the burrow is not an oligopoly.
sent1: if the limestone is not telegraphic then the fact that it is intangible and it is prenuptial does not hold. sent2: the limestone is a kind of an oligopoly if something is an intangible and it is prenuptial. sent3: something is an intangible if it is prenuptial. sent4: that something is both not an oligopoly and not a motorcycling is incorrect if that it is not a flak is not incorrect. sent5: if there is something such that it is a kind of a motorcycling and is a flak that the limestone is prenuptial is not incorrect. sent6: there is something such that it is a kind of a motorcycling and it is a flak. sent7: if something is prenuptial then it is an oligopoly. sent8: if the limestone is a kind of an intangible and/or it is telegraphic the burrow is not a kind of an oligopoly.
sent6 & sent5 -> int1: the limestone is prenuptial.; sent3 -> int2: the limestone is an intangible if it is not non-prenuptial.; int1 & int2 -> int3: the limestone is a kind of an intangible.; int3 -> int4: the limestone is an intangible and/or it is telegraphic.; int4 & sent8 -> hypothesis;
the NAD is a kind of an oligopoly.
$hypothesis$ = the burrow is not an oligopoly. ; $context$ = sent1: if the limestone is not telegraphic then the fact that it is intangible and it is prenuptial does not hold. sent2: the limestone is a kind of an oligopoly if something is an intangible and it is prenuptial. sent3: something is an intangible if it is prenuptial. sent4: that something is both not an oligopoly and not a motorcycling is incorrect if that it is not a flak is not incorrect. sent5: if there is something such that it is a kind of a motorcycling and is a flak that the limestone is prenuptial is not incorrect. sent6: there is something such that it is a kind of a motorcycling and it is a flak. sent7: if something is prenuptial then it is an oligopoly. sent8: if the limestone is a kind of an intangible and/or it is telegraphic the burrow is not a kind of an oligopoly. ; $proof$ = 
sent6 & sent5 -> int1: the limestone is prenuptial.; sent3 -> int2: the limestone is an intangible if it is not non-prenuptial.; int1 & int2 -> int3: the limestone is a kind of an intangible.; int3 -> int4: the limestone is an intangible and/or it is telegraphic.; int4 & sent8 -> hypothesis; __PROVED__