You are given string s. Your task is to determine if the given string s contains two non-overlapping substrings "AB" and "BA" (the substrings can go in any order).

Input

The only line of input contains a string s of length between 1 and 105 consisting of uppercase Latin letters.

Output

Print "YES" (without the quotes), if string s contains two non-overlapping substrings "AB" and "BA", and "NO" otherwise.

Examples

Input

ABA


Output

NO


Input

BACFAB


Output

YES


Input

AXBYBXA


Output

NO

Note

In the first sample test, despite the fact that there are substrings "AB" and "BA", their occurrences overlap, so the answer is "NO".

In the second sample test there are the following occurrences of the substrings: BACFAB.

In the third sample test there is no substring "AB" nor substring "BA".
from sys import stdin, stdout
import math,sys,heapq
from itertools import permutations, combinations
from collections import defaultdict,deque,OrderedDict
from os import path
import random
import bisect as bi
def yes():print('YES')
def no():print('NO')
if (path.exists('input.txt')): 
    #------------------Sublime--------------------------------------#
    sys.stdin=open('input.txt','r');sys.stdout=open('output.txt','w');
    def I():return (int(input()))
    def In():return(map(int,input().split()))
else:
    #------------------PYPY FAst I/o--------------------------------#
    def I():return (int(stdin.readline()))
    def In():return(map(int,stdin.readline().split()))
#sys.setrecursionlimit(1500)
def dict(a):
    d={} 
    for x in a:
        if d.get(x,-1)!=-1:
            d[x]+=1
        else:
            d[x]=1
    return d
def find_gt(a, x):
    'Find leftmost value greater than x'
    i = bi.bisect_left(a, x)
    if i != len(a):
        return i
    else:            
        return -1
        
def main():
    try:
        l=list(input())
        flag=[0,0]
        count=0
        i=0
        ansa=[]
        ansb=[]
        n=len(l)
        for i in range(1,n):
            if l[i]=='A' and l[i-1]=='B':
                ansa.append([i-1,i])
                
            elif l[i]=='B' and l[i-1]=='A':
                ansb.append([i-1,i])
        if len(ansb)==0 or len(ansa)==0:
            no()
        else:
            flag=0
            for x in range(len(ansa)):
                for y in range(len(ansb)):
                    if ansa[x][1]!=ansb[y][0] and ansa[x][0]!=ansb[y][1]:
                        #print(ansa[x],ansb[y])
                        flag=1
                        break        
            if flag:
                yes()
            else:
                no()
    except:
        pass
        
M = 998244353
P = 1000000007
 
if __name__ == '__main__':
    #for _ in range(I()):main()
    for _ in range(1):main()