Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
import java.util.*;
import java.math.*;
import java.io.*;
public class Solution
{
	public static void main(String[] args) throws IOException,FileNotFoundException {
		Scanner sc=new Scanner(System.in);
		int n=sc.nextInt();
		int m=sc.nextInt();
		char[][] s=new char[n][m];
		int l1=0,r1=0,l2=0,r2=0;
		boolean ok=true;
		for (int i=0;i<n ;i++ ) {
			s[i]=sc.next().toCharArray();
			if(!ok)
				continue;
			for (int j=0;j<m ;j++ ) {
				if(s[i][j]=='B'){
                     l1=i+1;r1=j+1;
                     break;
				}
			}
		}
		for (int i=n-1;i>=0 ;i-- ) {
			for (int j=m-1;j>=0 ;j-- ) {
				if (s[i][j]=='B') {
					l2=i+1;r2=j+1;
					break;
				}
			}
		}
		//System.out.println(l1+" "+r1+" "+l2+" "+r2);
		if(l2==0 && r2==0){
			System.out.println(l1+" "+r1);
		}
		else if (l1==0 && r1==0) {
			System.out.println(l2+" "+r2);
		}
		else {
			System.out.println((l1+l2)/2+" "+(r1+r2)/2);
		}
        
	}
}