Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner cv = new Scanner(System.in);
        int n = cv.nextInt();
        int m = cv.nextInt();
        boolean a=true,b=true;
        cv.nextLine();
        String arr[]=new String[n];
        int l=0,max=0,r=0,c=0,k1=0,k2=0;
        for (int i = 0; i < n ; i++) {
            arr[i]=cv.nextLine();
            for (int j = 0; j < m && b ; j++) {
                if (arr[i].charAt(j)=='B'){
                    k1=j;
                    k2=i;
                    b=false;
                }
            }
        }
        for (int i = 0; i <m ; i++) {
            for (int j = 0; j < n ; j++) {
                if(arr[j].charAt(i)=='B'){
                    c++;
                }
            }
            if(max<c){
                max=c;
            }
            c=0;
        }
        c=max/2 +k2;
        for (int i = 0; i < m ; i++) {
            if(arr[c].charAt(i)=='B'){
                r++;
            }
        }
        l=r/2+k1;
        System.out.println(c+1+" "+(l+1));
    }
}
