You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
char ss[5000];
long long v[5000], s[5000], p[40000], n, sz, i, j, k;
int main(void) {
  cin >> n;
  cin >> ss;
  sz = strlen(ss);
  for (i = 0; i < sz; i++) v[i] = ss[i] - '0';
  s[0] = v[0];
  p[s[0]]++;
  for (i = 1; i < sz; i++) {
    s[i] = s[i - 1] + v[i];
    p[s[i]]++;
  }
  for (i = 0; i < sz; i++)
    for (j = i + 1; j < sz; j++) p[s[j] - s[i]]++;
  if (n == 0) {
    for (i = 1; i < 39990; i++) k += p[i];
    k = k * p[0] * 2;
    k += p[0] * p[0];
    cout << k;
    return 0;
  }
  for (i = 1; (i * i <= n) && (i < 39990); i++)
    if ((n % i == 0) && (n / i < 39990)) {
      if (i * i == n)
        k += p[i] * p[i];
      else
        k += 2 * p[i] * p[n / i];
    }
  cout << k;
  return 0;
}
