You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long pre[4000 + 10];
map<long long, long long> _map;
int main() {
  long long a;
  cin >> a;
  string sh;
  cin >> sh;
  long long n = sh.length();
  sh = " " + sh;
  for (long long i = 1; i <= n; i++) {
    pre[i] = pre[i - 1] + (sh[i] - '0');
  }
  for (long long i = 1; i <= n; i++) {
    for (long long j = i; j <= n; j++) {
      _map[pre[j] - pre[i - 1]]++;
    }
  }
  long long res = 0;
  if (a == 0) {
    res = (n * (n + 1)) / 2 * _map[0] * 2 - _map[0] * _map[0];
    cout << res << endl;
    return 0;
  }
  for (long long i = 1; i <= n; i++) {
    for (long long j = i; j <= n; j++) {
      long long tmp = pre[j] - pre[i - 1];
      if (tmp == 0) continue;
      if (a % tmp == 0) {
        res += _map[a / tmp];
      }
    }
  }
  cout << res << endl;
}
