What’s the difference between these sentences:   I thought you might be interested in looking at this event. I thought you may be interested in looking at this event.
"May I go to the bathroom?" and "I asked if I might go to the bathroom."   The modal auxiliary 'may/might' is used to ask permission.     "He may not have understood your question." and "He might not have understood your question."   The same modal auxiliary is used for uncertainty.  Why?
I am trying to make a pirate ship and am trying to attach rope to the sails. my rope is made using a path, and soft body physics. I can not find a way to attach my rope to the sail. and I can not use pinned vertices because this is not a cloth modifier. How does the User Card popup work? We are experimenting with enhanced user card mouseover popups and have enabled them network wide. You can tell which users will trigger the popup because they have a 3-D drop shadowy look to their gravatar:    Hover your mouse over the gravatar and wait. Note that the user card mouseover popup will only be displayed if the following conditions are met:   Is the profile complete, and long enough? We enforce a minimum length requirement. The user's reputation must be >= 1k  If you have more links than are able to be displayed after truncation, those extra links will be shown in the bottom of the dialog. We order links at the bottom consistently -- if you include a twitter, google plus, linked in, or facebook those links are prioritized. It will be visible on a question and answer detail page, any page with a list of questions, and the /users list. It will not be shown when a question or answer is wiki'd. It will not be shown when excerpt summary is defined as &lt;!-- summary: &amp;nbsp; --&gt; we support explicitly specifying your user card excerpt summary using the following syntax:  &lt;!-- summary: This is my profile, there are others like it but this one is mine. --&gt;   The above example will result in:    This is now mostly complete.  The goal is allow people to show  off how awesome they are inline, without having to click through to the full user profile page. As mentioned on :     For something that can be done so   easily by accident, there should be   the ability to undo mistakes.   I know that I have clicked several times on a comment up-vote without actually wanting to.  I would suggest being able to cancel the up-vote (maybe only for a couple of minutes or even less than a minute, no problem, as long as I can undo a miss-click). How does the lens diameter influence photo quality? I have tested two different 50mm lenses in my camera. One was a Nikkor 50mm ∅52mm. The other one was a Sigma 50mm ∅72mm. I took some pictures with both lenses using the same setup for aperture and shutter speed, but couldn't notice significant differences in the quality of the pictures.   So, how does the diameter affects the photo quality, if it does? What advantages would the ∅72mm lens have over the ∅52mm one? Batch Convert Images from One Format to Another while maintaining directory structure, and removing originals I've looked at , and while it works there a few issues:   All converted images are placed in the directory from which the command is called. The original images are kept.   I need to convert around 70,000 .tif and .jpgs to .pngs.  It's really important the the files when converted are placed in their normal directories.    I can do a batch rm of .tff/.jpg's at the end if that's the best way to handle removing the old files. Is their a way to move multiple vertices gradually at a time? I have moved multiple vertices gradually but a set of vertices at a time not all at a time, as shown in the animation below (First I moved the four vertices from top, then three, then two and at last the last vertex).  I wanted to do the same thing as shown in the animation below but all at a time. Are +1/+1 counters different from +1/+1 effects? I know that children’s books is correct, but for some reason I want to say kids books, even though I know that it’s a plural possessive noun ending in an s.   A quick search on the web turns up Barnes &amp; Noble, who have a web page title that reads “Children's Books, Kids Books”.   Is the major bookseller wrong here? Or is there some exception I don’t remember?  More simply, is it kids books or kids’ books — and why? $$\sum_{k=1}^{\infty} \frac{1}{k^{\ln k}}.$$  I have some problems with this sum, I have tried most of the common methods, such as the ratio/root test, integral test, etc. I do believe it looks like a problem easily solvable by a direct comparison with some p-series, however, I do not know how to formulate the inequality.   I did try using the common fact that $\ln(x) \ll x^p$ for large $x$ but that of course only bounds it from below with a convergent series saying nothing about ours. Also I tried rewriting the 'summand' as $e^{\ln(k^{\ln k})}=e^{\ln k \cdot \ln k}$ but this did not really yield anything.   Any answer or hint would be greatly appreciated. Show $\sin x = bx$ has at least 3 real solutions. Show $\sin x=bx$ has at least 3 real solutions for every $b$, where $-\dfrac{2}{3 \pi} &lt; b &lt; \dfrac{2}{\pi}$.   Some useful facts I am trying to use:  Intermediate value theorem: If $f$ is a continuous real-valued function on $[a,b]$ and $d \in \mathbb{R}$ satisfies $f(a)&lt; d&lt; f(b)$, then there exists a point $c$ in $(a,b)$ such that $f(c) = d$.   Corollary: If $f$ is a continuous real-valued function on $[a,b]$, then $f([a,b])$ is a closed interval. $\mathbf L\mathbf D\mathbf L^\top$ Cholesky decomposition What does recursive cosine sequence converge to? I have a sequence defined as follow:  $a_0 = 1, a_n=\cos\left(a_{n-1}\right)$.  I want to count $\lim_{n\rightarrow\infty} a_n$ - it definitely does have limit by looking at the graph, the first few numbers of the limit are 0.7390851, but I have no idea, if that number is related to some other real number ($\pi$ or something like that).  The sequence is from , but they don't provide actual result for their own sequence. I am trying to classify using randomForest classification in GEE . However, I always get the error User memory limit exceeded, so I assume the number  of the feature are too large. Nevertheless, I saw many developers can classify even bigger dataset, so I am wondering if there is a better option there? The code can be accessed via  var fire= ee.FeatureCollection('users/spatola/recovery_rf_1712').map(function(feature){     var num = ee.Number.parse(feature.get('CLC_311'));     return feature.set('CLC_311', num);   }) var indices= ['EVI_mean','Dnbr','NBR2_mean','NBR2_min','NBR2_max','EVI_min','EVI_max']; var fire1=  fire.filter(ee.Filter.notNull(indices)); var fire2= fire1.select('Class_R','Dnbr','EVI_max','NBR2_max','imageId') var bands= ['NBR2_max', 'EVI_max']; var classProperty= 'Class_R'; var random= fire2.randomColumn('random'); var split_train= 0.8; var split_test= 0.2; var trainPartition= random.filter(ee.Filter.lt('random',split_train)); var testPartition= random.filter(ee.Filter.gte('random',split_test));  var RFtrained_c= ee.Classifier.smileRandomForest({  numberOfTrees: 100,  minLeafPopulation:2,  seed: 123,  }) .setOutputMode('CLASSIFICATION') .train({     features: trainPartition,     inputProperties: bands,     classProperty: classProperty,     }) print(RFtrained_c); var dict =  RFtrained_c.explain(); var test = testPartition.classify(RFtrained_c) print(test.first()) How can I recover photo files from a memory card with a corrupt filesystem? I know this is not specifically a photography issue but since many of us with prosumer/professional-level DLSRs use Compact Flash cards, it is bound to happen to others as well.  I have a Sandisk 16GB Ultra card that occasionally had the camera reporting inability to access the card. I had to reinsert the card to continue using it. I was able to read the card and transfer the photo files to my computer drive. Today, the same thing happened again, just that nearing the capacity of the card, it failed one last time and the camera was subsequently unable to read it anymore. Despite reinsertion.  My other CF cards never once exhibited this problem, so it's pretty much isolated to this card.  The card is similarly unrecognisable on my computer CF card reader. I think the filesystem is toast, but I suspect the photo files are still intact. I would like to find ways where I can inspect the raw binary data in the card and hopefully recover the photos? "At least one" - singular or plural subject? Windows 10 high memory usage (unknown reason) A few days ago I updated my PC to Windows 10. However, after some use my PC started to slow down until it was impossible to use – it was due to high memory usage. After a restart, everything came back to normal (total usage around 25% of 8GB of RAM). However, during a few hours of usage the memory builds up again to 70%, and if not restarted it further goes to 100%, and later on even freezes. Task manager does not help very much as it does not show all the processes (added screenshots below). Also tried RAMMap but it gives an error: "error refreshing database". I tried Googling this question, yet without much success.  I do not know much about PCs, but maybe some of you know this issue, or could help to find out what is using my RAM. How to stop an animation in C# / WPF? I have something like this:   barProgress.BeginAnimation(RangeBase.ValueProperty, new DoubleAnimation(     barProgress.Value, dNextProgressValue,     new Duration(TimeSpan.FromSeconds(dDuration)));   Now, how would you stop that animation (the DoubleAnimation)? The reason I want to do this, is because I would like to start new animations (this seems to work, but it's hard to tell) and eventually stop the last animation... Enqueuing Google Web Fonts the usual way, i.e., using the wp_enqueue_style function like so...  function wpse_google_webfonts() {     wp_enqueue_style( 'google-webfonts', 'http://fonts.googleapis.com/css?family=Ubuntu+Condensed|Open+Sans:400italic,700italic,400,700' ); } add_action( 'wp_enqueue_scripts', 'wpse_google_webfonts' );   ...results in a link tag placed in the header like so:  &lt;link rel='stylesheet' id='google-webfonts-css'  href='http://fonts.googleapis.com/css?family=Ubuntu+Condensed%7COpen+Sans%3A400italic%2C700italic%2C400%2C700&amp;#038;ver=3.5' type='text/css' media='all' /&gt;   As you can see, the resultant URL is encoded.  I am pretty sure it poses no problems, but to keep things clean and clear, I would like to go ahead and ask -- Is there a way to enqueue Google Web Fonts (via functions.php and not a plugin) in a way that the URL output is not encoded?  That's like so:  &lt;link rel='stylesheet' id='google-webfonts-css'  href='http://fonts.googleapis.com/css?family=Ubuntu+Condensed|Open+Sans:400italic,700italic,400,700?ver=3.5' type='text/css' media='all' /&gt;   Reason For Bounty  @webaware's answer is near perfect, especially because it's similar to the method employed in  theme.  The only problem in the output is that it's like this:  &lt;link rel='stylesheet' id='twentytwelve-fonts-css'  href='http://fonts.googleapis.com/css?family=Ubuntu+Condensed|Open+Sans:400italic,700italic,400,700&amp;#038;subset=latin,latin-ext' type='text/css' media='all' /&gt;   Notice the &amp;#038;? It should be &amp;, otherwise the font-files served only have the latin glyphs (i.e. the subset parameter in the URL is neglected unless you use &amp; and NOT its HTML entity).  Anyone who can help modify @webaware's answer so that the output's looks like this...  &lt;link rel='stylesheet' id='twentytwelve-fonts-css'  href='http://fonts.googleapis.com/css?family=Ubuntu+Condensed|Open+Sans:400italic,700italic,400,700&amp;subset=latin,latin-ext' type='text/css' media='all' /&gt;   ...wins the bounty. I am trying to get an intuitive idea of how the  affects Quantum computation. My understanding is that given a qubit $Q$ in superposition $Q_0 \left| 0 \right&gt; + Q_1 \left| 1 \right&gt;$, NCT states another Qubit $S$ cannot be designed such that $S$ is equivalent to the state of $Q$.   Now the catch is, what does Equivalent mean? It could mean either that:   $S = S_0 \left| 0 \right&gt; + S_1 \left| 1 \right&gt;$ such that $S_0 = Q_0, S_1 = Q_1$. Or it could mean that $S = Q$, meaning that if $S$ is observed to be some value ( for example 0) then $Q$ MUST be that same value, and vice versa.    So it seems that point 2, occurs anyways in entangled systems (particularly cat-states), so I can eliminate that option and conclude that that No Cloning states, given a qubit $Q$, it's impossible to make another qubit $S$ such that:  $S = S_0 \left| 0 \right&gt; + S_1 \left| 1 \right&gt;$ such that $S_0 = Q_0, S_1 = Q_1$.  Is this correct? Why do many anime not follow the manga? Why are they usually made shorter? Many anime do not follow the manga history and are made shorter. However there are a few that do follow it or try to finish the history with the manga like the big three (Naruto, Bleach, One Piece), Death Note, and FMA Brotherhood. But others finish the anime without the real ending like FMA, Ouran High School, Pandora Hearts, Tsubasa Reservoir Chronicle. Why is this so? Is it because of the high cost? Or the lack of popularity?