the housekeeper is not a kind of a years.
sent1: if something is a years then the fact that it is a dictyosome and it is eparchial is not true. sent2: the housekeeper is not a dictyosome and is eparchial. sent3: the fact that the bigamist does survive but it does not enter is incorrect. sent4: that the housekeeper is a kind of a dictyosome and is eparchial is not right. sent5: the housekeeper is not a kind of a dictyosome. sent6: that that something is not a dictyosome but it is eparchial is incorrect if it is a years is not wrong. sent7: the fact that the housekeeper is not microscopic but it is a dictyosome is not right. sent8: that that the proliferation is not a years but it is eparchial is correct is not true if the bigamist rafters triangulation. sent9: if the housekeeper is a kind of a years the fact that it is a dictyosome and it is eparchial does not hold.
sent6 -> int1: the fact that the housekeeper is not a dictyosome but it is eparchial is wrong if it is a years.; void -> assump1: Let's assume that the housekeeper is a years.; int1 & assump1 -> int2: the fact that the housekeeper is not a dictyosome and is eparchial is not correct.; int2 & sent2 -> int3: this is contradiction.; [assump1] & int3 -> hypothesis;
the housekeeper is a years.
sent3 -> int4: there exists something such that that it does survive and it does not enter does not hold.;
$hypothesis$ = the housekeeper is not a kind of a years. ; $context$ = sent1: if something is a years then the fact that it is a dictyosome and it is eparchial is not true. sent2: the housekeeper is not a dictyosome and is eparchial. sent3: the fact that the bigamist does survive but it does not enter is incorrect. sent4: that the housekeeper is a kind of a dictyosome and is eparchial is not right. sent5: the housekeeper is not a kind of a dictyosome. sent6: that that something is not a dictyosome but it is eparchial is incorrect if it is a years is not wrong. sent7: the fact that the housekeeper is not microscopic but it is a dictyosome is not right. sent8: that that the proliferation is not a years but it is eparchial is correct is not true if the bigamist rafters triangulation. sent9: if the housekeeper is a kind of a years the fact that it is a dictyosome and it is eparchial does not hold. ; $proof$ = 
sent6 -> int1: the fact that the housekeeper is not a dictyosome but it is eparchial is wrong if it is a years.; void -> assump1: Let's assume that the housekeeper is a years.; int1 & assump1 -> int2: the fact that the housekeeper is not a dictyosome and is eparchial is not correct.; int2 & sent2 -> int3: this is contradiction.; [assump1] & int3 -> hypothesis; __PROVED__