Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
first_line = map(int, raw_input().split())
m = first_line[0]
d = first_line[1]

thirty_one = [1, 3, 5, 7, 8, 10, 12]

col = 1
if(m in thirty_one):
  first_col = 7-d+1
  col += (31-first_col) / 7
  if((31-first_col) % 7 != 0):
    col += 1

elif(m not in thirty_one and m != 2):
  first_col = 7-d+1
  col += (30-first_col) / 7
  if((30-first_col) % 7 != 0):
    col += 1

else:
  first_col = 7-d+1
  col += (28-first_col) / 7
  if((28-first_col) % 7 != 0):
    col += 1

print col