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From io.Reader to string in Go Unable to parse query string for function Query, when using IMPORTRANGE Can "cattle" be singular? I've grown up on a farm, and my dad and his dad, apparently, always used "cattle" to refer to both the singular and plural forms of the domestic bovine. I've always assumed it's how the word "deer" is.  However, I've heard people say that this is incorrect and the singular is just "cow", but this has always offended us as a cow is a mother cattle, and is incorrect if you're referring to a steer, a bull, or a heifer.  So, is cattle singular as well as plural? If not, is there some general, non-gender-specific word that should be used instead? What is different about the Mac ISO image? Let $f:\mathbb{R}_+ \to \mathbb{R}_+$ be a monotone decreasing function defined on the positive real numbers with $$\int_0^\infty f(x)dx &lt;\infty.$$ Show that $$\lim_{x\to\infty} xf(x)=0.$$   This is my proof: Suppose not. Then there is $\varepsilon$  such that for any $M&gt;0$ there exists $x\geq M$ such that $xf(x)\geq \varepsilon$. So we can construct a sequence $(x_n)$ such that $x_n \to \infty $ and $x_n f(x_n ) \geq \varepsilon$. So $$\frac{\varepsilon}{x_n}\leq f(x_n) \implies \sum_{n\in\mathbb{N}}\frac{\varepsilon}{x_n} \leq  \sum_{n\in\mathbb{N}} f(x_n) \leq \int_0^1 f(x)dx.$$ So we get a contradiction.  I feal like I have the correct idea but some details are wrong.  Any help would be appreciated. Proving $\sum\limits_{k=1}^{n}{\frac{1}{\sqrt{k}}\ge\sqrt{n}}$ with induction How to have full bleed between two facing pages Indesign LCM. What am I missing? Problem statement:  Let $S$ be the set of all positive integers $n$ such that $n^2$ is a multiple of both $24$ and $108$. Which of the following integers are divisors of every integer $n$ in $S$? The choices are: $12, 24, 36, 72$. The solution is $12$ and $36$. My solution was $S = \{36, 36* 6^3, 36*6^5, ...\}$  I can't figure out this problem. I started by finding the $\text{lcm}(24,108)$ and solved for $n$. I got some of the numbers in the set $S$, but not all of them, and I don't see what I'm missing. Update: added the choices and what my results How can I remap Caps lock to both Escape and Control? I generally run Linux. I use Vim a lot, so the Escape key is extremely important. I also use other keyboard shortcuts a lot, so Control is "key" as well. On Linux, I've solved this by using  to map the Caps lock key to Escape if pressed by itself, or Control if pressed in combination with another key. This puts the best of both worlds within quick reach of my pinky finger. Is there any way I can do this on a Mac? Why do I need an extended partition? What is an extended partition? Why do I need to use it to install Ubuntu if I already have four partitions that are factory installed? I am trying to use a Bluetooth headset on an Ubuntu PC. I am able to connect phone to pc via BT. I can stream music to PC. But cannot hear call audio. I have checked in Android phone logs, and BT sco link is established. But when making a call or virtual call (play audio through sco path in Android phone) the audio is not audible in PC headset. SCO packets are NOT appearing in btmon logs either. Anyone successfully done this?  version- ubuntu 16.04 Installed- bluez, ofono, pulseaudio pactl sink: Name- bluez_sink.22_22_8E_DE_B9_2B,             Name: alsa_output.pci-0000_00_1b.0.iec958-stereo pactl source: Name-bluez_sink.22_22_8E_DE_B9_2B.monitor               Name: alsa_input.pci-0000_00_1b.0.analog-stereo Let $\mathbf{FinVec}$ denote the category of finite-dimensional real vector spaces and linear maps, let $F\colon\mathbf{FinVec}\rightarrow\mathbf{FinVec}$ be a functor. For each pair of objects $V,W$, the Hom-set $\operatorname{Hom}(V,W)$ is itself a finite-dimensional vector space and we equip it with the unique structure of a topological space/of a smooth manifold that is compatible with its vector space structure. The composition maps are then continuous/smooth. In this way, we view $\mathbf{FinVec}$ as enriched over the category $\mathbf{Top}$/$\mathbf{Diff}$ respectively. It then makes sense to ask whether the functor $F$ is enriched over $\mathbf{Top}$/$\mathbf{Diff}$. That is just to ask whether the induced map $F\colon\operatorname{Hom}(V,W)\rightarrow\operatorname{Hom}(FV,FW)$ is continuous/smooth for all $V,W$. (Irrelevant to the rest of the question, but the reason this is a useful notion is that it is the natural hypothesis assuring that the functor induces another functor on the category of topological/smooth vector bundles, applying the original functor fiberwise.) In the case $V=W$, by functoriality, we can restrict $F$ to a group homomorphism $\operatorname{GL}(V)\rightarrow\operatorname{GL}(V)$. If the functor is continuous/smooth, so is this map. Note that $\operatorname{GL}(V)$ is a Lie group. It is a general result that a measurable group homomorphism between Lie groups is automatically smooth. This begs the following questions:  What's an argument for the existence of functors that aren't continuous? Can we construct one? Given the above, it either happens that the restrictions to $\operatorname{GL}(V)\rightarrow\operatorname{GL}(V)$ are continuous and continuity fails elsewhere, or the induced maps will be non-measurable, so that the construction will necessarily have to involve choice to some extent. Are there continuous functors that aren't smooth? Given the above, a continuous functor will have smooth restrictions to $\operatorname{GL}(V)\rightarrow\operatorname{GL}(V)$, but smoothness may fail elsewhere. Give $\ker(\phi)$  for $\phi: \mathbb{Z} \to \mathbb{Z_7}$ such that $\phi(1) = 4$  So the generator of $\mathbb{Z}$ maps to $4$ and $\langle 4 \rangle = \{0,1,2,3,4,5,6\}$ so it has order seven.  so $\ker(\phi) = 7\mathbb{Z}$ because every seventh element will map to the identity under the given map. Is that the correct reasoning? Is Java's default value for Boolean 'true'? While browsing I have received notification on Google "Unusual traffic from your computer network"   We're sorry..."your computer or network may be sending automated queries. To protect our users, we can't process your request right now." See Google Help for more information.  Right now I am using the "Ubuntu 12.04" 32 bit version.  Any suggestion, why this is happens &amp; How it resolve?  Thank you for your worthy suggestion. How do I base64 encode (decode) in C? I have binary data in an unsigned char variable. I need to convert them to PEM base64 in c. I looked in openssl library but i could not find any function. Does any body have any idea? I'm looking for a single line regex which does the following:  Given a HTML tag with the "name" attribute, I want to replace it with my own attribute. If that tag lacks the name attribute, I want to implant my own attribute. The result should look like this:  &lt;IMG name="img1" ...&gt; =&gt; &lt;IMG name="myImg1" ...&gt; &lt;IMG ...&gt; =&gt; &lt;IMG name="myImg1" ...&gt;   Can this be done with a single line regex? Recovering accidentally deleted files Receiving commandline input while listening for connections in Python This is a pretty well known quote from the Star Wars movies. But isn't it a bit paradoxical?   It in itself is an absolute, and it was said by a Jedi (Obi-Wan if I recall correctly?). If this holds true, then is he leaning towards the Sith himself? If it isn't true, then both Jedi and Sith can deal in absolutes and the statement is pointless.  Surely it should be phased along the lines of "Jedi's should avoid dealing in absolutes" or something similar?