the ptomaine does resent escadrille and does parallel Buchner.
sent1: something parallels eyeshadow. sent2: that the dacha does not overbear press is not false. sent3: if the fact that the juror is not fewer and it is not instructional is not right then the grume is a E. sent4: if the ptomaine is fewer it does parallel Buchner. sent5: the ptomaine is fewer if the fact that the dacha is fewer is true. sent6: if there exists something such that it does parallel eyeshadow then the ptomaine is not a E. sent7: if the dacha does not parallel eyeshadow it does not parallel Buchner. sent8: that something is both not fewer and not instructional is not correct if it trespasses. sent9: the ptomaine is fewer if the dacha trespasses. sent10: if the fact that the grume either does parallel eyeshadow or is not a kind of a synergy or both does not hold the dacha does not parallel eyeshadow. sent11: either the dacha is fewer or it trespasses or both. sent12: something resents escadrille if it is a synergy. sent13: there exists nothing such that it is not a kind of a E and is not a kind of a synergy. sent14: the deuterium is a E and it riots.
sent1 & sent6 -> int1: the ptomaine is not a E.; void -> assump1: Let's assume that the ptomaine is not a synergy.; int1 & assump1 -> int2: the ptomaine is both not a E and not a synergy.; sent13 -> int3: that the fact that the ptomaine is not a kind of a E and is not a synergy is false is true.; int2 & int3 -> int4: this is contradiction.; [assump1] & int4 -> int5: the ptomaine is a kind of a synergy.; sent12 -> int6: the ptomaine resents escadrille if it is a synergy.; int5 & int6 -> int7: the ptomaine does resent escadrille.; sent11 & sent5 & sent9 -> int8: that the ptomaine is fewer is correct.; sent4 & int8 -> int9: the ptomaine parallels Buchner.; int7 & int9 -> hypothesis;
that the ptomaine does resent escadrille and it does parallel Buchner is false.
sent8 -> int10: if the juror is a trespass that it is both non-fewer and not instructional is incorrect.;
$hypothesis$ = the ptomaine does resent escadrille and does parallel Buchner. ; $context$ = sent1: something parallels eyeshadow. sent2: that the dacha does not overbear press is not false. sent3: if the fact that the juror is not fewer and it is not instructional is not right then the grume is a E. sent4: if the ptomaine is fewer it does parallel Buchner. sent5: the ptomaine is fewer if the fact that the dacha is fewer is true. sent6: if there exists something such that it does parallel eyeshadow then the ptomaine is not a E. sent7: if the dacha does not parallel eyeshadow it does not parallel Buchner. sent8: that something is both not fewer and not instructional is not correct if it trespasses. sent9: the ptomaine is fewer if the dacha trespasses. sent10: if the fact that the grume either does parallel eyeshadow or is not a kind of a synergy or both does not hold the dacha does not parallel eyeshadow. sent11: either the dacha is fewer or it trespasses or both. sent12: something resents escadrille if it is a synergy. sent13: there exists nothing such that it is not a kind of a E and is not a kind of a synergy. sent14: the deuterium is a E and it riots. ; $proof$ = 
sent1 & sent6 -> int1: the ptomaine is not a E.; void -> assump1: Let's assume that the ptomaine is not a synergy.; int1 & assump1 -> int2: the ptomaine is both not a E and not a synergy.; sent13 -> int3: that the fact that the ptomaine is not a kind of a E and is not a synergy is false is true.; int2 & int3 -> int4: this is contradiction.; [assump1] & int4 -> int5: the ptomaine is a kind of a synergy.; sent12 -> int6: the ptomaine resents escadrille if it is a synergy.; int5 & int6 -> int7: the ptomaine does resent escadrille.; sent11 & sent5 & sent9 -> int8: that the ptomaine is fewer is correct.; sent4 & int8 -> int9: the ptomaine parallels Buchner.; int7 & int9 -> hypothesis; __PROVED__