description: Theofanis has a riddle for you and if you manage to solve it, he will give you a Cypriot snack halloumi for free (Cypriot cheese).
  
  You are given an integer n. You need to find two integers l and r such that -10^{18} ≤ l < r ≤ 10^{18} and l + (l + 1) + … + (r - 1) + r = n.
  
  Input
  
  The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases.
  
  The first and only line of each test case contains a single integer n (1 ≤ n ≤ 10^{18}).
  
  Output
  
  For each test case, print the two integers l and r such that -10^{18} ≤ l < r ≤ 10^{18} and l + (l + 1) + … + (r - 1) + r = n. 
  
  It can be proven that an answer always exists. If there are multiple answers, print any.
  
  Example
  
  Input
  
  
  7
  1
  2
  3
  6
  100
  25
  3000000000000
  
  
  Output
  
  
  0 1
  -1 2 
  1 2 
  1 3 
  18 22
  -2 7
  999999999999 1000000000001
  
  Note
  
  In the first test case, 0 + 1 = 1.
  
  In the second test case, (-1) + 0 + 1 + 2 = 2.
  
  In the fourth test case, 1 + 2 + 3 = 6.
  
  In the fifth test case, 18 + 19 + 20 + 21 + 22 = 100.
  
  In the sixth test case, (-2) + (-1) + 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 = 25.
solution: import java.io.BufferedOutputStream;
  import java.io.BufferedReader;
  import java.io.IOException;
  import java.io.InputStreamReader;
  import java.io.PrintWriter;
  import java.util.StringTokenizer;
  
  public class Main {
  
    public static PrintWriter out;
  
    public static void main(String[] args) throws Exception {
      MyScanner ms = new MyScanner();
      out = new PrintWriter(new BufferedOutputStream(System.out));
      int t = ms.nextInt();
      while (t-- > 0) {
        long n = ms.nextLong();
        long a = -n + 0l + 1l;
        System.out.println(a + " " + n);
      }
      out.close();
    }
  
    static class MyScanner {
      BufferedReader br;
      StringTokenizer st;
  
      public MyScanner() {
        br = new BufferedReader(new InputStreamReader(System.in));
      }
  
      String next() {
        while (st == null || !st.hasMoreElements()) {
          try {
            st = new StringTokenizer(br.readLine());
          } catch (IOException e) {
            e.printStackTrace();
          }
        }
        return st.nextToken();
      }
  
      int nextInt() {
        return Integer.parseInt(next());
      }
  
      long nextLong() {
        return Long.parseLong(next());
      }
  
      double nextDouble() {
        return Double.parseDouble(next());
      }
  
      String nextLine() {
        String str = "";
        try {
          str = br.readLine();
        } catch (IOException e) {
          e.printStackTrace();
        }
        return str;
      }
    }
  }
  