Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
#pragma warning(disable : 4786)
#pragma warning(disable : 4996)
using namespace std;
int main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  int n, m;
  cin >> n >> m;
  char s[n][m];
  int start = -1;
  int x, y, a, b;
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < m; j++) {
      cin >> s[i][j];
    }
  }
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < m; j++) {
      if (s[i][j] == 'B' && start == -1) {
        start = 0;
        x = i;
        y = j;
      }
      if ((j == m - 1) && s[i][j] == 'B' && start != -1) {
        a = i;
        b = j;
        break;
      }
      if (s[i][j] == 'W' && s[i][j - 1] == 'B' && start != -1) {
        a = i;
        b = j;
        break;
      }
    }
  }
  cout << x + (abs(x - a)) / 2 + 1 << " " << y + (abs(x - a)) / 2 + 1;
}
