How do I get music which I have ripped from CDs into iTunes onto my iPhone so I can listen to it? It shows up in my library but I can't get it to sync to my iPhone.  I've clicked on the iPhone icon, clicked music and checked the album that was ripped. I've then synced the device but it but never shows up in my music on my iPhone.  Right now I'm dragging the songs to the iPhone icon but that doesn't look to be working ether. In my iTunes library the ripped album shows up in Compilations—I don't know what that means or how to get the album into the library itself I feel that's the problem because I've ripped a CD once before and it just showed up in my iPhone and library with no problem.
I've always managed my iPhone/iPad/iPod Manually, I recently updated to iTunes 11 and now I can see no way to get my music onto my device.  I used to be able to just drag songs from my library to my device, now there is seemingly no way to do this.  I can view the music on my device by clicking on it on the top right corner of iTunes, but I can't seem to get to a state where I can drag music from my computer onto my device.  I'm using iTunes 11.0.1.12 for Windows if that makes a difference.
How to load JAR files dynamically at Runtime? I have always believed that it was ok to replace a capacitor with a slightly higher voltage rated one. eg 16v with 25v.Going higher than this would risk the capacitance value being out at the working voltage. However I just read the following quote from this       Electrolytic capacitors are non-ferroelectric with a very low dielectric constant. Their capacitance is derived from a very high surface area and nanometer thick dielectric layers. Their capacitance is not a function of applied voltage.‐Design Solutions For DC Bias In Multilayer Ceramic Capacitors (August 2010 Electronic Engineering Times)   So does this rule not apply to aluminum electrolytics? Eg will I have no issues replacing an electrolytic 25v 100uf with a 50v 100uf assuming both are low esr, similar footprint and good quailty? Is the function differentiable at $0$? Let $$f(x) = \begin{cases}\begin{align*}&amp;\cos{\dfrac{1}{x}}, &amp;x \neq0 \\ &amp;0, &amp;x=0. \end{align*}\end{cases}$$ Is the function $F(x) = \displaystyle \int_{0}^x f dx$ differentiable at $0$?  We can see that the function $f(x)$ is continuous everywhere except $x=0$. In order to show differentiability we will need to show the derivatives from the left and right are equal. So we need to show that $$\lim_{h \to 0^+} \dfrac{F(x+h)-F(x)}{h} = \lim_{h \to 0^-} \dfrac{F(x+h)-F(x)}{h}.$$ The derivative from the right is $$\lim_{h \to 0^+} \dfrac{F(x+h)-F(x)}{h} = \lim_{h \to 0^+} \dfrac{\displaystyle \int_{0}^x\cos{\dfrac{1}{x+h}}-\int_{0}^x\cos{\dfrac{1}{x}}}{h}$$ and the derivative from the left is $$\lim_{h \to 0^-} \dfrac{F(x+h)-F(x)}{h} = \lim_{h \to 0^-} \dfrac{\displaystyle \int_{0}^x\cos{\dfrac{1}{x+h}}-\int_{0}^x\cos{\dfrac{1}{x}}}{h}.$$ I am not sure how to proceed. How do I install wine? Can someone please explain how I can install  in the following ways?   By using the package manager? By downloading and installing a pre-built package? Why do 'get' and 'have' work similarly in      I got/had my car repaired.    but differently – that is are not complemented in the same way although they still mean the same – in      I got someone to repair my car.    and      I had someone repair my car. I have reviewed this:   but it does not answer my question. The suggested fixes in this question is to set up FB, IG, and other social media pages. We have had these for months. We have 576 Instagram followers, 293 followers on Facebook, 17,425 views on Vimeo, Youtube, Pinterest and LinkedIn presence. Here is the response in a YouTube search:  Let's be clear. If you search for my company name and product name YT changes the spelling to something that doesn't exist and suggests a video with no matching result terms (using either spelling) disparaging OTHER luxury handbags, while insinuating it is referring to my handbags. When a user searches for our business, , Google and Youtube changes the spelling to Aslan Vaughn and displays these results:  For the first few months it just seemed like it was taking some time to percolate, but over 7 months we have had 17,500 unique visitors and nearly 90 backlinks.  The only results for Aslan Vaugn is the birth announcement of the second child of a musician in New Jersey. It is a Facebook post and has 14 likes. Google is favoring a spelling that has only two results with 14+ views over dozens of links and tens of thousands of views. How is this possible? An FB post with 14 likes is that much more popular than a business with 17,500 unique visitors (despite the Google obfuscation)? Is my company on some list? On other search engines my company covers the first few pages in results. Through Google, you cannot find our company no matter how many pages in you go. Unless you search for the term in quotes, . In which case we cover the first few pages here as well: Moving SQL Server to different domain What happens to the holes in the skull where teeth were developing? In Skeptics.SE, a question regarding the skulls of children arose. Depicting a scary skull where the permenent teeth are "hidden" inside the jaws and the milk teeth are in the their place.  After all milk teeth fall out, and the permanent teeth "rise", do the holes left by them filled up, or do we go around with holes in our jaws?    The picture: This question is NOT about access to USB or external drives.  WPS Witer and other just installed Ubuntu software can NOT open files saved on my /media directory. I keep getting the annoying message: « Could not read the contents of '/media': Permission denied ».   MY SIMPLE QUESTION REMAINS:  How can I access all files and folders on my user username/media/ directory?  I'm using Ubuntu 18.04.3 LTS.  Ubuntu's Nautilus can indeed access all files and folders in all locations. However, Ubuntu's software that I have downloaded (e.g. KRITA, WPS WRITER etc) can NOT access any file or folder on the /media directory. Thanks in advance. Prove that $||x|-|y||\le |x-y|$ How to install Eclipse? What's the policy about having multiple user accounts? Can a Mac be used by different users at the same time?  I mean to say that we have a single Mac but 3 users. Can they access the same machine remotely at the same time for developing applications on iPhone or Mac?  Does Mac OS X server allow us to do this?  If so, how do I configure it for that? Invoking Java main method with parameters from Eclipse During development (and for debugging) it is very useful to run a Java class' public static void main(String[] argv)  method directly from inside Eclipse (using the Run As context menu).  Is there a similarily quick way to specify command line parameters for the run? What I do now is go to the "Run Dialog", click through the various settings to the tab where I can specify VM and program arguments and enter them there.  Too many steps, plus I do not want to mix the more permanent runtime configuration settings with the one-off invokation parameters. What I want instead is to check a box somewhere (or have a separate menu item "Run as Java application with command line") and then be prompted for the commandline every time (with a nice history). Rolle's Theorem and the Mean Value Theorem Let $f\colon \mathbb{R} \to \mathbb{R}$ have derivatives of all orders. Suppose that $a &lt; b$ and that $f(a)=f(b)=f'(a)=f'(b) =0$. Prove that $f'''(c) = 0$ for some $c$ in $(a,b)$. Close Vs Closed and Open Vs. Opened Which board is proper to describe the state of any shop/restaurant?  For instance,     A restaurant with the board Close OR Closed?    A restaurant with the board Open OR Opened?   Well, if I think 'closed' is used when the restaurant is permanently or temporarily closed for more than a day (say for holidays or renovation), what about the conversation mentioned below? It takes -ed even for that day!     "Hey Mike, I forgot my specs at home. Do you see the restaurant there at distance? Is it open?   "Yeah, I do see. But it's closed.   I think open/opened or close/closed here is not a verb. If it isn't, then what is it in those examples? I have a table story_category in my database with corrupt entries. The next query returns the corrupt entries:  SELECT *  FROM  story_category  WHERE category_id NOT IN (     SELECT DISTINCT category.id      FROM category INNER JOIN         story_category ON category_id=category.id);   I tried to delete them executing:  DELETE FROM story_category  WHERE category_id NOT IN (     SELECT DISTINCT category.id      FROM category        INNER JOIN story_category ON category_id=category.id);   But I get the next error:      #1093 - You can't specify target table 'story_category' for update in FROM clause    How can I overcome this? Solving $\sqrt{x+5} = x - 1$ How do I calculate rotation caused by bounce friction? Background on color perception:  Due to the nature of the human eye and visual processing by the brain, there's an optical illusion that the same color will look different depending on the background.   It is known as the , illustrated below — center rectangles are identical:   Source:   An illustration  makes the effect of the background's color even more obvious:     Source:   (Note how the two upper-most colors in the second image appear the same, but are actually completely different.)    What about web design?  My question pertains to web design, specifically in this case, the color of link text on different backgrounds.  For a given color of text, how can one find the complementary color to make it appear the same on a certain background?    Let's take a look at an example for this question:  Consider my example below, with yellow text #FFF000 on the following backgrounds:    white #FFFFFF, black #000000, and grey #555555.          As expected, doesn't look the same at all. ()  How can we make it look the same on all three? Clearly, the text on the white background needs to be a darker yellow, and the one on the grey needs hue/tone adjustments. (The surrounding text will also affect it — but that's likely harder to account for.)  Can this perfect color somehow be calculated, based on the Hex, RGB or another system? That's where the crux of this question lies, as it would be much more efficient than manually approximating.