The game of Berland poker is played with a deck of n cards, m of which are jokers. k players play this game (n is divisible by k).

At the beginning of the game, each player takes n/k cards from the deck (so each card is taken by exactly one player). The player who has the maximum number of jokers is the winner, and he gets the number of points equal to x - y, where x is the number of jokers in the winner's hand, and y is the maximum number of jokers among all other players. If there are two or more players with maximum number of jokers, all of them are winners and they get 0 points.

Here are some examples:

  * n = 8, m = 3, k = 2. If one player gets 3 jokers and 1 plain card, and another player gets 0 jokers and 4 plain cards, then the first player is the winner and gets 3 - 0 = 3 points; 
  * n = 4, m = 2, k = 4. Two players get plain cards, and the other two players get jokers, so both of them are winners and get 0 points; 
  * n = 9, m = 6, k = 3. If the first player gets 3 jokers, the second player gets 1 joker and 2 plain cards, and the third player gets 2 jokers and 1 plain card, then the first player is the winner, and he gets 3 - 2 = 1 point; 
  * n = 42, m = 0, k = 7. Since there are no jokers, everyone gets 0 jokers, everyone is a winner, and everyone gets 0 points. 



Given n, m and k, calculate the maximum number of points a player can get for winning the game.

Input

The first line of the input contains one integer t (1 ≤ t ≤ 500) — the number of test cases.

Then the test cases follow. Each test case contains three integers n, m and k (2 ≤ n ≤ 50, 0 ≤ m ≤ n, 2 ≤ k ≤ n, k is a divisors of n).

Output

For each test case, print one integer — the maximum number of points a player can get for winning the game.

Example

Input


4
8 3 2
4 2 4
9 6 3
42 0 7


Output


3
0
1
0

Note

Test cases of the example are described in the statement.
from math import *
from copy import *
from string import *				# alpha = ascii_lowercase
from random import *
from sys import stdin
from sys import maxsize
from operator import *				# d = sorted(d.items(), key=itemgetter(1))
from itertools import *
from collections import Counter		# d = dict(Counter(l))
import math
import math
import time
# PradeepGhosh_2017076

def bin1(l,r,k,t,b,val,ans):
	if(l>r):
		return ans
	else:
		mid=(l+r)//2
		v=k**mid
		if(v==val):
			return v
		elif(v>val):
			ans=mid
			return bin1(mid+1,r,k,t,b,val,ans)
		else:
			return bin1(l,mid-1,k,t,b,val,ans)
		
def bin2(l,r,k,t,b,val,ans):
	if(l>r):
		return ans
	else:
		mid=(l+r)//2
		v=t*(k**mid)+b*(mid)
		if(v==val):
			return v
		elif(v>val):
			ans=mid
			return bin2(l,mid-1,k,t,b,val,ans)
		else:
			return bin2(mid+1,r,k,t,b,val,ans)

def SieveOfEratosthenes(n): 
      
    # Create a boolean array "prime[0..n]" and initialize 
    #  all entries it as true. A value in prime[i] will 
    # finally be false if i is Not a prime, else true. 
    prime = [-1 for i in range(n+1)] 
    p = 2
    while (p * p <= n): 
          
        # If prime[p] is not changed, then it is a prime 
        if (prime[p] == -1): 
              
            # Update all multiples of p 
            for i in range(p * p, n+1, p): 
                prime[i] = p
        p += 1
    l1=[]
    for i in range(2,n+1):
    	if(prime[i]==-1):
    		l1.append(i)
    return l1
def bin(l,r,ll,val):
	if(l>r):
		return -1
	else:
		mid=(l+r)//2
		if(val>=ll[mid][0] and val<=ll[mid][1]):
			return mid
		elif(val<ll[mid][0]):
			return bin(l,mid-1,ll,val)
		else:
			return bin(mid+1,r,ll,val)
def deci(n):
	s=""
	while(n!=0):
		if(n%2==0):
			n=n//2
			s="0"+s
		else:
			n=n//2
			s="1"+s
	return s
def diff(s1,s2):
	if(len(s1)<len(s2)):
		v=len(s1)
		while(v!=len(s2)):
			s1="0"+s1
			v=v+1
	else:
		v=len(s2)
		while(v!=len(s1)):
			s2="0"+s2
			v=v+1
	c=0
	for i in range(len(s1)):
		if(s1[i:i+1]!=s2[i:i+1]):
			c=c+1
	return c
from sys import stdin, stdout 
def fac(a,b):
	v=a
	while(a!=b):
		v*=a-1
		a=a-1
	return v
def bino(l,r,n):
	if(l>r):
		return -1
	else:
		mid=(l+r)//2
		val1=math.log((n/mid)+1,2)
		val2=int(val1)
		if(val1==val2):
			return val1
		elif(val1<1.0):
			return bino(l,mid-1,n)
		else:
			return bino(mid+1,r,n)

def binary(l,r,val,ans):
	if(l>r):
		return -1
	else:
		mid=(l+r)//2
		v=val**5-mid**5
		print(v)
		if(v==ans):
			print("HOHOHOH")
			return mid
		elif(v<ans):
			return binary(mid+1,r,val,ans)
		else:
			return binary(l,mid-1,val,ans)
def check(n):
	v=1
	while(n!=0):
		if(n%10==0 or n%10==1):
			n=n//10
		else:
			v=0
			break
	return v
def stairs(n,m,val,c,l):
	if(val>n):
		return 100000
	elif(val==n):
		if(l[val]!=-1):
			return l[val]
		elif(c%m==0):
			l[val]=c
			return l[val];
		else:
			l[val]=100000
			return l[val]
	else:
		# if(l[val]!=-1):
		# 	return l[val]
		# else:
		l[val]=min(stairs(n,m,val+1,c+1,l),stairs(n,m,val+2,c+1,l))
		return l[val]
def fact(n):
	if(n==0 or n==1):
		return 1
	else:
		return n*fact(n-1)

def some(n):
	s=0
	while(n!=0):
		s+=fact(n%10)
		n//=10
	return s
def bin(ll,l,r,val,ans):
    if(l>r):
        return ans
    else:
        mid=(l+r)//2
        if(ll[mid]>=val):
            ans=mid
            return bin(ll,l,mid-1,val,ans)
        else:
        	return bin(ll,mid+1,r,val,ans)
            
def fn(n):
	c=-1
	for i in range(2,int(sqrt(n))+1):
		if(n%2==0):
			c=i
			break
	if(c==-1):
		c=n
	return c
def check(n):
	val=0
	while(n!=0):
		if(n%10>1):
			val=-1
			break
		n=n//10
	return val

def gcd(a,b):
	if(b==0):
		return a
	else:
		return gcd(b,a%b)

if __name__ == '__main__':
	t=int(input())
	for i in range(t):
		n,m,k=map(int,input().split(" "))
		val=n//k
		if(val>=m):
			print(m)
		else:
			a=m-val
			if(a%(k-1)==0):
				print(val-(a//(k-1)))
			else:
				print(val-(a//(k-1)+1))