Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
const long long int MOD = 1e9 + 7;
const long long int INF = 1e18;
const long long int N = 1e6 + 20;
vector<long long int> g[N];
long long int vis[N];
int32_t main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);
  long long int tc = 1;
  while (tc--) {
    long long int n, m;
    cin >> n >> m;
    char a[n][m];
    vector<pair<long long int, long long int>> ans;
    for (long long int i = 0; i < n; i++) {
      for (long long int j = 0; j < m; j++) {
        cin >> a[i][j];
        if (a[i][j] == 'B') {
          ans.push_back({i + 1, j + 1});
        }
      }
    }
    long long int r = (ans[0].first + ans[ans.size() - 1].first) / 2;
    long long int c = (ans[0].second + ans[ans.size() - 1].second) / 2;
    cout << r << ' ' << c << '\n';
  }
}
