I have an account in Stack Overflow and several other Stack Exchange sites. Originally, my account was tied to my Facebook account but not anymore.   I am trying to log in/sign up to , but both log in/sign up pages only offer the option to use an existing Google+/Facebook account, or alternatively Wordpress, openID, etc.  Usually, when I sign up to a new Stack Exchange site, I am given the option to use my existing Stack Exchange account, but not with Super User.    I tried accessing the Stack Exchange site, and in my profile page, under "accounts" I can see Super User. However, when I click to go to that site, the top bar shows the "log in" button instead of my name/avatar.  What is going on?  EDIT: Of course, there is also the option to enter my e-mail address and password, which I ended up doing, and I could finally log into my (existing) Super User account.
I have an account on Stack Exchange but when I try to login to  I do not see the option Login with Stack Exchange.       Why is this option now not available?
UK coastline shapefile? sed - replace string with file contents I have two files: file1 and file2.  file1 has the following contents:  ---   host: "localhost"   port: 3000   reporter_type: "zookeeper"   zk_hosts:      - "localhost:2181"   file2 contains an IP address (1.1.1.1)  What I want to do is replace localhost with 1.1.1.1, so that the end result is:  ---   host: "1.1.1.1"   port: 3000   reporter_type: "zookeeper"   zk_hosts:      - "1.1.1.1:2181"   I have tried:  sed -i -e "/localhost/r file2" -e "/localhost/d" file1 sed '/localhost/r file2' file1 |sed '/localhost/d' sed -e '/localhost/r file2' -e "s///" file1   But I either get the whole line replaced, or the IP going to the line after the one I need to modify. Is there a continuous bijection from $[0,1]$ onto $[0,1] \times [0,1]$? That is with $I=[0,1]$ and $S=[0,1] \times [0,1]$, is there a continuous bijection $$ f: I \to S? $$  I know there is a continuous bijection $g:C \to I$ from the Cantor set $C$ to $[0,1]$. The square $S$ is compact so there is a continuous function  $$ h: C \to S. $$ But this leads nowhere. Is there a way to construct such an $f$?  I ask because I have a continuous functional $F:S \to \mathbb R$. For numerical reason, I would like to convert it into the functional $$ G: I \to \mathbb R, \\ G = F \circ f , $$ so that $G$ is continuous. Prove $(k,n+k)=1$ iff $(k,n)=1$ (a) Prove $(k,n+k)=1$ iff $(k,n)=1$. (b) Is it true that $(k,n+k)=d$ iff $(k,n)=d$? (all variables are integers, (a,b) means gcd(a,b))  For (a), I can only get so far.  $(k,n+k)=1\ \Rightarrow\ kq_1+(n+k)q_2=k(q_1+q_2)+nq_2=1$.  Note that we don't yet have that theorem (from a different class) that says something like if $d=(a,b)$, then $d$ is the smallest (or is it biggest) number which can be made by $ak_1+bk_2$, (which I'm not quite sure how it would help, anyway). So I'm stuck. If, one fine day, someone found a contradiction in ZFC (or even ZF), what implications would such an event have for mathematicians? Is there currently any backup axiomatic system on par with ZFC that would enable mathematicians to continue pursuing mathematics, should the unthinkable occur? Can I boil milk unattended (and still keep the pan clean)? Which objects can I use in a finalizer method? As far as I know, only a player character's non-temporary ability scores are considered for taking feats, taking prestige classes, etc. Meanwhile, any ability bonus that comes from spells, or magic items that are in effect only while worn, is not counted (except tomes which increase abilities permanently).  So a Fighter with low Int who wants to qualify for Combat Expertise can't use spells or items that gives an Int bonus to raise it high enough to qualify. Is that right?  For example:  Say our fighter has Str 12, so he can not take the Power Attack feat. Suppose he asks for a spell from the wizard to make his Str 16, or to borrow a ring which provides +4 Str from another character. (Or any other method that will provide him a non-permanent bonus). His Str is now 16. Can he take Power Attack with that non-permanent bonus now? Because after the spell duration ends or he takes off the ring, his Str score will be to low again to qualify for Power Attack. How do I craft command blocks? I went to my friends house, and he was playing Minecraft on the PC. He showed me a command block, but when I went home and opened Minecraft pocket edition, I went to the crafting table but I could not find any command blocks to craft.  What are command blocks and how do I craft them? Chat gives me really, really specific time gap notifications I don't think I ever understood the rationale behind this.  I get that the dot product $\mathbf{a} \cdot  \mathbf{b} =\lVert \mathbf{a}\rVert \cdot\lVert \mathbf{b}\rVert \cos\theta$ is derived from the cosine rule. (Do correct me if I'm wrong.)  However, I never really understood why $\mathbf{a} \times  \mathbf{b} =\lVert \mathbf{a}\rVert \cdot\lVert \mathbf{b} \rVert \sin\theta$. Is there a proof for this?  In addition, how does the vector cross product lead to orthogonal vectors?  I remember learning that they do and I know how to solve equations using the respective formulas, but I never got why is it so. Stack Overflow is getting a Meta of its own Tikz: adjusting pin anchor I was looking for a possibility to adjust the anchor of the text of a pin. Tikz does not allow this out of the box.   This question was already asked on the mailing list , Sept. 2009 without any reply till today or feature addition to pgf/tikz:  \documentclass[tikz]{standalone}  \begin{document}      \begin{tikzpicture}[          every pin/.style={anchor=west},          every pin edge/.style={anchor=west}]          \node [pin=60:test] at (0,1) {};          \node [pin={[anchor=west]60:test}] at (0,0) {};      \end{tikzpicture}  \end{document}   There is also a question with a suggested workaround here on  by defining an aligned pin style consisting of another node positioned at the end of the pin using \tikzlastnode:  \tikzset{     aligned pin/.style args={[#1,#2]#3:#4}{         pin={[inner sep=0pt,%               pin distance=#2,% new option, default = 3ex               label={[append after command={%                     node[inner sep=0pt,%                         xshift=-0.1cm,% modified, default = 0                         at=(\tikzlastnode.#3),%                         anchor=#1,%                     ]{#4}%                 }%             ]center:{}}%         ]#3:{}}%     } }   In this code, I have added a second unnamed option for pin distance within the square brackets.  MWE using the workaround showing the desired result:  \documentclass[tikz]{standalone}  \tikzset{     aligned pin/.style args={[#1,#2]#3:#4}{         pin={[inner sep=0pt,%             pin distance=#2,% new option, default = 3ex             label={[append after command={%                     node[%                         inner sep=0pt,%                         xshift=-0.1cm,% modified, default = 0                         at=(\tikzlastnode.#3),%                         anchor=#1,%                     ]{#4}%                 }%             ]center:{}}%         ]#3:{}}%     } } \begin{document} \tikz[pin distance=15mm, every pin/.style={fill=blue,text=white}] \node [circle,draw,     aligned pin={[west,3ex]0:X-Value},%     aligned pin={[west,3ex]45:Y-Value},%     aligned pin={[west,3ex]90:Z-Value}] {my circle}; \end{document}     I would like to add further options such as pin edge to adjust the style of the edge. Another addition would be xshift to finetune the position of the text (and yshift).  Is it possible to change the workaround to allow named options with default values if not specified?  Usage could look like this (without using necessarily all options):  node[aligned pin={[pin anchor=west,pin distance=1cm,pin edge={thick}]90:{txt}}]{};   If someone is interested in the implementation of the pin feature in tikz see  and do a textsearch for pin.  Update after answer by Qrrbrbirlbel:  To achieve almost the same result as my MWE use following code  % use preamble from Qrrbrbirlbel answer \begin{document}  \begin{tikzpicture}[every pin/.append style=draw, every pin edge/.style={thick}] \node[c] [ pin={[pin anchor=south west,pin edge pin anchor=south west,pin distance=6ex]90:Z-Value}, pin={[pin anchor=west,pin edge pin anchor=west,pin distance=6ex]45:Y-Value}, pin={[pin anchor=west,pin edge pin anchor=west,pin distance=6ex]0:X-Value} ] at (0,0) {}; \end{tikzpicture}  \end{document}     However, I would like to finetune the text positioning using inner sep=0 and a slight shift:  \newlength{\xshiftlength} \setlength{\xshiftlength}{0.5\widthof{Z}}   Following works:  \tikzset{   pin inner xsep/.style={tikz@pin@post/.append style={inner xsep=#1}} }   Apparently xshift cannot be added in the same way. It shifts more than only the text. How could a pin text xshift be added? So people have had similar problems showing colors on .ply files  and   but I don't think this is the same case.  I've exported a .ply file from a program called paraview with color info on it.  I've uploaded the file  and as you can see, the color info came with it.  But for whatever reason when I import it into blender and go look for the per-vertex color info where I would expect to find it, its empty:   Am I doing something wrong?  It seems like there had been a problem with impo but this is 2.81.  I would assume it was fixed? Uk Visa Refused need guidelines etc,,, Changing units of measurement in a simple regression model What is the best way to replace the file browse button in html? I know that it's possible to replace the browse button, which is generated in html, when you use input tag with type="file.  I'm not sure what is the best way, so if someone has experience with this please contribute. $(n+1)$th prime $p_{n+1}$ less than or equal to $p_1p_2\dots p_n+1$ On August 5, 41 days ago, I submitted an application for a UK visitor visa. This is the third time I have applied. The only notice I have received so far says this: "Unfortunately, the processing of your application has not been straightforward. This means that we will be unable to make a decision within our published customer service standards." What should I do? How do I upgrade to a newer version of Ubuntu?