You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
long long d[40000];
char s[4005];
void input() {
  int i, j, len, a, sum;
  long long res;
  scanf("%d %s", &a, &s);
  len = strlen(s);
  for ((i) = 0; (i) < (len); (i)++) {
    sum = 0;
    for ((j) = (i); (j) <= (len - 1); (j)++) {
      sum += s[j] - '0';
      d[sum]++;
    }
  }
  if (a == 0) {
    res = d[0] * len * (len + 1) - d[0] * d[0];
    printf("%I64d\n", res);
    return;
  }
  res = 0;
  for ((i) = (9 * len); (i) >= (1); (i)--)
    if (a % i == 0 && a / i <= 36000) res += d[i] * d[a / i];
  printf("%I64d", res);
}
int main() {
  input();
  return 0;
}
