You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int n, curr;
map<int, long long> cnt;
long long ans;
string s;
int main() {
  cin >> n >> s;
  for (size_t i = 0; i < s.size(); ++i) {
    curr = 0;
    for (size_t j = i; j < s.size(); ++j) {
      curr += (s[j] - '0');
      cnt[curr]++;
    }
  }
  ans = 0;
  if (!n) {
    if (cnt.find(0) == cnt.end()) {
      cout << "0\n";
    } else {
      for (map<int, long long>::iterator it = cnt.begin(); it != cnt.end();
           ++it) {
        ans += (cnt[0] * (*it).second);
        if ((*it).first) {
          ans += (cnt[0] * (*it).second);
        }
      }
      cout << ans << "\n";
    }
    return 0;
  }
  for (int i = 1; i * i <= n; ++i) {
    if (n % i == 0) {
      ans += (cnt[i] * cnt[n / i]);
      if (i * i != n) {
        ans += (cnt[i] * cnt[n / i]);
      }
    }
  }
  cout << ans << "\n";
  return 0;
}
