Given three iid random variables, $X,Y,Z$  following a Uniform $(0,1)$ distribution. Then, how to find $\Pr(X&gt;YZ)$?     Recently, I was asked this question in an interview, but I chocked there. Any hint will be appreciated.
$x,y,z$ are independent and uniform random on $[0,1]$.  I know that $P(x \geq yz) = 3/4$ by triple integrating the triple density function.  However, is there a easier way to get this solution? Without triple integration.
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