Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.util.Scanner;


public class JavaApplication17 {

    
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        int m,d,c=0;
        m=sc.nextInt();
        d=sc.nextInt();
        if(m==1||m==3||m==5||m==7||m==8||m==10||m==12){
        if(d==6||d==7){
           c=6; 
        }
        else
            c=5;
            
    }
        else if(m==2){
               if(d==1){
                   c=4;
               } 
               else
                   c=5;
                }
        else{
            if(d==7){
                c=6;
            }
            else
                c=5;
        }
        System.out.println(c);
    }
    
}