Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.

Petya loves long lucky numbers very much. He is interested in the minimum lucky number d that meets some condition. Let cnt(x) be the number of occurrences of number x in number d as a substring. For example, if d = 747747, then cnt(4) = 2, cnt(7) = 4, cnt(47) = 2, cnt(74) = 2. Petya wants the following condition to fulfil simultaneously: cnt(4) = a1, cnt(7) = a2, cnt(47) = a3, cnt(74) = a4. Petya is not interested in the occurrences of other numbers. Help him cope with this task.

Input

The single line contains four integers a1, a2, a3 and a4 (1 ≤ a1, a2, a3, a4 ≤ 106).

Output

On the single line print without leading zeroes the answer to the problem — the minimum lucky number d such, that cnt(4) = a1, cnt(7) = a2, cnt(47) = a3, cnt(74) = a4. If such number does not exist, print the single number "-1" (without the quotes).

Examples

Input

2 2 1 1


Output

4774


Input

4 7 3 1


Output

-1
import java.util.*;
import java.io.*;

public class cf145b {
	public static void main(String[] args) {
		PrintWriter out = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));
		Scanner in = new Scanner(System.in);
		int a = in.nextInt();
		int b = in.nextInt();
		int c = in.nextInt();
		int d = in.nextInt();
		int last = 0;
		if(Math.abs(c-d) > 1) {
			System.out.println("-1");
			return;
		}
		if(Math.abs(c-d)==1 && Math.min(a, b) < Math.max(c, d)) {
			System.out.println("-1");
			return;
		}
		if(c == d && (Math.max(a,b)<=c || Math.min(a, b)< c)) {
			System.out.println("-1");
			return;
		}
		while(a+b>0) {
			if(ok(a-1,b,c,d-(last==7?1:0))) {
				out.print(4);
				a--;
				d-= (last==7?1:0);
				last=4;
			}
			else {
				out.print(7);
				b--;
				c-= (last==4?1:0);
				last=7;
			}
		}
		out.println();
		out.flush();
	}
	//valid state if I just placed a 4
	static boolean ok(int a, int b, int c, int d) { 
	//	System.out.println("TRYING: " + a + " " + b + " " + c + " " + d);
		if(a<0||b<0||c<0||d<0) return false;
		if(c==0 && d==0) return b==0;
		if(c==d) return Math.min(a, b) >= c;
		if(c==d+1) return b>=c&&a>=d;
		return false;
	}
}
