Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
import java.util.*;
public class codeforces{
    public static void main(String[] args){
        int i,j,n,x=0,y=0,pos=-1,pos2=0,c;
        //long ans=0,a=0,b=0;
        //String s;
        Scanner sc=new Scanner(System.in);
        x=sc.nextInt();
        y=sc.nextInt();
        sc.nextLine();
        String s[]=new String[x];
        for(i=0;i<x;i++)
            s[i]=sc.nextLine();
        for(i=0;i<x;i++){
            for(j=0;j<y;j++){
                if(s[i].charAt(j)=='B'){
                    pos=i;
                    pos2=j;
                    break;
                }
            }
            if(pos!=-1)
                break;
        }
        c=0;
        for(i=0;i<y;i++){
            if(s[pos].charAt(i)=='B')
                ++c;
        }
        System.out.println((pos+c/2+1)+" "+(pos2+c/2+1));
    }
}