the bracken is both anemographic and a cheep.
sent1: if the fact that the snail is not a snuff but it does bypass Wu does not hold the cabinet is not araneidal. sent2: if the inclinometer is not a lug and is a kind of a pollinator then the dolphinfish does not organize. sent3: if the snail is not a kind of a snuff and does bypass Wu the bracken does bypass encaustic. sent4: the bracken is anemographic if it does bypass encaustic. sent5: if the cabinet is nonarbitrable then the dolphinfish does organize. sent6: the bracken is a kind of a cheep. sent7: the inclinometer does not lug and is a pollinator.
void -> assump1: Let's assume that that the snail does not snuff but it does bypass Wu is not true.; sent1 & assump1 -> int1: the cabinet is not araneidal.; sent2 & sent7 -> int2: the dolphinfish does not organize.;
$hypothesis$ = the bracken is both anemographic and a cheep. ; $context$ = sent1: if the fact that the snail is not a snuff but it does bypass Wu does not hold the cabinet is not araneidal. sent2: if the inclinometer is not a lug and is a kind of a pollinator then the dolphinfish does not organize. sent3: if the snail is not a kind of a snuff and does bypass Wu the bracken does bypass encaustic. sent4: the bracken is anemographic if it does bypass encaustic. sent5: if the cabinet is nonarbitrable then the dolphinfish does organize. sent6: the bracken is a kind of a cheep. sent7: the inclinometer does not lug and is a pollinator. ; $proof$ = 
void -> assump1: Let's assume that that the snail does not snuff but it does bypass Wu is not true.; sent1 & assump1 -> int1: the cabinet is not araneidal.; sent2 & sent7 -> int2: the dolphinfish does not organize.; __UNKNOWN__