TITLE: Factoring polynomial with 4 terms
QUESTION [1 upvotes]: I cant figure this out. $$\frac{x-5}{x^3-3x^2+7x-5}$$
I tried by grouping and got $$x^2(x-3)+1(7x-5)$$ for the denominator. I need to use partial fractions on this so I cant use that yet.

REPLY [0 votes]: Clearly (why? Inspection...) , $\,x=1\,$ is a root, thus
$$x^3-3x^2+7x-5=(x-1)(x^2-2x+5)$$
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