You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long m1[37000], m2[37000];
int32_t main() {
  ios_base::sync_with_stdio(false);
  cin.tie(0);
  cout.tie(0);
  long long a;
  cin >> a;
  string s;
  cin >> s;
  long long n = s.size();
  long long pref[n + 1];
  pref[0] = 0;
  for (long long i = 0; i < n; i++) {
    pref[i + 1] = pref[i] + s[i] - '0';
  }
  long long ct = 0;
  for (long long i = 0; i < n; i++) {
    for (long long j = i; j < n; j++) {
      long long sum = pref[j + 1] - pref[i];
      ct++;
      m1[sum]++;
      m2[sum] = 1;
    }
  }
  long long ans = 0;
  for (long long i = 0; i < 37000; i++) {
    if (m2[i] == 0) {
      continue;
    }
    long long z = i;
    long long l = m1[i];
    if (z == 0 && a != 0) {
      continue;
    }
    if (z == 0 && a == 0) {
      ans += (l * (ct));
      continue;
    }
    if (a % z == 0) {
      long long k = a / z;
      if (k >= 37000) {
        continue;
      }
      if (m2[k] == 1) {
        ans += ((m1[k]) * l);
      }
    }
  }
  cout << ans;
}
