I have purchased this stock image:    I wish to extend the pebble background substantially, to fill the image around 4x wider, keeping the same height.   So far I've tried:   Using PS CS5 content-aware filler, though whilst it starts out ok as you extend it a little bit, it begins to repeat the exact same background giving an extremely unnatural and badly edited look as you extend further. Using the Clone tool and Spot healing after stretching and cut-pasting various bits, after an hour of fiddling it becomes uncertain whether the image is getting better or worse and using this method will take forever and a day.   There must be a combination of the thousands of tools in Photoshop or CS5 that will help me do this much faster.  Any suggestion, blogs, guides or tutorials for this are welcome and appreciated.
I have an image with a woman, and I need to make an ad (size 260mmx125mm). I want to put the woman to the left side, but then right side becomes empty. So, how I should solve the problem? I have picked the color from image, but it is definitely different than in the actual picture.  Should I use the Clone Stamp Tool in Photoshop, or there is a better way to do this?  By the way, it will be used in print, so I need a good quality.
How to reach local computer via machine name instead of IP? Developer here prototyping a mobile app, somewhat new to mobile:   I have a simple HTTP service running (currently) on my main laptop with machine name latitude. Another laptop named vaio sharing the same WiFi network can access that service via http://latitude:8080 -- in other words, it can easily resolve the (current) IP 192.168.x.y (or whatever dynamic IP it has at that moment) of latitude somehow. Now my HTC Android phones, connected to the same WiFi network, can reach the IP address of latitude so opening in its browser http://192.168.x.y:8080 works. But I'd like to use the machine name here, too, like when I access the HTTP service from vaio, simply by typing http://latitude:8080 and have the phone resolve the current dynamic IP of latitude. This doesn't work, only get the standard browser error page: "Webpage not available".   Is there some DNS setting in Android I need to tweak? Haven't found anything from playing around with Settings, and a question like this is notoriously hard to google, too...  The One V has Android 4.0, and the One M7 has Android 4.2 in case that makes a difference.  (Note, this should work even when the Android is not USB-connected to my computers and is not acting as a WiFi Hotspot -- obviously, since it's consuming my main WiFi network anyway). How does an attacker's reach interact with the Mounted Combatant feat's ability to force an attack against the mount to target the rider instead? pgfplots: Clipping Everything Outside a Specific Area I want to add information to each column of a histogram. every node near coord is probably the best approach. It works well with bar plots but not with the histogram:  \documentclass{article}  \usepackage{pgfplots} \pgfplotsset{compat=newest} \usetikzlibrary{pgfplots.statistics}  \begin{document}  \begin{tikzpicture} \begin{axis}[ ybar interval, xticklabel=\pgfmathprintnumber\tick--\pgfmathprintnumber\nexttick, % Code to generate labels nodes near coords={ \pgfmathprintnumber{\pgfkeysvalueof{/data point/y}} }, every node near coord/.style={ anchor=south,xshift=9mm, }, % ] \addplot+[hist={bins=3}] table[row sep=\\,y index=0] { data\\ 1\\ 2\\ 1\\ 5\\ 4\\ 10\\ 7\\ 10\\ 9\\ 8\\ 9\\ 9\\ }; \end{axis} \end{tikzpicture}  \end{document}   I used every node near coord/.style to shift the labels.  The problem is that I have four labels for three columns/bars:    I addition I would like to center the labels. A workaround will be a manual adjustment (every node near coord/.style) just like in the shown example.  Update  Maybe clipping is a possibility. Is there a way to clip the labels (in this case the 7 in the right) away?  Like this: I want to print the floating point number with exactly two significant digits in bash (maybe using a common tool like awk, bc, dc, perl etc.).  Examples:   76543 should be printed as 76000 0.0076543 should be printed as 0.0076   In both cases the significant digits are 7 and 6. I have read some answers for similar problems like:      but the answers focus on limiting the number of decimal places (eg. bc command with scale=2 or printf command with %.2f) instead of significant digits.  Is there an easy way to format the number with exactly 2 significant digits or do I have to write my own function? Undo apt-get remove open* ubuntu 12.04 In JavaScript can I make a "click" event fire programmatically for a file input element? Notation question: $\ll$ Connect Java to a MySQL database I recently upgraded my computer's RAM to 4&nbsp;GB. My 32-bit Windows installation shows only 3574&nbsp;MB of the memory. How can I make Windows use the full amount of RAM? Why doesn't the mirror modifier work with object groups? Why doesn't the mirror modifier work with object groups? I have a group made of four objects to which I want to apply a mirror modifier. For me, it's not working. What are the steps to make apply a mirror modifier to a group of objects? A piecewise $C^1$ curve has Jordan measure zero. $\newcommand{\Reals}{\mathbb{R}}\gamma:[0,1]\to \Reals^2$ is an injective parametrization of a curve $\Gamma$, which is piecewise $C^1$ and the length of the curve is $L(\Gamma_k)&lt;\infty$.   1.1.: Show that for every $n\in N$ there is a decomposition $0=t_0&lt;t_1&lt; \dots &lt;t_n=1$ of $[0,1]$ so that $L(\Gamma_k) = \frac{L}{n}$ for $k=1,\dots ,n$ and $\Gamma_k=\operatorname{Im}(\gamma_k)$, $\gamma_k=\gamma|_{[t_{k-1},t_k]}$.   1.2.: Show that you can cover $\Gamma$ with a system of spheres of radius $\frac{L}{n}$.   1.3.: Use 1.2. and 1.3. to show that $\Gamma$ has Jordan measure zero.   I wasn't there when they discussed when a function has Jordan measure zero  and how those things correlate with this exercise so if someone could give me some hints that would be great. How can I delete everything from my MacBook Pro before selling it? I have a Mac that runs Snow Leopard and I intend to upgrade it to Mountain Lion and sell it on ebay. However, I only have one hard-drive, and I'm sure I can't use something in my OS to delete my OS and all user data.  Is there something for this that's built into the firmware that I can do on boot, or otherwise?   I have source code on my Mac for multiple corporations' proprietary software and I can't risk somebody gaining access through the use of any sort of disk recovery tool. I plan to use a 7 pass erase rather than simply deleting the directory. Storing two kinds of point geometry in shapefile or creating multipoint shapefiles? Following , can I have a mixture of two kinds of geometry in a shapefile of type point. Just like I have about shapefiles of type polygon or I should always create a shapefile of type multipoint in order to support multipoints in my layer?    My problem is as you see at , I can't use ogrinfo in order to understand that the geometry type of a multipoint shapefile will be known as wkbMultipoint or wkbPointwhen I use this line of code:    OGRwkbGeometryType GeometryType = poLayer -&gt;GetGeomType();     for a layer of type multipoint before programming.     Will OGR know a layer of type multipoint as wkbpoint or wkbmultipoint?   When we create a shapefile in ArcCatalog, we have point and multipoint, but not multipolyline or multipolygon for polyline and polygon.Why? Is there an easier way to install Chromium than what is described ?  Furthermore, is there an easier way to stay up to date with current Chromium releases rather than having to re-build Chromium each release? (a script which automatically grabs and installs the latest build possibly?).  Related: What is the difference between I play and I do play?  For example:  If someone were to ask to me, do you play soccer? Can I revert to the Mountain Lion style labels instead of Mavericks tags? How? I think it would make sense to split up the flag "This is not an answer" into three flag choices:   This should be a comment This should be an edit This should be a new question   If we had that, it would make it easier (and therefore more efficient) for mods to figure out what to do with answers flagged thusly. If $A\simeq\prod A_i$ then $\sum e_i=1$ Given $A$ commutative ring with unity. If we have rings $A_1,\dots, A_n$such that $A\simeq A_1\times \dots \times A_n$ there are $e_1,\dots,e_n$ idempotent elements of $A$ such that $e_1+\dots+e_n = 1$ and $e_i e_j =0$ if $i\neq j$.  I'm not sure how general the proof should be written...  The isomorphic relation suggest that if $f$ defines the isomorphism then there is a $(a_1,\dots, a_n)\in \prod A_i$ such that $f(a_1,\dots,a_n)=1\in A$. Could it work thinking of the idemmpotent terms as $e_i=(0,\dots,0, a_i,0, \dots,0)?$ This should satisfy $e_i e_j =0$ if $i\neq j$. But I have two problems with it (1) I don't see why $e_i$ should idempotent as no assumptions in regard to the existence of idempotent elements in $A_i$ has been made. (2) The sum $\sum e_i=1$ has no reason to be true. $f:I=[\pi,2\pi]\to \mathbb{R}^2$ be given by $f(t)=(\cos t,\sin t)$  which of the following are necessarily correct?  $1$. $\exists t_0\in I$ such that $f'(t_0)=\frac{1}{\pi}(f(2\pi)-f(\pi))$  $2$. $\nexists t_0\in I$ such that $f'(t_0)=\frac{1}{\pi}(f(2\pi)-f(\pi))$  $3$.$\exists t_0\in I$ such that $\pi||f'(t_0)||\ge ||(f(2\pi)-f(\pi)||$  $4$. $f'(t)=(-\sin t,\cos t)\forall t$  $4$ is clearly true, $1$ is true by Mean Value Theorem as $f$  satisfies all the conditions of MVT? have no idea of $2$ and $3$, Thank you for help What are the most commonly used and basic Apache htaccess redirects?