<image>

For given three points p0, p1, p2, print


COUNTER_CLOCKWISE


if p0, p1, p2 make a counterclockwise turn (1),


CLOCKWISE


if p0, p1, p2 make a clockwise turn (2),


ONLINE_BACK


if p2 is on a line p2, p0, p1 in this order (3),


ONLINE_FRONT


if p2 is on a line p0, p1, p2 in this order (4),


ON_SEGMENT


if p2 is on a segment p0p1 (5).

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p0 and p1 are not identical.

Input


xp0 yp0 xp1 yp1
q
xp20 yp20
xp21 yp21
...
xp2q-1 yp2q-1


In the first line, integer coordinates of p0 and p1 are given. Then, q queries are given for integer coordinates of p2.

Output

For each query, print the above mentioned status.

Examples

Input

0 0 2 0
2
-1 1
-1 -1


Output

COUNTER_CLOCKWISE
CLOCKWISE


Input

0 0 2 0
3
-1 0
0 0
3 0


Output

ONLINE_BACK
ON_SEGMENT
ONLINE_FRONT
#include <bits/stdc++.h>
using namespace std;

using ld = long double;
const ld eps = 1e-8, pi = acos(-1.0);

bool eq(ld a, ld b) {
	return abs(a - b) < eps;
}

using Point = complex<ld>;

class Line {
public:
	Point a, b;
};

ld dot(Point a, Point b) {
	return real(conj(a) * b);
}

ld cross(Point a, Point b) {
	return imag(conj(a) * b);
}

int ccw(Point a, Point b, Point c) {
	b -= a, c -= a;
	if (cross(b, c) > eps) return 1;
	if (cross(b, c) < -eps) return -1;
	if (dot(b, c) < 0) return 2;
	if (norm(b) < norm(c)) return -2;
	return 0;
}

int main()
{
	int q;
	ld p1x, p1y, p2x, p2y, x, y;
	cout << fixed << setprecision(9);
	cin >> p1x >> p1y >> p2x >> p2y;
	Point a(p1x, p1y), b(p2x, p2y);
	cin >> q;
	while (q--) {
		cin >> x >> y;
		Point c(x, y);
		switch (ccw(a, b, c))
		{
		case 1:
			cout << "COUNTER_CLOCKWISE" << endl;
			break;
		case -1:
			cout << "CLOCKWISE" << endl;
			break;
		case 2:
			cout << "ONLINE_BACK" << endl;
			break;
		case -2:
			cout << "ONLINE_FRONT" << endl;
			break;
		case 0:
			cout << "ON_SEGMENT" << endl;
			break;
		}
	}
	return 0;
}