Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
//package codeforces;


import java.util.Scanner;

public class Test {

	public static void main(String[] args) {
		Scanner input = new Scanner(System.in) ;
		int month = input.nextInt() ;
		int firstday = input.nextInt() - 1 ;
		int [] moonths = new int[12] ;
		moonths[0] = 31 ;
		moonths[1] = 28 ;
		moonths[2] = 31 ;
		moonths[3] = 30 ;
		moonths[4] = 31 ;
		moonths[5] = 30 ;
		moonths[6] = 31 ;
		moonths[7] = 31 ;
		moonths[8] = 30 ;
		moonths[9] = 31 ;
		moonths[10] = 30 ;
		moonths[11] = 31 ;
		int tot = firstday  + moonths[month - 1] ;
		int col = tot / 7; 
		if(tot %  7 != 0) {
			col ++ ;
		}
		System.out.println(col);
		input.close();
	}

}
