Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
import java.util.*;
import java.io.*;

public class A {
	public static void main(String args[]) throws IOException {
		Scanner in = new Scanner(System.in);
		int n = in.nextInt();
		int m = in.nextInt();
		char a[][] = new char[n][m];
		for (int i = 0; i < n; i++) {
			String s = in.next();
			for (int j = 0; j < m; j++) {
				a[i][j] = s.charAt(j);
			}
		}
		int minX = n + m;
		int maxX = 0;
		int minY = n + m;
		int maxY = 0;
		for (int i = 0; i < n; i++) {
			for (int j = 0; j < m; j++) {
				if (a[i][j] == 'B') {
					minX = Math.min(minX, i + 1);
					minY = Math.min(minY, j + 1);
					maxX = Math.max(maxX, i + 1);
					maxY = Math.max(maxY, j + 1);
				}
			}
		}
		System.out.println((minX + maxX)/2 + " " + (minY + maxY)/2);
		in.close();
	}
}
