I have gone around and around trying to reset my password.  I have repeatedly gone through the reset stages and I never get the email from you to reset my password.  over and over I wait for your response and I never get it.  I have the same email address and cannot remember my password  everything else is still the same   still I do not ever receive the password reset   I get nothing from you bmarrs@bcmvco.net
I have forgotten the password or username for my Google account, or I'm unable to access my account for other reasons.  How can I recover my account?  (This Q&amp;A is meant as a general description for all Google and Gmail username/password questions. See: )
Evaluate $\int_{\gamma} \frac{ |dz| }{z} $ where $\gamma $ is the unit circle I need to evaluate $\int_{\gamma} \frac{ |dz| }{z} $ where $\gamma $ is the unit circle.    Attempt: Let $\gamma(t) = e^{it} $ where $t \in [0,2 \pi]$. How can I get rid of the absolute values in the differential? Let $A$ , $B$ be topological spaces such that there for some subset $D$ of $B$ there is a homeomorphism form $A$ to $D$ and for some subset $E$ of $A$ there is a homeomorphism form $B$ to $E$ ; then must there exist a homeomorphism from $A$ to $B$ ? A tool to measure signal strength of wireless I want to know if there exists any command line option or GUI tool (Ubuntu 11.10) so that I can measure the strength of wireless signal at a given location. I have a house where the wireless is not easily accessible at all corners I want to know at which corners or rooms the signal is weak. An  is defined as $p = q\times d$ (for two point charges $\pm q$ separated by a distance $d$).    What is the physical meaning of this quantity?  Why does the direction of the electric dipole moment go from the negative charge to the positive charge? Another way of saying this, why electric dipole moment is a vector quantity? how to disable system apps without root? How to disable system apps without root?  My phone model is vivo x5 max+ and android 4.4.4  I have tried Debloater but it failed to connect (I am sure I've allowed USB debugging). Is there a way to substring a string in Python, to get a new string from the third character to the end of the string?  Maybe like myString[2:end]?  If leaving the second part means 'till the end', and if you leave the first part, does it start from the start? Shorter proof for some equvalences Let $(G,\cdot)$ be a group show that  A) $G$ is abelian  B) For all $x,y\in G: (xy)^{-1}=x^{-1}y^{-1}$  C) For all $x,y\in G: (xy)^{2}=x^{2}y^{2}$  D) There existst an $n\in \mathbb{Z}$ such that for all $x,y\in G$  $\displaystyle (xy)^{n-1}=x^{n-1}y^{n-1}$ and $\displaystyle (xy)^{n}=x^{n}y^{n}$ and $\displaystyle (xy)^{n+1}=x^{n+1}y^{n+1}$  are equivalent.    I showed $A\iff B,A\iff C$ and $A\iff D$. That was not really hard, except maybe $D\Rightarrow A$. I would like to do a circular argument, but i have no idea how.  Any hints?  Thanks in advance! The phrase "let alone" I notice that "let alone" is used in sentences that have a comma. The structure of the sentence is what comes before the comma is some kind of negative statement. Right after the comma is "let alone," followed by the rest of the sentence.  What does "let alone" mean here? Does it mean the same thing as "or even?" Can someone explain this phrase and sentences that have it? Suppose $G$ is a semigroup and it holds both left and right cancellation. Suppose $G$ is a semigroup and it holds both left and right cancellation. Also for each $a,b\in G$, $xa=b$ has solution in $G$. Prove G is a group.   I know this question looks very "old" style. First I think it's easy for me too since I already practice probelems like "semigroup, $xa=b$ and $ax=b$ have solution , then group" Or "finite semigroup, both left and right cancellation hold, then group ". But I still get stuck... My try:  First of course, for $xa=a$ , there exists $e_a$ such that $e_aa=a$. Now we need to proof $e_a$ is left identity for all elements. Then left inverse exists hence $G$ is a group. But the key is to proof $e_ab=b$ for all $b\in G$. Real world uses of hyperbolic trigonometric functions I covered hyperbolic trigonometric functions in a recent maths course. However I was never presented with any reasons as to why (or even if) they are useful.  Is there any good examples of their uses outside academia? Starcraft Installation asks for a mythical Disk 2 I just purchased the Starcraft Battle Chest containing Starcraft and BroodWar.  When I try to install Starcraft I get halfway through and I'm prompted to "Insert Disk 2".  The box did not contain a second disk.  My computer is Windows 7 (x64). What do I need to do to continue?  Box Contents:   Starcraft Disk Broodwar Disk WoW Trial Disk I have a conjecture that any two positive coprime integers $a$ and $b$ can be added to form any integer greater than or equal to $(a-1)(b-1)$.   This is true for $3$ and $5$, which can form any integer greater than or equal to $8$, where $8=3+5, 9=3+3+3, 10=5+5; k=3n+8$ or $3n+9$ or $3n+10$.  It is true for $4$ and $7$, which can form any integer greater than or equal to $18$, where $18=4+7+7, 19=4+4+4+7, 20=4+4+4+4+4, 21=7+7+7$, etc. How can it be proven that this will work for any two coprime numbers? Can I configure Ubuntu to never install a specific package even if it is required by another package I install? How to install VirtualBox from command line? I am a newbie. For some reasons, I need to install Virtualbox. I see that I can easily install it using the Software Center, but I trust most the apt-get install way, because I find it safer, less buggy, and it helps me accommodate more with the Terminal.  So, my question is the following: is there a way to install VirtualBox using the command line? I would prefer something easy, like apt-get install not unzipping, archiving, etc, because I still don't know how to do these in the Terminal. Answers no longer sorted by score/votes Find the last two digits of $9^{{9}^{9}}$ I have to find the last two decimal digits of the number $9^{{9}^{9}}$.  That's what I did:  $$m=100 , \phi(m)=40, a=9$$ $$(100,9)=1, \text{ so from Euler's theorem,we have :} 9^{40} \equiv 1 \pmod{100}$$  $$9^{{9}^{9}} \equiv 9^{9^{2+2+2+2+1}} \equiv 9^{9^2 \cdot 9^2 \cdot 9^2 \cdot 9^2 \cdot 9} \equiv 9^{81 \cdot 81 \cdot 81 \cdot 81 \cdot 9} \equiv 9^{(40+40+1) \cdot (40+40+1) \cdot (40+40+1) \cdot (40+40+1) \cdot 9} \equiv (9^{(40+40+1)})^{(40+40+1) \cdot (40+40+1) \cdot (40+40+1) \cdot 9} \equiv 9^9 \equiv 9^4 \cdot 9^4 \cdot 9 \equiv 6561 \cdot 6561 \cdot 9 \equiv 3721 \cdot 9 \\ \equiv 21 \cdot 9 \equiv 89 \pmod{100}$$  So,the last two digits are $8 \text{ and } 9$. $$$$But,is there also an other way two calculate the last two digits of $9^{{9}^{9}}$ or is the above the only one? How does gravity work on Star Wars ships? Inspired by the question , how does gravity work on the Millennium Falcon and other ships its size? The passengers are not strapped in and regularly move around just easily as they would on a planet with Earth's gravity.   The answer for the Death Star refers to gravity often being "coreward" (presumably taking advantage of the natural gravity an object of such substantial mass would have), but that doesn't apply for a small ship. So how is gravity accomplished? Limit at infinity of $x^{1/x}$ I encountered a problem: calculate $\lim\limits_{x\to\infty} x^{1/x}$  My solution is quite weird and I find no document explaining whether I am right or wrong!  My solution:  As $\lim\limits_{x\to\infty} 1/x = 0$  then $\lim\limits_{x\to\infty} x^{1/x} = \lim\limits_{x\to\infty} x^0  = 1$  My question is: Whether I am right or wrong, and could you please explain why? Two list-boxes, side by side, one with available items, the other with selected items, with arrows in between to move items back and forth. In case of a syntax error, pdflatex usually (in \errorstopmode) gets interactive and asks you what to do. I know I can press:   X to terminate S to enter \scrollmode (continue processing without stopping if further syntax errors arise, but stop for other errors) R to enter \nonstopmode (continue processing without stopping if further errors arise) Q to enter \batchmode (continue processing without stopping if further errors arise and suppress further output to the terminal)   Apparently, only the latter three (SRQ) can be provided implicitly by the respecive \...mode commands or the -interaction=...mode command line option. However, what I need is a mode that mimics the implicit pressing of X, that is, to make the pdflatex process terminate after the first error.