Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
N = int(input())

def divisor(N):
    ret = []
    for i in range(1, int(N**0.5)+1):
        if N % i == 0:
            ret.append(i)
            if N // i != i:
                ret.append(N//i)
    return ret


div_N = divisor(N)
div_N_1 = divisor(N-1)

ans = 0

for k in div_N[1:]:
    n = N
    while n % k == 0:
        n //= k
    if n % k == 1:
        ans += 1

ans += len(div_N_1) - 1

print(ans)
