that the proctoscope is not corrupt is correct.
sent1: the proctoscope is a Ferocactus if the fact that it is not alkaline is not incorrect. sent2: if the Saudi is a kind of a popover then it does not tighten proctoscope and it is not a basileus. sent3: the foster-nurse is not a kind of a Bushnell. sent4: the Saudi is not a doghouse if it tightens proctoscope and is not a basileus. sent5: the proctoscope is not corrupt if it is a Ferocactus. sent6: if the Saudi is a popover then it does not tighten proctoscope. sent7: if the foster-nurse is a doghouse then the fact that it is a kind of a Bushnell is true. sent8: the foster-nurse is a Bushnell if the fact that it is both not Ebionite and not a doghouse is wrong. sent9: the Saudi is a popover if the proctoscope is alkaline. sent10: if the Saudi does not tighten proctoscope and is not a kind of a basileus that it is not a doghouse hold.
void -> assump1: Let's assume that the proctoscope is alkaline.; sent9 & assump1 -> int1: the Saudi is a kind of a popover.; int1 & sent2 -> int2: the Saudi does not tighten proctoscope and is not a basileus.; int2 & sent10 -> int3: the Saudi is not a doghouse.;
$hypothesis$ = that the proctoscope is not corrupt is correct. ; $context$ = sent1: the proctoscope is a Ferocactus if the fact that it is not alkaline is not incorrect. sent2: if the Saudi is a kind of a popover then it does not tighten proctoscope and it is not a basileus. sent3: the foster-nurse is not a kind of a Bushnell. sent4: the Saudi is not a doghouse if it tightens proctoscope and is not a basileus. sent5: the proctoscope is not corrupt if it is a Ferocactus. sent6: if the Saudi is a popover then it does not tighten proctoscope. sent7: if the foster-nurse is a doghouse then the fact that it is a kind of a Bushnell is true. sent8: the foster-nurse is a Bushnell if the fact that it is both not Ebionite and not a doghouse is wrong. sent9: the Saudi is a popover if the proctoscope is alkaline. sent10: if the Saudi does not tighten proctoscope and is not a kind of a basileus that it is not a doghouse hold. ; $proof$ = 
void -> assump1: Let's assume that the proctoscope is alkaline.; sent9 & assump1 -> int1: the Saudi is a kind of a popover.; int1 & sent2 -> int2: the Saudi does not tighten proctoscope and is not a basileus.; int2 & sent10 -> int3: the Saudi is not a doghouse.; __UNKNOWN__