the asynergicness does not occur.
sent1: if that the smokescreen happens but the reproduction does not occur is not true then the brachiation does not occur. sent2: that the fact that the smokescreen but not the reproduction occurs is not correct is right if the asynergicness occurs. sent3: the allographicness does not occur. sent4: both the brachiation and the colloguing Helenium happens. sent5: the colloguing Helenium does not occur and the ding-dong happens if the avionicness does not occur. sent6: the fact that the underhandness happens and the expiring Iraq does not occur does not hold if the busying happens. sent7: the brachiation and the asynergicness happens if the colloguing Helenium does not occur.
void -> assump1: Let's assume that the fact that the asynergicness happens hold.; sent2 & assump1 -> int1: that the smokescreen happens but the reproduction does not occur does not hold.; int1 & sent1 -> int2: that the brachiation does not occur hold.; sent4 -> int3: the brachiation happens.; int2 & int3 -> int4: this is contradiction.; [assump1] & int4 -> hypothesis;
the asynergicness occurs.
$hypothesis$ = the asynergicness does not occur. ; $context$ = sent1: if that the smokescreen happens but the reproduction does not occur is not true then the brachiation does not occur. sent2: that the fact that the smokescreen but not the reproduction occurs is not correct is right if the asynergicness occurs. sent3: the allographicness does not occur. sent4: both the brachiation and the colloguing Helenium happens. sent5: the colloguing Helenium does not occur and the ding-dong happens if the avionicness does not occur. sent6: the fact that the underhandness happens and the expiring Iraq does not occur does not hold if the busying happens. sent7: the brachiation and the asynergicness happens if the colloguing Helenium does not occur. ; $proof$ = 
void -> assump1: Let's assume that the fact that the asynergicness happens hold.; sent2 & assump1 -> int1: that the smokescreen happens but the reproduction does not occur does not hold.; int1 & sent1 -> int2: that the brachiation does not occur hold.; sent4 -> int3: the brachiation happens.; int2 & int3 -> int4: this is contradiction.; [assump1] & int4 -> hypothesis; __PROVED__