Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
from math import sqrt


def f(x):
    ret = []
    for i in range(1, int(sqrt(x)) + 1):
        if x % i == 0:
            ret.append(i)
            ret.append(x // i)

    return ret


n = int(input())

ans = 1
for k in range(2, int(sqrt(n)) + 1):
    r = n
    while r % k == 0:
        r //= k

    if r % k == 1:
        ans += 1

li = f(n - 1)
for e in li:
    if e > int(sqrt(n)):
        ans += 1

print(ans)
