You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios::sync_with_stdio(false);
  cin.tie(0);
  cout.tie(0);
  int a;
  cin >> a;
  ;
  string in;
  cin >> in;
  int len = in.length();
  map<int, int> hor;
  int tp;
  long long int maxx = (len * (len + 1)) / 2;
  for (int i = 0; i < len; i++) {
    tp = 0;
    for (int j = i; j < len; j++) {
      tp += (int)(in[j] - '0');
      hor[tp]++;
    }
  }
  long long int ans = 0;
  for (int i = 0; i < len; i++) {
    tp = 0;
    for (int j = i; j < len; j++) {
      tp += (int)(in[j] - '0');
      if (tp == 0) {
        if (a == 0) ans += maxx;
      } else if (a % tp == 0 && hor.find(a / tp) != hor.end()) {
        ans += hor[a / tp];
      }
    }
  }
  cout << ans << '\n';
}
