Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
from sys import stdin, stdout

M, D = [int(y) for y in stdin.readline().rstrip().split()]

months_days = { 1 : 31,
                2 : 28,
                3 : 31,
                4 : 30,
                5 : 31,
                6 : 30,
                7 : 31,
                8 : 31,
                9 : 30,
                10 : 31,
                11 : 30,
                12 : 31 }

days = months_days[M] + D - 1

remainder = True
if days % 7 == 0:
    remainder = False

if remainder:
    print (days / 7) + 1
else:
    print (days / 7)

