the fact that the nucleotide is a pyxie if that the coreligionist is vascular is correct does not hold.
sent1: the nectarine is inconstant and it is a kind of a patter. sent2: if the coreligionist is not a Bedlam then the nucleotide is a pyxie. sent3: something is not vascular if it is both an everyman and a Bedlam. sent4: the nectarine is a kind of a coupling but it is not a caste. sent5: that the nucleotide does deflate spam is correct. sent6: the coreligionist is vascular if it is a kind of an everyman and is a kind of a Bedlam. sent7: the fact that the nectarine is not a Bedlam but it is a kind of a pyxie is wrong if it is not an everyman. sent8: the nectarine is not a caste. sent9: the nucleotide is an everyman. sent10: the nucleotide is a kind of a caste. sent11: the nucleotide does couple. sent12: if something is a caste and it is a kind of a Bedlam it is not a kind of an everyman. sent13: an everyman that is a kind of a Bedlam is vascular. sent14: if the nectarine does couple and it is vascular then it is not a caste. sent15: the fact that something is not a kind of an everyman if it is vascular and it is a pyxie is right. sent16: the coreligionist is not non-anguine and it slags Tay. sent17: if the nectarine is a coupling but it is not a kind of a caste the fact that the coreligionist is a kind of an everyman hold. sent18: the coreligionist is a kind of an everyman if the nectarine does couple and it is a kind of a caste.
sent17 & sent4 -> int1: the coreligionist is an everyman.; void -> assump2: Let's assume that the coreligionist is a Bedlam.; int1 & assump2 -> int2: the coreligionist is an everyman and is a kind of a Bedlam.; sent3 -> int3: if the coreligionist is an everyman and it is a Bedlam then that it is not vascular hold.; int2 & int3 -> int4: the coreligionist is not vascular.; void -> assump1: Let's assume that the coreligionist is vascular.; int4 & assump1 -> int5: this is contradiction.; [assump2] & int5 -> int6: the coreligionist is not a Bedlam.; int6 & sent2 -> int7: the nucleotide is a kind of a pyxie.; [assump1] & int7 -> hypothesis;
the disaccharide is not a pyxie.
$hypothesis$ = the fact that the nucleotide is a pyxie if that the coreligionist is vascular is correct does not hold. ; $context$ = sent1: the nectarine is inconstant and it is a kind of a patter. sent2: if the coreligionist is not a Bedlam then the nucleotide is a pyxie. sent3: something is not vascular if it is both an everyman and a Bedlam. sent4: the nectarine is a kind of a coupling but it is not a caste. sent5: that the nucleotide does deflate spam is correct. sent6: the coreligionist is vascular if it is a kind of an everyman and is a kind of a Bedlam. sent7: the fact that the nectarine is not a Bedlam but it is a kind of a pyxie is wrong if it is not an everyman. sent8: the nectarine is not a caste. sent9: the nucleotide is an everyman. sent10: the nucleotide is a kind of a caste. sent11: the nucleotide does couple. sent12: if something is a caste and it is a kind of a Bedlam it is not a kind of an everyman. sent13: an everyman that is a kind of a Bedlam is vascular. sent14: if the nectarine does couple and it is vascular then it is not a caste. sent15: the fact that something is not a kind of an everyman if it is vascular and it is a pyxie is right. sent16: the coreligionist is not non-anguine and it slags Tay. sent17: if the nectarine is a coupling but it is not a kind of a caste the fact that the coreligionist is a kind of an everyman hold. sent18: the coreligionist is a kind of an everyman if the nectarine does couple and it is a kind of a caste. ; $proof$ = 
sent17 & sent4 -> int1: the coreligionist is an everyman.; void -> assump2: Let's assume that the coreligionist is a Bedlam.; int1 & assump2 -> int2: the coreligionist is an everyman and is a kind of a Bedlam.; sent3 -> int3: if the coreligionist is an everyman and it is a Bedlam then that it is not vascular hold.; int2 & int3 -> int4: the coreligionist is not vascular.; void -> assump1: Let's assume that the coreligionist is vascular.; int4 & assump1 -> int5: this is contradiction.; [assump2] & int5 -> int6: the coreligionist is not a Bedlam.; int6 & sent2 -> int7: the nucleotide is a kind of a pyxie.; [assump1] & int7 -> hypothesis; __DISPROVED__