Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
const int MX = 1e3 + 10, MD = 1e9 + 7;
long long n, m, a[MX], ans, tmp;
string s[MX];
int main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cin >> n >> m;
  int flag1 = 0, flag2 = 0, len1 = 0, len2 = 0, st1 = 0, st2 = 0, flag3 = 0;
  for (int i = 0; i < n; i++) {
    cin >> s[i];
    for (int j = 0; j < s[i].size(); j++) {
      if (s[i][j] == 'B' && flag3 == 0) {
        if (flag1 == 0) {
          flag1 = 1;
          st1 = i + 1;
        }
        len1++;
      }
    }
    if (flag1 == 1) {
      flag3 = 1;
    }
  }
  for (int j = 0; j < m; j++) {
    for (int i = 0; i < n; i++) {
      if (s[i][j] == 'B') {
        if (flag2 == 0) {
          flag2 = 1;
          st2 = j + 1;
        }
        len2++;
      }
    }
    if (flag2 == 1) break;
  }
  cout << st1 + len1 / 2 << " " << st2 + len2 / 2 << endl;
}
