You have an array a of length n. For every positive integer x you are going to perform the following operation during the x-th second:

  * Select some distinct indices i_{1}, i_{2}, …, i_{k} which are between 1 and n inclusive, and add 2^{x-1} to each corresponding position of a. Formally, a_{i_{j}} := a_{i_{j}} + 2^{x-1} for j = 1, 2, …, k. Note that you are allowed to not select any indices at all.



You have to make a nondecreasing as fast as possible. Find the smallest number T such that you can make the array nondecreasing after at most T seconds.

Array a is nondecreasing if and only if a_{1} ≤ a_{2} ≤ … ≤ a_{n}.

You have to answer t independent test cases.

Input

The first line contains a single integer t (1 ≤ t ≤ 10^{4}) — the number of test cases.

The first line of each test case contains single integer n (1 ≤ n ≤ 10^{5}) — the length of array a. It is guaranteed that the sum of values of n over all test cases in the input does not exceed 10^{5}.

The second line of each test case contains n integers a_{1}, a_{2}, …, a_{n} (-10^{9} ≤ a_{i} ≤ 10^{9}).

Output

For each test case, print the minimum number of seconds in which you can make a nondecreasing.

Example

Input


3
4
1 7 6 5
5
1 2 3 4 5
2
0 -4


Output


2
0
3

Note

In the first test case, if you select indices 3, 4 at the 1-st second and 4 at the 2-nd second, then a will become [1, 7, 7, 8]. There are some other possible ways to make a nondecreasing in 2 seconds, but you can't do it faster.

In the second test case, a is already nondecreasing, so answer is 0.

In the third test case, if you do nothing at first 2 seconds and select index 2 at the 3-rd second, a will become [0, 0].
//package C;

import java.io.*;
import java.util.*;
import java.math.*;

public class Main {
    private static final long mod = (long) (1e9 + 7);

    public static void solve() {
        int t = in.nextInt();

        while (t-- > 0) {
            int n = in.nextInt();
            int[] nums = new int[n];
            for (int i = 0; i < nums.length; i++) {
                nums[i] = in.nextInt();
            }

            int[] max = new int[n];
            max[0] = nums[0];

            for (int i = 1; i < n; i += 1) {
                max[i] = Math.max(max[i - 1], nums[i]);
            }

            int[] diff = new int[n];

            for (int i = 0; i < n; i += 1) {
                diff[i] = max[i] - nums[i];
            }

            Arrays.sort(diff);

            long maxDiff = diff[n - 1];

            long ans = 0;

            while (maxDiff > 0) {
                maxDiff -= (long) Math.pow(2, ans);
                ans += 1;
            }

            out.println(ans);
        }
    }

    public static InputReader in = new InputReader();
    public static PrintWriter out;

    public static void main(String[] args) {
        out = new PrintWriter(System.out);
        solve();
        out.close();
    }

    private static long pow(long a, long b) {
        if (b == 0)
            return 1L;

        long val = pow(a, b / 2);

        if (b % 2 == 0)
            return val * val % mod;
        else
            return val * val % mod * a % mod;
    }

    private static class Pair<K, V> {
        K first;
        V second;

        public Pair(K first, V second) {
            this.first = first;
            this.second = second;
        }
    }

    static class InputReader {
        public BufferedReader reader;
        public StringTokenizer tokenizer;

        public InputReader() {
            reader = new BufferedReader(new InputStreamReader(System.in));
            tokenizer = null;
        }

        public String next() {
            while (tokenizer == null || !tokenizer.hasMoreTokens()) {
                try {
                    tokenizer = new StringTokenizer(reader.readLine());
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
            return tokenizer.nextToken();
        }

        public int nextInt() {
            return Integer.parseInt(next());
        }

        public double nextDouble() {
            return Double.parseDouble(next());
        }

        public long nextLong() {
            return Long.parseLong(next());
        }

        /**
         * When you call next(), that entire line will be skipped. No flushing buffers.
         * Doesn't work when you want to scan the remaining line.
         *
         * @return entire line
         */
        public String nextLine() {
            String str = "";
            try {
                str = reader.readLine();
                tokenizer = null;
            } catch (IOException e) {
                throw new RuntimeException(e);
            }
            return str;
        }
    }
}