You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
vector<long long int> vec;
long long int sum[4010];
long long int cntnum[40010];
int main() {
  long long int a, i, j, k;
  memset(cntnum, 0, sizeof(cntnum));
  scanf("%lld", &a);
  ;
  string str;
  cin >> str;
  int len = str.size();
  for (i = 0; i < len; i++) vec.push_back(str[i] - '0');
  sum[0] = 0;
  for (i = 1; i <= len; i++) sum[i] = sum[i - 1] + vec[i - 1];
  for (i = 1; i <= len; i++) {
    for (j = i; j <= len; j++) {
      long long int temp = sum[j] - sum[i - 1];
      cntnum[temp]++;
    }
  }
  long long int ans = 0;
  for (i = 0; i <= 36000; i++) {
    long long int temp = i;
    if (temp == 0) {
      if (a != 0) {
      } else {
        long long int temp1 = cntnum[i];
        ans = ans + temp1 * ((len * (len + 1))) - (temp1 * temp1);
      }
    } else if (a % temp == 0 and a != 0 and a / temp <= 36000) {
      ans = ans + (cntnum[i]) * (cntnum[a / temp]);
    }
  }
  cout << ans << endl;
  return 0;
}
