I want to remove duplicate entry from my array and my array is           ArrayTotal All Banks,Total All Banks,Total Domestic Banks,Total Domestic Banks,B2B Bank,B2B Bank,Bank of Montreal,Bank of Montreal,The Bank of Nova Scotia,The Bank of Nova Scotia,   we want to remove duplicate entry for this I am trying in php unique_array and I also tried in javascript         var uniqueNames = [];       $.each(names, function(i, el){       if($.inArray(el, uniqueNames) === -1) uniqueNames.push(el);       });       console.log(uniqueNames) its gave error Unexpected token A
How can I remove duplicate values from an array in PHP?
How to pronounce "Stannis's"? I know that the &quot;s&quot; becomes &quot;z&quot; when it comes after a voiced sound. And it is pronounced as &quot;s&quot; when it comes after a voiceless sound. I also know rules about possessives but I don't know how natives pronounce a word when it ends in S and &quot;apostrophe S&quot; is added to it. For example: &quot;Stannis's army&quot;. Do you add another syllable to it? Like Stannisiz? or just Stannis and ignore the possessive S? I really have difficulty in pronouncing words that end in S and possessive S is attached to it. Convert Month Number to Month Name Function in SQL I have months stored in SQL Server as 1,2,3,4,...12. I would like to display them as January,February etc. Is there a function in SQL Server like MonthName(1) = January? I am trying to avoid a CASE statement, if possible. Front suspension or full suspension mountain bike Group of even order contains an element of order 2 Learn Bayesian inference applied to astronomy / astrophysics? Partitioning $\{1,2,\ldots,k\}$ into $p$ subsets with equal sums, where $p$ is prime Let $p$ be a prime natural number. For which positive integer $k$ can the set $\{1,2,\ldots,k\}$ be partitioned into $p$ subsets with equal sums of elements ?  Obviously, $p\mid k(k+1)$. Hence, $p\mid k$ or $p\mid k+1$. All we have to do now is to show a construction. But I can't find one. I have tried partitioning the set and choose one element from each set but that hasn't yielded anything. Any hint will be appreciated. How to move a visible file to a hidden folder? I've only been using Ubuntu for two weeks and have been able to find answers to any problem I had, however this one defies my searches.  I want to move a visible programme file (wallch) to a hidden directory ./config/autostart.  I have been able to enter this directory and the subject file is not there and I want to have this program start at bootup.  Can anyone assist?  Thanking you Why shouldn't I mix tabs and spaces? USB is a popular standard and I was wondering whether there is some way to connect two or more computers using USB ports rather than the Ethernet ports. How do you add a timer to a C# console application Just this - How do you add a timer to a C# console application? It would be great if you could supply some example coding. (1) Does he not know? (2) Doesn't he know?  I don't usually see and hear questions formed in the first style. I was even surprised to know that it is grammatically correct. And actually it is the most &quot;proper&quot; way to form an interrogative sentence.  shows that the first style was much more popular before than now. What are your suggestions on choosing between these styles? And I will probably add the third one.  (3) He does not know?  EDIT: The answers have explained how to form a question, but have not actually provided an account on the usage of the first two forms. Especially I'm interested in the first form: does it sound formal, is it used in speech or only in writing, et cetera. $M$ connected $\iff$ $M$ and $\emptyset$ are the only subsets of $M$ open and closed at the same time I'm trying to understand this proof that:  $M$ connected $\iff$ $M$ and $\emptyset$ are the only subsets of $M$ open and closed at the same time  Which is:  If $M=A\cup B$ is a separation, then $A$ and $B$ are open and closed. Recriprocally, if $A\subset M$ is open and closed, then $M = A\cup(M-A)$. What? I know that if $M=A\cup B$ is a separation, $A$ and $B$ are both open. But why closed? Also, the 'recriprocally' part is totally nonsense to me. Anybody could help?  Also, there's another proof, which states: $M$ and $\emptyset$ are the only subsets of $M$ at the same time closed and open $\iff$ if $X\subset M$ has empty boundary, theb $X=M$ or $X=\emptyset$  which is proved as the following:  given $X\subset M$, we know the condition $X\cap \partial X = \emptyset$ implies $X$ is open, while the condition $\partial X \subset X$ implies $X$ is closed. Then, $X$ is open and closed $\iff$ $\partial X = X\cap \partial X = \emptyset$, this show $\iff$ for the theorem above.  First of all, I think that the condition $X$ has boundary empty implies that $X\cap \partial X$ is empty, but who said anything about $\partial X\subset X$? Also, where's the $\rightarrow$ of this proof? I can only see $\leftarrow$ Sometimes I'm looking for date-sensitive information and don't want to see results more than a certain age.  Is there a way to specify this in a Google search? Rationalize   $\dfrac{1}{\sqrt[3]{p^2}+\sqrt[3]{pq}+\sqrt[3]{q^2}}.$  How would I go about doing this without wading through lots of algebra?  Is there a trick similar to how you can multiply by $\dfrac{\sqrt a-\sqrt b}{\sqrt a-\sqrt b}$ with square roots?  Thanks in advance! I’m using tikz-cd for diagrams, and have a medium-sized diagram that I want to re-use several times.  However, when I try using a definition like:  \newcommand{\myarrow}{$\begin{tikzcd} A \ar{r} &amp; B \end{tikzcd}$   I get an error:  ERROR: Package pgfbasematrix Error: Single ampersand used with wrong catcode.   Is it possible to put a tikz-cd diagram into a defined command somehow? For example, you're a fashion designer who wants to get the opinion of both a professional and someone who doesn't know much about fashion. What's a term for the latter person? Infinite Series $\sum\limits_{k=1}^{\infty}\frac{k^n}{k!}$ How do I show for an ideal transformer $M^2=L_1L_2$? I've been stuck on this problem for about an hour.     In an ideal transformer, the same flux passes through all turns of the primary and of the secondary . Show that in this case $M^2=L_1L_2$, where $M$ is the mutual inductance of the coils, and $L_1$, $L_2$ are their individual self-inductances.   My first instinct was the following: If we isolate the response of each coil to the other one, we get the equations $N_1\Phi_1=MI_2$ and $N_2\Phi_2=MI_1$, where $\Phi$ is magnetic flux going through a single turn of the coil and $I$ is current. Likewise, if we isolate the response of each coil to itself, we get the equations $N_1\Phi_1=L_1I_1$ and $N_2\Phi_2=L_2I_2$. I would now naturally want to say "Now just multiply $N_1\Phi_1$ and $N_2\Phi_2$ both ways, and get the desired result!" i.e.,  $$(N_1\Phi_1)(N_2\Phi_2)=(MI_2)(MI_1)=(L_1I_1)(L_2I_2)\implies M^2=L_1L_2$$  But that's incorrect, because the response of the coils to themselves and to the other coil are different quantities (i.e. not necessarily equal).  Realizing this, I write down the more general equations.  $$N_1\Phi_1=MI_2+L_1I_1$$ $$N_2\Phi_2=MI_1+L_2I_2$$  Now even with the hypothesis that $\Phi_1=\Phi_2=\Phi$, I still can't see how the identity $M^2=L_1L_2$ follows. Could you help clear up my confusion?  *Taken from D. Griffiths Introduction to Electrodynamics (4th ed.), Problem 7.58. How do I add a custom keybind to a button on any website? Suppose an entire function $f$ is real if and only if $z$ is real. Prove that $f$ has at most $1$ zero. Let $f$ be an entire function. Suppose $f(z)$ is real if and only if $z$ is real. Prove that $f$ has at most $1$ zero. How to prove? Totally I have no idea... Please give the solution in detail since I do not understand.