the Creek is hatless.
sent1: there exists something such that it is hatless. sent2: the fact that the pairing is lunisolar but it is not a nib does not hold if it does not gap. sent3: that the maple is a disassociation and zoological does not hold. sent4: that everything does overjoy is not incorrect. sent5: the Aborigine is an ai. sent6: if the fact that the fact that something is lunisolar but it is not a kind of a nib is not false does not hold that it is Alpine is not incorrect. sent7: there exists something such that it is a Wayland. sent8: if something is resinlike and it forays then it does not liquidize. sent9: that if the fact that something is a gap or it is not Alpine or both is false then it is hatless is correct. sent10: if the fact that the Creek does liquidize and it is a gap is not correct then the tideway does not gap. sent11: the maple is not zoological if the fact that it is a disassociation and it is zoological is not right. sent12: if the pairing is a nib it is Alpine. sent13: if there exists something such that it does not overjoy and is an ai that the pairing is not a kind of a Wayland is true. sent14: if the pairing is Alpine then the Creek is a Wayland. sent15: if that the maple is not zoological is not wrong the fact that the Aborigine does foray and is a memsahib is wrong. sent16: the pairing is not a kind of a gap. sent17: the cellar is a kind of a foray if that the frogmouth foray is not false. sent18: something is not a memsahib if that it is a memsahib and is non-zoological does not hold. sent19: if there exists something such that it overjoys then that the tideway is an ai and is not hatless is not true. sent20: the fact that the Creek liquidizes and is a kind of a gap is not correct if the Aborigine is not a memsahib. sent21: the frogmouth is a disassociation and/or a foray. sent22: if that the cellar does not liquidize is true the fact that the maple is a memsahib but it is not zoological is not true. sent23: the cellar is resinlike. sent24: the cellar is a foray if the frogmouth is a disassociation. sent25: if something is a Wayland that is hatless that the Aborigine is not an ai hold. sent26: something is not a memsahib if that it does foray and it is a memsahib does not hold.
sent2 & sent16 -> int1: that the pairing is a kind of lunisolar thing that is not a nib is wrong.; sent6 -> int2: if that the pairing is a kind of lunisolar thing that is not a kind of a nib does not hold then it is Alpine.; int1 & int2 -> int3: the pairing is Alpine.; int3 & sent14 -> int4: the fact that the Creek is a kind of a Wayland is not false.; void -> assump1: Let's assume that that the Creek is hatless is not wrong.; int4 & assump1 -> int5: the Creek is a Wayland and is hatless.; int5 -> int6: something is a Wayland and hatless.; int6 & sent25 -> int7: the Aborigine is not an ai.; int7 & sent5 -> int8: this is contradiction.; [assump1] & int8 -> hypothesis;
the fact that the Creek is not hatted is true.
sent9 -> int9: the Creek is hatless if the fact that either it is a kind of a gap or it is not Alpine or both is not right.; sent18 -> int10: the maple is not a memsahib if that it is a memsahib but not zoological is not true.; sent8 -> int11: if the cellar is resinlike and does foray it does not liquidize.; sent21 & sent24 & sent17 -> int12: the cellar does foray.; sent23 & int12 -> int13: the cellar is resinlike and it forays.; int11 & int13 -> int14: the cellar does not liquidize.; sent22 & int14 -> int15: that the maple is a memsahib but it is non-zoological is not right.; int10 & int15 -> int16: the maple is not a kind of a memsahib.; int16 -> int17: there is something such that that it is not a memsahib is right.;
$hypothesis$ = the Creek is hatless. ; $context$ = sent1: there exists something such that it is hatless. sent2: the fact that the pairing is lunisolar but it is not a nib does not hold if it does not gap. sent3: that the maple is a disassociation and zoological does not hold. sent4: that everything does overjoy is not incorrect. sent5: the Aborigine is an ai. sent6: if the fact that the fact that something is lunisolar but it is not a kind of a nib is not false does not hold that it is Alpine is not incorrect. sent7: there exists something such that it is a Wayland. sent8: if something is resinlike and it forays then it does not liquidize. sent9: that if the fact that something is a gap or it is not Alpine or both is false then it is hatless is correct. sent10: if the fact that the Creek does liquidize and it is a gap is not correct then the tideway does not gap. sent11: the maple is not zoological if the fact that it is a disassociation and it is zoological is not right. sent12: if the pairing is a nib it is Alpine. sent13: if there exists something such that it does not overjoy and is an ai that the pairing is not a kind of a Wayland is true. sent14: if the pairing is Alpine then the Creek is a Wayland. sent15: if that the maple is not zoological is not wrong the fact that the Aborigine does foray and is a memsahib is wrong. sent16: the pairing is not a kind of a gap. sent17: the cellar is a kind of a foray if that the frogmouth foray is not false. sent18: something is not a memsahib if that it is a memsahib and is non-zoological does not hold. sent19: if there exists something such that it overjoys then that the tideway is an ai and is not hatless is not true. sent20: the fact that the Creek liquidizes and is a kind of a gap is not correct if the Aborigine is not a memsahib. sent21: the frogmouth is a disassociation and/or a foray. sent22: if that the cellar does not liquidize is true the fact that the maple is a memsahib but it is not zoological is not true. sent23: the cellar is resinlike. sent24: the cellar is a foray if the frogmouth is a disassociation. sent25: if something is a Wayland that is hatless that the Aborigine is not an ai hold. sent26: something is not a memsahib if that it does foray and it is a memsahib does not hold. ; $proof$ = 
sent2 & sent16 -> int1: that the pairing is a kind of lunisolar thing that is not a nib is wrong.; sent6 -> int2: if that the pairing is a kind of lunisolar thing that is not a kind of a nib does not hold then it is Alpine.; int1 & int2 -> int3: the pairing is Alpine.; int3 & sent14 -> int4: the fact that the Creek is a kind of a Wayland is not false.; void -> assump1: Let's assume that that the Creek is hatless is not wrong.; int4 & assump1 -> int5: the Creek is a Wayland and is hatless.; int5 -> int6: something is a Wayland and hatless.; int6 & sent25 -> int7: the Aborigine is not an ai.; int7 & sent5 -> int8: this is contradiction.; [assump1] & int8 -> hypothesis; __DISPROVED__