Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (x, y), he can move to (or attack) positions (x + 1, y), (x–1, y), (x, y + 1) and (x, y–1).

Iahub wants to know how many Coders can be placed on an n × n chessboard, so that no Coder attacks any other Coder.

Input

The first line contains an integer n (1 ≤ n ≤ 1000).

Output

On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.

On each of the next n lines print n characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.

If there are multiple correct answers, you can print any.

Examples

Input

2


Output

2
C.
.C
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintWriter;



/**
 *
 * @author Anextro
 */
public class Main {

    
    public static void main(String[] args) throws IOException {
        
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        BufferedWriter bw = new BufferedWriter(new PrintWriter(System.out));
        
        int n = Integer.parseInt(br.readLine());
        
        int[] f = new int[n+1];
        int[] d = new int[n+1];
        
        f[1]=1;d[1]=1;
        for(int i=2;i<=n;i++){
            d[i]=i-d[i-1];
            f[i] = 2*d[i] - 1 + f[i-1];
        }
       // System.out.println(d[3]+" "+d[4]+" ");
        bw.append(f[n]+"\n");
        boolean dot = false;
        
        char[][] data = new char[n][n];
        
       data[0][0]='C';
        for(int i=1;i<n;i++){
          if(data[0][i-1]=='C'){
              data[0][i]='.';
          }
          else  data[0][i]='C';
        }
        for(int i=1;i<n;i++){
            for(int j=0;j<n;j++){
                if(data[i-1][j]=='C'){
                    data[i][j]='.';
                }
                else    data[i][j]='C';
           }
        }
        for(int i=0;i<n;i++){
            String ln1="";
            for(int j=0;j<n;j++){
                ln1+=String.valueOf(data[i][j]);
           }
            bw.append(ln1+"\n");
        }
        bw.close();
    }
}
