For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.

* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.

Constraints

* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $key$ $x$


or


1 $key$


or


2 $key$


where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.

Output

For each get operation, print an integer in a line.

Example

Input

8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red


Output

1
4
0
0
import java.util.Map;
import java.util.Scanner;
import java.util.TreeMap;

public class Main {
	public static void main(String args[]) {
		Scanner scan = new Scanner(System.in);

		Map<String,Integer> map = new TreeMap<>();

		int n = scan.nextInt();

		for(int i=0; i<n; i++) {

			int query = scan.nextInt();
			String key = scan.next();

			switch(query) {

			case 0:
				int value = scan.nextInt();
				map.put(key, value);
				break;

			case 1:
				if(map.containsKey(key)) {
					System.out.println(map.get(key));
				}else
				System.out.println("0");
				break;
				
			case 2:
				map.remove(key);
			}
		}
	}
}

