the catacomb is a kind of a soberness and is a kind of a redundancy.
sent1: the bacchant is not a quadrivium. sent2: that something is both not a quadrivium and a Sangay does not hold if it is a redundancy. sent3: the bacchant is inspiratory. sent4: the bacchant is a quadrivium and is a soberness if the catacomb is not a kind of a soberness. sent5: the catacomb is a kind of a soberness that is a redundancy if the B-girl is not a redundancy. sent6: the fact that the bacchant is not a quadrivium but inspiratory is incorrect if the B-girl is a kind of a redundancy.
void -> assump1: Let's assume that the fact that the B-girl is a redundancy is not wrong.; sent6 & assump1 -> int1: that the bacchant is not a quadrivium but inspiratory is incorrect.; sent1 & sent3 -> int2: the fact that the bacchant is not a quadrivium but it is inspiratory hold.; int1 & int2 -> int3: this is contradiction.; [assump1] & int3 -> int4: the B-girl is not a kind of a redundancy.; int4 & sent5 -> hypothesis;
the fact that the B-girl is not a quadrivium but it is a kind of a Sangay does not hold.
sent2 -> int5: that the bacchant is not a quadrivium but a Sangay is wrong if that it is a redundancy is not false.;
$hypothesis$ = the catacomb is a kind of a soberness and is a kind of a redundancy. ; $context$ = sent1: the bacchant is not a quadrivium. sent2: that something is both not a quadrivium and a Sangay does not hold if it is a redundancy. sent3: the bacchant is inspiratory. sent4: the bacchant is a quadrivium and is a soberness if the catacomb is not a kind of a soberness. sent5: the catacomb is a kind of a soberness that is a redundancy if the B-girl is not a redundancy. sent6: the fact that the bacchant is not a quadrivium but inspiratory is incorrect if the B-girl is a kind of a redundancy. ; $proof$ = 
void -> assump1: Let's assume that the fact that the B-girl is a redundancy is not wrong.; sent6 & assump1 -> int1: that the bacchant is not a quadrivium but inspiratory is incorrect.; sent1 & sent3 -> int2: the fact that the bacchant is not a quadrivium but it is inspiratory hold.; int1 & int2 -> int3: this is contradiction.; [assump1] & int3 -> int4: the B-girl is not a kind of a redundancy.; int4 & sent5 -> hypothesis; __PROVED__