Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.io.*;
import java.util.*;
public class CandidateCode {
   public static void main(String args[] ) throws Exception {
      Scanner s=new Scanner(System.in);
      int a=s.nextInt();
      int b=s.nextInt();
      int c=0;
      int res=0;
      if(a==1||a==3||a==5||a==7||a==8||a==10||a==12){
         b=8-b;
         c=31-b;
         if(c%7==0){
            res=c/7;
         }else{
            res=c/7 +1;
         }
      }
      else if(a==2){
         b=8-b; 
         c=28-b;
         if(c%7==0){
            res=c/7; 
         }else{
            res=c/7 +1;
         }
      }
     else if(a==4||a==6||a==9||a==11){
        b=8-b; 
        c=30-b; 
        if(c%7==0){
           res=c/7;
        }else{
           res=c/7 +1;
        }
     } 
     System.out.print(res+1);
	//Write code here

   }
}
