Iahub likes chess very much. He even invented a new chess piece named Coder. A Coder can move (and attack) one square horizontally or vertically. More precisely, if the Coder is located at position (x, y), he can move to (or attack) positions (x + 1, y), (x–1, y), (x, y + 1) and (x, y–1).

Iahub wants to know how many Coders can be placed on an n × n chessboard, so that no Coder attacks any other Coder.

Input

The first line contains an integer n (1 ≤ n ≤ 1000).

Output

On the first line print an integer, the maximum number of Coders that can be placed on the chessboard.

On each of the next n lines print n characters, describing the configuration of the Coders. For an empty cell print an '.', and for a Coder print a 'C'.

If there are multiple correct answers, you can print any.

Examples

Input

2


Output

2
C.
.C
"""
██╗ ██████╗ ██╗    ██████╗  ██████╗  ██╗ █████╗
██║██╔═══██╗██║    ╚════██╗██╔═████╗███║██╔══██╗
██║██║   ██║██║     █████╔╝██║██╔██║╚██║╚██████║
██║██║   ██║██║    ██╔═══╝ ████╔╝██║ ██║ ╚═══██║
██║╚██████╔╝██║    ███████╗╚██████╔╝ ██║ █████╔╝
╚═╝ ╚═════╝ ╚═╝    ╚══════╝ ╚═════╝  ╚═╝ ╚════╝
"""                                        
__author__ = "Dilshod"
n = int(input())
if not n % 2:
	print(n * (n // 2))
else:
	print((n // 2 + 1) ** 2 + (n // 2) ** 2)
a = True
if n % 2:
	for i in range(n):
		ans = ""
		if a:
			ans += "C." * (n // 2) + "C"
			a = False
		else:
			ans += ".C" * (n // 2) + "."
			a = True
		print(ans)
else:
	for i in range(n):
		ans = ""
		if a:
			ans += "C." * (n // 2)
			a = False
		else:
			ans += ".C" * (n // 2)
			a = True
		print(ans)
