Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
from calendar import monthrange
n , k = map(int,input().strip().split())
l1 = [0,1,2,3,4,5,6,7]
l2 = 7 - l1[k] + 1
NOD = max(monthrange(2017,n))
A = []
if 7 - l1[k] == 0:
    A.append(1)
else:
    A.append(7-l1[k]+1)
for i in range(A[0]+7,NOD + 1,7):
    if i <= NOD:
        A.append(i)
    if NOD - i < 7 and (NOD - i + i) not in A:
        A.append(NOD - i + i)
print(len(A))

