Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.io.*;
import java.util.*;

public class Calender
{
	public static void main(String[] args)
	{
		int[] month = new int[13];
		month[1] = month[3] = month[5] = month[7] = month[8] = month[10] = month[12]= 31;
		month[4] =  month[6] = month[9] = month[11] = 30;
		month[2] = 28;
		
		Scanner in = new Scanner(System.in);
		int m = in.nextInt();
		int d = in.nextInt();
		
		int count =1;
		int p = month[m] - 8 +d;
	    p = p - 28;
	    
	    if(p>0)
	    	System.out.println(count+5);
	    else if(p<=-7)
			System.out.println(count+3);
		else
			System.out.println(count+4);
	}
}