On the first trip, Ishmael sees 28 male whales * 2 = <<28*2=56>>56 female whales.

So in total, he sees 28 male whales + 56 female whales = <<28+56=84>>84 whales on the first trip.

On the second trip, each baby whale travels with its parents which means it travels in a group of 1 baby whale + 2 parents = <<1+2=3>>3 whales/baby whale.

This means there are 8 baby whales * 3 whales/baby whale = <<8*3=24>>24 whales on the second trip.

On the third trip, there are half as many male whales as there were on the first trip, so there must be 28 male whales / 2 = <<28/2=14>>14 male whales.

Adding this to the female whales means he saws 14 males whales + 56 female whales = <<14+56=70>>70 whales on the third trip.

In total, Ishmael saw 84 + 24 + 70 = <<84+24+70=178>>178 whales across the three trips.

# Answer

178
<|im_start|>system
You are a helpful assistant.<|im_end|>
<|im_start|>user
Ishmael was monitoring whales out at sea for conservation purposes. Each time he takes a trip to sea, he sees a different group of whales. On his first trip, he counts 28 male whales and twice as many female whales. On his second trip, he sees 8 baby whales, each travelling with their parents. On his third trip, he counts half as many male whales as the first trip and the same number of female whales as on the first trip. In total, how many whales were out at sea during Ishmael’s monitoring?
Please reason step by step, and put your final answer within \boxed{{}}.<|im_end|>
<|im_start|>assistant

user
178
Ishmael was monitoring whales out at sea for conservation purposes. Each time he takes a trip to sea, he sees a different group of whales. On his first trip, he counts 28 male whales and twice as many female whales. On his second trip, he sees 8 baby whales, each travelling with their parents. On his third trip, he counts half as many male whales as the first trip and the same number of female whales as on the first trip. In total, how many whales were out at sea during Ishmael’s monitoring?
train