It used to be possible to disconnect a linked Microsoft account from a local account from the "Accounts" settings page, but Microsoft in their wisdom have removed this option.  I accidentally linked my Microsoft account (something I don't want as I have no desire for MS to be copying my account info to the cloud).  How do I go back to having a local account?
I set up Windows 10 and have been using it for months on a spare laptop.  When installing, I did not use a Microsoft account to enable all of the app connectivity because I don't need that functionality.  I do not want these features active on this device, and I used a simple user name during the install.  Everything was going fine until I read about the Linux/bash features that are available in the anniversary update.  I decided to try them out and entered my Microsoft Insider credentials to enable the features in the developer options of the Control Panel.  I didn't realize the primary account on this device would now become linked to that Microsoft account.  Is there a simple way to disassociate the Microsoft account from the local account, or are they now linked forever in an unholy union?  I can set up a new local account, but I'd rather not lose all the settings and folder preferences prior to my gaffe.
How to subtract a day from a date? I have a Python  object. What is the best way to subtract one day? vertically align top line of item contents with item number \begin{enumerate}     \item This looks good.     \item       $\begin{aligned}         \mathrm{This} &amp;= \mathrm{is} \\                       &amp;= \mathrm{not\ nicely\ aligned}       \end{aligned}$     \item \begin{tabular}{ccc}             &amp; Neither &amp; is \\        this &amp; table.  &amp;    \\     \end{tabular} \end{enumerate}   It currently looks like this:    But I want it to look like this:    Vertically-aligned so that the top line of the ... item contents, lines up with the item number. Keyboard shortcut to minimize a window on Ubuntu 18.10 Generally accepted root mean square (RMS) error for rectifying topographic maps This is a generic inquiry on the common practice/standard for determining the acceptable values of RMS when georeferencing topographic maps.  Is there an absolute value?  Some literature suggests that it should be "less than or equal to 1/2 of the side of a cell which make up the total resolution of the image." If we have a point charge and outside of it we have a non-conducting Gaussian sphere, then Gauss's law says that the net flux should be zero. I agree that the total field lines coming in are equal to the number of field lines coming out, but isn't it true that the magnitude of the electric field at those segments of the sphere where the field is coming in is greater than those where it is coming out? So when we integrate, wouldn't these areas, having a greater electric field, contribute more to the net flux? I don't see why they would cancel each other out. Limits of Poisson's ratio in isotropic solid How to stop "Monkey Test" and "Time Service" apps When I long-press the "home" button to close all apps, there is an app named "time service" with android symbol and another named "monkey test" that are always open.   How to stop this? What does it "they like me for me" mean? Understanding DNA match of 1,723 cM Can you take different archetype options at different levels? Once you've picked a subclass option at level 3, could you later take a different subclass option, or do you lock into a specialty at level 3 and then run with it for the rest of that class' progression?  For example, as a rogue, if you took the "Thief" archetype at level 3, giving you access to Fast Hands and Second Story Work, could you then take the "Assassin" archetype to give you the specific benefits that archetype gives instead of the "Thief" ones?  The  seems to imply that you couldn't:     At 3rd level, you choose an archetype that you emulate in the exercise of your rogue abilities: Thief, detailed at the end of the class description, or one from another source. Your archetype choice grants you features at 3rd level and then again at 9th, 13th, and 17th level.   but I'd like a more certain answer, especially one that refers to archetypes in general. Also I'm not ashamed to admit I'd prefer a source with some authority that tells me you can mix and match, but I am looking for the truth of the rules when all is said and done...   Different to  because the no on that demonstrates that you can't re-take a level of the same class. Taking different features for different levels is not the same thing, and would work differently. Similar to  but that one was specific to monks - which is why it didn't show up on any searches I did, and why it wouldn't on the searches of others. This question is specific enough to be clear and precise, but broad enough to be useful to others who aren't in the exact same situation/using the same class. In Java, why do people prepend fields with `this`? When referencing class variables, why do people prepend it with this? I'm not talking about the case when this is used to disambiguate from method parameters, but rather when it seems unnecessary.  Example:  public class Person {             private String name;      public String toString() {         return this.name;     } }   In toString, why not just reference name as name?  return name;   What does this.name buy?   a stackoverflow question whose code has this pre-pending. Insert issue with arrays Can you use the /testfor command in minecraft 1.8 to find out if a player has died ?  I need it for my map, where 2 players (Only) are pitted against eachother. I want it so that when one of them dies, it will detect the death and declare the victor. A triangle with vertices on the sides of a square, with one at a midpoint, cannot be equilateral I just synced my Mountain Lion Mail app with my Exchange work email account in order to have it locally on my machine (rather than continuously going through the web interface). However, now Mail fetches all the mails since the very beginning (which are a couple of years).  Is there a way (like on iOS devices) to tell Mail to only sync the last month or something configurable amount based on message count, download size or other similar restriction to prevent all messages from being stored locally? Was Red Shirt Security a rotating detail, like K.P, or was it a dedicated branch of Star Fleet like the M.P's are to the US Army? As I channel surfed the other day, I accidentally found an episode of Star Trek TOS, and I settled in to watch it. As always, it was a bad day to be a landing party Red Shirt Security person.    Their apparent lack of skill (training?) made me wonder: Was Red Shirt Security a rotating detail, like K.P. (Kitchen Patrol), that crew members with regular assigned duties were ordered to do when it was their turn, or was it a dedicated branch of Star Fleet like the M.P's (Military Police) are to the US Army? The Earth in all of its varieties has wide ranging climates. At the top level it has tropical, dry, temperate, continental, and polar climates. And yet often the planets depicted in science fiction are often single climate planets.    The forest moon of Endor The desert planet of Dune The desert planet of Tatooine The desert planet of Vulcan The outer planets in Firefly all appeared to be mostly desert (supiciously like Calfornia desert).  The inner planets in Firefly were all temperate or tropical.  The icy Breen homeworld The icy Andorian homeworld The icy Frost Giant planet   I'm not suggesting there are no Earth-like planets in science fiction, but it feels like it is less common than it should be. Considering the only planet we have as an example is our own, it seems like planets should be just as varied in the cosmos. Suppose that $5\leq q\leq p$ are both prime. Prove that $24|(p^2-q^2)$.   This is what I got so far. I figured that since $p,q$ are bigger than $5$, there are only odd primes for this conjecture. Then I can rename $p=2m+1,q=2n+1,m,n∈Z$.  We want to show $(p^2-q^2 )=24k,k∈Z$. By substituting $2m+1$ for $p$ and $2n+1$ for $q$, we get  $((2m+1)^2-(2n+1)^2)$. If we expand it, we get $4(m^2+n^2+m-n)$ Q. I think I can make $4(m^2+n^2+m-n)$ look like $24k$. How should I approach ?  And my prof. commented that "I would take this proof in small steps.  Rather than trying initially to prove that $24 | p^2-q^2$, look at the progress you already have.  You proved $4 | p^2-q^2$.  Can you prove 8 is a factor?  What about 3?  Then see if you can put together what you have to get 24 as a factor."  I am stuck here. Any helps? Does anyone know why typedefs of class names don't work like class names for the friend declaration?  class A { public: };  class B : public A { public:    typedef A SUPERCLASS; };  typedef A X;  class C { public:    friend class A;             // OK    friend class X;             // fails    friend class B::SUPERCLASS; // fails }; Don't invite people when moving their messages