solution: In order for $\log x^2$ to be defined, we must have $x^2 > 0$. This true for all $x$, except for $x = 0$. It follows that the domain of this function is $x < 0$ or $x > 0$. Therefore, our answer is $0 + 0 = \boxed{0}$.
prompt.content: <|im_start|>system
  You are a helpful assistant.<|im_end|>
  <|im_start|>user
  If the domain of the function $\log x^2$ is $x < a$ or $x > b$, for some $a$ and $b$, find $a + b$.
  Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
  <|im_start|>assistant
  
prompt.role: user
extra_info.answer: 0
extra_info.question: If the domain of the function $\log x^2$ is $x < a$ or $x > b$, for some $a$ and $b$, find $a + b$.
extra_info.split: test