Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.util.Scanner;
public class petr
{
    public static void main(String args[])
    {
        Scanner s= new Scanner(System.in);
        int m= s.nextInt();
        int d= s.nextInt();
        int n, a=0;
        n=30;
        if(m==1 || m==3 || m==5 || m==7 || m==8 || m==10 || m==12)
        n=31;
        else if(m==2)
        n=28;
        if(n==30)
        {
            if(d==7)
            {
                a=6;
            }
            else 
            {
                a=5;
            }
        }
        else if(n==31)
        {
            if(d>=6)
            {
                a=6;
            }
            else
            {
                a=5;
            }
        }
        else if(n==28)
        {
            if(d==1)
            {
                a=4;
            }
            else
            {
                a=5;
            }
        }
        System.out.println(a);
    }
}