## College Algebra (6th Edition)

a. 0 b. $\{ 4 \}$
$\frac{x-2}{2x} + 1 = \frac{x+1}{x}$ a. $x =0$ makes the denominator zero. So, $x \ne 0.$ b. $\frac{x-2}{2x} + 1 = \frac{x+1}{x} ; x \ne 0;$ $\frac{x-2+2x}{2x} = \frac{x+1}{x} ; x \ne 0;$ $\frac{3x-2}{2x} = \frac{x+1}{x} ; x \ne 0;$ Multiply both sides by $2x$. $2x(\frac{3x-2}{2x} ) =2x( \frac{x+1}{x} ); x \ne 0;$ $3x-2 = 2(x+1)$ $3x-2 = 2x+2$ $3x-2x = 2+2$ $x = 4$ $4$ is not the restricted value. So, Solution set $:\{ 4 \}$
The text passage contains a mathematical equation and its solution, including the steps to solve the equation and the final solution set.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
## College Algebra (6th Edition)

a. 0 b. $\{ 4 \}$
$\frac{x-2}{2x} + 1 = \frac{x+1}{x}$ a. $x =0$ makes the denominator zero. So, $x \ne 0.$ b. $\frac{x-2}{2x} + 1 = \frac{x+1}{x} ; x \ne 0;$ $\frac{x-2+2x}{2x} = \frac{x+1}{x} ; x \ne 0;$ $\frac{3x-2}{2x} = \frac{x+1}{x} ; x \ne 0;$ Multiply both sides by $2x$. $2x(\frac{3x-2}{2x} ) =2x( \frac{x+1}{x} ); x \ne 0;$ $3x-2 = 2(x+1)$ $3x-2 = 2x+2$ $3x-2x = 2+2$ $x = 4$ $4$ is not the restricted value. So, Solution set $:\{ 4 \}$
user
The text passage contains a mathematical equation and its solution, including the steps to solve the equation and the final solution set.

TYPE: SINGLE_QUESTION_WITH_ANSWER