• # question_answer In the figure emf of the cell is 2 V and internal resistance is negligible. The resistance of the voltmeter is 80 ohm. The reading of voltmeter will be A)  2.00 volt                     B)  1.33 voltC)  1.60 volt                     D)  0.80

The voltmeter is in parallel with $80\,\Omega$ resistance. Let equivalent resistance be $R'$Here $R'=40\Omega .$Now $20\,\Omega$ resistance is in series with $R'=$So, the equivalent resistance of the circuit$=20+40+60\Omega$ Current in the circuit = (2/60) amp. Current across $80\Omega$ resistance $=\frac{1}{2}\left[ \frac{2}{60} \right]=\frac{1}{60}\,amp.$ $\therefore$Reading of voltmeter $=80\times (1/60)=1.33\,V$ Hence, the correction option is [b].
The passage describes a physics problem involving a circuit with a cell, resistances, and a voltmeter. It includes a detailed calculation to determine the reading of the voltmeter and provides the correct answer.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
• # question_answer In the figure emf of the cell is 2 V and internal resistance is negligible. The resistance of the voltmeter is 80 ohm. The reading of voltmeter will be A)  2.00 volt                     B)  1.33 voltC)  1.60 volt                     D)  0.80

The voltmeter is in parallel with $80\,\Omega$ resistance. Let equivalent resistance be $R'$Here $R'=40\Omega .$Now $20\,\Omega$ resistance is in series with $R'=$So, the equivalent resistance of the circuit$=20+40+60\Omega$ Current in the circuit = (2/60) amp. Current across $80\Omega$ resistance $=\frac{1}{2}\left[ \frac{2}{60} \right]=\frac{1}{60}\,amp.$ $\therefore$Reading of voltmeter $=80\times (1/60)=1.33\,V$ Hence, the correction option is [b].
user
The passage describes a physics problem involving a circuit with a cell, resistances, and a voltmeter. It includes a detailed calculation to determine the reading of the voltmeter and provides the correct answer.

TYPE: SINGLE_QUESTION_WITH_ANSWER