You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int maxn = 554400;
char ss[maxn];
long long a, n;
long long x[maxn], s[maxn];
long long h[maxn];
int main() {
  cin >> a;
  cin >> ss;
  n = (long long)strlen(ss);
  for (int i = 0; i < n; i++)
    x[i + 1] = ss[i] - '0', s[i + 1] = s[i] + x[i + 1];
  long long i, j;
  for (i = 1; i <= n; i++)
    for (j = 0; j < i; j++) h[s[i] - s[j]]++;
  long long ans = 0;
  if (a == 0) {
    for (i = 0; i <= s[n]; i++) ans += h[0] * h[i];
  }
  for (i = 1; i <= s[n]; i++) {
    if ((a % i == 0) && (a / i <= s[n])) ans += h[i] * h[a / i];
  }
  cout << ans << endl;
}
