description: Petya has got an interesting flower. Petya is a busy person, so he sometimes forgets to water it. You are given n days from Petya's live and you have to determine what happened with his flower in the end.
  
  The flower grows as follows: 
  
    * If the flower isn't watered for two days in a row, it dies. 
    * If the flower is watered in the i-th day, it grows by 1 centimeter. 
    * If the flower is watered in the i-th and in the (i-1)-th day (i > 1), then it grows by 5 centimeters instead of 1. 
    * If the flower is not watered in the i-th day, it does not grow. 
  
  
  
  At the beginning of the 1-st day the flower is 1 centimeter tall. What is its height after n days?
  
  Input
  
  Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
  
  The first line of each test case contains the only integer n (1 ≤ n ≤ 100).
  
  The second line of each test case contains n integers a_1, a_2, ..., a_n (a_i = 0 or a_i = 1). If a_i = 1, the flower is watered in the i-th day, otherwise it is not watered.
  
  Output
  
  For each test case print a single integer k — the flower's height after n days, or -1, if the flower dies.
  
  Example
  
  Input
  
  
  4
  3
  1 0 1
  3
  0 1 1
  4
  1 0 0 1
  1
  0
  
  
  Output
  
  
  3
  7
  -1
  1
solution: from collections import Counter
  from math import ceil,floor,log2,gcd
  import bisect as bs
  #sorted(x.items(), key=lambda item: item[1])
  import sys
  input = sys.stdin.readline
  inp_lis = lambda: list(map(int, input().split()))      
  inp_multi=lambda: map(int,input().split())
  inp_int=lambda: int(input().strip())
  
  
  
  
  
  for _ in range(int(input().strip())):
      n=inp_int()
      a=inp_lis()
      c=1
      d=0
      for i in range(n):
          
          
          if a[i]==1:
              d=0
              
              if i!=0 and a[i-1]==1:
                  # print(i)
                  c+=5
              else:
                  c+=1
          else:
              
              d+=1
          if d==2:
              print(-1)
              break
                      
      if d!=2:
          print(c)
      
           
      