the Kennan does not impinge uremia.
sent1: the fact that the Kennan staves Kennan and is not Singaporean is not right. sent2: that the sundowner is homostylous and it beards is false. sent3: the sundowner is calcaneal but it does not stave Kennan if it is a usufruct. sent4: if the sundowner is a usufruct then that it does not stave Kennan is true. sent5: if the sundowner does not impinge Siphonaptera that it is homostylous and it is not a beard does not hold. sent6: the reference does not impinge shogun if the sundowner does impinge Siphonaptera and is calcaneal. sent7: if the chincherinchee is calcaneal then the reference is calcaneal. sent8: something impinges uremia if it is a kind of a Singaporean. sent9: the fact that the sundowner is homostylous and does beard is wrong if it does not impinge Siphonaptera. sent10: the sundowner does not stave Kennan. sent11: something does impinge uremia if the fact that it is not a Singaporean but a naiad is not correct. sent12: that the Kennan is a Singaporean and it is a naiad does not hold. sent13: that everything is homostylous thing that does not beard is not incorrect. sent14: if something is not a Singaporean then it is calcaneal thing that does impinge shogun. sent15: everything is apothegmatic but not Ceylonese. sent16: if the reference is calcaneal then the sundowner does not impinge Siphonaptera and it does not impinge uremia. sent17: the sundowner is not a beard. sent18: the fact that the sundowner is cystic is not wrong. sent19: if something does not impinge shogun the fact that the Kennan is a Singaporean and a naiad is wrong. sent20: if the Kennan is Singaporean it does impinge uremia. sent21: the reference does stave Kennan. sent22: the sundowner is a kind of a usufruct. sent23: if something does not impinge shogun that the Kennan is not a Singaporean but a naiad is false. sent24: everything is not a beard. sent25: something does impinge shogun. sent26: if the sundowner does not impinge Siphonaptera and does not impinge uremia the Kennan does not impinge uremia.
void -> assump1: Let's assume that the sundowner does not impinge Siphonaptera.; sent5 & assump1 -> int1: that the sundowner is homostylous thing that is not a beard is not true.; sent13 -> int2: the sundowner is homostylous and is not a beard.; int1 & int2 -> int3: this is contradiction.; [assump1] & int3 -> int4: the sundowner impinges Siphonaptera.; sent3 & sent22 -> int5: the sundowner is calcaneal but it does not stave Kennan.; int5 -> int6: the fact that the sundowner is calcaneal is true.; int4 & int6 -> int7: the sundowner does impinge Siphonaptera and it is calcaneal.; int7 & sent6 -> int8: the reference does not impinge shogun.; int8 -> int9: there is something such that it does not impinge shogun.; int9 & sent23 -> int10: that the Kennan is non-Singaporean a naiad is not correct.; sent11 -> int11: the Kennan does impinge uremia if that it is not a Singaporean and it is a naiad is not right.; int10 & int11 -> hypothesis;
the Kennan does not impinge uremia.
sent14 -> int12: the fact that the chincherinchee is the kind of calcaneal thing that impinges shogun if the chincherinchee is not a kind of a Singaporean is not wrong.;
$hypothesis$ = the Kennan does not impinge uremia. ; $context$ = sent1: the fact that the Kennan staves Kennan and is not Singaporean is not right. sent2: that the sundowner is homostylous and it beards is false. sent3: the sundowner is calcaneal but it does not stave Kennan if it is a usufruct. sent4: if the sundowner is a usufruct then that it does not stave Kennan is true. sent5: if the sundowner does not impinge Siphonaptera that it is homostylous and it is not a beard does not hold. sent6: the reference does not impinge shogun if the sundowner does impinge Siphonaptera and is calcaneal. sent7: if the chincherinchee is calcaneal then the reference is calcaneal. sent8: something impinges uremia if it is a kind of a Singaporean. sent9: the fact that the sundowner is homostylous and does beard is wrong if it does not impinge Siphonaptera. sent10: the sundowner does not stave Kennan. sent11: something does impinge uremia if the fact that it is not a Singaporean but a naiad is not correct. sent12: that the Kennan is a Singaporean and it is a naiad does not hold. sent13: that everything is homostylous thing that does not beard is not incorrect. sent14: if something is not a Singaporean then it is calcaneal thing that does impinge shogun. sent15: everything is apothegmatic but not Ceylonese. sent16: if the reference is calcaneal then the sundowner does not impinge Siphonaptera and it does not impinge uremia. sent17: the sundowner is not a beard. sent18: the fact that the sundowner is cystic is not wrong. sent19: if something does not impinge shogun the fact that the Kennan is a Singaporean and a naiad is wrong. sent20: if the Kennan is Singaporean it does impinge uremia. sent21: the reference does stave Kennan. sent22: the sundowner is a kind of a usufruct. sent23: if something does not impinge shogun that the Kennan is not a Singaporean but a naiad is false. sent24: everything is not a beard. sent25: something does impinge shogun. sent26: if the sundowner does not impinge Siphonaptera and does not impinge uremia the Kennan does not impinge uremia. ; $proof$ = 
void -> assump1: Let's assume that the sundowner does not impinge Siphonaptera.; sent5 & assump1 -> int1: that the sundowner is homostylous thing that is not a beard is not true.; sent13 -> int2: the sundowner is homostylous and is not a beard.; int1 & int2 -> int3: this is contradiction.; [assump1] & int3 -> int4: the sundowner impinges Siphonaptera.; sent3 & sent22 -> int5: the sundowner is calcaneal but it does not stave Kennan.; int5 -> int6: the fact that the sundowner is calcaneal is true.; int4 & int6 -> int7: the sundowner does impinge Siphonaptera and it is calcaneal.; int7 & sent6 -> int8: the reference does not impinge shogun.; int8 -> int9: there is something such that it does not impinge shogun.; int9 & sent23 -> int10: that the Kennan is non-Singaporean a naiad is not correct.; sent11 -> int11: the Kennan does impinge uremia if that it is not a Singaporean and it is a naiad is not right.; int10 & int11 -> hypothesis; __DISPROVED__