the Manhattan does not segregate match.
sent1: the emcee is a kind of a Italic and it does swap. sent2: if the Manhattan does swap it does not segregate match. sent3: something that is not a Amaranthus does flock burden. sent4: if the emcee does not segregate match the Manhattan segregate match and does stuff. sent5: there exists nothing that does not dado Tyler and is a eruditeness. sent6: the Manhattan is a kind of a eruditeness. sent7: the snuffers does not segregate match. sent8: if the potluck is not a Amaranthus it does not segregate match and does not swap. sent9: the Manhattan is a kind of a stuff that does dado Tyler. sent10: the emcee is a Amaranthus. sent11: if something does not segregate match and it does not swap it is not a kind of a Italic. sent12: the Manhattan is a eruditeness if the perennial does not segregate match. sent13: the perennial does not flock burden if that it does not dado Tyler and it is a kind of a eruditeness is incorrect. sent14: if the perennial is not a eruditeness then it does not flock burden. sent15: the emcee is a gut. sent16: the Manhattan is not a kind of a Italic. sent17: if the emcee is a Italic and it segregates match the perennial is not a kind of a Amaranthus. sent18: that the emcee segregates match and flocks burden is not right. sent19: the Manhattan does dado Tyler. sent20: something does flock burden if it does not segregate match.
sent1 -> int1: the emcee is a kind of a Italic.; void -> assump1: Let's assume that the emcee does segregate match.; int1 & assump1 -> int2: the emcee is a kind of a Italic and it does segregate match.; int2 & sent17 -> int3: that the perennial is a Amaranthus is wrong.; sent3 -> int4: the perennial flocks burden if it is not a Amaranthus.; int3 & int4 -> int5: the perennial does flock burden.; sent5 -> int6: the fact that the perennial does not dado Tyler but it is a eruditeness is false.; sent13 & int6 -> int7: the perennial does not flock burden.; int5 & int7 -> int8: this is contradiction.; [assump1] & int8 -> int9: the emcee does not segregate match.; int9 & sent4 -> int10: the Manhattan does segregate match and stuffs.; int10 -> hypothesis;
the potluck is not Italic.
sent11 -> int11: if the potluck does not segregate match and does not swap then it is not a Italic.;
$hypothesis$ = the Manhattan does not segregate match. ; $context$ = sent1: the emcee is a kind of a Italic and it does swap. sent2: if the Manhattan does swap it does not segregate match. sent3: something that is not a Amaranthus does flock burden. sent4: if the emcee does not segregate match the Manhattan segregate match and does stuff. sent5: there exists nothing that does not dado Tyler and is a eruditeness. sent6: the Manhattan is a kind of a eruditeness. sent7: the snuffers does not segregate match. sent8: if the potluck is not a Amaranthus it does not segregate match and does not swap. sent9: the Manhattan is a kind of a stuff that does dado Tyler. sent10: the emcee is a Amaranthus. sent11: if something does not segregate match and it does not swap it is not a kind of a Italic. sent12: the Manhattan is a eruditeness if the perennial does not segregate match. sent13: the perennial does not flock burden if that it does not dado Tyler and it is a kind of a eruditeness is incorrect. sent14: if the perennial is not a eruditeness then it does not flock burden. sent15: the emcee is a gut. sent16: the Manhattan is not a kind of a Italic. sent17: if the emcee is a Italic and it segregates match the perennial is not a kind of a Amaranthus. sent18: that the emcee segregates match and flocks burden is not right. sent19: the Manhattan does dado Tyler. sent20: something does flock burden if it does not segregate match. ; $proof$ = 
sent1 -> int1: the emcee is a kind of a Italic.; void -> assump1: Let's assume that the emcee does segregate match.; int1 & assump1 -> int2: the emcee is a kind of a Italic and it does segregate match.; int2 & sent17 -> int3: that the perennial is a Amaranthus is wrong.; sent3 -> int4: the perennial flocks burden if it is not a Amaranthus.; int3 & int4 -> int5: the perennial does flock burden.; sent5 -> int6: the fact that the perennial does not dado Tyler but it is a eruditeness is false.; sent13 & int6 -> int7: the perennial does not flock burden.; int5 & int7 -> int8: this is contradiction.; [assump1] & int8 -> int9: the emcee does not segregate match.; int9 & sent4 -> int10: the Manhattan does segregate match and stuffs.; int10 -> hypothesis; __DISPROVED__