## Algebra 1

Solution:($\frac{7}{10}$,$\frac{-4}{5}$)
Given: 4x+y=2 and 3y+2x=-1 3(4x+y=2)=12x+3y=6 (12x+3y)-(3y+2x)=6-(-1) (Subtract two equations) 12x+3y-3y-2x=7 (Simplify) 12x-2x=7 (Simplify) 10x=7 x=$\frac{7}{10}$ (Divide both sides by 10) Plug in value of x: 4($\frac{7}{10}$)+y=2 =>$\frac{14}{5}$+y=2 => y=2-$\frac{14}{5}$=>y=$\frac{-4}{5}$ Solution ($\frac{7}{10}$,$\frac{-4}{5}$)
The text passage contains a system of linear equations and a detailed step-by-step solution to find the values of x and y. The solution is provided at the beginning and confirmed at the end.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
## Algebra 1

Solution:($\frac{7}{10}$,$\frac{-4}{5}$)
Given: 4x+y=2 and 3y+2x=-1 3(4x+y=2)=12x+3y=6 (12x+3y)-(3y+2x)=6-(-1) (Subtract two equations) 12x+3y-3y-2x=7 (Simplify) 12x-2x=7 (Simplify) 10x=7 x=$\frac{7}{10}$ (Divide both sides by 10) Plug in value of x: 4($\frac{7}{10}$)+y=2 =>$\frac{14}{5}$+y=2 => y=2-$\frac{14}{5}$=>y=$\frac{-4}{5}$ Solution ($\frac{7}{10}$,$\frac{-4}{5}$)
user
The text passage contains a system of linear equations and a detailed step-by-step solution to find the values of x and y. The solution is provided at the beginning and confirmed at the end.

TYPE: SINGLE_QUESTION_WITH_ANSWER