You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long int vis[10000000];
long long int dp[10000000];
int main() {
  long long int i, j, k, l, n, m, q, sum, p, d;
  d = 0;
  cin >> n;
  string s;
  cin >> s;
  l = s.length();
  for (i = 0; i < l; i++) dp[i + 1] = s[i] - '0';
  for (i = 1; i <= l; i++) dp[i] = dp[i] + dp[i - 1];
  for (i = 1; i <= l; i++) {
    for (j = i; j <= l; j++) {
      d++;
      p = dp[j] - dp[i - 1];
      vis[p]++;
    }
  }
  if (n == 0) {
    p = 2 * d * vis[0];
    p = p - vis[0] * vis[0];
    cout << p;
    exit(0);
  }
  sum = 0;
  for (i = 1; i <= 1000000; i++) {
    if (i > n) continue;
    if ((n % i) != 0) {
      continue;
    }
    if ((n / i) > 1000999) {
      continue;
    }
    sum += vis[i] * vis[n / i];
  }
  cout << sum;
}
