Cat5 ethernet cables use only 2 pairs for Ethernet what are the other 2 pairs for ?  Pin Color               Function 1   White with Green    +TD 2   Green               -TD 3   White with Orange   +RD 4   Blue                Not Used 5   White with Blue     Not Used 6   Orange              -RD 7   White with Brown    Not Used 8   Brown               Not Used
This might seem a stupid question but why do Ethernet cables have 8 wires? Cat5 cables were just using 4 of the 8 wires, so only 4 are actualy 'needed'. Why not 12 or 16 wires?
$A^TA+I$ is always invertible? Android design convention for saying a user needs to complete an action first? I've read the Android design conventions, but can't see a good solution.  I have a 3 tab mobile application. Tabs 2 and 3 need a selection made on screen 1 before they will work. The user enters at Screen 1, and the tab options are along the top. If they attempt to open screen 2 or 3, I would like to advise them to make a selection first. 'notifications' are the closest answer I can see from the Android design guidelines. Anybody have any other solutions?  Thanks  Andy Bibliography in Texmaker How to open new tab in browser in selenium 3.0? I have tried multiple actions but it is not working.  It always close the first tab and then it open link in the same page.  // Driver is launched package WebBrowserCommands;  import org.openqa.selenium.By; import org.openqa.selenium.Keys; import org.openqa.selenium.WebDriver; import org.openqa.selenium.chrome.ChromeDriver; import org.openqa.selenium.interactions.Actions;  public class OpenBrowser   {     public static void main(String[] args) throws Exception {         System.setProperty("webdriver.chrome.driver","/Users/ss108/Desktop/Util/SELENIUM SUPPORT/chromedriver");          WebDriver driver = new ChromeDriver();          driver.manage().window().maximize();         // Driver is launched          //We have two ways         boolean Indriectway = true;         //Boolean to understand both method          if(!Indriectway){             //Using String to take value.             String URL = "https://www.google.com";             driver.get(URL);              String PageSourceFirst = driver.getPageSource();             //We have took title in PageSourceFirst             System.out.println(PageSourceFirst);              //Get Title Command             String TitleFrist = driver.getTitle();             //We have took title in TitleFirst             System.out.println("Tile of WebSite is " + TitleFrist);              //Get Current URL             String CurrentURLFirst = driver.getCurrentUrl();             System.out.println("Current URL is " + CurrentURLFirst);              Actions act=new Actions(driver);             act.contextClick(driver.findElement(By.linkText("Gmail"))).perform();             Thread.sleep(10000);             act.contextClick(driver.findElement(By.linkText("Gmail"))).sendKeys(Keys.ARROW_DOWN).sendKeys(Keys.RETURN).build().perform();                    // Try to open page using right click and action arrow down **but it is not working**              driver.close();          }else {             //Using directly             driver.get("https://www.facebook.com");             String PageSourceSecond = driver.getPageSource();             System.out.println(PageSourceSecond);              //Get Title Command             System.out.println("Tile of WebSite is " + driver.getTitle());             //Get Current URL             System.out.println("Current URL is " + driver.getCurrentUrl());             driver.quit();          }     } }   Second method  1- Same result getting   System.setProperty("webdriver.chrome.driver","/Users/ss108/Desktop/Util/SELENIUM SUPPORT/chromedriver");     WebDriver driver = new ChromeDriver();     driver.get("https://www.facebook.com")     Robot robot = new Robot();     robot.keyPress(KeyEvent.VK_META);     robot.keyPress(KeyEvent.VK_T);     robot.keyRelease(KeyEvent.VK_T);     robot.keyRelease(KeyEvent.VK_META);       driver.get("https://www.google.com")   Third method  String selectLinkOpeninNewTab = Keys.chord(Keys.CONTROL,Keys.RETURN);  driver.findElement(By.linkText("urlLink")).sendKeys(selectLinkOpeninNewTab);   however none of them work for what I am trying. Maximum of $|\sin(z)|$ as $\{z: |z| \leq 1 \} $  So according to the Maximum Principle, the maximum is when $|z|=1$. I tried using the fact that $\sin z= \dfrac {e^{iz}-e^{-iz}}{2i}$, but didn't know how to continue from there. Setting $z=e^{it}$ doesn't help much.  I saw this question was answered before, however the answer uses hyperbolic functions ($\sinh, \cosh$) which I haven't actually studied.  Thanks in advance for any assistance! I know that non-married lovers address each other by saying “This is my girlfriend/boyfriend.” I know that married couples address each other by calling “my wife/husband”.  I also know that gay lovers who are not married (yet?) address each other by saying "my boyfriend" (for gays) and "my girlfriend" (for lesbians).  But if they are married, how do they address each other?  And how do we describe them? I mean if they are gays, are they “husband and husband” or “husband and wife” (one of them acts like the wife)? And if they are lesbians, are they “wife and wife” or “husband and wife” (one of them acts as the husband)?  I know they can be referred to as a gay couple or gay lovers from , but I couldn't find the answer to address each of the two. QGIS apply style to shapefile If an email message contains an email address in the body, Gmail automatically converts it into a mailto: link, which is helpful.  And many times each day I've enjoyed being able to right-click a mailto: link in an email (within Gmail) and then click "Copy email address" in the context menu.  Then I can paste that email address into a program (such as when I want to search a database).  However, within the past month or so, I've noticed that I can't right-click and click "Copy email address" without Gmail then popping open a "New Message" panel and changing my current URL to have ?compose=new at the end.  I wonder if it's related to .  How can I disable it?  I'm tried of having to click the "Discard draft" trash can button so many times throughout the day. Is it still possible to install Ubuntu to an external harddrive with UEFI? It looks like  isn't possible with UEFI, where as with MBR there wasn't a big difference between external and internal. Is that true or is it still possible?  Is it even possible to combine both boot methods? I am carrying out research to look at differences in fish density and fish species richness when using two different underwater visual census methods. My data was originally count data but then typically this is changed to fish density but I have still decided to use a Poisson GLM, which I hope is right.   model1 &lt;- glm(g_den ~ method + site + depth, poisson)   My 3 predictor variables are method, site and depth which I ordered as factors when I input them.   My response variables are grouper species richness, grouper density and the same for other fish groups. I am aware that density is not an integer and it is numerical data e.g 1.34849. I am now however getting this error:      In dpois(y, mu, log = TRUE) : non-integer x = 0.037500   I've been reading up and many people suggest using an offset, is this the most advisable thing to do? How do I disable the volume control overlay? When changing the volume on a Mac, you get a big ugly gray bezel showing the change in volume. This is super annoying when (say) watching a movie. Is there any way to disable this? Show $S = f^{-1}(f(S))$ for all subsets $S$ iff $f$ is injective Let $f: A \rightarrow B$ be a function. How can we show that for all subsets $S$ of $A$, $S \subseteq f^{-1}(f(S))$? I think this is a pretty simple problem but I'm new to this so I'm confused.  Also, how can we show that $S = f^{-1}(f(S))$ for all subsets $S$ iff $f$ is injective? Application of Liouville's Theorem Let $f(z)$ be an entire function such that $$|f(z)|&lt;\frac{1}{|\text{Im}(z)|},\qquad z\in\Bbb C-\Bbb R.$$ The question asked me to prove that $f(z)=0$. At least looking at it, it really seems to have an application of Liouville's theorem lurking around somewhere, but I haven't found it.   My thoughts first led me to think about doing this by contradiction and using Picard's little theorem. So, I've considered a strip containing the real axis (say of width $2$ for simplicity). This will imply the complement maps into the unit disk, which implies that this strip has to map almost everywhere else on the complex plane. Now, on the imaginary axis, I know that $f(z)$ will vanish as $z\to\infty$, and this seems like it might be useful. I'm sort of under the impression $f(z)$ might have an essential singularity at $\infty$, which would mean $f(1/z)$ has an essential singularity at $0$. Either way, it of course can't have a pole at $\infty$ because of $f(z)$ vanishing on the imaginary axis, and if it is a removable singularity, it must be $0$, which still gives the solution. Therefore, I think it must have something to do with $f(z)$ having an essential singularity at $\infty$.   I was hoping to combine this with the above inequality and deduce a contradiction, but I haven't thought of one yet.   Any hints or suggestions? I'm studying for a prelim. exam, so this isn't homework.  Update: So, in the spirit of searching methods using the essential singularity at $z=0$, we have $$\left|f\left(\frac{1}{z}\right)\right|\leq\frac{1}{\left|\text{Im}\left(\frac{1}{z}\right)\right|}=\frac{|z|^2}{|y|}.$$ Thus, for $|y|&gt;1$, we have $$\left|f\left(\frac{1}{z}\right)\right|&lt;|y|\left|f\left(\frac{1}{z}\right)\right|&lt;|z|^2.$$ Thus, if I can show that $|f(1/z)|$ is a polynomial, we'll know it can't have an essential singularity at the origin, concluding my proof. rsync two existing directories copying everything I have two file servers in two locations. Currently both have the same data, which generally is unmodified (used for read only access).When the second server was set up (the one I'm sshing to) the data was copied over LAN and has since been moved geographically.  I'm trying to use rsync for the first time on the required directories. An example command;  sudo rsync -avz --ignore-existing -P --dry-run /media/Storage/OSs/ user@mydomain:/mnt/Storage/OSs/   I've tried using -c -t -u (Additionally went on the remote server and updated the timestamps to today) also but every time I execute a dry run it wants to copy everything!  Additionally the user is the same for both machines with the same UID.  *Edit  After playing around a bit more, I've found that rsync does not like the whitespace in the subdirectory names; For instance if I use ' to escape local shell &amp; \ to escape remote shell     sudo rsync -avz --ignore-existing -P '/media/Storage/OSs/Windows/Windows server 2011/' 'user@mydomain:/mnt/Storage/OSs/Windows/Windows\ server\ 2011/'   Then all is well, my theory is then that rsync does not like the subdirectories with whitespaces. I have thousands of subdirectories; the only solution I can think of is to write a small python/shell script to run each sub directory separately but is undesirable. I would like to put an address in my document as follows:  |                             | |                     Name    | |                     Street #| |                     City    | |                     ZIP     | |                             |   where the | mark the left and right page borders. I would like the items of the address (Name, Street etc.) to be left-flushed, but the box right-flushed so that the longest item touches the right page border.  Is there a simple way to accomplish this? Suppose I wanted to travel to one of the recently discovered potentially Earth-like planets such as Kepler 186f that is 490 light years away. Assuming I had a powerful rocket and enough fuel, how long would it take me? How do I enable auto-login in LightDM? I want user foo to auto-login using LightDM (which has been used by Ubuntu since version 11.10). How would I do that? Did any Quidditch games ever end by agreement of the Captains? The game can only end when the Snitch has been caught, or by mutual agreement of the two teams' Captains; the latter is very rare, however, as one team would have to lose. (source: HP Wikia on Golden Snitch)   Is there an example from canon of this resolution to the game ever happening? Prove that $\frac4{abcd} \geq \frac a b + \frac bc + \frac cd +\frac d a$ Let $a, b, c$ and $d$ be positive real numbers such that $a+b+c+d = 4$. Prove that $$\frac4{abcd} \geq \frac a b + \frac bc + \frac cd +\frac d a .$$   How can I approach this using only the ? Are there any other methods that do not involve the AM-GM inequality? Hosting multiple distinct folders for distinct domains