the lexicographicness happens and the informationalness occurs.
sent1: if the loading and the nim happens then the incompatibleness does not occur. sent2: that the fetch happens results in the incompatibleness. sent3: if the loading does not occur the non-mineralness and the brooming Macleod occurs. sent4: the pop-up occurs. sent5: the informationalness occurs. sent6: the welt but not the biopiracy happens. sent7: the fetch happens. sent8: that that the incompatibleness does not occur and the nim does not occur is right is wrong if the circumduction occurs. sent9: the mineral and the loading occurs. sent10: if the nim does not occur and the circumduction does not occur the lexicographicness occurs.
sent9 -> int1: that the loading occurs hold.; void -> assump1: Let's assume that the nim occurs.; int1 & assump1 -> int2: the loading and the nim occurs.; int2 & sent1 -> int3: the incompatibleness does not occur.; sent2 & sent7 -> int4: the incompatibleness occurs.; int3 & int4 -> int5: this is contradiction.; [assump1] & int5 -> int6: the nim does not occur.;
that the brooming Macleod occurs is not incorrect.
$hypothesis$ = the lexicographicness happens and the informationalness occurs. ; $context$ = sent1: if the loading and the nim happens then the incompatibleness does not occur. sent2: that the fetch happens results in the incompatibleness. sent3: if the loading does not occur the non-mineralness and the brooming Macleod occurs. sent4: the pop-up occurs. sent5: the informationalness occurs. sent6: the welt but not the biopiracy happens. sent7: the fetch happens. sent8: that that the incompatibleness does not occur and the nim does not occur is right is wrong if the circumduction occurs. sent9: the mineral and the loading occurs. sent10: if the nim does not occur and the circumduction does not occur the lexicographicness occurs. ; $proof$ = 
sent9 -> int1: that the loading occurs hold.; void -> assump1: Let's assume that the nim occurs.; int1 & assump1 -> int2: the loading and the nim occurs.; int2 & sent1 -> int3: the incompatibleness does not occur.; sent2 & sent7 -> int4: the incompatibleness occurs.; int3 & int4 -> int5: this is contradiction.; [assump1] & int5 -> int6: the nim does not occur.; __UNKNOWN__