When using the Stack Exchange iOS app, the edit button for suggesting edits appears to be missing when viewing posts from a per-site meta.     App Version: 1.6.4 Device: iPad mini 2G (Wi-Fi) OS Version: Version 10.3 (Build 14E277)
I love the  that was recently added onto Stack Exchange. However, this feature seems to be missing in per-site metas.  For instance:  Server Fault Meta:    DBA Meta    The parent websites, do have the edit/improve this post link however.
What exactly is weakly informative prior? Is there a precise definition of weakly informative prior?  How is it different from a subjective prior with broad support? At least one prime between $\sqrt{n}$ and $n$? Prove that for all $n&gt;2$ there exists at least one prime $p$ such that $\sqrt{n}&lt;p&lt;n$ using elementary methods.  My try: If not, $\sum_{p&lt;\sqrt{n}} (\lfloor n/p \rfloor-\lfloor \sqrt{n}/p \rfloor) \geq n-\sqrt{n}$  then...? Is a constant condition more costly than switching shaders? "big enough to do this" My question is what is the difference among these three sentences.   He is big enough to do such  heavy works. He is not big enough to do such heavy works. He is small enough to do such  heavy works.   I am so much confused between 2 and 3.Also, I don't get what the 3rd one means. Getting attributes of Enum's value CPU on Ubuntu running high In the terminal I used "top" to check the processes and how much of the CPU was being used as I thought max was 100%, so I restored 292,000 photos with recoverjpeg on my sda1 HDD, I opened the folder and the Nautalis is  fluctuating between 130% and 170% , should I close the program and am I at risk of my gpu locking up ? Even though JRE 8 is installed on my MAC OS Yosemite, the error - " No Java Runtime present,requesting to install " Dropping the '-ing' in noun adjuncts I always remember many verbs ending in -ing.  Swimming club/cap and shaving foam for example. I now see increased use of swim club and shave foam.  Why has this happened, is it correct use of English ? Am I technically allowed to look up cards during a Magic tournament match? Am I allowed to look up a card during a game, if it's being played with serious Rules Enforcement? Either to read the full card from the Gatherer, or to try to find the exact card I'm vaguely thinking of.  Two possible scenarios:   An opponent has revealed a card previously, and I want to remember the exact details. (Something like the exact wording of a sorcery, mana cost, keywords on a creature, subtypes, etc. etc.) I have a "name a card and remove it from the opponent's deck" type card, and I want to, say, ask google for "Blue Gearhulk" to remember that it's that that one is called "Torrential Gearhulk".   Obviously, in casual or semi-casual games neither of these are a problem. Any reasonable opponent will just re-reveal the known card (assuming it IS still guaranteed to be known) or will accept "I name the Blue Gearhulk".  Also obviously, it seems unlikely that I (or anyone else) would get to the stage of playing at the REL without knowing the cards too thoroughly for this to be relevant.  But in principle... is it permitted? Or not? (and if not, is there a good reason, or just "we decided 'No'"?) I have my mobile phone (Samsung Galaxy S2) running on ICS. Recently I activated Microsoft Exchnage ActiveSync to connect to my corporate email. It disabled all the security options like 'Pattern Unlock'. I hated it, and removed my microsoft active exchange account from the phone, but these options are still disabled. How do I get it enabled? Uniform Continuity implies Continuity Let $f$ be a function from a metric space $X$ to a metric space $Y$. Show that if $f$ is uniformly continuous on $X$ then $f$ is continuous on $X$. Show that the converse is not true.  Uniform continuity definition:  $∀ε&gt;0:∃δ&gt;0:∀p,q∈X:d_{X}(p,q)&lt;δ⟹d_{Y}(f(p),f(q))&lt;ε$  Continuity definition:  $∀ε&gt;0:∀p∈X:∃δ&gt;0:∀q∈X:d_{X}(p,q)&lt;δ⟹d_{Y}(f(p),f(q))&lt;ε$  I wonder if these proofs are correct and if they are formal enough?    Uniform continuity ⟹ Continuity   Let $f$ be uniformly continuous. Fix $ε_{0}$, obtain $δ_{0}(ε_{0})$ (as a function of $ε_{0}$), fix any $p_{0}$ and $q_{0}$ and we know that:   $d_{X}(p_{0},q_{0})&lt;δ_{0}⟹d_{Y}(f(p_{0}),f(q_{0}))&lt;ε_{0}$   If we want to prove that $f$ is continuous at $p_{0}$, we fix $ε_{0}$ and we pick the same $δ_{0}$ as above and fix any $q_{0}$ and we are assured by 1. that   $d_{X}(p_{0},q_{0})&lt;δ_{0}⟹d_{Y}(f(p_{0}),f(q_{0}))&lt;ε_{0}$   Since $p_{0}$ was arbitrary, $f$ is continuous at $X$.     Continuity $\color{red}{\implies}$ Uniform continuity   Let $f$ be continuous. Fix $ε_{0}$, fix any obtain $p_{0}$ and $p_{1}$, obtain both $δ_{0}(ε_{0},p_{0})$ and $δ_{1}(ε_{0},p_{1})$ (not necessarily equal), fix any $q_{0}$ and $q_{1}$ and we know that:   $d_{X}(p_{0},q_{0})&lt;δ_{0}⟹d_{Y}(f(p_{0}),f(q_{0}))&lt;ε_{0}$  $d_{X}(p_{1},q_{1})&lt;δ_{1}⟹d_{Y}(f(p_{1}),f(q_{1}))&lt;ε_{0}$   For $f$ to be uniformly continuous, if we fix $ε_{0}$, obtain $δ$, fix any $p_{0}$, $p_{1}$, $q_{0}$ and $q_{0}$ we must have that:   $d_{X}(p_{0},q_{0})&lt;δ⟹d_{Y}(f(p_{0}),f(q_{0}))&lt;ε_{0}$  $d_{X}(p_{1},q_{1})&lt;δ⟹d_{Y}(f(p_{1}),f(q_{1}))&lt;ε_{0}$   But those two implications need not hold for the same $δ$ as shown above. Suppose we pick $δ_{0}$ and w.l.o.g. we suppose $δ_{0}&gt;δ_{1}$. Then it could be the case that   $δ_{1}&lt;d_{X}(p_{1},q_{1})&lt;δ_{0}$  but we cannot conclude ⟹$d_{Y}(f(p_{1}),f(q_{1}))&lt;ε_{0}$.  Therefore, continuity does not imply uniform continuity. What can I do if my USB flash drive is write-protected or read-only? Creating additional Virtual Host Ubuntu Server How to set up a wi-fi hotspot with an Ubuntu laptop (access point mode)? I've read , and carefully followed the instructions provided. I am sure the wireless card in my laptop supports going into wireless access point mode. But unfortunately, when I use the following command to start hostapd service it throws an error:   $ sudo service hostapd stop  Starting advanced IEEE 802.11 management hostapd                      [fail]    The instructions mentioned above said this could possibly be because my wireless card does not support the g mode, and provided the wiki of hostapd. But what is g mode? I tried to switch to a, or b mode, but it just didn't work.  Can anyone help with this or recommend a tool like connectify in windows ?  ps. I am using Ubuntu 12.04, 32 bit. I have an ADSL wired network, and I want to share it by setting my laptop into a WiFi hotspot with  my windows phone. How many physical degrees of freedom does the $\mathrm{SU(N)}$ Yang-Mills theory have? I am unit testing a .NET application (.exe) that uses an app.config file to load configuration properties.  The unit test application itself does not have an app.config file.    When I try to unit test a method that utilizes any of the configuration properties, they return null.  I'm assuming this is because the unit test application is not going to load in the target application's app.config.  Is there a way to override this or do I have to write a script to copy the contents of the target app.config to a local app.config?     post kind-of asks this question but the author is really looking at it from a different angle than I am.  EDIT: I should mention that I'm using VS08 Team System for my unit tests. I have a nominal variable (different topics of conversation, coded as topic0=0 etc) and a number of scale variables (DV) such as the length of a conversation.   How can I derive correlations between the nominal and scale variables? I read somewhere that companies are not required to pay dividends to shareholders (this is correct, yes?).   If so, then if company A never pays dividends to its shareholders, then what is the point of owning company A's stock? Surely the right to one vote for company A's Board can't be that valuable.   What is it that I'm missing? extending convergence radius using one boundary point Show that if $f(z)=\sum\limits_{n\geq0}a_nz^n$ is analytic in $\{z\in\mathbb{C}:|z|&lt;1\}\cup\{1\}$ and $\forall n\geq0:a_n\geq0$ then the radius of convergence of the power series is strictly larger than $1$.  My approach:   Let $D=\{z\in\mathbb{C}:|z|\leq1\}$.  We have that $f(1)$ converges, so $\sum\limits_{n\geq 0} a_n&lt;\infty$. Moreover since the $a_n$'s are all positive we have that $|a_n|=a_n$, therefore $\sum\limits_{n\geq 0} |a_n|=\sum\limits_{n\geq 0} a_n&lt;\infty$.  Let $f_n(z)=a_nz^n$, then $\forall z\in D, n\geq 0$ we have:  $$|f_n(z)|=|a_nz^n|=|a_n|\cdot|z^n|=a_n\cdot |z|^n\leq a_n\cdot 1^n\leq a_n$$  Then, applying Weierstrass M-test we get that the power series is convergent in $D$.  Now, I need to "find" an open ball $B$ such that $D\subset B$ and the power series is convergent in it.  Edit  $f$ is analytic in $1$, so there is an open set $U$ that contains $1$ such that   $$f(z)=\sum\limits_{n\geq 0} b_n(z-1)^n$$  Does it mean that the series is convergent in $U$?   I can see that we have that the two series coincide in $D\cap U$. Adobe Creative Suite alternative The programs that I am mainly interested in is Adobe Photoshop, Adobe Illustrator (create vector art), Adobe Flash (for animation), Adobe Premiere Pro (edit video), Adobe After Effects (VFX/motion graphics), Adobe Dreamweaver (code HTML/CSS). But can boil down to a video editing software, graphics software and photo editing software.  I understand alternatives such as Inkscape is like Illustrator, Blender is a good substitute for Adobe Flash. Notepad++ for Dreamweaver but if you haven't noticed, these programs are from different companies. What I do appreciate about Adobe is under the master collection, I get all these programs, but I don't appreciate the price (because I can't afford) or the subscription model (I like to buy once and forget) they now have.  I have searched online and can't find something that packs in programs such as Adobe, even if it's just a photo editing software and vector software.  I found Corel Draw, but I'm so confused if they provide a master collection (collection of their software for a price) that will satisfy my needs.  Is there an alternative to Adobe Creative Suite for designers/enthusiast?