the fact that the fact that the idesia edges idesia and does not bethink Rumpelstiltskin does not hold if the taproot is three-piece is not correct.
sent1: that the idesia does edge idesia and it does bethink Rumpelstiltskin does not hold. sent2: the idesia does edge idesia. sent3: if the idesia does edge idesia but it does not bethink Rumpelstiltskin the taproot is not three-piece. sent4: that if the taproot is three-piece the fact that the fact that the idesia edges idesia and does bethink Rumpelstiltskin is not right is right hold. sent5: if the taproot bethinks Rumpelstiltskin the fact that the idesia edges idesia but it is not three-piece is incorrect. sent6: if the idesia does edge idesia and bethinks Rumpelstiltskin then the taproot is not three-piece. sent7: the idesia does not bethink Rumpelstiltskin. sent8: the fact that the taproot edges idesia but it does not bethink Rumpelstiltskin is wrong if the idesia is three-piece. sent9: the taproot is not aphoristic if the fact that the idesia is aphoristic but it is not a kind of a ganoid is not true. sent10: the idesia does edge idesia but it does not bethink Rumpelstiltskin if the taproot is not non-three-piece.
void -> assump2: Let's assume that the idesia does edge idesia but it does not bethink Rumpelstiltskin.; sent3 & assump2 -> int1: the taproot is not three-piece.; void -> assump1: Let's assume that the taproot is three-piece.; int1 & assump1 -> int2: this is contradiction.; [assump2] & int2 -> int3: the fact that the idesia edges idesia and does not bethink Rumpelstiltskin is not true.; [assump1] & int3 -> hypothesis;
the taproot is emphysematous but it is not aphoristic.
$hypothesis$ = the fact that the fact that the idesia edges idesia and does not bethink Rumpelstiltskin does not hold if the taproot is three-piece is not correct. ; $context$ = sent1: that the idesia does edge idesia and it does bethink Rumpelstiltskin does not hold. sent2: the idesia does edge idesia. sent3: if the idesia does edge idesia but it does not bethink Rumpelstiltskin the taproot is not three-piece. sent4: that if the taproot is three-piece the fact that the fact that the idesia edges idesia and does bethink Rumpelstiltskin is not right is right hold. sent5: if the taproot bethinks Rumpelstiltskin the fact that the idesia edges idesia but it is not three-piece is incorrect. sent6: if the idesia does edge idesia and bethinks Rumpelstiltskin then the taproot is not three-piece. sent7: the idesia does not bethink Rumpelstiltskin. sent8: the fact that the taproot edges idesia but it does not bethink Rumpelstiltskin is wrong if the idesia is three-piece. sent9: the taproot is not aphoristic if the fact that the idesia is aphoristic but it is not a kind of a ganoid is not true. sent10: the idesia does edge idesia but it does not bethink Rumpelstiltskin if the taproot is not non-three-piece. ; $proof$ = 
void -> assump2: Let's assume that the idesia does edge idesia but it does not bethink Rumpelstiltskin.; sent3 & assump2 -> int1: the taproot is not three-piece.; void -> assump1: Let's assume that the taproot is three-piece.; int1 & assump1 -> int2: this is contradiction.; [assump2] & int2 -> int3: the fact that the idesia edges idesia and does not bethink Rumpelstiltskin is not true.; [assump1] & int3 -> hypothesis; __DISPROVED__