Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
int n, m, a[2000][2000], ans = -1, mx, my;
char s[200];
int main() {
  cin >> n >> m;
  for (int i = 1; i <= n; i++) {
    cin >> s;
    for (int j = 0; j <= m - 1; j++) {
      if (s[j] == 'W')
        a[i][j + 1] = 0;
      else
        a[i][j + 1] = 1;
    }
  }
  for (int i = 1; i <= n; i++) {
    for (int j = 1; j <= m; j++) {
      for (int k = 0; k <= max(n, m); k++) {
        if (i - k < 0 || j - k < 0) continue;
        if (a[i + k][j] + a[i - k][j] + a[i][j - k] + a[i][j + k] +
                a[i - k][j - k] + a[i - k][j + k] + a[i + k][j - k] +
                a[i + k][j + k] ==
            8) {
          if (k > ans) {
            ans = k;
            mx = i, my = j;
          }
        }
      }
    }
  }
  cout << mx << " " << my << endl;
  return 0;
}
