Intermediate Algebra (12th Edition)

$(x+8)^2+(y+5)^2=5$
$\bf{\text{Solution Outline:}}$ Use the Center-Radius Form of the equation of circles to get the equation with the given center, $C( -8,-5 ),$ and the given radius, $r= \sqrt{5} .$ $\bf{\text{Solution Details:}}$ With the given center, then $h= -8$ and $k= -5 .$ Using the Center-Radius Form of the equation of circles which is given by $(x-h)^2+(y-k)^2=r^2,$ the equation of the circle is \begin{array}{l}\require{cancel} (x-(-8))^2+(y-(-5))^2=(\sqrt{5})^2 \\\\ (x+8)^2+(y+5)^2=5 .\end{array}
The text passage provides a solution to a problem involving the equation of a circle in the Center-Radius Form, but it does not contain a direct question or an answer to a question.
no_question
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
Intermediate Algebra (12th Edition)

$(x+8)^2+(y+5)^2=5$
$\bf{\text{Solution Outline:}}$ Use the Center-Radius Form of the equation of circles to get the equation with the given center, $C( -8,-5 ),$ and the given radius, $r= \sqrt{5} .$ $\bf{\text{Solution Details:}}$ With the given center, then $h= -8$ and $k= -5 .$ Using the Center-Radius Form of the equation of circles which is given by $(x-h)^2+(y-k)^2=r^2,$ the equation of the circle is \begin{array}{l}\require{cancel} (x-(-8))^2+(y-(-5))^2=(\sqrt{5})^2 \\\\ (x+8)^2+(y+5)^2=5 .\end{array}
user
The text passage provides a solution to a problem involving the equation of a circle in the Center-Radius Form, but it does not contain a direct question or an answer to a question.

TYPE: NO_QUESTION