Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
import java.util.Scanner;

public class Main {
    public static void main(String args[]) {
        Scanner sc = new Scanner(System.in);
        int r = sc.nextInt();
        int c = sc.nextInt();
        Character arr[][] = new Character[r][c];
        for (int i = 0; i < r; i++) {
            String s = sc.next();
            for (int j = 0; j < c; j++) {
                arr[i][j] = s.charAt(j);
            }
        }
        int gx = 0;
        int gy = 0;
        boolean flag = false;
        int cnt = 0;
        for (int i = 0; i < r; i++) {
            if (flag) {
                break;
            } else {
                for (int j = 0; j < c; j++) {
                    if (arr[i][j] == 'B') {
                        gx = j;
                        flag = true;
                        cnt++;
                        gy = i;
                    }
                }
            }
        }
        cnt--;
        /*
         * GY = ROW GX = COL CNT = Count
         */
        int r1 = gy;
        int c1 = gx - cnt;
        System.out.print((((2 * r1 + cnt) / 2) + 1) + " " + (((2 * c1 + cnt) / 2) + 1));
        sc.close();
    }
}