title: setting the startup position of child form in vb.net
body: <p>I have a Mdi parent container and i am using menu item to open child forms in MDI Parent Form.</p>
  
  <p>Here is the code for opening the child form</p>
  
  <pre><code>Dim childform1 as new Form3
  childform1.MDIParent = me
  childform1.show()
  </code></pre>
  
  <p>The above code is working fine. The problem is with the startup position of the child form. i.e. child form doesn't open at required position(just right below the menubar) instead it opens at position randomly. like sometimes near the required position and other times where it wishes.. lol is there any standard way to position it. I tried <a href="https://stackoverflow.com/questions/1811821/mdi-child-form-start-position-problem">MDI Child Form Start Position Problem</a> answer by calculating and its positioned near by where i want. But I want to look for a standard way for doing this.</p>