I am new to this field.Actually I am learning PHP/MYSQL.Five min before I asked a question in StackOverflow.And when I googling this suddenly my question appears.How does StackOverflow index very fast in google.I have PHP site which is indexing by google.But not all pages.Seriously How to do that.
How is it that questions posted to the Stack Overflow show up as #1 in Google search results just minutes after being submitted? What SEO practices are being used to generate this sort of up-to-the-minute accuracy?
How does the garage system work in GTA V? Minecraft Survival Mode How do I improve boot speed? Does it exist a free interactive geometry software, like GeoGebra, which works for 3D geometry? I would be able to draw spheres, great circles, and so on. How to draw a border around character in a formula? So far everything I found on the matter of borders only applies to the text mode.  I want to be able to do something like  $x_i = y$   so the result will be like the ordinary "xi = z" formula with the border around "i"?  The common answers seems to be the fbox or boxed commands. Yet they render their argument in the standart mode, unless specified to do otherwise with the specific mode. For example, the following code  \[ x_i, \boxed{x}_i, x_{\boxed{i}}, \boxed{x}_{\boxed{i}} \]   produces two normal xi figures, and another two with an oversized i. How would you count occurrences of a string (actually a char) within a string? I am doing something where I realised I wanted to count how many /s I could find in a string, and then it struck me, that there were several ways to do it, but couldn't decide on what the best (or easiest) was.  At the moment I'm going with something like:  string source = "/once/upon/a/time/"; int count = source.Length - source.Replace("/", "").Length;   But I don't like it at all, any takers?  I don't really want to dig out RegEx for this, do I?  I know my string is going to have the term I'm searching for, so you can assume that...  Of course for strings where length > 1,  string haystack = "/once/upon/a/time"; string needle = "/"; int needleCount = ( haystack.Length - haystack.Replace(needle,"").Length ) / needle.Length; If the distribution of test statistic is bimodal, does p-value mean anything? I have for quite some time now tried to find a satisfactory answer to this, but I haven't yet. In perturbation theory, with small parameter $\lambda$, we expand the eigenstate as  $$| E \rangle=| E^{(0)} \rangle + \lambda | b \rangle + ...$$  Where $| E^{(0)} \rangle$ is an eigenstate of the unperturbed Hamiltonian. The problem is that when there is degeneracy, there is a choice of these eigenstates. I know the answer is that they are chosen to be eigenvectors of the perturbing Hamiltonian, but my question is why. Lenovo Yoga 13 Realtek wireless driver Currently in my last year of high school, and I have always been told that  does not exist by my physics teachers. Today my girlfriend in the year below asked me what centrifugal force was, I told her it didn't exist, and then she told me her textbook said it did, and defined it as "The apparent force experienced towards the outside of a circle is the centrifugal force and is due to the mass of the object resisting the inward centripetal acceleration that the object is experiencing". I was pretty shocked to hear this after a few years of being told that it does not exist.  I did some reading and found out all sorts of things about pseudo forces and reference frames. I was wondering if someone could please explain to me what is going on? Is it wrong to say that centrifugal force does not exist?   This has always nagged me a bit as I often wonder that if every force has a reaction force then a centripetal force must have a reaction centrifugal force, but when I asked my teachers about this they told me that centrifugal force does not exist. How to make sure I'm not using any proprietary software after installation? I know I can check the currently installed non-free software with the following command (assuming aptitude is FOSS):  aptitude search '?installed (?section(restricted) | ?section(multiverse))'   And I can remove the "restricted" and "multiverse" sources (and not add any PPA's) to keep that list empty. I'm assuming from this point, whenever I apt install something, that something is either in the allowed sources or it is not found.  Is this enough? Does this make sure all software I'm running (in Ubuntu) is open-source? What's the purpose of two capacitors in parallel? What's the purpose of the two capacitors in parallel on each side of the regulator in      I've seen similar setups in other similar circuits and can guess that it's related to one being polarized an one not, but I don't really understand what's going on there. To make your opinion known on MSE you need both up and downvotes. Given at the moment you need 125 rep to downvote on this site, the voting patterns will be skewed positive because not everyone is active on the site.   This is to be expected for regular Stack Exchange sites as you are expected to be involved in the community before you are deemed knowledgeable enough to be part of the community voice. However, MSE is different because you are voting for the entirety of the Stack Exchange network and you shouldn't need to be active on MSE itself to have a voice on changes to the entire network.  This is especially important for questions like  because it will effect every network to do with coding at all. This was brought up in .  I would suggest reducing the rep required to downvote on MSE down to 100 (or 101) rep. This is the amount you get for the site association bonus. This is given once you achieve 200 rep on any network site and shows that you are active in at least one community. I think this would be the perfect use of the association bonus in showing that you are a member of the Stack Exchange community. How can I specify JUnit test dependencies? Why is the empty set considered an interval? What is the difference between "till" and "until"? What is the difference between till and until?    When to use till or until? Please explain with examples. Tikzpicture-figure: Order plot data (asc/desc)? I am using a tikzpicture for plotting. the values I want to plot are typical (X,Y) pairs. The x-value is an uninteresting id-value. I want to order the bins ascending/descending according to the y-value, but how do I do that? The figure seems to automatically take the x-values for ordering, how can I override that? (I am not particularly fixed to tikzpicture - its just the first thing that actually worked and displayed the plot....) Following minimal-working example, how could I achieve a reordering according to the y-value?  \documentclass{article} \usepackage[english]{babel} \usepackage[T1]{fontenc} \usepackage[utf8]{inputenc} \usepackage{relsize} \usepackage{times} \usepackage{url} \usepackage{latexsym} \usepackage{graphicx} \usepackage{colortbl} \usepackage{color} \usepackage{caption} \usepackage{pgfplots, pgfplotstable} \usetikzlibrary{arrows} \usepackage{amsmath} \usepackage{multirow} \usepackage{booktabs}  \usepackage{filecontents} \definecolor{OgAns}{rgb}{0, 0.8, 0.4}  \begin{filecontents}{testdata.dat} 1   30 2   44 4   26 3   39 \end{filecontents}  \begin{document} \begin{figure} \begin{tikzpicture}         \begin{axis}[                ybar stacked,             ymin=0,             ymax=100,             bar width=5pt,             legend style={at={(0.35, -0.4)},anchor=south west},             legend columns=-1                       ]           \addplot[ybar,fill=OgAns]  file {testdata.dat};          \end{axis}     \end{tikzpicture} \end{figure}   \end{document} C++11 does not deduce type when std::function or lambda functions are involved Can you deliver it [when,after] it [is | will be] assembled? Possible to bake texture to new UV map? I have a finished model where the UV maps overlap - lots of wood that isn't detailed to be particular to the model.    I'd like to re-map the texture so that specific details can be added. I'd like to rebuild the UV map into non-overlapping islands, without losing the current texture application, and preferably without manually pulling apart the islands.  Is this possible?