the individualist is not a Nox.
sent1: The grooving does service individualist. sent2: if the individualist does service grooving and it is economical it is not a Nox. sent3: if that the pommel is radiotelephonic is true then the fact that the individualist dibbles hold. sent4: the pommel is non-radiotelephonic if it does service grooving and it is economical. sent5: if something is a dibble it is economical. sent6: if the pommel does dibble then the individualist is radiotelephonic. sent7: something services grooving if that it is a kind of a dibble and it is not radiotelephonic is not true. sent8: the pommel is radiotelephonic.
sent3 & sent8 -> int1: the individualist is a kind of a dibble.; sent5 -> int2: if the individualist is a dibble then it is economical.; int1 & int2 -> int3: the individualist is economical.;
that the ackee does service grooving is not wrong.
sent7 -> int4: that the ackee services grooving is not incorrect if that it is a dibble and it is not radiotelephonic is false.;
$hypothesis$ = the individualist is not a Nox. ; $context$ = sent1: The grooving does service individualist. sent2: if the individualist does service grooving and it is economical it is not a Nox. sent3: if that the pommel is radiotelephonic is true then the fact that the individualist dibbles hold. sent4: the pommel is non-radiotelephonic if it does service grooving and it is economical. sent5: if something is a dibble it is economical. sent6: if the pommel does dibble then the individualist is radiotelephonic. sent7: something services grooving if that it is a kind of a dibble and it is not radiotelephonic is not true. sent8: the pommel is radiotelephonic. ; $proof$ = 
sent3 & sent8 -> int1: the individualist is a kind of a dibble.; sent5 -> int2: if the individualist is a dibble then it is economical.; int1 & int2 -> int3: the individualist is economical.; __UNKNOWN__