title: ggmap Plot by City over Lat/Long
body: <p>I'm trying to create a map using <code>ggmap</code> that plots circles on the coordinates of different cities with a value input as the diameter/radius.</p>
  
  <pre><code>City         Diameter/Radius
  Atlanta      100000
  Chicago      200000
  New York     300000
  Los Angeles  400000
  Miami        500000
  </code></pre>
  
  <p>I have achieved this in the past, but I had to index/match city names to the <code>zipcode</code> data set that contained a list of approximately 3000 cities and their lat/long sets. See below for aggregated data set:</p>
  
  <pre><code>     Date          city Total.Conversions      lat       long    newdate
  1  6/7/15       Chicago            132726 41.85000  -87.65000 2015-06-07
  2 6/11/15      New York            118858 40.75074  -73.99653 2015-06-11
  3 6/10/15       Houston             98766 40.24185  -80.21445 2015-06-10
  4 5/25/15       Atlanta             95496 42.56055  -77.47257 2015-05-25
  5  6/8/15        Dallas             93477 41.34558  -75.97596 2015-06-08
  6 6/12/15 San Francisco             88536 37.78483 -122.72780 2015-06-12
  </code></pre>
  
  <p>Although this seemed like a good idea at first, there was some data loss and overall the outputs weren't correct. The code and output looked like so:</p>
  
  <pre><code>map &lt;- get_map(location=c(lon = -98.35, lat = 39.50), zoom = 4, source="google",maptype="roadmap",crop=FALSE)
  ggmap(map)
  ggmap(map, legend = "none")+geom_point(aes(x = testdata$long, y = testdata$lat), data = testdata, alpha = .7, 
                        color = "darkgreen", size = (testdata$Total.Conversions)/5000)
  </code></pre>
  
  <p><a href="https://i.stack.imgur.com/ZRSqM.jpg" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/ZRSqM.jpg" alt="ggMap"></a></p>
  
  <p><strong>Is there any way to plot data by using city names/DMAs/states rather than using lat/long coordinates?</strong> If so, what is the best way to approach this situation? Your help would be greatly appreciated.</p>
  
  <p>Thanks in advance!</p>