You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
void solve();
int main() {
  int t = 1;
  while (t--) solve();
  return 0;
}
long long a;
string s;
long long sum[5000][5000];
const long long C = 1000500;
long long cnt[C];
void solve() {
  cin >> a >> s;
  for (long long i = 0; i < s.length(); ++i) {
    long long cur = 0;
    for (long long j = i; j < s.length(); ++j) {
      cur += s[j] - '0';
      ++cnt[cur];
    }
  }
  long long res = 0;
  if (a == 0) {
    for (long long i = 1; i < C; ++i) res += cnt[i];
    res *= cnt[0];
    res *= 2;
    res += cnt[0] * cnt[0];
    cout << res << "\n";
    return;
  }
  for (long long i = 1; i < C; ++i)
    if (a % i == 0 && a / i < C) {
      res += cnt[i] * cnt[a / i];
    }
  cout << res;
}
