title: Identifying cell in Openpyxl
body: <p>I've been working on a project, in which I search an .xlsx document for a cell containing a specific value "x". I've managed to get so far, but I can't extract the location of said cell. </p>
  
  <p>This is the code I have come up with:</p>
  
  <pre><code>from openpyxl import load_workbook
  wb = load_workbook(filename = 'Abstract.xlsx', use_iterators = True)
  ws = wb.get_sheet_by_name(name = 'Abstract')
  for row in ws.iter_rows():
      for cell in row:
          if cell.value == "E01234":
              print "TRUE"
  </code></pre>
  
  <p>When I run this script, if there is a cell with the value "E01234" in the refereed .xlsx, it prints TRUE. What I need now is to get the row and column address (ie: A4) of the cell with the "E01234" value.
  Further down in my project, </p>
  
  <p>I wish to edit another cell on the same row as the identified one.</p>
  
  <p>Any insights?</p>