Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
# -*- coding: utf-8 -*-
"""
Created on Mon Aug 27 22:04:05 2018

@author: japes
"""
def check(n,m,arr):
    for i in range (n):
        for j in range (m):
            if arr[i][j]=='B':
                flagi_r=i
                flagi_c=j
                return flagi_r,flagi_c
def row_end(n,m,r_i,c_i,arr):
    for i in range(r_i,n+1):
        t= arr[i]
        if t[c_i]=='W'or t[c_i]=='#':
            return i-1
def column_end(n,m,r_i,c_i,arr):
    for i in range(c_i,m+1):
        t=arr[r_i]
        if t[i]=='W'or t[i]=='#':
            return i-1
    
n,m=map(int,input().split())
arr=[]
for i in range(n):
    t=input()
    t+='#'
    arr.append(t)
arr.append('#'*m)
r_i,c_i=check(n,m,arr)
r_e=row_end(n,m,r_i,c_i,arr)
c_e=column_end(n,m,r_i,c_i,arr)
r=r_i+int((r_e-r_i)/2)+1
c=c_i+int((c_e-c_i)/2)+1
print(r,c)