# 2. An alternating current is represented by the equation I=20sin 100mt. Compute its frequency and the maximum r.m.s values of current.<

Question

2. An alternating current is represented by the equation I=20sin 100mt.
Compute its frequency and the maximum r.m.s values of current.
Ans: 50Hz,20A,14.14A

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1 year 2021-09-03T17:31:28+00:00 1 Answers 30 views 0

1. Explanation:

The general equation of an AC current is given by :

$$I=I_o sin\omega t$$

Where

I₀ is the peak value of current

$$\omega$$ is angular frequency

$$As\ \omega=2\pi f$$

So,

$$f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{100\pi}{2\pi}\\\\f=50\ Hz$$

We know that,

$$I_{rms}=\dfrac{I_0}{\sqrt{2}}\\\\=\dfrac{20}{\sqrt{2}}\\\\I_{rms}=14.14\ A$$

So, the frequency is 50 Hz and the maximum rms value of current is 14.14 A.
The text passage contains a mathematical question related to alternating current, asking for the computation of frequency and the maximum r.m.s. values of current. An answer is also provided in the text.
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# 2. An alternating current is represented by the equation I=20sin 100mt. Compute its frequency and the maximum r.m.s values of current.<

Question

2. An alternating current is represented by the equation I=20sin 100mt.
Compute its frequency and the maximum r.m.s values of current.
Ans: 50Hz,20A,14.14A

in progress 0
1 year 2021-09-03T17:31:28+00:00 1 Answers 30 views 0

1. Explanation:

The general equation of an AC current is given by :

$$I=I_o sin\omega t$$

Where

I₀ is the peak value of current

$$\omega$$ is angular frequency

$$As\ \omega=2\pi f$$

So,

$$f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{100\pi}{2\pi}\\\\f=50\ Hz$$

We know that,

$$I_{rms}=\dfrac{I_0}{\sqrt{2}}\\\\=\dfrac{20}{\sqrt{2}}\\\\I_{rms}=14.14\ A$$

So, the frequency is 50 Hz and the maximum rms value of current is 14.14 A.
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The text passage contains a mathematical question related to alternating current, asking for the computation of frequency and the maximum r.m.s. values of current. An answer is also provided in the text.

TYPE: SINGLE_QUESTION_WITH_ANSWER