Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner in=new Scanner(System.in);
        int m=in.nextInt();
        int d=in.nextInt();
        
        if(m==1 ||m==3 ||m==5 ||m==7 ||m==8 ||m==10 || m==12)
        {
            if(d==6 || d==7)
            {
                System.out.println("6");
            }
            else{
                System.out.println("5");
            }
        }
        else if(m==2){
            if(d>1)
                System.out.println("5");
            else{
                System.out.println("4");
            }
        }
        else{
            if(d==7)
                System.out.println("6");
            else{
                System.out.println("5");
            }
        }
    }
    
}
