Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
const int M = 2 * 100000 + 1;
vector<int> adj[M];
int dx[] = {1, -1, 0, 0};
int dy[] = {0, 0, 1, -1};
int kx[] = {2, 2, -2, -2, 1, -1, 1, -1};
int ky[] = {1, -1, 1, -1, 2, 2, -2, -2};
int grid[100][100];
int level[M];
int previous[M];
bool visited[M];
bool con[M];
int row = 8, col = 8;
int process[M];
int parent[M];
int main() {
  ios_base::sync_with_stdio(false);
  int n, m;
  cin >> n >> m;
  char ch;
  int x, y, cnt = 0;
  bool flag = 0;
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < m; j++) {
      cin >> ch;
      if (ch == 'B') {
        cnt++;
        if (!flag) x = i, y = j, flag = 1;
      }
    }
  }
  double sq = sqrt(cnt);
  int p = (sq / 2) + 1;
  cout << x + p << " " << y + p << "\n";
  return 0;
}
