Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  int n, m, cnt = 0;
  cin >> n >> m;
  char a[n][m], prev;
  int s, e, a1, a2, i, j, f = 0;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      cin >> a[i][j];
    }
  }
  for (i = 0; i < n; i++) {
    prev = a[i][0];
    if (prev == 'B') {
      f = 1;
      s = 0;
    }
    for (j = 1; j < m; j++) {
      if (prev == 'W' && a[i][j] == 'B') {
        s = j;
        f = 1;
      } else if (prev == 'B' && a[i][j] == 'W') {
        e = j - 1;
      }
      prev = a[i][j];
    }
    if (a[i][j - 1] == 'B') {
      e = j - 1;
    }
    if (f == 1) {
      if (e == s)
        a1 = i + 1;
      else
        a1 = ((i + 1 + e - s) + (i + 1)) / 2;
      a2 = ((s + e) / 2) + 1;
      break;
    }
  }
  cout << a1 << "\t" << a2;
  return 0;
}
