Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

public class Div2_760A {

	public static void main(String[] args) throws IOException {
		BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));

		StringTokenizer inputData = new StringTokenizer(reader.readLine());
		int m = Integer.parseInt(inputData.nextToken());
		int wD = Integer.parseInt(inputData.nextToken());

		int nD;
		if (m == 2) {
			nD = 28;
		} else if (m <= 7 && (m & 1) == 1) {
			nD = 31;
		} else if (8 <= m && (m & 1) == 0) {
			nD = 31;
		} else {
			nD = 30;
		}

		int cD = 1;
		int numC = 1;

		if (wD != 1) {
			cD += 8 - wD;
			wD = 1;
			numC++;
		}

		while (cD + 7 <= nD) {
			cD += 7;
			numC++;
		}
		System.out.println(numC);

	}

}
