You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
const int MaxN = 4e3;
using namespace std;
map<int, int> cnt;
int n;
char s[MaxN + 5];
int a[MaxN + 5], f[MaxN + 5];
int main() {
  while (~scanf("%d", &n)) {
    scanf("%s", s + 1);
    int len = strlen(s + 1);
    f[0] = 0;
    cnt.clear();
    for (int i = 1; i <= len; i++) {
      a[i] = s[i] - '0';
      f[i] = f[i - 1] + a[i];
    }
    for (int i = 1; i <= len; i++) {
      for (int j = i; j <= len; j++) {
        int tmp = f[j] - f[i - 1];
        cnt[tmp]++;
      }
    }
    long long ans = 0;
    for (int i = 1; i <= len; i++) {
      for (int j = i; j <= len; j++) {
        int t = f[j] - f[i - 1];
        if (t == 0 && n == 0) {
          ans = ans + 1LL * (len + 1) * len / 2;
        } else if (t != 0 && n % t == 0) {
          if (cnt[n / t]) ans = ans + cnt[n / t];
        }
      }
    }
    printf("%I64d\n", ans);
  }
}
