You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int N = 5e3 + 20;
long long A, p[N];
char s[N];
map<long long, long long> mp;
int main() {
  while (cin >> A) {
    p[0] = 0, mp.clear();
    scanf("%s", s + 1);
    int n = strlen(s + 1);
    for (int i = 1; i <= n; i++) p[i] = p[i - 1] + (s[i] - '0');
    long long res = 0, zero = 0;
    for (int i = 0; i <= n; i++) {
      for (int j = i + 1; j <= n; j++) {
        mp[p[j] - p[i]]++;
        if (p[j] - p[i])
          res++;
        else
          zero++;
      }
    }
    long long ans = 0;
    if (A == 0) {
      ans += (zero * res) * 2ll + zero * zero;
      cout << ans << endl;
      continue;
    }
    for (int i = 0; i <= n; i++) {
      for (int j = i + 1; j <= n; j++) {
        long long x = p[j] - p[i];
        if (x == 0) continue;
        if (x && (A % x) == 0) ans += mp[A / x];
      }
    }
    cout << ans << endl;
  }
  return 0;
}
