the ordinand does not overuse copper but it is monatomic.
sent1: that something is uncut if it is not a disparagement is true. sent2: if the Capsicum is Appalachians the lac is a cut. sent3: if the Capsicum does overuse copper then that the ordinand is monatomic is right. sent4: if the naphtha does funnel then the fact that it is monatomic is true. sent5: the ordinand is not a kind of a Appalachians but it is an ionization. sent6: the Capsicum is a Appalachians if that it is monatomic is correct. sent7: if something is not Appalachians it is uncut. sent8: the ordinand is not a kind of a disparagement if the Capsicum inherits but it is not a humanism. sent9: the ordinand is a disparagement. sent10: that either something does overuse copper or it is not monatomic or both is not wrong. sent11: if the fact that the Capsicum is not monatomic is not wrong then the ordinand does not overuse copper and is monatomic. sent12: the fact that the ordinand is a kind of a Appalachians is not incorrect if it overuses copper. sent13: the Capsicum is both not a disparagement and monatomic if the lac is not monatomic. sent14: if something is monatomic then the fact that it is not a kind of a Appalachians and is a kind of a cut does not hold. sent15: if that the lac is a kind of non-Appalachians thing that cuts does not hold then it is non-Appalachians. sent16: if the lac is not a kind of a disparagement then it does not overuse copper. sent17: the Capsicum is a Appalachians if the lac is Appalachians. sent18: there exists something such that that it is a humanism and/or it does not inherit is not correct.
void -> assump1: Let's assume that the Capsicum is monatomic.; sent6 & assump1 -> int1: the Capsicum is Appalachians.; int1 & sent2 -> int2: the lac is a cut.; sent1 -> int3: if the lac is not a disparagement it does not cut.;
that the fact that the ordinand does not overuse copper and is monatomic is wrong is not incorrect.
$hypothesis$ = the ordinand does not overuse copper but it is monatomic. ; $context$ = sent1: that something is uncut if it is not a disparagement is true. sent2: if the Capsicum is Appalachians the lac is a cut. sent3: if the Capsicum does overuse copper then that the ordinand is monatomic is right. sent4: if the naphtha does funnel then the fact that it is monatomic is true. sent5: the ordinand is not a kind of a Appalachians but it is an ionization. sent6: the Capsicum is a Appalachians if that it is monatomic is correct. sent7: if something is not Appalachians it is uncut. sent8: the ordinand is not a kind of a disparagement if the Capsicum inherits but it is not a humanism. sent9: the ordinand is a disparagement. sent10: that either something does overuse copper or it is not monatomic or both is not wrong. sent11: if the fact that the Capsicum is not monatomic is not wrong then the ordinand does not overuse copper and is monatomic. sent12: the fact that the ordinand is a kind of a Appalachians is not incorrect if it overuses copper. sent13: the Capsicum is both not a disparagement and monatomic if the lac is not monatomic. sent14: if something is monatomic then the fact that it is not a kind of a Appalachians and is a kind of a cut does not hold. sent15: if that the lac is a kind of non-Appalachians thing that cuts does not hold then it is non-Appalachians. sent16: if the lac is not a kind of a disparagement then it does not overuse copper. sent17: the Capsicum is a Appalachians if the lac is Appalachians. sent18: there exists something such that that it is a humanism and/or it does not inherit is not correct. ; $proof$ = 
void -> assump1: Let's assume that the Capsicum is monatomic.; sent6 & assump1 -> int1: the Capsicum is Appalachians.; int1 & sent2 -> int2: the lac is a cut.; sent1 -> int3: if the lac is not a disparagement it does not cut.; __UNKNOWN__