description: You are given a string s of length n consisting of characters a and/or b.
  
  Let \operatorname{AB}(s) be the number of occurrences of string ab in s as a substring. Analogically, \operatorname{BA}(s) is the number of occurrences of ba in s as a substring.
  
  In one step, you can choose any index i and replace s_i with character a or b.
  
  What is the minimum number of steps you need to make to achieve \operatorname{AB}(s) = \operatorname{BA}(s)?
  
  Reminder:
  
  The number of occurrences of string d in s as substring is the number of indices i (1 ≤ i ≤ |s| - |d| + 1) such that substring s_i s_{i + 1} ... s_{i + |d| - 1} is equal to d. For example, \operatorname{AB}(aabbbabaa) = 2 since there are two indices i: i = 2 where aabbbabaa and i = 6 where aabbbabaa.
  
  Input
  
  Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 1000). Description of the test cases follows.
  
  The first and only line of each test case contains a single string s (1 ≤ |s| ≤ 100, where |s| is the length of the string s), consisting only of characters a and/or b.
  
  Output
  
  For each test case, print the resulting string s with \operatorname{AB}(s) = \operatorname{BA}(s) you'll get making the minimum number of steps.
  
  If there are multiple answers, print any of them.
  
  Example
  
  Input
  
  
  4
  b
  aabbbabaa
  abbb
  abbaab
  
  
  Output
  
  
  b
  aabbbabaa
  bbbb
  abbaaa
  
  Note
  
  In the first test case, both \operatorname{AB}(s) = 0 and \operatorname{BA}(s) = 0 (there are no occurrences of ab (ba) in b), so can leave s untouched.
  
  In the second test case, \operatorname{AB}(s) = 2 and \operatorname{BA}(s) = 2, so you can leave s untouched. 
  
  In the third test case, \operatorname{AB}(s) = 1 and \operatorname{BA}(s) = 0. For example, we can change s_1 to b and make both values zero.
  
  In the fourth test case, \operatorname{AB}(s) = 2 and \operatorname{BA}(s) = 1. For example, we can change s_6 to a and make both values equal to 1.
solution: import java.io.BufferedReader;
  import java.io.IOException;
  import java.io.InputStreamReader;
  import java.io.OutputStreamWriter;
  import java.io.PrintWriter;
  import java.util.StringTokenizer;
  
  public class A_AB_Balance {
  	
  	 static Scanner in=new Scanner();
      
      static PrintWriter out=new PrintWriter( new OutputStreamWriter(System.out) );
  
      static int n,testCases;
      
      static char a[];
      
      static void solve(){
          
          int count=0;
          
          for(int i=0;i<n-1;i++){
              
              if( a[i]=='a' && a[i+1]=='b' ){
                  
                  count++;
                  
              }else if( a[i]=='b' && a[i+1]=='a' ) {
              
              count--;
                  
              }
              
          }
          
          if(count==0){
              
              out.println(new String(a) );
              out.flush();
              
              return;
              
          }
          
          if(count==1){
              
              for(int i=0;i<n-1;i++){
                  
                  out.print(a[i]);
                  out.flush();
              }
              
              out.println("a");
              out.flush();
              
          }else{
          
          for(int i=0;i<n-1;i++){
              
              out.print(a[i]);
              out.flush();
              
          }
          
          out.println("b");
          out.flush();
          
          }
          
      }
      
      public static void main(String[] args) throws IOException {
          
          testCases=in.nextInt();
          
          for(int t=0;t<testCases;t++){
              
              a=in.next().toCharArray();
              
              n=a.length;
              
              solve();
              
          }
          
          in.close();
          
      }
      	static long gcd(long a, long b)
      {
        if (b == 0)
          return a;
        return gcd(b, a % b);
      }
  	
     static void merge(long a[],int left,int right,int mid){
          
          int n1=mid-left+1,n2=right-mid;
          
          long L[]=new long[n1];
          
          long R[]=new long[n2];
          
          for(int i=0;i<n1;i++){
              
              L[i]=a[left+i];
              
          }
          
          for(int i=0;i<n2;i++){
              
              R[i]=a[mid+1+i];
              
          }
          
          int i=0,j=0,k1=left;
          
          while(i<n1 && j<n2){
              
              if( L[i]<=R[j] ){
                  
                  a[k1]=L[i];
                  
                  i++;
                  
              }else{
                  
                  a[k1]=R[j];
                  
                  j++;
                  
              }
              
              k1++;
              
          }
          
          while(i<n1){
              
              a[k1]=L[i];
              
              i++;
              
              k1++;
              
          }
          
          while(j<n2){
              
              a[k1]=R[j];
              
              j++;
              k1++;
              
          }
          
      }
      
      static void sort(long a[],int left,int right){
          
          if(left>=right){
              
              return;
              
          }
          
          int mid=(left+right)/2;
          
          sort(a,left,mid);
          
          sort(a,mid+1,right);
          
          merge(a,left,right,mid);
          
      }
  	
  	  static class Scanner{
          
          BufferedReader in;
          StringTokenizer st;
  
          public Scanner() {
          
              in=new BufferedReader( new InputStreamReader(System.in) );
              
          }
          
          String next() throws IOException{
              
              while(st==null || !st.hasMoreElements()){
                  
                  st=new StringTokenizer(in.readLine());
                  
              }
              
              return st.nextToken();
              
          }
          
          int nextInt() throws IOException{
              
              return Integer.parseInt(next());
              
          }
          
          long nextLong() throws IOException{
              
              return Long.parseLong(next());
              
          }
          
          String nextLine() throws IOException{
              
              return in.readLine();
              
          }
          
          char nextChar() throws IOException{
              
              return next().charAt(0);
              
          }
          
          double nextDouble() throws IOException{
              
              return Double.parseDouble(next());
              
          }
          
          float nextFloat() throws IOException{
              
              return Float.parseFloat(next());
              
          }
          
          boolean nextBoolean() throws IOException{
              
              return Boolean.parseBoolean(next());
              
          }
          
  		
          void close() throws IOException{
              
              in.close();
              
          }
          
      }
  	
  }
  /*
  
  4
  b
  aabbbabaa
  abbb
  abbaab
  
  
  */