Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.

//package code;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Code {

    public static void main(String[] args) throws IOException {
        int n=0;
        int p, q;
        String s;
        BufferedReader w = new BufferedReader(new InputStreamReader(System.in));
        s = w.readLine();
        p = Integer.parseInt(s.substring(0, s.indexOf(' ')));
        q = Integer.parseInt(s.substring(s.indexOf(' ') + 1));

        if (p == 1 || p == 3 || p == 5 || p == 7 || p == 8 || p == 10 || p == 12) {
            n = 31 - (8 - q);
        }
        if (p == 2) {
            n = 28 - (8 - q);
        }
        if (p == 4 || p == 6 || p == 9 || p == 11) {
            n = 30 - (8 - q);
        }
        System.out.println((int)(Math.ceil(n/7.0)+1));
    }

}
