The next roll will be his 11th roll.

The total on this tenth roll to have an average of 3 is 33, because 3 * 11 = <<33=33>>33

His current total is 31 because 1 + 3 + 2 + 4 + 3 + 5 + 6 + 1 + 4 + 2= <<1+3+2+4+3+5+6+1+4+2=31>>31

He needs to roll a 2 because 33 - 31 = <<33-31=2>>2

# Answer

2
<|im_start|>system
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<|im_start|>user
Ronald is rolling a die and won't stop rolling until the average of all his rolls is a 3. He rolls a 1, a 3, a 2, a 4, a 3, a 5, a 3, a 4, a 4 and a 2. What does he need to roll on the next roll to be able to stop?
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
2
Ronald is rolling a die and won't stop rolling until the average of all his rolls is a 3. He rolls a 1, a 3, a 2, a 4, a 3, a 5, a 3, a 4, a 4 and a 2. What does he need to roll on the next roll to be able to stop?
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