Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
int main() {
  long int a, b, i, j;
  cin >> a >> b;
  char str[a][b];
  long int r, c, len1 = 0, r_no, r_no_1, c_no, c_no_1;
  for (i = 0; i < a; i++)
    for (j = 0; j < b; j++) {
      cin >> str[i][j];
      if (str[i][j] == 'B') {
        r = i;
        c = j;
      }
    }
  for (i = r + 1; i < a; i++) {
    if (str[i][c] != 'B') break;
  }
  r_no = i - 1;
  for (i = r_no; i >= 0; i--) {
    if (str[i][c] != 'B') break;
  }
  r_no_1 = i + 1;
  r_no = (r_no + r_no_1) / 2;
  for (i = c; i < b; i++) {
    if (str[r][i] != 'B') break;
  }
  c_no = i - 1;
  for (i = c_no; i >= 0; i--) {
    if (str[r][i] != 'B') break;
  }
  c_no_1 = i + 1;
  c_no = (c_no + c_no_1) / 2;
  cout << r_no + 1 << " " << c_no + 1;
}
