the elimination does not melanize cot.
sent1: there is something such that that it is methodological and/or it is not a N is not true. sent2: the mango is a kind of a parry but it is not orthodontic. sent3: the fact that if something does not melanize austereness then the fact that it is not modifiable but a N does not hold is true. sent4: that the mango is unmodifiable is not wrong if it is a parry that is orthodontic. sent5: the elimination does stand if there is something such that that it is not methodological or it is a N or both does not hold. sent6: the fact that the reenactor is not methodological or is not a kind of a N or both does not hold if the mango is not a N. sent7: the mango does not melanize austereness and is not a Beckley. sent8: something melanizes cot if it is a kind of a stand. sent9: if there exists something such that that it is not methodological or it is not a N or both is not true the elimination is a stand. sent10: if the mango parries but it is not orthodontic then it is not modifiable. sent11: the elimination does not melanize cot if the mango does not melanize cot and is not unmodifiable.
sent10 & sent2 -> int1: the mango is not modifiable.; void -> assump1: Let's assume that the mango is a kind of a N.; int1 & assump1 -> int2: the mango is non-modifiable thing that is a N.; sent3 -> int3: that the mango is unmodifiable a N does not hold if it does not melanize austereness.; sent7 -> int4: the mango does not melanize austereness.; int3 & int4 -> int5: that the mango is not modifiable but it is a N is incorrect.; int2 & int5 -> int6: this is contradiction.; [assump1] & int6 -> int7: the mango is not a N.; int7 & sent6 -> int8: the fact that either the reenactor is not methodological or it is not a N or both is not correct.; int8 -> int9: there is something such that the fact that it is not methodological or it is not a N or both is not true.; int9 & sent9 -> int10: the elimination is a stand.; sent8 -> int11: if the fact that the elimination is a stand hold it does melanize cot.; int10 & int11 -> hypothesis;
that the elimination does not melanize cot is not false.
$hypothesis$ = the elimination does not melanize cot. ; $context$ = sent1: there is something such that that it is methodological and/or it is not a N is not true. sent2: the mango is a kind of a parry but it is not orthodontic. sent3: the fact that if something does not melanize austereness then the fact that it is not modifiable but a N does not hold is true. sent4: that the mango is unmodifiable is not wrong if it is a parry that is orthodontic. sent5: the elimination does stand if there is something such that that it is not methodological or it is a N or both does not hold. sent6: the fact that the reenactor is not methodological or is not a kind of a N or both does not hold if the mango is not a N. sent7: the mango does not melanize austereness and is not a Beckley. sent8: something melanizes cot if it is a kind of a stand. sent9: if there exists something such that that it is not methodological or it is not a N or both is not true the elimination is a stand. sent10: if the mango parries but it is not orthodontic then it is not modifiable. sent11: the elimination does not melanize cot if the mango does not melanize cot and is not unmodifiable. ; $proof$ = 
sent10 & sent2 -> int1: the mango is not modifiable.; void -> assump1: Let's assume that the mango is a kind of a N.; int1 & assump1 -> int2: the mango is non-modifiable thing that is a N.; sent3 -> int3: that the mango is unmodifiable a N does not hold if it does not melanize austereness.; sent7 -> int4: the mango does not melanize austereness.; int3 & int4 -> int5: that the mango is not modifiable but it is a N is incorrect.; int2 & int5 -> int6: this is contradiction.; [assump1] & int6 -> int7: the mango is not a N.; int7 & sent6 -> int8: the fact that either the reenactor is not methodological or it is not a N or both is not correct.; int8 -> int9: there is something such that the fact that it is not methodological or it is not a N or both is not true.; int9 & sent9 -> int10: the elimination is a stand.; sent8 -> int11: if the fact that the elimination is a stand hold it does melanize cot.; int10 & int11 -> hypothesis; __DISPROVED__