the fact that the refrigerant is not a Cottus but it does ferment town is correct.
sent1: the simple does not ring. sent2: the fact that the simple does not ferment town is true if it is not a stardom. sent3: the refrigerant is not a Cottus but it does ferment town if the simple does not ferment town. sent4: the simple is xerographic and/or it does harangue beading. sent5: if the fact that either something is xerographic or it does not harangue beading or both is wrong then that it does ring is not wrong. sent6: something is not a kind of a stardom if it is xerographic and/or it does not harangue beading.
sent5 -> int1: the simple rings if that it is xerographic and/or it does not harangue beading is false.; void -> assump1: Let's assume that that either the simple is xerographic or it does not harangue beading or both is false.; int1 & assump1 -> int2: the simple is a kind of a ring.; int2 & sent1 -> int3: this is contradiction.; [assump1] & int3 -> int4: the simple is xerographic and/or it does not harangue beading.; sent6 -> int5: if the simple is xerographic and/or does not harangue beading it is not a kind of a stardom.; int4 & int5 -> int6: the simple is not a stardom.; int6 & sent2 -> int7: the simple does not ferment town.; int7 & sent3 -> hypothesis;
$hypothesis$ = the fact that the refrigerant is not a Cottus but it does ferment town is correct. ; $context$ = sent1: the simple does not ring. sent2: the fact that the simple does not ferment town is true if it is not a stardom. sent3: the refrigerant is not a Cottus but it does ferment town if the simple does not ferment town. sent4: the simple is xerographic and/or it does harangue beading. sent5: if the fact that either something is xerographic or it does not harangue beading or both is wrong then that it does ring is not wrong. sent6: something is not a kind of a stardom if it is xerographic and/or it does not harangue beading. ; $proof$ = 
sent5 -> int1: the simple rings if that it is xerographic and/or it does not harangue beading is false.; void -> assump1: Let's assume that that either the simple is xerographic or it does not harangue beading or both is false.; int1 & assump1 -> int2: the simple is a kind of a ring.; int2 & sent1 -> int3: this is contradiction.; [assump1] & int3 -> int4: the simple is xerographic and/or it does not harangue beading.; sent6 -> int5: if the simple is xerographic and/or does not harangue beading it is not a kind of a stardom.; int4 & int5 -> int6: the simple is not a stardom.; int6 & sent2 -> int7: the simple does not ferment town.; int7 & sent3 -> hypothesis; __PROVED__