Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.util.Scanner;
public class P760A
{
	public static void main(String[] args)
	{
	 Scanner scan=new Scanner(System.in);
	 int m,d,tot,noc=0;
	 m=scan.nextInt();
	 d=scan.nextInt();
	 if(m==1||m==3||m==5||m==7||m==8||m==10||m==12)
		tot=31;
	 else if(m==2)
		tot=28;
	 else
		tot=30;
	 tot-=(7-d+1);
	 ++noc;
	 if(tot%7==0)
		noc+=tot/7;
	 else
		noc+=tot/7+1;
	 System.out.println(noc);
	}
}