You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int N = 4005;
int sum[N];
int sl[N * 9];
int main() {
  int a;
  string s;
  cin >> a;
  getchar();
  getline(cin, s);
  sum[0] = 0;
  int n = s.size();
  for (int i = 0; i < n; i++) {
    sum[i + 1] = sum[i] + s[i] - '0';
  }
  for (int i = 1; i <= n; i++) {
    for (int j = i; j <= n; j++) sl[sum[j] - sum[i - 1]]++;
  }
  long long res = 0;
  for (int i = 1; i <= n; i++)
    for (int j = i; j <= n; j++) {
      int tmp = sum[j] - sum[i - 1];
      if (a == 0) {
        if (tmp == 0)
          res += n * (n + 1) / 2;
        else
          res += sl[0];
      } else {
        if (tmp > 0 && (a % tmp == 0) && (a / tmp < N * 9)) res += sl[a / tmp];
      }
    }
  cout << res;
  return 0;
}
