title: bash - how to remove first 2 lines from output
body: <p>I have the following output in a text file:</p>
  
  <pre><code>106 pages in list
  .bookmarks
  20130516 - Daily Meeting Minutes
  20130517 - Daily Meeting Minutes
  20130520 - Daily Meeting Minutes
  20130521 - Daily Meeting Minutes
  </code></pre>
  
  <p>I'm looking to remove the first 2 lines from my output. This particular shell script that I use to execute, always has those first 2 lines.</p>
  
  <p>This is how I generated and read the file:</p>
  
  <pre><code>#Lists
  PGLIST="$STAGE/pglist.lst";
  RUNSCRIPT="$STAGE/runPagesToMove.sh";
  
  #Get List of pages
  $ATL_BASE/confluence.sh $CMD_PGLIST $CMD_SPACE "$1" &gt; "$PGLIST";
  
  # BUILD executeable script
  echo "#!/bin/bash" &gt;&gt; $RUNSCRIPT 2&gt;&amp;1
  IFS=''
  while read line
    do
       echo "$ATL_BASE/conflunce.sh $CMD_MVPAGE $CMD_SPACE "$1" --title \"$line\" --newSpace \"$2\" --parent \"$3\"" &gt;&gt; $RUNSCRIPT 2&gt;&amp;1
  done &lt; $PGLIST
  </code></pre>
  
  <p>How do I remove those top 2 lines?</p>