Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
    import java.util.*;
    import java.lang.*;
    public class Solution{
        
    public static void main(String[] args){
        Scanner s=new Scanner(System.in);
        int n=s.nextInt();
        int m=s.nextInt();
        int count=0,sum=0,sum1=0;
        s.nextLine();
        String a[]=new String[n];
        for(int i=0;i<n;i++)
            a[i]=s.nextLine();
        for(int i=0;i<n;i++){
            for(int j=0;j<m;j++){
                if(a[i].charAt(j)=='B')
                    count++;
            }
        }
        for(int k=0;k<n;k++){
            for(int k1=0;k1<m;k1++){
                if(a[k].charAt(k1)=='B'){
                    sum=sum+(k+1);
                    sum1=sum1+(k1+1);
                }
            }
        }
        System.out.println(sum/count+" "+sum1/count);
        
        
    }
  
    
}
    