Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
import java.util.ArrayList;
        import java.util.Arrays;
        import java.util.Scanner;

public class Singleton_Pattern {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int m = sc.nextInt();
        sc.nextLine();
        int x = 0;
        int y =-1;
        int count = 0;
        int startindex=-1;
        for (int i = 0; i <n ; i++) {
            String s = sc.nextLine();
            if (x==1)
                continue;
            if (s.contains("B")){
                x=1;
                if (startindex==-1)
                startindex=i;

                for (int j = 0; j <s.length() ; j++) {
                    if (s.charAt(j)=='B'){
                       // System.out.println("inside");
                        if (y==-1){
                            y = j;
                        }
                        count++;
                    }
                }
            }
        }
//        System.out.println(count);
//        System.out.println(startindex);
//        System.out.println(y);
        System.out.println(startindex+1+(count/2) +" "+ (y + 1+(count/2)));

    }
}
