Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
const int MAX = 1e5;
using namespace std;
int main() {
  ios::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(0);
  ;
  int n, m;
  cin >> n >> m;
  char arr[n + 1][m + 1];
  for (int i = 1; i <= n; i++) {
    for (int j = 1; j <= m; j++) {
      cin >> arr[i][j];
    }
  }
  for (int i = 1; i <= n; i++) {
    for (int j = 1; j <= m; j++) {
      if (arr[i][j] == 'B') {
        int len = 1;
        for (int k = j + 1; k <= m; k++) {
          if (arr[i][k] == 'B') len++;
        }
        int row = j + (len / 2);
        len = 1;
        for (int k = i + 1; k <= n; k++) {
          if (arr[k][j] == 'B') len++;
        }
        cout << i + (len / 2) << " " << row << '\n';
        return 0;
      }
    }
  }
}
