Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.io.PrintWriter;
import java.util.*;

public class A393 {
	public static boolean flag;
	public static String color = "RBYG";
	public static StringBuffer s;
	public static int D,M,A[] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
	public static int ans[] = new int[color.length()];

	public static void main(String[] args) {
		Scanner cin = new Scanner(System.in);
		PrintWriter out = new PrintWriter(System.out);
		M = cin.nextInt();
		D = cin.nextInt();

		int i = 1, j = D;
		for(i=1; A[M] > 0; i++) {
			
			for(; j<=7 && A[M] > 0; j++) {
				A[M]--;
			}
			j = 1;
		}
		out.printf("%d\n", i-1);
		cin.close();
		out.flush();
	}
}
