Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.util.Calendar;
import java.util.GregorianCalendar;
import java.util.Scanner;

public class A {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int m = scanner.nextInt();
        int d = scanner.nextInt();
        d=d-1;
        int result =1;
        boolean start = false;
        int[] dates = {-1,31,28,31,30,31,30,31,31,30,31,30,31};
        for(int i=0;i<dates[m];i++){
            d = d%7;
            if(d == 0 && start){
                result++;
            }
            d++;
            start = true;
        }
        System.out.println(result);

    }

}