Whenever I'm browsing or downloading , I'll randomly get these long spikes of no internet connectivity. It only happens in Ubuntu versions like Ubuntu,Xubuntu,Kubuntu and so on. Tried on arch and my internet was fine the whole day. What should I provide?
I have a HP Pavilion dm4-2070us which has an Intel Corporation Centrino Wireless-N 1000 adapter.   The problem is that my computer doesn't show the wireless networks after I upgraded my system to Ubuntu 11.10. Following is my output for sudo lshw -class network:  *-network DISABLED          description: Wireless interface    product: Centrino Wireless-N 1000    vendor: Intel Corporation    physical id: 0    bus info: pci@0000:01:00.0    logical name: wlan0    version: 00    serial: 8c:a9:82:81:5a:30    width: 64 bits    clock: 33MHz    capabilities: pm msi pciexpress bus_master cap_list ethernet physical wireless    configuration: broadcast=yes driver=iwlagn driverversion=3.0.0-12-generic firmware=39.31.5.1 build 35138 latency=0 link=no multicast=yes wireless=IEEE 802.11bgn    resources: irq:42 memory:c2500000-c2501fff  *-network    description: Ethernet interface    product: AR8151 v2.0 Gigabit Ethernet    vendor: Atheros Communications    physical id: 0    bus info: pci@0000:08:00.0    logical name: eth0    version: c0    serial: 2c:41:38:07:f3:e3    size: 100Mbit/s    capacity: 1Gbit/s    width: 64 bits    clock: 33MHz    capabilities: pm msi pciexpress vpd bus_master cap_list ethernet physical tp 10bt 10bt-fd 100bt 100bt-fd 1000bt-fd autonegotiation    configuration: autonegotiation=on broadcast=yes driver=atl1c driverversion=1.0.1.0-NAPI duplex=full firmware=N/A ip=192.168.1.7 latency=0 link=yes multicast=yes port=twisted pair speed=100Mbit/s    resources: irq:44 memory:c1400000-c143ffff ioport:2000(size=128)   The output for rfkill list all:  0: hp-wifi: Wireless LAN     Soft blocked: no     Hard blocked: no 1: hp-bluetooth: Bluetooth     Soft blocked: no     Hard blocked: no 2: phy0: Wireless LAN     Soft blocked: no     Hard blocked: no 3: hp-wwan: Wireless WAN     Soft blocked: no     Hard blocked: no   I have also searched about the status of the WiFi network being shown as disabled. Somehow everything pointed to the fact that my wireless device is switched off and it can be switched on from Windows only. However, I don't have windows partition and it has just Ubuntu 11.10 so I don't see any point in switching the device on in Windows.
How to get a tool that can only break specific blocks and has a name? Firstly, how do I read it? Is below right? With braces   $$p \vdash (q \Rightarrow p)$$  The given proof is:    ${p}$, premise ${q}$, assumption  $p$ by (1) // what???  ${q} \Rightarrow p$ by implication introduction with 2 and 2.1 QED...    I can't really get the link between $p$ and $q$ in 2.1 ... Does anybody know how to add the shapefile name to a field in the file's attribute table?  I've found a description:     'You have to use inline variable in CalculateField like %Name% in   expresssion so that whatever the name of the file is, the string will   be inserted based on Name of the dbase file !'   I've tried to CalculateField tool with %Name%, but I got message:  Executing: CalculateField "2011-11-6 15_41_point" DBFName %Name% PYTHON # Start Time: Thu Dec 08 23:34:23 2011 WARNING 000405: No records within table Succeeded at Thu Dec 08 23:34:24 2011 (Elapsed Time: 1.00 seconds)   Where is my mistake? Prove or the disprove the existence of a limit of integrals Let $A \subset \mathbb{R}^2$ be the annulus defined, in polar coordinates, as  $$ A = \{ (r, \theta) \in [0, \infty) \times [0, 2\pi) : 2 \leq r \leq 3 \} \, .$$ Let $F: A \to A$, $F:(r, \theta) \mapsto (r, r \theta \text{ (mod } 2\pi))$. Let $g : A \to \mathbb{R}$ be a continuous function. Discuss the existence of the limit $$ \lim_{n \to \infty} \int_A g \circ F^{(n)}(x) \, \text{d}x \, ,$$ where $F^{(n)} = F \circ F \circ \dots \circ F$ denotes the composition of $F$ with itself $n$ times.  I cannot find a way to attack this problem. Here's what I tried: if $g \circ F^{(n)}$ converged, I think we could take the limit under the integral sign. So I tried to show the convergence of $F^{(n)}$. If it converged, then the limit function must send every point to a fixed point of $F$. So I determined the fixed points of $F$. But I don't think $F^{(n)}$ converges. I've found several answers on switching between an Adapter and a Battery. But I need to autmoatically switch between two batteries. One of them is 'hotplugable'.  Problem: I've got a Solarcell which charges a ~16000mAh Li-Ion battery (BATa). Once in a while, the Solarcell doesn't manage to charge the battery enough. It's crucial that I have 3.0 to 4.1 Volts on my VSYS but the voltage will drop below this value if the Solarcell wasn't able to do its job (cloudy weather, vulcano eruption [joke], dirty cells, etc).  My Plan: I've come up with the idea to feed the VSYS with a additional, hotplugable backup battery (BATb) which does get connected to VSYS if BATa drops below ~3.1v.  So basically I need a Low-Voltage-Cutoff (using a Z-Diode with a Mosfet?) which, when cutoff happens, opens another Mosfet..?         &ndash; Schematic created using   I'm not sure about the selection of M2 and how to wire it, so it will be conductive if M1 won't forward power anymore.  And I know about another electrical problem: Just using a Z-Diode (D1) with M1 will render M1 to something like a resistor, not a switch. I've read, that I could use something like a Shut Reference (i.e. TI's TL43xx). Again I'm not sure how to chose the correct one and how to wire it. Please rate and comment. I want to improve; constructive criticism is highly appreciated. Please take style into account as well.  The following proof is solely based on vector space related axioms. Axiom names are italicised. They are defined in Wikipedia (see vector space article).  Vector spaces - Multiplying by zero scalar yields zero vector  \begin{array}{lrll} \text{Let} &amp; \dots &amp; \text{be} &amp; \dots \\ \hline &amp; F &amp;&amp; \text{a field.} \\ &amp; V &amp;&amp; \text{a vector space over $F$.} \\ &amp; 0 &amp;&amp; \text{an identity element of addition of $F$.} \\ &amp; \mathbf{0} &amp;&amp; \text{an identity element of addition of $V$.} \\ &amp; \mathbf{v} &amp;&amp; \text{an arbitrary vector in $V$.} \\ \end{array}  $$\text{Then, }0\mathbf{v} = \mathbf{0}.$$  Proof. We will denote by $1$ an identity element of scalar multiplication; we will denote by $(-\mathbf{v})$ an additive inverse of $\mathbf{v}$. \begin{align*} 0\mathbf{v} &amp;= 0\mathbf{v} + \mathbf{0}                     &amp;&amp; \text{by }\textit{Identity element of vector addition} \\ &amp;= 0\mathbf{v} + (\mathbf{v} + (-\mathbf{v}))   &amp;&amp; \text{by }\textit{Inverse elements of vector addition} \\ &amp;= (0\mathbf{v} + \mathbf{v}) + (-\mathbf{v})   &amp;&amp; \text{by }\textit{Associativity of vector addition} \\ &amp;= (0\mathbf{v} + 1\mathbf{v}) + (-\mathbf{v})  &amp;&amp; \text{by }\textit{Identity element of scalar multiplication} \\ &amp;= ((0 + 1)\mathbf{v}) + (-\mathbf{v})          &amp;&amp; \text{by }\textit{Distributivity of scalar multiplication (field addition)} \\ &amp;= ((1 + 0)\mathbf{v}) + (-\mathbf{v})          &amp;&amp; \text{by }\textit{Commutativity of field addition} \\ &amp;= (1\mathbf{v}) + (-\mathbf{v})                &amp;&amp; \text{by }\textit{Identity element of field addition} \\ &amp;= \mathbf{v} + (-\mathbf{v})                   &amp;&amp; \text{by }\textit{Identity element of scalar multiplication} \\ &amp;= \mathbf{0}                                   &amp;&amp; \text{by }\textit{Inverse elements of vector addition} \\ \end{align*} QED Was Dumbledore aware that Professor Snape took points from Harry/Gryffindor unfairly? In many situations, we see Professor Snape behave in an unfair manner.   Snape unfairly and arbitrarily takes house points away from Harry/Gryffindors.  Was Dumbledore aware of this and, if so, did he just not care, or did he support this to somehow help Snape's double agent role? Why would one limit username format? Many websites when ask you to create a new "username", will limit you in some way, most often like "username should only contain letters and underscores" or something alike.  This results in inability to use my email as username and forces me to come up with new unique string all the time.  What is the rationale behind this?  Why not just let users use their emails, as a simple to remember and always unique?   What is generally wrong with having symbols like *&amp;%$#@ as a part of username? Obtain user and kernel time of a running process? Is there way to determine using standard Linux/Unix tools how much a process has spent in User mode and how much waiting for kernel?  In other words, exactly the "user" and "sys" values that you get when using time, but during process runtime?  NOTE: one way is to use WBEM and enumerate Linux_UnixProcess, but I need to use other tool than this; my aim is to verify what WBEM provider tells me, i.e. I need to use different tool. Sponsor Gallery, Page, or Something Like That? Unable to disable assignment rules I have a condition where I need to disable standard Lead Assignment Rules if certain criteria are met.   if(emailWithAccIdMap.containsKey(ledRec.Email) &amp;&amp; emailWithAccIdMap.get(ledRec.Email) != null &amp;&amp; !openOppMap.isEmpty() &amp;&amp; openOppMap.get(emailWithAccIdMap.get(ledRec.Email)) != null &amp;&amp; openOppMap.get(emailWithAccIdMap.get(ledRec.Email)).Owner.isActive ==true){                     ledRec.Status = 'Duplicate';                     System.debug('Changing the Status');                     //then assign the original lead owner to new lead owner                     ledRec.OwnerId = openOppMap.get(emailWithAccIdMap.get(ledRec.Email)).OwnerId;                     ledRec.Account_Name__c = openOppMap.get(emailWithAccIdMap.get(ledRec.Email)).AccountId;                     ledRec.Field_for_Lead_Workflow__c = true;                     Database.DMLOptions dmo = new Database.DMLOptions();                     dmo.assignmentRuleHeader.useDefaultRule = false;                     ledRec.setOptions(dmo);                     //since owner is assigned, it shouledRec not pass through round robin                     ledRec.checkAssignment__c = false;  }   This is my code snippet which is running on before insert. The control is entering the IF condition as the debug statement is getting printed. Yet, the owner assigned through this snippet is being overridden by the assignment rules.  I also tried executing this in after insert trigger context but it did not work. Can somebody tell me what I'm doing wrong? How do I install OpenStack? How do you get the index of the current iteration of a foreach loop? Is there some rare language construct I haven't encountered (like the few I've learned recently, some on Stack Overflow) in C# to get a value representing the current iteration of a foreach loop?  For instance, I currently do something like this depending on the circumstances:  int i = 0; foreach (Object o in collection) {     // ...     i++; } If $X,Y$ are equivalence relations, so is $X \times Y$ How do I change text on the submission button in the node form? Check if one list contains element from the other Can I simplify an expression into form which uses my own definitions? Automatically Locate Included Images Question about probable fixed use of "what do you do?" and "how do you do?" Do we always have to use the question how do you do? fixed in greeting people? Can we ask it in other situations rather than greetings? Like when we are wondering how someone is doing the given task.  Do we always have to use the question what do you do? for asking about sojeone's job? Can we use it sonetimes instead of ** what are you doing?** What does "off of" mean? I have read a sentence from “Diary of a Wimpy Kid 4”:     The teachers have really been cracking down on kids copying off of each other this year.   How to understand "off of"? Please parse it.