I am making this sauce, which is extremely hot (as in hot peppers) that is being served cold (as in temperature). People who try it ask me what it is, so I say it is "cold hot sauce", which is a bit problematic, as the two are literal antonyms, even if not in the particular context.  So is there another world I could use for (extremely) hot that makes it clear it is indeed very hot? "Spicy" comes to mind but it is a big understatement. Anything else?
I never know how to order food correctly but succinctly the first time. :(  Basically: I can't eat hot stuff (i.e. most pepper, similar spices, ...).  On the one hand, I don't want to say "Please don't make it spicy", because I really don't mind spice (heck, a lot of them are great!) -- I just don't want it to be hot spice.  On the other hand "Please don't make it hot" would seem to imply I'd like my food cold!  Possibilities I've considered:   "Please don't add hot spice" just sounds weird "Please don't add pepper" is the best I've thought of so far, but I'm pretty sure I've come across foods without pepper (or apparently so) which nevertheless tasted pretty hot. And not just that, but it would also exclude bell peppers, etc. which I don't mind much.   Any ideas for how to communicate this clearly? The fewer words the better, haha.
How do i convert a binary int into a string? Troubleshoot High CPU usage by the "System" process Why is polyploidy lethal for some organisms while for others is not? is the multiplication of number of chromosomal sets from 2n to 3n (triploidy), 4n (tetraploidy) and so on. It is quite common in plants, for example many crops like wheat or Brassica forms. It seems to be rarer in animals but still it is present among some amphibian species like Xenopus.  As I know in mammals polyploidy is lethal (I don't mean tissue - limited polyploidy). I understand that triploidy is harmful due to stronger influence of maternal or paternal epigenetic traits that cause abnormal development of placenta, but why there is no tetraploid mammals? If every pair of congruence equations admits solutions, then the entire system admits solutions Let a system of three linear congruence equations in integers be given;      \begin{cases}x\equiv b_1\mod c_1\\ x\equiv b_2\mod c_2\\ x\equiv b_3\mod c_3\\ \end{cases}   with $c_1,c_2,c_3\in\mathbb Z_{+}$. Show that, if every pair of congruence equations admits solutions, then the entire system admits solutions.    Now, if every pairs admits solutions, then for example $b_1\equiv b_2\equiv a\mod \gcd(c_1,c_2)$ for some $a$ then;   $x-a\equiv b_1-a\mod c_1$  $x-a\equiv b_2-a\mod c_2$  replacing $x$ by $x':=\frac{x-y}{\gcd(c_1,c_2)}$, we obtain:  $x'\equiv b_1'\mod c_1'$  $x'\equiv b_2'\mod c_2'$  and since $\gcd(c_1,c_2)=1$ by Chinese Remainder Theorem we have a unique solution $\mod{c_1'c_2'}$, so $x\equiv (\gcd(c_1,c_2)x'+a)\mod{\operatorname{lcm(c_1',c_2')}}\quad(1)$  We can do it with another pair (take $2$nd and $3$rd, since we know that such a pair admits solutions;  $x\equiv(\gcd(c_2,c_3)x''+a')\mod{\operatorname{lcm(c_2',c_3')}}\quad(2)$  Now how can I show that for the pair $(1)$ and $(2)$ also solutions exist ? Apparently, there are $\frac{(2n)!}{2^nn!}$ ways to break $2n$ people into partnerships. Why?   An explanation reads that there are $2n!$ ways to line people up. If we just pair adjacent people in the line up, we would have overcounted. So we must divide by $2^n n!$.  My question is why do we divide by $2^n n!$ specifically to adjust for overcounting?  Furthermore, this problem can apparently be solved by taking a skip factorial of odd values:  $(2n-1)(2n-3)(2n-5) ... (5)(3)(1)$  Why is that so? What does this skip factorial have to do with the problem? Does lower resolution result in better signal-to-noise ratio, given the same sensor size? With the release of the Canon EOS R5/R6, there have been many saying that they prefer the 20MP R6 camera over the 45MP R5 camera, due to its lower price but also because of &quot;better low-light performance.&quot; In camera comparison sites, I've also seen the sentiment that bigger pixels (lower resolution) = better low light performance. However, is this a myth? Here is my reasoning for this. Let's say that there are two full-frame sensors, one 20MP sensor and a 80MP sensor. According to many people, the 80MP sensor would be terrible for low-light photography since the pixels are smaller. However, each 2x2 block in the 80MP sensor could be mapped, and in post averaged to a 1x1 pixel, effectively making the image into a 20MP image. This could also be done in-camera as an option. Would this image have just the same amount of usable information as the image from the 20MP sensor? In other terms, since both sensors are 35mm sensors (i.e. equal area), the amount of light falling onto the sensor is the same. So, at the end of the day, there will be no difference between a 20MP image and a 20MP image that has been downsampled from 80MP, right? So their low-light performance would be the same. You even get an advantage from having the option to get 80MP photos if you wanted. Why do people say that a lower-resolution camera has better low-light performance, when it should theoretically be the same as one with higher resolution (all other factors equal)? Note: this question is about sensors with the same size but with different pixel density. Hence, it is different from  asking about different sensor sizes. I am aware that a full-frame camera will have better low-light signal due to its bigger area than an APS-C sensor, but what about the similarly sized sensors? Restore console session after remote desktop disconnects? I understand that information cannot be transmitted at a velocity greater than speed of light. I think of this in terms of the radio broadcast: the station sends out carrier frequencies $\omega_c$ but the actual content is carried in the modulated wave, the sidebands $\omega_c\pm\omega_m$. The modulation envelop has its group velocity and this is the speed at which information is being transmitted. We also know, for example, that x-rays in glass have a phase velocity which is greater than the speed of light in vacuum.   My question is, what exactly is it that is travelling faster than the speed of light?    EDIT: I know it couldn't be anything physical as its superluminal. My problem is, what is it that has absolutely no information content yet we associate a velocity with it. Numpy installation? I used VIRTUALBOX to install Ubuntu 12.04 on my windows pc. I used apt-get to install Python 2.7 that shipped with 12.04. I followed the directives I saw on this site to install Numpy, Scipy, Matplot all failed. I download tar source file of these modules. How do I install them manually? Someone pls help, I'm getting frustrated. Free, open-source substitutes for Mendeley? Pass by Reference / Value in C++ i would like to know how to prove that if $a^2+b^2=c^2$ then   a) $3|a$ or $3|b$  b) $5|a$ or $5|b$ or $5|c$  c) $4|a$ or $4|b$   Also that $a^2+b^2+c^2+1$ can't be divisible by 8  Thank you very much! How can I download an older version of OS X/macOS? Sometimes it's hard to search for older versions of macOS &amp; OS X  on the App Store.  This is an attempt to provide the canonical QA for this issue, as per the Meta QA -  I expect it to be modified over time to hopefully become a complete information resource.  How can I get any older version of a Mac OS to be able to run as a VM, or to reinstall on my Mac? How to save/restore Sublime Text 2 configs/plugins to migrate to another computer? How do I set the proper exposure for nighttime moon photos? All my attempts to get a good shot of the full moon with my DSLR result in an overexposed circle on a black background.  I've tried using a tripod, remote shutter release, low ISO, and long exposure, but nothing has worked so far.  What combination of ISO and exposure time that will produce good results?   I particularly want to catch a full moon with the reddish effect when it is close to the horizon. I have already read the question about  but this is not what I want, I want to be able to click on the file in Dash or in Nautilus and be able to open it with the specified app.  For example I have this case right now:  When I click on an EXE file it does not get executed by Wine, instead I get the following:    If I try to look for Wine in the Open With context menu option it is there. I am fine executing it from there the first time, but then the following times Wine does not appears selected in the main Context menu:    I then went to Properties to the Open With Tab to look for Wine. It was not in the Default apps nor was it in the Recommended ones when I clicked and search on Show other applications    This is not limited to EXE extensions. It also has happened with MKV files, MP4 files, JPG, PNG, MP3 and even SVG and CSS. So instead of trying to find a way of solving it for one, I want a way that can be done to any type of extension that can:   Make the app the default of that extension Appear on the context menu in Nautilus when I right click on the file Appears on the "Open With" tab on the Property window of the file Correctly executes the specified app when I click on the file with Dash   This might sound like it should be common sense for an app to execute the file but it does not always work like that. So for the cases where it actually does not work, how to fix it. A reset of the extension?, An update of the files that can open said extension?, an addition of the app via a command line or GUI tool? Switching OS remotely using TeamViewer I have a dual boot system with Ubuntu 16.04 and Windows 7. Windows 7 is automatically booted (default in the bootloader). On both OS I have TeamViewer installed.  When I'm working remotely and want to switch to Ubuntu I have to reboot the PC but then automatically Windows is booted again (I'm not in front of the PC, so I cannot use the bootloader). How can I in such a case switch to Ubuntu, i.e. starting Ubuntu? And how can I switch back to Windows? I am on Ubuntu and I did this command:  $ uname -a Linux slabrams-desktop 2.6.32-29-generic #58-Ubuntu SMP Fri Feb 11 19:00:09 UTC 2011 i686 GNU/Linux   Does it mean I am on 32bit or 64 bit processor?  The reason I am trying to figure this out is that I was getting errors which looked like this:  cannot execute binary file   and from Googling, I thought it was a processor issue.  Any ideas? Pointwise limit of continuous functions not Riemann integrable Can you negate the Frightened condition by not looking at the source of your fear? As the title says, if you cause a creature to be Frightened of you, as in the Frightened condition, but they can somehow manage to not see you, do they stop rolling with disadvantage to attacks/ability checks?  Below are scenarios to illustrate my question.  Scenarios:   If a creature is frightened of you, and they turn their back against you to hit someone else, would they no longer have disadvantage to attack rolls/ability checks? If a creature is frightened of you and they have Blindsight, can they close their eyes to stop seeing you, and hence stop rolling with disadvantage? If a creature has 60 ft of movement and is frightened of you, and there is a corner they can reach in 15 ft that will block you from sight, can they run to that corner to stop being frightened, then run back to attack without disadvantage? Assume they would not provoke OA to do this, although the OA is immaterial to the question.