You are given a long decimal number a consisting of n digits from 1 to 9. You also have a function f that maps every digit from 1 to 9 to some (possibly the same) digit from 1 to 9.

You can perform the following operation no more than once: choose a non-empty contiguous subsegment of digits in a, and replace each digit x from this segment with f(x). For example, if a = 1337, f(1) = 1, f(3) = 5, f(7) = 3, and you choose the segment consisting of three rightmost digits, you get 1553 as the result.

What is the maximum possible number you can obtain applying this operation no more than once?

Input

The first line contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of digits in a.

The second line contains a string of n characters, denoting the number a. Each character is a decimal digit from 1 to 9.

The third line contains exactly 9 integers f(1), f(2), ..., f(9) (1 ≤ f(i) ≤ 9).

Output

Print the maximum number you can get after applying the operation described in the statement no more than once.

Examples

Input


4
1337
1 2 5 4 6 6 3 1 9


Output


1557


Input


5
11111
9 8 7 6 5 4 3 2 1


Output


99999


Input


2
33
1 1 1 1 1 1 1 1 1


Output


33
import java.io.*;
import java.util.*;
import java.lang.*;
import java.math.*;
public final  class Main  {
    public static boolean[] prime;
    public static final class FastScanner {
        BufferedReader br;
        StringTokenizer st;

        public FastScanner() {
            try {
                br = new BufferedReader(new InputStreamReader(System.in));
                st = new StringTokenizer(br.readLine());
            } catch (Exception e) {
                e.printStackTrace();
            }
        }

        public long nextLong() {
            return Long.parseLong(next());
        }

        public String next() {
            if (st.hasMoreTokens()) return st.nextToken();
            try {
                st = new StringTokenizer(br.readLine());
            } catch (Exception e) {
                e.printStackTrace();
            }
            return st.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }

        public String nextLine() {
            String line = "";
            if (st.hasMoreTokens()) line = st.nextToken();
            else try {
                return br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            while (st.hasMoreTokens()) line += " " + st.nextToken();
            return line;
        }

        public double nextDouble() {
            return Double.parseDouble(next());
        }
    }
    public static final class MF {
        public static long gcd(long a, long b) {
            long var;
            while (a % b > 0) {
                var = b;
                b = a % b;
                a = var;
            }
            return b;
        }

        public static int nod(long x) {
            int i = 0;
            while (x != 0) {
                i++;
                x = x / 10;
            }
            return i;
        }

        public static int nob(long x) {
            return (int) Math.floor(Math.log(x) / Math.log(2)) + 1;
        }

        public static int[] FastradixSort(int[] f) {
            int[] to = new int[f.length];
            {
                int[] b = new int[65537];
                for (int i = 0; i < f.length; i++) b[1 + (f[i] & 0xffff)]++;
                for (int i = 1; i <= 65536; i++) b[i] += b[i - 1];
                for (int i = 0; i < f.length; i++) to[b[f[i] & 0xffff]++] = f[i];
                int[] d = f;
                f = to;
                to = d;
            }
            {
                int[] b = new int[65537];
                for (int i = 0; i < f.length; i++) b[1 + (f[i] >>> 16)]++;
                for (int i = 1; i <= 65536; i++) b[i] += b[i - 1];
                for (int i = 0; i < f.length; i++) to[b[f[i] >>> 16]++] = f[i];
                int[] d = f;
                f = to;
                to = d;
            }
            return f;
        }

        public static void Primesieve(int n) {
            for (int i = 0; i < n; i++)
                prime[i] = true;
            for (int p = 2; p * p < n; p++) {
                if (prime[p] == true) {
                    for (int i = p * p; i < n; i += p)
                        prime[i] = false;
                }
            }
        }
    }
    public static void main(String args[]) {
        FastScanner sc = new FastScanner();
        PrintWriter pw = new PrintWriter(System.out);
        int n,t=0,i;
        n=sc.nextInt();
        String str=sc.next();
        char[] prr;
        prr=str.toCharArray();
        int[] arr=new int[10];
        for(i=1;i<10;i++)
            arr[i]=sc.nextInt();
        for(i=0;i<n;i++)
        {
            if(t==1)
            {
                if((arr[(str.charAt(i)-48)])>=(str.charAt(i)-48))
                {
                    prr[i]=(char)(arr[str.charAt(i)-48]+48);
                }
                else
                    break;
            }
            else
            {
                if(arr[(str.charAt(i)-48)]>(str.charAt(i)-48))
                {
                    prr[i]=(char)(arr[str.charAt(i)-48]+48);
                    t=1;
                }
            }
        }
        for(i=0;i<n;i++)
            pw.print(prr[i]);
        pw.flush();
        pw.close();
    }

}