TITLE: Covariance and Variance
QUESTION [2 upvotes]: Given two random variables $X$ and $Y$ , I wish to find $Cov(X + Y, X − Y )$ assuming that
$(a)$ $X$ and $Y$ are independent and 
$(b)$ $X$ and $Y$ are dependent & $Var(X) = Var(Y )$
I started with $$Cov(X + Y, X − Y) = Cov(X, X-Y) + Cov(Y, X-Y) = Var(X)- Cov(X,Y) + Cov(Y,X)- Var(Y)$$ 
such that for $a)$ we have $Var(x) - Var (Y)$ and for $b)$ we have $0$. 
Just checking if my method is correct thanks!

REPLY [1 votes]: Indeed. $~\mathsf {Cov}(X+Y,X-Y)= \mathsf {Var}(X)-\mathsf {Var}(Y)$ whether or not $X,Y$ are independent.  It is a property of the bilinearity of covariance.
Of course, this equals zero when the variances are equal.
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