You are given two arrays a and b, both of length n. All elements of both arrays are from 0 to n-1.

You can reorder elements of the array b (if you want, you may leave the order of elements as it is). After that, let array c be the array of length n, the i-th element of this array is c_i = (a_i + b_i) \% n, where x \% y is x modulo y.

Your task is to reorder elements of the array b to obtain the lexicographically minimum possible array c.

Array x of length n is lexicographically less than array y of length n, if there exists such i (1 ≤ i ≤ n), that x_i < y_i, and for any j (1 ≤ j < i) x_j = y_j.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of elements in a, b and c.

The second line of the input contains n integers a_1, a_2, ..., a_n (0 ≤ a_i < n), where a_i is the i-th element of a.

The third line of the input contains n integers b_1, b_2, ..., b_n (0 ≤ b_i < n), where b_i is the i-th element of b.

Output

Print the lexicographically minimum possible array c. Recall that your task is to reorder elements of the array b and obtain the lexicographically minimum possible array c, where the i-th element of c is c_i = (a_i + b_i) \% n.

Examples

Input


4
0 1 2 1
3 2 1 1


Output


1 0 0 2 


Input


7
2 5 1 5 3 4 3
2 4 3 5 6 5 1


Output


0 0 0 1 0 2 4 
import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.util.TreeMap;
import java.util.Scanner;

/**
 * Built using CHelper plug-in
 * Actual solution is at the top
 */
public class Main {
    public static void main(String[] args) {
        InputStream inputStream = System.in;
        OutputStream outputStream = System.out;
        Scanner in = new Scanner(inputStream);
        PrintWriter out = new PrintWriter(outputStream);
        TaskE solver = new TaskE();
        solver.solve(1, in, out);
        out.close();
    }

    static class TaskE {
        public void solve(int testNumber, Scanner in, PrintWriter out) {
            int n = in.nextInt();
            int a[] = new int[n];
            TreeMap<Integer, Integer> set = new TreeMap<>();

            for (int i = 0; i < n; ++i)
                a[i] = in.nextInt();
            for (int i = 0; i < n; ++i) {
                int x = (in.nextInt());
                Integer temp = set.get(x);
                if (temp == null) {
                    set.put(x, 1);
                } else set.put(x, 1 + temp);
            }

            for (int i = 0; i < a.length; i++) {
                int x = a[i];
                int comp = n - x;
                Integer want = set.higherKey(comp - 1);
                if (want == null) {
                    want = set.firstKey();
                }
                Integer temp = set.get(want);
                if (temp == 1) {
                    set.remove(want);
                } else set.put(want, temp - 1);

                out.printf("%d", (want + x) % n);
                if (i != a.length - 1)
                    out.print(" ");
            }
        }

    }
}

