You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long sum[360005] = {0};
long long cur[360005] = {0};
int main() {
  string str;
  long long n;
  cin >> n;
  cin >> str;
  long long siz = str.size();
  long long qq;
  cur[0] = 0;
  for (long long i = 1; i <= siz; i++) {
    cur[i] = cur[i - 1] + str[i - 1] - '0';
  }
  for (long long i = 0; i <= (siz - 1); i++) {
    for (long long j = i + 1; j <= siz; j++) {
      sum[cur[j] - cur[i]]++;
    }
  }
  unsigned long long ans = 0;
  qq = siz * 9;
  if (n == 0) {
    ans = siz * (siz + 1);
    ans *= sum[0];
    ans -= sum[0] * sum[0];
  } else {
    long long maa = min(n, qq);
    for (long long i = 1; i <= maa; i++) {
      if (n % i == 0) {
        if ((n / i) <= qq) {
          long long a1, a2;
          a1 = sum[i];
          a2 = sum[n / i];
          ans += a1 * a2;
        }
      }
    }
  }
  cout << ans << endl;
  return 0;
}
