Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.Scanner;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 *
 * @author Bisoye
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Scanner in = new Scanner(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        AFindSquare solver = new AFindSquare();
        solver.solve(1, in, out);
        out.close();
    }

    static class AFindSquare {
        public void solve(int testNumber, Scanner in, PrintWriter out) {
            int n = Integer.parseInt(in.next()), m = Integer.parseInt(in.next());
            char[][] T = new char[n][m];
            int tc = -1, tr = -1, bc = -1, br = -1;
            for (int i = 0; i < n; i++) {
                String str = in.next();
                for (int j = 0; j < m; j++) {
                    T[i][j] = str.charAt(j);
                    if (str.charAt(j) == 'B') {
                        br = i;
                        bc = j;
                        if (tc == -1) {
                            tr = i;
                            tc = j;
                        }
                    }
                }
            }

            out.println(String.format("%d %d", 1 + (tr + ((br - tr) / 2)), 1 + (tc + ((bc - tc) / 2))));
        }

    }
}

