Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
def divisors(n):
  ret=[]
  for i in range(1,int(n**0.5)+1):
    if n%i==0:
      ret.append(i)
      if n//i!=i:
        ret.append(n//i)
  return ret

n=int(input())
divs1=divisors(n)
divs2=divisors(n-1)
cnt=len(divs2)-1
for val in divs1:
  if val==1:
    continue
  tmp=n
  while tmp%val==0:
    tmp=tmp//val
  if tmp%val==1:
    cnt+=1
print(cnt)