Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
import java.util.Scanner;
public class Main {
    static final int MAXN=116;
    static final int MAXM=116;
    static int n,m,r,c;
    static char arr[][]=new char[MAXN][MAXM];

    static final int inf = (int) 1e9;
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        n=sc.nextInt();
        m=sc.nextInt();
        for (int i=0;i<n;i++){
            String temp=sc.next();
            for(int j=0;j<m;j++){
                arr[i][j]=temp.charAt(j);
            }
        }
        int minX=inf,maxX=-inf,minY=inf,maxY=-inf;
        for(int i=0;i<n;i++){
            for(int j=0;j<m;j++){
                if(arr[i][j]=='B'){
                    minX=Math.min(minX,i);
                    maxX=Math.max(maxX,i);
                    minY=Math.min(minY,j);
                    maxY=Math.max(maxY,j);
                }
            }
        }
        c=(minY+maxY)/2+1;
        r=(minX+maxX)/2+1;
        System.out.print(r+" "+c);
    }
}
