Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.util.HashMap;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		HashMap daysInEachMonth = new HashMap();
		daysInEachMonth.put(1,31);
		daysInEachMonth.put(2,28);
		daysInEachMonth.put(3,31);
		daysInEachMonth.put(4,30);
		daysInEachMonth.put(5,31);
		daysInEachMonth.put(6,30);
		daysInEachMonth.put(7,31);
		daysInEachMonth.put(8,31);
		daysInEachMonth.put(9,30);
		daysInEachMonth.put(10,31);
		daysInEachMonth.put(11,30);
		daysInEachMonth.put(12,31);
		
		
		int d,m,numOfDays,numOfCols;
		int firstCol;
		Scanner in = new Scanner(System.in);
		m = in.nextInt();
		d = in.nextInt();
		numOfDays = (int) daysInEachMonth.get(m);
		firstCol = d - 8 < 0 ? (d-8)*-1 : d-8;
		numOfCols = 1;
		numOfCols += (numOfDays-firstCol) / 7 ;
		numOfCols += (numOfDays-firstCol) % 7 == 0? 0 : 1;
		System.out.println(numOfCols);
		
		
	}

}
