Snuke has an integer sequence, a, of length N. The i-th element of a (1-indexed) is a_{i}.

He can perform the following operation any number of times:

* Operation: Choose integers x and y between 1 and N (inclusive), and add a_x to a_y.



He would like to perform this operation between 0 and 2N times (inclusive) so that a satisfies the condition below. Show one such sequence of operations. It can be proved that such a sequence of operations always exists under the constraints in this problem.

* Condition: a_1 \leq a_2 \leq ... \leq a_{N}

Constraints

* 2 \leq N \leq 50
* -10^{6} \leq a_i \leq 10^{6}
* All input values are integers.

Input

Input is given from Standard Input in the following format:


N
a_1 a_2 ... a_{N}


Output

Let m be the number of operations in your solution. In the first line, print m. In the i-th of the subsequent m lines, print the numbers x and y chosen in the i-th operation, with a space in between. The output will be considered correct if m is between 0 and 2N (inclusive) and a satisfies the condition after the m operations.

Examples

Input

3
-2 5 -1


Output

2
2 3
3 3


Input

2
-1 -3


Output

1
2 1


Input

5
0 0 0 0 0


Output

0
#include <cstdio>
#include <iostream>
#include <cmath>
#include <cstring>
#include <sstream>
#include <algorithm>
#include <cstdlib>
#include <map>
#include <queue>
#include <utility>
#include <vector>
#include <set>
#include <memory.h>
#include <iomanip>
#include <bitset>
#include <list>
#include <stack>
#include <deque>

using namespace std;

#define mod 1000000007

int main()
{
	int n;
	cin >> n;
	int a[100001];
	int tmp = 0;
	for(int i = 0; i < n; i++){
		cin >> a[i];
		if(abs(a[tmp]) < abs(a[i])) tmp = i;
	}
	cout << 2 * n - 2 << endl;
	for(int i = 0; i < n; i++){
		if(i != tmp) cout << tmp + 1 << " " << i + 1 << endl;
	}
	if(a[tmp] > 0){
		for(int i = 1; i < n; i++){
			cout << i << " " << i + 1 << endl;
		}
	} else {
		for(int i = n; i > 1; i--){
			cout << i << " " << i - 1 << endl;
		}
	}
	return 0;
}