I need to bypass or find a way to make a zte prestige w/o sim card boost (mobile) into a wifi phone or a phone that can at the very least connect to wifi for internet. it will connect to wifi but it wont open anything so there's no way to get internet or get to a browser because of FRP Google Lock. Anyone know how I can use the internet at the very least and/or bypass the google frp or get internet browsing capabilities? Thank you, appreciate any help.
I won a Samsung Galaxy S6 Edge, signed into it with my Google account, played around with it, wiped it, and sold it.  Now the person can't get past setup because it's saying he must login with an account previously synced to the phone.   Is there anything I can do from my side to remove this lock?
How to download packages from a command-line given repository? It is not about the common download &amp; install thing, what apt (aptitude, etc) does, it is a scripted download a package file.  I found the dget tool for this task, which works quite well. But, unfortunately, it doesn't have any option to specify a different repository URL as it is given in the /etc/apt/sources.list.  Is it somehow possible? Actually, a dget-like functionality would be the best, but where I can also specify the repo URL.    P.s. thank you very much the scripts, but I would like to prefer a debian tool for this very simple task. It will be part of a buildscript, for external usage, and any unneeded complexity has intolerable collateral costs. It must be done by a debian tool.  P.s.2. Finally I solved this with updating the system-wide repos, and downloading the packages with dget. Thank you very much the scripts! Does the sign of scores or of loadings in PCA or FA have a meaning? May I reverse the sign? I performed principal component analysis (PCA) with R using two different functions (prcomp and princomp) and observed that the PCA scores differed in sign. How can it be?  Consider this:  set.seed(999) prcomp(data.frame(1:10,rnorm(10)))$x              PC1        PC2  [1,] -4.508620 -0.2567655  [2,] -3.373772 -1.1369417  [3,] -2.679669  1.0903445  [4,] -1.615837  0.7108631  [5,] -0.548879  0.3093389  [6,]  0.481756  0.1639112  [7,]  1.656178 -0.9952875  [8,]  2.560345 -0.2490548  [9,]  3.508442  0.1874520 [10,]  4.520055  0.1761397  set.seed(999) princomp(data.frame(1:10,rnorm(10)))$scores          Comp.1     Comp.2  [1,]  4.508620  0.2567655  [2,]  3.373772  1.1369417  [3,]  2.679669 -1.0903445  [4,]  1.615837 -0.7108631  [5,]  0.548879 -0.3093389  [6,] -0.481756 -0.1639112  [7,] -1.656178  0.9952875  [8,] -2.560345  0.2490548  [9,] -3.508442 -0.1874520 [10,] -4.520055 -0.1761397   Why do the signs (+/-) differ for the two analyses? If I was then using principal components PC1 and PC2 as predictors in a regression, i.e. lm(y ~ PC1 + PC2), this would completely change my understanding of the effect of the two variables on y depending on which method I used! How could I then say that PC1 has e.g. a positive effect on y and PC2 has e.g. a negative effect on y?    In addition: If the sign of PCA components is meaningless, is this true for factor analysis (FA) as well? Is it acceptable to flip (reverse) the sign of individual PCA/FA component scores (or of loadings, as a column of loading matrix)? I am trying to find the formula for the number $f(n,k)$ which is defined as the number of $k$-subsets of $[n]$ in which no two elements are consecutive numbers in $[n]$.  From the simple thinking I had made up following recursion:  $$f(n,k) = f(n-1,k) + f(n-2, k-1) $$  This is true since I can construct without last element of $[n]$ then make up $k$-subsets, then otherwise must contain the last element of $[n]$ then construct remaining $k-1$ elements among $[n-2]$ since with the last one, I can't use $n-1$.  However, I had never learned any techniques regarding changing those recursion into a well-summarized formula in terms of $n$ and $k$.  Any guidance would be appreciate. I am looking for a list of all English words that are their own antonyms. Off the top of my head, I can only think of "either", "fast", "to dust" and "to lease", but there must be dozens more. Can you provide a link to a comprehensive list, if such exists?  Also, what are such words most commonly called? I like the term "Janus word" I once heard, but is that widely understood?  Edited by popular demand to make it absolutely clear that this is not a community wiki poll. Is there any built-in way to get the length of an iterable in python? For example, files, in Python, are iterable - they iterate over the lines in the file. I want to count the number of lines.   One quick way is to do this:  lines = len(list(open(fname)))   However, this loads the whole file into memory (at once). This rather defeats the purpose of an iterator (which only needs to keep the current line in memory).  This doesn't work:  lines = len(line for line in open(fname))   as generators don't have a length.  Is there any way to do this short of defining a count function?  def count(i):     c = 0     for el in i: c += 1     return c   To clarify, I understand that the whole file will have to be read! I just don't want it in memory all at once I would like to automate some services using cron jobs.  When I try to edit the crontab file at /etc/crontab, I am not able to save it as it says that it is read only.   What can I do? Maximum Likelihood Estimate with different parameters Finding $\int^{\infty}_{0}\frac{\ln^2(x)}{(1-x^2)^2} dx$ Calculate  $$\int^{\infty}_{0}\frac{\ln^2(x)}{(1-x^2)^2}dx$$   I have tried to put $\displaystyle x=\frac{1}{t}$ and $\displaystyle dx=-\frac{1}{t^2}dt$  $$ \int^{\infty}_{0}\frac{t^2\ln^2(t)}{(t^2-1)^2}dt$$  $$\frac{1}{2}\int^{\infty}_{0}t\ln^2(t)\frac{2t}{(t^2-1)^2}dt$$  $$ \frac{1}{2}\bigg[-t\ln^2(t)\frac{1}{t^2-1}+\int^{\infty}_{0}\frac{\ln^2(t)}{t^2-1}+2\int^{\infty}_{0}\frac{\ln(t)}{t^2-1}dt\bigg]$$  How can I solve it? Calculating the limit $\lim((n!)^{1/n})$ Find $\lim_{n\to\infty} ((n!)^{1/n})$. The question seemed rather simple at first, and then I realized I was not sure how to properly deal with this at all. My attempt: take the logarithm,  $$\lim_{n\to\infty} \ln((n!)^{1/n}) =  \lim_{n\to\infty} (1/n)\ln(n!) =  \lim_{n\to\infty} (\ln(n!)/n)$$ Applying L'hopital's rule:  $$\lim_{n\to\infty} [n! (-\gamma + \sum(1/k))]/n! = \lim_{n\to\infty} (-\gamma + \sum(1/k))=  \lim_{n\to\infty} (-(\lim(\sum(1/k) - \ln(n)) + \sum(1/k))  = \lim_{n\to\infty} (\ln(n) + \sum(1/k)-\sum(1/k)  = \lim_{n\to\infty} (\ln(n))$$ I proceeded to expand the $\ln(n)$ out into Maclaurin form $$\lim_{n\to\infty} (n + (n^2/2)+...) = \infty$$ Since I $\ln$'ed in the beginning, I proceeded to e the infinity  $$= e^\infty  = \infty$$  So am I write in how I approached this or am I just not on the right track? I know it diverges, I was just wanted to try my best to explicitly show it. How to install and use Ubuntu from a USB flash drive on Windows 8? I made a hair particle system and set the Dupli Group to a group of 3 objects. Each of the 3 objects has:   it's origin set to be touching the XY plane (on layer 2) it's Scale applied to 1 and it's Rotation applied to 0     I am trying to get each of the objects to sit directly on top of the ground, but instead, they are centered in the plane, half above the plane and half below the plane:      What am I doing wrong? Here is . Get selected value in dropdown list using JavaScript Automating "Stay Awake" I use my personal Android smartphone for development. Every morning, I go to Settings \ Developer Options \ Stay Awake and check the box.  At the end of the day, I uncheck the box — since otherwise any notification (including the "fully charged" one) will trigger the screen on, and it will stay on from that point on.  How can these two operations be automated? Delete commits from a branch in Git I recall having heard somewhere that the only 1-manifolds (second countable, Hausdorff, connected spaces locally homeomorphic to $\mathbb R$) are $\mathbb R$ and $S^1$. Is this true? If so, is there a reasonably elementary proof? Identify GoogleTv from Android app Comma use with nonessential appositives Sorry, I do not know the language terminology. Is this a case of nonessential appositive?  Which of the following sentence has a correct comma use? Comma before &quot;should&quot;  Importantly, two frail subgroups of stroke population, long-term residential care and cognitive impairment patients, should not be excluded from the rehabilitation.  No comma before &quot;should&quot;  Importantly, two frail subgroups of stroke population, long-term residential care and cognitive impairment patients should not be excluded from the rehabilitation. Getting secondary citations right I have some questions regarding secondary citations (in an computer-science research paper that should be published in a journal). I know that they should be avoided when possible, but it is not always that easy. More specifically, my situation is this:  Article A says:     The average value of ... in ... is ... [B]. [C]’s study says that in ... the value is ...   This statement is exactly what i need for my paper. If I read [B] and [C], I see that [A] cited them correctly and if I would have found these two other articles myself, I would have written the same.  Now how to cite this in a correct way?      [B] and [C] say (cited in [A]) ...   and do a “bad” secondary quote;    [B] and [C] say ...   and neglect the investigation done by [A] and peform citation plagiarism;    [A] says ...   and neglect that the data was the achievement of [B] and [C].    [A] says based on the findings of [B] and [C] ...   and do a secondary quote again. What's the fixed size of the suggested edit queue? "Delete this answered question?" when the only answer is deleted Looks like there's a small bug in the UI: I posted a question here on meta.SE which ended up being just something dumb I was doing and no use to anyone in the future. At first I posted an answer saying what the dumb thing was, but then I realized that the whole thing had no value, so I deleted the answer, and then deleted the question — whereupon it asked me:  Delete this answered question? We do not recommend deleting questions with answers because doing so deprives future readers of this knowledge. Repeated deletion of answered questions can result in your account being blocked from asking. Are you sure you wish to delete?  (Screenshot below) Probably shouldn't ask (or add to the tally) if the only answers are deleted ones...