I created a path connecting different segments and than I created the 3D effect using the command extrude &amp; bevel Do you know how I can fix the imperfections (in the 3d effect and in the connections among the segments) you see in the screenshot?
I have created a logo with pen tool in Illustrator but between lines (where they intersect with each other) there is a gap where it gets the color of the background.  Something like this:  (Black color is the background color) - As you can see where the paths join each other there is a kinda dotted black line. I Grouped them but still the same. I converted to jpeg just to be sure it is not only shown like that but same effect.   NOTE: I want to export that logo as SVG file type and use it in the WEB. I tried some solutions given like anti-aliasing in preferences or art optimize when saving for optimization. But still I have same problem. I want to get that logo in SVG and put it on the web where it will display clean without those strange gaps.  How can i get rid of this?
If I my motherboard is SATAI, can it use SATAII hard drives? Is there a way to test an application where you simulate a hundred different clients connecting to a IIS server and asking the same data? At the customer where our project is running they have 400 computers and they often do stress tests with all computers. I on the other hand have only got my laptop... (and a development server).  (In my case the data is asked through a WebORB Gateway). How can I recover my account? I tried to log into Minecraft today to find that my password isn't working. I tried to change it, but I can't login to my email because I forgot the answer to my security question. I tried changing the email to a different one, but that didn't work for some reason (it kept saying "invalid email"). I don't have my transation ID because I forgot which credit card I used.  Does this mean that I have to buy a new Minecraft account? Going back twice required to return to search results in the tags view Deleting a comment (mine) shouldn't count as a comment vote I had an old question that I revisited in order to link it in a new answer. I noticed that in the comments Steven A Lowe had a funny comment that I -- at the time -- had responded to with "why can't I upvote comments?"  Well, of course, now I can.  So, I voted Steven's comment up then went to delete mine. I got the warning box that I can only submit comment votes once every 5 seconds. This seems like a bug to me. Deleting is not the same as voting. How do I check the series $\sum_{n=2}^{\infty} \frac{(-1)^n }{n+(-1)^n}$ for absolute convergence/conditional convergence ?  How can I solve this problem? Is every solution of Einstein field equations unique? Einstein's equation is  $$8 \pi T_{ab} = G_{ab},$$  where the left side contains the stress-energy tensor and the right side contains the Einstein tensor.  Is there exactly one unique stress-energy tensor corresponding to a given spacetime curvature? Or is it possible for one curvature (i.e. one spacetime metric) to be produced by multiple different mass configurations? Is it safe to put a clothes washer outdoors? How to force the browser to reload cached CSS and JavaScript files If $f \in L_p \cap L_q$, $1 \leq p < r < q < \infty$ then $f \in L_r$. If $f \in L_p \cap L_q$ and $1 \leq p &lt; r &lt; q &lt; \infty$ then $f \in L_r$.   Proof: Let $E = \{ x \in X: \left\lvert f \right\rvert \leq 1 \}$. Then, $$\int \left\lvert f \right\rvert^r \mathrm{d}\mu = \int_E \left\lvert f \right\rvert^r \mathrm{d}\mu+\int_{E^C} \left\lvert f \right\rvert^r \mathrm{d}\mu \leq \int_E \left\lvert f \right\rvert^p \mathrm{d}\mu+\int_{E^C} \left\lvert f \right\rvert^q \mathrm{d}\mu$$ $$\leq \int \left\lvert f \right\rvert^p \mathrm{d}\mu+\int \left\lvert f \right\rvert^q \mathrm{d}\mu &lt; \infty.$$ Thus, $f \in L_r$.  I just want to make sure I am somehow not missing anything. Thanks I am a beginner to python coding in GIS. I want to calculate the total number of counts in raster attribute table. In order to do that:   I would like to build a attribute table of raster data use a loop through attribute table using ARCPY.SearchCursor()   Therefore, I wrote a code to build an attribute table. However, I am getting an error while running the code and not able to figure out the error in the code.  Code:  import arcpy # Create the geoprocessing object  import arcgisscripting gp = arcgisscripting.create()  #To overwrite output arcpy.env.overwriteOutput = True  #Set environment settings gp.workspace = "C:/Subhasis/Test/raster-read"  #Build Raster Attribute Table gp.BuildRasterAttributeTable_management("sti-9", "Overwrite")  Error Message: Traceback (most recent call last):   File "C:/Subhasis/Test/raster-read/test.py", line 15, in &lt;module&gt;     gp.BuildRasterAttributeTable_management("sti-9", "Overwrite") ExecuteError: ERROR 000049: Failed to build attribute table Failed to execute (BuildRasterAttributeTable). Why do the eigenvectors for two similar matrixes differ by a large amount Proving Eigenvalue squared is Eigenvalue of $A^2$ The question is: Prove that if $\lambda$ is an eigenvalue of a matrix A with corresponding eigenvector x, then $\lambda^2$ is an eigenvalue of $A^2$ with corresponding eigenvector x.  I assume I need to start with the equation $Ax=\lambda x$ and end up with $A^2 x=\lambda^2 x$ but between those I am kind of lost. I have manipulated the equations several different ways and just can't seem to end up where I need to be. Help would be greatly appreciated as I believe this will be on a test tomorrow. Which cameras have built-in HDR? When taking landscape photos, I often struggle with dynamic range. I have either a burned out skies or landscapes are too dark.  Now I'm reading  that some cameras can take 3 pictures with different exposures, and combine them automatically to one image with higher dynamic range.   So my question is, which cameras have this feature? "std::endl" vs "\n" Many C++ books contain example code like this...  std::cout &lt;&lt; "Test line" &lt;&lt; std::endl;   ...so I've always done that too. But I've seen a lot of code from working developers like this instead:  std::cout &lt;&lt; "Test line\n";   Is there a technical reason to prefer one over the other, or is it just a matter of coding style? Let's stop displaying a user's accept rate My feature request (or anti-feature-request perhaps) is the following: Let's stop displaying a user's accept rate.  For those of you who know "Fawlty Towers", the whole issue of a visible accept rate and our behavior towards it starts to feel like .   We generally seem to agree that harassing a user about it is not appropriate and that our decision to answer a question should not depend on it, yet we display it in varying terrorist-threat-levels of color. Yes dear users, please don't pay any attention to the brightly orange colored percentage you see there. And whatever you do, don't bring it up.  But as long as you're displaying the accept rate, people will comment on it, criticize users for it and possibly reconsider answering because of it. And while I'm of the opinion that a low accept rate should not stop you from answering (we're here to make the internet better after all) and that the possible reputation gain (or lack thereof) should not factor in either, I can't blame users for considering it. It's in their face after all. And we're only people.   So let's take the issue off the table. Or at least partially. Information about a user's acceptance behavior can still always be gathered from the profile. But at least that would be less in-your-face.   "But it helps me to see if a user is a help vampire!" I'm still wondering if those are of the sparkly variety as well, but I digress. So what? If the question is bad, downvote it. Evaluate a question on its individual value. There is no need to take a user's history into account. There might be a correlation between the quality of a question and a user's accept rate, but there doesn't have to be. And if there is, the bigger problem is the question's quality.  "Exactly! A user with a low accept rate might indicate there's a problem!" I'm not arguing we should get rid of the accept-rate value within SO/SE. After all, this Q&amp;A works based on up and downvotes, as well as the acceptance of an answer. But why not use it behind the scenes to (very occasionally) nudge the user with a statement like:      "You have received several answers to your questions, yet have not accepted an answer as correct or helpful in a while. You might want to evaluate them and where possible ".    After all, in the various questions with regards to comments on low accept rates, if any comments are encouraged at all, then they are of this soft variety. So why not let the system take care of that?  I feel this would take the whole issue of accept rate off the table, while still providing the user with the information he might have missed or needs. (As a bonus, it would reduce the frequency with which the topic is brought up here on Meta) And those users who would ignore this information are most likely not convinced by a displayed percentage either. Number of integer solutions of $x^2 + y^2 = k$ I'm looking for some help disproving an answer provided on a  I posted about computing the number of double square combinations for a given integer.    The original question is from the Facebook Hacker Cup       Source: Facebook Hacker Cup   Qualification Round 2011      A double-square number is an integer $X$   which can be expressed as the sum of   two perfect squares. For example, 10   is a double-square because $10 = 3^2 + 1^2$.   Given $X$, how can we determine the   number of ways in which it can be   written as the sum of two squares? For   example, $10$ can only be written as $3^2 + 1^2$   (we don't count $1^2 + 3^2$ as being different). On the other hand,   $25$ can be written as $5^2 + 0^2$ or as   $4^2 + 3^2$.      You need to solve this problem for $0 \leq X \leq 2,147,483,647$.      Examples:      $10 \Rightarrow 1$      $25 \Rightarrow 2$      $3 \Rightarrow 0$      $0 \Rightarrow 1$      $1 \Rightarrow 1$   In response to my original question about optimizing this for F#, I got the following response which I'm unable to confirm solves the given problem correctly.       Source:       Again, the number of integer solutions   of $x^2 + y^2 = k$ is four times the   number of prime divisors of $k$ which   are equal to $1 \bmod 4$.      Knowing this, writing a program which   gives the number of solutions is easy:   compute prime numbers up to $46341$ once   and for all.      Given $k$, compute the prime divisors of   $k$ by using the above list (test up to   $\sqrt{k}$). Count the ones which are   equal to $1 \bmod 4$, and sum. Multiply   answer by $4$.   When I go through this algorithm for $25$, I get $8$ which is not correct.          For each prime factor (pf) of $25$ ($5$, $5$ are prime factors of $25$)         if pf % $4$ = $1$ (true for both $5$'s), add $1$ to count      return $4$ * count (count would be $2$ here).          So for $25$, this would be $8$ the least possible value for :$ \lfloor \frac{a+b}{c}\rfloor +\lfloor \frac{b+c}{a} \rfloor+\lfloor \frac{c+a}{b} \rfloor $ How to handle ordinal categorical variable as independent variable I am using a logit model. My dependent variable is binary. However I have an independent variable which is categorical and contains the responses: 1.very good, 2.good, 3.average, 4.poor and 5.very poor. So, it is ordinal ("quantitative categorical"). I am not sure how to handle this in the model. I am using gretl.  [Note from @ttnphns: Although the question says the model is logit (because the dependent is categorical), the crucial issue - ordinal independent variables - is basically alike, be the dependent categorical or quantitative. Therefore the question is equally relevant to, say, linear regression too - as it is to logistic regression or other logit model.] Adding a text node to tikz drawing