Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
import java.util.Scanner;

public class tg {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		int m = sc.nextInt();
		char[][] arr = new char[n][m];
		for(int i=0;i<n;i++){
			String temp = sc.next();
			for(int j=0;j<m;j++){
				arr[i][j]=temp.charAt(j);
			}
		}
		for(int i=0;i<n;i++){
			for(int j=0;j<m;j++){
				if(arr[i][j]=='B'){
					int len = 1;
					int pt = j;
					while(++j<m && arr[i][j]=='B'){
						len++;
					}
					if(len%2!=0){
						int flag=0;
						for(int x=1;x<len && i+x<n;x++){
							for(int y=0;y<len && y+pt<m;y++){
								if(arr[i+x][y+pt]!='B'){
									flag=1;
									break;
								}
							}
							if(flag==1){
								break;
							}
						}
						if(flag==0){
							System.out.println((i+1+len/2)+" "+(pt+1+len/2));
							return;
						}
					}
					
				}
			}
		}
		

	}

}
