Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
#include <bits/stdc++.h>
using namespace std;
const int Maxk = 1005;
string mul(string a, string b) {
  int res[Maxk];
  memset(res, 0, sizeof(res));
  reverse(a.begin(), a.end());
  reverse(b.begin(), b.end());
  for (int i = 0; i < a.length(); i++) {
    for (int j = 0; j < b.length(); j++) {
      res[i + j] += (a[i] - '0') * (b[j] - '0');
    }
  }
  for (int i = 0; i < Maxk; i++) {
    if (res[i] >= 10) {
      res[i + 1] += (res[i] / 10);
      res[i] %= 10;
    }
  }
  string ret;
  bool flag = false;
  for (int i = Maxk - 1; i >= 0; i--) {
    if (flag || res[i]) {
      flag = true;
      ret = ret + (char)(res[i] + '0');
    }
  }
  if (ret == "") ret = "0";
  return ret;
}
string add(string a, string b) {
  if (a.length() < b.length()) swap(a, b);
  while (a.length() != b.length()) {
    b = '0' + b;
  }
  for (int i = a.length() - 1; i >= 0; i--) {
    a[i] += (b[i] - '0');
    if (a[i] > '9' && i) {
      a[i] -= 10;
      a[i - 1]++;
    }
  }
  if (a[0] > '9') {
    a[0] -= 10;
    a = '1' + a;
  }
  return a;
}
const int m[] = {-1, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
int main() {
  int n, k;
  scanf("%d%d", &n, &k);
  int s = m[n];
  s--;
  int cnt = 1;
  while (s--) {
    k++;
    if (k == 8) {
      cnt++;
      k = 1;
    }
  }
  cout << cnt << endl;
}
