While using the command "sed" for find and replace, I wanted to know how one could find a constant and replace it with a variable inside the quotation syntax of sed?  I wanted to replace constant 3 with variable name "hourid" Here is what I tried.  sed -i 's@3@hourid$@g' file_name.txt   I want to know how to provide a right syntax for replacing variable "hourid"
I want to do:  cat update_via_sed.sh | sed 's/old_name/new_name/' &gt; new_update_via_sed.sh   in my program.  But I want to use variables, e.g.  old_run='old_name_952' new_run='old_name_953'   I have tried using them but the substitution doesn't happen (no error). I have tried:  cat update_via_sed.sh | sed 's/old_run/new_run/' cat update_via_sed.sh | sed 's/$old_run/$new_run/' cat update_via_sed.sh | sed 's/${old_run}/${new_run}/'
Legality of using names in a game? How can I have one keyboard input layout and multiples languages in Ubuntu 17.10? If I have English language I can't type "'e" and get an "é", as I can do in Portuguese and Spanish.  When I manage to do that on Settings -> Region &amp; Language, I'm able to change languages, but it also changes the keyboard layout.  Is there any way to change language (Portuguese or Spanish for example) and set the keyboard input layout (US International for example)? CPT Template Not Showing - Getting 404 I'm developing a Custom Post Type plugin, which works fine in dev. Now that I've moved it to production, I'm getting a 404 when I try to display the template for the CPT.   So, two questions:  1- Is there some mechanism to determine the path WP took to get through the hierarchy?  2- Why wouldn't it just give me the single or index page?  I've dumped $wp_query and a stacktrace at the end of the 404. Here's part of what I found:  [query] =&gt; Array     (         [page] =&gt;          [pagename] =&gt; refletters/proximity     )  [request] =&gt; SELECT   wp_posts.* FROM wp_posts  WHERE 1=1  AND (wp_posts.ID = '0') AND wp_posts.post_type = 'page'  ORDER BY wp_posts.post_date DESC  [posts] =&gt; Array     (     )  [queried_object] =&gt;  [queried_object_id] =&gt; 0   And the stack trace:  2013-04-27 22:16:41 - 24.52.197.40 - TRACE - index.php - 404.php[39] -      wordpress/wp-content/themes/notoriousconsultant/404.php[39] - aaLog-&gt;logtrace     wordpress/wp-includes/template-loader.php[50] - include     wordpress/wp-blog-header.php[16] - require_once     wordpress/index.php[17] - require   Thanks for your help. Why are there so many different ways to measure disk usage? Can I programmatically open the devtools from a Google Chrome extension? Are Windows file timestamps timezone aware? Is it because Rey just saved BB-8 from a net, and then the droid just decides to follow her about - or is it for some other reason?  Does BB-8 have any idea who Rey is prior to being rescued by her?  Just wondering as she literally tells the droid to go elsewhere. Is $\{0\}$ a field? Consider the set $F$ consisting of the single element $I$.  Define addition and multiplication such that $I+I=I$ and $I \times I=I$ .  This ring satisfies the field axioms:   Closure under addition.  If $x, y \in F$, then $x = y = I$, so $x + y = I + I = I \in F$. Closure under multiplication.  $x \times y = I \times I = I \in F$ Existence of additive identity.  $\forall x \in F$ (i.e., for $x=I$), $x + I = x$, so $I$ is the additive identity. Existence of mulitiplicative identity. $\forall x \in F, x \times I = x$, so $I$ is the multiplicative identity. Additive inverse. $\forall x \in F, \exists y = I \in F: x + y = I$ Multiplicative inverse. $\forall x \in F, \exists y = I \in F: x \times y = I$.  However, because the additive identity need not have a multiplicative inverse, this is a vacuous truth. Commutativity of addition.  $\forall x, y \in F, x + y = I = y + x$ Commutativity of multiplication.  $\forall x, y \in F, x \times y = I = y \times x$ Associativity of addition.  $\forall x, y, z \in F$, $(x + y) + z = I + I = I$ and $x + (y + z) = I + I = I$, so $(x + y) + z = x + (y + z)$ Associativity of multiplication.  $\forall x, y, z \in F$, $(x \times y) \times z = I \times I = I$ and $x \times (y \times z) = I \times I = I$, so $(x \times y) \times z = x \times (y \times z)$ Distributivity of multiplication over addition. $I \times (I + I) = I$ and $I \times I + I \times I = I$, so $\forall x,y,z \in F, x(y+z) = xy+xz$   Based on the above, $\{I\}$ seems to qualify as a field.  If $I$ is assumed to be a real number, then the unique solution of $I + I = I$ and $I \times I = I$ is, of course, $I = 0$.  So, is {0} a field, or is there generally considered to be an additional field axiom which would exclude it?  Specifically, is it required for the multiplicative identity to be distinct from the additive identity? How can I design a tree graph with node shapes as this photo? Shouldn't this be a pretty straightforward operation? However, I see there's neither a size() nor length() method. Is there a term for words that when reversed, form other words? I'm aware of what a palindrome is. What do you call words that, when reversed, form other words, such as ton (not) and part (trap)? Objective C const NSString * vs NSString * const Why do modern mountain bike forks no longer use boots on fork stanchions? Why do modern mountain bike forks no longer use boots on fork stanchions? Older mountain bikes used to have them on the forks, and lefty and headshocks still do. Why have these fallen out of fashion and would putting aftermarket fork boots on your stanchions be productive or not? Nonlinear function continuous but not bounded I would like an example of a map $f:H\rightarrow R$, where $H$ is a (infinite dimensional) Hilbert space, and $R$ is the real numbers, such that $f$ is continuous, but $f$ is not bounded on the close unit ball $\{ x\in H : \|x\| \leq 1\}$.  Actually, $H$ could be replaced by any Banach space (but not just a normed space-- that's too easy).  My motivation is that if $f$ is linear, this is impossible; but I have next to no intuition about non-linear functions.  Edit: Here's an example for $c_0$ which is even differentiable (disclaimer: I found it here: ).  Define $f:c_0\rightarrow F$ (where F is your field, real or complex) by $$ f(x) = \sum_{n=1}^\infty x_n^n \qquad (x=(x_n)). $$  You can estimate the sum by a geometric progression, so it does converge.  A bit of checking shows that f is Frechet differentible (so certainly continuous).  But $f(1,1,\cdots,1,0,\cdots)=n$ (if there are $n$ ones) so $f$ is not bounded on the closed unit ball.  What I don't immediately see is how to adapt this to $\ell^2$, say. Grub rescue prompt, repair grub Under what conditions will healers switch targets? I've been using healers lately, which I haven't really utilized much before. I've noticed that they will sometimes switch targets, even when their original target still lives.   What conditions are needed for healers to switch targets? Importing QGIS3 processing tools in standalone script Inspired by , but for QGIS 3 (and therefore Python 3), I would like to use the QGIS processing algorithms in a standalone Python script without a GUI, with a standard installation of Ubuntu Linux. A simple import processing is insufficient: import processing processing.run(    &quot;qgis:rasterlayerstatistics&quot;,    {        'INPUT': .'/somefile.tif',        'BAND': 1,        'OUTPUT_HTML_FILE': './result.html'    } )  Results in: Traceback (most recent call last):   File &quot;&lt;stdin&gt;&quot;, line 1, in &lt;module&gt; ModuleNotFoundError: No module named 'processing'  How do you get access to the QGIS processing module to use the QGIS processing algorithms in a standalone Python script (not the QGIS interpreter)? Rights if we possess Carta di Soggiorno? I have searched the internet but could not find specific information so if we have got the following document "Carta di Soggiorno di Familiare di Un Cittadino Dell'Unione" (Residence Card of a family member of a Union Citizen, Italy) issued by the Italian authority, what rights do we possess of working inside Italy and EU? What about travelling? Will we be requiring visas for the states which are are not in Schengen? MySQL Prepared statements with a variable size variable list How would you write a prepared MySQL statement in PHP that takes a differing number of arguments each time? An example such query is:  SELECT `age`, `name` FROM `people` WHERE id IN (12, 45, 65, 33)   The IN clause will have a different number of ids each time it is run.  I have two possible solutions in my mind but want to see if there is a better way.  Possible Solution 1 Make the statement accept 100 variables and fill the rest with dummy values guaranteed not to be in the table; make multiple calls for more than 100 values.  Possible Solution 2 Don't use a prepared statement; build and run the query checking stringently for possible injection attacks. As the topic is there exist a homeomorphism between either pair of $(0, 1),(0,1],[0,1]$