You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long sum[4001];
long long getsum(int a, int b) {
  if (a == 0) return sum[b];
  return sum[b] - sum[a - 1];
}
map<long long, int> ss;
int main() {
  long long a;
  cin >> a;
  string s;
  cin >> s;
  int n = s.size();
  for (int i = 0; i < n; i++) {
    sum[i] += (s[i] - '0');
    if (i) sum[i] += sum[i - 1];
  }
  long long as = 0;
  long long s0 = 0;
  for (int i = 0; i < n; i++) {
    for (int ii = i; ii < n; ii++) {
      as++;
      if (getsum(i, ii) <= a) {
        ss[getsum(i, ii)]++;
      }
      if (getsum(i, ii) == 0) {
        s0++;
      }
    }
  }
  long long v = 0;
  for (int i = 0; i < n; i++) {
    for (int ii = i; ii < n; ii++) {
      long long su = getsum(i, ii);
      if (su == 0 && a == 0)
        v += as;
      else if (a == 0) {
        v += s0;
      } else if (su > 0 && su <= a) {
        if (a % su == 0) {
          v += ss[a / su];
        }
      }
    }
  }
  cout << v << endl;
}
