Running Kubuntu 18.04.  I created a bootable USB using KDE Partition Manager and a Ubuntu Gnome ISO file.   It contains boot, casper, etc. folders.  But when I reboot with this USB drive attached, it is not shown as a boot option.   How do I boot using this drive?
This is the third time I've tried to install Ubuntu Server 14.04.03 64-bit on the same laptop, and each time it caused different problems.  Each time I wrote the same iso image to a USB flash drive by using a different application and OS.   Universal USB Installer (pendrivelinux.com) from Windows WinImage writer from Windows built-in image writer from Linux Mint 17.2    The iso image is the same in all three cases, the USB flash drive is the same, and the laptop is the same. However each time the installation of Ubuntu gave me different installation options. For example, the last time I installed Ubuntu, it didn't show all the packages to choose while installing (Basic Ubuntu server, etc.).
Why does kinetic energy increase quadratically, not linearly, with speed? As  says:     [...] the kinetic energy of a non-rotating object of mass $m$ traveling at a speed $v$ is $\frac{1}{2}mv^2$.   Why does this not increase linearly with speed? Why does it take so much more energy to go from $1\ \mathrm{m/s}$ to $2\ \mathrm{m/s}$ than it does to go from $0\ \mathrm{m/s}$ to $1\ \mathrm{m/s}$?  My intuition is wrong here, please help it out! How do I change the plymouth bootscreen? With regards to Plymouth --  Are there alternative boot screens available?  What's the easiest way to change the boot screen? I'm calling a function in Python which I know may stall and force me to restart the script.   How do I call the function or what do I wrap it in so that if it takes longer than 5 seconds the script cancels it and does something else? Closed form solution for slope coefficients in bivariate regression In a univariate regression, $Y=a+bX+e$, the solution for slope b is given by $COV(X,Y)/VAR(X)$.  Is there a similar expression for a bivariate regression $Y=a+bX+cZ+e$. What is the closed form solution for b and c in this case? I applied for a 90-day visa and got a long-term visit, single-entry tourist visa. The date given is 09-March-2015, and it's valid until 07-May-2015.  My agent says the 7th is the latest date I can travel to Dubai; once I enter I need to count 90 days. I entered on the 10th of March.    Is it true, or where can I get it checked?    Can I stay for another month, or do I need to leave before the 7th of May? Effect on loading a DC motor - load torque Could someone give a (detailed) explanation (perhaps with formulas) of how the load (torque) affects the armature current of a DC motor (separately excited or shunt or series)?  As the load torque increases the speed of the motor decreases, and assuming the terminal voltage stays constant, the EMF will become lower and thus the armature current will increase.  But could someone give me the formula that shows the relation between load torque and armature current?  Is it something like:   \$T_\text{developed} = T_\text{shaft} + T_\text{friction windage} + T_\text{load}\$ ,   where \$T_\text{developed} = K \, \text{flux}_\text{pole} \,I_\text{armature}\$ ?  But then you have  \$P_d = P_s + P_{f_w} + P_l   \$  where \$P_d = K \,\text{flux}_\text{pole}\, I_\text{armature}  \,\omega_m\$  In the last formula you can't see that as the increase due to \$P_\text{load }\$ the armature current increases because maybe someone can say the speed \$\omega_m\$ increases.  And how come at no-load the armature current and thus the torque developed is zero? Is it really zero, or do I have to assume there is some current flowing?  Could also explain me the principle of torque developed. Because at no load, the shaft torque is equal to torque developed, right? Delete the entire table rendered from different pages using Javascript How to inset a face? I am trying to set up a Minecraft rig mouth that will have more controls and will be rounded, but I am having issues trying to figure out what this guy did here. First, he did what looked like a loop cut and slide, but instead of drawing a line it selected all the edges it passed through. He then cut to a new clip where the mouth was already set up like this.    The video is in 3 times speed but if you download a youtube plugin you can slow it down to 0.25 speed of the video and then if you do the spacebar trick you can slow it down so it shows 1 frame at a time and it is really slow.  if you want or need to see the video.  All I am asking is how can I create those 8 basic segments. "POSSIBLE BREAK-IN ATTEMPT!" in /var/log/secure — what does this mean? I've got a CentOS 5.x box running on a VPS platform. My VPS host misinterpreted a support inquiry I had about connectivity and effectively flushed some iptables rules.  This resulted in ssh listening on the standard port and acknowledging port connectivity tests. Annoying.   The good news is that I require SSH Authorized keys.  As far as I can tell, I don't think there was any successful breach.  I'm still very concerned about what I'm seeing in /var/log/secure though:     Apr 10 06:39:27 echo sshd[22297]: reverse mapping checking getaddrinfo for 222-237-78-139.tongkni.co.kr failed - POSSIBLE BREAK-IN ATTEMPT! Apr 10 13:39:27 echo sshd[22298]: Received disconnect from 222.237.78.139: 11: Bye Bye Apr 10 06:39:31 echo sshd[22324]: Invalid user edu1 from 222.237.78.139 Apr 10 06:39:31 echo sshd[22324]: reverse mapping checking getaddrinfo for 222-237-78-139.tongkni.co.kr failed - POSSIBLE BREAK-IN ATTEMPT! Apr 10 13:39:31 echo sshd[22330]: input_userauth_request: invalid user edu1 Apr 10 13:39:31 echo sshd[22330]: Received disconnect from 222.237.78.139: 11: Bye Bye Apr 10 06:39:35 echo sshd[22336]: Invalid user test1 from 222.237.78.139 Apr 10 06:39:35 echo sshd[22336]: reverse mapping checking getaddrinfo for 222-237-78-139.tongkni.co.kr failed - POSSIBLE BREAK-IN ATTEMPT! Apr 10 13:39:35 echo sshd[22338]: input_userauth_request: invalid user test1 Apr 10 13:39:35 echo sshd[22338]: Received disconnect from 222.237.78.139: 11: Bye Bye Apr 10 06:39:39 echo sshd[22377]: Invalid user test from 222.237.78.139 Apr 10 06:39:39 echo sshd[22377]: reverse mapping checking getaddrinfo for 222-237-78-139.tongkni.co.kr failed - POSSIBLE BREAK-IN ATTEMPT! Apr 10 13:39:39 echo sshd[22378]: input_userauth_request: invalid user test Apr 10 13:39:39 echo sshd[22378]: Received disconnect from 222.237.78.139: 11: Bye Bye     What exactly does "POSSIBLE BREAK-IN ATTEMPT" mean?  That it was successful? Or that it didn't like the IP the request was coming from? Why are the United States often referred to as America? What's the main difference between int.Parse() and Convert.ToInt32 surjective immersion $\mathbb{R}^2 \to \mathbb{R}^2$ which is not a diffeomorphism Does there exist a surjective immersion $\mathbb{R}^2 \to \mathbb{R}^2$ which is not a diffeomorphism?  I tried to modify $\exp: \mathbb{C} \to \mathbb{C}$ to be surjective, but I find it hard to preserve the property of being immersion.  I also noticed that if we replace $\mathbb{R}^2$ with $S^2$ or any other compact simply connected manifold, no such immersion exists, because then it would be a covering map (as a local diffeomorphism from compact space, thus proper), but since the manifold is simply connected, it must be a diffeomorphism. So what I decided to do is to start a small case with only 3 people. There are three possible combinations that I could pair up the people, using the symbols A, B, and C to represent the persons involved: A&amp;B, A&amp;C, B&amp;C. The probability of each pair having the same birthday is $1\over365$ (the first guy gets any birthday, and the second guy only gets one birthday to choose from). What my intuition directed me to do next is to find the probability that any of the three events are true, or the union of the three events, which involved adding up the probabilities.   To put this generally, the equation for the probability SHOULD be:  ${n \choose 2} \div 365$  However, clearly this is not the case since $n \choose 2$ gets over 365 when $n = 28$. And with 28 people, there is obviously still a chance that they all have different birthdays (Person 1 has Jan. 1, Person 2 has Jan. 2. ... Person 28 has Jan. 28). Could anyone tell me what's wrong with my intuition? I don't want to know what's the right solution, I just want to know what's wrong with my solution .. it makes sense to my intuition, even though it's incorrect. I have backups up everything, but I'm still uneasy about the process and would like confirmation. I'd rather do this one time correctly. I want to shrink /dev/sda6/ by 200GB and reallocate it to /dev/sda2. I boot a LiveCD and turn off LinuxSwap (locked otherwise). I've been reading that it is very hard to move &quot;left&quot; when partitioning and other AskUbuntu threads are confusing me. Do I need to resize /dev/sda6 by 200GB &quot;preceding&quot; (rather than &quot;following&quot;), and then resize /dev/sda4 by 200GB? A little guidance would ease my nerves of messing everything up. Thank you ahead of time. Proof of linear independence of $e^{at}$ Given $\left\{ a_{i}\right\} _{i=0}^{n}\subset\mathbb{R}$ which are distinct, show that $\left\{ e^{a_{i}t}\right\} \subset C^{0}\left(\mathbb{R},\mathbb{R}\right)$,  form a linearly independent set of functions.   Any tips on how to go about this proof. I tried a working from the definition of an exponential and combining sums but that didn't seem to get me anywhere. I saw a tip on the internet that said write it in the form  $\mu_{1}e^{a_{1}t}+\dots+\mu_{n}e^{a_{n}t}=0$ to try to show $\mu_{1}=\dots=\mu_{n}=0$ considering each term of the left hand side must be positive, but I can't get my head around that because while I understand $e^{x}&gt;0\forall x\in\mathbb{R}$ I cannot see why $\mu_{i}$ must be positive in any case. I have thought about differentiating but that doesn't seem to help. The question did originally ask for a "rigourous" proof but I'll take any hints right now and the provided the solution of 'is obvious' is most unhelpful to me.  Any input would be fantastic. Thank you. youtube-dl unable to download audio how to resolve that issue? All I remember is the guy was sent to a planet to test something or he did something illegal, and time moved really fast on the planet but slow to the outside world. He had to fix something to leave the planet I think. His dad was also dying and he checked how many days he had left every day, but in the end his dad didn't actually die as time was fast. It took place on a sandy planet. Assuming i have a line that i want to add to a file without opening an editor.  How could i append this line  alias list='ls -cl --group-directories-first'   to this file  config.fish Distribution of range of Uniform $(0,1)$ distribution Let $X_1,...,X_n$ be iid as $U \sim [0,1]$ with pdf $f(x) = 1(0 &lt;x&lt; 1)$. Determine the range distribution.   I have managed to determine the distribution of the minimum and the maximum, however I cannot/do not know how to determine the distribution of range.   Minimum:  $f_N = n(1-x)^{n-1}$ and maximum $f_M= nx^{n-1}$   I am aware that the calculation of range distribution is based on convolution: $f_R=\int f_{N,M}(x,x-r)dx$, However I cannot get the correct result, which according to my lecture slides is : $f_R= n(n-1)r^{n-2}(1-r)$  Could someone break this down for me ? My math background is not great How did the Tesseract come to Earth from Asgard?