Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
N = int(input())

def check(p):
  _N = N
  while _N%p == 0:
    _N //= p
  return (_N-1)%p == 0

n = int(N**0.5) + 1
P0 = set([N])
P1 = set([N-1])
for i in range(2, n+1):
  if (N-1)%i == 0:
    P1.add(i)
    P1.add((N-1)//i)
  if N%i == 0:
    P0.add(i)
    P0.add(N//i)

P0.discard(1)
P1.discard(1)
ans = len(P1)
for p in P0:
  ans += check(p)

print(ans)