title: Linux bash script to extract IP address
body: <p>I want to make big script on my Debian 7.3 ( something like translated and much more new user friendly enviroment ). I have a problem. I want to use only some of the informations that commands give me. For example my ifconfig looks like:</p>
  
  <pre><code>eth0      Link encap:Ethernet  HWaddr 08:00:27:a3:e3:b0  
            inet addr:192.168.1.103  Bcast:192.168.1.255  Mask:255.255.255.0
            inet6 addr: fe80::a00:27ff:fea3:e3b0/64 Scope:Link
            UP BROADCAST RUNNING MULTICAST  MTU:1500  Metric:1
            RX packets:1904 errors:0 dropped:0 overruns:0 frame:0
            TX packets:2002 errors:0 dropped:0 overruns:0 carrier:0
            collisions:0 txqueuelen:1000 
            RX bytes:1309425 (1.2 MiB)  T
  </code></pre>
  
  <p>I want to display only the IP address in line: echo "Your IP address is: (IP_ADDRESS )". Is there any command that allow me to do such a thing, to search in stream for informations I want to get?. I know about <code>grep</code> and <code>sed</code> but I am not really good with them.</p>
  
  <p>Edit: Firstly to say thank you for helping me with this problem, now I know much more. Secondly to say project is in progress. If anyone would be interested in it just pm me. </p>