Since $\sqrt{16}<\sqrt{20}<\sqrt{25}$, or, equivalently, $4<\sqrt{20}<5$, the smallest integer greater than or equal to $\sqrt{20}$ must be $5$. Thus, $\lceil{\sqrt{20}}\rceil^2=5^2=\boxed{25}$.
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Evaluate $\lceil{\sqrt{20}}\rceil^2$.
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
25
Evaluate $\lceil{\sqrt{20}}\rceil^2$.
test