# Simon is making wreaths to sell .he has 60 bows, 36 silk roses and 48 silk carnation .he wantsto put the same numbers of items on each wreath all the items on a wreath Will be the same type . how many items can Simon pun on each wreath?

1
by JosefaOseguera
Comment has been deleted

2015-01-01T03:21:25-05:00

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We must assume that he must put a whole number of objects in each wreath so we must find the greatest common factor

60=2 time 2 times 3 times 5
36=2 times 2 times 3 times 3
48=2 times 2 times 2 times 2 times 3

the factors are 2 times 2 times 3 or 12
there can be 12 wreath max
we total them up and divide by 12
60+36+48=144
144/12=12
12 items per wreath
The text passage contains a word problem about Simon making wreaths with a specific number of items, and it also provides a detailed solution to the problem.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
# Simon is making wreaths to sell .he has 60 bows, 36 silk roses and 48 silk carnation .he wantsto put the same numbers of items on each wreath all the items on a wreath Will be the same type . how many items can Simon pun on each wreath?

1
by JosefaOseguera
Comment has been deleted

2015-01-01T03:21:25-05:00

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
We must assume that he must put a whole number of objects in each wreath so we must find the greatest common factor

60=2 time 2 times 3 times 5
36=2 times 2 times 3 times 3
48=2 times 2 times 2 times 2 times 3

the factors are 2 times 2 times 3 or 12
there can be 12 wreath max
we total them up and divide by 12
60+36+48=144
144/12=12
12 items per wreath
user
The text passage contains a word problem about Simon making wreaths with a specific number of items, and it also provides a detailed solution to the problem.

TYPE: SINGLE_QUESTION_WITH_ANSWER