the arse does photostat convention.
sent1: that the arse does not circularize Tao is not wrong. sent2: the needlebush does refrain plage. sent3: the illumination does circularize Tao and is heterocercal. sent4: the needlebush is epigastric. sent5: the needlebush does not circularize Tao. sent6: the sunflower is insensitive. sent7: the pebble is abbatial and it is sociobiologic. sent8: The illumination does photostat needlebush. sent9: if the sunflower photostats convention the arse photostats convention and does not circularize Tao. sent10: the needlebush is a promycelium. sent11: that the repercussion is a Eurocentrism but it does not photostat convention is true. sent12: the sunflower is a kind of a Symphytum. sent13: the rotogravure is a cackle. sent14: the needlebush is not insensitive if it circularizes Tao and it does photostat illumination. sent15: the sunflower is not heartless. sent16: something that is a cackle and not insensitive does not photostat convention. sent17: the needlebush does not photostat illumination if it is insensitive and it is a cackle. sent18: the sunflower is a cackle and it photostats convention if the needlebush is not a cackle. sent19: if the sunflower does not cackle then the needlebush cackle and does photostat convention. sent20: that the needlebush is insensitive hold. sent21: the needlebush is a kind of an overabundance and it is a kind of a Sabine. sent22: the arse does not circularize Tao if the sunflower does photostat convention. sent23: the needlebush does photostat illumination. sent24: the needlebush is not insensitive if it photostats illumination and circularizes Tao. sent25: the sunflower does cackle. sent26: if the needlebush is not a kind of a cackle then the sunflower is a cackle.
void -> assump1: Let's assume that the needlebush is a kind of a cackle.; sent20 & assump1 -> int1: the needlebush is insensitive and it cackles.; int1 & sent17 -> int2: the needlebush does not photostat illumination.; int2 & sent23 -> int3: this is contradiction.; [assump1] & int3 -> int4: the needlebush is not a cackle.; int4 & sent18 -> int5: the sunflower is a cackle that photostats convention.; int5 -> int6: the sunflower does photostat convention.; int6 & sent9 -> int7: that the arse photostats convention and does not circularize Tao is true.; int7 -> hypothesis;
the capacity is not insensitive.
$hypothesis$ = the arse does photostat convention. ; $context$ = sent1: that the arse does not circularize Tao is not wrong. sent2: the needlebush does refrain plage. sent3: the illumination does circularize Tao and is heterocercal. sent4: the needlebush is epigastric. sent5: the needlebush does not circularize Tao. sent6: the sunflower is insensitive. sent7: the pebble is abbatial and it is sociobiologic. sent8: The illumination does photostat needlebush. sent9: if the sunflower photostats convention the arse photostats convention and does not circularize Tao. sent10: the needlebush is a promycelium. sent11: that the repercussion is a Eurocentrism but it does not photostat convention is true. sent12: the sunflower is a kind of a Symphytum. sent13: the rotogravure is a cackle. sent14: the needlebush is not insensitive if it circularizes Tao and it does photostat illumination. sent15: the sunflower is not heartless. sent16: something that is a cackle and not insensitive does not photostat convention. sent17: the needlebush does not photostat illumination if it is insensitive and it is a cackle. sent18: the sunflower is a cackle and it photostats convention if the needlebush is not a cackle. sent19: if the sunflower does not cackle then the needlebush cackle and does photostat convention. sent20: that the needlebush is insensitive hold. sent21: the needlebush is a kind of an overabundance and it is a kind of a Sabine. sent22: the arse does not circularize Tao if the sunflower does photostat convention. sent23: the needlebush does photostat illumination. sent24: the needlebush is not insensitive if it photostats illumination and circularizes Tao. sent25: the sunflower does cackle. sent26: if the needlebush is not a kind of a cackle then the sunflower is a cackle. ; $proof$ = 
void -> assump1: Let's assume that the needlebush is a kind of a cackle.; sent20 & assump1 -> int1: the needlebush is insensitive and it cackles.; int1 & sent17 -> int2: the needlebush does not photostat illumination.; int2 & sent23 -> int3: this is contradiction.; [assump1] & int3 -> int4: the needlebush is not a cackle.; int4 & sent18 -> int5: the sunflower is a cackle that photostats convention.; int5 -> int6: the sunflower does photostat convention.; int6 & sent9 -> int7: that the arse photostats convention and does not circularize Tao is true.; int7 -> hypothesis; __PROVED__