Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
N = int(input())

if N == 2:
    print(1)
    exit()

if N == 3:
    print(2)
    exit()

ans = []
for n in range(1, int(N ** 0.5) + 1):
    if (N - 1) % n == 0:
        ans.append(n)
        ans.append((N - 1) // n)

for k in range(2, int(N ** 0.5) + 1):
    x = N
    while x % k == 0:
        x //= k

    if 1 in (x % k - k, x % k):
        ans.append(k)

print(len(set(ans)))
