title: Use a function for each of the ways you're printing out things?
body: <p>Rewrite this program to use a function for each of the ways you're printing out things. Try to pass pointers to these functions so they work on the data. Remember you can declare a function to accept a pointer, but just use it like an array.</p>
  
  <p>How do you do? I have c code which are with for looping printing out index array and pointer index. Here right code without function:</p>
  
  <pre><code>       int main(int argc, char * argv[])
         {
  
         int number[] = {123, 456, 789};
         char *strchars[] = {
           "ABC", "DEF", "GHI"
         };
  
         int count = sizeof(number) / sizeof(int);
         int i = 0;
  
         for(i = 0; i &lt; count; i++) {
            printf("%s has %d \n", strchars[i], number[i]);
         }
  
         // with pointers
  
         int *po_number = number;
         char **po_strchars = strchars;
  
         // loop with pointiers
  
         for(i = 0; i &lt; count; i++) {
             printf("%s has %d \n", *(po_strchars+i), *(po_number+i));
         }
         return 0;
      }
  </code></pre>
  
  <p>But i need use for each of the ways printing out things. But I can't figure out. Here my code with functions but without pointer and chars only integer. Give me how to make it right:</p>
  
  <pre><code>    #include &lt;stdio.h&gt;
      // void print_arg(int a[], int b[]);
  
      // now it right?
  
      // void print_arg(int a[], int b[])
  
      void print_arg(int a, int b);
  
      // or now it right?
  
      void print_arg(int a, int b)
      {
            int a;
            int b;
            int count = sizeof(a) / sizeof(int);
            int i = 0;
                //and it
            for(i = 0; i &lt; count; i++) {
                printf("%d and %d\n", a[i], b[i]);
            }
      } 
  
      int main(void)
      {
            int number[] = {22, 32, 22, 82, 2};
            int strchars[] = {12, 12, 12, 12, 12};
  
            int count = sizeof(number) / sizeof(int);
            print_arg(number[], strchars[]);
  
            return 0;
      }
  </code></pre>