You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int main() {
  long long a;
  long long sum[4010] = {0};
  map<int, long long> freq;
  string s;
  cin >> a >> s;
  for (int i = 0; i < s.size(); ++i) {
    sum[i + 1] = sum[i] + s[i] - '0';
  }
  for (int i = 0; i < s.size(); ++i) {
    for (int j = i; j < s.size(); ++j) {
      long long val = sum[j + 1] - sum[i];
      freq[val]++;
    }
  }
  if (a == 0) {
    long long n = s.size();
    n = (n * (n + 1) - freq[0]) * freq[0];
    cout << n << endl;
    return 0;
  }
  long long ret = 0;
  for (int i = 0; i < s.size(); ++i) {
    for (int j = i; j < s.size(); ++j) {
      long long val = sum[j + 1] - sum[i];
      if (val == 0 || a % val) continue;
      ret += freq[a / val];
    }
  }
  cout << ret << endl;
  return 0;
}
