You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int a;
int d[4001], cnt[4001 * 10];
char str[4001];
int main() {
  scanf("%d %s", &a, str);
  int n = strlen(str);
  for (int i = 0; i < n; ++i) d[i] = str[i] - '0';
  for (int i = 0; i < n; ++i) {
    int sum = 0;
    for (int j = i; j < n; ++j) {
      sum += d[j];
      ++cnt[sum];
    }
  }
  long long ans = 0;
  for (int i = 0; i < n; ++i) {
    int sum = 0;
    for (int j = i; j < n; ++j) {
      sum += d[j];
      if (sum > 0 && a % sum == 0 && a / sum <= n * 10)
        ans += cnt[a / sum];
      else if (sum == 0 && a == 0)
        ans += n * (n + 1) / 2;
    }
  }
  printf("%I64d\n", ans);
  return 0;
}
