I'm trying to properly render the following formula:    This is what I've got so far:  aufgel"ost nach $B^A$ ergibt sich  \begin{equation}     \boxed{B^A = \mathit{VS} \cdot \frac{_{\textbar n}A_x + \mathrm{"a}_{x:n} \cdot \gamma}{(1 - \beta) \cdot \mathrm{"a}_{x:t} - t \cdot \alpha^Z}} \end{equation}  bzw. f"ur $t = n$   Rendered result:    However, I can't find the symbol for the actuarial angle for the letters n and t in the numerator and denominator in the AMS symbols list.
How do you write this in LaTeX:
how to have a custom zsh auto_cd command Instead of the normal cd I've created my own function  function cd {     builtin cd "$@" &amp;&amp; ls -F }   This works great for when I use commands like cd someDir/subDir but not when I change directories via zsh's auto_cd someDir/subDir.  Is there a way to customize what command gets called for auto_cd? Asks a question; never responds to answers/comments What do we call someone who asks a question and never responds to answers/comments?    Think of it more as "a pattern of behavior" (somebody who has asked many questions and never responded). I had unresponsive in mind, but that doesn't say that they asked in the first place. Javascript remoting: to invokeAction or not to invokeAction Digging in deeper to Javascript Remoting and I'm a bit confused.  The  starts off by showing how to set up everything and uses code like the following:  function getRemoteAccount() {     var accountName = document.getElementById('acctSearch').value;      // This remoting call will use the page's timeout value     Visualforce.remoting.Manager.invokeAction(         '{!$RemoteAction.AccountRemoter.getAccount}',         accountName,          handleResult     ); }   However, I've also seen examples where Visualforce.remoting.Manager.invokeAction is never called.  They end up looking something like the following:  function getText() {   var text = "";   JSRemotingBasicsController.doGetText(     function(result, event) {       // do something here     }   ); }   I'm wondering what is the point to using Visualforce.remoting.Manager.invokeAction when you can just reference the RemoteAction directly like the second example?  Is there something I'm missing?  Is there a time where the second example doesn't work? Where to find Birth and Death Records for Bucharest, Romania? My husband's family came from Bucharest. Specifically his mother was born in Sibiu.  I have been able to piece together names and relations of several grand and great grandparents from word of mouth and some fortunate pictures they had of the cemetery in Sibiu.  I cannot however find any records of birth's and death's for any of them.   Are there sites or organizations that hold records for Romania? Establishing a Basis for $F[x]/(f(x))$ Hypothesis:   $f(x) = a_0 + a_1 x + \ldots + a_n x^n \in F[x]$ s.t. $f(x)$ irreducible over field $F$. $deg(f(x)) = n \ge 1$. Let $V = (f(x)) \subset F[x]$.   Goal: Show that $\mathcal{B} = \{1 + V, x + V, x^2 + V, \ldots , x^{n-1} + V\}$ forms a basis for $E = F[x]/V$  Attempt:   Linear Independence: If this set weren't linearly independent, then a non-trivial $b_i \in F$ would satisfy  $$ b_0 + b_1x + \ldots + b_{n-1} x^{n-1} + V = 0 + V $$   But this would then imply that $b_0 + b_1x + \ldots + b_{n-1} x^{n-1}  \in 0 + V$. But this would contradict $V = (f(x))$ since it is impossible that $f(x)\,\,|\,\,b_0 + b_1x + \ldots + b_{n-1} x^{n-1}$ of strictly lower degree.  Now how would I show that this set spans $F[x]/V$? How do I get the form id of my form? I've just begun to make my modules and I'm at a standstill. I got this code from someone else and am trying to customize it:  function hook_form_alter(&amp;$form, &amp;$form_state, $form_id) {   if ($form_id == 'the form id for the node form') {     $form['#submit'][] = 'my_custom_submit_handler';   } } Scientists have found very bright source of light which they call  and the are found to be . So these black holes are so massive that they cannot be formed by a supernova. So how are these formed? Proving the set of points at which a function diverges to $\infty$ is countable Let $f\colon\mathbb{R}\to\mathbb{R}$. Prove that the set    $$\{x \mid \mbox{if $y$ converges to $x$, then $f(y)$ converges to $\infty$}\}$$ is countable.   My book told me to consider  $g(x)=\arctan(f(x))$, then it said "it is easy to see the set is countable." But I still can't understand what it mean. Guests see the Protected notice , somewhat displaced:    Logged in, all is fine:    It actually belongs there, at the bottom, but then it has some design glitches, or it needs to be placed at the top.  Verified on Firefox and Chrome stable. How to prevent mail from our website going into spam mail of users? I work for an educational services company based in India. We've around one million students enrolled as users. We're frequently facing the problem of our bulk mailers regarding upcoming exams, new product launches and promotions going into spam mail folders of the students. Is the problem in the headlines? Or where else? what can we do to reduce this number?   This is killing us, we cannot have an impossibly large precentage of mails not being opened..Please help. Graph Theory: Tree has at least 2 vertices of degree 1 What is the best way to parse html in C#? Strange bug with "MessageName[a,b] is not of the form symbol::name ", Debugger & cursor location Using \footnote in a figure's \caption Maybe this is an easy one, but I struggled with this now too long :)  I want to have a footnote in a caption of a figure, see the example.   \begin{figure}[!ht]   \caption{a figure caption\footnote{where i got it from}}   \label{somelabel}   \begin{center}        \pgfuseimage{...}   \end{center} \end{figure}   The compilation error reads as follows  ! Argument of \@caption has an extra }. &lt;inserted text&gt;              \par  l.192 ...i got it from}}   The actual tex code for my figure with the answer of Leo  \pgfdeclareimage[width=6cm]{aba.medcenter}{aba.medcenter}  \begin{figure}[!ht]   \begin{minipage}{\textwidth}     \caption[Medcenter Monthly Medication System]{Medcenter\textsuperscript\textregistered Monthly Medication System\footnote{Quelle Bild: http://www.amazon.com/dp/B000RZPL0M}}     \label{aba.medcenter}     \begin{center}       \pgfuseimage{aba.medcenter}     \end{center}   \end{minipage} \end{figure}   leads to the error  ! LaTeX Error: Command \itshape invalid in math mode.   in the same line. If I comment out the foot note, everything compiles fine. \textsuperscript\texttrademark isn't the problem, too. Short brandable domain vs. long keyword domain Where can I safely store my stuff? What is the difference between == and ===?  How exactly does the loosely == comparison work? How exactly does the strict === comparison work?  What would be some useful examples? How did Enrico Fermi calculate the classical Fermi Problem? From Wikipedia: Fermi was known for his ability to make good approximate calculations with little or no actual data, hence the name. One example is his estimate of the strength of the atomic bomb detonated at the Trinity test, based on the distance travelled by pieces of paper dropped from his hand during the blast. Fermi's estimate of 10 kilotons of TNT was remarkably close to the now-accepted value of around 20 kilotons, a difference of less than one order of magnitude.  I have not been able to find any references explaining how he made this calculation. Please provide a reference or an example calculation.  See also: What program can be used to package software into one executable? I need to package an application into a single executable file (so that I don't have to install it, so that it will be portable).  Does anybody know what I can use to make a program portable? I am just looking for some clarification on this exercise:  Let $A = \{a,b,c,d\}$. Give an example of a relation $R$ on $A^2$ which is reflexive, symmetric, and not transitive.  I understand that if I was only dealing with $A$ and and not $A^2$ I could give an answer similar to:  $R = \{(a,a),(a,b),(a,d),(b,a),(b,b),(c,c),(d,a),(d,d)\}$  Here $R$ is reflexive, symmetric, and not transitive.  What is confusing me is the fact that we have $A^2$. I am not sure what I am missing here. I am looking through my book to see if I can figure this out, but if someone could help shed some light on this it would be appreciated.  Thanks,  Tony