You are given a sequence of numbers a1, a2, ..., an, and a number m.

Check if it is possible to choose a non-empty subsequence aij such that the sum of numbers in this subsequence is divisible by m.

Input

The first line contains two numbers, n and m (1 ≤ n ≤ 106, 2 ≤ m ≤ 103) — the size of the original sequence and the number such that sum should be divisible by it.

The second line contains n integers a1, a2, ..., an (0 ≤ ai ≤ 109).

Output

In the single line print either "YES" (without the quotes) if there exists the sought subsequence, or "NO" (without the quotes), if such subsequence doesn't exist.

Examples

Input

3 5
1 2 3


Output

YES


Input

1 6
5


Output

NO


Input

4 6
3 1 1 3


Output

YES


Input

6 6
5 5 5 5 5 5


Output

YES

Note

In the first sample test you can choose numbers 2 and 3, the sum of which is divisible by 5.

In the second sample test the single non-empty subsequence of numbers is a single number 5. Number 5 is not divisible by 6, that is, the sought subsequence doesn't exist.

In the third sample test you need to choose two numbers 3 on the ends.

In the fourth sample test you can take the whole subsequence.
import java.io.*;
import java.util.*;

public class CF577B {
	public static void main(String[] args) throws IOException {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		StringTokenizer st = new StringTokenizer(br.readLine());
		int n = Integer.parseInt(st.nextToken());
		int m = Integer.parseInt(st.nextToken());
		if (n >= m) {
			System.out.println("YES");
			return;
		}
		st = new StringTokenizer(br.readLine());
		int[] aa = new int[n];
		for (int i = 0; i < n; i++)
			aa[i] = Integer.parseInt(st.nextToken()) % m;
		boolean[] pp = new boolean[m];
		boolean[] qq = new boolean[m];
		for (int i = 0; i < n; i++) {
			qq[aa[i]] = true;
			for (int a = 1; a < m; a++)
				if (pp[a])
					qq[(a + aa[i]) % m] = true;
			if (qq[0]) {
				System.out.println("YES");
				return;
			}
			for (int a = 0; a < m; a++)
				pp[a] = qq[a];
		}
		System.out.println("NO");
	}
}
