You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int INF = 2e9;
const long long BIG_INF = 1e18;
const long long MOD = 1e9 + 7;
const int maxn = 4e3 + 5, maxsum = 9 * maxn + 5;
int n, x, a[maxn], cnt[maxsum];
string s;
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  cin >> x >> s;
  n = (int)s.size();
  for (int i = 0; i < n; i++) a[i] = (s[i] - '0');
  for (int l = 0; l < n; l++) {
    int sum = 0;
    for (int r = l; r < n; r++) {
      sum += a[r];
      cnt[sum]++;
    }
  }
  long long ans = 0;
  for (int l = 0; l < n; l++) {
    int sum = 0;
    for (int r = l; r < n; r++) {
      sum += a[r];
      if (!sum) {
        if (!x) ans += (long long)n * (long long)(n + 1) / 2;
        continue;
      }
      int y = x / sum;
      if (x % sum == 0 && y < maxsum) ans += (long long)cnt[y];
    }
  }
  cout << ans << "\n";
  return 0;
}
