1. ## algebara2

hi i really need help

(-1/3)(1/6)square((-1/3)(1/6)-(-1/3)square))=
1/108(-1/18-1/9)=1/108(-1/9)=1/972

i know i got the wrong answer but i tried to find out several ways but i get the wrong answer " the answer suposed to be 1/648" how \HELP

2. Originally Posted by samarox16
hi i really need help

(-1/3)(1/6)square((-1/3)(1/6)-(-1/3)square))=
1/108(-1/18-1/9)=1/108(-1/9)=1/972

i know i got the wrong answer but i tried to find out several ways but i get the wrong answer " the answer suposed to be 1/648" how \HELP
I really cannot understand what the question is, can you be clearer?

3. Originally Posted by samarox16
hi i really need help

(-1/3)(1/6)square((-1/3)(1/6)-(-1/3)square))=
1/108(-1/18-1/9)=1/108(-1/9)=1/972

i know i got the wrong answer but i tried to find out several ways but i get the wrong answer " the answer suposed to be 1/648" how \HELP
Although it is easy to trace your question from the given answer, it is better if you present your questions in ways that can be understood by all. You tried, basing from your correct use of parentheses, but the two "square" did not help. I assume you did not know yet that "a^2" is the symbol for "a,squared" or "a, square" or "square of a"
If you like to learn/use LaTex, the "a^2" will appear as the familiar "a, squared" as you would write it on paper.

(-1/3)[(1/6)^2]*[(-1/3)(1/6) -(-1/3)^2]
= (-1/3)(1/36)*[(-1/18) -(1/9)]
= (-1/108)*[(-1 +2(-1))/18]
= (-1/108)*[(-3)/18]
= (-1/108)(-1/6)
The content structure consists of a user posting a mathematical problem and their attempt at solving it, followed by two responses from other users, one asking for clarification and the other providing a solution.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
1. ## algebara2

hi i really need help

(-1/3)(1/6)square((-1/3)(1/6)-(-1/3)square))=
1/108(-1/18-1/9)=1/108(-1/9)=1/972

i know i got the wrong answer but i tried to find out several ways but i get the wrong answer " the answer suposed to be 1/648" how \HELP

2. Originally Posted by samarox16
hi i really need help

(-1/3)(1/6)square((-1/3)(1/6)-(-1/3)square))=
1/108(-1/18-1/9)=1/108(-1/9)=1/972

i know i got the wrong answer but i tried to find out several ways but i get the wrong answer " the answer suposed to be 1/648" how \HELP
I really cannot understand what the question is, can you be clearer?

3. Originally Posted by samarox16
hi i really need help

(-1/3)(1/6)square((-1/3)(1/6)-(-1/3)square))=
1/108(-1/18-1/9)=1/108(-1/9)=1/972

i know i got the wrong answer but i tried to find out several ways but i get the wrong answer " the answer suposed to be 1/648" how \HELP
Although it is easy to trace your question from the given answer, it is better if you present your questions in ways that can be understood by all. You tried, basing from your correct use of parentheses, but the two "square" did not help. I assume you did not know yet that "a^2" is the symbol for "a,squared" or "a, square" or "square of a"
If you like to learn/use LaTex, the "a^2" will appear as the familiar "a, squared" as you would write it on paper.

(-1/3)[(1/6)^2]*[(-1/3)(1/6) -(-1/3)^2]
= (-1/3)(1/36)*[(-1/18) -(1/9)]
= (-1/108)*[(-1 +2(-1))/18]
= (-1/108)*[(-3)/18]
= (-1/108)(-1/6)
user
The content structure consists of a user posting a mathematical problem and their attempt at solving it, followed by two responses from other users, one asking for clarification and the other providing a solution.

TYPE: SINGLE_QUESTION_WITH_ANSWER