You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
long long ans[4003][4003];
long long ct[4003 * 100];
using namespace std;
int main() {
  long long a, c = 0;
  cin >> a;
  string s;
  cin >> s;
  long long l = s.length();
  for (long long i = 0; i < (4003 * 100); i++) ct[i] = 0;
  for (long long i = 0; i < l; i++) {
    ans[i][1] = s[i] - '0';
    ct[ans[i][1]]++;
    c++;
  }
  for (long long i = 2; i <= l; i++) {
    for (long long j = 0; j <= (l - i); j++) {
      ans[j][i] = ans[j][i - 1] + ans[j + i - 1][1];
      ct[ans[j][i]]++;
      c++;
    }
  }
  long long result = 0;
  if (a == 0) result += (ct[0] * c);
  for (long long i = 1; i < (4003 * 100); i++) {
    if (a % i == 0)
      if ((a / i) <= 4003 * 100) result += ct[(a / i)] * ct[i];
  }
  cout << result << endl;
}
