×

# Linear equations with one unknown

Enter an equation or problem
Formatting help
Camera input is not recognized!

We think you wrote:

This solution deals with linear equations with one unknown.

Solution found

## Step by Step Solution

### Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

1/4*(1/3*k+9)-(6)=0

## Step  1  :

            1
Simplify   —
3


#### Equation at the end of step  1  :

   1     1
(— • ((— • k) +  9)) -  6  = 0
4     3


## Step  2  :

#### Rewriting the whole as an Equivalent Fraction :

Adding a whole to a fraction

Rewrite the whole as a fraction using  3  as the denominator :

         9     9 • 3
9 =  —  =  —————
1       3


Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

#### Adding fractions that have a common denominator :

Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

 k + 9 • 3     k + 27
—————————  =  ——————
3           3


#### Equation at the end of step  2  :

   1   (k + 27)
(— • ————————) -  6  = 0
4      3


## Step  3  :

            1
Simplify   —
4


#### Equation at the end of step  3  :

   1   (k + 27)
(— • ————————) -  6  = 0
4      3


## Step  4  :

#### Equation at the end of step  4  :

  (k + 27)
———————— -  6  = 0
12


## Step  5  :

#### Rewriting the whole as an Equivalent Fraction :

Subtracting a whole from a fraction

Rewrite the whole as a fraction using  12  as the denominator :

         6     6 • 12
6 =  —  =  ——————
1       12


#### Adding fractions that have a common denominator :

Adding up the two equivalent fractions

 (k+27) - (6 • 12)     k - 45
—————————————————  =  ——————
12               12


#### Equation at the end of step  5  :

  k - 45
——————  = 0
12


## Step  6  :

#### When a fraction equals zero :

 6.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

  k-45
———— • 12 = 0 • 12
12


Now, on the left hand side, the  12  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
k-45  = 0

#### Solving a Single Variable Equation :

Solve  :    k-45 = 0

Add  45  to both sides of the equation :

k = 45

## One solution was found :

k = 45
The text passage provides a step-by-step solution to a linear equation with one unknown, specifically solving for \( k \) in the equation \( \frac{1}{4} \left( \frac{1}{3} k + 9 \right) - 6 = 0 \).
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
×

# Linear equations with one unknown

Enter an equation or problem
Formatting help
Camera input is not recognized!

We think you wrote:

This solution deals with linear equations with one unknown.

Solution found

## Step by Step Solution

### Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

1/4*(1/3*k+9)-(6)=0

## Step  1  :

            1
Simplify   —
3


#### Equation at the end of step  1  :

   1     1
(— • ((— • k) +  9)) -  6  = 0
4     3


## Step  2  :

#### Rewriting the whole as an Equivalent Fraction :

Adding a whole to a fraction

Rewrite the whole as a fraction using  3  as the denominator :

         9     9 • 3
9 =  —  =  —————
1       3


Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

#### Adding fractions that have a common denominator :

Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

 k + 9 • 3     k + 27
—————————  =  ——————
3           3


#### Equation at the end of step  2  :

   1   (k + 27)
(— • ————————) -  6  = 0
4      3


## Step  3  :

            1
Simplify   —
4


#### Equation at the end of step  3  :

   1   (k + 27)
(— • ————————) -  6  = 0
4      3


## Step  4  :

#### Equation at the end of step  4  :

  (k + 27)
———————— -  6  = 0
12


## Step  5  :

#### Rewriting the whole as an Equivalent Fraction :

Subtracting a whole from a fraction

Rewrite the whole as a fraction using  12  as the denominator :

         6     6 • 12
6 =  —  =  ——————
1       12


#### Adding fractions that have a common denominator :

Adding up the two equivalent fractions

 (k+27) - (6 • 12)     k - 45
—————————————————  =  ——————
12               12


#### Equation at the end of step  5  :

  k - 45
——————  = 0
12


## Step  6  :

#### When a fraction equals zero :

 6.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

  k-45
———— • 12 = 0 • 12
12


Now, on the left hand side, the  12  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
k-45  = 0

#### Solving a Single Variable Equation :

Solve  :    k-45 = 0

Add  45  to both sides of the equation :

k = 45

## One solution was found :

k = 45
user
The text passage provides a step-by-step solution to a linear equation with one unknown, specifically solving for \( k \) in the equation \( \frac{1}{4} \left( \frac{1}{3} k + 9 \right) - 6 = 0 \).

TYPE: SINGLE_QUESTION_WITH_ANSWER