I am trying to bind a custom command to the key binding SUPER+P. I found that it doesn't work when the Unity plugin is enabled in the CompizConfig settings manager, but it does work when Unity is disabled.  All the keybindings listed in the Unity plugin settings are disabled. But it seems as though SUPER+P is being bound regardless.   Does anyone have suggestions on how I can get SUPER+P to run my command without disabling Unity plugin?
In ubuntu 11.04 there was a workaround using gconf-editor and setting key /apps/gnome_settings_daemon/plugins/xrandr/active to false.  However there is no such key in gconf-manager using ubuntu 11.10 (gnome 3).
What stops other benders from mastering the four elements? How many points in RSA, such that $m^e = m \bmod n$ For every RSA-cryptosystem, there exist some messages $m$, for which it holds that $m^e \equiv m \pmod n$ As to the question, how many such messages exist, this question has already been asked and answered here:  However, I do only understand the answer up to a certain point Suppose that $n$ is only 1 prime. Then it holds that the number of unconcealable messages is $\gcd(e-1, p-1)+1$ This is because in $m^e \equiv m \pmod  p$ , either $m = 0$ or $m \not= 0$. In the latter case $m$ can be expressed as $g^t$, where $g$ is a Generator in $\mathbb{Z_p}$ $g^{t*e} \equiv g^t \pmod p$ $g^{t(e-1) \bmod p -1 } \equiv g^{0 \bmod p -1} \pmod p$ $t(e-1) \equiv 0 \pmod {p-1} $ has exactly $\gcd(e-1, p-1)$  solutions, so the total number of unconcealable messages is, together with $m=0$ , $\gcd(e-1, p-1)+1$ When we now look at real RSA, which has two prime factors in its modulus, it holds that the number of unconcealable messages is $(\gcd(e-1, p-1)+1)\cdot(\gcd(e-1, q-1)+1)$ Why is that so? I suppose it has to do with CRT, but I just cant understand why. How to concatenate text from multiple rows into a single text string in SQL server? Consider a database table holding names, with three rows:  Peter Paul Mary   Is there an easy way to turn this into a single string of Peter, Paul, Mary? What is the best format to capture addresses for a universal user-base? What is the best and most usable format to capture address information from a universal user base? I was thinking to have the system detect the country by IP address and have that selected by default, and then state/province droplist would be populated accordingly. But the issue is some countries have states and provinces and some do not. Some have postal codes and some do not. Is there a universal standard to capture complete address info to ensure efficiency for most users?  FYI: I did research on here and while there are some questions that are close, none are about this exact same question (unless I missed something) I saw that it has been already reported that also they have earned courious badge but the badge has not been given. but their answers say that they must wait a day and the badge will be awarded.  In my case its 8/5 and it was 5/5 long time ago and I have never received a message telling that I have earned it. its just telling me that the next badge to be awarded is Curious badge.  this is my profile: If $x+{1\over x} = r $ then what is $x^3+{1\over x^3}$? If $$x+{1\over x} = r $$ then what is $$x^3+{1\over x^3}$$  Options: $(a) 3,$ $(b) 3r,$ $(c)r,$ $(d) 0$ How to create svg symbols that have modifiable fill color, stroke color and stroke width? I want to create some svg symbols for Qgis using Inkscape, those symbols must have attributes as described in the question. For the last two days, I have been experimenting as instructed by  and mimicked some symbols came bundled with qgis that have desired attributes without any success.  Finally I experimented with the simplest form of symbol: I created an svg that contains only a circle in Inkscape and tried to modify it.  The original file () have this line:  &lt;path    sodipodi:type="arc"    style="fill:#ffffff;fill-opacity:1;stroke:#000000;stroke-width:1.01988637;stroke-miterlimit:4;stroke-opacity:1;stroke-dasharray:none"   I modified it into:  &lt;path    sodipodi:type="arc"    style="fill:param(fill) #ffffff;fill-opacity:1;stroke:param(outline) #000000;stroke-width:param(stroke-width) 1.01988637;stroke-miterlimit:4;stroke-opacity:1;stroke-dasharray:none"   Saved as  and selected it as point symbol, but Qgis couldn't change all three parameters at the same time.  What did I do wrong or should do differently?  My system: Qgis 1.8.0 on Ubuntu 12.04 64 bit, Inkscape 0.48, Gedit 3.4.1 text editor. When is partial differentiation commutitive Consider a function: $$f:\mathbb R ^2\to\mathbb R $$ when does $$\dfrac {\partial f(x,t)}{\partial t\partial x}=\dfrac {\partial f(x,t)}{\partial x\partial t}$$  Thinking about it in terms of the limit definition of derivative,  and thinking about it as taking slices of surfaces and measuring the slope on the edge, seems to be giving me the feeling that answer is always.  However I have some memories of there being requirements like piecewise continuous, and smooth.   What is the full set of conditions? I'm looking for a closed-form expression (in terms of $n$), that will give the sequence  $$ (s_n) = \left( \frac{3}{10}, \, \frac{3}{10} + \frac{33}{100}, \, \frac{3}{10} + \frac{33}{100} + \frac{333}{1000}, \dots \right). $$  Can anyone think of one? I made a related post to this question several minutes ago but I realized I was interpreting the sequence wrong. How to run scripts without typing the full path? I'd like to know if there is a way to run  program/shell script without typing full path:  /opt/idea/bin/idea.sh Zip using Oracle Stored Procedure I have some questions with string theory:   Why is it that there is exactly 4 large spacetime dimensions while the rest remain small? It is a nonlocal QFT. How could that fit in GR? I  and am I sometimes find myself writing something like this:     XXX is a project I admire and am very interested in.   The "I &#60;verb> and am &#60;something>" feels strange here. It somehow sounds more natural in the third person: "He admires and is very interested in...."  Am I just imagining things – is it OK to use this construction, or should I use something completely different? Let $R$ be a ring such that $x^4=x$ for every $x\in R$. Is this ring commutative? I've installed Xcode and MacPorts on a brand new mid-2013 MacBook Air, but MacPorts doesn't work, saying that it cannot find anything.  mba:~ cnst$ sudo port install wget Warning: The Command Line Tools for Xcode don't appear to be installed; most ports will likely fail to build. Warning: See http://guide.macports.org/chunked/installing.xcode.html for more information. ---&gt;  Computing dependencies for wgetError: Unable to execute port: can't read "build.cmd": Failed to locate 'make' in path: '/opt/local/bin:/opt/local/sbin:/bin:/sbin:/usr/bin:/usr/sbin' or at its MacPorts configuration time location, did you move it? mba:~ cnst$   And, indeed, there is no make or clang in the path, but it is definitely installed, though:  mba:~ cnst$ find /Applications -name "clang" -or -name "make" /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/clang /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/lib/clang /Applications/Xcode.app/Contents/Developer/usr/bin/make mba:~ cnst$   Why is there no make or clang in the path?  Why MacPorts doesn't work?  I notice that  mentions that you have to install something from ADC, Apple Command Line Developer Tools, but ADC doesn't work since last Thursday or Friday due to their security breach, so, the developer tools are nowhere to be found.  What's the proper solution here? How to find all the available tools in mac terminal? I am trying to setup a bunch of development projects in my Mac. I have to run various tools like python, ruby, scala, groovy etc.  To see if a tool is available I use options like   ruby --version.    Instead I would like to see all the list of tools available in Mac terminal via a single command. What is the command/options for it? Which is correct: "one or more is" or "one or more are"? Use the result of FPeval to color a table cell I am trying to give a table cell a grayscale color value based on it's numeric value. So far I have the following code  \documentclass{article} \usepackage{fp,xcolor,colortbl} \FPeval{\resb}{0.5}  \newcommand{\he}[1]{%     \FPeval{\resa}{2 * #1}%     \cellcolor[gray]{\resa}%     #1  }  \begin{document} \begin{tabular}{| c | c | c |}     \hline     \he{0.1} &amp; \he{0.2} &amp; \he{0.3} \\     \hline     \he{0.5} &amp; \he{0.8} &amp; \he{1.0} \\     \hline \end{tabular} \end{document}   The tables contain all floating point numbers. The error I get is :   Undefined control sequence. &lt;argument&gt; \resa    Is there a way I can use the result from the FPeval to color the cell? Let $\{a_n\}$ be defined as follows: $$a_1 = 2, a_{n+1}=\dfrac{1}{3-a_n}$$ $n \geq 1$.   Does $\{a_n\}$  converge?    Using the monotone convergence thereom, if the sequence is both bounded below and decreasing, $\forall n\in\mathbb{N}, n\geq 1$, then we can say the sequence converges.  I'm having trouble proving that the sequence is bounded below by induction.    Claim: The sequence is bounded below by $0$.  Base Case:  $n=1$  $a_1 = 2 \geq 0$, so this holds.  Induction Step  Suppose that $a_k \geq 0$, for some $k \in\mathbb{N}$. (IH)  Prove $a_k \geq 0\to a_{k+1} \geq 0$  I have some difficulty here.  $a_{k}=\dfrac{1}{3-a_{k-1}} \geq 0$  $a_{k+1}=\dfrac{1}{3-a_{k}}$, but we know $a_k \geq 0$, but we don't know how much bigger. It could be that $a_k = 4$, and then I have $a_{k+1}=\dfrac{1}{3-4}$, which is negative, and does not confirm with my claim of being bounded below by $0$. Have I gone somewhere wrong in my induction? Photoshop resize circularly