You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int h[36020];
int main() {
  char sir[4005];
  int a, n, i, j, suma, v[4005];
  cin >> a;
  cin.get();
  cin.get(sir + 1, 4005);
  n = strlen(sir + 1);
  v[0] = 0;
  for (i = 1; i <= n; i++) v[i] = v[i - 1] + (sir[i] - '0');
  for (i = 1; i <= n; i++)
    for (j = i; j <= n; j++) {
      suma = v[j] - v[i - 1];
      h[suma]++;
    }
  long long int rasp = 0;
  for (i = 1; i <= n; i++)
    for (j = i; j <= n; j++) {
      suma = v[j] - v[i - 1];
      if (a == 0) {
        if (suma == 0)
          rasp += ((n * (n + 1)) / 2);
        else
          rasp += h[0];
      } else if (suma != 0)
        if (a % suma == 0) rasp += (((a / suma) < 36020) ? h[a / suma] : 0);
    }
  cout << rasp << '\n';
  return 0;
}
