Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.util.Objects;
import java.util.Scanner;


public class HelloWorld
{
	  
	
	
	public static void main(String[] args)
	{
		
		Scanner in = new Scanner (System.in);
		int Month= in.nextInt();
		Scanner in2 = new Scanner (System.in);
		int sDay= in.nextInt();
		sDay=8-sDay;
		double dayNum = 0;
		switch(Month){
		case 1:dayNum=31;break;
		case 3:dayNum=31;break;
		case 5:dayNum=31;break;
		case 7:dayNum=31;break;
		case 8:dayNum=31;break;
		case 10:dayNum=31;break;
		case 12:dayNum=31;break;
		
		case 2:dayNum=28;break;
		
		case 4:dayNum=30;break;
		case 6:dayNum=30;break;
		case 9:dayNum=30;break;
		case 11:dayNum=30;break;
		}
		dayNum=dayNum-sDay;

		dayNum=Math.ceil(dayNum/7);
		System.out.println((int)dayNum+1);
	}

	

}