Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
def divisors(n):
    i = 1
    table = set()
    while i * i <= n:
        if not n % i:
            table.add(i)
            table.add(n//i)
        i += 1
    table = list(table)
    return table
N = int(input())
k = 2
res = 0
while k*k<=N:
    n = N
    while not n%k:
        n//=k
    if (n%k==1 or n==1) and n!=N:
        res += 1
    k += 1
a = divisors(N-1)
print(len(a)+res)