Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
const long long int N = 1000005;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);
  long long int n, m;
  cin >> n >> m;
  char s[n + 2][m + 2];
  for (long long int i = 1; i <= n; i++) {
    for (long long int j = 1; j <= m; j++) cin >> s[i][j];
  }
  long long int f = 0, k;
  long long int st = 0, en;
  for (long long int i = 1; i <= n; i++) {
    for (long long int j = 1; j <= m; j++) {
      if (s[i][j] == 'B') {
        f = i;
        k = j;
        break;
      }
    }
    if (f) break;
  }
  for (long long int j = k; j <= m; j++) {
    if (s[f][j] == 'W') {
      en = j - 1;
      break;
    } else if (j == m) {
      en = j;
      break;
    }
  }
  long long int y = (k + en) / 2;
  for (long long int i = f; i <= n; i++) {
    if (s[i][k] == 'W') {
      cout << (f + i - 1) / 2 << ' ' << y;
      break;
    } else if (i == n) {
      cout << (f + i) / 2 << ' ' << y;
      break;
    }
  }
  return 0;
}
