that the ravine is not a kind of a lichen and is not stemless is not right.
sent1: the drainplug is not Orthodox if the honoree settles Lucullus. sent2: the ravine is leafy. sent3: if the ravine is not a lichen and not stemless the honoree is Orthodox. sent4: that the ravine is a lichen but it is not stemless is false. sent5: the drainplug is aperiodic but it does not settle Lucullus if the honoree is Orthodox. sent6: the fact that the syncretism is non-leafy thing that settles Lucullus is not right. sent7: the drainplug does not settle Lucullus. sent8: if the syncretism is leafy and does not settle Lucullus then the ravine is stemless. sent9: if the ravine is a lichen and not stemless then the honoree is Orthodox. sent10: the ravine is leafy but it is not a lichen. sent11: the ravine is not a lichen. sent12: that the honoree is not Orthodox but it is a lichen is incorrect. sent13: if the honoree is Orthodox then the drainplug does not settle Lucullus. sent14: if the syncretism settles Lucullus and it is leafy the ravine is not a lichen. sent15: if the drainplug is a kind of aperiodic thing that is not a lichen then the ravine is not stemless. sent16: the drainplug is not stemless if the ravine settles Lucullus. sent17: the syncretism is not aperiodic. sent18: the syncretism is leafy. sent19: the fact that the syncretism is not leafy is correct if the drainplug is a kind of aperiodic thing that does settle Lucullus. sent20: the ravine is not Orthodox and is not a lichen. sent21: the ravine is stemless if the syncretism is not leafy but it settles Lucullus. sent22: if the honoree does settle Lucullus but it is not aperiodic the drainplug is Orthodox. sent23: the syncretism settles ravine.
void -> assump1: Let's assume that the ravine is both not a lichen and not stemless.; sent3 & assump1 -> int1: the honoree is Orthodox.; int1 & sent5 -> int2: the drainplug is aperiodic and does not settle Lucullus.;
$hypothesis$ = that the ravine is not a kind of a lichen and is not stemless is not right. ; $context$ = sent1: the drainplug is not Orthodox if the honoree settles Lucullus. sent2: the ravine is leafy. sent3: if the ravine is not a lichen and not stemless the honoree is Orthodox. sent4: that the ravine is a lichen but it is not stemless is false. sent5: the drainplug is aperiodic but it does not settle Lucullus if the honoree is Orthodox. sent6: the fact that the syncretism is non-leafy thing that settles Lucullus is not right. sent7: the drainplug does not settle Lucullus. sent8: if the syncretism is leafy and does not settle Lucullus then the ravine is stemless. sent9: if the ravine is a lichen and not stemless then the honoree is Orthodox. sent10: the ravine is leafy but it is not a lichen. sent11: the ravine is not a lichen. sent12: that the honoree is not Orthodox but it is a lichen is incorrect. sent13: if the honoree is Orthodox then the drainplug does not settle Lucullus. sent14: if the syncretism settles Lucullus and it is leafy the ravine is not a lichen. sent15: if the drainplug is a kind of aperiodic thing that is not a lichen then the ravine is not stemless. sent16: the drainplug is not stemless if the ravine settles Lucullus. sent17: the syncretism is not aperiodic. sent18: the syncretism is leafy. sent19: the fact that the syncretism is not leafy is correct if the drainplug is a kind of aperiodic thing that does settle Lucullus. sent20: the ravine is not Orthodox and is not a lichen. sent21: the ravine is stemless if the syncretism is not leafy but it settles Lucullus. sent22: if the honoree does settle Lucullus but it is not aperiodic the drainplug is Orthodox. sent23: the syncretism settles ravine. ; $proof$ = 
void -> assump1: Let's assume that the ravine is both not a lichen and not stemless.; sent3 & assump1 -> int1: the honoree is Orthodox.; int1 & sent5 -> int2: the drainplug is aperiodic and does not settle Lucullus.; __UNKNOWN__