The Little Elephant enjoys recursive functions.

This time he enjoys the sorting function. Let a is a permutation of an integers from 1 to n, inclusive, and ai denotes the i-th element of the permutation. The Little Elephant's recursive function f(x), that sorts the first x permutation's elements, works as follows:

  * If x = 1, exit the function. 
  * Otherwise, call f(x - 1), and then make swap(ax - 1, ax) (swap the x-th and (x - 1)-th elements of a). 



The Little Elephant's teacher believes that this function does not work correctly. But that-be do not get an F, the Little Elephant wants to show the performance of its function. Help him, find a permutation of numbers from 1 to n, such that after performing the Little Elephant's function (that is call f(n)), the permutation will be sorted in ascending order.

Input

A single line contains integer n (1 ≤ n ≤ 1000) — the size of permutation.

Output

In a single line print n distinct integers from 1 to n — the required permutation. Numbers in a line should be separated by spaces.

It is guaranteed that the answer exists.

Examples

Input

1


Output

1 

Input

2


Output

2 1 
import java.io.*;
import java.math.BigInteger;
import java.util.*;

public class Main {
	public static void main(String[] args) throws IOException {
		(new Main()).solve();
	}

	public Main() {
	}
	
	MyReader in = new MyReader();
	PrintWriter out = new PrintWriter(System.out);
	
	void solve() throws IOException {
		//BufferedReader in = new BufferedReader(new
		//InputStreamReader(System.in));
		//Scanner in = new Scanner(System.in);
		int n = in.nextInt();
		out.print(n + " ");
		if (n > 1) {
			out.print("1 ");
			for (int i = 2; i < n; i++) {
				out.print(i + " ");
			}
		}
		
		out.close(); 
		
	}
	
	class MyReader {
		private BufferedReader in;
		String[] parsed;
		int index = 0;

		public MyReader() {
			in = new BufferedReader(new InputStreamReader(System.in));
		}

		public int nextInt() throws NumberFormatException, IOException {
			if (parsed == null || parsed.length == index) {
				read();
			}
			return Integer.parseInt(parsed[index++]);
		}

		public long nextLong() throws NumberFormatException, IOException {
			if (parsed == null || parsed.length == index) {
				read();
			}
			return Long.parseLong(parsed[index++]);
		}
		
		public double nextDouble() throws NumberFormatException, IOException {
			if (parsed == null || parsed.length == index) {
				read();
			}
			return Double.parseDouble(parsed[index++]);
		}
		
		public String nextString() throws IOException {
			if (parsed == null || parsed.length == index) {
				read();
			}
			return parsed[index++];
		}

		private void read() throws IOException {
			parsed = in.readLine().split(" ");
			index = 0;
		}

		public String readLine() throws IOException {
			return in.readLine();
		}
	};	

};

