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If sintheta=n"sin"(theta+2alp...

Updated On: 27-06-2022

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Text Solution

Solution : Given <br> sintheta=nsin(theta+2alpha)<br> =>(sintheta)/(sin(theta+2alpha))=n <br> apply componendo dividendo rule,<br> =>(sintheta+sin(theta+2alpha))/(sintheta−sin(theta+2alpha))=(n+1)/(n-1)<br> applying sinC+sinD=2sin((C+D)/2)cos((C-D)/2) and sinC−sinD=2sin((C-D)/2)cos((C+D)/2) formula<br> =>(2sin(theta+alpha)cosalpha)/(2sinalphacos(theta+alpha))=(n+1)/(n-1)<br> =>(tan(theta+alpha))/(tanalpha)=(n+1)/(n-1)<br> =>tan(theta+alpha)=(n+1)/(n-1)tanalpha
The text passage contains a mathematical problem and its solution, specifically dealing with trigonometric identities and transformations.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
Home

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English

>

Class 11

>

Maths

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Chapter

>

Transformation Formulae

>

If sintheta=n"sin"(theta+2alp...

Updated On: 27-06-2022

Get Answer to any question, just click a photo and upload the photo and get the answer completely free,

Text Solution

Solution : Given <br> sintheta=nsin(theta+2alpha)<br> =>(sintheta)/(sin(theta+2alpha))=n <br> apply componendo dividendo rule,<br> =>(sintheta+sin(theta+2alpha))/(sintheta−sin(theta+2alpha))=(n+1)/(n-1)<br> applying sinC+sinD=2sin((C+D)/2)cos((C-D)/2) and sinC−sinD=2sin((C-D)/2)cos((C+D)/2) formula<br> =>(2sin(theta+alpha)cosalpha)/(2sinalphacos(theta+alpha))=(n+1)/(n-1)<br> =>(tan(theta+alpha))/(tanalpha)=(n+1)/(n-1)<br> =>tan(theta+alpha)=(n+1)/(n-1)tanalpha
user
The text passage contains a mathematical problem and its solution, specifically dealing with trigonometric identities and transformations.

TYPE: SINGLE_QUESTION_WITH_ANSWER