the adenine is not non-Croatian but it is not harmonic.
sent1: something is a Croatian but it is not harmonic if it does not deduce vac. sent2: the adenine is a Croatian if it is a cittern. sent3: the adenine is cautious. sent4: that the oca is a cittern is not false if it does deduce vac. sent5: if the fesse is a kind of a Croatian the oca does deduce vac. sent6: that the oca is cautious and it is incongruous is incorrect. sent7: if that the fesse is not a Croatian is not incorrect then the fact that the adenine is not Croatian but it is not a kind of a harmonic is false. sent8: if something is a Croatian then the fact that it is a Blighia that is not a Aalst is wrong. sent9: the oca is not a kind of a cittern if that the fact that it is both cautious and incongruous is true does not hold.
void -> assump1: Let's assume that the fesse is a kind of a Croatian.; sent5 & assump1 -> int1: the oca deduces vac.; int1 & sent4 -> int2: that the oca is a cittern is correct.; sent9 & sent6 -> int3: the oca is not a cittern.; int2 & int3 -> int4: this is contradiction.; [assump1] & int4 -> int5: the fesse is not a Croatian.; int5 & sent7 -> hypothesis;
the adenine is both Croatian and not a harmonic.
sent1 -> int6: if the adenine does not deduce vac it is a Croatian that is not a harmonic.;
$hypothesis$ = the adenine is not non-Croatian but it is not harmonic. ; $context$ = sent1: something is a Croatian but it is not harmonic if it does not deduce vac. sent2: the adenine is a Croatian if it is a cittern. sent3: the adenine is cautious. sent4: that the oca is a cittern is not false if it does deduce vac. sent5: if the fesse is a kind of a Croatian the oca does deduce vac. sent6: that the oca is cautious and it is incongruous is incorrect. sent7: if that the fesse is not a Croatian is not incorrect then the fact that the adenine is not Croatian but it is not a kind of a harmonic is false. sent8: if something is a Croatian then the fact that it is a Blighia that is not a Aalst is wrong. sent9: the oca is not a kind of a cittern if that the fact that it is both cautious and incongruous is true does not hold. ; $proof$ = 
void -> assump1: Let's assume that the fesse is a kind of a Croatian.; sent5 & assump1 -> int1: the oca deduces vac.; int1 & sent4 -> int2: that the oca is a cittern is correct.; sent9 & sent6 -> int3: the oca is not a cittern.; int2 & int3 -> int4: this is contradiction.; [assump1] & int4 -> int5: the fesse is not a Croatian.; int5 & sent7 -> hypothesis; __DISPROVED__