Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
n=input().split()
k=int(n[0])
h=int(n[1])
if (k==1) or (k==3) or (k==5) or (k==7) or (k==8) or (k==10) or (k==12):
    if (h==6) or (h==7):
        print(6)
    else:
        print(5)
if k==2:
    if h==1:
        print(4)
    else:
        print(5)
if (k==4) or (k==6) or (k==9) or (k==11):
    if  (h==7):
        print(6)
    else:
        print(5)