What is the interview when preliminary average is 8.662 (3) ?
CREATE TABLE "final_competition" (
  "state" text,
  "preliminary_average" text,
  "interview" text,
  "swimsuit" text,
  "evening_gown" text,
  "semifinal_average" text
);
SELECT "interview" FROM "final_competition" WHERE "preliminary_average"='8.662 (3)';