The Order of Scribe's wizard's level 6 feature Manifest Mind (TCoE, p.78) states (emphasis mine):  Whenever you cast a wizard spell on your turn, you can cast it as if you were in the spectral mind's space, instead of your own, using its senses. You can do so a number of times per day equal to your proficiency bonus, and you regain all expended uses when you finish a long rest.  So the way I read it you could cast misty step from the Manifest Mind space, the problem is that it can be up to 300ft away from the wizard's position, allowing me to misty step up to 330ft. Is this right?
Can you teleport farther away with misty step if you have a double from Invoke Duplicity? The Channel Divinity feature says:     you can cast spells as though you were in the illusion's space, but   you must use your own senses. (PHB 63)   If you were where your duplicate is, you could step to a space 30ft from its position. So if it is 60ft from you, you could teleport to a space 90ft from your actual position. But the spell says that:     you teleport up to 30 feet (PHB 260)   This would put a hard limit on the distance you can travel.  Which rule takes precedence here?
Could not make temporary scratch layer permanent I want to make a temporary scratch layer permanent but it shows  Could not make temporary scratch layer permanent. Error: Creation of field addr:street_1 failed (OGR error: Can't create field addr_str_4 in Shape DBF file, reason unknown.) How can I fix this error?  This is my attribute table. Lasso regression feature selection I have been reading many articles on LASSO regression, and everyone claims that LASSO address multicollinearity showing contour plots of cost function touching the corner of the diamond(x1+x2). In the first place, I didn't understand how does this phenomenon translate to addressing multicollinearity when there are many groups of correlated variables in the data.  Verbatim from one of the research paper: "• If there are grouped variables (highly correlated between each other) LASSO tends to select one variable from each group ignoring the others". How to connect to remote X-Server (logged in via ssh) When I'm logged on to another host (e.g via ssh), how do I connect to the XServer of that machine (same user is logged in and is running a desktop (gnome))?  You may ask way I wish to do that: There are commands that don't open an X-Window, e.g. xinput, xhost, etc.. and there are situations where you want to run them from remote. With Unix script, I'd like to add values in column 1 if text in column 2 is the same and print the sum.  I have a file that is:    7 GeneA 2 GeneB 6 GeneC 2 GeneB 9 GeneA   I want the output to look like:   16 GeneA 4  GeneB 6  GeneC   Thanks Creating a query that uses criteria from two tables? indicates that the water pipes should bonded to the electrical ground even if a grounding rod is used. How would one normally tell if that is the case? Is that bonding required to be accessible, or can it be hidden behind walls or buried? Where in the water system would it normally be bonded (e.g., before the main water shutoff, after, at the hot water tank)?  I recently had my electrical panel relocated and replaced, and don't recall seeing anything running from the panel to a water pipe - in the old panel or new. The electrician put in an intersystem bonding bridge, so the new ground rod, ground from the panel, and ground from the cable service are connected to it. I suppose that's where the bond from the water pipe would go? How do I send a file as an email attachment using Linux command line? For example, you're doing a research for a car to purchase. You get a list of cars with engine number, city where a car was assembled, and a color. What's missing is make, model and price. Upper bound for $\sqrt[n]{n!}$ if the curvature is constant and positive, then it is on the circunference I'm trying to prove that if $\alpha(t)=(x(t),y(t))$ is a $C^2$ regular curve $(\alpha'\neq0)$ with constant and positive curvature, then $\alpha$ is on the circunference and if $\alpha$ is the circunference, then its curvature is constant.  I solved the second part since $\alpha$ is the circunference, then $\alpha(t)=(r\cos\theta,r\sin\theta)$, so $|\alpha'(t)|=r$, I need help in the first part.  Thanks a lot. Where can I find sugar cane? I played several hours a started three different worlds in Minecraft, but I have never found any sugar canes. I read on Minecraft wiki to search near water but still no luck. Do you have more hints? Is it possible to re-create an environment that allow sugar canes to naturally grow? How can I break an align environment for a paragraph? I would like to have two displayed equations, broken by a short paragraph, but with aligned equal signs (as if using the align environment).  Is there some way to "break" the align environment temporarily? I know from reading about the gravitational waves detected by Ligo, that when an object has angular acceleration, it produces gravitational waves.  I'm wondering if an object creates gravitational waves when only accelerating in one direction, however?   I'm also curious as to how the nature of the waves would differ in this case. Can you transfer a Windows 7 XP-mode VHD to a new PC without the need for reactivation? At the moment I am running Vista 32 bit and use VPC 2007 a lot. I have several Windows 2000 Virtual Machines set up with complex software configurations. For me, one of the advantages of working with VPCs is that a Virtual Machine can easily be copied to another PC (like a notebook). Also, when I move to a new PC, I can immediately work with my existing Virtual Machines without the need to reinstall all applications.   I am thinking about buying a new pc with Windows 7 64 bit pro, and using the XP-Mode Virtual Machine that comes with Windows 7. The advantages would be support for more memory (so being able to run more Virtual Machines simultaneously) and having a licenced XP Virtual Machine.  I would like to know if you can transfer a VHD that is based on the XP-mode VHD to another machine without Activation issues. The other machine will of course, also be running Windows 7. I would guess that this would not be a problem.   However, I did read about a guy who had to reinstall his Windows 7 because of a harddisk failure, and could not access his XP-mode VHD anymore because it demanded re-activation.  So can you transfer a Windows 7 XP-mode VHD to a new PC without the need for reactivation? How do I recover my Google account (or Gmail) password or username? How can I String.Format a TimeSpan object with a custom format in .NET? What is the recommended way of formatting TimeSpan objects into  a string with a custom format? Why use hex? Hey! I was looking at this code at   I noticed that in some situations they used hex numbers, like in line 134:  for (j = 1; val &amp;&amp; j &lt;= 0x80; j &lt;&lt;= 1, q++)   Now why would they use the 0x80? I am not that good with hex but I found an online hex to decimal and it gave me 128 for 0x80.  Also before line 134, on line 114 they have this:  small_n = (n &amp; 0xffff0000) == 0;   The hex to decimal gave me 4294901760 for that hex number. So here in this line they are making a bit AND and comparing the result to 0??  Why not just use the number? Can anyone please explain and please do give examples of other situations.  Also I have seen large lines of code where it's just hex numbers and never really understood why :( So, I know that $\max(-X_{(1)},X_{(n)})$ is a sufficient statistic for the parameter $\theta$. But can I also say that $(X_{(1)},X_{(n)})$ are jointly sufficient for the parameter $\theta$ ?  In other words, can a single parameter have jointly sufficient statistics? Supersymmetry in Quantum Field Theory I have an idea of supersymmetry in quantum mechanics, can you suggest a book on "supersymmetry in quantum field theory", which has sufficient mathematical rigour like "Peskin and Schroeder" What kind of noun is 'picture'? I'm not sure of the right place to ask this, but I got confused trying to understand how the computer will interpret the sentence:     This is my picture.   In actual sense, the real owner of the picture should be the photographer not the person who was photographed... or am I getting something wrong? So, it seems the confusing thing about 'picture' is determining who the real owner of the picture is. So is there a special category for these kind of nouns or an official clarification somewhere?  Thanks