You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int dp[4009];
char s[4009];
int main() {
  long long a;
  cin >> a;
  scanf("%s", s);
  int n = strlen(s);
  for (int i = 0; i < n; i++) {
    dp[i + 1] = dp[i] + (s[i] - '0');
  }
  map<long long, long long> mpp;
  for (int i = 1; i <= n; i++) {
    for (int j = i; j <= n; j++) {
      int sum = dp[j] - dp[i - 1];
      mpp[sum]++;
    }
  }
  long long ans = 0;
  if (a == 0) {
    for (map<long long, long long>::iterator it = mpp.begin(); it != mpp.end();
         ++it) {
      if (it->first != 0) ans += 1ll * 2 * mpp[0] * it->second;
    }
    ans += mpp[0] * mpp[0];
  } else {
    for (int i = 1; i * i <= a; i++) {
      if (a % i == 0) {
        long long val;
        if (i * i == a) {
          val = 1ll * mpp[i] * mpp[i];
        } else {
          val = 1ll * mpp[i] * mpp[a / i] * 2;
        }
        ans += val;
      }
    }
  }
  cout << ans << endl;
  return 0;
}
