There are N integers X_1, X_2, \cdots, X_N, and we know that A_i \leq X_i \leq B_i. Find the number of different values that the median of X_1, X_2, \cdots, X_N can take.

Constraints

* 2 \leq N \leq 2 \times 10^5
* 1 \leq A_i \leq B_i \leq 10^9
* All values in input are integers.

Input

Input is given from Standard Input in the following format:


N
A_1 B_1
A_2 B_2
:
A_N B_N


Output

Print the answer.

Examples

Input

2
1 2
2 3


Output

3


Input

3
100 100
10 10000
1 1000000000


Output

9991
#include <bits/stdc++.h>
using namespace std;

int main() {
    int N;  cin >> N;
    vector<long long> A(N), B(N);
    for (int i = 0; i < N; ++i) cin >> A[i] >> B[i];
    sort(A.begin(), A.end());
    sort(B.begin(), B.end());

    long long ans;
    if (N % 2) ans =  B[N / 2] - A[N / 2] + 1;
    else ans = B[N / 2 - 1] + B[N / 2] - A[N / 2 - 1] - A[N / 2] + 1;
    cout << ans << endl;
}
