title: Fastest way of submitting shelved changelist
body: <p>I have shelved a changelist(say X) and I have ensured its correctness. Now i want to submit the changelist. I can </p>
  
  <ol>
  <li>p4 unshelve -s X -c Y where Y is a new changelist i create before executing this command.
  Then p4 shelve -c X -d and lastly p4 submit -c Y</li>
  <li>Otherwise I can unshelve X, delete the shelve X and move the local copies to changelist X(p4 reopen -c X  ) and submit X.</li>
  <li>The last option is to unshelve X, delete shelve X, p4 change(and edit description) and finally p4 submit</li>
  </ol>
  
  <p>What are your suggestions with regards to :-</p>
  
  <ol>
  <li>Use 1/3 but copy paste the description that X already had to new changelists</li>
  <li>Use 2 but copy each opened file manually in command p4 reopen.</li>
  </ol>
  
  <p>The only advantage of 2 over 1 and 3 is that I don't have to delete X(because it turned out to be my submitted changelist, while in other cases it still is "pending").</p>