There is a right triangle with legs of length a and b. Your task is to determine whether it is possible to locate the triangle on the plane in such a way that none of its sides is parallel to the coordinate axes. All the vertices must have integer coordinates. If there exists such a location, you have to output the appropriate coordinates of vertices.

Input

The first line contains two integers a, b (1 ≤ a, b ≤ 1000), separated by a single space.

Output

In the first line print either "YES" or "NO" (without the quotes) depending on whether the required location exists. If it does, print in the next three lines three pairs of integers — the coordinates of the triangle vertices, one pair per line. The coordinates must be integers, not exceeding 109 in their absolute value.

Examples

Input

1 1


Output

NO


Input

5 5


Output

YES
2 1
5 5
-2 4


Input

5 10


Output

YES
-10 4
-2 -2
1 2
import java.io.*;
import java.util.*;

import static java.lang.Math.*;

public class Main extends PrintWriter {
    BufferedReader in;
    StringTokenizer stok;
    final Random rand = new Random(31);
    final int inf = (int) 1e9;
    final long linf = (long) 1e18;

    final static String IO = "_std";

    void solve() throws IOException {
        int a = nextInt();
        int b = nextInt();
        for (int i = 1; i < a; i++) {
            int j = (int) floor(sqrt(a * a - i * i));
            if (i * i + j * j != a * a) {
                continue;
            }
            int x = j;
            int y = -i;
            double d = sqrt(x * x + y * y);
            x = (int) floor(x * b / d);
            y = (int) floor(y * b / d);
            if (x * x + y * y != b * b) {
                continue;
            }
            if (y + j == 0) {
                continue;
            }
            println("YES");
            println("0 0");
            println(i + " " + j);
            println((x + i) + " " + (y + j));
            return;
        }
        println("NO");
    }

    Main() {
        super(System.out);
        in = new BufferedReader(new InputStreamReader(System.in));
    }

    Main(String fileIn, String fileOut) throws IOException {
        super(fileOut);
        in = new BufferedReader(new FileReader(fileIn));
    }

    public static void main(String[] args) throws IOException {
        Main main;
        if ("_std".equals(IO)) {
            main = new Main();
        } else if ("_iotxt".equals(IO)) {
            main = new Main("input.txt", "output.txt");
        } else {
            main = new Main(IO + ".in", IO + ".out");
        }
        main.solve();
        main.close();
    }

    String next() throws IOException {
        while (stok == null || !stok.hasMoreTokens()) {
            String s = in.readLine();
            if (s == null) {
                return null;
            }
            stok = new StringTokenizer(s);
        }
        return stok.nextToken();
    }

    int nextInt() throws IOException {
        return Integer.parseInt(next());
    }

    long nextLong() throws IOException {
        return Long.parseLong(next());
    }

    double nextDouble() throws IOException {
        return Double.parseDouble(next());
    }

    int[] nextIntArray(int len) throws IOException {
        int[] a = new int[len];
        for (int i = 0; i < len; i++) {
            a[i] = nextInt();
        }
        return a;
    }

    int[] nextIntArraySorted(int len) throws IOException {
        int[] a = nextIntArray(len);
        shuffle(a);
        Arrays.sort(a);
        return a;
    }

    void shuffle(int[] a) {
        for (int i = 1; i < a.length; i++) {
            int x = rand.nextInt(i + 1);
            int _ = a[i];
            a[i] = a[x];
            a[x] = _;
        }
    }

    void shuffleAndSort(int[] a) {
        shuffle(a);
        Arrays.sort(a);
    }

    boolean nextPermutation(int[] p) {
        for (int a = p.length - 2; a >= 0; --a) {
            if (p[a] < p[a + 1])
                for (int b = p.length - 1; ; --b)
                    if (p[b] > p[a]) {
                        int t = p[a];
                        p[a] = p[b];
                        p[b] = t;
                        for (++a, b = p.length - 1; a < b; ++a, --b) {
                            t = p[a];
                            p[a] = p[b];
                            p[b] = t;
                        }
                        return true;
                    }
        }
        return false;
    }

    <T> List<T>[] createAdjacencyList(int n) {
        List<T>[] res = new List[n];
        for (int i = 0; i < n; i++) {
            res[i] = new ArrayList<>();
        }
        return res;
    }
}