Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, m, i, j, jl, jr, iu, id;
  string s;
  cin >> n >> m;
  int a[n + 2][m + 2];
  for (i = 0; i < n + 2; i++) {
    for (j = 0; j < m + 2; j++) {
      a[i][j] = 1;
    }
  }
  for (i = 1; i <= n; i++) {
    cin >> s;
    for (j = 1; j <= m; j++) {
      if (s[j - 1] == 'B') a[i][j] = 0;
    }
  }
  for (i = 1; i <= n; i++) {
    for (j = 1; j <= m; j++) {
      if (a[i][j] == 0) {
        iu = i;
        id = i;
        jl = j;
        jr = j;
        while (a[iu][j] == 0 && a[iu][j] == a[id][j] && a[i][jl] == a[i][jr] &&
               a[i][jl] == 0) {
          iu++;
          id--;
          jl--;
          jr++;
        }
        if (a[iu][j] == 1 and a[id][j] == 1 and a[i][jr] == 1 and
            a[i][jl] == 1) {
          cout << i << " " << j;
        }
      }
    }
  }
  return 0;
}
