You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
char str[4050];
int a[4050];
int b[40010];
int main() {
  int m, n;
  while (scanf("%d%s", &m, str) != EOF) {
    n = strlen(str);
    for (int i = 0; i < n; i++) a[i] = str[i] - '0';
    memset(b, 0, sizeof(b));
    for (int i = 0; i < n; i++) {
      int s = 0;
      for (int j = i; j < n; j++) {
        s += a[j];
        b[s]++;
      }
    }
    long long ans = 0;
    for (int i = 0; i < n; i++) {
      int s = 0;
      for (int j = i; j < n; j++) {
        s += a[j];
        if (s > 0 && m % s == 0 && m / s <= n * 9) {
          ans += b[m / s];
        } else if (s == 0 && m == 0)
          ans += (n * (n + 1) / 2);
      }
    }
    printf("%I64d\n", ans);
  }
  return 0;
}
