You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
inline int read() {
  int first = 0, f = 1;
  char ch = getchar();
  for (; ch < '0' || ch > '9';) {
    if (ch == '-') f = -1;
    ch = getchar();
  }
  for (; ch >= '0' && ch <= '9';) {
    first = first * 10 + ch - '0';
    ch = getchar();
  }
  return first * f;
}
long long a, ans;
string s;
map<long long, long long> m;
int main() {
  cin >> a >> s;
  for (int i = 0; i < s.size(); i++) {
    long long tmp = 0;
    for (int j = i; j < s.size(); j++) tmp += s[j] - '0', m[tmp]++;
  }
  if (!a) ans = m[0] * (s.size() * (s.size() + 1) - m[0]);
  for (long long i = 1; i * i <= a; i++)
    if (a % i == 0) ans += m[i] * m[a / i] * (i * i == a ? 1 : 2);
  cout << ans;
}
