While I was browsing Google Flights, I noticed something that I haven't seen before. It said that if I booked the itinerary chosen, they'd be on separate tickets. This text was also in red, which I took as meaning it could be undesirable. I'm aware that this is risky for connecting flights, but is there any downside if they're both "one way" flights that are several days apart?
Is there any substantial disadvantage to booking two one-way tickets, versus a round trip ticket?  Booking vacation travel with family of four for winter, from Northeast US to Mexico.  Round trip is pricy and no preferred travel times.  Two one ways is slightly cheaper with much preferred timing.      Different airlines there and back, both reputable national US carriers.
Movie with "Where do the tubes go?" I'm trying to find a movie with an underground facility with people wearing white suits. The people have been affected such that they show no curiosity. There is one person that does and asks one of his co-workers where a tube leads to.      At the end there is an uprising where everyone gets to see the surface and sunlight.   What is the name of this movie? Why I cannot ping 192.168.0.108 (my computer IP?) Ipconfig says that my IP is 192.168.0.108 C:\Users\vbcbu&gt;Reply from 192.168.0.108: Destination host unreachable.ip 'Reply' is not recognized as an internal or external command, operable program or batch file.  C:\Users\vbcbu&gt;ipconfig  Windows IP Configuration   Ethernet adapter Ethernet:     Media State . . . . . . . . . . . : Media disconnected    Connection-specific DNS Suffix  . :  Wireless LAN adapter Local Area Connection* 12:     Media State . . . . . . . . . . . : Media disconnected    Connection-specific DNS Suffix  . :  Wireless LAN adapter Local Area Connection* 13:     Media State . . . . . . . . . . . : Media disconnected    Connection-specific DNS Suffix  . :  Wireless LAN adapter Wi-Fi 2:     Connection-specific DNS Suffix  . : www.tendawifi.com    Link-local IPv6 Address . . . . . : fe80::3804:2d04:a591:7142%6    IPv4 Address. . . . . . . . . . . : 192.168.0.108    Subnet Mask . . . . . . . . . . . : 255.255.255.0    Default Gateway . . . . . . . . . : 192.168.0.1  Ethernet adapter Bluetooth Network Connection:     Media State . . . . . . . . . . . : Media disconnected    Connection-specific DNS Suffix  . :  C:\Users\vbcbu&gt;  I can ping router at 192.168.0.1 I can't ping 192.168.0.108 C:\Users\vbcbu&gt;ping 192.168.0.1  Pinging 192.168.0.1 with 32 bytes of data: Reply from 192.168.0.1: bytes=32 time=2ms TTL=64 Reply from 192.168.0.1: bytes=32 time=24ms TTL=64  Ping statistics for 192.168.0.1:     Packets: Sent = 2, Received = 2, Lost = 0 (0% loss), Approximate round trip times in milli-seconds:     Minimum = 2ms, Maximum = 24ms, Average = 13ms Control-C ^C C:\Users\vbcbu&gt;ping 192.168.0.8  Pinging 192.168.0.8 with 32 bytes of data: Reply from 192.168.0.108: Destination host unreachable. Reply from 192.168.0.108: Destination host unreachable. Reply from 192.168.0.108: Destination host unreachable. Reply from 192.168.0.108: Destination host unreachable.  Ping statistics for 192.168.0.8:     Packets: Sent = 4, Received = 4, Lost = 0 (0% loss),  C:\Users\vbcbu&gt;ping 192.168.0.8  Pinging 192.168.0.8 with 32 bytes of data: Reply from 192.168.0.108: Destination host unreachable. Reply from 192.168.0.108: Destination host unreachable. Properties of $x_k=\frac{a_{k+1}-a_{k}}{a_{k+1}}$ where $\{a_n\}$ is unbounded, strictly increasing sequence of positive reals How to reconcile the cashless human/Federation society with human traders and merchants From a variety of sources, including , we know that the Federation (or at least the humans) don't use money. This raises the problem that humans frequently visit worlds where there is currency, and, in the case of DS9, operate a station that has currency frequently in use (for example, Federation personnel frequently attend Quark's bar). Additionally, we see human traders.   My question is, how do humans get "money" (credits, latinum, etc.)? How would a human even get the resources to purchase their own merchant ship or the resources to fill its cargo holds with merchandise? If Federation personnel can simply be given money for the asking, why haven't they poured so much money down Quark's throat that he chokes on it? Does time freeze at Absolute Zero? Time has many definitions per se, but the basic idea being it's "the measurement of change" so as we know, all matter looses it's ability of changing with the loss of kinetic energy. and the where it becomes zero is the absolute zero (−273.15°C). so my question would be, will time stop/freeze at Absolute zero? and does time get slow while reaching there? How to Remove shortcut arrow from desktop icons? How do I turn off the arrow for desktop icons? What is the meaning of speed of light $c$ in $E=mc^2$? is the famous mass-energy equation of Albert Einstein. I know that it tells that mass can be converted to energy and vice versa. I know that $E$ is energy, $m$ is mass of a matter and $c$ is speed of light in vacuum.   What I didn't understood is how we will introduce speed of light?  Atom bomb is made using this principle which converts mass into energy; in that the mass is provided by uranium but where did speed of light comes into play? How can speed of light can be introduced in atom bomb? I always thought of current as the time derivative of charge, $\frac{dq}{dt}$. However, I found out recently that it is the ampere that is the base unit and not the coulomb. Why is this? It seems to me that charge can exist without current, but current cannot exist without charge. So the logical choice for a base unit would be the coulomb. Right? If you run a code snippet, a hat still appears (hats are above snippets in the Z-order) When I turn 13 years old, will some of my Roblox account restrictions unlock automatically? How to choose a lens for my first DSLR? I am considering buying my first DSLR.  How do I know whether I need a 18-200 lens, 17-85, or 18-55? Or something else? How to add percent sign to NSString How to remove enamel from wire? How to make blocks in spawn unbreakable in survival? So on my multiplayer server on Minecraft Education Edition I can't seem to figure out how to make the blocks in spawn unbreakable. I know adventure mode fixes that but it's a survival world. I don't want them in adventure, so how do I make the blocks in spawn unbreakable? I see a lot of interesting programs out there that can only be obtained by adding a "PPA" to the system but, if I'm understanding correctly, we should stay within the official "repositories" for adding software to our system.   Is there any way for a novice to know if a "PPA" is safe or if it should be avoided? What tips should the user know about when dealing with a PPA?. Proving a triangle with different edge colors exists in a graph. This is again some homework translated (hopefully not too badly) from my book  The graph $K_{n}$ is colored using $n$ different colors, in a way that each color is used at least once. Prove that there exists a triangle with its edges colored in different colors. When selecting components, is there a way to control the "selection distance/area"? I don't want to select a component, even if I click ~20 pixels away from it.    Thanks in advance! Why did the Emperor remain motionless while Darth Vader threw him off the balcony? I'm wondering whether this was a movie sin but his body position seemed to stay the same? Also why didn't he stop using Force Lightning? He continued to use it even as he was falling down.   I'm also wondering whether Palpatine meant to electrocute Vader or was it just a coincidence (because he kept firing Force Lightning) .  It makes no sense as he just stood there allowing Vader to throw him. I'm trying to define a new environment that consists of a split environment inside an equation environment. But I'm getting an error. Here's what I'm doing:  \documentclass[a4paper,12pt]{article} \usepackage[brazil]{babel} \usepackage[utf8]{inputenc} \usepackage{amsmath} \newenvironment{example}{\begin{equation}\begin{split}}{\end{split}\end{equation}}  \begin{document} \begin{example}oi\end{example} \end{document}   And the error message I'm getting is:   ERROR: LaTeX Error: \begin{split} on input line 8 ended by \end{example}.   I then tried a few other cases. If I remove the splits and define example to be just equation, it runs fine. If I remove the equations and define example to be just split, I get the exact same error message.  In other words: I only get this error when split is involved. Is there a way to make this work?  EDIT: The reason I'm doing this, is because I want a convenient way to create split-equations. I know it's similar to align. I prefer split-equations because the entire line of equations gets a single number for referencing (it's even placed in the middle line). align, however, will force me to \notag each line, otherwise I get a number for each line in the equation (which tends to get messy when equations are long and numerous). It's not the end of the world, but the split-equation combination is just quicker and easier (if I can manage to define a command for it).  Alternatively, the multline environment is not appropriate either, because it doesn't let you manually align each line (like aligning the equal signs). Instead it only lets you push everything left or right.  EDIT2: I just tried this:  \newenvironment{example}{ \begin{equation}\split}{\endsplit \end{equation}}   and got this error  ERROR: LaTeX Error: \begin{equation} on input line 8 ended by \end{example}.   Which is weird, because removing \split and \endsplit entirely doesn't return any errors (so it's not equation's fault). I am trying to prove that:  Let $f$ be analytic in the closed unit disc with $f(z)\leq 1$ for $|z|\leq1$.  For a given $0&lt;r&lt;1$ and $|z_1|,|z_2|\leq r$, $z_1\neq z_2$ then,   $$\left|\frac{f(z_2)-f(z_1)}{z_2-z_1}\right|\leq \frac{1}{(1-r)^2}.$$  My attempt is: part a  of the question asks to prove $$\left|\sum_k^\infty a_nz^n\right|\leq \frac{ |z^k|}{1-|z|}.$$   So, \begin{eqnarray*}  \left|\frac{f(z_2)-f(z_1)}{z_2-z_1}\right|&amp;=&amp; \frac{|\sum_1^\infty a_nz_2^n-\sum_1^\infty a_nz_1^n|}{|z_2-z_1|}\\  &amp;\leq&amp; \frac{\frac{ |z_1 |}{1-|z_1|}+\frac{ |z _2|}{1-|z_2|}}{|z_2-z_1|}\\  &amp;\leq&amp;\frac{1}{(1-r)^2} \frac{   |z_2| ({1-|z_1|})+  |z _1| (1-|z_2|) }{|z_2-z_1|}\\ \end{eqnarray*} But could not prove that the last term is controlled by 1.