The title says all. I tried several syntax, all failed. Maybe this is not possible with a single shoot... Of course, search engines didn't help, nor the manual that is difficult to understand, nor the info command. All lack an example with a range of "kind of" preselection
In a file with lots of lines I want to delete lines that starts with HERE IT IS.  How can I do this using only command-line tools?
I have designed a VF page to create a new record in which I am trying to display the value of a pick-list field. I have set a default value for this pick-list field. When trying to create the record using the salesforce native page, the value with which pick-list loads is the one I set as default but when creating the same record using VF page, the pick-list loads with "--None--" as default value.  Can anyone suggest If this is salesforce related bug or Am I doing anything wrong ? How to secure Elliptic Curve ElGamal encryption against known plaintext attacks? If I have an encoding function  $f(x)$ that maps a message $m$ to a point $P$ on a suitable Elliptic Curve $E$ . If I have the public key $Q$ of my recepient then I can encrypt the message as follows:  Choosing a random number $k &lt; n -1 $ where $n$ is the order of the curve E .  Calculating $C = [k] G $ where $G$ is the generator point of the curve E   Calculating $R = [k]Q $ where $Q$ is the recipient's public key   Now the message is encrypted by adding $P$ to $R$ to get          $C_e$ $( = R + P)$ which is sent along with $C$ to the recepient.  DECRYPTION:  Now for the recepient to decrypt my message they compute $R = [privatekey] C $ (where $C = [k]G $) and simply subtract $R$ from $C_e$ to get the encoded point $P$ back which is then decoded by an inverse function $f^{-1}(x)$ to recover $m$.  Now , two problems arise : If the attacker knows the plaintext (suppose if I follow a particular format of data while sending messages ) he could encode his guessed plaintext and subtract it from $C_e$ to recover $ R $ back ! . If I used that same $ R  $ to encrypt further "blocks" of my message then the security of the later parts of my message has been breached!   I realize that doing  something like a scalar multiplication over and over again for every block of data, would be a huge drawback in efficiency and speed.   Is there any way to compute a different $ R $ for every block of data, without using much resources and that too quickly ?   Does reusing the same $R$ for another message break security ?  NOTE: This question is for educational purposes only. It's for the sake of expanding my knowledge on Crypto. my 4 week old daughter will not stop crying. We've tried everything from sucking, both on pacifiers and fingers to breastfeeding, white noise, movement, diaper is clean she doesn't seem to have a fever.   We've tried everything we can read about and think of.  We are both a little bit ill, the common cold and the baby may have gotten it and be upset but we are just at the end of our nerves when nothing helps our poor little one!   Does anyone know anything we can do to help? Rails Previous Sunday in Relation to Any DateTime How to force the Y axis to only use integers in Matplotlib? Calculating $\sum_{n=1}^\infty\frac{1}{(n-1)!(n+1)}$ I want to calculate the sum:$$\sum_{n=1}^\infty\frac{1}{(n-1)!(n+1)}=$$  $$\sum_{n=1}^\infty\frac{n}{(n+1)!}=$$ $$\sum_{n=1}^\infty\frac{n+1-1}{(n+1)!}=$$ $$\sum_{n=1}^\infty\frac{n+1}{(n+1)!}-\sum_{n=1}^\infty\frac{1}{(n+1)!}=$$ $$\sum_{n=1}^\infty\frac{1}{n!}-\sum_{n=1}^\infty\frac{1}{(n+1)!}.$$  I know that $$\sum_{n=0}^\infty\frac{1}{n!}=e$$  so $$\sum_{n=1}^\infty\frac{1}{n!}=\sum_{n=0}^\infty\frac{1}{n!}-1=e-1$$  But, what can I do for $$\sum_{n=1}^\infty\frac{1}{(n+1)!}$$ ?  Am I allowed to start a sum for $n=-1$ ? How can I bring to a something similar to $$\sum_{n=0}^\infty\frac{1}{n!}$$? Upgrading from Yosemite to El Capitan, but not Sierra We have an older iMac (Model A1311, Mid 2011). It has been running Yosemite. We have run into some of the WIFI issues associated with Yosemite.   Is it possible to upgrade to El Capitan but not Sierra?   El Cap has been out longer. Its my wife's computer, its older, and I really don't want to be debugging Sierra until a few  more "dot" releases come out. I am not asking about the two factor authentication process where the user needs to enter both a password and a one-time-password.  Gmail recently (I don't know from when exactly) changed their login process which is depicted in the following screenshot:     So, the new steps are as follows:   Enter email   Click Next  Enter password   Click Sign In    as opposed to the previous and usual way of logging in:   Enter email and password   Click Sign In    Isn't the new process non-user friendly requiring extra user interactions?  Since, Google does not usually make UX blunders can you explain the reasoning behind the new process? I'm looking for details like user interaction simplicity or any other hidden advantages.  Note: The question  doesn't cover the reason behind the change while Mervin Johnsingh's answer cites Google's reason. Why do the major and minor groove exist in DNA? So I know that the major/minor groove arise from the offset pairing of the two strands in the helix.  All my textbook tells me is that "pitch causes the off-set pairing of DNA and this gives rise to the major and minor grooves."  I'm not too sure what this is saying.  What exactly is pitch and how does it give rise to the grooves? KernelEvents::REQUEST is not fired on cached pages I'm looking for a word that can describe a person who does nice things for other people (e.g holding the door open, carrying someone's things) but only for self gain; this person only does nice things to make themselves look good in the eyes of others, but doesn't actually care about the well-being of the people they're helping. iMac only show flashing folder with question mark after formatting OS X partition drive Today i format my "OS X El capitan" partition for installing "Yosemite". But due an error in bootable yosemite usb it didn't install on this partition. After some hours when i turned on iMac and hold down "option" key for boot into usb but just blank screen and mouse show. And every time when i turend on iMac it only show flashing folder with question mark. I've tried to resolve it by reseting "NVRAM". But after restarting problem still same.  Also I've tried many "Startup key combinations for Mac" but didn't work any combination on startup.  Also i have important data in my other one partition. Please can anyone tell me what i do for resolving that issue Without loosing my data? How many different/unique $4$-letter arrangements are there of the letters in the word Mississauga?  I'm thinking we need permutations? I already tried finding each letter and still don't get it... any help?   So far I've broken it off to:-  $M=1$  $I=2$  $S=4$  $A=2$  $U=1$  $G=1$  However, I don't really know what to do next. When do you use POST and when do you use GET? Partitioning with varying partition size Why are two universal objects isomorphic? How are the number of views in a question calculated? I saw it's not just a page views number, because, if I press F5 several times, it won't increase the number of views.  They could store my IP address in a table, but wouldn't that make it slow? They would need to query a database one more time for each request. How can I edit/create new launcher items in Unity by hand? Styling an input type="file" button How do you style an input type="file" button? top command in cygwin? I am starting to use Cygwin(64) on my Windows 8 laptop, however, the top command is not recognized. I have read online that I need to get the procps package, but it is not available on the 'Cygwin Setup' package selections. How should I go about installing the procps package so that I can use top?  ps. for whatever reason ps and kill both work so I would think top would be included in whatever package allowed those guys to work, but there is no top command.