Pre-Calc Exam Notes 16

# Pre-Calc Exam Notes 16 - 16 Chapter 1 Right Triangle...

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16 Chapter 1 Right Triangle Trigonometry §1.3 Example 1.15 O A B α As another application of trigonometry to astronomy, we will Fnd the distance from the earth to the sun. Let O be the center of the earth, let A be a point on the equator, and let B represent an object (e.g. a star) in space, as in the picture on the right. If the earth is positioned in such a way that the angle OAB = 90 , then we say that the angle α = OBA is the equatorial parallax of the object. The equatorial parallax of the sun has been observed to be ap- proximately α = 0.00244 . Use this to estimate the distance from the center of the earth to the sun. Solution: Let B be the position of the sun. We want to Fnd the length of OB . We will use the actual radius of the earth, mentioned at the end of Example 1.14, to get OA = 3956.6 miles. Since OAB = 90 , we have OA OB = sin α OB = OA sin α = 3956.6 sin 0.00244 = 92908394 , so the distance from the center of the earth to the sun is approximately 93 million miles
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The text passage contains an example problem from a pre-calculus exam, specifically dealing with the application of trigonometry to estimate the distance from the earth to the sun using the concept of equatorial parallax.
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Pre-Calc Exam Notes 16

# Pre-Calc Exam Notes 16 - 16 Chapter 1 Right Triangle...

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16 Chapter 1 Right Triangle Trigonometry §1.3 Example 1.15 O A B α As another application of trigonometry to astronomy, we will Fnd the distance from the earth to the sun. Let O be the center of the earth, let A be a point on the equator, and let B represent an object (e.g. a star) in space, as in the picture on the right. If the earth is positioned in such a way that the angle OAB = 90 , then we say that the angle α = OBA is the equatorial parallax of the object. The equatorial parallax of the sun has been observed to be ap- proximately α = 0.00244 . Use this to estimate the distance from the center of the earth to the sun. Solution: Let B be the position of the sun. We want to Fnd the length of OB . We will use the actual radius of the earth, mentioned at the end of Example 1.14, to get OA = 3956.6 miles. Since OAB = 90 , we have OA OB = sin α OB = OA sin α = 3956.6 sin 0.00244 = 92908394 , so the distance from the center of the earth to the sun is approximately 93 million miles
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The text passage contains an example problem from a pre-calculus exam, specifically dealing with the application of trigonometry to estimate the distance from the earth to the sun using the concept of equatorial parallax.

TYPE: SINGLE_QUESTION_WITH_ANSWER