Pre-Calculus Homework Solutions 123

Pre-Calculus Homework Solutions 123 - CEB 6. SAS 7. A w E w...

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125 Chapter 5 29. m 5 } ( ( y x 2 2 2 2 y x 1 1 ) ) } 5 } 7 0 2 2 3 3 } or 2 } 4 3 } 30. No, R w X w is not an altitude of n RST .The slope of S w T w is 1. The product of the slopes of S w T w and R w X w is 2 } 4 3 } , not 2 1. Thus, the segments are not perpendicular. 31. Given: C w A w > C w B w , A w D w > B w D w Prove: C and D are on the perpendicular bisector of A w B w . Proof: 32. Given: / BAC , P is in the interior of / BAC , PD 5 PE Prove: AP #\$ is the angle bisector of / BAC Proof: A B D P E C C D E B A y x ( 2 1, 6) (3, 3) R S (1, 8) T y x ( 2 1, 6) (3, 3) R S (1, 8) T Statements Reasons 1. / BAC , P is in the interior of / BAC , PD 5 PE 1. Given 2. P w D w > P w E w 2. Def. of > 3. P w D w ' A w B w , P w E w ' A w C w 3. Distance from a point to a line is measured along ' segment from the point to the line. 4. / ADP and / AEP are rt. ? 4. Def. of ' 5. n ADP and n AEP are rt. n s 5. Def. of rt. n 6. A w P w > A w P w 6. Reflexive Property 7. n ADP > n AEP 7. HL 8. / DAP > / EAP 8. CPCTC 9. AP #\$ is the angle bisector of / BAC 9. Def. of / bisector Statements Reasons 1. C w A w > C w B w , A w D w > B w D w 1. Given 2. C w D w > C w D w 2. Reflexive Property 3. n ACD > n BCD 3. SSS 4. / ACD > / BCD 4. CPCTC 5. C w E w > C w E w 5. Reflexive Property 6. n CEA > n
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Unformatted text preview: CEB 6. SAS 7. A w E w > B w E w 7. CPCTC 8. E is the midpoint of A w B w . 8. Def. of midpoint 9. / CEA > / CEB 9. CPCTC 10. / CEA and / CEB form a linear pair. 10. Def. of linear pair 11. / CEA and / CEB are supplementary. 11. Supplement Theorem 12. m / CEA 1 m / CEB 5 180 12. Def. of suppl. ? 13. m / CEA 1 m / CEA 5 180 13. Substitution 14. 2( m / CEA ) 5 180 14. Substitution 15. m / CEA 5 90 15. Division Property 16. / CEA and / CEB are rt. ? . 16. Def. of rt. / 17. C w D w ' A w B w 17. Def. of ' 18. C w D w is the perpendicular bisector of A w B w . 18. Def. of ' bisector 19. C and D are on the perpendicular bisector of A w B w . 19. Def. of points on a line...
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This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.

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Pre-Calculus Homework Solutions 123

Pre-Calculus Homework Solutions 123 - CEB 6. SAS 7. A w E w...

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125 Chapter 5 29. m 5 } ( ( y x 2 2 2 2 y x 1 1 ) ) } 5 } 7 0 2 2 3 3 } or 2 } 4 3 } 30. No, R w X w is not an altitude of n RST .The slope of S w T w is 1. The product of the slopes of S w T w and R w X w is 2 } 4 3 } , not 2 1. Thus, the segments are not perpendicular. 31. Given: C w A w > C w B w , A w D w > B w D w Prove: C and D are on the perpendicular bisector of A w B w . Proof: 32. Given: / BAC , P is in the interior of / BAC , PD 5 PE Prove: AP #\$ is the angle bisector of / BAC Proof: A B D P E C C D E B A y x ( 2 1, 6) (3, 3) R S (1, 8) T y x ( 2 1, 6) (3, 3) R S (1, 8) T Statements Reasons 1. / BAC , P is in the interior of / BAC , PD 5 PE 1. Given 2. P w D w > P w E w 2. Def. of > 3. P w D w ' A w B w , P w E w ' A w C w 3. Distance from a point to a line is measured along ' segment from the point to the line. 4. / ADP and / AEP are rt. ? 4. Def. of ' 5. n ADP and n AEP are rt. n s 5. Def. of rt. n 6. A w P w > A w P w 6. Reflexive Property 7. n ADP > n AEP 7. HL 8. / DAP > / EAP 8. CPCTC 9. AP #\$ is the angle bisector of / BAC 9. Def. of / bisector Statements Reasons 1. C w A w > C w B w , A w D w > B w D w 1. Given 2. C w D w > C w D w 2. Reflexive Property 3. n ACD > n BCD 3. SSS 4. / ACD > / BCD 4. CPCTC 5. C w E w > C w E w 5. Reflexive Property 6. n CEA > n
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Unformatted text preview: CEB 6. SAS 7. A w E w > B w E w 7. CPCTC 8. E is the midpoint of A w B w . 8. Def. of midpoint 9. / CEA > / CEB 9. CPCTC 10. / CEA and / CEB form a linear pair. 10. Def. of linear pair 11. / CEA and / CEB are supplementary. 11. Supplement Theorem 12. m / CEA 1 m / CEB 5 180 12. Def. of suppl. ? 13. m / CEA 1 m / CEA 5 180 13. Substitution 14. 2( m / CEA ) 5 180 14. Substitution 15. m / CEA 5 90 15. Division Property 16. / CEA and / CEB are rt. ? . 16. Def. of rt. / 17. C w D w ' A w B w 17. Def. of ' 18. C w D w is the perpendicular bisector of A w B w . 18. Def. of ' bisector 19. C and D are on the perpendicular bisector of A w B w . 19. Def. of points on a line...
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This note was uploaded on 12/19/2011 for the course MAC 1140 taught by Professor Dr.zhan during the Fall '10 term at UNF.

Ask a homework question - tutors are online
user
The text appears to be a snippet from a Pre-Calculus homework solution set, containing geometric proofs and explanations.

TYPE: NO_QUESTION

The text does not contain any explicit mathematical questions that require solving. Instead, it provides solutions and explanations for geometric proofs and concepts. There are no unanswered mathematical questions present in the text.