if the blueberry is a Pempheridae then the lapdog is different.
sent1: the lapdog is different if it is a quack. sent2: the fact that if the lapdog is prosthodontics and it is different the blueberry does not overbear iterative is true. sent3: something is a quack if it is not astrocytic. sent4: the blueberry is incompatible if it does overbear iterative. sent5: something is incompatible if the fact that it is prosthodontics thing that does not overbear iterative is not true. sent6: that the blueberry is a kind of prosthodontics thing that does not overbear iterative is false. sent7: if the blueberry is a Pempheridae and is incompatible the lapdog is not astrocytic.
sent5 -> int1: if that the blueberry is prosthodontics but it does not overbear iterative is not right then it is incompatible.; int1 & sent6 -> int2: the fact that the blueberry is incompatible is not false.; void -> assump1: Let's assume that the blueberry is a Pempheridae.; int2 & assump1 -> int3: the blueberry is both a Pempheridae and incompatible.; int3 & sent7 -> int4: the lapdog is not astrocytic.; sent3 -> int5: the lapdog is a quack if it is not astrocytic.; int4 & int5 -> int6: the lapdog is a quack.; int6 & sent1 -> int7: the lapdog is different.; [assump1] & int7 -> hypothesis;
$hypothesis$ = if the blueberry is a Pempheridae then the lapdog is different. ; $context$ = sent1: the lapdog is different if it is a quack. sent2: the fact that if the lapdog is prosthodontics and it is different the blueberry does not overbear iterative is true. sent3: something is a quack if it is not astrocytic. sent4: the blueberry is incompatible if it does overbear iterative. sent5: something is incompatible if the fact that it is prosthodontics thing that does not overbear iterative is not true. sent6: that the blueberry is a kind of prosthodontics thing that does not overbear iterative is false. sent7: if the blueberry is a Pempheridae and is incompatible the lapdog is not astrocytic. ; $proof$ = 
sent5 -> int1: if that the blueberry is prosthodontics but it does not overbear iterative is not right then it is incompatible.; int1 & sent6 -> int2: the fact that the blueberry is incompatible is not false.; void -> assump1: Let's assume that the blueberry is a Pempheridae.; int2 & assump1 -> int3: the blueberry is both a Pempheridae and incompatible.; int3 & sent7 -> int4: the lapdog is not astrocytic.; sent3 -> int5: the lapdog is a quack if it is not astrocytic.; int4 & int5 -> int6: the lapdog is a quack.; int6 & sent1 -> int7: the lapdog is different.; [assump1] & int7 -> hypothesis; __PROVED__