So when i save a duplicate file from the net, the system automatically adds a (1) right at the end, before the extension and I have no idea if I can change it.  How do i keep the original file name so I can overwrite the existing one without manually removing the (1)?  Can it be done?
When I save a file (e.g. Images) to a folder which already exist there, Chrome adds a (N) where N is first available number. This causes I have multiple copies of same file! How can I disable Chrome's auto file renaming?   Thanks
Should laptops remain plugged in when their battery is 100% charged? When your laptop's battery is 100% charged, should you leave it plugged in so any battery power doesn't get used, or will that cause overcharging, overheating, etc.? Should the laptop be unplugged when the battery level is 100%?  I'm asking because my laptop's screen tends to get dim when unplugged, so I don't like to run it on battery. Determining confidence interval with one observation (for Poisson distribution) Fourier transform of $\exp(-t^2)$ using contour integration. I'm trying to do a volumetric light on Cycles, and I've followed tutorials, but nothing has worked yet. How can I make a proper volumetric light in Blender, like the following one?    But to leave the light in the middle, like, almost a star, is this possible? I'm at the point to use an image plane besides the light which would be better... I need to use it moving the camera.  I'm actually trying to do this because I want to simulate the brightness of the Sun.  I tried the effect, but it still gave me an error: Is there any shortcut/easy way to switch this system proxy settings? Received an email intended for another person I'm not really sure how email routing works, but someone ordered something on Amazon and I received the email instead of them.  Or maybe we both got it, I don't know.  The order doesn't show up in my account, so I'm certain I wasn't charged for it, but I shouldn't be getting other peoples' emails.  We'll say that my email is johndoe1@gmail.com, and somebody who's email is john.doe1@gmail.com places an order on Amazon.  The confirmation email is sent to me at johndoe1@gmail.com.  I checked the email header, and it did say To: john.doe1@gmail.com which is not my email address.  At first I thought that Google ignores periods in email addresses, but I tested the account setup and it doesn't give any error when you put a period in the address.  I didn't create the account; I just used the "check availability" function and the address I chose with a period was fine.  Maybe someone with knowledge about how Email works could tell me why this happened.  Is this a bug in the way Amazon sends emails?  Or is it a bug in how Google receives them?  Who should I report this issue to? How do you explain the value of native files to an uneducated client? If you design a piece for print. It gets reproduced several times over the course of a few years. Then the client doesn't return for any work for a few more years. And suddenly you are contacted asking for native files (Indesign, Illustrator, Photoshop). As the client puts it, "We just want to be able to make minor changes, we aren't designers."  Now, there is absolutely value in the native files. They are my "secret recipe" as a designer and anyone asking for that recipe should provide compensation for the ease of reusing, repurposing, and altering the recipe.  How do you explain to this client that there is value in the native files?  How do you counter the "But we already paid for the design." argument?  Note: I know I own the files. I know my contract states I own the files. Heck even without a contract, US Copyright law states I own the files.  What I'm seeking is an elegant, less argumentative, method of explaining the file ownership to the uneducated client. Reciting legal statutes and contract clauses doesn't often make for friendly client relations. My goal is to find a method of explaining so it is fully understood by the client without the appearance of a contract clause which forces them to do something against their will. I want the client to respect and not resent these types of contract clauses. My keyboard has no "media" keys; can I control media without them? If in Pete's World there's no Doctor, how is there a Torchwood? Main Reference + Appendix with "Other Sources" I need your help with references. I have 1 main reference section, and I want to include a second list of references as an appendix. For the main reference I use:  \newpage  \bibliographystyle{plainnat}  \bibliography{library}   The problem is that I don't know how to include the second list using a different bib file, and then calling the function \nocite{*} to show every sources inside the file.   I have the appendix part workout. I need your help to design the function to call the second bibliography, and that does't interfere with the main reference:   \newpage  \appendix  \section{Other Sources} \label{app:ReferencesB}   In addition, I will prefer that the word References is not shown after Other Sources.  Thank you so much!! I'm reading the proof of the multiplicative property of $$s_k(n)=\sum_{d|(n,k)}f(d)g\bigg( \frac kd\bigg)$$ The book wrote that in order to understand the proof, we need to know if $a,b,k,m$ are integers such that $(a,k)=(b,m)=1$, then $$(ab,km)=(a,m)(b,k).$$  I have written proof, but I don't know is it consistent, and this seems used more tools than it necessarily has to.   My proof: Let $$S_1=\{d: d|(a,m), d&gt;0\}\\S_2=\{d: d|(b,k), d&gt;0\}\\S=\{d:d|(ab,km), d&gt;0\}.$$ I will prove the statement by showing that the function $\phi:S_1\times S_2\to S$ defined as $$\phi(d_1,d_2)=d_1d_2$$ is bijective, and complete the proof by connecting the maximal elements from these partial ordering sets.  Obviously, for $d_1\in S_1, d_2\in S_2$, this tells us $d_1 $ is both divisor of $a$ and $m$, and $d_2$ is both divisor of $b$ and $k$, hence $d_1d_2$ is both divisor of $ab$ and $km$, so we can tell $\phi(S_1\times S_2)\subseteq S$.  To show one-to-one, if we have $c_1,d_1\in S_1$ and $c_2,d_2\in S_2$ such that $$\phi(c_1,c_2)=\phi(d_1,d_2)$$ then $$c_1c_2=d_1d_2$$  In particular, $c_1|d_1d_2$, we need to show $c_1|d_1$. Indeed, if $(c_1,d_2)&gt;1$, this implies $a,k$ have common factor larger than $1$, contradicts the assumption. Therefore $c_1|d_1$. A similar argument implies $d_1|c_1$, therefore $c_1=d_1$. Again a similar argument implies $c_2=d_2$, which shows one-to-one.   To show onto, let $d\in S$, since $d|ab$, we can split $d$ into $d_1d_2$ such that $d_1|a$ and $d_2|b$. Since $(a,k)=1$, we see $(d_1,k)=1$, by property of $S$ we see also $d_1|m$, therefore $d_1\in S_1$, a similar argument implies $d_2\in S_2$. So every number in $S$ has a preimage in $S_1\times S_2$  This completes the proof. Is there any mistake in the proof?     Edit: A proof about the statement: If $d|ab$ then there are $d_1,d_2$ such that $d=d_1d_2$ and $d_1|a, d_2|b$.  Let $ab=p_1^{e_1}\cdots p_r^{e_r}$ for distinct prime factors $p_1,\cdots,p_r$, then we can write $$a=p_1^{x_1}\cdots p_r^{x_r}\\b=p_1^{y_1}\cdots p_r^{y_r}$$ where some of $x_i, y_i$ can be zero, and $x_i+y_i=e_i$ for all $i=1,\cdots,r$.  Since $d|ab$, we can write $$d=p_1^{f_1}\cdots p_r^{f_r}$$ with $f_i\leq e_i$ for all $i=1,\cdots,r$. Then since $$f_i\leq x_i+y_i$$ Split into two cases:   Case 1: $f_i&gt; x_i$, then we can choose $g_i=x_i$ and $h_i=f_i-x_i$.  Case 2: $f_i\leq x_i$, then we can choose $g_i=f_i$ and $h_i=0$.  Then the choice $$d_1=\prod_{i=1}^r p_i^{g_i}, \quad d_2=\prod_{i=1}^r p_i^{h_i}$$ will prove the statement. We have to prove that  "the product of two numbers ending in 6 also ends with 6" mathematically.  I have no clue how to start. I don't want you to prove it for me! but some hints would be very helpful as I'm totally stuck on how to start this prove. Pigeonhole-principle with two choices I am able to solve this sort of problem pretty easily.     An arm wrestler is the champion for a period of 75 hours. The arm   wrestler had at least one match an hour, but no more than 125 total   matches. Show that there is a period of consecutive hours during which   the arm wrestler had exactly 24 matches.   However this homework problem I can't seem to figure out.     Tyler has five weeks to prepare for his driver’s test. His mother   volunteers to ride with him for either 15 minutes or one half hour   every day until the test but not for more than 15 hours in all. Show   that during some period of consecutive days, Tyler and his mother will   drive for exactly 8.75 hours.   If I try doing it the same way as the first problem. I get $70$ pigeons and $95$ pigeon holes. I honestly don't know where to start with this problem. I thought that maybe I could assume that they only drove $.25$ hours on each day and prove that there is a period of consecutive days where they drove for exactly $8.75$ hours. Then I could say that we assume there is one day that they drove for $.5$ hours and work my way up, but I can't seem to get that to work either. How do you get \mathbb{1} to work (characteristic function of a set)? I am trying to get the digit one printed the \mathbb{} font in math mode, however the command  \mathbb{1}   outputs some rubbish. I certainly saw the character I am after in some pdf's generated from latex, hence my question: how do you get it to work? Why did the writers select the date November 5, 1955 in Back to the Future? Is there any significance to the date November 5, 1955 that was chosen in Back to the Future? Is it one of the directors birthday or something like that or were there specific real life events that day in history?   I am not looking for in-universe answers. Value passed with request.setAttribute() is not available by request.getParameter() $\Bbb{Z}_{26} \rtimes_{\alpha} \Bbb{Z}_{5} \cong \Bbb{Z}_{26} \times \Bbb{Z}_{5}$ as groups. Can players on a PC and an Xbox play together in any way? I.e. can Xbox users connect to a (modfied?) PC server, or vice versa? jQuery scrolltop firefox not working Check which IPs or web-sites an app is communicating with? Usually they do it behind the scenes. So I'd love to know where apps are actually sending data and from whom they are actually getting responses.