You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int N = 4e3 + 10;
map<int, int> cnt;
int a;
char s[N];
int main() {
  for (; ~scanf("%d", &a);) {
    scanf("%s", s);
    cnt.clear();
    int n = strlen(s), tot = 0;
    for (int i = 0; i < n; i++) s[i] -= '0';
    for (int i = 0; i < n; i++) {
      int t = 0;
      for (int j = i; j < n; j++) {
        tot++;
        t += s[j];
        cnt[t]++;
      }
    }
    long long result = 0;
    for (int i = 0; i < n; i++) {
      int t = 0;
      for (int j = i; j < n; j++) {
        t += s[j];
        if (!a) {
          if (!t)
            result += tot;
          else
            result += cnt[0];
        } else if (t && a % t == 0)
          result += cnt[a / t];
      }
    }
    cout << result << endl;
  }
  return 0;
}
