Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
n, m = map(int, input().split())
f = True
begin1 = (0, 0)
begin2 = (0, 0)
end1 = (0, 0)
end2 = (0, 0)
last_st = input()
if f and "B" in last_st:
    begin1 = (1, last_st.index("B") + 1)
    st1 = last_st[::-1]
    begin2 = (1, m - st1.index("B"))
    f = False

for i in range(1, n):
    st = input()
    if f and "B" in st:
        begin1 = (i+1, st.index("B")+1)
        st1 = st[::-1]
        begin2 = (i+1, m-st1.index("B"))
        f = False

    if not f and "B" not in st and "B" in last_st:
        end1 = (i, last_st.index("B")+1)
        last_st1 = last_st[::-1]
        end2 = (i, m-last_st1.index("B"))
    last_st = st

if sum(end1) == 0:
    end1 = (n, last_st.index("B"))
print((begin1[0] + end1[0])//2, (begin1[1] + begin2[1])//2)

