What 2008 has 14.2% as the 2009?
CREATE TABLE "grade_distribution" (
  "score" text,
  "2007" text,
  "2008" text,
  "2009" text,
  "2010" text,
  "2011" text,
  "2012" text
);
SELECT "2008" FROM "grade_distribution" WHERE "2009"='14.2%';