Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
n = int(input())
a = [n]
if n != 2:
    a.append(n - 1)

def div_(N, k):
    while N % k == 0:
        N /= k
    if N % k == 1:
        a.append(k)

for k in range(2, int(n ** 0.5) + 1):
    if n % k == 0:
        div_(n,k)
        if k != n / k:
            div_(n, n // k)

    if (n - 1) % k == 0:
        a.append(k)
        if k != (n - 1) / k:
            a.append((n - 1) // k)

print(len(a))