title: Not able to jump from tableViewCell to another viewController using segue
body: <p>Hi I'm new to swift and Xcode 6 so I tried to perform the segue to jump from cell to another viewController shown as below:-</p>
  
  <p><img src="https://i.stack.imgur.com/51jnZ.png" alt="Segue using storyboard"></p>
  
  <p>Also I tried to go programmatically with below code:-</p>
  
  <pre><code> override func tableView(tableView: UITableView, didSelectRowAtIndexPath indexPath: NSIndexPath) {
      println("selected row \(indexPath.row)")
      self.performSegueWithIdentifier("segueCust", sender: self)
  }
  </code></pre>
  
  <p>Still I'm not able to perform and if run above code then app crash with following error:-</p>
  
  <pre><code>Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Receiver (&lt;swiftDemo.DetailTableViewController: 0x7fdab1606ee0&gt;) has no segue with identifier 'segueCust''
  </code></pre>
  
  <p>No idea why this error is coming as in storyboard I have assigned the segue with this identifier.</p>
  
  <p>Moreover,below segue method is never called.</p>
  
  <pre><code> override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject!)
  </code></pre>
  
  <p>Also I have add a button and perform segue using storyboard from one viewController to another then it's working fine.
  So far I might be missing or doing a silly mistake. Any help would be appreciated.
  Thanks in advance.</p>