We have $g(16) = 4$, so $t(g(16)) = t(4) = 3- g(4) = 3-\sqrt{4} = 3-2 = \boxed{1}$.
Question:
If $t(x) = 3-g(x)$ and $g(x) = \sqrt{x}$, then what is $t(g(16))$?
Answer:
Let's think step by step.

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If $t(x) = 3-g(x)$ and $g(x) = \sqrt{x}$, then what is $t(g(16))$?
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