Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
def Main(m, d):
  month = [31, 28, 31, 30,31,30,31,31,30,31,30,31]
  # print(len(month))
  # print(sum(month))

  day = [1,2,3,4,5,6,7]
  M = month[m - 1]

  if M == 31 and (d == 6 or d == 7):
    print(6)
    return 0
  if M == 31 and ( 1 <= d <= 5):
    print(5)
    return 0
  if M == 30 and d == 7:
    print(6)
    return 0
  if M == 30 and (1 <= d <= 6):
    print(5)
    return 0

  if M == 28 and d == 1:
    print(4)
    return 0
  if M == 28 and  (2 <= d <= 7):
    print(5)



  # rez = day[d - 1]
  # col = 0
  # sm = 0
  # for i in range(d , 50):
  #   if i % 7 == 0:
  #     col += 1
  #   sm += 1
  #   if sm > M:
  #     break
  #
  # print(i)
  # print(col)
  # print(sm)

if __name__ == '__main__':
  m , d = map(int, input().split())
  Main(m,d)