In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)

To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.

What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?

Assume that you have sufficient numbers of banknotes, and so does the clerk.

Constraints

* N is an integer between 1 and 10^{1,000,000} (inclusive).

Input

Input is given from Standard Input in the following format:


N


Output

Print the minimum possible number of total banknotes used by you and the clerk.

Examples

Input

36


Output

8


Input

91


Output

3


Input

314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170


Output

243
import java.io.PrintStream;
import java.util.Scanner;

public class Main {
	public static void main(String[] args) throws Exception{
		new Main(new Scanner(System.in), System.out, System.err).exec();
	}
	public final Scanner sc;
	public final PrintStream out, err;
	public Main(final Scanner sc, final PrintStream out, final PrintStream err) {
		this.sc = sc;this.out = out;this.err = err;
	}
	static public final long pair(int a, int b) {return (((long)a) << 32) + b;}
	static public final int getPair1(long v) {return (int)(v >> 32);}
	static public final int getPari2(long v) {return (int)(v & 0xFFFFFFFF);}

	static public final long quad(long a, long b, long c, long d) {
		return ((a&0xFFFF)<< 48) + ((b&0xFFFF)<< 32) + ((c&0xFFFF)<< 16) +(d&0xFFFF);}
	static public final int getQuad1(long v) {return (int)( v >> 48          );}
	static public final int getQuad2(long v) {return (int)((v >> 32) & 0xFFFF);}
	static public final int getQuad3(long v) {return (int)((v >> 16) & 0xFFFF);}
	static public final int getQuad4(long v) {return (int)( v        & 0xFFFF);}

	static public final long record(int e, int m, int i) {
		return quad(-1, e, m, i);
	}
	static public final int re(long record) {
		return getQuad2(record);
	}
	static public final int rm(long record) {
		return getQuad3(record);
	}
	static public final int ri(long record) {
		return getQuad4(record);
	}

	//------------------------------------------

	private int p;
	private int[] inv;
	private int[] fact;
	private int[] finv;
	public final int mod(long v) {
		v %= p;
		return (int)(v < 0 ? v+p : v);
	}
	public final int mul(long a, long b) {
		return mod(a*b);
	}
	public final void initFact(double limit, double p) {
		initFact((int)limit, (int)p);
	}
	public final void initFact(int limit, int p) {
		this.p = p;
		this.inv = new int[limit+1];
		this.fact = new int[limit+1];
		this.finv = new int[limit+1];
		fact[1] = finv[1] = inv[0] = inv[1] = 1;
		for(int i=2;i<=limit;i++) {
			int a = p / i;
			int b = p % i;
			inv[i]  = mul(-a, inv[b]);
			fact[i] = mul(fact[i-1], i);
			finv[i] = mul(finv[i-1], inv[i]);
		}
	}
	public final int comb(int m, int n) {
		return mul(mul(fact[m], finv[n]), finv[m-n]);
	}
	//------------------------------------------
	static long lcm (long a, long b) {
		long temp;
		long c = a;
		c *= b;
		while((temp = a%b)!=0) {
			a = b;
			b = temp;
		}
		return (long)(c/b);
	}

	//------------------------------------------



	public void exec() throws Exception{
		final String N = sc.next();
		final int[] cost = new int[N.length()+1];
		final int[] pay = new int[N.length()+1];
		final int[] ret = new int[N.length()+1];

		for(int i=0;i<N.length();i++) {
			cost[i+1] = N.charAt(i)-'0';
		}

		int up = 0;
		for(int i=N.length();i>0;i--) {
			int num = cost[i]+up;
			if(num == 5) {
				if(cost[i-1]>=5) {
					pay[i] = 0;
					up = 1;
					continue;
				}else {
					pay[i] = 5;
					up = 0;
					continue;
				}
			}
			if(num < 5) {
				pay[i] = num;
				up = 0;
				continue;
			}
			if(num > 5) {
				pay[i] = 0;
				up = 1;
				continue;
			}
		}
		pay[0] = up;
//		err.println(Arrays.toString(pay));

		int sum = 0;
		// 支払いの枚数集計
		for(int i=0;i<N.length()+1;i++) {
			sum+=pay[i];
		}

		// お釣りの計算
		for(int i=N.length();i>0;i--) {
			ret[i] = pay[i] - cost[i];
			if(ret[i] < 0) {
				pay[i-1]--;
				ret[i]+=10;
			}
		}
//		err.println(Arrays.toString(ret));

		// お釣りの集計
		for(int i=0;i<N.length()+1;i++) {
			sum+=ret[i];
		}
		out.println(sum);
	}
}
