description: Vlad has n friends, for each of whom he wants to buy one gift for the New Year.
  
  There are m shops in the city, in each of which he can buy a gift for any of his friends. If the j-th friend (1 ≤ j ≤ n) receives a gift bought in the shop with the number i (1 ≤ i ≤ m), then the friend receives p_{ij} units of joy. The rectangular table p_{ij} is given in the input.
  
  Vlad has time to visit at most n-1 shops (where n is the number of friends). He chooses which shops he will visit and for which friends he will buy gifts in each of them.
  
  Let the j-th friend receive a_j units of joy from Vlad's gift. Let's find the value α=min\\{a_1, a_2, ..., a_n\}. Vlad's goal is to buy gifts so that the value of α is as large as possible. In other words, Vlad wants to maximize the minimum of the joys of his friends.
  
  For example, let m = 2, n = 2. Let the joy from the gifts that we can buy in the first shop: p_{11} = 1, p_{12}=2, in the second shop: p_{21} = 3, p_{22}=4.
  
  Then it is enough for Vlad to go only to the second shop and buy a gift for the first friend, bringing joy 3, and for the second — bringing joy 4. In this case, the value α will be equal to min\{3, 4\} = 3
  
  Help Vlad choose gifts for his friends so that the value of α is as high as possible. Please note that each friend must receive one gift. Vlad can visit at most n-1 shops (where n is the number of friends). In the shop, he can buy any number of gifts.
  
  Input
  
  The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input.
  
  An empty line is written before each test case. Then there is a line containing integers m and n (2 ≤ n, 2 ≤ n ⋅ m ≤ 10^5) separated by a space — the number of shops and the number of friends, where n ⋅ m is the product of n and m.
  
  Then m lines follow, each containing n numbers. The number in the i-th row of the j-th column p_{ij} (1 ≤ p_{ij} ≤ 10^9) is the joy of the product intended for friend number j in shop number i.
  
  It is guaranteed that the sum of the values n ⋅ m over all test cases in the test does not exceed 10^5.
  
  Output
  
  Print t lines, each line must contain the answer to the corresponding test case — the maximum possible value of α, where α is the minimum of the joys from a gift for all of Vlad's friends.
  
  Example
  
  Input
  
  
  5
  
  2 2
  1 2
  3 4
  
  4 3
  1 3 1
  3 1 1
  1 2 2
  1 1 3
  
  2 3
  5 3 4
  2 5 1
  
  4 2
  7 9
  8 1
  9 6
  10 8
  
  2 4
  6 5 2 1
  7 9 7 2
  
  
  Output
  
  
  3
  2
  4
  8
  2
solution: import java.io.*;
  import java.util.*;
   
  public class Solution extends PrintWriter {
      
      
      void solve() {
          int t = sc.nextInt();
          for(int i = 1; i <= t; i++) {
              test_case();
          }
      }
      
      void test_case() {
          m = sc.nextInt();
          n = sc.nextInt();
          p = new int[m][n];
          for(int i = 0; i < m; i++) {
              for(int j = 0; j < n; j++) {
                  p[i][j] = sc.nextInt();
              }
          }
          
          int[] best = new int[n]; 
          for(int j = 0; j < n; j++) {
              for(int i = 0; i < m; i++) {
                  best[j] = Math.max(best[j], p[i][j]);
              }
          }
          
          int ans = 0;
          for(int i = 0; i < m; i++) {
              int[][] cp = new int[n][2];
              TreeMap<Integer, Integer> freq = new TreeMap<>();
              for(int j = 0; j < n; j++) {
                  cp[j][0] = p[i][j];
                  cp[j][1] = j;
                  freq.put(best[j], freq.getOrDefault(best[j], 0) + 1);
              }
              Arrays.sort(cp, Comparator.comparing(arr -> arr[0]));
              int right = 0;
              for(int j = n-1; j >= 0; j--) {
                  freq.put(best[cp[j][1]], freq.get(best[cp[j][1]])-1);
                  if(freq.get(best[cp[j][1]]) == 0) freq.remove(best[cp[j][1]]);
                  right = cp[j][0];
                  if(j <= n-2) {
                      ans = Math.max(ans, Math.min(freq.isEmpty()?1<<30:freq.firstKey(), right));
                  }
              }
          }
          println(ans);
      }
      
      int n;
      int m;
      int[][] p;
      
          
  //  Main() throws FileNotFoundException { super(new File("output.txt")); }
  //  InputReader sc = new InputReader(new FileInputStream("test_input.txt"));
    Solution() { super(System.out); }
    InputReader sc = new InputReader(System.in);
    static class InputReader {
        InputReader(InputStream in) { this.in = in; } InputStream in;
        
        private byte[] buf = new byte[16384];
        private int    curChar;
        private int    numChars;
        
   
        public int read() {
            if (numChars == -1)
                throw new InputMismatchException();
            if (curChar >= numChars) {
                curChar = 0;
                try {
                    numChars = in.read(buf);
                } catch (IOException e) {
                    throw new InputMismatchException();
                }
                if (numChars <= 0)
                    return -1;
            }
            return buf[curChar++];
        }
   /*
        private String nextLine() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            StringBuilder res = new StringBuilder();
            do {
                res.appendCodePoint(c);
                c = read();
            } while (!isEndOfLine(c));
            return res.toString();
        }*/
   
        public String nextString() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            StringBuilder res = new StringBuilder();
            do {
                res.appendCodePoint(c);
                c = read();
            } while (!isSpaceChar(c));
            return res.toString();
        }
   
        public long nextLong() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = read();
            }
            long res = 0;
            do {
                if (c < '0' || c > '9')
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = read();
            } while (!isSpaceChar(c));
            return res * sgn;
        }
   
        public int nextInt() {
            int c = read();
            while (isSpaceChar(c))
                c = read();
            int sgn = 1;
            if (c == '-') {
                sgn = -1;
                c = read();
            }
            int res = 0;
            do {
                if (c < '0' || c > '9')
                    throw new InputMismatchException();
                res *= 10;
                res += c - '0';
                c = read();
            } while (!isSpaceChar(c));
            return res * sgn;
        }
   
        private boolean isSpaceChar(int c) {
            return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
        }
   
        private boolean isEndOfLine(int c) {
            return c == '\n' || c == '\r' || c == -1;
        }
    }
   
      public static void main(String[] $) {
          new Thread(null, new Runnable() {
              public void run() {
                  long start = System.nanoTime();
                  try {Solution solution = new Solution(); solution.solve(); solution.flush();} 
                  catch (Exception e) {e.printStackTrace(); System.exit(1);}
                  System.err.println((System.nanoTime()-start)/1E9);
              }
          }, "1", 1 << 27).start();
   
      }
  }