In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)

To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.

What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?

Assume that you have sufficient numbers of banknotes, and so does the clerk.

Constraints

* N is an integer between 1 and 10^{1,000,000} (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the minimum possible number of total banknotes used by you and the clerk.

Examples

Input

36


Output

8


Input

91


Output

3


Input

314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170


Output

243
import java.io.*;
import java.util.Arrays;
import java.util.StringTokenizer;

public class Main {

    private static FastReader in = new FastReader(System.in);
    private static PrintWriter out = new PrintWriter(System.out);

    private static final long MOD = (long) 1e9 + 7;

    public static void main(String[] args) {
        solve();
        out.flush();
    }

    private static void solve() {
        solveForN(in.next());
    }

    private static void solveForN(String n) {
        String s = "0" + n;
        char[] ch = s.toCharArray();
        int[] a = new int[ch.length];
        for (int i = 0; i < ch.length; i++) {
            a[i] = ch[i] - '0';
        }

        int ans = 0;
        // 下から見るんかーい
        for (int i = a.length - 1; i > 0; i--) {
            if (a[i] == 5 && a[i - 1] >= 5) {
                a[i - 1]++;
                a[i] -= 10;
            } else if (a[i] > 5) {
                a[i - 1]++;
                a[i] -= 10;
            }
            ans += Math.abs(a[i]);
        }
        ans += Math.abs(a[0]);

        // out.println(Arrays.toString(a));

        out.println(ans);
    }

    // https://www.geeksforgeeks.org/fast-io-in-java-in-competitive-programming/
    static class FastReader {
        BufferedReader br;
        StringTokenizer st;

        FastReader(InputStream inputStream) {
            br = new BufferedReader(new
                    InputStreamReader(inputStream));
        }

        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException  e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }

        int nextInt() {
            return Integer.parseInt(next());
        }

        long nextLong() {
            return Long.parseLong(next());
        }

        double nextDouble() {
            return Double.parseDouble(next());
        }

        String nextLine() {
            String str = "";
            try {
                str = br.readLine();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return str;
        }

        // https://qiita.com/masakinpo/items/5f77f2a879578a85a0bb
        public int[] nextIntArray(int n) {
            int[] a = new int[n];
            for (int i = 0; i < n; i++)
                a[i] = nextInt();
            return a;
        }

        public long[] nextLongArray(int n) {
            long[] a = new long[n];
            for (int i = 0; i < n; i++)
                a[i] = nextLong();
            return a;
        }
    }
}
