# How do you find the derivative of 2x^2+x-1?

Apr 13, 2017

$\frac{\mathrm{dy}}{\mathrm{dx}} \left(2 {x}^{2} + x - 1\right) = 4 x + 1$

#### Explanation:

Use the power rule $r {\left(a\right)}^{r - 1}$ and recall that the derivative of a constant is $0$

Therefore the derivative is,

$\frac{\mathrm{dy}}{\mathrm{dx}} = 2 \cdot 2 {x}^{2 - 1} + 1 {x}^{1 - 0} - 0$

$\frac{\mathrm{dy}}{\mathrm{dx}} = 4 x + 1$
The text passage contains a mathematical question about finding the derivative of a function, and it provides the answer to that question.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
# How do you find the derivative of 2x^2+x-1?

Apr 13, 2017

$\frac{\mathrm{dy}}{\mathrm{dx}} \left(2 {x}^{2} + x - 1\right) = 4 x + 1$

#### Explanation:

Use the power rule $r {\left(a\right)}^{r - 1}$ and recall that the derivative of a constant is $0$

Therefore the derivative is,

$\frac{\mathrm{dy}}{\mathrm{dx}} = 2 \cdot 2 {x}^{2 - 1} + 1 {x}^{1 - 0} - 0$

$\frac{\mathrm{dy}}{\mathrm{dx}} = 4 x + 1$
user
The text passage contains a mathematical question about finding the derivative of a function, and it provides the answer to that question.

TYPE: SINGLE_QUESTION_WITH_ANSWER