Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
N=int(input())
if N==2:
    print(1)
    exit()
DN={N}
k=2
while(k*k<=N):
    if N%k==0:
        DN.add(k)
        DN.add(N//k)
    k+=1
DN1={N-1}
k=2
while(k*k<=(N-1)):
    if (N-1)%k==0:
        DN1.add(k)
        DN1.add((N-1)//k)
    k+=1
DN1=len(DN1)
#print(DN)
#print(DN1)
ans=0
for K in DN:
    tmp=N
    while(tmp>=K):
        if tmp%K==0:
            tmp//=K
        else:
            tmp%=K
    if tmp==1:
        ans+=1

#print(ans)
print(DN1+ans)
