Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(false), cin.tie(NULL), cout.tie(NULL);
  int n, m;
  cin >> n >> m;
  char a[n + 1][m + 1];
  for (int i = 1; i <= n; i++)
    for (int j = 1; j <= m; j++) cin >> a[i][j];
  int f1 = 0, f2 = 0, f3 = 0, f4 = 0;
  int top, down;
  for (int i = 1; i <= n; i++) {
    for (int j = 1; j <= m; j++) {
      if (a[i][j] == 'B') {
        top = i;
        f1 = 1;
        break;
      }
    }
    if (f1) break;
  }
  for (int i = n; i >= 1; i--) {
    for (int j = 1; j <= m; j++) {
      if (a[i][j] == 'B') {
        down = i;
        f2 = 1;
        break;
      }
    }
    if (f2) break;
  }
  int ctr = 0;
  int left;
  for (int i = 1; i <= m; i++)
    if (a[top][i] == 'B') {
      left = i;
      break;
    }
  for (int i = 1; i <= m; i++) {
    if (a[top][i] == 'B') ctr++;
  }
  int mid = (top + down) / 2;
  int mid2 = left + (ctr / 2);
  cout << mid << " " << mid2;
  return 0;
}
