Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e5 + 5;
const long long mod = 1e9 + 7;
const int alphabet = 26;
const int inf = INT_MAX;
const long long linf = 1e18 + 9;
inline long long cnm(char ch) { return (ch - '0'); }
inline long long cap(char ch) { return (ch - 'a'); }
inline void instr(string& s, long long& n) {
  cin >> s;
  n = s.length();
}
inline void instr(string& s) { cin >> s; }
template <typename T>
T gcd(T a, T b) {
  if (a == 0) return b;
  return gcd(b % a, a);
}
char s[200][200];
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);
  long long i, j, k, m, n;
  cin >> n >> m;
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      cin >> s[i][j];
    }
  }
  for (i = 0; i < n; i++) {
    for (j = 0; j < m; j++) {
      if (s[i][j] == 'B') {
        long long cnt = 1, x = i, y = j;
        j++;
        while (s[i][j] == 'B' and j < m) j++;
        long long len = j - y;
        len /= 2;
        x = x + len;
        y = y + len;
        x++;
        y++;
        cout << x << " " << y;
        return 0;
      }
    }
  }
  return 0;
}
