I didn't see this answered satisfactorily anywhere, so I figured I'd ask.  Every time I go to do something requiring privileges, such as install a program, open restricted folders, etc., I'm prompted for the account password, even though my user account is an administrator.  How do I get it to stop prompting me for my password when doing such actions?
Inspired by this ....  I am the sole person using my system with 12.04. Every time I issue a sudo command; the system asks for the user password (which is good in its own way).  However I was thinking; without activating the root account; how can I execute the sudo commands which will not ask for user password to authenticate.  NOTE: I want to execute sudo command without authenticating via password; only when they are executed via terminal. I don't want to remove this extra layer of security from other functions such a while using 'Ubuntu software center' or executing a bash script by drag-drop something.sh file to the terminal.
Are there any versions of t-SNE for streaming data? Tourism on Schengen business visa? I am an Indian citizen living in UK on a tier 2 visa. Recently, I have received Short stay Schengen visas (multiple entry, business trips for 1 year) for travelling to France. (Applied at French embassy Edinburgh)  Unfortunately, the tickets I have provided in my visa application needs to be cancelled as my business trip got cancelled. And I will be travelling for business probably after 4 months.  So, for now, I am planning my first entry to France for tourism purpose.  Is it okay to travel with Short stay Schengen visas (business) for tourism purpose for the very first entry to France?   I am worried because my itinerary provided for visa application is changed now. And moreover it is now for a tourism purpose. Can we implement temporary automatic comment ban on 'x' number of validated rude comment flags? There's been problems with abusive comments since the site started.   We still haven't managed to conquer the issue.   Users can be issued chat bans and post bans. The API automatically bans IP addresses with validated spam flags. (Would it be difficult to implement comment bans? Would mods have the power to impose comment restrictions?).   Although comments have been classically referred to as second class citizens, rude comments on the site are the one place that is driving people away.   Can we implement temporary automatic comment ban on 'x' number of validated rude comment flags? It would probably be better if the exact heuristics were not disclosed publicly, much like the serial voting scripts  This question  was asked 7 years ago. Can we revisit it?  This question is related, but is asking for a more complex approach: How to install and configure Wine? How do I boot into recovery mode? As a new user, I find it impossible to contribute to the community or to even begin contributing. I know why the reputation system is in place and I respect it, but at the same time it is too hard on new users.  It started with me wanting to upvote a question...     "Vote Up requires 15 reputation"   Just to appreciate a good question that helped me I need 15 rep? OK..., so I find out how I can get reputation points. More or less, I need to ask a question for +5 and add an answer for +10. I don't have any questions at the moment and I don't want to spam a random question, but I did happen to have a slightly different answer to the earlier question that I wanted to upvote. So I try to answer...     This question is protected to prevent "thanks!", "me too!", or spam answers by new users. To answer it, you must have earned at least 10 reputation on this site.   Now... I know this doesn't apply to every question, but at the same time, this means I'm forced to answer yet another question, and I don't want to go around looking for random questions and spam irrelevant answers...  Now I'm stuck. So I try to talk to some other users in the chat rooms about how to go about getting reputation points and how they first started. I entered into a "casual chat room".     You must have 20 reputation on Meta Stack Overflow to talk here.   Yes... I can understand why this is enforced, because we don't want new users to spam chat rooms, but all I wanted to do was ask for help. So I can't even talk to anyone about my newbie problems. So okay, I'll just settle for upvoting comments in the question that helped me. I don't see an upvote hover-over button so I can't even do that.    So now I'm stuck at 1 reputation point, unable to cross that 15 rep barrier, and even after posting this question I'll only have 6 rep points and still unable to do anything, and I'll be forced to look for questions to answer. Yes, I should be contributing to the community, but I shouldn't need to begin answering or making questions to upvote questions and answers. This only spurs more spam/irrelevant answers if anything.   Very, very, very new-user unfriendly. Find expected value of $\frac{1}{1+\xi}$ Find expected value of $\frac{1}{1+\xi}$ if $\xi$ has Poisson distribution.  My try:  $$E\left[ \frac{1}{1+\xi}\right]=\sum_{k=0}^{\infty}{x}_{k}{p}_{k}=\sum_{k=0}^{\infty}\frac{1}{k+1}\frac{\lambda^ke^{-\lambda}}{k!}$$  Is it right? Sudo not available in guest login Minimal and characteristic polynomial have same set of irreducible factors Let $V$ be a vector space over a field $F$ (not necessarily algebraically closed), and $T:V\rightarrow W$ be a $F$-linear map. If $c(T)$ and $m(T)$ denote the characteristic and minimal polynomial respectively, then I want to show that $c(T)$ and $m(T)$ have the same set of irreducible factors.  I know that the claim is true if $F$ is algebraically closed, because then the two polynomials have the same roots. The typical reasoning one gives when $F$ is not algebraically closed is: Take an algebraic closure of $F$, say $K$, and look at $m(T)$ and $c(T)$ in $K$ to conclude the proof. But as far as I know, the proof that any root of $c(T)$ is a root of $m(T)$ requires the fact that $V$ is a $K$-vector space. But we only know that $V$ is an $F$-vector space. I can't understand how to proceed after this. FICA was not withheld from my paycheck Hello personal finance,  I was filing my taxes for 2016 and I just found out that I transitioned from Non-Resident-Alien to Resident Alien around September last year by passing substantial presence test. After doing some research, I have found out that I qualify as a resident alien for the whole tax year (from January 2016).   Unfortunately, my employer did not know about this change in status, so for all of 2016 no Social Security or Medicare taxes were withheld.   I have found out that I need to correct this, and I need help figuring out a few things.    Should I have a W-2 re-issued? I spoke to two accountants and one said I should, the other said I shouldn't. I don't know which one to believe.  Who pays for the FICA I should have paid last year? Is it my employer's problem to fix or mine?  Should I file the taxes with the old or the new W-2?  As best as I understand it, the new W-2 will be written as if I made this contributions. So there will be a discrepancy between what I actually earned and what the W-2 says. How should I handle this discrepancy? Declare it as extra income? Or claim it back in case I earned less than I should have? Finite Series - reciprocals of sines Find the sum of the finite series $$\sum _{k=1}^{k=89} \frac{1}{\sin(k^{\circ})\sin((k+1)^{\circ})}$$ This problem was asked in a test in my school. The answer seems to be $\dfrac{\cos1^{\circ}}{\sin^21^{\circ}}$ but I do not know how. I have tried reducing it using sum to product formulae and found out the actual value and it agrees well. Haven't been successful in telescoping it. Roman numerals used for ordinals Suppose $K/F$ is an extension field, and $E_1$ and $E_2$ are two intermediate subfields of finite degree. Let $E$ be the subfields of $K$ generated by $E_1$ and $E_2$. I'm trying to prove that $$ [E:F]\leq[E_1:F][E_2:F].$$  Since $E_1$ and $E_2$ are finite extensions, I suppose they have bases $\{a_1,\dots,a_n\}$ and $\{b_1,\dots,b_m\}$, respectively. If $E_1=F$ or $E_2=F$, then the inequality is actually equality, so I suppose both are proper extension fields. I think $E=F(a_1,\dots,a_n,b_1,\dots,b_m)$. Since $\{a_1,\dots,a_n,b_1,\dots,b_m\}$ is a spanning set for $E$ over $F$,  $$[E:F]\leq n+m\leq nm=[E_1:F][E_2:F]$$ since $m,n&gt;1$.  Is this sufficient? I'm weirded out since the problem did not ask to show $[E:F]\leq [E_1:F]+[E_2:F]$ which I feel will generally be a better upper bound. What does it mean that GUIkit is being deprecated? How to play DVDs in Ubuntu 16.04? Possible Duplicate:             TL;DR: sudo apt-get install ... saying "Unable to correct problems, you have held broken packages."   The problem  I was trying to get the WebApps feature for PP and QQ following .  I ran the sudo add-apt-repository ppa:webapps/preview command to add the repository, but i got a connection error. Since I know my current ISP gives a shaky connection, I tried again and sure enough, it worked.  Then I ran sudo apt-get install unity-webapps-preview, but I realized we had to update apt-get first, so I hit Ctrl + C to stop it. Then I ran sudo apt-get update which worked w/o a fuss, but when I ran sudo apt-get install unity-webapps-preview again later, it showed an error message. Here's the dump:  Reading package lists... Done Building dependency tree        Reading state information... Done Some packages could not be installed. This may mean that you have requested an impossible situation or if you are using the unstable distribution that some required packages have not yet been created or been moved out of Incoming. The following information may help to resolve the situation:  The following packages have unmet dependencies:  unity-webapps-preview : Depends: xul-ext-unity but it is not going to be installed                          Depends: xul-ext-websites-integration but it is not going to be installed                          Depends: xul-ext-webaccounts but it is not going to be installed E: Unable to correct problems, you have held broken packages.   I think this might be because of me interrupting the earlier command. It hadn't got a chance to output anything, though — I stopped it pretty fast.  What I tried  Commands  I tried these:-   sudo apt-get install --fix-broken sudo apt-get autoclean sudo apt-get autoremove sudo apt-get -f install   But even after running sudo apt-get upgrade after every try, none of them worked.  Purging  I tried purging the repository, but that didn't work either. First, I got the package using sudoapt-get install ppa-purgeand then tried to purge the WebApps repo usingsudo ppa-purge ppa:webapps/preview`.  Manually installing dependencies  If you look at the error dump carefully, it says:     Depends: xul-ext-unity but it is not going to be installed   Depends: xul-ext-websites-integration but it is not going to be installed   Depends: xul-ext-webaccounts but it is not going to be installed   So I tried installing them manually. I ran sudo apt-get install xul-ext-unity, but got this:     Depends: xul-ext-websites-integration but it is not going to be installed   Breaks: firefox (>= 15.+) but 16.0~b6+build1-0ubuntu0.12.04.1~mfn4 is to be installed   I have no idea what the second part means, but I tried resolving the first. Running sudo apt-get install xul-ext-websites-integration gave:     xul-ext-websites-integration : Breaks: firefox (>= 15.+) but 16.0~b6+build1-0ubuntu0.12.04.1~mfn4 is to be installed   As a last resort, I tried sudo apt-get install xul-ext-webaccounts, but that gave the sane message too:     Breaks: firefox (>= 14.+) but 16.0~b6+build1-0ubuntu0.12.04.1~mfn4 is to be installed   What does Breaks: firefox (&gt;= 14.+) but 16.0~b6+build1-0ubuntu0.12.04.1~mfn4 is to be installed mean?  Research  I tried searching , looking at a couple of , looking at  and searching on AU, but to no avail. Help would be appreciated. "In a party people shake hands with one another" In a party people shake hands with one another (not necessarily everyone with everyone else).   (a) Show that 2 people shake hands the same no. of times.   (b) Show that the number of people who shake hands an odd no. of time is even.        I find this question to be very tough and I can't find a way to even start answering this. It would be great if I could get a small hint in order for me to at least start it. Way to detect frozen video with ffmpeg? Is there a way to detect frozen video with ffmpeg? I only need to know if there are rather large regions of frozen video, say 10 seconds or more.   I'm familar with the  filter.   Maybe you could first difference adjacent frames, then use blackdetect to tell whether the difference has not changed? I'm not sure how to perform the difference though. How to write this boolean expression using only NOR gates? I'm having some trouble understanding how I can convert a boolean expression to a NOR-gate only expression.   What I'm working with looks like \$T = A B' C + A' B C' + A B\$. How would I go into implementing it with NOR gates? Wifi hotspot software package other than ap-hotspot?