I have Ubuntu 17.04 on my Asus laptop.  After login I cannot write anything to /dev/sda6  It tells me that the disk is in read-only mode:    How can I fix it?
Whenever I boot Ubuntu, I get a message that it cannot mount my windows partition, and I can choose to either wait, skip or manually mount.  When I try to enter my Windows partition through Nautilus I get a message saying that this partition is hibernated and that I need to enter the file system and properly close it, something I have done with no problem so I don't know why this happens.    Here's my partition table, if any more data is needed please let me know.     Device Boot      Start         End      Blocks   Id  System /dev/sda1            2048    20000767     9999360   83  Linux /dev/sda2        20002814   478001151   228999169    5  Extended /dev/sda3   *   478001152   622532607    72265728    7  HPFS/NTFS/exFAT /dev/sda4       622532608   625141759     1304576   82  Linux swap / Solaris /dev/sda5        20002816   478001151   228999168   83  Linux
Are comments on answers to my question supposed to show up in my recent activity I want to schedule my script for last Saturday of every month. I have come up with the below:  45 23 22-28 * *  test $(date +\%u) -eq 6 &amp;&amp; echo "4th Saturday"  &amp;&amp; sh  /folder/script.sh    Is this correct or I need to change it? I can't test it right now as it will be invoked only on last saturday. Please advise.  I have the below for last sunday of every month but i can't understand much of it. The first part gives 24 which is sunday and after -eq gives 7 which i don't know what it means:  00 17  * * 0 [ $(cal -s | tail -2 | awk '{print $1}') -eq $(date | awk '{print $3}') ] &amp;&amp; /folder/script.sh   Can i modify the above to get last saturday?  With Romeo's help I was help to come up with the below answer:  00 17 * * 6 [ $(cal -s | tail -2 | awk '{print $7}') -eq $(date | awk '{print $3}') ] &amp;&amp; /folder/script.sh Describe the equivalence classes in terms of familiar mathematical objects Computing second partial derivative with polar coordinates Consider the polar coordinates with $x=r\cos\theta$ and $y=r\sin\theta$.  I can show using the chain rule that $$\frac{\partial}{\partial x} = \frac{x}{r} \frac{\partial}{\partial r} -\frac{y}{r^2} \frac{\partial}{\partial \theta}$$   What is the method to compute $\dfrac{\partial^2}{\partial x^2}$? I don't know how to do it. Asks a question; never responds to answers/comments What do we call someone who asks a question and never responds to answers/comments?    Think of it more as "a pattern of behavior" (somebody who has asked many questions and never responded). I had unresponsive in mind, but that doesn't say that they asked in the first place. Script to raise a single window to the front Some conditions require that a person lie in bed all the time until recovered. Is there a name for such conditions or people experiencing them at the moment?   For example,      I am currently &lt;bed sick&gt; and can't help you with your homework.   I tried looking for bed sick but hit a dead end. How do I use the GUI to search for files in GNOME? On the command line I regularly use locate, or more often a locate x | grep y pattern to find a file I know exists but can't find!  I'd like something that did this quickly in the GUI. Can't find it if it's there.  Here's my confusion   In the applications/overview I can see Search and Indexing. This seems to be a configuration tool. But if this is a server, I can't find a client. In applications I find Nepomuk File Indexing -- I think this is a KDE thing? Ditto, no client? I've installed tracker. This is a strange mix of powerful and unreliable/limited. e.g. it doesn't find files like locate does (returns no results where locate returns 96 results), but is will unpack every tag I've added to my photos! And you can't limit by folder for a quick search within a folder. The old Gnome 2 Search for files... thing is not in the Accessories menu anymore.   I feel that this is basic/core-level functionality and I can't help feeling I'm missing something obvious. Is the set of all finite sequences of letters of Latin alphabet countable/uncountable? How to prove either? I am trying to grab the capital letters of a couple of words and wrap them in span tags. I am using  for extract and wrapping purposes, but it's not outputting anything.  preg_replace("/[A-Z]/", "&lt;span class=\"initial\"&gt;$1&lt;/span&gt;", $str) ..and I don't mean finding out why it doesn't compile, I mean serious debugging: breakpoints, figuring out value of variables at a given moment during run/compile, stepping, examining a stack (is there one?), etc. All the things that we take for granted when debugging a "real" programming language. Since TeX is "turing-complete", I would like to be able to really see what is going on internally.   I'm guessing that a GUI interface for the debugger would be too much to ask, but if it exists, I'd love to hear about it. Open terminal window and execute Python script on startup I have a Python script which I would like to execute at every startup. I can run it by adding this to the startup applications:  python3 /path/to/script.py   That works, but it doesn't open a terminal window, so I can't see the program's output. How could I make it open a terminal window and execute the script in there?  Note: I get the window to stay open with input(' ') at the end of the Python script. Thanks! Change bend angle and swap node position on arrow Changing the style of the first *typeset* line of a paragraph Suppress Fancy header and footer on first page only. What is a substitute for red or white wine in a recipe? Case insensitive 'Contains(string)' Horizontal overflow on my profile page The question says to solve this equation: $(z+1)^5 = z^5$  I did. Just want to find out if I did it properly and if my run-around logic makes sense.  First I begin my writing the equations as:  $$ (z+1)^5 = z^5$$ $$ \mathbf{e}^{5 \mathbf{Log}(z+1)} = \mathbf{e}^{5 \mathbf{Log}(z)} $$ So $$  \mathbf{Log}(z+1) = \ln|z+1| + \mathbf{Arg}(z+1)i $$   $$  \mathbf{Log}(z) = \ln|z| + \mathbf{Arg}(z)i $$   Now, because the natural logarithm is one-to-one, I write:  $$ \ln |z| = \ln |z+1| \Rightarrow |z| = |z+1|$$   So assign $ z = a +bi$   So that $|z| = \sqrt{a^2 +b^2} = |z+1| = \sqrt{(a+1)^2 +b^2} \Rightarrow a^2 +b^2 = (a+1)^2 +b^2 \Rightarrow a^2 = (a+1)^2 \Rightarrow a = -\frac12 $  So, $z = -\frac12 + bi$ and $z+1 = \frac12 + bi$ for some $b \in \mathbb R$  Now to find $b$  $$ \mathbf{Arg}(z+1) = \mathbf{Arg}(z)$$ $$ \tan^{-1} \frac{b}{\frac12} = \pi - \tan^{-1}\frac{b}{-\frac12}$$  I have a feeling this last part isn't quite right, so I just want to find out if I'm approaching this question properly?  Ultimately, I get $ z = -\frac12$ which upon inspection...is wrong... What happens to the Matrix if Neo takes the blue pill? If Neo defies his fate and refuses to be removed from the Matrix (by taking the blue pill) what happens next?   Would another "The One" get selected by The Architect or The Oracle and is there anything to suggest that the current instance of The Matrix actually could have multiple "The One"'s (perhaps one of the 'potentials') in the event that the Chosen One manages to get himself killed or simply refuses to play ball?