the hierarch is not unlikely and does drain hierarch.
sent1: if that the hierarch is a miotic hold it is celebratory. sent2: that the hierarch is a kind of a miotic is correct. sent3: the midge drains hierarch. sent4: the hierarch is not celebratory if the fact that it is not unlikely and it drains hierarch is not right.
void -> assump1: Let's assume that that the hierarch is not unlikely and does drain hierarch does not hold.; sent4 & assump1 -> int1: the hierarch is not celebratory.; sent1 & sent2 -> int2: the hierarch is celebratory.; int1 & int2 -> int3: this is contradiction.; [assump1] & int3 -> hypothesis;
$hypothesis$ = the hierarch is not unlikely and does drain hierarch. ; $context$ = sent1: if that the hierarch is a miotic hold it is celebratory. sent2: that the hierarch is a kind of a miotic is correct. sent3: the midge drains hierarch. sent4: the hierarch is not celebratory if the fact that it is not unlikely and it drains hierarch is not right. ; $proof$ = 
void -> assump1: Let's assume that that the hierarch is not unlikely and does drain hierarch does not hold.; sent4 & assump1 -> int1: the hierarch is not celebratory.; sent1 & sent2 -> int2: the hierarch is celebratory.; int1 & int2 -> int3: this is contradiction.; [assump1] & int3 -> hypothesis; __PROVED__