Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
#include <bits/stdc++.h>
using namespace std;
inline int in() {
  int x;
  cin >> x;
  return x;
}
template <typename T>
istream &operator>>(istream &in, vector<T> &vec) {
  for (int i = 0; i < vec.size(); ++i) in >> vec[i];
  return in;
}
template <typename T>
ostream &operator<<(ostream &out, const vector<T> &vec) {
  for (int i = 0; i < vec.size(); ++i) out << vec[i] << " ";
  return out;
}
int main() {
  int n = in(), m = in();
  int z;
  if (n == 2)
    z = 28;
  else if (n == 4 || n == 6 || n == 9 || n == 11)
    z = 30;
  else
    z = 31;
  z = z + m - 7 - 1;
  int f = z / 7 + (z % 7 > 0);
  cout << f + 1;
  return 0;
}
