Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
import java.util.Scanner;
public class Main {
	
	public static void main(String[] args) {
		// TODO 自动生成的方法存根
		Scanner in=new Scanner(System.in);
		String Line;
		int n,m;
		int r,c;
		int x1=0,y1=0,x2=0,y2=0;
		int flag=0;
		n=in.nextInt();
		m=in.nextInt();
		Line=in.nextLine();
		
		for(int i=1;i<=n;i++) {
			Line=in.nextLine();
			
			for(int j=0;j<Line.length();j++) {
				if(Line.charAt(j)=='B'&&flag==0) {
					x1=x2=i;
					y1=y2=j+1;
					flag=1;
				}else {
					if(Line.charAt(j)=='B') {
						x2=i;
						y2=j+1;
					}
				}
			}
		}
		r=(x1+x2)/2;
		c=(y1+y2)/2;
		System.out.println(r+" "+c);
	}

}
