Homework Help

# the square root of 243x^13

schooledmom | Salutatorian

Posted June 20, 2013 at 1:56 PM via web

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the square root of 243x^13

Tagged with algebra 1, math

llltkl | College Teacher | Valedictorian

Posted June 20, 2013 at 2:34 PM (Answer #1)

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`sqrt (243x^13)=(243x^13)^(1/2)` (by changing the radical form into exponent form)

`=(243)^(1/2)*(x^13)^(1/2)`  (applying `(xy)^m=x^m*y^m` )

`=(243)^(1/2)*x^(13/2)`  (applying `(x^m)^n = x^(mn)` )

`=(3*3*3*3*3)^(1/2) *(x^(13/2))`

= `3^(5/2)*x^(13/2)`

=`9sqrt3*x^6sqrtx ` (expressing in the radical form again)
The text passage contains a mathematical question about finding the square root of an algebraic expression, and a detailed answer is provided.
single_question_with_answer
Given a text passage, determine:
    1. If it contains a mathematical question (including word problems or calculations)
    2. If an answer to that mathematical question is provided in the text

First, describe the content structure you found in 1-2 sentences.

Then provide your analysis in the following format:
TYPE: <one of the following values>
- NO_QUESTION
- SINGLE_QUESTION
- SINGLE_QUESTION_WITH_ANSWER
- MULTIPLE_QUESTIONS
- MULTIPLE_QUESTIONS_WITH_ANSWERS
system
Homework Help

# the square root of 243x^13

schooledmom | Salutatorian

Posted June 20, 2013 at 1:56 PM via web

dislike 1 like

the square root of 243x^13

Tagged with algebra 1, math

llltkl | College Teacher | Valedictorian

Posted June 20, 2013 at 2:34 PM (Answer #1)

dislike 1 like

`sqrt (243x^13)=(243x^13)^(1/2)` (by changing the radical form into exponent form)

`=(243)^(1/2)*(x^13)^(1/2)`  (applying `(xy)^m=x^m*y^m` )

`=(243)^(1/2)*x^(13/2)`  (applying `(x^m)^n = x^(mn)` )

`=(3*3*3*3*3)^(1/2) *(x^(13/2))`

= `3^(5/2)*x^(13/2)`

=`9sqrt3*x^6sqrtx ` (expressing in the radical form again)
user
The text passage contains a mathematical question about finding the square root of an algebraic expression, and a detailed answer is provided.

TYPE: SINGLE_QUESTION_WITH_ANSWER