# Physics lab 3 - Objective The kinematics of projectile...

• Lab Report
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Objective: The kinematics of projectile motion in the Earth’s gravitational field will be studied to gain an understanding of horizontal range, maximum height range, time of flight, and trajectory of the projectile. Introduction This lab studies the motion of a projectile in two dimensions. The gravitational force acts only in the vertical direction in projectile motion, thus the motion is broken into its vertical behavior and its horizontal behavior which exhibits no force and acts independently of the vertical motion. These two independent motions give rise to position as a function of time in component for (x,y), to velocity as a function of time in component form (ax,ay). When time is eliminated between the x and y equations, the trajectory or equation of the path of the projectile is obtained. In order to determine the motion the initial velocity and launch angle of the projectile are used. The range of the projectile, the maximum height of the projectile above the launch point,

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the time of flight of the projectile, and the path (trajectory) that the projectile describes will all be measured in this lab. These will be studied as a function of the launch angle. dv x dt = a x = 0 The projectile is launched with an initial velocity at an angle ( θ ), and that velocity, in the x direction, does not accelerate because there is no outside force acting on it in the horizontal. dx dt = v x = constant = v o cos θ The velocity in the x direction ( v x ¿ is equal to the initial velocity multiplied by the cos θ at which it was launched. θ represents the launch angle. x =( v o cos θ ) t …….…………………..1) The x motion of a projectile is found by taking the velocity in the x direction ( v o cos θ ) and multiplying it by the time of flight (t), in other words, the time that the projectile is in the air. dv y dt = a y =− g The only force acting on the projectile in the y direction is gravity, which is negative because it’s acting downward. dy dt = v y = v o sin θ ¿ The velocity in the y direction is equal to initial vertical velocity ( v o sin θ ) subtracted by gravity (g) multiplied by the time of flight (t). y = ( v o sin θ ) t gt 2 2 ………………….2) To find the y motion of the projectile travels (y), use the second kinematic equation and replace v o with v o sin θ which is the initial vertical velocity. y = x tan θ ( gx 2 ) 2 ( v o cos θ ) 2 ……….……...3) The trajectory of the projectile (y) is achieved by combining equations 1 & 2. The trajectory is a combination of the x and y motions of the projectile.
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The text passage is a physics lab report introduction that discusses the kinematics of projectile motion, including the equations for horizontal and vertical components of motion, and the trajectory of the projectile. It does not contain any specific mathematical questions or answers to such questions.
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TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
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# Physics lab 3 - Objective The kinematics of projectile...

• Lab Report
• 8
• 67% (3) 2 out of 3 people found this document helpful

This preview shows pages 1–3. Sign up to view the full content.

Objective: The kinematics of projectile motion in the Earth’s gravitational field will be studied to gain an understanding of horizontal range, maximum height range, time of flight, and trajectory of the projectile. Introduction This lab studies the motion of a projectile in two dimensions. The gravitational force acts only in the vertical direction in projectile motion, thus the motion is broken into its vertical behavior and its horizontal behavior which exhibits no force and acts independently of the vertical motion. These two independent motions give rise to position as a function of time in component for (x,y), to velocity as a function of time in component form (ax,ay). When time is eliminated between the x and y equations, the trajectory or equation of the path of the projectile is obtained. In order to determine the motion the initial velocity and launch angle of the projectile are used. The range of the projectile, the maximum height of the projectile above the launch point,

This preview has intentionally blurred sections. Sign up to view the full version.

the time of flight of the projectile, and the path (trajectory) that the projectile describes will all be measured in this lab. These will be studied as a function of the launch angle. dv x dt = a x = 0 The projectile is launched with an initial velocity at an angle ( θ ), and that velocity, in the x direction, does not accelerate because there is no outside force acting on it in the horizontal. dx dt = v x = constant = v o cos θ The velocity in the x direction ( v x ¿ is equal to the initial velocity multiplied by the cos θ at which it was launched. θ represents the launch angle. x =( v o cos θ ) t …….…………………..1) The x motion of a projectile is found by taking the velocity in the x direction ( v o cos θ ) and multiplying it by the time of flight (t), in other words, the time that the projectile is in the air. dv y dt = a y =− g The only force acting on the projectile in the y direction is gravity, which is negative because it’s acting downward. dy dt = v y = v o sin θ ¿ The velocity in the y direction is equal to initial vertical velocity ( v o sin θ ) subtracted by gravity (g) multiplied by the time of flight (t). y = ( v o sin θ ) t gt 2 2 ………………….2) To find the y motion of the projectile travels (y), use the second kinematic equation and replace v o with v o sin θ which is the initial vertical velocity. y = x tan θ ( gx 2 ) 2 ( v o cos θ ) 2 ……….……...3) The trajectory of the projectile (y) is achieved by combining equations 1 & 2. The trajectory is a combination of the x and y motions of the projectile.
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### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern
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The text passage is a physics lab report introduction that discusses the kinematics of projectile motion, including the equations for horizontal and vertical components of motion, and the trajectory of the projectile. It does not contain any specific mathematical questions or answers to such questions.

TYPE: NO_QUESTION