description: The robot is located on a checkered rectangular board of size n × m (n rows, m columns). The rows in the board are numbered from 1 to n from top to bottom, and the columns — from 1 to m from left to right.
  
  The robot is able to move from the current cell to one of the four cells adjacent by side.
  
  The sequence of commands s executed by the robot is given. Each command is denoted by one of the symbols 'L', 'R', 'D' or 'U', and triggers the movement to left, right, down or up, respectively.
  
  The robot can start its movement in any cell. The robot executes the commands starting from the first one, strictly in the order in which they are listed in s. If the robot moves beyond the edge of the board, it falls and breaks. A command that causes the robot to break is not considered successfully executed.
  
  The robot's task is to execute as many commands as possible without falling off the board. For example, on board 3 × 3, if the robot starts a sequence of actions s="RRDLUU" ("right", "right", "down", "left", "up", "up") from the central cell, the robot will perform one command, then the next command will force him to cross the edge. If the robot starts moving from the cell (2, 1) (second row, first column) then all commands will be executed successfully and the robot will stop at the cell (1, 2) (first row, second column).
  
  <image> The robot starts from cell (2, 1) (second row, first column). It moves right, right, down, left, up, and up. In this case it ends in the cell (1, 2) (first row, second column).
  
  Determine the cell from which the robot should start its movement in order to execute as many commands as possible.
  
  Input
  
  The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases.
  
  The next 2t lines contain descriptions of the test cases.
  
  In the description of each test case, the first line contains two integers n and m (1 ≤ n, m ≤ 10^6) — the height and width of the field that the robot is located on. The second line of the description is a string s consisting solely of characters 'L', 'R', 'D' and 'U' — the sequence of commands the robot executes. The string has a length from 1 to 10^6 commands.
  
  It is guaranteed that the total length of s over all test cases does not exceed 10^6.
  
  Output
  
  Print t lines, each of which contains the answer to the corresponding test case. The answer to the test case are two integers r (1 ≤ r ≤ n) and c (1 ≤ c ≤ m), separated by a space — the coordinates of the cell (row number and column number) from which the robot should start moving to perform as many commands as possible.
  
  If there are several such cells, you may output any of them.
  
  Example
  
  Input
  
  
  4
  1 1
  L
  1 2
  L
  3 3
  RRDLUU
  4 3
  LUURRDDLLLUU
  
  
  Output
  
  
  1 1
  1 2
  2 1
  3 2
solution: import static java.lang.Math.max;
  import static java.lang.Math.min;
  import static java.lang.Math.abs;
  import static java.lang.System.out;
  import java.util.*;
  import java.io.*;
  import java.math.*;
  /*
  -> Give your 100%, that's it!
  -> Rules To Solve Any Problem:
      1. Read the problem.
      2. Think About It.
      3. Solve it!
  */
  
  public class Template {
      
  	static int mod = 1000000007;
  
  	public static void main(String[] args){
          FastScanner sc = new FastScanner();
          PrintWriter out = new PrintWriter(System.out);
          int yo = sc.nextInt();
          while (yo-- > 0) {
              int n = sc.nextInt();
              int m = sc.nextInt();
              char[] s = sc.next().toCharArray();
              int len = s.length;
              int index = len-1;
              int R = 0;
              int D = 0;
              
              int size = 0;
              int max = 0;
              int min = 0;
              for(int i = 0; i < len; i++){
                  if(s[i] == 'R' || s[i] == 'L'){
                      if(s[i] == 'R') R++;
                      else R--;
                      max = max(R,max);
                      min = min(R,min);
                      size = (max-min+1);
                      if(size > m){
                          index = min(index,i-1);
                          break;
                      }
                  }
              }
              
              size = 0;
              max = 0;
              min = 0;
              for(int i = 0; i < len; i++){
                  if(s[i] == 'D' || s[i] == 'U'){
                      if(s[i] == 'D') D++;
                      else D--;
                      max = max(D,max);
                      min = min(D,min);
                      size = (max-min+1);
                      if(size > n){
                          index = min(index,i-1);
                          break;
                      }
                  }
              }
              
              
              int row = 0;
              int minR = 0;
              int col = 0;
              int minC = 0;
              // out.println(index);
              for(int i = 0; i <= index; i++){
                  if(s[i] == 'R' || s[i] == 'L'){
                      if(s[i] == 'R') row++;
                      else row--;
                      if(row < 0){
                          minR = min(minR,row);
                      }
                  }
                  else {
                      if(s[i] == 'D') col++;
                      else col--;
                      if(col < 0){
                          minC = min(minC,col);
                      }
                  }
              }
              if(minR < 0){
                  row = minR*-1;    
              }
              else {
                  row = 0;
              }
              if(minC < 0){
                  col = minC*-1;
              }
              else {
                  col = 0;
              }
              
              out.println((col+1) + " " + (row+1));
              
          }
          out.close();
  	}
      
     
      
      
      /*
      Source: hu_tao
           Random stuff to try when stuck:
              - use bruteforcer
              - always check for n = 1, n = 2, so on
              -if it's 2C then it's dp
              -for combo/probability problems, expand the given form we're interested in
              -make everything the same then build an answer (constructive, make everything 0 then do something)
              -something appears in parts of 2 --> model as graph
              -assume a greedy then try to show why it works
              -find way to simplify into one variable if multiple exist
              -treat it like fmc (note any passing thoughts/algo that could be used so you can revisit them)
              -find lower and upper bounds on answer
              -figure out what ur trying to find and isolate it
              -see what observations you have and come up with more continuations
              -work backwards (in constructive, go from the goal to the start)
              -turn into prefix/suffix sum argument (often works if problem revolves around adjacent array elements)
              -instead of solving for answer, try solving for complement (ex, find n-(min) instead of max)
              -draw something
              -simulate a process
              -dont implement something unless if ur fairly confident its correct
              -after 3 bad submissions move on to next problem if applicable
              -do something instead of nothing and stay organized
              -write stuff down
           Random stuff to check when wa:
              -if code is way too long/cancer then reassess
              -switched N/M
              -int overflow
              -switched variables
              -wrong MOD
              -hardcoded edge case incorrectly
           Random stuff to check when tle:
              -continue instead of break
              -condition in for/while loop bad
           Random stuff to check when rte:
              -switched N/M
              -long to int/int overflow
              -division by 0
              -edge case for empty list/data structure/N=1
        */
  
  	public static class Pair {
  		int x;
  		int y;
  
  		public Pair(int x, int y) {
  			this.x = x;
  			this.y = y;
  		}
  	}
  
  	public static void sort(int[] arr) {
  		ArrayList<Integer> ls = new ArrayList<Integer>();
  		for (int x : arr)
  			ls.add(x);
  		Collections.sort(ls);
  		for (int i = 0; i < arr.length; i++)
  			arr[i] = ls.get(i);
  	}
  
  	public static long gcd(long a, long b) {
  		if (b == 0)
  			return a;
  		return gcd(b, a % b);
  	}
  
  	static boolean[] sieve(int N) {
  		boolean[] sieve = new boolean[N + 1];
  		for (int i = 2; i <= N; i++)
  			sieve[i] = true;
  
  		for (int i = 2; i <= N; i++) {
  			if (sieve[i]) {
  				for (int j = 2 * i; j <= N; j += i) {
  					sieve[j] = false;
  				}
  			}
  		}
  		return sieve;
  	}
  
  	public static long power(long x, long y, long p) {
  		long res = 1L;
  		x = x % p;
  		while (y > 0) {
  			if ((y & 1) == 1)
  				res = (res * x) % p;
  			y >>= 1;
  			x = (x * x) % p;
  		}
  		return res;
  	}
  
  	public static void print(int[] arr, PrintWriter out) {
  		//for debugging only
  		for (int x : arr)
  			out.print(x + " ");
  		out.println();
  	}
      
      public static int log2(int a){
          return (int)(Math.log(a)/Math.log(2));
      }
  
  	static class FastScanner {
  		private int BS = 1 << 16;
  		private char NC = (char) 0;
  		private byte[] buf = new byte[BS];
  		private int bId = 0, size = 0;
  		private char c = NC;
  		private double cnt = 1;
  		private BufferedInputStream in;
  
  		public FastScanner() {
  			in = new BufferedInputStream(System.in, BS);
  		}
  
  		public FastScanner(String s) {
  			try {
  				in = new BufferedInputStream(new FileInputStream(new File(s)), BS);
  			} catch (Exception e) {
  				in = new BufferedInputStream(System.in, BS);
  			}
  		}
  
  		private char getChar() {
  			while (bId == size) {
  				try {
  					size = in.read(buf);
  				} catch (Exception e) {
  					return NC;
  				}
  				if (size == -1)
  					return NC;
  				bId = 0;
  			}
  			return (char) buf[bId++];
  		}
  
  		public int nextInt() {
  			return (int) nextLong();
  		}
  
  		public int[] readInts(int N) {
  			int[] res = new int[N];
  			for (int i = 0; i < N; i++) {
  				res[i] = (int) nextLong();
  			}
  			return res;
  		}
  
  		public long[] readLongs(int N) {
  			long[] res = new long[N];
  			for (int i = 0; i < N; i++) {
  				res[i] = nextLong();
  			}
  			return res;
  		}
  
  		public long nextLong() {
  			cnt = 1;
  			boolean neg = false;
  			if (c == NC)
  				c = getChar();
  			for (; (c < '0' || c > '9'); c = getChar()) {
  				if (c == '-')
  					neg = true;
  			}
  			long res = 0;
  			for (; c >= '0' && c <= '9'; c = getChar()) {
  				res = (res << 3) + (res << 1) + c - '0';
  				cnt *= 10;
  			}
  			return neg ? -res : res;
  		}
  
  		public double nextDouble() {
  			double cur = nextLong();
  			return c != '.' ? cur : cur + nextLong() / cnt;
  		}
  
  		public double[] readDoubles(int N) {
  			double[] res = new double[N];
  			for (int i = 0; i < N; i++) {
  				res[i] = nextDouble();
  			}
  			return res;
  		}
  
  		public String next() {
  			StringBuilder res = new StringBuilder();
  			while (c <= 32)
  				c = getChar();
  			while (c > 32) {
  				res.append(c);
  				c = getChar();
  			}
  			return res.toString();
  		}
  
  		public String nextLine() {
  			StringBuilder res = new StringBuilder();
  			while (c <= 32)
  				c = getChar();
  			while (c != '\n') {
  				res.append(c);
  				c = getChar();
  			}
  			return res.toString();
  		}
  
  		public boolean hasNext() {
  			if (c > 32)
  				return true;
  			while (true) {
  				c = getChar();
  				if (c == NC)
  					return false;
  				else if (c > 32)
  					return true;
  			}
  		}
  	}
  
  	//	For Input.txt and Output.txt	
  	//	FileInputStream in = new FileInputStream("input.txt");
  	//	FileOutputStream out = new FileOutputStream("output.txt");
  	//	PrintWriter pw = new PrintWriter(out);
  	//	Scanner sc = new Scanner(in);
  }