the evanescence happens.
sent1: the overrefining stretched occurs if the fact that the honoring and/or the permeableness occurs is not true. sent2: the fact that the honoring happens and/or the impermeableness does not occur is wrong if the hostile does not occur. sent3: that the paging minded does not occur is prevented by the overrefining stretched. sent4: if the paging minded occurs but the overrefining rebus does not occur then that the evanescence happens hold. sent5: that the hostileness but not the impermeableness happens does not hold if the honoring happens. sent6: the paging Tennessean and the bonanza happens. sent7: the fact that not the unipolarness but the submersible occurs is false if the watercolor does not occur. sent8: the non-hostileness prevents that the honoring happens. sent9: the paging Tennessean happens. sent10: the submersible occurs. sent11: that both the paging Tennessean and the bonanza happens prevents the overrefining rebus. sent12: that both the non-unipolarness and the submersible happens is caused by that the hostile happens. sent13: the honoring does not occur. sent14: the fact that the non-mucinousness and the remarriage occurs is false. sent15: the watercolor does not occur.
void -> assump1: Let's assume that the hostile happens.; sent12 & assump1 -> int1: not the unipolarness but the submersible occurs.; sent7 & sent15 -> int2: the fact that the non-unipolarness and the submersible happens is wrong.; int1 & int2 -> int3: this is contradiction.; [assump1] & int3 -> int4: the hostile does not occur.; int4 & sent2 -> int5: that the honoring occurs and/or the impermeableness does not occur is false.; int5 & sent1 -> int6: the overrefining stretched happens.; int6 & sent3 -> int7: the paging minded occurs.; sent11 & sent6 -> int8: the overrefining rebus does not occur.; int7 & int8 -> int9: the paging minded but not the overrefining rebus occurs.; int9 & sent4 -> hypothesis;
the fact that the non-mucinousness and the remarriage occurs is false.
 -> hypothesis;
$hypothesis$ = the evanescence happens. ; $context$ = sent1: the overrefining stretched occurs if the fact that the honoring and/or the permeableness occurs is not true. sent2: the fact that the honoring happens and/or the impermeableness does not occur is wrong if the hostile does not occur. sent3: that the paging minded does not occur is prevented by the overrefining stretched. sent4: if the paging minded occurs but the overrefining rebus does not occur then that the evanescence happens hold. sent5: that the hostileness but not the impermeableness happens does not hold if the honoring happens. sent6: the paging Tennessean and the bonanza happens. sent7: the fact that not the unipolarness but the submersible occurs is false if the watercolor does not occur. sent8: the non-hostileness prevents that the honoring happens. sent9: the paging Tennessean happens. sent10: the submersible occurs. sent11: that both the paging Tennessean and the bonanza happens prevents the overrefining rebus. sent12: that both the non-unipolarness and the submersible happens is caused by that the hostile happens. sent13: the honoring does not occur. sent14: the fact that the non-mucinousness and the remarriage occurs is false. sent15: the watercolor does not occur. ; $proof$ = 
void -> assump1: Let's assume that the hostile happens.; sent12 & assump1 -> int1: not the unipolarness but the submersible occurs.; sent7 & sent15 -> int2: the fact that the non-unipolarness and the submersible happens is wrong.; int1 & int2 -> int3: this is contradiction.; [assump1] & int3 -> int4: the hostile does not occur.; int4 & sent2 -> int5: that the honoring occurs and/or the impermeableness does not occur is false.; int5 & sent1 -> int6: the overrefining stretched happens.; int6 & sent3 -> int7: the paging minded occurs.; sent11 & sent6 -> int8: the overrefining rebus does not occur.; int7 & int8 -> int9: the paging minded but not the overrefining rebus occurs.; int9 & sent4 -> hypothesis; __PROVED__