Twice the number of hours in a typical earth day is 24*2=<<24*2=48>>48 hours.

Eight hours less than twice the number of hours in a typical earth day is 48-8=<<48-8=40>>40 hours.

If the distance between these two planets is 4,000 parsecs, then the average speed on this voyage was 4000/40=<<4000/40=100>>100 parsecs per hour.

# Answer

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During the most recent voyage of the Starship Conundrum, the spacecraft traveled from Planet X to Planet Y in eight hours less than twice the number of hours in a typical earth day.  If the distance between these two planets is 4,000 parsecs, what was the average speed, in parsecs per hour, of the Starship Conundrum during this most recent voyage?
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user
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During the most recent voyage of the Starship Conundrum, the spacecraft traveled from Planet X to Planet Y in eight hours less than twice the number of hours in a typical earth day.  If the distance between these two planets is 4,000 parsecs, what was the average speed, in parsecs per hour, of the Starship Conundrum during this most recent voyage?
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