solution: Since three of the roots of $p(x)$ are 1, 2, and 3, we can write
  \[p(x) = (x - 1)(x - 2)(x - 3)(x - r).\]Then
  \begin{align*}
  p(0) + p(4) &= (-1)(-2)(-3)(-r) + (3)(2)(1)(4 - r) \\
  &= 6r + 24 - 6r = \boxed{24}.
  \end{align*}
prompt.content: <|im_start|>system
  You are a helpful assistant.<|im_end|>
  <|im_start|>user
  Let $p(x)$ be a monic polynomial of degree 4.  Three of the roots of $p(x)$ are 1, 2, and 3.  Find $p(0) + p(4).$
  Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
  <|im_start|>assistant
  
prompt.role: user
extra_info.answer: 24
extra_info.question: Let $p(x)$ be a monic polynomial of degree 4.  Three of the roots of $p(x)$ are 1, 2, and 3.  Find $p(0) + p(4).$
extra_info.split: test