You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
int n, first, H[40005], B[200005], r;
string A;
long long res;
int main() {
  cin >> first >> A;
  n = A.size();
  int i, j, s;
  for (i = 0; i < n; i++) {
    s = 0;
    for (j = i; j < n; j++) {
      s += A[j] - '0';
      H[s]++;
    }
  }
  if (first == 0) {
    res = (long long)H[0] * n * (n + 1);
    res -= (long long)H[0] * H[0];
    cout << res << "\n";
    return 0;
  }
  for (i = 1; i * i <= first; i++)
    if (first % i == 0) {
      B[++r] = i;
      if (i * i < first) B[++r] = first / i;
    }
  sort(B + 1, B + r + 1);
  for (i = 1; i <= r; i++)
    if (B[i] < 40005 && first / B[i] < 40005)
      res += (long long)H[B[i]] * H[first / B[i]];
  cout << res << "\n";
  return 0;
}
