solution: Adding the first given equation to the second, we have $a+2b+c=5$. Then, subtracting the third given equation from this last equation, we get $2b=10$, so $b=5$. Plugging this value of $b$ into the first given equation, we find that $a=3$. Plugging this value of $a$ into the third given equation, we find that $c=-8$. Thus, the product $abc=3\cdot5\cdot-8=\boxed{-120}$.
prompt.content: <|im_start|>system
  You are a helpful assistant.<|im_end|>
  <|im_start|>user
  If $a+b=8$, $b+c=-3$, and $a+c= -5$, what is the value of the product $abc$?
  Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
  <|im_start|>assistant
  
prompt.role: user
extra_info.answer: -120
extra_info.question: If $a+b=8$, $b+c=-3$, and $a+c= -5$, what is the value of the product $abc$?
extra_info.split: test