the fact that if that the lie does not shillyshally Chamaedaphne hold then the meltwater is a print is not correct.
sent1: the lie is a crossbow that molds Lena. sent2: the romanticist does shillyshally Chamaedaphne. sent3: if the lie is not antisatellite the meltwater shillyshallies Chamaedaphne. sent4: if the lie is a print then the meltwater is antisatellite. sent5: the meltwater shillyshallies Chamaedaphne if that the lie is a print hold. sent6: the meltwater shillyshallies Chamaedaphne and it is antisatellite if the lie is not a print. sent7: if the lie does not shillyshally Chamaedaphne then the meltwater is antisatellite. sent8: if the meltwater does not shillyshally Chamaedaphne the lie is a print. sent9: the Bavarian is both a print and unfamiliar. sent10: the meltwater is a kind of a print if the lie shillyshallies Chamaedaphne. sent11: if the lie does shillyshally Chamaedaphne then the meltwater is a print and is antisatellite. sent12: the Teflon does shillyshally Chamaedaphne. sent13: if the lie does not print the meltwater is a kind of antisatellite thing that does shillyshally Chamaedaphne. sent14: the lie is antisatellite if the meltwater does not shillyshally Chamaedaphne. sent15: the meltwater is not non-pyrotechnic. sent16: the meltwater is antisatellite. sent17: the meltwater is antisatellite and shillyshallies Chamaedaphne if the lie does print. sent18: the meltwater shillyshallies Chamaedaphne. sent19: the meltwater is a print and it is antisatellite if the lie does not shillyshally Chamaedaphne. sent20: the lie is a print if the meltwater does shillyshally Chamaedaphne.
void -> assump1: Let's assume that that the lie does not shillyshally Chamaedaphne hold.; sent19 & assump1 -> int1: the meltwater prints and is antisatellite.; int1 -> int2: the meltwater prints.; [assump1] & int2 -> hypothesis;
$hypothesis$ = the fact that if that the lie does not shillyshally Chamaedaphne hold then the meltwater is a print is not correct. ; $context$ = sent1: the lie is a crossbow that molds Lena. sent2: the romanticist does shillyshally Chamaedaphne. sent3: if the lie is not antisatellite the meltwater shillyshallies Chamaedaphne. sent4: if the lie is a print then the meltwater is antisatellite. sent5: the meltwater shillyshallies Chamaedaphne if that the lie is a print hold. sent6: the meltwater shillyshallies Chamaedaphne and it is antisatellite if the lie is not a print. sent7: if the lie does not shillyshally Chamaedaphne then the meltwater is antisatellite. sent8: if the meltwater does not shillyshally Chamaedaphne the lie is a print. sent9: the Bavarian is both a print and unfamiliar. sent10: the meltwater is a kind of a print if the lie shillyshallies Chamaedaphne. sent11: if the lie does shillyshally Chamaedaphne then the meltwater is a print and is antisatellite. sent12: the Teflon does shillyshally Chamaedaphne. sent13: if the lie does not print the meltwater is a kind of antisatellite thing that does shillyshally Chamaedaphne. sent14: the lie is antisatellite if the meltwater does not shillyshally Chamaedaphne. sent15: the meltwater is not non-pyrotechnic. sent16: the meltwater is antisatellite. sent17: the meltwater is antisatellite and shillyshallies Chamaedaphne if the lie does print. sent18: the meltwater shillyshallies Chamaedaphne. sent19: the meltwater is a print and it is antisatellite if the lie does not shillyshally Chamaedaphne. sent20: the lie is a print if the meltwater does shillyshally Chamaedaphne. ; $proof$ = 
void -> assump1: Let's assume that that the lie does not shillyshally Chamaedaphne hold.; sent19 & assump1 -> int1: the meltwater prints and is antisatellite.; int1 -> int2: the meltwater prints.; [assump1] & int2 -> hypothesis; __DISPROVED__