description: Petya has got an interesting flower. Petya is a busy person, so he sometimes forgets to water it. You are given n days from Petya's live and you have to determine what happened with his flower in the end.
  
  The flower grows as follows: 
  
    * If the flower isn't watered for two days in a row, it dies. 
    * If the flower is watered in the i-th day, it grows by 1 centimeter. 
    * If the flower is watered in the i-th and in the (i-1)-th day (i > 1), then it grows by 5 centimeters instead of 1. 
    * If the flower is not watered in the i-th day, it does not grow. 
  
  
  
  At the beginning of the 1-st day the flower is 1 centimeter tall. What is its height after n days?
  
  Input
  
  Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
  
  The first line of each test case contains the only integer n (1 ≤ n ≤ 100).
  
  The second line of each test case contains n integers a_1, a_2, ..., a_n (a_i = 0 or a_i = 1). If a_i = 1, the flower is watered in the i-th day, otherwise it is not watered.
  
  Output
  
  For each test case print a single integer k — the flower's height after n days, or -1, if the flower dies.
  
  Example
  
  Input
  
  
  4
  3
  1 0 1
  3
  0 1 1
  4
  1 0 0 1
  1
  0
  
  
  Output
  
  
  3
  7
  -1
  1
solution: #include <bits/stdc++.h>
  using namespace std;
  vector<string> split(const string& s, char c) {
    vector<string> v;
    stringstream ss(s);
    string x;
    while (getline(ss, x, c)) v.emplace_back(x);
    return move(v);
  }
  template <typename T, typename... Args>
  inline string arrStr(T arr, long long n) {
    stringstream s;
    s << "[";
    for (long long i = 0; i < n - 1; i++) s << arr[i] << ",";
    s << arr[n - 1] << "]";
    return s.str();
  }
  template <typename t>
  void evars(vector<vector<t>> a) {
    for (auto i : a) {
      for (auto j : i) {
        cout << j << " ";
      }
      cout << "\n";
    }
  }
  inline void __evars_begin(long long line) { cout << "#" << line << ": "; }
  template <typename T>
  inline void __evars_out_var(vector<T> val) {
    cout << arrStr(val, val.size());
  }
  template <typename T>
  inline void __evars_out_var(T* val) {
    cout << arrStr(val, 10);
  }
  template <typename T>
  inline void __evars_out_var(T val) {
    cout << val;
  }
  inline void __evars(vector<string>::iterator it) { cout << "\n"; }
  template <typename T, typename... Args>
  inline void __evars(vector<string>::iterator it, T a, Args... args) {
    cout << it->substr((*it)[0] == ' ', it->length()) << "=";
    __evars_out_var(a);
    cout << "; ";
    __evars(++it, args...);
  }
  void solve() {
    long long n;
    cin >> n;
    vector<long long> vals(n + 1);
    for (long long i = 1; i < n + 1; ++i) cin >> vals[i];
    vals[0] = 0;
    long long a = 0, b = 0;
    bool is_ok = true;
    for (long long i = 1; i < n + 1; ++i) {
      if (vals[i] && vals[i - 1]) {
        a++;
      } else if (vals[i] && !vals[i - 1]) {
        b++;
      } else if (!vals[i] && !vals[i - 1] && i != 1) {
        is_ok = false;
        break;
      }
    }
    (!is_ok) ? cout << -1 << "\n" : cout << (5 * a + b + 1) << "\n";
  }
  int32_t main() {
    clock_t begin = clock();
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    long long t;
    cin >> t;
    while (t--) solve();
    return 0;
  }
  