Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
string tab[120];
int ans[120][2];
int vis[120][120];
int main() {
  int n, m;
  cin >> n >> m;
  int cnt = 0;
  memset(vis, false, sizeof(vis));
  for (int i = 0; i < n; i++) cin >> tab[i];
  for (int i = 0; i < n; i++) {
    for (int j = 0; j < m; j++)
      if (tab[i][j] == 'B' && vis[i][j] == false) {
        int x = i, y = j, k;
        for (k = y; k < m; k++) {
          if (tab[x][k] == 'W') {
            ans[cnt][0] = x + (k - y - 1) / 2;
            ans[cnt][1] = y + (k - y - 1) / 2;
            cnt++;
            break;
          }
        }
        if (k == m) {
          ans[cnt][0] = x + (k - y - 1) / 2;
          ans[cnt][1] = y + (k - y - 1) / 2;
          cnt++;
        }
        for (int g = i; g < i + k - y; g++)
          for (int z = j; z < k; z++) vis[g][z] = true;
        j = k - 1;
      }
  }
  for (int i = 0; i < cnt; i++)
    cout << ans[i][0] + 1 << " " << ans[i][1] + 1 << endl;
}
