title: jQuery plugin .fn question
body: <p>I seem to be having some problems creating a jquery plugin.  I am testing a simple plugin in firebug console and the function is not being defined as I would expect. Here is the code pattern I am using</p>
  
  <pre><code>jQuery.fn.test = function () {console.log("runs")}
  </code></pre>
  
  <p>I am trying to call the function with this call which is not working.</p>
  
  <pre><code>$.test()
  </code></pre>
  
  <p>But this call does</p>
  
  <pre><code>$.fn.test()
  </code></pre>
  
  <p>I don't think this is how it is supposed to work so I think I am doing something wrong, although all the documentation seems to agree that I should be correct.  Any one have any advice?</p>
  
  <p>Thanks,
  Cory</p>