For a dictionary $M$ that stores elements formed by a pair of a string key and an integer value, perform a sequence of the following operations. Note that each key in $M$ must be unique.

* insert($key$, $x$): Insert an element formed by a pair of $key$ and $x$ to $M$.
* get($key$): Print the value with the specified $key$. Print 0 if there is no such element.
* delete($key$): Delete the element with the specified $key$.

Constraints

* $1 \leq q \leq 200,000$
* $1 \leq x \leq 1,000,000,000$
* $1 \leq $ length of $key$ $ \leq 20$
* $key$ consits of lower case letters

Input

The input is given in the following format.


$q$
$query_1$
$query_2$
:
$query_q$


Each query $query_i$ is given by


0 $key$ $x$


or


1 $key$


or


2 $key$


where the first digits 0, 1 and 2 represent insert, get and delete operations respectively.

Output

For each get operation, print an integer in a line.

Example

Input

8
0 blue 4
0 red 1
0 white 5
1 red
1 blue
2 red
1 black
1 red


Output

1
4
0
0
#include<iostream>
#include<vector>
#include<bitset>
#include<string>
#include<cmath>
#include<algorithm>
#include<stack>
#include<list>
#include<queue>
#include<map>
#include<numeric>
using namespace std;
#define rep(i,x) for(int i=0;i<x;i++)
#define re(i,x,y) for(int i=x;i<y;i++)
int INF=1e9;
const long long mod=1e9+7;
typedef long long ll;
int main(){
    map<string,int>m;
    int q;
    cin>>q;
    while(q--){
        int t,y;
        string x;
        cin>>t;
        if(t==0){
            cin>>x>>y;
            m[x]=y;
        }
        if(t==1){
            cin>>x;
            cout<<m[x]<<endl;
        }
        if(t==2){
            cin>>x;
            m.erase(x);
        }
    }
    return 0;
}
