You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
import java.io.*;
import java.util.*;
public final class rectangles_sum
{
    static BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
	static FastScanner sc=new FastScanner(br);
    static PrintWriter out=new PrintWriter(System.out);
	static int maxn=(int)(1e6);
	
	public static void main(String args[]) throws Exception
	{
		int x=sc.nextInt();char[] arr=sc.next().toCharArray();int n=arr.length;int[] a=new int[n];long[] cnt=new long[maxn];
		for(int i=0;i<n;i++)
		{
			a[i]=arr[i]-'0';
		}
		//out.println(Arrays.toString(a));
		for(int i=0;i<n;i++)
		{
			int sum=0;
			for(int j=i;j<n;j++)
			{
				sum=sum+a[j];cnt[sum]++;
			}
		}
		long res=0,all=(n*(n+1))>>1L;
		for(int i=0;i<n;i++)
		{
			int sum=0;
			for(int j=i;j<n;j++)
			{
				sum=sum+a[j];
				if(sum==0 && x==0)
				{
					res=res+all;
				}
				else if(sum!=0 && (x%sum)==0 && (x/sum)<maxn)
				{
					res=(res+cnt[x/sum]);
				}
			}
		}
		out.println(res);out.close();
	}
}
class FastScanner
{
    BufferedReader in;
    StringTokenizer st;

    public FastScanner(BufferedReader in) {
        this.in = in;
    }
	
    public String nextToken() throws Exception {
        while (st == null || !st.hasMoreTokens()) {
            st = new StringTokenizer(in.readLine());
        }
        return st.nextToken();
    }
	
	public String next() throws Exception {
		return nextToken().toString();
	}
	
    public int nextInt() throws Exception {
        return Integer.parseInt(nextToken());
    }

    public long nextLong() throws Exception {
        return Long.parseLong(nextToken());
    }

    public double nextDouble() throws Exception {
        return Double.parseDouble(nextToken());
    }
}