Since the father is walking 3 times as fast as his son, their speeds are in a ratio of 3:1 respectively

They started at the same time so they will cover distance at the same ratio of 3:1

Each portion of the distance they covered is 16/(3+1) = <<16/(3+1)=4>>4m

The father covered three portions of the distance which is 3*4m = <<3*4=12>>12m from his end

# Answer

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<|im_start|>system
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<|im_start|>user
A father and a son start approaching each other at the same time from opposite ends of a hallway that is 16m long. If the father is walking three times as fast as the son, at what distance from the father's end of the hallway will they meet?
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user
12
A father and a son start approaching each other at the same time from opposite ends of a hallway that is 16m long. If the father is walking three times as fast as the son, at what distance from the father's end of the hallway will they meet?
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