Re-arranging, $x^2 - 5x - 14 \le 0$. The left-hand quadratic factors as $x^2 - 5x - 14 = (x - 7)(x + 2) \le 0$. Thus, $x-7$ and $x+2$ have opposite signs, so $-2 \le x \le 7$ and $\boxed{x \in [-2,7]}$.
Question:
For what values of $x$ is it true that $x^2 - 5x - 4 \le 10$? Express your answer in interval notation.
Answer:
Let's think step by step.

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x \in [-2,7]
For what values of $x$ is it true that $x^2 - 5x - 4 \le 10$? Express your answer in interval notation.
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