solution: The sequence of odd numbers 1, 3, 5, 7, and so on, is an arithmetic sequence, with common difference 2.  Therefore, the $2003^{\text{rd}}$ term is $1+2002\cdot2=\boxed{4005}$.
prompt.content: <|im_start|>system
  You are a helpful assistant.<|im_end|>
  <|im_start|>user
  What is the 2003rd term of the sequence of odd numbers 1, 3, 5, 7, $\dots$?
  Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
  <|im_start|>assistant
  
prompt.role: user
extra_info.answer: 4005
extra_info.question: What is the 2003rd term of the sequence of odd numbers 1, 3, 5, 7, $\dots$?
extra_info.split: test