there exists something such that it is not a transplanter.
sent1: if something that is a transplanter meets antelope it is not a Hawaiian. sent2: the fact that the holmium is both not calculous and non-home is incorrect. sent3: the fact that the holmium is both not a commensal and not non-calculous is not correct if there is something such that that it meets antelope hold. sent4: that the andesite is not a Ethiopian and not home is not correct. sent5: The antelope does meet stoma. sent6: something is not calculous if it does meet northernness and is a transplanter. sent7: the stoma does meet antelope. sent8: if something is a transplanter and meets northernness it is not Hawaiian. sent9: the fact that the leash is a Hawaiian is not wrong if the sink is simple. sent10: that either something does not meet northernness or it is not non-Hawaiian or both is not correct if it is not a transplanter. sent11: the ohmage does meet northernness if the leash is a Hawaiian. sent12: there exists something such that the fact that it is a Ethiopian and does not home is false. sent13: the sink is a simple if there is something such that that it is both not Ethiopian and not a home is incorrect. sent14: the fact that the holmium is not commensal and it is not calculous is false if something meets antelope. sent15: if something is a kind of a home the sink is simple.
sent4 -> int1: there exists something such that that it is not a kind of a Ethiopian and it does not home is not correct.; int1 & sent13 -> int2: the sink is simple.; int2 & sent9 -> int3: the leash is Hawaiian.; int3 & sent11 -> int4: the ohmage does meet northernness.; void -> assump1: Let's assume that the ohmage is a transplanter.; int4 & assump1 -> int5: the ohmage meets northernness and it is a kind of a transplanter.; sent6 -> int6: if the ohmage does meet northernness and is a transplanter it is not calculous.; int5 & int6 -> int7: the ohmage is not calculous.; sent7 -> int8: there exists something such that it does meet antelope.; int8 & sent14 -> int9: that the holmium is both not a commensal and not calculous is incorrect.; int9 -> int10: there exists something such that the fact that it is both not a commensal and not calculous is not right.;
the rathole is not a simple.
sent10 -> int11: if the sink is not a transplanter the fact that it does not meet northernness and/or it is a Hawaiian is not right.;
$hypothesis$ = there exists something such that it is not a transplanter. ; $context$ = sent1: if something that is a transplanter meets antelope it is not a Hawaiian. sent2: the fact that the holmium is both not calculous and non-home is incorrect. sent3: the fact that the holmium is both not a commensal and not non-calculous is not correct if there is something such that that it meets antelope hold. sent4: that the andesite is not a Ethiopian and not home is not correct. sent5: The antelope does meet stoma. sent6: something is not calculous if it does meet northernness and is a transplanter. sent7: the stoma does meet antelope. sent8: if something is a transplanter and meets northernness it is not Hawaiian. sent9: the fact that the leash is a Hawaiian is not wrong if the sink is simple. sent10: that either something does not meet northernness or it is not non-Hawaiian or both is not correct if it is not a transplanter. sent11: the ohmage does meet northernness if the leash is a Hawaiian. sent12: there exists something such that the fact that it is a Ethiopian and does not home is false. sent13: the sink is a simple if there is something such that that it is both not Ethiopian and not a home is incorrect. sent14: the fact that the holmium is not commensal and it is not calculous is false if something meets antelope. sent15: if something is a kind of a home the sink is simple. ; $proof$ = 
sent4 -> int1: there exists something such that that it is not a kind of a Ethiopian and it does not home is not correct.; int1 & sent13 -> int2: the sink is simple.; int2 & sent9 -> int3: the leash is Hawaiian.; int3 & sent11 -> int4: the ohmage does meet northernness.; void -> assump1: Let's assume that the ohmage is a transplanter.; int4 & assump1 -> int5: the ohmage meets northernness and it is a kind of a transplanter.; sent6 -> int6: if the ohmage does meet northernness and is a transplanter it is not calculous.; int5 & int6 -> int7: the ohmage is not calculous.; sent7 -> int8: there exists something such that it does meet antelope.; int8 & sent14 -> int9: that the holmium is both not a commensal and not calculous is incorrect.; int9 -> int10: there exists something such that the fact that it is both not a commensal and not calculous is not right.; __UNKNOWN__