As you probably know, Anton goes to school. One of the school subjects that Anton studies is Bracketology. On the Bracketology lessons students usually learn different sequences that consist of round brackets (characters "(" and ")" (without quotes)).

On the last lesson Anton learned about the regular simple bracket sequences (RSBS). A bracket sequence s of length n is an RSBS if the following conditions are met:

  * It is not empty (that is n ≠ 0). 
  * The length of the sequence is even. 
  * First <image> charactes of the sequence are equal to "(". 
  * Last <image> charactes of the sequence are equal to ")". 



For example, the sequence "((()))" is an RSBS but the sequences "((())" and "(()())" are not RSBS.

Elena Ivanovna, Anton's teacher, gave him the following task as a homework. Given a bracket sequence s. Find the number of its distinct subsequences such that they are RSBS. Note that a subsequence of s is a string that can be obtained from s by deleting some of its elements. Two subsequences are considered distinct if distinct sets of positions are deleted.

Because the answer can be very big and Anton's teacher doesn't like big numbers, she asks Anton to find the answer modulo 109 + 7.

Anton thought of this task for a very long time, but he still doesn't know how to solve it. Help Anton to solve this task and write a program that finds the answer for it!

Input

The only line of the input contains a string s — the bracket sequence given in Anton's homework. The string consists only of characters "(" and ")" (without quotes). It's guaranteed that the string is not empty and its length doesn't exceed 200 000.

Output

Output one number — the answer for the task modulo 109 + 7.

Examples

Input

)(()()


Output

6


Input

()()()


Output

7


Input

)))


Output

0

Note

In the first sample the following subsequences are possible:

  * If we delete characters at the positions 1 and 5 (numbering starts with one), we will get the subsequence "(())". 
  * If we delete characters at the positions 1, 2, 3 and 4, we will get the subsequence "()". 
  * If we delete characters at the positions 1, 2, 4 and 5, we will get the subsequence "()". 
  * If we delete characters at the positions 1, 2, 5 and 6, we will get the subsequence "()". 
  * If we delete characters at the positions 1, 3, 4 and 5, we will get the subsequence "()". 
  * If we delete characters at the positions 1, 3, 5 and 6, we will get the subsequence "()". 



The rest of the subsequnces are not RSBS. So we got 6 distinct subsequences that are RSBS, so the answer is 6.
import java.io.*;
import java.util.StringTokenizer;

public class _785D {

    static final long MOD = 1_000_000_007;
    static long[] factorials = new long[200_001 * 2];

    static {
        factorials[0] = 1;
        for (int i = 1; i < factorials.length; i++)
            factorials[i] = factorials[i - 1] * i % MOD;
    }

    static long pow(long a, long n) {
        long ans = 1;
        while (n > 0) {
            if (n % 2 == 1) ans = ans * a % MOD;
            a = a * a % MOD;
            n /= 2;
        }
        return ans;
    }

    static long inv(long x) {
        return pow(x, MOD - 2);
    }

    static long nChoosek(int n, int k) {
        if (n < 0 || k < 0 || k > n) return 0;
        return factorials[n] * inv(factorials[k]) % MOD * inv(factorials[n - k]) % MOD;
    }


    public static void main(String[] args) throws Exception {
        Reader.init(System.in);
        BufferedWriter cout = new BufferedWriter(new OutputStreamWriter(System.out));

        char[] a = Reader.next().toCharArray();
        long ans = 0;
        if (a.length > 0) {
            int L = 0, R = 0;
            for (int i = 0; i < a.length; i++)
                if (a[i] == ')') R++;

            for (int i = 0; i < a.length; i++) {
                if (a[i] == '(') {
                    L++;
                    ans = (ans + nChoosek(L + R - 1, L)) % MOD;
                } else R--;

            }
        }

        System.out.println(ans);
        cout.close();
    }

    static class Pair<U extends Comparable<U>, V extends Comparable<V>> implements Comparable<Pair<U, V>> {
        final U _1;
        final V _2;

        private Pair(U key, V val) {
            this._1 = key;
            this._2 = val;
        }

        public static <U extends Comparable<U>, V extends Comparable<V>> Pair<U, V> instanceOf(U _1, V _2) {
            return new Pair<U, V>(_1, _2);
        }

        @Override
        public String toString() {
            return _1 + " " + _2;
        }

        @Override
        public int hashCode() {
            int res = 17;
            res = res * 31 + _1.hashCode();
            res = res * 31 + _2.hashCode();
            return res;
        }

        @Override
        public int compareTo(Pair<U, V> that) {
            int res = this._1.compareTo(that._1);
            if (res < 0 || res > 0) return res;
            else return this._2.compareTo(that._2);
        }

        @Override
        public boolean equals(Object obj) {
            if (this == obj) return true;
            if (!(obj instanceof Pair)) return false;
            Pair<?, ?> that = (Pair<?, ?>) obj;
            return _1.equals(that._1) && _2.equals(that._2);
        }
    }

    /**
     * Class for buffered reading int and double values
     */
    static class Reader {
        static BufferedReader reader;
        static StringTokenizer tokenizer;

        /**
         * call this method to initialize reader for InputStream
         */
        static void init(InputStream input) {
            reader = new BufferedReader(new InputStreamReader(input));
            tokenizer = new StringTokenizer("");
        }

        /**
         * get next word
         */
        static String next() throws IOException {
            while (!tokenizer.hasMoreTokens()) {
                // TODO add check for eof if necessary
                tokenizer = new StringTokenizer(reader.readLine());
            }
            return tokenizer.nextToken();
        }

        static int nextInt() throws IOException {
            return Integer.parseInt(next());
        }

        static double nextDouble() throws IOException {
            return Double.parseDouble(next());
        }
    }

    static class ArrayUtil {
        static void swap(int[] a, int i, int j) {
            int tmp = a[i];
            a[i] = a[j];
            a[j] = tmp;
        }

        static void swap(long[] a, int i, int j) {
            long tmp = a[i];
            a[i] = a[j];
            a[j] = tmp;
        }

        static void swap(double[] a, int i, int j) {
            double tmp = a[i];
            a[i] = a[j];
            a[j] = tmp;
        }

        static void swap(char[] a, int i, int j) {
            char tmp = a[i];
            a[i] = a[j];
            a[j] = tmp;
        }

        static void swap(boolean[] a, int i, int j) {
            boolean tmp = a[i];
            a[i] = a[j];
            a[j] = tmp;
        }

        static void reverse(int[] a, int i, int j) {
            for (; i < j; i++, j--)
                swap(a, i, j);
        }

        static void reverse(long[] a, int i, int j) {
            for (; i < j; i++, j--)
                swap(a, i, j);
        }

        static void reverse(double[] a, int i, int j) {
            for (; i < j; i++, j--)
                swap(a, i, j);
        }

        static void reverse(char[] a, int i, int j) {
            for (; i < j; i++, j--)
                swap(a, i, j);
        }

        static void reverse(boolean[] a, int i, int j) {
            for (; i < j; i++, j--)
                swap(a, i, j);
        }

        static long sum(int[] a) {
            int sum = 0;
            for (int i : a)
                sum += i;
            return sum;
        }

        static long sum(long[] a) {
            long sum = 0;
            for (long i : a)
                sum += i;
            return sum;
        }

        static double sum(double[] a) {
            double sum = 0;
            for (double i : a)
                sum += i;
            return sum;
        }

        static int max(int[] a) {
            int max = Integer.MIN_VALUE;
            for (int i : a)
                if (i > max) max = i;
            return max;
        }

        static int min(int[] a) {
            int min = Integer.MAX_VALUE;
            for (int i : a)
                if (i < min) min = i;
            return min;
        }

        static long max(long[] a) {
            long max = Long.MIN_VALUE;
            for (long i : a)
                if (i > max) max = i;
            return max;
        }

        static long min(long[] a) {
            long min = Long.MAX_VALUE;
            for (long i : a)
                if (i < min) min = i;
            return min;
        }
    }
}