the fact that the fact that the edger is a kind of a demarche and is not a Parthian is incorrect is right.
sent1: if that the edger is parabolic but it is not a demarche is incorrect the plethodont is not a kind of a Parthian. sent2: the adz is a demarche. sent3: that if that the plethodont does not fit and is non-parabolic is incorrect then the fact that the plethodont fit is not wrong hold. sent4: the fact that the plethodont is both a fitting and not parabolic does not hold. sent5: if the basswood does not fit then that the plethodont is not parabolic and it is not tegular is not right. sent6: the fact that the fact that the edger is parabolic and is not a Parthian is incorrect is true. sent7: the fact that the plethodont is a Parthian and does not refine ritualist does not hold. sent8: the fact that the edger is a bind but not bulbar is not true. sent9: that the plethodont is not a fitting but non-parabolic does not hold. sent10: if something is tegular then the fact that it is a demarche and non-Parthian is wrong. sent11: the edger is a Parthian if that it is both not Parthian and not parabolic is not true. sent12: the plethodont is not a fitting if the edger is not a kind of a demarche. sent13: that the plethodont is non-parabolic thing that is not a demarche does not hold. sent14: something is non-fitting and is Rhodesian if it is incompatible. sent15: the fact that the plethodont is not a fitting and it is not a kind of a Parthian is not correct. sent16: if the fact that something is not fitting and it is not autoecious is incorrect it is a fitting. sent17: if the plethodont is not a Parthian then the edger is non-fitting. sent18: the plethodont is not fitting if the fact that the edger is a kind of a demarche and is not a Parthian is not right. sent19: the fact that the edger is a kind of a fitting that is not a kind of a demarche is wrong.
void -> assump1: Let's assume that that the edger is a demarche but it is not a Parthian is false.; sent18 & assump1 -> int1: the plethodont is not a fitting.; sent3 & sent9 -> int2: the plethodont is a fitting.; int1 & int2 -> int3: this is contradiction.; [assump1] & int3 -> hypothesis;
that the edger is a demarche but not Parthian is wrong.
sent10 -> int4: that the edger is a demarche and is not a Parthian is false if it is tegular.; sent14 -> int5: if the basswood is incompatible then the fact that it does not fit and it is Rhodesian is right.;
$hypothesis$ = the fact that the fact that the edger is a kind of a demarche and is not a Parthian is incorrect is right. ; $context$ = sent1: if that the edger is parabolic but it is not a demarche is incorrect the plethodont is not a kind of a Parthian. sent2: the adz is a demarche. sent3: that if that the plethodont does not fit and is non-parabolic is incorrect then the fact that the plethodont fit is not wrong hold. sent4: the fact that the plethodont is both a fitting and not parabolic does not hold. sent5: if the basswood does not fit then that the plethodont is not parabolic and it is not tegular is not right. sent6: the fact that the fact that the edger is parabolic and is not a Parthian is incorrect is true. sent7: the fact that the plethodont is a Parthian and does not refine ritualist does not hold. sent8: the fact that the edger is a bind but not bulbar is not true. sent9: that the plethodont is not a fitting but non-parabolic does not hold. sent10: if something is tegular then the fact that it is a demarche and non-Parthian is wrong. sent11: the edger is a Parthian if that it is both not Parthian and not parabolic is not true. sent12: the plethodont is not a fitting if the edger is not a kind of a demarche. sent13: that the plethodont is non-parabolic thing that is not a demarche does not hold. sent14: something is non-fitting and is Rhodesian if it is incompatible. sent15: the fact that the plethodont is not a fitting and it is not a kind of a Parthian is not correct. sent16: if the fact that something is not fitting and it is not autoecious is incorrect it is a fitting. sent17: if the plethodont is not a Parthian then the edger is non-fitting. sent18: the plethodont is not fitting if the fact that the edger is a kind of a demarche and is not a Parthian is not right. sent19: the fact that the edger is a kind of a fitting that is not a kind of a demarche is wrong. ; $proof$ = 
void -> assump1: Let's assume that that the edger is a demarche but it is not a Parthian is false.; sent18 & assump1 -> int1: the plethodont is not a fitting.; sent3 & sent9 -> int2: the plethodont is a fitting.; int1 & int2 -> int3: this is contradiction.; [assump1] & int3 -> hypothesis; __DISPROVED__