the flintstone does bark Donatello.
sent1: the Eritrean is a Borassus. sent2: there exists something such that it does not bypass Nijinsky and does radicalize. sent3: if the Eritrean does not green the flintstone does not bypass recompense and is a kind of a Borassus. sent4: the Pretender does not bypass enamine and does not bark Donatello if the promenade tires. sent5: the flintstone bypasses recompense. sent6: if something does not bypass recompense and is a Borassus then it does not bark Donatello. sent7: if something is not a Borassus it is a kind of a miotic and does bypass recompense. sent8: something does bypass enamine. sent9: the fact that the flintstone is not a kind of a miotic is correct if there is something such that it does not bypass enamine. sent10: the promenade is not lentic if the torsion is not lentic and it is not a archdeacon. sent11: the torsion is not lentic. sent12: if the panicle is non-green then the flintstone is not a Borassus. sent13: if the Eritrean bypasses recompense then the fact that the flintstone is a green is true. sent14: if the flintstone is not a miotic then that it does not bark Donatello and it greens is not correct. sent15: there exists something such that it does not bypass enamine. sent16: the Eritrean is a miotic if the flintstone is a kind of a miotic. sent17: if the panicle does tire but it is not lentic the Eritrean does tire. sent18: if something is not lentic then the fact that it is a tire is not incorrect. sent19: the Eritrean bypasses recompense and it is a kind of a Borassus. sent20: if something does tire the fact that it does not bypass enamine and is not a miotic is not correct.
sent19 -> int1: the Eritrean does bypass recompense.; int1 & sent13 -> int2: that the flintstone is green hold.; void -> assump1: Let's assume that the flintstone does not bark Donatello.; int2 & assump1 -> int3: the fact that the flintstone does not bark Donatello but it is green hold.; sent15 & sent9 -> int4: the flintstone is not miotic.; sent14 & int4 -> int5: the fact that the flintstone does not bark Donatello and is a green is not right.; int3 & int5 -> int6: this is contradiction.; [assump1] & int6 -> hypothesis;
the flintstone does not bark Donatello.
sent6 -> int7: the flintstone does not bark Donatello if it does not bypass recompense and it is a Borassus.; sent20 -> int8: the fact that the Eritrean does not bypass enamine and it is not a kind of a miotic does not hold if it is a tire.;
$hypothesis$ = the flintstone does bark Donatello. ; $context$ = sent1: the Eritrean is a Borassus. sent2: there exists something such that it does not bypass Nijinsky and does radicalize. sent3: if the Eritrean does not green the flintstone does not bypass recompense and is a kind of a Borassus. sent4: the Pretender does not bypass enamine and does not bark Donatello if the promenade tires. sent5: the flintstone bypasses recompense. sent6: if something does not bypass recompense and is a Borassus then it does not bark Donatello. sent7: if something is not a Borassus it is a kind of a miotic and does bypass recompense. sent8: something does bypass enamine. sent9: the fact that the flintstone is not a kind of a miotic is correct if there is something such that it does not bypass enamine. sent10: the promenade is not lentic if the torsion is not lentic and it is not a archdeacon. sent11: the torsion is not lentic. sent12: if the panicle is non-green then the flintstone is not a Borassus. sent13: if the Eritrean bypasses recompense then the fact that the flintstone is a green is true. sent14: if the flintstone is not a miotic then that it does not bark Donatello and it greens is not correct. sent15: there exists something such that it does not bypass enamine. sent16: the Eritrean is a miotic if the flintstone is a kind of a miotic. sent17: if the panicle does tire but it is not lentic the Eritrean does tire. sent18: if something is not lentic then the fact that it is a tire is not incorrect. sent19: the Eritrean bypasses recompense and it is a kind of a Borassus. sent20: if something does tire the fact that it does not bypass enamine and is not a miotic is not correct. ; $proof$ = 
sent19 -> int1: the Eritrean does bypass recompense.; int1 & sent13 -> int2: that the flintstone is green hold.; void -> assump1: Let's assume that the flintstone does not bark Donatello.; int2 & assump1 -> int3: the fact that the flintstone does not bark Donatello but it is green hold.; sent15 & sent9 -> int4: the flintstone is not miotic.; sent14 & int4 -> int5: the fact that the flintstone does not bark Donatello and is a green is not right.; int3 & int5 -> int6: this is contradiction.; [assump1] & int6 -> hypothesis; __PROVED__