the overlook does not obligate and is a velour.
sent1: everything is a mescaline but not a erroneousness. sent2: the glyph is not a stiff if there is something such that the fact that it does not enfeoff Canada and is not edible is not right. sent3: a conservative that is obligate is not a kind of a mescaline. sent4: if the glyph is a kind of a stiff then the fact that the overlook is not obligate but it is a velour is false. sent5: there exists something such that that it does not enfeoff Canada and is not edible is false. sent6: something enfeoffs barroom and it is a kind of a conservative if it is not a kind of a stiff.
sent5 & sent2 -> int1: the glyph is not stiff.; sent6 -> int2: the glyph does enfeoff barroom and it is a kind of a conservative if it is not a stiff.; int1 & int2 -> int3: the glyph does enfeoff barroom and it is a conservative.; int3 -> int4: the glyph is a kind of a conservative.; void -> assump1: Let's assume that the glyph does obligate.; int4 & assump1 -> int5: the glyph is a kind of a conservative and it does obligate.; sent3 -> int6: if the glyph is conservative and it does obligate it is not a mescaline.; int5 & int6 -> int7: the glyph is not a mescaline.; sent1 -> int8: the glyph is a mescaline but it is not a kind of a erroneousness.; int8 -> int9: the glyph is a mescaline.; int7 & int9 -> int10: this is contradiction.; [assump1] & int10 -> int11: the fact that the glyph obligates is not correct.;
that the overlook is non-obligate and a velour is false.
$hypothesis$ = the overlook does not obligate and is a velour. ; $context$ = sent1: everything is a mescaline but not a erroneousness. sent2: the glyph is not a stiff if there is something such that the fact that it does not enfeoff Canada and is not edible is not right. sent3: a conservative that is obligate is not a kind of a mescaline. sent4: if the glyph is a kind of a stiff then the fact that the overlook is not obligate but it is a velour is false. sent5: there exists something such that that it does not enfeoff Canada and is not edible is false. sent6: something enfeoffs barroom and it is a kind of a conservative if it is not a kind of a stiff. ; $proof$ = 
sent5 & sent2 -> int1: the glyph is not stiff.; sent6 -> int2: the glyph does enfeoff barroom and it is a kind of a conservative if it is not a stiff.; int1 & int2 -> int3: the glyph does enfeoff barroom and it is a conservative.; int3 -> int4: the glyph is a kind of a conservative.; void -> assump1: Let's assume that the glyph does obligate.; int4 & assump1 -> int5: the glyph is a kind of a conservative and it does obligate.; sent3 -> int6: if the glyph is conservative and it does obligate it is not a mescaline.; int5 & int6 -> int7: the glyph is not a mescaline.; sent1 -> int8: the glyph is a mescaline but it is not a kind of a erroneousness.; int8 -> int9: the glyph is a mescaline.; int7 & int9 -> int10: this is contradiction.; [assump1] & int10 -> int11: the fact that the glyph obligates is not correct.; __UNKNOWN__