You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
import java.util.*;
import java.io.*;


public class Solution {

	static class FastScanner implements Closeable {
	    BufferedReader in;
	    StringTokenizer st;
	    FastScanner() throws IOException {
	        in = new BufferedReader(new InputStreamReader(System.in));
	    }
	    String next() throws IOException {
	        while (st == null || !st.hasMoreTokens()) {
	            String line = in.readLine();
	            if (line == null) {
	            	return null;
	            }
	            st = new StringTokenizer(line);
	        }
	        return st.nextToken();
	    }
	    int nextInt() throws IOException {
	        return Integer.parseInt(next());
	    }
	    public void close() throws IOException {
	        in.close();
	        st = null;
	    }
	}

	
	public static void main(String[] args) throws IOException{
		
		try(FastScanner sc = new FastScanner();
			PrintWriter out = new PrintWriter(System.out)){
			
			int a = sc.nextInt();
			String str = sc.next();
			char[] arr1 = str.toCharArray();
			int[] arr = new int[arr1.length];
			for(int i = 0; i < arr.length; i++)
				arr[i] = arr1[i] - '0';

			int[] sum = new int[9*4000];
			for(int i = 0; i < str.length(); i++){
				int s = 0;
				for(int j = i; j < str.length(); j++){
					s += arr[j];
					sum[s]++;
				}
			}

			int n = str.length();
			if(a == 0){
				long x = (long)sum[0]*(n)*(n+1) - (long)sum[0]*sum[0];
				out.println(x);
				return;
			}

			long x = 0L;
			for(int i = 1; i < 9*4000; i++){
				if(a % i == 0){
					int y = a/i;
					x += (long)(sum[i]*(long)(y <= 9*4000?sum[y]:0));
				}
			}

			out.println(x);
		}

	}	
}

