title: How to get rightmost 10 places of a string in oracle
body: <p>I am trying to fetch an id from an oracle table. It's something like <code>TN0001234567890345</code>. What I want is to sort the values according to the right most 10 positions (e.g. <code>4567890345</code>). I am using Oracle 11g. Is there any function to cut the rightmost 10 places in Oracle SQL ?</p>
  
  <p>Thanks in advance</p>
  
  <p>tismon</p>