the comforter does not lap Plattdeutsch and is non-anosmic.
sent1: that if the medlar is categorical then that the fact that the journal is a slice and not cryptanalytic does not hold is not incorrect is correct. sent2: if the fact that the medlar is a fellowship and it is categorical is not right then the comforter is not a patch. sent3: the comforter does not lap Plattdeutsch and is not anosmic if it does not patch. sent4: if the journal is not categorical then the fact that the medlar is a fellowship and categorical is wrong. sent5: the medlar is categorical if it is both not a fellowship and a patch. sent6: there exists something such that it is a slice and it is cryptanalytic. sent7: something is not a fellowship and is a kind of a patch if it does not whang archerfish. sent8: if the fact that something does slice and is not cryptanalytic is wrong that it laps Plattdeutsch is not wrong.
that the comforter does not lap Plattdeutsch and is not anosmic does not hold.
sent8 -> int1: if that the journal slices and is not cryptanalytic is not right then it does lap Plattdeutsch.; sent7 -> int2: the medlar is not a fellowship but a patch if it does not whang archerfish.;
$hypothesis$ = the comforter does not lap Plattdeutsch and is non-anosmic. ; $context$ = sent1: that if the medlar is categorical then that the fact that the journal is a slice and not cryptanalytic does not hold is not incorrect is correct. sent2: if the fact that the medlar is a fellowship and it is categorical is not right then the comforter is not a patch. sent3: the comforter does not lap Plattdeutsch and is not anosmic if it does not patch. sent4: if the journal is not categorical then the fact that the medlar is a fellowship and categorical is wrong. sent5: the medlar is categorical if it is both not a fellowship and a patch. sent6: there exists something such that it is a slice and it is cryptanalytic. sent7: something is not a fellowship and is a kind of a patch if it does not whang archerfish. sent8: if the fact that something does slice and is not cryptanalytic is wrong that it laps Plattdeutsch is not wrong. ; $proof$ = 
__UNKNOWN__