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				   [(a-b)2 + (a2/20 - { (17-b)x(b-13) }1/2 )2]
a, b are variables (like usually used x.)
can you tell me how to find the minimum value of the above expression and for what values of a and b will it be maximum.........


6 years ago

Share

										Ans:$f(a, b) = (a-b)^{2}+(\frac{a^{2}}{20}-\sqrt{(17-b).(b-13)})^{2}$$f(a, b) = a^{2} + \frac{a^{4}}{400}-2ab-\frac{a^{2}}{10}.\sqrt{(17-b).(b-13)}+ ((17-b).(b-13))$$13\leq b\leq 17$$\frac{\partial f(a, b)}{\partial a} =2a + \frac{a^{3}}{100}-2b-\frac{a}{5}\sqrt{(17-b)(b-13)} = 0$From here, you will get the value of a in the form of b.Put that value in the equation & you will get the equation in b.Then differentiate the function w.r.t b & equate it to zero.Calculate b from the equation & select appropriate from the value b/w 13 & 17 for maxima & minima.Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

2 years ago
										Can you explain how to get a in form of b from last equation.

2 years ago

# Other Related Questions on Differential Calculus

Plz help me solve this question. It is from chapter limits and derivatives . I did not find that in the list,

Krishna, write your questions that you want to ask, to related to limits and derivative. But you studied the defnition of limits and derivative clearly.

 Kumar 3 months ago

Try desmos (Google it ) ... It is used to graph the function.. Then you can set y as a parameter and then you will see that the function as x-> 0 the graph tends to infinity (for some values...

 rishabh 3 months ago

Kumar the question is lim x--> 0 ((y^2 - (y-x)^2)^1/x). / (8xy - 4x^2 + (8xy)^1/2)^3 I have also attached the image of it with the question please take a look

 Sujith krishna 3 months ago
Why does lhl and rhl are not equal in this question.w hat should i do in these type of questions

coz this is not 0/0 inderminate form ...it is exact 0/0 which is not defined(n.d.)

 Nishant Vora one month ago

 Nishant Vora one month ago

Why cannot we write tan[x]/[x] as 1 when x tends towards zero..and if is in 0/0 form why didnt u used lhospital rule

 Samaksh one month ago
i can not solve this inequality please sir how to solve this inequality Ix+1I+Ix-2I

i am trying to write conditions in the answer but after posting the conditions are vanishing , you can see above, dont know why is it happening.... :(

 DR STRANGE 13 days ago

Ix+1I+Ix-2I = 2x-1 ….....for x>2 =x+1 -(x-2) = 3 …......for -1 = -(x+1) -(x-2) = 1-2x ….......for x

 DR STRANGE 13 days ago

mistake............................................................... =3 for...... -1 = 1-2x ….for x

 DR STRANGE 13 days ago
If alpha is a real root of the equation ax 2 +bx+c and beta is a real root of equation -ax 2 +bx+c. Show that there exists a root gama of the equation (a/2)x 2 +bx+c which lies between alpha...

 Ajay 6 months ago

Small Mistake in last para posting again..............................................................................................................

 Ajay 6 months ago

We have Similarly, So if P(x) = a/2 x 2 +bx +c, then and are off opposite sign and hence there must exist a root between the two numbers.

 mycroft holmes 6 months ago
In the listed image can you tell me how beta*gamma = 2 ….. . . .. ??

The value of gamma is still not correct, either printing mistake or you gave me wrong value. The correct value of gamma is below

 Ajay 5 months ago

Thankyou so much............................. …......................................................................!

 Anshuman Mohanty 5 months ago

Yes sorry..... . . . .it is not so clear.. ok the values are beta = α + α^2 + α^4 and gamma = α^3 + α^5 + α^7

 Anshuman Mohanty 5 months ago
if |z - i| Options: a*) 14 b) 2 c) 28 d) None of the above

If |z-i| = ?? PLs complete the question

 Nishant Vora one month ago

Got it! [z + 12 – 6 i ] can be rewritten as [ z – i + 12 – 5 i] => | z – i | and => |12 – 5 i | = sqrt ( 12^2 + 5^2) = 13......................(2) => | z + 12 – 6 i | => | z + 12 – 6 i |...

 Divya one month ago

I tried posting the question several times, it kept cutting off the rest of the question. Here: If | z-1| Options: a*) 14 b) 2 c) 28 d) None of the above

 Divya one month ago
View all Questions »

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USE CODE: chait6

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More Questions On Differential Calculus
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
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Use Coupon: CART20 and get 20% off on all online Study Material

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Total Price: R

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coupon code: MOB20 | View Course list

Get extra R 1,600 off
USE CODE: chait6

				   [(a-b)2 + (a2/20 - { (17-b)x(b-13) }1/2 )2]
a, b are variables (like usually used x.)
can you tell me how to find the minimum value of the above expression and for what values of a and b will it be maximum.........


6 years ago

Share

										Ans:$f(a, b) = (a-b)^{2}+(\frac{a^{2}}{20}-\sqrt{(17-b).(b-13)})^{2}$$f(a, b) = a^{2} + \frac{a^{4}}{400}-2ab-\frac{a^{2}}{10}.\sqrt{(17-b).(b-13)}+ ((17-b).(b-13))$$13\leq b\leq 17$$\frac{\partial f(a, b)}{\partial a} =2a + \frac{a^{3}}{100}-2b-\frac{a}{5}\sqrt{(17-b)(b-13)} = 0$From here, you will get the value of a in the form of b.Put that value in the equation & you will get the equation in b.Then differentiate the function w.r.t b & equate it to zero.Calculate b from the equation & select appropriate from the value b/w 13 & 17 for maxima & minima.Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

2 years ago
										Can you explain how to get a in form of b from last equation.

2 years ago

# Other Related Questions on Differential Calculus

Plz help me solve this question. It is from chapter limits and derivatives . I did not find that in the list,

Krishna, write your questions that you want to ask, to related to limits and derivative. But you studied the defnition of limits and derivative clearly.

 Kumar 3 months ago

Try desmos (Google it ) ... It is used to graph the function.. Then you can set y as a parameter and then you will see that the function as x-> 0 the graph tends to infinity (for some values...

 rishabh 3 months ago

Kumar the question is lim x--> 0 ((y^2 - (y-x)^2)^1/x). / (8xy - 4x^2 + (8xy)^1/2)^3 I have also attached the image of it with the question please take a look

 Sujith krishna 3 months ago
Why does lhl and rhl are not equal in this question.w hat should i do in these type of questions

coz this is not 0/0 inderminate form ...it is exact 0/0 which is not defined(n.d.)

 Nishant Vora one month ago

 Nishant Vora one month ago

Why cannot we write tan[x]/[x] as 1 when x tends towards zero..and if is in 0/0 form why didnt u used lhospital rule

 Samaksh one month ago
i can not solve this inequality please sir how to solve this inequality Ix+1I+Ix-2I

i am trying to write conditions in the answer but after posting the conditions are vanishing , you can see above, dont know why is it happening.... :(

 DR STRANGE 13 days ago

Ix+1I+Ix-2I = 2x-1 ….....for x>2 =x+1 -(x-2) = 3 …......for -1 = -(x+1) -(x-2) = 1-2x ….......for x

 DR STRANGE 13 days ago

mistake............................................................... =3 for...... -1 = 1-2x ….for x

 DR STRANGE 13 days ago
If alpha is a real root of the equation ax 2 +bx+c and beta is a real root of equation -ax 2 +bx+c. Show that there exists a root gama of the equation (a/2)x 2 +bx+c which lies between alpha...

 Ajay 6 months ago

Small Mistake in last para posting again..............................................................................................................

 Ajay 6 months ago

We have Similarly, So if P(x) = a/2 x 2 +bx +c, then and are off opposite sign and hence there must exist a root between the two numbers.

 mycroft holmes 6 months ago
In the listed image can you tell me how beta*gamma = 2 ….. . . .. ??

The value of gamma is still not correct, either printing mistake or you gave me wrong value. The correct value of gamma is below

 Ajay 5 months ago

Thankyou so much............................. …......................................................................!

 Anshuman Mohanty 5 months ago

Yes sorry..... . . . .it is not so clear.. ok the values are beta = α + α^2 + α^4 and gamma = α^3 + α^5 + α^7

 Anshuman Mohanty 5 months ago
if |z - i| Options: a*) 14 b) 2 c) 28 d) None of the above

If |z-i| = ?? PLs complete the question

 Nishant Vora one month ago

Got it! [z + 12 – 6 i ] can be rewritten as [ z – i + 12 – 5 i] => | z – i | and => |12 – 5 i | = sqrt ( 12^2 + 5^2) = 13......................(2) => | z + 12 – 6 i | => | z + 12 – 6 i |...

 Divya one month ago

I tried posting the question several times, it kept cutting off the rest of the question. Here: If | z-1| Options: a*) 14 b) 2 c) 28 d) None of the above

 Divya one month ago
View all Questions »

• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: R 15,000
• View Details
Get extra R 6,000 off
USE CODE: chait6

Get extra R 1,600 off
USE CODE: chait6

More Questions On Differential Calculus
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