There is literally no download link except for the bittorent file. Can anyone link me the direct download?
Please could someone tell me where can I download Ubuntu 32bit without using a torrent? Thanks
How to show loading spinner in jQuery? In Prototype I can show a "loading..." image with this code:  var myAjax = new Ajax.Request( url, {method: 'get', parameters: pars,  onLoading: showLoad, onComplete: showResponse} );  function showLoad () {     ... }   In jQuery, I can load a server page into an element with this:  $('#message').load('index.php?pg=ajaxFlashcard');   but how do I attach a loading spinner to this command as I did in Prototype? Where are the key wardens and where are my Infernal Machines to create a Hellfire Ring/Hellfire Amulet? In order to obtain a Hellfire Ring or Amulet, one has to work their way through the Uber Boss system of harvesting machines and organs to produce a legendary ring or amulet ().  To create the infernal machine required to open the portals to the Ubers, the keys are drops from mobs nick named Key Wardens.  Where are the various key wardens?  Are there any requirements for making the machines drop? What's the drop rate on different difficulty settings? bases and binary I can not figure this out.   I started off by making a table and putting the base(2) on one side, the number in the middle and the remainder in the third row and for 2010 I got 11111011010 but I cant find the next two numbers please help and please explain in detail.  Thank you =)   to express 2010 in base 2, we use exactly 8 ones and 3 zeros. find the next two integers in base 2 that use the same number of ones and zeros Change web folders names with uppercase to lowercase or not? How to block sites with iptables Let $G$ be a connected planar graph with a planar embedding where every face boundary is a cycle of even length. Prove that $G$ is bipartite.  Any hints/tips will be greatly appreciated. I am being driven crazy by the fact that my media keys aren't working for iTunes. Such a pain! How can I fix this? I've tried the whole Chrome Extensions thing, that being I deleted all my extensions. Still, nothing has fixed this. Thanks to all who reply! Find $\sum_{n=1}^\infty \frac{n^3}{n!}$. I have to find the sum of the following series:  $$\sum\limits_{n=1}^\infty \frac{n^3}{n!}$$  I know how to prove the convergence of this series, but how do i find the sum. I can't use the properties of derivation or integration of the series, i have to do it using the definition that a series converges iff it's sequence of partial sum converges. htaccess subdomain Straight lines - product of slope of perpendicular lines. Let $l$ be a line with slope $\frac{1}{0}$, and $m$ a line with slope $0$.  Now, line $l$ is perpendicular to line $l$, therefore the product of the slope of line $l$ and the slope of line $m$ equals $-1$. This implies that $\frac{1}{0} \times 0 = -1$! Sql Server string to date conversion I want to convert a string like this:  '10/15/2008 10:06:32 PM'   into the equivalent DATETIME value in Sql Server.  In Oracle, I would say this:  TO_DATE('10/15/2008 10:06:32 PM','MM/DD/YYYY HH:MI:SS AM')    implies that I must parse the string into one of the , and then convert using one of those codes.  That seems ludicrous for such a mundane operation.  Is there an easier way? Infinitely number of primes in the form $4n+1$ proof Question: Are there infinitely many primes of the form $4n+3$ and $4n+1$?  My attempt: Suppose the contrary that there exist finitely many primes of the form $4n+3$, say $k+1$ of them: $3,p_1,p_2,....,p_k$  Consider $N = 4p_1p_2p_3...p_k+3$, $N$ cannot be a prime of this form. So suppose that $N$=$q_1...q_r$, where $q_i∈P$  Claim: At least one of the $q_i$'s is of the form $4n+3$:  Proof for my claim: $N$ is odd $\Rightarrow q_1,...,q_r$ are odd $\Rightarrow q_i \equiv 1\ (\text{mod }4)$ or $q_i ≡ 3\ (\text{mod }4)$  If all $q_1,...q_r$ are of the form $4n+1$, then $(4n+1)(4m+1)=16nm+4n+4m+1 = 4(\cdots) +1$  Therefore, $N=q_1...q_r = 4m+1$. But $N=4p_1..p_k+3$, i.e. $N≡3\ (\text{mod }4)$, $N$ is congruent to $1\ \text{mod }4$ which is a contradiction.  Therefore, at least one of $q_i \equiv 3\ (\text{mod }4)$. Suppose $q_j\equiv 3\ (\text{mod }4)$  $\Rightarrow$ $q_j=p_i$ for some $1\leq i \leq k$ or $q_j =3$  If $q_j=p_i≠3$ then $q_j$ | $N = 4p_1...p_k + 3 \Rightarrow q_j=3$ Contradiction!  If $q_j=3$ ($\neq p_i$, $1\leq i \leq k$) then $q_j | N = 4 p_1...p_k + 3 \Rightarrow q_j=p_t$ for some $1 \leq i \leq k$ Contradiction!  In fact, there must be also infinitely many primes of the form $4n+1$ (according to my search), but the above method does not work for its proof. I could not understand why it does not work. Could you please show me?  Regards Decode escaped Url without using HttpUtility.UrlDecode Is there any function that converts an escaped Url string to its unescaped form? System.Web.HttpUtility.UrlDecode() can do that job but I don't want to add a reference to System.Web.dll. Since my app is not a web application, I don't want to add a dependency for only using a function in an assembly.  UPDATE: Check  about the same issue. Limit of Series with differences of Floor function Suppose I have some theorem in the paper  Section 1 Theorem 1.1. Let ...  And then later in the paper I want to recall the theorem by reprinting it  Section 4 We recall Theorem 1.1: Theorem 1.1. Let ...  What's the proper way to do this? overbrace/underbrace but with an arrow instead Is there a similar command to \overbrace{foo}^{bar} but instead of braces, an arrow pointing up/down?  EDIT: Here's a little demonstration of how I'd expect something like this to work:    And possible syntax would be \overarrow{a=b}^{\text{theorem X}} Optional argument to \item I am typesetting an ordered list where the entries may appear out of order, but should be assumed in order otherwise. I don't want to have to jump through \setcounter hoops to do this. That is, I want something like  \begin{enumerate}   \item First   \item Second   \item[8] Eighth!   \item Ninth!   \item[4] Fourth \end{enumerate}   to give the following Good output, instead of the Bad output:    A minimum working example follows.  \documentclass{article} \usepackage{enumitem} % preferably something compatible with this guy \begin{document}  Good:  \begin{enumerate}   \item[1.] First   \item[2.] Second   \item[8.] Eighth!   \item[9.] Ninth!   \item[4.] Fourth \end{enumerate}  Bad:  \begin{enumerate}   \item First   \item Second   \item[8] Eighth!   \item Ninth!   \item[4] Fourth \end{enumerate}  \end{document}   It should be noted that I don't want to have to specify the period afterwards, in case my list using a different numbering, e.g. Roman. Compatibility with enumitem is preferred, but not required.  What is the correct way of going about this? If $G$ has no proper subgroup, prove that $G$ is cyclic of order $p$, where $p$ is a prime number.     I know that since $G $is a group with no proper subgroups, $g \in G$ is not just the identity. I don't know where to go from there. When i tried to install PIP for python3 in Ubuntu 18.04.2 LTS  Command I used:   root@DESKTOP-0BEE3OD:/mnt/c# apt install python3-pip  E: Could not read response to hello message from hook [ ! -f /usr/bin/snap ] || /usr/bin/snap advise-snap --from-apt 2&gt;/dev/null || true: Success   I am not able to fix this error. What is an quick way to create a new blank file in Lion? In Windows, one can create a new file using Right Click -> Add New -> Type of File. Is there an analogous action in Lion?  I just want to create a new blank file on my Desktop.