solution: Since \begin{align*}
  (3x-2)(4x+1)-(3x-2)4x+1 &=(3x-2)(4x+1-4x)+1 \\
  &=(3x-2) \cdot 1 +1 =3x-1,
  \end{align*} when $x=4$ we have the value $3 \cdot 4 -1 =\boxed{11}$.
prompt.content: <|im_start|>system
  You are a helpful assistant.<|im_end|>
  <|im_start|>user
  What is the value of $$
  (3x-2)(4x+1)-(3x-2)4x+1
  $$ when $x=4$?
  Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
  <|im_start|>assistant
  
prompt.role: user
extra_info.answer: 11
extra_info.question: What is the value of $$
  (3x-2)(4x+1)-(3x-2)4x+1
  $$ when $x=4$?
extra_info.split: test