You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, a;
  cin >> a;
  string array;
  cin >> array;
  n = array.size();
  map<int, int> mapp;
  vector<int> line(n);
  for (int i = 0; i < n; i++) line[i] = array[i] - '0';
  vector<int> partial(n + 1, 0);
  for (int i = 0; i < n; i++) partial[i + 1] = partial[i] + line[i];
  for (int i = 1; i < n + 1; i++)
    for (int j = 0; j < i; j++) {
      if (mapp.find(partial[i] - partial[j]) == mapp.end())
        mapp[partial[i] - partial[j]] = 1;
      else
        mapp[partial[i] - partial[j]] += 1;
    }
  long long result = 0;
  if (a == 0) {
    int zero = 0, nonzero = 0;
    if (mapp.find(0) != mapp.end()) zero = mapp[0];
    map<int, int>::iterator it = mapp.begin();
    while (it != mapp.end()) {
      if ((*it).first != 0) nonzero += (*it).second;
      it++;
    }
    if (zero != 0) result = zero * 1ll * zero + 2 * zero * 1ll * nonzero;
    cout << result;
    return 0;
  }
  for (int i = 1; i * i <= a; i++) {
    if (((a % i) == 0) && (mapp.find(i) != mapp.end()) &&
        (mapp.find(a / i) != mapp.end())) {
      if (i * i == a)
        result += mapp[i] * 1ll * mapp[i];
      else
        result += 2 * mapp[i] * 1ll * mapp[a / i];
    }
  }
  cout << result;
  return 0;
}
