I recently pulled a  from a Kaladesh booster box, and placed it into a deck I was working on. When playtesting the deck with some friends, I noticed a card with a clear visual marker on the card on the top of my deck. When I pulled it my next turn, it was my Padeem I had recently obtained.   Its a very, very clear marker, a white oval on the backside of the card. If it was on the front, I would just live with it, but I don't want to bring these cards to a LGS event and get accused of marking my cards, or having one of my friends always know whats in my hand. The frontside of the card is completely clean.   Do I have any options here? Can I get a refund or sell this type of card to someone who collects misprints? Am I just going to have to fill in the circle, and hope its not noticeable?
I bought a Magic the Gathering display box today with cards from the new edition Innistrad. Unfortunately one of the cards in a booster pack was damaged. It is not just a simple scratch - one corner is bent and a small part of the card is missing. According to different trading platforms this card would be worth about 6 Dollars minimum in mint condition. So it is not really expensive but also not totally worthless.  What can I do about this? Can I obtain a replacement card from the producer (WotC) or from the store I bought it from? How can I prove that the card was damaged when I opened the booster pack? I am sure I am not the first person who got a damaged card from a booster pack. How are such issues usually handled?
I have a question about deriving the coordinate representation of momentum operator from the commutation relation, $[x,p]= i$.  One derivation (ref W. Greiner's Quantum Mechanics: An Introduction, 4th edi, p442) is as following: $$ \langle x|[x,p]|y \rangle = \langle x|xp-px|y \rangle = (x-y) \langle x|p|y \rangle. $$ On the other hand,  $ \langle x|[x,p]|y \rangle = i \langle x|y \rangle = i \delta (x-y)$. Thus $$ (x-y) \langle x|p|y \rangle = i \delta(x-y). \tag{1} $$  We use $(x-y) \delta(x-y) = 0$. Take the derivative with respect to $x$; we have $\delta(x-y) + (x-y) \delta'(x-y) = 0$. Thus $$ (x-y) \delta'(x-y) = - \delta(x-y). \tag{2} $$  Comparing Eqs. (1) and (2), we identify $$ \langle x|p|y \rangle = -i \delta'(x-y). \tag{3} $$  In addition, we can add $\alpha \delta(x-y)$ on the right-hand side of Eq. (3), i.e. $$ \langle x|p|y \rangle = -i \delta'(x-y)  + \alpha \delta(x-y), $$ and $[x,p] = i$ is still satisfied. We can also add $$ \frac{\beta}{\sqrt{|x-y|}}\delta(x-y)$$ on the RHS of Eq. (3).  Here $\alpha$ and $\beta$ are two real numbers.  My question is, what is the most general expression of $\langle x|p|y \rangle$? Can we always absorb the additional term into a phase factor like Dirac's quantum mechanics book did?  Thank you very much in advance. Runtime error : ERROR 000358: Invalid expression using SelectLayerByAttribute in ArcPy? I cannot for the life of me persuade SelectLayerByAttribute to work (I need to automate this for a complex script).  Working in ArcMap's python console on already loaded shapefile, the format below:  import arcpy from arcpy import env arcpy.env.workspace = r"C:/Users/.../working" arcpy.SelectLayerByAttribute_management("layer", "NEW_SELECTION", " 'ATTRIBUTE' = 'Criterion' ")   results in error:     Runtime error : ERROR 000358:   Invalid expression Failed to execute (SelectLayerByAttribute).   An alternative method:  import arcgisscripting import arcpy gp = arcgisscripting.create(9.3) gp.workspace = "C://...//working" sFile = "C://...//working//shapefile.shp" lyr = "layer" gp.makefeatureLayer_management(sFile, lyr) gp.toolbox = "management" gp.SelectLayerByAttribute("layer", "NEW_SELECTION", " 'ATTRIBUTE' = 'Criterion' ")   .. selects everything, including features that don't meet the criterion!  Does anyone have any idea what's going wrong?  I've read some pages on , but found no solution that works here. The working directory is correct. The attribute field and criterion are correctly specified (case sensitive etc), etc. Its very confusing. How to stop mysql from running at boot time? Currently, my MySQL server starts on every server boot. For a couple reasons, this is undesirable behavior. Is there a way to disable this behavior? Row colour gaps in tabularx with \aboverulesep and \{} \documentclass[]{article} \usepackage[table,dvipsnames]{xcolor} \usepackage{multicol,booktabs,tabularx}  % Table settings \renewcommand{\aboverulesep}{1pt} \renewcommand{\belowrulesep}{1pt}  \begin{document}     \begin{tabularx}{\textwidth}{@{}X l@{}}         This is Header 1 &amp; This is Header 2 \\         \toprule         \rowcolor{Apricot}         This is Text 1 &amp; This is Text 2 \\\midrule         This is Text 1 &amp; This is Text 2 \\\midrule         This is Text 1 &amp; This is Text 2 \\         \bottomrule     \end{tabularx} \end{document}   I have the above table MWE using tabularx, and I am trying to colour the row from the table. However, due to the use of my \aboverulesep and \belowrulesep, I now have gaps above and below my table row that is not coloured.   Also, because of the use of my @{} on either side of the table to 'remove' the excess padding on the sides of the table, the row colour is being applied in those padding as well.   Qn 1: How can I colour the aforementioned gaps (arising due to the \aboverulesep) in, while maintaining the rule separation?   Qn 2: How to remove the colour from the two sides of the table?     EDIT  This is in response to Zarko's answer. I want to maintain the use of @{} on either side to remove the padding. If I were to adapt this into your answer, like so:  % @Zarko's answer \documentclass{article} \usepackage[table,dvipsnames]{xcolor} \usepackage{booktabs, cellspace, tabularx}  % Table settings \renewcommand{\aboverulesep}{0pt} \renewcommand{\belowrulesep}{0pt} \setlength\cellspacetoplimit{5pt} \setlength\cellspacebottomlimit{5pt}  \begin{document}     \begin{tabularx}{\textwidth}{@{}SX Sl@{}}% &lt;-- S is append for activate additional vertical space          This is Header 1 &amp; This is Header 2 \\         \toprule         \rowcolor{Apricot}         This is Text 1 &amp; This is Text 2 \\\midrule         This is Text 1 &amp; This is Text 2 \\\midrule         This is Text 1 &amp; This is Text 2 \\         \bottomrule     \end{tabularx} \end{document}   I obtain this:   and so my second question (Qn2) is still unresolved.. For Qn 1, I prefer to use the solution by @Skillmon with \renewcommand{\arraystretch}{1.15} as I need not add a new package. Is it possible to use more than 20 layers? Is it possible to use more than 20 Scene layers or Render layers in Blender? My current idea is to use the dual graph, and prove that that is a bipartite graph, and so proving the statement. But I can't seem to figure out how even degree for all verticies means that it is bipartite.  Any help is appreciated. Thanks! Square roots -- positive and negative Why are springs shaped the way they are? Why are springs coiled the way they are? Why not some other shape? Is the shape due to its elasticity or something? How to sort two lists (which reference each other) in the exact same way Beam size and material for 15 feet long swing I need to create a 15 feet span beam for kid swing (300 lbs load / 150 lbs and 2 swings assumption). One end will bolt to the tree (just for convenience).  What "treated lumber" lumber size and material I should use? Or is it better / cheaper to use metal pipe (from the plumbing department)?  I guess 4x8x16 or two (2) 2x8x16 would do it according to this website . But I do like a clean look of metal. My wife would concern about big piece of lumber running on top of the kid (that looks heavy visually). Test for convergence of the series $\sum_{n=2}^\infty\frac{1}{(\ln n)^{\ln n}}$ Could I have a hint for testing the convergence of the following series please?  $$\sum_{n=2}^\infty\frac{1}{(\ln n)^{\ln n}}$$  Edit  The integral test does not work because $\int_1^n\frac{1}{(\ln x)^{\ln x}}dx$ has not an elementary primitive.  Thank You. The following definition is needed for my actual question:  For $A, B \in \mathcal{M}_{n \times n}$ define $$  \langle A, B \rangle = \text{Trace}(B^{T}A) = \sum_{j=1}^{n}\sum_{i=1}^{n}b_{ij} \, a_{ij} $$  And here is the actual question:  For $B \in \mathcal{M}_{n \times n}$ show that $$ \text{Trace}(B)^{2} \:\leq\: n \,\text{Trace}(B^{T}B) $$  I know I have to use the Cauchy-Schwarz Inequality, but I wasn't exactly sure how to.  Here is my attempt:  Since I only have one matrix I decided to use the identity matrix $$ \begin{align} \text{Trace}(B)^{2} \:&amp;\leq\: n \,\text{Trace}(B^{T}B) \\ \text{Trace}(I^{T}B)^{2} \:&amp;\leq\: n \, \langle B, B \rangle \\ \langle I_{n}, B \rangle^{2} \:&amp;\leq\: n \, \Vert B \Vert^{2} \\ \langle I_{n}, B \rangle \:&amp;\leq\: \sqrt{n} \, \Vert B \Vert \end{align} $$  I feel like I either did it incorrect, or that I'm close but am missing something. How do you kill the devil? Uninstall, Activate, Deactivate a plugin: typical features & how-to I'm making a WordPress plugin. What are typical things I should include in the uninstall feature?  For example, should I delete any tables I created in the install function?  Do I clean up my option entries?  Anything else? Choice of personal pronoun in single-author papers Consider two different shaped containers having same area: one is cylinder, the other is like an inverted pyramid (roughly). Both have the same level of water, the weight of the inverted pyramidal container will therefore be greater than that of the cylinder. But I know from Pascal's law that the pressure should be same in both containers. If the base areas are the same then the force (weight as measured by a scale) should also be the same. Why are the weights different? How to add flavouring ingredients to steamed or boiled veggies? I can not see how mathematically one can divide the numerator and denominator by theta. Can some one explain this in a different way. When you divide two fractions you multiply the first fraction by the reciprocal of the second. This is not the case here.     Divide numerator and denominator by $\theta$. ($\sin\theta$ also works.) $$\eqalign{\lim_{\theta\to0}\dfrac{\sin\theta}{8\theta+\tan\theta}&amp;= \lim_{\theta\to0}\dfrac{\dfrac{\sin\theta}\theta}{8+\dfrac{\sin\theta}\theta\cdot\dfrac1{\cos\theta}}\\&amp;=\dfrac{\lim\limits_{\theta\to0}\dfrac{\sin\theta}\theta}{8+\lim\limits_{\theta\to0}\dfrac{\sin\theta}\theta\lim\limits_{\theta\to0}\dfrac1{\cos\theta}}\\&amp;=\dfrac1{8+1\cdot1}\\&amp;=\dfrac19.}$$ How can I run scripts automatically when Ubuntu starts up so I don't have to run them manually after startup? For what values of $\alpha$, does this integral converge? For what values of $\alpha&gt;0$ this integral converges $$\int_0^{\infty} \frac {\sin x}{x^{\alpha}}dx $$