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For given three points p0, p1, p2, print


COUNTER_CLOCKWISE


if p0, p1, p2 make a counterclockwise turn (1),


CLOCKWISE


if p0, p1, p2 make a clockwise turn (2),


ONLINE_BACK


if p2 is on a line p2, p0, p1 in this order (3),


ONLINE_FRONT


if p2 is on a line p0, p1, p2 in this order (4),


ON_SEGMENT


if p2 is on a segment p0p1 (5).

Constraints

* 1 ≤ q ≤ 1000
* -10000 ≤ xi, yi ≤ 10000
* p0 and p1 are not identical.

Input


xp0 yp0 xp1 yp1
q
xp20 yp20
xp21 yp21
...
xp2q-1 yp2q-1


In the first line, integer coordinates of p0 and p1 are given. Then, q queries are given for integer coordinates of p2.

Output

For each query, print the above mentioned status.

Examples

Input

0 0 2 0
2
-1 1
-1 -1


Output

COUNTER_CLOCKWISE
CLOCKWISE


Input

0 0 2 0
3
-1 0
0 0
3 0


Output

ONLINE_BACK
ON_SEGMENT
ONLINE_FRONT
#include <iostream>
#include <fstream>
#include <string>
#include <iomanip>
#include <math.h>
using namespace std;

class Point {
    public:
    double x, y;

    Point(double x = 0, double y = 0): x(x), y(y) {}

    Point operator + (Point p) { return Point(x+p.x, y+p.y); }
    Point operator - (Point p) { return Point(x-p.x, y-p.y); }
    Point operator * (double a) { return Point(a*x, a*y); }
    Point operator / (double a) { return Point(x/a, y/a); }

    double abs() {return sqrt(norm()); }
    double norm() {return x*x + y*y; }
};

typedef Point Vector;


double dot(Vector a, Vector b) {
    return a.x * b.x + a.y * b.y;
}

double cross(Vector a, Vector b) {
    return a.x*b.y - a.y*b.x;
}

int main(){
    //cinの入力元をテキストファイルに(テスト用)
    #if 0
    std::ifstream in("input.txt");
    std::cin.rdbuf(in.rdbuf());
    #endif

    Point p0, p1;
    int q;
    string message[6] = {"ERROR", "COUNTER_CLOCKWISE", "CLOCKWISE", "ONLINE_BACK", "ONLINE_FRONT", "ON_SEGMENT"};

    //標準入力
    cin >> p0.x;
    cin >> p0.y;
    cin >> p1.x;
    cin >> p1.y;
    cin >> q;

    Vector v01 = p1 - p0;

    for(int i=0; i<q; i++){
        int num = 0;
        Point p2;
        cin >> p2.x;
        cin >> p2.y;

        Vector v02= p2 - p0;

        double Dot = dot(v01, v02);
        double Cross = cross(v01, v02);

        if(Cross > 0){num = 1;}
        else if (Cross < 0){num = 2;}
        else
        {
            if(Dot < 0){num = 3;}
            else{
                if(v01.norm() < v02.norm()){num = 4;}
                else{num = 5;}
            }
        }
        cout << message[num] << "\n";
    }
    return 0;
}

