the cinch pecks favorite.
sent1: if something is not compatible and is a fossil then the fact that it is not a Opisthobranchia hold. sent2: something is non-sober thing that is not a kind of a Sphinx if it does not peck favorite. sent3: something does not appreciate or it does not peck Moselle or both if it pecks favorite. sent4: there is something such that it is not a fossil. sent5: the Parks is non-compatible thing that is fossil. sent6: if the cinch does peck Moselle it either is not a puddler or is not compatible or both. sent7: the Parks is not compatible but it is a puddler if it does not peck Moselle. sent8: The Moselle pecks cinch. sent9: the cinch is a kind of a Opisthobranchia if it is not a puddler or not compatible or both. sent10: if a non-sober thing is not a Sphinx then it is not a kind of a Opisthobranchia. sent11: the cinch pecks Moselle.
sent2 -> int1: the cinch does not sober and it is not a Sphinx if it does not peck favorite.; void -> assump1: Let's assume that that the cinch does peck favorite is incorrect.; int1 & assump1 -> int2: the cinch does not sober and it is not a kind of a Sphinx.; sent10 -> int3: the cinch is not a Opisthobranchia if it is not sober and it is not a kind of a Sphinx.; int2 & int3 -> int4: the cinch is not a Opisthobranchia.; sent6 & sent11 -> int5: the cinch is not a puddler or not compatible or both.; sent9 & int5 -> int6: the cinch is a kind of a Opisthobranchia.; int4 & int6 -> int7: this is contradiction.; [assump1] & int7 -> hypothesis;
the setscrew does not appreciate or it does not peck Moselle or both.
sent3 -> int8: if the setscrew pecks favorite it does not appreciate and/or it does not peck Moselle.; sent1 -> int9: the Parks is not a Opisthobranchia if it is both not compatible and a fossil.; int9 & sent5 -> int10: the Parks is not a Opisthobranchia.;
$hypothesis$ = the cinch pecks favorite. ; $context$ = sent1: if something is not compatible and is a fossil then the fact that it is not a Opisthobranchia hold. sent2: something is non-sober thing that is not a kind of a Sphinx if it does not peck favorite. sent3: something does not appreciate or it does not peck Moselle or both if it pecks favorite. sent4: there is something such that it is not a fossil. sent5: the Parks is non-compatible thing that is fossil. sent6: if the cinch does peck Moselle it either is not a puddler or is not compatible or both. sent7: the Parks is not compatible but it is a puddler if it does not peck Moselle. sent8: The Moselle pecks cinch. sent9: the cinch is a kind of a Opisthobranchia if it is not a puddler or not compatible or both. sent10: if a non-sober thing is not a Sphinx then it is not a kind of a Opisthobranchia. sent11: the cinch pecks Moselle. ; $proof$ = 
sent2 -> int1: the cinch does not sober and it is not a Sphinx if it does not peck favorite.; void -> assump1: Let's assume that that the cinch does peck favorite is incorrect.; int1 & assump1 -> int2: the cinch does not sober and it is not a kind of a Sphinx.; sent10 -> int3: the cinch is not a Opisthobranchia if it is not sober and it is not a kind of a Sphinx.; int2 & int3 -> int4: the cinch is not a Opisthobranchia.; sent6 & sent11 -> int5: the cinch is not a puddler or not compatible or both.; sent9 & int5 -> int6: the cinch is a kind of a Opisthobranchia.; int4 & int6 -> int7: this is contradiction.; [assump1] & int7 -> hypothesis; __PROVED__