the fact that there is something such that if it is not a Caproidae then it is periodic is not true.
sent1: the fact that the growth is a kind of a Caproidae is not incorrect if it is definite and does not concoct growth. sent2: there exists something such that if it does not concoct buspirone then it does rope houseplant. sent3: the fact that that the growth is not indefinite but it does concoct growth does not hold is true. sent4: if that something is not indefinite and it does not concoct growth is wrong it is periodic.
void -> assump2: Let's assume that the growth is not indefinite and does not concoct growth.; sent1 & assump2 -> int1: the growth is a Caproidae.; void -> assump1: Let's assume that the growth is not a kind of a Caproidae.; int1 & assump1 -> int2: this is contradiction.; [assump2] & int2 -> int3: the fact that the growth is not indefinite and it does not concoct growth is not right.; sent4 -> int4: if the fact that the growth is a kind of non-indefinite thing that does not concoct growth is incorrect then it is periodic.; int3 & int4 -> int5: the growth is periodic.; [assump1] & int5 -> int6: if the growth is not a Caproidae then it is periodic.; int6 -> hypothesis;
$hypothesis$ = the fact that there is something such that if it is not a Caproidae then it is periodic is not true. ; $context$ = sent1: the fact that the growth is a kind of a Caproidae is not incorrect if it is definite and does not concoct growth. sent2: there exists something such that if it does not concoct buspirone then it does rope houseplant. sent3: the fact that that the growth is not indefinite but it does concoct growth does not hold is true. sent4: if that something is not indefinite and it does not concoct growth is wrong it is periodic. ; $proof$ = 
void -> assump2: Let's assume that the growth is not indefinite and does not concoct growth.; sent1 & assump2 -> int1: the growth is a Caproidae.; void -> assump1: Let's assume that the growth is not a kind of a Caproidae.; int1 & assump1 -> int2: this is contradiction.; [assump2] & int2 -> int3: the fact that the growth is not indefinite and it does not concoct growth is not right.; sent4 -> int4: if the fact that the growth is a kind of non-indefinite thing that does not concoct growth is incorrect then it is periodic.; int3 & int4 -> int5: the growth is periodic.; [assump1] & int5 -> int6: if the growth is not a Caproidae then it is periodic.; int6 -> hypothesis; __DISPROVED__