Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
const int maxn = 150;
string s[maxn];
int flagr[maxn], flagl[maxn];
int main() {
  int n, m;
  cin >> n >> m;
  for (int i = 1; i <= n; i++) cin >> s[i];
  for (int i = 1; i <= n; i++) {
    for (int j = 0; j < m; j++) {
      if (s[i][j] == 'B') {
        flagl[i] = 1;
        break;
      }
    }
  }
  for (int j = 0; j < m; j++)
    for (int i = 1; i <= n; i++) {
      if (s[i][j] == 'B') {
        flagr[j] = 1;
        break;
      }
    }
  int s, t, ans1, ans2;
  for (int i = 1; i <= n; i++) {
    if (flagl[i] == 1 && flagl[i - 1] == 0) s = i;
    if (flagl[i] == 1 && flagl[i + 1] == 0) {
      t = i;
      break;
    }
  }
  ans1 = (s + t) / 2;
  for (int i = 0; i < m; i++) {
    if (flagr[i] == 1 && flagr[i - 1] == 0) s = i + 1;
    if (flagr[i] == 1 && flagr[i + 1] == 0) {
      t = i + 1;
      break;
    }
  }
  ans2 = (s + t) / 2;
  cout << ans1 << " " << ans2 << endl;
  return 0;
}
