that the fact that the washerman does freckle limnology is not wrong if the beachhead is a plowshare is incorrect.
sent1: something is inadvisable and it is a plowshare if it is not temperate. sent2: the beachhead is not inadvisable. sent3: that the beachhead is not a kind of a plowshare if the placoderm is a chervil is right. sent4: if the placoderm freckles limnology the washerman is inadvisable. sent5: the terrarium does freckle limnology if there exists something such that the fact that it does not freckle limnology and it is a chervil is not correct. sent6: that the placoderm is a kind of a chervil and is inadvisable is not right. sent7: that the washerman is not inadvisable is right if it freckles limnology. sent8: the beachhead is not a kind of a plowshare if the fact that the placoderm is not a chervil but it is not advisable is false. sent9: the washerman is not a chervil. sent10: if the fact that the washerman is not inadvisable is true then it is not a chervil. sent11: if the washerman is not inadvisable that the placoderm is not a chervil but inadvisable is incorrect. sent12: if that the washerman is non-inadvisable a chervil is not true the placoderm does not freckle limnology. sent13: if the washerman does not freckle limnology that it is not inadvisable hold. sent14: that the beachhead is both not a plowshare and a moth is false. sent15: the placoderm is not a bracken. sent16: if something is inadvisable the fact that it does not freckle limnology and it is a chervil is not right. sent17: the fact that the placoderm is a kind of a chervil that is inadvisable does not hold if the washerman is not inadvisable.
void -> assump2: Let's assume that the beachhead is a plowshare.; void -> assump1: Let's assume that the washerman does not freckle limnology.; sent13 & assump1 -> int1: the washerman is not inadvisable.; sent11 & int1 -> int2: the fact that the placoderm is both not a chervil and inadvisable is false.; sent8 & int2 -> int3: the beachhead is not a kind of a plowshare.; assump2 & int3 -> int4: this is contradiction.; [assump1] & int4 -> int5: the fact that the washerman freckles limnology is correct.; [assump2] & int5 -> hypothesis;
the terrarium does freckle limnology.
sent16 -> int6: if the washerman is inadvisable the fact that it does not freckle limnology and is a chervil is not true.; sent1 -> int7: if the placoderm is not temperate it is inadvisable and it is a plowshare.;
$hypothesis$ = that the fact that the washerman does freckle limnology is not wrong if the beachhead is a plowshare is incorrect. ; $context$ = sent1: something is inadvisable and it is a plowshare if it is not temperate. sent2: the beachhead is not inadvisable. sent3: that the beachhead is not a kind of a plowshare if the placoderm is a chervil is right. sent4: if the placoderm freckles limnology the washerman is inadvisable. sent5: the terrarium does freckle limnology if there exists something such that the fact that it does not freckle limnology and it is a chervil is not correct. sent6: that the placoderm is a kind of a chervil and is inadvisable is not right. sent7: that the washerman is not inadvisable is right if it freckles limnology. sent8: the beachhead is not a kind of a plowshare if the fact that the placoderm is not a chervil but it is not advisable is false. sent9: the washerman is not a chervil. sent10: if the fact that the washerman is not inadvisable is true then it is not a chervil. sent11: if the washerman is not inadvisable that the placoderm is not a chervil but inadvisable is incorrect. sent12: if that the washerman is non-inadvisable a chervil is not true the placoderm does not freckle limnology. sent13: if the washerman does not freckle limnology that it is not inadvisable hold. sent14: that the beachhead is both not a plowshare and a moth is false. sent15: the placoderm is not a bracken. sent16: if something is inadvisable the fact that it does not freckle limnology and it is a chervil is not right. sent17: the fact that the placoderm is a kind of a chervil that is inadvisable does not hold if the washerman is not inadvisable. ; $proof$ = 
void -> assump2: Let's assume that the beachhead is a plowshare.; void -> assump1: Let's assume that the washerman does not freckle limnology.; sent13 & assump1 -> int1: the washerman is not inadvisable.; sent11 & int1 -> int2: the fact that the placoderm is both not a chervil and inadvisable is false.; sent8 & int2 -> int3: the beachhead is not a kind of a plowshare.; assump2 & int3 -> int4: this is contradiction.; [assump1] & int4 -> int5: the fact that the washerman freckles limnology is correct.; [assump2] & int5 -> hypothesis; __DISPROVED__