I want to center h1 next to my img but I can't because of img's padding  it's what I want any soltuion?      &lt;header&gt;       &lt;div class="logo"&gt;         &lt;img src="imgs/logo.svg" alt="Gori News | LOGO"&gt;&lt;h1&gt;Gori News&lt;/h1&gt;         &lt;/div&gt;       &lt;/header&gt;   header{   width:100%;   max-width: 1800px;   height:99px;   background:#FFF;   margin:0 auto;   background: #FFFFFF;   box-shadow: 0px 4px 5px rgba(0, 0, 0, 0.13);   border-radius: 14px; } header h1{   font-family: Ropa Sans;   font-style: normal;   font-weight: normal;   font-size: 70px;   line-height: 75px;   /* identical to box height */   color: #212121;   text-shadow: 2px 4px 4px rgba(0, 0, 0, 0.25);   display: inline-block; } header img{   margin:12px; }
I have a div with two images and an h1. All of them need to be vertically aligned within the div, next to each other. One of the images needs to be absolute positioned within the div. What is the CSS needed for this to work on all common browsers? &lt;div id=&quot;header&quot;&gt;   &lt;img src=&quot;..&quot; &gt;&lt;/img&gt;   &lt;h1&gt;testing...&lt;/h1&gt;   &lt;img src=&quot;...&quot;&gt;&lt;/img&gt; &lt;/div&gt;
Proofs with limit superior and limit inferior: $\liminf a_n \leq \limsup a_n$ I am stuck on proofs with subsequences. I do not really have a strategy or starting point with subsequences.   NOTE: subsequential limits are limits of subsequences  Prove: $a_n$ is bounded $\implies \liminf a_n \leq \limsup a_n$   Proof:  Let $a_n$ be a bounded sequence. That is, $\forall_n(a_n \leq A)$.  If $a_n$ converges then $\liminf a_n = \lim a_n = \limsup a_n$ and we are done.  Otherwise $a_n$ has a set of subsequential limits we need to show $\liminf a_n \leq \limsup a_n$:  This is where I am stuck... Is there a way to open a raster that is stored in ESRI V10.0 Geodatabase in QGIS V2.4?    I can open the vector layer, but there does not seems to be a way to open a raster. Does the series $\sum\limits_{n=1}^\infty \frac{1}{n^3 \sin^2n}$ converge or diverge? I have this series given by $$\sum\limits_{n=1}^\infty \frac{1}{n^3 \sin^2n}.$$ I know that the terms are all nonnegative. Can I get a subsequence of $\frac{1}{n^3 \sin^2n}$ such that its sum diverges to $+\infty$? Why use iterators instead of array indices? Take the following two lines of code:  for (int i = 0; i &lt; some_vector.size(); i++) {     //do stuff }   And this:  for (some_iterator = some_vector.begin(); some_iterator != some_vector.end();     some_iterator++) {     //do stuff }   I'm told that the second way is preferred. Why exactly is this? Can a hotel kick you out if you let an unregistered guest share a room with you? We are going to an event and because of this event all hotels are fully booked. Now a friend wants to join us, but can't find accommodation. We are okay with him crashing in our hotel room, either on the couch or on a self-inflatable mattress. We have done this in the past where we secretly sneaked the "guest" in.   It is not that we don't want to pay the tourist tax, it is that when ask and the hotel says no, we can't sneak him in, because we drew attention to ourself. In many hotels you can just order another bed, but there are also a lot that don't have that service.   I don't have any ethical problems with my behavior of secretly hosting a guest. I did pay for the room. I don't like being sneaky about it, since again I do pay for the hotel room. Also if I have to choose between sneaking someone in the room to crash on the couch or let him/her sleep on bench in the park. I opt for the first.   Am I just worrying to much and will being honest about it in the end be acceptable to most if not all hotels? Pascal's triangle in tikz I would like to typeset the top part of Pascal's triangle. To get the triangle with the names of the binomial coefficients, i.e., {n \choose k}, I used the following code  \begin{tikzpicture} \foreach \n in {0,...,4} {   \foreach \k in {0,...,\n} {     \node at (\k-\n/2,-\n) {${\n \choose \k}$};   } } \end{tikzpicture}   The result is this   Now I want to be equally lazy and do something like this for the values of the binomial coefficients, i.e., replace {\n \choose \k} in the node label with \CalculateBinomialCoefficient{\n}{\k} where \CalculateBinomialCoefficient is a hypothetical macro that calculates the binomial coefficient. Has anyone done something like that?  The result should look like this: I would like to know how to upgrade from my current version of Ubuntu to the next stable from the Command line interface? Find an explicit isomorphism of the map $h: \Bbb F_5[x]/(x^2+x+2) \to \Bbb F_5[x]/(x^2+4x+2)$  I take the question to mean showing the 2 rings are isomorphic by finding an explicit mapping of each element.   I think $x^2+x+2$ and $x^2+4x+2$ are irreducible over $\Bbb F_5$, so these are both fields.  Also $x^2=4x+3$ in the first case and $x^2=x+3$ in the second.  But beyond these basic facts I'm not sure how I should proceed. Prove that $\Vert f(b)-f(a)-f'(a)(b-a) \Vert\leq \sup_{x\in [a,b]} \Vert f''(x)\Vert\Vert b-a\Vert^2$ Let $\Omega$ be an open set in $\Bbb{R}^n$ and $f:\Omega\to \Bbb{R}^m $ be of class $\Bbb{C}^2.$ Let $a,b$ be in $\Omega$ such that $[a,b]\subset \Omega.$ Prove that  \begin{align}\Vert f(b)-f(a)-f'(a)(b-a) \Vert\leq \sup_{x\in [a,b]} \Vert f''(x)\Vert\Vert b-a\Vert^2.\end{align} where $$f'(a)(b-a)=\big&lt;\nabla f(x),(b-a)\big&gt;=\sum^{n}_{k=1}\frac{\partial f_i}{\partial x_k}(a)(b_k-a_k).$$  I  think the idea of Mean Value Theorem for $C'$ functions in $\Bbb{R}^n$ () will help me in showing it but I don't know how to! Please, can anyone show me a proof or reference? I want to open a file for reading, the C++ way. I need to be able to do it for:   text files, which would involve some sort of read line function. binary files, which would provide a way to read raw data into a char* buffer. How do I identify SMD components? (or how do I identify any component) When do I clear US customs and immigration if connecting at a US airport to my final destination elsewhere in the US? Could someone recommend a free and/or open source GIS application that can orthorectify map images? Can you launch Remote Desktop via URL? Will reformatting my hard drive fix bad sectors on it? How to create a new figure in MATLAB? Language hints for quoted code In  I tried to add  for syntax formatting to code blocks quoted from the question. However, it seems they won't be honoured if I write them as a comment in my own part of the post, and if I include the hint in the qutotation as well then I have some ugly empty space before the code block. There should be a way to write these things properly. Relativity Of Simultaneity Confusion I've been racking my brain trying to think of a grammatically correct sentence that uses same without the earlier in the same (see!) phrase.  It is the same It is the very same I have 10 things all the same I have 10 of the same things The same boy as last time did it again The boy did the same thing as last time  I am discounting same-day dry cleaning and any similar phrases that might crop up because using a hyphen is acceptable which suggests it's an atomic phrase and it sounds awkward if inverted:  They have a same-day dry cleaning service. Their dry cleaning service is same-day. - Sounds odd but might be acceptable in some situations Their dry cleaning service is done on the same day. - Sounds better  So I don't think it's possible when same is used by itself. Can someone either explain why same must always have the before it or provide a grammatically correct counter-example? Email Templates: Conditional Greeting Based on Time of Day