AquaMoon has n friends. They stand in a row from left to right, and the i-th friend from the left wears a T-shirt with a number a_i written on it. Each friend has a direction (left or right). In the beginning, the direction of each friend is right.

AquaMoon can make some operations on friends. On each operation, AquaMoon can choose two adjacent friends and swap their positions. After each operation, the direction of both chosen friends will also be flipped: left to right and vice versa.

AquaMoon hopes that after some operations, the numbers written on the T-shirt of n friends in the row, read from left to right, become non-decreasing. Also she wants, that all friends will have a direction of right at the end. Please find if it is possible.

Input

The input consists of multiple test cases. The first line contains a single integer t (1 ≤ t ≤ 50) — the number of test cases.

The first line of each test case contains a single integer n (1 ≤ n ≤ 10^5) — the number of Aquamoon's friends.

The second line contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 10^5) — the numbers, written on the T-shirts.

It is guaranteed that the sum of n for all test cases does not exceed 10^5.

Output

For each test case, if there exists a possible sequence of operations, print "YES" (without quotes); otherwise, print "NO" (without quotes).

You can print each letter in any case (upper or lower).

Example

Input


3
4
4 3 2 5
4
3 3 2 2
5
1 2 3 5 4


Output


YES
YES
NO

Note

The possible list of operations in the first test case:

  1. Swap a_1 and a_2. The resulting sequence is 3, 4, 2, 5. The directions are: left, left, right, right. 
  2. Swap a_2 and a_3. The resulting sequence is 3, 2, 4, 5. The directions are: left, left, right, right. 
  3. Swap a_1 and a_2. The resulting sequence is 2, 3, 4, 5. The directions are: right, right, right, right. 
import sys
input = lambda: sys.stdin.readline().rstrip("\r\n")
for _ in range(int(input())):
    n=int(input())
    arr=[int(x) for x in input().split()]
    temp=sorted(arr)
    d={}
    for i in range(n):
        if arr[i] not in d:
            d[arr[i]]=[0,0]
            d[arr[i]][0],d[arr[i]][1]=0,0
        d[arr[i]][i%2]+=1
    f=True
    for i in range(n):
        if d[temp[i]][i%2]>0:
            d[temp[i]][i%2]-=1
        else:
            f=False
    if f:
        print('YES')
    else:
        print('NO')