Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.util.*;
import java.lang.*;
import java.math.*;
public class Main{
	public static void main(String[] args) {
      Scanner sc= new Scanner(System.in);
      int m=sc.nextInt();
      int d=sc.nextInt();
      int add=0,j,ans=0;
      if(m==2){
      	if(d<=7){
      		ans=7-d;
      		add++;
      	}
      	for(j=1+ans+7;j<=28;j=j+7)
      		add++;
      	if(j-7<28)
      		add++;
      }
      if((m%2!=0&&m<8)||m==8||m==10||m==12){
      	if(d<=7){
      		ans=7-d;
      		add++;
      	}
      	for(j=1+ans+7;j<=31;j=j+7)
      		add++;
      	if(j-7<31)
      		add++;
      }
      else if((m%2==0&&m<7&&m!=2)||m==9||m==11){
      	if(d<=7){
      		ans=7-d;
      		add++;
      	}
      	for(j=1+ans+7;j<=30;j=j+7)
      		add++;
      	if(j-7<30)
      		add++;
      }
      System.out.println(add);
    }
}