You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long ans, n, q, a[4005], b[40005];
char s[4005];
int main() {
  scanf("%d", &q);
  scanf("%s", s + 1);
  n = strlen(s + 1);
  for (int i = 1; i <= n; i++) a[i] = a[i - 1] + s[i] - 48;
  for (int i = 1; i <= n; i++)
    for (int j = 0; j < i; j++) b[a[i] - a[j]]++;
  for (int i = sqrt(q); i; i--)
    if (q % i == 0 && i < 40005 && q / i < 40005)
      ans += b[i] * b[q / i] * ((q / i != i) + 1);
  if (!q) ans = b[0] * n * (n + 1) - b[0] * b[0];
  printf("%I64d\n", ans);
  return 0;
}
