I have a secondary internal hard drive to store files. However, Snap programs in Ubuntu do not have the permissions to open the files on the secondary hard drive. To open files with certain Snap apps, I have to copy them first to the primary Ubuntu drive to access them. Desired solution: How do I enable Snap access to contents on my secondary internal HDD as if it was my main hard drive with full permissions.
I have Ubuntu 18.04 LTS installed. I inserted USB-flash to my laptop. It was automounted to /media/username/DISKLABEL and opened in Nautilus. I can read and write objects to it. How can I access it from the application, which is installed as Snap? I tried snaps of the following applications such as gedit, arduino-mhall119, organize-my-files. All them show me errors if I navigate to /media folder:    Could not read the contents of Media Error opening the directory of '/media': permission denied  Output of active Snap  is below: $ snap interfaces  | grep -v &quot;.*-$&quot; Slot                             Plug :browser-support                 organize-my-files :core-support                    core:core-support-plug :cups-control                    gedit :desktop                         gedit,organize-my-files :desktop-legacy                  gedit,organize-my-files :gsettings                       gedit,organize-my-files :home                            arduino-mhall119,gedit,organize-my-files :network                         arduino-mhall119,gedit,organize-my-files,pulsemixer :opengl                          organize-my-files :pulseaudio                      organize-my-files,pulsemixer :unity7                          arduino-mhall119,gedit,organize-my-files :wayland                         gedit :x11                             arduino-mhall119,organize-my-files,pulsemixer gnome-3-26-1604:gnome-3-26-1604  gedit gtk-common-themes:gtk3-themes    gedit gtk-common-themes:icon-themes    gedit gtk-common-themes:sound-themes   gedit -                                arduino-mhall119:serial-port -                                gedit:avahi-observe -                                gedit:mount-observe  Updates:  connecting mount-observe to Gedit with snap connect gedit:mount-observe does not help. it seems that we need special Snap with support of  interface.
Say that Player X is 2nd in the initiative. 1st is the Black Court vampire that is in a rage and taking a swing at Player X. Player X gets a built in defense [Athletics/Fists + 4dF] but can Player X instead use his action this turn to cast his Rote Evocation Shield?  It is not his turn in the initiative order. A Block is an Action that a Player can take on his turn.   Thematically though, it seems to make sense that the char could cast a Rote Evocation Shield in response to an attack ahead of him in the initiative order. At least thematically in the books. Also, the example in YS252, shows him reacting to an attack by Agatha Hagglethorn by bring up his shield.  I am hoping there is some as yet undiscovered dark corner where this concept is covered or squashed. The word "quad" generally means 4. Quadratics don't have 4 of anything. Can anyone explain where the name comes from? How to call alert after all ajax requests are done? Do I need a transit visa at Istanbul Airport to enter Istanbul for city sightseeing or hotel accommodation?. All services provided free by the Turkish Airline. I am Nigerian citizen and booked Turkish Airline flight to Nigeria with 12hours layover at Istanbul Airport. Connect Error (2054) - mysql_old_password issue still not solved Surface of genus $g$ does not retract to circle (Hatcher exercise) I'm trying exercise 9 on page 53 in  but I need some help with it. The exercise is:  In the surface $M_g$ of genus $g$, let $C$ be a circle that separates $M_g$ into two compact subsurfaces $M_h^\prime $ and $M_k^\prime$ obtained from the closed surfaces $M_h$ and $M_k$ by deleting an open disk from each. Show that $M_h^\prime$ does not retract onto its boundary circle $C$, and hence $M_g$ does not retract onto $C$. [Hint: abelianize $\pi_1$.] But show that $M_g$ does retract onto the nonseparating circle $C^\prime$ in the figure.    My first question is: assume there wasn't the hint, how would I think of abelianising? What does it mean exactly?  I thought I could do this by contradiction: if it retracts the induced map $i_\ast : \pi_1(C) \rightarrow \pi_1(M_h^\prime) $ is injective. I know $\pi_1(C) \cong \mathbb{Z}$, then I computed $\pi_1(M_h^\prime) \cong \mathbb{Z}$ and then I think I'm stuck. Right? Do you agree with $\pi_1(M_h^\prime) \cong \mathbb{Z}$ and being stuck after that?  What do I need to know to make progress? Many thanks for your help! Successfully connected to a bluetooth speaker, but how do i direct sound there? Kind of converse of Kolmogorov maximal inequality Let $S_n=\zeta_1+...+\zeta_n$ where $\zeta_i$ are independent with $E\zeta_i=0, E\zeta_i^2=\sigma_i^2&lt;\infty, |\zeta_i|&lt;K$.  Then, $P(\max_{1 \leq m  \leq n}|S_m| \leq x) \leq (x+K)^2/\operatorname{var}(S_n)$.  How do we show this?  The hint says that I should use the fact that $S_n^2-\sum_{m \leq n}\sigma_m^2$ is a martingale. But I am totally clueless....  Any hint would be appreciated! Thanks and regards. Extra semicolon near answers header On all the SE sites that I checked, the text that normally says something like “1 Answer” now says “1 Answer;” (with a semicolon seemingly in superscript):    The HTML for that part of the page looks like this (the semicolon is on the fourth line from bottom):              &lt;div id="answers"&gt;                  &lt;a name="tab-top"&gt;&lt;/a&gt;                 &lt;div id="answers-header"&gt;                     &lt;div class="subheader answers-subheader"&gt;                         &lt;h2&gt;                                 1 Answer                         &lt;/h2&gt;                         &lt;div&gt;                             &lt;div id="tabs"&gt;         &lt;a href="/questions/18587301/which-is-good-il-editor?answertab=active#tab-top" title="Answers with the latest activity first"&gt;             active         &lt;/a&gt;         &lt;a href="/questions/18587301/which-is-good-il-editor?answertab=oldest#tab-top" title="Answers in the order they were provided"&gt;             oldest         &lt;/a&gt;         &lt;a class="youarehere" href="/questions/18587301/which-is-good-il-editor?answertab=votes#tab-top" title="Answers with the highest score first"&gt;             votes         &lt;/a&gt; &lt;/div&gt; ;                         &lt;/div&gt;                     &lt;/div&gt;                 &lt;/div&gt; Prove that a set of connectives is inadequate It is relatively easy to prove that a given set of connectives is adequate. It suffices to show that the standard connectives can be built from the given set. It is proven that the set $\{\lor, \land, \neg\}$ is adequate, and from that set it can be inferred (applying De Morgan laws and such) that $\{\lor, \neg\}$, $\{\land, \neg\}$ and $\{\to, \neg\}$ are also adequate.  Nevertheless, I'm stuck trying to understand how to prove that a given set of connectives is inadequate. I know I have to prove that a standard connective can't be build using only the connectives of the given set, but I can't figure out how to do it.  FYI, I'm trying to prove that $\{\lor, \land\}$ and $\{\leftrightarrow, \neg\}$ are inadequate sets of connectives.  Thanks in advance. Isomorphism $H_n(D^n, S^{n - 1};A)$ and $A$ The homomorphism $a \mapsto [[a \cdot f]]$ is supposed to be an isomorphism between $A$ and $H_n(D^n, S^{n - 1};A)$ for any homeomorphism $f: \Delta^n \to D^n$. I have proven that it is well defined and injective, but why is it surjective?  The group $H_n(D^n, S^{n - 1};A)$ is generated by elements of the form $a \cdot \sigma + b \cdot \tau + c \cdot \partial(\kappa)$ where $\sigma: \Delta^n \to D^n$, $\tau: \Delta^n \to S^{n - 1}$ and $\kappa: \Delta^{n + 1} \to D^{n + 1}$ and I do not see how an element of this form represents the same equivalence class of $[[m \cdot f]]$ for some $m \in A$. We can write $\sigma$ as $f f^{-1} \sigma$ to get $f$ in there, but I don't see that working out. Any hints? AWS S3, Paperclip missing required :bucket option Word 2010 Number of pages without first page I show the number of pages as 1 / 4, with 4 being the total number of pages. But I do not want to count the first page.  Important: I know how to do it for the current page number (Starting at ..), I mean the total number of pages.  So if the document has one cover page + 3 pages, I want to show it as 1/3, 2/3 ..., not as 1/4. What is an intuitive way of understanding Ostrogradsky instability? Is there a way of explaining why no differential equations in physics exceed order two without delving into Lagrangian and Hamiltonian mechanics - i.e. from Newtonian mechanics? Moreover, is there such an alternative proof, which focuses more on physical reasoning than abstract mathematics? How does linear regression use the normal distribution? In linear regression, each predicted value is assumed to have been picked from a normal distribution of possible values. See below.  But why is each predicted value assumed to have come from a normal distribution? How does linear regression use this assumption? What if possible values are not normally distributed? Is it true that $(R\times S)[G]\cong R[G]\times S[G]$? Capitalize and punctuate "let us continue this discussion in chat" Stack Exchange has a feature to help move extended discussions out of comments and into chat, but when you use it, it automatically writes the following message for you:  let us   Could we get the orthography fixed?  I'd like it to read:  Let us .  That's a capital letter at the beginning and a period at the end. Is there any "superlogarithm" or something to solve $x^x$? Is there any "superlogarithm" or something to solve an equation like this:  $$x^x = 10?$$ Random plot based on a specific random seed While I was investigating a problem I had with lexical closures in Javascript code, I came along this problem in Python:  flist = []  for i in xrange(3):     def func(x): return x * i     flist.append(func)  for f in flist:     print f(2)   Note that this example mindfully avoids lambda. It prints "4 4 4", which is surprising. I'd expect "0 2 4".   This equivalent Perl code does it right:  my @flist = ();  foreach my $i (0 .. 2) {     push(@flist, sub {$i * $_[0]}); }  foreach my $f (@flist) {     print $f-&gt;(2), "\n"; }   "0 2 4" is printed.  Can you please explain the difference ?    Update:   The problem is not with i being global. This displays the same behavior:  flist = []  def outer():     for i in xrange(3):         def inner(x): return x * i         flist.append(inner)  outer() #~ print i   # commented because it causes an error  for f in flist:     print f(2)   As the commented line shows, i is unknown at that point. Still, it prints "4 4 4".