description: You are given three integers n, a, b. Determine if there exists a permutation p_1, p_2, …, p_n of integers from 1 to n, such that:
  
    * There are exactly a integers i with 2 ≤ i ≤ n-1 such that p_{i-1} < p_i > p_{i+1} (in other words, there are exactly a local maximums).
  
    * There are exactly b integers i with 2 ≤ i ≤ n-1 such that p_{i-1} > p_i < p_{i+1} (in other words, there are exactly b local minimums).
  
  
  
  
  If such permutations exist, find any such permutation.
  
  Input
  
  The first line of the input contains a single integer t (1 ≤ t ≤ 10^4) — the number of test cases. The description of test cases follows.
  
  The only line of each test case contains three integers n, a and b (2 ≤ n ≤ 10^5, 0 ≤ a,b ≤ n).
  
  The sum of n over all test cases doesn't exceed 10^5.
  
  Output
  
  For each test case, if there is no permutation with the requested properties, output -1.
  
  Otherwise, print the permutation that you are found. If there are several such permutations, you may print any of them.
  
  Example
  
  Input
  
  
  3
  4 1 1
  6 1 2
  6 4 0
  
  
  Output
  
  
  1 3 2 4
  4 2 3 1 5 6
  -1
  
  Note
  
  In the first test case, one example of such permutations is [1, 3, 2, 4]. In it p_1 < p_2 > p_3, and 2 is the only such index, and p_2> p_3 < p_4, and 3 the only such index.
  
  One can show that there is no such permutation for the third test case.
solution: 
  import java.io.BufferedReader;
  import java.io.IOException;
  import java.io.InputStreamReader;
  import java.util.*;
  public class bb{
  	public static void main(String[] args){
  		FastReader sc = new FastReader();
  		int t=sc.nextInt();
  		while(t-->0){
  			int n=sc.nextInt();
  			int a=sc.nextInt();
  			int b=sc.nextInt();
  			int p=n-(a+b)-2;
  			int tol=n-2;
  			if(p<0)System.out.println(-1);
  			else {
  				int ceil=(int)Math.ceil(tol/2d);
  				int dif=Math.abs(a-b);
  				if(a>ceil || b>ceil|| dif>1) System.out.println(-1);
  				else {
  					int ans[]= new int [n];
  					if(a>b) { // HLH
  						int h=n;
  						for(int i=1;i<n && a>0;i+=2) {
  							ans[i]=h--;
  							a--;
  						}
  						for(int i=0;i<n;i++) {
  							if(ans[i]==0)ans[i]=h--;
  						}
  						  
  					}else if(b>a) { // LHL
  						int l=1;
  						for(int i=1;i<n && b>0;i+=2) {
  							ans[i]=l++;
  							b--;
  						}
  						for(int i=0;i<n;i++) {
  							if(ans[i]==0)ans[i]=l++;
  						}
  					}else {
  						int h=n;int l=1;
  						for(int i=1;i<n && a>0;i+=2) {
  							ans[i]=h--;
  							a--;
  						}
  						for(int i=0;i<n && l<=h;i++) {
  							if(ans[i]==0)ans[i]=l++;
  						}
  					}
  					print(ans);
  				}
  			}
  		}		 
      }
  
  	static class pair {
  		int x;int y;
  		 pair(int x,int y){
  			this.x=x;
  			this.y=y;
  		}
  		
  	}
  	static void sort(int a[]) {
  		ArrayList<Integer> aa= new ArrayList<>();
  		for(int i:a)aa.add(i);
  		Collections.sort(aa);
  		int j=0;
  		for(int i:aa)a[j++]=i;
  	}
  	static ArrayList<Integer> primeFac(int n){
  		ArrayList<Integer>ans = new ArrayList<Integer>();
  		int lp[]=new int [n+1];
  		Arrays.fill(lp, 0);  	//0-prime
  		for(int i=2;i<=n;i++) {
  			if(lp[i]==0) {
  				for(int j=i;j<=n;j+=i) {
  					if(lp[j]==0) lp[j]=i;
  				}
  			}
  		}
  		int fac=n;
  		while(fac>1) {
  			ans.add(lp[fac]);
  			fac=fac/lp[fac];
  		}
  		print(ans);
  		return ans;
  	}
  	static ArrayList<Long> prime_in_given_range(long l,long r){
  		ArrayList<Long> ans= new ArrayList<>();
  		int n=(int)Math.sqrt(r)+1;
  		int prime[]=sieve_of_Eratosthenes(n);
  		long res[]=new long [(int)(r-l)+1];
  		for(int i=0;i<=r-l;i++) {
  			res[i]=i+l;
  		}
  		for(int i=0;i<prime.length;i++) {
  			if(prime[i]==1) {
  				System.out.println(2);
  				for(int j=Math.max((int)i*i, (int)(l+i-1)/i*i);j<=r;j+=i) {
  					res[j-(int)l]=0; 
  				}
  			}
  		}
  		for(long i:res) if(i!=0)ans.add(i);
  		return ans;
  	}
  	static int [] sieve_of_Eratosthenes(int n) {
  		int prime[]=new int [n];
  		Arrays.fill(prime, 1);  // 1-prime | 0-not prime
  		prime[0]=prime[1]=0;
  		for(int i=2;i<n;i++) {
  			if(prime[i]==1) {
  				for(int j=i*i;j<n;j+=i) {
  					prime[j]=0;
  				}
  			}
  		}
  		return prime;
  	}
  	static long binpow(long a,long b) {
  		long res=1;
  		if(b==0)return a;
  		if(a==0)return 1;
  		while(b>0) {
  			if((b&1)==1) {
  				res*=a;
  			}
  			a*=a;
  			b>>=1;
  		}
  		return res;
  	}
  	static void print(int a[]) {
  		for(int i:a) {
  			System.out.print(i+" ");
  		}
  		System.out.println();
  	}
  	static void print(long a[]) {
  		System.out.println(a.length);
  		for(long i:a) {
  			System.out.print(i+" ");
  		}
  		System.out.println();
  	}
  	static void print(ArrayList<Integer> a) {
  		System.out.println(a.size());
  		for(long i:a) {
  			System.out.print(i+" ");
  		}
  		System.out.println();
  	}
  	static class FastReader {
  		BufferedReader br;
  		StringTokenizer st;
  
  		public FastReader()
  		{
  			br = new BufferedReader(
  				new InputStreamReader(System.in));
  		}
  		int [] fastArray(int n) {
  			int a[]=new int [n];
  			for(int i=0;i<n;i++) {
  				a[i]=nextInt();
  			}
  			return a;
  		}
  		String next()
  		{
  			while (st == null || !st.hasMoreElements()) {
  				try {
  					st = new StringTokenizer(br.readLine());
  				}
  				catch (IOException e) {
  					e.printStackTrace();
  				}
  			}
  			return st.nextToken();
  		}
  
  		int nextInt() { return Integer.parseInt(next()); }
  
  		long nextLong() { return Long.parseLong(next()); }
  
  		double nextDouble()
  		{
  			return Double.parseDouble(next());
  		}
  
  		String nextLine()
  		{
  			String str = "";
  			try {
  				str = br.readLine();
  			}
  			catch (IOException e) {
  				e.printStackTrace();
  			}
  			return str;
  		}
  	}
  
  }