You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
import java.io.*;
import java.util.*;

public class solution {
    public static void main(String[] args) throws java.lang.Exception {
        in.init(System.in);
        int a=in.nextInt();
        String s=in.next();
        int n=s.length(),i,j;
        long[] map=new long[36100];
        int[] sum=new int[n+1];
        sum[0]=0;for (i=1;i<=n;++i) sum[i]=sum[i-1]+(int)s.charAt(i-1)-(int)'0';
        long kq=0;
        for (i=1;i<=n;++i) for (j=0;j<i;++j) map[sum[i]-sum[j]]++;
        if (a==0) {
             for (i=0;i<=sum[n];++i) kq+=map[0]*map[i];
        }
        for (i=1;i<=sum[n];++i) if (a%i==0&a/i<=sum[n]) kq+=map[i]*map[a/i];
        System.out.println(kq);
    }
}

class in {
    static BufferedReader reader;
    static StringTokenizer tokenizer;
    static void init(InputStream input) {
        reader = new BufferedReader(
                     new InputStreamReader(input) );
        tokenizer = new StringTokenizer("");
    }
    static String next() throws IOException {
        while ( ! tokenizer.hasMoreTokens() ) {
            
            tokenizer = new StringTokenizer(
                   reader.readLine() );
        }
        return tokenizer.nextToken();
    }
    static int nextInt() throws IOException {
        return Integer.parseInt( next() );
    }
    static double nextDouble() throws IOException {
        return Double.parseDouble( next() );
    }
}