You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long int x_array[5000], y_array[5000];
long long int dx[50001], dy[50001];
int main() {
  int a;
  char str[5000];
  long long int cnt = 0;
  scanf("%d", &a);
  scanf("%s", str);
  int len = strlen(str);
  for (int i = 0; i < len; i++) {
    int j = i + 1;
    x_array[j] = x_array[j - 1] + str[i] - '0';
    y_array[j] = y_array[j - 1] + str[i] - '0';
  };
  for (int i = 1; i <= len; i++) {
    for (int j = i; j <= len; j++) {
      dx[x_array[j] - x_array[i - 1]]++;
      dy[y_array[j] - y_array[i - 1]]++;
    }
  }
  if (a != 0) {
    for (int i = 1; i < 50000; i++) {
      if (dx[i] && a % i == 0) {
        int temp = a / i;
        if (temp >= 50000) continue;
        cnt += dx[i] * dy[temp];
      }
    }
  } else if (a == 0) {
    for (int i = 1; i < 50000; i++) {
      cnt += dx[0] * dy[i] + dx[i] * dy[0];
    }
    if (dx[0]) cnt += dx[0] * dy[0];
  }
  printf("%I64d\n", cnt);
  return 0;
}
