My home page in Firefox [v4.0] and Internet Explorer [v9.0.8112.16421, Update Versions RTM (KB982861)] is currently set to Google but when I depress the quick start icon to start up either browser, I am getting the following immediate results:  Unable to connect (In Firefox)     Firefox can't establish a connection to the server at www.google.com.         The site could be temporarily unavailable or too busy. Try again in a few moments.   If you are unable to load any pages, check your computer's network connection.   If your computer or network is protected by a firewall or proxy, make sure that Firefox is permitted to access the Web.      Internet Explorer cannot display the webpage     What you can try:      Diagnose Connection Problems      More information      This problem can be caused by a variety of issues, including:         Internet connectivity has been lost.   The website is temporarily unavailable.   The Domain Name Server (DNS) is not reachable.   The Domain Name Server (DNS) does not have a listing for the website's domain.   There might be a typing error in the address.   If this is an HTTPS (secure) address, click Tools, click Internet Options, click Advanced, and check to be sure the SSL and TLS protocols are enabled under the security section.         For offline users      You can still view subscribed feeds and some recently viewed webpages.      To view subscribed feeds:          Click the Favorites button , click Feeds, and then click the feed you want to view.         To view recently visited webpages (might not work on all pages):          Press Alt, click File, and then click Work Offline.   Click the Favorites button, click History, and then click the page you want to view.      Thankfully, I am able to use one browser that I have installed on my computer (Mathon v3.0.20.5000) to search online for technical assistance in this matter.  I have seen several WinSock error issues mentioned; but, they are pointing to Windows XP and I am using Windows 7 Pro and remain uncertain whether anything identified as a fix for one OS will work in another.  Things I've tried:   HiJackThis Complete scan with Avira AntiVirus Premium.   What am I overlooking?  What should I do to address this problem?
If I can generally reach web pages on the Internet but can't reach a specific one, how do I troubleshoot what the cause is as an end user?       This question was a .   Read the  for more details or  yourself
Shortest path from points in one layer to points in another layer via roads in QGIS I'm looking for a way to calculate the shortest path from addresses to subway stations via a network of roads.  I have the , however, the addresses and subway stations are point layers that do not overlap with vertices in the roads layer.  In QGIS, is there a way to calculate the shortest distance from the address/subway station points to the roads, create vertices at those locations, then calculate the shortest distance via the roads network?   black squares - addresses white circles - subway stops gray lines - roads Find the determinant of the following matrix Suppose that $S_0$ and A are positive numbers, let $$S_{n+1} = \frac{1}{2}\left(S_n +\frac{A}{S_n}\right)$$ with $n \geq 0 $.      (a)Show that $S_{n+1} \geq \sqrt{A} $ if $n \geq 0$       (b)Show that $S_{n+1} \leq S_n $ , if $n \geq 1$      (c) Show that $s= \lim\limits_{n \rightarrow \infty} S_n$ exists      (d) find s   (a) Show that $S_{n+1} \geq \sqrt{A} $ if $n \geq 0$  Given $$P_n:  S_{n+1} = \frac{1}{2}\left(S_n +\frac{A}{S_n}\right) \geq \sqrt{A}$$  $$P_0: S_{1} = \frac{1}{2}\left(S_0 +\frac{A}{S_0}\right) \geq \sqrt{A}  $$  We assume that $P_n$ is true  $$P_{n+1}: S_{n+2}= \frac{1}{2}\left(S_{n+1} +\frac{A}{S_{n+1}}\right)$$ by assumption $$S_{n+2}= \frac{1}{2}\left(S_{n+1}\left(1 +\frac{A}{(S_{n+1})^2}\right)\right) \geq \frac{1}{2}\left(\sqrt{A}\left(1 +\frac{A}{(\sqrt{A})^2}\right)\right)$$ $$ S_{n+2}= \frac{1}{2}\left(S_{n+1} +\frac{A}{S_{n+1}}\right) \geq \sqrt{A}  $$  It follows that $S_{n+1} \geq \sqrt{A} $    (b) Show that $S_{n+1} \leq S_n $ , if $n \geq 1$  $$S_{n+1} \leq S_n$$ $$\frac{1}{2}\left(S_n +\frac{A}{S_n}\right) \leq S_n $$ Dividing by $S_n$ $$\frac{1}{2}\left(1 +\frac{A}{S_n^2}\right) \leq 1 $$ $$\frac{A}{2S_n^2} \leq \frac{1}{2}$$ $$A \leq S_n^2$$ $$S_n \geq \sqrt{A}$$ As  $S_{n+1} \leq S_n$ yields a true statement, it follows $S_{n+1} \leq S_n$ is true.    (c) Show that $s= \lim\limits_{n \rightarrow \infty} S_n$ exists  Since $S_{n+1} \leq S_n$, the sequence is non-increasing,   using the non-increasing theorem stating that      if $\{S_n\}$ is non-increasing then $$\lim\limits_{n \rightarrow &gt; \infty} S_n = \inf\{S_n\} $$     (d) find s    Is the argumentation in (a) and (b) appropriate? Also, I have to admit I m getting less confident in my argumentation (c) and (d). How to proceed in (c) and (d)?  Much appreciated for your input or help. Name an Armor Stand using the Standard Galactic Alphabet The Standard Galactic Alphabet is what appears in the Enchanting Table. Is there a way to give a name to an Armor Stand using these character.  I know there is a LingoJam Translator that give ASCII characters that look like the SGA, but that is not what I'm looking for. Can I use the same characters as the Enchanting Table? How to iterate over arguments in a Bash script I have a complex command that I'd like to make a shell/bash script of.  I can write it in terms of $1 easily:  foo $1 args -o $1.ext   I want to be able to pass multiple input names to the script. What's the right way to do it?    And, of course, I want to handle filenames with spaces in them. Expansion of $(1+\sqrt{2})^n$ How to saveHTML of DOMDocument without HTML wrapper? Predefined Coordinate Systems missing in QGIS 2 in QGis 1.8 were lots of predefined coordinate systems (national projections). Where have they all gone in qgis 2.0? I specifically need the Gauß-Krüger-Projections Zone 1 to 5.  Is there any plugin to load those coordinate systems? I have some conditions for some background job to run:  condition-command &amp;&amp; condition-command &amp;&amp; background-job &amp;   The problem is: I want the conditions to block until the job runs, as if I had run:  condition-command; condition-command; background-job &amp;   But it isn't a condition, if previous command fails I do not want the job to run.  I realised it is asynchronous, but it should not, in my mind the both following scripts should be the same, but they do not:  sleep 2; echo foo &amp; sleep 1; echo bar; wait   # prints foo, then bar: correct sleep 2 &amp;&amp; echo foo &amp; sleep 1; echo bar; wait # prints bar, then foo: bug   I know if I test $? variable it would work, or if I put the last one inside a subshell (but then I would lost job controls, I want to avoid daemons), but I want to know why bash make it this way, where is it documented? Is there any way to prevent this behaviour?  Edit: Chained ifs is disgusting, that is why I will not accept it as a alternative way. Edit 2: I know a subshell is possible, but it will not work for me, let us imagine I want to run a bunch of commands then wait in the end. It will be possible if i check the existence of /proc/$PID directory, but it would be a pain in the neck if there are several jobs. Edit 3: The main question is WHY bash does it, where is it documented? Whether or not it has a solution is a bonus! By 18 years of age, I want a brand new car that's $43,668 I'm from Arizona and I will be 18 in 4 months. I make about $1,200 a month from my job. I have $600 in my bank account and I don't plan to  spend any of it until I'm  18.     I'm looking to get a brand new Jeep Wrangler Rubicon that costs about  $43,000. The down payment is 10% (about $5,000) with an APR of  4.28%. The duration is 60 months with a monthly payment of  $800.  I don't have any credit. My friend suggested that I ask my parents to put my name on one of their credit cards so that I can build some credit. I'm not sure how that works. Can someone suggest a good way of going about this so I can get this car on or around my birthday?  My mom does finance work  for a big company and she told me that I should get a cheaper car. I really want this one and I'm willing to work for it. I'm getting a second job to get more money rolling in. My mom said that the only way that this would work is if I have a down payment of $15-20k. She also said that not everyone qualifies  for a car like this one. What can get me to qualify ASAP when I turn 18? Layover at Tokyo Narita airport: can I travel outside, and what kind of visa would I need? I am travelling from Singapore to San Francisco and the airline has a layover of 7.5 hours at Tokyo Airport (NRT). I am wondering if I would be allowed to go out to experience the city for a while in some form a visitor visa.  I know Singapore has such facilities, but does anyone know if I can do it in Tokyo? Any suggestions or pointers are welcome. Note - I do not have a visa for Japan yet, but I am hoping that 1 day visitor visa could be possible at airport. Does not the mass of those living on the Earth add on to the mass of the Earth or is it too negligible to be cared for? : Earth weighs about 13,170,000,000,000,000,000,000,000 pounds (or   5,974,000,000,000,000,000,000,000 kilograms). Since Earth is too big   to be placed on a scale, scientists use mathematics and the laws of   gravity to figure out Earth's weight.   So, this seems to be a constant. But I guess it doesn't consider the things that are on the earth, the trees, buildings, people, animals, water etc...  So, are all the above mentioned things' mass is too small or negligible to be left off? what is the real use case of dependency injection? I want to know which sentence is correct. If i say     Guess, what it is?   or     Guess, what is it?   which one is correct? Is there an option to create and Opt-in a user in the same API call? CW complex such that action induces action of group ring on cellular chain complex. Let $X$ be a space that satisfies the hypotheses used to construct a universal cover $\overline{X}$. Let $\pi = \pi_1(X)$ and consider the action of the group $\pi$ on the space $\overline{X}$ given by the isomorphism of $\pi$ with $\text{Aut}(\overline{X})$. Let $A$ be an abelian group and let $\mathbb{Z}[\pi]$ act trivially on $A$, $a \cdot \sigma = a$ for $\sigma \in \pi$ and $a \in A$.  Now, assume that $X$ is a CW complex. How do I see that $\overline{X}$ is a CW complex such that the action of $\pi$ on $\overline{X}$ induces an action of the group ring $\mathbb{Z}[\pi]$ on the cellular chain complex $C_*(\overline{X})$ such that each $C_q(\overline{X})$ is a free $\mathbb{Z}[\pi]$-module and$$C_*(X; A) \cong A \otimes_{\mathbb{Z}[\pi]} C_*(\overline{X})?$$ Is it ever revealed what Crookshanks is? When Hermione first got her pet thing Crookshanks, there was a mention that it looked kinda like a cat, but wasn't.  Was it ever revealed what Crookshanks really was? Why is the detection of gravitational waves so significant? LIGO has announced the detection of gravitational waves on 11 Feb, 2016. I was wondering why the detection of gravitational waves was so significant?   I know it is another confirmation of general relativity (GR), but I thought we had already confirmed GR beyond much doubt. What extra stuff would finding gravitational waves teach us? Is the detection of gravitational waves significant in and of itself, or is there data which can be extracted from the waves which will be more useful? Show that the conditional statement is a tautology without using a truth table I have been attempting to use identities to get to the answer but I am unable to get anywhere. Here is the equation I am trying to prove tautological without using truth tables:  $[(p\rightarrow q) \land (q \rightarrow r)] \rightarrow (p \rightarrow r )$  And here is my attempt at using identities to work my way up. (a link to a page with a table of logical equivalence identities: )  $\lnot [(p \rightarrow q) \land (q \rightarrow r)] \lor (p \rightarrow r)$  $\lnot [(\lnot p \lor q) \land (q \rightarrow r)] \lor (p \rightarrow r)$  $[\lnot (\lnot p \lor q) \land \lnot (q \rightarrow r)] \lor (p \rightarrow r)$  $[(p\land \lnot q) \land (q \land \lnot r)] \lor (p \rightarrow r)$  I don't know where to go from there. Related questions with over 99 score display incorrectly The score for the 4 questions are 111, 1218, 261 and 5 respectively, but they display 2 digits per line. This is an obvious bug in design.