<image>

For given three points p0, p1, p2, print


COUNTER_CLOCKWISE


if p0, p1, p2 make a counterclockwise turn (1),


CLOCKWISE


if p0, p1, p2 make a clockwise turn (2),


ONLINE_BACK


if p2 is on a line p2, p0, p1 in this order (3),


ONLINE_FRONT


if p2 is on a line p0, p1, p2 in this order (4),


ON_SEGMENT


if p2 is on a segment p0p1 (5).

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p0 and p1 are not identical.

Input


xp0 yp0 xp1 yp1
q
xp20 yp20
xp21 yp21
...
xp2q-1 yp2q-1


In the first line, integer coordinates of p0 and p1 are given. Then, q queries are given for integer coordinates of p2.

Output

For each query, print the above mentioned status.

Examples

Input

0 0 2 0
2
-1 1
-1 -1


Output

COUNTER_CLOCKWISE
CLOCKWISE


Input

0 0 2 0
3
-1 0
0 0
3 0


Output

ONLINE_BACK
ON_SEGMENT
ONLINE_FRONT
#include<iostream>
#include<cstdio>
#include<vector>
#include<queue>
#include<map>
#include<string>
#include <math.h>
#include<algorithm>
#include<functional>
#define ll long long
#define inf  999999999
#define pa pair<int,int>
#define EPS (1e-10)
#define equals(a,b) (fabs((a)-(b))<EPS)

using namespace std;

class Point{
	public:
	double x,y;
	Point(double x=0,double y=0):x(x),y(y) {}
	Point operator + (Point p) {return Point(x+p.x,y+p.y);}
	Point operator - (Point p) {return Point(x-p.x,y-p.y);}
	Point operator * (double a) {return Point(x*a,y*a);}
	Point operator / (double a) {return Point(x/a,y/a);}
	double absv() {return sqrt(norm());}
	double norm() {return x*x+y*y;}
	bool operator < (const Point &p) const{
		return x != p.x ? x<p.x: y<p.y;
	}
	bool operator == (const Point &p) const{
		return fabs(x-p.x)<EPS && fabs(y-p.y)<EPS;
	}
};
typedef Point Vector;

struct Segment{
Point p1,p2;
};


double dot(Vector a,Vector b){
	return a.x*b.x+a.y*b.y;
}
double cross(Vector a,Vector b){
	return a.x*b.y-a.y*b.x;
}

//----------------kokomade temple------------


int main(){
int n;
double a1,a2,a3,a4,a5,a6;
cin>>a1>>a2>>a3>>a4;
cin>>n;
Point p0,p1,p2;
Vector v01,v02;
p0.x=a1,p0.y=a2,p1.x=a3,p1.y=a4;
v01=p1-p0;

for(int i=0;i<n;i++){
cin>>a5>>a6;
p2.x=a5,p2.y=a6;
v02=p2-p0;

if(cross(v01,v02)>0) cout<<"COUNTER_CLOCKWISE"<<endl;
else if(cross(v01,v02)<0) cout<<"CLOCKWISE"<<endl;
else if(dot(v01,v02)<0) cout<<"ONLINE_BACK"<<endl;
else if(v01.norm() < v02.norm()) cout<<"ONLINE_FRONT"<<endl;
else cout<<"ON_SEGMENT"<<endl;



}



return 0;
}