Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
const int mod = 1e9 + 7;
const int inf = 0x3f3f3f3f;
const long long INF = 0x3f3f3f3f3f3f3f3f;
const int maxn = 2e6 + 50;
char ch[250][250];
int main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  int n, m;
  cin >> n >> m;
  for (int i = 1; i <= n; ++i) cin >> ch[i] + 1;
  int x1 = -1, y1 = -1, x2 = -1, y2 = -1;
  for (int i = 1; i <= n and x1 < 0; ++i) {
    for (int j = 1; j <= m and x1 < 0; ++j)
      if (ch[i][j] == 'B') {
        x1 = i, y1 = j;
      }
  }
  for (int i = n; i and x2 < 0; --i) {
    for (int j = m; j and x2 < 0; --j)
      if (ch[i][j] == 'B') {
        x2 = i, y2 = j;
      }
  }
  cout << (x1 + x2) / 2 << " " << (y1 + y2) / 2;
  return 0;
}
