Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#sys.stdout=open("output.txt", 'w')
#sys.stdout.write("Yes" + '\n')
#from  sys import stdin
#input=stdin.readline
#a = sorted([(n, i) for i, n in enumerate(map(int, input().split()))])
# from collections import Counter
# import sys
#s="abcdefghijklmnopqrstuvwxyz"
#arr=sorted([(int(x),i) for i,x in enumerate(input().split())])
#n=int(input())
#n,k=map(int,input().split())
#arr=list(map(int,input().split()))
#arr=list(map(int,input().split
n,m=map(int,input().split())
ls=[input() for i in range(n)]
#print(ls)
x=[]
y=[]
for i in range(n):
    for j in range(m):
        if ls[i][j]=="B":
            x.append(i+1)
            y.append(j+1)
print(sum(x)//len(x),sum(y)//len(y))


