Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
inline long long int power(long long int x, long long int y) {
  long long int res = 1;
  x = x % 1000000007;
  while (y > 0) {
    if (y & 1) res = (res * x) % 1000000007;
    y = y >> 1;
    x = (x * x) % 1000000007;
  }
  return res % 1000000007;
}
inline long long int sum(long long int a, long long int b) {
  return ((a + b) % 1000000007 + 1000000007) % 1000000007;
}
inline long long int mul(long long int a, long long int b) {
  return ((a * b) % 1000000007 + 1000000007) % 1000000007;
}
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  cout.tie(0);
  ;
  long long int n, m;
  cin >> n >> m;
  string A[n];
  for (int i = 0; i < n; ++i) {
    cin >> A[i];
  }
  pair<long long int, long long int> start;
  for (int i = 0; i < n; ++i) {
    bool e = false;
    for (int j = 0; j < m; ++j) {
      if (A[i][j] == 'B') {
        start.first = i;
        start.second = j;
        e = true;
        break;
      }
    }
    if (e) break;
  }
  pair<long long int, long long int> end;
  for (int i = n - 1; i >= 0; i--) {
    bool e = false;
    for (int j = m - 1; j >= 0; j--) {
      if (A[i][j] == 'B') {
        end.first = i;
        end.second = j;
        e = true;
        break;
      }
    }
    if (e) break;
  }
  cout << (start.first + end.first) / 2 + 1 << " "
       << (start.second + end.second) / 2 + 1 << "\n";
  return 0;
}
