Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = long double;
using uint = unsigned int;
using ull = unsigned long long;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using vi = vector<int>;
using vl = vector<long long>;
void solve() {
  int N, M;
  cin >> N >> M;
  vector<string> bd(N);
  for (int i = 0; (i) < (N); (i)++) cin >> bd[i];
  int index = 0;
  int start = -1, end = -1;
  while (true) {
    if (bd[index / M][index % M] == 'B') {
      start = index;
      break;
    }
    index++;
  }
  while (index < M * N) {
    if (bd[index / M][index % M] == 'B') {
      end = index;
    }
    index++;
  }
  cout << (start / M + end / M) / 2 + 1 << " " << (start % M + end % M) / 2 + 1
       << endl;
}
int main() {
  cin.tie(nullptr);
  cout.tie(nullptr);
  ios_base::sync_with_stdio(false);
  solve();
  return 0;
}
