Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
import java.util.Scanner;

public class FindSquare_1028A {
	public static void main(String[] args) {
		Scanner input = new Scanner(System.in);
		int n = input.nextInt();
		int m = input.nextInt();
		int x = 0, y = 0, count = 0;
		boolean flagX = false, flagY = false;
		for (int i = 0; i < n; i++) {
			String str = input.next();
			if (str.contains("B") && flagY == false) {
				flagY = true;
				y = i;
			}
			for (int j = 0; j < m; j++) {
				if (str.charAt(j) == 'B') {
					if (flagX == false) {
						flagX = true;
						x = j;
					}
					count++;
				}
			}
		}
		System.out.println(String.valueOf(y + (int) Math.ceil(Math.sqrt(count) / 2)) + " "
				+ String.valueOf(x + (int) Math.ceil(Math.sqrt(count) / 2)));
		input.close();
	}
}