the fact that the sutler is not an insubordination if the fact that the footbath does not lather lectin and is irresistible is wrong is not correct.
sent1: if the footbath is resistible the sutler is not an insubordination. sent2: everything does not lather rewrite. sent3: if the sutler is an insubordination it is not a ruddle and it is a alpha-naphthol. sent4: the sutler is a alpha-naphthol if it is an insubordination. sent5: if something does not lather rewrite the fact that that it lathers lectin and it is a concreteness hold is wrong. sent6: the sutler is not an insubordination if the footbath does not lather lectin and is not resistible. sent7: if the sutler is inglorious then the footbath is not resistible. sent8: if that the footbath does not lather lectin and it is not resistible is not correct the sutler is a kind of an insubordination. sent9: if something is not a ruddle but it is a kind of a alpha-naphthol it is inglorious. sent10: if the sutler is inglorious the footbath does lather lectin and is not resistible. sent11: the sutler is not an insubordination if that the footbath does lather lectin and is not resistible is false. sent12: the footbath ruddles. sent13: the footbath is not resistible. sent14: the sutler is a alpha-naphthol. sent15: if the sutler is inglorious then the footbath does not lather lectin and it is not resistible. sent16: that the footbath does not lather lectin but it is resistible does not hold.
void -> assump2: Let's assume that the sutler is an insubordination.; sent3 & assump2 -> int1: the sutler is not a ruddle but a alpha-naphthol.; sent9 -> int2: if the sutler is not a kind of a ruddle but it is a kind of a alpha-naphthol then it is inglorious.; int1 & int2 -> int3: the sutler is inglorious.; int3 & sent15 -> int4: the footbath does not lather lectin and is not resistible.; void -> assump1: Let's assume that that the footbath does not lather lectin and is not resistible is not right.; int4 & assump1 -> int5: this is contradiction.; [assump2] & int5 -> int6: the sutler is not a kind of an insubordination.; [assump1] & int6 -> hypothesis;
the dictionary is irresistible.
sent5 -> int7: that the footbath lathers lectin and is a concreteness is not true if it does not lather rewrite.; sent2 -> int8: the footbath does not lather rewrite.; int7 & int8 -> int9: that the footbath does lather lectin and is a concreteness does not hold.; int9 -> int10: there is nothing that lathers lectin and is a kind of a concreteness.; int10 -> int11: the fact that that the sutler lathers lectin and is a concreteness does not hold hold.;
$hypothesis$ = the fact that the sutler is not an insubordination if the fact that the footbath does not lather lectin and is irresistible is wrong is not correct. ; $context$ = sent1: if the footbath is resistible the sutler is not an insubordination. sent2: everything does not lather rewrite. sent3: if the sutler is an insubordination it is not a ruddle and it is a alpha-naphthol. sent4: the sutler is a alpha-naphthol if it is an insubordination. sent5: if something does not lather rewrite the fact that that it lathers lectin and it is a concreteness hold is wrong. sent6: the sutler is not an insubordination if the footbath does not lather lectin and is not resistible. sent7: if the sutler is inglorious then the footbath is not resistible. sent8: if that the footbath does not lather lectin and it is not resistible is not correct the sutler is a kind of an insubordination. sent9: if something is not a ruddle but it is a kind of a alpha-naphthol it is inglorious. sent10: if the sutler is inglorious the footbath does lather lectin and is not resistible. sent11: the sutler is not an insubordination if that the footbath does lather lectin and is not resistible is false. sent12: the footbath ruddles. sent13: the footbath is not resistible. sent14: the sutler is a alpha-naphthol. sent15: if the sutler is inglorious then the footbath does not lather lectin and it is not resistible. sent16: that the footbath does not lather lectin but it is resistible does not hold. ; $proof$ = 
void -> assump2: Let's assume that the sutler is an insubordination.; sent3 & assump2 -> int1: the sutler is not a ruddle but a alpha-naphthol.; sent9 -> int2: if the sutler is not a kind of a ruddle but it is a kind of a alpha-naphthol then it is inglorious.; int1 & int2 -> int3: the sutler is inglorious.; int3 & sent15 -> int4: the footbath does not lather lectin and is not resistible.; void -> assump1: Let's assume that that the footbath does not lather lectin and is not resistible is not right.; int4 & assump1 -> int5: this is contradiction.; [assump2] & int5 -> int6: the sutler is not a kind of an insubordination.; [assump1] & int6 -> hypothesis; __DISPROVED__