title: using bash (sed/awk) to extract rows AND columns in CSV files?
body: <p>Is bash capable of handling extracting rows and columns from csv files?  Hoping I don't have to resort to python..</p>
  
  <p>My 5-column csv file looks like:</p>
  
  <pre><code>Rank,Name,School,Major,Year
  1,John,Harvard,Computer Science,3
  2,Bill,Yale,Political Science,4
  3,Mark,Stanford,Biology,1
  4,Jane,Princeton,Electrical Engineering,3
  5,Alex,MIT,Management Economics,2
  </code></pre>
  
  <p>I only want to extract the 3rd, 4th, and 5th column contents, ignoring the first row, so output looks like:</p>
  
  <pre><code>Harvard,Computer Science,3
  Yale,Political Science,4
  Stanford,Biology,1
  Princeton,Electrical Engineering,3
  MIT,Management Economics,2
  </code></pre>
  
  <p>So far I can only get awk to print out either each row, or each column of my CSV file, but not specific cols/rows like this case! Can bash do this?</p>