For given three integers $a, b, c$, print the minimum value and the maximum value.

Constraints

* $-1,000,000,000 \leq a, b, c \leq 1,000,000,000$

Input

The input is given in the following format.


$a \; b \; c\;$


Three integers $a, b, c$ are given in a line.

Output

Print the minimum and maximum values separated by a space in a line.

Example

Input

4 5 3


Output

3 5
#include <bits/stdc++.h>

using namespace std;
#define rep_i(i, n) for (int i = 0; i < (n); ++i)
#define rep_ll(i, n) for (long long i = 0; i < (n); ++i)
#define r_rep_i(i, start, end) for (int i = (start); i < (end); ++i)
#define r_rep_ll(i, start, end) for (long long i = (start); i < (end); ++i)
#define debug_vi(v) copy((v).begin(), (v).end(), ostream_iterator<int>(cout, " "));
#define debug_vll(v) copy((v).begin(), (v).end(), ostream_iterator<long long>(cout, " "));
#define debug_vd(v) copy((v).begin(), (v).end(), ostream_iterator<double>(cout, " "));
#define sort_v(v) sort((v).begin(), (v).end()); //昇順
#define d_sort_vi(v) sort((v).begin(), (v).end(), greater<int>()); //降
#define d_sort_vd(v) sort((v).begin(), (v).end(), greater<double>()); //昇順
#define say(t) cout << (t) << endl;
#define sum_vi(v) accumulate((v).begin(), (v).end(), 0);
#define sum_vll(v)accumulate((v).begin(), (v).end(), 0LL);

int main(){
  int a, b, c;cin >> a >> b >> c;
  cout << min(min(a, b), c) << " " << max(max(a, b), c) << endl;
}
