You are given two integers x and y. You can perform two types of operations: 

  1. Pay a dollars and increase or decrease any of these integers by 1. For example, if x = 0 and y = 7 there are four possible outcomes after this operation: 
    * x = 0, y = 6; 
    * x = 0, y = 8; 
    * x = -1, y = 7; 
    * x = 1, y = 7. 

  2. Pay b dollars and increase or decrease both integers by 1. For example, if x = 0 and y = 7 there are two possible outcomes after this operation: 
    * x = -1, y = 6; 
    * x = 1, y = 8. 



Your goal is to make both given integers equal zero simultaneously, i.e. x = y = 0. There are no other requirements. In particular, it is possible to move from x=1, y=0 to x=y=0.

Calculate the minimum amount of dollars you have to spend on it.

Input

The first line contains one integer t (1 ≤ t ≤ 100) — the number of testcases.

The first line of each test case contains two integers x and y (0 ≤ x, y ≤ 10^9).

The second line of each test case contains two integers a and b (1 ≤ a, b ≤ 10^9).

Output

For each test case print one integer — the minimum amount of dollars you have to spend.

Example

Input


2
1 3
391 555
0 0
9 4


Output


1337
0

Note

In the first test case you can perform the following sequence of operations: first, second, first. This way you spend 391 + 555 + 391 = 1337 dollars.

In the second test case both integers are equal to zero initially, so you dont' have to spend money.
"""
    Author : thekushalghosh
    Team   : CodeDiggers
"""
import sys,math,cmath,time
start_time = time.time()

################# ---- USER DEFINED INPUT FUNCTIONS ---- #################
def inp():
    return(int(input()))
def inlt():
    return(list(map(int,input().split())))
def insr():
    s = input()
    return(s[:len(s) - 1])
def invr():
    return(map(int,input().split()))
##########################################################################
################# ---- THE ACTUAL CODE STARTS BELOW ---- #################

def solve():
    a,b = invr()
    c,d = invr()
    if (a >= 0 and b >= 0) or (a <= 0 and b <= 0):
        print(min((d * min(abs(a),abs(b))) + (c * abs(b - a)),c * (abs(a) + abs(b))))
    else:
        print(c * (abs(a) + abs(b)))
    
################## ---- THE ACTUAL CODE ENDS ABOVE ---- ##################
##########################################################################
def main():
    ONLINE_JUDGE = __debug__
    if not ONLINE_JUDGE:
        sys.stdin = open('input.txt','r')
        sys.stdout = open('output.txt','w')
    else:
        input = sys.stdin.readline
    t = 1
    t = inp()
    for tt in range(t):
        solve()
    if not ONLINE_JUDGE:
        print("Time Elapsed:",time.time() - start_time,"seconds")

############## ---- USER DEFINED PROGRAMMING FUNCTIONS ---- ##############
def counter(a):
    q = [0] * max(a)
    for i in range(len(a)):
        q[a[i] - 1] = q[a[i] - 1] + 1
    return(q)

main()
sys.stdout.close()
