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For given three points p0, p1, p2, print


COUNTER_CLOCKWISE


if p0, p1, p2 make a counterclockwise turn (1),


CLOCKWISE


if p0, p1, p2 make a clockwise turn (2),


ONLINE_BACK


if p2 is on a line p2, p0, p1 in this order (3),


ONLINE_FRONT


if p2 is on a line p0, p1, p2 in this order (4),


ON_SEGMENT


if p2 is on a segment p0p1 (5).

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p0 and p1 are not identical.

Input


xp0 yp0 xp1 yp1
q
xp20 yp20
xp21 yp21
...
xp2q-1 yp2q-1


In the first line, integer coordinates of p0 and p1 are given. Then, q queries are given for integer coordinates of p2.

Output

For each query, print the above mentioned status.

Examples

Input

0 0 2 0
2
-1 1
-1 -1


Output

COUNTER_CLOCKWISE
CLOCKWISE


Input

0 0 2 0
3
-1 0
0 0
3 0


Output

ONLINE_BACK
ON_SEGMENT
ONLINE_FRONT
#include<bits/stdc++.h>
using namespace std;

#define ld long double
#define eps 1e-9
struct vec{
	ld x , y;
	vec(ld _x = 0 , ld _y = 0) : x(_x) , y(_y){}
	friend vec operator +(vec A , vec B){return vec(A.x + B.x , A.y + B.y);}
	friend vec operator -(vec A , vec B){return vec(A.x - B.x , A.y - B.y);}
	friend ld operator *(vec A , vec B){return A.x * B.x + A.y * B.y;}
	friend ld operator %(vec A , vec B){return A.x * B.y - A.y * B.x;}
	ld len(){return sqrt(x * x + y * y);}
};

vec getvec(){int x , y; cin >> x >> y; return vec(x , y);}

int main(){
	vec A = getvec() , B = getvec() - A; int Q;
	for(cin >> Q ; Q ; --Q){
		vec C = getvec() - A;
		if(B % C > eps) puts("COUNTER_CLOCKWISE");
		else if(B % C < -eps) puts("CLOCKWISE");
		else if(B * C < 0) puts("ONLINE_BACK");
		else puts(B.len() + eps > C.len() ? "ON_SEGMENT" : "ONLINE_FRONT");
	}
	return 0;
}

