You are given a sequence of numbers a1, a2, ..., an, and a number m.

Check if it is possible to choose a non-empty subsequence aij such that the sum of numbers in this subsequence is divisible by m.

Input

The first line contains two numbers, n and m (1 ≤ n ≤ 106, 2 ≤ m ≤ 103) — the size of the original sequence and the number such that sum should be divisible by it.

The second line contains n integers a1, a2, ..., an (0 ≤ ai ≤ 109).

Output

In the single line print either "YES" (without the quotes) if there exists the sought subsequence, or "NO" (without the quotes), if such subsequence doesn't exist.

Examples

Input

3 5
1 2 3


Output

YES


Input

1 6
5


Output

NO


Input

4 6
3 1 1 3


Output

YES


Input

6 6
5 5 5 5 5 5


Output

YES

Note

In the first sample test you can choose numbers 2 and 3, the sum of which is divisible by 5.

In the second sample test the single non-empty subsequence of numbers is a single number 5. Number 5 is not divisible by 6, that is, the sought subsequence doesn't exist.

In the third sample test you need to choose two numbers 3 on the ends.

In the fourth sample test you can take the whole subsequence.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;


public class prb577D {
	int n;
	int m;
	int a[];
	
	void readInput() throws IOException{
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		String s = br.readLine();
		String ss[] = s.split(" ");
		n = Integer.parseInt(ss[0]);
		m = Integer.parseInt(ss[1]);
		s = br.readLine();
		ss = s.split(" ");		
		a = new int[n];
		for(int i=0; i<n; i++)
			a[i] = Integer.parseInt(ss[i]);
	}
	
	void solve(){
		int DP[][] = new int[2][m];
		for(int i=0; i<n; i++){
			int x = a[i]%m;
			DP[1][x] = 1;
			for(int j=0; j<m; j++)
				if (DP[0][j] == 1)
					DP[1][(j+x)%m] = 1;
			if (DP[1][0]==1){
				System.out.println("YES");
				return;
			}			
			for(int j=0; j<m; j++)
				DP[0][j] = DP[1][j];
		}
		
		System.out.println("NO");
	}

	public static void main(String[] args) throws IOException {		
		prb577D p = new prb577D();
		p.readInput();
		p.solve();
	}

}
