Evaluating $f(x)$ for $x=3$ and $x=-3$, we have \[\left\{ \begin{aligned} f(3)& = a \cdot 3^4 - b \cdot 3^2 + 3 + 5, \\ f(-3) &= a \cdot (-3)^4 - b \cdot (-3)^2 + (-3) + 5. \end{aligned} \right.\]If we subtract the second equation from the first equation, all the terms but one cancel out, and we get \[f(3) - f(-3) = 3 - (-3) = 6.\]Thus, if $f(-3) = 2,$ then $f(3) = f(-3) + 6 = 2 + 6 = \boxed{8}.$
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
If $f(x)=ax^4-bx^2+x+5$ and $f(-3)=2,$ then what is the value of $f(3)$?
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
8
If $f(x)=ax^4-bx^2+x+5$ and $f(-3)=2,$ then what is the value of $f(3)$?
test