You have a string of decimal digits s. Let's define bij = si·sj. Find in matrix b the number of such rectangles that the sum bij for all cells (i, j) that are the elements of the rectangle equals a in each rectangle.

A rectangle in a matrix is a group of four integers (x, y, z, t) (x ≤ y, z ≤ t). The elements of the rectangle are all cells (i, j) such that x ≤ i ≤ y, z ≤ j ≤ t.

Input

The first line contains integer a (0 ≤ a ≤ 109), the second line contains a string of decimal integers s (1 ≤ |s| ≤ 4000).

Output

Print a single integer — the answer to a problem.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64d specifier.

Examples

Input

10
12345


Output

6


Input

16
439873893693495623498263984765


Output

40
#include <bits/stdc++.h>
using namespace std;
char s[5000];
int sum[5000], cnt[5000 * 10];
int main() {
  int a;
  scanf("%d", &a);
  scanf("%s", s);
  int N = strlen(s);
  sum[0] = 0;
  for (int i = 0; i < N; i++) sum[i + 1] = sum[i] + s[i] - '0';
  for (int i = 0; i < N; i++)
    for (int j = i + 1; j <= N; j++) {
      cnt[sum[j] - sum[i]]++;
    }
  long long ans = 0;
  if (a == 0) ans += (long long)cnt[0] * N * (N + 1) / 2;
  for (int i = 1; i <= sum[N]; i++) {
    if (a % i == 0 && a / i <= sum[N]) {
      ans += (long long)cnt[i] * cnt[a / i];
    }
  }
  printf("%I64d\n", ans);
  return 0;
}
