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# How many way 5 rings can go on 4 fingers? (A) 3x4 (B) 5C4

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Director
Joined: 29 Oct 2004
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How many way 5 rings can go on 4 fingers? (A) 3x4 (B) 5C4 [#permalink]

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27 Dec 2004, 14:11
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

How many way 5 rings can go on 4 fingers?
(A) 3x4
(B) 5C4
(C) 5P4
(D) 5^4
(E) 4^5

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Manager
Joined: 29 Jul 2004
Posts: 61

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27 Dec 2004, 22:14
5 choices for the 1st finger, 4 for the 2nd, etc so my answer is C, 5P4.

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GMAT Club Legend
Joined: 15 Dec 2003
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28 Dec 2004, 00:09
Agree with C. This is a permutation problem whereby there is no replacement of selected items. Once the first ring goes onto the first finger, there will be 4 rings left to choose from for the 2nd finger and so on. B would have been the answer to: In how many ways can one select four rings out of 5.
_________________

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Paul

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Director
Joined: 29 Oct 2004
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Kudos [?]: 258 [0], given: 0

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28 Dec 2004, 06:49
The answer was (E): 4^5 which I don't get either. I came out the same result as you guys. Can someone explain?

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Joined: 15 Dec 2003
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28 Dec 2004, 08:00
E is clearly wrong. It is assuming that the same ring can be used again for another finger once picked.
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Paul

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Director
Joined: 08 Jul 2004
Posts: 595

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02 Jan 2005, 22:04
It will be 4^5 if you assume one can put all rings on a finger ie more than one ring per finger is possible.
S

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GMAT Club Legend
Joined: 15 Dec 2003
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02 Jan 2005, 22:07
saurya_s wrote:
It will be 4^5 if you assume one can put all rings on a finger ie more than one ring per finger is possible.
S

Wow, that never crossed my mind! You are so right
_________________

Best Regards,

Paul

Kudos [?]: 537 [0], given: 0

Manager
Joined: 29 Jul 2004
Posts: 61

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02 Jan 2005, 22:22
saurya_s wrote:
It will be 4^5 if you assume one can put all rings on a finger ie more than one ring per finger is possible.
S

I guess I built in an assumption that wasn't in the problem. I thought that you couldn't have more than 1 ring on each finger. I understand the answer now.

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02 Jan 2005, 22:22
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# How many way 5 rings can go on 4 fingers? (A) 3x4 (B) 5C4

Moderator: chetan2u

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.
The passage contains a mathematical question and provides the correct answer within the text. The question is about combinatorics, specifically how many ways 5 rings can be placed on 4 fingers.

**Content Structure:**
- The passage starts with a date and time.
- It then introduces a GMAT Club Daily Prep context.
- Finally, it presents a combinatorics problem and provides answer choices.

**Analysis:**
single_question_with_answer

the question is clearly stated, and the correct answer (e) is provided in the text. the explanation for why the answer is 4^5 is also given, which is that each ring can be placed on any of the 4 fingers, and there are 5 rings, leading to 4^5 possible combinations.
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
It is currently 24 Nov 2017, 04:32

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# How many way 5 rings can go on 4 fingers? (A) 3x4 (B) 5C4

Author Message
Director
Joined: 29 Oct 2004
Posts: 847

Kudos [?]: 258 [0], given: 0

How many way 5 rings can go on 4 fingers? (A) 3x4 (B) 5C4 [#permalink]

### Show Tags

27 Dec 2004, 14:11
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

How many way 5 rings can go on 4 fingers?
(A) 3x4
(B) 5C4
(C) 5P4
(D) 5^4
(E) 4^5

Kudos [?]: 258 [0], given: 0

Manager
Joined: 29 Jul 2004
Posts: 61

Kudos [?]: [0], given: 0

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27 Dec 2004, 22:14
5 choices for the 1st finger, 4 for the 2nd, etc so my answer is C, 5P4.

Kudos [?]: [0], given: 0

GMAT Club Legend
Joined: 15 Dec 2003
Posts: 4284

Kudos [?]: 537 [0], given: 0

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28 Dec 2004, 00:09
Agree with C. This is a permutation problem whereby there is no replacement of selected items. Once the first ring goes onto the first finger, there will be 4 rings left to choose from for the 2nd finger and so on. B would have been the answer to: In how many ways can one select four rings out of 5.
_________________

Best Regards,

Paul

Kudos [?]: 537 [0], given: 0

Director
Joined: 29 Oct 2004
Posts: 847

Kudos [?]: 258 [0], given: 0

### Show Tags

28 Dec 2004, 06:49
The answer was (E): 4^5 which I don't get either. I came out the same result as you guys. Can someone explain?

Kudos [?]: 258 [0], given: 0

GMAT Club Legend
Joined: 15 Dec 2003
Posts: 4284

Kudos [?]: 537 [0], given: 0

### Show Tags

28 Dec 2004, 08:00
E is clearly wrong. It is assuming that the same ring can be used again for another finger once picked.
_________________

Best Regards,

Paul

Kudos [?]: 537 [0], given: 0

Director
Joined: 08 Jul 2004
Posts: 595

Kudos [?]: 283 [0], given: 0

### Show Tags

02 Jan 2005, 22:04
It will be 4^5 if you assume one can put all rings on a finger ie more than one ring per finger is possible.
S

Kudos [?]: 283 [0], given: 0

GMAT Club Legend
Joined: 15 Dec 2003
Posts: 4284

Kudos [?]: 537 [0], given: 0

### Show Tags

02 Jan 2005, 22:07
saurya_s wrote:
It will be 4^5 if you assume one can put all rings on a finger ie more than one ring per finger is possible.
S

Wow, that never crossed my mind! You are so right
_________________

Best Regards,

Paul

Kudos [?]: 537 [0], given: 0

Manager
Joined: 29 Jul 2004
Posts: 61

Kudos [?]: [0], given: 0

### Show Tags

02 Jan 2005, 22:22
saurya_s wrote:
It will be 4^5 if you assume one can put all rings on a finger ie more than one ring per finger is possible.
S

I guess I built in an assumption that wasn't in the problem. I thought that you couldn't have more than 1 ring on each finger. I understand the answer now.

Kudos [?]: [0], given: 0

02 Jan 2005, 22:22
Display posts from previous: Sort by

# How many way 5 rings can go on 4 fingers? (A) 3x4 (B) 5C4

Moderator: chetan2u

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.
user
The passage contains a mathematical question and provides the correct answer within the text. The question is about combinatorics, specifically how many ways 5 rings can be placed on 4 fingers.

**Content Structure:**
- The passage starts with a date and time.
- It then introduces a GMAT Club Daily Prep context.
- Finally, it presents a combinatorics problem and provides answer choices.

**Analysis:**
TYPE: SINGLE_QUESTION_WITH_ANSWER

The question is clearly stated, and the correct answer (E) is provided in the text. The explanation for why the answer is 4^5 is also given, which is that each ring can be placed on any of the 4 fingers, and there are 5 rings, leading to 4^5 possible combinations.