You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int INFint = 2147483647;
const long long INF = 9223372036854775807ll;
const long long MOD = 1000000007ll;
long long cnt[100000];
int main() {
  ios_base::sync_with_stdio(0);
  long long a;
  cin >> a;
  string s;
  cin >> s;
  for (int i = 0; i < s.size(); i++) {
    long long sum = 0;
    for (int j = i; j < s.size(); j++) {
      sum += s[j] - '0';
      cnt[sum]++;
    }
  }
  long long ans = 0;
  if (a == 0) {
    ans = cnt[0] * cnt[0];
    for (int i = 1; i < 100000; i++) {
      ans += cnt[0] * cnt[i] * 2;
    }
  } else {
    for (int i = 1; i < 100000; i++) {
      if (i <= a) {
        if (a % i == 0 && a / i < 100000) ans += cnt[i] * cnt[a / i];
      } else
        break;
    }
  }
  cout << ans << endl;
  fprintf(stderr, "\nTIME = %lf\n", 1.0 * clock() / CLOCKS_PER_SEC);
  return 0;
}
