If Antonella spent $3 and now has $11, that means initially she had $3 + $11 = $<<3+11=14>>14

Let the number of loonies Antonella had be L and the number of toonies be T.

Initially she had in her purse a total of 1L + 2T = $14

We also know that she had 10 coins in total or 10=L+T

That means initially she had T=10-L toonies

Combining both equations we know that 14=1L+2*(10-L)

If we multiply through the parentheses, we get 14=1L+20-2L

If we combine the variables on one side and the constants on another, we get -6=-1L or L=6

Knowing the value of L, we can solve for T= 10 - L = 10 - 6 = <<10-6=4>>4

# Answer

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<|im_start|>user
Antonella has ten Canadian coins in her purse that are either loonies or toonies. A loonie equals $1 and a toonie equals $2. If she bought a $3 Frappuccino and still has $11, how many toonies did she initially have?
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
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user
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Antonella has ten Canadian coins in her purse that are either loonies or toonies. A loonie equals $1 and a toonie equals $2. If she bought a $3 Frappuccino and still has $11, how many toonies did she initially have?
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