x| + x. if y<1 then |x| + x < 1 or |x| + x </= 0............ [</= --- lesser than or equal to]

|x| </= -x .... now this can happen only when x </= 0

so y has to be 0.. Statement 2 is sufficient.

D.
_________________

"You have to find it. No one else can find it for you." - Bjorn Borg

Kudos [?]: 708 [0], given: 1

Re: DS: absolute value   [#permalink] 27 Oct 2008, 17:32
Display posts from previous: Sort by
user
The given text is a GMAT Club Daily Prep post and a question from a user. The content structure includes a date and time stamp, a brief description of the GMAT Club Daily Prep service, and a math question.

TYPE: NO_QUESTION

The text does not contain a mathematical question that requires solving or a word problem. The math question is actually a part of the user's post at the end, but it is not integrated into the main content of the text, which is about the GMAT Club Daily Prep service.