You are given a string s consisting of n lowercase Latin letters. Polycarp wants to remove exactly k characters (k ≤ n) from the string s. Polycarp uses the following algorithm k times:

  * if there is at least one letter 'a', remove the leftmost occurrence and stop the algorithm, otherwise go to next item; 
  * if there is at least one letter 'b', remove the leftmost occurrence and stop the algorithm, otherwise go to next item; 
  * ... 
  * remove the leftmost occurrence of the letter 'z' and stop the algorithm. 



This algorithm removes a single letter from the string. Polycarp performs this algorithm exactly k times, thus removing exactly k characters.

Help Polycarp find the resulting string.

Input

The first line of input contains two integers n and k (1 ≤ k ≤ n ≤ 4 ⋅ 10^5) — the length of the string and the number of letters Polycarp will remove.

The second line contains the string s consisting of n lowercase Latin letters.

Output

Print the string that will be obtained from s after Polycarp removes exactly k letters using the above algorithm k times.

If the resulting string is empty, print nothing. It is allowed to print nothing or an empty line (line break).

Examples

Input

15 3
cccaabababaccbc


Output

cccbbabaccbc


Input

15 9
cccaabababaccbc


Output

cccccc


Input

1 1
u


Output
import java.util.*;
import java.io.*;
 
public class codeforces {
	public static long GCD(long a, long b) {
 
		return b == 0 ? a : GCD(b, a % b);
	}
 
	public static long C(int a, int b, long[][] s) {
		int m = (int) 1e9 + 7;
		if (s[a][b] >= 0) {
			return s[a][b];
		} else if (a < b | a < 0 | b < 0) {
			s[a][b] = 0;
			return 0;
		} else if (a == b | b == 0) {
			s[a][b] = 1;
			return 1;
		} else {
			return s[a][b] = (C(a - 1, b, s) % m + C(a - 1, b - 1, s) % m) % m;
		}
 
	}
 
	public static void main(String[] args) throws IOException {
 
		Scanner sc = new Scanner(System.in);
		PrintWriter pw = new PrintWriter(System.out);
		int a= sc.nextInt();
		int b= sc.nextInt();
		int B=b;
		String c=sc.next();
		int [] q=new int[26];
		int [] Q=new int[26];
		for(int i=0;i<a;i++) {
			q[c.charAt(i)-97]+=1;
		}
		for(int i=0;i<26;i++) {
			if (B>=q[i]) {
		        Q[i]=q[i];
		        B-=q[i];
		        q[i]=0;
		}
		    else {
		        Q[i]=B;
		        break;
		    }
		}
		for(int i=0;i<a;i++) {
			if (Q[c.charAt(i)-97]==0 || 0>=b)
		        pw.print(c.charAt(i));
		    else {
		        Q[c.charAt(i)-97]-=1;
		        b--;
		    }
		}
		pw.flush();
		
		
	}
 
	static class Scanner {
		StringTokenizer st;
		BufferedReader br;
 
		public Scanner(InputStream s) {
			br = new BufferedReader(new InputStreamReader(s));
		}
 
		public Scanner(FileReader r) {
			br = new BufferedReader(r);
		}
 
		public String next() throws IOException {
			while (st == null || !st.hasMoreTokens())
				st = new StringTokenizer(br.readLine());
			return st.nextToken();
		}
 
		public int nextInt() throws IOException {
			return Integer.parseInt(next());
		}
 
		public long nextLong() throws IOException {
			return Long.parseLong(next());
		}
 
		public String nextLine() throws IOException {
			return br.readLine();
		}
 
		public double nextDouble() throws IOException {
			String x = next();
			StringBuilder sb = new StringBuilder("0");
			double res = 0, f = 1;
			boolean dec = false, neg = false;
			int start = 0;
			if (x.charAt(0) == '-') {
				neg = true;
				start++;
			}
			for (int i = start; i < x.length(); i++)
				if (x.charAt(i) == '.') {
					res = Long.parseLong(sb.toString());
					sb = new StringBuilder("0");
					dec = true;
				} else {
					sb.append(x.charAt(i));
					if (dec)
						f *= 10;
				}
			res += Long.parseLong(sb.toString()) / f;
			return res * (neg ? -1 : 1);
		}
 
		public boolean ready() throws IOException {
			return br.ready();
		}
 
	}
 
}
