For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.

* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.

Constraints

* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $key$ $x$


or


1 $key$


or


2 $key$


where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.

Output

For each get operation, print an integer in a line.

Example

Input

8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red


Output

1
4
0
0
import java.io.*;
import java.util.*;

class Main{
	public static void main(String[] args) throws IOException{
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		String[] str = br.readLine().split(" ");
		int q = Integer.parseInt(str[0]);
		SortedMap<String, Integer> mpa = new TreeMap<String, Integer>();
		for(int i = 0; i < q; i++){
			str = br.readLine().split(" ");
			int op = Integer.parseInt(str[0]);
			if(op == 0){
				String key = str[1];
				int x = Integer.parseInt(str[2]);
				mpa.put(key, x);
			}else if(op == 1){
				String key = str[1];
				if(mpa.containsKey(key)) System.out.println(mpa.get(key));
				else System.out.println(0);
			}else{
				String key = str[1];
				if(mpa.containsKey(key)) mpa.remove(key);
			}
		}
	}
}

