description: Petya has got an interesting flower. Petya is a busy person, so he sometimes forgets to water it. You are given n days from Petya's live and you have to determine what happened with his flower in the end.
  
  The flower grows as follows: 
  
    * If the flower isn't watered for two days in a row, it dies. 
    * If the flower is watered in the i-th day, it grows by 1 centimeter. 
    * If the flower is watered in the i-th and in the (i-1)-th day (i > 1), then it grows by 5 centimeters instead of 1. 
    * If the flower is not watered in the i-th day, it does not grow. 
  
  
  
  At the beginning of the 1-st day the flower is 1 centimeter tall. What is its height after n days?
  
  Input
  
  Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
  
  The first line of each test case contains the only integer n (1 ≤ n ≤ 100).
  
  The second line of each test case contains n integers a_1, a_2, ..., a_n (a_i = 0 or a_i = 1). If a_i = 1, the flower is watered in the i-th day, otherwise it is not watered.
  
  Output
  
  For each test case print a single integer k — the flower's height after n days, or -1, if the flower dies.
  
  Example
  
  Input
  
  
  4
  3
  1 0 1
  3
  0 1 1
  4
  1 0 0 1
  1
  0
  
  
  Output
  
  
  3
  7
  -1
  1
solution: import java.util.*;
  public class Main{
       public static void main(String args[]){
            Scanner sc=new Scanner(System.in);
            int t=sc.nextInt();
            for(int q=0;q<t;q++){
                 int growth=1;
                 int n=sc.nextInt();
                 int a[]=new int[n];
                 for(int i=0;i<n;i++)
                   a[i]=sc.nextInt();
                 for(int i=0;i<n;i++){
                      if(a[i]==0){
                          if(i+1<a.length&&a[i+1]==0){
                              growth=-1;
                              break;
                          }
                      }
                        
                       else if(a[i]==1){
                            if(i-1>=0&&a[i-1]==1){
                                 growth+=5;
                                 
                            }
                            else
                                growth+=1;
                       }
                 }
                 System.out.println(growth);
            }
       }
  }