Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
int main() {
  int n, m;
  cin >> n >> m;
  int A[n][m];
  char a;
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < m; j++) {
      cin >> a;
      if (a == 'W')
        A[i][j] = 0;
      else
        A[i][j] = 1;
    }
  }
  int aa, bb;
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < m; j++) {
      if (A[i][j] == 1) {
        if ((i > 0 && A[i - 1][j] == 1) || (j > 0 && A[i][j - 1] == 1)) {
        } else {
          int b = 0, c = 0, d = i, e = j;
          while (d < n && A[d][j] == 1) {
            d++;
            b++;
          }
          while (e < m && A[i][e] == 1) {
            c++;
            e++;
          }
          if (b % 2 != 0 && c % 2 != 0) {
            aa = i + b / 2;
            bb = j + c / 2;
          }
        }
      }
    }
  }
  cout << aa + 1 << " " << bb + 1;
}
