the fact that the khamsin does not rendezvous swiz and it is not a Whirlaway is incorrect.
sent1: the microscope does not pleach ACE. sent2: the microscope does not pleach thermometer. sent3: something is not a conservative and does badge if the fact that it pleaches thermometer is true. sent4: the fact that the condiment pleaches thermometer is not incorrect if that it does not render Sirach and it is rejective is not right. sent5: if something is a Whirlaway it does rendezvous Midland. sent6: if something rendezvous Midland the fact that it does not render Sirach and it is rejective does not hold. sent7: the fact that the Reticulum does not rendezvous Midland is true. sent8: if the condiment does rendezvous set-to the microscope is not a Whirlaway and rendezvous set-to. sent9: if the fact that the microscope is not a kind of a Whirlaway is not wrong the khamsin does not rendezvous swiz and is not a kind of a Whirlaway. sent10: if something that is not a kind of a conservative does badge it does rendezvous set-to. sent11: the condiment does rendezvous Midland if the Reticulum does not rendezvous Midland. sent12: The fact that the Midland does not rendezvous Reticulum is true.
sent6 -> int1: if the fact that the condiment does rendezvous Midland is not wrong that it does not render Sirach and it is not non-rejective is false.; sent11 & sent7 -> int2: the fact that the condiment does rendezvous Midland is not false.; int1 & int2 -> int3: that the condiment does not render Sirach but it is rejective is not right.; int3 & sent4 -> int4: the condiment pleaches thermometer.; sent3 -> int5: the condiment is not a kind of a conservative but it does badge if that it pleaches thermometer is not wrong.; int4 & int5 -> int6: the condiment is not a kind of a conservative but it is a badge.; sent10 -> int7: that if the condiment is not the conservative and does badge the fact that the condiment rendezvous set-to is right is not incorrect.; int6 & int7 -> int8: the condiment does rendezvous set-to.; int8 & sent8 -> int9: the microscope is not a Whirlaway and rendezvous set-to.; int9 -> int10: the microscope is not a Whirlaway.; int10 & sent9 -> hypothesis;
$hypothesis$ = the fact that the khamsin does not rendezvous swiz and it is not a Whirlaway is incorrect. ; $context$ = sent1: the microscope does not pleach ACE. sent2: the microscope does not pleach thermometer. sent3: something is not a conservative and does badge if the fact that it pleaches thermometer is true. sent4: the fact that the condiment pleaches thermometer is not incorrect if that it does not render Sirach and it is rejective is not right. sent5: if something is a Whirlaway it does rendezvous Midland. sent6: if something rendezvous Midland the fact that it does not render Sirach and it is rejective does not hold. sent7: the fact that the Reticulum does not rendezvous Midland is true. sent8: if the condiment does rendezvous set-to the microscope is not a Whirlaway and rendezvous set-to. sent9: if the fact that the microscope is not a kind of a Whirlaway is not wrong the khamsin does not rendezvous swiz and is not a kind of a Whirlaway. sent10: if something that is not a kind of a conservative does badge it does rendezvous set-to. sent11: the condiment does rendezvous Midland if the Reticulum does not rendezvous Midland. sent12: The fact that the Midland does not rendezvous Reticulum is true. ; $proof$ = 
sent6 -> int1: if the fact that the condiment does rendezvous Midland is not wrong that it does not render Sirach and it is not non-rejective is false.; sent11 & sent7 -> int2: the fact that the condiment does rendezvous Midland is not false.; int1 & int2 -> int3: that the condiment does not render Sirach but it is rejective is not right.; int3 & sent4 -> int4: the condiment pleaches thermometer.; sent3 -> int5: the condiment is not a kind of a conservative but it does badge if that it pleaches thermometer is not wrong.; int4 & int5 -> int6: the condiment is not a kind of a conservative but it is a badge.; sent10 -> int7: that if the condiment is not the conservative and does badge the fact that the condiment rendezvous set-to is right is not incorrect.; int6 & int7 -> int8: the condiment does rendezvous set-to.; int8 & sent8 -> int9: the microscope is not a Whirlaway and rendezvous set-to.; int9 -> int10: the microscope is not a Whirlaway.; int10 & sent9 -> hypothesis; __DISPROVED__