<image>

For given three points p0, p1, p2, print


COUNTER_CLOCKWISE


if p0, p1, p2 make a counterclockwise turn (1),


CLOCKWISE


if p0, p1, p2 make a clockwise turn (2),


ONLINE_BACK


if p2 is on a line p2, p0, p1 in this order (3),


ONLINE_FRONT


if p2 is on a line p0, p1, p2 in this order (4),


ON_SEGMENT


if p2 is on a segment p0p1 (5).

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p0 and p1 are not identical.

Input


xp0 yp0 xp1 yp1
q
xp20 yp20
xp21 yp21
...
xp2q-1 yp2q-1


In the first line, integer coordinates of p0 and p1 are given. Then, q queries are given for integer coordinates of p2.

Output

For each query, print the above mentioned status.

Examples

Input

0 0 2 0
2
-1 1
-1 -1


Output

COUNTER_CLOCKWISE
CLOCKWISE


Input

0 0 2 0
3
-1 0
0 0
3 0


Output

ONLINE_BACK
ON_SEGMENT
ONLINE_FRONT
#include<iostream>
#include<cstdio>
#include<string>
#include<algorithm>
#include<cmath>
#include<vector>
#include<stack>
#include<climits>
#include<cstring>
#include<queue>
#include<complex>
using namespace std;

const double EPS = 1e-8;
const double INF = 1e12;

typedef complex<double> P;

double cross(const P &a, const P &b){
    return imag(conj(a)*b);
}

double dot(const P &a, const P &b){
    return real(conj(a)*b);
}

int ccw(P a, P b, P c){
    b -= a;
    c -= a;
    if(cross(b,c) > 0) return +1;
    if(cross(b,c) < 0) return -1;
    if(dot(b,c) < 0) return +2;
    if(norm(b) < norm(c)) return -2;
    return 0;
}

struct L : public vector<P> {
  L(const P &a, const P &b) {
    push_back(a); push_back(b);
  }
};

bool intersectLL(const L &l, const L &m){
    return abs(cross(l[1]-l[0], m[1]-m[0])) > EPS ||
    abs(cross(l[1]-m[0], m[1]-m[0])) < EPS;
}

bool intersectLS(const L &l, const L &s) {
  return cross(l[1]-l[0], s[0]-l[0])*       // s[0] is left of l
         cross(l[1]-l[0], s[1]-l[0]) < EPS; // s[1] is right of l
}
bool intersectLP(const L &l, const P &p) {
  return abs(cross(l[1]-p, l[0]-p)) < EPS;
}
bool intersectSS(const L &s, const L &t) {
  return ccw(s[0],s[1],t[0])*ccw(s[0],s[1],t[1]) <= 0 &&
         ccw(t[0],t[1],s[0])*ccw(t[0],t[1],s[1]) <= 0;
}
bool intersectSP(const L &s, const P &p) {
  return abs(s[0]-p)+abs(s[1]-p)-abs(s[1]-s[0]) < EPS; // triangle inequality
}

int main(){
  int q;
  double x0,y0,x1,y1, x2, y2;
  cin >> x0 >> y0 >> x1 >> y1 >> q;
  P p0(x0, y0), p1(x1, y1);

  for (int i=0;i<q;i++){
    cin >> x2 >> y2;
    P p2(x2, y2);
    int res = ccw(p0, p1, p2);
    if(res == 1) cout << "COUNTER_CLOCKWISE" << endl;
    if(res == -1) cout << "CLOCKWISE" << endl;
    if(res == 2) cout << "ONLINE_BACK" << endl;
    if(res == -2) cout << "ONLINE_FRONT"<< endl;
    if(res == 0) cout << "ON_SEGMENT" << endl;
  }
  return 0;
}