I just made an "Expedite review" request to apple for a major bug yesterday and Apple approved the app in few hours.  Now (Today) I want to request Expedite review again of-course for a major reason.  What is the chance of approval again?  Will that affect my future requests?
If my app is live and users are facing a critical issue, can I upload another build and ask Apple to make it live within a day or two?
Solution of trigonometric equation $0 = x\cos(x)+2$ Optimized rendering of a cube mesh world I want to render a cube-mesh (a.k.a. Minecraft-style) world. If I render each existing cube it will eat up FPS pretty quickly. How can I optimize it? I understand that the point is to not render invisible meshes (faces?) but my problem is to find out what is invisible and what isn't. Is it possible to run two windows sessions from the same computer at the same time? A friend asked me if it is possible to have two screen/keyboards/mouse connected to one computer, and allowing two users to use the computer as if they where using two different computers (one sessions for each input/output)  Is it possible? Eclipse menus are cut off or don't show I'm using Ubuntu 13.10 (with JDK 1.7.0_45).  I've downloaded and uncompressed Eclipse Kepler for Java EE Developers.  The software menus are messed up. I didn't notice similar problems in other software.  When I click any menu in Eclipse, the drop-down seems to be "cut". Sometimes the drop-down shows, but the options are invisible.  I tried Eclipse Indigo, but the same problem occurs. Difference In Eigenvectors Fiction novel or movie about sentient dinosaurs I remember parts of a story about some researchers finding a society of sentient dinosaurs. I believe they lived underground. From what I recall there were some steam punk elements and I think crystals were important.  From what I recall (this might be wrong) there was a book and also a movie about that story.  In the process, humans lived with these dinosaurs. I am not sure if that was like that from the beginning or if that happened later.  Any idea what that story might be? Which answer do I accept if I have multiple correct answers? Archimedes' principle for two liquid layers Problem: I have a cylindrical vessel of height $H$ and radius $R$. There are two liquid layers in the vessel. The first has density $D_1$ and height $h_1$, the second has density $D_2$ and height $h_2$. The second liquid is floating on the first liquid (thus $D_2 &lt; D_1$) and they are both entirely within the vessel ($h_1+h_2 \le H$). Now I have a cube of density $D$ and edge length $n$. The cube fits into the vessel ($n \le \sqrt2R$) but it might not be completely inside it ($n&gt;H$ is possible). I place it into the vessel such that one side is horizontal (the cube is not lopsided). Some liquid might overflow as a result. How do I use Archimedes' principle to calculate the topmost liquid level after placing the cube? I can ignore damping and other physical effects. EDIT: Note that the only values I know are $H, R, D_1, h_1, D_2, h_2, n$ and their abovementioned constraints.  My workings: I tried using the formula directly, where $\text{weight of cube}=\text{weight of displaced liquid}$. I first get $Dn^3=D_2n^2s_2$ where $s_2$ is the height submerged in the second liquid. If $s_2 \le h_2$ then the cube is only submerged in the second liquid. So the answer is $\min(H, h_1+h_2+{n^2s_2\over\pi R^2})$, accounting for overflows. This case is simple. But if $s_2&gt;h_2$ then the cube can be submerged in the first liquid too. I thought of subtracting the weight of the second liquid displaced to obtain the height submerged in first liquid, but realize that I don't know that. The weight displaced depends on the final liquid height, which can be affected by overflows, whether the cube fits totally within the two liquids, etc. In fact, it can be the case that after the liquid level rises, the cube now displaces more of the second liquid, causing it to not be submerged in the first (is that even possible?) It seems very messy and I have no idea how to start. :( Does anyone have a nice solution to this problem? Can I have two UK visas simultaneously? I have a visitor UK visa valid until October 2017.  I also want to apply for a Tier 4 student visa. My studies in the UK start in September 2017.  If I apply for the student visa in June, will they simply issue an overlapping student visa, or will they cancel my visitor visa and I will not be able to come to the UK until September?  I am worried because in a similar situation with Schengen visas, my existing visa was canceled. In Inno Setup is it possible to add conditional statements to what in the [Run] section gets executed? Alternatively is it possible to manually update the built in progress bar? Basically I have 2 MSIs included and using Inno Setup as a bootstrapper, and depending on user input one or both of the MSIs are to be installed.  I have something working using Exec statements in CurStepChanged but it doesn't update the progress bar as the files are extracted and it looks like the installer is stalled.  I guess the end result is I want some progress bar updates while the files are extracted to the temp folder.  The following is my current code:  procedure CurStepChanged(CurStep: TSetupStep); var     ResultCode: Integer; begin     if(CurStep = ssInstall) then begin         if(InstallServer) then begin             ExtractTemporaryFile('ServerSetup.msi');             Exec('msiexec',ExpandConstant('/i "{tmp}\ServerSetup.msi" /qb INSTALLDIR="{code:GetInstallPath}\Server\" ALLUSERS=2'),'', SW_SHOW, ewWaitUntilTerminated, ResultCode);         end;         if(InstallClient) then begin             ExtractTemporaryFile('ClientSetup.msi');             Exec('msiexec',ExpandConstant('/i "{tmp}\ClientSetup.msi" /qb INSTALLDIR="{code:GetInstallPath}\Client\" ALLUSERS=2'),'', SW_SHOW, ewWaitUntilTerminated, ResultCode);         end;     end; end; Resize multiple layers around their respective anchor points remove files when name does NOT contain some words Zero-dimensional ideals and finite-dimensional algebras I encountered in the literature the term zero-dimensional ideal, however I can not find a relevant definition anywhere in Atiyah-MacDonald or Matsumura. In fact, I encounted the statement:      $I$ is a zero-dimensional ideal of $k[x_1,\dots,x_n]$ $\Leftrightarrow$ $k[x_1,\dots,x_n]/I$ is a finite-dimensional $k$-vector space, where we assume that $k$ is algebraically closed.   Question 1: What is the definition of the dimension of an ideal?  Question 2: How do we prove the above statement?  Question 3: Is $k$ being algebraically closed a necessary condition for the statement to be true? I would like to delete, from the following figure:  the top circle, but without removing the black edge that separate the orange part from the gray part. The figure above has been obtained by the following code: \documentclass[border=0.2cm]{standalone}  % Required packages \usepackage[dvipsnames]{xcolor} \usepackage{tikz}   \begin{document} \begin{tikzpicture}[thick, set/.style = {circle,      minimum size = 3cm,      fill=black!30}]  % Set A \node[set,label={135:$A$}] (A) at (0,0) {};  % Set B \node[set,label={45:$B$}] (B) at (1.8,0) {};   % Intersection \begin{scope} \clip (0,0) circle(1.5cm); \clip (1.8,0) circle(1.5cm); \clip (0.9,1.5) circle(1.5cm); \fill[orange!60](0,0) circle(1.5cm); \end{scope}  % Circles outline \draw (0,0) circle(1.5cm); \draw (1.8,0) circle(1.5cm); \draw (0.9,1.5) circle(1.5cm);  \end{tikzpicture} \end{document}  A rough example of the desired result is: Lost passport with Schengen visa Estimating Uniform distribution endpoints using data with errors Suppose I have a random variable $X$ ~ $Unif(0,\theta)$ where I want to estimate $\theta$. I draw a sample $X_1,...,X_n$.One way is to get a point estimate using e.g.  maximum likelihood estimation via the sufficient statistic $X_{(n)}$.  However, suppose I want a 95% confidence interval of sorts on the value of $\theta$, how should I construct one?  The reason why I am interested in confidence interval is because of the following issue, which is actually my main question (the above prelude on confidence interval is just a suggestion on possible approach). So actually my sample came with some noise, in a sense that I actually observe $X_1+E_1,...,X_n+E_n$ where $E_i$~$N(0,\sigma_i^2)$ independently from each other and from the $X$'s. How should I make some form of statistical estimation about $\theta$? I would prefer some form of confidence estimate. image of polynomial map is not an algebraic set I am doing an exercise about algebraic geometry, where the exercise  tell us to provide example of the image of polynomial map $f:\mathbb{C}^{m}\rightarrow \mathbb{C}^{n}$ that is not an algebraic set. But I am thinking that the image of every polynomial is $\mathbb{C}$ thus every polynomial map is surjective. What have I misunderstand? Theorem. Let $(X,\mathcal B,\mu)$ a finite measure space, where $\mu$ is a positive measure. Let $\mathcal A\subset \mathcal B$ an algebra generating $\cal B$. Then for all $B\in\cal B$ and $\varepsilon&gt;0$, we can find $A\in\cal A$ such that $$\mu(A\Delta B)=\mu(A\cup B)-\mu(A\cap B)&lt;\varepsilon.$$  I don't think there is a proof in this site. It's a useful result for several reasons:  We know what the algebra generated by a collection of sets is, but not what the generated $\sigma$-algebra is. The map $\rho\colon \cal B\times\cal B\to \Bbb R_+$, $\rho(A,A')=\mu(A\Delta A')$ gives a pseudo-metric on $\cal B$. This makes a link between generating for an algebra and dense for the pseudo-metric. We say that a $\sigma$-algebra is separable if it's generated by a countable class of sets. In this case, the algebra generated by this class is countable. An with the mentioned result, we can show that $L^p(\mu)$ is separable for $1\leq p&lt;\infty$, which makes a link between the two notions. In ergodic theory, we have to test mixing conditions only an a generating algebra, not on all the $\sigma$-algebra. What I am looking for is the equivalent of System.Windows.SystemParameters.WorkArea for the monitor that the window is currently on.  Clarification:  The window in question is WPF, not WinForm. Using Perl to change the url homepage for Internet Explorer