Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.util.Scanner;

public class Main{
	public static void main(String[]args){
		Scanner sc = new Scanner(System.in);
//		ArrayList <String> al = new ArrayList<String>();
		String[] input;
		int[] daysInMonth = {31,28,31,30,31,30,31,31,30,31,30,31};
		while(sc.hasNextLine()){
			input = sc.nextLine().split(" ");
			int m = Integer.parseInt(input[0]);
			int d = Integer.parseInt(input[1]);
			int totalDays = daysInMonth[m-1];
			int cols = ((totalDays + (d-1))/7);
			if((totalDays + (d-1))%7!=0){
				cols++;
			}
			System.out.println(cols);

		}

	}


}

    		   			  	 			    			 	