title: Greater than float with awk
body: <p>I found some questions about this, but none of them really answered to my question.</p>
  
  <p>I have a tabulated file like this:</p>
  
  <pre><code>2   10610   0   0   0   0.0105292
  2   10649   0   0   0   0.041959
  2   10682   0   0   0   0.0449746
  2   10705   0   0   0   0.0441639
  2   10797   2   0   0   0.0342728
  2   10955   0   0   0   0.0136986
  2   10957   0   0   0   0.0135135
  2   11124   0   0   0   0.0583367
  2   11336   1   0   0   0.0219502
  </code></pre>
  
  <p>and I used this command: </p>
  
  <pre><code>awk '{if ($6 &gt; 0.4) print $6}' myfile
  </code></pre>
  
  <p>And here is the output:</p>
  
  <pre><code>0.0105292
  0.041959
  0.0449746
  0.0441639
  0.0342728
  0.0136986
  0.0135135
  0.0583367
  0.0219502
  </code></pre>
  
  <p>It's returning all the value for the 6th column. Here i should get no results since the condition is not respected. So I guess awk is not considering $6 as a float.</p>
  
  <p>I tried other syntax but I still have the same problem.</p>
  
  <p>I also tried the command on the first column and there it's working...</p>
  
  <p>ps: I'm on MacOSX</p>
  
  <p><strong>Edit:</strong> Though it's working when I use awk '{print $6}' </p>