the rebound does not spring-clean manana.
sent1: the scut removes screen if it is a kind of a bradawl. sent2: the fact that something is non-open-hearth thing that does remove centrist is not correct if that it removes screen is not wrong. sent3: the Brazil is rheologic and/or it is ecclesiastical. sent4: the rebound does spring-clean manana if the Brazil is not rheologic and/or it is ecclesiastical. sent5: the scut is not open-hearth but it removes centrist if that the busbar does removes centrist hold. sent6: the scut is a bradawl. sent7: if the fact that the Brazil either is non-rheologic or is ecclesiastical or both is false the busbar does remove centrist.
void -> assump1: Let's assume that that the Brazil is not rheologic and/or it is ecclesiastical is not right.; sent7 & assump1 -> int1: the busbar removes centrist.; int1 & sent5 -> int2: the scut is not open-hearth but it removes centrist.; sent2 -> int3: if the scut removes screen then that it is not open-hearth and it does remove centrist is incorrect.; sent1 & sent6 -> int4: the scut removes screen.; int3 & int4 -> int5: that the scut is not open-hearth but it does remove centrist is not right.; int2 & int5 -> int6: this is contradiction.; [assump1] & int6 -> int7: the Brazil either is not rheologic or is ecclesiastical or both.; int7 & sent4 -> hypothesis;
$hypothesis$ = the rebound does not spring-clean manana. ; $context$ = sent1: the scut removes screen if it is a kind of a bradawl. sent2: the fact that something is non-open-hearth thing that does remove centrist is not correct if that it removes screen is not wrong. sent3: the Brazil is rheologic and/or it is ecclesiastical. sent4: the rebound does spring-clean manana if the Brazil is not rheologic and/or it is ecclesiastical. sent5: the scut is not open-hearth but it removes centrist if that the busbar does removes centrist hold. sent6: the scut is a bradawl. sent7: if the fact that the Brazil either is non-rheologic or is ecclesiastical or both is false the busbar does remove centrist. ; $proof$ = 
void -> assump1: Let's assume that that the Brazil is not rheologic and/or it is ecclesiastical is not right.; sent7 & assump1 -> int1: the busbar removes centrist.; int1 & sent5 -> int2: the scut is not open-hearth but it removes centrist.; sent2 -> int3: if the scut removes screen then that it is not open-hearth and it does remove centrist is incorrect.; sent1 & sent6 -> int4: the scut removes screen.; int3 & int4 -> int5: that the scut is not open-hearth but it does remove centrist is not right.; int2 & int5 -> int6: this is contradiction.; [assump1] & int6 -> int7: the Brazil either is not rheologic or is ecclesiastical or both.; int7 & sent4 -> hypothesis; __DISPROVED__