Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
N = int(input())


def make_divisors(n):
    for i in range(1, int(n ** 0.5) + 1):
        if n % i == 0:
            yield i
            if i != n // i:
                yield n // i


ans = len(tuple(make_divisors(N - 1))) - 1

it = make_divisors(N)
next(it)

for k in it:
    tmp = N
    while not tmp % k:
        tmp //= k
    if tmp % k == 1:
        ans += 1
print(ans)
