description: Petya has got an interesting flower. Petya is a busy person, so he sometimes forgets to water it. You are given n days from Petya's live and you have to determine what happened with his flower in the end.
  
  The flower grows as follows: 
  
    * If the flower isn't watered for two days in a row, it dies. 
    * If the flower is watered in the i-th day, it grows by 1 centimeter. 
    * If the flower is watered in the i-th and in the (i-1)-th day (i > 1), then it grows by 5 centimeters instead of 1. 
    * If the flower is not watered in the i-th day, it does not grow. 
  
  
  
  At the beginning of the 1-st day the flower is 1 centimeter tall. What is its height after n days?
  
  Input
  
  Each test contains multiple test cases. The first line contains the number of test cases t (1 ≤ t ≤ 100). Description of the test cases follows.
  
  The first line of each test case contains the only integer n (1 ≤ n ≤ 100).
  
  The second line of each test case contains n integers a_1, a_2, ..., a_n (a_i = 0 or a_i = 1). If a_i = 1, the flower is watered in the i-th day, otherwise it is not watered.
  
  Output
  
  For each test case print a single integer k — the flower's height after n days, or -1, if the flower dies.
  
  Example
  
  Input
  
  
  4
  3
  1 0 1
  3
  0 1 1
  4
  1 0 0 1
  1
  0
  
  
  Output
  
  
  3
  7
  -1
  1
solution: import java.util.*;
  import java.lang.*;
  
  public class Main
  {
  	public static void main (String[] args) //throws java.lang.Exception
  	{
  		Scanner sc=new Scanner(System.in);
  		int t=sc.nextInt(),n,i,j,h;
  		boolean die;
  		int[] a;
  		while(t-- >0){
  		    n=sc.nextInt();
  		    h=1;
  		    a=new int[n];
  		    die=false;
  		    for(i=0;i<n;i++){
  		    a[i]=sc.nextInt();
  		    if(a[i]==1){
  		        if(i!=0&&a[i-1]==1)
  		        h+=5;
  		        else
  		        h+=1;
  		    }
  		    else{
  		        if(i!=0&&a[i-1]==0)
  		        h=-1;
  		    }
  		    if(h==-1)
  		    die=true;
  		   // break;
  		    }
  		    if(die==true)
  		    System.out.println(-1);
  		    else
  		    System.out.println(h);
  		    
  		}
  		
  	}
  }