Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class Calendar {
	private static int month, firstday;
	private static int[] monthLength = {31,28,31,30,31,30,31,31,30,31,30,31};

	public static void main(String[] args) throws IOException {
		//FileReader file = new FileReader("test.txt");
		//BufferedReader in = new BufferedReader(file);
		
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		
		String[] parts = in.readLine().split(" ");
		month = Integer.parseInt(parts[0]);
		firstday = Integer.parseInt(parts[1]);
		
		int days = monthLength[month-1] + firstday - 1;
		System.out.println((int)Math.ceil(days/7.0));
	}

}
