Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
N = int(input())

def divisors(n):
    ret = set()
    m = 1
    while m*m <= n:
        if n%m==0:
            ret.add(m)
            ret.add(n//m)
        m += 1
    return ret

a = divisors(N)
b = divisors(N-1)

ans = len(b)-1
for k in a:
    if k==1: continue
    n = N
    while n%k==0:
        n //= k
    if n%k == 1:
        ans += 1

print(ans)
