The relay run is 4 times the length of last year’s race, so 300 meters x 4 = <<300*4=1200>>1200 meters.

With 6 tables along the route, the distance between tables is 1200 meters / 6 tables = <<1200/6=200>>200 meters.

The distance between tables 1 and 3 is 200 meters x 2 = <<200*2=400>>400 meters.

# Answer

400
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Giselle is in charge of the relay run on track and field day. Last year, the race was 300 meters. This year, it will be 4 times as long. Giselle needs to set up 6 tables for the relay run. The distance between the tables must be the same and the last table will be at the finish line. What is the distance between table 1 and table 3 in meters?
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
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user
400
Giselle is in charge of the relay run on track and field day. Last year, the race was 300 meters. This year, it will be 4 times as long. Giselle needs to set up 6 tables for the relay run. The distance between the tables must be the same and the last table will be at the finish line. What is the distance between table 1 and table 3 in meters?
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