Andrew was very excited to participate in Olympiad of Metropolises. Days flew by quickly, and Andrew is already at the airport, ready to go home. He has n rubles left, and would like to exchange them to euro and dollar bills. Andrew can mix dollar bills and euro bills in whatever way he wants. The price of one dollar is d rubles, and one euro costs e rubles.

Recall that there exist the following dollar bills: 1, 2, 5, 10, 20, 50, 100, and the following euro bills — 5, 10, 20, 50, 100, 200 (note that, in this problem we do not consider the 500 euro bill, it is hard to find such bills in the currency exchange points). Andrew can buy any combination of bills, and his goal is to minimize the total number of rubles he will have after the exchange.

Help him — write a program that given integers n, e and d, finds the minimum number of rubles Andrew can get after buying dollar and euro bills.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 10^8) — the initial sum in rubles Andrew has. 

The second line of the input contains one integer d (30 ≤ d ≤ 100) — the price of one dollar in rubles. 

The third line of the input contains integer e (30 ≤ e ≤ 100) — the price of one euro in rubles.

Output

Output one integer — the minimum number of rubles Andrew can have after buying dollar and euro bills optimally.

Examples

Input


100
60
70


Output


40


Input


410
55
70


Output


5


Input


600
60
70


Output


0

Note

In the first example, we can buy just 1 dollar because there is no 1 euro bill.

In the second example, optimal exchange is to buy 5 euro and 1 dollar.

In the third example, optimal exchange is to buy 10 dollars in one bill.

/* package codechef; // don't place package name! */
 
import java.util.*;
import java.lang.*;
import java.io.*;
 
/* Name of the class has to be "Main" only if the class is public. */
public class AA
{
	public static void main (String[] args) throws java.lang.Exception
	{
		// your code goes here
		Scanner sc=new Scanner(System.in);
		int n,d,e,min=Integer.MAX_VALUE;
		n=sc.nextInt();
		d=sc.nextInt();
		e=sc.nextInt();
        while(n>=0)
        {
            min=Math.min(min,n%d);
            n=n-(5*e);
        }
        System.out.println(min);
	}
}