the fact that the sheldrake is seamanlike is not incorrect.
sent1: that the Taurus is not a martinet and it does not debrief logic is not correct. sent2: everything does not debrief logic. sent3: if something is a kind of non-inland a martinet then it is not seamanlike. sent4: the fact that something is terminological and it is seamanlike if it is not inland is not incorrect. sent5: the Taurus is not a kind of a martinet if the fact that it is a kind of a Permian and it is not cross-linguistic does not hold. sent6: the fact that the Taurus is a Permian but not cross-linguistic is wrong if the sheldrake is inland.
void -> assump1: Let's assume that the sheldrake is inland.; sent6 & assump1 -> int1: the fact that the Taurus is a Permian but it is not cross-linguistic is false.; int1 & sent5 -> int2: the Taurus is not a martinet.; sent2 -> int3: that the Taurus does not debrief logic is not false.; int2 & int3 -> int4: the Taurus is not a martinet and does not debrief logic.; int4 & sent1 -> int5: this is contradiction.; [assump1] & int5 -> int6: the sheldrake is not inland.; sent4 -> int7: the sheldrake is terminological and seamanlike if it is not inland.; int6 & int7 -> int8: the sheldrake is terminological and it is seamanlike.; int8 -> hypothesis;
the sheldrake is not seamanlike.
sent3 -> int9: the sheldrake is not seamanlike if it is not inland and it is a martinet.;
$hypothesis$ = the fact that the sheldrake is seamanlike is not incorrect. ; $context$ = sent1: that the Taurus is not a martinet and it does not debrief logic is not correct. sent2: everything does not debrief logic. sent3: if something is a kind of non-inland a martinet then it is not seamanlike. sent4: the fact that something is terminological and it is seamanlike if it is not inland is not incorrect. sent5: the Taurus is not a kind of a martinet if the fact that it is a kind of a Permian and it is not cross-linguistic does not hold. sent6: the fact that the Taurus is a Permian but not cross-linguistic is wrong if the sheldrake is inland. ; $proof$ = 
void -> assump1: Let's assume that the sheldrake is inland.; sent6 & assump1 -> int1: the fact that the Taurus is a Permian but it is not cross-linguistic is false.; int1 & sent5 -> int2: the Taurus is not a martinet.; sent2 -> int3: that the Taurus does not debrief logic is not false.; int2 & int3 -> int4: the Taurus is not a martinet and does not debrief logic.; int4 & sent1 -> int5: this is contradiction.; [assump1] & int5 -> int6: the sheldrake is not inland.; sent4 -> int7: the sheldrake is terminological and seamanlike if it is not inland.; int6 & int7 -> int8: the sheldrake is terminological and it is seamanlike.; int8 -> hypothesis; __PROVED__