## Question

Secondary 1 | Maths

Anyone can contribute an answer, even non-tutors.

##### Megan

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It would be great if you could solve and explain the question to me.

Date Posted: 1 year ago
Views: 124
Eric Nicholas K
1 year ago
Replacing a by 1/2,
1/a = 1 divided by a = 1 divided by 1/2 = 1 x 2 = 2.

Replacing b by 1/4,
1/b = 1 divided by b = 1 divided by 1/4 = 1 x 4 = 4.

Replacing d by -1/5,
1/d = 1 divided by d = 1 divided by (-1/5) = 1 x (-5) = -5.

Now, 1/a - 1/b = 1/c + 1/d.

But 1/a = 2, 1/b = 4 and 1/d = -5.

So, 2 - 4 = 1/c - 5
1/c = 2 - 4 + 5 = 3
1/c = 3
1 = 3c
c = 1/3
The text contains a mathematical question and its solution, where the problem involves solving for the value of 'c' given the values of 'a', 'b', and 'd'.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
## Question

Secondary 1 | Maths

Anyone can contribute an answer, even non-tutors.

##### Megan

chevron_right chevron_right

It would be great if you could solve and explain the question to me.

Date Posted: 1 year ago
Views: 124
Eric Nicholas K
1 year ago
Replacing a by 1/2,
1/a = 1 divided by a = 1 divided by 1/2 = 1 x 2 = 2.

Replacing b by 1/4,
1/b = 1 divided by b = 1 divided by 1/4 = 1 x 4 = 4.

Replacing d by -1/5,
1/d = 1 divided by d = 1 divided by (-1/5) = 1 x (-5) = -5.

Now, 1/a - 1/b = 1/c + 1/d.

But 1/a = 2, 1/b = 4 and 1/d = -5.

So, 2 - 4 = 1/c - 5
1/c = 2 - 4 + 5 = 3
1/c = 3
1 = 3c
c = 1/3
user
The text contains a mathematical question and its solution, where the problem involves solving for the value of 'c' given the values of 'a', 'b', and 'd'.

TYPE: SINGLE_QUESTION_WITH_ANSWER