<image>

For given three points p0, p1, p2, print


COUNTER_CLOCKWISE


if p0, p1, p2 make a counterclockwise turn (1),


CLOCKWISE


if p0, p1, p2 make a clockwise turn (2),


ONLINE_BACK


if p2 is on a line p2, p0, p1 in this order (3),


ONLINE_FRONT


if p2 is on a line p0, p1, p2 in this order (4),


ON_SEGMENT


if p2 is on a segment p0p1 (5).

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p0 and p1 are not identical.

Input


xp0 yp0 xp1 yp1
q
xp20 yp20
xp21 yp21
...
xp2q-1 yp2q-1


In the first line, integer coordinates of p0 and p1 are given. Then, q queries are given for integer coordinates of p2.

Output

For each query, print the above mentioned status.

Examples

Input

0 0 2 0
2
-1 1
-1 -1


Output

COUNTER_CLOCKWISE
CLOCKWISE


Input

0 0 2 0
3
-1 0
0 0
3 0


Output

ONLINE_BACK
ON_SEGMENT
ONLINE_FRONT
#include<bits/stdc++.h>
using namespace std;
typedef struct { double x,y;} point;

double nai(point a,point b){ return a.x*b.x+a.y*b.y; }

int main(){
point p1,p2;
double x,y;
cin>>x>>y;
p1.x=x;
p1.y=y;
cin>>x>>y;
p2.x=x;
p2.y=y;
point vec={p2.x-p1.x , p2.y-p1.y};
//point e={vec.x/sqrt(nai(vec,vec)) , vec.y/sqrt(nai(vec,vec))};
int q;
cin>>q;
for(int i=0;i<q;i++){
cin>>x>>y;
point p;
p.x=x-p1.x;
p.y=y-p1.y;
point j={p.x*vec.x+p.y*vec.y,vec.x*p.y-vec.y*p.x};
if(j.y>0){
cout<<"COUNTER_CLOCKWISE"<<endl;
}else if(j.y<0){
cout<<"CLOCKWISE"<<endl;
}else{
if(j.x<0){
cout<<"ONLINE_BACK"<<endl;
}else if(nai(p,p)>nai(vec,vec)){
cout<<"ONLINE_FRONT"<<endl;
}else{
cout<<"ON_SEGMENT"<<endl;
}

}


}
return 0;
}

