Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
const long long INF = 1e9 + 5;
const long long N = 205;
void solve();
int32_t main() {
  ios::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  ;
  cout << fixed << setprecision(10);
  long long _ = 1;
  while (_--) solve();
  return 0;
}
void solve() {
  long long n, m;
  cin >> n >> m;
  char a[n][m];
  for (long long i = 0; i < n; i++) {
    string s;
    cin >> s;
    for (long long j = 0; j < m; j++) {
      a[i][j] = s[j];
    }
  }
  long long black = 0;
  for (long long i = 0; i < n; i++) {
    for (long long j = 0; j < m; j++) {
      if (a[i][j] == 'B') black++;
    }
  }
  black = (black + 1) / 2;
  long long pos = 0;
  long long x = 0, y = 0;
  for (long long i = 0; i < n; i++) {
    for (long long j = 0; j < m; j++) {
      if (a[i][j] == 'B') {
        pos++;
        if (pos == black) {
          x = i + 1;
          y = j + 1;
          break;
        }
      }
    }
  }
  cout << x << " " << y << "\n";
}
