Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
def divisors(n):
  small = []
  large = []
  i = 1
  while i * i <= n:
    if not n % i:
      small.append(i)
      large.append(n // i)
    i += 1
  if small[-1] == large[-1]:
    large.pop()
  return small + large[::-1]

n = int(input())
res = set(divisors(n - 1))
res.remove(1)

for d in divisors(n):
  if d == 1:
    continue
  now = n
  # simulation
  while not now % d:
    now //= d
  if now % d == 1:
    res.add(d)

print(len(res))