Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.

Let next(x) be the minimum lucky number which is larger than or equals x. Petya is interested what is the value of the expression next(l) + next(l + 1) + ... + next(r - 1) + next(r). Help him solve this problem.

Input

The single line contains two integers l and r (1 ≤ l ≤ r ≤ 109) — the left and right interval limits.

Output

In the single line print the only number — the sum next(l) + next(l + 1) + ... + next(r - 1) + next(r).

Please do not use the %lld specificator to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specificator.

Examples

Input

2 7


Output

33


Input

7 7


Output

7

Note

In the first sample: next(2) + next(3) + next(4) + next(5) + next(6) + next(7) = 4 + 4 + 4 + 7 + 7 + 7 = 33

In the second sample: next(7) = 7
import java.util.*;
import java.util.Map.Entry;
import java.io.*;
import java.awt.Point;
import java.math.BigInteger;

import static java.lang.Math.*;

public class CodeforcesC implements Runnable {

    final boolean ONLINE_JUDGE = System.getProperty("ONLINE_JUDGE") != null;

    BufferedReader in;
    PrintWriter out;
    StringTokenizer tok = new StringTokenizer("");

    void init() throws FileNotFoundException {
        if (ONLINE_JUDGE) {
            in = new BufferedReader(new InputStreamReader(System.in));
            out = new PrintWriter(System.out);
        } else {
            in = new BufferedReader(new FileReader("input.txt"));
            out = new PrintWriter("output.txt");
        }
    }

    String readString() throws IOException {
        while (!tok.hasMoreTokens()) {
            try {
                tok = new StringTokenizer(in.readLine());
            } catch (Exception e) {
                return null;
            }
        }
        return tok.nextToken();
    }

    int readInt() throws IOException {
        return Integer.parseInt(readString());
    }

    long readLong() throws IOException {
        return Long.parseLong(readString());
    }

    double readDouble() throws IOException {
        return Double.parseDouble(readString());
    }

    public static void main(String[] args) {
        new Thread(null, new CodeforcesC(), "", 128 * (1L << 20)).start();
    }

    long timeBegin, timeEnd;

    void time() {
        timeEnd = System.currentTimeMillis();
        System.err.println("Time = " + (timeEnd - timeBegin));
    }

    long memoryTotal, memoryFree;

    void memory() {
        memoryFree = Runtime.getRuntime().freeMemory();
        System.err.println("Memory = " + ((memoryTotal - memoryFree) >> 10)
                + " KB");
    }

    void debug(Object... objects) {
        if (DEBUG) {
            for (Object o : objects) {
                System.err.println(o.toString());
            }
        }
    }

    int[] readIntArray(int n) throws IOException {
        int[] array = new int[n];
        for (int i = 0; i < n; i++)
            array[i] = readInt();
        return array;
    }

    public void run() {
        try {
            timeBegin = System.currentTimeMillis();
            memoryTotal = Runtime.getRuntime().freeMemory();
            init();
            solve();
            out.close();
            time();
            memory();
        } catch (Exception e) {
            e.printStackTrace(System.err);
            System.exit(-1);
        }
    }

    boolean DEBUG = false;

    void solve() throws IOException {

        int l = readInt();
        int r = readInt();

        int n = 9;
        int[] ten = new int[n + 1];

        ten[0] = 1;

        for (int i = 1; i <= n; i++)
            ten[i] = 10 * ten[i - 1];

        long answer = 0;

        List<Long> luckyNumbers = new ArrayList<Long>();
        
        for (int length = 1; length <= n; length++) {
            for (int cur = 0; cur < (1 << length); cur++) {
                int value = 0;
                for (int j = 0; j < length; j++) {
                    if (((1 << j) & cur) == (1 << j))
                        value += ten[j] * 7;
                    else
                        value += ten[j] * 4;
                }
                //out.println(value);
                luckyNumbers.add(1l * value);
            }
        }
        
        luckyNumbers.add(4444444444l);
        
        long lastNumber = l;
        
        for (long luckyNumber : luckyNumbers) {
            if (luckyNumber > r) {
                answer += 1l * (r - lastNumber + 1) * luckyNumber;
                break;
            }
            if (luckyNumber >= l) {
                answer += 1l * (luckyNumber - lastNumber + 1) * luckyNumber;
                lastNumber = luckyNumber + 1;
            }
        }
        
        out.println(answer);
    }
}