the fact that the irregular does not occur if the perpendicularness happens is not right.
sent1: the checkering or the isothermicness or both happens. sent2: both the tooling kipper and the effort happens. sent3: the perpendicularness does not occur if the checkers occurs or the isothermicness does not occur or both. sent4: that the effort happens is right. sent5: that both the foliaceousness and the tooling kipper occurs yields that the isothermicness does not occur. sent6: if the fact that the irregular occurs is right the foliaceousness happens.
void -> assump1: Let's assume that the irregular occurs.; sent6 & assump1 -> int1: the foliaceousness happens.; sent2 -> int2: the tooling kipper occurs.; int1 & int2 -> int3: the foliaceousness and the tooling kipper occurs.; int3 & sent5 -> int4: the isothermicness does not occur.; int4 -> int5: the checkering occurs and/or the isothermicness does not occur.; int5 & sent3 -> int6: the perpendicular does not occur.; void -> assump2: Let's assume that the perpendicular happens.; int6 & assump2 -> int7: this is contradiction.; [assump1] & int7 -> int8: the irregularness does not occur.; [assump2] & int8 -> hypothesis;
$hypothesis$ = the fact that the irregular does not occur if the perpendicularness happens is not right. ; $context$ = sent1: the checkering or the isothermicness or both happens. sent2: both the tooling kipper and the effort happens. sent3: the perpendicularness does not occur if the checkers occurs or the isothermicness does not occur or both. sent4: that the effort happens is right. sent5: that both the foliaceousness and the tooling kipper occurs yields that the isothermicness does not occur. sent6: if the fact that the irregular occurs is right the foliaceousness happens. ; $proof$ = 
void -> assump1: Let's assume that the irregular occurs.; sent6 & assump1 -> int1: the foliaceousness happens.; sent2 -> int2: the tooling kipper occurs.; int1 & int2 -> int3: the foliaceousness and the tooling kipper occurs.; int3 & sent5 -> int4: the isothermicness does not occur.; int4 -> int5: the checkering occurs and/or the isothermicness does not occur.; int5 & sent3 -> int6: the perpendicular does not occur.; void -> assump2: Let's assume that the perpendicular happens.; int6 & assump2 -> int7: this is contradiction.; [assump1] & int7 -> int8: the irregularness does not occur.; [assump2] & int8 -> hypothesis; __DISPROVED__