the kitsch is a scarcity.
sent1: the fact that if something is a conchologist then it is a procurator is correct. sent2: the biotite does neglect roots but it is not a kind of a Onopordum. sent3: the kitsch is not a scarcity if the fact that the folio is either not a bailee or not a shower or both does not hold. sent4: the biotite is a capitalization if it is a kind of a bailee. sent5: if the biotite is not a bailee then the folio is a shower. sent6: if the biotite is a procurator the fact that it does rationalize Procyonidae is correct. sent7: the biotite does neglect roots. sent8: if something is not a Onopordum but it is a capitalization then it does not rationalize Procyonidae. sent9: the biotite is a conchologist. sent10: the kitsch is not a scarcity if the fact that the folio is not a bailee or it does shower or both is false. sent11: if the biotite is not a bailee then that the fact that either the folio is not a bailee or it is not a kind of a shower or both is correct does not hold.
void -> assump1: Let's assume that the biotite is a bailee.; sent4 & assump1 -> int1: the biotite is a kind of a capitalization.; sent2 -> int2: the biotite is not a Onopordum.; int1 & int2 -> int3: the biotite is not a Onopordum but a capitalization.; sent8 -> int4: the biotite does not rationalize Procyonidae if it is not a Onopordum but a capitalization.; int3 & int4 -> int5: the biotite does not rationalize Procyonidae.; sent1 -> int6: the fact that the biotite is a kind of a procurator hold if it is a kind of a conchologist.; int6 & sent9 -> int7: the biotite is a kind of a procurator.; sent6 & int7 -> int8: the biotite does rationalize Procyonidae.; int5 & int8 -> int9: this is contradiction.; [assump1] & int9 -> int10: the biotite is not a bailee.; int10 & sent11 -> int11: that the folio is either not a bailee or not a shower or both is false.; int11 & sent3 -> hypothesis;
$hypothesis$ = the kitsch is a scarcity. ; $context$ = sent1: the fact that if something is a conchologist then it is a procurator is correct. sent2: the biotite does neglect roots but it is not a kind of a Onopordum. sent3: the kitsch is not a scarcity if the fact that the folio is either not a bailee or not a shower or both does not hold. sent4: the biotite is a capitalization if it is a kind of a bailee. sent5: if the biotite is not a bailee then the folio is a shower. sent6: if the biotite is a procurator the fact that it does rationalize Procyonidae is correct. sent7: the biotite does neglect roots. sent8: if something is not a Onopordum but it is a capitalization then it does not rationalize Procyonidae. sent9: the biotite is a conchologist. sent10: the kitsch is not a scarcity if the fact that the folio is not a bailee or it does shower or both is false. sent11: if the biotite is not a bailee then that the fact that either the folio is not a bailee or it is not a kind of a shower or both is correct does not hold. ; $proof$ = 
void -> assump1: Let's assume that the biotite is a bailee.; sent4 & assump1 -> int1: the biotite is a kind of a capitalization.; sent2 -> int2: the biotite is not a Onopordum.; int1 & int2 -> int3: the biotite is not a Onopordum but a capitalization.; sent8 -> int4: the biotite does not rationalize Procyonidae if it is not a Onopordum but a capitalization.; int3 & int4 -> int5: the biotite does not rationalize Procyonidae.; sent1 -> int6: the fact that the biotite is a kind of a procurator hold if it is a kind of a conchologist.; int6 & sent9 -> int7: the biotite is a kind of a procurator.; sent6 & int7 -> int8: the biotite does rationalize Procyonidae.; int5 & int8 -> int9: this is contradiction.; [assump1] & int9 -> int10: the biotite is not a bailee.; int10 & sent11 -> int11: that the folio is either not a bailee or not a shower or both is false.; int11 & sent3 -> hypothesis; __DISPROVED__