the fact that the wilderness is not a indiction hold.
sent1: if something is a kind of non-peaceful thing that steels stocktaker then it conventionalizes monogamy. sent2: if something does fear hopscotch then it is not peaceful and does not steel stocktaker. sent3: if the wilderness is a kind of a Mogul it is a kind of a VDU. sent4: if the buzzer is scalar thing that is a mend the crankshaft does not conventionalize monogamy. sent5: something that is not peaceful and does not steel stocktaker does not conventionalize monogamy. sent6: if the fact that something is not a mend and/or is not a kind of a snooker does not hold then it is a indiction. sent7: the crankshaft does not fear ylem and it does not conventionalize stringer. sent8: the fact that the wilderness is not a mend or it does not snooker or both is not correct if the buzzer is not a mend. sent9: the fact that the wilderness hugs is true. sent10: the crankshaft does fear hopscotch. sent11: there exists something such that it is adaptive. sent12: if the buzzer is a schoolfriend it is scalar. sent13: the buzzer is a schoolfriend if there is something such that it is a Mogul and adaptive. sent14: the buzzer is peaceful. sent15: if that something is not a kind of a mend or it is a snooker or both is not right then that it is a indiction is not wrong. sent16: The hopscotch does fear crankshaft. sent17: if there exists something such that it is peaceful and a indiction the crankshaft is a kind of a schoolfriend. sent18: something is a Mogul and it is adaptive. sent19: if the crankshaft does not steel stocktaker and it is not a kind of a schoolfriend then it does mend. sent20: something is a scalar. sent21: if something does fear hopscotch it does not steel stocktaker. sent22: something is not adaptive if that it is both not scalar and adaptive is false. sent23: that the wilderness is not a indiction hold if the buzzer is not a indiction and is not adaptive.
sent18 & sent13 -> int1: the fact that the buzzer is a schoolfriend is correct.; int1 & sent12 -> int2: the buzzer is a kind of a scalar.; void -> assump1: Let's assume that the buzzer does mend.; int2 & assump1 -> int3: the buzzer is a kind of a scalar that mends.; int3 & sent4 -> int4: the fact that the crankshaft does not conventionalize monogamy is correct.; sent5 -> int5: that the crankshaft does conventionalize monogamy is not incorrect if it is a kind of unpeaceful thing that does not steel stocktaker.; sent2 -> int6: if the crankshaft fears hopscotch it is unpeaceful thing that does not steel stocktaker.; int6 & sent10 -> int7: the crankshaft is not peaceful and it does not steel stocktaker.; int5 & int7 -> int8: the crankshaft conventionalizes monogamy.; int4 & int8 -> int9: this is contradiction.; [assump1] & int9 -> int10: the buzzer does not mend.; int10 & sent8 -> int11: the fact that that the wilderness is not a mend and/or it is not a kind of a snooker is not true is correct.; sent6 -> int12: if the fact that either the wilderness is not a mend or it does not snooker or both does not hold it is a indiction.; int11 & int12 -> hypothesis;
the wilderness is not a indiction.
sent22 -> int13: if the fact that the buzzer is both non-scalar and not non-adaptive does not hold then it is not non-adaptive.;
$hypothesis$ = the fact that the wilderness is not a indiction hold. ; $context$ = sent1: if something is a kind of non-peaceful thing that steels stocktaker then it conventionalizes monogamy. sent2: if something does fear hopscotch then it is not peaceful and does not steel stocktaker. sent3: if the wilderness is a kind of a Mogul it is a kind of a VDU. sent4: if the buzzer is scalar thing that is a mend the crankshaft does not conventionalize monogamy. sent5: something that is not peaceful and does not steel stocktaker does not conventionalize monogamy. sent6: if the fact that something is not a mend and/or is not a kind of a snooker does not hold then it is a indiction. sent7: the crankshaft does not fear ylem and it does not conventionalize stringer. sent8: the fact that the wilderness is not a mend or it does not snooker or both is not correct if the buzzer is not a mend. sent9: the fact that the wilderness hugs is true. sent10: the crankshaft does fear hopscotch. sent11: there exists something such that it is adaptive. sent12: if the buzzer is a schoolfriend it is scalar. sent13: the buzzer is a schoolfriend if there is something such that it is a Mogul and adaptive. sent14: the buzzer is peaceful. sent15: if that something is not a kind of a mend or it is a snooker or both is not right then that it is a indiction is not wrong. sent16: The hopscotch does fear crankshaft. sent17: if there exists something such that it is peaceful and a indiction the crankshaft is a kind of a schoolfriend. sent18: something is a Mogul and it is adaptive. sent19: if the crankshaft does not steel stocktaker and it is not a kind of a schoolfriend then it does mend. sent20: something is a scalar. sent21: if something does fear hopscotch it does not steel stocktaker. sent22: something is not adaptive if that it is both not scalar and adaptive is false. sent23: that the wilderness is not a indiction hold if the buzzer is not a indiction and is not adaptive. ; $proof$ = 
sent18 & sent13 -> int1: the fact that the buzzer is a schoolfriend is correct.; int1 & sent12 -> int2: the buzzer is a kind of a scalar.; void -> assump1: Let's assume that the buzzer does mend.; int2 & assump1 -> int3: the buzzer is a kind of a scalar that mends.; int3 & sent4 -> int4: the fact that the crankshaft does not conventionalize monogamy is correct.; sent5 -> int5: that the crankshaft does conventionalize monogamy is not incorrect if it is a kind of unpeaceful thing that does not steel stocktaker.; sent2 -> int6: if the crankshaft fears hopscotch it is unpeaceful thing that does not steel stocktaker.; int6 & sent10 -> int7: the crankshaft is not peaceful and it does not steel stocktaker.; int5 & int7 -> int8: the crankshaft conventionalizes monogamy.; int4 & int8 -> int9: this is contradiction.; [assump1] & int9 -> int10: the buzzer does not mend.; int10 & sent8 -> int11: the fact that that the wilderness is not a mend and/or it is not a kind of a snooker is not true is correct.; sent6 -> int12: if the fact that either the wilderness is not a mend or it does not snooker or both does not hold it is a indiction.; int11 & int12 -> hypothesis; __DISPROVED__