Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
// package problems_A;

import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        int m = in.nextInt();
        List<String> list = new ArrayList<>();
        int indexOfFirstB = -1;
        int indexOfFirstBRow = -1;
        for (int i = 0; i < n; i++) {
            String s = in.next();
            list.add(s);
            if (indexOfFirstB == -1) {
                indexOfFirstB = s.indexOf('B');
                indexOfFirstBRow = i;
            }
        }
        int cntB = 0;
        for (int i = 0; i < n; i++) cntB = list.get(i).contains("B") ? cntB + 1 : cntB;

        int[] center = new int[2];
        center[0] = (indexOfFirstB + (cntB-1)/2) + 1;
        center[1] = indexOfFirstBRow + (cntB-1)/2 +1;
        System.out.println(center[1]+" "+center[0]);

    }
}
