Ex 5.4

Chapter 5 Class 8 Squares and Square Roots
Serial order wise

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### Transcript

Ex 5.4, 5 Find the least number which must be added to each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (v) 6412Rough 160 × 0 = 325 161 × 1 = 161 Here, Remainder = 12 Since remainder is not 0, So, 6412 is not a perfect square We need to find the least number that must be added to 6412 so as to get a perfect square Now, Thus, we add 812 – 6412 to the number ∴ Number to added = 812 − 6412 = 6561 – 6412 = 149 Thus, Perfect square = 6412 + 149 Let’s check Thus, we add 149 to 6412 to get a perfect square. Perfect square = 6561 & Square root of 6561 = 81 Rough 160 × 0 = 325 161 × 1 = 161
The text passage contains a mathematical problem from a chapter on squares and square roots, specifically asking for the least number that must be added to 6412 to make it a perfect square, and the square root of the resulting perfect square.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
Ex 5.4

Chapter 5 Class 8 Squares and Square Roots
Serial order wise

This video is only available for Teachoo black users

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class

### Transcript

Ex 5.4, 5 Find the least number which must be added to each of the following numbers so as to get a perfect square. Also find the square root of the perfect square so obtained. (v) 6412Rough 160 × 0 = 325 161 × 1 = 161 Here, Remainder = 12 Since remainder is not 0, So, 6412 is not a perfect square We need to find the least number that must be added to 6412 so as to get a perfect square Now, Thus, we add 812 – 6412 to the number ∴ Number to added = 812 − 6412 = 6561 – 6412 = 149 Thus, Perfect square = 6412 + 149 Let’s check Thus, we add 149 to 6412 to get a perfect square. Perfect square = 6561 & Square root of 6561 = 81 Rough 160 × 0 = 325 161 × 1 = 161
user
The text passage contains a mathematical problem from a chapter on squares and square roots, specifically asking for the least number that must be added to 6412 to make it a perfect square, and the square root of the resulting perfect square.

TYPE: SINGLE_QUESTION_WITH_ANSWER