description: Monocarp is the coach of the Berland State University programming teams. He decided to compose a problemset for a training session for his teams.
  
  Monocarp has n problems that none of his students have seen yet. The i-th problem has a topic a_i (an integer from 1 to n) and a difficulty b_i (an integer from 1 to n). All problems are different, that is, there are no two tasks that have the same topic and difficulty at the same time.
  
  Monocarp decided to select exactly 3 problems from n problems for the problemset. The problems should satisfy at least one of two conditions (possibly, both):
  
    * the topics of all three selected problems are different; 
    * the difficulties of all three selected problems are different. 
  
  
  
  Your task is to determine the number of ways to select three problems for the problemset.
  
  Input
  
  The first line contains a single integer t (1 ≤ t ≤ 50000) — the number of testcases.
  
  The first line of each testcase contains an integer n (3 ≤ n ≤ 2 ⋅ 10^5) — the number of problems that Monocarp have.
  
  In the i-th of the following n lines, there are two integers a_i and b_i (1 ≤ a_i, b_i ≤ n) — the topic and the difficulty of the i-th problem.
  
  It is guaranteed that there are no two problems that have the same topic and difficulty at the same time.
  
  The sum of n over all testcases doesn't exceed 2 ⋅ 10^5.
  
  Output
  
  Print the number of ways to select three training problems that meet either of the requirements described in the statement.
  
  Example
  
  Input
  
  
  2
  4
  2 4
  3 4
  2 1
  1 3
  5
  1 5
  2 4
  3 3
  4 2
  5 1
  
  
  Output
  
  
  3
  10
  
  Note
  
  In the first example, you can take the following sets of three problems:
  
    * problems 1, 2, 4; 
    * problems 1, 3, 4; 
    * problems 2, 3, 4. 
  
  
  
  Thus, the number of ways is equal to three.
solution: import java.util.*;
  import java.io.*;
  public class Main {
  		static long mod = 1000000007;
  		static PrintWriter out = new PrintWriter(new BufferedOutputStream(System.out));
  		public static void main(String[] args) throws IOException  {
  			FastReader sc = new FastReader();
  			int t = sc.nextInt();
  			while( t-- > 0) {
  				long n = sc.nextLong();
  				HashMap<Long,Long> fst= new HashMap<>();
  				HashMap<Long,Long> scnd = new HashMap<>();
  				long x[] = new long[(int)n];
  				long y[] = new long[(int)n];
  				for( int i = 0 ;i < n ;i++) {
  					long a = sc.nextLong();
  					long b = sc.nextLong();
  					x[i] = a;
  					y[i] = b;
  					if( !fst.containsKey(a)) {
  						fst.put( a, 1L);
  					}
  					else {
  						fst.put(a, fst.get(a)+1);
  					}
  					if( !scnd.containsKey(b)) {
  						scnd.put(b, 1L);
  					}
  					else {
  						scnd.put(b, scnd.get(b)+1);
  					}
  				}
  				long sum = (n)*(n-2)*(n-1)/6L;
  			//	out.println("sum " + sum);
  				long temp = 0;
  				for( int i = 0 ;i < n;i++) {
  					if( fst.get(x[i]) > 1) {
  				//		out.println( x[i] +" " + y[i]);
  						temp+=(fst.get(x[i]) -1)*(scnd.get(y[i]) - 1);
  		//				out.println(temp);
  					}
  				}
  				out.println(sum - temp);
  			}
  			out.flush();
  		}
  		
  		public static boolean ifpowof2(long n ) {
  			return ((n&(n-1)) == 0);
  		}
  		
  		public static int[] nextLargerElement(int[] arr, int n)	{ 
  			Stack<Integer> stack = new Stack<>();
  			int rtrn[] = new int[n];
  			rtrn[n-1] = -1;
  	        stack.push( n-1);
  	        for( int i = n-2 ;i >= 0 ; i--){
  	            int temp = arr[i];
  	            int lol = -1;
  	            while( !stack.isEmpty() && arr[stack.peek()] <= temp){
  	            	if(arr[stack.peek()] == temp ) {
  	            		lol = stack.peek();
  	            	}
  	                stack.pop();
  	            }
  	            if( stack.isEmpty()){
  	            	if( lol != -1) {
  	            		rtrn[i] = lol;
  	            	}
  	            	else {
  	            		rtrn[i] = -1;
  	            	}
  	            }
  	            else{
  	            	rtrn[i] = stack.peek();
  	            }
  	            stack.push( i);
  	        }
  	        return rtrn;
  		}
  		
  		static int gcd(int a, int b)
  		{
  			if (a == 0)
  				return b;
  			return gcd(b % a, a);
  		}
  		
  			   
  		 static int lcm(int a, int b)
  		 {
  			 return (a / gcd(a, b)) * b;
  		 }
  		 
  
  		 static long rightmostsetbit(long n) {
  			 return n&-n;
  		 }
  		 
  		 static long leftmostsetbit(long n)
  		    {
  		        long k = (long)(Math.log(n) / Math.log(2));
  		        return 1 << k;
  		    }
  	 
  		 static HashMap<Long,Long> primefactor( long n){
  			 HashMap<Long ,Long> hm = new HashMap<>();
  			 long temp = 0;
  			 while( n%2 == 0) {
  				 temp++;
  				 n/=2;
  			 }	
  			 if( temp!= 0) {
  				 hm.put( 2L, temp);
  			 }
  			 long c = (long)Math.sqrt(n);
  			 for( long i = 3 ; i <= c ; i+=2) {
  				 temp = 0;
  				 while( n% i == 0) {
  					 temp++;
  					 n/=i;
  				 }
  				 if( temp!= 0) {
  					 hm.put( i, temp);
  				 }
  	 		 }
  	 		 if( n!= 1) {
  	 			 hm.put( n , 1L);
  	 		 }
  	 		 return hm;	
  		 }
  	 
  		 static class FastReader {
  			 BufferedReader br;
  			 StringTokenizer st;
  		 
  			 public FastReader()
  			 {
  				 br = new BufferedReader(new InputStreamReader(System.in));
  			 }
  		        
  			 String next()
  			 {
  				 while (st == null || !st.hasMoreElements()) {
  					 try {
  						 st = new StringTokenizer(br.readLine());
  					 }
  					 catch (IOException e) {
  						 e.printStackTrace();
  					 }
  				 }
  				 return st.nextToken();
  			 }
  		 
  			 int nextInt() { return Integer.parseInt(next()); }
  			 
  			 long nextLong() { return Long.parseLong(next()); }
  			 
  			 double nextDouble()
  			 {
  				 return Double.parseDouble(next());
  			 }	
  		 
  			 String nextLine()
  			 {
  				 String str = "";
  				 try {
  					 str = br.readLine();
  				 }
  				 catch (IOException e) {
  					 e.printStackTrace();
  				 }
  				 return str;
  			 }
  		 }	
  }