I'm capturing screenshot from a XAML element using the  plugin and it returns me a Stream.    public ICommand CaptureCommand =&gt; new Command&lt;VisualElement&gt;(OnCapture);     async void OnCapture(VisualElement element)    {        var stream = await element.CaptureImageAsync();    }    How can I save the image I have captured using the Stream I got to a folder on my Android device as a png file?
I have a StreamReader object that I initialized with a stream, now I want to save this stream to disk (the stream may be a .gif or .jpg or .pdf).  Existing Code:  StreamReader sr = new StreamReader(myOtherObject.InputStream);    I need to save this to disk (I have the filename). In the future I may want to store this to SQL Server.   I have the encoding type also, which I will need if I store it to SQL Server, correct?
Splitting pieces of a mesh into a new object Which graphics formats can be included in documents processed by latex or pdflatex? There several types of graphics files. In no particular order .jpeg .eps .pdf .png .tif .jif (and no doubt others). Some work with latex, dvips and some work with pdflatex. How am I supposed to know which?  Just to confuse matters, metapost produces .eps but I can use these with pdflatex as long as I put in a four line incantation.  Can anyone explain this? Java - How to reduce the size of third-party jars to reduce the size of your application Virtual box is not working on windows 10 What is the physical significance of the imaginary part when plane waves are represented as $e^{i(kx-\omega t)}$? I've read that plane wave equations can be represented in various forms, like sine or cosine curves, etc. What is the part of the imaginary unit $i$ when plane waves are represented in the form $$f(x) = Ae^{i (kx - \omega t)},$$ using complex exponentials? I've recently installed pgAdmin 1.18.1 and noticed a strange thing:  Long json query results are shortened to 256 symbols and then ' (...)' is added.  Could someone help me disable this shortening? Rules for Profiles Are there any rules concerning what I can put in my profile? Is there an Autocorrect feature in TeXStudio 2.6.2? I was wondering if there's an Autocorrect feature in TexStudio 2.6.2 that works like in MS Word so that if I have to type a certain word many times, the editor writes it for me as soon as I press spacebar after I finish typing the shortcut for that particular word. (Eg. phl --> photolithography)   I've already searched StackExchange for similar questions and read Qrrbrbirlbel's comment  . I've tried my hand at the Macros but it's not working properly, maybe some bug that needs TeXStudio to re-start for it take action or maybe I simply don't know how to make it work.  Can someone help me, please? Can I travel to Schengen countries that were not on my itinerary when I applied? Recurrence relation for right-angled triangles stuck-together Show $f(x)=x\ln x$ is not uniformly continuous Show $f:(0,\infty)\rightarrow \mathbb{R}, f(x)=x\ln x$ on $(0,\infty)$ is not uniformly continuous.    I think that the general way to prove that something is not continuous in a metric space is to let $\epsilon=...$ and show that $\forall\delta&gt;0$, $d&#39;(f(x)-f(y))&gt;\epsilon$. I can't use the Mean Value Theorem because we haven't gone over it yet.    Here's an attempt: Let $\epsilon=1$. Without loss of generality, let $x&gt;y&gt;0$. $|x\ln x-y\ln y|&lt;|(x-y)(\ln x)|\leq|x-y||\ln x|$...$\delta=\frac{\epsilon}{\ln x}$ and therefore doesn't work for all $x$? Suppose $G$ is a semigroup and it holds both left and right cancellation. Suppose $G$ is a semigroup and it holds both left and right cancellation. Also for each $a,b\in G$, $xa=b$ has solution in $G$. Prove G is a group.   I know this question looks very "old" style. First I think it's easy for me too since I already practice probelems like "semigroup, $xa=b$ and $ax=b$ have solution , then group" Or "finite semigroup, both left and right cancellation hold, then group ". But I still get stuck... My try:  First of course, for $xa=a$ , there exists $e_a$ such that $e_aa=a$. Now we need to proof $e_a$ is left identity for all elements. Then left inverse exists hence $G$ is a group. But the key is to proof $e_ab=b$ for all $b\in G$. Convert one date format into another in PHP If $A^{2n}=I$, then $A^n=\pm I$ where $A\in M_n(\mathbb{R})$ Let $A\in M_n(\mathbb{R})$be a matrix. Then, if we have $A^{2n}=I$, can we say that $A^n=\pm I$?  I think yes, because the annihilating polynomial is $x^{2n}-1$. Therefore the characteristic polynomial should be one of $x^n-1$ or $x^n+1$. Thus, since the matrix consists of real numbers, therefore, the matrix $A^n=\pm I$. Am I wrong?Thanks beforehand. Do multi-use keys get discarded when finished with? As with many resident evil games, you sometimes needs to collect certain keys to open certain doors, and resident evil 7 has plenty of these around.  Some keys are clearly single use, and get left in the lock in which you use them. However, there are a number of keys that can be used on multiple doors. For example, the Scorpion Key.  I am concerned that I might end up carrying these around needlessly and using up valuable inventory space, so...  Do these multi-use keys get discarded when you use them on all the doors they apply to? Or do you get a warning saying the key is no longer needed? (like previous games are known to do) I'm having an odd issue - When I try to zoom in on a detail using my MMB, the "camera" in the 3D view seems to be cutting off the exterior surface of my object and showing me the inside instead. I'd expect this behavior, but only when I was much more zoomed in.  If I zoom out a bit (one click on the scroll wheel) then I can see the exterior as I intend.  Is there any way to adjust this behavior?  Thanks! I've been stuck on this problem for about an hour.     In an ideal transformer, the same flux passes through all turns of the primary and of the secondary . Show that in this case $M^2=L_1L_2$, where $M$ is the mutual inductance of the coils, and $L_1$, $L_2$ are their individual self-inductances.   My first instinct was the following: If we isolate the response of each coil to the other one, we get the equations $N_1\Phi_1=MI_2$ and $N_2\Phi_2=MI_1$, where $\Phi$ is magnetic flux going through a single turn of the coil and $I$ is current. Likewise, if we isolate the response of each coil to itself, we get the equations $N_1\Phi_1=L_1I_1$ and $N_2\Phi_2=L_2I_2$. I would now naturally want to say "Now just multiply $N_1\Phi_1$ and $N_2\Phi_2$ both ways, and get the desired result!" i.e.,  $$(N_1\Phi_1)(N_2\Phi_2)=(MI_2)(MI_1)=(L_1I_1)(L_2I_2)\implies M^2=L_1L_2$$  But that's incorrect, because the response of the coils to themselves and to the other coil are different quantities (i.e. not necessarily equal).  Realizing this, I write down the more general equations.  $$N_1\Phi_1=MI_2+L_1I_1$$ $$N_2\Phi_2=MI_1+L_2I_2$$  Now even with the hypothesis that $\Phi_1=\Phi_2=\Phi$, I still can't see how the identity $M^2=L_1L_2$ follows. Could you help clear up my confusion?  *Taken from D. Griffiths Introduction to Electrodynamics (4th ed.), Problem 7.58. SyntaxError: invalid syntax // SyntaxError: unexpected EOF while parsing How do I detect text inside of this, this is HTML &amp; this is XPath. I tried  HTML     &lt;span class="messageText"&gt;Hello.&lt;/span&gt; XPath     //*[@id="liveAgentChatLogText"]/span[22]/span[2]   I tried with this but it didn't work, it said no such element found.  driver.find_element(By.XPATH, '//*[@id="liveAgentChatLogText"]//*[contains(string(.), "Hello")]') Total combinations from number of unique combination? How can you find count of the total combinations possible if you have the count of unique combinations? Suppose I need to form a sum of $3$ using $\{1,2\}$ Unique combn. $(1+1+1)$, $(1+2)$ hence '$2$' unique but total is '$3$' i.e, $(1+1+1)$, $(1+2)$, $(2+1)$ I know the elements used to make the combination Note: Number of unique combinations (ie. 2 here) is known. How can I find the total number of combination given the unique combinations? One hour Lufthansa transit time in Frankfurt from Bangalore to Dublin