Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, m;
  cin >> n >> m;
  char a[n][m];
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < m; j++) {
      cin >> a[i][j];
    }
  }
  int count1 = 0, c = 0, count2 = 0, count4 = 0, k, row, column;
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < m; j++) {
      if (a[i][j] == 'B') {
        count2++;
        row = i;
        column = j;
        k = j, c = i;
        while ((a[i][k] == 'B' && (k < m))) {
          k++;
        }
        k--;
        while ((a[c][j] == 'B') && (c < n)) c++;
        c--;
        break;
      }
      if ((i == n - 1) && (j == m - 1) && (count2 == 0)) cout << "0 0 ";
    }
    if (count2 != 0) break;
  }
  if (count2 != 0) {
    cout << (((c + row) / 2) + 1) << " " << (((k + column) / 2) + 1);
  }
}
