You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int a, n;
char s[4002];
int sum[4002], b[4002];
map<int, int> mm;
int main() {
  scanf("%d", &a);
  scanf("%s", s);
  n = strlen(s);
  int i;
  for (i = 1; i <= n; ++i) {
    b[i] = int(s[i - 1]) - 48;
    sum[i] = sum[i - 1] + b[i];
  }
  int j;
  long long kq = 0;
  for (i = 1; i <= n; ++i) {
    for (j = i; j <= n; ++j) mm[sum[j] - sum[i - 1]]++;
  }
  if (a == 0) {
    kq = (long long)mm[0] * (n * (n + 1) / 2 - mm[0]) * 2 +
         (long long)mm[0] * mm[0];
    printf("%I64d", kq);
    return 0;
  }
  for (i = 1; i <= n; ++i) {
    for (j = 1; j <= n; ++j) {
      if (sum[j] - sum[i - 1] > 0 && a % (sum[j] - sum[i - 1]) == 0) {
        kq += (long long)(mm[a / (sum[j] - sum[i - 1])]);
      }
    }
  }
  printf("%I64d", kq);
}
