Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
def divisor(n):
    res = []
    
    i = 1
    while i*i <= n:
        if not n % i:
            res.append(i)
            if (i*i != n): res.append(n//i)     
        
        i += 1
        
    return res

N = int(input())
ans = 0

for d in divisor(N):
    if d == 1: continue
    n = N
    
    while not n % d:
        n //= d
        
    if n%d == 1: ans += 1
    
print(ans + len(divisor(N-1))-1)