I try to clone a database from an Sql Server on my local machine v15 (2019) to a server machine v14(2017). I did a .bak file and when I tried to import on the server side it says:  System.Data.SqlClient.SqlError: The database was backed up on a server running version 15.00.4083. That version is incompatible with this server, which is running version 14.00.2037. Either restore the database on a server that supports the backup, or use a backup that is compatible with this server. (Microsoft.SqlServer.SmoExtended)  Is there a &quot;compatibility&quot; backup mode on the 14-15 Sql Server versions? local (on docker, Linux):  Microsoft SQL Server 2019 (RTM-CU8-GDR) (KB4583459) - 15.0.4083.2 (X64)   Nov  2 2020 18:35:09   Copyright (C) 2019 Microsoft Corporation  Developer Edition (64-bit) on Linux (Ubuntu 18.04.5 LTS)   distant (on Windows Server)  Microsoft SQL Server 2017 (RTM-GDR) (KB4583456) - 14.0.2037.2 (X64) Nov  2 2020 19:19:59   Copyright (C) 2017 Microsoft Corporation Standard Edition (64-bit) on Windows Server 2019 Standard 10.0  (Build 17763: ) (Hypervisor)
When trying to restore a backup to a SQL Server Express 2008 database I got the following error:  Restore failed for Server '...\SQLEXPRESS'.  (Microsoft.SqlServer.SmoExtended) System.Data.SqlClient.SqlError: The database was backed up on a server running version 10.50.1600.  That version is incompatible with this server, which is running version 10.00.2531.  Either restore the database on a server that supports the backup, or use a backup  that is compatible with this server. (Microsoft.SqlServer.Smo)   Is there a way to get a backup which is compatible with the older (in my case 10.00.2531) version from the newer (in my case 10.50.1600) version of SQL Server Express?
Review option on mobile phone not available? Say, I have foo-1.2.3.deb which depends on perl and python, however, running command:  dpkg -i ./foo-1.2.3.deb   won't install these dependencies. So I must apt-get install perl python by hand.  How to make dpkg -i install these dependencies for me automatically? Identify this novel: youngsters psychologically tested for abilities/profession, hero wants to author the tests, society uses moving walkways What is a socket? I have the following problem.      Let $f:D\to \mathbb C$ be a holomorphic function, where $D=\{z:|z|\leq 1\}.$ Let $$f(z)=\sum_{n=0}^\infty c_nz^n.$$ Let $l_2(A)$ denote the Lebesgue measure of a set $A\subseteq \mathbb C$ and $G=f(D).$ Prove that $$l_2(G)=\pi\sum_{n=1}^\infty n|c_n|^2.$$   After a long struggle I managed to come up with the following formula $$l_2(G)=\iint_D |f\,&#39;(z)|^2dxdy.$$ It looks like the right thing to use because $$f\,&#39;(z)=\sum_{n=1}^\infty nc_nz^{n-1},$$ which is similar to what I have to prove. I understand that the $\pi$ will appear when I integrate something over the angle $\phi$ in polar coordinates. But I don't know how to find the square of the absolute value of the right-hand side to even start integrating...  EDIT: The function is supposed to be  (one-to-one). (I'm not perfectly sure I'm translating the term correctly. The (Polish) word in the statement of the problem was "jednolistna". I have not met it before.) May someone help me? I am trying to use induction to prove that the formula for finding the $n$-th term of the Fibonacci sequence is:   $$F_n=\frac{1}{\sqrt{5}}⋅\left(\frac{1+\sqrt{5}}{2}\right)^n-\frac{1}{\sqrt{5}}⋅\left(\frac{1-\sqrt{5}}{2}\right)^n.$$  I tried to put $n=1$ into the equation and prove that if $n=1$ works then $n=2$ works and it should work for any number, but it didn't work. I need to prove that this formula gives the $n$th Fibonacci number. The topic which haunted me for two years until I gave up on it. But now I am doing engineering and this topic suddenly popped out of my textbook from nowhere. I seriously need to understand this topic because I wasn't able to do so in the past. I have read many book on 'energy' and it came to nothing. Maybe just because the many books I have read all said 'energy' is something which doesn't 'exist'! It is 'abstract'! It is just a number which represents the state or orientation of a system. But then I see so many examples that 'uses' energy to do 'work'. But the question here is that if anything doesn't exist in this universe, then how can the same thing be used to do something that exist?  My problem is that I didn't understood the topic 'energy' and all the other topics related to it (work, power etc.) Prove that $E$ is disconnected iff there exists two open disjoint sets $A$,$B$ in $X$ Test for the convergence of the sequence $S_n =\frac1n \left(1 + \frac{1}{2} + \frac{1}{3} + \cdots+ \frac{1}{n}\right)$ How can particles be emitted from particles? In a scene with two particle system configured as boids and boids brain set to fight, one swarm attacks the other. I would like to emit child particles as lines (laser or something) to visualize some fighting action. I couldn't find a way to setup the line emitting particle system, either they are created from the plane or further cones will be added. Is there a way to do this as I saw on a  but I didn't get the trick? Blend file   At blendersushi  the author says:  PARTICLE INSTANCE MODIFIER &gt; PARTICLES With this stacking thing, we can now pretty much emit Particles from emitted Particles, &gt; if you know how to set it up. Not very obvious, but basically you Instance some meshes &gt; (using Instance Modifier) and then add Particle System to the object with Instance &gt; Modifier. Make sure you have &quot;Use Modifier Stack&quot; turned on.  But I can't get this to work. This winter I am planning to track my downhill skiing/snowboarding using a GPS.  Most of my riding will occur at the same resort.  I would like to be able to create a sort of "heatmap" that shows the amount of runs that I have made in a given area.  As I add more and more GPS traces to my database, my goal would be to see a sort of linear heatmap of the most traveled areas.  Given the nature of downhill skiing, you would expect the uphill chairlift lines will be the "hottest" because it will be the only places visited over-and-over again.  Given that 1) my track will not be the same every time and 2) the area covered by following one "run" may be a few hundred feet wide, what might be the best way to analyze this "linear" data to create a sort of heatmap?  My thoughts were to buffer the lines, then intersect the polys to get a sort of Venn Diagram thing going.  My preference is to use open-source technologies.  I've got QGIS and PostGIS loaded and available.  UPDATE: In regards to @blah238's response, I was thinking of something that might be able to "collect" the number of passes ("runs") through an area, and then symbolize by the count.  Conceptually, this would be similar to ArcGIS "" (but for lines, not points) or  (but for multiple line in roughly the same area).  A more visual example of a similar concept might be a traffic-flow map, where highly-congested areas would equate to "highly-traveled" ski runs/areas:    I've read the following questions that may give some ideas, but they don't really address what I am trying to accomplish: Combining jquery functions - on() hover/mouseenter/mouseleave If $f \colon [a,b] \rightarrow \mathbb{R}$, then show that there exists $c \in [a,b]$ such that $\int_a^c f = \int_c^b f$ If $f \colon [a,b]\rightarrow \mathbb{R}$, then show that there exists $c \in [a,b]$ such that $c \in [a,b]$ such that $\int_a^c f = \int_c^b f$.  I think that I have to proceed with the Mean Value Theorem of Integrals... How to prove and interpret $\operatorname{rank}(AB) \leq \operatorname{min}(\operatorname{rank}(A), \operatorname{rank}(B))$? Layers tab not showing Usually my layers tab appears in the area of the red circle, but I did something that changed it. I would like to know how to get it back. Thanks! Is this NPN transistor AND logic gate practical? How to find out what init mode system is using? I was looking at this and I'm not sure how to find out which startup service is used on my machine (Ubuntu 14.04 on Digital Ocean). Can it use all of them? (upstart, system v, systemd) A geometric reason why the square of the focal length of a hyperbola is equal to the sum of the squares of the axes? When I teach conics, I give a simple geometric argument for the Pythagorean relation for ellipses. (By "Pythagorean relation" I mean the fact that the square of the focal length $c$ is the difference of the squares of the semimajor and semiminor axes, i.e. $c^2=|a^2-b^2|$ for the ellipse defined by $\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$.) The picture argument goes as follows: just draw the obvious isosceles triangle from the two foci to one of the two points at the end of the minor axis. We see two right triangles; in each, one leg is the focal length $c$ and the other leg is the semiminor axis, while the hypotenuse is the semimajor axis. The result follows from the Pythagorean theorem applied to this right triangle.  But when it comes to the Pythagorean relation for hyperbolas, I can't think of an equally convincing picture to draw. Instead I have to give a rather inelegant algebraic argument for the relation $c^2=a^2+b^2$ (for the hyperbola defined by $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$, with focal length $c$), directly from the definition of the hyperbola. The messy details are below.*  Now, obviously there is an asymmetry between the argument for the ellipse and the argument for the hyperbola: the ellipse argument is almost trivial and doesn't involve working straight from the locus definition, but the hyperbola argument is tedious and does require working straight from the definition. So, my question:     Is there an equally persuasive picture I could draw to convince high   school students of the Pythagorean relation for hyperbolas -- without having to get technical with points at infinity, say?   The natural triangle to draw is the right triangle with legs from the center to a vertex and from that vertex to an asymptote, which has legs of length $a$ and $b$; but then the problem becomes why the length along the asymptote should be equal to $c$. I doubt there is a purely (Euclidean) geometrical reason because this triangle lies on the asymptote, not on the hyperbola itself; I suspect some sort of limiting procedure will be required.    [*] The tedious algebraic details:     The foci lie at $(\pm c,0)$.   Say $a&gt;b$. Then hyperbola is the locus of points $(x,y)$ such that       $$\left|\sqrt{(x+c)^2+y^2}-\sqrt{(x-c)^2+y^2}\right|=2a$$      Assume for simplicity the expression between the absolute value bars   is positive. (The algebra is even more tedious if we don't make such a   simplifying assumption.) Then moving the right root to the other side   and squaring gives      $$(x+c)^2+y^2=4a^2+(x-c)^2+y^2+4a\sqrt{(x-c)^2+y^2}$$      Simplifying gives      $$xc-a^2=a\sqrt{(x-c)^2+y^2}$$      and upon squaring again we have      $$x^2c^2-2xca^2+a^4=a^2(x^2-2xc+c^2+y^2)=a^2x^2-2xca^2+c^2a^2+a^2y^2$$      which reduces to      $$x^2(c^2-a^2)-y^2a^2=a^2(c^2-a^2)$$      Defining $b^2:=c^2-a^2$ brings the equation into the form   $x^2/a^2+y^2/b^2=1$, and the Pythagorean relation follows from the   definition of $b$. Local translations in curved spacetime A global Poincare transformation on a scalar field induces  $$\delta(a, \lambda)\phi(x) = [a^{\mu}+\lambda^{\mu\nu}x_{\nu}]\partial_{\mu}\phi(x). \tag{11.46}$$  In curved spacetime we replace $a^{\mu} \rightarrow \xi^{\mu}(x)$, but I read that in fact this new spacetime dependent parameter $\xi^{\mu}$ eats up the effect of the "orbital part of global Lorentz", so that in fact $\xi^{\mu}(x)=a^{\mu}(x)+\lambda^{\mu\nu}(x)x_{\nu}$, and we effectively have to treat $\xi^{\mu}$ and $\lambda^{ab}$ (the spin part of Lorentz) as the basis for gauge transformations.  I don't understand why this should be, any comments that might help? Why does the new local translation parameter include the effect of what globally used to be rotations/boosts?  References:   D.Z. Freedman &amp; A. Van Proeyen, SUGRA, 2012; p. 225. Will Windows 10 Technical Preview be upgradable to final release? Is there any information about if Windows 10 Technical Preview will then be upgradable to the final release ?  I'm asking that because I would like to use it on my primary PC (I'm aware of the risks but I accept them), in place of Windows 8.1 But I'd like to avoid to reinstall all after the release of the final version.