<image>

For given three points p0, p1, p2, print


COUNTER_CLOCKWISE


if p0, p1, p2 make a counterclockwise turn (1),


CLOCKWISE


if p0, p1, p2 make a clockwise turn (2),


ONLINE_BACK


if p2 is on a line p2, p0, p1 in this order (3),


ONLINE_FRONT


if p2 is on a line p0, p1, p2 in this order (4),


ON_SEGMENT


if p2 is on a segment p0p1 (5).

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p0 and p1 are not identical.

Input


xp0 yp0 xp1 yp1
q
xp20 yp20
xp21 yp21
...
xp2q-1 yp2q-1


In the first line, integer coordinates of p0 and p1 are given. Then, q queries are given for integer coordinates of p2.

Output

For each query, print the above mentioned status.

Examples

Input

0 0 2 0
2
-1 1
-1 -1


Output

COUNTER_CLOCKWISE
CLOCKWISE


Input

0 0 2 0
3
-1 0
0 0
3 0


Output

ONLINE_BACK
ON_SEGMENT
ONLINE_FRONT
#include<bits/stdc++.h>
using namespace std;
typedef complex<double> P;
#define x real()
#define y imag()

string ccw(P a,P b,P c){
  P ab=b-a,ac=c-a;
  P k=ac*conj(ab);
  if(k.y>0)return "COUNTER_CLOCKWISE";
  if(k.y<0)return "CLOCKWISE";
  if(k.x<0)return "ONLINE_BACK";
  if(abs(ab)<abs(ac))return "ONLINE_FRONT";
  return "ON_SEGMENT";
}

int main(){
  double x0,y0,x1,y1,x2,y2;
  cin>>x0>>y0>>x1>>y1;
  P a(x0,y0);
  P b(x1,y1);
  int n;
  cin>>n;
  while(n--){
    cin>>x2>>y2;
    P c(x2,y2);
    cout<< ccw(a,b,c) <<endl;
  }
  return 0;
}