You are given two strings a and b. You have to remove the minimum possible number of consecutive (standing one after another) characters from string b in such a way that it becomes a subsequence of string a. It can happen that you will not need to remove any characters at all, or maybe you will have to remove all of the characters from b and make it empty.

Subsequence of string s is any such string that can be obtained by erasing zero or more characters (not necessarily consecutive) from string s.

Input

The first line contains string a, and the second line — string b. Both of these strings are nonempty and consist of lowercase letters of English alphabet. The length of each string is no bigger than 105 characters.

Output

On the first line output a subsequence of string a, obtained from b by erasing the minimum number of consecutive characters.

If the answer consists of zero characters, output «-» (a minus sign).

Examples

Input

hi
bob


Output

-


Input

abca
accepted


Output

ac


Input

abacaba
abcdcba


Output

abcba

Note

In the first example strings a and b don't share any symbols, so the longest string that you can get is empty.

In the second example ac is a subsequence of a, and at the same time you can obtain it by erasing consecutive symbols cepted from string b.
#include <bits/stdc++.h>
using namespace std;
template <typename T>
using min_pq = priority_queue<T, vector<T>, greater<T>>;
template <typename T>
using max_pq = priority_queue<T>;
const int inf = 2e9 + 5;
const long long l_inf = 2e18 + 5;
const int mod_v = 1e9 + 7;
const int max_n = 1e5 + 5;
const int dx[4] = {-1, 0, 1, 0};
const int dy[4] = {0, 1, 0, -1};
template <typename T>
T gcd(T a, T b) {
  while (b) {
    T temp = a % b;
    a = b;
    b = temp;
  }
  return a;
}
template <typename T>
tuple<T, T, T> egcd(T a, T b) {
  T x1 = 1, x2 = 0, y1 = 0, y2 = 1;
  while (b) {
    T q = a / b, r = a % b;
    T new_x = x1 - q * x2, new_y = y1 - q * y2;
    x1 = x2, y1 = y2, x2 = new_x, y2 = new_y;
    a = b, b = r;
  }
  return make_tuple(a, x1, y1);
}
inline long long lcm(long long a, long long b) { return a * b / gcd(a, b); }
template <typename T>
inline T mod(T a, T b = mod_v) {
  return (a % b + b) % b;
}
template <typename T>
inline T mod_inv(T a, T b = mod_v) {
  return mod(get<1>(egcd(a, b)), b);
}
template <typename T>
inline T sum(T a, T b, T m = mod_v) {
  return mod(mod(a, m) + mod(b, m), m);
}
template <typename T>
inline T difference(T a, T b, T m = mod_v) {
  return mod(mod(a, m) - mod(b, m), m);
}
inline long long product(long long a, long long b, long long m = mod_v) {
  return mod(mod(a, m) * mod(b, m), m);
}
inline long long quotient(long long a, long long b, long long m = mod_v) {
  return mod(mod(a, m) * mod_inv(b, m), m);
}
template <typename T, typename T2>
ostream &operator<<(ostream &s, const pair<T, T2> &p) {
  return s << p.first << ' ' << p.second << ' ';
}
template <typename T, typename T2>
istream &operator>>(istream &s, pair<T, T2> &p) {
  return s >> p.first >> p.second;
}
template <typename T>
ostream &operator<<(ostream &s, const vector<T> &v) {
  for (auto it : v) s << it << ' ';
  return s;
}
template <typename T>
istream &operator>>(istream &s, vector<T> &v) {
  for (auto it = (v).begin(), it_ = (v).end(); it != it_; ++it) s >> *it;
  return s;
}
template <typename T>
void read_range(T beg, T end) {
  while (beg != end) cin >> *beg++;
}
template <typename T>
void print_range(T beg, T end) {
  while (beg != end) cout << *beg++ << ' ';
}
struct reader {
  template <typename T>
  reader &operator,(T &v) {
    cin >> v;
    return *this;
  }
} rdr;
struct debugger {
  template <typename T>
  debugger &operator,(const T &v) {
    cerr << v << ", ";
    return *this;
  }
} dbg;
int ar[max_n], ar2[max_n];
string s, t;
bool f(int st, int len) {
  if (st == 0 and len == t.length()) return true;
  if (st == 0) return ar2[len] >= 0;
  if (st + len == t.length()) return ar[st - 1] < s.length();
  return ar[st - 1] < ar2[st + len];
}
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cin >> s >> t;
  int pos = 0;
  for (int i = 0; i < t.length(); ++i) {
    while (pos < s.length() and s[pos] != t[i]) ++pos;
    ar[i] = pos;
    ++pos;
  }
  pos = s.length() - 1;
  for (int i = t.length() - 1; i >= 0; --i) {
    while (pos >= 0 and s[pos] != t[i]) --pos;
    ar2[i] = pos;
    --pos;
  }
  int ans = t.length(), l = 0, r = t.length() - 1;
  for (int i = 0; i < t.length(); ++i) {
    int lo = 0, hi = t.length() - i;
    while (lo < hi) {
      int md = (lo + hi) / 2;
      if (f(i, md))
        hi = md;
      else
        lo = md + 1;
    }
    if (f(i, lo) and lo < ans) {
      ans = lo;
      l = i;
      r = i + lo - 1;
    }
  }
  if (l == 0 and r == t.length() - 1)
    cout << "-";
  else
    for (int i = 0; i < t.length(); ++i)
      if (i < l or i > r) cout << t[i];
  return 0;
}
