Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
int main() {
  int N, M;
  cin >> N;
  cin >> M;
  char mas[N][M];
  for (int i = 0; i < N; i++) {
    for (int j = 0; j < M; j++) {
      cin >> mas[i][j];
    }
  }
  int posx1, posy1;
  for (int i = 0; i < N; i++) {
    int ok = 0;
    for (int j = 0; j < M; j++) {
      if (mas[i][j] == 'B') {
        posx1 = i;
        posy1 = j;
        ok = 1;
        break;
      }
    }
    if (ok == 1) {
      break;
    }
  }
  int posx2, posy2;
  posx2 = posx1;
  posy2 = posy1;
  while (mas[posx2][posy2] == 'B') {
    posx2++;
    posy2++;
  }
  posx1++;
  posy1++;
  posx1 = posx1 + (posx2 - posx1) / 2;
  posy1 = posy1 + (posy2 - posy1) / 2;
  cout << posx1 << " " << posy1;
  return 0;
}
