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For given three points p0, p1, p2, print


COUNTER_CLOCKWISE


if p0, p1, p2 make a counterclockwise turn (1),


CLOCKWISE


if p0, p1, p2 make a clockwise turn (2),


ONLINE_BACK


if p2 is on a line p2, p0, p1 in this order (3),


ONLINE_FRONT


if p2 is on a line p0, p1, p2 in this order (4),


ON_SEGMENT


if p2 is on a segment p0p1 (5).

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p0 and p1 are not identical.

Input


xp0 yp0 xp1 yp1
q
xp20 yp20
xp21 yp21
...
xp2q-1 yp2q-1


In the first line, integer coordinates of p0 and p1 are given. Then, q queries are given for integer coordinates of p2.

Output

For each query, print the above mentioned status.

Examples

Input

0 0 2 0
2
-1 1
-1 -1


Output

COUNTER_CLOCKWISE
CLOCKWISE


Input

0 0 2 0
3
-1 0
0 0
3 0


Output

ONLINE_BACK
ON_SEGMENT
ONLINE_FRONT
xp0, yp0, xp1, yp1 = map(int, input().split())
q = int(input())

xp1 = complex(xp1 - xp0, yp1 - yp0)
eps = 1e-8

for _ in range(q):
    x, y = map(int, input().split())
    xp2 = complex(x - xp0, y - yp0)

    temp = xp1.conjugate() * xp2
    dot = temp.real
    cross = temp.imag
    if abs(cross) < eps:
        if dot == 0:
            print("ON_SEGMENT")
        elif dot > 0:
            if abs(xp1) >= abs(xp2):
                print("ON_SEGMENT")
            else:
                print("ONLINE_FRONT")
        else:
            print("ONLINE_BACK")
    elif cross > 0:
        print("COUNTER_CLOCKWISE")
    else:
        print("CLOCKWISE")

