the insinuation does not occur.
sent1: that the spilling occurs is correct. sent2: either the shopping animosity or the lightedness or both occurs. sent3: the non-unresentfulness and the spill happens if the estimate does not occur. sent4: the dissolution does not occur if both the neap and the insinuation happens. sent5: if the fact that either the shopping journal does not occur or the ponderableness does not occur or both is not true then the estimate does not occur. sent6: if the unresentfulness does not occur the spilling and the dissolution happens. sent7: the unresentfulness does not occur and the estimate does not occur. sent8: if the lighted occurs the fact that the neap occurs is true. sent9: if the shopping animosity happens the neap occurs.
sent2 & sent9 & sent8 -> int1: the neap happens.; void -> assump1: Let's assume that the insinuation occurs.; int1 & assump1 -> int2: both the neap and the insinuation happens.; int2 & sent4 -> int3: the dissolution does not occur.; sent7 -> int4: the unresentfulness does not occur.; sent6 & int4 -> int5: both the spilling and the dissolution occurs.; int5 -> int6: the dissolution occurs.; int3 & int6 -> int7: this is contradiction.; [assump1] & int7 -> hypothesis;
the insinuation occurs.
$hypothesis$ = the insinuation does not occur. ; $context$ = sent1: that the spilling occurs is correct. sent2: either the shopping animosity or the lightedness or both occurs. sent3: the non-unresentfulness and the spill happens if the estimate does not occur. sent4: the dissolution does not occur if both the neap and the insinuation happens. sent5: if the fact that either the shopping journal does not occur or the ponderableness does not occur or both is not true then the estimate does not occur. sent6: if the unresentfulness does not occur the spilling and the dissolution happens. sent7: the unresentfulness does not occur and the estimate does not occur. sent8: if the lighted occurs the fact that the neap occurs is true. sent9: if the shopping animosity happens the neap occurs. ; $proof$ = 
sent2 & sent9 & sent8 -> int1: the neap happens.; void -> assump1: Let's assume that the insinuation occurs.; int1 & assump1 -> int2: both the neap and the insinuation happens.; int2 & sent4 -> int3: the dissolution does not occur.; sent7 -> int4: the unresentfulness does not occur.; sent6 & int4 -> int5: both the spilling and the dissolution occurs.; int5 -> int6: the dissolution occurs.; int3 & int6 -> int7: this is contradiction.; [assump1] & int7 -> hypothesis; __PROVED__