that the fact that the hogfish is not a kind of a rig and is not labyrinthine is false is correct if the parsley does not brazen diazoxide.
sent1: if the parsley is not a rig that the hogfish is a rig that does not brazen diazoxide is not true. sent2: if the parsley is not a rig then the fact that the hogfish does not brazen diazoxide and is not labyrinthine is not correct. sent3: that the hogfish is not a kind of a rig but it is labyrinthine is not true. sent4: that the parsley does not rig and it is not labyrinthine is not true. sent5: if the parsley does brazen diazoxide it is not a rig. sent6: that the hogfish is not labyrinthine and it does not rig does not hold if the parsley is not labyrinthine. sent7: the parsley does not brazen plunk. sent8: the fact that the hogfish does not rig and it does not brazen diazoxide is incorrect. sent9: the umber is not labyrinthine. sent10: if the parsley is not a rig that the hogfish is a rig and not labyrinthine is not right. sent11: the fact that the hogfish is both not a rig and labyrinthine is not true if the parsley does not brazen diazoxide. sent12: that the parsley does not brazen MST and it does not slug umber is wrong. sent13: if the parsley does rig that it does not override bib hold. sent14: if the parsley is labyrinthine that the hogfish does not brazen diazoxide and is not a rig does not hold. sent15: the fact that the hamster is not labyrinthine but it is equal does not hold. sent16: the fact that the parsley does not brazen diazoxide and is not labyrinthine does not hold if the hogfish does not rig. sent17: if the parsley does not rig the fact that the hogfish is labyrinthine thing that does not brazen diazoxide is false. sent18: if the parsley does not brazen diazoxide then it is not a rig. sent19: that the hogfish is not a rig and it is not labyrinthine is wrong if the parsley does brazen diazoxide. sent20: the fact that the hogfish is both not a rig and not a eosin is not correct. sent21: the fact that if the parsley is not a rig then that the hogfish is not a rig but labyrinthine is wrong is true.
void -> assump1: Let's assume that that the parsley does not brazen diazoxide is right.; sent18 & assump1 -> int1: that the parsley is not a rig is right.;
$hypothesis$ = that the fact that the hogfish is not a kind of a rig and is not labyrinthine is false is correct if the parsley does not brazen diazoxide. ; $context$ = sent1: if the parsley is not a rig that the hogfish is a rig that does not brazen diazoxide is not true. sent2: if the parsley is not a rig then the fact that the hogfish does not brazen diazoxide and is not labyrinthine is not correct. sent3: that the hogfish is not a kind of a rig but it is labyrinthine is not true. sent4: that the parsley does not rig and it is not labyrinthine is not true. sent5: if the parsley does brazen diazoxide it is not a rig. sent6: that the hogfish is not labyrinthine and it does not rig does not hold if the parsley is not labyrinthine. sent7: the parsley does not brazen plunk. sent8: the fact that the hogfish does not rig and it does not brazen diazoxide is incorrect. sent9: the umber is not labyrinthine. sent10: if the parsley is not a rig that the hogfish is a rig and not labyrinthine is not right. sent11: the fact that the hogfish is both not a rig and labyrinthine is not true if the parsley does not brazen diazoxide. sent12: that the parsley does not brazen MST and it does not slug umber is wrong. sent13: if the parsley does rig that it does not override bib hold. sent14: if the parsley is labyrinthine that the hogfish does not brazen diazoxide and is not a rig does not hold. sent15: the fact that the hamster is not labyrinthine but it is equal does not hold. sent16: the fact that the parsley does not brazen diazoxide and is not labyrinthine does not hold if the hogfish does not rig. sent17: if the parsley does not rig the fact that the hogfish is labyrinthine thing that does not brazen diazoxide is false. sent18: if the parsley does not brazen diazoxide then it is not a rig. sent19: that the hogfish is not a rig and it is not labyrinthine is wrong if the parsley does brazen diazoxide. sent20: the fact that the hogfish is both not a rig and not a eosin is not correct. sent21: the fact that if the parsley is not a rig then that the hogfish is not a rig but labyrinthine is wrong is true. ; $proof$ = 
void -> assump1: Let's assume that that the parsley does not brazen diazoxide is right.; sent18 & assump1 -> int1: that the parsley is not a rig is right.; __UNKNOWN__