Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1

import java.util.Scanner;

public class find_square {
 public static void main(String[] args) {
	Scanner sc = new Scanner(System.in);
	int n = sc.nextInt(),m=sc.nextInt();
	int r1=0,rf=0,c1=0,cf=0;
	boolean rr=false,cc=false;
	int c[][]=new int[n][m];
	for(int i=0;i<n;i++){
		String s = sc.next();
		for(int j=0;j<m;j++){
			c[i][j]=s.charAt(j)-'a';
		}}
	for(int i=0;i<n;i++){
		for(int j=0;j<m;j++){
			if(c[i][j]=='B'-'a'){
			//	System.out.println(i+" "+j);
				if(!rr) {r1=i;rr=true; };
				if(!cc) {c1=j;cc=true;};
				cf=j;rf=i;
			}
		}
	}
	int r=(r1+rf+2)/2;
	int ccc = (c1+cf+2)/2;
	//System.out.println(c1+"  "+cf);
	System.out.println(r+" "+ccc);
}
}
