Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
def divisors(n):
    lst = []; i = 1
    while i * i <= n:
        q, r = divmod(n, i)
        if r == 0:
            lst.append(i)
            if i != q: lst.append(q)
        i += 1
    return lst

N = int(input())
ans = len(divisors(N-1)) - 1
divs = divisors(N)
for k in divs:
    if k == 1: continue
    temp = N
    while temp % k == 0: temp //= k
    if temp % k == 1: ans += 1
print(ans)