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For given three points p0, p1, p2, print


COUNTER_CLOCKWISE


if p0, p1, p2 make a counterclockwise turn (1),


CLOCKWISE


if p0, p1, p2 make a clockwise turn (2),


ONLINE_BACK


if p2 is on a line p2, p0, p1 in this order (3),


ONLINE_FRONT


if p2 is on a line p0, p1, p2 in this order (4),


ON_SEGMENT


if p2 is on a segment p0p1 (5).

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p0 and p1 are not identical.

Input


xp0 yp0 xp1 yp1
q
xp20 yp20
xp21 yp21
...
xp2q-1 yp2q-1


In the first line, integer coordinates of p0 and p1 are given. Then, q queries are given for integer coordinates of p2.

Output

For each query, print the above mentioned status.

Examples

Input

0 0 2 0
2
-1 1
-1 -1


Output

COUNTER_CLOCKWISE
CLOCKWISE


Input

0 0 2 0
3
-1 0
0 0
3 0


Output

ONLINE_BACK
ON_SEGMENT
ONLINE_FRONT
#include <iostream>
#include <cmath>

using namespace std;

typedef long scalar;
class point{
	public:
	scalar x;
	scalar y;
	void print(){
		cout << x << " " << y; 
	}
	scalar cross(point a){//??????
		return x * a.y - y * a.x;
	}
	scalar dot(point a){//??????
		return x * a.x + y * a.y;
	}
	scalar norm2(void){
		return x * x + y * y;
	}
	scalar norm(void){
		return sqrt(norm2());
	}
	point operator =(point a){
		this->x = a.x;
		this->y = a.y;
		return *this;
	}
	point operator +(point a){
		point r;
		r.x = this->x + a.x;
		r.y = this->y + a.y;
		return r;
	}
	point operator -(point a){
		point r;
		r.x = this->x - a.x;
		r.y = this->y - a.y;
		return r;
	}
};

point operator *(scalar t, point a){
	point r;
	r.x = t * a.x; 
	r.y = t * a.y; 
	return r;
}


int main(){
	point p0, p1, p2;
	point p01,p02;
	int q;
	scalar crossproduct,innerproduct;
	cout.precision(20);
	cin >> p0.x >> p0.y >> p1.x >> p1.y;
	cin >> q;
	for(int i = 0;i < q;i++){
		cin >> p2.x >> p2.y;
		p01 = p1-p0;
		p02 = p2-p0;
		crossproduct = p01.cross(p02);
		innerproduct = p01.dot(p02);
		if(crossproduct > 0)
			cout << "COUNTER_CLOCKWISE" << endl;
		else if(crossproduct < 0)
			cout << "CLOCKWISE" << endl;
		else if(innerproduct < 0)
			cout << "ONLINE_BACK" << endl;
		else if(p02.norm2() > p01.norm2())
			cout << "ONLINE_FRONT" << endl;
		else 
			cout << "ON_SEGMENT" << endl;
	}
	return 0;
}