title: Batch script to remove rows in a CSV that are empty for a certain column
body: <p>Lets say Im having the following entries:</p>
  
  <pre><code>*ARTNR;*BESTAND;*HERSTARTNR;*WG;*WG2;*LWG;*LWG2
  1000;2758;;PAS;;Passive Bauelemente;
  5800;0;;PAS;MIC;Passive Bauelemente;Microchip Technology
  5801;0;;AKT;AMP;Aktive Bauelemente;TE connectivity
  5802;0;;PAS;;Passive Bauelemente;
  5803;0;"PDZ 4,3B  7""SOD323";AKT;;Aktive Bauelemente;
  5804;0;;MEC;HON;Elektromechanik;Honeywell
  5805;0;;MEC;;Elektromechanik;
  5806;0;;MEC;;Elektromechanik;
  5807;0;;MEC;HON;Elektromechanik;Honeywell
  5809;0;;AKT;ORS;Aktive Bauelemente;Osram Opto Semiconductors
  5810;0;61240090;MEC;;Elektromechanik;
  5811;0;AT89C55WD-24PU;AKT;ATM;Aktive Bauelemente;Atmel
  5815;0;;MEC;;Elektromechanik;
  5816;0;;MEC;;Elektromechanik;
  </code></pre>
  
  <p>I now want to remove all rows that are empty on the colum, *HERSTARTNR like
  the first row. Is this possible with a batch script?</p>
  
  <p>Thank you</p>