Good night,  I'm using the Elsevier journal template, I need to set up a table like Image 1. I'm a beginner in TeX and I still have not understood how to merge cells into a table. Ideally, the table should be in the format of Image 2. The code I have in the template is:  \begin{table}[h] \centering \begin{tabular}{l l l l l} \hline \textbf{Author} &amp; \textbf{Year} &amp; \textbf{Blockchain} &amp; \textbf{Implementation}\\ \hline {[31]} &amp; 2018 &amp; Ethereum &amp; None \\ {[33]} &amp; 2018 &amp; Ethereum &amp; Simulation \\ {[34]} &amp; 2017 &amp; Ethereum &amp; Simulation \\ {[36]} &amp; 2018 &amp; Ethereum &amp; Complete \\ {[37]} &amp; 2017 &amp; Ethereum &amp; Simulation \\ \hline \end{tabular} \caption{Related Work.} \end{table}   Table from template:     Table I need:    The second image I did in Word, but it must be in the format of the template I'm using.
Here is a simple table.  I want to merge 4 cells. I want to combine the three "this" cells area in this table. I thought I have to use multirow and multicolum at same time. However, I could not find how to use it.  If possible, could you post the modified LaTeX source code?     My LaTeX code:  \documentclass{article} \usepackage{multirow}% http://ctan.org/pkg/multirow \usepackage{hhline}% http://ctan.org/pkg/hhline \begin{document}  \begin{table}[ph] \begin{center} \begin{tabular}{c|c|c|c|c} \hline \multirow{2}{*}{Raaa (k)} &amp; \multicolumn{4}{c}{C ()} \\ \hhline{~----}  &amp; 3.3 &amp; 2.5 &amp; 1 &amp; 0.5 \\ \hline \multirow{2}{*}{Raaa (k)} &amp; \multirow{2}{*}{this} &amp; this &amp; 0.5 &amp; 0.6\\ \hhline{~~~--}            &amp;                       &amp; this &amp; 0.7 &amp; 1.2 \\ \hline \end{tabular} \caption{R, C ripple size} \label{T:peak} \end{center} \end{table} \end{document}
Relative log file matching with linux? Why does default auto.arima stop at (5,2,5)? The function auto.arima in the forecast package of R is a powerful tool to identify the best ARIMA(p,d,q) model for a given data series. In the   of the function, they report the following:  auto.arima(y, d=NA, max.p=5, max.q=5, max.order=5, max.d=2, start.p=2, start.q=2, ...)   According to the above function it seems that, by default, auto.arima tries to find the best model among all the combination having:   p equal or lower than 5 q equal or lower than 5 d equal or lower than 2 order equal or lower to 5, i.e. p + q + d  ≤ 5.   However, why does the default code stops at these conditions? Is there any particular reason why p, q and d should be equal or lower than 5, 5 and 2 and their sum lower than 5? Creating shapefile from Excel file in QGIS? I am using QGIS 2.6.1 and have worked in an Excel file database (which was actually converted from a Shapefile). I have managed to convert it as CSV file and load it into QGIS (displays data fine) but I have trouble to convert it to a shapefile.  I can view it but I can´t add or alter data in this file. I think I have to save it as a database.   Any clues how to convert the xlsl-data to a database and finally to a shapefile? In ZFC, a good way of ordering sets by cardinality is by leveraging the notion of an injection. We define: $$X \lesssim Y \leftrightarrow \mbox{ there exists an injection } X \rightarrow Y.$$  Alternatively, we can leverage the notion of a partial surjection, by which I mean a partial function that hits every point of its codomain at least once.  $$Y \succsim X \leftrightarrow \mbox{ there exists a partial surjection } Y \rightarrow X.$$  Now in ZFC, these approaches are equivalent, in the sense that $$X \lesssim Y \iff Y \succsim X.$$  But if we just consider ZF (that is, we drop choice) then the equivalence breaks down. However, we've still got the forward implication, because the converse of an injection is always a partial surjection.  A specific question. Define that two sets are weakly equipotent iff $X \succsim Y$ and $Y \succsim X$. Question: does weak equipotence imply genuine equipotence? I'm guessing "no."  A general question: In broad terms, how would the structure of the cardinal numbers in ZF be altered by adopting $\succsim$ rather than $\lesssim$ as the fundamental order relation, and taking equality of cardinal numbers to correspond to weak equipotence of sets? I'm guessing this would hide a lot of the (usually very complicated) structure of the cardinal numbers in ZF.  Remark. The order symbols can be written \lesssim and \succsim. Setting Objects to Null/Nothing after use in .NET VirtualBox 5.0.40 crashes the whole host since update to kernel 4.13.0-26-generic Reprojecting raster from lat/lon to UTM in R? How restrict page for users logged? Show how if Alice uses the same value of $k$ to sign two different messages $m_1$ and $m_2$, using the ElGamal signature scheme, Eve can recover the value of $a$ from the corresponding signatures $(m_1, r_1, s_1)$ and $(m_2, r_2, s_2)$. (Note: you are allowed to assume that if $\gcd(a, n) = d$ then there are $d$ solutions to the congruence $ax \equiv b \pmod n$.)     ElGamal Signature Scheme:      Key Gen:      Compute $y = g^x \;\bmod p$.      The public key is $(p, g, y)$. The secret key is $(p, g, x)$      Signature Gen:      Choose a random $k$ such that $0 &lt; k &lt; p − 1$ and $\gcd(k, p − 1) = 1$      Compute $r = g^k \;\bmod p$ and $s = k^{-1}(m – xr) \;\bmod{p-1}$   Thoughts: So far, I can tell that $r_1$ and $r_2$ are equal and $s_1$ and $s_2$ are closely related since the only variation is $m$.  We can relate the two equations for $s$, by solving them for $-xr$:  $$s_1k - m_1 \equiv s_2k - m_2 \pmod p$$  $$(s_1 - s_2)k \equiv m_1 - m_2 \pmod p$$  Let $a = s_1 - s_2$, then we know from the question that for $\gcd(a, n) = d$ there are $d$ solutions for $k$.  Now the forger can compute $g^k$ for each solution to k, until $r$ is found.  Then compute $xr \equiv m_1 - ks_1 \pmod{p-1}$  There are $d&#39; = \gcd(r, p-1)$ solutions for $x$.  The forger can compute $g^x$ for all the $x$s found until she finds $y$.  Once she has $y$ she knows the proper $x$ which can be used to find $m_1$ and $m_2$.  How does this look? Info Icon vs Question Mark Applications Not Reopening After Restart From the top of my head, Danish "De" (practically never used), German "Sie", Chinese "您", French "vous", Spanish "usted" are a formal way of addressing someone, especially if one isn't familiar with the addressee. Did English ever have this? It sounds as though Proto-Indo-European might have had this (based on my 4 examples), but perhaps someone can enlighten me? Custom hard edges in Blender What is a good general document size for web page mockups and prototypes? I do mockups and prototypes of sites and designs all the time, but I've always wondered if there is a standard size or width I should be using. Generally I'll make my document either 1024, 1200, or 2560px wide, depending on what I'm doing.  So what do you think? What is a good or standard size for this? What would happen if I used regeneration on a creature that was the target of Annihilating Fire? For example, what would happen if a freshly cast  were to be regenerated in response to ?  My hypothesis is that it depends on whose turn it is. The regeneration being essentially a replacement effect, when two replacement effects were to be applied simultaneously, they are to be chosen in APNAP order. Is this correct?  I haven't thought this through to the end, though, so I'm not sure what would happen in the end. Today I had some time and felt like writing a relatively good answer on Stack Overflow; explaining both the underlying mechanisms and good practices, unlike usual declarative answers in a "do that" style.  It took me like an hour of time, $50 if I were free lance. It'll bring me nothing but 3-5 occasional views, and - if I get lucky - some ignorant comments.  You know, it's quite discouraging.  Instead of pride for the job that was done, I feel frustrated. I know, this answer may offer help to the OP, if he ever notices it (being already satisfied with other answers).  So the only fate the answer will meet is to sink forever, below thousands other questions, falling like snow.  So, being a programmer, I am thinking of efficiency. It's a waste of time to spend so much effort to answer one question when there is no way to [actually] reuse it. So, I wouldn't do it again but just turn back into short answers mode without explanations.       Seeing other answers, I don't think I am only one with such feeling.  The current policy is driving knowledgeable and educational users away, yet it attracts inexperienced ones in numbers. Ones who will tell you to use [some technology] which they never have laid their hands upon. Ones who write answers just because they have learned some "good practice" from other questions, and this "knowledge" becomes an endless source of rep points.  The idea of Stack Overflow is rotten. It was excellent when trees were high and traffic was low.  It turned bad now; it has become a honeypot for all the "enthusiast programmers" of the world, eager to share their 2 cents faster than you can say the word "close".  You're killing a great resource. Despite all the nice words and proper declarations, it discourages the reuse of the knowledge. And encourages fast on-site answers.  Of course, the rules will tell you contrary. It's all nice and proper (if you don't mind it's strict mutual exclusivity). But mechanically, technologically it works in the way I described.  I tried to write a tag wiki. You know, it was biggest waste of time in my life. As a matter of fact, it is not a wiki at all; you can't even link to a certain section. Not to mention that nobody ever has the idea to read tag wikis.  Reference questions? Don't make me laugh. There is no good mechanism to store and categorize links. Favorites, although intended for the different purpose, are a chunk of crap when you want to use it as a reference. So, you can't compete with 30-seconds answers: a question will get 5 answers before you can even find an appropriate link.  Okay, I can organize links myself but, there are some problems:   I am just a human. I cannot remember everything I am just a human and I cannot answer questions at rate of 1 qpm. One person cannot fight the Tide. It's helpless. When technology makes people writing fast [incomplete] answers -  no good will of proper declarations can do a thing.  Even if a question gets finally closed, it won't hurt anyone - the hydra grew two more already.   You'll call me a brute for insulting honest users and innocent volunteers, but that's fact: There are much more inexperienced users than experienced ones. And inexperienced users have much more spare time to hang over than experts who have their job to do. So, from that fact we can conclude that most of the answers on Stack Overflow have a low quality. Nobody cares. But I do.   There should be a technical way to limit the activity of not-so-knowledgeable-yet-eager-to-answer users. There should be a technical preference for the closing a question over answering it (have a silly answer for the silly question? welcome to comments). There should be a technical solution to accumulate and structure knowledge, a system that lets you choose a good answer instead of writing it by hand.   That's the only way. Otherwise Stack Overflow will remain an automated dispenser of bad practices.  Well, I just felt like letting it out again. Thank you for reading. Is there any example that for cardinal numbers $\kappa &lt; \lambda$, we have $2^\kappa = 2^\lambda$?  My guess is that it only depends on whether GCH holds. Is it true? How to batch resize an image and create multiple sizes (with Photoshop)? I want to batch resize an image in multiple sizes with Photoshop.  The sizes are most of the time the same so I would like to have profiles for a set of fixed sizes. Ideally I just need to open my source image and click on "Batch Profile #1" and then Photoshop is creating/saving X different sizes of that image as an output in a specific folder.  This is what i want: Switching to different font size(s) locally I have found a strange behavior in TikZ. When using the \draw ... to ... syntax and trying to place nodes along the line with the node[...]{...} syntax, the nodes do not turn up at the expected location.  \documentclass{standalone} \usepackage{tikz} \begin{document} \begin{tikzpicture}   \draw(0,0) to[out=60,in=120] (1,0) node[midway]{x}; \end{tikzpicture} \end{document}     How is this done properly?