Let s be the number of times the small bell rings, and b be the number of times the big bell rings.

We know that s + b = 52 and s = 4 + 1/3b.

Substituting the second equation into the first equation, we get 4 + 1/3b + b = 52

Subtracting 4 from both sides, we get 1/3b + b = 48

Combining like terms, we get 4/3b = 48

Dividing both sides of the equation by 4/3, we get b = 36

# Answer

36
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Martin rings the small bell 4 times more than 1/3 as often as the big bell. If he rings both of them a combined total of 52 times, how many times does he ring the big bell?
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
36
Martin rings the small bell 4 times more than 1/3 as often as the big bell. If he rings both of them a combined total of 52 times, how many times does he ring the big bell?
train