Walter fell 4 meters and an additional three times that depth which is 3*4 = 12 meters

He fell for a total of 4+12 = <<4+12=16>>16 meters

The eighth platform is 16 meters high and the platforms are evenly spaced so each platform is 16/8 = <<16/8=2>>2 meters high

David was located 4 meters below the 16 meter level which is 16-4 = <<16-4=12>>12 meters high

Each platform is 2 meters high so 12 meters would mean the 12/2 = <<12/2=6>>6th platform

# Answer

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<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Walter fell from the eighth platform of some scaffolding and fell past David after falling 4 meters. If he fell for an additional three more times that depth before hitting the ground, and the platforms are evenly spaced out in height, what platform was David on?
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
6
Walter fell from the eighth platform of some scaffolding and fell past David after falling 4 meters. If he fell for an additional three more times that depth before hitting the ground, and the platforms are evenly spaced out in height, what platform was David on?
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