description: There are n block towers in a row, where tower i has a height of a_i. You're part of a building crew, and you want to make the buildings look as nice as possible. In a single day, you can perform the following operation:
  
    * Choose two indices i and j (1 ≤ i, j ≤ n; i ≠ j), and move a block from tower i to tower j. This essentially decreases a_i by 1 and increases a_j by 1. 
  
  
  
  You think the ugliness of the buildings is the height difference between the tallest and shortest buildings. Formally, the ugliness is defined as max(a)-min(a). 
  
  What's the minimum possible ugliness you can achieve, after any number of days?
  
  Input
  
  The first line contains one integer t (1 ≤ t ≤ 1000) — the number of test cases. Then t cases follow.
  
  The first line of each test case contains one integer n (2 ≤ n ≤ 100) — the number of buildings.
  
  The second line of each test case contains n space separated integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 10^7) — the heights of the buildings.
  
  Output
  
  For each test case, output a single integer — the minimum possible ugliness of the buildings.
  
  Example
  
  Input
  
  
  3
  3
  10 10 10
  4
  3 2 1 2
  5
  1 2 3 1 5
  
  
  Output
  
  
  0
  0
  1
  
  Note
  
  In the first test case, the ugliness is already 0.
  
  In the second test case, you should do one operation, with i = 1 and j = 3. The new heights will now be [2, 2, 2, 2], with an ugliness of 0.
  
  In the third test case, you may do three operations: 
  
    1. with i = 3 and j = 1. The new array will now be [2, 2, 2, 1, 5], 
    2. with i = 5 and j = 4. The new array will now be [2, 2, 2, 2, 4], 
    3. with i = 5 and j = 3. The new array will now be [2, 2, 3, 2, 3]. 
  
  The resulting ugliness is 1. It can be proven that this is the minimum possible ugliness for this test.
solution: import java.io.BufferedReader;
  import java.io.IOException;
  import java.io.InputStream;
  import java.io.InputStreamReader;
  import java.io.PrintWriter;
  import java.util.StringTokenizer;
  import java.util.stream.IntStream;
  
  public class ClosingTheGap {
      private static final boolean TEST_CASES = true;
  
      void solve(int testCaseNo, InputReader in, PrintWriter out) {
          int n = in.nextInt();
          int[] a = new int[n];
          for (int i = 0; i < n; i++) {
              a[i] = in.nextInt();
          }
          int sum = IntStream.of(a).sum();
          int ans = 1;
          if (sum % n == 0) {
              ans = 0;
          }
          out.println(ans);
          ;
      }
  
      private static class InputReader {
          public BufferedReader reader;
          public StringTokenizer tokenizer;
  
          public InputReader(InputStream stream) {
              reader = new BufferedReader(new InputStreamReader(stream), 32768);
              tokenizer = null;
          }
  
          public String readLine() {
              try {
                  return reader.readLine();
              } catch (IOException e) {
                  throw new RuntimeException(e);
              }
          }
  
          public String next() {
              while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                  try {
                      tokenizer = new StringTokenizer(reader.readLine());
                  } catch (IOException e) {
                      throw new RuntimeException(e);
                  }
              }
              return tokenizer.nextToken();
          }
  
          public long nextLong() {
              return Long.parseLong(next());
          }
  
          public int nextInt() {
              return Integer.parseInt(next());
          }
      }
  
      public static void main(String[] args) {
          InputReader in = new InputReader(System.in);
          PrintWriter out = new PrintWriter(System.out);
          int testCases = TEST_CASES ? in.nextInt() : 1;
          ClosingTheGap solver = new ClosingTheGap();
          for (int testCase = 0; testCase < testCases; testCase++) {
              solver.solve(testCase, in, out);
          }
          out.flush();
          out.close();
      }
  }
  