You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
int n;
int i, j, k;
int v[400000];
long long tot[400000];
long long m;
long long ans = 0;
int main() {
  scanf("%I64d\n", &m);
  for (; (v[++n] = (getchar() - 48)) || 1;)
    if (v[n] < 0 || v[n] > 9) break;
  --n;
  for (i = 2; i <= n; i++) v[i] += v[i - 1];
  for (i = 1; i <= n; i++)
    for (j = 0; j < i; j++) tot[v[i] - v[j]]++;
  if (!m) {
    for (i = 0; i <= v[n]; i++) ans += tot[0] * tot[i];
  }
  for (i = 1; i <= v[n]; i++)
    if ((m % i == 0) && (m / i <= v[n])) ans += tot[i] * tot[m / i];
  printf("%I64d", ans);
}
