Area51 has .   Shouldn't this proposal be killed immediately? I mean, if this proposal were allowed to be flourished, then in no time you will see Hindi SO, Hebrew SO, Chinese SO, Dutch SO, Malay SO, Arabic SO and all the same SOes with the same set of content and same target audience except different languages.  In fact this is already happening, just see how the , ,  proposals littered over Area51 and you will get a sense of how serious the situation is. All these are huge duplication of work and contribute to a great fragmentation of audience, this is of course something SO doesn't encourage.   The longer you allow it to gain steam or even to let it gain supporters, the harder it is to kill it later. So why the mods are not taking action now and kill the proposal immediately?
I want to propose for a Persian version of Super User (I will explain why later) so I want to create a proposal in Area 51, but this means non-English question and answers, Is this OK? P.S: This may be a question for other non-English proposals too. Update: The main question is: How can non-English site proposals pass the Commitment phase? How can the English community support non-English proposals? You can find some information in  about the Stack Exchange 2.0 Site Creation Process (specially Commitment phase):  How does this thermometer work? Intuitively, if Jon Skeet says that he’ll participate in the Sock Puppet Stack Exchange, that commitment is a better sign that the site will succeed than if we get a commitment from a random Internet user who has never participated in Stack Overflow. Sure, they’re both wonderful people, I’m sure, but Jon Skeet has proven that he likes to participate in Stack Overflow so it’s a good bet that he’ll participate in SockExchange, too. .... we’re going to require a selection of existing users with certain badges and reputation that proves that they’ll participate. For instance (and I’m making these numbers up), we might require that a site get at least 100 commitments from people with the Teacher badge, at least 20 from people with the Enthusiast badge, and at least 50 from people with a reputation of 1000 or more on some of our sites.
Faction Membership Limits in Fallout 4 Are there any limitations to the faction memberships you can have in Fallout 4?  I'm brand-new to the Fallout universe, and just got to the point of being invited to the Brotherhood of Steel. However, I'm a bit concerned about their politics and how it may affect my standing with other factions I may encounter.  If I join the Brotherhood, will there be other factions that I can't join? Are there any other factions that have such limitations?  Note: I'm still not very far into the game, and not very familiar with the Fallout 4 universe in general, so please make liberal use of spoiler markdown in your answers. Essentially, the only things that need to be un-spoilered are Yes/No answers for the questions asked above. Directory-tree listing in Python The names of the derived functors $\operatorname{Tor}$ and $\operatorname{Ext}$ seem quite cryptic to me. Does anyone know what these abbreviations stand for? I would be glad if someone could tell me where these names come from. Sensitivity to initial conditions and topological transitivity Forgive the possibly naive question, but I'm returning to a basic undergrad-level study of chaotic dynamical systems and can't quite seem to reconcile the notion that in order for a dynamical system to be considered chaotic, it must have positive global Lyapunov exponents. Such exponents, of course, drive the divergence of trajectories. However, topological transitivity implies that trajectories can get arbitrarily close as well over some finite time. It seems that positive Lyapunov exponents would disallow this mixing. Is there a point at which these positive exponents no longer describe the system, and the mixing behavior begins? I use Chrome as my default browser. This includes my browser for work.  We have a trac setup that uses folder paths (see example) for the different projects  Example:   main.employertracsite.com/projects/projectname   I want the ability to manually sort the results that are displayed in the auto-complete.  Chrome displays auto-complete based on the usage history of a web address. Which means that a project that isn't my main focus is displayed in the url instead of the one that I've been using more lately.  Example:   main.employertracsite.com/projects/alliance is the project that I'm not using all the time anymore and is showing up in auto-complete main.employertracsite.com/projects/horde is the project that I am using more often now and want to show up in the auto-complete   I don't want to delete the alliance from my history, but I do want the ability to be able to manually adjust which project shows up in auto-complete. This will be more usable for me in the future because I'm constantly on different projects full-time and they each have their own area.  I also do not want to delete my history. I've setup a plane with a particle emitter system. When I render the footage and the particles are glowing. Where do I find the settings for that? Evaluate $ 1 + \frac{1}{3}\frac{1}{4}+\frac{1}{5}\frac{1}{4^2}+\frac{1}{7}\frac{1}{4^3}+\dots$ Evaluate $$ 1 + \frac{1}{3}\frac{1}{4}+\frac{1}{5}\frac{1}{4^2}+\frac{1}{7}\frac{1}{4^3}+\dots$$  All i could do was to see that $$\frac{1}{3}=\frac{1}{2.1+1},\frac{1}{5}=\frac{1}{2.2+1},\frac{1}{7}=\frac{1}{2.3+1},\dots$$  SO, we should be able to write   $$ 1 + \frac{1}{3}\frac{1}{4}+\frac{1}{5}\frac{1}{4^2}+\frac{1}{7}\frac{1}{4^3}+\dots=1+\sum_{n=1}^{\infty}\frac{1}{2n+1}.\frac{1}{4^n}$$  This is what i could simplify the given question to...   But, this is doing me no good.. I could not go any further..  I would be thankful if some one can help me to clear this.  I would request users who are trying to help me to just give necessary hints but not post it as answer.  Thank You. Can't access select https sites on Linux over PPPoE My internet connection used to be a direct LAN connection to my provider. Back then, everything would load fine on both Windows and Ubuntu (dual boot). However, a while ago they started needing me to dial (PPPoE) using a username and password. Gateway, subnet mask, IP, DNS servers all stayed the same. But since then, I haven't been able to browse certain websites on Ubuntu, even though there have been no such issues on Windows. Some example websites are -  (although share.ovi.com loads fine, and nokia.com loads fine),  (works on Chrome(ium) and Opera but not on Firefox (both 3.6 and 4)) Mozilla  and other random websites.  Some of the websites that don't load show timeout messages and for some websites (like the moz addons one), the browser will keep trying to load without an end (I've left it like that even for hours but not noticed anything different happen).  I have tried changing the DNS servers to public ones. I have even tried booting from a Fedora LiveCD and then changing the DNS to those (and even to the ones of OpenDNS), but the exact same thing happens. What could be inherently wrong with some config within Linux itself that is causing this problem?  Does anyone know why this is happening and how it can be fixed?  Note: This question has been  on SU, but not gotten any responses.  Update: Just saw  that someone else was having similar problem and solved it by putting a NetworkManager.conf file in /etc/NetworkManager. What needs to be in that file? Prove that $f$ has finite number of roots Let $f:[0,1]\to \mathbb{R}$ be a differentiable function. If there do not exist any $x\in[0,1]$ such that $f(x)=f'(x)=0$, prove that $f$ has only finite number of zeros in $[0,1]$.   I'm not getting any idea how to proceed. In Texas Hold'em poker, there are some cases where a particular card, often called kicker, acts as a tiebreaker between players to determine who wins the pot, or if the pot has to be shared.  For some combinations such as three or four of a kind, there is no doubt: the kicker is the 5th card of the chosen combination, and determines the winner.  Example     Alice has 7 and 10   Bob has 7 and K   On the board are 7, 7, 2, 3, 4   In that case, both have a three of a kind. But because Bob has a king and Alice only a 10, he wins.  Most of poker websites explaining the rules clearly mention the role of the kicker applying to three of a kind and double pairs. But much fewer say something about colors, straights and full houses, and I found many contradicting answers. I also asked the question to some used online poker players and they also gave me contradicting answers.  I have tried to search for official tournament rules, but most of them only explain what happens with bad behaviors, bad deals, incorrect or confusing betting, showing cards when you shouldn't, acting when it's not your turn, etc. without mentioning subtleties about combinations at all.  To simplify my question, I will take three examples; I think it's better to start with examples before getting to the general answer if one exists. So, what's happening in the following 3 examples? Could you give a more generalized answer?  Example 1 - Flushes     Alice has 2&clubs; and 3&clubs;   Bob has 4&clubs; and 5&clubs;   On the board are 6&clubs;, 8&clubs;, 10&clubs;, 2&hearts;, 5&diams;   Contradicting answer 1: it's a tie, because the highest card included in the flush is the 10, which everybody chooses to include in their 5 showdown cards. Contradicting answer 2: Bob wins, because he has the greatest private card that is part of the flush  Example 2 - Straight     Alice has 6 and K   Bob has 6 and J   On the board are 4, 5, 7, 8, 10   Contradicting answer 1: it's a tie, because the greatest card in the straight is the 8 for both Alice and Bob Contradicting answer 2: Alice wins, because she owns an extra king, compared to the jack of Bob  Example 3 - Full house     Alice has 3 and 7   Bob has 3 and 6   On the board are 3, 3, 2, 2, 5   Contradicting answer 1: it's a tie, because one is supposed to choose only five cards to make a combination, and a full house is already five cards. There couldn't be any kicker, and thus their showdowns are strictly equals. Contradicting answer 2: Alice wins because of her extra 7, compared to the 6 of Bob  Thank you very much for your answers.  Note: I'm unable to post next to you, so I edit my own post; strange not be able to answer to an answer.  Ok, So if I summarize what you are saying :   In the flush case, Bob wins because at some point, their hand differs. Technically, I can continue comparing the highest private card to decide who wins. I had it correct. In the straight case, if the highest card of the straight is public, then it's technically always a tie, no matter what the players had as second private card (asuming that only one of the two cards was part of the straight). In a full house if both players have the same triplet and the same pair, it's always a tie, no matter what the players had as second private card (assuming again that only one of the two was part of the full house).   Please confirm me that what I summarized is correct.  Thank you for your answer. Zero to the zero power – is $0^0=1$? Could someone provide me with a good explanation of why $0^0=1$?  My train of thought:  $x&gt;0$  $0^x=0^{x-0}=0^x/0^0$, so  $0^0=0^x/0^x=\,?$  Possible answers:   $0^0\cdot0^x=1\cdot0^0$, so $0^0=1$ $0^0=0^x/0^x=0/0$, which is undefined   PS. I've read the  on mathforum.org, but it isn't clear to me. Why is this sentence wrong? "He went to home." Three linked question on non-negative definite matrices. 1.a symmetric matrix in $\mathbb{M}_n(\mathbb{R})$ is said to be non-negative definite if $x^Tax≥0$ for all (column) vectors $x\in \mathbb{R}^n$. Which of the following statements are true? (a) If a real symmetric $n\times n$ matrix is non-negative definite, then all of its eigenvalues are non-negative. (b) If a real symmetric $n\times n$ matrix has  all of its eigenvalues are non-negative , then it is non-negative definite. (c) If $ A\in \mathbb{M}_n(\mathbb{R})$, then $AA^T$ is non-negetive definite. 2. only one of the following matrices is non-negetive definite. Find it. (a) $\begin{pmatrix} 5 &amp; -3 \\ -3 &amp; 5 \end{pmatrix}$. (b) $\begin{pmatrix} 1 &amp; -3 \\ -3 &amp; 5 \end{pmatrix}$. (c) $\begin{pmatrix} 1 &amp; 3 \\ 3 &amp; 5 \end{pmatrix}$.      3.let $B$ be the real symmetric non-negative definite $2×2$ matrix such that $B^2=A$ where $A$ where is the non-negetive definite matrix in question $2$.write down the characteristic polynomial of $B$.      My thoughts..  For1.  (a) &amp; (b) are true but not sure about (c). For 2. (a) is the correct option since it has all positive eigen values.they are $2,8$. For 3. Eigen values of $B$ will be $\sqrt{2}$ and $\sqrt{8}$. So the answer is $x^2-3√2x+4=0$.      Can anybody help me to verify the solutions of the above problems. Using a transistor as a switch I am attaching a motor to an ATmega32 chip. I want to build an H-bridge but before doing that, I want to control the motor using the chip. I bought few NPN Transistors from RadioShack. I have 5V running though the breadboard. I attached Vcc to the Collector, Base to the Pin, and Emitter to the motor. And other wire of motor is hooked up to Ground. Unfortunately, the power coming out of the transistor is too low, the motor is barely moving (As opposed to when I hook up my motor straight to 5V). What is wrong? Do I need a different transistor or is my setup wrong? If it is the transistor, can you please recommend the right one, I am not too good at those. Even though JRE 8 is installed on my MAC OS Yosemite, the error - " No Java Runtime present,requesting to install " I started by Time Series Analysis by Hamilton, but I am lost hopelessly. This book is really too theoretical for me to learn by myself.   Does anybody have a recommendation for a textbook on time series analysis that's suitable for self-study? Why are there no byte or short literals in Java? I can create a literal long by appending an L to the value; why can't I create a literal short or byte in some similar way? Why do I need to use an int literal with a cast?  And if the answer is "Because there was no short literal in C", then why are there no short literals in C?  This doesn't actually affect my life in any meaningful way; it's easy enough to write (short) 0 instead of 0S or something. But the inconsistency makes me curious; it's one of those things that bother you when you're up late at night. Someone at some point made a design decision to make it possible to enter literals for some of the primitive types, but not for all of them. Why? By taking courses, I have learned topic A. Through self-studying and discussion with others, I have explored topic B.    I also study topic A outside the classroom. What I want to emphasis is that topic B is not in my curriculum, but I study it on my own. Extracurricular activities can include both activities contributed to academic study although outside the normal curriculum, but also activities not contributed to academic study such as sports, volunteer work, etc. I want to emphasis the former activities. Do you say "outside classes", when mentioning study by yourself, i.e.      Outside classes, I have explored B.      If it were you, how would you rewrite the first quote for the same       meaning?    Thanks! How to get all Perfect or Near-Perfect Matchings of a graph What is the order of $(\mathbb{Z} \oplus \mathbb{Z})/ \langle (2,2) \rangle$ and is it cyclic? Evidently, $(\mathbb{Z} \oplus \mathbb{Z})/ \langle (2,2) \rangle$ has order $4$, but I think it's infinite.   The four cosets are listed as $(0,0) +  \langle (2,2) \rangle$, $(0,1) +  \langle (2,2) \rangle$, $(1,0)+  \langle (2,2) \rangle$ and $(1,1) +  \langle (2,2) \rangle$. However, $(2,0)$ doesn't appear to be in any of these cosets. Maybe the answer I'm being told is wrong.