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# DS: X^2+ BX+ C=0,---> R,S are solutions of the

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Manager
Joined: 08 Apr 2004
Posts: 137
Location: Corea
Followers: 1

Kudos [?]: 170 [0], given: 0

DS: X^2+ BX+ C=0,---> R,S are solutions of the [#permalink]  07 Sep 2004, 06:24
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
DS: X^2+ BX+ C=0,---> R,S are solutions of the equation.Is R* S>0?
1. B<0
2. C<0
Director
Joined: 20 Jul 2004
Posts: 593
Followers: 1

Kudos [?]: 48 [0], given: 0

B.

Since R and S are solutions of the equation, the equation can be written as x^2 - (R+S)x + RS = 0

In this case, B = -(R+S) and C = RS.
From II, C < 0 => RS < 0, Ans to the question: No.
Joined: 31 Dec 1969
Location: India
Concentration: General Management, Strategy
GMAT 1: 710 Q49 V0
GMAT 2: 740 Q40 V50
GMAT 3: 700 Q48 V38
GPA: 3.6
Followers: 0

Kudos [?]: 89 [0], given: 87116

For the roots to be real and distinct in a quadratic equation, the determinant b^2-4ac > o

here b = B
c=C
a = 1

so, w have B^2 - 4C > 0

Now, 1) B < 0. Doesn't matter as B^2 is always +ve. So we dont know if B^2- 4C will be +ve or not. So insufficient

2) C<0. Sufficient. The B^2 - 4C will be > than 0.

Hence B.
Director
Joined: 16 Jun 2004
Posts: 893
Followers: 2

Kudos [?]: 19 [0], given: 0

guest was me..sorry forgot to login earlier.
Manager
Joined: 02 Apr 2004
Posts: 224
Location: Utrecht
Followers: 1

Kudos [?]: 13 [0], given: 0

Great work guys!

I took C as answer, while now it is obvious for me as well that B is sufficient. We need to understand the value of C to answer the question.

Regards,

Alex
Similar topics Replies Last post
Similar
Topics:
5 In the equation x^2+bx+c=0, b and c are constants, and x is 1 06 Mar 2014, 20:26
43 If r and s are the roots of the equation x^2 + bx + c = 0 27 20 Oct 2012, 11:12
If equation x^2+bx+c=0 have two same roots, b=? (1) c=9 (2) 2 21 Jun 2008, 18:16
How many integers can let x^2+bx+c=0? B and c are constants. 2 18 Aug 2006, 22:33
x^2+bx+c=0 b,c are constant integers, how many pairs of 5 06 May 2006, 02:44
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Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 04 May 2015, 10:49

### GMAT Club Daily Prep

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# Events & Promotions

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# DS: X^2+ BX+ C=0,---> R,S are solutions of the

Author Message
TAGS:
Manager
Joined: 08 Apr 2004
Posts: 137
Location: Corea
Followers: 1

Kudos [?]: 170 [0], given: 0

DS: X^2+ BX+ C=0,---> R,S are solutions of the [#permalink]  07 Sep 2004, 06:24
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
DS: X^2+ BX+ C=0,---> R,S are solutions of the equation.Is R* S>0?
1. B<0
2. C<0
Director
Joined: 20 Jul 2004
Posts: 593
Followers: 1

Kudos [?]: 48 [0], given: 0

B.

Since R and S are solutions of the equation, the equation can be written as x^2 - (R+S)x + RS = 0

In this case, B = -(R+S) and C = RS.
From II, C < 0 => RS < 0, Ans to the question: No.
Joined: 31 Dec 1969
Location: India
Concentration: General Management, Strategy
GMAT 1: 710 Q49 V0
GMAT 2: 740 Q40 V50
GMAT 3: 700 Q48 V38
GPA: 3.6
Followers: 0

Kudos [?]: 89 [0], given: 87116

For the roots to be real and distinct in a quadratic equation, the determinant b^2-4ac > o

here b = B
c=C
a = 1

so, w have B^2 - 4C > 0

Now, 1) B < 0. Doesn't matter as B^2 is always +ve. So we dont know if B^2- 4C will be +ve or not. So insufficient

2) C<0. Sufficient. The B^2 - 4C will be > than 0.

Hence B.
Director
Joined: 16 Jun 2004
Posts: 893
Followers: 2

Kudos [?]: 19 [0], given: 0

guest was me..sorry forgot to login earlier.
Manager
Joined: 02 Apr 2004
Posts: 224
Location: Utrecht
Followers: 1

Kudos [?]: 13 [0], given: 0

Great work guys!

I took C as answer, while now it is obvious for me as well that B is sufficient. We need to understand the value of C to answer the question.

Regards,

Alex
Similar topics Replies Last post
Similar
Topics:
5 In the equation x^2+bx+c=0, b and c are constants, and x is 1 06 Mar 2014, 20:26
43 If r and s are the roots of the equation x^2 + bx + c = 0 27 20 Oct 2012, 11:12
If equation x^2+bx+c=0 have two same roots, b=? (1) c=9 (2) 2 21 Jun 2008, 18:16
How many integers can let x^2+bx+c=0? B and c are constants. 2 18 Aug 2006, 22:33
x^2+bx+c=0 b,c are constant integers, how many pairs of 5 06 May 2006, 02:44
Display posts from previous: Sort by
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