They say "years are like dominoes, tumbling one after the other". But would a year fit into a grid? I don't think so.

Limak is a little polar bear who loves to play. He has recently got a rectangular grid with h rows and w columns. Each cell is a square, either empty (denoted by '.') or forbidden (denoted by '#'). Rows are numbered 1 through h from top to bottom. Columns are numbered 1 through w from left to right.

Also, Limak has a single domino. He wants to put it somewhere in a grid. A domino will occupy exactly two adjacent cells, located either in one row or in one column. Both adjacent cells must be empty and must be inside a grid.

Limak needs more fun and thus he is going to consider some queries. In each query he chooses some rectangle and wonders, how many way are there to put a single domino inside of the chosen rectangle?

Input

The first line of the input contains two integers h and w (1 ≤ h, w ≤ 500) – the number of rows and the number of columns, respectively.

The next h lines describe a grid. Each line contains a string of the length w. Each character is either '.' or '#' — denoting an empty or forbidden cell, respectively.

The next line contains a single integer q (1 ≤ q ≤ 100 000) — the number of queries.

Each of the next q lines contains four integers r1i, c1i, r2i, c2i (1 ≤ r1i ≤ r2i ≤ h, 1 ≤ c1i ≤ c2i ≤ w) — the i-th query. Numbers r1i and c1i denote the row and the column (respectively) of the upper left cell of the rectangle. Numbers r2i and c2i denote the row and the column (respectively) of the bottom right cell of the rectangle.

Output

Print q integers, i-th should be equal to the number of ways to put a single domino inside the i-th rectangle.

Examples

Input

5 8
....#..#
.#......
##.#....
##..#.##
........
4
1 1 2 3
4 1 4 1
1 2 4 5
2 5 5 8


Output

4
0
10
15


Input

7 39
.......................................
.###..###..#..###.....###..###..#..###.
...#..#.#..#..#.........#..#.#..#..#...
.###..#.#..#..###.....###..#.#..#..###.
.#....#.#..#....#.....#....#.#..#..#.#.
.###..###..#..###.....###..###..#..###.
.......................................
6
1 1 3 20
2 10 6 30
2 10 7 30
2 2 7 7
1 7 7 7
1 8 7 8


Output

53
89
120
23
0
2

Note

A red frame below corresponds to the first query of the first sample. A domino can be placed in 4 possible ways.

<image>
import java.io.*;
import java.lang.reflect.Array;
import java.util.*;
public class test {
    int max = 0;
    long max1 = 0;
    boolean visited[][];
    int parent[];
    boolean bi=true;
    StringBuilder cout=new StringBuilder("");
    int color[];
    PrintStream out = System.out;
    int signx[] = {1,-1,0 ,0, 1, -1,-1,1};
    int signy[]=  {0,0,1,-1,  1,-1,1,-1};
    public static void main(String args[]) throws IOException {
        test obj = new test();
        obj.start();
    }

    void start() throws IOException {
   // Reader sc = new Reader();
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
       // Scanner sc=new Scanner(System.in);
        String s[]=br.readLine().split(" ");
        int n=Integer.parseInt(s[0]);
        int m=Integer.parseInt(s[1]);
        char a[][]=new char[n][m];
        for(int i=0;i<n;i++)
        {
            for(int j=0;j<m;j++)
            {
                a[i][j]=(char)br.read();
            }
            br.readLine();
        }
        int t=Integer.parseInt(br.readLine());
        int h[][]=new int[n][m];
        int v[][]=new int[n][m];
        for(int i=0;i<n;i++)
        {
            for(int j=1;j<m;j++)
            {
                if(a[i][j]=='.'&&a[i][j-1]=='.')
                    h[i][j]=h[i][j-1]+1;
                else
                    h[i][j]=h[i][j-1];
            }
        }
        for(int j=0;j<m;j++)
        {
            for(int i=1;i<n;i++)
            {
                if(a[i][j]=='.'&&a[i-1][j]=='.')
                    v[i][j]=v[i-1][j]+1;
                else
                    v[i][j]=v[i-1][j];
            }
        }
     //   println(h,n,m);
       // out.println();
        //println(v,n,m);
      while(t-->0)
      {
          String str[]=br.readLine().split(" ");
          int r1=Integer.parseInt(str[0])-1;
          int w1=Integer.parseInt(str[1])-1;
          int r2=Integer.parseInt(str[2])-1;
          int w2=Integer.parseInt(str[3])-1;
          int count=0;
          for(int i=w1;i<=w2;i++)
          {
              count+=v[r2][i]-v[r1][i];
          }
          for(int i=r1;i<=r2;i++)
          {
              count+=h[i][w2]-h[i][w1];
          }
          out.println(count);

      }

    }


    //<---------------------------------------------------------------------------------------------------------------->//

    //printing 2-d array
    private void println(int[][] a,int n,int m) {
        for(int i=0;i<n;i++)
        {
            for(int j=0;j<m;j++)
                System.out.print(a[i][j]+" ");
            System.out.println();
        }

    }
    void dfs(char a[][],char t,int i,int j,int n,int m,int p,int q)
    {
        //  out.print(" "+i+" "+j+" "+t);
        visited[i][j]=true;
        for(int c=0;c<4;c++)
        {
            int temp=i+signx[c];
            int temp1=j+signy[c];
            if(temp>=0&&temp<n&&temp1>=0&&temp1<m)
            {
                if(a[temp][temp1]==t&&(temp!=p||temp1!=q)&&!visited[temp][temp1])
                    dfs(a,t,temp,temp1,n,m,i,j);
                else if(a[temp][temp1]==t&&(temp!=p||temp1!=q)&&visited[temp][temp1]) {
                    max = 1;
                }
            }
        }

    }
    void println(ArrayList<Long> a)
    {
        for (Long b:a
                ) {
            System.out.print(b+" ");
        }
    }


    //modified dfs for chessboard, matrix
    void dfs(char a[][],int i,int j,char t,int n,int m,int d,int p,int q,boolean visited[][])
    {

    }


    //constructing segment tree
    private void constructseg(long[] seg, long[] input, int p, int q, int pos) {
        if(p==q)
        {
            seg[pos]=input[p];
            return;
        }
        int mid=(q+p)/2;
        constructseg(seg,input,p,mid,2*pos+1);
        constructseg(seg,input,mid+1,q,2*pos+2);
        seg[pos]=seg[2*pos+1]+seg[2*pos+2];
    }

    /*  void bipartite(ArrayList<Integer> a[],int i)
      {
          int presentcolor=color[i];
          int nextcolor;
          if(color[i]==0) {
              nextcolor=1;
            b.add(i);
          }
          else
          {
              nextcolor=0;
              c.add(i);
          }
          for(int j=0;j<a[i].size();j++)
          {
              if(color[a[i].get(j)]==presentcolor)
                  bi=false;
              else if(color[a[i].get(j)]==-1)
              {
                  color[a[i].get(j)]=nextcolor;
                  bipartite(a,a[i].get(j));
              }
          }

      }*/
    //traversing through a arrayList graph
    void dfs(ArrayList<Integer> node[],int i)
    {

      /*  visited[i]=true;
   /*     if(cat[i]==1) {
            count++;
        }
        else
            count=0;
        if(count>k) {
            return;
        }
        if(node[i].size()==1&&i!=0) {
            max += 1;
        }
        for (int j = 0; j < node[i].size(); j++) {
            if(!visited[node[i].get(j)]) {
                max--;
                dfs(node, node[i].get(j));
            }
        }*/

    }


    //printing arraylist array
    void println(ArrayList<Integer> a[])
    {
        for (ArrayList<Integer> b:a
                ) {
            System.out.println(b.toString());
        }
    }

    //sorting 2 array based on a, Complexity is O(n^2)
    void sort(int a[],int b[],int n)
    {
        for(int i=1;i<n;i++)
        {
            int index=i;
            for(int j=i-1;j>=0;j--)
            {
                //  println(a);
                if(a[index]<a[j])
                {
                    int temp=a[index];
                    int temp2=b[index];
                    a[index]=a[j];
                    b[index]=b[j];
                    a[j]=temp;
                    b[j]=temp2;
                    index=j;

                }
                else
                    break;
            }
        }

    }
    // to create and initialize Integer array
    private int[] intArray(int a, Scanner sc) {
        int temp[]=new int[a];
        for(int i=0;i<a;i++) {
            temp[i]=sc.nextInt();
        }
        return temp;
    }

    private int[] intArray(int a, Reader sc) throws IOException {
        int temp[]=new int[a];
        for(int i=0;i<a;i++) {
            temp[i]=sc.nextInt();
        }
        return temp;
    }// / to create and initialize Long Array
    private long[] longArray(int a, Scanner sc) {
        long temp[]=new long[a];
        for(int i=0;i<a;i++) {
            temp[i]=sc.nextLong();
        }
        return temp;
    }

    // displaying Map contents key--value
    public static void printMap(Map mp) {
        Iterator it = mp.entrySet().iterator();
        while (it.hasNext()) {
            Map.Entry pair = (Map.Entry)it.next();
            System.out.println(pair.getKey() + " = " + pair.getValue());
            it.remove(); // avoids a ConcurrentModificationException
        }
    }


    // Return arrayList of minimum factor of number
    // 24= 2*2*2*3;
    private ArrayList<Integer> minFactor(int a) {
        ArrayList<Integer> obj=new ArrayList<>();
        for(int i=2;i<=a;i++)
        {
            while(a!=0&&a%i==0)
            {
                obj.add(i);
                a/=i;
            }
        }
        return obj;
    }


    // check whether the number is prime or not
    public static boolean isPrimeNumber(int i) {
        int factors = 0;
        int j = 1;

        while(j <= i)
        {
            if(i % j == 0)
            {
                factors++;
            }
            j++;
        }
        return (factors == 2);
    }

    // creating and initializing arrayList
    private void initArrayList(ArrayList<Integer>[] tempa) {
        for(int i=0;i<tempa.length;i++)
            tempa[i]=new ArrayList<>();
    }

    // return factorial contents as ArrayList
    private ArrayList<Integer> factdigit(int i)
    {
        ArrayList<Integer> temp=new ArrayList<>();
        for(int j=i;j>1;j--)
        {
            temp.add(j);
        }
        return temp;
    }

    //printing Integer array
    private  void println(int a[])
    {
        for(int i=0;i<a.length;i++)
            System.out.print(a[i]+" ");
    }
    int factorial(int n){
        if (n == 0)
            return 1;
        else
            return((n %1000000007)* (factorial(n-1)%1000000007));
    }
}





class Reader {
    final private int BUFFER_SIZE = 1 << 16;
    private DataInputStream din;
    private byte[] buffer;
    private int bufferPointer, bytesRead;

    public Reader() {
        din = new DataInputStream(System.in);
        buffer = new byte[BUFFER_SIZE];
        bufferPointer = bytesRead = 0;
    }

    public Reader(String file_name) throws IOException {
        din = new DataInputStream(new FileInputStream(file_name));
        buffer = new byte[BUFFER_SIZE];
        bufferPointer = bytesRead = 0;
    }

    public String readLine() throws IOException {
        byte[] buf = new byte[300]; // line length
        int cnt = 0, c;
        while ((c = read()) != -1) {
            if (c == '\n')
                break;
            buf[cnt++] = (byte) c;
        }
        return new String(buf, 0, cnt);
    }

    public int nextInt() throws IOException {
        int ret = 0;
        byte c = read();
        while (c <= ' ')
            c = read();
        boolean neg = (c == '-');
        if (neg)
            c = read();
        do {
            ret = ret * 10 + c - '0';
        } while ((c = read()) >= '0' && c <= '9');

        if (neg)
            return -ret;
        return ret;
    }

    public long nextLong() throws IOException {
        long ret = 0;
        byte c = read();
        while (c <= ' ')
            c = read();
        boolean neg = (c == '-');
        if (neg)
            c = read();
        do {
            ret = ret * 10 + c - '0';
        }
        while ((c = read()) >= '0' && c <= '9');
        if (neg)
            return -ret;
        return ret;
    }

    public double nextDouble() throws IOException {
        double ret = 0, div = 1;
        byte c = read();
        while (c <= ' ')
            c = read();
        boolean neg = (c == '-');
        if (neg)
            c = read();

        do {
            ret = ret * 10 + c - '0';
        }
        while ((c = read()) >= '0' && c <= '9');

        if (c == '.') {
            while ((c = read()) >= '0' && c <= '9') {
                ret += (c - '0') / (div *= 10);
            }
        }

        if (neg)
            return -ret;
        return ret;
    }

    private void fillBuffer() throws IOException {
        bytesRead = din.read(buffer, bufferPointer = 0, BUFFER_SIZE);
        if (bytesRead == -1)
            buffer[0] = -1;
    }

    private byte read() throws IOException {
        if (bufferPointer == bytesRead)
            fillBuffer();
        return buffer[bufferPointer++];
    }

    public void close() throws IOException {
        if (din == null)
            return;
        din.close();
    }
}

//Pair implementation
class Pair<A, C> {
    public A a;
    public C c;

    Pair(A a, C c) {
        this.a = a;
        this.c = c;
    }

    A getKey() {
        return this.a;
    }

    C getValue() {
        return this.c;
    }

    void print() {
        System.out.println(this.a + " " + this.c);
    }
}