title: How to get flow record details of a netflow packet
body: <p>I've used jflow to capture the netflow packets. By running the <a href="https://github.com/aptivate/netgraph/tree/master/jflow-0.3/examples/print">print example</a> I could observe this kind of output. </p>
  
  <pre><code>13.243.146.68.41472 -&gt; 10.100.0.126.13570 285212682 0
  0.43.0.0.18 -&gt; 0.199.0.0.4352 8321715 100
  53.2.7.225.3571 -&gt; 0.0.1.67.37446 323 5
  1.187.0.3.323 -&gt; 6.0.0.10.28807 0 183
  0.0.0.0.0 -&gt; 0.0.0.0.3571 0 10
  1.1.0.53.0 -&gt; 0.18.17.0.323 889257984 26
  0.0.0.0.0 -&gt; 0.0.0.0.0 0 146
  192.168.1.1.6775 -&gt; 0.53.0.18.0 754988289 112
  </code></pre>
  
  <p>This seems to printed inside DatagramSocket.receive(DatagramPacket) method. How can I print these details like host address , destination address etc of a netflow record on my own. </p>
  
  <p>Also I couldn't figure out what's meant by the last two parameters of above output.</p>