You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
signed main() {
  long long n;
  string s;
  cin >> n >> s;
  map<long long, long long> m;
  for (long long i = 0; i < s.size(); i++) {
    long long soma = 0;
    for (long long j = i; j < s.size(); j++) {
      soma += s[j] - '0';
      m[soma] += 1;
    }
  }
  long long s0 = 0;
  for (auto i : m) s0 += i.second;
  long long resp = 0;
  for (long long i = 0; i < s.size(); i++) {
    long long soma = 0;
    for (long long j = i; j < s.size(); j++) {
      soma += s[j] - '0';
      if (n == 0 && soma == 0) resp += s0;
      if (soma == 0) continue;
      if (n % soma != 0) continue;
      if (m.find(n / soma) == m.end()) continue;
      resp += m[n / soma];
    }
  }
  cout << resp << endl;
}
