the kaon does not comfort Sherrington.
sent1: if something is a burr then it is a kind of a static. sent2: the cleats does not meddle if the kaon comforts Sherrington and is a static. sent3: if the cleats is non-static thing that does not meddle then the kaon is not a burr. sent4: if the kaon is not an interstate then it is not nonalcoholic but a nominalism. sent5: if the dragnet is not non-carangid then the cleats is a checklist. sent6: if the huckleberry does not draw Lordship and is a kind of a FICA then it is a burr. sent7: if something is not nonalcoholic but it is a nominalism it is a kind of a burr. sent8: the kaon is both not crosswise and nonalcoholic if it is not a kind of a Gospel. sent9: everything does meddle and it is a checklist. sent10: the kaon is not an interstate.
sent4 & sent10 -> int1: the kaon is both not nonalcoholic and a nominalism.; sent7 -> int2: the kaon is a kind of a burr if it is not nonalcoholic and it is a nominalism.; int1 & int2 -> int3: the kaon is a kind of a burr.; sent1 -> int4: the kaon is a static if it is a burr.; int3 & int4 -> int5: the kaon is a static.; void -> assump1: Let's assume that the kaon comforts Sherrington.; int5 & assump1 -> int6: the kaon does comfort Sherrington and is a kind of a static.; int6 & sent2 -> int7: the cleats does not meddle.; sent9 -> int8: the cleats does meddle and is a checklist.; int8 -> int9: the fact that the cleats meddles is true.; int7 & int9 -> int10: this is contradiction.; [assump1] & int10 -> hypothesis;
the kaon does comfort Sherrington.
$hypothesis$ = the kaon does not comfort Sherrington. ; $context$ = sent1: if something is a burr then it is a kind of a static. sent2: the cleats does not meddle if the kaon comforts Sherrington and is a static. sent3: if the cleats is non-static thing that does not meddle then the kaon is not a burr. sent4: if the kaon is not an interstate then it is not nonalcoholic but a nominalism. sent5: if the dragnet is not non-carangid then the cleats is a checklist. sent6: if the huckleberry does not draw Lordship and is a kind of a FICA then it is a burr. sent7: if something is not nonalcoholic but it is a nominalism it is a kind of a burr. sent8: the kaon is both not crosswise and nonalcoholic if it is not a kind of a Gospel. sent9: everything does meddle and it is a checklist. sent10: the kaon is not an interstate. ; $proof$ = 
sent4 & sent10 -> int1: the kaon is both not nonalcoholic and a nominalism.; sent7 -> int2: the kaon is a kind of a burr if it is not nonalcoholic and it is a nominalism.; int1 & int2 -> int3: the kaon is a kind of a burr.; sent1 -> int4: the kaon is a static if it is a burr.; int3 & int4 -> int5: the kaon is a static.; void -> assump1: Let's assume that the kaon comforts Sherrington.; int5 & assump1 -> int6: the kaon does comfort Sherrington and is a kind of a static.; int6 & sent2 -> int7: the cleats does not meddle.; sent9 -> int8: the cleats does meddle and is a checklist.; int8 -> int9: the fact that the cleats meddles is true.; int7 & int9 -> int10: this is contradiction.; [assump1] & int10 -> hypothesis; __PROVED__