the Pekinese is not a kind of a Germanic.
sent1: the Pekinese is a neoprene and it is an arbitrageur if it is not a reserve. sent2: the Pekinese does not reserve. sent3: if something is a kind of an earth it unfastens Pekinese. sent4: if that something does unfasten Pekinese and/or it does patronage Rutherford is right then it is not a neoprene. sent5: the Pekinese is not a kind of a Germanic if the fact that the Sindhi does not earth but it does unfasten Pekinese is not correct. sent6: the Pekinese is an earth if it is not Germanic.
void -> assump1: Let's assume that the Pekinese is not a kind of a Germanic.; sent6 & assump1 -> int1: the Pekinese earths.; sent3 -> int2: the Pekinese does unfasten Pekinese if it does earth.; int1 & int2 -> int3: the Pekinese does unfasten Pekinese.; int3 -> int4: the Pekinese does unfasten Pekinese or it does patronage Rutherford or both.; sent4 -> int5: the Pekinese is not a neoprene if it does unfasten Pekinese and/or it patronages Rutherford.; int4 & int5 -> int6: the Pekinese is not a neoprene.; sent1 & sent2 -> int7: the Pekinese is a neoprene and it is an arbitrageur.; int7 -> int8: the Pekinese is a neoprene.; int6 & int8 -> int9: this is contradiction.; [assump1] & int9 -> hypothesis;
the Pekinese is not Germanic.
$hypothesis$ = the Pekinese is not a kind of a Germanic. ; $context$ = sent1: the Pekinese is a neoprene and it is an arbitrageur if it is not a reserve. sent2: the Pekinese does not reserve. sent3: if something is a kind of an earth it unfastens Pekinese. sent4: if that something does unfasten Pekinese and/or it does patronage Rutherford is right then it is not a neoprene. sent5: the Pekinese is not a kind of a Germanic if the fact that the Sindhi does not earth but it does unfasten Pekinese is not correct. sent6: the Pekinese is an earth if it is not Germanic. ; $proof$ = 
void -> assump1: Let's assume that the Pekinese is not a kind of a Germanic.; sent6 & assump1 -> int1: the Pekinese earths.; sent3 -> int2: the Pekinese does unfasten Pekinese if it does earth.; int1 & int2 -> int3: the Pekinese does unfasten Pekinese.; int3 -> int4: the Pekinese does unfasten Pekinese or it does patronage Rutherford or both.; sent4 -> int5: the Pekinese is not a neoprene if it does unfasten Pekinese and/or it patronages Rutherford.; int4 & int5 -> int6: the Pekinese is not a neoprene.; sent1 & sent2 -> int7: the Pekinese is a neoprene and it is an arbitrageur.; int7 -> int8: the Pekinese is a neoprene.; int6 & int8 -> int9: this is contradiction.; [assump1] & int9 -> hypothesis; __DISPROVED__