Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
using pii = pair<int, int>;
using pll = pair<long long, long long>;
const int oo = 0x3f3f3f3f;
const long long long_inf = LONG_LONG_MAX / 2 - 2;
const int mod1 = 1500000001;
mt19937 rng(197);
mt19937 rnv(time(nullptr));
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  cout.tie(0);
  int n, m;
  cin >> n >> m;
  int lefter = 9999, righter = -1, upper = 99999, downer = -1;
  for (int i = 0; i < n; ++i) {
    string s;
    cin >> s;
    for (int j = 0; j < m; ++j) {
      if (s[j] == 'B') {
        lefter = min(j, lefter);
        righter = max(j, righter);
        upper = min(i, upper);
        downer = max(i, downer);
      }
    }
  }
  cout << (upper + downer) / 2 + 1 << ' ' << (lefter + righter) / 2 + 1;
}
