What follows is a question wrapped in a word problem.   Facing an opponent attacking with an undefined, yet non-lethal, number of 1/1 tokens, I block one of them with . Once I am able to cast a spell during the Declare Blockers step, I cast  targeting my Seeker of the Way. (Recognizing Process trigger and lifelink gained.) Combat damage happens.  One damage is dealt to Seeker of the Way, triggering the Arcbond. Seeker of the Way deals 1 damage to each other creature, and each player. Lifelink causes me to gain life for each point of damage dealt.  Now, for the purposes of accounting +1/+1 counters gained by a , is the damage dealt by Seeker of the Way one blot of damage to the all the creatures, or separate spats of damage done to each creature? Would the Ajani's Pridemate gain one counter, because I've gained life, or multiple counters, because I've gained life multiple times?
Some cards in magic has something happen for each {something}. For instance:  makes you gain 2 life for each creature you control. Tapping  adds one green mana to your mana pool, and you gain 1 life for each non-land card revealed.  How is this life gained: all at once or "one bit" at a time? Say I tap Selvala and 1 land, and 2 non-lands are revealed: do I gain 2 life, or do I gain 1 life two times? Would  have one or two +1/+1 counters placed on it if I had it in play at that point?
I've been very into acoustics lately, specifically the harmonic series. I find it fascinating how the harmonic series works as a sort of guideline to harmony, and how we base tuning systems on trying to estimate the intervals from the harmonic series.  As you've probably gathered already, I know close to nothing about acoustics. But I would love an acoustic textbook that's suitable for dummies like myself. How does the drift velocity of electrons in a conductor depend on the temperature? How does the drift velocity of electrons in a conductor depend on the temperature?  I have two contradicting views for this.    First, we can say that increasing the temperature of the conductor will increase the kinetic energy of the electrons. Hence, their drift velocity should increase with increase in temperature.  Or, from the relation $v_d = \frac{eE}{m}T$ ($T$ is the relaxation time) we can say that the drift velocity is directly proportional to the relaxation time. Increasing the temperature will obviously decrease the relaxation time - as collisions will become more frequent - and thus decrease the drift velocity. Hence, an increase in the temperature will cause a decrease in the drift velocity.   So which view is correct? I'm running a VPS of a german provider and want to switch from Ubuntu to CentOS. There I tried to install firewalld (was not preinstalled), but it always fails with the error  ERROR: Failed to load nf_conntrack module: modprobe: ERROR: could not find module by name='nf_conntrack' modprobe: ERROR: could not insert 'nf_conntrack': Function not implemented modprobe: ERROR: Error running install command for nf_conntrack modprobe: ERROR: could not insert 'nf_conntrack': Operation not permitted   Obviously the nf_conntrack kernel module was not found. Since this is a VPS, I cannot tinker with the kernel modules. On the support site of my provider I found a list of available kernel modules, for example:  ip_conntrack_netbios_ns ipt_conntrack    ip_conntrack    ip_conntrack_ftp    ip_conntrack_irc   Since nf_conntrack is not listed here, does that mean, that I cannot use firewalld? Is it possible to run it without this module?  I guess I could use iptables, if I wanted to (it seems to run correctly). But as I have more experience with firewalld, I would like to stick with it.    CentOS Linux release 7.7.1908 (Core)  uname -a: Linux xxxxxx.xxxxxxxx.xxx 3.10.0-042stab140.1 #1 SMP Thu Aug 15 13:32:22 MSK 2019 x86_64 x86_64 x86_64 GNU/Linux Expressing $1.24\overline{123}=1.24\;123\;123\;123\;\ldots$ as the ratio of two integers Where can I get a device with 'Ubuntu for phones' pre-installed? Canonical has recently announced , which is Ubuntu with a specific interface for mobile devices.  Where can I get phones with this version of Ubuntu pre-installed? If no devices are available yet, where can I pre-order one? Is there a good Valgrind substitute for Windows? The website I'm working is allegedly going to have a massive hit rate soon after launch. The client is talking about the possibility  of around 2500 hits per second over a day or so.   Ignoring the fact that this hit rate is probably wild client optimism and apart from getting the largest servers possible, what is the best way that Drupal should be configured to support a large hit rate.  I've read Scaling the , ,  and many other pages, but what I'm looking for is real experience of doing this, what works, what doesn't, and what to expect. How can I quickly level up in World of Warcraft? I've been playing for months and I'm barely at level 40, while my classmates play less than I do and have multiple lvl 80 characters.  Is there a better way to level fast in World of Warcraft than just completing quests? No non-trivial clopen sets in $\mathbb{R}$? How to give a direct proof? How to give a direct proof of the following result?     Let $A$ be a subset of $\mathbb{R}$ such that $A$ is both open and closed. Then $A$ is either empty or all of $\mathbb{R}$?   My work:   If $A$ is not empty, let $u \in A$. Then there is some open interval $(a,b)$ such that $$u \in (a,b) \subset A.$$  Now if $\mathbb{R} - A$ is not empty either, then let $v \in \mathbb{R} - A$. Then there is some open interval $(c,d)$ such that  $$v \in (c,d) \subset \mathbb{R} - A.$$  Suppose that $u &lt; v$.   Since $$\emptyset \subset (a,b) \cap (c,d) \subset A \cap (\mathbb{R} - A) = \emptyset,$$ we must have $$(a,b) \cap (c,d) = \emptyset.$$ So we can conlclude that $$b \leq c.$$ But $b \in A$ and $c \in \mathbb{R} - A$. So we must have $$b &lt; c.$$  What next? Can anybody here please help complete the proof from here on?  An edit based on a comment by Marc Paul:   Let us assume that the set $A$ is a non-trivial clopen set in $\mathbb{R}$. Let us define a function $f \colon \mathbb{R} \to \mathbb{R}$ as follows:  $$f(x) \colon= \begin{cases} 1 \ \mbox{ for } \ x \in A; \\ 0 \ \mbox{ for } \ x \in \mathbb{R} - A. \end{cases}$$   Let $V$ be an open set in the range space $\mathbb{R}$. We show that the inverse image set $f^{-1}(V)$ is open in the domain space $\mathbb{R}$.   The following cases arise:   If $0, 1 \in V$, then $f^{-1}(V) = \mathbb{R}$.   If $0 \in V$ but $1 \not\in V$, then $f^{-1}(V) = \mathbb{R} - A$.   If $1 \in V$ but $0 \not\in V$, then $f^{-1}(V) = A$.   And, if $0 \not\in V$ and $1 \not\in V$, then $f^{-1}(V) = \emptyset$.   Thus, $f^{-1}(V)$ is open in the domain space $\mathbb{R}$.   Hence the function $f$ is continuous.   What next? How does this lead to our desired conclusion?   [Yet another edit, again based on valuable comments from Marc Paul: ]  So if both $A$ and $\mathbb{R} - A$ were non-empty, then let's suppose $a \in A$ and $b \in \mathbb{R} - A$, and we can assume without any loss of generality that $a &lt; b$.   Then $f(a) = 1$ and $f(b) = 0$. So by the intermediate value theorem there is a real number $c \in (a,b)$ such that $f(c) = 1/2$, which is a contradiction because the image set of $f$ does not contain $1/2$. Rep line graph: Say "only 200+ accounts displayed" at all times As discovered/discussed , the cross-site reputation graph doesn't show accounts that have less than 200 reputation. The problem is that, unless you have zero accounts over that bar, it doesn't tell you that. I think the "Accounts must have a minimum of 200 reputation to appear in this graph" notice should appear either (A) at all times or (B) if you have any accounts below 200. Concatenate multiple files with two blank lines as delimiter? I'm trying to join Markdown files with two newlines between each file.   I've tried using the following command:  paste -sd '\n\n' file1.md file2.md   This joins the files with a newline, but not two newlines, as I need.   What command can I use to join an arbitrary number of files with two \n characters between each join? Automatically hide old comments Comments are useful. Many, many posts need some small amount of meta discussion, and comments fulfill this need.   Comments are also noisy and distracting. Occasionally, someone will post an insightful and informative comment that complements the post its attached to... But more often, they're tangential, quickly irrelevant and in the way: stale comments show up first, making newer comments less visible.  The guidance here for a long time has been that comments are transient, . And yet, some do hang around for months or years because .   So let's fix that.   I propose that all comments older than 7 days be hidden by default unless the comment has been up-voted in the past 30 days. Hidden comments should be indicated by a note below the post ("add / show 3 more comments") and made visible to anyone who cares to click it.   This doesn't destroy anything, but it would get it out of the way of most readers - and hopefully encourage folks to edit it into the actual answers as a result.  Note: I previously suggested this . Other  have been . However, I'm not suggesting that comments be automatically deleted, and they should be hidden based purely on the age / activity of the comment itself, not of the post to which they're attached. I'm looking for an easy and robust way to strip all the comments from a listing. My approach (passing \@gobble to the commentstyle key) correctly removes all the one-line comments and block comments. However, the white space left behind by by block comments remains, creating useless gaps in my listing. See the screenshot below (the red rectangle is my emphasis). Any idea?    \documentclass{article}  \usepackage{xcolor} \usepackage[T1]{fontenc} \renewcommand{\ttdefault}{pcr} \usepackage{listings}  \makeatletter \lstset% {%   basicstyle   = \ttfamily,   morecomment  = [l]{//},   morecomment  = [s]{/*}{*/},   frame        = single,   commentstyle = \itshape\color[gray]{.5},   rulecolor    = \color{black},   breaklines, } \makeatother  \usepackage{filecontents} \begin{filecontents*}{sample.c} #include &lt;stdio.h&gt;  /*  block comment taking up white space */ main() {     float fahr, celsius;     float lower, upper, step;     lower   = 0;    /* lower limit of temperature scale */     upper   = 300;  /* upper limit */     step    = 20;   /* step size */     celsius = lower;     printf("\nCelsius\tFahr\n");     while (celsius &lt;= upper)        {         fahr = (9.0/5.0) * celsius+32.0;         printf("%3.0f\t%6.1f\n", celsius, fahr);         celsius = celsius + step;     } } \end{filecontents*}  \begin{document} \makeatletter \lstinputlisting[caption={with comments}]{sample.c} \lstinputlisting[caption={without comments},commentstyle={\@gobble}]{sample.c} \makeatother \end{document} What is the purpose of a serial number? C++ map access discards qualifiers (const) The following code says that passing the map as const into the operator[] method discards qualifiers: #include &lt;iostream&gt; #include &lt;map&gt; #include &lt;string&gt;  using namespace std;  class MapWrapper { public:     const int &amp;get_value(const int &amp;key) const {         return _map[key];     }  private:     map&lt;int, int&gt; _map; };  int main() {     MapWrapper mw;     cout &lt;&lt; mw.get_value(42) &lt;&lt; endl;     return 0; }  Is this because of the possible allocation that occurs on the map access? Can no functions with map accesses be declared const? MapWrapper.cpp:10: error: passing const std::map&lt;int, int, std::less&lt;int&gt;, std::allocator&lt;std::pair&lt;const int, int&gt; &gt; &gt; as this argument of  _Tp&amp; std::map&lt;_Key, _Tp, _Compare, _Alloc&gt;::operator[](const _Key&amp;)  [with _Key = int, _Tp = int, _Compare = std::less&lt;int&gt;,  _Alloc = std::allocator&lt;std::pair&lt;const int, int&gt; &gt;] discards qualifiers Is it positive or negative for the average website to allow search engines to index user comments? I've been trying to answer this question myself by researching and searching on google but I haven't been able to come with a final answer. I have some hypothesis I would like share anyway:   The average website intends to reach the higher audience possible. User generated content by comments is an efficient way of increasing the relevance and the valuable information of the average website. Indexing comments will make any site attractive to spammers. Indexing comments is more convenient for new/low-traffic websites than it is for old/high-traffic websites. The web in general is currently choosing not to index comments in the average website because of fear to the SPAMMERS. The average author of a content-valuable comment would like his comment to be indexed Not indexing comments discourages the creation of content-valuable comments.   So, what do you think finally? Is it positive or negative for the average website to allow search engines to index user comments? Why? factorization of a^n+1? Bounding the integral $\int_{2}^{x} \frac{\mathrm dt}{\log^{n}{t}}$ If $x \geq 2$, then how do we prove that $$\int_{2}^{x} \frac{\mathrm dt}{\log^{n}{t}} = O\Bigl(\frac{x}{\log^{n}{x}}\Bigr)?$$ Calculating CR of monsters that do not deal calculable damage Do the -ing and to-infinitive "verbs" that follow catenative verbs always take the grammatical function of "noun"? I'm wondering whether or not the verb form that follows a catenative verb has the grammatical function of a noun or of a verb, and whether or not it depends on the first catenative verb.  "I like to run" "I like running"  the -ing and the to infinitive can easily be switched in this sentence, and it seems to be implying "I like [the act of[running]]", so both the infinitive and the gerund are nouns.  "I like to run marathons"/"I like running marathons"   These seem like they might still be nouns but need "verb powers" to take the object, and then these sentences really turn into "I like [the act of [running marathons]]"/ "I like [to be in the state of [running marathons]]".  Is this true for both the -ing (and so it would be a gerund) and the to-infinitive? Are they, sort of, initially verbs so that they can take the object, and then the verb + object becomes a noun phrase?  If this is true, I'm also wondering if the same rules apply for a catenative verb such as "start".  "I started to run in the mornings" "I started running marathons in 2008"  "start" is a catenative verb that isn't a cognitive/emotion verb, and specifically suggests action. So what is the grammatical function of the to-infinitive and -ing verb forms? are they verbs? are they nouns? It just seems incorrect to say that their grammatical function is a noun, but everything I've seen on the internet is pretty vague. I've also seen that to-infinitives are never verbs, but only from one source and it just doesn't seem right to me.  So any ideas on the true grammatical function of the -ing and the to-infinitive after a catenative verb? And is it universal across catenative verbs, or does it depend on the verb category?