You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
std::map<int, long long> set;
int main() {
  int a;
  char s[4001];
  scanf("%d", &a);
  scanf("%s", s);
  set.clear();
  if (a == 0) set[0] = 0;
  for (int i = 1; i * i <= a; i++)
    if (a % i == 0) {
      set[i] = 0;
      if (i * i != a) set[a / i] = 0;
    }
  long long ans = 0;
  for (int i = 0; s[i]; i++) {
    int sum = 0;
    for (int j = i; s[j]; j++) {
      sum += s[j] - '0';
      if (set.find(sum) != set.end()) set[sum]++;
    }
  }
  for (int i = 1; i * i <= a; i++)
    if (a % i == 0) {
      long long v = (long long)set[i] * set[a / i];
      ans += v;
      if (i * i != a) ans += v;
    }
  int len = strlen(s);
  if (a == 0) {
    ans += set[0] * (1 + len) * len;
    ans -= set[0] * set[0];
  }
  printf("%I64d\n", ans);
}
