Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
const int AX = 115 + 6;
char s[AX][AX];
int main() {
  int n, m;
  scanf("%d%d", &n, &m);
  for (int i = 0; i < n; i++) {
    scanf("%s", s[i]);
  }
  int sx, sy, ex = -1, ey = -1;
  for (int i = 0; i < n; i++) {
    sx = -1;
    for (int j = 0; j < m; j++) {
      if (s[i][j] == 'B') {
        for (int k = i; k < n; k++) {
          if (s[k][j] == 'B')
            ex = max(ex, k);
          else
            break;
        }
        for (int k = j; k < m; k++) {
          if (s[i][k] == 'B')
            ey = max(ey, k);
          else
            break;
        }
        sx = i;
        sy = j;
        break;
      }
      if (sx == i) break;
    }
    if (~sx) break;
  }
  printf("%d %d\n", (ex + sx) / 2 + 1, (ey + sy) / 2 + 1);
  return 0;
}
