Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class contst {
	public static void main(String[] args) throws IOException {
		BufferedReader br = new BufferedReader( new InputStreamReader (System.in));
		String s = br.readLine();
		StringTokenizer st = new StringTokenizer(s);
		int m = Integer.parseInt(st.nextToken());
		int d = Integer.parseInt(st.nextToken());
		int res = 0;
		switch(m){
		case 1:
		case 3:
		case 5:
		case 7:
		case 8:
		case 10:
		case 12: res = (d < 6)? 5 : 6;break;
		case 2: res = (d == 1)? 4 : 5;break;
		default: res = (d < 7)? 5 : 6;
		}
		System.out.println(res);
	}
	
	
}