You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 111111;
long long met[MAXN];
char s[MAXN];
int n;
long long ans;
long long getMet(int i) {
  if (i >= MAXN || i < 0) return 0;
  return met[i];
}
int a, i, j;
int main() {
  scanf("%d\n", &a);
  gets(s);
  n = strlen(s);
  for (i = 0; i < n; i++) {
    int sum = 0;
    for (j = i; j < n; j++) {
      sum += s[j] - '0';
      met[sum]++;
    }
  }
  if (a == 0) {
    for (i = 1; i < MAXN; i++) ans += getMet(0) * getMet(i);
    ans *= 2;
    ans += getMet(0) * getMet(0);
  } else {
    for (i = 1; i < MAXN; i++) {
      if (a % i == 0) {
        ans += getMet(i) * getMet(a / i);
      }
    }
  }
  cout << ans;
  return 0;
}
