The chickens at Colonel Thompson's Ranch have a mean weight of 1850g, with a standard deviation of 150g

The chickens at Colonel Thompson's Ranch have a mean weight of 1850g, with a standard deviation of 150g

215 points

The chickens at Colonel Thompson's Ranch have a mean weight of 1850 g, with a standard deviation of 150 g. The weights of the chickens are closely approximated by a normal curve. Find the percent of all chickens having weights between 1606 g and 2288 g.

The chickens
homework

S
9.9k points

Our goal is to find all chickens having weights between 1606g and 2288g. To do this we start by finding the z-scores for the separate weights with $\mu = 1850$, and $\sigma = 150$. The equation for the z-score is,

$$z = \frac{x-\mu}{\sigma}$$

for the first weight of 1606g I get,

$$z = \frac{1606-1850}{150}\approx -1.63$$

and for the second weight of 2288g I get,

$$z = \frac{2288-1850}{150}\approx 2.92$$

so we are looking for the area under the normal curve for

this can be found by using the standard normal table. The area to the left of z = 2.92 is 0.9982. The area to the left of z = -1.63 is 0.0516. To get the area under the curve we take,

A = 0.9982 - 0.0516 = 0.9466

or 94.66% of all chickens have weights between 1606g and 2288g.

T
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Excerpt from file: BUS520Assignment3:Motivation,Stress,andCommunication DueWeek6andworth200points Researchacompanyatwhichyouwouldliketowork(notyourcurrentemployer)andwriteasix toeight(68)pagepaperinwhichyou: 1.Createabriefjobdescriptionforapositionwithinthecompanyyouresearchthatyouwould liketofill....

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The text passage contains a mathematical question about finding the percentage of chickens with weights between 1606g and 2288g, and it also provides a detailed solution to this problem.
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The chickens at Colonel Thompson's Ranch have a mean weight of 1850g, with a standard deviation of 150g

The chickens at Colonel Thompson's Ranch have a mean weight of 1850g, with a standard deviation of 150g

215 points

The chickens at Colonel Thompson's Ranch have a mean weight of 1850 g, with a standard deviation of 150 g. The weights of the chickens are closely approximated by a normal curve. Find the percent of all chickens having weights between 1606 g and 2288 g.

The chickens
homework

S
9.9k points

Our goal is to find all chickens having weights between 1606g and 2288g. To do this we start by finding the z-scores for the separate weights with $\mu = 1850$, and $\sigma = 150$. The equation for the z-score is,

$$z = \frac{x-\mu}{\sigma}$$

for the first weight of 1606g I get,

$$z = \frac{1606-1850}{150}\approx -1.63$$

and for the second weight of 2288g I get,

$$z = \frac{2288-1850}{150}\approx 2.92$$

so we are looking for the area under the normal curve for

this can be found by using the standard normal table. The area to the left of z = 2.92 is 0.9982. The area to the left of z = -1.63 is 0.0516. To get the area under the curve we take,

A = 0.9982 - 0.0516 = 0.9466

or 94.66% of all chickens have weights between 1606g and 2288g.

T
0 points

Oh Snap! This Answer is Locked

Thumbnail of first page

Excerpt from file: BUS520Assignment3:Motivation,Stress,andCommunication DueWeek6andworth200points Researchacompanyatwhichyouwouldliketowork(notyourcurrentemployer)andwriteasix toeight(68)pagepaperinwhichyou: 1.Createabriefjobdescriptionforapositionwithinthecompanyyouresearchthatyouwould liketofill....

Filename: BUS 520 Assignment 3 Motivation, Stress, and Communication.docx

Filesize: < 2 MB

Print Length: 9 Pages/Slides

Words: 189

Surround your text in *italics* or **bold**, to write a math equation use, for example, $x^2+2x+1=0$ or $$\beta^2-1=0$$

Use LaTeX to type formulas and markdown to format text. See example.
user
The text passage contains a mathematical question about finding the percentage of chickens with weights between 1606g and 2288g, and it also provides a detailed solution to this problem.

TYPE: SINGLE_QUESTION_WITH_ANSWER