I recently got a laptop (XPS 15) with 3200 * 1800 screen.  After updating drivers, Chrome looks like:   The tabs won't fill the red part of the screen.  I tried the follows in about:flags with no luck:   Enabled HiDPI setting - resulted in a very bad layout. Enabled Stacked Tabs - resulted in the above picture, tabs stacked but not fitting whole width. Played with touch screen options, no luck, context menu made larger, so does the tabs but still not fitting whole width. (Touch Optimized UI and Enable touch event) Reseting to factory default - no luck. Changed the Let me choose one scaling level for all my displays which was suggested in the duplicated question with no luck.   Any idea how to make tabs fit whole bar ?  EDIT: Using Windows 8.1
If I open up many tabs in Chrome, the Tabs start to shrink. This is usually a normal behavior if the tabs would use the whole availible space, BUT in my case the tabs shrink too much. They don't use up the whole availible space anymore, but only go until somwhere at three quarters of the window. The more tabs I open, the larger the availible space gets until it reaches a maximum. This strikes me as somewhat not so normal.  Another funny thing is, if I use a second Monitor to extend my Desktop, Tabs will be smaller on the second Desktop and will only fill half the availible space from the beginning. For example right now I have 6 tabs open, which fill out approximately half the availible space. If I open more tabs, only the tab size reduces. This has not been like that when I first installed the browser.  This is what it looks like:    Is there any solution for this?   I hereby explicitly mean NO extensions. I found enough extensions to handle tabs. I just want them to behave normally without any of those tab-extensions. Re-Installing Chrome does NOT work, I tried that.
Determinant of an $n\times n$ complex matrix as an $2n\times 2n$ real determinant If $A$ is an $n\times n$ complex matrix. Is it possible to write $\vert \det A\vert^2$ as a $2n\times 2n$ matrix with blocks containing the real and imaginary parts of $A$?  I remember seeing such a formula, but can not remember where. Any details, (and possibly references) for such a result would be greatly appreciated. Making an elastic waistband on clothing? I'd like to play Dragon Age Inquision in english instead of the language of my operating system, but it seems to default to that and I can't find a way to change it. I already tried setting the Origin client language to english, but that didn't change anything.  Where can I change the language for Dragon Age: Inquisition? How to recognise/thank great cabin crew? Those of us who fly a lot will know that there is a bit of a variety in cabin crew. Some (sadly more common on certain airlines) do the very bare minimum to ensure a safe flight, but nothing more. Many (especially on airlines noted for good customer service) provide a good service.  Every so often though, you come across a flight crew who go the extra mile. These are the ones always friendly, always helpful, always thinking ahead and solving the problem before it has happened. One moment they're serving you your drink, the next reassuring a little old lady about the flight, the next magicing a colouring book to turn an impending toddler crisis into a happy small child, then answering queries on arrivals and immigration for a first time travaller, then back to offer you a top up of what you're drinking (which they've remembered exactly). Not very often found, but very much appreciated when you happen across them on your travels!  In the case when you do luck out and find yourself on a flight with a great cabin crew (who go well beyond what you normally experience as "good" on that airline/kind of airline), is there a standard/common way to recognise them at the end of the flight? Not just to thank them then and there, but also to let the airline know that this person/group are what the rest of their staff should be aspiring to. Is there any standard way, or does it vary entirely by carrier? Let $(x_n)_{n\in \mathbb{N}}$ be a sequence of real numbers. A well known result is:     The sequence $(x_n)_{n\in \mathbb{N}}$ converges to $a\in \mathbb{R}$ if and only if every subsequence $(x_{n_k})_{k\in \mathbb{N}}$ converges to $a\in \mathbb{R}$.   Now, I'm working on an exercise which essentialy asks to prove the following:     The sequence $(x_n)_{n\in \mathbb{N}}$ converges to $a\in \mathbb{R}$ if and only if for every subsequence $(x_{n_k})_{k\in \mathbb{N}}$ there is a (sub)subsequence $(x_{n_{k_j}})_{j\in \mathbb{N}}$ which converges to $a$.   Now, one direction is trivial. If in fact $(x_n)_{n\in \mathbb{N}}$ converges to $a$, then by the result I've mentioned, every subsequence of $(x_{n})_{n\in \mathbb{N}}$ converges to $a$. Let then $(x_{n_k})_{k\in \mathbb{N}}$ be an arbitrary subsequence. In that case, we know that it is a subsequence of itself, and hence we've found a (sub)subsequence which converges to $a$.  The other way around seems quite complicated for me. The reason is as follows: I must assume that every subsequence $(x_{n_k})_{k\in \mathbb{N}}$ has a (sub)subsequence which converges to $a$ and the proof that the original one converges to $a$.  My problem is exactly that "a". If it had all (sub)subsequences converging to $a$, then by the result i've mentionted, the subsequence $(x_{n_k})_{k\in \mathbb{N}}$ would converge to $a$. In that case, we would have every subsequence converging to $a$ and the result would follow.  My idea to prove the claim was then:  First remember that a subsequence is the restriction of the original one $x: \mathbb{N}\to \mathbb{R}$ to an infinite subset $\mathbb{N}'\subset \mathbb{N}$. In that case a (sub)subsequence is the restriction of $\tilde{x} = x|\mathbb{N}'$ to an infinite subset $\mathbb{N}''\subset \mathbb{N}$. But since $\tilde{x}$ is the restriction of $x$ to $\mathbb{N}'$ and since $\mathbb{N}''\subset \mathbb{N}'$, the restriction of $\tilde{x}$ to $\mathbb{N}''$ is itself the restriction of $x$ to $\mathbb{N}''$.  In other words, every (sub)subsequence can be viewed as a subsequence of the original one. Considering this, by hypothesis every subsequence has a (sub)subsequence which converges to $a$. But by this argument, this means that we can replace every subsequence with a convergent one. And then we can use the result I stated.  Is my idea correct? Is this really the way to prove the claim? My only doubt is that I need every subsequence converging to $a$ to use the result. In this case I can't see how I can argue that this implies every subsequence converges to $a$.  How can I finish this proof? When documenting location, should current or historical place names be used? When I am documenting records, do I use the name of a city or country as it is called today or as it was in the year an ancestor was there?  Related to: derivative of cost function for Logistic Regression I am going over the lectures on Machine Learning at Coursera.   I am struggling with the following. How can the partial derivative of   $$J(\theta)=-\frac{1}{m}\sum_{i=1}^{m}y^{i}\log(h_\theta(x^{i}))+(1-y^{i})\log(1-h_\theta(x^{i}))$$  where $h_{\theta}(x)$ is defined as follows  $$h_{\theta}(x)=g(\theta^{T}x)$$ $$g(z)=\frac{1}{1+e^{-z}}$$  be $$ \frac{\partial}{\partial\theta_{j}}J(\theta) =\sum_{i=1}^{m}(h_\theta(x^{i})-y^i)x_j^i$$  In other words, how would we go about calculating the partial derivative with respect to $\theta$ of the cost function (the logs are natural logarithms):  $$J(\theta)=-\frac{1}{m}\sum_{i=1}^{m}y^{i}\log(h_\theta(x^{i}))+(1-y^{i})\log(1-h_\theta(x^{i}))$$ I'm glad the outside overlay scrollbars are finally gone.  But the scrollbar is still a razor thin line that becomes a less razor thin scrollbar, but still thin scrollbar, when the mouse hovers.  How can I get a normal scrollbar? I.e., like in other OSes, like in Firefox, a scrollbar that doesn't change depending on what the mouse points to, and with a nice width.  I already tried  gsettings set com.canonical.desktop.interface scrollbar-mode normal   but no luck. This is almost surely an Arzela-Ascoli question, since it comes from an old exam of which such problems are quite common. Unfortunately, I can't seem to get it though.  $\{ f_n \}$ is a sequence of functions $[0,1] \to \mathbb{R}$ satisfying $|f_n'(x)| \leq \frac{1 + |\ln (x)|}{\sqrt{x}}$ and $-10 \leq \int_0^1 f_n(x) dx \leq 10$ for every $n$. The question is to show the existence of a uniformly convergent subsequence.  In these kinds of situations, the bounds given usually turn into something nice  to force uniform boundedness. Maybe I could hope to establish equicontinuity using the integral somehow, but I'm not told that the $f_n$ are always positive, so the absolute values would probably screw things up anyway.  Is it an easy problem I'm missing or is this totally the wrong track? If so, what's the right track? Show that the locus formed by z in the equation $z^3 + iz = 1$  never crosses the co-ordinate axes in the Argand plane. Further show that $$|z| = \sqrt{\dfrac{-\Im(z)}{2\Re(z)\Im(z) +1}}$$  Concept: $z=x+iy$ $z^3=(x+iy)^3=x^3-3xy^2+i(3x^2y-y^3)$ $iz=-y+ix$ Combined equation is $x^3-3xy^2-y-1+i(3x^2y-y^3+x)=0$ How do we proceed from here onward? Algebraic dual of $\mathbb{R}^{\mathbb{N}}$ As in the title, my question is: What is the algebraic dual space of $\mathbb{R}^{\mathbb{N}}$ - the space of all $\mathbb{R}$-valued sequences. I think that it should be the direct sum $\bigoplus_{\mathbb{N}} \mathbb{R}$, via the natural duality, but I cannot proof it. Prove that for all non-negative integers $m,n$, $\frac{(2m)!(2n)!}{m!n!(m + n)!}$ is an integer. Prove that for all non-negative integers $m,n$, $\frac{(2m)!(2n)!}{m!n!(m + n)!}$ is an integer.   I'm not familiar to factorial and I don't have much idea, can someone show me how to prove this? Thank you. How to check type of variable in Java? Consider this picture of sun beams streaming onto the valley through the clouds.    Given that the valley is only (at a guess) 3km wide, with simple trigonometry and the angles of the beams, this gives the result that the position of the light source is being a few tens of km away at most.   What is wrong with the analysis? can't login as mysql user root from normal user account in ubuntu 16.04 I just installed Ubuntu 16.04 LTS along with the packages php, mariadb and nginx. I ran mysql_secure_installation and changed the root password.  Now when I try to login to mysql using the root account while logged in Ubuntu as normal user account I get access denied.   When I login using sudo mysql, mysql doesn't even ask me password. If I run mysql_secure_installtion I see that old settings never got set permanently.   What am I doing wrong? Did not get notification about new privilege Many times it takes me a while to properly compose my question before posting. Sometimes it's just a jumble of ideas and concepts, and is not something I'd want seen immediately. However, there is no way to save a partial question unless you post it.  This should work exactly like it does in Gmail. There, once you start composing your question, it's autosaved as a draft. If your browser crashes or you need to come back later to complete it, it will be there for you to finish and post later.  Optionally, allow multiple draft questions and a page to edit/delete them. If needed, make them expire after some amount of time. I'm doing some web scraping and sites frequently use HTML entities to represent non ascii characters. Does Python have a utility that takes a string with HTML entities and returns a unicode type?  For example:  I get back:  &amp;#x01ce;   which represents an "ǎ" with a tone mark.  In binary, this is represented as the 16 bit 01ce.  I want to convert the html entity into the value  u'\u01ce' It seems like maybe cancelled downvote might be less...weird? I am considering buying a Dell XPS 15 laptop. The laptop has a Nvidia 420m card which should work with Linux but I keep reading that the Nvidia Optimus technology isn't supported on Linux. I am not really interested in switching from Nvidia to Intel to save power but need to know that the Nvidia card will in fact work if I installed Ubuntu.  If anyone has experience using a Nvidia card with Optimus technology or even better the exact laptop in question (Dell XPS 15 with 1GB NVIDIA® GeForce®  GT 420M) it would be great.  A major problem holding people back from adopting Linux is this sort of hardware issue. I am a long term Ubuntu user and supporter who can't afford to make a mistake with a purchase like this. I don't want to spend £500+ to find I have no graphics acceleration because Windows 7 is not an option.