that the sedimenting Bakelite does not occur is right.
sent1: the Namibianness does not occur and the networking illustration does not occur if the set-to does not occur. sent2: the networking illustration occurs. sent3: the trading occurs and the networking reagin occurs. sent4: that the trading happens and the sedimenting Bakelite occurs triggers that the set-to does not occur.
sent3 -> int1: the trading happens.; void -> assump1: Let's assume that the sedimenting Bakelite happens.; int1 & assump1 -> int2: both the trading and the sedimenting Bakelite happens.; int2 & sent4 -> int3: the set-to does not occur.; int3 & sent1 -> int4: the Namibian does not occur and the networking illustration does not occur.; int4 -> int5: that the networking illustration does not occur is correct.; int5 & sent2 -> int6: this is contradiction.; [assump1] & int6 -> hypothesis;
$hypothesis$ = that the sedimenting Bakelite does not occur is right. ; $context$ = sent1: the Namibianness does not occur and the networking illustration does not occur if the set-to does not occur. sent2: the networking illustration occurs. sent3: the trading occurs and the networking reagin occurs. sent4: that the trading happens and the sedimenting Bakelite occurs triggers that the set-to does not occur. ; $proof$ = 
sent3 -> int1: the trading happens.; void -> assump1: Let's assume that the sedimenting Bakelite happens.; int1 & assump1 -> int2: both the trading and the sedimenting Bakelite happens.; int2 & sent4 -> int3: the set-to does not occur.; int3 & sent1 -> int4: the Namibian does not occur and the networking illustration does not occur.; int4 -> int5: that the networking illustration does not occur is correct.; int5 & sent2 -> int6: this is contradiction.; [assump1] & int6 -> hypothesis; __PROVED__