description: You are given three integers n, a, b. Determine if there exists a permutation p_1, p_2, …, p_n of integers from 1 to n, such that:
  
    * There are exactly a integers i with 2 ≤ i ≤ n-1 such that p_{i-1} < p_i > p_{i+1} (in other words, there are exactly a local maximums).
  
    * There are exactly b integers i with 2 ≤ i ≤ n-1 such that p_{i-1} > p_i < p_{i+1} (in other words, there are exactly b local minimums).
  
  
  
  
  If such permutations exist, find any such permutation.
  
  Input
  
  The first line of the input contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases. The description of test cases follows.
  
  The only line of each test case contains three integers n, a and b (2 ≤ n ≤ 10^5, 0 ≤ a,b ≤ n).
  
  The sum of n over all test cases doesn't exceed 10^5.
  
  Output
  
  For each test case, if there is no permutation with the requested properties, output -1.
  
  Otherwise, print the permutation that you are found. If there are several such permutations, you may print any of them.
  
  Example
  
  Input
  
  
  3
  4 1 1
  6 1 2
  6 4 0
  
  
  Output
  
  
  1 3 2 4
  4 2 3 1 5 6
  -1
  
  Note
  
  In the first test case, one example of such permutations is [1, 3, 2, 4]. In it p_1 < p_2 > p_3, and 2 is the only such index, and p_2> p_3 < p_4, and 3 the only such index.
  
  One can show that there is no such permutation for the third test case.
solution: problem_num = int(input())
  for i in range(problem_num):
      arr = list(map(int,input().split()))
      if abs(arr[1]-arr[2])>=2 or arr[1] + arr[2] > arr[0] - 2:
          print(-1)
          continue
  
      init = 0
      lst = [init]
      if arr[1]>arr[2]:
          for j in range(arr[1]):
              lst.append(init + j + 1)
              lst.append(init - j - 1)
          for j in range(arr[0]-arr[1]-arr[2]-2):
              lst.append(init-j-arr[1]-1)
      if arr[1]<arr[2]:
          for j in range(arr[2]):
              lst.append(init - j - 1)
              lst.append(init + j + 1)
          for j in range(arr[0]-arr[1]-arr[2]-2):
              lst.append(init+j+arr[2]+1)
      if arr[1]==arr[2]:
          for j in range(arr[2]):
              lst.append(init + j + 1)
              lst.append(init - j - 1)
          for j in range(arr[0]-arr[1]-arr[2]-1):
              lst.append(init+j+arr[2]+1)
      min_val = min(lst)
      lst = [str(i-min_val+1) for i in lst]
      print(' '.join(lst))
  