An integer is divisible by 12 if and only if it is divisible by both 3 and 4.  Because $2+0+0+4=6$ is divisible by 3, 2004 is divisible by 3.  Also, the last two digits of 2004 form a multiple of 4, so 2004 is divisible by 4 as well. Therefore, 2004 is divisible by 12 and hence leaves a remainder of $\boxed{0}$ when divided by 12.
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
What is the remainder of 2004 divided by 12?
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
0
What is the remainder of 2004 divided by 12?
test