You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int N = 4444;
const int M = N * 10;
int s[N], c[M];
char str[N];
int main() {
  long long a;
  while (cin >> a >> str) {
    int n = strlen(str);
    s[0] = 0;
    for (int i = 0; i < n; i++) s[i + 1] = str[i] - '0';
    for (int i = 1; i <= n; i++) s[i] += s[i - 1];
    for (int i = 0; i < M; i++) c[i] = 0;
    for (int i = 1; i <= n; i++)
      for (int j = i; j <= n; j++) c[s[j] - s[i - 1]]++;
    long long ans = 0;
    for (int i = 1; i <= n; i++) {
      for (int j = i; j <= n; j++) {
        long long ds = s[j] - s[i - 1];
        if (ds == 0) {
          if (a == 0) ans += (long long)(n + 1) * n >> 1;
        } else {
          if (a % ds) continue;
          if (a / ds >= M) continue;
          ans += c[a / ds];
        }
      }
    }
    cout << ans << endl;
  }
  return 0;
}
