Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.

Petya loves long lucky numbers very much. He is interested in the minimum lucky number d that meets some condition. Let cnt(x) be the number of occurrences of number x in number d as a substring. For example, if d = 747747, then cnt(4) = 2, cnt(7) = 4, cnt(47) = 2, cnt(74) = 2. Petya wants the following condition to fulfil simultaneously: cnt(4) = a1, cnt(7) = a2, cnt(47) = a3, cnt(74) = a4. Petya is not interested in the occurrences of other numbers. Help him cope with this task.

Input

The single line contains four integers a1, a2, a3 and a4 (1 ≤ a1, a2, a3, a4 ≤ 106).

Output

On the single line print without leading zeroes the answer to the problem — the minimum lucky number d such, that cnt(4) = a1, cnt(7) = a2, cnt(47) = a3, cnt(74) = a4. If such number does not exist, print the single number "-1" (without the quotes).

Examples

Input

2 2 1 1


Output

4774


Input

4 7 3 1


Output

-1
#include <bits/stdc++.h>
using namespace std;
int a, b, c, d;
int main() {
  while (scanf("%d%d%d%d", &a, &b, &c, &d) != EOF) {
    if (abs(c - d) > 1) {
      puts("-1");
      continue;
    }
    if (c == d) {
      int a1 = a - (c + 1);
      int b1 = b - c;
      if (a1 >= 0 && b1 >= 0) {
        for (int i = 1; i <= a1; i++) printf("4");
        for (int i = 1; i <= c; i++) printf("47");
        for (int i = 1; i <= b1; i++) printf("7");
        printf("4");
        puts("");
        continue;
      }
      a1 = a - c;
      b1 = b - c;
      if (a1 < 0 || b1 < 1)
        puts("-1");
      else {
        printf("74");
        for (int i = 1; i <= a1; i++) printf("4");
        for (int i = 1; i < c; i++) printf("74");
        for (int i = 1; i <= b1; i++) printf("7");
        puts("");
      }
    } else if (c > d) {
      int a1 = a - c;
      int b1 = b - c;
      if (a1 < 0 || b1 < 0)
        puts("-1");
      else {
        for (int i = 1; i <= a1; i++) printf("4");
        for (int i = 1; i <= c; i++) printf("47");
        for (int i = 1; i <= b1; i++) printf("7");
      }
    } else if (d > c) {
      int a1 = a - d;
      int b1 = b - d;
      if (a1 < 0 || b1 < 0)
        puts("-1");
      else {
        printf("74");
        for (int i = 1; i <= a1; i++) printf("4");
        for (int i = 1; i <= d - 2; i++) printf("74");
        for (int i = 1; i <= b1; i++) printf("7");
        printf("74");
      }
    }
  }
}
