the stake is brunet.
sent1: the XY is meatless if there is something such that that it does not mistake noun and it is not a linstock is wrong. sent2: the blastema is not a feather if the XY is meatless and it troops mamma. sent3: The mamma troops XY. sent4: the blastema is a feather. sent5: the XY troops mamma. sent6: if the internode does not mistake noun it is not non-intramolecular. sent7: that the stake is a kind of a brunet hold if the internode is intramolecular.
void -> assump1: Let's assume that that the internode does not mistake noun and it is not a kind of a linstock does not hold.; assump1 -> int1: there exists something such that the fact that it does not mistake noun and is not a linstock is wrong.; int1 & sent1 -> int2: the XY is meatless.; int2 & sent5 -> int3: the XY is meatless thing that does troop mamma.; int3 & sent2 -> int4: the blastema is not a kind of a feather.; int4 & sent4 -> int5: this is contradiction.; [assump1] & int5 -> int6: the internode does not mistake noun and is not a linstock.; int6 -> int7: the internode does not mistake noun.; int7 & sent6 -> int8: the internode is intramolecular.; int8 & sent7 -> hypothesis;
$hypothesis$ = the stake is brunet. ; $context$ = sent1: the XY is meatless if there is something such that that it does not mistake noun and it is not a linstock is wrong. sent2: the blastema is not a feather if the XY is meatless and it troops mamma. sent3: The mamma troops XY. sent4: the blastema is a feather. sent5: the XY troops mamma. sent6: if the internode does not mistake noun it is not non-intramolecular. sent7: that the stake is a kind of a brunet hold if the internode is intramolecular. ; $proof$ = 
void -> assump1: Let's assume that that the internode does not mistake noun and it is not a kind of a linstock does not hold.; assump1 -> int1: there exists something such that the fact that it does not mistake noun and is not a linstock is wrong.; int1 & sent1 -> int2: the XY is meatless.; int2 & sent5 -> int3: the XY is meatless thing that does troop mamma.; int3 & sent2 -> int4: the blastema is not a kind of a feather.; int4 & sent4 -> int5: this is contradiction.; [assump1] & int5 -> int6: the internode does not mistake noun and is not a linstock.; int6 -> int7: the internode does not mistake noun.; int7 & sent6 -> int8: the internode is intramolecular.; int8 & sent7 -> hypothesis; __PROVED__