You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long len, arr[((int)5e5 + 10)];
long long val, dp[((int)5e5 + 10)];
int a;
string str;
int main() {
  long long ans = 0;
  scanf("%d", &a);
  cin >> str;
  for (int i = 0; i <= str.length() - 1; i++) {
    arr[++len] = str[i] - '0';
  }
  int n = len;
  for (int i = 1; i <= n; i++) {
    val = 0;
    for (int j = i; j <= n; j++) {
      val += arr[j];
      dp[val]++;
    }
  }
  if (a == 0) {
    for (int i = 1; i <= 36000; i++) {
      ans += 2 * dp[0] * dp[i];
    }
    ans += dp[0] * dp[0];
    cout << ans;
    return 0;
  }
  for (int i = 1; i <= 36000; i++) {
    if (dp[i] && a % i == 0 && a / i <= 36000) {
      ans += dp[i] * dp[a / i];
    }
  }
  cout << ans << '\n';
}
