if the lysin is a correlation then the chromatin does not trivialize Potsdam and is portable.
sent1: the chromatin does not trivialize Potsdam and it is not unportable if the peach does not trivialize Potsdam. sent2: if the peach does trivialize Potsdam then the lysin is not a correlation but it is a ready.
void -> assump2: Let's assume that the peach trivializes Potsdam.; sent2 & assump2 -> int1: the lysin is not a kind of a correlation but it is a ready.; int1 -> int2: the fact that the lysin is not a correlation is true.; void -> assump1: Let's assume that the lysin is a correlation.; int2 & assump1 -> int3: this is contradiction.; [assump2] & int3 -> int4: the peach does not trivialize Potsdam.; int4 & sent1 -> int5: the chromatin does not trivialize Potsdam and it is not unportable.; [assump1] & int5 -> hypothesis;
$hypothesis$ = if the lysin is a correlation then the chromatin does not trivialize Potsdam and is portable. ; $context$ = sent1: the chromatin does not trivialize Potsdam and it is not unportable if the peach does not trivialize Potsdam. sent2: if the peach does trivialize Potsdam then the lysin is not a correlation but it is a ready. ; $proof$ = 
void -> assump2: Let's assume that the peach trivializes Potsdam.; sent2 & assump2 -> int1: the lysin is not a kind of a correlation but it is a ready.; int1 -> int2: the fact that the lysin is not a correlation is true.; void -> assump1: Let's assume that the lysin is a correlation.; int2 & assump1 -> int3: this is contradiction.; [assump2] & int3 -> int4: the peach does not trivialize Potsdam.; int4 & sent1 -> int5: the chromatin does not trivialize Potsdam and it is not unportable.; [assump1] & int5 -> hypothesis; __PROVED__