There is a country with n citizens. The i-th of them initially has a_{i} money. The government strictly controls the wealth of its citizens. Whenever a citizen makes a purchase or earns some money, they must send a receipt to the social services mentioning the amount of money they currently have.

Sometimes the government makes payouts to the poor: all citizens who have strictly less money than x are paid accordingly so that after the payout they have exactly x money. In this case the citizens don't send a receipt.

You know the initial wealth of every citizen and the log of all events: receipts and payouts. Restore the amount of money each citizen has after all events.

Input

The first line contains a single integer n (1 ≤ n ≤ 2 ⋅ 10^{5}) — the numer of citizens.

The next line contains n integers a_1, a_2, ..., a_n (0 ≤ a_{i} ≤ 10^{9}) — the initial balances of citizens.

The next line contains a single integer q (1 ≤ q ≤ 2 ⋅ 10^{5}) — the number of events.

Each of the next q lines contains a single event. The events are given in chronological order.

Each event is described as either 1 p x (1 ≤ p ≤ n, 0 ≤ x ≤ 10^{9}), or 2 x (0 ≤ x ≤ 10^{9}). In the first case we have a receipt that the balance of the p-th person becomes equal to x. In the second case we have a payoff with parameter x.

Output

Print n integers — the balances of all citizens after all events.

Examples

Input


4
1 2 3 4
3
2 3
1 2 2
2 1


Output


3 2 3 4 


Input


5
3 50 2 1 10
3
1 2 0
2 8
1 3 20


Output


8 8 20 8 10 

Note

In the first example the balances change as follows: 1 2 3 4 → 3 3 3 4 → 3 2 3 4 → 3 2 3 4

In the second example the balances change as follows: 3 50 2 1 10 → 3 0 2 1 10 → 8 8 8 8 10 → 8 8 20 8 10
(function() {
var INPUT = ``;
var OUTPUT = ``;

var main = function() {"use strict";
    // TODO
    var n = rdN();
    var A = [null].concat(rdArN());
    var LC = crAr(n + 1, 0);
    var CS = [];
    var q = rdN();

    while (q --> 0) {
        var input = rdArN();
        var op = input[0];
        if (op === 1) {
            var p = input[1];
            var x = input[2];
            A[p] = x;
            LC[p] = CS.length;
        } else if (op === 2) {
            var x = input[1];
            CS.push(x);
        }
    }
    for (var i = CS.length - 2; i >= 0; --i) {
        CS[i] = Math.max(CS[i], CS[i+1]);
    }
    //prAr(LC);
    //prAr(CS);
    for (var i = 1; i <= A.length; ++i) {
        var lc = LC[i];
        var cs = CS[lc];
        if (A[i] < cs) {
            A[i] = cs;
        }
    }
    prAr(A.slice(1));
};

if(INPUT){INPUT=INPUT.split('\n').reverse();
readline=()=>INPUT.pop();
write=(...s)=>{OUTPUT+=[...s].join(' ')};
print=(...s)=>{write(...s);OUTPUT+='\n'};}
const
rdS=readline,
rdN=()=>+rdS(),
rdArS=()=>rdS().split(' '),
rdArN=()=>rdArS().map(v=>+v),
wr=write,
pr=print,
prAr=(a)=>pr(...a),
prOb=(o)=>pr(JSON.stringify(o,null,4)),
crAr=function(length,...fillArgs){return new Array(length).fill(...fillArgs);},
getPrimes=function(n){var sieve=crAr(n+1,true);for(var i=2,j=4;j<sieve.length;j=Math.pow(++i,2)){if(sieve[j]){for(;j<sieve.length;j+=i){sieve[j]=false;}}}var primes=[];for(i=2;i<sieve.length;++i){if(sieve[i]){primes.push(i);}}return primes;},
defineProperty=(o,pN,v)=>Object.defineProperty(o,pN,{configurable:true,enumerable:false,value:v});
defineProperty(Array.prototype,'sortLt',function(){return this.sort((a,b)=>a-b);});
defineProperty(Array.prototype,'sortGt',function(){return this.sort((a,b)=>b-a);});
defineProperty(Set.prototype,'union',function(s){return new Set([...this,...s]);});
defineProperty(Set.prototype,'intersection',function(s){return new Set([...this].filter((v)=>s.has(v)));});
defineProperty(Set.prototype,'difference',function(s){return new Set([...this].filter((v)=>!s.has(v)));});

main();
return OUTPUT;
})();