You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long num[40000], digit[4010];
char s[4010];
int main() {
  long long a;
  cin >> a >> s;
  int len = strlen(s);
  for (int i = 0; i < len; i++) {
    digit[i + 1] = s[i] - '0';
  }
  memset(num, 0, sizeof(num));
  long long zero = 0;
  for (int i = 1; i <= len; i++) {
    long long temp = 0;
    for (int j = i; j <= len; j++) {
      temp += digit[j];
      num[temp]++;
      zero++;
    }
  }
  long long ans = 0;
  if (a == 0) {
    ans = num[0] * zero * 2 - num[0] * num[0];
  } else {
    for (int i = 1; i * i <= a; i++) {
      if (num[i] > 0 && a / i <= 40000 && a % i == 0) {
        if (i * i == a)
          ans += num[i] * num[i];
        else
          ans += num[i] * num[a / i] * 2;
      }
    }
  }
  cout << ans << endl;
  return 0;
}
