You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
import java.io.*;
import java.util.*;
public class AA {
	static PrintWriter pw;
	public static void main(String[] args)throws Throwable {
		pw=new PrintWriter(System.out);
		MyScanner sc=new MyScanner();
		
		int n=sc.nextInt();
		char [] s=sc.next().toCharArray();
		int [] c=new int [s.length*10+5];
		for(int i=0;i<s.length;i++){
			int sum=0;
			for(int j=i;j<s.length;j++){
				sum+=(s[j]-'0');
				c[sum]++;
			}
		}
		long ans=0;
		for(int i=0;i<s.length;i++){
			int sum=0;
			for(int j=i;j<s.length;j++){
				sum+=(s[j]-'0');
				if(sum>0){				
					if(n%sum==0 && n/sum<s.length*10+5)
						ans+=c[n/sum];
				}else
					if(n==0)
						ans+=s.length*(s.length+1)/2;
			}
		}
		pw.println(ans);
		pw.flush();
		pw.close();
	}
	
	static class MyScanner {
		BufferedReader br;
		StringTokenizer st;
		public MyScanner() {
			br = new BufferedReader(new InputStreamReader(System.in));
		}
		String next() {while (st == null || !st.hasMoreElements()) {
			try {st = new StringTokenizer(br.readLine());}
			catch (IOException e) {e.printStackTrace();}}
		return st.nextToken();}
		int nextInt() {return Integer.parseInt(next());}
		long nextLong() {return Long.parseLong(next());}
		double nextDouble() {return Double.parseDouble(next());}
		String nextLine(){String str = "";
		try {str = br.readLine();}
		catch (IOException e) {e.printStackTrace();}
		return str;}
	}
}