You are given an array a consisting of n positive integers. Find a non-empty subset of its elements such that their sum is even (i.e. divisible by 2) or determine that there is no such subset.

Both the given array and required subset may contain equal values.

Input

The first line contains a single integer t (1 ≤ t ≤ 100), number of test cases to solve. Descriptions of t test cases follow.

A description of each test case consists of two lines. The first line contains a single integer n (1 ≤ n ≤ 100), length of array a.

The second line contains n integers a_1, a_2, …, a_n (1 ≤ a_i ≤ 100), elements of a. The given array a can contain equal values (duplicates).

Output

For each test case output -1 if there is no such subset of elements. Otherwise output positive integer k, number of elements in the required subset. Then output k distinct integers (1 ≤ p_i ≤ n), indexes of the chosen elements. If there are multiple solutions output any of them.

Example

Input


3
3
1 4 3
1
15
2
3 5


Output


1
2
-1
2
1 2

Note

There are three test cases in the example.

In the first test case, you can choose the subset consisting of only the second element. Its sum is 4 and it is even.

In the second test case, there is only one non-empty subset of elements consisting of the first element, however sum in it is odd, so there is no solution.

In the third test case, the subset consisting of all array's elements has even sum.
from math import *
from copy import *
from string import *				# alpha = ascii_lowercase
from random import *
from sys import stdin
from sys import maxsize
from operator import *				# d = sorted(d.items(), key=itemgetter(1))
from itertools import *
from collections import Counter		# d = dict(Counter(l))
import math

def bin1(l,r,k,t,b,val,ans):
	if(l>r):
		return ans
	else:
		mid=(l+r)//2
		v=k**mid
		if(v==val):
			return v
		elif(v>val):
			ans=mid
			return bin1(mid+1,r,k,t,b,val,ans)
		else:
			return bin1(l,mid-1,k,t,b,val,ans)
		
def bin2(l,r,k,t,b,val,ans):
	if(l>r):
		return ans
	else:
		mid=(l+r)//2
		v=t*(k**mid)+b*(mid)
		if(v==val):
			return v
		elif(v>val):
			ans=mid
			return bin2(l,mid-1,k,t,b,val,ans)
		else:
			return bin2(mid+1,r,k,t,b,val,ans)

def SieveOfEratosthenes(n): 
      
    # Create a boolean array "prime[0..n]" and initialize 
    #  all entries it as true. A value in prime[i] will 
    # finally be false if i is Not a prime, else true. 
    prime = [True for i in range(n+1)] 
    p = 2
    while (p * p <= n): 
          
        # If prime[p] is not changed, then it is a prime 
        if (prime[p] == True): 
              
            # Update all multiples of p 
            for i in range(p * p, n+1, p): 
                prime[i] = False
        p += 1
    l=[]
    for i in range(2,n+1):
    	if(prime[i]):
    		l.append(i)
    return l
def bin(l,r,ll,val):
	if(l>r):
		return -1
	else:
		mid=(l+r)//2
		if(val>=ll[mid][0] and val<=ll[mid][1]):
			return mid
		elif(val<ll[mid][0]):
			return bin(l,mid-1,ll,val)
		else:
			return bin(mid+1,r,ll,val)
def deci(n):
	s=""
	while(n!=0):
		if(n%2==0):
			n=n//2
			s="0"+s
		else:
			n=n//2
			s="1"+s
	return s
def diff(s1,s2):
	if(len(s1)<len(s2)):
		v=len(s1)
		while(v!=len(s2)):
			s1="0"+s1
			v=v+1
	else:
		v=len(s2)
		while(v!=len(s1)):
			s2="0"+s2
			v=v+1
	c=0
	for i in range(len(s1)):
		if(s1[i:i+1]!=s2[i:i+1]):
			c=c+1
	return c
from sys import stdin, stdout 
def fac(a,b):
	v=a
	while(a!=b):
		v*=a-1
		a=a-1
	return v
def bino(l,r,n):
	if(l>r):
		return -1
	else:
		mid=(l+r)//2
		val1=math.log((n/mid)+1,2)
		val2=int(val1)
		if(val1==val2):
			return val1
		elif(val1<1.0):
			return bino(l,mid-1,n)
		else:
			return bino(mid+1,r,n)

def binary(l,r,ll,val,ans):
	if(l>r):
		return ans
	else:
		mid=(l+r)//2
		if(ll[mid]<=val):
			ans=mid+1
			return binary(mid+1,r,ll,val,ans)
		else:
			return binary(l,mid-1,ll,val,ans)
def odd(n,ans,s):
	if(n%2!=0 or n in s):
		return ans
	else:
		s.add(n)
		return odd(n//2,ans+1,s)

if __name__ == '__main__':
	t=int(stdin.readline())
	for i in range(t):
		n=int(stdin.readline())
		l=list(map(int,stdin.readline().split(" ")))
		if(n==1):
			if(l[0]%2==0):
				print(1)
				print(1)
			else:
				print(-1)
		else:
			c=0
			ind=0
			l1=[]
			for i in range(n):
				if(l[i]%2==0):
						c=1
						ind=i+1
						break
				else:
					l1.append(i+1)
			if(c==0):
				if(n%2==0):
					print(n)
					print(*l1)
				else:
					print(n-1)
					print(*l1[0:n-1])
			else:
				print(c)
				print(ind)
