You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
char s[4003];
int sa[4003];
map<int, int> Count;
int main() {
  int a, len;
  scanf("%d", &a);
  scanf("%s", s);
  int n = strlen(s);
  for (int i = (0); i < (n); i++) sa[i + 1] = sa[i] + s[i] - '0';
  for (int i = (1); i < (n + 1); i++)
    for (int j = (0); j < (i); j++)
      if (a == 0 || sa[i] - sa[j] > 0) Count[sa[i] - sa[j]]++;
  long long answer = 0LL;
  if (a == 0) {
    answer = Count[0];
    answer = answer * n * (n + 1);
    answer -= (long long)Count[0] * (long long)Count[0];
  } else {
    for (typeof((Count).begin()) it = (Count).begin(); it != (Count).end();
         it++)
      if (a % (it->first) == 0) {
        if (Count.count(a / (it->first)) != 0)
          ;
        answer += (long long)(it->second) * (long long)Count[a / it->first];
      }
  }
  printf("%lld\n", answer);
  return 0;
}
