You have a computer literacy course in your university. In the computer system, the login/logout records of all PCs in a day are stored in a file. Although students may use two or more PCs at a time, no one can log in to a PC which has been logged in by someone who has not logged out of that PC yet.

You are asked to write a program that calculates the total time of a student that he/she used at least one PC in a given time period (probably in a laboratory class) based on the records in the file.

The following are example login/logout records.

* The student 1 logged in to the PC 1 at 12:55
* The student 2 logged in to the PC 4 at 13:00
* The student 1 logged in to the PC 2 at 13:10
* The student 1 logged out of the PC 2 at 13:20
* The student 1 logged in to the PC 3 at 13:30
* The student 1 logged out of the PC 1 at 13:40
* The student 1 logged out of the PC 3 at 13:45
* The student 1 logged in to the PC 1 at 14:20
* The student 2 logged out of the PC 4 at 14:30
* The student 1 logged out of the PC 1 at 14:40


For a query such as "Give usage of the student 1 between 13:00 and 14:30", your program should answer "55 minutes", that is, the sum of 45 minutes from 13:00 to 13:45 and 10 minutes from 14:20 to 14:30, as depicted in the following figure.

<image>



Input

The input is a sequence of a number of datasets. The end of the input is indicated by a line containing two zeros separated by a space. The number of datasets never exceeds 10.

Each dataset is formatted as follows.

> N M
>  r
>  record1
>  ...
>  recordr
>  q
>  query1
>  ...
>  queryq
>

The numbers N  and M  in the first line are the numbers of PCs and the students, respectively. r  is the number of records. q  is the number of queries. These four are integers satisfying the following.

> 1 ≤ N  ≤ 1000, 1 ≤ M  ≤ 10000, 2 ≤ r  ≤ 1000, 1 ≤ q  ≤ 50

Each record consists of four integers, delimited by a space, as follows.

> t  n  m  s

s  is 0 or 1. If s  is 1, this line means that the student m  logged in to the PC n  at time t . If s  is 0, it means that the student m  logged out of the PC n  at time t . The time is expressed as elapsed minutes from 0:00 of the day. t , n  and m  satisfy the following.

> 540 ≤ t  ≤ 1260, 1 ≤ n  ≤ N , 1 ≤ m  ≤ M

You may assume the following about the records.
* Records are stored in ascending order of time t.
* No two records for the same PC has the same time t.
* No PCs are being logged in before the time of the first record nor after that of the last record in the file.
* Login and logout records for one PC appear alternatingly, and each of the login-logout record pairs is for the same student.

Each query consists of three integers delimited by a space, as follows.

> ts  te  m

It represents "Usage of the student m  between ts  and te ". ts , te  and m  satisfy the following.

> 540 ≤ ts  < te  ≤ 1260, 1 ≤ m  ≤ M

Output

For each query, print a line having a decimal integer indicating the time of usage in minutes. Output lines should not have any character other than this number.

Example

Input

4 2
10
775 1 1 1
780 4 2 1
790 2 1 1
800 2 1 0
810 3 1 1
820 1 1 0
825 3 1 0
860 1 1 1
870 4 2 0
880 1 1 0
1
780 870 1
13 15
12
540 12 13 1
600 12 13 0
650 13 15 1
660 12 15 1
665 11 13 1
670 13 15 0
675 11 13 0
680 12 15 0
1000 11 14 1
1060 12 14 1
1060 11 14 0
1080 12 14 0
3
540 700 13
600 1000 15
1000 1200 11
1 1
2
600 1 1 1
700 1 1 0
5
540 600 1
550 650 1
610 620 1
650 750 1
700 800 1
0 0


Output

55
70
30
0
0
50
10
50
0
#include<iostream>
#include<cstring>
using namespace std;

int t[1005];
bool used[10005][1000];

int main(){
	int n,m,r,q;
	int a,b,c,d;
	int i,j,k;
	while(cin>>n>>m){
		if(!n)break;
		memset(used,false,sizeof(used));
		cin>>r;
		for(i=0;i<r;i++){
			cin>>a>>b>>c>>d;
			a-=540,b--,c--;
			if(d==1)t[b]=a;
			else{
				for(j=t[b];j<a;j++)used[c][j]=true;
			}
		}
		cin>>q;
		for(i=0;i<q;i++){
			cin>>a>>b>>c;
			a-=540,b-=540,c--,d=0;
			for(j=a;j<b;j++)if(used[c][j])d++;
			cout<<d<<endl;
		}
	}
}

