title: print every nth line into a row using gawk
body: <p>I have a very huge file in which I need to obtain every nth line and print it into a row.</p>
  
  <p>My data:</p>
  
  <pre><code>1      937  4.320194
  2      667  4.913314
  3      934  1.783326
  4      940  -0.299312
  5      939  2.309559
  6      936  3.229496
  7      611  -1.41808
  8      608  -1.154019
  9      606  2.159683
  10     549  0.767828
  </code></pre>
  
  <p>I want my data to look like this:</p>
  
  <pre><code>1      937  4.320194
  3      934  1.783326
  5      939  2.309559
  7      611  -1.41808
  9      606  2.159683
  </code></pre>
  
  <p>This is of course an example, I want every 10th line for my huge data file.  I tried this so far:</p>
  
  <pre><code> NF == 6 {
       if(NR%10) {print;}
       }
  </code></pre>