You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int main() {
  int a;
  string s;
  cin >> a >> s;
  map<int, long long> m;
  int n = s.size();
  int pre[n];
  pre[0] = s[0] - '0';
  for (int i = 1; i < n; i++) {
    pre[i] = pre[i - 1] + s[i] - '0';
  }
  for (int i = 0; i < n; i++) {
    int temp = 0;
    for (int j = i; j < n; j++) {
      if (i == 0)
        temp = pre[j];
      else
        temp = pre[j] - pre[i - 1];
      m[temp]++;
    }
  }
  if (a == 0) {
    long long z = 0, o = 0;
    for (auto first : m) {
      if (first.first == 0) {
        z += first.second;
      } else
        o += first.second;
    }
    cout << 2LL * z * o + z * z << endl;
    return 0;
  }
  long long ans = 0;
  for (auto first : m) {
    if (first.first != 0 && a % first.first == 0 && m.count(a / first.first)) {
      ans += m[a / first.first] * first.second;
    }
  }
  cout << ans;
  return 0;
}
