Ubuntu LTS versions receive 5 years of support.  Occasionally, new point-releases are made for LTS versions.  For example, Ubuntu 14.04.1 LTS was released on July 24 2014, which replaces 14.04.  How long are security updates provided for the original 14.04 release (or other LTS versions)?  The  has no end of life date defined for 14.04.  Edit:  that point-releases are just snapshots of the bug fixes released so far, thus all versions receive the same duration of support.
There are so called "point releases" for LTS versions of Ubuntu. 10.04.3 for instance.  What are those "point releases" releases?
How to keep vehicles upgrades equipped in Jetpack Joyride? I have Jetpack Joyride for Android, but every time I start the game I have to equip the magnetic upgrades to all vehicles, except the teleporter, which is the only one already equipped.  I had once a game crash that undid my last 2 magnets purchases, so I ended up with only the teleporter and 20k less in cash. After that, I've bought every vehicle magnet, but still the only one that will remain equipped is the teleport.  Anyone already found some similar bug? How could I fix this, it's kinda annoying have to mannually enable 5 different upgrades every time I want to play. Problem 4.3.32 in Linear Algebra, Lay:  Let $V$ and $W$ be vector spaces, let $T:V\to W$ be a linear transformation, and let $\{\mathbf{v}_1, \dots , \mathbf{v}_p \}$ be a subset of $V$. Suppose that $T$ is a one-to-one transformation [...]. Show that if the set of images $\{T(\mathbf{v}_1), \dots ,T(\mathbf{v}_p)\}$ is linearly dependent, then $\{\mathbf{v}_1, \dots , \mathbf{v}_p \}$ is linearly dependent. This fact shows that a one-to-one linear transformation maps a linearly independent set onto a linearly independent set.  All I can think of doing: If $\{T(\mathbf{v}_1), \dots ,T(\mathbf{v}_p)\}$ is linearly dependent, then there exist weights $c_1, \dots, c_p$, not all zero, so that $$c_1 T(\mathbf{v}_1) + \cdots + c_p T(\mathbf{v}_p) = \mathbf{0}$$ Since $T$ is linear: $$c_1 T(\mathbf{v}_1) + \cdots + c_p T(\mathbf{v}_p) = T(c_1\mathbf{v}_1) + \cdots + T(c_p \mathbf{v}_p)=T(c_1 \mathbf{v}_1 +\cdots + c_p \mathbf{v}_p)=\mathbf{0}$$ So the set $\{\mathbf{v}_1, \dots , \mathbf{v}_p \}$ must be linearly dependent. Am I missing something? And why must $T$ be on-to-one for this to be true? An example showing that it is not true if $T$ is not one-to-one would be great! How can I add a folder to the launcher for quick access to it. In this particular case I wish to drag it to the launcher. Calling delete on variable allocated on the stack URW-Garamond with mathdesign is typesetting vertical double-quote as vertical double-quote I just started using URW-Garamond with mathdesign, and it's typesetting straight double-quote character as a straight double-quote rather than a right double-quote.  How can I fix this?  That is, when I put this in my header:  \usepackage[T1]{fontenc} \usepackage[urw-garamond]{mathdesign}   I get a nice Garamond in my output, but " in my input file produces a Garamond version of the same character in the output.  If I use two single-quotes instead, it comes out properly as a double right-quote.  I could switch to typing '' or set up a macro, but this is undesirable for more than one reason.  Is there any way to use urw-garamond without this non-traditional behavior for "? Can we implement a dead time on answers for high reputation user Summary: High reputation users on SO come swooping in the second a simple question is posted, and get the first answer in before I've even opened my Python interpreter to test my idea out.  This actually is a problem because it prevents use lower users who aren't as good  at programming from getting any answers in.  This makes it very hard to build up reputation.  Thus, I propose a short dead time for high reputation users where their answers do not appear.  The Problem: This isn't just reputation.  By answering questions and having discussions with OP, we all get better at our language.  Teaching is one of the best ways of learning, and a more well versed population is absolutely good for SO.  (If anyone wants to argue that, go home)  While its nice to have folks who can quickly answer nearly all questions in a jiffy, its a little frustrating for those of use who simply aren't as fast, but still want to contribute.  The result is that many people do not answer questions because they feel like they just can't get an edge in.  SO should aim to incentivize as many answers by as many users as possible.  The most answers from the most users is the most beneficial situation for the site and the community. Once we accept this idea, it is clear that something needs to be done to address the issue at hand    The Solution: Luckily, this is an easy problem to solve; we use a dead time.  High reputation users can post answers whenever they like, but they won't appear until after the dead time is completed.  The trick is balance, a dead time which is too long will harm the OP as the question will remain unanswered, however, a dead time which is too short won't actually fix the problem.  There definitely needs to be a discussion about what "high reputation" means and what dead time to use, but it should be independent of whether y'all agree that this is a problem.  So, what do you think?  EDIT: Wow, -18, I leave for lunch for 30 minutes and this is what happens!  I guess y'all think this is a bad idea, but let me try to clarify a few things on which I was unclear earlier.  This is not about reputation.  This is not about getting the first answer just for the sake of getting to say "in before..."  This is about learning.  By getting a shot at answering questions before the high reputation users, people learn. Think of it as doing an example problem in class before the teacher does it. You get a chance to try it yourself, test your knowledge, and if you fail, then the teacher is right behind you to show the correct solution.  This is what I'm trying to accomplish. However, seeing the solution, and then trying to answer the question, is not very helpful. This is how I view the status quo.    In response to Mr. Pieters' answer and comments: You're absolutely right, this is not about quantity, its about quality.  The fastest answer isn't always the best.  But asking the high reputation users to take a step back for a few minutes is a means of getting there.    Hopefully this clears things up a bit. Receiving commandline input while listening for connections in Python I have the name of a function in JavaScript as a string. How do I convert that into a function pointer so I can call it later?  Depending on the circumstances, I may need to pass various arguments into the method too.  Some of the functions may take the form of namespace.namespace.function(args[...]). How to implement Bitcount using only Bitwise operators? How to read the content of a file to a string in C? We all know that a simple statement such as:  SELECT * FROM stuff;   should not produce an ordered result. However, when I try to demonstrate this, it always comes out in primary key order.  Moreover a statement such as:  SELECT thing,whatever FROM stuff GROUP BY thing,whatever;   always appears to sort thing by the last field in the GROUP BY clause, which is not at all helpful.  The question is, under what circumstances does SQL SERVER order the result even if unasked, and what can I do to stop this?  I am trying to demonstrate to my students that order is indeterminate unless specified, but this is not helping my case.  I admit that I am working with a small set of sample data.  Thanks How do I backup and restore SMS Messages? How do I backup and restore SMS Messages? Can you trade Pokemon from 7th gen (Sun/Moon) to 6th gen (XY, ORAS) and back? Title says it all, I don't see confirmation in  and a cursory google search seemed to say assume no and speculate about the pokemon bank. D+ and D- on USB I'm making a small project which will take +5v from USB, What should I do with the D+ and D-, keep it open or short them to ground or do I have to add some components?  I want to run ATMEGA168 and 16x2 LCD with back light. I would like to transform 5V 500mA (from USB power) into 12V with a few cheap components.  Is this possible with the help of some generic parts (and not with the help of some expensive transformer, etc.)?  Also, how many milliamps would this provide? Does someone falling into a black hole see the end of the universe? This question was prompted by . Notoriously, if you calculate the Schwarzschild coordinate time for anything, matter or light, to reach the event horizon the result is infinite. This implies that the universe ages by an infinite time before someone falling into the black hole reaches the event horizon, so could that person see the universe age by an infinite time?  To be more precise, suppose the observer starts falling from rest at time $t = 0$ and some initial distance $r &gt; r_s$. If we wait for some time $T$ then shine a light ray at the falling observer. Will the light ray always reach the falling observer before they cross the event horizon? If not, what is the formula for the longest time $T$ that we can wait and still be sure the ray will catch the observer? If $T$ is not bounded it implies that observer could indeed see the end of the universe.  I can think of a qualitative argument for an upper limit on $T$, but I'm not sure how sound my argument is. The proper time for the observer to fall to the event horizon is finite - call this $\tau$. The proper time for the light ray to reach the horizon is zero, therefore the light ray will reach the observer before they cross the event horizon only if $T &lt; \tau$. Hence $T$ is bounded and the observer won't see the end of the universe.  I think a more rigorous approach would be to determine the equations of motion (in the Schwarzschild coordinates) for the falling observer and the light ray, and then find the condition for the light to reach the falling observer at some distance $\epsilon$ from the event horizon. Then take the limit as $\epsilon \rightarrow 0$. In principle this seems straightforward, but in practice the algebra rapidly defeated me. Even for a light ray the radial distance:time equation isn't closed form (Wolfram claims it needs the $W$ function) and for the falling observer the calculation is even harder. When should I upgrade my camera body? How to control fan speed? How can I control the computer's fan speed?  On Windows there is a wonderful program called . How can we prove charge invariance under Lorentz Transformation? How to hide TabPage from TabControl How to hide TabPage from TabControl in WinForms 2.0?