Does it mean any day in a timeframe of 60 days max to the action, in other words: it could be 1 day or 59 days before?
I know that both can mean "inside" but what I don't have clear is whether both mean the same when talking about time. For example:   The party is in two days = The party is within two days ??   According to this link  within means a limit that can be exceeded, so I'm wondering too if say "the party is within two days max" is correct or redundant.
How can I get the size of an array from a pointer in C? I've allocated an "array" of mystruct of size n like this:  if (NULL == (p = calloc(sizeof(struct mystruct) * n,1))) {  /* handle error */ }   Later on, I only have access to p, and no longer have n. Is there a way to determine the length of the array given just the pointer p?  I figure it must be possible, since free(p) does just that. I know malloc() keeps track of how much memory it has allocated, and that's why it knows the length; perhaps there is a way to query for this information? Something like...  int length = askMallocLibraryHowMuchMemoryWasAlloced(p) / sizeof(mystruct)   I know I should just rework the code so that I know n, but I'd rather not if possible. Any ideas? Galois extension is (not) transitive Let $ K/ L /F $ be fields. If $K / L$ is Galois and $ L / F $ is Galois, then $ K / F$ is Galois. We mentioned this very quickly in today's class without justifying. But I have trouble seeing this. Any help is appreciated.  Our definition for $ K / F$ being Galois is the $F$-automorphism group $G = G( K / F) : = \{ \sigma \in aut (G) : \sigma_F = id_F \}$ fixes only $F$, i.e. $ \{ x \in K : \sigma (x) = x \text { for all } \sigma \in G  \} = F$.  But we also showed that $ K /F$ is Galois if and only if $ K/F$ is normal and separable. Can the union axiom be weakened? It is written everywhere that gravity is curvature of spacetime caused by the mass of the objects or something to the same effect. This raises a question with me: why isn't spacetime curved due to other forces or aspects of bodies?  Why isn't it that there are curvatures related to the charge of a body or the spin of particles or any other characteristics? public class doublePrecision {     public static void main(String[] args) {          double total = 0;         total += 5.6;         total += 5.8;         System.out.println(total);     } }   The above code prints:  11.399999999999   How would I get this to just print (or be able to use it as) 11.4? tikz trees: How to not draw a single edge In many countries an application for a PhD position includes a written research proposal, so my questions is what are some advises/strategies to come up with a good topic/idea for a PhD research proposal and how can one assess the quality/fruitfulness of an idea? As an undergraduate student one just doesn't have the experience to foresee which ideas might have promising research results and which probably won't have. (And I doubt that potential supervisors have the time to comment on every idea of every potential applicant in cases where it is possible to establish some kind of contact before the actual application.) I know that there exists at least one solution, because $ax \equiv b \mod m \implies ax - b = qm$  Rearranging terms gives $ax - qm = b$, and since $d | a$ and $d | m$, so $d | b$ it can be said that $b \equiv 0 \mod d$.  I implemented Euclid's extended algorithm and have been able to experimentally verify that the claim holds, but I do not see a pattern or how I can begin to show there are exactly $d$ solutions.  def euclid_extended(x, y, i=0):   if y == 0:     print("iteration {0} returns ({1}, {2}, {3}) - base case hit with ({4}, {5})".format(i, x, 1, 0, x, y))     return (x, 1, 0)   else:     (d, a, b) = euclid_extended(y, x % y, i + 1)     print("iteration {0}. ({4}, {5}) =&gt; ({1}, {2}, {3})".format(i, d, b, a - b * (x//y), x, y))     return (d, b, a - b * (x//y)) I've been trying to track a footage taken by my Samsung Galaxy Note 8.0 (GT-n5100) tablet. It has a good 5 mp camera and I tracked the footage well. But the problem arises at the time of solving the camera. The solve error is too high (more than 2). I don't know the width the tablet's camera sensor or the focal length or any other specifications. So my question is, has anybody been able to solve the camera on footage shot by a smartphone and if yes,  what camera and lense specs did you feed to the Blender? It was nice to discover the option for a room owner to add any user to a room, even if their rep is too low.     ...so I notified the user in question, and as instructed on the next screen, I had them got to chat.stackoverflow.com so that I'd be able to add them.    ...but when they did their part, and I did my part, I got the message:    Obviously both frustrated, the user's next logical question was:  "So I just have ask a couple questions and get someone to upvote them, right?"    Needless to say, we don't want to encourage new users to post questions for the sole purpose of bypassing a frustrating, misdocumented rule.  I realize this will likely quickly get closed since it has at least one  - which hasn't been touched in 5½ years.  However it would be nice if the issue was revisited:  Ideally, it would be cool if RO's did have the option of deciding who had access to the room they "own", but short of that, is it possible to remove the 6 "misleading" words from that page? Prove that $G$ is abelian iff $\varphi(g) = g^2$ is a homomorphism I'm working on the following problem:     Let $G$ be a group. Prove that $G$ is abelian if and only if   $\varphi(g) = g^2$ is a homomorphism.   My solution: First assume that $G$ is an abelian group and let $g, h \in G$. Observe that $\varphi(gh) = (gh)^2 = (gh)(gh) = g^2h^2 = \varphi(g)\varphi(h)$. Thus, $\varphi$ is a homomorphism.  I'm having trouble completing the proof in the reverse direction. Assume that $\varphi$ is a homomorphism. We then know that $\varphi(gh) = \varphi(g)\varphi(h)$ and $\varphi(hg) = \varphi(h)\varphi(g)$. However, I don't see a way to use this to show that $gh = hg$.  Could anyone lend a helping hand? Browsing folders with more than 100000 images I am using UBUNTU 18.10 and I had problem with TL-WN822n v5 driver in UBUNTU and Kali (4.19.0-kali5-amd64)  The problem is driver=rtl8xxxu so I found a driver in this page :   and installed the driver on Kali and it worked perfectly fine but when I wanted to install it on my ubuntu, after I ran the sudo dkms install rtl8192eu/1.0; I got this error :   Kernel preparation unnecessary for this kernel.  Skipping...  Building module: cleaning build area... 'make' all KVER=4.18.0-25-generic...(bad exit status: 2) ERROR (dkms apport): binary package for rtl8192eu: 1.0 not found Error! Bad return status for module build on kernel: 4.18.0-25-generic (x86_64) Consult /var/lib/dkms/rtl8192eu/1.0/build/make.log for more information.   and This is my Log file (/var/lib/dkms/rtl8192eu/1.0/build/make.log) :  DKMS make.log for rtl8192eu-1.0 for kernel 4.18.0-25-generic (x86_64) Sun Jul  7 13:35:02 +0430 2019 make ARCH=arm64 CROSS_COMPILE= -C /lib/modules/4.18.0-25-generic/build  M=/var/lib/dkms/rtl8192eu/1.0/build  modules make[1]: Entering directory '/usr/src/linux-headers-4.18.0-25-generic'   CC [M]  /var/lib/dkms/rtl8192eu/1.0/build/core/rtw_cmd.o gcc: error: unrecognized command line option ‘-mlittle-endian’; did you mean ‘-fconvert=little-endian’? make[2]: *** [scripts/Makefile.build:325:/var/lib/dkms/rtl8192eu/1.0/build/core/rtw_cmd.o] Error 1 make[1]: *** [Makefile:1534:_module_/var/lib/dkms/rtl8192eu/1.0/build] Error 2 make[1]: Leaving directory '/usr/src/linux-headers-4.18.0-25-generic' make: *** [Makefile:1710: modules] Error 2   What's the problem ?? Number of permutations of $n$ elements where no number $i$ is in position $i$ "Whom" or "who" where the referent is both subject and object? I understand there has been so much on this topic but I am still confused. I get that if the person is the subject it is who and anything else is whom. However, I'm really struggling to work out this rule for the following sentence:     The scope of which his account of morality applies to is therefore restricted to those whom/who the ‘notion of justification to a being of that kind makes sense.’   Should it be who or whom? I can't work out the subject and object. Insert data only if record does not exist Chat gives me really, really specific time gap notifications Reflection is quad dependent and looks non realistic Im rendering varous objects with a Sharp glossy effect but the reflections are quad dependent on the object (image below), meaning they behave separately within every quad making it look 8bit-like. Can anyone tell me why this happens?. (Im pretty sure subdividing would fix it but I want to know why I cant have a low poly object reflecting normaly.  The object has 2 modifiers: Subdiv Surface and Solidify. (Perhaps the Subdiv is causing it?). Help me you Blender savys I dont have a powerful CPU to test and test within every render would take me hours and hours.  Image: I want to prove that in an infinite dimensional normed space $X$, the weak closure of the unit sphere $S=\{ x\in X : \| x \| = 1 \}$ is the unit ball $B=\{ x\in X : \| x \| \leq 1 \}$.  $\\$  Here is my attempt with what I know:  I know that the weak closure of $S$ is a subset of $B$ because $B$ is norm closed and convex, so it is weakly closed, and $B$ contains $S$.  But I need to show that $B$ is a subset of the weak closure of $S$.  $\\$  for small $\epsilon &gt; 0$, and some $x^*_1,...,x^*_n \in X^*$, I let $U=\{ x : \langle x, x^*_i \rangle &lt; \epsilon , i = 1,...,n \} $  then $U$ is a weak neighbourhood of $0$  What I think I need to show now is that $U$ intersects $S$, but I don't know how. How do I mention my own products in answers? Twice now I've seen questions on Stack Overflow where one of my company's products might provide an answer to the question.  One was a slightly vague connection about object-relational mapping, but the other was a specific question about workshop/event management where we have a product which is almost an exact match for the questioner's needs.  Of course the questioner should take a pinch of salt with anything I say about it, but it might be useful to have the product brought to his attention as one possible solution.  What are the rules and guidelines about answering with something I worked on?