Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
const int MX = 1147483646;
const long long MX2 = 3223372036854775800;
const int MOD = 1000000007;
int main() {
  cin.tie(NULL);
  cout.tie(0);
  ios::sync_with_stdio(false);
  int n, m;
  cin >> n >> m;
  int i, j;
  string s[1000];
  int sy, sx;
  int ey, ex;
  bool f = 0;
  for (i = 1; i <= n; i++) {
    cin >> s[i];
    for (j = 0; j < m; j++) {
      if (s[i][j] == 'B' && f == 0) {
        sy = i;
        sx = j + 1;
        f = 1;
      }
    }
  }
  f = 0;
  for (i = n; i >= 1; i--) {
    for (j = m - 1; j >= 0; j--) {
      if (s[i][j] == 'B' && f == 0) {
        ey = i;
        ex = j + 1;
        f = 1;
      }
    }
  }
  cout << (sy + ey) / 2 << " " << (sx + ex) / 2;
  return 0;
}
