the fact that the smut is healthful is not false.
sent1: the fact that that the hemp does mimeograph and is a kind of a panda is not right is correct if the boot is not paschal. sent2: something that is a kind of a panda is a kind of paschal thing that is not eparchial. sent3: if that the hemp is not a kind of a panda hold the smut is not healthful. sent4: if that the hemp is a mimeograph and it is a panda is not correct then the smut is not healthful. sent5: the boot is a panda and a mimeograph if the hemp is not a unthoughtfulness. sent6: that the boot is not eparchial is right. sent7: if that something is a unthoughtfulness that does harry Tetrao is not true it is not a unthoughtfulness. sent8: the smut is paschal. sent9: the boot is eparchial if it is paschal.
void -> assump1: Let's assume that the boot is paschal.; sent9 & assump1 -> int1: the boot is eparchial.; int1 & sent6 -> int2: this is contradiction.; [assump1] & int2 -> int3: the boot is not paschal.; int3 & sent1 -> int4: the fact that the hemp is both a mimeograph and a panda is wrong.; int4 & sent4 -> hypothesis;
the smut is healthful.
sent2 -> int5: if the boot is a panda then it is both paschal and not eparchial.; sent7 -> int6: the hemp is not a unthoughtfulness if that it is a unthoughtfulness and it harries Tetrao does not hold.;
$hypothesis$ = the fact that the smut is healthful is not false. ; $context$ = sent1: the fact that that the hemp does mimeograph and is a kind of a panda is not right is correct if the boot is not paschal. sent2: something that is a kind of a panda is a kind of paschal thing that is not eparchial. sent3: if that the hemp is not a kind of a panda hold the smut is not healthful. sent4: if that the hemp is a mimeograph and it is a panda is not correct then the smut is not healthful. sent5: the boot is a panda and a mimeograph if the hemp is not a unthoughtfulness. sent6: that the boot is not eparchial is right. sent7: if that something is a unthoughtfulness that does harry Tetrao is not true it is not a unthoughtfulness. sent8: the smut is paschal. sent9: the boot is eparchial if it is paschal. ; $proof$ = 
void -> assump1: Let's assume that the boot is paschal.; sent9 & assump1 -> int1: the boot is eparchial.; int1 & sent6 -> int2: this is contradiction.; [assump1] & int2 -> int3: the boot is not paschal.; int3 & sent1 -> int4: the fact that the hemp is both a mimeograph and a panda is wrong.; int4 & sent4 -> hypothesis; __DISPROVED__