description: Berland Music is a music streaming service built specifically to support Berland local artist. Its developers are currently working on a song recommendation module.
  
  So imagine Monocarp got recommended n songs, numbered from 1 to n. The i-th song had its predicted rating equal to p_i, where 1 ≤ p_i ≤ n and every integer from 1 to n appears exactly once. In other words, p is a permutation.
  
  After listening to each of them, Monocarp pressed either a like or a dislike button. Let his vote sequence be represented with a string s, such that s_i=0 means that he disliked the i-th song, and s_i=1 means that he liked it.
  
  Now the service has to re-evaluate the song ratings in such a way that:
  
    * the new ratings q_1, q_2, ..., q_n still form a permutation (1 ≤ q_i ≤ n; each integer from 1 to n appears exactly once); 
    * every song that Monocarp liked should have a greater rating than every song that Monocarp disliked (formally, for all i, j such that s_i=1 and s_j=0, q_i>q_j should hold). 
  
  
  
  Among all valid permutations q find the one that has the smallest value of ∑_{i=1}^n |p_i-q_i|, where |x| is an absolute value of x.
  
  Print the permutation q_1, q_2, ..., q_n. If there are multiple answers, you can print any of them.
  
  Input
  
  The first line contains a single integer t (1 ≤ t ≤ 10^4) — the number of testcases.
  
  The first line of each testcase contains a single integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of songs.
  
  The second line of each testcase contains n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n) — the permutation of the predicted ratings.
  
  The third line contains a single string s, consisting of n characters. Each character is either a 0 or a 1. 0 means that Monocarp disliked the song, and 1 means that he liked it.
  
  The sum of n over all testcases doesn't exceed 2 ⋅ 10^5.
  
  Output
  
  For each testcase, print a permutation q — the re-evaluated ratings of the songs. If there are multiple answers such that ∑_{i=1}^n |p_i-q_i| is minimum possible, you can print any of them.
  
  Example
  
  Input
  
  
  3
  2
  1 2
  10
  3
  3 1 2
  111
  8
  2 3 1 8 5 4 7 6
  01110001
  
  
  Output
  
  
  2 1
  3 1 2
  1 6 5 8 3 2 4 7
  
  Note
  
  In the first testcase, there exists only one permutation q such that each liked song is rating higher than each disliked song: song 1 gets rating 2 and song 2 gets rating 1. ∑_{i=1}^n |p_i-q_i|=|1-2|+|2-1|=2.
  
  In the second testcase, Monocarp liked all songs, so all permutations could work. The permutation with the minimum sum of absolute differences is the permutation equal to p. Its cost is 0.
solution: 
  import java.io.BufferedReader;
  import java.io.BufferedWriter;
  import java.io.IOException;
  import java.io.InputStreamReader;
  import java.io.OutputStreamWriter;
  import java.io.PrintWriter;
  import java.util.*;
  import java.util.concurrent.ThreadLocalRandom;
  
  //import com.sun.tools.javac.code.Attribute.Array;
  
  
  
  public class a729 {
  
  	public static void main(String[] args) throws IOException {
     
  		
  		try {
  			
  //			System.out.println(printDivisors(1));
  			
  		BufferedWriter out = new BufferedWriter(
  	            new OutputStreamWriter(System.out));
  		BufferedReader br = new BufferedReader(
  		        new InputStreamReader(System.in));
  		PrintWriter pt = new PrintWriter(System.out);
  		FastReader sc = new FastReader();
  
  		int t = sc.nextInt();
  	
  for(int o = 0 ; o<t;o++){
  int n = sc.nextInt();
  int[] arr = new int[n];
  for(int i = 0 ; i<n;i++) {
  	arr[i] = sc.nextInt();
  	}
  String s = sc.next();
  int c = 0;
  for(int i = 0 ; i<n;i++) {
  	if(s.charAt(i) == '1') {
  		c++;
  	}
  }
  if(c == 0 || c == n) {
  	for(int i = 0 ; i<n;i++) {
  		System.out.print(arr[i] + " " );
  	}
  	System.out.println();
  continue;
  }
  ArrayList<Integer> al1 = new ArrayList<Integer>();
  ArrayList<Integer> al2 = new ArrayList<Integer>();
  for(int i =0 ;  i<n;i++) {
  	if(s.charAt(i) == '1'){
  		al1.add(arr[i]);
  	}else{
  		al2.add(arr[i]);
  	}
  }
  int v1 = n - c + 1;
  int v2 = 1;
  HashMap<Integer, Integer> map = new HashMap<Integer, Integer>();
  Collections.sort(al1);
  Collections.sort(al2);
  for(int x : al1) {
  	map.put(x, v1);
  	v1++;
  }
  for(int x : al2) {
  	map.put(x, v2);
  	v2++;
  }
  int[] ans = new int[n];
  for(int i = 0 ; i<n;i++) {
  	ans[i] = map.get(arr[i]);
  }
  for(int i = 0 ; i<n;i++) {
  System.out.print(ans[i] + " ");
  }
  
  System.out.println();
  }
       }catch(Exception e) {
      	 return;
       }
       }
       
       
  //------------------------------------------------------------------------------------------------------------------------------------------------
  	
  	
  	
  	
  	
  	static int cntDivisors(int n)
      {
          int cnt = 0;
  		for (int i=1; i<=Math.sqrt(n); i++)
          {
              if (n%i==0)
              {
                  if (n/i == i)
                  	cnt++;
                  	
                  else 
                  	cnt+=2;
              }
          }
      
      return cnt;
      }
  	
  	
  	
  	public static long findgcd(long[] arr,int v) {
  		int n = arr.length;
  		long g = arr[v];
  		for(int i = v ; i<n;i+=2) {
  			g = gcd(g, arr[i]);
  		}
  		return g;
  	}
  	
  	public static int count(long x) {
  		int a = 0;
  		while(x>0) {
  			x/=2;
  			a++;
  		}
  		return a;
  		
  	}
  	
  
  	public static long ncr(long[] fac, int n , int r , long m) {
  		return fac[n]*(modInverse(fac[r], m))%m *(modInverse(fac[n-r], m))%m; 
  	}
  	
  	
  	public static void build(int [][] seg,char []arr,int idx, int lo , int hi) {
  	if(lo == hi) {
  //		seg[idx] = arr[lo];
  		seg[idx][(int)arr[lo]-'a'] = 1;
  		
  		return;
  	}
  	int mid = (lo + hi)/2;
  build(seg,arr,2*idx+1, lo, mid);
  build(seg,arr,idx*2+2, mid +1, hi);
  //seg[idx] = Math.min(seg[2*idx+1],seg[2*idx+2]);
  for(int i = 0 ; i<27;i++) {
  	seg[idx][i] = seg[2*idx+1][i] + seg[2*idx + 2][i];
  }
  	}
  //for f/inding minimum in range 
  public static void query(int[][]seg,int[]ans,int idx , int lo , int hi , int l , int r) {
  	if(lo>=l && hi<=r) {
  		for(int i = 0 ; i<27;i++) {
  			ans[i]+= seg[idx][i];
  		}
  		return ;
  	}
  if(hi<l || lo>r) {
  	return;
  }
  int mid = (lo + hi)/2;
  query(seg,ans,idx*2 +1, lo, mid, l, r);
  query(seg,ans,idx*2 + 2, mid + 1, hi, l, r);
  //return Math.min(left, right);
  }
  //// for sum
  //
  public static void update(int[][]seg,char[]arr,int idx, int lo , int hi , int node , char val) {
  if(lo == hi) {
  //	seg[idx] += val;
  seg[idx][val-'a']++;
  seg[idx][arr[node]-'a']--;
  
  }else {
  int mid = (lo + hi )/2;
  if(node<=mid && node>=lo) {
  update(seg,arr, idx * 2 +1, lo, mid, node, val);
  }else {
  update(seg,arr, idx*2 + 2, mid + 1, hi, node, val);
  }
  //seg[idx] = seg[idx*2 + 1] + seg[idx*2 + 2];
  for(int i = 0 ; i<27;i++) {
  	seg[idx][i] = seg[2*idx+1][i] + seg[2*idx + 2][i];
  }
  }
  
  }
  	
  	
  	
  	
  	
  	
  	public static int lower_bound(int array[], int low, int high, int key){
  	// Base Case
  	if (low > high) {
  	return low;
  	}
  
  	// Find the middle index
  	int mid = low + (high - low) / 2;
  
  	// If key is lesser than or equal to
  	// array[mid] , then search
  	// in left subarray
  	if (key <= array[mid]) {
  
  	return lower_bound(array, low,
  	            mid - 1, key);
  	}
  
  	// If key is greater than array[mid],
  	// then find in right subarray
  	return lower_bound(array, mid + 1, high,
  	        key);
  	}
  	
  	public static int upper_bound(int arr[], int low,
              int high, int key){
  // Base Case
  if (low > high || low == arr.length)
  return low;
  
  // Find the value of middle index
  int mid = low + (high - low) / 2;
  
  // If key is greater than or equal
  // to array[mid], then find in
  // right subarray
  if (key >= arr[mid]) {
  return upper_bound(arr, mid + 1, high,
                  key);
  }
  
  // If key is less than array[mid],
  // then find in left subarray
  return upper_bound(arr, low, mid - 1,
              key);
  }
  
  //	-----------------------------------------------------------------------------------------------------------------------------------------------
  	public static long gcd(long a, long b){
          if (a == 0)
              return b;
          return gcd(b % a, a);
      }
  //--------------------------------------------------------------------------------------------------------------------------------------------------------
  	public static long modInverse(long a, long m){
          long m0 = m;
          long y = 0, x = 1;
   
          if (m == 1)
              return 0;
   
          while (a > 1) {
              // q is quotient
              long q = a / m;
   
              long t = m;
   
              // m is remainder now, process
              // same as Euclid's algo
              m = a % m;
              a = t;
              t = y;
   
              // Update x and y
              y = x - q * y;
              x = t;
          }
   
          // Make x positive
          if (x < 0)
              x += m0;
   
          return x;
      }
  
  		
  
  //-----------------------------------------------------------------------------------------------------------------------------------
  
  	//segment tree
  	//for finding minimum in range 
  //	public static void build(int [] seg,int []arr,int idx, int lo , int hi) {
  //		if(lo == hi) {
  //			seg[idx] = arr[lo];
  //			return;
  //		}
  //		int mid = (lo + hi)/2;
  //	build(seg,arr,2*idx+1, lo, mid);
  //	build(seg,arr,idx*2+2, mid +1, hi);
  //	seg[idx] = Math.min(seg[2*idx+1],seg[2*idx+2]);
  //	}
  ////for finding minimum in range 
  //public static int query(int[]seg,int idx , int lo , int hi , int l , int r) {
  //		if(lo>=l && hi<=r) {
  //			return seg[idx];
  //		}
  //	if(hi<l || lo>r) {
  //		return Integer.MAX_VALUE;
  //	}
  //	int mid = (lo + hi)/2;
  //	int left = query(seg,idx*2 +1, lo, mid, l, r);
  //	int right = query(seg,idx*2 + 2, mid + 1, hi, l, r);
  //	return Math.min(left, right);
  //}
  //	// for sum
  //
  //public static void update(int[]seg,int idx, int lo , int hi , int node , int val) {
  //	if(lo == hi) {
  //		seg[idx] += val;
  //	}else {
  //int mid = (lo + hi )/2;
  //if(node<=mid && node>=lo) {
  //	update(seg, idx * 2 +1, lo, mid, node, val);
  //}else {
  //	update(seg, idx*2 + 2, mid + 1, hi, node, val);
  //}
  //seg[idx] = seg[idx*2 + 1] + seg[idx*2 + 2];
  //
  //}
  
  //}
  //---------------------------------------------------------------------------------------------------------------------------------------
  
  
  	static void shuffleArray(int[] ar)
  	  {
  	    // If running on Java 6 or older, use `new Random()` on RHS here
  	    Random rnd = ThreadLocalRandom.current();
  	    for (int i = ar.length - 1; i > 0; i--)
  	    {
  	      int index = rnd.nextInt(i + 1);
  	      // Simple swap
  	      int a = ar[index];
  	      ar[index] = ar[i];
  	      ar[i] = a;
  	    }
  	  }
  //-----------------------------------------------------------------------------------------------------------------------------------------------------------
  
  }
  
  
  class FastReader {
      BufferedReader br;
      StringTokenizer st;
  
      public FastReader()
      {
          br = new BufferedReader(
              new InputStreamReader(System.in));
      }
  
      String next()
      {
          while (st == null || !st.hasMoreElements()) {
              try {
                  st = new StringTokenizer(br.readLine());
  
              
              
              
              
              }
              catch (IOException e) {
                  e.printStackTrace();
              }
          }
          return st.nextToken();
      }
  
      int nextInt() { return Integer.parseInt(next()); }
  
      long nextLong() { return Long.parseLong(next()); }
  
      double nextDouble()
      {
          return Double.parseDouble(next());
      }
  
      String nextLine()
      {
          String str = "";
          try {
              str = br.readLine();
          }
          catch (IOException e) {
              e.printStackTrace();
          }
          return str;
      }
  }
  //------------------------------------------------------------------------------------------------------------------------------------------------------------
  class SegmentTree{
  	
  int n;
  	public SegmentTree(int[] arr,int n) {
  		this.arr = arr;
  		this.n = n;
  	}
  	int[] arr = new int[n];
  //	int n = arr.length;
  	int[] seg = new int[4*n];
  	void build(int idx, int lo , int hi) {
  		if(lo == hi) {
  			seg[idx] = arr[lo];
  			return;
  		}
  		int mid = (lo + hi)/2;
  	build(2*idx+1, lo, mid);
  	build(idx*2+2, mid +1, hi);
  	seg[idx] = Math.min(seg[2*idx+1],seg[2*idx+2]);
  	}
  	int query(int idx , int lo , int hi , int l , int r) {
  		if(lo<=l && hi>=r) {
  			return seg[idx];
  		}
  	if(hi<l || lo>r) {
  		return Integer.MAX_VALUE;
  	}
  	int mid = (lo + hi)/2;
  	int left = query(idx*2 +1, lo, mid, l, r);
  	int right = query(idx*2 + 2, mid + 1, hi, l, r);
  	return Math.min(left, right);
  	}
  	
  	
  }
  //-----------------------------------------------------------------------------------------------------------------------------------------------------------
  class coup{
  	char a; 
  	int b;
  	public coup(char a , int b) {
  		this.a = a;
  		this.b = b;
  	}
  }
  
  class trip{
  	int a , b, c;
  	public trip(int a , int b, int c) {
  		this.a = a;
  		this.b = b;
  		this.c = c;
  	}
  }
  //---------------------------------------------------------------------------------------------------------------------------------------------------------------
  