What 2011 has 12.7% as the 2010?
CREATE TABLE "grade_distribution" (
  "score" text,
  "2007" text,
  "2008" text,
  "2009" text,
  "2010" text,
  "2011" text,
  "2012" text
);
SELECT "2011" FROM "grade_distribution" WHERE "2010"='12.7%';