Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
N=int(input())
if N==2:
    print(1)
    exit()

ans=0
def f(x):
    out=set()
    for i in range(1, int(x**(1/2))+1):
        if x%i==0:
            out.add(i)
            out.add(x//i)
    out=list(out)
    out.sort()
    return out[1:]

tmp=f(N)
for K in tmp:
    x=N
    while x>=K:
        if x%K==0:
            x=x//K
        else:
            x=x%K
            
    if x==1:
        ans+=1
        
tmp=f(N-1)
ans+=len(tmp)
print(ans)