description: Vlad has n friends, for each of whom he wants to buy one gift for the New Year.
  
  There are m shops in the city, in each of which he can buy a gift for any of his friends. If the j-th friend (1 ≤ j ≤ n) receives a gift bought in the shop with the number i (1 ≤ i ≤ m), then the friend receives p_{ij} units of joy. The rectangular table p_{ij} is given in the input.
  
  Vlad has time to visit at most n-1 shops (where n is the number of friends). He chooses which shops he will visit and for which friends he will buy gifts in each of them.
  
  Let the j-th friend receive a_j units of joy from Vlad's gift. Let's find the value α=min\\{a_1, a_2, ..., a_n\}. Vlad's goal is to buy gifts so that the value of α is as large as possible. In other words, Vlad wants to maximize the minimum of the joys of his friends.
  
  For example, let m = 2, n = 2. Let the joy from the gifts that we can buy in the first shop: p_{11} = 1, p_{12}=2, in the second shop: p_{21} = 3, p_{22}=4.
  
  Then it is enough for Vlad to go only to the second shop and buy a gift for the first friend, bringing joy 3, and for the second — bringing joy 4. In this case, the value α will be equal to min\{3, 4\} = 3
  
  Help Vlad choose gifts for his friends so that the value of α is as high as possible. Please note that each friend must receive one gift. Vlad can visit at most n-1 shops (where n is the number of friends). In the shop, he can buy any number of gifts.
  
  Input
  
  The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input.
  
  An empty line is written before each test case. Then there is a line containing integers m and n (2 ≤ n, 2 ≤ n ⋅ m ≤ 10^5) separated by a space — the number of shops and the number of friends, where n ⋅ m is the product of n and m.
  
  Then m lines follow, each containing n numbers. The number in the i-th row of the j-th column p_{ij} (1 ≤ p_{ij} ≤ 10^9) is the joy of the product intended for friend number j in shop number i.
  
  It is guaranteed that the sum of the values n ⋅ m over all test cases in the test does not exceed 10^5.
  
  Output
  
  Print t lines, each line must contain the answer to the corresponding test case — the maximum possible value of α, where α is the minimum of the joys from a gift for all of Vlad's friends.
  
  Example
  
  Input
  
  
  5
  
  2 2
  1 2
  3 4
  
  4 3
  1 3 1
  3 1 1
  1 2 2
  1 1 3
  
  2 3
  5 3 4
  2 5 1
  
  4 2
  7 9
  8 1
  9 6
  10 8
  
  2 4
  6 5 2 1
  7 9 7 2
  
  
  Output
  
  
  3
  2
  4
  8
  2
solution: import java.util.*;
  import java.io.*;
  import java.math.*;
  import java.lang.*;
  
  public class NewYearsProblem {
      
      // static int mod = 998244353;
      static int mod = 1000000007;
  
      public static class Reader {
          final private int BUFFER_SIZE = 1 << 16;
          private DataInputStream din;
          private byte[] buffer;
          private int bufferPointer, bytesRead;
   
          public Reader()
          {
              din = new DataInputStream(System.in);
              buffer = new byte[BUFFER_SIZE];
              bufferPointer = bytesRead = 0;
          }
   
          public Reader(String file_name) throws IOException
          {
              din = new DataInputStream(
                  new FileInputStream(file_name));
              buffer = new byte[BUFFER_SIZE];
              bufferPointer = bytesRead = 0;
          }
   
          public String readLine() throws IOException
          {
              byte[] buf = new byte[64]; // line length
              int cnt = 0, c;
              while ((c = read()) != -1) {
                  if (c == '\n') {
                      if (cnt != 0) {
                          break;
                      }
                      else {
                          continue;
                      }
                  }
                  buf[cnt++] = (byte)c;
              }
              return new String(buf, 0, cnt);
          }
   
          public int nextInt() throws IOException
          {
              int ret = 0;
              byte c = read();
              while (c <= ' ') {
                  c = read();
              }
              boolean neg = (c == '-');
              if (neg)
                  c = read();
              do {
                  ret = ret * 10 + c - '0';
              } while ((c = read()) >= '0' && c <= '9');
   
              if (neg)
                  return -ret;
              return ret;
          }
   
          public long nextLong() throws IOException
          {
              long ret = 0;
              byte c = read();
              while (c <= ' ')
                  c = read();
              boolean neg = (c == '-');
              if (neg)
                  c = read();
              do {
                  ret = ret * 10 + c - '0';
              } while ((c = read()) >= '0' && c <= '9');
              if (neg)
                  return -ret;
              return ret;
          }
   
          public double nextDouble() throws IOException
          {
              double ret = 0, div = 1;
              byte c = read();
              while (c <= ' ')
                  c = read();
              boolean neg = (c == '-');
              if (neg)
                  c = read();
   
              do {
                  ret = ret * 10 + c - '0';
              } while ((c = read()) >= '0' && c <= '9');
   
              if (c == '.') {
                  while ((c = read()) >= '0' && c <= '9') {
                      ret += (c - '0') / (div *= 10);
                  }
              }
   
              if (neg)
                  return -ret;
              return ret;
          }
   
          private void fillBuffer() throws IOException
          {
              bytesRead = din.read(buffer, bufferPointer = 0,
                                   BUFFER_SIZE);
              if (bytesRead == -1)
                  buffer[0] = -1;
          }
   
          private byte read() throws IOException
          {
              if (bufferPointer == bytesRead)
                  fillBuffer();
              return buffer[bufferPointer++];
          }
   
          public void close() throws IOException
          {
              if (din == null)
                  return;
              din.close();
          }
      }
  
      public static void main(String[] args) throws Exception {
          Reader scn = new Reader();
          PrintWriter pw = new PrintWriter(System.out);
          int t = scn.nextInt();
          outer : while(t-->0){
              int m = scn.nextInt();
              int n = scn.nextInt();
              int[][] arr = new int[m][n];
              for(int i=0; i<m; i++){
              	for(int j=0; j<n; j++){
              		arr[i][j] = scn.nextInt();
              	}
              }
              int[] maxJoy = new int[n];
              for(int i=0; i<n; i++){
              	int max = 0;
              	for(int j=0; j<m; j++){
              		max = Math.max(max, arr[j][i]);
              	}
              	maxJoy[i] = max;
              }
              int alpha = 0;
              for(int i=0; i<m; i++){
              	Pair[] ar = new Pair[n];
              	for(int j=0; j<n; j++){
              		ar[j] = new Pair(arr[i][j], j);
              	}
              	sort(ar);
              	int index1 = ar[0].idx;
              	int index2 = ar[1].idx;
              	int min = ar[1].x;
              	for(int j=0; j<n; j++){
              		if(j == index1 || j == index2){
              			continue;
              		}
              		min = Math.min(min, maxJoy[j]);
              	}
              	alpha = Math.max(alpha, min);
              }
              pw.println(alpha);
          }
          pw.close();
      }
  
      public static class Pair implements Comparable<Pair>{
          int x;
          int idx;
  
          Pair(int x, int idx){
              this.x = x;
              this.idx = idx;
          }
  
          public int compareTo(Pair o){
          	return o.x - this.x;
          }
      }
  
      private static void sort(int[] arr) {
          List<Integer> list = new ArrayList<>();
          for (int i=0; i<arr.length; i++){
              list.add(arr[i]);
          }
          Collections.sort(list); // collections.sort uses nlogn in backend
          for (int i = 0; i < arr.length; i++){
              arr[i] = list.get(i);
          }
      }
  
      private static void sort(long[] arr) {
          List<Long> list = new ArrayList<>();
          for(int i=0; i<arr.length; i++){
              list.add(arr[i]);
          }
          Collections.sort(list); // collections.sort uses nlogn in backend
          for (int i = 0; i < arr.length; i++){
              arr[i] = list.get(i);
          }
      }
  
      private static void sort(Pair[] arr) {
          List<Pair> list = new ArrayList<>();
          for(int i=0; i<arr.length; i++){
              list.add(arr[i]);
          }
          Collections.sort(list); // collections.sort uses nlogn in backend
          for (int i = 0; i < arr.length; i++){
              arr[i] = list.get(i);
          }
      }
  
      private static void reverseSort(int[] arr){
          List<Integer> list = new ArrayList<>();
          for (int i=0; i<arr.length; i++){
              list.add(arr[i]);
          }
          Collections.sort(list, Collections.reverseOrder()); // collections.sort uses nlogn in backend
          for (int i = 0; i < arr.length; i++){
              arr[i] = list.get(i);
          }
      }
  
      private static void reverseSort(long[] arr){
          List<Long> list = new ArrayList<>();
          for (int i=0; i<arr.length; i++){
              list.add(arr[i]);
          }
          Collections.sort(list, Collections.reverseOrder()); // collections.sort uses nlogn in backend
          for (int i = 0; i < arr.length; i++){
              arr[i] = list.get(i);
          }
      }
  
      private static void reverseSort(ArrayList<Integer> list){
          Collections.sort(list, Collections.reverseOrder());
      }
  
      private static int lowerBound(int[] arr, int x){
          int n = arr.length, si = 0, ei = n - 1;
          while(si <= ei){
              int mid = si + (ei - si)/2;
              if(arr[mid] == x){
                  if(mid-1 >= 0 && arr[mid-1] == arr[mid]){
                      ei = mid-1;
                  }else{
                      return mid;
                  }
              }else if(arr[mid] > x){
                  ei = mid - 1; 
              }else{
                  si = mid+1;
              }
          }
          return si; 
      }
  
      private static int upperBound(int[] arr, int x){
          int n = arr.length, si = 0, ei = n - 1;
          while(si <= ei){
              int mid = si + (ei - si)/2;
              if(arr[mid] == x){
                  if(mid+1 < n && arr[mid+1] == arr[mid]){
                      si = mid+1;
                  }else{
                      return mid + 1;
                  }
              }else if(arr[mid] > x){
                  ei = mid - 1; 
              }else{
                  si = mid+1;
              }
          }
          return si; 
      }
  
      private static int upperBound(ArrayList<Integer> list, int x){
          int n = list.size(), si = 0, ei = n - 1;
          while(si <= ei){
              int mid = si + (ei - si)/2;
              if(list.get(mid) == x){
                  if(mid+1 < n && list.get(mid+1) == list.get(mid)){
                      si = mid+1;
                  }else{
                      return mid + 1;
                  }
              }else if(list.get(mid) > x){
                  ei = mid - 1; 
              }else{
                  si = mid+1;
              }
          }
          return si; 
      }
  
      // (x^y)%p in O(logy)
      private static long power(long x, long y){
          long res = 1; 
          x = x % mod;
          while(y > 0){
              if ((y & 1) == 1){
                  res = (res * x) % mod;
              }
              y = y >> 1; 
              x = (x * x) % mod;
          }
          return res;
      }
  
      public static boolean nextPermutation(int[] arr) {
          if(arr == null || arr.length <= 1){
              return false;
          }
          
          int last = arr.length-2;
          while(last >= 0){
              if(arr[last] < arr[last+1]){
                  break;
              }
              last--;
          }
  
          if (last < 0){
                return false;
          }
          
          if(last >= 0){
              int nextGreater = arr.length-1;
              for(int i=arr.length-1; i>last; i--){
                  if(arr[i] > arr[last]){
                      nextGreater = i;
                      break;
                  }
              }
              swap(arr, last, nextGreater);
          }
          
          reverse(arr, last+1, arr.length-1);
          return true;
      }
      
      private static void swap(int[] arr, int i, int j){
          int temp = arr[i];
          arr[i] = arr[j];
          arr[j] = temp;
      }
      
      private static void reverse(int[] arr, int i, int j){
          while(i < j){
              swap(arr, i++, j--);
          }
      }
  
      private static String reverseStr(String s){
          StringBuilder sb = new StringBuilder(s);
          return sb.reverse().toString();
      }
  
      // TC- O(logmax(a,b))
      private static int gcd(int a, int b) {
          if(a == 0){
              return b;
          }
          return gcd(b%a, a);
      }
  
      private static long gcd(long a, long b) {
          if(a == 0L){
              return b;
          }
          return gcd(b%a, a);
      }
  
      private static long lcm(long a, long b) {
          return a / gcd(a, b) * b;
      }
  
      // TC- O(logmax(a,b))
      private static int lcm(int a, int b) {
          return a / gcd(a, b) * b;
      }
  
      private static long inv(long x){
          return power(x, mod - 2);
      }
  
      private static long summation(long n){
          return (n * (n + 1L)) >> 1;
      } 
  }