Does Platform 9 3/4 have some sort of Magical Blood Detection Charm?   For example, let's say that a Muggle saw a Hogwarts student pass through Platform 9 3/4 as though the wall was intangible, what would happen if the Muggle attempted to do the same? Would a charm exist to block them off since they don't have magical genes?  Does the same apply to Squibs? Or since they have wizard genes, but just repressed and not active, they can pass through the Platform?
Suppose someone from "Harry's world" married a Muggle, and they want to escort their child. Can the Muggle parent get through to the Hogwarts platform?
How to connect to Android through SSH over 3G/4G public IP? Why doesn't bash expand this variable when I prefix a command with a "one time variable assignment" If I run this bash command and prefix the statement, so that the variable fruit should exist, but only for the duration of this command:  $ fruit=apple echo $fruit  $   The result is an empty line. why?  To quote a comment from wildcard on :     parameter expansion is done by the shell, and the "fruit" variable is   not a shell variable; it's only an environment variable within the   environment of the "echo" command   An environment variable is still a variable, so surely this should still be available to the echo command? How to switch from Resident visa to Tourist visa status in the Schengen area? I have a 1-year residence permit from one Schengen country that is now expiring. Upon its expiration, I would like to get my 90/180 days validity as a tourist to stay, or return here as soon as possible.  I understand that the tourist short-stay scheme is based on the 90/180 days "counter". But what happens if my previous stay was not tourism but residence (as searching year). Wouldn't that mean that I can quickly exit and re-enter the Schengen area to activate my tourist stay?   Also, is there a way to change this purpose of stay without exiting the Schengen area? Defining commands/abbreviations that contain numbers I tend to use \newcommand to define macros for symbols I use often, e.g. \newcommand{\hankel}{H^{(1)}_0}.  One inconvenience of this approach is the fact that command names cannot include numbers.  What I ideally want is to map something like \H0 to H^{(1)}_0.  I imagine this could be done with some macro expansion/snippet package, or one might use \newcommand to define a command that takes a parameter, etc.  Before I start experimenting, though -- is there a canonical way of dealing with this problem? How do we initialise unpacked arrays in Verilog? Suppose I declare an unpacked array of size say 8 bits wide. reg b[7:0];  If I want to assign b[7] = 1,b[6] = 1, b[5] = 1, ......b[0] = 1, then apart from assigning value to each bit is there a way to assign any combination of bits say 8'bA8, to b? For instance if I execute this code(below) in verilog: module tb();     reg [7:0]a;     reg b[7:0];     initial begin         $monitor(&quot;a = %b,b = &quot;,a);         a = 8'hA8;         b = 8'hA8; // Line 7     end endmodule  I get this error: C:\iverilog\bin&gt;iverilog -o a test.v test.v:7: error: Cannot assign to array b. Did you forget a word index? 1 error(s) during elaboration.  I am using Icarus Verilog on a command prompt on Windows 10 operating system. How can I tell what version of Linux I'm using? Often times I will ssh into a new client's box to make changes to their website configuration without knowing much about the server configuration. I have seen a few ways to get information about the system you're using, but are there some standard commands to tell me what version of Unix/Linux I'm on and basic system information (like if it is a 64-bit system or not), and that sort of thing?  Basically, if you just logged into a box and didn't know anything about it, what things would you check out and what commands would you use to do it? These may be separate questions, but the following MWE:    \usepackage{pdfpages} ...   \addcontentsline{lot}{subsection}{\ref{tab:UserRoles} \textbf{User Roles}}   \includepdf[pages={-}, pagecommand={\label{tab:UserRoles}}, offset=0in -1in, addtolist={9, table, {The User Roles table}, tab:UserRoles}]{UserRolesTable}   ...   has several unexpected behaviors.   I get the following warning:  Package pdfpages Warning: There's something wrong with the entries of `addtolist'. Not all entries were processed. Check `addtolist' [in the MWE]."    Probably due to the \label not being bound to the inserted pdf (in a table environment), my inserted PDF is numbered using the section, and not the expected "Table X" value.   The manually-inserted LoT line (which also uses the section number rather than the incremented table number) is not formatted like the other lines in the LoT - the number lines up, but the table caption itself is not aligned with the others in the list.   The source PDF has no errors and displays correctly in the output PDF.  PDFLaTeX -> BibTex    MWE:  \documentclass[11pt,letterpaper,twoside,final]{article} \usepackage{pdfpages} \begin{document} \listoftables \begin{center} \textbf{Table \ref{tab:UserRoles} - The User Roles Table} \addcontentsline{lot}{subsection}{\ref{tab:UserRoles}  \textbf{User Roles}} % manual entry in ToC  \includepdf[pages={-}, pagecommand={\label{tab:UserRoles}}, offset=0in -1in, addtolist={9, table, {The User Roles table}, tab:UserRoles, lot}]{UserRolesTable} \end{center} \end{document} I want my intent to be launched when the user goes to a certain url: for example, the android market does this with  urls. so does youtube. I want mine to do that too. If $\sum{a_n}$ converges does that imply that $\sum{\frac{a_n}{n}}$ converges? I know if $\sum{a_n}$ converges absolutely then $\sum{\frac{a_n}{n}}$ converges since $0\le \frac{|a_n|}{n} \le |a_n| $ for all $n$ so it converges absolutely by the basic comparison test and therefore converges. However, I cannot prove the convergence of $\sum \frac{a_n}{n}$ if $\sum{a_n}$ converges but not absolutely even though I suspect it to be true. Can you give me a proof or a counterexample for this? Qualcomm Atheros AR9462 with Ubuntu 18.10 I can't enable the Wifi (nothing happens when press enable button) and in Wifi settings it says:     "No Wi-Fi Adapter Found"   I have tried several things from other questions/answers here but nothing worked. Here some information if this is helpful for the answer:     Device: Lenovo Miix 2 11   sudo lspci:  Network controller: Qualcomm Atheros AR9462 Wireless Network Adapter (rev 01)   sudo lshw -C network:  *-network DISABLED            description: Wireless interface    product: AR9462 Wireless Network Adapter    vendor: Qualcomm Atheros    physical id: 0    bus info: pci@0000:02:00.0    logical name: wlp2s0    version: 01    serial: 48:d2:24:8a:ea:e6    width: 64 bits    clock: 33MHz    capabilities: pm msi pciexpress bus_master cap_list rom ethernet physical wireless    configuration: broadcast=yes driver=ath9k driverversion=4.18.0-16-generic firmware=N/A latency=0 link=no multicast=yes wireless=IEEE 802.11    resources: irq:18 memory:f0400000-f047ffff memory:f0480000-f048ffff   sudo lsmod | grep ath:  ath3k                  20480  0 bluetooth             548864  12 btrtl,btintel,btbcm,bnep,ath3k,btusb ath9k                 151552  0 ath9k_common           36864  1 ath9k ath9k_hw              475136  2 ath9k_common,ath9k ath                    36864  3 ath9k_common,ath9k,ath9k_hw mac80211              794624  1 ath9k cfg80211              663552  5 wl,ath9k_common,ath9k,ath,mac80211   In system settings it shows the Wifi-Adapter Name:  Qualcomm Atheros AR9462   Edit:  lspci -knn | grep Net -A3; rfkill list:  02:00.0 Network controller [0280]: Qualcomm Atheros AR9462 Wireless Network Adapter [168c:0034] (rev 01) Subsystem: Lenovo AR9462 Wireless Network Adapter [17aa:3214] Kernel driver in use: ath9k Kernel modules: ath9k, wl 0: phy0: Wireless LAN     Soft blocked: no     Hard blocked: no 1: ideapad_wlan: Wireless LAN     Soft blocked: no     Hard blocked: yes 2: ideapad_bluetooth: Bluetooth     Soft blocked: yes     Hard blocked: yes Website is under maintenance - how to restrict access? I remember that the main character is trying to find the group that destroyed his home planet while he was on a mission. His planet was very difficult to live on and the people became expert in martial arts and were the best soldiers in the galaxy. They were mercenaries and often helped against tyrants. There was a very memorable section in at least one book about an initiation task that the main character had to do in that he had to survive in their wilderness for days. He was at some point surrounded in a old building by thousands of poisonous worm/snake creatures that he managed to survive until rescued by the leaders. Unable to use built in events (Event Reference) Salesforce has functions that do a lot of basic web app functionality for you, called Event Reference. They can be found here   On the editRecord Event Reference, found here   essentaily, I create a   &lt;ui:button label="Edit" press="{!c.editRecord}"/&gt;   on my component, reference the attribute on the page and add the function from the docs in the controller  editRecord : function(component, event, helper) {     var editRecordEvent = $A.get("e.force:editRecord");      console.log("record id is: " + component.get("v.item.Id"));     console.log("editRecordEvent value is: " + editRecordEvent);      editRecordEvent.setParams({         "recordId": component.get("v.item.Id")     });      editRecordEvent.fire(); }   correct?  Here is the odd thing. From the console.logs, I get the record id, but the editRecordEvent returns undefined. What is going on? Is there something I need to reference in my component to use Event Reference? What is the difference between CentOS "DVD" vs "Everything" ISOs What is the connection between Poisson brackets and commutators? The Poisson bracket is defined as:  $$\{f,g\} ~:=~ \sum_{i=1}^{N} \left[  \frac{\partial f}{\partial q_{i}} \frac{\partial g}{\partial p_{i}} - \frac{\partial f}{\partial p_{i}} \frac{\partial g}{\partial q_{i}} \right]. $$  The anticommutator is defined as:  $$ \{a,b\} ~:=~ ab + ba. $$  The commutator is defined as:  $$ [a,b] ~:=~ ab - ba. $$  What are the connections between all of them?  Edit: Does the Poisson bracket define some uncertainty principle as well? Can you tell me the difference in the meaning of the two sentences below?  As a defining relative clause.     The location which was called Central Park was a park in New York.    As a non-defining relative clause.     The location, which was called Central Park, was a park in New York. Why crontab scripts are not working? Solve the integral $\int_0^\infty x/(x^3+1) dx$ I'm new here!  The problem: integrate from zero to infinity x over the quantity x cubed plus one dx. I checked on wolfram alpha and the answer is that the indefinite integral is this:  $$\int \frac{x}{1+x^3} dx = \frac{1}{6}\left(\log(x^2-x+1)-2 \log(x+1)+2 \sqrt{3} \arctan((2 x-1)/\sqrt{3})\right)+\text{constant}$$  and the definite integral is this:  $$\int_0^\infty \frac{x}{1+x^3} dx = \frac{2 \pi}{3 \sqrt{3}}\approx 1.2092$$  I am trying to figure out all the steps in between. I see that there are logs, which are equivalent to the ln variant that i am more familiar with, which means it was integrating $1/x$ at some point; I also see an inverse tangent in there.  I started with long division to simplify and I got (which could be wrong because I am very tired right now) $x/(x^3+1) = x^2+ 1/(x^3+1)$ which seems to be a step in the right direction. Wolfram Alpha thinks I definitely did that step wrong. The two equations do not evaluate as equal.  Then I cheated and took the wolfram alpha factorization of $(x^3+1) = (x+1)(x^2-x+1)$...I probably should have known that but didn't offhand. Now it is looking like $x^2$ plus the partial fraction decomposition $1/(x^3+1) = A/(x+1)+(Bx+C)/(x^2-x+1)$. Am I heading in the right direction with this? At this point do I just plug in and crunch? Are there surface-mount pin header footprints for KiCAD? Is it possible to terminate a running thread without setting/checking any flags/semaphores/etc.?