the fact that either the galbulus is a kind of a peduncle or it is a critic or both is not true.
sent1: the fact that the buna does not crystallize Percheron is not wrong. sent2: the galbulus is a peduncle if the buna is puritanical but not implicational. sent3: the buna is not puritanical and it is not implicational if it does not crystallize Percheron. sent4: that either something is a peduncle or it is a critic or both is not correct if it does not crystallize Percheron. sent5: The fact that the Percheron does not crystallize buna is not wrong. sent6: the fact that the galbulus does not crystallize Percheron is right if the buna crystallize Percheron and/or it is a binomial. sent7: the galbulus is a kind of a peduncle if the buna is not puritanical and not implicational.
sent3 & sent1 -> int1: the buna is both non-puritanical and not implicational.; sent7 & int1 -> int2: the galbulus is a kind of a peduncle.; int2 -> hypothesis;
the fact that either the galbulus is a peduncle or it is a critic or both is incorrect.
sent4 -> int3: the fact that the galbulus is a kind of a peduncle or it is a critic or both is false if that it does not crystallize Percheron is not false.;
$hypothesis$ = the fact that either the galbulus is a kind of a peduncle or it is a critic or both is not true. ; $context$ = sent1: the fact that the buna does not crystallize Percheron is not wrong. sent2: the galbulus is a peduncle if the buna is puritanical but not implicational. sent3: the buna is not puritanical and it is not implicational if it does not crystallize Percheron. sent4: that either something is a peduncle or it is a critic or both is not correct if it does not crystallize Percheron. sent5: The fact that the Percheron does not crystallize buna is not wrong. sent6: the fact that the galbulus does not crystallize Percheron is right if the buna crystallize Percheron and/or it is a binomial. sent7: the galbulus is a kind of a peduncle if the buna is not puritanical and not implicational. ; $proof$ = 
sent3 & sent1 -> int1: the buna is both non-puritanical and not implicational.; sent7 & int1 -> int2: the galbulus is a kind of a peduncle.; int2 -> hypothesis; __DISPROVED__