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For given three points p0, p1, p2, print


COUNTER_CLOCKWISE


if p0, p1, p2 make a counterclockwise turn (1),


CLOCKWISE


if p0, p1, p2 make a clockwise turn (2),


ONLINE_BACK


if p2 is on a line p2, p0, p1 in this order (3),


ONLINE_FRONT


if p2 is on a line p0, p1, p2 in this order (4),


ON_SEGMENT


if p2 is on a segment p0p1 (5).

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p0 and p1 are not identical.

Input


xp0 yp0 xp1 yp1
q
xp20 yp20
xp21 yp21
...
xp2q-1 yp2q-1


In the first line, integer coordinates of p0 and p1 are given. Then, q queries are given for integer coordinates of p2.

Output

For each query, print the above mentioned status.

Examples

Input

0 0 2 0
2
-1 1
-1 -1


Output

COUNTER_CLOCKWISE
CLOCKWISE


Input

0 0 2 0
3
-1 0
0 0
3 0


Output

ONLINE_BACK
ON_SEGMENT
ONLINE_FRONT
#include <cstdio>           // printf(), scanf()

static const double EPS = 1e-10;

static const int COUNTER_CLOCKWISE = 1;
static const int CLOCKWISE = -1;
static const int ONLINE_BACK = 2;
static const int ONLINE_FRONT = -2;
static const int ON_SEGMENT = 0;

class Point
{
public:
	double x, y;

	Point(double x = 0, double y = 0): x(x), y(y) {}
	Point operator - (Point p) { return Point(x - p.x, y - p.y); }
};

typedef Point Vector;

double
norm(Vector a)
{
	return a.x * a.x + a.y * a.y;
}

double
dot(Vector a, Vector b)
{
	return a.x * b.x + a.y * b.y;
}


double
cross(Vector a, Vector b)
{
	return a.x * b.y - a.y * b.x;
}

int
ccw(Point p0, Point p1, Point p2)
{
	Vector a = p1 - p0;
	Vector b = p2 - p0;

	if (cross(a, b) > EPS)
		return COUNTER_CLOCKWISE;

	if (cross(a, b) < -EPS)
		return CLOCKWISE;

	if (dot(a, b) < -EPS)
		return ONLINE_BACK;

	if (norm(a) < norm(b))
		return ONLINE_FRONT;

	return ON_SEGMENT;
}

int
main(int argc, char** argv)
{
	/*x                       -2 (#0)         -1 (#1)      0 (#2)        1 (#3)               2 (#4)     x*/
	const char* output[5] = {"ONLINE_FRONT", "CLOCKWISE", "ON_SEGMENT", "COUNTER_CLOCKWISE", "ONLINE_BACK"};
	Point p0, p1, p2;
	int x, y;
	int x1, y1, x2, y2;
	int q, i;
	int ix;

	scanf("%d %d %d %d", &x1, &y1, &x2, &y2);
	p0.x = x1, p0.y = y1;
	p1.x = x2, p1.y = y2;

	scanf("%d", &q);
	for (i = 0; i < q; ++i)
	{
		scanf("%d %d", &x, &y);
		p2.x = x, p2.y = y;

		ix = ccw(p0, p1, p2);
		printf("%s\n", output[ix + 2]);
	}

	return 0;
}