the bean is Piagetian if the semaphore is inopportune.
sent1: the cotton is not inopportune. sent2: the fact that the semaphore is Piagetian hold if that it is an impossible hold. sent3: the fact that the semaphore is not impossible if the fact that the bean is not a sucrose is right hold. sent4: the daffodil does override escapee if it is not a lygaeid. sent5: the bean is inopportune if the fact that the semaphore is not an extinction and does slug chromium does not hold. sent6: the semaphore is not Piagetian if the bean is not an impossible. sent7: if the semaphore is not an impossible then it is not inopportune. sent8: if something is inopportune the fact that it is not a sucrose and it is not impossible is not right. sent9: the fact that if the semaphore is not the impossible the semaphore is inopportune is correct. sent10: if something is a Gambian it is an impossible. sent11: something is inopportune if it is an impossible.
void -> assump1: Let's assume that the bean is not a kind of a sucrose.; sent3 & assump1 -> int1: that the semaphore is not an impossible is not false.; int1 & sent7 -> int2: the semaphore is not inopportune.; void -> assump2: Let's assume that the semaphore is inopportune.; int2 & assump2 -> int3: this is contradiction.; [assump1] & int3 -> int4: that the bean is a sucrose hold.;
if the boffin is a kind of a Gambian it is an impossible.
sent10 -> hypothesis;
$hypothesis$ = the bean is Piagetian if the semaphore is inopportune. ; $context$ = sent1: the cotton is not inopportune. sent2: the fact that the semaphore is Piagetian hold if that it is an impossible hold. sent3: the fact that the semaphore is not impossible if the fact that the bean is not a sucrose is right hold. sent4: the daffodil does override escapee if it is not a lygaeid. sent5: the bean is inopportune if the fact that the semaphore is not an extinction and does slug chromium does not hold. sent6: the semaphore is not Piagetian if the bean is not an impossible. sent7: if the semaphore is not an impossible then it is not inopportune. sent8: if something is inopportune the fact that it is not a sucrose and it is not impossible is not right. sent9: the fact that if the semaphore is not the impossible the semaphore is inopportune is correct. sent10: if something is a Gambian it is an impossible. sent11: something is inopportune if it is an impossible. ; $proof$ = 
void -> assump1: Let's assume that the bean is not a kind of a sucrose.; sent3 & assump1 -> int1: that the semaphore is not an impossible is not false.; int1 & sent7 -> int2: the semaphore is not inopportune.; void -> assump2: Let's assume that the semaphore is inopportune.; int2 & assump2 -> int3: this is contradiction.; [assump1] & int3 -> int4: that the bean is a sucrose hold.; __UNKNOWN__