Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.util.Scanner;

public class Ideone {

	public static void main(String[] args) 
	{
		// TODO Auto-generated method stub
		Scanner sc = new Scanner(System.in);
		int m = sc.nextInt();
		int d = sc.nextInt();
		if(m==1 || m==3 || m==5 || m==7||m==8 || m==10|| m==12)
		{
			int val = 7-d+1;
			int daysleft = 31-val;
			for(int i=1;i<=6;i++)
			{
				if(7*i>=daysleft)
				{
					System.out.println(i+1);
					break;
				}
			}
		}
		else if(m==2)
		{
			int val = 7-d+1;
			int daysleft = 28	-val;
			for(int i=1;i<=6;i++)
			{
				if(7*i>=daysleft)
				{
					System.out.println(i+1);
					break;
				}
			}
		}
		else
		{
			int val = 7-d+1;
			int daysleft = 30-val;
			for(int i=1;i<=6;i++)
			{
				if(7*i>=daysleft)
				{
					System.out.println(i+1);
					break;
				}
			}
		}
		sc.close();
	}
}