Calculus Volume 1

Chapter 6

Checkpoint

6.1

$1212$ units2

6.2

$310310$ unit2

6.3

$2+222+22$ units2

6.4

$5353$ units2

6.5

$5353$ units2

6.7

$π 2 π 2$

6.8

$8π8π$ units3

6.9

$21π21π$ units3

6.10

$10π310π3$ units3

6.11

$60π60π$ units3

6.12

$15π215π2$ units3

6.13

$8π8π$ units3

6.14

$12π12π$ units3

6.15

$11π611π6$ units3

6.16

$π6π6$ units3

6.17

Use the method of washers; $V=∫−11π[(2−x2)2−(x2)2]dxV=∫−11π[(2−x2)2−(x2)2]dx$

6.18

$1 6 ( 5 5 − 1 ) ≈ 1.697 1 6 ( 5 5 − 1 ) ≈ 1.697$

6.19

$Arc Length ≈ 3.8202 Arc Length ≈ 3.8202$

6.20

$Arc Length = 3.15018 Arc Length = 3.15018$

6.21

$π 6 ( 5 5 − 3 3 ) ≈ 3.133 π 6 ( 5 5 − 3 3 ) ≈ 3.133$

6.22

$12 π 12 π$

6.23

$70 / 3 70 / 3$

6.24

$24 π 24 π$

6.25

$88$ ft-lb

6.26

Approximately $43,255.243,255.2$ ft-lb

6.27

$156,800156,800$ N

6.28

Approximately 7,164,520,000 lb or 3,582,260 t

6.29

$M = 24 , x – = 2 5 m M = 24 , x – = 2 5 m$

6.30

$(−1,−1)(−1,−1)$ m

6.31

The centroid of the region is $(3/2,6/5).(3/2,6/5).$

6.32

The centroid of the region is $(1,13/5).(1,13/5).$

6.33

The centroid of the region is $(0,2/5).(0,2/5).$

6.34

$6π26π2$ units3

6.35
1. $ddxln(2x2+x)=4x+12x2+xddxln(2x2+x)=4x+12x2+x$
2. $ddx(ln(x3))2=6ln(x3)xddx(ln(x3))2=6ln(x3)x$
6.36

$∫ x 2 x 3 + 6 d x = 1 3 ln | x 3 + 6 | + C ∫ x 2 x 3 + 6 d x = 1 3 ln | x 3 + 6 | + C$

6.37

$4 ln 2 4 ln 2$

6.38
1. $ddx(ex2e5x)=ex2−5x(2x−5)ddx(ex2e5x)=ex2−5x(2x−5)$
2. $ddt(e2t)3=6e6tddt(e2t)3=6e6t$
6.39

$∫ 4 e 3 x d x = − 4 3 e −3 x + C ∫ 4 e 3 x d x = − 4 3 e −3 x + C$

6.40
1. $ddt4t4=4t4(ln4)(4t3)ddt4t4=4t4(ln4)(4t3)$
2. $ddxlog3(x2+1)=x(ln3)(x2+1)ddxlog3(x2+1)=x(ln3)(x2+1)$
6.41

$∫ x 2 2 x 3 d x = 1 3 ln 2 2 x 3 + C ∫ x 2 2 x 3 d x = 1 3 ln 2 2 x 3 + C$

6.42

There are $81,377,39681,377,396$ bacteria in the population after $44$ hours. The population reaches $100100$ million bacteria after $244.12244.12$ minutes.

6.43

At $5%5%$ interest, she must invest $223,130.16.223,130.16.$ At $6%6%$ interest, she must invest $165,298.89.165,298.89.$

6.44

$38.9038.90$ months

6.45

The coffee is first cool enough to serve about $3.53.5$ minutes after it is poured. The coffee is too cold to serve about $77$ minutes after it is poured.

6.46

A total of $94.1394.13$ g of carbon remains. The artifact is approximately $13,30013,300$ years old.

6.47
1. $ddx(tanh(x2+3x))=(sech2(x2+3x))(2x+3)ddx(tanh(x2+3x))=(sech2(x2+3x))(2x+3)$
2. $ddx(1(sinhx)2)=ddx(sinhx)−2=−2(sinhx)−3coshxddx(1(sinhx)2)=ddx(sinhx)−2=−2(sinhx)−3coshx$
6.48
1. $∫sinh3xcoshxdx=sinh4x4+C∫sinh3xcoshxdx=sinh4x4+C$
2. $∫sech2(3x)dx=tanh(3x)3+C∫sech2(3x)dx=tanh(3x)3+C$
6.49
1. $ddx(cosh−1(3x))=39x2−1ddx(cosh−1(3x))=39x2−1$
2. $ddx(coth−1x)3=3(coth−1x)21−x2ddx(coth−1x)3=3(coth−1x)21−x2$
6.50
1. $∫1x2−4dx=cosh−1(x2)+C∫1x2−4dx=cosh−1(x2)+C$
2. $∫11−e2xdx=−sech−1(ex)+C∫11−e2xdx=−sech−1(ex)+C$
6.51

$52.95 ft 52.95 ft$

Section 6.1 Exercises

1.

$32 3 32 3$

3.

$13 12 13 12$

5.

$36 36$

7.

243 square units

9.

4

11.

$2(e−1)2e2(e−1)2e$

13.

$1313$

15.

$343343$

17.

$5252$

19.

$1212$

21.

$9292$

23.

$9292$

25.

$332332$

27.

$e−2e−2$

29.

$274274$

31.

$43−ln(3)43−ln(3)$

33.

$1212$

35.

$1212$

37.

$−2(2−π)−2(2−π)$

39.

$1.067 1.067$

41.

$0.852 0.852$

43.

$7.523 7.523$

45.

$3 π − 4 12 3 π − 4 12$

47.

$1.429 1.429$

49.

$33,333.3333,333.33$ total profit for $200200$ cell phones sold

51.

$3.2633.263$ mi represents how far ahead the hare is from the tortoise

53.

$343 24 343 24$

55.

$4 3 4 3$

57.

$π − 32 25 π − 32 25$

Section 6.2 Exercises

63.

8 units3

65.

$32323232$ units3

67.

$724πr2h724πr2h$ units3

69.

$π24π24$ units3

71.

$22$ units3

73.

$π240π240$ units3

75.

$4096π54096π5$ units3

77.

$8π98π9$ units3

79.

$π2π2$ units3

81.

$207π207π$ units3

83.

$4π54π5$ units3

85.

$16π316π3$ units3

87.

$ππ$ units3

89.

$16π316π3$ units3

91.

$72π572π5$ units3

93.

$108π5108π5$ units3

95.

$3π103π10$ units3

97.

$26π26π$ units3

99.

$9π9π$ units3

101.

$π20(75−4ln5(2))π20(75−4ln5(2))$ units3

103.

$m2π3(b3−a3)m2π3(b3−a3)$ units3

105.

$4a2bπ34a2bπ3$ units3

107.

$2π22π2$ units3

109.

$2ab2π32ab2π3$ units3

111.

$V=2π3(2r3-3r2h+h3)V=2π3(2r3-3r2h+h3)$ units3

113.

$π3(h+R)(h−2R)2π3(h+R)(h−2R)2$ units3

Section 6.3 Exercises

115.

$54π54π$ units3

117.

$81π81π$ units3

119.

$512π7512π7$ units3

121.

$2π2π$ units3

123.

$2π32π3$ units3

125.

$2π2π$ units3

127.

$4π54π5$ units3

129.

$64π364π3$ units3

131.

$32π532π5$ units3

133.

$7 π 6 7 π 6$

135.

$48 π 48 π$

137.

$113 π 5 113 π 5$

139.

$512 π 7 512 π 7$

141.

$96π596π5$ units3

143.

$28π1528π15$ units3

145.

$3π103π10$ units3

147.

$π6·22/35-1110=π1012·22/3-11≈2.5286π6·22/35-1110=π1012·22/3-11≈2.5286$ units3

149.

$0.98760.9876$ units3

151.

$3232$ units3

153.

$496π15496π15$ units3

155.

$398π15398π15$ units3

157.

$15.907415.9074$ units3

159.

$13πr2h13πr2h$ units3

161.

$πr2hπr2h$ units3

163.

$πa2πa2$ units3

Section 6.4 Exercises

165.

$2 26 2 26$

167.

$2 17 2 17$

169.

$π 6 ( 17 17 − 5 5 ) π 6 ( 17 17 − 5 5 )$

171.

$13 13 − 8 27 13 13 − 8 27$

173.

$4 3 4 3$

175.

$2.0035 2.0035$

177.

$123 32 123 32$

179.

$10 10$

181.

$20 3 20 3$

183.

$1 675 ( 229 229 − 8 ) 1 675 ( 229 229 − 8 )$

185.

$1 8 ( 4 5 + ln ( 9 + 4 5 ) ) 1 8 ( 4 5 + ln ( 9 + 4 5 ) )$

187.

$1.201 1.201$

189.

$15.2341 15.2341$

191.

$49 π 3 49 π 3$

193.

$70 π 2 70 π 2$

195.

$8 π 8 π$

197.

$120 π 26 120 π 26$

199.

$π 6 ( 17 17 − 1 ) π 6 ( 17 17 − 1 )$

201.

$9 2 π 9 2 π$

203.

$10 10 π 27 ( 73 73 − 1 ) 10 10 π 27 ( 73 73 − 1 )$

205.

$25.645 25.645$

207.

$π ( π + 2 ) π ( π + 2 )$

209.

$10.5017 10.5017$

211.

$2323$ ft

213.

$2 2$

215.

217.

Section 6.5 Exercises

219.

$150150$ ft-lb

221.

$200 J 200 J$

223.

$11$ J

225.

$39 2 39 2$

227.

$ln ( 243 ) ln ( 243 )$

229.

$332 π 15 332 π 15$

231.

$100 π 100 π$

233.

$20 π 15 20 π 15$

235.

$66$ J

237.

$55$ cm

239.

$3636$ J

241.

$18,75018,750$ ft-lb

243.

Weight $=323×109lb=323×109lb$

Work $=43×1012ft-lb=43×1012ft-lb$

245.

$9.71 × 10 2 N m 9.71 × 10 2 N m$

247.

a. $3,000,0003,000,000$ lb, b. $750,000750,000$ lbs

249.

$23.25π23.25π$ million ft-lb

251.

$A ρ H 2 2 A ρ H 2 2$

253.

Section 6.6 Exercises

255.

$5 4 5 4$

257.

$( 2 3 , 2 3 ) ( 2 3 , 2 3 )$

259.

$( 7 4 , 3 2 ) ( 7 4 , 3 2 )$

261.

$3 L 4 3 L 4$

263.

$π 2 π 2$

265.

$e 2 + 1 e 2 − 1 e 2 + 1 e 2 − 1$

267.

$π 2 − 4 π π 2 − 4 π$

269.

$1 4 ( 1 + e 2 ) 1 4 ( 1 + e 2 )$

271.

$( a 3 , b 3 ) ( a 3 , b 3 )$

273.

$( 0 , π 8 ) ( 0 , π 8 )$

275.

$( 0 , 3 ) ( 0 , 3 )$

277.

$( 0 , 4 π ) ( 0 , 4 π )$

279.

$( 5 8 , 1 3 ) ( 5 8 , 1 3 )$

281.

$2 m π 3 2 m π 3$

283.

$π a 2 b π a 2 b$

285.

$( 4 3 π , 4 3 π ) ( 4 3 π , 4 3 π )$

287.

$( 1 2 , 2 5 ) ( 1 2 , 2 5 )$

289.

$( 0 , 28 9 π ) ( 0 , 28 9 π )$

291.

Center of mass: $(a6,4a25),(a6,4a25),$ volume: $2πa492πa49$

293.

Volume: $2π2a2(b+a)2π2a2(b+a)$

Section 6.7 Exercises

295.

$1 x 1 x$

297.

$− 1 x ( ln x ) 2 − 1 x ( ln x ) 2$

299.

$ln ( x + 1 ) + C ln ( x + 1 ) + C$

301.

$ln ( x ) + 1 ln ( x ) + 1$

303.

$cot ( x ) cot ( x )$

305.

$7 x 7 x$

307.

$csc ( x ) sec x csc ( x ) sec x$

309.

$−2 tan x −2 tan x$

311.

$1 2 ln ( 5 3 ) 1 2 ln ( 5 3 )$

313.

$2 − 1 2 ln ( 5 ) 2 − 1 2 ln ( 5 )$

315.

$1 ln ( 2 ) − 1 1 ln ( 2 ) − 1$

317.

$1 2 ln ( 2 ) 1 2 ln ( 2 )$

319.

$1 3 ( ln x ) 3 1 3 ( ln x ) 3$

321.

$2 x 3 x 2 + 1 x 2 − 1 2 x 3 x 2 + 1 x 2 − 1$

323.

$x −2 − ( 1 / x ) ( ln x − 1 ) x −2 − ( 1 / x ) ( ln x − 1 )$

325.

$e x e − 1 e x e − 1$

327.

$1 1$

329.

$− 1 x 2 − 1 x 2$

331.

$π − ln ( 2 ) π − ln ( 2 )$

333.

$1 x 1 x$

335.

$e 5 − 6 units 2 e 5 − 6 units 2$

337.

$ln ( 4 ) − 1 units 2 ln ( 4 ) − 1 units 2$

339.

$2.8656 2.8656$

341.

$3.1502 3.1502$

Section 6.8 Exercises

349.

True

351.

False; $k=ln(2)tk=ln(2)t$

353.

$2020$ hours

355.

No. The relic is approximately $871871$ years old.

357.

$71.9271.92$ years

359.

$55$ days $66$ hours $2727$ minutes

361.

$12 12$

363.

$8.618 % 8.618 %$

365.

$6766.76 6766.76$

367.

$99$ hours $1313$ minutes

369.

$239,179239,179$ years

371.

$P′(t)=43e0.01604t.P′(t)=43e0.01604t.$ The population is always increasing.

373.

The population reaches $1010$ billion people in $2027.2027.$

375.

$P′(t)=2.259e0.06407t.P′(t)=2.259e0.06407t.$ The population is always increasing.

Section 6.9 Exercises

377.

$e x and e − x e x and e − x$

379.

381.

383.

385.

$3 sinh ( 3 x + 1 ) 3 sinh ( 3 x + 1 )$

387.

$− tanh ( x ) sech ( x ) − tanh ( x ) sech ( x )$

389.

$4 cosh ( x ) sinh ( x ) 4 cosh ( x ) sinh ( x )$

391.

$x sech 2 ( x 2 + 1 ) x 2 + 1 x sech 2 ( x 2 + 1 ) x 2 + 1$

393.

$6 sinh 5 ( x ) cosh ( x ) 6 sinh 5 ( x ) cosh ( x )$

395.

$1 2 sinh ( 2 x + 1 ) + C 1 2 sinh ( 2 x + 1 ) + C$

397.

$1 2 sinh 2 ( x 2 ) + C 1 2 sinh 2 ( x 2 ) + C$

399.

$1 3 cosh 3 ( x ) + C 1 3 cosh 3 ( x ) + C$

401.

$ln ( 1 + cosh ( x ) ) + C ln ( 1 + cosh ( x ) ) + C$

403.

$cosh ( x ) + sinh ( x ) + C cosh ( x ) + sinh ( x ) + C$

405.

$4 1 − 16 x 2 4 1 − 16 x 2$

407.

$sinh ( x ) cosh 2 ( x ) + 1 sinh ( x ) cosh 2 ( x ) + 1$

409.

$− csc ( x ) − csc ( x )$

411.

$− 1 ( x 2 − 1 ) tanh −1 ( x ) − 1 ( x 2 − 1 ) tanh −1 ( x )$

413.

$1 a tanh −1 ( x a ) + C 1 a tanh −1 ( x a ) + C$

415.

$x 2 + 1 + C x 2 + 1 + C$

417.

$cosh −1 ( e x ) + C cosh −1 ( e x ) + C$

419.

421.

$37.30 37.30$

423.

$y = 1 c cosh ( c x ) y = 1 c cosh ( c x )$

425.

$−0.521095 −0.521095$

427.

$10 10$

Review Exercises

435.

False

437.

False

439.

441.

$162 π 5 162 π 5$

443.

a. $4,4,$ b. $128π7,128π7,$ c. $64π564π5$

445.

a. $1.949,1.949,$ b. $21.952,21.952,$ c. $17.09917.099$

447.

a. $316,316,$ b. $452π15,452π15,$ c. $31π631π6$

449.

$245.282 245.282$

451.

Mass: $12,12,$ center of mass: $(1835,922)(1835,922)$

453.

$17 + 1 8 ln ( 33 + 8 17 ) 17 + 1 8 ln ( 33 + 8 17 )$

455.

Volume: $3π4,3π4,$ surface area: $π(2−sinh−1(1)+sinh−1(16)−25716)π(2−sinh−1(1)+sinh−1(16)−25716)$

457.

11:02 a.m.

459.

$π ( 1 + sinh ( 1 ) cosh ( 1 ) ) π ( 1 + sinh ( 1 ) cosh ( 1 ) )$

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The text passage appears to be a collection of answers to various calculus problems, likely from a textbook or solution manual. Each problem is numbered and the answer is provided, but the questions themselves are not included in the text.
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the passage contains multiple answers to mathematical questions, but does not include the questions themselves. each answer is associated with a specific problem number (e.g., 6.1, 6.2, etc.). the answers cover a range of calculus topics, including integrals, derivatives, volumes, arc lengths, and applications of calculus to real-world problems.
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    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
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system
Calculus Volume 1

Chapter 6

Checkpoint

6.1

$1212$ units2

6.2

$310310$ unit2

6.3

$2+222+22$ units2

6.4

$5353$ units2

6.5

$5353$ units2

6.7

$π 2 π 2$

6.8

$8π8π$ units3

6.9

$21π21π$ units3

6.10

$10π310π3$ units3

6.11

$60π60π$ units3

6.12

$15π215π2$ units3

6.13

$8π8π$ units3

6.14

$12π12π$ units3

6.15

$11π611π6$ units3

6.16

$π6π6$ units3

6.17

Use the method of washers; $V=∫−11π[(2−x2)2−(x2)2]dxV=∫−11π[(2−x2)2−(x2)2]dx$

6.18

$1 6 ( 5 5 − 1 ) ≈ 1.697 1 6 ( 5 5 − 1 ) ≈ 1.697$

6.19

$Arc Length ≈ 3.8202 Arc Length ≈ 3.8202$

6.20

$Arc Length = 3.15018 Arc Length = 3.15018$

6.21

$π 6 ( 5 5 − 3 3 ) ≈ 3.133 π 6 ( 5 5 − 3 3 ) ≈ 3.133$

6.22

$12 π 12 π$

6.23

$70 / 3 70 / 3$

6.24

$24 π 24 π$

6.25

$88$ ft-lb

6.26

Approximately $43,255.243,255.2$ ft-lb

6.27

$156,800156,800$ N

6.28

Approximately 7,164,520,000 lb or 3,582,260 t

6.29

$M = 24 , x – = 2 5 m M = 24 , x – = 2 5 m$

6.30

$(−1,−1)(−1,−1)$ m

6.31

The centroid of the region is $(3/2,6/5).(3/2,6/5).$

6.32

The centroid of the region is $(1,13/5).(1,13/5).$

6.33

The centroid of the region is $(0,2/5).(0,2/5).$

6.34

$6π26π2$ units3

6.35
1. $ddxln(2x2+x)=4x+12x2+xddxln(2x2+x)=4x+12x2+x$
2. $ddx(ln(x3))2=6ln(x3)xddx(ln(x3))2=6ln(x3)x$
6.36

$∫ x 2 x 3 + 6 d x = 1 3 ln | x 3 + 6 | + C ∫ x 2 x 3 + 6 d x = 1 3 ln | x 3 + 6 | + C$

6.37

$4 ln 2 4 ln 2$

6.38
1. $ddx(ex2e5x)=ex2−5x(2x−5)ddx(ex2e5x)=ex2−5x(2x−5)$
2. $ddt(e2t)3=6e6tddt(e2t)3=6e6t$
6.39

$∫ 4 e 3 x d x = − 4 3 e −3 x + C ∫ 4 e 3 x d x = − 4 3 e −3 x + C$

6.40
1. $ddt4t4=4t4(ln4)(4t3)ddt4t4=4t4(ln4)(4t3)$
2. $ddxlog3(x2+1)=x(ln3)(x2+1)ddxlog3(x2+1)=x(ln3)(x2+1)$
6.41

$∫ x 2 2 x 3 d x = 1 3 ln 2 2 x 3 + C ∫ x 2 2 x 3 d x = 1 3 ln 2 2 x 3 + C$

6.42

There are $81,377,39681,377,396$ bacteria in the population after $44$ hours. The population reaches $100100$ million bacteria after $244.12244.12$ minutes.

6.43

At $5%5%$ interest, she must invest $223,130.16.223,130.16.$ At $6%6%$ interest, she must invest $165,298.89.165,298.89.$

6.44

$38.9038.90$ months

6.45

The coffee is first cool enough to serve about $3.53.5$ minutes after it is poured. The coffee is too cold to serve about $77$ minutes after it is poured.

6.46

A total of $94.1394.13$ g of carbon remains. The artifact is approximately $13,30013,300$ years old.

6.47
1. $ddx(tanh(x2+3x))=(sech2(x2+3x))(2x+3)ddx(tanh(x2+3x))=(sech2(x2+3x))(2x+3)$
2. $ddx(1(sinhx)2)=ddx(sinhx)−2=−2(sinhx)−3coshxddx(1(sinhx)2)=ddx(sinhx)−2=−2(sinhx)−3coshx$
6.48
1. $∫sinh3xcoshxdx=sinh4x4+C∫sinh3xcoshxdx=sinh4x4+C$
2. $∫sech2(3x)dx=tanh(3x)3+C∫sech2(3x)dx=tanh(3x)3+C$
6.49
1. $ddx(cosh−1(3x))=39x2−1ddx(cosh−1(3x))=39x2−1$
2. $ddx(coth−1x)3=3(coth−1x)21−x2ddx(coth−1x)3=3(coth−1x)21−x2$
6.50
1. $∫1x2−4dx=cosh−1(x2)+C∫1x2−4dx=cosh−1(x2)+C$
2. $∫11−e2xdx=−sech−1(ex)+C∫11−e2xdx=−sech−1(ex)+C$
6.51

$52.95 ft 52.95 ft$

Section 6.1 Exercises

1.

$32 3 32 3$

3.

$13 12 13 12$

5.

$36 36$

7.

243 square units

9.

4

11.

$2(e−1)2e2(e−1)2e$

13.

$1313$

15.

$343343$

17.

$5252$

19.

$1212$

21.

$9292$

23.

$9292$

25.

$332332$

27.

$e−2e−2$

29.

$274274$

31.

$43−ln(3)43−ln(3)$

33.

$1212$

35.

$1212$

37.

$−2(2−π)−2(2−π)$

39.

$1.067 1.067$

41.

$0.852 0.852$

43.

$7.523 7.523$

45.

$3 π − 4 12 3 π − 4 12$

47.

$1.429 1.429$

49.

$33,333.3333,333.33$ total profit for $200200$ cell phones sold

51.

$3.2633.263$ mi represents how far ahead the hare is from the tortoise

53.

$343 24 343 24$

55.

$4 3 4 3$

57.

$π − 32 25 π − 32 25$

Section 6.2 Exercises

63.

8 units3

65.

$32323232$ units3

67.

$724πr2h724πr2h$ units3

69.

$π24π24$ units3

71.

$22$ units3

73.

$π240π240$ units3

75.

$4096π54096π5$ units3

77.

$8π98π9$ units3

79.

$π2π2$ units3

81.

$207π207π$ units3

83.

$4π54π5$ units3

85.

$16π316π3$ units3

87.

$ππ$ units3

89.

$16π316π3$ units3

91.

$72π572π5$ units3

93.

$108π5108π5$ units3

95.

$3π103π10$ units3

97.

$26π26π$ units3

99.

$9π9π$ units3

101.

$π20(75−4ln5(2))π20(75−4ln5(2))$ units3

103.

$m2π3(b3−a3)m2π3(b3−a3)$ units3

105.

$4a2bπ34a2bπ3$ units3

107.

$2π22π2$ units3

109.

$2ab2π32ab2π3$ units3

111.

$V=2π3(2r3-3r2h+h3)V=2π3(2r3-3r2h+h3)$ units3

113.

$π3(h+R)(h−2R)2π3(h+R)(h−2R)2$ units3

Section 6.3 Exercises

115.

$54π54π$ units3

117.

$81π81π$ units3

119.

$512π7512π7$ units3

121.

$2π2π$ units3

123.

$2π32π3$ units3

125.

$2π2π$ units3

127.

$4π54π5$ units3

129.

$64π364π3$ units3

131.

$32π532π5$ units3

133.

$7 π 6 7 π 6$

135.

$48 π 48 π$

137.

$113 π 5 113 π 5$

139.

$512 π 7 512 π 7$

141.

$96π596π5$ units3

143.

$28π1528π15$ units3

145.

$3π103π10$ units3

147.

$π6·22/35-1110=π1012·22/3-11≈2.5286π6·22/35-1110=π1012·22/3-11≈2.5286$ units3

149.

$0.98760.9876$ units3

151.

$3232$ units3

153.

$496π15496π15$ units3

155.

$398π15398π15$ units3

157.

$15.907415.9074$ units3

159.

$13πr2h13πr2h$ units3

161.

$πr2hπr2h$ units3

163.

$πa2πa2$ units3

Section 6.4 Exercises

165.

$2 26 2 26$

167.

$2 17 2 17$

169.

$π 6 ( 17 17 − 5 5 ) π 6 ( 17 17 − 5 5 )$

171.

$13 13 − 8 27 13 13 − 8 27$

173.

$4 3 4 3$

175.

$2.0035 2.0035$

177.

$123 32 123 32$

179.

$10 10$

181.

$20 3 20 3$

183.

$1 675 ( 229 229 − 8 ) 1 675 ( 229 229 − 8 )$

185.

$1 8 ( 4 5 + ln ( 9 + 4 5 ) ) 1 8 ( 4 5 + ln ( 9 + 4 5 ) )$

187.

$1.201 1.201$

189.

$15.2341 15.2341$

191.

$49 π 3 49 π 3$

193.

$70 π 2 70 π 2$

195.

$8 π 8 π$

197.

$120 π 26 120 π 26$

199.

$π 6 ( 17 17 − 1 ) π 6 ( 17 17 − 1 )$

201.

$9 2 π 9 2 π$

203.

$10 10 π 27 ( 73 73 − 1 ) 10 10 π 27 ( 73 73 − 1 )$

205.

$25.645 25.645$

207.

$π ( π + 2 ) π ( π + 2 )$

209.

$10.5017 10.5017$

211.

$2323$ ft

213.

$2 2$

215.

217.

Section 6.5 Exercises

219.

$150150$ ft-lb

221.

$200 J 200 J$

223.

$11$ J

225.

$39 2 39 2$

227.

$ln ( 243 ) ln ( 243 )$

229.

$332 π 15 332 π 15$

231.

$100 π 100 π$

233.

$20 π 15 20 π 15$

235.

$66$ J

237.

$55$ cm

239.

$3636$ J

241.

$18,75018,750$ ft-lb

243.

Weight $=323×109lb=323×109lb$

Work $=43×1012ft-lb=43×1012ft-lb$

245.

$9.71 × 10 2 N m 9.71 × 10 2 N m$

247.

a. $3,000,0003,000,000$ lb, b. $750,000750,000$ lbs

249.

$23.25π23.25π$ million ft-lb

251.

$A ρ H 2 2 A ρ H 2 2$

253.

Section 6.6 Exercises

255.

$5 4 5 4$

257.

$( 2 3 , 2 3 ) ( 2 3 , 2 3 )$

259.

$( 7 4 , 3 2 ) ( 7 4 , 3 2 )$

261.

$3 L 4 3 L 4$

263.

$π 2 π 2$

265.

$e 2 + 1 e 2 − 1 e 2 + 1 e 2 − 1$

267.

$π 2 − 4 π π 2 − 4 π$

269.

$1 4 ( 1 + e 2 ) 1 4 ( 1 + e 2 )$

271.

$( a 3 , b 3 ) ( a 3 , b 3 )$

273.

$( 0 , π 8 ) ( 0 , π 8 )$

275.

$( 0 , 3 ) ( 0 , 3 )$

277.

$( 0 , 4 π ) ( 0 , 4 π )$

279.

$( 5 8 , 1 3 ) ( 5 8 , 1 3 )$

281.

$2 m π 3 2 m π 3$

283.

$π a 2 b π a 2 b$

285.

$( 4 3 π , 4 3 π ) ( 4 3 π , 4 3 π )$

287.

$( 1 2 , 2 5 ) ( 1 2 , 2 5 )$

289.

$( 0 , 28 9 π ) ( 0 , 28 9 π )$

291.

Center of mass: $(a6,4a25),(a6,4a25),$ volume: $2πa492πa49$

293.

Volume: $2π2a2(b+a)2π2a2(b+a)$

Section 6.7 Exercises

295.

$1 x 1 x$

297.

$− 1 x ( ln x ) 2 − 1 x ( ln x ) 2$

299.

$ln ( x + 1 ) + C ln ( x + 1 ) + C$

301.

$ln ( x ) + 1 ln ( x ) + 1$

303.

$cot ( x ) cot ( x )$

305.

$7 x 7 x$

307.

$csc ( x ) sec x csc ( x ) sec x$

309.

$−2 tan x −2 tan x$

311.

$1 2 ln ( 5 3 ) 1 2 ln ( 5 3 )$

313.

$2 − 1 2 ln ( 5 ) 2 − 1 2 ln ( 5 )$

315.

$1 ln ( 2 ) − 1 1 ln ( 2 ) − 1$

317.

$1 2 ln ( 2 ) 1 2 ln ( 2 )$

319.

$1 3 ( ln x ) 3 1 3 ( ln x ) 3$

321.

$2 x 3 x 2 + 1 x 2 − 1 2 x 3 x 2 + 1 x 2 − 1$

323.

$x −2 − ( 1 / x ) ( ln x − 1 ) x −2 − ( 1 / x ) ( ln x − 1 )$

325.

$e x e − 1 e x e − 1$

327.

$1 1$

329.

$− 1 x 2 − 1 x 2$

331.

$π − ln ( 2 ) π − ln ( 2 )$

333.

$1 x 1 x$

335.

$e 5 − 6 units 2 e 5 − 6 units 2$

337.

$ln ( 4 ) − 1 units 2 ln ( 4 ) − 1 units 2$

339.

$2.8656 2.8656$

341.

$3.1502 3.1502$

Section 6.8 Exercises

349.

True

351.

False; $k=ln(2)tk=ln(2)t$

353.

$2020$ hours

355.

No. The relic is approximately $871871$ years old.

357.

$71.9271.92$ years

359.

$55$ days $66$ hours $2727$ minutes

361.

$12 12$

363.

$8.618 % 8.618 %$

365.

$6766.76 6766.76$

367.

$99$ hours $1313$ minutes

369.

$239,179239,179$ years

371.

$P′(t)=43e0.01604t.P′(t)=43e0.01604t.$ The population is always increasing.

373.

The population reaches $1010$ billion people in $2027.2027.$

375.

$P′(t)=2.259e0.06407t.P′(t)=2.259e0.06407t.$ The population is always increasing.

Section 6.9 Exercises

377.

$e x and e − x e x and e − x$

379.

381.

383.

385.

$3 sinh ( 3 x + 1 ) 3 sinh ( 3 x + 1 )$

387.

$− tanh ( x ) sech ( x ) − tanh ( x ) sech ( x )$

389.

$4 cosh ( x ) sinh ( x ) 4 cosh ( x ) sinh ( x )$

391.

$x sech 2 ( x 2 + 1 ) x 2 + 1 x sech 2 ( x 2 + 1 ) x 2 + 1$

393.

$6 sinh 5 ( x ) cosh ( x ) 6 sinh 5 ( x ) cosh ( x )$

395.

$1 2 sinh ( 2 x + 1 ) + C 1 2 sinh ( 2 x + 1 ) + C$

397.

$1 2 sinh 2 ( x 2 ) + C 1 2 sinh 2 ( x 2 ) + C$

399.

$1 3 cosh 3 ( x ) + C 1 3 cosh 3 ( x ) + C$

401.

$ln ( 1 + cosh ( x ) ) + C ln ( 1 + cosh ( x ) ) + C$

403.

$cosh ( x ) + sinh ( x ) + C cosh ( x ) + sinh ( x ) + C$

405.

$4 1 − 16 x 2 4 1 − 16 x 2$

407.

$sinh ( x ) cosh 2 ( x ) + 1 sinh ( x ) cosh 2 ( x ) + 1$

409.

$− csc ( x ) − csc ( x )$

411.

$− 1 ( x 2 − 1 ) tanh −1 ( x ) − 1 ( x 2 − 1 ) tanh −1 ( x )$

413.

$1 a tanh −1 ( x a ) + C 1 a tanh −1 ( x a ) + C$

415.

$x 2 + 1 + C x 2 + 1 + C$

417.

$cosh −1 ( e x ) + C cosh −1 ( e x ) + C$

419.

421.

$37.30 37.30$

423.

$y = 1 c cosh ( c x ) y = 1 c cosh ( c x )$

425.

$−0.521095 −0.521095$

427.

$10 10$

Review Exercises

435.

False

437.

False

439.

441.

$162 π 5 162 π 5$

443.

a. $4,4,$ b. $128π7,128π7,$ c. $64π564π5$

445.

a. $1.949,1.949,$ b. $21.952,21.952,$ c. $17.09917.099$

447.

a. $316,316,$ b. $452π15,452π15,$ c. $31π631π6$

449.

$245.282 245.282$

451.

Mass: $12,12,$ center of mass: $(1835,922)(1835,922)$

453.

$17 + 1 8 ln ( 33 + 8 17 ) 17 + 1 8 ln ( 33 + 8 17 )$

455.

Volume: $3π4,3π4,$ surface area: $π(2−sinh−1(1)+sinh−1(16)−25716)π(2−sinh−1(1)+sinh−1(16)−25716)$

457.

11:02 a.m.

459.

$π ( 1 + sinh ( 1 ) cosh ( 1 ) ) π ( 1 + sinh ( 1 ) cosh ( 1 ) )$

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The text passage appears to be a collection of answers to various calculus problems, likely from a textbook or solution manual. Each problem is numbered and the answer is provided, but the questions themselves are not included in the text.

TYPE: MULTIPLE_QUESTIONS_WITH_ANSWERS

The passage contains multiple answers to mathematical questions, but does not include the questions themselves. Each answer is associated with a specific problem number (e.g., 6.1, 6.2, etc.). The answers cover a range of calculus topics, including integrals, derivatives, volumes, arc lengths, and applications of calculus to real-world problems.