I'm not able to run the following example in Texmaker:  \documentclass{article} \usepackage{nomencl} \makenomenclature \begin{document} \section*{Main equations} \begin{equation} a=\frac{N}{A} \end{equation}%  \nomenclature{$a$}{The number of angels per unit area}% \nomenclature{$N$}{The number of angels per needle point}% \nomenclature{$A$}{The area of the needle point}% The equation $\sigma = m a$% \nomenclature{$\sigma$}{The total mass of angels per unit area}% \nomenclature{$m$}{The mass of one angel} follows easily.  \printnomenclature  \end{document}   I use MiKTeX under Windows with the following Texmaker configuration:    and run the sequence:    I followed  to configure my editor without success. Thanks for your help
I have used the package nomencl. In my code I have incorporated the \nomenclature as well. But when I compile, it is not showing me any results. My code is :  \documentclass[pdftex,12pt,a4paper]{report} \usepackage{nomencl} \makenomenclature \begin{document} ---page numbering and other things included----- \include{symbols} -----others--- \end{document}   symbols.tex  \chapter*{NOTATIONS} \addcontentsline{toc}{chapter}{Notations} \nomenclature{$G_e$}{Equivalent Shear Modulus} \printnomenclature   Shall I use \nomenclature while explaining the chapter. Will It give me the same results? like  \documentclass[pdftex,12pt,a4paper]{report} \usepackage{nomencl} \makenomenclature \begin{document} ---page numbering and other things included----- \include{symbols} \include{chap3-calculate_w} -----others--- \end{document}   symbols.tex  \chapter*{NOTATIONS} \addcontentsline{toc}{chapter}{Notations} \printnomenclature   chap3-calculate_w.tex  \chapter{SETTLEMENT RESPONSE OF GEOSYNTHETIC REINFORCED GRANULAR FILL SOFT SOIL} \label{chap:W} \section{INTRODUCTION} In this thesis, the methodology to determine an  Equivalent single layer shear modulus \nomenclature{$G_e$}{Equivalent Shear Modulus},$G_e$ value for a...etc   I am not getting the output in both these. Can someone help me with this?
How to exit from an application which doesn’t exit on press back button? I have this table definition as part of a invoice  \begin{tabularx}{\textwidth}[ht]{lXrr}%   It worked fine for years until I have a very short word in the X column for the first time. Now my table is very small in width and centered horizontally on the page.  In my expectation the X column should fill up all space until the width of the table reaches the width of the page except the margins.  I have read about workarounds specifying something like 1.2\textwidth, but I don't like that, because the table is a template included via \include, so it would affect all my invoices.  I also tried \linewidth, \hsize and \columnwidth, but everything results in the same layout.  Is there a way to make the only X column expand so that it uses all available space?    Complete included table definition (Rechnungstabelle.tex):  \newcommand{\Rechnungstabelle}[4]{% vielen Dank für Ihren Auftrag. \noindent \begin{tabularx}{\textwidth}[ht]{lXrr}% \toprule% \bf{Anzahl} &amp; \bf{Bezeichnung} &amp; \bf{Einzelpreis} &amp; \bf{Gesamtpreis} \\% \midrule% #1% \bottomrule% &amp; \bf{Rechnungsbetrag}  &amp; &amp; \bf{\EUR{#2}} \\% \ifthenelse{\equal{#3}{}}{}{&amp; Enthaltene MwSt. 19\% &amp; &amp; \EUR{#3} \\}% \ifthenelse{\equal{#4}{}}{}{&amp; * Enthaltene MwSt. 7\% &amp; &amp; \EUR{#4} \\}% \end{tabularx}% }   Changing the table header row to  \bf{Anzahl} &amp; \bf{Bezeichnung} \hspace{\textwidth} &amp; \bf{Einzelpreis} &amp; \bf{Gesamtpreis} \\%   is a workaround, but I don't think that would be good TeX style.  Minimum example for reproducing:  \documentclass[ fontsize=12pt,                  paper=a4,                 foldmarks=TBMPL,                 fromalign=center,                 ngerman                 ]{scrlttr2} \usepackage{babel} \usepackage[utf8]{inputenx} \usepackage[right]{eurosym} \usepackage{tabularx} \usepackage{ltablex} \usepackage{booktabs} \usepackage{ifthen}  \input{Rechnungstabelle} \begin{document} \begin{letter}  \Rechnungstabelle{     1,0 h &amp; Do something &amp; \EUR{99,00} &amp; \EUR{99,00} \\      }     {99,00}     {}{} \end{letter} \end{document} Questions with many upvotes should not be closable I see a lot of good, well-writen and constructive questions (that are probably not only good for me) closed, by various reasons which I fail to digest, so I propose the idea that questions with n upvotes should not be closable.  This would be in my opinion very much in the spirit of "", and unless I'm wrong, it would be beneficial for the users to choose by themselves whether the site should have or not x question. The ones which are low quality never get many upvotes anyway.  The only cons I can think of are... DB space? And at a minimum there's the pro of more popular pages with more ads (for the admins), and questions people like (for the users).  I'm also counting for , in the lines of Google's "", but questions  are more like what I'm aiming at (probably that question has not many upvotes for this though). Let $K/F$ be a finite field extension and suppose that $F$ is infinite. Is it possible to have a nonzero polynomial $p \in K[x_1,...,x_n]$ that vanishes in $F^n$? How do I select elements of an array given condition? I have to travel to Germany and Switzerland for business purpose. I have already been here 2 years ago. I have applied for business visa to the German consulate twice and both times the application got rejected. They have put a green stamp on the last page twice. The reason is the purpose and information submitted regarding intended stay is not reliable. I have submitted the documents to Swiss consulate and they have accepted and granted me a visa. Now I have to first travel to Germany and then to Switzerland.  So my question is, with a Schengen business visa granted by Switzerland, may I enter in Germany? Does the rejection stamp has any impact for entering at German airport ? Does it mean I cannot travel to Germany but to other Schengen countries ? How to disable Windows 10 memory compression? my former wrong assumption: it drains my notebook battery and I've no shortage of RAM. In Task manager you see ntoskrnl.exe is eating more CPU time than any other process. this feature does not appear to be optional and came 2 days ago with the 1st Win10 Update (Win10Pro in my case).  Edit:  I want to disable it, at least to exclude it as a culprit for my (unproven) assumptions. That process never came to my attention in the last 2 months and in task manager's long name it's called "system memory and compressed memory". $\mathbb{Q}(\sqrt{n}) \cong \mathbb{Q}(\sqrt{m})$ iff $n=m$ Page 105 of D. Burton's A First Course in Rings and Ideals reads     It is not difficult to show that if (I'll call them $n$ and $m$ instead of $n_1$ and $n_2$) $n$, $m$ are square free integers, then $\mathbb{Q}(\sqrt{n}) \cong \mathbb{Q}(\sqrt{m})$ if and only if $n=m$.   Well, it is getting difficult for me, any help or would be appreciated.    My progress so far: Suppose $\phi :\mathbb{Q}(\sqrt{n})\to\mathbb{Q}(\sqrt{m})$ is an isomorphism. Then $\phi(u)=u$ for every $u \in \mathbb{Q}$, so that $\phi(\sqrt{n})^2=\phi(n)=n$. If $\phi(\sqrt{n})=a+b\sqrt{m}$ for some $a,b\in\mathbb{Q}$, then $(a+b\sqrt{m})^2=a^2+b^2m + 2ab\sqrt{m}=n$ implies $$a^2+b^2m = n$$ and $$2ab=0.$$  Then $b=0$ cannot happen since that would imply that $\sqrt{n}\in\mathbb{Q}$, where $n$ is a square-free integer. Also $a=b=0$ cannot happen. Hence $a=0$ and we have $$b^2m=n.$$ If $\psi:\mathbb{Q}(\sqrt{n})\to\mathbb{Q}(\sqrt{m})$ were an isomorphism then there would exist some $s\in\mathbb{Q}$ such that $$s^2m=n,$$ then $s=b$ or $s=-b$. Therefore the only isomorphisms from $\mathbb{Q}(\sqrt{n})$ to $\mathbb{Q}(\sqrt{n})$ are $\phi(u+v\sqrt{n})=u+vs\sqrt{m}$ and $\psi(u+v\sqrt{n})=u-vs\sqrt{m}$.    I don't know if there's an easier way and I don't know if I'm in the correct way here. Thanks beforehand :) Lagrangian of an effective potential If there is a system, described by an Lagrangian $\mathcal{L}$ of the form   $$\mathcal{L} = T-V = \frac{m}{2}\left(\dot{r}^2+r^2\dot{\phi}^2\right) + \frac{k}{r},\tag{1}$$   where $T$ is the kinetic energy and $V$ the potential energy, it is also possible to define the total energy $E$ of the system   $$ E = T + V =\frac{m}{2}\left(\dot{r}^2+r^2\dot{\phi}^2\right) - \frac{k}{r}.\tag{2}$$  If the angular momentum $M$ is defined by $$ M = m r^{2} \dot{\phi},\tag{3}$$ then $E$ can be written as  $$ E = \frac{m}{2}\dot{r}^2 + \underbrace{\frac{M^2}{2mr^2}-\frac{k}{r}}_{V_\textrm{eff}\left(r\right)},\tag{4}$$  where the last two terms are written as new, "effective" potential $V_\textrm{eff}\left(r\right)$.    In addition, using the definition of $M$, the Lagrangian $\mathcal{L}$ can be written as  $$ \mathcal{L} = \frac{m}{2}\dot{r}^2 + \underbrace{\frac{M^2}{2mr^2}+\frac{k}{r}}_{-V_\textrm{eff}\left(r\right)},\tag{5}$$  where the sign of $V_\textrm{eff}\left(r\right)$ has been changed, since $\mathcal{L} = T-V$. But from this argument, it appears that there are two different possible ways to construct the same effective potential. This seems to me contradictory. Where is my mistake? On an upcoming trip, I will be taking a desktop computer and monitor as checked luggage (on a United/Continental flight). What should I be aware of when doing this? What needs to be done to properly protect all the components? Are there any airline policies I should be aware of? Relative pronouns "where" and "when": where can they be omitted? I know the "omitting-rules" regarding the relative pronouns who/which/that and whose. How does it work with where and when? In the first sentence I cannot omit where but I can easily omit when in the second sentence. What is the rule?   I saw John in the shop where you bought your brown T-shirt. I met Laura on the day (when) I missed the train to Barcelona. Detect Chrome extension first run / update Inequality: $x^2+y^2+xy\ge 0$ I want to prove that $x^2+y^2+xy\ge 0$ for all $x,y\in \mathbb{R}$.  My "proof":  Suppose wlog that $x\ge y$, so $x^2\cdot x\ge x^2\cdot y\ge y^2\cdot y=y^3$ (because $x^2\ge 0$ so we can multiply both sides by it without changing the inequality sign) giving $x^3\ge y^3$. Substracting we have $x^3-y^3\ge 0$ or $(x-y)(x^2+xy+y^2)\ge 0$. Since $x\ge y$ we can divide by $x-y$ to get $x^2+xy+y^2\ge 0$.  Is it right?  Thanks for your help! Recovering lost text which was copy pasted from a website to MS Word Why do gaps appear in my mesh when I animate it? As I attempt to complete a "Walk cycle" with my model, the mesh at the pants line separates from the skin as the model moves or as I rotate the controls. This happens in many places on my model and it reveals the model interior. It is a one piece mesh, though, so I don't understand why this happens. Is this caused by weight painting problems? How can I fix this? `du -sh` reports different used size than `df -h` Possible Duplicates:             df -h says that I have 494G used on /var:  Filesystem            Size  Used Avail Use% Mounted on /dev/sda3             564G  494G   41G  93% /var   But du -sh /var says it's 350G  What makes them different? AES Mix Column Transformation Section 3.4.3 "The MixColumns Step"(page 39) of , it states     The columns of the state are considered as polynomials over   $\operatorname{GF}(2^8)$ and multiplied modulo $x^4 + 1$ with a fixed polynomial $c(x)$.      The polynomial $c(x)$ is given by   $c(x) = \mathtt{03} \cdot x^3 + \mathtt{01} \cdot x^2 + \mathtt{01} \cdot x + \mathtt{02}$      Let $b(x) \equiv c(x) \cdot a(x) \pmod{x^4 + 1}$. Then         How this polynomial multiplication modulo $x^4+1$ is converted to Matrix Multiplication? Presumably after an update, google chrome has very serious problems with page rendering. I want to downgrade it. (Switching to vmlinuz.old and initrd.img.old did not help).  $ apt-cache policy google-chrome-stable google-chrome-stable:   Installed: 35.0.1916.153-1   Candidate: 35.0.1916.153-1   Version table:  *** 35.0.1916.153-1 0         500 http://dl.google.com/linux/chrome/deb/ stable/main i386 Packages         100 /var/lib/dpkg/status   on a computer where google chrome works ok:  $ apt-cache policy google-chrome-stable google-chrome-stable:   Installed: 34.0.1847.132-1   Candidate: 35.0.1916.153-1   Version table:      35.0.1916.153-1 0         500 http://dl.google.com/linux/chrome/deb/ stable/main amd64 Packages  *** 34.0.1847.132-1 0         100 /var/lib/dpkg/status   (If I had the .deb on the 2nd computer, everything would be easier. But there's no .deb. And no old .deb's on the google site.)  So I try:  $ sudo aptitude install google-chrome-stable=34.0.1847.132-1 Unable to find a version "34.0.1847.132-1" for the package "google-chrome-stable" Unable to find a version "34.0.1847.132-1" for the package "google-chrome-stable" No packages will be installed, upgraded, or removed. 0 packages upgraded, 0 newly installed, 0 to remove and 0 not upgraded. Need to get 0 B of archives. After unpacking 0 B will be used.   You see, it does not work. The Synaptic manager also shows no version that I could set.  So, how do I downgrade google-chrome-stable?  Probably someone knows an archive of old google-chrome .deb's? Proving the limit of a function of a sequence is equal to the function of the limit of that sequence Suppose $f$ is a continuous function at $x = c$ in $[a,b]$.  Prove that for any sequence ${x_n}$ in $[a,b]$ converting to $c$, the sequence $\{f(x_n)\}$ converges to $f(c)$.  That is, $$ \lim_{n\to\infty}f(x_n)= f\left(\lim_{n\to\infty}x_n\right)$$    This proof seems simple but there are a few things that I need to know first. If $\{x_n\}$ converges to $c$, is it sufficient to substitute $c$ in for $\lim_{n\to\infty}x_n$?  Also needing some guidance on the structure of this proof.  Thanks! Getting percent sign into an URL in a footnote I'm using the url package. Now, I have some some url with a percent sign in it and want to place it in a footnote. When I let the % where it is, I get a comment, and the whole thing fails to compile because of some unmatched brackets. When it's at the end of a line, it doesn't show up at all in the result. When I write \% instead, this gets literally into the output—but I want the url to be displayed correctly.  What could I do?