You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
inline void boostIO() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
}
long long a, m, x, i, j, ans, sum[4004];
string s;
map<int, int> multiples;
int main() {
  boostIO();
  cin >> a >> s;
  s = "#" + s;
  for (i = 1; i < s.size(); ++i) sum[i] = sum[i - 1] + s[i] - '0';
  for (i = 0; i < s.size(); ++i)
    for (j = i + 1; j < s.size(); ++j) multiples[sum[j] - sum[i]]++, ++m;
  for (i = 0; i < s.size(); ++i)
    for (j = i + 1; j < s.size(); ++j) {
      x = (sum[j] - sum[i]);
      if (x == 0) {
        if (a == 0) ans += m;
      } else if (a % x == 0 && multiples.count(a / x) > 0) {
        ans += multiples[a / x];
      }
    }
  cout << ans << endl;
  return 0;
}
