that there is something such that it is a Caravaggio does not hold.
sent1: something is both not a Mayan and not a interposition if it is not a alkalemia. sent2: the bluejacket does lime leeway. sent3: if the Cakchiquel is either not a Caravaggio or not a patella or both then it does lime leeway. sent4: if the bluejacket limes leeway then it is not a kind of a patella. sent5: the Cakchiquel is a interposition if the bluejacket is not a kind of a patella and it is not a kind of a Caravaggio. sent6: the bluejacket does receive. sent7: the Cakchiquel is a kind of a capitalism. sent8: the Cakchiquel is not a voluntary. sent9: the Cakchiquel is not a alkalemia and is a kind of a capitalism. sent10: the Cakchiquel is not a Mayan and not a patella if it is not a kind of a alkalemia. sent11: The leeway does lime bluejacket.
sent4 & sent2 -> int1: the bluejacket is not a patella.; void -> assump1: Let's assume that the bluejacket is not a Caravaggio.; int1 & assump1 -> int2: the bluejacket is not a patella and is not a Caravaggio.; int2 & sent5 -> int3: the fact that the Cakchiquel is a kind of a interposition is correct.; sent1 -> int4: if the Cakchiquel is not a alkalemia then it is not a Mayan and is not a kind of a interposition.; sent9 -> int5: the Cakchiquel is not a kind of a alkalemia.; int4 & int5 -> int6: the fact that the Cakchiquel is not a Mayan and it is not a interposition is true.; int6 -> int7: the Cakchiquel is not a kind of a interposition.; int3 & int7 -> int8: this is contradiction.; [assump1] & int8 -> int9: the bluejacket is a Caravaggio.; int9 -> hypothesis;
there exists something such that it does rationalize tankage.
$hypothesis$ = that there is something such that it is a Caravaggio does not hold. ; $context$ = sent1: something is both not a Mayan and not a interposition if it is not a alkalemia. sent2: the bluejacket does lime leeway. sent3: if the Cakchiquel is either not a Caravaggio or not a patella or both then it does lime leeway. sent4: if the bluejacket limes leeway then it is not a kind of a patella. sent5: the Cakchiquel is a interposition if the bluejacket is not a kind of a patella and it is not a kind of a Caravaggio. sent6: the bluejacket does receive. sent7: the Cakchiquel is a kind of a capitalism. sent8: the Cakchiquel is not a voluntary. sent9: the Cakchiquel is not a alkalemia and is a kind of a capitalism. sent10: the Cakchiquel is not a Mayan and not a patella if it is not a kind of a alkalemia. sent11: The leeway does lime bluejacket. ; $proof$ = 
sent4 & sent2 -> int1: the bluejacket is not a patella.; void -> assump1: Let's assume that the bluejacket is not a Caravaggio.; int1 & assump1 -> int2: the bluejacket is not a patella and is not a Caravaggio.; int2 & sent5 -> int3: the fact that the Cakchiquel is a kind of a interposition is correct.; sent1 -> int4: if the Cakchiquel is not a alkalemia then it is not a Mayan and is not a kind of a interposition.; sent9 -> int5: the Cakchiquel is not a kind of a alkalemia.; int4 & int5 -> int6: the fact that the Cakchiquel is not a Mayan and it is not a interposition is true.; int6 -> int7: the Cakchiquel is not a kind of a interposition.; int3 & int7 -> int8: this is contradiction.; [assump1] & int8 -> int9: the bluejacket is a Caravaggio.; int9 -> hypothesis; __DISPROVED__