Consider a table of size n × m, initially fully white. Rows are numbered 1 through n from top to bottom, columns 1 through m from left to right. Some square inside the table with odd side length was painted black. Find the center of this square.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 115) — the number of rows and the number of columns in the table.

The i-th of the next n lines contains a string of m characters s_{i1} s_{i2} … s_{im} (s_{ij} is 'W' for white cells and 'B' for black cells), describing the i-th row of the table.

Output

Output two integers r and c (1 ≤ r ≤ n, 1 ≤ c ≤ m) separated by a space — the row and column numbers of the center of the black square.

Examples

Input

5 6
WWBBBW
WWBBBW
WWBBBW
WWWWWW
WWWWWW


Output

2 4


Input

3 3
WWW
BWW
WWW


Output

2 1
// http://codeforces.com/problemset/problem/1028/A

import java.util.Scanner;

public class Solution {

	public static void main(String[] args) {
		Scanner read = new Scanner(System.in);
		
		int n = read.nextInt();
		int m = read.nextInt();
		
		read.nextLine();

		char[][] s = new char[n][m];
		for (int i = 0; i < n; ++i) {
			s[i] = read.nextLine().toCharArray();
		}
		
		int xMin = Integer.MAX_VALUE;
		int xMax = Integer.MIN_VALUE;
		int yMin = Integer.MAX_VALUE;
		int yMax = Integer.MIN_VALUE;
		
		for (int i = 0; i < n; ++i) {
			for (int j = 0; j < m; ++j) {
				if (s[i][j] == 'B') {
					xMin = Math.min(i, xMin);
					xMax = Math.max(i, xMax);
					yMin = Math.min(j, yMin);
					yMax = Math.max(j, yMax);
				}
 			}
		}
		
		System.out.println( 
			( (xMin+xMax)/2 + 1 )
			+ " " +
			( (yMin+yMax)/2 + 1 )
		);
		
		// Close scanner
		read.close();
	}

}