I’m trying to find a feature selection package in R that can be used for regression. Most of the packages implement their methods for classification using a factor or class for the response variable. In particular I’m interested if there’s something using random forest for that purpose. Also if someone knows some good paper in this field would be welcome.
I am very new to R. I am learning machine learning right now. Very sorry, if this question appears to be very basic.  I am trying to find a good feature selection package in R.  I went through Boruta package. It is a good package but I read that it is only useful for classification.  I want to do implement feature selection in R for regression tasks. I went through the caret package documentation but for my level, it is very difficult to understand.  Can any one please point me to a good tutorial or list any good packages or most frequently used packages in R for feature selection.  Any help would be appreciated. Thanks in advance.
Trying to put a footnote in subsection title:  \subsection{Effect of Lateral Confinement on SW Band Structure\footnote{Parts of this sub--section are based on \citet{Venkat2013}}}   produces the following error:  Argument of \@sect has an extra } ...section are based on \citet{Venkat2013}}}   I am using:   \documentclass[paper=A4, fontsize=12, toc=listof, toc=index, toc=bib]{scrreprt}   Please advise. Standardize Training and Validation Data $ \int_{-2}^{0} \frac{x}{\sqrt{e^x+(x+2)^2}} dx $ = -$  2.887270... $  The function has no antiderivate and there's no symmetry here to help, if you solve this I would be thankful if you would for a highschooler ^^ Short story where the Earth has been kept inside a force field for millennia What would be an English equivalent for the Mexican Spanish word tocayo? Presently, how much information can a quantum computer store, in how many qubits? What restrictions are there and how does it vary across realizations (efficiency of data storage, ease of reading and writing, etc)? When does Bleeding Attack effect apply? I've designed for a campaign a duo of rogues. My character is as , and his follower is a Knife Mistress. Couple of question about them. Our party is about to ambush several . My Sniper will hide near their camp, and shoot the weakest one when fight begins. His follower will then rush the troll and slice him in several pieces. My Sniper has the Bleeding attack feat:  Bleeding Attack (Ex) Benefit: A rogue with this ability can cause living opponents to  by hitting them with a sneak attack. This attack causes the target to take 1 additional point of damage each round for each die of the rogue's sneak attack (e.g., 4d6 equals 4 points of bleed). Bleeding creatures take that amount of damage every round at the start of each of their turns. The bleeding can be stopped by a DC 15 Heal check or the application of any effect that heals hit point damage.  Emphasis mine. Thus, a normal enemy would bleed every turn, until he get cleaned of the bleeding effect. However, troll have a special ability, which is  5 (acid/fire)  Regeneration (Ex) A creature with this ability is difficult to kill. Creatures with regeneration heal damage at a fixed rate, as with , but they cannot die as long as their regeneration is still functioning (although creatures with regeneration still fall unconscious when their hit points are below 0). Certain attack forms, typically fire and acid, cause a creature’s regeneration to stop functioning on the round following the attack. During this round, the creature does not heal any damage and can die normally. The creature's descriptive text describes the types of damage that cause the regeneration to cease functioning.  So, the troll will automatically get rid of the bleeding effect during his first turn. My question is: Does the bleeding effect apply before the regeneration, or get neglected, because the troll will heal during his turn? Am I right to assume that, Bleeding attack effect getting triggered at the beginning of the troll turn, it will deal him the damages before the wounds heals? How to negate a specific symbol? I want to negate the symbol whose code is \models (this would be specific to Formal Logic). How can I do that? I tried a number of combination, but didn't find how this could be done. I tried \neqmodels, \nemodels, \notmodels, \nmodels  but all of them are wrong.  Is there a general way to negate symbols? My sisters and I all have iPhones under the same account. I also have an iPad under the same account. I am trying to get the iMessage on my iPad compatible with my phone number, not email address.   The only phone number choice to choose from is my sister's iPhone number. How can I choose my phone number for iMessage on my iPad? For some reason, I can no longer access the Winterbash 2015 page--when I try, I get redirected to the  instead, just like Winterbash is over. Except, we should still have almost another two weeks. Also, I can no longer see hat-related features on SE sites. What happened to the hats?!  UPDATE: The hats seem to be back now. But the question still remains, why did they disappear, and is it going to happen again? Showing that $e^z=z$ has infinitely many solutions One of our review problems for my complex analysis final is the following:     Show that $e^z=z$ has infinitely many solutions in $\mathbb{C}$.   I've seen a few solutions online, but none of them have used material that was covered in our introductory complex analysis course. Would anyone be able to provide a simple solution?  I'm trying to think of ways to invoke bounding in some way but I can't seem to come up with anything. Can the weak force create a bound state? My understanding is that the exchange of Z bosons could yield an attractive or repulsive "force" between two fermions. For most combinations the electromagnetic or strong interactions will take place.  However, if we have two neutrinos, or a neutrino and a charged lepton, only the weak interaction comes into play. Are these possible bound states? I am moving from one job to another (postdoc to tenure track) this summer and I have papers in several stages of being written, these go from handwritten notes with all the necessary arguments to under revision at a journal. All the papers will have my new contact information put on them but where is the line for changing affiliation? It seems obvious to me that the one that is still in the handwritten notes stage will get the new affiliation and that the ones under revision won't. So somewhere in between is a line.   Where is it?  There are some similar questions so far (see  and  but they do not seem to be quite the same situation since I am not changing fields and the appointments are not concurrent. Translation help review queue? Do messages in archive count to your inbox space? Pretty much as the title says, do messages in archive count to your total inbox space? How can I resize a partition with Disk Utility? I have 2 partitions, I reduced the size of one and want to expand the other to fill the now available space.   How do I expand the Lion Partition into the empty grey space beneath Macintosh HD partition? How to play MP3 files using Rhythmbox? Yesterday I just installed the Ubuntu 12.04 for the first time, the problem is that I can't play and of the MP3 files that I have.    I get this error:       Required plugin could not be found Python (v2.7) requires to install plugins to play media files of the following type: MPEG-1 Layer 3 (MP3) decoder   Please help me so I can play the files. Thanks Not sure if there is a cultural difference. In our family it is considered normal to frighten the child so that he behaves the way we want.  Example- Parent: Eat that quickly or the God will punish you! Parent: Don't go on the stairs. The ghost is hiding there and it'll catch you! Parent: Be quiet or the police will grab you!  Does this kind of behavior from the parent's side has any abnormal effects on the baby in the longer run? Can this behavior be accepted as normal?  Has any research been done on this aspect? joomla 2.5 in module install.mysql.utf8.sql dosent work After T-2, why not send back another T-800?