Vasya tries to break in a safe. He knows that a code consists of n numbers, and every number is a 0 or a 1. Vasya has made m attempts to enter the code. After each attempt the system told him in how many position stand the right numbers. It is not said in which positions the wrong numbers stand. Vasya has been so unlucky that he hasn’t entered the code where would be more than 5 correct numbers. Now Vasya is completely bewildered: he thinks there’s a mistake in the system and it is self-contradictory. Help Vasya — calculate how many possible code variants are left that do not contradict the previous system responses.

Input

The first input line contains two integers n and m (6 ≤ n ≤ 35, 1 ≤ m ≤ 10) which represent the number of numbers in the code and the number of attempts made by Vasya. Then follow m lines, each containing space-separated si and ci which correspondingly indicate Vasya’s attempt (a line containing n numbers which are 0 or 1) and the system’s response (an integer from 0 to 5 inclusively).

Output

Print the single number which indicates how many possible code variants that do not contradict the m system responses are left.

Examples

Input

6 2
000000 2
010100 4


Output

6


Input

6 3
000000 2
010100 4
111100 0


Output

0


Input

6 3
000000 2
010100 4
111100 2


Output

1
import os,io
from sys import stdout
# import collections
# import random
# import math
# from operator import itemgetter
input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
# from collections import Counter
# from decimal import Decimal
# import heapq
# from functools import lru_cache

# import sys
# import threading
# sys.setrecursionlimit(10**6)
# threading.stack_size(102400000)

# from functools import lru_cache
# @lru_cache(maxsize=None)

######################
# --- Maths Fns  --- #
######################
def primes(n):
    sieve = [True] * n
    for i in range(3,int(n**0.5)+1,2):
        if sieve[i]:
            sieve[i*i::2*i]=[False]*((n-i*i-1)//(2*i)+1)
    return [2] + [i for i in range(3,n,2) if sieve[i]]

def binomial_coefficient(n, k):
    if 0 <= k <= n:
        ntok = 1
        ktok = 1
        for t in range(1, min(k, n - k) + 1):
            ntok *= n
            ktok *= t
            n -= 1
        return ntok // ktok
    else:
        return 0

def powerOfK(k, max):
    if k == 1:
        return [1]
    if k == -1:
        return [-1, 1]

    result = []
    n = 1
    while n <= max:
        result.append(n)
        n *= k
    return result

def divisors(n):
    i = 1
    result = []
    while i*i <= n:
        if n%i == 0:
            if n/i == i:
                result.append(i)
            else:
                result.append(i)
                result.append(n/i)
        i+=1
    return result

# @lru_cache(maxsize=None)
def digitsSum(n):
    if n == 0:
        return 0
    r = 0
    while n > 0:
        r += n % 10
        n //= 10
    return r

######################
# ---- GRID Fns ---- #
######################
def isValid(i, j, n, m):
    return i >= 0 and i < n and j >= 0 and j < m

def print_grid(grid):
    for line in grid:
        print(" ".join(map(str,line)))

######################
# ---- MISC Fns ---- #
######################
def kadane(a,size):
    max_so_far = 0
    max_ending_here = 0

    for i in range(0, size):
        max_ending_here = max_ending_here + a[i]
        if (max_so_far < max_ending_here):
            max_so_far = max_ending_here

        if max_ending_here < 0:
            max_ending_here = 0
    return max_so_far

def prefixSum(arr):
    for i in range(1, len(arr)):
        arr[i] = arr[i] + arr[i-1]
    return arr

def ceil(n, d):
    if n % d == 0:
        return n // d
    else:
        return (n // d) + 1

# INPUTS  --------------------------
# s = input().decode('utf-8').strip()
# n = int(input())
# l = list(map(int, input().split()))
# t = int(input())
# for _ in range(t):
# for _ in range(t):


n, k = list(map(int, input().split()))
q = []
for _ in range(k):
    a, b = list(map(lambda x: x.decode('utf-8').strip(), input().split()))
    q.append((list(map(int, a)), int(b)))

code, correct = max(q, key=lambda x: x[1])
codeb = int("".join(map(str, code)), 2)
possibles = set()

def generate(n, correct, codeb, l, s):
    if correct == 0:
        while len(l) < n:
            l.append(1)
        p = int("".join(map(str, l)), 2)

        s.add(p)
        return

    if n - len(l) < correct:
        return

    generate(n, correct-1, codeb, l+[0], s)
    generate(n, correct, codeb, l+[1], s)

result = None
memo = {}
for code, correct in q:
     codeb = int("".join(map(str, code)), 2)
     newSetOfPossibles = set()

     if correct in memo:
         newSetOfPossibles = memo[correct]
     else:
         generate(n, correct, codeb, [], newSetOfPossibles)
         memo[correct] = newSetOfPossibles

     newSetOfPossibles = set(list(map(lambda x: x^codeb, list(newSetOfPossibles))))
     if not result:
         result = newSetOfPossibles
     else:
         result = result.intersection(newSetOfPossibles)

print(len(result))
