Here is my code: public static void numberToWords(int number){     int lastDigit;      if(number &lt; 0){         System.out.println(&quot;Invalid Value&quot;);     }     while(number != 0) {         lastDigit = number % 10; // lastDigit = 3         number = number / 10;         reverse(number);          if (lastDigit == 0) {             System.out.println(&quot;ZERO&quot;);         }         if (lastDigit == 1) {             System.out.println(&quot;ONE&quot;);         }         if (lastDigit == 2) {             System.out.println(&quot;TWO&quot;);         }         if (lastDigit == 3) {             System.out.println(&quot;THREE&quot;);         }         if (lastDigit == 4) {             System.out.println(&quot;FOUR&quot;);         }         if (lastDigit == 5) {             System.out.println(&quot;FIVE&quot;);         }         if (lastDigit == 6) {             System.out.println(&quot;SIX&quot;);         }         if (lastDigit == 7) {             System.out.println(&quot;SEVEN&quot;);         }         if (lastDigit == 8) {             System.out.println(&quot;EIGHT&quot;);         }         if (lastDigit == 9) {             System.out.println(&quot;NINE&quot;);         }     } }  public static void reverse(int a){     int finalDigit = 0;     int reverse1 = 0;      while(a &gt; 0) {         finalDigit = a % 10;         reverse1 = reverse1 * 10 + finalDigit;         a = a / 10;     } }  My digits are printed as strings as desired, but they come in reverse order. I tried to add the reverse method into the conversion method but the results are always the same, can't figure out how to reverse it.
I always thought Java uses pass-by-reference. However, I've seen a couple of blog posts (for example, ) that claim that it isn't (the blog post says that Java uses pass-by-value). I don't think I understand the distinction they're making. What is the explanation?
Share your experiences on exploring iOS 7 with us..  Whether you found hidden or little-known feature of iOS 7 or can explain how a big feature makes a difference, we're looking for objective reports of how the new OS affects your workflow.  Also provide details on how to achieve that feature, and if possible, include a relevant image too (hold Home and Lock for a screenshot on your iOS device).    Please post one tip per answer. Please also check to see if your answer has already been posted - duplicate answers will be deleted in favour of the original answer on any given topic. To search answers for this question use inquestion:101382 (or inquestion:this, directly from the question page) in addition to your search terms in the search box in the upper right hand corner of this page. Is there a term for coining a phrase for a word that already exists? No file output after rendering? I usually am able to render successfully to the c:\tmp folder, but when I came into work today, I rendered out the image on my work laptop, and everything seems to work, but I'm not getting an output to the tmp directory.  Does anyone know how to make this work? How to search for all questions with bounties across the network? I wanted to search for questions on all SE sites that had a bounty. I am not sure if it is possible, and if it is how can I?   I have seen other questions that show how to find questions on each individual site, but how can I find all of them in one search from the homepage stackexchange.com? If this has been asked already, please let me know.  It has been suggested that the question was already asked (click  for the question), but that question only showed how to find those questions on each separate site or some complex way to search. I am hoping to find a way to search for bountied questions easily or for someone to create a way to do this. Show that the polynomial $X^5 + X^3 + \bar{1}$ in $(\mathbb{Z}/2\mathbb{Z}[X])$ is irreducible Show that the polynomial $X^5 + X^3 + \bar{1}$ in $(\mathbb{Z}/2\mathbb{Z})[X]$ is irreducible. (Hint: if it were reducible, it would either have a root or be of the form $g(X) \cdot h(x)$, where deg$g(X) = 2$ and deg$h(X) = 3$) Recall that $\bar{a}$ is shorthand for the coset $a + 2\mathbb{Z} \space $in$ \space (\mathbb{Z}/2\mathbb{Z})[X]$ (for any $a \in \mathbb{Z}$)  This question is worth $7$ marks out of a possible $75$, this is my solution..  $f(X) = X^5 + X^3 + \bar{1}$ is irreducible in $\mathbb{Z}/2\mathbb{Z}[X]$ iff it has no roots in $\mathbb{Z}/2\mathbb{Z}$. Since $f(\bar{0}) = \bar{1}$ and $f(\bar{1}) = \bar{1}$, it follows that $f(x)$ is irreducible in $\mathbb{Z}/2\mathbb{Z}[X]$.  Would this be a sufficient answer? am I missing something? Sometimes I hear sentences that sound conditional to me, just because of the (unassertive) ordering of the words. I don't know if I can come up with a proper example. Consider this:          I'd be a lot better, had she stayed with me.        And I guess it's equivalent to this conditional form: If she had stayed with me, I would have been a lot better.  So, this is my question: In what ways can you make a sentence conditional without using conditional conjunctions (if, unless, etc)? And what are their equivalent conditional forms? Fighter War Magic, Using Booming Blade / GFB If my Fighter (Eldritch Knight) use War Magic (PHB p. 75) to use the cantrip Booming Blade, will I be able to use my Extra Attack, and bonus action attack, to make 3 attacks at level 7? If $A/I \cong A/J$ as rings and $I\subseteq J,$ then $I=J.$ Let $A$ be a commutative Noetherian ring and let $I$ and $J$ be ideals of $A.$  Suppose that $I\subseteq J$ and that $A/I \cong A/J$ as rings.  I want to prove that $I=J.$    Observations so far:  1) If we drop the hypothesis $I\subseteq J,$ then the result is false:  $$\mathbb{Q}[X,Y]/(X)\cong \mathbb{Q}[X,Y]/(Y) \text{ but } (X)\neq (Y).$$  2) If $A/I\cong A/J$ as $A$-modules, then $I=J$:  $$I=\mathrm{Ann}_A(A/I)=\mathrm{Ann}_A(A/J)=J.$$  I'm now a bit stuck as to how to proceed. Any hints would be most helpful!  Many thanks :) How to avoid tripping over UTF-8 BOM when reading files I'm consuming a data feed that has recently added a Unicode BOM header (U+FEFF), and my rake task is now messed up by it.  I can skip the first 3 bytes with file.gets[3..-1] but is there a more elegant way to read files in Ruby which can handle this correctly, whether a BOM is present or not? Intuitive explanation of the tower property of conditional expectation I understand how to define conditional expectation and how to prove that it exists.  Further, I think I understand what conditional expectation means intuitively. I can also prove the tower property, that is if $X$ and $Y$ are random variables (or $Y$ a $\sigma$-field) then we have that  $$\mathbb E[X] = \mathbb{E}[\mathbb E [X | Y]].$$  My question is: What is the intuitive meaning of this? It seems quite puzzling to me.  (I could find similar questions but not this one.) The first time I learnt LaTeX, I thought \newcommand properly fits for inline mode and \newenvironment for displayed mode.  Later I noticed it is not correct. So the question is   What is the rule of thumb when deciding whether we should use one over the other one? I just bought an Xbox 360 game with wrong region. What should I do? I just bought a  game (Forza 4) for my Xbox 360 (bought in the US). When I tried to play the game, it wouldn't load because of region issue. Is there a legal way to solve this (no crack)? How do you transpose tensors? We transpose a matrix $A$ by replacing $A_{ij}$ with $A_{ji}$, for all $i$ and $j$.  However, in case $A$ has more than two dimensions (that is, it is a tensor), I don't know how to apply the transpose operation.   If A has dimensions $3\times 3 \times 8$, then what will replace $A_{ijk}$?  If $A$ has shape $3\times 3\times 8\times 8$, then what will replace $A_{ijkl}$? Modifying cat command to number paragraphs and display last paragraph only I have a text file for which I need to do three things:   Modify the "cat" command to highlight keywords whilst showing the complete contents of the file.  Modify the "cat" command to automatically number the paragraphs. These are separated by a single blank line.  Modify the "cat" command to display the final paragraph only.    The tricky part is that all of these need to be done by modifying the cat command.   I've seen many forum posts explaining that cat is not meant for this - and I can entirely see why. However, the challenge is that I have to use cat! I develop an application in which i constantly get samples of heart pulse.  I defined an interval of t seconds.  In each t seconds I have n samples.  In every interval, I want to calculate the tendency of those n samples. For example, lets say I have n = 5, and I have samples with values {70, 88, 95, 103, 115}. I want to recognize I have a growth in the heart pulse, and I want to have some measure for the rate of grows/decrease/almost no change.  I thought on two approaches for solving this problem.   I calculate the linear approximation for the n samples using linear regression by applying least squares implemented by the normal equations. (I treat each sample as two coordinates vector with x coordinate as time and y coordinate as heart pulse). I get from the normal equations a linear function of the form y = mx+b and my measure for the tendency is the slope, i.e. the m value. The second approach is to calculate the correlation (pearson's correlation) between vector x and vector y when x is the time and y is the heart pulse.   I'm asking which approach do you think is better for my problem (determining the tendency of heart pulses). Or, do you have a better algorithm for solving this problem? Find $P(n+1)$ for a polynomial P Fix a nonnegative integer $n$. Let $P(x)$ be a polynomial of degree $n$ (over the real numbers) such that for all $k\in\left\{0,1,\ldots,n\right\}$, we have $P(k)=\dfrac{k}{k+1}$. Find $P(n+1)$.   My attempt:  I consider a new polynomial $Q(x)=(x+1)P(x)-x$. This $Q$ is a polynomial of degree $\leq n+1$ satisfying: $Q(k)=0\quad\forall k\in\{0,1,2,\ldots,n\}$. Therefore $Q(x)=\lambda x(x-1)\cdots(x-n)$ for a certain real $\lambda$. Hence, $Q(-1)=\lambda \cdot (-1)^{n+1}(n+1)!$, but also $Q(-1)=(-1+1)P(-1)+1=1$. Comparing these, we get $\lambda \cdot (-1)^{n+1} (n+1)! = 1$, thus $\lambda=\dfrac{(-1)^{n+1}}{(n+1)!}$. Since $Q(n+1)=\lambda(n+1)!$ then $Q(n+1)=(-1)^{n+1} $, and from $P(x) = \dfrac{Q(x)+x}{x+1}$ we deduce: $$P(n+1)=\dfrac{(-1)^{n+1}+n+1}{n+2}.$$ I doubted that the answer were $P(n+1)=\frac{n+1}{n+2}$ but the term $(-1)^{n+1}$ wasn’t expected. Is there any mistake here? Does someone have an alternative proof? Expression Functions for Lightning Web Components How can expression functions similar to Visualforce and Lightning Aura Components be achieved within lightning web components?   For example, &lt;template if:true={index % 5 == 0}&gt;&lt;br&gt;&lt;/template&gt; expression index % 5 == 0 is not compyling at all.  accountList.html  &lt;template&gt;     &lt;template if:true={accounts.data}&gt;         &lt;template for:each={accounts.data} for:item='item' for:index='index'&gt;             &lt;!--LWC DOES NOT SUPPORT EXPRESSION FUNCTIONS--&gt;             &lt;!--&lt;template if:true={index % 5 == 0}&gt;&lt;br&gt;&lt;/template&gt;--&gt;             {item}         &lt;/template&gt;     &lt;/template&gt; &lt;/template&gt;   accountList.js  import {LightningElement, wire} from 'lwc'; import getAccounts from '@salesforce/apex/TestController.getAccounts';  export default class AccountList extends LightningElement {      @wire(getAccounts) accounts;  }   Since LWC doesn't support Expression Functions, I'd like to know how to implement them. What does increased caster level affect? A  adds +1 caster level, what does this affect?   Damage from spells? (Like fireball) Duration and area of effect? "Amount" of effect (Like number of missiles from magic missile) Spells known by a wizard (ie +1 caster level mean a level 2 wizard gets the spells as if they were level 3?) Anything else? Bevel is not symmetrical Can't install Ubuntu 18.10 on XPS 15 - EFI\BOOT\mmx64.efi not found I tried to install Ubuntu 18.10 on my XPS 15 9570 earlier. Everything was working fine until I got to the partition selection part of the installation. That's when the installer crashed and I had to shut down my machine. I think it's because I had my SATA configuration set to RAID ON instead of AHCI, which is now fixed.  Now when I try to run the installer from my bootable USB I get the following error  Failed to open \EFI\BOOT\mmx64.efi - Not Found Failed to load image \EFI\BOOT\mmx64.efi: Not Found Failed to start MokManager: Not Fond Something has gone seriously wrong: import_mok_state() failed   Hoping someone might have some idea as to what is going on