I can press like more than 5 buttons in my keyboard at same time but if hold these 3 buttons { D+(S or A or W)+ I } together I can't press anything else after them Thanks.
When I slam my hand onto my keyboard, only a maximum of 6 keys will be registered, I've tested this for the past few minutes and was unable to get more than 6. Is this the same on all keyboards? If not, what would be the distinguishing factor, If yes: why 6 specifically?  For clarification: I do not have a usecase for this, I am simply curious
How to center text vertically within a textbox in Photoshop It's pretty annoying that you can't center text vertically in Ps automatically, like you can in Indd. It's even more annoying that the bounding box of text can't be 'collapsed' or 'fit to text', like in Indd.  I could convert the text to shape, but then I lose coloring. I could convert to smart object, but then its not vector anymore, for when I export to pdf.  Is there a work around anyone knows of that would make it easier to center text vertically? Using separation of variables to solve the wave equation Expressing Gain in Decibels? What is the difference between "I've been to China" and "I've gone to China"? Different probability density transformations due to Jacobian factor What is the simplest way to generate a dodecahedron? I've been thinking of animating some dice and while most are easy to make, I'm having some trouble figuring out a way to generate a regular dodecahedron. I could hand build it but it would be potentially uneven. Would using the base of a 5 sided cylinder and then some variation on spin be the best option or is there a better way? Why does an object with a glossy shader render in black? When I apply a glossy shader to the material of my text, the text becomes just black. Why?    I have lamp and everything, but the problem persists. The text is red before I add the glossy shader.  I'm using Cycles render.   Thanks! Prove that $(a+1)(a+2)...(a+b)$ is divisible by $b!$ The problem is following, prove that:  $$(a+1)(a+2)...(a+b)\text{ is divisible by } b!\text{ for every positive integer a,b}$$    I've tried solving this problem using mathematical induction, but I don't think that i did it correctly. Here's what i've done  $1.\ b=1\ (Basis)$  $$b!| (a+1)(a+2)...(a+b)$$ $$1 | a+1 \text{, which is true}$$  $2.\ b=k\ (Induction\ Hypothesis)$  $$k! | (a+1)(a+2)...(a+k)\text{, we assume it's true}$$ $$k!*n = (a+1)(a+2)...(a+k)\text{, n is some positive integer}$$  $3.\ b=k+1\ (Inductive\ Step)$  In order to prove I should get:  $$(k+1)!*m = (a+1)(a+2)...(a+k)(a+k+1)\text{, where m is some positive integer}$$ $$(a+1)(a+2)...(a+k)(a+k+1) = k!*n*(a+k+1)$$ $$(a+1)(a+2)...(a+k)(a+k+1) = (k+1)!*n + k!*n*a$$ $$(a+1)(a+2)...(a+k)(a+k+1) - a(a+1)(a+2)...(a+k) = (k+1)!*n$$ $$(a+1)(a+2)...(a+k)(k+1) = (k+1)!*n$$  And as you can see I'm returning at the beginning.  Also I've tried to use the fact that in b consecutive numbers, there must be at least one that divides b, but since i eliminate that number (because I couldn't be sure that the quotient is divisible with (b-1) or (b-2) or ... or 2. And after this i can't continue with (b-1) using this method, because it's not necessary for the other (b-1) to be consecutive. Why should I use an Initialization Vector (IV) when I have unique keys? I took a look at  but my question is not the same.  I have unique keys encrypting each plaintext (in CBC mode, AES-256) and I do not use a key to encrypt more than one plaintext. Is it insecure to use null IVs in this case? If it is insecure, why? I am trying to burn a shapefile to a raster using GDAL's RasterizeLayer. I pre-create an area of interest raster from a different shapefile, given a specific pixel size. This AOI then serves as a base for all following rasterizations (same number of collumns and rows, same projection and geotransform).  The issue occurs, however, when I go to burn the shapes to their own raster, based on the same pixel size and projections. The link below (don't have enough rep to post the image), shows the original shapefile in tan, and the dark pink where RasterizeLayer has burned data. The light pink is nodata values for the dark pink raster data. The grey is the AOI based on which the shapefile burn was completed.  Given the extents of the shapefile polygons, I would expect to see burn values in the bottom two corners, as well as the two pixels underneath the data that does show. Obviously, however, this is not the case.    As follows is the code that I used to generate these. All of the shapes were created using QGIS, and were all created in the same projection.  (It should be noted that the gridding in the picture shown was just to give an idea of the pixel size I was using.)  from osgeo import ogr from osgeo import gdal  aoi_uri = 'AOI_Raster.tif' aoi_raster = gdal.Open(aoi_uri)  def new_raster_from_base(base, outputURI, format, nodata, datatype):      cols = base.RasterXSize     rows = base.RasterYSize     projection = base.GetProjection()     geotransform = base.GetGeoTransform()     bands = base.RasterCount      driver = gdal.GetDriverByName(format)      new_raster = driver.Create(str(outputURI), cols, rows, bands, datatype)     new_raster.SetProjection(projection)     new_raster.SetGeoTransform(geotransform)      for i in range(bands):         new_raster.GetRasterBand(i + 1).SetNoDataValue(nodata)         new_raster.GetRasterBand(i + 1).Fill(nodata)      return new_raster  shape_uri = 'activity_3.shp' shape_datasource = ogr.Open(shape_uri) shape_layer = shape_datasource.GetLayer()  raster_out = 'new_raster.tif'  raster_dataset = new_raster_from_base(aoi_raster, raster_out, 'GTiff',                                 -1, gdal.GDT_Int32) band = raster_dataset.GetRasterBand(1) nodata = band.GetNoDataValue()  band.Fill(nodata)  gdal.RasterizeLayer(raster_dataset, [1], shape_layer, burn_values=[1])   Is this a bug in GDAL, or is RasterizeLayer burning data based on something other than just the presence or lack of a polygon within a specified pixel area?  The files that I was using can be found . Is Autopilot Openstack 16.04 available? I use dd in its simplest form to clone a hard drive:  dd if=INPUT of=OUTPUT   However, I read in the manpage that dd knows a blocksize parameter. Is there an optimal value for the blocksize parameter that will speed up the cloning procedure? Batch File Copy and Move without overwriting I'm trying to create a batch file (to run in the background) that will copy a single file without overwriting any file in the destination with the same name, and then move the file, again not overwriting if there is a file in the destination with the same name?  I'm using this at the moment, but it is overwriting.  copy %1 dest move %1 dest $\lim_{n\to \infty}f(nx)=0$ implies $\lim_{x\to \infty}f(x)=0$ Can anyone help me with this problem?     Let $f:[0,\infty)\longrightarrow \mathbb R$ be a continuous function such that for each $x&gt;0$, we have $\lim_{n\to \infty}f(nx)=0$. Then prove that $\lim_{x\to \infty}f(x)=0$.   Our teacher told first to prove Baire's theorem, and then show that this is a consequence of that theorem. I proved Baire's theorem, and I spend a few hours thinking on how Baire's theorem is related to this problem, but I couldn't find anything. I'd really appreciate your help. If the big bang was the birth of everything, and the big bang was an event in the sense that it had a location and a time (time 0), wouldn't that mean that our universe has a center?  Where was the big bang? What is there now? Are we moving away from the center still? Are these even valid questions? How to smooth camera animation to have fluid feel? When dealing with camera motion, its very sensitive to any movement discontinuities. Is there a way to easily achieve natural looking motion when dealing with complicated motion paths and timings?  Follow path animation feels too robotic unless I adjust all the keyframe easings carefully and this has to be re-done everytime the animation changes (the automatic bezier type just doesn't work). How does Delta baryon decay conserve angular momentum? jQuery/JavaScript to replace broken images It would be nice to  for .  As it is, SE kind of stands out (in a not cool way): Please could someone tell me where can I download Ubuntu 32bit without using a torrent? Thanks