You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
char str[4008];
long long f[40000];
int main() {
  long long a, len, i, j, tmp, ans;
  scanf("%I64d%s", &a, str);
  len = strlen(str);
  memset(f, 0, sizeof(f));
  for (i = 0; i < len; i++) {
    tmp = 0;
    for (j = i; j < len; j++) {
      tmp += str[j] - '0';
      f[tmp]++;
    }
  }
  ans = 0;
  for (i = 0; i < len; i++) {
    tmp = 0;
    for (j = i; j < len; j++) {
      tmp += str[j] - '0';
      if (tmp != 0 && a % tmp == 0 && a / tmp < 40000)
        ans += f[a / tmp];
      else if (tmp == 0 && a == 0)
        ans += (len + 1) * len / 2;
    }
  }
  printf("%I64d", ans);
  return 0;
}
