Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
import java.util.*;

public class Solution {

  private static Scanner sc = new Scanner(System.in);

  public static void main(String[] args) {
    int n = sc.nextInt(), m = sc.nextInt();
    int[] topLeft = new int[2], bottomRight = new int[2];
    char[][] a = new char[n][m];
    for (int i = 0; i < n; i++) {
      a[i] = sc.next().toCharArray();
    }
    for (int i = 0; i < n; i++) {
      for (int j = 0; j < m; j++) {
        if (a[i][j] == 'B') {
          topLeft = new int[]{i + 1, j + 1};
        }
      }
    }
    for (int i = n - 1; i >= 0; i--) {
      for (int j = m - 1; j >= 0; j--) {
        if (a[i][j] == 'B') {
          bottomRight = new int[]{i + 1, j + 1};
        }
      }
    }
    System.out.println((topLeft[0] + bottomRight[0]) / 2 + " " + (topLeft[1] + bottomRight[1]) / 2);
  }

}