The order of this field being 26, and the divisors of 6 being 1, 2, 3, 6, the subfields of GF(64) are GF(2), GF(22) = GF(4), GF(23) = GF(8), and GF(64) itself.
Ред овог поља 26 и делитељи 6 су 1, 2, 3, 6, подпоља GF(64) су GF(2), GF(22) = GF(4), GF(23) = GF(8) и GF(64) .