You are given a string s consisting of n lowercase Latin letters. Polycarp wants to remove exactly k characters (k ≤ n) from the string s. Polycarp uses the following algorithm k times:

  * if there is at least one letter 'a', remove the leftmost occurrence and stop the algorithm, otherwise go to next item; 
  * if there is at least one letter 'b', remove the leftmost occurrence and stop the algorithm, otherwise go to next item; 
  * ... 
  * remove the leftmost occurrence of the letter 'z' and stop the algorithm. 



This algorithm removes a single letter from the string. Polycarp performs this algorithm exactly k times, thus removing exactly k characters.

Help Polycarp find the resulting string.

Input

The first line of input contains two integers n and k (1 ≤ k ≤ n ≤ 4 ⋅ 10^5) — the length of the string and the number of letters Polycarp will remove.

The second line contains the string s consisting of n lowercase Latin letters.

Output

Print the string that will be obtained from s after Polycarp removes exactly k letters using the above algorithm k times.

If the resulting string is empty, print nothing. It is allowed to print nothing or an empty line (line break).

Examples

Input

15 3
cccaabababaccbc


Output

cccbbabaccbc


Input

15 9
cccaabababaccbc


Output

cccccc


Input

1 1
u


Output
# -*- coding: utf-8 -*-
"""
Created on Thu Jun 21 20:42:12 2018

@author: Lenovo Ideapad
"""

n,k=map(int,input().split())
s=list(input())
#a=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
s_p=[['a',0] for i in range(n)]
for i in range(n):
    s_p[i]=[s[i],i]
#print(s_p)
s_p.sort()
#print(s_p)
s_p=s_p[k:]
#print(s_p)
s_p.sort(key=lambda x: x[1])
#print(s_p)

for i in s_p:
    print(i[0],end="")
print()
#counter=[0 for i in range(26)]
#for i in s:
#    counter[ord(i)-97]+=1
##print(counter)
#while(k>0):
#    for i in range(0,26):
#        c=counter[i]
#        while(c>0 and k>0):
#            s.remove(chr(i+97))
#            c-=1
#            k-=1
#        if k<=0:
#            break
#print(*s,sep="")