the skilletfish is not merciful.
sent1: something startles industrialization but it is not agential if it does overcloud. sent2: the dope is a sixtieth if it does not startle skilletfish and is not a mandatary. sent3: that something does startle industrialization but it is not agential is wrong if it does startle skilletfish. sent4: if the testudo is not a sixtieth but it is isomeric then the skilletfish is not merciful. sent5: the testudo is isomeric. sent6: the nonconformist does startle industrialization. sent7: the testudo does not startle skilletfish if that either the skilletfish is a sixtieth or it is a kind of a mandatary or both is incorrect. sent8: the testudo is not a sixtieth and is isomeric if the dope is a kind of a sixtieth. sent9: the skilletfish is not a mandatary if the testudo is a sixtieth. sent10: the fact that something does overcloud and it is merciful is not true if it does startle skilletfish. sent11: if the fact that the testudo does not overcloud and does startle skilletfish is true then the dope is not a sixtieth. sent12: the dope overclouds and is a Utah. sent13: if the testudo does not startle skilletfish the tool does not dropkick paging and is a column.
sent3 -> int1: that the dope does startle industrialization but it is not agential is not true if it startles skilletfish.; void -> assump1: Let's assume that the dope startles skilletfish.; int1 & assump1 -> int2: that the dope does startle industrialization but it is non-agential is not correct.; sent1 -> int3: the dope does startle industrialization but it is not agential if it overclouds.; sent12 -> int4: the fact that the dope overclouds is true.; int3 & int4 -> int5: the dope does startle industrialization but it is not agential.; int2 & int5 -> int6: this is contradiction.; [assump1] & int6 -> int7: the dope does not startle skilletfish.;
the skilletfish is merciful.
$hypothesis$ = the skilletfish is not merciful. ; $context$ = sent1: something startles industrialization but it is not agential if it does overcloud. sent2: the dope is a sixtieth if it does not startle skilletfish and is not a mandatary. sent3: that something does startle industrialization but it is not agential is wrong if it does startle skilletfish. sent4: if the testudo is not a sixtieth but it is isomeric then the skilletfish is not merciful. sent5: the testudo is isomeric. sent6: the nonconformist does startle industrialization. sent7: the testudo does not startle skilletfish if that either the skilletfish is a sixtieth or it is a kind of a mandatary or both is incorrect. sent8: the testudo is not a sixtieth and is isomeric if the dope is a kind of a sixtieth. sent9: the skilletfish is not a mandatary if the testudo is a sixtieth. sent10: the fact that something does overcloud and it is merciful is not true if it does startle skilletfish. sent11: if the fact that the testudo does not overcloud and does startle skilletfish is true then the dope is not a sixtieth. sent12: the dope overclouds and is a Utah. sent13: if the testudo does not startle skilletfish the tool does not dropkick paging and is a column. ; $proof$ = 
sent3 -> int1: that the dope does startle industrialization but it is not agential is not true if it startles skilletfish.; void -> assump1: Let's assume that the dope startles skilletfish.; int1 & assump1 -> int2: that the dope does startle industrialization but it is non-agential is not correct.; sent1 -> int3: the dope does startle industrialization but it is not agential if it overclouds.; sent12 -> int4: the fact that the dope overclouds is true.; int3 & int4 -> int5: the dope does startle industrialization but it is not agential.; int2 & int5 -> int6: this is contradiction.; [assump1] & int6 -> int7: the dope does not startle skilletfish.; __UNKNOWN__