When searching for "model mommy" there are 0 results.  I think the search should have found  result, at least.    I was able to find some posts by the same search without quotes, but also had to sort through some irrelevant results just because they contained one of the words.
The new search function allows quoted queries that include punctuation, and this is fantastic, most of the time. However, the search considers the punctuation as part of the word itself, so searches for "a test" will not show results containing a test,, a test., or a test?. The reverse is also true.  Is this the intended behavior ? &lt;--(space added so that behavior will show in results.)  It seems that the logical way to do fix this (while maintaining character search) is for queries with punctuation to match results with punctuation, while queries without punctuation to match either with and without.    Example:  vs     A more practical example is described in Arjan's answer below.
Setting proxy for apt from terminal Why does universal generalization work? (the rule of inference) I am a seafarer (marine engineer) and I have to often visit different countries. This time I received my sign-off from Iran and they stamped my passport. Would this cause a problem for getting a US C1D1 visa since my next company wants me to have this visa? I am an indian national. If $X$ and $Y$ are sets, their cartesian product $X\times Y$ is a set. In ZFC set theory, every element object is a set. We know or feel that if $X$ and $Y$ are sets, their cartesian product $X\times Y$ is a set.  My question is: Why if $X$ and $Y$ are sets, their cartesian product $X\times Y$ is a set? How do I add a repository from behind a proxy? I've a problem at the office. We're behind a proxy (which is set and applied at ubuntu proxy settings) and when I try to add a repository from terminal, I get:      Error reading --some url here--: urlopen error [Errno 113] No route to host   I've tried with   Launchpad-getkeys script. I get this (image)      I've tried with another "hack", without luck   Press Alt-F2 and type gksu gedit /usr/lib/python2.6/dist-packages/softwareproperties/ppa.py Find line 88, change keyserver.ubuntu.com to hkp://keyserver.ubuntu.com:80 Save, close and reboot.    Does anyone know if I could solve this problem in any way? Thanks Rename Multiple files in unix I have multiple files whose names look like this  2313_ABCDEAUG2014_PQRST_0_.pdf 3244_ABCDEAUG2014_PQRST_0_.pdf 4234_ABCDEAUG2014_PQRST_0_.pdf   t want to rename the file in the following format.  AZ-2014-08-2313.pdf AZ-2014-08-3244.pdf   Please suggest. switch a theme different per user role I plan to use the member plugin by Justin Tadlock  I wish to know if how could I, on the front side, auto switch to a theme according to a role status.. for example authors would have the site presented using theme 1 while editor would have the site presenter using theme 2  I would rather have 2 different theme rather than conditionals within one theme structure  Thank you in advance "Two are better than one" or "Two is better than one"? I just came across the phrase "Two are better than one", but I had always heard it in my head as "Two is better than one". This is partially due to the Boys Like Girls song. Which one of these is actually correct? An equivalence relation is defined by three properties: reflexivity, symmetry and transitivity.  Doesn't symmetry and transitivity implies reflexivity? Consider the following argument.  For any $a$ and $b$, $a R b$ implies $b R a$ by symmetry. Using transitivity, we have $a R a$.  Source: Exercise 8.46, P195 of Mathematical Proofs, 2nd (not 3rd) ed. by Chartrand et al Prologue:  This is an effort to follow up on  which is marked as a duplicate of  highly voted and status-declined feature request (although they seem to be different, one focusing on the OP and the other on the downvoter).   My New Year's resolution was to downvote more.  So on January 3rd or so, I saw a post that was low quality, and downvoted.  Two days later, I came back to see if it was ready to be deleted or had gotten piled with downvotes, to find it with a significant positive score!  At which point, I noticed that the answer had been significantly improved.  So I retracted my downvote, changed it to an upvote, and immediately resumed my dearth of downvoting again.  I think I have a responsibility to downvote bad posts, despite that oh-so-painful -1 rep penalty.  But if I am also going to have the responsibility to follow up on every downvote I cast, I'm not going to bother. I don't want my downvote to leave a residual penalty on posts that were once low quality, and I am not going to trouble myself to keep checking up on every post I downvoted.  Can a downvoter have an option to be notified when a post they voted down was edited?  I wouldn't make this an automatic thing, because not all downvoters want it, and it isn't applicable to all cases of downvoting (although  that this should be part of the responsibility of a downvoter).  Personally, I would make this a universal toggle on-off option on the user profile page, not a question-by-question option, but I don't have strong feelings about it. How do I install drivers for an Intel HD Graphics? In System Info in 11.10, the graphics driver wasn't detected. I use ACER Aspire 4750 with Intel Core i3-2340M and Intel HD Graphics 3000 graphic card  How to install the driver for my Ubuntu? Legendre's formula counts the number of positive integers less than or equal to a number $x$ which are not divisible by any of the first $a$ primes: $$\begin{align} &amp;\phi(x,a)=\lfloor x \rfloor-\sum_{p_i\le a}\left\lfloor \dfrac{ x }{(p_i)}\right\rfloor+\sum_{p_i&lt;p_j\le a}\left\lfloor\dfrac{ x}{(p_ip_j)}\right\rfloor-\sum_{p_i&lt;p_j&lt;p_k\le a}\left\lfloor \dfrac{x}{(p_ip_jp_k)}\right\rfloor+\dots \end{align}$$ then $\pi(x)=\phi\bigl(x,\pi (\sqrt{x})\bigr)+\pi (\sqrt{x})-1$ as given .  My question is, why does $\bigl\lfloor\phi(x,\lfloor\sqrt{x}\rfloor)+\sqrt{x}-1\bigr\rfloor$ also equal $\pi(x)?$ How to keep the console window open in Visual C++? I'm starting out in Visual C++ and I'd like to know how to keep the console window.  For instance this would be a typical "hello world" application:   int _tmain(int argc, _TCHAR* argv[]) {     cout &lt;&lt; "Hello World";     return 0; }   What's the line I'm missing? Find the ratio of $\frac{\int_{0}^{1} \left(1-x^{50}\right)^{100} dx}{\int_{0}^{1} \left(1-x^{50}\right)^{101} dx}$ Why are Only Real Things Measurable? Why can't we measure imaginary numbers? I mean, we can take the projection of a complex wave to be the "viewable" part, so why are imaginary numbers given this immeasurable descriptor? Namely with operators in quantum mechanics, why must measurable quantities be Hermitian, and consequently real? Obviously, this suggested edit should never have been approved. Because it's very, very minor.  Is it acceptable for me to "rollback" this edit? Does the suggested editor lose the +2 rep when I roll it back? Should I comment on one of his questions, explaining not to make too minor edits like this?  Is there anything I should do to notify the reviewers that approved  too minor suggested edit? Proving Geometric Hahn-Banach Implies Analytic Hahn-Banach I've come across a proof online of the H.B theorem using the goemetric version.   There is a step in the proof which im not sure why is true and it is as follows:   Let $X$ be a linear space and $M \subset X \times \Bbb R$ be a maximal subspace.  Then $M = G(F)$ for $F :X \to \Bbb R$ linear.   Someone can show me why this is true?   Maybe I misunderstood the proof, its the last paragraph of Matrin's answer here -.   Thanks a lot for helping! Edit - Original Title: Is there an alternative way to achieve border-collapse:collapse in CSS (in order to have a collapsed, rounded corner table)?  Since it turns out that simply getting the table's borders to collapse does not solve the root problem, I have updated the title to better reflect the discussion.  I am trying to make a table with rounded corners using the CSS3 border-radius property. The table styles I'm using look something like this:  table {     -moz-border-radius:10px;     -webkit-border-radius:10px;     border-radius:10px }   Here's the problem. I also want to set the border-collapse:collapse property, and when that is set border-radius no longer works. Is there a CSS-based way I can get the same effect as border-collapse:collapse without actually using it?  Edits:  I've made a simple page to demonstrate the problem  (Firefox/Safari only).  It seems that a large part of the problem is that setting the table to have rounded corners does not affect the corners of the corner td elements. If the table was all one color, this wouldn't be a problem since I could just make the top and bottom td corners rounded for the first and last row respectively. However, I am using different background colors for the table to differentiate the headings and for striping, so the inner td elements would show their rounded corners as well.  Summary of proposed solutions:  Surrounding the table with another element with round corners doesn't work because the table's square corners "bleed through."  Specifying border width to 0 doesn't collapse the table.  Bottom td corners still square after setting cellspacing to zero.  Using JavaScript instead- works by avoiding the problem.  Possible solutions:  The tables are generated in PHP, so I could just apply a different class to each of the outer th/tds and style each corner separately. I'd rather not do this, since it's not very elegant and a bit of a pain to apply to multiple tables, so please keep suggestions coming.  Possible solution 2 is to use JavaScript (jQuery, specifically) to style the corners. This solution also works, but still not quite what I'm looking for (I know I'm picky). I have two reservations:    this is a very lightweight site, and I'd like to keep JavaScript to the barest minimum  part of the appeal that using border-radius has for me is graceful degradation and progressive enhancement. By using border-radius for all rounded corners, I hope to have a consistently rounded site in CSS3-capable browsers and a consistently square site in others (I'm looking at you, IE).   I know that trying to do this with CSS3 today may seem needless, but I have my reasons. I would also like to point out that this problem is a result of the w3c specification, not poor CSS3 support, so any solution will still be relevant and useful when CSS3 has more widespread support. How can analytically be  the ?   I found some extremely synthetic equations which from the  (in particular $\mathbf{F} = m \mathbf{a}$) tried to obtain the Kepler's laws, but even if it seemed to be a nice procedure they were too much incomplete. Let $L$ denote the set of all lines in the Euclidean plane $\Bbb R^2$. We say that two lines $L$ and $M$ are parallel if either $L = M$ or $L$ and $M$ have no points in common.  Using Euclid’s Parallel Postulate prove that parallelism is an equivalence relation on the set $L$.  I need some help determining if I have the right idea about this.  $L=L$ which means that $L$ is parallel to itself. So this is reflexive.  Suppose we have $L || M$. Then Either $L=M$ or $L$ and $M$ share no points. So Then $M=L$ or $M$ and $L$ share no points. Then $M||L$. So this is symmetric.  Suppose we have $L || M$ and $M || N$. So then either $L=M$ or $L$ and $M$ share no points and either $M=N$ or $M$ and $N$ share no points. So we have that either $L=N$ or $L$ and $N$ share no points. So $L || N$. So then this is transitive.  So from all of this, parallelism is an equivalence relation. I'm not sure if this is correct or not. Any help would be appreciated.