First find the number of cheaper coats Karen will have to purchase over 30 years: 30 years / 5 years/coat = <<30/5=6>>6 coats

Then multiply that number by the cost of one cheaper coat to find the total cost of that option: 6 coats * $120/coat = $<<6*120=720>>720

Then find the number of more expensive coats Karen will have to purchase over 30 years: 30 years / 15 years/coat = <<30/15=2>>2 coats

Then multiply that number by the cost of one expensive coat to find the total cost of that option: 2 coats * $300/coat = $<<2*300=600>>600

Then subtract the total cost of the more expensive coats from the total cost of the less expensive coats to find the difference: $720 - $600 = $<<720-600=120>>120

# Answer

120
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Karen is considering her winter coat options. One coast costs $300 and will last for 15 years. The other coat costs $120 and will last for five years. How much money would Karen save over 30 years by buying the more expensive cost?
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
120
Karen is considering her winter coat options. One coast costs $300 and will last for 15 years. The other coat costs $120 and will last for five years. How much money would Karen save over 30 years by buying the more expensive cost?
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