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For given three points p0, p1, p2, print


COUNTER_CLOCKWISE


if p0, p1, p2 make a counterclockwise turn (1),


CLOCKWISE


if p0, p1, p2 make a clockwise turn (2),


ONLINE_BACK


if p2 is on a line p2, p0, p1 in this order (3),


ONLINE_FRONT


if p2 is on a line p0, p1, p2 in this order (4),


ON_SEGMENT


if p2 is on a segment p0p1 (5).

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p0 and p1 are not identical.

Input


xp0 yp0 xp1 yp1
q
xp20 yp20
xp21 yp21
...
xp2q-1 yp2q-1


In the first line, integer coordinates of p0 and p1 are given. Then, q queries are given for integer coordinates of p2.

Output

For each query, print the above mentioned status.

Examples

Input

0 0 2 0
2
-1 1
-1 -1


Output

COUNTER_CLOCKWISE
CLOCKWISE


Input

0 0 2 0
3
-1 0
0 0
3 0


Output

ONLINE_BACK
ON_SEGMENT
ONLINE_FRONT
#include<bits/stdc++.h>
using namespace std;
const double eps = 1e-10;
struct Node
{
    double x, y;
    Node(double xx = 0, double yy = 0){
        x = xx; y = yy;
    }

    Node operator + (Node b){
        return Node(x+b.x, y+b.y);
    }
    Node operator - (Node b){
        return Node(x-b.x, y-b.y);
    }
    Node operator * (double a){
        return Node(a*x, a*y);
    }
    Node operator / (double a){
        return Node(x/a, y/a);
    }

    double norm(){return x*x+y*y;}
    double len(){
        return sqrt(norm());
    }

    bool operator < (const Node &p) const{
        return x!=p.x ? x<p.x : y<p.y;
    }

    bool operator == (const Node &p) const {
        return fabs(x-p.x)<eps && fabs(y-p.y)<eps;
    }
};

typedef Node vtr;

struct line{
    Node a, b;
    line(Node x, Node y){
        a = x, b = y;
    }
};

//向量点积
double dot(vtr a, vtr b){
    return a.x*b.x+a.y*b.y;
}

//向量叉积
double cross(vtr a, vtr b){
    return a.x*b.y-a.y*b.x;
}

//投影 求垂足坐标
//点p在直线p1p2上的投影
Node project(line s, Node p)
{
    vtr base = s.b-s.a;
    double r = dot(p-s.a, base)/base.norm();
    return s.a+base*r;
}

//映象 求p以s为对称轴的对称点
Node reflect(line s, Node p){
    return p+(project(s, p)-p)*2.0;
}

int ccw(Node p0, Node p1, Node p2)
{
    vtr a = p1-p0;
    vtr b = p2-p0;
    if(cross(a, b) > eps) return 1;
    if(cross(a, b) < -eps) return -1;
    if(dot(a, b) < -eps) return 2;
    if(a.norm() < b.norm()) return -2;
    return 0;
}

int main()
{
    Node p0, p1, p2;
    cin>>p0.x>>p0.y>>p1.x>>p1.y;
    int q; scanf("%d", &q);
    while(q--)
    {
        cin >> p2.x >> p2.y;
        switch(ccw(p0, p1, p2))
        {
            case 1:cout<<"COUNTER_CLOCKWISE"<<endl; break;
			case -1: cout<<"CLOCKWISE"<<endl; break;
			case 2: cout<<"ONLINE_BACK"<<endl; break;
			case -2: cout<<"ONLINE_FRONT"<<endl; break;
			case 0: cout<<"ON_SEGMENT"<<endl; break;
        }
    }
    return 0;
}

