the apse is a Andricus and/or is a kind of a native.
sent1: if something is a kind of a LTM but it is not hymenopterous then it is not avascular. sent2: the fact that the Merlot is a LTM and is a optative does not hold if there are non-hymenopterous things. sent3: if there is something such that it is not hymenopterous that the Merlot is not a LTM and is a kind of a optative is not true. sent4: that something is a Andricus and/or is a kind of a native is incorrect if it is not a Solvay. sent5: the aileron is a kind of a Solvay. sent6: if something is a kind of a native it is a LTM and non-hymenopterous. sent7: the aileron is avascular. sent8: the apse is a kind of a native if the fact that the Merlot is not a LTM but it is a optative does not hold. sent9: something is optative a Solvay if it is not avascular. sent10: a avascular Solvay is not hymenopterous. sent11: if the Merlot is a kind of a LTM then the apse is native.
sent5 & sent7 -> int1: the aileron is both a Solvay and avascular.; sent10 -> int2: if the aileron is both a Solvay and avascular the fact that it is not hymenopterous is not incorrect.; int1 & int2 -> int3: the aileron is not hymenopterous.; int3 -> int4: there are non-hymenopterous things.; int4 & sent3 -> int5: the fact that the Merlot is both not a LTM and a optative does not hold.; int5 & sent8 -> int6: the apse is a native.; int6 -> hypothesis;
the apse is a optative.
sent9 -> int7: if the aileron is not avascular then it is a optative and it is a kind of a Solvay.; sent6 -> int8: if the aileron is a native it is a LTM that is not hymenopterous.; sent1 -> int9: the aileron is not avascular if it is a kind of a LTM and it is not hymenopterous.;
$hypothesis$ = the apse is a Andricus and/or is a kind of a native. ; $context$ = sent1: if something is a kind of a LTM but it is not hymenopterous then it is not avascular. sent2: the fact that the Merlot is a LTM and is a optative does not hold if there are non-hymenopterous things. sent3: if there is something such that it is not hymenopterous that the Merlot is not a LTM and is a kind of a optative is not true. sent4: that something is a Andricus and/or is a kind of a native is incorrect if it is not a Solvay. sent5: the aileron is a kind of a Solvay. sent6: if something is a kind of a native it is a LTM and non-hymenopterous. sent7: the aileron is avascular. sent8: the apse is a kind of a native if the fact that the Merlot is not a LTM but it is a optative does not hold. sent9: something is optative a Solvay if it is not avascular. sent10: a avascular Solvay is not hymenopterous. sent11: if the Merlot is a kind of a LTM then the apse is native. ; $proof$ = 
sent5 & sent7 -> int1: the aileron is both a Solvay and avascular.; sent10 -> int2: if the aileron is both a Solvay and avascular the fact that it is not hymenopterous is not incorrect.; int1 & int2 -> int3: the aileron is not hymenopterous.; int3 -> int4: there are non-hymenopterous things.; int4 & sent3 -> int5: the fact that the Merlot is both not a LTM and a optative does not hold.; int5 & sent8 -> int6: the apse is a native.; int6 -> hypothesis; __PROVED__