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Is "performance" singular or also plural? As most of you know, in the Microsoft Store, there are . This means that on Windows I can emulate Ubuntu and have the Ubuntu command line directly on Windows.  The question is very easy: what can’t I do from the Ubuntu command line emulated in Windows that I can do on a proper Linux-based Ubuntu? Is it useful to download this Ubuntu application, install it, and work just with it instead of the real OS? Is it possible to install all the development libraries? Can I write (or not) device drivers? In other words: what are the limits?  What features of Ubuntu Linux-based are missing from Ubuntu-on-Windows?  New answers are welcome: I know that every software is always changing by improving characteristics and features! Norm and unit sphere Using Newton's Law of Universal Gravitation to find distance, with the question not giving sufficient information to substitute into the equation. Problem:  $F = \frac{(G m_1 m_2)}{r^2}$  An object of unknown mass is placed directly between the Earth and the Moon such that the forces of gravity acting on the object are equal from both the Earth and the Moon. The distance from the Moon to the object is exactly one-tenth of the distance from the Moon to Earth. Using the above formula, determine the distance from the Moon to the Earth.  Given is:  The factor $G≈6.67∙10−11\mathbf{N(\frac{m^2}{kg^2})}$ is a universal constant.  Mass of Earth $≈5.972∙10^{24}\mathbf{kg}$   Mass of the Moon as $≈7.348∙10^{22}\mathbf{kg}$  Mass of unknown object = $m$  My solution:  $F = \frac{(6.67 *10^-11) m (7.348*10^{24})}{R^2}$  $F = \frac{(6.67 *10^-11) (5.92* 10^22) m}{10R^2}$  As gravitational force acting on the object is equal   $\frac{(5.92\cdot 10^22)}{100r^2} = \frac{(7.348*10^{24})}{r^2}$  $R = 1.24 \cdot 10^4 KM$  Is this a viable solution to the problem? Please provide feedback. Thank you! What is the easiest way to update/upgrade an offline Ubuntu machine with the help of a Windows machine that has internet access?  This question also applies to installing new packages offline and not only updates/upgrades.  The Linux system shall remain completely cut off from the Windows machine, meaning there should be no ethernet connection or the likes between the two computers.  Update:  Please have patience, since I haven't updated this since two weeks. There are some complications getting apt-offline to work properly on Lubuntu and all other methods seem to be too old and deprecated:  AptOff - last update 2006 AptMedium - last update 2007 Keryx - last update 2011, looks like this project was discontinued  I hope I will be able to somehow update the offline machine, finally.  While I was still not able to update/upgrade the offline system due to authentication errors, I accepted an answer, because it's taking too long. Prove if $n \in \mathbb N$, then $\frac{1}{2!}+\frac{2}{3!}+\frac{3}{4!}+\cdots+\frac{n}{\left(n+1\right)!} = 1-\frac{1}{\left(n+1\right)!}$   So I proved the base case where $n=1$ and got $\frac{1}{2}$  Then since $n=k$ implies $n=k+1$ I setup the problem like so:  $\frac{k}{(k+1)!}+\frac{(k+1)}{(k+2)!}=1-\frac{1}{(k+2)!}$  After trying to simplify it I got the following:  $\frac{k(k+2)!+(k+1)(k+1)!}{(k+1)!(k+2)!}=1-\frac{1}{(k+2)!}$  However, I'm having trouble simplifying it to match the RHS.  Hints? How do I get my Broadcom BCM4313 working correctly? Let $X_1, \cdots, X_n$ be a random sample from the PDF: $f(x;\theta) = (\theta + 1) x^{\theta}$ with $0&lt;x&lt;1$ and $\theta &gt; -1$.  The likelihood function is: \begin{align} L(\theta) &amp;= f(x_1, \cdots, x_n; \theta) \mathbb{1}\{0&lt;x&lt;1\} \mathbb{1}\{\theta &gt;-1\}\\ &amp;= \prod_{i=1}^{n}{f(x_i ; \theta)}\mathbb{1}\{0&lt;x&lt;1\} \mathbb{1}\{\theta &gt;-1\}\\ &amp;= \prod_{i=1}^{n}{(\theta+1)x_i^{\theta}}\mathbb{1}\{0&lt;x&lt;1\} \mathbb{1}\{\theta &gt;-1\} \\ &amp;=(\theta+1)^n \left( \prod_{i=1}^n{x_i}\right)^\theta \end{align}  We look at the log likelihood $l(\theta)$ and take the derivative of this since it is easier to deal with and it is allowed because the log is monotonic:  \begin{align} l(\theta) = n\log(\theta+1) + \theta \left( \sum_{i=1}^n{\log(x_i)} \right) \end{align}  $\implies \frac{d}{d\theta} = \frac{n}{\theta+1} + \sum_{i=1}^n{\log(x_i)} = 0$  $\implies \hat{\theta}_{MLE} = -\frac{n}{\sum_{i=1}^n{\log(x_i)}} - 1$  However, this doesn't look right. java.lang.NoClassDefFoundError: javax/servlet/jsp/jstl/core/Config a cold vs flu / the flu Have you got a cold? Have you got flu? Have you got the flu?  Why can't we say a flu or the cold in the previous examples? Overall reputation scores are headed nowhere but up.  Pretty soon there will be thousands of mods.  What to do?  Thoughts on possibilities:   Thousands of mods is fine.  Carry on. Adjust the threshold values for high-level SO privileges. Do a straight-up inflation adjustment.  You had x rep, then at the turn of the year we applied the Consumer Rep Index to all scores, now you have (x / inflation) rep. Implement a rep decay mechanism, so that inactivity sheds some of the overall rep that's built up. I have a 10 stock portfolio and considering market conditions that are on the rise when this question in being asked, a few of them did hit their 52-week high price.  I would like to call myself a long term investor and I do not like to trade so much. If I take "Buy low sell high" as gospel then this is in my opinion a good selling position.  On one hand, I think I should lock my profit because stocks don't hit a 52-week high every day, but on the other hand, there is nothing wrong with the company and it is very well positioned to go up even further.  Any suggestions? Proof of convergence of sequences Problem: Show that if $x_n\to 5$ then $\dfrac{x_n +1}{\sqrt{x_n -1}} \to 3$.  So I know $|x-5|&lt;\epsilon$ and I need to show that $\left|\dfrac{x_n +1}{\sqrt{x_n -1}} -3\right| &lt; \epsilon$.  I tried applying the triangle inequality (and a bit of algebra) to get $$\left|\frac{x_n +1}{\sqrt{x_n -1}} -3\right| \leq |x_n -5| \left |\frac{1}{\sqrt{x_n -1}}\right| + \left|\frac{6}{\sqrt{x_n-1}} -3\right|.$$  From this I know that $|x_n -5| &lt;\epsilon$ and can show that $\left |\dfrac{1}{\sqrt{x_n -1}}\right|&lt;1$. So my only problem is the second part of the sum. I have no idea what to do with it to get everything to be less than $\epsilon$. Removing intercept from GLM for multiple factorial predictors only works for first factor in model How confident is my model? Is there a way to know? When to use an object pronoun or a possessive adjective before a gerund The rule says that we can use a possessive adjective or an object pronoun before a gerund. Is there a rule  that says when to use each or are they interchangeable? Some say that it's wrong to use an object pronoun before a gerund. I'm stuck underground.   I can't mine any further to reach lava. There is no water nearby, and zombies can't reach me.  I can't see to find any blocks to suffocate my character.  NBTEdit and similar programs don't work on Mac, so I can't edit my save file to escape. I have hardly any blocks so cannot jump and lay my way up. I can't see, and do not have any torches, so can't make a staircase back up. I don't want to make new save as I have an awesome house filled with stuff that took me ages to find.    How can I get back to the surface? Say if $A$ is an $n \times  n$ matrix, why is it that if $A^{T}A$ is positive definite, the matrix $A$ is then invertible? All I know is $A^{T}A$ gives a symmetric matrix but what does $A^{T}A$ is positive definite tell or imply or hint about the matrix $A$ itself that leads to the fact that it will be invertible? How to list all nodes of nodetype A which has the current node referenced? So this is what I'm trying to do in Drupal 6:  Node type A is video, node type B is a person Nodetype A has a reference field where you can enter a reference to any Node from nodetype B  how can I create a block view which will be displayed on nodes from node type b, which will show all the nodes from node type A where the current node from node type B is referenced? For a specific package, can I find out why it is installed?  So, can I see or it's manually installed, or that it is installed as a dependency of another package? Or that it is installed as part of the distro?