I'm new to stack exchange, so please let me know if there is anything I should do to make my question more clear. I'm new to LaTeX, and I am trying to make a graph of the equation  from special relativity.  I want my y-axis to be gamma and my x-axis to be the velocity, v. I have my graph (picture below), but I just want to do one more thing.  When I graphed the function, I used 1/(1-x^2) as my function (basically, x acts as v/c) so the max value would be 1, which would represent 1c (the speed of light).  How do I add $c$ to each of the numbers on the x-axis? For example, how do I turn 0.2 into 0.2c? I have seen other questions like this, but they are graphing data, not functions, so the code doesn't work for my graph.  If possible, I'd like to not have to enter the equation as a data set; I want to keep it as a function.  Thank you in advance! Also, here is my current code for the graph (please let me know if something can be improved): \begin{tikzpicture}     \begin{axis}[scaled y ticks=false, xlabel=$v$, ylabel=$\gamma$, ymax=5]         \addplot[domain=0:1,samples=1000] {1/sqrt(1-x^2)};     \end{axis} \end{tikzpicture}  My current graph:
Hi i want to put this simbol "%" in the tick labels only in the x axis how can i do?
How to use an optimization solver to get t-stats and p-values for the estimates? How can I write multiple lines in a subscript? Is there a way to force a line break inside a math mode text?  My example:  \[   \underbrace{....}_\text{Some long text that should be multiline} \]   Trying  \text{Some long text that\\ should be multiline}   Didn't do the trick. Screen resolution stuck at 1024x768 Checking out  and  (and some papers) was a bit difficult for understanding Group Action. The closest to understanding was this part:    I understand the definition of homomorphism (a structure-preserving map between two algebraic structures of the same type). And from what I understand the symmetric group is a group of functions (bijective functions) mapping elements of a set $X$ onto itself.  However I get confused at this line:     ...an action of $G$ on $X$ may be formally defined as a group homomorphism $\phi$ from $G$ to the symmetric group of $X$.   That seems to be the definition of group action, but I am having trouble understanding how to apply that.  What that says to me is it is a homomorphism (function) $f \colon X \rightarrow S$ where $S$ is a set of bijective functions on $X$. That itself seems weird, I thought a group action would result in a number or something related to $\{1, 2, 3\}$ (defined next).  Continuing, if we have a set $X = \{1, 2, 3\}$ and a group $(*,\{4, 5, 6\})$, then the symmetric group of $X$ would be something like $S = \{1 \rightarrow 2, 2 \rightarrow 3, \dots \}$, and $\phi$ would be something like $f : \{4, 5, 6\} \rightarrow S$. That doesn't make sense to me and I feel like I'm interpreting something wrong. I don't see how mapping to a set of functions $S$ will result in an action on the set. Is fractional scaling ( ) available in 18.04 LTS yet? I am waiting until this is available before I install. What "time travel" story required the traveller to mentally reconstruct his world in order to return to it? Here's what I remember about it:   The protagonist is sent a relatively short distance into the future (maybe a year? I've forgotten). When he arrives in this "future" he finds himself in a completely different world, with non-human inhabitants. The inhabitants use a machine to teach him their torturous language. He tries to return home, and (eventually) finds himself in a realm of chaos/nothingness. He laboriously reconstructs in his mind everything he can remember about his home and finds himself back there somehow. The twist is      that in his "home" reality everyone speaks the language he was taught by the non-human inhabitants at his first stop. I'm trying to get the subcaptions and captions in sanserif font and Uppercased. According the manual of the caption package this should be possible in the following way.However, this doesnt seem to work. Am I defining something in the wrong way here?  \documentclass{article} \usepackage{floatrow} \usepackage[demo]{graphicx} \usepackage{subfig} \usepackage{caption} \floatsetup[figure]{subcapbesideposition = top}  \captionsetup{labelfont={sf,up}, labelsep=period, format = plain, singlelinecheck = false, textfont=rm, skip = 2pt} \captionsetup[subfloat]{labelfont = {up,sf},format = plain,textfont = rm,labelformat = simple, labelsep = period}  \begin{document}   \begin{figure}[h!]   \ffigbox[\textwidth]     {\begin{subfloatrow}         \sidesubfloat[]{\includegraphics[width = 0.4\textwidth]{A.pdf}}%         \sidesubfloat[]{\includegraphics[width = 0.4\textwidth]{B.pdf}}%       \end{subfloatrow}       \begin{subfloatrow}         \sidesubfloat[]{\includegraphics[width = 0.4\textwidth]{C.pdf}}%         \sidesubfloat[]{\includegraphics[width = 0.4\textwidth]{D.pdf}}%       \end{subfloatrow}}     {\caption{this is a caption}} \end{figure}  \end{document} When a ball is tossed straight up, does it experience momentary equilibrium at top of its path? This question has been asked many times all over the Internet and answers can be found on places such as yahoo and ask.com, but I'm not satisfied with those answers and I don't trust the validity of those places.  This seems like a more appropriate place to ask.  So, here's my train of thought and I would like to ask you if you think I'm right or wrong.  Even though most of the answers point to the fact that the ball does not achieve equilibrium because the force of gravity is constantly acting upon it, thus causing an acceleration, I still think there's a moment of equilibrium and here's why:  When the ball is traveling up, it's accelerating towards the ground and eventually reaches a point at which its speed reaches 0.  At this moment, isn't the reason the speed is 0 is due to the fact that net force is 0?  The force that made the ball travel in the upward direction was canceled out by the gravitational force.  So, the sum of forces at that brief moment is equal to 0, otherwise the ball would be moving.  I don't think gravity is the only force acting on the ball at that moment, since the throwing force was acting on it as well, until both canceled each other out for that brief moment.  Am I right or wrong? Why can't I adopt children despite having a steading in Falkreath? I bought two pieces of land. One from Morthal, and one from Falkreath. Morthal was the first plot of land I purchased. I only finished half of it. I bought the plot of land in falkreath because I liked the nature better. I finished the house completely in Falkreath. Every time I try to adopt a child off the streets it keeps saying "I have a place but no room for you" Even though I have the bedrooms in my Falkreath house. Why can I not adopt a child and have him/her live at my house in Falkreath? What's the action of banging two beers together called? Evolving Pokemon based on CP vs Moves Many people are evolving their pokemons based on the CP. However, there's a growing number of people evolving based on Moves instead of CP. In other words, choosing pokemons that have the highest Moves to keep, even if it isn't necessarily the highest CP. I am new to pokemon and don't quite understand the difference between the two. Thus, which strategy is better? I am using a local (company) network which provides some servers which are also available from the outside (through one public static IP and port forwarding). And there are some domains which are pointing to the public IP.  What I want is my domains pointing to the local IPs when being inside the local network. I know I will need a local (internal) DNS server which changes the domains to the IPs. I am able to setup the DHCP server to deliver the DNS to the local clients (so this won't be any problem).  What kind of DNS server software can I use to:   repeat all domains like a DNS would do that but for only my domains use the local values Where can I get flight info for a flight a month ago for an insurance claim? Flight stat sites will only show a weeks worth of data. How to find out which (not installed) Debian package a file belongs to? On Debian systems (and derivatives):  $ dpkg --search /bin/ls coreutils: /bin/ls   That is, the file /bin/ls belongs to the Debian package named coreutils.  But this only works if the package is installed. What if it's not? Is it correct to sometimes capitalize words mid-sentence in computer user interfaces? Verify mysqldump backup is corruption free What's the difference between mobile and desktop processors? I just read about the new Samsung Galaxy Note Edge having a 2.7&nbsp;GHz quad-core processor and 3GB of RAM.  The laptop I bought last year by HP is 4&nbsp;GB of RAM and 2.3&nbsp;GHz quad-core and my iMac is even older and is 2.5&nbsp;GHz i5.  Does this mean that the new Samsung gadget is more powerful than my desktop?  Is the 2.7&nbsp;GHz the same kind of GHz as non-mobile devices (is it scaled up, or compared, etc.)?  Why, in terms of power, do modern computers not have two of those Samsung quad-core processors running in parallel pushing out 5.4&nbsp;GHz processing power for the amount of electrical energy as two Galaxy Note batteries? Old phone cannot connect to computer, the "computer connection" icon appears on phone I would like to get some pictures and audio out of an AT&amp;T SGH-a687 phone onto my Mac computer. I first tried connecting it to a New PC Studio on a PC, but there was a problem after transfer 2 photos, so I tried again. But the PC could no longer detect the phone, even though the "connected to computer" icon appears on the phone. I tried a different cable, different USB ports. No use.  So I downloaded the Samsung Kies on my Mac. Same thing, it tries to search for the phone once I connect the phone, but the computer doesn't detect anything. The phone still shows the "connected to computer" icon.  There is also Bluetooth (no internet on the phone) on the phone, but it failed to send the picture each time I tried.  What can I do at this point? Please also suggest data extraction software for either Mac or PC, if that's the easier route. A real $2 \times 2 $ matrix $M$ such that $M^2 = \tiny \begin{pmatrix} -1&0 \\ 0&-1-\epsilon \\ \end{pmatrix}$ , then : A real $2 \times 2 $ matrix $M$ such that $$M^2 =  \begin{pmatrix} -1&amp;0 \\ 0&amp;-1-\epsilon  \\   \end{pmatrix}$$ (a) exists for all $\epsilon &gt; 0$. (b) does not exist for any $\epsilon &gt; 0$. (c) exists for some $\epsilon &gt; 0$. (d) None of the above is true.  Attempt: I couldn't think of any theory base to prove / disprove the existence of such a matrix. Could someone please give me a hint on how to go about this problem? Thank you very much for your help in this regard. Most of the time, it should be really easy to determine who is my ally and who is not. The people who try to kill me are most likely my foes, whereas the people who entered the dungeon with me are probably my allies.   But sometimes it’s not that simple. What if one of my party members got replaced by an evil doppelganger, who plans to kill me in the near future? What if one of my allies infiltrated the court of the evil king and I accidentally have to fight her, while she is (unbeknownst to me) under the effect of a  spell? What if a character fell in love with the BBEG and just wants to save him from himself, while the BBEG hates the character and actively tries to murder him?  Most spells and abilities that affect others specify the targets as “creatures” or “willing creatures”. Some explicitly affect allies only. That’s why I want to know, how to determine who’s allied with whom. Do I have to think that someone is my ally for someone to count as my ally? Does someone else have to believe to be my ally in order to count? Do both of us have to agree on being allies? Is there an objective observer who determines who’s allied? Can Person A be the ally of Person B, while Person B is not the ally of Person A?  There are many examples for spells/abilities that care about allies, among others:   the Exalted Champion feature from the  (SCAG, p. 132-133), that grants allies within 30 feet advantage on Wisdom saving throws. the Inspiring Surge feature from the  (SCAG, p. 128), that allows one or two allies within 60 feet to make a melee weapon attack as a reaction.   With features like this, you could accidentally affect someone who’s not actually your ally. You could fail to affect someone who is actually your ally, but you don’t know it (yet). Or you could affect someone who doesn’t want to be affected (because they don’t want to be allied with you). This all depends on the interpretation of the word “ally”. I’m not sure if "ally" is a defined game term (but I don’t think so), or if I have to rely on the dictionary definition. That’s why I want to ask:  How do I determine who’s allied with whom?