Since the angles in a triangle adds up to 180, and A is 40 degrees, B and C have a total of 180-60 = <<180-60=120>>120 degrees.

Since B is two times bigger than C, the total of the angles of B and C is equal to 2C+C = 120

3C=120

The angle of C is C=120/3

C is <<40=40>>40

Since B is two times as big as C, B is 2*40 = 80 degrees.

# Answer

80
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
In a triangle with angles A, B, and C, A is 60 degrees, and B is two times as big as C. Calculate the angle of B.
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
80
In a triangle with angles A, B, and C, A is 60 degrees, and B is two times as big as C. Calculate the angle of B.
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