Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.util.*;
import java.io.*;


public class A {
	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		 int a, b, cnt = 0, left; 
		 int[] m = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

		a = in.nextInt();
		b = in.nextInt();

		left = m[a-1];
		if(b != 1) { left -= (8-b); cnt = 1; }
		if(left % 7 == 0) cnt += (left / 7);
		else cnt += (left / 7 + 1);


		System.out.println(cnt);

	}
}