Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(false);
  int numR, numC;
  cin >> numR >> numC;
  vector<int> posR;
  vector<int> posC;
  int startR, startC, endR, endC;
  for (int row = 0; row < numR; row++) {
    string str;
    cin >> str;
    for (int col = 0; col < numC; col++) {
      if (str[col] == 'B') {
        posR.push_back(row);
        posC.push_back(col);
      }
    }
  }
  if (posR.size() < 1) {
    cout << 0 << " " << 0 << endl;
    return 0;
  }
  startR = posR.front();
  startC = posC.front();
  endR = posR.back();
  endC = posC.back();
  int ansR, ansC;
  ansR = startR + (endR - startR) / 2 + 1;
  ansC = startC + (endC - startC) / 2 + 1;
  cout << ansR << " " << ansC << endl;
  return 0;
}
