I like the chat feature and I am one of the regular users for it. The thing is, sometimes I love to read what guys talk about in a chat room, but without being visible to them usually to avoid pings  (we have a very good chat community in Travel.SE). Currently I open another browser where I am not logged in and open the chat there to see it without appearing. I also can load the transcript but that requires me to refresh.  Is there a way to be a spectator in a chat room (your name not in the users list) and without being logged out? If not can that be done?  Note: There is a  which suggested the transcript, which is not a practical solution IMO. So I am reviving that request again hoping it will get attention.
E.g.  I know that I can browse the chat when I'm not logged on. But what if I am logged on and want to spare the inconvenience of logging off/multiple browsers?
How do I read the history of my reputation? Why is electric field lines away from (+) and toward (-)? I have a questions about the electric field lines.   Well in the basic learning, we know that:   The electric field lines extend away from a positive charge They move forward a negative charge   Let's take parallel plates, which make a uniform electric field.If we take the basic learning, which I mentioned, in accounts, it's very easy to understand that this is the direction of a positive charge object if we put the object between the plate (move away the positive charged plate and toward negatively charged plate).  The problem is if we put a negative charged object between. Isn't the electric field reversed ? Given two ciphertexts $c_1 = enc(p_1)$ and $c_2= enc(p_2)$ using any additive homomorphic encryption scheme (or specifically Paillier).   Can we find out whether the underlying plaintexts $p_1,p_2$ are equal without decrypting $c_1,c_2$ i.e. homomorphically? "He committed a crime killing/by killing a bird" Which wording with kill should be used here:     He committed a crime (killing/by killing) a bird.   My guess is the answer would be by killing. But I am really confused with the answer killing.   My questions relating to this sentence are:   Which one is correct and why? (or are they both correct?) If one of them is incorrect, why is it incorrect? (or, if both of them are, why?) If they are both correct, what is the difference in meaning? If they are both correct, what is the difference in their grammar? When do I pronounce a non-existent “r” between adjacent vowel sounds? If I say two words consecutively, with the first ending in a vowel sound and the second starting with one, when is it correct to include a non-existent r between those two words?  Examples from phrases I've heard:        I saw (r)a movie   They saw (r)us   Law (r)and order   That's the idea, (r)anyway.      I heard the last one in the movie Edge of Tomorrow yesterday.  Is this grammatically correct? If so, is the omission of the r grammatically incorrect? Are there any rules regarding this? US Election results 2016: What went wrong with prediction models? First it was , now the US election. Many model predictions were off by a wide margin, and are there lessons to be learned here? As late as 4 pm PST yesterday, the betting markets were still favoring Hillary 4 to 1.  I take it that the betting markets, with real money on the line, should act as an ensemble of all the available prediction models out there. So it's not far-fetched to say these models didn't do a very good job.  I saw one explanation was voters were unwilling to identify themselves as Trump supporters. How could a model incorporate effects like that?  One macro explanation I read is the rise of . The question then is how could a statistical model capture a macro trend like that?  Are these prediction models out there putting too much weight on data from polls and sentiment, not enough from where the country is standing in a 100 year view? I am quoting a friend's comments. Do any clones refuse Order 66? When the clones are issued      telling them to turn on the Jedi,    do any of them refuse to carry out the order? stop Ipod from asking for old Apple ID password Recently, I've changed my Apple ID because my old E-mail has been hacked. Now that I set the new one as my apple ID, the old Apple account still appears when I open almost all my apps on my Ipod Touch (4th Gen.), asking for the password to my old Apple ID. When I put in the old password to my old Apple ID, it'll keep asking for it no matter how many times I type it in. How do I fix this while keeping my account secure? Any suggestions would help! Marginal probability derived from joint probability distribution of a poisson process and binomial process I thought I figured out this problem, but my answer is different than the solutions manual. Hoping someone here can stear me in the correct direction:     Assume the number of automobile collisions that occur on a given stretch of highway per year is a Poisson random variable $X$ with $\mu = 20$. The probability is $p=0.05$ that there will be one or more fatalities in each accident; occurrences of fatalities are independent from one collision to the next. If $Y$ is the number of collisions with one or more fatalities on this stretch of road in one year, find the probability law for $Y$.   So as said, X is poisson, so:  $$p_X(x) = \frac{20^x}{x!}e^{-20}$$  The conditional probability of $Y$ given $X=x$ is a Binomial random variable:  $$p_{Y\mid X}(y\mid x) = \binom{x}{y}p^yq^{x-y}$$  where $Y =$ number of fatal traffic accidents and $x =$ given number of accidents (from poisson distribution)  Therefore the joint probability for $X$ and $Y$ is:  $$p_{X,Y}(x,y)= p_{Y\mid X}\cdot p_X(x) = \binom{x}{y}p^yq^{x-y}\frac{20^x}{x!} e^{-20}$$  to find the marginal probability of $Y$, I sum over $P_{X,Y}$ for all $x$:  \begin{align} p_Y(y) &amp; = \sum_{x=y}^\infty{\binom{x}{y}p^yq^{x-y}\frac{20^x}{x!}e^{-20}} = \frac{(20p)^ye^{-20}}{y!} \sum_{x=y}^\infty {20^{x-y}\frac{q^{x-y}}{(x-y)!}} \\[10pt] &amp; = \frac{(20p)^ye^{-20}}{y!} \sum_{x-y=0}^\infty {20^{x-y}\frac{q^{x-y}}{(x-y)!}} = \frac{(20p)^ye^{-20}}{y!}e^{20q} \end{align}  So:   $$p_Y(y) = \frac{(20p)^ye^{-20p}}{y!}$$  however, the correct answer is apparently $p_Y(y)=\dfrac{e^{-1}}{y!}$ Problem about a process with bins of balls workspace switching via ctrl + alt + arrow not working after upgrade to 13.04, how to fix this? How do I find out which folder an app is in in iOS 11? In older versions of iOS, if I searched for an app with Spotlight, it would tell me which folder the app was in. (E.g., this feature still works on my iPad, which is running iOS 9, but not on my iPod Touch, which is running iOS 11.)  This feature seems to have been removed at some point. When I search for an app under iOS 11 using Spotlight, it will find the app and let me run it, but it doesn't tell me which folder it is in.  How can I find out which folder an app is in now? What font is "z" in "z-score"? I suspect that the name server provided by my ADSL modem/router is buggy. Whenever I browse to a website for the first time in ubuntu, resolving the domain name takes at least 15 seconds.  To work around that problem, I changed the nameserver configuration in /etc/resolv.conf from 192.168.1.1 (my ADSL modem) to 8.8.8.8 (google's primary DNS). This seems to fix the problem, but unfortunately my changes to /etc/resolv.conf are overwritten by "NetworkManager" at each startup.  What is the proper way to configure the name server IP in ubuntu 10.4? How does PK know better than Jaggu? In , PK knows about Jaggu's boyfriend that he didn't cheat/left her in Belgium. But PK only read the mind of Jaggu. PK didn't know about Tapasvi's lies. How does he know that Sarfaraz still loves Jaggu in the ending? In the Harry Potter universe, there is a spell that unlocks things. In the books and movies, there are many occasions where the main characters use this spell to open doors in wizard buildings (such as the door leading to where the Philosopher's Stone is hidden, or a door in the Magical Congress Of USA headquarters). Hermione knows the spell in her first year, which seems to indicate it's pretty easy to learn/cast, especially for the average adult wizard.   What I'm wondering, then, is why do wizards lock their doors when it's so easy to unlock them? And if it's so easy to unlock locked doors, why aren't there more doors locked with enchantments? Why was the previous Code of Conduct FAQ (and all answers) removed? Let $S = \{ax + by: x,y \in \mathbb{Z}\}$  and let $e &gt; 0$ be the smallest element in $S$. Prove that $e \mid a$, and hence prove that $e = \gcd(a,b)$  I'm afraid I can't provide much of my initial working here because I'm at a loss of how to start.  I suppose that to show $e\mid a$ I would have to show that $eg = a$ for some $g \in \mathbb{Z}$. But I have no idea how I would do this. The Weyl equidistribution theorem states that the sequence of fractional parts ${n \xi}$, $n = 0, 1, 2, \dots$ is uniformly distributed for $\xi$ irrational.   This can be proved using a bit of ergodic theory, specifically the fact that an irrational rotation is uniquely ergodic with respect to Lebesgue measure. It can also be proved by simply playing with trigonometric polynomials (i.e., polynomials in $e^{2\pi i k x}$ for $k$ an integer) and using the fact they are dense in the space of all continuous functions with period 1.  In particular, one shows that if $f(x)$ is a continuous function with period 1, then for any $t$,  $\int_0^1 f(x) dx = \lim \frac{1}{N} \sum_{i=0}^{N-1} f(t+i \xi)$. One shows this by checking this (directly) for trigonometric polynomials via the geometric series.  This is a very elementary and nice proof.  The general form of Weyl's theorem states that if $p$ is a monic integer-valued polynomial, then the sequence ${p(n \xi)}$ for $\xi$ irrational is uniformly distributed modulo 1.  I believe this can be proved using extensions of these ergodic theory techniques -- it's an exercise in Katok and Hasselblatt.  I'd like to see an elementary proof.  Can the general form of Weyl's theorem be proved using the same elementary techniques as in the basic version? Adjectives and nouns to describe an answer that doesn't answer the question? I've heard of the adjectives 'nonresponsive' or , but are they restricted to law^?     Collins Dictionary:  =       not responsive, not reacting to a stimulus   The definition above differs from the definitions of adjectives like 'equivocate,  evade' and nouns like , but these are negative and accusive; I prefer neutral connotation.  ^Only if you wish, please see: ,  by David Berg,  by Thomas A. Mauet.