Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
#!/usr/bin/env pypy3
# -*- coding: UTF-8 -*-
import sys
import re
import math
import itertools
import collections
import bisect
#sys.stdin=file('input.txt')
#sys.stdout=file('output.txt','w')
#10**9+7
mod=1000000007
#mod=1777777777
pi=3.1415926535897932
IS=float('inf')
xy=[(1,0),(-1,0),(0,1),(0,-1)]
bs=[(-1,-1),(-1,1),(1,1),(1,-1)]
def niten(a,b): return abs(a-b) if a>=0 and b>=0 else  a+abs(b) if a>=0 else abs(a)+b if b>=0 else abs(abs(a)-abs(b))
def fib(n): return [(seq.append(seq[i-2] + seq[i-1]), seq[i-2])[1] for seq in [[0, 1]] for i in range(2, n)]
def gcd(a,b): return a if b==0 else gcd(b,a%b)
def lcm(a,b): return a*b/gcd(a,b)
def eucl(x1,y1,x2,y2): return ((x1-x2)**2+(y1-y2)**2)**0.5
def choco(xa,ya,xb,yb,xc,yc,xd,yd): return 1 if abs((yb-ya)*(yd-yc)+(xb-xa)*(xd-xc))<1.e-10 else 0
def pscl(num,l=[1]):
    for i in range(num):
        l = map(lambda x,y:x+y,[0]+l,l+[0])
    return l

m,d=[int(i) for i in input().split()]
m0=[4,6,9,11]
m1=[1,3,5,7,8,10,12]
if m in m0:
    if d==7:
        ans=6
    else:
        ans=5
elif m in m1:
    if d>=6:
        ans=6
    else:
        ans=5
else:
    if d==1:
        ans=4
    else:
        ans=5
print(ans)