You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
import java.io.*;
import java.util.*;

public class cf364a {
  static FastIO in = new FastIO(), out = in;

  public static void main(String[] args) {
    int a = in.nextInt();
    String s = in.next().trim();
    int n = s.length();
    int[][] v = new int[n][n];
    for(int i=0; i<n; i++)
      for(int j=0; j<n; j++)
        v[i][j] = (s.charAt(i)-'0')*(s.charAt(j)-'0');
    int MAX = 4000*10;
    long[] sums = new long[MAX];
    for(int i=0; i<n; i++) {
      int tmp = 0;
      for(int j=i; j<n; j++) {
        tmp += s.charAt(j)-'0';
        sums[tmp]++;
      }
    }
    long ans = 0;
    if(a == 0) ans = sums[0]*sums[0];
    for(int i=1; i<MAX; i++) {
      if(a == 0) ans += 2*sums[0]*sums[i];
      else if(a%i == 0 && a/i < MAX) ans += sums[i]*sums[a/i];
    }
    out.println(ans);
    out.close();
  }

  static class FastIO extends PrintWriter {
    BufferedReader br;
    StringTokenizer st;

    public FastIO() {
      this(System.in, System.out);
    }

    public FastIO(InputStream in, OutputStream out) {
      super(new BufferedWriter(new OutputStreamWriter(out)));
      br = new BufferedReader(new InputStreamReader(in));
      scanLine();
    }

    public void scanLine() {
      try {
        st = new StringTokenizer(br.readLine().trim());
      } catch (Exception e) {
        throw new RuntimeException(e.getMessage());
      }
    }

    public int numTokens() {
      if (!st.hasMoreTokens()) {
        scanLine();
        return numTokens();
      }
      return st.countTokens();
    }

    public String next() {
      if (!st.hasMoreTokens()) {
        scanLine();
        return next();
      }
      return st.nextToken();
    }

    public double nextDouble() {
      return Double.parseDouble(next());
    }

    public long nextLong() {
      return Long.parseLong(next());
    }

    public int nextInt() {
      return Integer.parseInt(next());
    }
  }
}
