You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
import java.io.*;
import java.util.*;

public class A
{
	private final static int len = 40000;
	public static void main(String [] args) throws IOException
	{
		Scanner in = new Scanner(System.in);
		int a = in.nextInt();
		char [] word = in.next().toCharArray();

		int n = word.length;
		int [] easy = new int[n];
		for(int i = 0 ; i < n ; i++)
			easy[i] = word[i] - '0';


		long [] sum = new long[n+1];
		for(int i = 1 ; i <= n ; i++)
			sum[i] = sum[i-1] + easy[i-1];

		long [] calc = new long[len];
		for(int i = 0 ; i < n ; i++)
			for(int j = i ; j < n ; j++)
				calc[((int) (sum[j + 1] - sum[i]))]++;

		long res = 0;

		for(int x = 0 ; x < n ; x++)
			for(int y = x ; y < n ; y++)
			{
				long have = sum[y+1] - sum[x];
				if(have == 0 && a == 0)
				{
					res += n*(n+1)/2;
					continue;
				}
				if(have == 0 && a != 0)
					continue;

				if(a % have != 0)
					continue;
				long tmp = a/have;
				if(tmp >= len)
					continue;

				res += calc[((int) tmp)];
			}


		System.out.println(res);

	}

}
