Well this  answered a  today, however his profile say "I no longer work at Stack Exchange". Did he join again to support Stack Exchange, or is he just a member?  I doubt because still he has a diamond.
As far as I know, the diamond symbol is given to the folks who  are the community elected moderators, for example,  are employees of the Stack Exchange, Inc., for example,   In those regards,  is neither a , nor is he a part of the  since March 1st, 2012. So my question is, other than the fact that he is the , is there any other reason why he still has the diamond symbol next to his name and whether he can still exercise his moderation abilities? :) Note: I do not have any problems with him having the Diamond Symbol. I just wanted to know the reason and whether he still has those privileges or not. In fact, I'd be very happy to know that he still has those privileges because, you know, he knows the site, the Best. :) Note: as of October 2017, .
Firstly, how do I read it? Is below right? With braces   $$p \vdash (q \Rightarrow p)$$  The given proof is:    ${p}$, premise ${q}$, assumption  $p$ by (1) // what???  ${q} \Rightarrow p$ by implication introduction with 2 and 2.1 QED...    I can't really get the link between $p$ and $q$ in 2.1 ... There is a shop in the starting area on the island of Koholint, and if you are fast enough to dance around the shopkeeper, you can steal from him. Once you steal from him, though, your title in the game changes to "THIEF".    Is there any way to change your title back to your name without reverting to a different past save or starting over? Assume I have many TeX files. For the sake of simplicity, also asssume they are in a single folder or directory.  I want to input all files from within my main LaTeX document. Actually I can create a list of those files using C# in advance.  To enrich my view about LaTeX or TeX, could you tell me whether or not this job can be done only by using pure TeX or LaTeX? Let $G$ be a group and $c\in G$. Define $*$ on $G$ by: $x*y=xdy$ for all $x,y\in G$, where $d$ is the inverse of $c$. Prove $(G,*)$ is a group. Let $G$ be a group and $c$ be a fixed element of $G$. Define a new operation $*$ on G by:   $$x*y=xdy$$   for all $x$ and $y$ in $G$, where $d$ is the inverse of $c$. Prove that $G$ is a group under the operation $*$.    If you want to check, this problem is in the book “A Course In Group Theory”, by John F. Humphreys (problem $3$, page $28$)   I know what are the axioms that $(G,*)$ must obey in order to be a group and I did show that all the axioms where obeyed except the inverse axiom.  My problem is that, whenever I try to verify what would the inverse be for some element $x$, I get an equation where the $x$ is cancelled in both sides.  Can please someone guide me?  Thank you!  (P.S.: This is NOT a homework assignment, I’m studying Group Theory by this book and got problems solving this question) I want to install lubuntu on my current (pre-existing) Ubuntu Install because of it's light-weight footprint.   Can I preserve currently installed apps after installation? I'm really having a hard time with this topic in probability theory and I was wondering if someone has any tricks, tips or anything useful to help me understand it. In my notes I am told that $X\sim$Uniform$[0,1]$ and $Y\sim$Uniform$[0,1]$. My professor wrote:      $f_{X+Y}(Z) = \int_0^Z f_X(x) f_Y(Z-x)\;dx \neq Z$   Then somehow he came up with these cases where $Z$ is defined, and used that in making the pdf. I'm just not sure of how he did this or how he also came to find $P(X_1+X_2\le 2)$. Can someone help me fill in the blanks? I went to him directly but he just said the same thing as in lecture and wasn't helpful. What is the correct possessive for nouns ending in "‑s"? How do we control web page caching, across all browsers? Some guy called one of my Snipplr submissions "crap" because I used if ($_SERVER['REQUEST_METHOD'] == 'POST') instead of if ($_POST)  Checking the request method seems more correct to me because that's what I really want to do. Is there some operational difference between the two or is this just a code clarity issue? Prove that $$\cos(\pi/11)+\cos(3\pi/11)+\cos(5\pi/11)+\cos(7\pi/11)+\cos(9\pi/11)=1/2$$ using Euler's formula.  Everything I tried has failed so far.  Here is one thing I tried, but obviously didn't work. $$\Re e \{e^{\frac{\pi}{11}i}(1+e^{\frac{2\pi}{11}i}+e^{\frac{4\pi}{11}i}+e^{\frac{6\pi}{11}i}+e^{\frac{8\pi}{11}i}) \}=\frac{1}{2}$$ $$\Re e \{e^{\frac{\pi}{11}i}(1+\sqrt[11]{e^{2\pi i}}+\sqrt[11]{e^{4\pi i}}+\sqrt[11]{e^{6\pi i}}+\sqrt[11]{e^{8\pi i}}) \}=\frac{1}{2}$$ $$\Re e \{e^{\frac{\pi}{11}i}(1+\sqrt[11]{1}+\sqrt[11]{1}+\sqrt[11]{1}+\sqrt[11]{1}) \}=\frac{1}{2}$$ $$\Re e \{5e^{\frac{\pi}{11}i} \}=\frac{1}{2}$$ $$5\cos(\frac{\pi}{11})=\frac{1}{2}$$ Which isn't true :D  Thanks in advance To display a sensitivity analysis I want to produce a . In the plot a specific base case value is compared to the values produced after changing parameters in the model. I started from this . With this I was able to get this MWE:   \usepackage{pgf} \usepackage{tikz} \usepackage{pgfplots} \pgfplotsset{compat=newest} \usetikzlibrary{positioning} \usetikzlibrary{calc} \usetikzlibrary{intersections,backgrounds} \usetikzlibrary{decorations.pathmorphing}  \pgfplotsset{     TornadoPlot/.style={% Overall settings         width = 1\textwidth,     line width=1pt,     tick style={line width=0.8pt},     xmin = -50, xmax = 50,     xtick       = {-50, -40, -30, -20, -10, 0, 10, 20, 30, 40, 50},     xticklabels = {-50, -40, -30, -20, -10, 0, 10, 20, 30, 40, 50},     xmajorgrids = true,     minor x tick num = 1,     tick align = outside,     xtick pos = left, ytick pos = left,     xbar, bar shift=0pt,     height = 7cm,     enlarge y limits = 0.1, ytick = {0,1,2,3,4,5,6},     nodes near coords={         \pgfkeys{/pgf/fpu=true}%         \pgfmathparse{\pgfplotspointmeta}%         \pgfmathprintnumber{\pgfmathresult}     },     nodes near coords align = {horizontal},     before end axis/.code={         \draw ({rel axis cs:0,0}-|{axis cs:0,0}) -- ({rel axis cs:0,1}-|{axis    cs:0,0});     }              } }  \begin{document} \begin{tikzpicture}     \begin{axis}[TornadoPlot, legend style={at={(0.975,0.25)}}]             \addplot[fill=green!40] coordinates{(-3.5,0) (-16,1) (-17.5,2) (-19,3) (-34,4) (-27,5) (-22,6)};             \addplot[fill=red!40] coordinates{(4,0) (19,1) (12.5,2) (28.5,3) (34,4) (82,5) (38,6)};             \legend{upside, downside}      \end{axis} \end{tikzpicture} \end{document}   However, one of the bars (82, 5) has a positive x value that is outside the range of the domain of the plot. Can I restrict the length of that bar and force a break, while still displaying the original value of x? I have seen  for vertical bar-charts, but so far I have not been able to reproduce this for my tornado plot. I'm trying to recall a story I read in the 1960s or 1970s, but which I suspect was older than that.  It was about a quasi-immortal family in the twentieth century who lived in a rural area and kept a low profile. It was a stand-alone story and only the family, and perhaps distant relatives, had unusual powers. I don't think they were aliens, just some offshoot of humanity.   They were of varying ages, ranging from relatively young to thousands of years old. They had lived in Europe before immigrating to the American colonies. Each person had a distinctive set of psi powers, ranging from the grandpa, pa, ma and son. I believe the youngest, just called Baby, was the most powerful and least human looking, and lived in the attic. He slept most of the time.  Nothing remains in my memory of the plot.  As I recall, the story had a Theodore Sturgeon feeling to it, with a humorous, ironic touch, but it probably wasn't his. I haven't been able to identify it from looking at a list of his works.  I probably read it in an anthology, but I might have seen it in an old magazine. I'm just not sure.  If anyone can help me identify it, I'd be grateful. Then I can scratch that mental itch. How do I make a textbox that only accepts numbers? I have a windows forms app with a textbox control that I want to only accept integer values. In the past I've done this kind of validation by overloading the KeyPress event and just removing characters which didn't fit the specification. I've looked at the MaskedTextBox control but I'd like a more general solution that could work with perhaps a regular expression, or depend on the values of other controls.  Ideally this would behave such that pressing a non numeric character would either produce no result or immediately provide the user with feedback about the invalid character. I currently have a 75% credit utilization, which I know is not favorable on about 35,000 revolving credit.  I am getting my year end bonus and plan on using that to completely pay off all of my credit cards leaving me with a 0% credit utilization.  Currently my credit score is 668, mostly due to my utilization, I pay everything on time, but just have too much debt, which is why i'm paying it all off.  My question is how much will paying off all my revolving credit and having a 0% utilization on 35,000 credit availability positively effect my credit score? Edit: The previous title didn't really ask the same thing as the question (sorry about that), so I've changed it. To clarify, I understand that the action isn't always a minimum. My questions are in the points 1. and 2. below.  I understand that &quot;principle of least action&quot; is somewhat of a misnomer, since we find that to determine the path taken by a system, we need only impose the condition that the action be stationary, i.e., that $\delta S$ should vanish to first order for small variations of the path, and this leads to the Euler-Lagrange equations. In The Classical Theory of Fields, Landau &amp; Lifshitz discuss the relativistic action for a free particle:  So for a free particle the action must have the form $$S = -\alpha \int_a^b ds$$ (...) It is easy to see that $\alpha$ must be a positive quantity for all particles. In fact, as we saw [earlier], $\int_a^b ds$ has its maximum value along a straight world line; by integrating along a curved world line we can make the integral arbitrarily small. Thus the integral $\int_a^b ds$ with the positive sign cannot have a minimum; with the opposite sign it clearly has a minimum, along the straight world line.  There is also a footnote, addressed a couple of paragraphs earlier, but which is relevant:  Strictly speaking, the principle of least action asserts that the integral $S$ must be a minimum only for infinitesimal lengths of the path of integration. For paths of arbitrary length we can say only that $S$ must be an extremum, not necessarily a minimum.  I have two questions regarding this:  How is the condition &quot;the action must be a minimum for infinitesimal displacements&quot; formulated? I've never heard of that outside of Landau &amp; Lifshitz's books, and in Mechanics they mention it as well but doesn't go into detail. Is this discussed a bit more somewhere?  If for the whole path the action only needs to be stationary, how can we make the argument for the negative sign? If the action had to be a minimum then it would make sense, but surely the fact that $\delta S$ = 0 isn't affected by an overall sign? How to ignore accent in SQLite query (Android) Display the Number of Comment Upvotes In Recent Activity Pages It would be helpful if we could see the number of upvotes cast for our comments, or other people's comments in response to us directly in the user profile in either the activity tab or the response tab respectively. It should be quite easy to implement (e.g. sharing a single partial view for displaying comments).  It could be useful, since we can evaluate the legitimacy of the comment and address horrible mistakes sooner. Evaluating the infinite product $\prod\limits_{k=2}^\infty \left ( 1-\frac1{k^2}\right)$ Evaluate the infinite product $$\lim_{ n\rightarrow\infty }\prod_{k=2}^{n}\left ( 1-\frac{1}{k^2} \right ).$$  I can't see anything in this limit , so help me please. Let $f: \mathbb{R} \to \mathbb{R}$ be continuous. Then $G = \{ (x, f(x) ) : x \in \mathbb{R} \} $ is a closed set.  My try: Suppose $(z_n) =  (x_n, f(x_n) ) $ is sequence in $G$ with limit $(x,y)$. We must show $(x,y) \in G$. Since $x_n \to x$ and since $f$ is continuous, then we must have that $f(x_n) \to f(x) $. Since limits are unique. Then $y = f(x) $. Is this enough to conlude that $(x,y) \in G $ ? Hence showing $G$ is closed ?  thanks JSON URL from StackExchange API returning jibberish?