You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 4005;
int b[MAXN];
map<int, int> r;
map<int, int>::iterator it;
char s[MAXN];
int main() {
  int n, a;
  scanf("%d", &a);
  scanf("%s", s);
  n = strlen(s);
  for (int i = 1; i <= n; i++) {
    b[i] = s[i - 1] - '0';
  }
  for (int i = 1; i <= n; i++) {
    int res = 0;
    for (int j = i; j <= n; j++) {
      res += b[j];
      r[res]++;
    }
  }
  long long ans = 0;
  for (it = r.begin(); it != r.end(); ++it) {
    int v = it->first;
    int x = it->second;
    if (a > 0 && v == 0) continue;
    if (v == 0) {
      ans += (long long)x * n * (n + 1) / 2;
      continue;
    }
    if (a % v != 0) continue;
    int v2 = a / v;
    ans += (long long)x * r[v2];
  }
  cout << ans << endl;
  return 0;
}
