Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  int x, y, m, a, b, c, d, k = 0;
  string z;
  vector<string> s;
  cin >> x >> y;
  for (int i = 1; i <= x; i++) {
    cin >> z;
    s.push_back(z);
    m = z.find('B');
    if (m >= 0) {
      a = i;
      b = m + 1;
      if (i == x) {
        c = i;
        for (int j = 0; j < y; j++) {
          if (s[i - 1][j] == 'B') d = j + 1;
        }
      } else {
        for (i++; i <= x; i++) {
          cin >> z;
          s.push_back(z);
          m = z.find('B');
          if (m < 0) {
            c = i - 1;
            for (int j = 0; j < y; j++) {
              if (s[c - 1][j] == 'B') d = j + 1;
            }
            break;
          } else if (i == x) {
            c = i;
            for (int j = 0; j < y; j++) {
              if (s[i - 1][j] == 'B') d = j + 1;
            }
            break;
          }
        }
        break;
      }
      break;
    }
  }
  cout << (a + c) / 2 << " " << (b + d) / 2;
}
