98 {\displaystyle \!{\bar {X}}-0{.}98} and X ¯ + 0.98. {\displaystyle \!{\bar {X}}+0.98.} This does not mean there is 0.95 probability that the value of parameter μ is in the interval obtained by using the currently computed value of the sample mean, ( x ¯ − 0.98 , x ¯ + 0.98 ) . {\displaystyle ({\bar {x}}-0.98,\,{\bar {x}}+0.98).} Instead, every time the measurements are repeated, there will be another value for the mean X of the sample.
98 {\displaystyle \!{\bar {X}}-0{.}98} e X ¯ + 0.98. {\displaystyle \!{\bar {X}}+0.98.} Isto non implica que hai unha probabilidade de 0.95 de atopar o parámetro μ no intervalo obtido empregando o valor efectivamente establecido para o valor medio da mostra. ( x ¯ − 0.98 , x ¯ + 0.98 ) . {\displaystyle ({\bar {x}}-0.98,\,{\bar {x}}+0.98).} Cada vez que se repitan as medicións, darán outro valor para a media X da mostra.