solution: Since $\sqrt{16}<\sqrt{20}<\sqrt{25}$, or, equivalently, $4<\sqrt{20}<5$, the smallest integer greater than or equal to $\sqrt{20}$ must be $5$. Thus, $\lceil{\sqrt{20}}\rceil^2=5^2=\boxed{25}$.
prompt.content: <|im_start|>system
  You are a helpful assistant.<|im_end|>
  <|im_start|>user
  Evaluate $\lceil{\sqrt{20}}\rceil^2$.
  Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
  <|im_start|>assistant
  
prompt.role: user
extra_info.answer: 25
extra_info.question: Evaluate $\lceil{\sqrt{20}}\rceil^2$.
extra_info.split: test