Here is the screenshot of the problem
I think everyone has known - we need to install katoolin to use Kali Linux Tools on Ubuntu. Before did anything I had looked through the internet and also found out these solutions: ,   So here are my steps:  apt-get install git git clone https://github.com/LionSec/katoolin.git &amp;&amp; cp katoolin/katoolin.py /usr/bin/katoolin chmod +x  /usr/bin/katoolin sudo katoolin   Then, to add Kali Linux repositories and update them, I selected option 1 from the katoolin Menu  Then, to view the available categories and install all available tools, I selected option 2 from the main menu of katoolin and then pressed 0.   But after that I got this:    What do you want to do ?>    1) Add Kali repositories & Update  2) View Categories 3) Install classicmenu indicator 4) Install Kali menu 5) Help   kat > 2  ************************** All Categories **************************  1) Information Gathering                      8) Exploitation Tools 2) Vulnerability Analysis                     9) Forensics Tools 3) Wireless Attacks                           10) Stress Testing 4) Web Applications                           11) Password Attacks 5) Sniffing & Spoofing                        12) Reverse Engineering 6) Maintaining Access                         13) Hardware Hacking 7) Reporting Tools                            14) Extra  0) All   Select a category or press (0) to install all Kali linux tools .  Furthermore, I got an error in Software Updater - it didn't let me do anything. Ubuntu just hung up. I solved this problem by deleting kali linux repositories in katoolin and then in Software Updater.  Does anyone know how to install Kali Linux tools in Ubuntu 16.04 in a proper way?
Remove "Set as desktop background" from Windows context menu extending convergence radius using one boundary point Show that if $f(z)=\sum\limits_{n\geq0}a_nz^n$ is analytic in $\{z\in\mathbb{C}:|z|&lt;1\}\cup\{1\}$ and $\forall n\geq0:a_n\geq0$ then the radius of convergence of the power series is strictly larger than $1$.  My approach:   Let $D=\{z\in\mathbb{C}:|z|\leq1\}$.  We have that $f(1)$ converges, so $\sum\limits_{n\geq 0} a_n&lt;\infty$. Moreover since the $a_n$'s are all positive we have that $|a_n|=a_n$, therefore $\sum\limits_{n\geq 0} |a_n|=\sum\limits_{n\geq 0} a_n&lt;\infty$.  Let $f_n(z)=a_nz^n$, then $\forall z\in D, n\geq 0$ we have:  $$|f_n(z)|=|a_nz^n|=|a_n|\cdot|z^n|=a_n\cdot |z|^n\leq a_n\cdot 1^n\leq a_n$$  Then, applying Weierstrass M-test we get that the power series is convergent in $D$.  Now, I need to "find" an open ball $B$ such that $D\subset B$ and the power series is convergent in it.  Edit  $f$ is analytic in $1$, so there is an open set $U$ that contains $1$ such that   $$f(z)=\sum\limits_{n\geq 0} b_n(z-1)^n$$  Does it mean that the series is convergent in $U$?   I can see that we have that the two series coincide in $D\cap U$. How can I view the Android internal partition table? I've rooted my device, put it in recovery mode, and have linked it to PC by .  How can I view the list of storage devices and partitions?  Note: fdisk doesn't work. I've recently been trying to introduce myself to formal logic, and I've hit a stumbling point:  In the text I'm reading, a valid argument is defined as "an argument in which it is impossible for the premises to be true and at the same time the conclusion false."  The text then later prompts me to declare whether it's possible for an argument to be valid with a contradiction for a conclusion. The answer key then claims that yes, it is in fact possible, but offers no further explanation. I'm also supposed to create an example.  I just can't wrap my head around this one.  Here's the example I've worked up, is this a valid argument?   If grass is green then it is raining.  If water is wet then it is not raining.  Therefore: It is raining and not raining.   My head hurts. The Lie algebra of $SL_n(\mathbb C)$ are the matrices where the trace is $0$. But what is the Lie algebra of $SL_n(\mathbb H)$ where $\mathbb H$ is the quaternions? Function $f: \mathbb{R} \to \mathbb{R}$ that takes each value in $\mathbb{R}$ three times Does there exist a function $f: \mathbb{R} \to \mathbb{R}$ that takes each value in $\mathbb{R}$ three times? If not, how could I prove that such a function does not exist? How to find the URLs accessed by iOS Apps? What's the best way to take a picture of an LCD or CRT screen? I have seen many bad pictures of LCD and CRT screens. How do I get a good picture of an LCD or CRT screen? Let $D := \{z \in \mathbb{C}: |z| &lt; 1\}$ and $f\colon D \rightarrow \mathbb{C}$ be holomorphic. Suppose $\lvert f(z)\rvert \leq 1$ on $D$, show that $$\frac{|f(0)| - |z|}{1 + |f(0)||z|} \leq |f(z)| \leq \frac{|f(0)| + |z|}{1 - |f(0)||z|} \ \forall z \in D.$$  I have tried using Cauchy Integral Formula to $f$ and expanding $f$ at $0$, but I have no idea why $f(0)$ appears in the inequality in the former case. Both answers and hints are appreciated and thanks in advance! GRUB2 does not show Windows 8 option to boot into after Dual Boot Yesterday, I tried to dualboot Ubuntu 16.04 onto my hard drive, creating a new partition for Ubuntu alongside my existing Windows 8. First, I disabled the fast-boot option in Windows 8, and still GRUB did not load, and it went directly to Windows boot-up. Then I did some research and found this article:     Basically, I issued the BCDEdit command in Windows, and entered in the following code:  bcdedit /set {bootmgr} path \EFI\ubuntu\grubx64.efi   When I reboot, I get a basic GRUB2 terminal, and after I type in the exit command, then a second Shell prompt appears, and after typing the exit command again, the GRUB2 menu to select the OS to boot finally appears... with only Ubuntu and Ubuntu memory test as options, not Windows 8.  After booting into Ubuntu, I tried to run the Boot-repair Utility, but that shows this following error:   How do I approach this problem? The Pastebin log is here:   Thanks for the help! Specifically, if diary Tom Riddle had succeeded, how would he have strengthened the present day Voldemort?   In , @Pearsonartphoto gives a quote from J.K. Rowling in his answer regarding what would have happened if Tom Riddle had succeeded in fully manifesting from his diary memory form to a full human form.     Q: In Harry Potter and the Chamber of Secrets, what would have happened if Ginny had died and Tom Riddle had escaped the diary?   J.K. Rowling: I can’t answer that fully until all seven books are finished, but it would have strengthened the present-day Voldemort considerably.    - FAQ - Wayback Machine   As well, I've read all seven Harry Potter books many, many times and I haven't been able to ferret out any overt details regarding exactly how the present day Voldemort would've been strengthened by co-existing with diary Tom Riddle.  Specifically, how would the reincarnation of 16-year-old Tom Riddle have strengthened the 67-year-old present-day Voldemort at the time of Chamber of Secrets?  &#9733; I would love an answer from canon, any of J.K. Rowling's interviews, or Pottermore, or an answer constructed within the spirit of canon. How do I have no default web browser, so the system asks what browser to use when I click on a link? I use Internet Explorer for some things and Chrome for others. I'd like to have a choice when I click on a link of which browser to open the link in. Is this possible in Windows? I am currently running Windows 8, although there should be similarities between versions.  To the best of my knowledge this isn't possible. Is Innate Spellcasting counterspellable? On p.85 of Xanathar’s Guide to Everything, there’s a section clarifying that you need to perceive a spell being cast (by either a verbal, somatic or material component) in order to counterspell it.  It then goes on saying this :     If the need for a spell’s components has been removed by a special ability, such as the sorcerer’s Subtle Spell feature or the Innate Spellcasting trait possessed by many creatures, the casting of the spell is imperceptible.   The thing is that many monsters’ Innate spellcasting specify that only material components are discarded (not verbal or somatic). So I am not sure whether you can actually counterspell innate spellcasting when the stat block only mentions removing material components.  There seems to be  supporting that such spells could be counterspelled (although it is confusing a bit).  It basically comes down to whether the above quote’s “many creatures” refers to all creatures with innate spellcasting, or only those that forgo all spell components to innanely cast. So, which is it ? How to clone a Windows 10 dell onto an SSD I've recently bought a Dell Inspiron 3650, and would like to clone the disk onto a samsung SSD I have bought for it, in order to speed up boot times etc.  Samsung provide a clone tool called "Samsung data migration", which I've had success with in the past for cloning a system from a HDD to SSD.  Having tried it on the dell, the disk is not bootable, Leaving me with an error that no bootable media can be found. I've tried using a recovery usb to fix any boot system errors, but this fails with an error.  Booting into windows on the old HDD, the system recognises the disks have the same ID and disables the SSD, so it looks like the clone was successful.  I've tried disabling secure boot in the bios and then doing the clone, but this doesn't make a difference.  What else should I try? The system has Windows 10 home installed and is brand new, straight out of the box. How to set an image as a background for Frame in Swing GUI of java? USB flash drive autorun Derivative of a factorial What is ${\partial\over \partial x_i}(x_i !)$ where $x_i$ is a discrete variable?  Do you consider $(x_i!)=(x_i)(x_i-1)...1$ and do product rule on each term, or something else? Thanks. Summoning an item in 1.9 with motion When I put   /summon Item ~ ~2 ~ {Item:{id:"minecraft:diamond",Count:1b,Motion:[0.0,0.8,0.0]}}    in a command block, it summons the diamond with Count:1b but it doesn't follow the Motion Tag. Does anyone know how to get the Motion Tag working? Too big addon list, what should I do? How expand names and keep it all? Is an Anti-Symmetric Relation also Reflexive? According to the definition of an Anti-Symmetric Relation if xRy and yRx then x = y  Which means, effectively, x is in relation with itself. Does this mean that anti-symmetry implies reflexive property as well?