You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
import java.util.*;
import java.math.*;
import java.io.*;
import java.text.*;

public class A {

    //public static PrintWriter pw;
    public static PrintWriter pw = new PrintWriter(System.out);

    public static void solve() throws IOException {
//	pw=new PrintWriter(new FileWriter("C:\\Users\\shree\\Downloads\\small_output_in"));
        FastReader sc = new FastReader();
        int a = sc.I();
        char s[] = sc.next().toCharArray();

        int n = s.length;
        int c[]=new int[n];
        for(int i=0;i<n;i++) c[i]=s[i]-'0';

        int b[] = new int[40001];

        for(int i=0;i<n;i++){
            int ss = 0;
            for(int j=i;j<n;j++){
                ss += c[j];
                b[ss]++;
            }
        }

        long ans = 0;

        for(int i=0;i<n;i++){
            int ss = 0;

            for(int j=i;j<n;j++){
                ss += c[j];
                if(ss == 0){
                    if(a == 0)	ans += n*(n+1)/2;
                }
                else{

                    if(a%ss==0 && (a/ss)<= 40000) {
                        ans += b[a/ss];

                    }

                }

            }
        }

        pw.println(ans);
        pw.close();


    }

    public static void main(String[] args) {
        new Thread(null, new Runnable() {
            public void run() {
                try {

                    solve();
                } catch (Exception e) {
                    e.printStackTrace();
                }
            }
        }, "1", 1 << 26).start();

    }

    static BufferedReader br;
    static long M = (long) 1e9 + 7;

    static class FastReader {

        StringTokenizer st;

        public FastReader() throws FileNotFoundException {
            //br=new BufferedReader(new FileReader("C:\\Users\\shree\\Downloads\\B-small-practice.in"));
            br = new BufferedReader(new InputStreamReader(System.in));

        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int I() {
            return Integer.parseInt(next());
        }

        long L() {
            return Long.parseLong(next());
        }

        double D() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }

        public boolean hasNext() throws IOException {
            while (st == null || !st.hasMoreTokens()) {
                String s = br.readLine();
                if (s == null) {
                    return false;
                }
                st = new StringTokenizer(s);
            }
            return true;
        }

    }
}