On Monday, Mr Castiel ate 2/5*600 = <<2/5*600=240>>240 sausages.

The remaining number of sausages after he ate 240 on Monday is 600-240 = <<600-240=360>>360

On Tuesday, he ate half of the remaining sausages, a total of 360/2 = <<360/2=180>>180.

The remaining number of sausages that he saved for Friday after eating 180 on Tuesday is 360-180 = <<360-180=180>>180.

On Friday, Mr Castiel ate 3/4*180 = <<3/4*180=135>>135 of the sausages he had kept.

The remaining number of sausages after he ate 135 on Friday is 180-135 = <<180-135=45>>45

# Answer

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Mr Castiel prepared 600 boar sausages on the weekend. He ate 2/5 of them on Monday, half of the remaining on Tuesday and saved the rest for Friday. If he ate 3/4 of the remaining boar sausages on Friday, how many sausages are left?
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user
45
Mr Castiel prepared 600 boar sausages on the weekend. He ate 2/5 of them on Monday, half of the remaining on Tuesday and saved the rest for Friday. If he ate 3/4 of the remaining boar sausages on Friday, how many sausages are left?
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