Hi I am from India and have B1 . Can I come to US without a B2 visa. I had previously used this visa for official purpose. Will there be any problem relating to immigration. I will be staying with my friend what other formality do I have to do?
I got a B1/B2 visa earlier this year when I traveled to the US for a business trip from my company. It expires in 2013 and I'd love to visit the United States again, but for no other purpose than traveling.  I wonder:        If I can legally travel to US with B1/B2 visa without a real business need (assuming I'm honest);   If I have to work at my current company to be able to use it.      I live in Russia.
Probability that all three shirts were worn Mr. Jones has three shirts: Red, Green and White. Each day he picks randomly a red shirt with probability of $\frac{1}{2}$, green with probability of $\frac{1}{3}$ and white with probability of $\frac{1}{6}$.     What is the probability that he wears all three shirts after 6 days?   My try:   $$\binom{6}{1}\binom{5}{1}\binom{4}{1}\frac{1}{2}\cdot\frac{1}{3}\cdot\frac{1}{6}\cdot[\binom{3}{2}(\frac{1}{2})^2\cdot[\frac{1}{3}+\frac{1}{6}]+[\binom{3}{2}(\frac{1}{3})^2\cdot[\frac{1}{2}+\frac{1}{6}]+[\binom{3}{2}(\frac{1}{6})^2\cdot[\frac{1}{2}+\frac{1}{3}]+\binom{3}{1}\binom{2}{1}\frac{1}{2}\cdot\frac{1}{3}\cdot\frac{1}{6}]$$  First, we pick possessions for red, green and white. Then, we multiply it by the other combinations possible of the other three possessions left, and summing it up (I didn't count all possibilities). The problem is the answer is bigger than 1, so it must be wrong. Also, I guess there is more elegant way.  Thanks in advance. I am new to the glmnet package, and I am still unsure of how to interpret the results. Could anyone please help me read the following trace plot?  The graph was obtaining by running the following:  library(glmnet) return &lt;- matrix(ret.ff.zoo[which(index(ret.ff.zoo)==beta.df$date[2]), ]) data   &lt;- matrix(unlist(beta.df[which(beta.df$date==beta.df$date[2]), ][ ,-1]),                   ncol=num.factors) model  &lt;- cv.glmnet(data, return, standardize=TRUE)  op &lt;- par(mfrow=c(1, 2)) plot(model$glmnet.fit, "norm",   label=TRUE) plot(model$glmnet.fit, "lambda", label=TRUE) par(op) Making an invisible pressure plate I'm trying to build a teleporter. I want the player to be teleported from the first sign(left) to the right sign(right). So, when the player steps on the red wool on the left, he will automatically be teleported to the red wool on the right. I do not want to use any pressure plats.It might work with the testfor comment, but I didn't figure out, put that only works with a radius. BTW I'm in 1.10.2 bou I could probably change the version if necessary.     The testfor command block should activate the teleport command block,when the player is detected. Now, I'm not really the expert, so I know non of the commands that you would need to build this construction. Please help, I would highly appreciate it! If you need any more details, ask me! What is a more efficient way to draw this tree? I have drawn the following tree in TikZ. What I don't like about it is   that I have to manually adjust the sibling distance for each level; and the syntax is too cumbersome.   It has been suggested to me by @percusse and @AlanMunn that using tikz-qtree and/or forest may be a more efficient way to produce the same result. But I don't have experience in using either package.   It would be nice if someone can reproduce my example using either of these packages, so that I can have quick example to learn from instead of reading a 150-page manual trying to find an answer.    \documentclass{standalone} \usepackage{tikz} \usepackage{amsmath}  \begin{document}  \tikzset{   % Two node styles for game trees: solid and hollow   solid node/.style={circle,draw,inner sep=1.2,fill=black},   hollow node/.style={circle,draw,inner sep=1.2}, }  % macro for entering payoffs \newcommand\payoff[1]{   $\begin{pmatrix} #1 \end{pmatrix}$ }  \begin{tikzpicture}[font=\footnotesize]   \tikzset{     level 1/.style={level distance=15mm,sibling distance=65mm},     level 2/.style={level distance=15mm,sibling distance=30mm},     level 3/.style={level distance=15mm,sibling distance=15mm},     level 4/.style={level distance=15mm,sibling distance=10mm},   }    \node[hollow node,label=above:{Nature}]{}     child{node[solid node,label=left:{P1}]{}       child{node(l1)[solid node]{}         child{node[solid node,label=below:{\payoff{1\\-1}}]{}edge from parent node[left]{L}}         child{node[solid node,label=below:{\payoff{0\\0}}]{}edge from parent node[right]{R}}         edge from parent node[left]{U}       }       child{node(l2)[solid node]{}         child{node[solid node,label=below:{\payoff{0\\0}}]{}edge from parent node[left]{L}}         child{node[solid node,label=below:{\payoff{2\\-2}}]{}edge from parent node[right]{R}}         edge from parent node[right]{D}       }       edge from parent node[left,xshift=-10]{A}     }     child{node[solid node,label=right:{P1}]{}       child{node(r1)[solid node]{}         child{node[solid node,label=below:{\payoff{-2\\2}}]{}edge from parent node[left]{L}}         child{node[solid node,label=below:{\payoff{0\\0}}]{}edge from parent node[right]{R}}         edge from parent node[left]{U}       }       child{node(r2)[solid node]{}         child{node[solid node,label=below:{\payoff{0\\0}}]{}edge from parent node[left]{L}}         child{node[solid node,label=below:{\payoff{-1\\1}}]{}edge from parent node[right]{R}}         edge from parent node[right]{D}       }       edge from parent node[right,xshift=10]{B}     }   ;    \draw[dashed](l1)--(l2)--node[midway,above]{P2}(r1)--(r2); \end{tikzpicture}  \end{document} Why does `find` not delete the files it found? I'm trying to understand why the find command is not deleting files in one particular case. I've got the following command:  find C:\\path\\to\\Pictures\\pmcctv -name cap_*.jpg -o -name cap_*.ogg -o -name cap_*.flv -o -name cap_*.mp4 -o -name cap_*.webm -mtime +7   Which returns the files I would expect:  C:\path\to/Pictures/pmcctv/cap_20160915T193251_620067800.jpg C:\path\to/Pictures/pmcctv/cap_20160915T193322_742708800.jpg C:\path\to/Pictures/pmcctv/cap_20160916T081046_394767500.jpg C:\path\to/Pictures/pmcctv/cap_20160916T081125_615129600.jpg C:\path\to/Pictures/pmcctv/cap_20160916T081129_503678200.jpg C:\path\to/Pictures/pmcctv/cap_20160916T081255_842394600.jpg C:\path\to/Pictures/pmcctv/cap_20160916T161008_693586800.jpg C:\path\to/Pictures/pmcctv/cap_20160916T161012_749396800.jpg C:\path\to/Pictures/pmcctv/cap_20160916T161043_774132200.jpg C:\path\to/Pictures/pmcctv/cap_20160916T161150_497251900.jpg C:\path\to/Pictures/pmcctv/cap_20160916T161154_437379600.jpg C:\path\to/Pictures/pmcctv/cap_20160916T161337_350955300.jpg C:\path\to/Pictures/pmcctv/cap_20160916T161341_452596000.jpg C:\path\to/Pictures/pmcctv/cap_20160916T161412_870774000.jpg C:\path\to/Pictures/pmcctv/cap_20160916T161443_969064400.jpg C:\path\to/Pictures/pmcctv/cap_20160916T161554_468109900.jpg C:\path\to/Pictures/pmcctv/cap_20160916T161558_378086000.jpg C:\path\to/Pictures/pmcctv/cap_20160916T161916_668433100.jpg   Now if I try to run the same command with -delete, the files are not deleted:  find C:\\path\\to\\Pictures\\pmcctv -name cap_*.jpg -o -name cap_*.ogg -o -name cap_*.flv -o -name cap_*.mp4 -o -name cap_*.webm -mtime +7 -delete   I've also tried with -exec rm, but they are also not deleted:  find C:\\path\\to\\Pictures\\pmcctv -name cap_*.jpg -o -name cap_*.ogg -o -name cap_*.flv -o -name cap_*.mp4 -o -name cap_*.webm -mtime +7 -exec rm {} \;   find returns no error and the files are owned by me with permissions 644.  Any idea what could be causing this?  (note: I've cut the commands to make it more readable but normally there's no line break) Can someone help me out and explain or point me in the right direction on how to check video drivers and see if my video card running okay?  I had 10.04 installed on my Thinkpad r61 with Compiz Manager and life was great, until the machine took water damage. I bought an ASUS (X54H) since and am trying out 12.04, but the desktop just doesn't look right.  I always struggled with video driver installation. There are no proprietary drivers available in the hardware manager.  When I run lspci | grep VGA:  00:02.0 VGA compatible controller: Intel Corporation 2nd Generation Core Processor Family Integrated Graphics Controller (rev 09)   I will greatly appreciate your help. I want to use Linux more, but like I said video drivers appear to be my biggest concern. I have also tried 12.04 on my desktop PC, but again failed to configure video card, so switched back to Windows 7. Prove $\lim\limits_{n\to\infty}n^{-1/(p+1)}(1^{1^p}\cdot 2^{2^p}\cdots n^{n^p})^{n^{-p-1}}=e^{-1/(p+1)^2}$ Prove that for real number $p\geq  0$ we have   $$\lim_{n\to\infty}\frac{(1^{1^p} \cdot2^{2^p}\cdots n^{n^p})^\frac{1}{n^{p+1}}}{n^\frac{1}{(p+1)}} = \exp\left(\dfrac{-1}{(p+1)^2}\right).$$ I´m not sure how to start with this proof, how can I do it? $$ \limsup ( a_n b_n ) \leqslant \limsup a_n \limsup b_n  $$ I also have to prove, if $ \lim a_n $ exists then: $$ \limsup ( a_n b_n  ) = \limsup a_n \limsup b_n  $$ Help please, it´s not a homework I want to learn. Let $R$ be a ring (unital, not necessarily commutative), $M$ a finitely presented left $R$ module. Suppose $m_1,\ldots,m_n\in M$ generate $M$. This determines a surjection $f:R^n\to M$.     Must the kernel of $f$ be finitely generated?   This is true by definition if the generating set $m_1,\ldots,m_n$ is the one coming from the finite presentation of $M$. Can spells with movable areas of effect be moved out of sight or behind obstacles? With spells like Moonbeam or Flaming Sphere, how should we treat the movement of their areas-of-effect when it comes to passing them behind a thick pillar or around a blind corner?  Should we treat any movement of them as if they are being 're-cast' (and so requiring a clear unobstructed view)? Or could a mage presumably will them somewhere out-of-sight? Why $SU(3)$ and not $U(3)$? Interface naming in Java Most OO languages prefix their interface names with a capital I, why does Java not do this?  What was the rationale for not following this convention?  To demonstrate what I mean, if I wanted to have a User interface and a User implementation I'd have two choices in Java:        Class = User, Interface = UserInterface   Class = UserImpl, Interface = User      Where in most languages:     Class = User, Interface = IUser   Now, you might argue that you could always pick a most descriptive name for the user implementation and the problem goes away, but Java's pushing a POJO approach to things and   most IOC containers use DynamicProxies extensively.  These two things together mean that you'll have lots of interfaces with a single POJO implementation.  So, I guess my question boils down to: "Is it worth following the broader Interface naming convention especially in light of where Java Frameworks seem to be heading?" How do I calculate standard errors for sums of OLS coefficients? Embedding ordinals in $\mathbb{Q}$ All countable ordinals are embeddable in $\mathbb{Q}$.  For "small" countable ordinals, it is simple to do this explicitly.  $\omega$ is trivial, $\omega+1$ can be e.g. done as $\{\frac{n}{n+1}:n\in \mathbb{N}\} \cup \{1\}$.   $\omega*2$ can be done as $\{\frac{n}{n+1}:n\in \mathbb{N}\} \cup \{1+\frac{n}{n+1}:n\in \mathbb{N}\}$, and $\omega*n$ as $\bigcup_{i\le n} \{i+\frac{n}{n+1}:n\in \mathbb{N}\}$  That immediately also gives $\omega^2$ as  $\bigcup_{i \in \mathbb{N}} \{i+\frac{n}{n+1}:n\in \mathbb{N}\}$  And going further is still relatively easy: We can biject the above embedding of $\omega^2$ onto a single interval $(0,1)$, e.g. through $f(x)=1-\frac{1}{x+1}$ since this is an order preserving bijection from $\mathbb{Q}^+$ to $(0,1)$, allowing us to get $\omega^2+n$, $\omega^2*n$ etc. And by iterating that process, we can get any ordinal below $\omega^\omega$.   But this sort of embedding fails at $\omega^\omega$ as the iteration of $f$ doesn't seem compatible with taking the infinite union - figuratively speaking, we'd squish things to $0$. So what would an explicit embedding of $\omega^\omega$ look like? And the question, then, is if it is possible to give an explicit embedding of $\epsilon_0$? Is the fact that Peano arithmetic cannot prove well-foundedness of $\epsilon_0$ an indication that it cannot be embedded by such elementary functions and their iterations?  And what about even bigger countable ordinals such as the Veblen ordinals, Feferman-Schütte, Bachmann-Howard? From its definition, even if the above all are possible, I assume that the definitive bound of where one can define an effective procedure for the embedding must be Church–Kleene - is that a correct conclusion?  Lastly, does the situation change when we use $\mathbb{R}$ instead of $\mathbb{Q}$, which would allow us to use, perhaps, more easily understood yet inherently complex functions?  Edited because $\omega^2 \neq \omega^\omega$ How to roll the viewport? How do I rotate the viewport around the local (to the view port) - Z axis?  Basically what you would  get if you were to hit R with the camera selected in camera view. Before Mavericks, I could use /etc/launchd.conf file to change maximum system resource consumption, for example:  limit maxfiles 16384 unlimited limit maxproc 16384 unlimited   It no longer works in Mavericks.  What is the correct way to do it in the recent version of OS X? Best way to randomize an array with .NET Which other nations are there in Attack on Titan world aside Eldia and Marley? In the Attack on Titan wikia they often mention other nations aside Eldia and Marley which supposedly have more advanced technology than this 2 nations. Which other known nations are there in Attack on Titan world aside Eldia and Marley and why are they more advanced than Marley when only Eldia is supposed to be isolated from the world? Setting proxy for apt from terminal Possible Duplicate:          I have tried changing my proxy settings in a terminal as:  export HTTP_PROXY=http://10.1.3.1:8080   and  export http_proxy=http://10.1.3.1:8080   but when I try to install a new package or update apt-get, apt-get starts displaying messages from which it seems it is trying to connect to a previously set proxy:  sudo apt-get update   0% [Connecting to 10.1.2.2 (10.1.2.2)] [Connecting to 10.1.2.2 (10.1.2.2)   I have tried setting the proxy via bashrc file but that din work either. As far as I remember 10.1.2.2 was set using GNOME GUI but I don't have access to the GUI right now so I am trying to set it from terminal. I would like to add my bibliography to my presentation in IEEE format. What should I add to my preamble and code.  \documentclass{beamer} \setbeamertemplate{footline}[page number]  \usepackage{graphicx} \usepackage{booktabs} \begin{document} \section{Reference} \begin{frame} \frametitle{Reference}  \end{frame}   I'm using the same bibTex which I use to make the IEEE paper.