You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
using ll = int64_t;
using vll = vector<ll>;
using vvll = vector<vll>;
using pll = pair<ll, ll>;
using vpll = vector<pll>;
ll a, n;
vll inp;
void func() {
  cin >> a;
  string s;
  cin >> s;
  n = s.length();
  inp.resize(n);
  for (ll i = 0; i < n; i++) {
    inp[i] = s[i] - '0';
  }
  vll cnt(9 * n + 1, 0);
  for (ll i = 0; i < n; i++) {
    ll x = 0;
    for (ll j = i; j < n; j++) {
      x += inp[j];
      cnt[x]++;
    }
  }
  ll ans = 0;
  if (a == 0) {
    ll total = accumulate(cnt.begin(), cnt.end(), 0ll);
    ans = 2 * (cnt[0] * total);
    ans -= cnt[0] * cnt[0];
  } else {
    for (ll i = 1; i < 9 * n + 1; i++) {
      if (i > a) break;
      if (a % i == 0) {
        ll j = a / i;
        if (j < 9 * n + 1) {
          ans += cnt[i] * cnt[j];
        }
      }
    }
  }
  cout << ans << endl;
}
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(nullptr);
  cout.tie(nullptr);
  ;
  ll t = 1;
  for (ll i = 1; i <= t; i++) {
    func();
  }
}
