Snuke has an integer sequence, a, of length N. The i-th element of a (1-indexed) is a_{i}.

He can perform the following operation any number of times:

* Operation: Choose integers x and y between 1 and N (inclusive), and add a_x to a_y.



He would like to perform this operation between 0 and 2N times (inclusive) so that a satisfies the condition below. Show one such sequence of operations. It can be proved that such a sequence of operations always exists under the constraints in this problem.

* Condition: a_1 \leq a_2 \leq ... \leq a_{N}

Constraints

* 2 \leq N \leq 50
* -10^{6} \leq a_i \leq 10^{6}
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
a_1 a_2 ... a_{N}


Output

Let m be the number of operations in your solution. In the first line, print m. In the i-th of the subsequent m lines, print the numbers x and y chosen in the i-th operation, with a space in between. The output will be considered correct if m is between 0 and 2N (inclusive) and a satisfies the condition after the m operations.

Examples

Input

3
-2 5 -1


Output

2
2 3
3 3


Input

2
-1 -3


Output

1
2 1


Input

5
0 0 0 0 0


Output

0
#include <iostream>
#include <cstdio>
#include <cstring>
#include <climits>
#include <string>
#include <algorithm>
#include <cmath>
#include <vector>
#include <stack>
#include <queue>
#include <map>
#include <sstream>
using namespace std;
typedef pair<int, int> pii;
typedef long long int ll;

int N, a;
int m;
int idx = 1;

int main() {

  cin >> N;
  for(int i = 1; i <= N; i++) {
    cin >> a;
    if (abs(a) > abs(m)) {
      m = a;
      idx = i;
    }
  }

  cout << 2 * N - 2 << endl;
  for(int i = 1; i <= N; i++) {
    if (i == idx) {
      continue;
    }
    cout << idx << " " << i << endl;
  }

  for(int i = 1; i < N; i++) {
    if (m >= 0) {
      cout << i << " " << i + 1 << endl;
    } else {
      cout << N - i + 1 << " " << N - i << endl;
    }
  }

  return 0;
}
