the fact that if the beech does not tube then the brad is not orthodontic and/or it is megakaryocytic is false.
sent1: if the beech is a kind of a tube then either the brad is not orthodontic or it is megakaryocytic or both. sent2: if something is not a tube then it is not orthodontic. sent3: the brad is orthodontic and/or is megakaryocytic. sent4: the beech is not megakaryocytic and/or is orthodontic. sent5: the brad does not dive beech. sent6: the brad is orthodontic and/or it is megakaryocytic if the beech is not orthodontic. sent7: if the beech is not orthodontic then the brad is not orthodontic or it is megakaryocytic or both.
sent2 -> int1: the beech is not orthodontic if it does not tube.; void -> assump1: Let's assume that the beech is not a tube.; int1 & assump1 -> int2: the beech is not orthodontic.; sent7 & int2 -> int3: the brad is not orthodontic and/or is megakaryocytic.; [assump1] & int3 -> hypothesis;
$hypothesis$ = the fact that if the beech does not tube then the brad is not orthodontic and/or it is megakaryocytic is false. ; $context$ = sent1: if the beech is a kind of a tube then either the brad is not orthodontic or it is megakaryocytic or both. sent2: if something is not a tube then it is not orthodontic. sent3: the brad is orthodontic and/or is megakaryocytic. sent4: the beech is not megakaryocytic and/or is orthodontic. sent5: the brad does not dive beech. sent6: the brad is orthodontic and/or it is megakaryocytic if the beech is not orthodontic. sent7: if the beech is not orthodontic then the brad is not orthodontic or it is megakaryocytic or both. ; $proof$ = 
sent2 -> int1: the beech is not orthodontic if it does not tube.; void -> assump1: Let's assume that the beech is not a tube.; int1 & assump1 -> int2: the beech is not orthodontic.; sent7 & int2 -> int3: the brad is not orthodontic and/or is megakaryocytic.; [assump1] & int3 -> hypothesis; __DISPROVED__