Since $y$ and $\sqrt{x}$ are inversely proportional, this means that $y\sqrt{x}=k$ for some constant $k$.  Substituting the given values, when $x=24$ and $y=15$, we find that $15\sqrt{24}=30\sqrt{6}=k$.  Therefore, when $y=3$, we can solve for $x$: \begin{align*}
3\cdot\sqrt{x}&=30\sqrt{6}\\
\Rightarrow\qquad (\sqrt{x})^2&=(10\sqrt{6})^2\\
\Rightarrow\qquad x&=100\cdot6\\
&=\boxed{600}
\end{align*}
Question:
The value of $y$ varies inversely as $\sqrt x$ and when $x=24$, $y=15$. What is $x$ when $y=3$?
Answer:
Let's think step by step.

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600
The value of $y$ varies inversely as $\sqrt x$ and when $x=24$, $y=15$. What is $x$ when $y=3$?
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