Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.util.Scanner;

public class Petrandacalendar760A {


	private static Scanner scan;

	public static void main(String[] args) {

		scan = new Scanner(System.in);

		int month = scan.nextInt();
		int firstDay = scan.nextInt();

		double monthDays = 0;

		switch (month) {
		case 4:
			monthDays = 30;
			break;
		case 6:
			monthDays = 30;
			break;
		case 9:
			monthDays = 30;
			break;
		case 11:
			monthDays = 30;
			break;
		case 2:
			monthDays = 28;
			break;
			default:
				monthDays = 31;
				break;


		}
		int columns = 1;

		double firstWeek = 8-firstDay;
		monthDays -= firstWeek;
		double answer = Math.ceil((monthDays/7));
		columns += answer;

		System.out.println(columns);





		}
	}
