Is there a way that we can find an optimum tree (highly accurate) from a random forest?   The purpose is to run some samples manually through the optimum tree and see how the tree classify the given sample.   I am using Scikit-learn for data analysis and my model has ~100 trees. Is it possible to find out an optimum tree and run some samples manually?  Thanks
I am using scikit learn  to build a Random Forest classifier.  I have heard that it might be possible to build a single decision tree from a Random  Forest. The suggestion  is that although the decision tree may not be as good a classifier as the Random Forest it may be better than the decision tree you would get by using the standard method.  However I haven't been able to find this method online. Does it exist?     My question is not about extracting one  of the decision trees from a Random Forest. It is asking about a method to construct a new decision tree from the whole Random Forest, perhaps by combining the trees in the Random Forest somehow.
Limit of $\prod\limits_{k=2}^n\frac{k^3-1}{k^3+1}$ Calculate $$\lim_{n \to \infty} \frac{2^3-1}{2^3+1}\times \frac{3^3-1}{3^3+1}\times \cdots \times\frac{n^3-1}{n^3+1}$$ No idea how to even start. White screen of death: Fatal error: Allowed memory size of X bytes exhausted I have a issue with my Drupal installation, for example:   when I enable or disable the modules, It redirects me to a blank page, when I create a new content type and save it, redirects me to a blank page, when I add a new view and save it, it redirects me to a blank page, when I try to clear the cache, it redirects me back to a blank page, or in similar cases.   Basically all the confirmation pages redirect me to a white screen. When I refresh it again, it shows me the page. I tried to increase the PHP memory value but it doesn't help.  Are there any other solutions for this?  The error which I'm having:      Fatal error: Allowed memory size of 100663296 bytes exhausted (tried to allocate 8192 bytes) in sites/all/modules/views/plugins/views_plugin_localization_none.inc on line 1 Monitor cell value and copy it to another cell How do you reset the sa password? Given that $a$~$\mathcal{N}(\mu, \Sigma)$ and $\mu$~$\mathcal{N}(0, \sigma^2 I)$, Is $p(a|\Sigma, \sigma)=\int p(a|\mu, \Sigma)p(\mu|\sigma)d\mu$ again a Normal distribution? And how to estimate the mean and variance respectively? Thanks a lot! Short Story/Novella in Which People Living in What they Think is Small Town Fifties America Find Look Magazine and Don't Recognize Anything in It This is probably from the mid-to-late fifties.  It involved families living in what seemed to be normal, small town America of the time.  But two boys found in a garbage dump or in a nearby landfill a copy of "LOOK" magazine from their time period (1955? 1957?).  Their problem was that they and their families didn't recognize any of the people or events that were reported in the magazine.    The tone of the articles in the magazine matched their actual lives in that the magazine reported world events, trouble spots, celebrities, politics, and had advertisements for cigarettes and TVs, etc. but the facts were completely different. I think the magazine was a magazine from 'real' America and they were living in a 'fake' America, i.e., they had been brought up in a separate isolated environment with everything different but now had found something from the 'real' world. The tone of the story was that they were never supposed to know about any of this. Maybe, just maybe, part of it was a story about Marilyn Monroe but none of the people had ever heard of her. I can't remember much more than that but I have a nagging thought that they were part of some controlled environment experiment by the US Military. I'm stuck with this integral  $\int\frac {\cos^4x}{\sin^3x} dx$    which I rewrote as  $\int \csc^3x \cos^4xdx$  then after using the half angle formula twice for $\cos^4x$ I got this  $\frac 14\int \csc^3x (1+\cos(2x))(1+\cos(2x))dx$   then after solving those products I got these integrals  $\frac 14 \{\int \csc^3xdx+2\int \csc^3x \cos(2x)dx + \int \csc^3x \cos^2(2x)dx\}$  I do know how to solve the $\int \csc^3xdx$ one but I'm totally lost on the other ones, any tips/help/advice would be highly appreciated! thanks in advance guys! How to import a module given the full path? How can I load a Python module given its full path? Note that the file can be anywhere in the filesystem, as it is a configuration option. Elementary derivation of certian identites related to the Riemannian Zeta function and the Euler-Mascheroni Constant Is the proof of these identities possible, only using elementary differential and integral calculus? If it is, can anyone direct me to the proofs? ( or give a hint for the solution )  1)$$\int_0^\infty { e^{-x^2} \ln x }\,dx = -\tfrac14(\gamma+2 \ln 2) \sqrt{\pi} $$  2)$$\int_0^\infty { e^{-x} \ln^2 x }\,dx = \gamma^2 + \frac{\pi^2}{6} $$  3) $$\gamma = \int_0^1 \frac{1}{1+x} \sum_{n=1}^\infty x^{2^n-1} \, dx$$  and lastly,  4) $$\zeta(s) = \frac{e^{(\log(2\pi)-1-\gamma/2)s}}{2(s-1)\Gamma(1+s/2)} \prod_\rho \left(1 - \frac{s}{\rho} \right) e^{s/\rho}\!$$  I personally think the last is obtained from a simple use of the Weierstrass factorization theorem. I'm unsure as to what substitution is used.  $\gamma$ is the Euler-Mascheroni constant and $\zeta(s)$ is the Riemannian Zeta function.  Thanks in advance. Under what circumstances can the word "be" be used directly without any change? Possible Duplicate:          2 examples first:  1.It is announced that the accounting class of the 3rd and 4th hours on the morning of this Wednesday be cancelled  2.It is expected that everybody and each household be on guard  Someone told me this kind of examples above appears in the textbook as strict sentences to be taught in the classroom, so is that right for the usage of be  Meantime I looked up the word be at thefreedictionary.com and found one piece of interpretation says :      Archaic Used with the past participle of certain intransitive verbs to   form the perfect tense: "Where be those roses gone which sweetened so   our eyes?" (Philip Sidney).   So is there any connection between the archaic usage &amp; the examples above? BTW, how to understand the short phrase "the 3rd and 4th hours". Many thanks! I am being flown out by a company for an on-site visit. Will I earn miles for this trip, or will the company? Is there any formula for number of divisors of $a \times b$? Let $a$ and $b$ be two numbers,    Number of divisors of $a$ is $n_1$; Number of divisors of $b$ is $n_2$;    How to find the number of divisors $N$ of product $a \times b$ by using known number of divisors of factors $n_1$ and $n_2$?  If $a = 20$ and $b = 21$, then $n_1 = 6$ (number of divisors of $a$), $n_2 = 4$ (number of divisors of $b$. Then $a \times b = 420$ and $N = 32$ (number of divisors of $a \times b$).  Is there a formula to find $N$ in terms of $n_1$ and $n_2$? Is it consistent with ZF for there to exist a set $S$ such that the power set $P(S)$ is countable? If so, what is the weakest form of the axiom of choice needed to prove that no such set exists? I guess I can live with the fact that the  changes size drastically when he transforms, but why does his shirt rip off and not his pants?  I think that we need a little better answer than "it keeps us tied to the fact that inside he's still human". When $\operatorname{Hom}_{R}(M,N)$ is finitely generated as $\mathbb Z$-module or $R$-module? Assume that $M$ and $N$ are two finitely generated $R$-modules. Then $\operatorname{Hom}_{R}(M,N)$ is a finitely generated $\mathbb Z$-module and/or $R$-module (in this case, assume that $R$ is commutative)?   Note that $R$ is not Noetherian ring. Is there any counterexample (for any cases)? How can I play Pokémon GO without Internet? I downloaded Pokémon GO on my Samsung Galaxy Express and I can play it at home, but when I go outside I can't play because there is no Internet.  How can I play Pokémon GO without Internet outside? How do I scan for viruses with ClamAV? Is this correct? "One of the things that makes him great is..." ubuntu 18.04 LTS bluetooth [0cf3:3004] discovery not working I would like to migrate apps and their data from one phone to another without too much faffing around, like:   rooting (very convoluted device specific process with a lot of ambiguity around it and often involving running closed source software from random vendors that you have to believe does the right thing), using app specific backup export/import facilities if at all exist (too manual, seems the only option though).   I am ok with:   using a PC to help facilitate the process, manual copying/pasting files (within reason).   Ideally, I would like to have a process that works something like this:   select apps that I would like to have in their current state on the other phone, bundle them together and store somewhere (external SD card or PC), put that bundle on the other phone and somehow install and recover their state.   A bit like  works.  So far I have tried :    - unfortunately, like many others, requires rooting,  - seemed promising but Helium has never been, nor ever will be, compatible with any device running anything less than Android 4.0 and it does not work on certain phones.  - Q: Does it backup data of apps? A: No, currently it only backup the apk files of apps. and skimmed through a number of articles including  (looks like even if I was willing to root I would have a hard time).