the remedy does not daub.
sent1: the bearskin is a kind of cerebral thing that is not a daub. sent2: the remedy does daub if something that is cerebral does not forget. sent3: the bearskin does forget or it apologizes or both if something is cerebral. sent4: if something acquaints Bohr then it is cerebral thing that does not forget. sent5: something is not a kind of a valvule. sent6: there exists something such that the fact that it does not exacerbate hold. sent7: if there exists something such that it does not exacerbate then that the remedy is both a daub and non-cerebral does not hold. sent8: if that the remedy is a daub but it is not cerebral is not correct it is cerebral. sent9: if there exists something such that it is not a kind of a valvule then the bearskin does acquaint Bohr.
sent5 & sent9 -> int1: the bearskin acquaints Bohr.; sent4 -> int2: if the bearskin acquaints Bohr then it is cerebral and does not forget.; int1 & int2 -> int3: the bearskin is cerebral thing that does not forget.; int3 -> int4: there exists something such that it is cerebral and it does not forget.; int4 & sent2 -> hypothesis;
the gynecologist does apologize and is not a kind of a Utopian.
sent6 & sent7 -> int5: that that the remedy is a daub but it is not cerebral is not incorrect is not true.; sent8 & int5 -> int6: the remedy is cerebral.; int6 -> int7: something is cerebral.; int7 & sent3 -> int8: the fact that the bearskin forgets or it apologizes or both is correct.;
$hypothesis$ = the remedy does not daub. ; $context$ = sent1: the bearskin is a kind of cerebral thing that is not a daub. sent2: the remedy does daub if something that is cerebral does not forget. sent3: the bearskin does forget or it apologizes or both if something is cerebral. sent4: if something acquaints Bohr then it is cerebral thing that does not forget. sent5: something is not a kind of a valvule. sent6: there exists something such that the fact that it does not exacerbate hold. sent7: if there exists something such that it does not exacerbate then that the remedy is both a daub and non-cerebral does not hold. sent8: if that the remedy is a daub but it is not cerebral is not correct it is cerebral. sent9: if there exists something such that it is not a kind of a valvule then the bearskin does acquaint Bohr. ; $proof$ = 
sent5 & sent9 -> int1: the bearskin acquaints Bohr.; sent4 -> int2: if the bearskin acquaints Bohr then it is cerebral and does not forget.; int1 & int2 -> int3: the bearskin is cerebral thing that does not forget.; int3 -> int4: there exists something such that it is cerebral and it does not forget.; int4 & sent2 -> hypothesis; __DISPROVED__