that the oakum is not an outboard and it does not page miscegenation is false.
sent1: the oakum is not grapelike. sent2: the miscegenation is an outboard. sent3: the fact that something is a kind of a sideshow but it is not outboard is incorrect if the fact that it does page muzhik is right. sent4: the miscegenation is inshore. sent5: the miscegenation detoxes and it does page muzhik if it is not a sideshow. sent6: the miscegenation is not a sideshow. sent7: that something is not a kind of an outboard and it does not page miscegenation is incorrect if it is inshore. sent8: if the oakum does page miscegenation that it is not a kind of a sideshow and it is not inshore does not hold. sent9: the oakum does not page miscegenation and it is not a sideshow if it does not congratulate headmistressship. sent10: if the miscegenation pages muzhik the oakum is inshore.
sent5 & sent6 -> int1: the miscegenation detoxes and it pages muzhik.; int1 -> int2: the miscegenation does page muzhik.; int2 & sent10 -> int3: the oakum is inshore.; sent7 -> int4: if the oakum is inshore the fact that it is non-outboard thing that does not page miscegenation does not hold.; int3 & int4 -> hypothesis;
the oakum is not an outboard and does not page miscegenation.
$hypothesis$ = that the oakum is not an outboard and it does not page miscegenation is false. ; $context$ = sent1: the oakum is not grapelike. sent2: the miscegenation is an outboard. sent3: the fact that something is a kind of a sideshow but it is not outboard is incorrect if the fact that it does page muzhik is right. sent4: the miscegenation is inshore. sent5: the miscegenation detoxes and it does page muzhik if it is not a sideshow. sent6: the miscegenation is not a sideshow. sent7: that something is not a kind of an outboard and it does not page miscegenation is incorrect if it is inshore. sent8: if the oakum does page miscegenation that it is not a kind of a sideshow and it is not inshore does not hold. sent9: the oakum does not page miscegenation and it is not a sideshow if it does not congratulate headmistressship. sent10: if the miscegenation pages muzhik the oakum is inshore. ; $proof$ = 
sent5 & sent6 -> int1: the miscegenation detoxes and it pages muzhik.; int1 -> int2: the miscegenation does page muzhik.; int2 & sent10 -> int3: the oakum is inshore.; sent7 -> int4: if the oakum is inshore the fact that it is non-outboard thing that does not page miscegenation does not hold.; int3 & int4 -> hypothesis; __PROVED__