Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
#include <bits/stdc++.h>
using namespace std;
const long long int N = 1e5 + 5;
const long long int INF = 1e18;
const long long int mod = 1e9 + 7;
int main() {
  long long int n, m;
  cin >> n >> m;
  if (n == 2) {
    long long int cur = (7 - m + 1) % 7;
    long long int rem = 28 - cur;
    long long int col = rem / 7;
    long long int colrem = rem % 7;
    if (cur) {
      cur = 1;
    }
    if (colrem == 0) {
      cout << cur + col << endl;
    } else {
      cout << 1 + cur + col << endl;
    }
  } else if (n <= 7) {
    if (n % 2) {
      long long int cur = (7 - m + 1) % 7;
      long long int rem = 31 - cur;
      long long int col = rem / 7;
      long long int colrem = rem % 7;
      if (cur) {
        cur = 1;
      }
      if (colrem == 0) {
        cout << cur + col << endl;
      } else {
        cout << 1 + cur + col << endl;
      }
    } else {
      long long int cur = (7 - m + 1) % 7;
      long long int rem = 30 - cur;
      long long int col = rem / 7;
      long long int colrem = rem % 7;
      if (cur) {
        cur = 1;
      }
      if (colrem == 0) {
        cout << cur + col << endl;
      } else {
        cout << 1 + cur + col << endl;
      }
    }
  } else if (n > 7) {
    if (n % 2) {
      long long int cur = (7 - m + 1) % 7;
      long long int rem = 30 - cur;
      long long int col = rem / 7;
      long long int colrem = rem % 7;
      if (cur) {
        cur = 1;
      }
      if (colrem == 0) {
        cout << cur + col << endl;
      } else {
        cout << 1 + cur + col << endl;
      }
    } else {
      long long int cur = (7 - m + 1) % 7;
      long long int rem = 31 - cur;
      long long int col = rem / 7;
      long long int colrem = rem % 7;
      if (cur) {
        cur = 1;
      }
      if (colrem == 0) {
        cout << cur + col << endl;
      } else {
        cout << 1 + cur + col << endl;
      }
    }
  }
}
