Why can't I resize the /dev/sda9 partition? I have plenty of unallocated space for it.
Previously, I have installed Windows 7 on my 320 GB laptop with three partitions 173, 84 and 63 GB each. The 63 GB partition was where the Windows was installed. The rest were for file containers.  Now I changed my OS to Ubuntu 12.04 LTS. I installed Ubuntu by replacing the entire Windows 7 on the 63 GB partition. The rest of the partitions remain as an NTFS Windows partition and I can still access them both (the 173 and 84 GB partitions).  Now I want to change the two partitions of Windows into an Ubuntu format partitions plus most importantly, I want to extend the 63 GB partition to more than a 100 GB because at the moment I am running out of disk space. Whenever I try to install any application, especially using wine, it always complains for a shortage of disk space.  How do I do the extending activity before I entirely format my laptop again and lose all the important files on my partitions?
Is there any way I can separate a List&lt;SomeObject&gt; into several separate lists of SomeObject, using the item index as the delimiter of each split?  Let me exemplify:  I have a List&lt;SomeObject&gt; and I need a List&lt;List&lt;SomeObject&gt;&gt; or List&lt;SomeObject&gt;[], so that each of these resulting lists will contain a group of 3 items of the original list (sequentially).  eg.:   Original List: [a, g, e, w, p, s, q, f, x, y, i, m, c] Resulting lists: [a, g, e], [w, p, s], [q, f, x], [y, i, m], [c]   I'd also need the resulting lists size to be a parameter of this function. Named Credentials - Merge Fields not Resolving So I want to texture clothing for example that I created using the mirror modifier. But I want the 2 sides of the clothing piece to have individual designs for instance but it is not possible since the original and the mirrored surfaces use the same UV-coordinates. How can I change that? Time traveler asks archaeologist for help in transporting a girl from dinosaur Earth to present day Many decades ago, I read a short story about a time traveler who asks an archaeologist for help.  He convinces the archaeologist that he can time travel by bringing him back a freshly killed dinosaur (small one.)  The time traveler needs help because when traveling back in time to the age of the dinosaurs he met a girl and wants to transport her back to the present.  However only one person can travel in time at a time so he needs the archaeologist at the other end to wait for the girl.  The archaeologist agrees to help.  Unfortunately after the traveler goes back he and the girl find themselves in the middle of a battle between aliens on Earth.  They are chased by a dinosaur and never make it back to the present.  The archaeologist meanwhile is digging for evidence that the traveler went back in time and the story or my recollection of it ends with that. showing a collection of sets contain all closed sets Let $X$ be infinite set and $a \in X $. Let $$\mathscr{F} = \{ A \subset X: |A| \; \; finite \; \;, a \notin A \}$$  Then $\mathscr{F}$ is the set all of all closed sets for some topology $\mathcal{T} $ on $X$. Also, any two continuous maps $f,g: (X, \mathscr{T}) \to Y$ ( $Y$ is metric space) have the property that if $f(b) = g(b)$ for all $b \neq a $, then $f(a) = g(a)$.  In my notes my professor posted this theorem without proof, so I was wondering what is best way to proof this theorem. I have two submit buttons in a form. How do I determine which one was hit serverside? How can I send a custom desktop notification? I have a custom script and I want to send a desktop notification (the one that appears in the top right corner of the screen) with a custom message. How do I do that? What would be the the mathematical equivalent of this excel formula? =PMT() I need to create a JavaScript form that does the same calculation as this =PMT() function.   mortgage = 220000 rate= 4.75% term = 30   The example formula I have is =PMT(4.75%/12,30*12,220000*-1)  What would be the equation for this function? I tried to look up this function but it doesn't explain it very well. In Adobe Photoshop I am able to select multiple layers at once with Shift+Click.  How can I do that in GIMP? Extend tourist visa stay in USA due to coronavirus and waive I-539 fee My mom has come to US on a tourist visa and her I-94 expires on the first week of May.   Due to the coronavirus, travel restrictions have been imposed in our home country (India). Also we want to avoid the risk of traveling in flights at this time.  Is there an easy way to to extend her stay in the US by one or two months?  I am aware that we should fill out an  to extend our stay. But in-order to submit the online application it requires a fee of $370.    Is filing I-539 the easiest way to extend her stay at this time? If so, is it possible to waive the fee due to the coronavirus situation?  After filing I-539 should she wait for an approval to continue her stay? Or is the receipt good enough?   Can you please help me with these? Thanks!  [Edit 1]:  With the current situation of the virus, traveling anywhere sounds like a very risky operation, especially for elders.   That is the main reason behind this question. If the US government will allow visitors to overstay until Covid-19 settles down! For an architectural visualization, I would like to use MakeHuman models, but:   Only get them to render white with a black outline (on reflection surface too, if possible). Interact with light like normal human bodies in the scene (cast shadows, etc).   I can do the outline in freestyle, but any in-Cycles solution would be appreciated (OSL?) I have connected speakers to the back panel of my computer at work and I would like to have them always enabled (I can switch them off on the speaker casing). However when I connect headphones on the front panel system automatically says that the rear output is unplugged.  I found a solution to disable auto detection with Alsamixer and it works almost ok except the fact that after system restart I need to reconfigure the settings again... How can I set this once and forget about it? biblatex: change name of author according to language? Usually a name stays the same in whatever language. So, whenever I quote a work by Knuth -- be it in an English article or a German one -- I will quote him as Donald E. Knuth.  This is not always the case with ancient or medieval names. They are spelled differently in different languages. Two examples in English | German | French:   Aristotle | Aristoteles | Aristote Thomas Aquinas | Thomas von Aquin | Thomas d'Aquin   This means that when I write an English article, I need a bib-file that contains the English names, but when I want to write a German article, I need to go through my bib file and change the names accordingly. Depending on how often I in fact publish in English or German this could keep me busy and is prone to error.  So, I though, maybe I could have the different names already included in one single bib-file and let biblatex choose the correct name according to the primary language used in the document. Any ideas?  NB: I do not want to use in one single document both spellings Aristotle and Aristoteles (as the following MWE might make you think). Of course, if the article's primary language is English, then all the references to Aristotle will use the English spelling of his name. However, I want to be able to write articles in different languages, without (a) having to edit my bib-files each time or (b) generally maintaing not one single bib-file but two different ones, one for each language, or (c) having two distinct entries in one bib-file  MWE  % !TEX TS-program = lualatexmk \documentclass{scrartcl}  \usepackage{fontspec}         \setmainfont[Ligatures=TeX]{Times New Roman}  \usepackage[ngerman, british]{babel} \usepackage[babel]{csquotes} \usepackage[style=verbose,abbreviate=false,backend=biber]{biblatex}  \usepackage{filecontents}  \begin{filecontents}{\jobname.bib} @book{aristotle:ross:1924,     Author = {Aristotle},    % It is here, I think, that something could be done, e.g., ...     Title = {Metaphysics},     % ... british=Aristotle,ngerman=Aristoteles,french=Aristote     Editor = {William David Ross},     Commentator = {William David Ross},     Introduction = {William David Ross},     Hyphenation = {british},     Location = {Oxford},     Publisher = {Clarendon Press},     Volumes = {2},     Year = {1924}} \end{filecontents}  \addbibresource{\jobname.bib}  \begin{document}  \selectlanguage{british} Some English text.\footcite{aristotle:ross:1924}  \selectlanguage{ngerman} Etwas Text auf Deutsch.\footcite{aristotle:ross:1924}  \end{document} To find all $n$ such that $(n-1)!+1$ is a perfect power of $n$ Replacing NAs with latest non-NA value As a mod when should I vote to close content that is not flagged? I know mods are supposed to step in to quickly close seriously problematic posts and otherwise allow the community to vote to close a post.  But what about when there are four close votes on a question, and I personally feel the question should be closed but isn't worthy of mod super-mega closing? Should I cast the final vote like a normal user (even though it's technically binding) or should I sit back and wait  for the community?  For me the problem is complicated because on UX.SE we hover close to the point where there's not enough high-rep activity to quickly close posts and I was one of those high rep users that used to VtC.  Should I always treat my mod close vote as binding and reserve it for extreme situations, or should I treat my close vote as "normal" when it's the fifth and final vote anyway? An awful identity We take place on $\mathbb C(x_1,...,x_r,x'_1,...,x'_p,u_0,...,u_r,u'_0,...,u'_p)$ with $r,p\in \mathbb N$     Show that :   $$\displaystyle{\sum_{i=1}^r \left(   \frac{\prod_{j=0}^r (u_j-x_i) \prod_{j=1}^p (x'_j-x_i) }{  \prod_{1\leq j\leq r, j\neq i     }(x_j-x_i) \prod_{j=0}^p (u'_j-x_i)}      \right)}-\displaystyle{\sum_{i=0}^p \left(   \frac{\prod_{j=0}^r (u'_i-u_j) \prod_{j=1}^p (u'_i-x'_j) }{  \prod_{0\leq j\leq p, j\neq i     }(u'_i-u'_j) \prod_{j=1}^r (u'_i-x_j)}      \right)}=\displaystyle{\sum_{i=1}^p x'_i +\sum_{i=0}^r u_i -\sum_{i=1}^r x_i-\sum_{i=0}^p u'_i}$$   I have seen this exercise in an old book at the library. Unfortunately there was no indication how can I solve the problem.   Anyway if someone can give me some ideas it will be greatful.   NB: Sorry for the title, I have not had other ideas A property of every real polynomial. Question: For every polynomial $P(x)$ of degree at n we have $$\sum_{i=0}^{n+1}(-1)^i\binom{n+1}{i}P(i)=0$$  Well I was inducting on degree of the polynomial, for $n=0$ its true and I got a bit confused in the inductive step, actually I cant figure the inductive step.   Is this property (if true) a famous one?  Thank you for your help. why could a check if (document.addEventListener) returns false Some people love creating or fostering the creation of events that are noisy, chaotic and fun, such as parties, arguments, reunions, etc. Sometimes there's a negative connotation to this (like in provoking an argument), but sometimes there is not (like in organising a big, noisy party).  The word I'm looking for would be the English equivalent to the Spanish armadanzas, just in case this is helpful.  Any ideas?