Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
import java.util.Scanner;

public class P1208A {
     public static void main (String[] args) { 
        Scanner entrada = new Scanner(System.in);
        int n=entrada.nextInt();
        int m=entrada.nextInt();
        String [] x = new String[n+1];
        int contx=0,conty=0,cont=0;

        for (int i =0; i <= n; i++) x[i]=entrada.nextLine();
        
        for (int i = 1; i <=n; i++) 
                 for (int j = 0; j <m; j++){
                     if(x[i].charAt(j)=='B'){
                         contx=contx+j;
                         conty=conty+i;
                         cont++;                            
               }
                 }
                 
        
        
        /* for (int i = 1; i <=n; i++) 
             if(contx==0)  
                 for (int j = 0; j <m; j++){
                     if(x[i].charAt(j)=='B' && contx==0){ 
                         if(j==0)contx=1;
                         else contx=j;
                     }
                     else if(x[i].charAt(j)=='B'&&x[i].charAt(j+1)=='B')contx=(j-contx)/2;       
                 }
         
         for (int i = 0; i <= m; i++) {
             if(conty==0)
                 for (int j = 1; j <n; j++) {
                     if(x[j].charAt(i)=='B' && conty==0){ 
                         if(j==1)conty=1;
                         else conty=j;
                     }
                     
                     else if((x[j].charAt(i)=='B'&& x[j+1].charAt(i)!='B')||(x[j].charAt(i)=='B'&& j+1==n)){
                         conty=(j+conty+1)/2;
                     }
                     
                 }
             
         }
       */
         
         
         System.out.print(((conty/cont))+" ");
         System.out.print((contx/cont)+1);
             
             
         
         
        
      
     }
    
}
