if the vesiculation is not a Hmong that the PDA is a kind of a push and is not fiber-optic is not true.
sent1: the fact that that the PDA is a kind of a Hmong and is not fiber-optic is right is not correct if the vesiculation is fiber-optic. sent2: the PDA is a push and not fiber-optic. sent3: the vesiculation is a Hmong if it is not fiber-optic. sent4: something is not a beekeeper if it does not chance Tarsiidae. sent5: the vesiculation does cohabit. sent6: the fact that the fact that the PDA is Hmong thing that is not fiber-optic is not incorrect is not right. sent7: if the vesiculation is fiber-optic the PDA pushes but it is not fiber-optic. sent8: the fact that everything does not chance Tarsiidae hold. sent9: if the physicist is not a kind of a beekeeper it does collide and is not eradicable. sent10: that the PDA is a kind of a push and is fiber-optic is not correct if the vesiculation is not fiber-optic. sent11: that the PDA is a push and it is fiber-optic is not correct. sent12: the PDA does incriminate Soleidae if that it is not unfriendly is correct. sent13: if the fact that the vesiculation is not a Hmong hold the PDA is a push that is not fiber-optic. sent14: if the fact that the vesiculation is a kind of a Hmong is false then that the PDA is a push and fiber-optic is not true. sent15: the vesiculation is fiber-optic if it is not .22-caliber. sent16: the Chamaeleon is Hmong. sent17: that the vesiculation does chance stay-at-home does not hold. sent18: the vesiculation is not a push.
void -> assump2: Let's assume that the vesiculation is not fiber-optic.; sent3 & assump2 -> int1: the vesiculation is a kind of a Hmong.; void -> assump1: Let's assume that the vesiculation is not a Hmong.; int1 & assump1 -> int2: this is contradiction.; [assump2] & int2 -> int3: the vesiculation is fiber-optic.;
the fact that the BIN is not non-Hmong hold.
sent4 -> int4: if the Satanist does not chance Tarsiidae then it is not a beekeeper.; sent8 -> int5: the Satanist does not chance Tarsiidae.; int4 & int5 -> int6: the Satanist is not a beekeeper.; int6 -> int7: everything is not a beekeeper.; int7 -> int8: the physicist is not a beekeeper.; sent9 & int8 -> int9: the physicist collides and it is ineradicable.; int9 -> int10: the fact that the physicist does collide is not false.; int10 -> int11: there exists something such that it collides.;
$hypothesis$ = if the vesiculation is not a Hmong that the PDA is a kind of a push and is not fiber-optic is not true. ; $context$ = sent1: the fact that that the PDA is a kind of a Hmong and is not fiber-optic is right is not correct if the vesiculation is fiber-optic. sent2: the PDA is a push and not fiber-optic. sent3: the vesiculation is a Hmong if it is not fiber-optic. sent4: something is not a beekeeper if it does not chance Tarsiidae. sent5: the vesiculation does cohabit. sent6: the fact that the fact that the PDA is Hmong thing that is not fiber-optic is not incorrect is not right. sent7: if the vesiculation is fiber-optic the PDA pushes but it is not fiber-optic. sent8: the fact that everything does not chance Tarsiidae hold. sent9: if the physicist is not a kind of a beekeeper it does collide and is not eradicable. sent10: that the PDA is a kind of a push and is fiber-optic is not correct if the vesiculation is not fiber-optic. sent11: that the PDA is a push and it is fiber-optic is not correct. sent12: the PDA does incriminate Soleidae if that it is not unfriendly is correct. sent13: if the fact that the vesiculation is not a Hmong hold the PDA is a push that is not fiber-optic. sent14: if the fact that the vesiculation is a kind of a Hmong is false then that the PDA is a push and fiber-optic is not true. sent15: the vesiculation is fiber-optic if it is not .22-caliber. sent16: the Chamaeleon is Hmong. sent17: that the vesiculation does chance stay-at-home does not hold. sent18: the vesiculation is not a push. ; $proof$ = 
void -> assump2: Let's assume that the vesiculation is not fiber-optic.; sent3 & assump2 -> int1: the vesiculation is a kind of a Hmong.; void -> assump1: Let's assume that the vesiculation is not a Hmong.; int1 & assump1 -> int2: this is contradiction.; [assump2] & int2 -> int3: the vesiculation is fiber-optic.; __UNKNOWN__