the foot is not unlike.
sent1: if the taffrail does not think attorneyship and it does not think taffrail then the hitchhiker is not a copyright. sent2: the lychgate is a kind of a reverse if the fact that the hitchhiker is anemographic is correct. sent3: something is anemographic if that it does not think taffrail and it does not copyright does not hold. sent4: the taffrail does not copyright if the obstruction is a kind of a vertex. sent5: the fact that the obstruction is both cardiopulmonary and reverse is not right. sent6: something that posts wetness is a copyright or not a choc or both. sent7: the obstruction does think attorneyship if it is a vertex. sent8: if the fact that the obstruction is not cardiopulmonary is right the lychgate is not a kind of a vertex and it is not anemographic. sent9: if the hitchhiker does not think attorneyship and it does not think taffrail then the foot is like. sent10: the hitchhiker does not think taffrail. sent11: if the lychgate is not anemographic then the foot is a kind of a reverse and it is unlike. sent12: if that something does not think attorneyship and does not think taffrail does not hold it is anemographic. sent13: if that the obstruction is cardiopulmonary but it is not a reverse is not correct then it is a vertex. sent14: the fact that the taffrail is a kind of a copyright is true.
sent12 -> int1: if that the hitchhiker does not think attorneyship and it does not think taffrail is not true it is anemographic.; void -> assump1: Let's assume that that the hitchhiker does not think attorneyship and it does not think taffrail is false.; int1 & assump1 -> int2: the hitchhiker is anemographic.; int2 & sent2 -> int3: the lychgate is reverse.;
the foot is unlike.
sent6 -> int4: the taffrail is a kind of a copyright and/or it is not a kind of a choc if it does post wetness.;
$hypothesis$ = the foot is not unlike. ; $context$ = sent1: if the taffrail does not think attorneyship and it does not think taffrail then the hitchhiker is not a copyright. sent2: the lychgate is a kind of a reverse if the fact that the hitchhiker is anemographic is correct. sent3: something is anemographic if that it does not think taffrail and it does not copyright does not hold. sent4: the taffrail does not copyright if the obstruction is a kind of a vertex. sent5: the fact that the obstruction is both cardiopulmonary and reverse is not right. sent6: something that posts wetness is a copyright or not a choc or both. sent7: the obstruction does think attorneyship if it is a vertex. sent8: if the fact that the obstruction is not cardiopulmonary is right the lychgate is not a kind of a vertex and it is not anemographic. sent9: if the hitchhiker does not think attorneyship and it does not think taffrail then the foot is like. sent10: the hitchhiker does not think taffrail. sent11: if the lychgate is not anemographic then the foot is a kind of a reverse and it is unlike. sent12: if that something does not think attorneyship and does not think taffrail does not hold it is anemographic. sent13: if that the obstruction is cardiopulmonary but it is not a reverse is not correct then it is a vertex. sent14: the fact that the taffrail is a kind of a copyright is true. ; $proof$ = 
sent12 -> int1: if that the hitchhiker does not think attorneyship and it does not think taffrail is not true it is anemographic.; void -> assump1: Let's assume that that the hitchhiker does not think attorneyship and it does not think taffrail is false.; int1 & assump1 -> int2: the hitchhiker is anemographic.; int2 & sent2 -> int3: the lychgate is reverse.; __UNKNOWN__