Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
n=int(input())
orgn=n
m=n-1
orgm=m
ncounter=1
mcounter=1
for i in range(2,int(m**0.5)+1):
	if m % i == 0:
		tmpc=1
		m //= i
		while m % i ==0:
			tmpc += 1
			m //= i
		mcounter *= tmpc + 1

if m == orgm and m != 1:
	mcounter += 1
elif m > int(orgm**0.5):
	mcounter *= 2
mcounter -= 1


for i in range(2,int(n**0.5)+1):
	if orgn % i == 0:
		n = orgn // i
		while n % i ==0:
			n //= i
		if n % i == 1:
			ncounter += 1

print(ncounter+mcounter)

