the spindleberry does not squeegee redhorse.
sent1: if the bimetallist is not a Reich but it is not non-uncial then the carper is a cellarage. sent2: if the bimetallist is authorial and is a kind of a cellarage the spindleberry does not squeegee redhorse. sent3: something is a kind of a cellarage if it is not non-multilateral. sent4: if there exists something such that it is arboreal then the fact that the mender is a stylization but it does not squeegee penalty is false. sent5: there is something such that it is arboreal. sent6: that the skylark is both a victualer and not arboreal is not true. sent7: that the bimetallist is multilateral is not wrong if the carper is multilateral thing that is not a combretum. sent8: if the carper is multilateral or it is not authorial or both then the spindleberry does squeegee redhorse. sent9: the Maltese is a kind of a stylization if the carper does not squeegee penalty. sent10: if there exists something such that the fact that it is a kind of non-comparative thing that is a stylization is not correct then the Maltese is not a stylization. sent11: if that the bailiwick is not a kind of an upset and is a victualer is false it is not a victualer. sent12: if the skylark is not a victualer it is a combretum and it is authorial. sent13: the bimetallist is not a Reich and is uncial. sent14: if something is not a stylization then it is a cellarage that does squeegee penalty. sent15: if there exists something such that the fact that it is a stylization and it does not squeegee penalty does not hold the bimetallist is authorial. sent16: if the bailiwick does not powwow Tyler the fact that it is not a kind of an upset and is a kind of a victualer is not correct. sent17: the carper does not squeegee penalty if it is a cellarage and it is authorial. sent18: if something is authorial and it is a cellarage it is not a comparative. sent19: if the fact that the skylark is a kind of a victualer but it is not arboreal is not right it is not a victualer. sent20: that the mender is both not a comparative and a stylization is not correct.
sent1 & sent13 -> int1: the carper is a cellarage.; void -> assump1: Let's assume that the carper is authorial.; int1 & assump1 -> int2: the carper is a kind of a cellarage and it is authorial.; int2 & sent17 -> int3: the carper does not squeegee penalty.; int3 & sent9 -> int4: the Maltese is a stylization.; sent20 -> int5: there is something such that that it is not comparative and it is a kind of a stylization is incorrect.; int5 & sent10 -> int6: the Maltese is not a kind of a stylization.; int4 & int6 -> int7: this is contradiction.; [assump1] & int7 -> int8: the carper is not authorial.; int8 -> int9: the carper either is multilateral or is not authorial or both.; int9 & sent8 -> hypothesis;
the skylark is not a comparative.
sent18 -> int10: the skylark is not a kind of a comparative if it is a kind of authorial thing that is a cellarage.; sent19 & sent6 -> int11: the skylark is not a victualer.; sent12 & int11 -> int12: the skylark is a combretum that is authorial.; int12 -> int13: the skylark is authorial.; sent14 -> int14: if the skylark is not a kind of a stylization it is a cellarage and squeegees penalty.;
$hypothesis$ = the spindleberry does not squeegee redhorse. ; $context$ = sent1: if the bimetallist is not a Reich but it is not non-uncial then the carper is a cellarage. sent2: if the bimetallist is authorial and is a kind of a cellarage the spindleberry does not squeegee redhorse. sent3: something is a kind of a cellarage if it is not non-multilateral. sent4: if there exists something such that it is arboreal then the fact that the mender is a stylization but it does not squeegee penalty is false. sent5: there is something such that it is arboreal. sent6: that the skylark is both a victualer and not arboreal is not true. sent7: that the bimetallist is multilateral is not wrong if the carper is multilateral thing that is not a combretum. sent8: if the carper is multilateral or it is not authorial or both then the spindleberry does squeegee redhorse. sent9: the Maltese is a kind of a stylization if the carper does not squeegee penalty. sent10: if there exists something such that the fact that it is a kind of non-comparative thing that is a stylization is not correct then the Maltese is not a stylization. sent11: if that the bailiwick is not a kind of an upset and is a victualer is false it is not a victualer. sent12: if the skylark is not a victualer it is a combretum and it is authorial. sent13: the bimetallist is not a Reich and is uncial. sent14: if something is not a stylization then it is a cellarage that does squeegee penalty. sent15: if there exists something such that the fact that it is a stylization and it does not squeegee penalty does not hold the bimetallist is authorial. sent16: if the bailiwick does not powwow Tyler the fact that it is not a kind of an upset and is a kind of a victualer is not correct. sent17: the carper does not squeegee penalty if it is a cellarage and it is authorial. sent18: if something is authorial and it is a cellarage it is not a comparative. sent19: if the fact that the skylark is a kind of a victualer but it is not arboreal is not right it is not a victualer. sent20: that the mender is both not a comparative and a stylization is not correct. ; $proof$ = 
sent1 & sent13 -> int1: the carper is a cellarage.; void -> assump1: Let's assume that the carper is authorial.; int1 & assump1 -> int2: the carper is a kind of a cellarage and it is authorial.; int2 & sent17 -> int3: the carper does not squeegee penalty.; int3 & sent9 -> int4: the Maltese is a stylization.; sent20 -> int5: there is something such that that it is not comparative and it is a kind of a stylization is incorrect.; int5 & sent10 -> int6: the Maltese is not a kind of a stylization.; int4 & int6 -> int7: this is contradiction.; [assump1] & int7 -> int8: the carper is not authorial.; int8 -> int9: the carper either is multilateral or is not authorial or both.; int9 & sent8 -> hypothesis; __DISPROVED__