You have an array a of length n. For every positive integer x you are going to perform the following operation during the x-th second:

  * Select some distinct indices i_{1}, i_{2}, …, i_{k} which are between 1 and n inclusive, and add 2^{x-1} to each corresponding position of a. Formally, a_{i_{j}} := a_{i_{j}} + 2^{x-1} for j = 1, 2, …, k. Note that you are allowed to not select any indices at all.



You have to make a nondecreasing as fast as possible. Find the smallest number T such that you can make the array nondecreasing after at most T seconds.

Array a is nondecreasing if and only if a_{1} ≤ a_{2} ≤ … ≤ a_{n}.

You have to answer t independent test cases.

Input

The first line contains a single integer t (1 ≤ t ≤ 10^{4}) — the number of test cases.

The first line of each test case contains single integer n (1 ≤ n ≤ 10^{5}) — the length of array a. It is guaranteed that the sum of values of n over all test cases in the input does not exceed 10^{5}.

The second line of each test case contains n integers a_{1}, a_{2}, …, a_{n} (-10^{9} ≤ a_{i} ≤ 10^{9}).

Output

For each test case, print the minimum number of seconds in which you can make a nondecreasing.

Example

Input


3
4
1 7 6 5
5
1 2 3 4 5
2
0 -4


Output


2
0
3

Note

In the first test case, if you select indices 3, 4 at the 1-st second and 4 at the 2-nd second, then a will become [1, 7, 7, 8]. There are some other possible ways to make a nondecreasing in 2 seconds, but you can't do it faster.

In the second test case, a is already nondecreasing, so answer is 0.

In the third test case, if you do nothing at first 2 seconds and select index 2 at the 3-rd second, a will become [0, 0].
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Comparator;

public class d {
    static BufferedReader s = new BufferedReader(new InputStreamReader(System.in));
    public static void main(String[] args) throws IOException {
        StringBuilder sb = new StringBuilder();
       String[] ss=s();
       int t=i(ss[0]);
       while(t-->0){
           String[] st=s();
           int n=i(st[0]);
           long[] a=new long[n];
           String[] ss1=s();
           for(int i=0;i<n;i++){
               a[i]=i(ss1[i]);
           }
           long x=0;long max=a[0];
           for(int i=1;i<n;i++){
               if(a[i]<max){
                    long k=(long)(Math.log(max-a[i]+1)/Math.log(2));
                    if(a[i]+Math.pow(2,k)-1<max){
                        k++;
                      //  System.out.println('h');
                    }
                   // a[i]+=Math.pow(2,k);
               //    System.out.println(k);
                    x=Math.max(x,k);

               }
               max=Math.max(a[i],max);
           }

           sb.append((x)+"\n");

       }
        System.out.println(sb.toString());

    }
    static String[] s() throws IOException {
        return s.readLine().trim().split("\\s+");
    }

    static int i(String ss) {
        return Integer.parseInt(ss);
    }

    static long l(String ss) {
        return Long.parseLong(ss);
    }


    static int MAXN;
    static int[] spf;
    static void sieve() {
        spf[1] = 1;
        for (int i=2; i<MAXN; i++)
            spf[i] = i;
        for (int i=4; i<MAXN; i+=2)
            spf[i] = 2;
        for (int i=3; i*i<MAXN; i++)
        {
            if (spf[i] == i)
            {
                for (int j=i*i; j<MAXN; j+=i)

                    if (spf[j]==j)
                        spf[j] = i;
            }
        }
    }
    static long powerwithmod(long  x, long y, long p) {
        long  res = 1;
        x = x % p;
        while (y > 0) {
            if ((y & 1) == 1)
                res = (res * x) % p;
            y = y >> 1;
            x = (x * x) % p;
        }
        return res;
    }static long[] fac ;
    static void calculatefac(long mod){
        fac[0]=1;
        for (int i = 1 ;i <= MAXN; i++)
            fac[i] = fac[i-1] * i % mod;
    }
    static long nCrModPFermat(int n, int r, long mod) {
        if (r == 0)
            return 1;
        fac[0] = 1;
        return (fac[n]*
                modInverse(fac[r], mod)
                % mod * modInverse(fac[n-r], mod)
                % mod) % mod;
    }static long modInverse(long a, long m)
    {
        return (powerwithmod(a, m - 2, m));
    }





}

class Student12 {
    int  l;long r;
    public Student12(int l, long r) {
        this.l = l;
        this.r = r;
    }

    public String toString()
    {
        return this.l+" ";
    }
}
class Sortbyroll12 implements Comparator<Student12> {

    public int compare(Student12 a, Student12 b){
        if(a.l<=b.r) return -1;
     /*   else if(a.r==b.r){
            if(a.r==b.r){
                return 0;
            }
            if(a.r<b.r) return -1;
            return 1;}*/
        return 1;  }
}