that that the fishpond is a kind of a dexamethasone that does not trench is not true if the mod is empirical does not hold.
sent1: if there is something such that it does bargain lari either the Calla is empirical or it is not a trench or both. sent2: the vinyl is a Akron. sent3: something is empirical if it is empirical or it is not a trench or both. sent4: if that the deification is a Oviedo but it is not a Karelian is not right the fact that it is not adynamic is not incorrect. sent5: everything is not non-Cuban. sent6: the fact that the mod does bargain fruitwood but it is not Falstaffian is incorrect. sent7: if the mod is Frankish but it is not a Oviedo then it is not expendable. sent8: that the fishpond is a dexamethasone but it is not a kind of a trench is false if the mod does not trench. sent9: if the mod is not a trench then that the fishpond is both a dexamethasone and a trench is false. sent10: the fact that the fishpond is a kind of Frankish thing that is not a dexamethasone is not correct. sent11: if the mod is not expendable then it is not a kind of a trench. sent12: if something is a Cuban then the fact that it is both not a dexamethasone and not Australian is not correct. sent13: the fact that that the mod is a dexamethasone but it does not trench is not true if the fishpond is a kind of a Oviedo is correct. sent14: if there is something such that that it is not a dexamethasone and is not Australian is wrong the mod bargains lari. sent15: the antiknock is a Oviedo but it does not gripe Meccano. sent16: if that the mod is Frankish but it is not a Oviedo does not hold it is non-empirical.
void -> assump2: Let's assume that that the mod is Frankish but it is not a kind of a Oviedo is not true.; sent16 & assump2 -> int1: the mod is not empirical.; void -> assump1: Let's assume that that the mod is empirical is not wrong.; int1 & assump1 -> int2: this is contradiction.; [assump2] & int2 -> int3: the mod is Frankish but it is not a Oviedo.; int3 & sent7 -> int4: the mod is not expendable.; int4 & sent11 -> int5: the fact that the mod is not a trench is correct.; int5 & sent8 -> int6: that the fishpond is a dexamethasone and is not a trench is not right.; [assump1] & int6 -> hypothesis;
the fact that the vinyl is a Akron that does not trench is right.
$hypothesis$ = that that the fishpond is a kind of a dexamethasone that does not trench is not true if the mod is empirical does not hold. ; $context$ = sent1: if there is something such that it does bargain lari either the Calla is empirical or it is not a trench or both. sent2: the vinyl is a Akron. sent3: something is empirical if it is empirical or it is not a trench or both. sent4: if that the deification is a Oviedo but it is not a Karelian is not right the fact that it is not adynamic is not incorrect. sent5: everything is not non-Cuban. sent6: the fact that the mod does bargain fruitwood but it is not Falstaffian is incorrect. sent7: if the mod is Frankish but it is not a Oviedo then it is not expendable. sent8: that the fishpond is a dexamethasone but it is not a kind of a trench is false if the mod does not trench. sent9: if the mod is not a trench then that the fishpond is both a dexamethasone and a trench is false. sent10: the fact that the fishpond is a kind of Frankish thing that is not a dexamethasone is not correct. sent11: if the mod is not expendable then it is not a kind of a trench. sent12: if something is a Cuban then the fact that it is both not a dexamethasone and not Australian is not correct. sent13: the fact that that the mod is a dexamethasone but it does not trench is not true if the fishpond is a kind of a Oviedo is correct. sent14: if there is something such that that it is not a dexamethasone and is not Australian is wrong the mod bargains lari. sent15: the antiknock is a Oviedo but it does not gripe Meccano. sent16: if that the mod is Frankish but it is not a Oviedo does not hold it is non-empirical. ; $proof$ = 
void -> assump2: Let's assume that that the mod is Frankish but it is not a kind of a Oviedo is not true.; sent16 & assump2 -> int1: the mod is not empirical.; void -> assump1: Let's assume that that the mod is empirical is not wrong.; int1 & assump1 -> int2: this is contradiction.; [assump2] & int2 -> int3: the mod is Frankish but it is not a Oviedo.; int3 & sent7 -> int4: the mod is not expendable.; int4 & sent11 -> int5: the fact that the mod is not a trench is correct.; int5 & sent8 -> int6: that the fishpond is a dexamethasone and is not a trench is not right.; [assump1] & int6 -> hypothesis; __DISPROVED__