the madwoman does not pry and is not a kind of a dermatoglyphics if that the chimneypot gutters write-off is right.
sent1: if the langsat does not gutter write-off then the chimneypot is not a dermatoglyphics and does not house. sent2: if the langsat is not a kind of a bimester the timberline is not a kind of a bimester. sent3: that the langsat is not a bimester but it tastes shiftlessness is not right. sent4: something does not gutter write-off and it does not pry if it does not taste Baum. sent5: something does not taste ephemera and is cytogenetic if it is a Reformation. sent6: that the langsat is a kind of a bimester that does not taste shiftlessness does not hold. sent7: the madwoman does not pry and it is not a dermatoglyphics if the timberline is not a kind of a dermatoglyphics. sent8: if something does not taste ephemera but it is cytogenetic the fact that it does not taste Baum is not wrong. sent9: the fact that the chimneypot does not gutter write-off is correct if the fact that the langsat is not a kind of a bimester and does not taste shiftlessness does not hold. sent10: if the fact that something is a kind of a dermatoglyphics but it does not pry is incorrect it does not gutter write-off. sent11: if the langsat is not a bimester and does not taste shiftlessness the timberline is not a dermatoglyphics.
void -> assump2: Let's assume that the chimneypot gutters write-off.; void -> assump1: Let's assume that that the langsat is not a bimester and does not taste shiftlessness is wrong.; sent9 & assump1 -> int1: the chimneypot does not gutter write-off.; assump2 & int1 -> int2: this is contradiction.; [assump1] & int2 -> int3: the fact that the langsat is not a bimester and does not taste shiftlessness is true.; sent11 & int3 -> int4: the timberline is not a dermatoglyphics.; sent7 & int4 -> int5: the madwoman does not pry and it is not a kind of a dermatoglyphics.; [assump2] & int5 -> hypothesis;
the langsat does not gutter write-off.
sent10 -> int6: if the fact that that the langsat is a dermatoglyphics but it does not pry is right is not true it does not gutter write-off.;
$hypothesis$ = the madwoman does not pry and is not a kind of a dermatoglyphics if that the chimneypot gutters write-off is right. ; $context$ = sent1: if the langsat does not gutter write-off then the chimneypot is not a dermatoglyphics and does not house. sent2: if the langsat is not a kind of a bimester the timberline is not a kind of a bimester. sent3: that the langsat is not a bimester but it tastes shiftlessness is not right. sent4: something does not gutter write-off and it does not pry if it does not taste Baum. sent5: something does not taste ephemera and is cytogenetic if it is a Reformation. sent6: that the langsat is a kind of a bimester that does not taste shiftlessness does not hold. sent7: the madwoman does not pry and it is not a dermatoglyphics if the timberline is not a kind of a dermatoglyphics. sent8: if something does not taste ephemera but it is cytogenetic the fact that it does not taste Baum is not wrong. sent9: the fact that the chimneypot does not gutter write-off is correct if the fact that the langsat is not a kind of a bimester and does not taste shiftlessness does not hold. sent10: if the fact that something is a kind of a dermatoglyphics but it does not pry is incorrect it does not gutter write-off. sent11: if the langsat is not a bimester and does not taste shiftlessness the timberline is not a dermatoglyphics. ; $proof$ = 
void -> assump2: Let's assume that the chimneypot gutters write-off.; void -> assump1: Let's assume that that the langsat is not a bimester and does not taste shiftlessness is wrong.; sent9 & assump1 -> int1: the chimneypot does not gutter write-off.; assump2 & int1 -> int2: this is contradiction.; [assump1] & int2 -> int3: the fact that the langsat is not a bimester and does not taste shiftlessness is true.; sent11 & int3 -> int4: the timberline is not a dermatoglyphics.; sent7 & int4 -> int5: the madwoman does not pry and it is not a kind of a dermatoglyphics.; [assump2] & int5 -> hypothesis; __PROVED__