She has 8 points from red buckets because 4 x 2 = <<4*2=8>>8

She has 15 points from green buckets because 5 x 3 = <<5*3=15>>15

She has spent $2 on games because 2 x 1 = <<2*1=2>>2

She has $1 left to spend because 3 - 2 = <<3-2=1>>1

She can play one more game because 1 / 1 = <<1/1=1>>1

The best bucket gives three points because 3 > 2

The most she can earn in the final game is 15 because 5 x 3 = <<5*3=15>>15

The most she can score overall is 38 because 8 + 15 + 15 = <<8+15+15=38>>38

# Answer

38
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Tiffany attends the carnival and her mother gives her $3 to play on a ring toss game. For every red bucket she tosses a ring into she gets 2 points. For every green bucket she gets three points. She gets zero points for a miss. Every play costs her $1 and she gets 5 rings per play. She's played two games and already gotten 4 red buckets and 5 green buckets. If she plays until her money runs out, what is the most total points she can get for all three games?
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
38
Tiffany attends the carnival and her mother gives her $3 to play on a ring toss game. For every red bucket she tosses a ring into she gets 2 points. For every green bucket she gets three points. She gets zero points for a miss. Every play costs her $1 and she gets 5 rings per play. She's played two games and already gotten 4 red buckets and 5 green buckets. If she plays until her money runs out, what is the most total points she can get for all three games?
train