description: Alice and Bob play the following game. Alice has a set S of disjoint ranges of integers, initially containing only one range [1, n]. In one turn, Alice picks a range [l, r] from the set S and asks Bob to pick a number in the range. Bob chooses a number d (l ≤ d ≤ r). Then Alice removes [l, r] from S and puts into the set S the range [l, d - 1] (if l ≤ d - 1) and the range [d + 1, r] (if d + 1 ≤ r). The game ends when the set S is empty. We can show that the number of turns in each game is exactly n.
  
  After playing the game, Alice remembers all the ranges [l, r] she picked from the set S, but Bob does not remember any of the numbers that he picked. But Bob is smart, and he knows he can find out his numbers d from Alice's ranges, and so he asks you for help with your programming skill.
  
  Given the list of ranges that Alice has picked ([l, r]), for each range, help Bob find the number d that Bob has picked.
  
  We can show that there is always a unique way for Bob to choose his number for a list of valid ranges picked by Alice.
  
  Input
  
  Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 1000). Description of the test cases follows.
  
  The first line of each test case contains a single integer n (1 ≤ n ≤ 1000).
  
  Each of the next n lines contains two integers l and r (1 ≤ l ≤ r ≤ n), denoting the range [l, r] that Alice picked at some point.
  
  Note that the ranges are given in no particular order.
  
  It is guaranteed that the sum of n over all test cases does not exceed 1000, and the ranges for each test case are from a valid game.
  
  Output
  
  For each test case print n lines. Each line should contain three integers l, r, and d, denoting that for Alice's range [l, r] Bob picked the number d.
  
  You can print the lines in any order. We can show that the answer is unique.
  
  It is not required to print a new line after each test case. The new lines in the output of the example are for readability only. 
  
  Example
  
  Input
  
  
  4
  1
  1 1
  3
  1 3
  2 3
  2 2
  6
  1 1
  3 5
  4 4
  3 6
  4 5
  1 6
  5
  1 5
  1 2
  4 5
  2 2
  4 4
  
  
  Output
  
  
  1 1 1
  
  1 3 1
  2 2 2
  2 3 3
  
  1 1 1
  3 5 3
  4 4 4
  3 6 6
  4 5 5
  1 6 2
  
  1 5 3
  1 2 1
  4 5 5
  2 2 2
  4 4 4
  
  Note
  
  In the first test case, there is only 1 range [1, 1]. There was only one range [1, 1] for Alice to pick, and there was only one number 1 for Bob to pick.
  
  In the second test case, n = 3. Initially, the set contains only one range [1, 3]. 
  
    * Alice picked the range [1, 3]. Bob picked the number 1. Then Alice put the range [2, 3] back to the set, which after this turn is the only range in the set. 
    * Alice picked the range [2, 3]. Bob picked the number 3. Then Alice put the range [2, 2] back to the set. 
    * Alice picked the range [2, 2]. Bob picked the number 2. The game ended. 
  
  
  
  In the fourth test case, the game was played with n = 5. Initially, the set contains only one range [1, 5]. The game's turn is described in the following table. 
  
  Game turn| Alice's picked range| Bob's picked number| The range set after  
  ---|---|---|---  
  Before the game start| | |  \{ [1, 5] \}   
  1| [1, 5]| 3|  \{ [1, 2], [4, 5] \}  
  2| [1, 2]| 1|  \{ [2, 2], [4, 5] \}   
  3| [4, 5]| 5|  \{ [2, 2], [4, 4] \}   
  4| [2, 2]| 2|  \{ [4, 4] \}   
  5| [4, 4]| 4|  \{ \}  (empty set)
solution: # DEFINING SOME GOOD STUFF
  import heapq
  import sys
  from math import *
  import threading
  from heapq import *
  from itertools import count
  from pprint import pprint
  from collections import defaultdict
  from heapq import heapify, heappop, heappush
  
  # threading.stack_size(10**8)
  # sys.setrecursionlimit(300000)
  '''
  -> if you are increasing recursionlimit then remember submitting using python3 rather pypy3
  -> sometimes increasing stack size don't work locally but it will work on CF
  '''
  
  mod = 10 ** 9+7
  inf = 10 ** 15
  decision = ['NO', 'YES']
  yes = 'YES'
  no = 'NO'
  
  # ------------------------------FASTIO----------------------------
  import os
  
  from io import BytesIO, IOBase
  
  BUFSIZE = 8192
  
  
  class FastIO(IOBase):
      newlines = 0
  
      def __init__(self, file):
          self._fd = file.fileno()
          self.buffer = BytesIO()
          self.writable = "x" in file.mode or "r" not in file.mode
          self.write = self.buffer.write if self.writable else None
  
      def read(self):
          while True:
              b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
              if not b:
                  break
              ptr = self.buffer.tell()
              self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
          self.newlines = 0
          return self.buffer.read()
  
      def readline(self):
          while self.newlines == 0:
              b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
              self.newlines = b.count(b"\n")+(not b)
              ptr = self.buffer.tell()
              self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
          self.newlines -= 1
          return self.buffer.readline()
  
      def flush(self):
          if self.writable:
              os.write(self._fd, self.buffer.getvalue())
              self.buffer.truncate(0), self.buffer.seek(0)
  
  
  class IOWrapper(IOBase):
      def __init__(self, file):
          self.buffer = FastIO(file)
          self.flush = self.buffer.flush
          self.writable = self.buffer.writable
          self.write = lambda s: self.buffer.write(s.encode("ascii"))
          self.read = lambda: self.buffer.read().decode("ascii")
          self.readline = lambda: self.buffer.readline().decode("ascii")
  
  
  sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
  input = lambda: sys.stdin.readline().rstrip("\r\n")
  
  
  # ________________________FAST FACTORIAL______________________________#
  class Factorial:
      def __init__(self, MOD):
          self.MOD = MOD
          self.factorials = [1, 1]
          self.invModulos = [0, 1]
          self.invFactorial_ = [1, 1]
  
      def calc(self, n):
          if n <= -1:
              print("Invalid argument to calculate n!")
              print("n must be non-negative value. But the argument was "+str(n))
              exit()
          if n < len(self.factorials):
              return self.factorials[n]
          nextArr = [0] * (n+1-len(self.factorials))
          initialI = len(self.factorials)
          prev = self.factorials[-1]
          m = self.MOD
          for i in range(initialI, n+1):
              prev = nextArr[i-initialI] = prev * i % m
          self.factorials += nextArr
          return self.factorials[n]
  
      def inv(self, n):
          if n <= -1:
              print("Invalid argument to calculate n^(-1)")
              print("n must be non-negative value. But the argument was "+str(n))
              exit()
          p = self.MOD
          pi = n % p
          if pi < len(self.invModulos):
              return self.invModulos[pi]
          nextArr = [0] * (n+1-len(self.invModulos))
          initialI = len(self.invModulos)
          for i in range(initialI, min(p, n+1)):
              next = -self.invModulos[p % i] * (p // i) % p
              self.invModulos.append(next)
          return self.invModulos[pi]
  
      def invFactorial(self, n):
          if n <= -1:
              print("Invalid argument to calculate (n^(-1))!")
              print("n must be non-negative value. But the argument was "+str(n))
              exit()
          if n < len(self.invFactorial_):
              return self.invFactorial_[n]
          self.inv(n)  # To make sure already calculated n^-1
          nextArr = [0] * (n+1-len(self.invFactorial_))
          initialI = len(self.invFactorial_)
          prev = self.invFactorial_[-1]
          p = self.MOD
          for i in range(initialI, n+1):
              prev = nextArr[i-initialI] = (prev * self.invModulos[i % p]) % p
          self.invFactorial_ += nextArr
          return self.invFactorial_[n]
  
  
  class Combination:
      def __init__(self, MOD):
          self.MOD = MOD
          self.factorial = Factorial(MOD)
  
      def ncr(self, n, k):
          if k < 0 or n < k:
              return 0
          k = min(k, n-k)
          f = self.factorial
          return f.calc(n) * f.invFactorial(max(n-k, k)) * f.invFactorial(min(k, n-k)) % self.MOD
  
      def npr(self, n, k):
          if k < 0 or n < k:
              return 0
          f = self.factorial
          return (f.calc(n) * f.invFactorial(n-k)) % self.MOD
  
  
  # _______________SEGMENT TREE ( logn range modifications )_____________#
  
  class SegmentTree:
      def __init__(self, data, default = 0, func = lambda a, b: max(a, b)):
          """initialize the segment tree with data"""
          self._default = default
          self._func = func
          self._len = len(data)
          self._size = _size = 1 << (self._len-1).bit_length()
  
          self.data = [default] * (2 * _size)
          self.data[_size:_size+self._len] = data
          for i in reversed(range(_size)):
              self.data[i] = func(self.data[i+i], self.data[i+i+1])
  
      def __delitem__(self, idx):
          self[idx] = self._default
  
      def __getitem__(self, idx):
          return self.data[idx+self._size]
  
      def __setitem__(self, idx, value):
          idx += self._size
          self.data[idx] = value
          idx >>= 1
          while idx:
              self.data[idx] = self._func(self.data[2 * idx], self.data[2 * idx+1])
              idx >>= 1
  
      def __len__(self):
          return self._len
  
      def query(self, start, stop):
          if start == stop:
              return self.__getitem__(start)
          stop += 1
          start += self._size
          stop += self._size
  
          res = self._default
          while start < stop:
              if start & 1:
                  res = self._func(res, self.data[start])
                  start += 1
              if stop & 1:
                  stop -= 1
                  res = self._func(res, self.data[stop])
              start >>= 1
              stop >>= 1
          return res
  
      def __repr__(self):
          return "SegmentTree({0})".format(self.data)
  
  
  # ____________________MY FAVOURITE FUNCTIONS_______________________#
  
  
  def lower_bound(li, num):
      answer = len(li)
      start = 0
      end = len(li)-1
  
      while (start <= end):
          middle = (end+start) // 2
          if li[middle] >= num:
              answer = middle
              end = middle-1
          else:
              start = middle+1
      return answer  # min index where x is not less than num
  
  
  def upper_bound(li, num):
      answer = len(li)
      start = 0
      end = len(li)-1
  
      while (start <= end):
          middle = (end+start) // 2
          if li[middle] <= num:
              start = middle+1
  
          else:
              answer = middle
              end = middle-1
      return answer  # max index where x is greater than num
  
  
  def abs(x):
      return x if x >= 0 else -x
  
  
  def binary_search(li, val):
      # print(lb, ub, li)
      ans = -1
      lb = 0
      ub = len(li)-1
      while (lb <= ub):
          mid = (lb+ub) // 2
          # print('mid is',mid, li[mid])
          if li[mid] > val:
              ub = mid-1
          elif val > li[mid]:
              lb = mid+1
          else:
              ans = mid  # return index
              break
      return ans
  
  
  def kadane(x):  # maximum sum contiguous subarray
      sum_so_far = 0
      current_sum = 0
      for i in x:
          current_sum += i
          if current_sum < 0:
              current_sum = 0
          else:
              sum_so_far = max(sum_so_far, current_sum)
      return sum_so_far
  
  
  def pref(li):
      pref_sum = [li[0]]
      for i in range(1, len(li)):
          pref_sum.append(pref_sum[-1]+i)
      return pref_sum
  
  
  def SieveOfEratosthenes(n):
      prime = [{1, i} for i in range(n+1)]
      p = 2
      while (p <= n):
          for i in range(p * 2, n+1, p):
              prime[i].add(p)
          p += 1
      return prime
  
  
  def primefactors(n):
      factors = []
      while (n % 2 == 0):
          factors.append(2)
          n //= 2
      for i in range(3, int(sqrt(n))+1, 2):  # only odd factors left
          while n % i == 0:
              factors.append(i)
              n //= i
      if n > 2:  # incase of prime
          factors.append(n)
      return factors
  
  
  def prod(li):
      ans = 1
      for i in li:
          ans *= i
      return ans
  
  
  # _______________________________________________________________#
  def given():
      a = list(map(int, input().split()))
      return a
  
  
  def givenStringList():
      s = list(input())
      return s
  
  
  def givenStringListInt():
      s = [int(x) for x in givenStringList()]
      return s
  
  
  # _________________________________________________________________#
  
  
  def main():
      karmanya = given()[0]
      # karmanya = 1
      while karmanya != 0:
          karmanya -= 1
          # s = input()
          n = given()[0]
          rang = []
          for i in range(n):
              l,r = given()
              rang.append([r-l+1, l, r])
          rang.sort()
          ans = []
          done = [0]*n
          for i in rang:
              l,r = i[1], i[2]
              for j in range(l, r+1):
                  if done[j-1] == 0:
                      done[j-1] = 1
                      print(l, r, j)
                      break
          print('')
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  
  main()
  # t = threading.Thread(target=main)
  # t.start()
  # t.join()