Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
n=int(input())
ans=0
nmcc=0
i=1
d=[]
while i*i<=n:
  if n%i==0:
    d.append(i)
    if i*i!=n:
      d.append(n//i)
  i+=1
for i in d:
  if i==1:
    continue
  tmp=n
  while tmp%i==0:
    tmp//=i
  tmp%=i
  if tmp==1:
    ans+=1

i=1
while i*i<=(n-1):
  if (n-1)%i==0:
    nmcc+=1
    if i*i!=n-1:
      nmcc+=1
  i+=1
nmcc-=1
print(ans+nmcc)
  