I have two creatures and barrage of expendables on the battlefield. My opponent casts a spell with the effect: "Each opponent sacrifices a creature" Can I choose to sacrifice creature 1, then before my opponent's spell resolves, sacrifice creature 1 as the cost for barrage of expendables, thus resulting in only having lost creature 1?
Say I have a Zombie token, , and  on the battlefield. Can I sacrifice the Zombie token to activate both the Altar's and Seer's abilities?  Similarly, if I have one card in hand, and  and  on the battlefield can I discard the one card to both of their abilities?  If I have a  with 3 charge counters can I activate both of its abilities by tapping it to add a counter, and tapping it to remove 3 counters and destroy a permanent without untapping it in between?
Why are the orbits of planets in the Solar System nearly circular? Except for Mercury, the planets in the Solar System .  Is this property special to the Solar System?  :     Most exoplanets with orbital periods of 20 days or less have near-circular orbits of very low eccentricity. That is believed to be due to tidal circularization, an effect in which the gravitational interaction between two bodies gradually reduces their orbital eccentricity. By contrast, most known exoplanets with longer orbital periods have quite eccentric orbits. (As of July 2010, 55% of such exoplanets have eccentricities greater than 0.2 while 17% have eccentricities greater than 0.5.) This is not an observational selection effect, since a planet can be detected about equally well regardless of the eccentricity of its orbit. The prevalence of elliptical orbits is a major puzzle, since current theories of planetary formation strongly suggest planets should form with circular (that is, non-eccentric) orbits.   What is special about the Solar System that orbits of planets here are nearly circular, but elsewhere they are moderately or highly eccentric? I am trying to use Stack Exchange Andoid App to use my accounts in Stack Overflow &amp; Area 51.   For the Area 51, there is only Area 51 Discussion. Even Area 51 Discussion isn't working in the App!   VERSION 1.0.51  When adding this site, it's showing the correct full name as in this screen-shot:     However, when I pin this site to my fav sites in Stack Exchange, it is showing: Unknown Site. When clicking it, it shows black screen then just quit the App!  Here is the screen-shot:       Is the site not yet capable with Android? or is it a bug in the App itself?  PS: this question isn't duplicate:   In the previous versions of the App, the site was opening but with Unknown Site name. However, in this version, it quits the app when pressing the area site! It isn't opening at all! This question is also to track this bug in the App. As it's about the site name issue &amp; the content as well. If $A,B,C$ are matrices I am thinking how to show that $$ A(B + C) = AB + AC$$  Is possible to show without sums like $\sum_i a_i, ..., \sum_j b_j$? It seems if I do the proof with many indexes then is tedious and I don't learn much from it. Why is Newton's method not widely used in machine learning? This is something that has been bugging me for a while, and I couldn't find any satisfactory answers online, so here goes:  After reviewing a set of lectures on convex optimization, Newton's method seems to be a far superior algorithm than gradient descent to find globally optimal solutions, because Newton's method can provide a guarantee for its solution, it's affine invariant, and most of all it converges in far fewer steps. Why is second-order optimization algorithms, such as Newton's method not as widely used as stochastic gradient descent in machine learning problems? How can I minimise the time to get a new UK passport? shade plane with a color function color(x,y) Why is $a^{-1}$ mod $p$ equal to $a^{p-2}$ mod $p$ in modular arithmetic? How do I alter a language item link? I am looking to modify the default output of Drupal 8 of links in a certain situation, the language switcher. Ideally I want to be able to do that in a twig template and not have to produce a  that overwwrites that whole link generation system and add a BIG if for the cases I need to overwrite.  I think the output layout should be controllable in the twig template similar to  (this answer outputs the same url for every languages)  I am using bootstrap as a base theme so i'd like to use the bootstrap markup for my links (btn btn-primary, dropdown)  Here is my code I am trying to make links--language-block.html.twig  {%- if links|length == 2 -%}     {# show only alternate language button #}     {%- for key, item in links -%}         {%- if not item.attributes['#options']['set_active_class'] -%} {# &lt;--- this is always true!? #}             &lt;a href="{{ item.link['#url'] }}" class="btn btn-primary"&gt;{{ item.link['#title'] }}&lt;/a&gt; {# #url is always the same what ever the language it is pointing to! #}         {%- endif -%}     {%- endfor -%} {%- elseif links|length &gt; 2  -%}     {# show selected language in button and other languages in drop down #}     &lt;button class="btn btn-primary dropdown-toggle" type="button" data-toggle="dropdown"&gt;{{ selectedLanguage }}&lt;span class="caret"&gt;&lt;/span&gt;&lt;/button&gt;     &lt;ul class="dropdown-menu"&gt;         {% for key, item in links %}             {%- if not item.attributes['#options']['set_active_class'] -%} {# &lt;--- this is always true!? #}             &lt;li&gt;&lt;a href="{{ item.link['#url'] }}"&gt;{{ item.link['#title'] }}&lt;/a&gt;&lt;/li&gt;             {% endif %}         {% endfor %}     &lt;/ul&gt; {%- endif -%}   Anyone has an idea on how to do this? Is adjoint of singular matrix singular? What would be its rank? Let $A$ be a square and singular matrix of order $n$.  Is $\operatorname{adj}(A)$ necessarily singular? What would be the rank of $\operatorname{adj}(A)$? Seems that I just proved $2=4$. Post Link for Tag Info Wiki's display text should be better than "unknown" The displayed text for a [Post Link] where the underlying Id corresponds to a Tag/Info Wiki (where the link redirects successfully) is just &quot;unknown&quot;. For example, if you've ever edited a tag wiki: . It would be nice if this could be better identified. Creating a copy of primary database and attaching the copy database in the same sql instance I just got into a project in which we have only one SQL Server 2012 copy. We have 12 databases attached to the primary instance of SQL Server 2012.  As I don't have SQL Server 2012 or supporting OS, I have to depend on the primary instance of SQL Server 2012.  I am not sure whether it is good to create copy/clone of all 12 databases and attach it to same instance and work on the copy for data manipulation and query testing purpose.  Based on Kin's query  SELECT    SERVERPROPERTY ('MachineName') AS PhysicalMachineName,    SERVERPROPERTY ('ServerName') AS SQLServerName,    SERVERPROPERTY ('Edition') AS ServerEdition,    CAST(SUBSTRING(@@Version,charindex('SQL',@@version, 1),15) AS VARCHAR(255)) +  ' + '         + CAST (SERVERPROPERTY ('productlevel')AS VARCHAR (50)) + ' + (Build'        + CAST (SERVERPROPERTY ('ProductVersion') AS VARCHAR (50)) +')' AS ProductVersion,     RIGHT(@@version, (Len(@@Version)-charindex('Windows',@@version, 1))+1) AS [O.S.],  SERVERPROPERTY ('Collation') AS Collation   Following is the output. I ignored PhysicalMachineName and SQLServerName.  ServerEdition : Business Intelligence Edition (64-bit) ProductVersion : SQL Server 2012 + RTM + (Build11.0.2100.60) O.S.           : Windows NT 6.1 &lt;X64&gt; (Build 7601: Service Pack 1)  Collation      : SQL_Latin1_General_CP1_CI_AS Show that $d_b(x,y)=\frac{d(x,y)}{1+d(x,y)}$ is a metric. where $(X,d)$ is a metric and $x,y \in X$.  I know we need to show:   non-negativity: $d(x,y)\geq$ 0 $d(x,y)=0$ if and only if $x=y$ symmetry: $d(x,y)=d(y,x)$ $d(x,z)\leq d(x,y) + d(y,z)$   I think we need to consider the derivative of $f(t)=\frac{t}{1+t}$ however I am not sure what to do next. RGB and CMYK: Why both? Any of you who have at least little experience with graphic design software, photography or professional printing, must have -almost undoubtedly- have gone through this: 'the struggle' of RGB and CMYK colour spaces.  Now, there are many questions regarding matters of 'which should I choose', 'what is what' and converting problems, but that's not really what I'm after here.  As a graphic designer with only a couple of years of experience, I still have this struggle from time, and find the whole CMYK/RGB choosing/converting/saving situation quite confusing, to say the least. I do know that RGB is meant for digital end purposes, and CMYK is suitable for printing.  I have always been wondering about the neccesity of this whole thing. So, my question is: why are there these two colour profiles, instead of just having one?   Wouldn't it be a lot easier if printers or software could convert any RGB file to a CMYK printing document instead? I'm pretty sure it does already exist, by the way, because printing an RGB file sometimes simply prints the right colours for me. Alas, not always (doesn't seem to be related to the printer of software I print from).    I have gone trough some RGB vs. CMYK-related questions and found this, a.o., (), an answer of user DKuntz2 (thanks DKuntz2):     RGB is a light-based theory. All colors begin with black "darkness",   to which different color "lights" are added to produce visible colors.   RGB "maxes" at white, which is the equivalent of having all "lights"   on at full brightness (red, green, blue).      CMYK is a color-based theory. All colors start with white "paper", to   which different color "inks" are added to produce output colors. CMYK   "maxes" at black, at which point all "inks" are applied at 100% (cyan,   magenta, yellow, black).   Not sure if this is entirely right, though, because some people disagreed with DKuntz2:     I disagree. With RGB you start with black - the absence of light; with   CMYK you start with white paper.   – e100  Although this does clarify the differences fairly well, I still don't see the point of the two colour profiles(/spaces)    Side question: What happens when you work in an RGB document in photoshop, then press ctrl+y? Photoshop says the document is RGB/8/CMYK, but it can't be both. Right?  EDIT:  Big thanks for the answers, the (current) three below are very informative and interesting. I understand the whole thing a bit better, although it's all very complicated and in-depth to me. Especially when I read about terms like colour models, colour profiles, colour spaces, colour spectra and gamut all one after another.  As much as I would like to accept an answer as the desired one, I feel that my question in the core isn't fully answered yet. What I would really like to emphasize is what I asked about earlier: Wouldn't it be a lot easier if printers or software could convert any RGB file to a CMYK printing document instead?. As Alan Gilbertson explained, the reason is - if I understand correctly - basically a 'lost-in-translation' thing that makes the conversion not 100% accurate, and the colours to possibly be a bit distorted.  However, I still don't see how the solution cannot be an automated conversion done by a printer. Should be possible with modern technology; if you can convert RGB to CMYK in Photoshop, why can't a printer do the exact same for you? As was also said in the answers, the slightest differences in colours and colour spaces, can not be seen by the human eye. And that's what it all comes down to: what we want to see. Be it on a screen or on a sheet of paper.  The fact that this question has three very long answers, or even moreso the fact that there are so many questions about these two colour models (I now know the right term, yay) kind of proves that this is way more complicated than it should be. Can a creature with blindsight that is not immune to the Blinded condition suffer the effects of Blindness? Programming language books explain that value types are created on the stack, and reference types are created on the heap, without explaining what these two things are. I haven't read a clear explanation of this.  I understand what a stack is. But,    Where and what are they (physically in a real computer's memory)? To what extent are they controlled by the OS or language run-time? What is their scope? What determines the size of each of them? What makes one faster? I'm trying to create a join/relate in QGIS where I have a shapefile of buildings and to that I would like to join a non-spatial table (.csv-file) containing people who work in each building. So I have multiple records in my table that I would like to be able to join to my single features in my shapefile. I can only run a join in QGIS where the first record is joined to the shapefile feature (ie building) but subsequent records get removed. Could someone let me know how to complete this join/relate in QGIS? How do I add .e00 data into my QGIS project? Short story (maybe two in the same collection) about Alien education versus Earth I read this somewhere in the 1990s, but it was probably older. I vaguely remember it as being two stories in sequence in an anthology. One was a story involving an Earth administrator comparing Earth curriculum to Mars curriculum and the second was just a class listing for Martian curriculum.  In the first story, what sticks out in my head was the Earth administrator proudly claiming some high value of WPM for reading for his students and the Martian admitting that their rate was lower, and then added a comment along the lines of that the Martian students, when reading at the rate attained at Earth, could not recall every word of the book and recite them back verbatim. In the curriculum listing, I remember that the physical education classes included Tightrope Walking and Advanced Tightrope Walking. In short, the implication was that Mars held its children, and therefore its citizens, to much higher standards, at the cost of sacrificing actual childhood. The children never played, just studied and drilled.  In retrospect, it might not have been Mars... I know one side was Earth and the other was a planet in the Solar System, and Mars sounds about right, but so does Venus. Either way, it was the casual arrogance of the extra-terrestrial society and the blustering attempts of the Earth administrator that stuck out for me. How to Solve this Arithmetic Progression Question? Please help-  Four different integers form an increasing AP.One of these numbers is equal to the sum of the squares of the other three numbers.Then- find all the four numbers.  I assumed the numbers to be $a,a+d,a+2d,a+3d$ and wlog let $a+3d$ this number and according to question-  $a^2+(a+d)^2+(a+2d)^2=a+3d$  but I could not solve the above equation.