You have an array a of length n. For every positive integer x you are going to perform the following operation during the x-th second:

  * Select some distinct indices i_{1}, i_{2}, …, i_{k} which are between 1 and n inclusive, and add 2^{x-1} to each corresponding position of a. Formally, a_{i_{j}} := a_{i_{j}} + 2^{x-1} for j = 1, 2, …, k. Note that you are allowed to not select any indices at all.



You have to make a nondecreasing as fast as possible. Find the smallest number T such that you can make the array nondecreasing after at most T seconds.

Array a is nondecreasing if and only if a_{1} ≤ a_{2} ≤ … ≤ a_{n}.

You have to answer t independent test cases.

Input

The first line contains a single integer t (1 ≤ t ≤ 10^{4}) — the number of test cases.

The first line of each test case contains single integer n (1 ≤ n ≤ 10^{5}) — the length of array a. It is guaranteed that the sum of values of n over all test cases in the input does not exceed 10^{5}.

The second line of each test case contains n integers a_{1}, a_{2}, …, a_{n} (-10^{9} ≤ a_{i} ≤ 10^{9}).

Output

For each test case, print the minimum number of seconds in which you can make a nondecreasing.

Example

Input


3
4
1 7 6 5
5
1 2 3 4 5
2
0 -4


Output


2
0
3

Note

In the first test case, if you select indices 3, 4 at the 1-st second and 4 at the 2-nd second, then a will become [1, 7, 7, 8]. There are some other possible ways to make a nondecreasing in 2 seconds, but you can't do it faster.

In the second test case, a is already nondecreasing, so answer is 0.

In the third test case, if you do nothing at first 2 seconds and select index 2 at the 3-rd second, a will become [0, 0].
import java.io.*;
import java.util.*;

public class C633_C {

	public static void main(String[] args) throws IOException{
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out));
		StringTokenizer st;
		
		int T = Integer.parseInt(br.readLine());
		for(int t = 0; t<T; t++) {
			int n = Integer.parseInt(br.readLine());
			int[] arr = new int[n];
			st = new StringTokenizer(br.readLine());
			for(int i = 0; i<n; i++) {
				arr[i] = Integer.parseInt(st.nextToken());
			}
			long max = 0;
			long before = 0;
			for(int i = 1; i<=n-1; i++) {
				long diff = arr[i] - arr[i-1]-before;
				if(diff <0) {
					before = -diff;
					max = Math.max(max, -diff);
				}
				else {
					before = 0;
				}
				
			}
			
			int x = 0;
			
			while(max >0) {
				max /= 2;
				x ++;
			}
			bw.write(x+"\n");

		}

		bw.flush();
		br.close();
		bw.close();
	}
}


