Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
import java.util.*;
import java.io.*;

public class Main {

	static char[][] matrix;
	static int n, m;
	static Scanner console;
	
	public static void main(String[] args) {
		console = new Scanner(System.in);
		n = console.nextInt(); m = console.nextInt();
		matrix = new char[n][m];
		console.nextLine();
		String row;
		int lenb = 0;
		for(int i = 0; i < n; i++) {
			row = console.nextLine();
//			System.out.println(row);
			for(int j = 0; j<m; j++)
				matrix[i][j] = row.charAt(j);
		}
		int i = 0, j = 0;
		outer: for(i = 0; i < n; i++) {
			for(j = 0; j<m; j++) {
				if(matrix[i][j] == 'B') {
					lenb++;
					if(j == m - 1 || matrix[i][j+1] == 'W') break outer;
				}
			}
		}
		System.out.println((i + 1 + lenb / 2) + " " + (j + 1 - lenb / 2));
	}
}
