I needed some expensive items in the game and forgot it changes your name. I need to know if , in the 3ds download version, I can get rid of the title "Thief"?
There is a shop in the starting area on the island of Koholint, and if you are fast enough to dance around the shopkeeper, you can steal from him. Once you steal from him, though, your title in the game changes to "THIEF".    Is there any way to change your title back to your name without reverting to a different past save or starting over?
I am trying to find the equation of characteristic curves and solution of the partial differential equation $$x\frac{\partial u}{\partial y}-y\frac{\partial u}{\partial x}=u$$ $u(x,0)=\sin(\frac{\pi}{4}x)$ .   What I did: $$\frac{dx}{-y}=\frac{dy}{x}=\frac{du}{u}$$ with  From first two equalities $$\frac{dx}{-y}=\frac{dy}{x}$$ by solving we get $x^2+y^2=c_1$ for some constant $c_1$. Now I am stuck with the third and rest of the equalities to come up with a suitable manipulation to solve the problem. How can I do this? Any help would be great. Thanks. What does the '!!!' syntax mean in javascript? How can I add a "C" wire to my thermostat? How do I get a Realtek RTL8723BE wireless card to work? Show that, if $a$ and $h$ are positive numbers, $h &lt; a^2$, then $$\sqrt{a^2 + h}-a &lt; \frac{h}{2a} &lt; a - \sqrt{a^2 - h}$$  I've been working on this problem for about 2 hours now, but I've made no progress. I'm not looking for an answer, but I just need some help to get me started since we didn't practice inequalities this complex in highschool. Thanks.   All I can tell is that we're supposed to take the square root of an expression at some point since one inequality ( h &lt; a^2 ) becomes two.   Edit : Thank you guys for the replies, but I'd appreciate only hints in the future (like Robert Israel) so that I can learn. Regardless, I found a different way to do it, so it's cool :) Is cancer caused by vitamin B17 deficiency? There's this exercise: let $\,f\,$ be analytic on $$D:=\{z\;\;;\;\;|z|&lt;1\}\,\,,\,|f(z)|\leq 1\,\,,\,\,\forall\,z\in D$$  and $\,z=0\,$  a zero of order $\,m\,$ of $\,f\,$.  Prove that $$\forall z\in D\,\,,\,\,|f(z)|\leq |z|^m$$  My solution: Induction on $\,m\,$: for $\,m=1\,$ this is exactly the lemma of Schwarz, thus we can assume truth for $\,k&lt;m\,$ and prove for $\,k=m&gt;1\,$ . Since $\,f(z)=z^mh(z)\,\,,\,h(0)\neq 0\,$ analytic in $\,D\,$ ,  put  $$g(z):=\frac{f(z)}{z}=z^{m-1}h(z)$$   Applying the inductive hypothesis and using Schwarz lemma $\,\,(***)\,\,$ we get that  $$|g(z)|=\left|\frac{f(z)}{z}\right|=|z|^{m-1}|h(z)|\stackrel{ind. hyp.}\leq |z|^{m-1}\Longrightarrow |f(z)|\leq |z^m|$$ and we're done...almost: we still have to prove $\,|g(z)|\leq 1\,$ for all $\,z\in D$ in order to be able to use the inductive hypothesis and this is precisely the part where I have some doubts: this can be proved as follows (all the time we work with $\,z\in D\,$):  $(1)\,\,$ For $\,f(z)=z^mh(z)\,$ we apply directly Schwarz lemma and get $$|f(z)|=|z|^m|h(z)|\leq |z|\Longrightarrow |z|^{m-1}h(z)|\leq 1$$ And since now the function $\,f_1(z)=z^{m-1}h(z)\,$ fulfills the conditions of S.L. we get  $(2)\,\,$ Applying again the lemma,  $$|f_1(z)|=|z|^{m-1}|h(z)|\leq |z|\Longrightarrow |z^{m-2}h(z)|\leq 1$$and now the function $\,f_2(z):=z^{m-2}h(z)\,$ fulfills the conditions of them  lemma so...etc.  In the step$\,m-1\,$ we get  $$|z||h(z)|\leq |z|\Longrightarrow {\color{red}{\mathbf{|h(z)|\leq 1}}}\,$$  and this is what allows us to use the inductive hypothesis in $\,\,(***)\,\,$ above.  My question: Is there any way I can't see right now to deduce directly, or in a shorter way, that $\,|h(z)\leq 1\,$ ? Do stone quarries respawn in Hearthfire? Why would you put Identity Increment other than 1 in SQL? How do we prove that  $\operatorname{rank}(A) = \operatorname{rank}(AA^T) = \operatorname{rank}(A^TA)$ ?  Is it always true? I've been reading a lot about dual-booting, and it seems as easy as loading Windows and then loading Linux with GRUB, but everybody says that Windows loves to trash GRUB when it gets the opportunity. What are some steps I can take to prevent this from happening (other than using Windows' bootloader, I want to keep this as simple as possible)? Iterated self-composition of arbitrary function Does there exist some notation that represents the iterative composition of a single-input, single-output function with itself? As in, say, $f_5(x)=f(f(f(f(f(x)))))$.  In other words, going by the above (incorrect, I'm pretty sure) notation:  $f(x)=x+1$, $f_n(m)=m+n$  I'm looking for the correct way to express the notion of "$f_n(x)$" for any $f$. R.Java not generated How to redirect and append both stdout and stderr to a file with Bash? Custom toolbar location XP A few years ago Umber Ferrule wrote that the toolbars in the taskbar are defined in   HKEY_CURRENT_USER\Software\Microsoft\Windows\CurrentVersion\Explorer\Streams.   This looks very plausible but cannot be the entire story.  Deleting this key will in no way affect the taskbar and on rebooting the system the key magically reappears.  Why do I want to know?  Simple.  I would like to export the key to a reg. file as a convenient backup. Sum over all non-evil numbers How to deserialize a JSON String to Apex How can I deserialize this json object:      {     "response": {         "count": 1,         "benchmark": 0.22567009925842,         "requests": [             {                 "request": {                     "id": 537481,                     "image_thumbnail": "",                     "title": "Request for new bin(s) - residential",                     "description": "Propmain ref  3234-1114",                     "status": "submitted",                     "address": "36 Pine Tree Close",                     "location": "Peterborough, England",                     "zipcode": "PE1 1EJ",                     "user": "",                     "date_created": 1417173208,                     "count_comments": 0,                     "count_followers": 0,                     "count_supporters": 0,                     "lat": 52.599967,                     "lon": -0.233482,                     "user_follows": 0,                     "user_comments": 0,                     "user_request": 1,                     "rank": "0"                 }             }         ],         "status": {             "type": "success",             "message": "Success",             "code": 200,             "code_message": "Ok"         }     } }   What i've tried:   Map&lt;String,Object&gt; rawObj = (Map&lt;String,Object&gt;) JSON.deserializeUntyped(jsonString);     Map&lt;String,Object&gt; responseObj = (Map&lt;String,Object&gt;)rawObj.get('response');     List&lt;Object&gt; reqs = (List&lt;Object&gt;) responseObj.get('requests');     System.debug('Map Size = ' + reqs.size());     Map&lt;String, Object&gt; i = new Map&lt;String, Object&gt; ();     for (Object x : reqs) {          i = (Map&lt;String, Object&gt;)x; }     Map&lt;String,Object&gt; requests = (Map&lt;String,Object&gt;)i.get('request');     System.debug('Map Size = ' + i.size());     for (String field : i.keySet()){          Object id = i.get(field);         Object title = i.get('title');         System.debug('Id : ' + id);         System.debug('title : ' + title);          //System.debug('Title : ' + title);       } How could we improve our planned post notice improvements? Megan has written a .  I've seen a bunch of discussion about it on chat - but it feels like having it purely on the blog is a little clunky.  So specifically - what does the MSE community feel about the proposed post notices for closed questions? What's missing, or what should be added? What are some of the lessons we've learnt that could be helpful here? Which is the preferred way to convert an Enum to a String in .NET 3.5?   Enum.GetName Enum.Format ToString   Why should I prefer one of these over the others? Does one perform better? Values of the limit $\lim\limits_{x\to+\infty}\left(\sqrt{(x+a)(x+b)}-x\right)$ Hi I have a question regarding finding the values of limit for the following question.  Let $a, b \in \mathbb R$. Find the limit $$\lim_{x\to+\infty}\left(\sqrt{(x+a)(x+b)}-x\right)$$