the fact that that the webcam is not a rustiness but it is a letters is incorrect is correct.
sent1: if the Quechua is not a kind of a letters that the webcam eliminates MBA and is a seasonal does not hold. sent2: the fact that the Quechua is a rustiness and/or it is not a letters is right if it is not a lambert. sent3: if the tamp is not a letters then the fact that the fact that the webcam is not a rustiness and is a kind of a letters is not right is right. sent4: there is something such that it is a kind of a seasonal. sent5: the fact that the tamp does not eliminate MBA but it is a semitone does not hold. sent6: if something is a kind of a rustiness and/or it is not a letters it is not a letters. sent7: the fact that the Quechua is not afebrile and is not a hypnotherapy is not true if it is not spectrographic. sent8: the fact that something does not eliminate MBA and/or it is not a seasonal is incorrect if it is a semitone. sent9: the webcam is not a letters if the fact that it is not a kind of a semitone and it does not eliminate MBA is not true. sent10: if the fact that the tamp does not eliminate MBA and it is not a semitone is wrong then it is not a kind of a letters. sent11: that the tamp does not eliminate MBA and is not a semitone is not right if there is something such that it is seasonal. sent12: if the fact that the Quechua is not afebrile and it is not a hypnotherapy does not hold then it is not a kind of a lambert. sent13: that the webcam is both a rustiness and a letters is not right. sent14: that the tamp is not a seasonal is not wrong if that the Quechua does not eliminate MBA and/or it is not a seasonal is not right. sent15: if the tamp is a semitone it is not a kind of a letters.
sent4 & sent11 -> int1: the fact that the tamp does not eliminate MBA and is not a semitone does not hold.; int1 & sent10 -> int2: the tamp is not a kind of a letters.; int2 & sent3 -> hypothesis;
the webcam is not a rustiness and letters.
sent8 -> int3: the fact that the Quechua does not eliminate MBA or it is not a seasonal or both is not correct if it is a semitone.;
$hypothesis$ = the fact that that the webcam is not a rustiness but it is a letters is incorrect is correct. ; $context$ = sent1: if the Quechua is not a kind of a letters that the webcam eliminates MBA and is a seasonal does not hold. sent2: the fact that the Quechua is a rustiness and/or it is not a letters is right if it is not a lambert. sent3: if the tamp is not a letters then the fact that the fact that the webcam is not a rustiness and is a kind of a letters is not right is right. sent4: there is something such that it is a kind of a seasonal. sent5: the fact that the tamp does not eliminate MBA but it is a semitone does not hold. sent6: if something is a kind of a rustiness and/or it is not a letters it is not a letters. sent7: the fact that the Quechua is not afebrile and is not a hypnotherapy is not true if it is not spectrographic. sent8: the fact that something does not eliminate MBA and/or it is not a seasonal is incorrect if it is a semitone. sent9: the webcam is not a letters if the fact that it is not a kind of a semitone and it does not eliminate MBA is not true. sent10: if the fact that the tamp does not eliminate MBA and it is not a semitone is wrong then it is not a kind of a letters. sent11: that the tamp does not eliminate MBA and is not a semitone is not right if there is something such that it is seasonal. sent12: if the fact that the Quechua is not afebrile and it is not a hypnotherapy does not hold then it is not a kind of a lambert. sent13: that the webcam is both a rustiness and a letters is not right. sent14: that the tamp is not a seasonal is not wrong if that the Quechua does not eliminate MBA and/or it is not a seasonal is not right. sent15: if the tamp is a semitone it is not a kind of a letters. ; $proof$ = 
sent4 & sent11 -> int1: the fact that the tamp does not eliminate MBA and is not a semitone does not hold.; int1 & sent10 -> int2: the tamp is not a kind of a letters.; int2 & sent3 -> hypothesis; __PROVED__