Consider the bibliography file biblio.bib  @article{Sutter-TheFreeLunchIsOver,   author={Herb Sutter},   title={The Free Lunch Is Over: A Fundamental Turn Toward Concurrency in Software},   journal={Dr.\ Dobb's Journal},   year={2005},   volume={30},   number={3},   month= mar }   and the latex file main.tex  \documentclass{article} %\documentclass{IEEEtran} \usepackage[backend=biber,bibstyle=ieee]{biblatex} \addbibresource{biblio.bib} \begin{document} \cite{Sutter-TheFreeLunchIsOver} \printbibliography \end{document}   No matter whether we are using the article class or the ieeetran class, a "no." without a number is printed to the PDF obtained from pdflatex main &amp;&amp; biber main &amp;&amp; pdflatex main:    I have no idea why the number entry (number={3}) in the .bib file is ignored and whether the printing of "no." without a number is a bug or a feature. Apparently, it is hard to turn off, since the biblatex-ieee documentation also has this bug/feature as of March 2, 2017.  In any case, I'd like to avoid "no., " altogether or to have "no. 3," instead. Any help?
When compiling a tex file including references (by Texstudio editor and Miktex distribution) using biblatex with bibtex backend and ieee style, the results of the displayed references in the output pdf is messed up at the "volume" and "issue number" entries as follows:   The volume label "vol." is missing (Ref. 1 &amp; 2 in the given example below). The numeric issue number "3" is missing (Ref. 1 in the given example). The issue number label "no." is displayed although NO input entry was being given (Ref. 2 in the given example).   If it helps, this behavior was noticed after the recent update of Miktex on March 11, 2017, including  package (ver. 1.2a 2017-03-02). As before which, everything was going fine!  So is this issue noticed by someone else? Is there any idea about the reason of such strange act by biblatex?  \documentclass{article} \usepackage{filecontents} \begin{filecontents}{reference.bib}     @article{author1,         author  = "George Green",         title   = "Basic latex",         year    = "2000",         journal = "Sharelatex Journal",         volume  = "10",         number  = "3",         pages   = "100--101"     }     @article{author2,         author  = "Carol White",         title   = "Basic studio",         year    = "2010",         journal = "Club Journal",         volume  = "20",         pages   = "200--201"     } \end{filecontents} \usepackage[backend=bibtex, style=ieee]{biblatex}  \addbibresource{reference.bib} \begin{document}     Hi there! \\     Ref 1 Green \cite{author1}. \\     Ref 2 White \cite{author2}.     \printbibliography  \end{document}   The output is as follows:
I am travelling to Budapest and therefore have a Schengen Visa. I hold an Indian passport and a valid US visa. I'm travelling from Chicago-Heathrow-Budapest and returning by Budapest-Dublin-Chicago.  Would I need a transit visa for UK/Ireland?  UPDATE  Hoping this will help someone someday.   I was not allowed to board my return flight (BUD-DUB-ORD) because I do not hold an overnight Irish Transit Visa. They said I could have transited happily if the connecting flight was in the same day, but because I would have to originally land at 10 PM and catch the connecting flight next morning at 10 AM, I needed a transit visa. Well, I thought it was BS, but couldn't help comply with the rules. I booked another last minute ticket and flew via Warsaw via LOT. If $a$ and $b$ are relatively prime, prove that $a + 2b$ and $2a+b$ are also relatively prime or have a $\gcd$ of $3$.  I'm very new to number theory so please don't assume I am familiar with some of the terminology. How can Star Trek: Countdown ever be considered canon? What is a good way to draw images using pygame? How can I show that $y'=\sqrt{|y|}$ has infinitely many solutions? Show that the first order differential equation $y'(x)=\sqrt{|y(x)|}$ with intial value $y(1/2)= 1/16$ has infinitely many solutions on the interval [−1, 1].  My thought were to show that this equation has two solutions (just by ansatz, or just looking at the interval $]0, 1]$ to get $y'(x) = \sqrt{|y(x)|}$) and deduce from that that there must be infinitely many solutions since the solution set forms a vector space. I've got a nagging feeling this isn't the way to go though. Can anybody give me a hint where to look? Why did Bilbo physically age faster than Gollum? Is there to make the login screen appear on the external display in 18.04? How to Translate Content type name using i18n module? I am developing a multilingual site that supports English and Norsk bokmal. I have set English as my default language. I wanted to translate the contents and the other things in the site.  My real problem started when I found that I was unable to see the translation of the content type's name. I went to admin/config/regional/translate/translate and translated everything, but still my content type's name is not translated.  I have attached a screenshot of the translation page. Still I don't find a way to translate the content type's name. XGBoost Loss function Approximation With Taylor Expansion As an example, take the objective function of the XGBoost model on the $t$'th iteration:  $$\mathcal{L}^{(t)}=\sum_{i=1}^n\ell(y_i,\hat{y}_i^{(t-1)}+f_t(\mathbf{x}_i))+\Omega(f_t)$$  where $\ell$ is the loss function, $f_t$ is the $t$'th tree output and $\Omega$ is the regularization. One of the (many) key steps for fast calculation is the approximation:  $$\mathcal{L}^{(t)}\approx \sum_{i=1}^n\ell(y_i,\hat{y}_i^{(t-1)})+g_tf_t(\mathbf{x}_i)+\frac{1}{2}h_if_t^2(\mathbf{x}_i)+\Omega(f_t),$$  where $g_i$ and $h_i$ are the first and second derivatives of the loss function.   What I'm asking for is convincing arguments to demystify why the above approximation works:  1) How does XGBoost with the above approximation compare to XGBoost with the full objective function? What potentially interesting, higher-order behavior is lost in the approximation?  2) It's a bit hard to visualize (and depends on the loss function) but, if the loss function has a large cubic component, then the approximation will likely fail. How is it that this doesn't cause problems for XGBoost? GTA 5 Social club I used to play gta 5 online on my ps3 but it ended up breaking and I can't use it anymore I purchased the game for xbox 360 and started playing the game all over again and some of you know how hard that can be specially online.. So I was wondering if I could somehow transfer my old ps3 social club account to my xbox an use it on xbox from now on? Looking for an intuitive explanation why the row rank is equal to the column rank for a matrix Permanently removing apache2 It seems a simple apt-get remove apache2 does not completely remove apache2 as I can still see it on one of the processes when running top. How does one remove apache2 completely on his ubuntu server?  It's not removed indeed:  ~# which apache2 /usr/sbin/apache2 ~# whereis apache2 apache2: /usr/sbin/apache2 /etc/apache2 /usr/lib/apache2 /usr/share/apache2 /usr/share/man/man8/apache2.8.gz   But when I do apt-get remove apache2 again:  # apt-get remove apache2 Reading package lists... Done Building dependency tree Reading state information... Done Package apache2 is not installed, so not removed 0 upgraded, 0 newly installed, 0 to remove and 0 not upgraded. Calculate difference between two dates (number of days)? Custom function won't refresh as inputs are changed Are these intended activities legal to do in the USA under the VWP? I'm a British citizen traveling to the USA next month with an ESTA to see my fiancee. I'm traveling there to plan our wedding, talk about a location to get married, and probably finalise a date and a booking with my fiancee (US citizen). This is the primary reason for my trip to the USA. Am I allowed to do this as a tourist? I would like to know for when the CBP officer asks me if this thing is allowed.  Am I allowed to enter the USA, on a separate trip (probably later this year), for the sole purpose of marrying my fiancee, provided I can persuade the CBP officer I intend to leave at the end of my trip? My fiancee and I are moving to the UK next year. What is the advantage on saving the money for the overlord when you have 9 drones, and not filling your supply first and then getting the overlord?  In my theory, in the first case you get to wait the saving time with 9 drones, and get to wait almost the same time with 10 drones in the second case. Second case should be better, since 10 drones mine faster than 9? So why does everybody go with the first case?  All this is assuming you go 12 pool or something like that, where you will get more drones after the overlord. 6- and 8-pools are obviously different. How to output multiple image sizes from one design? I am designing an app for Android and as you may know that Android uses 6 different density buckets from LDPI to XXXHDPI.   Is there a way to save multiple outputs of different sizes from one design using either Photoshop, Illustrator, or another software?  If not will I have to resize it 6 times or is there an easy way? Possessive 's for things Is this a correct demonstration for why elements above untriseptium cannot exist? With the confirmation that elements 113, 115, 117, and 118 are indeed fundamental elements that are now to be named on the periodic table, the next question is: what is the highest atomic number possible for an element? Feynman had a go at this years ago, and he derived (according to my limited understanding) that above element-137 (informally denoted 'Feynmanium') the electrons in the nearest orbit about the nucleus would be traveling at a velocity greater than the speed of light. (Note I am considering the Bohr model of the atom in this question.) I wished to demonstrate to my friends why this is and I came up with the following explanation.  According to Bohr's quantum condition, the angular momentum of an electron about the nucleus is given by $$ L=m_evr_n=n\hslash \implies r_n=\frac{n\hslash}{m_ev},$$ where $m_e$ is the mass of the electron, $v$ its velocity, $n$ an integer, and $r_n$ the radius of the $n$th possible orbit. Because we are concerned with the nearest orbit to the nucleus, $n=1$; and thus $$r=\frac{\hslash}{m_ev}.$$   Now, according to Coulomb's law, if the electron orbits about the nucleus the centripetal motion can be described by $$\frac{Ze^2}{4\pi\epsilon_or}=m_ev^2, $$ where $Z$ denotes the number of protons in the nucleus (the atomic number), and $e$ the elementary charge. Solving for $Z$ and substituting in $r$ from above yields $$Z=\frac{4\pi\epsilon_o \hslash v}{e^2}. $$ But what is $v$? Well, the maximum velocity an electron could ever have is the speed of light, and we wish to find the atomic number associated with an orbiting electron traveling at this speed, so we set $v=c$ and obtain our final result of $$Z=\frac{4\pi\epsilon_o\hslash c}{e^2}\approx 137.521,$$ which implies that for $Z&gt;137$, the electrons at a position of $n=1$ in the Bohr model would have a velocity $&gt;c$; and thus the highest atomic number achievable on the periodic table is 137.  Again, I just want to make sure this is a correct method for deriving element-137 before presenting. Perhaps one could explain how relativity plays a role here. I know Feynman used the Dirac equation to get this result...so could anyone (subsequently of course) expatiate on this in a simplistic manner? Thanks! Reading console input in MonoDevelop