Bob is an avid fan of the video game "League of Leesins", and today he celebrates as the League of Leesins World Championship comes to an end! 

The tournament consisted of n (n ≥ 5) teams around the world. Before the tournament starts, Bob has made a prediction of the rankings of each team, from 1-st to n-th. After the final, he compared the prediction with the actual result and found out that the i-th team according to his prediction ended up at the p_i-th position (1 ≤ p_i ≤ n, all p_i are unique). In other words, p is a permutation of 1, 2, ..., n.

As Bob's favorite League player is the famous "3ga", he decided to write down every 3 consecutive elements of the permutation p. Formally, Bob created an array q of n-2 triples, where q_i = (p_i, p_{i+1}, p_{i+2}) for each 1 ≤ i ≤ n-2. Bob was very proud of his array, so he showed it to his friend Alice.

After learning of Bob's array, Alice declared that she could retrieve the permutation p even if Bob rearranges the elements of q and the elements within each triple. Of course, Bob did not believe in such magic, so he did just the same as above to see Alice's respond.

For example, if n = 5 and p = [1, 4, 2, 3, 5], then the original array q will be [(1, 4, 2), (4, 2, 3), (2, 3, 5)]. Bob can then rearrange the numbers within each triple and the positions of the triples to get [(4, 3, 2), (2, 3, 5), (4, 1, 2)]. Note that [(1, 4, 2), (4, 2, 2), (3, 3, 5)] is not a valid rearrangement of q, as Bob is not allowed to swap numbers belong to different triples.

As Alice's friend, you know for sure that Alice was just trying to show off, so you decided to save her some face by giving her any permutation p that is consistent with the array q she was given. 

Input

The first line contains a single integer n (5 ≤ n ≤ 10^5) — the size of permutation p.

The i-th of the next n-2 lines contains 3 integers q_{i, 1}, q_{i, 2}, q_{i, 3} (1 ≤ q_{i, j} ≤ n) — the elements of the i-th triple of the rearranged (shuffled) array q_i, in random order. Remember, that the numbers within each triple can be rearranged and also the positions of the triples can be rearranged.

It is guaranteed that there is at least one permutation p that is consistent with the input. 

Output

Print n distinct integers p_1, p_2, …, p_n (1 ≤ p_i ≤ n) such that p is consistent with array q. 

If there are multiple answers, print any. 

Example

Input


5
4 3 2
2 3 5
4 1 2


Output


1 4 2 3 5 
import java.io.*;
import java.util.*;
import java.math.*;
public class Main
{
	static long mod=1000000007l;
	static int max=Integer.MAX_VALUE,min=Integer.MIN_VALUE;
	static long maxl=Long.MAX_VALUE,minl=Long.MIN_VALUE;
	static BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
	static StringTokenizer st;
    static int max(int a,int b){return Math.max(a,b);}
    static int min(int a,int b){return Math.min(a,b);}
    static int abs(int a){return Math.abs(a);}
    static long max(long a,long b){return Math.max(a,b);}
    static long min(long a,long b){return Math.min(a,b);}
    static long abs(long a){return Math.abs(a);}
    static int sq(int a){return (int)Math.sqrt(a);}
    static long sq(long a){return (long)Math.sqrt(a);}
    static int ncr(int n,int c,long m)
    {
    	long a=1l;
        for(int x=n-c+1;x<=n;x++)a=((a*x)%m);
        long b=1l;
        for(int x=2;x<=c;x++)b=((b*x)%m);
        long v=(div((int)b,m-2,m)%m);
        return (int)((a*v)%m);
    }
    static int fib(int n) 
    { 
        double p=(1+Math.sqrt(5))/2; 
        return (int)Math.round(Math.pow(p,n)/Math.sqrt(5)); 
    }
    static boolean[] sieve(int n)
    {
    	boolean bo[]=new boolean[n+1];
    	bo[0]=true;bo[1]=true;
    	for(int x=4;x<=n;x+=2)bo[x]=true;
    	for(int x=3;x*x<=n;x+=2)
    	{
    		if(!bo[x])
    		{
    			for(int y=x*x;y<=n;y+=x)bo[y]=true;
    		}
    	}
    	return bo;
    }
    static int gcd(int a,int b)
    {
    	if(b==0)return 0;
    	return gcd(b,a%b);
    }
    static long div(long a,long b,long m) 
    {
        long r=1l;
        a%=m;  
        while(b>0)
        {
            if((b&1)==1)r=(r*a)%m; 
            b>>=1;
            a=(a*a)%m;  
        } 
        return r; 
    }
    static int i()throws IOException
    {
    	if(!st.hasMoreTokens()) st=new StringTokenizer(br.readLine());
    	return Integer.parseInt(st.nextToken());
    }
    static long l()throws IOException
    {
    	if(!st.hasMoreTokens())st=new StringTokenizer(br.readLine());
    	return Long.parseLong(st.nextToken());
    }
    static String s()throws IOException
    {
    	if(!st.hasMoreTokens())st=new StringTokenizer(br.readLine());
    	return st.nextToken();
    }
    static double d()throws IOException
    {
    	if(!st.hasMoreTokens())st=new StringTokenizer(br.readLine());
    	return Double.parseDouble(st.nextToken());
    }
    static char c()throws IOException
    {
    	if(!st.hasMoreTokens())st=new StringTokenizer(br.readLine());
    	return st.nextToken().charAt(0);
    }
    static boolean b()throws IOException
    {
    	if(!st.hasMoreTokens())st=new StringTokenizer(br.readLine());
    	return Boolean.parseBoolean(st.nextToken());
    }
    static void p(Object p){System.out.print(p);}
    static void p(String p){System.out.print(p);}
    static void p(int p){System.out.print(p);}
    static void p(double p){System.out.print(p);}
    static void p(long p){System.out.print(p);}
    static void p(char p){System.out.print(p);}
    static void p(boolean p){System.out.print(p);}
    static void pl(Object p){System.out.println(p);}
    static void pl(String p){System.out.println(p);}
    static void pl(int p){System.out.println(p);}
    static void pl(char p){System.out.println(p);}
    static void pl(double p){System.out.println(p);}
    static void pl(long p){System.out.println(p);}
    static void pl(boolean p){System.out.println(p);}
    static void pl(){System.out.println();}
    static int[] ari(int n)throws IOException
    {
    	int ar[]=new int[n];
    	st=new StringTokenizer(br.readLine());
    	for(int x=0;x<n;x++) ar[x]=Integer.parseInt(st.nextToken());
    	return ar;
    }
    static int[][] ari(int n,int m)throws IOException
    {
    	int ar[][]=new int[n][m];
    	for(int x=0;x<n;x++)
    	{
    		st=new StringTokenizer(br.readLine());
    		for(int y=0;y<m;y++)ar[x][y]=Integer.parseInt(st.nextToken());
    	}
    	return ar;
    }
    static long[] arl(int n)throws IOException
    {
    	long ar[]=new long[n];
    	st=new StringTokenizer(br.readLine());
    	for(int x=0;x<n;x++) ar[x]=Long.parseLong(st.nextToken());
    	return ar;
    }
    static long[][] arl(int n,int m)throws IOException
    {
    	long ar[][]=new long[n][m];
    	for(int x=0;x<n;x++)
    	{
    		st=new StringTokenizer(br.readLine());
    		for(int y=0;y<m;y++)ar[x][y]=Long.parseLong(st.nextToken());
    	}
    	return ar;
    }
    static String[] ars(int n)throws IOException
    {
    	String ar[]=new String[n];
    	st=new StringTokenizer(br.readLine());
    	for(int x=0;x<n;x++) ar[x]=st.nextToken();
    	return ar;
    }
    static double[] ard(int n)throws IOException
    {
    	double ar[]=new double[n];
    	st=new StringTokenizer(br.readLine());
    	for(int x=0;x<n;x++)ar[x]=Double.parseDouble(st.nextToken());
    	return ar;
    }
    static double[][] ard(int n,int m)throws IOException
    {
    	double ar[][]=new double[n][m];
    	for(int x=0;x<n;x++)
    	{
    		st=new StringTokenizer(br.readLine());
    		for(int y=0;y<m;y++)ar[x][y]=Double.parseDouble(st.nextToken());
    	}
    	return ar;
    }
    static char[] arc(int n)throws IOException
    {
    	char ar[]=new char[n];
    	st=new StringTokenizer(br.readLine());
    	for(int x=0;x<n;x++)ar[x]=st.nextToken().charAt(0);
    	return ar;
    }
    static char[][] arc(int n,int m)throws IOException
    {
    	char ar[][]=new char[n][m];
    	for(int x=0;x<n;x++)
    	{
    		String s=br.readLine();
    		for(int y=0;y<m;y++)ar[x][y]=s.charAt(y);
    	}
    	return ar;
    }
    static void p(int ar[])
    {
    	StringBuilder sb=new StringBuilder("");;
    	for(int a:ar) sb.append(a+" ");
    	System.out.println(sb);
    }
    static void p(int ar[][])
    {
    	StringBuilder sb;
    	for(int a[]:ar)
    	{
    		sb=new StringBuilder("");
    		for(int aa:a) sb.append(aa+" ");
    		System.out.println(sb);
    	}
    }
    static void p(long ar[])
    {
    	StringBuilder sb=new StringBuilder("");
    	for(long a:ar)sb.append(a+" ");
    	System.out.println(sb);
    }
    static void p(long ar[][])
    {
    	StringBuilder sb;
    	for(long a[]:ar)
    	{
    		sb=new StringBuilder("");
    		for(long aa:a)sb.append(aa+" ");
    		System.out.println(sb);
    	}
    }
    static void p(String ar[])
    {
    	StringBuilder sb=new StringBuilder("");
    	for(String a:ar)sb.append(a+" ");
    	System.out.println(sb);
    }
    static void p(double ar[])
    {
    	StringBuilder sb=new StringBuilder("");
    	for(double a:ar)sb.append(a+" ");
    	System.out.println(sb);
    }
    static void p(double ar[][])
    {
    	StringBuilder sb;
    	for(double a[]:ar)
    	{
    		sb=new StringBuilder("");
    		for(double aa:a)sb.append(aa+" ");
    		System.out.println(sb);
    	}
    }
    static void p(char ar[])
    {
    	StringBuilder sb=new StringBuilder("");
		for(char aa:ar)sb.append(aa+" ");
		System.out.println(sb);
    }
    static void p(char ar[][])
    {
    	StringBuilder sb;
    	for(char a[]:ar)
    	{
    		sb=new StringBuilder("");
    		for(char aa:a)sb.append(aa+" ");
    		System.out.println(sb);
    	}
    }
    static public void main(String[] args)throws Exception
    {
    	st=new StringTokenizer(br.readLine());
    	int n=i();
    	LinkedList<LinkedList<Integer>> ar[]=new LinkedList[n+1];
    	for(int x=0;x<=n;x++)
    	{
    		ar[x]=new LinkedList<>();
    	}
    	for(int x=2;x<n;x++)
    	{
    		int a=i();
    		int b=i();
    		int c=i();
    		LinkedList<Integer> l=new LinkedList<>();
    		l.add(a);
    		l.add(b);
    		l.add(c);
    		ar[a].add(l);
    		ar[b].add(l);
    		ar[c].add(l);
    	}
    	int a[]=new int[n];
    	for(int x=1;x<=n;x++)
    	{
    		if(ar[x].size()==1)
    		{
    			a[0]=x;
    			break;
    		}
    	}
    	o:
    	for(int x=1;x<=n;x++)
    	{
    		if(ar[x].size()==2)
    		{
    			for(LinkedList<Integer> aa:ar[x])
    			{
    				for(int bb:aa)
    				{
    					if(bb==a[0])
    					{
    						a[1]=x;
    						break o;
    					}
    				}
    			}
    		}
    	}
    	LinkedList<Integer> qq=ar[a[0]].get(0);
    	for(int k:qq)
    	{
    		if(k!=a[0]&&k!=a[1])
    			{a[2]=k;
    			break;
    			}
    	}
    	oo:
    	for(int x=3;x<n;x++)
    	{
    		LinkedList<LinkedList<Integer>> kl=ar[a[x-2]];
    		//pl(kl);
    		for(LinkedList<Integer> jl:kl)
    		{
    			if(jl.contains(a[x-1])&&(!(jl.contains(a[x-3]))))
    			{
    				for(int tt:jl)
    				{
    					if(tt!=a[x-2]&&tt!=a[x-1])
    					{
    						a[x]=tt;
    						continue oo;
    					}
    				}
    			}
    		}
    	}
    	p(a);
    }
    	
    	
    	
    	
    	
    	
    	
    	
    	
    	
    	
    	
    	
    	
    	
    	
    	
    	
}
