You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int32_t main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  int64_t a;
  string s;
  cin >> a >> s;
  vector<int64_t> pre(s.length() + 1);
  pre[0] = 0;
  for (int64_t i = 0; i < s.length(); i++) {
    pre[i + 1] = pre[i] + s[i] - '0';
  }
  vector<int64_t> exist(4005 * 9);
  for (int64_t i = 1; i < pre.size(); i++) {
    for (int64_t j = i; j < pre.size(); j++) {
      exist[pre[j] - pre[i - 1]]++;
    }
  }
  int64_t ans = 0;
  for (int64_t i = 1; i < pre.size(); i++) {
    for (int64_t j = i; j < pre.size(); j++) {
      int64_t cur = pre[j] - pre[i - 1];
      if (a == 0) {
        if (cur == 0)
          ans += s.length() * (s.length() - 1) / 2 + s.length();
        else
          ans += exist[0];
      } else if (a != 0 && cur != 0 && a % cur == 0 && a / cur <= 4000 * 9)
        ans += exist[a / cur];
    }
  }
  cout << ans << endl;
  return 0;
}
