description: Vlad has n friends, for each of whom he wants to buy one gift for the New Year.
  
  There are m shops in the city, in each of which he can buy a gift for any of his friends. If the j-th friend (1 ≤ j ≤ n) receives a gift bought in the shop with the number i (1 ≤ i ≤ m), then the friend receives p_{ij} units of joy. The rectangular table p_{ij} is given in the input.
  
  Vlad has time to visit at most n-1 shops (where n is the number of friends). He chooses which shops he will visit and for which friends he will buy gifts in each of them.
  
  Let the j-th friend receive a_j units of joy from Vlad's gift. Let's find the value α=min\\{a_1, a_2, ..., a_n\}. Vlad's goal is to buy gifts so that the value of α is as large as possible. In other words, Vlad wants to maximize the minimum of the joys of his friends.
  
  For example, let m = 2, n = 2. Let the joy from the gifts that we can buy in the first shop: p_{11} = 1, p_{12}=2, in the second shop: p_{21} = 3, p_{22}=4.
  
  Then it is enough for Vlad to go only to the second shop and buy a gift for the first friend, bringing joy 3, and for the second — bringing joy 4. In this case, the value α will be equal to min\{3, 4\} = 3
  
  Help Vlad choose gifts for his friends so that the value of α is as high as possible. Please note that each friend must receive one gift. Vlad can visit at most n-1 shops (where n is the number of friends). In the shop, he can buy any number of gifts.
  
  Input
  
  The first line of the input contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input.
  
  An empty line is written before each test case. Then there is a line containing integers m and n (2 ≤ n, 2 ≤ n ⋅ m ≤ 10^5) separated by a space — the number of shops and the number of friends, where n ⋅ m is the product of n and m.
  
  Then m lines follow, each containing n numbers. The number in the i-th row of the j-th column p_{ij} (1 ≤ p_{ij} ≤ 10^9) is the joy of the product intended for friend number j in shop number i.
  
  It is guaranteed that the sum of the values n ⋅ m over all test cases in the test does not exceed 10^5.
  
  Output
  
  Print t lines, each line must contain the answer to the corresponding test case — the maximum possible value of α, where α is the minimum of the joys from a gift for all of Vlad's friends.
  
  Example
  
  Input
  
  
  5
  
  2 2
  1 2
  3 4
  
  4 3
  1 3 1
  3 1 1
  1 2 2
  1 1 3
  
  2 3
  5 3 4
  2 5 1
  
  4 2
  7 9
  8 1
  9 6
  10 8
  
  2 4
  6 5 2 1
  7 9 7 2
  
  
  Output
  
  
  3
  2
  4
  8
  2
solution: import java.io.OutputStream;
  import java.io.IOException;
  import java.io.InputStream;
  import java.io.PrintWriter;
  import java.util.*;
  import java.io.IOException;
  import java.io.BufferedReader;
  import java.io.InputStreamReader;
  import java.io.InputStream;
  
  public class Main {
  
      public static void main(String[] args) {
          InputStream inputStream = System.in;
          OutputStream outputStream = System.out;
          InputReader in = new InputReader(inputStream);
          PrintWriter out = new PrintWriter(outputStream);
          TaskA solver = new TaskA();
          int t;
          t = in.nextInt();
          //t = 1;
          while (t > 0) {
              solver.call(in,out);
              t--;
          }
          out.close();
      }
  
      static class TaskA {
          int m, n;
          int[][] arr;
          public void call(InputReader in, PrintWriter out) {
              m = in.nextInt();
              n = in.nextInt();
  
              arr = new int[m][n];
              for (int i = 0; i < m; i++) {
                  for (int j = 0; j < n; j++) {
                      arr[i][j] = in.nextInt();
                  }
              }
              int l, r, mid;
              l = 0;
              r = (int)1e9 + 7;
  
              while(l + 1 < r){
                  mid = (l + r)/2;
                  if(ans(mid)){
                      l = mid;
                  }
                  else{
                      r = mid;
                  }
              }
              out.println(l);
          }
          public boolean ans(int mid){
              Map<Integer, Integer> map = new HashMap<>();
              int b, c = 0;
  
              for (int j = 0; j < n; j++) {
                  b = 0;
                  for (int i = 0; i < m; i++) {
                      if(arr[i][j]>=mid) {
                          b++;
                          map.put(i, map.getOrDefault(i, 0) + 1);
                          if(map.get(i)>1){
                              c++;
                          }
                      }
  
                  }
                  if(b==0){
                      return false;
                  }
              }
              return c!=0;
          }
      }
  
      static int gcd(int a, int b)
      {
          if (a == 0)
              return b;
          return gcd(b % a, a);
      }
  
      static int lcm(int a, int b)
      {
          return (a / gcd(a, b)) * b;
      }
  
      static class answer implements Comparable<answer>{
          int a, b;
  
          public answer(int a, int b) {
              this.a = a;
              this.b = b;
          }
  
          @Override
          public int compareTo(answer o) {
              return o.a - this.a;
          }
      }
  
      static class arrayListClass {
          ArrayList<Integer> arrayList2 ;
  
          public arrayListClass(ArrayList<Integer> arrayList) {
              this.arrayList2 = arrayList;
          }
      }
  
      static long gcd(long a, long b)
      {
          if (b == 0)
              return a;
          return gcd(b, a % b);
      }
  
      static void sort(long[] a) {
          ArrayList<Long> l=new ArrayList<>();
          for (long i:a) l.add(i);
          Collections.sort(l);
          for (int i=0; i<a.length; i++) a[i]=l.get(i);
      }
  
      static final Random random=new Random();
  
      static void shuffleSort(int[] a) {
          int n = a.length;
          for (int i=0; i<n; i++) {
              int oi=random.nextInt(n), temp=a[oi];
              a[oi]=a[i]; a[i]=temp;
          }
          Arrays.sort(a);
      }
  
      static class InputReader {
          public BufferedReader reader;
          public StringTokenizer tokenizer;
  
          public InputReader(InputStream stream) {
              reader = new BufferedReader(new InputStreamReader(stream), 32768);
              tokenizer = null;
          }
  
          public String next() {
              while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                  try {
                      tokenizer = new StringTokenizer(reader.readLine());
                  } catch (IOException e) {
                      throw new RuntimeException(e);
                  }
              }
              return tokenizer.nextToken();
          }
  
          public int nextInt() {
              return Integer.parseInt(next());
          }
          public long nextLong(){
              return Long.parseLong(next());
          }
          public double nextDouble() {
              return Double.parseDouble(next());
          }
  
      }
  }