title: Unix Bash Script running but no output
body: <p>I'm trying to create a bash script that will loop through a set of files according to their file type and then create a directory with the file name and then run the file through a javascript and have it outputted into the created directory.</p>
  
  <pre><code>#!/bin/bash
  
  FILES=/home/ndevon/BRAD/Original_Files/*60_R1.fastq.gz
  for f in $FILES
  do
       echo mkdir $f
       echo nohup /home/pszoevenyi/executables/FastQC/./fastqc [-t 2] [-o $f] [-
  f fastq] $f &amp;
  done
  </code></pre>
  
  <p>However when I run this everything seems to work correctly but there is no output. I have checked the active jobs using ps x and it tells me that there is a -bash command type in the queue but it has a Ss status. I'm very new to unix and bash, I actually started today but I cannot figure out why this isn't working. </p>
  
  <p>Thanks</p>