You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int N = 5000;
const int M = 50000;
char str[N];
int cntS[M];
int main() {
  int a;
  scanf("%d", &a);
  scanf(" %s", str);
  int len = strlen(str);
  for (int i = 0; i < len; i++) {
    int curSum = 0;
    for (int s = i; s < len; s++) {
      curSum += str[s] - '0';
      cntS[curSum]++;
    }
  }
  long long ans = 0;
  if (a == 0) {
    long long allC = (long long)len * (long long)(len + 1) / (long long)2;
    long long allZ = cntS[0];
    ans = 2 * (allC - allZ) * allZ + allZ * allZ;
    printf("%lld", ans);
    return 0;
  }
  for (int i = 0; i < len; i++) {
    int curSum = 0;
    for (int s = i; s < len; s++) {
      curSum += str[s] - '0';
      if (curSum == 0) continue;
      int t = a / curSum;
      if (t * curSum == a && t < M) {
        ans += cntS[t];
      }
    }
  }
  printf("%lld", ans);
  return 0;
}
