Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, m;
  cin >> n >> m;
  char S[n][m + 1];
  int i, j;
  int x1, x2, x3, x4, x5, x6, x7, x8;
  for (i = 0; i < n; i++) {
    cin >> S[i];
    S[i][m] = '\0';
  }
  int ulr = -1, ulc = -1, urr = -1, urc = -1;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      if (S[i][j] == 'B') {
        x1 = i;
        x2 = j;
        break;
      }
    }
  }
  for (i = 0; i < n; i++) {
    for (j = m - 1; j >= 0; j--) {
      if (S[i][j] == 'B') {
        x3 = i;
        x4 = j;
        break;
      }
    }
  }
  for (i = n - 1; i >= 0; i--) {
    for (j = 0; j < m; j++) {
      if (S[i][j] == 'B') {
        x5 = i;
        x6 = j;
        break;
      }
    }
  }
  for (i = n - 1; i >= 0; i--) {
    for (j = m - 1; j >= 0; j--) {
      if (S[i][j] == 'B') {
        x7 = i;
        x8 = j;
        break;
      }
    }
  }
  int a1 = x1 + x5;
  a1 = a1 / 2;
  a1++;
  int b1 = x2 + x4;
  b1 = b1 / 2;
  b1++;
  cout << a1 << " " << b1;
}
