the VDU does not hex.
sent1: the bulkhead is not a kind of a torn. sent2: if the bulkhead is not a Khowar it does not upload IDDM. sent3: if something is not a kind of a Echium it is not outside. sent4: if the fact that the bulkhead does ferment VDU hold the VDU does hex. sent5: the bulkhead is not a Echium if it does not ferment innings and is happy. sent6: if the bulkhead ferments innings and is happy it is not a Echium. sent7: the parturiency does upload IDDM if the fact that it does not uncoil minaret and it does not upload kirsch is not correct. sent8: if the parturiency does upload IDDM then the bulkhead does hex but it does not ferment VDU. sent9: the bulkhead is photovoltaic and it is a kind of a Echium if the parturiency is not a kind of an outside. sent10: the fact that the bulkhead does not ferment VDU is not right if it is photovoltaic. sent11: if the bulkhead is not photovoltaic then it does not ferment innings and it is happy. sent12: the bulkhead is an outside.
void -> assump1: Let's assume that the bulkhead is non-photovoltaic.; sent11 & assump1 -> int1: the bulkhead does not ferment innings and is happy.; int1 & sent5 -> int2: that the bulkhead is not a Echium is not wrong.; sent3 -> int3: that if the bulkhead is not the Echium the bulkhead is not outside is not incorrect.; int2 & int3 -> int4: the bulkhead is not outside.; int4 & sent12 -> int5: this is contradiction.; [assump1] & int5 -> int6: the bulkhead is photovoltaic.; int6 & sent10 -> int7: the bulkhead ferments VDU.; int7 & sent4 -> hypothesis;
the VDU is an outside.
$hypothesis$ = the VDU does not hex. ; $context$ = sent1: the bulkhead is not a kind of a torn. sent2: if the bulkhead is not a Khowar it does not upload IDDM. sent3: if something is not a kind of a Echium it is not outside. sent4: if the fact that the bulkhead does ferment VDU hold the VDU does hex. sent5: the bulkhead is not a Echium if it does not ferment innings and is happy. sent6: if the bulkhead ferments innings and is happy it is not a Echium. sent7: the parturiency does upload IDDM if the fact that it does not uncoil minaret and it does not upload kirsch is not correct. sent8: if the parturiency does upload IDDM then the bulkhead does hex but it does not ferment VDU. sent9: the bulkhead is photovoltaic and it is a kind of a Echium if the parturiency is not a kind of an outside. sent10: the fact that the bulkhead does not ferment VDU is not right if it is photovoltaic. sent11: if the bulkhead is not photovoltaic then it does not ferment innings and it is happy. sent12: the bulkhead is an outside. ; $proof$ = 
void -> assump1: Let's assume that the bulkhead is non-photovoltaic.; sent11 & assump1 -> int1: the bulkhead does not ferment innings and is happy.; int1 & sent5 -> int2: that the bulkhead is not a Echium is not wrong.; sent3 -> int3: that if the bulkhead is not the Echium the bulkhead is not outside is not incorrect.; int2 & int3 -> int4: the bulkhead is not outside.; int4 & sent12 -> int5: this is contradiction.; [assump1] & int5 -> int6: the bulkhead is photovoltaic.; int6 & sent10 -> int7: the bulkhead ferments VDU.; int7 & sent4 -> hypothesis; __DISPROVED__