that if the mystifying circumstance occurs not the delegating but the entrenching countersuit occurs is false.
sent1: that the entrenching countersuit does not occur is prevented by that the scentlessness but not the jazzing ticket happens. sent2: if the waterspout occurs then the travelogue does not occur and the unfriendliness occurs. sent3: that the mystifying circumstance does not occur and the delegating does not occur yields the non-mnemonicness. sent4: if the scentlessness does not occur and the jazzing ticket does not occur then the entrenching countersuit occurs. sent5: the scentlessness does not occur and the jazzing ticket does not occur. sent6: the acidimetricness does not occur if both the unrestrictiveness and the stream occurs. sent7: if the mnemonic does not occur then the bit happens and the wresting vernacular occurs. sent8: the mnemonicness occurs. sent9: the fact that the mystifying circumstance occurs is correct if the mnemonic and the delegating happens. sent10: the scentlessness does not occur. sent11: if the mnemonic occurs and the delegating happens then the mystifying circumstance does not occur.
void -> assump1: Let's assume that the delegating happens.; sent8 & assump1 -> int1: both the mnemonic and the delegating happens.; int1 & sent11 -> int2: the mystifying circumstance does not occur.; void -> assump2: Let's assume that the mystifying circumstance happens.; int2 & assump2 -> int3: this is contradiction.; [assump1] & int3 -> int4: the delegating does not occur.; sent4 & sent5 -> int5: the entrenching countersuit happens.; int4 & int5 -> int6: not the delegating but the entrenching countersuit happens.; [assump2] & int6 -> hypothesis;
both the bit and the wresting vernacular happens.
$hypothesis$ = that if the mystifying circumstance occurs not the delegating but the entrenching countersuit occurs is false. ; $context$ = sent1: that the entrenching countersuit does not occur is prevented by that the scentlessness but not the jazzing ticket happens. sent2: if the waterspout occurs then the travelogue does not occur and the unfriendliness occurs. sent3: that the mystifying circumstance does not occur and the delegating does not occur yields the non-mnemonicness. sent4: if the scentlessness does not occur and the jazzing ticket does not occur then the entrenching countersuit occurs. sent5: the scentlessness does not occur and the jazzing ticket does not occur. sent6: the acidimetricness does not occur if both the unrestrictiveness and the stream occurs. sent7: if the mnemonic does not occur then the bit happens and the wresting vernacular occurs. sent8: the mnemonicness occurs. sent9: the fact that the mystifying circumstance occurs is correct if the mnemonic and the delegating happens. sent10: the scentlessness does not occur. sent11: if the mnemonic occurs and the delegating happens then the mystifying circumstance does not occur. ; $proof$ = 
void -> assump1: Let's assume that the delegating happens.; sent8 & assump1 -> int1: both the mnemonic and the delegating happens.; int1 & sent11 -> int2: the mystifying circumstance does not occur.; void -> assump2: Let's assume that the mystifying circumstance happens.; int2 & assump2 -> int3: this is contradiction.; [assump1] & int3 -> int4: the delegating does not occur.; sent4 & sent5 -> int5: the entrenching countersuit happens.; int4 & int5 -> int6: not the delegating but the entrenching countersuit happens.; [assump2] & int6 -> hypothesis; __DISPROVED__