There are n integers b1, b2, ..., bn written in a row. For all i from 1 to n, values ai are defined by the crows performing the following procedure:

  * The crow sets ai initially 0. 
  * The crow then adds bi to ai, subtracts bi + 1, adds the bi + 2 number, and so on until the n'th number. Thus, ai = bi - bi + 1 + bi + 2 - bi + 3.... 



Memory gives you the values a1, a2, ..., an, and he now wants you to find the initial numbers b1, b2, ..., bn written in the row? Can you do it?

Input

The first line of the input contains a single integer n (2 ≤ n ≤ 100 000) — the number of integers written in the row.

The next line contains n, the i'th of which is ai ( - 109 ≤ ai ≤ 109) — the value of the i'th number.

Output

Print n integers corresponding to the sequence b1, b2, ..., bn. It's guaranteed that the answer is unique and fits in 32-bit integer type.

Examples

Input

5
6 -4 8 -2 3


Output

2 4 6 1 3 


Input

5
3 -2 -1 5 6


Output

1 -3 4 11 6 

Note

In the first sample test, the crows report the numbers 6, - 4, 8, - 2, and 3 when he starts at indices 1, 2, 3, 4 and 5 respectively. It is easy to check that the sequence 2 4 6 1 3 satisfies the reports. For example, 6 = 2 - 4 + 6 - 1 + 3, and  - 4 = 4 - 6 + 1 - 3.

In the second sample test, the sequence 1,  - 3, 4, 11, 6 satisfies the reports. For example, 5 = 11 - 6 and 6 = 6.
import java.util.*;
import java.io.*;
public class Main {
	public static long mod= (long) (1e9 +7);
	public static void main(String args[]){
			InputReader s= new InputReader(System.in);
			OutputStream outputStream= System.out;
			PrintWriter out= new PrintWriter(outputStream);
			int n= s.nextInt();
			int arr[]= new int[n+1];
			int ans[]= new int[n+1];
			for(int i = 0;i<n;i++){
				arr[i]= s.nextInt();
			}
			int sum = 0;
			//ans[n-1] = arr[n-1];
			for(int i=n-1;i>=0;i--){
				sum = arr[i+1] + arr[i];
				ans[i] = sum;
 			}
			for(int i=0;i<n;i++){
				out.print(ans[i]+" ");
			}
			out.close();
	}
	static class InputReader {

	    public BufferedReader reader;
	    public StringTokenizer tokenizer;
 
	    public InputReader(InputStream inputstream) {
	      reader = new BufferedReader(new InputStreamReader(inputstream));
	      tokenizer = null;
	    }
	    
	    public String nextLine(){
	    	String fullLine=null;
	    	while (tokenizer == null || !tokenizer.hasMoreTokens()) {
	            try {
	              fullLine=reader.readLine();
	            } catch (IOException e) {
	              throw new RuntimeException(e);
	            }
	            return fullLine;
	          }
	          return fullLine;
	    }
		public String next() {
	      while (tokenizer == null || !tokenizer.hasMoreTokens()) {
	        try {
	          tokenizer = new StringTokenizer(reader.readLine());
	        } catch (IOException e) {
	          throw new RuntimeException(e);
	        }
	      }
	      return tokenizer.nextToken();
	    }
		public long nextLong() {
		      return Long.parseLong(next());
		    }
	    public int nextInt() {
	      return Integer.parseInt(next());
	    }
	  }
	static class Pair implements Comparable<Pair>
	{
		long f,s;
		Pair(long ii, long cc)
		{
			f=ii;
			s=cc;
		}
		
		public int compareTo(Pair o) 
		{
			return Long.compare(this.f, o.f);
		}
		
	}
	public static int gcd(int number1, int number2) {  
		if(number2 == 0){
			return number1;
		} 
		return gcd(number2, number1%number2); 
	}
	public static int combinations(int n,int r){
		if(n==r) return 1;
		if(r==1) return n;
		if(r==0) return 1;
		return combinations(n-1,r)+ combinations(n-1,r-1);
	}
	public static long binomialCoeff(int n, int k)
	{
	    long C[][]= new long[n+1][k+1];
	    int i, j;
	 
	    // Caculate value of Binomial Coefficient in bottom up manner
	    for (i = 0; i <= n; i++)
	    {
	        for (j = 0; j <= Math.min(i, k); j++)
	        {
	            // Base Cases
	            if (j == 0 || j == i)
	                C[i][j] = 1;
	 
	            // Calculate value using previosly stored values
	            else
	                C[i][j] = C[i-1][j-1] + C[i-1][j];
	        }
	    }
	 
	    return C[n][k];
	}
	public static int expo(int a, int b){
	    if (b==1)
	        return a;
	    if (b==2)
	        return a*a;

	    if (b%2==0){
	            return expo(expo(a,b/2),2);
	    }
	    else{
	        return a*expo(expo(a,(b-1)/2),2);
	    }
	}
	
	public static void sieve(int N){
		int arr[]= new int[N+1];
		for(int i=2;i<Math.sqrt(N);i++){
			if(arr[i]==0){
				for(int j= i*i;j<= N;j= j+i){
					arr[j]=1;
				}
			}
		}
		// All the i for which arr[i]==0 are prime numbers.
	}
}

