Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.util.*;
import java.io.*;

public class main {
	
	public static void main(String[] args){
		
		Scanner in = new Scanner(System.in);
		int m = in.nextInt();
		int d = in.nextInt();
		int p=0,j,NoC=0,q=0;
		
		int[][] A = new int[7][7];
		int[] month = new int[13];
		month[1]=month[3]=month[5]=month[7]=month[8]=month[10]=month[12]=31;
	    month[4]=month[6]=month[9]=month[11]=30;
	    month[2]=28;
	    
	    
	    for(int i=0;i<8-d;i++)
	    {
	    	A[d-1+i][0]=1+i;
	        p=1+i;
	    }
	    
	    for(int i=1;i<7;i++)
	    {
	    	for(j=0;j<7;j++)
	    	{
	    		p++;
	    		A[j][i]=p;
	    	    if(p==month[m])
	    	    {
	    		    NoC=i;
	    	    }
	    	}
	    		
	    }
	    System.out.println(NoC+1);
		 
	}

}
