Snuke has an integer sequence, a, of length N. The i-th element of a (1-indexed) is a_{i}.

He can perform the following operation any number of times:

* Operation: Choose integers x and y between 1 and N (inclusive), and add a_x to a_y.



He would like to perform this operation between 0 and 2N times (inclusive) so that a satisfies the condition below. Show one such sequence of operations. It can be proved that such a sequence of operations always exists under the constraints in this problem.

* Condition: a_1 \leq a_2 \leq ... \leq a_{N}

Constraints

* 2 \leq N \leq 50
* -10^{6} \leq a_i \leq 10^{6}
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
a_1 a_2 ... a_{N}


Output

Let m be the number of operations in your solution. In the first line, print m. In the i-th of the subsequent m lines, print the numbers x and y chosen in the i-th operation, with a space in between. The output will be considered correct if m is between 0 and 2N (inclusive) and a satisfies the condition after the m operations.

Examples

Input

3
-2 5 -1


Output

2
2 3
3 3


Input

2
-1 -3


Output

1
2 1


Input

5
0 0 0 0 0


Output

0
#include <iostream>

using namespace std;

int main(int argc, char *argv[]) {
	int N;
	cin >> N;

	int min = 0, max = 0;
	int min_idx = 0, max_idx = 0;
	for (int i = 0; i < N; i++) {
		int A;
		cin >> A;
		if (min > A) {
			min = A; min_idx = i;
		}

		if (max < A) {
			max = A; max_idx = i;
		}
	}

	cout << 2 * N - 1 << endl;
	if (abs(min) < abs(max)) {
		for (int i = 0; i < N; i++) {
			//A[i] += max;
			cout << max_idx + 1 << " " << i + 1 << endl;
		}

		for (int i = 0; i < N - 1; i++) {
			//A[i + 1] += A[i];
			cout << i + 1 << " " << i + 2 << endl;
		}
	} else {
		for (int i = 0; i < N; i++) {
			//A[i] += min;
			cout << min_idx + 1 << " " << i + 1 << endl;
		}

		for (int i = N - 1; i >= 1; i--) {
			//A[i - 1] += A[i];
			cout << i + 1 << " " << i << endl;
		}
	}

	return 0;
}