In the first round, Lorelei did 3/4 * 180 jumps = <<3/4*180=135>>135 jumps.

In the second round, Hattie did 2/3 * 180 jumps = <<2/3*180=120>>120 jumps, while

Lorelei did 120 jumps + 50 jumps = <<120+50=170>>170 jumps.

The total number of jumps for the two in both rounds is 170 jumps + 120 jumps + 135 jumps + 180 jumps = <<170+120+135+180=605>>605 jumps

# Answer

605
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Hattie and her friend Lorelei are doing a jumping contest using a jumping rope. Hattie does 180 jumps in the first round, while Lorelei jumps 3/4 as many times as Hattie jumped. In the second round, Lorelei does 50 more jumps than Hattie. If Hattie managed to jump 2/3 times the number of jumps she did in the first round, calculate the total number of jumps the two did in the two rounds.
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
605
Hattie and her friend Lorelei are doing a jumping contest using a jumping rope. Hattie does 180 jumps in the first round, while Lorelei jumps 3/4 as many times as Hattie jumped. In the second round, Lorelei does 50 more jumps than Hattie. If Hattie managed to jump 2/3 times the number of jumps she did in the first round, calculate the total number of jumps the two did in the two rounds.
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