Suppose you take a large arbitrary positive electric charge $Q$. Then, given a distance $r$, we can calculate the escape velocity $v$ necessary for an electron to escape the positive charge (just like a rocket trying to escape Earth's gravity).   Could this escape velocity be equal or greater to $c$? Would this create a space from which no negative charge can escape? A sort of "black hole" for negatively charged particles? Does this mean no positively charged particle could enter this space? Is this a sort of "white hole" for positively charged particles? Suppose that you "free" one of the positive charges inside. The electric force would obviously repel it incredibly strongly. I seem to remember something about that the speed of particles falling into a black hole approaches the speed of light. Would a positive particle escaping from our "white hole" appear to be moving at the speed of light, at the event horizon?   I tried to make some back-of-the-envelope calculations, but without taking relativity into consideration I don't really trust the results.
So I was thinking about something for the past while  Consider a large spherical foam-ball with homogeneous density. Where a foam ball is defined as an object that can absorb matter with 0 friction (example: a gravitational well without an object inside). This is a purely theoretical construct.  If the foam-ball has a radius R and a charge Q. What charge must the foam-ball have, such that there is well defined sphere or horizon such that any object with a negative charge (even if it is the slightest bit) must travel faster than C in order to escape the field of the ball.  Aka what charge would turn this into a black-hole for all objects with opposite sign on their charge?  Once again I assume the foam-ball is a single particle, that doesn't repel itself... its just a very large homogenous 'thing' with charge.
Send authors an inbox message if their question is closed Let $p&gt;3$ be a prime. Prove that $24 \mid p^2-1$.   I know this is very basic and old hat to many, but I love this question and I am interested in seeing whether there are any proofs beyond the two I already know. I have installed Ubuntu on my laptop and now I want to remove it and the Grub Loader. How I can do it without the Windows installation disk (I cannot use the Recovery Console). Highlight elements in the matrix I have a matrix and need to highlight some elements in the matrix. I have found how to highlight a single element (I want to put the cell in the square):  $$ A = \begin{bmatrix} \fbox{0} &amp; \fbox{0} &amp; 0 \\  \fbox{0} &amp; \fbox{0} &amp; 0 \\ 1 &amp; 1 &amp; 1 \\  \end{bmatrix}$$   But how can I outline elements of the submatrix like in the picture below? I need just a frame where some elements are located. How to get only filename using sed How can I get only the filename using sed? I've this  out_file=$(echo $in_file|sed "s/\(.*\.\).*/\1mp4/g")   But I get the path too /root/video.mp4, and I want only video.mp4. I have noticed that guest quarters on the Enterprise D have fruit bowls on their tables.  A prominent instance is the fruit bowl in Berlinghoff Rasmussen's quarters in "".  The first thing that Rasmussen does when Data takes him to his guest quarters is take a piece of fruit and shove it in his pocket.  Who replicates fruit for these fruit bowls before guests arrive?  More generally, who removes unused fruit and tidies quarters after guests leave?  Is there a ship hospitality staff, perhaps including Guinan's wait staff in Ten Forward? How do I split a forest tree into two trees with proper vertical alignment? \documentclass[oneside,12pt]{article} \usepackage{geometry} \usepackage{microtype} \usepackage[utf8]{inputenc} \usepackage[T1]{fontenc} \usepackage{lmodern}  \usepackage{enumitem} \setlist[enumerate,1]{label=\bfseries\Alph*,align=left,leftmargin=*,   labelsep=1.5em} \setlist[enumerate,2]{label=\arabic*.,labelindent=1em,labelsep=1.5em,   leftmargin=*}  \usepackage{amssymb} \usepackage{amsmath} \usepackage{amsthm} \theoremstyle{definition} \newtheorem*{sol}{Solution}  \usepackage{forest} \forestset{   ass/.append style={     before computing xy={l=\baselineskip},     no edge   },   prooftree/.style={     for tree={       child anchor=north,       parent anchor=south     }   } }  \begin{document} \subsection*{Exercises 29} \begin{enumerate} \item Use QL trees to evaluate the entailment claims (1) to (10) in Exercises   28A.   \begin{enumerate}   \item $\forall x(Fx\supset Gx)\vDash\forall x(Gx\supset Fx)$      \begin{forest}       prooftree       [$\forall x(Fx\supset Gx)$       [$\neg\forall x(Gx\supset Fx)\checkmark$,ass       [$\exists x\neg(Gx\supset Fx)\checkmark$,ass       [$\neg(Ga\supset Fa)\checkmark$,ass       [$Ga$,ass       [$\neg Fa$,ass       [$(Fa\supset Ga)\checkmark$,ass       [$\neg Fa$] [$Ga$]]]]]]]]     \end{forest}      $\neg Fa$ and $Ga$ make the premisses and the negation of conclusion true.     Thus, the entailment is invalid.   \item $\forall x(Fx\supset Gx)\vDash\forall x(\neg Gx\supset\neg Fx)$      \begin{forest}       prooftree       [$\forall x(Fx\supset Gx)$       [$\neg\forall x(\neg Gx\supset\neg Fx)\checkmark$,ass       [$\exists x\neg(\neg Gx\supset\neg Fx)\checkmark$,ass       [$\neg(\neg Ga\supset\neg Fa)\checkmark$,ass       [$\neg Ga$,ass       [$\neg\neg Fa$,ass       [$(Fa\supset Ga)\checkmark$,ass       [$\neg Fa$ [*,ass]] [$Ga$ [*,ass]]]]]]]]]     \end{forest}      Since the tree closes, the entailment is valid.   \item $\forall x\exists yLxy\vDash\forall y\exists xLyx$      \begin{forest}       prooftree       [$\forall x\exists yLxy$       [$\neg\forall y\exists xLyx\checkmark$,ass       [$\exists y\neg\exists xLyx\checkmark$,ass       [$\neg\exists xLax\checkmark$,ass       [$\forall x\neg Lax$,ass       [$\exists yLay\checkmark$,ass       [$Lab$,ass]]]]]]]     \end{forest}      \begin{forest}       prooftree       [$\neg Lab$,ass [*,ass]]     \end{forest}   \item $\forall x((Fx\wedge Gx)\supset Hx)\vDash\forall     x(Fx\supset(Gx\supset Hx))$   \item $(\forall xFx\vee\forall xGx)\vDash\forall(Fx\vee Gx)$   \item $\forall x(Fx\supset Gx),\forall x(\neg Gx\supset Hx)\vDash     \forall x(Fx\supset\neg Hx)$   \item $\exists x(Fx\wedge Gx),\forall x(\neg Hx\supset\neg Gx)\vDash     \exists x(Fx\wedge Hx)$   \item $\forall x\exists y(Fy\supset Gx)\vDash\forall y\exists x(Gx\supset     Fy)$   \item $\forall x\forall y(Lxy\supset Lyx)\vDash\forall xLxx$   \item $\forall x(\exists yLxy\supset\forall zLzx)\vDash\forall x\forall y     (Lxy\supset Lyx)$   \end{enumerate} \end{enumerate} \end{document}   Usually, I have to manually split a forest tree into two to emulate page breaking in a forest tree. However, the second tree doesn't vertically align with the first as in the picture below. How can I vertically align them together? @cfr Cannot replace a packed image in the uv image editor I was trying to replace an image in my UV image editor, but the image defaults to a different image. how do I fix this? What is the difference between 32-bit and 64-bit Ubuntu? I've heard the 64-bit platform performs better and can detect more than 4GB of RAM. Also, while some apps haven't ported to 64-bit yet, ia32-libs lets a 64-bit machine run them.  If so, why not promote 64-bit over 32-bit? Why should I use a private variable in a property accessor? Generating values from a multivariate Gaussian distribution I am currently trying to simulate values of a $N$-dimensional random variable $X$ that has a multivariate normal distribution with mean vector $\mu = (\mu_1,...,\mu_N)^T$ and covariance matrix $S$.  I am hoping to use a procedure similar to the inverse CDF method, meaning that I want to first generate a $N$-dimensional uniform random variable $U$ and then plug that into the inverse CDF of this distribution, so to generate value $X$.  I am having issues because the procedure is not well documented and there are slight differences between the  and a .  In my case, I am also choosing the parameters of the distribution randomly. In particular, I generate each of the means, $\mu_i$, from a uniform distribution $U(20,40)$. I then build the covariance matrix $S$ using the following procedure:   Create a lower triangular matrix $L$ where $L(i,i) = 1$ for $i=1..N$ and $L(i,j)  = U(-1,1)$ for  $i &lt; j$ Let $S = LL^T$ where $L^T$ denotes the transpose of $L$.   This procedure allows me to ensure that $S$ is symmetric and positive definite. It also provides a lower triangular matrix $L$ so that $S = LL^T$, which I believe is required to generate values from the distribution.  Using the guidelines on Wikipedia, I should be able to generate values of $X$ using a $N$-dimensional uniform as follows:   $X = \mu + L * \Phi^{-1}(U)$   According to the MATLAB function however, this is typically done as:   $X = \mu + L^T * \Phi^{-1}(U)$   Where $\Phi^{-1}$ is the inverse CDF of a $N$-dimensional, separable, normal distribution, and the only difference between both methods is simply whether to use $L$ or $L^T$.  Is MATLAB or Wikipedia the way to go? Or are both wrong? Regarding ,  it is not possible to combine complex powers in the usual way:  $$ (x^y)^z = x^{yz} $$  There was mention of multi-valued functions, is there some theory that makes this all work out correctly? If $A$ an integral domain contains a field $K$ and $A$ over $K$ is a finite-dimensional vector space, then $A$ is a field. User deleting code after question has been answered If a user keeps  (thus making the answer meaningless), what should we do? Rollback the edit (what if the user just deletes the code again)? Delete the question?  More examples (same user): ,  (see also edit histories). Why don't we consider centrifugal force on a mass placed on earth? Let us say a block of mass is placed on the surface of earth. Then while drawing the forces on that body, we say:   Force $F = mg$ acting towards the center of Earth. Normal reaction $N$ offered by the surface of Earth.   If no other forces are acting, we say $F=N$. But what about the centrifugal force $m\omega^2R$ . Why don't we ever bring that into picture? What am I missing? Are there massless bosons at scales above electroweak scale? Spontaneous electroweak symmetry breaking (i.e. $SU(2)\times U(1)\to U(1)_{em}$ ) is at scale about 100 Gev. So, for , gauge bosons $Z$ &amp; $W$ have masses about 100 GeV. But before this spontaneous symmetry breaking ( i.e. Energy > 100 GeV) the symmetry $SU(2)\times U(1)$ is not broken, and therefore gauge bosons are massless.  The same thing happens when we go around energy about $10^{16}$ GeV, where we have the Grand Unification between electroweak and strong interactions, in some bigger group ($SU(5)$, $SO(10)$ or others). So theoretically we should find gauge bosons $X$ and $Y$ with masses about $10^{16}$ GeV after GUT symmetry breaks into the Standard Model gauge group $SU(3)\times SU(2)\times U(1)$, and we should find massless X and Y bosons at bigger energies (where GUT isn't broken).  So this is what happened in the early universe: when temperature decreased, spontaneous symmetry breaking happened and firstly $X$ &amp; $Y$ gauge bosons obtained mass and finally $Z$ &amp; $W$ bosons obtained mass.   Now, I ask: have I understood this correctly? In other words, if we make experiments at energy above the electroweak scale (100 GeV) we are where $SU(2)\times U(1)$ isn't broken and then we should (experimentally) find $SU(2)$ and $U(1)$ massless gauge bosons, i.e. $W^1$, $W^2$, $W^3$ and $B$ with zero mass? But this is strange, because if I remember well in LHC we have just make experiments at energy about 1 TeV, but we haven't discovered any massless gauge bosons. Why can't a single photon produce an electron-positron pair? In reading through old course material, I found the assignment (my translation):     Show that a single photon cannot produce an electron-positron pair, but needs additional matter or light quanta.   My idea was to calculate the wavelength required to contain the required energy ($1.02$ MeV), which turned out to be $1.2\times 10^{-3}$ nm, but I don't know about any minimum wavelength of electromagnetic waves. I can't motivate it with the conservation laws for momentum or energy either.  How to solve this task? How to obtain optimal hyperparameters after nested cross validation? Directory size calculation difference I need to get the size of directory in terminal for signing purposes. I'm using following command:  du -s /path/to/dir   I'm multiplying the result by traditional UNIX block size (512 bytes) and get actual directory size in bytes. However, the Finder's "Get Info" dialog window shows the size slightly smaller than the one calculated with the terminal command. And it seems that it's reproducible on any folder/bundle. What am I missing? So what I'm looking for here is something like PHP's  function.  This is so I can debug my scripts by seeing what's the state of the object in question.