Write a program which manipulates a sequence $A = \\{a_0, a_1, ..., a_{n-1}\\}$ by the following operations:

* min($b, e$): report the minimum element in $a_b, a_{b+1}, ..., a_{e-1}$
* max($b, e$): report the maximum element in $a_b, a_{b+1}, ..., a_{e-1}$

Constraints

* $1 \leq n \leq 1,000$
* $-1,000,000,000 \leq a_i \leq 1,000,000,000$
* $1 \leq q \leq 1,000$
* $0 \leq b < e \leq n$

Input

The input is given in the following format.


$n$
$a_0 \; a_1, ..., \; a_{n-1}$
$q$
$com_1 \; b_1 \; e_1$
$com_2 \; b_2 \; e_2$
:
$com_{q} \; b_{q} \; e_{q}$


In the first line, $n$ (the number of elements in $A$) is given. In the second line, $a_i$ (each element in $A$) are given. In the third line, the number of queries $q$ is given and each query is given in the following $q$ lines. $com_i$ denotes a type of query. 0 and 1 represents min($b, e$) and max($b, e$) respectively.

Output

For each query, print the minimum element or the maximum element in a line.

Example

Input

7
8 3 7 1 9 1 4
3
0 0 3
0 1 5
1 0 7


Output

3
1
9
#include <bits/stdc++.h>
using namespace std;
int main(void){
    int n,a,q,com,b,e;
    std::deque<int> deq;
    priority_queue<int,std::vector<int>,std::greater<int>> que1;
    priority_queue<int> que2;
    cin >> n;
    for (int i=0;i<n;i++) {
        cin >> a;
        deq.emplace_back(a);
    }
    cin >> q;
    for (int j=0;j<q;j++) {
        cin >> com >> b >> e;
        if ( com==0 ) {
            for (int k=b;k<e;k++) {
                que1.push(deq[k]);
            }
            cout << que1.top() << endl;
            for (int l=b;l<e;l++) {
                que1.pop();
            }
        } else if ( com==1 ) {
            for (int m=b;m<e;m++) {
                que2.push(deq[m]);
            }
            cout << que2.top() << endl;
            for (int n=b;n<e;n++) {
                que2.pop();
            }
        }
    }
}

