the barking pronghorn does not occur.
sent1: that the bypassing liza does not occur is prevented by that the twining Romansh happens. sent2: if the stoning does not occur then both the empiricness and the sowing occurs. sent3: the barking pronghorn happens if that the bypassing liza does not occur and/or the testing occurs is false. sent4: the bypassing guide happens if the twining hairball occurs. sent5: the testing does not occur if the twining Romansh does not occur and the improbableness does not occur. sent6: the twining Romansh does not occur. sent7: if the empiricness and the bypassing guide happens the barking pronghorn does not occur. sent8: the testing happens. sent9: the bypassing liza occurs if that the twining Romansh does not occur and the improbableness does not occur does not hold. sent10: the fact that both the twining Romansh and the probableness happens is wrong. sent11: the stoning does not occur. sent12: the turbulence is brought about by that the emergency occurs. sent13: that the sow happens is caused by that the stoning does not occur. sent14: the testing does not occur if the twining Romansh occurs and the improbableness does not occur.
void -> assump1: Let's assume that the twining Romansh does not occur and the improbableness does not occur.; sent5 & assump1 -> int1: the testing does not occur.; int1 & sent8 -> int2: this is contradiction.; [assump1] & int2 -> int3: that the twining Romansh does not occur and the improbableness does not occur is incorrect.; int3 & sent9 -> int4: the bypassing liza happens.; sent2 & sent11 -> int5: both the empiricness and the sowing happens.; int5 -> int6: the empiricness happens.;
the barking pronghorn occurs.
$hypothesis$ = the barking pronghorn does not occur. ; $context$ = sent1: that the bypassing liza does not occur is prevented by that the twining Romansh happens. sent2: if the stoning does not occur then both the empiricness and the sowing occurs. sent3: the barking pronghorn happens if that the bypassing liza does not occur and/or the testing occurs is false. sent4: the bypassing guide happens if the twining hairball occurs. sent5: the testing does not occur if the twining Romansh does not occur and the improbableness does not occur. sent6: the twining Romansh does not occur. sent7: if the empiricness and the bypassing guide happens the barking pronghorn does not occur. sent8: the testing happens. sent9: the bypassing liza occurs if that the twining Romansh does not occur and the improbableness does not occur does not hold. sent10: the fact that both the twining Romansh and the probableness happens is wrong. sent11: the stoning does not occur. sent12: the turbulence is brought about by that the emergency occurs. sent13: that the sow happens is caused by that the stoning does not occur. sent14: the testing does not occur if the twining Romansh occurs and the improbableness does not occur. ; $proof$ = 
void -> assump1: Let's assume that the twining Romansh does not occur and the improbableness does not occur.; sent5 & assump1 -> int1: the testing does not occur.; int1 & sent8 -> int2: this is contradiction.; [assump1] & int2 -> int3: that the twining Romansh does not occur and the improbableness does not occur is incorrect.; int3 & sent9 -> int4: the bypassing liza happens.; sent2 & sent11 -> int5: both the empiricness and the sowing happens.; int5 -> int6: the empiricness happens.; __UNKNOWN__