Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
const long long maxn = 115 + 1;
long long n, m;
char table[maxn][maxn];
pair<long long, long long> get_first() {
  for (long long i = 1; i <= n; ++i) {
    for (long long j = 1; j <= m; ++j) {
      if (table[i][j] == 'B') return make_pair(i, j);
    }
  }
}
int main() {
  ios::sync_with_stdio(false);
  cin >> n >> m;
  for (long long i = 1; i <= n; ++i) {
    for (long long j = 1; j <= m; ++j) {
      cin >> table[i][j];
    }
  }
  auto f = get_first();
  long long sx = f.first, sy = f.second;
  long long ex = sx, ey = sy;
  while (table[ex][sy] == 'B') {
    ++ex;
    if (ex > n) break;
  }
  --ex;
  while (table[sx][ey] == 'B') {
    ++ey;
    if (ey > m) break;
  }
  --ey;
  cout << (sx + ex) / 2 << " " << (sy + ey) / 2 << endl;
  return 0;
}
