You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
const int dx[] = {1, 0, -1, 0};
const int dy[] = {0, 1, 0, -1};
using namespace std;
int sum[4444];
long long baai[40000];
int main() {
  cin.tie(0);
  ios::sync_with_stdio(false);
  int a;
  cin >> a;
  string s;
  cin >> s;
  int n = s.size();
  for (int i = 1; i <= n; i++) sum[i] = sum[i - 1] + (s[i - 1] - '0');
  for (int l = 1; l <= n; l++)
    for (int r = l; r <= n; r++) {
      baai[sum[r] - sum[l - 1]]++;
    }
  long long ans = 0;
  if (a == 0) {
    long long c1 = 0;
    for (int i = 1; i < 40000; i++) c1 += baai[i];
    long long total = c1 + baai[0];
    ans = total * total - c1 * c1;
    cout << ans << endl;
    return 0;
  }
  for (int d = 1; d * d <= a; d++) {
    if (a % d != 0) continue;
    if (a / d < 40000) {
      long long tmp = baai[d] * baai[a / d];
      if (d * d != a) tmp *= 2;
      ans += tmp;
    }
  }
  cout << ans << endl;
  return 0;
}
