You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int a;
char str[100002];
int sum[100002];
int cnt[100002];
int main() {
  scanf("%d\n", &a);
  gets(str);
  int len = strlen(str);
  sum[0] = (str[0] - '0');
  for (int i = 1; i < len; i++) {
    sum[i] = sum[i - 1] + (str[i] - '0');
  }
  int id, x, y, mx = 0;
  for (int i = 0; i < len; i++) {
    for (int j = i; j < len; j++) {
      if (i > 0)
        id = sum[j] - sum[i - 1];
      else
        id = sum[j];
      cnt[id]++;
      mx = max(mx, id);
    }
  }
  long long ans = 0;
  for (int i = 0; i < len; i++) {
    for (int j = i; j < len; j++) {
      if (i > 0)
        x = sum[j] - sum[i - 1];
      else
        x = sum[j];
      if (a == 0) {
        ans += cnt[0];
      }
      if (x == 0) continue;
      if (a % x != 0) continue;
      y = a / x;
      if (y > mx) continue;
      ans = ans + (long long)(cnt[y]);
    }
  }
  cout << ans << endl;
  return 0;
}
