In some other world, today is Christmas.

Mr. Takaha decides to make a multi-dimensional burger in his party. A level-L burger (L is an integer greater than or equal to 0) is the following thing:

* A level-0 burger is a patty.
* A level-L burger (L \geq 1) is a bun, a level-(L-1) burger, a patty, another level-(L-1) burger and another bun, stacked vertically in this order from the bottom.



For example, a level-1 burger and a level-2 burger look like `BPPPB` and `BBPPPBPBPPPBB` (rotated 90 degrees), where `B` and `P` stands for a bun and a patty.

The burger Mr. Takaha will make is a level-N burger. Lunlun the Dachshund will eat X layers from the bottom of this burger (a layer is a patty or a bun). How many patties will she eat?

Constraints

* 1 \leq N \leq 50
* 1 \leq X \leq ( the total number of layers in a level-N burger )
* N and X are integers.

Input

Input is given from Standard Input in the following format:


N X


Output

Print the number of patties in the bottom-most X layers from the bottom of a level-N burger.

Examples

Input

2 7


Output

4


Input

1 1


Output

0


Input

50 4321098765432109


Output

2160549382716056
import java.util.Scanner;

public class Main{
  public static void main(String[] args){
    Scanner sc = new Scanner(System.in);
    int N = sc.nextInt();
    long X = sc.nextLong();

    long[] layer = new long[N + 1];
    long[] paty = new long[N + 1];
    layer[0] = 1;
    paty[0] = 1;
    for(int i = 1; i <= N; i++){
      layer[i] = 2 * layer[i - 1] + 3;
      paty[i] = 2 * paty[i - 1] + 1;
    }

    long ans = 0;
    int i = N;
    while(i >= 1){
      if(X == 2 * layer[i - 1] + 3){
        ans += 2 * paty[i - 1] + 1;
        break;
      }else if(X > layer[i - 1] + 2){
        ans += paty[i - 1] + 1;
        X -= layer[i - 1] + 2;
        i--;
      }else if(X == layer[i - 1] + 2){
        ans += paty[i - 1] + 1;
        break;
      }else if(X == layer[i - 1] + 1){
        ans += paty[i - 1];
        break;
      }else{
        X--;
        i--;
      }
    }

    if(i == 0 && X == 1){ans++;}

    System.out.println(ans);
    sc.close();
  }
}
