Given is a positive integer N.

We will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.

* Operation: if K divides N, replace N with N/K; otherwise, replace N with N-K.



In how many choices of K will N become 1 in the end?

Constraints

* 2 \leq N \leq 10^{12}
* N is an integer.

Input

Input is given from Standard Input in the following format:


N


Output

Print the number of choices of K in which N becomes 1 in the end.

Examples

Input

6


Output

3


Input

3141


Output

13


Input

314159265358


Output

9
def divisor(N):
    div = []
    for i in range(1, int(N ** 0.5 + 1)):
        if N % i == 0:
            div.append(i)
            if i * i != N:
                div.append(N // i)
    return sorted(div)


N = int(input())
ans = set()
div = divisor(N)
for d in div:
    p = N // d
    while d % p == 0 and p != 1:
        d = d // p
    if (d - 1) % p == 0:
        ans.add(p)
for d in divisor(N - 1):
    ans.add(d)
print(len(ans) - 1 if 1 in ans else len(ans))
