You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long H[20000000], A[4005];
char s[4005];
long long bsearch(long long x, long long n) {
  int l = 0, r = n + 1, mid;
  while (r - l > 1) {
    mid = l + r >> 1;
    if (H[mid] <= x)
      l = mid;
    else
      r = mid;
  }
  return l;
}
int main() {
  int a, n, i, num, l, r, x, t;
  long long ans;
  scanf("%d%s", &a, s + 1), n = strlen(s + 1);
  for (i = 1; i <= n; i++) A[i] = s[i] - '0';
  num = 0;
  for (l = 1; l <= n; l++) {
    x = 0;
    for (r = l; r <= n; r++) x += A[r], H[++num] = x;
  }
  sort(H + 1, H + 1 + num);
  ans = 0;
  for (l = 1; l <= n; l++) {
    x = 0;
    for (r = l; r <= n; r++) {
      x += A[r];
      if (!x) {
        if (!a) ans += num;
        continue;
      } else {
        if (a % x) continue;
        t = a / x;
      }
      ans += bsearch(t, num) - bsearch(t - 1, num);
    }
  }
  printf("%I64d\n", ans);
  return 0;
}
