title: how to execute two commands stored in one bash variable
body: <p>Let's say there is one bash variable </p>
  
  <blockquote>
    <p>run1="date"</p>
  </blockquote>
  
  <p>I need to execute <code>date</code> by </p>
  
  <blockquote>
    <p>${run1}</p>
  </blockquote>
  
  <p>And it works, since it prints current time. But if I put two commands in the variable,</p>
  
  <blockquote>
    <p>run2="date; echo foo"</p>
  </blockquote>
  
  <p>I can't execute the commands stored in variable <code>run2</code>, since <code>${run2}</code> complains </p>
  
  <blockquote>
    <p>date;: command not found</p>
  </blockquote>