Bob is an avid fan of the video game "League of Leesins", and today he celebrates as the League of Leesins World Championship comes to an end! 

The tournament consisted of n (n ≥ 5) teams around the world. Before the tournament starts, Bob has made a prediction of the rankings of each team, from 1-st to n-th. After the final, he compared the prediction with the actual result and found out that the i-th team according to his prediction ended up at the p_i-th position (1 ≤ p_i ≤ n, all p_i are unique). In other words, p is a permutation of 1, 2, ..., n.

As Bob's favorite League player is the famous "3ga", he decided to write down every 3 consecutive elements of the permutation p. Formally, Bob created an array q of n-2 triples, where q_i = (p_i, p_{i+1}, p_{i+2}) for each 1 ≤ i ≤ n-2. Bob was very proud of his array, so he showed it to his friend Alice.

After learning of Bob's array, Alice declared that she could retrieve the permutation p even if Bob rearranges the elements of q and the elements within each triple. Of course, Bob did not believe in such magic, so he did just the same as above to see Alice's respond.

For example, if n = 5 and p = [1, 4, 2, 3, 5], then the original array q will be [(1, 4, 2), (4, 2, 3), (2, 3, 5)]. Bob can then rearrange the numbers within each triple and the positions of the triples to get [(4, 3, 2), (2, 3, 5), (4, 1, 2)]. Note that [(1, 4, 2), (4, 2, 2), (3, 3, 5)] is not a valid rearrangement of q, as Bob is not allowed to swap numbers belong to different triples.

As Alice's friend, you know for sure that Alice was just trying to show off, so you decided to save her some face by giving her any permutation p that is consistent with the array q she was given. 

Input

The first line contains a single integer n (5 ≤ n ≤ 10^5) — the size of permutation p.

The i-th of the next n-2 lines contains 3 integers q_{i, 1}, q_{i, 2}, q_{i, 3} (1 ≤ q_{i, j} ≤ n) — the elements of the i-th triple of the rearranged (shuffled) array q_i, in random order. Remember, that the numbers within each triple can be rearranged and also the positions of the triples can be rearranged.

It is guaranteed that there is at least one permutation p that is consistent with the input. 

Output

Print n distinct integers p_1, p_2, …, p_n (1 ≤ p_i ≤ n) such that p is consistent with array q. 

If there are multiple answers, print any. 

Example

Input


5
4 3 2
2 3 5
4 1 2


Output


1 4 2 3 5 

/**
 * Date: 19 Nov, 2019
 * Link: https://codeforces.com/contest/1255/problem/C
 * 
 * @author Prasad Chaudhari
 * @linkedIn: https://www.linkedin.com/in/prasad-chaudhari-841655a6/
 * @git: https://github.com/Prasad-Chaudhari
 */
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collection;
import java.util.Collections;
import java.util.Comparator;
import java.util.LinkedList;
import java.util.PriorityQueue;

public class C_1255 {

    public static void main(String[] args) throws IOException {
        // TODO code application logic here
        FastIO in = new FastIO();
        int n = in.ni();
        ArrayList<LinkedList<Integer>> q = new ArrayList<>();
        ArrayList<LinkedList<Integer>> pos = new ArrayList<>();
        for (int i = 0; i <= n; i++) {
            pos.add(new LinkedList<>());
        }
        for (int i = 0; i < n - 2; i++) {
            LinkedList<Integer> l = new LinkedList<>();
            for (int j = 0; j < 3; j++) {
                int p = in.ni();
                l.add(p);
                pos.get(p).add(i);
            }
            Collections.sort(l);
            q.add(l);
        }
        int one = -1;
        for (int i = 1; i <= n; i++) {
            if (pos.get(i).size() == 1) {
                one = i;
                break;
            }
        }
        // System.out.println(one);
        Collections.sort(q.get(pos.get(one).peek()), new Comparator<Integer>() {
            @Override
            public int compare(Integer a, Integer b) {
                return Integer.compare(pos.get(a).size(), pos.get(b).size());
            }
        });
        // print(q.get(pos.get(one).peek()));
        LinkedList<Integer> ans = new LinkedList<>();
        Comparator<LinkedList<Integer>> c = new Comparator<LinkedList<Integer>>() {
            @Override
            public int compare(LinkedList<Integer> a, LinkedList<Integer> b) {
                return Integer.compare(a.size(), b.size());
            }
        };
        PriorityQueue<LinkedList<Integer>> pq = new PriorityQueue<>(c);
        pq.add(q.get(pos.get(one).peek()));
        for (int i = 0; i < n; i++) {
            LinkedList<Integer> p = new LinkedList<>();
            while (!pq.isEmpty()) {
                p = pq.remove();
                if (p.size() != 0) {
                    break;
                }
            }
            // print(p);
            PriorityQueue<LinkedList<Integer>> pq2 = new PriorityQueue<>(c);
            ans.add(p.remove());
            for (int poss : pos.get(ans.peekLast())) {
                q.get(poss).remove(ans.peekLast());
                pq2.add(q.get(poss));
            }
            while (!pq.isEmpty()) {
                pq2.add(pq.remove());
            }
            pq2.add(p);
            pq = pq2;
            // System.out.println();
        }
        for (int i : ans) {
            in.println(i);
        }
        in.bw.flush();
    }

    /*
     * 5 4 5 3 2 5 1 1 3 5
     */

    private static void print(Collection c) {
        for (Object i : c) {
            System.out.print(i + " ");
        }
        System.out.println();
    }

    static class Data implements Comparable<Data> {

        int a, b;

        public Data(int a, int b) {
            this.a = a;
            this.b = b;
        }

        @Override
        public int compareTo(Data o) {
            if (a == o.a) {
                return Integer.compare(b, o.b);
            }
            return Integer.compare(a, o.a);
        }

        public static void sort(int a[]) {
            Data d[] = new Data[a.length];
            for (int i = 0; i < a.length; i++) {
                d[i] = new Data(a[i], 0);
            }
            Arrays.sort(d);
            for (int i = 0; i < a.length; i++) {
                a[i] = d[i].a;
            }
        }
    }

    static class FastIO {

        private final BufferedReader br;
        private final BufferedWriter bw;
        private String s[];
        private int index;

        public FastIO() throws IOException {
            br = new BufferedReader(new InputStreamReader(System.in));
            bw = new BufferedWriter(new OutputStreamWriter(System.out, "UTF-8"));
            s = br.readLine().split(" ");
            index = 0;
        }

        public int ni() throws IOException {
            return Integer.parseInt(nextToken());
        }

        public double nd() throws IOException {
            return Double.parseDouble(nextToken());
        }

        public long nl() throws IOException {
            return Long.parseLong(nextToken());
        }

        public String next() throws IOException {
            return nextToken();
        }

        public String nli() throws IOException {
            try {
                return br.readLine();
            } catch (IOException ex) {

            }
            return null;
        }

        public int[] gia(int n) throws IOException {
            int a[] = new int[n];
            for (int i = 0; i < n; i++) {
                a[i] = ni();
            }
            return a;
        }

        public int[] gia(int n, int start, int end) throws IOException {
            validate(n, start, end);
            int a[] = new int[n];
            for (int i = start; i < end; i++) {
                a[i] = ni();
            }
            return a;
        }

        public double[] gda(int n) throws IOException {
            double a[] = new double[n];
            for (int i = 0; i < n; i++) {
                a[i] = nd();
            }
            return a;
        }

        public double[] gda(int n, int start, int end) throws IOException {
            validate(n, start, end);
            double a[] = new double[n];
            for (int i = start; i < end; i++) {
                a[i] = nd();
            }
            return a;
        }

        public long[] gla(int n) throws IOException {
            long a[] = new long[n];
            for (int i = 0; i < n; i++) {
                a[i] = nl();
            }
            return a;
        }

        public long[] gla(int n, int start, int end) throws IOException {
            validate(n, start, end);
            long a[] = new long[n];
            for (int i = start; i < end; i++) {
                a[i] = nl();
            }
            return a;
        }

        public int[][][] gwtree(int n) throws IOException {
            int m = n - 1;
            int adja[][] = new int[n + 1][];
            int weight[][] = new int[n + 1][];
            int from[] = new int[m];
            int to[] = new int[m];
            int count[] = new int[n + 1];
            int cost[] = new int[n + 1];
            for (int i = 0; i < m; i++) {
                from[i] = i + 1;
                to[i] = ni();
                cost[i] = ni();
                count[from[i]]++;
                count[to[i]]++;
            }
            for (int i = 0; i <= n; i++) {
                adja[i] = new int[count[i]];
                weight[i] = new int[count[i]];
            }
            for (int i = 0; i < m; i++) {
                adja[from[i]][count[from[i]] - 1] = to[i];
                adja[to[i]][count[to[i]] - 1] = from[i];
                weight[from[i]][count[from[i]] - 1] = cost[i];
                weight[to[i]][count[to[i]] - 1] = cost[i];
                count[from[i]]--;
                count[to[i]]--;
            }
            return new int[][][] { adja, weight };
        }

        public int[][][] gwg(int n, int m) throws IOException {
            int adja[][] = new int[n + 1][];
            int weight[][] = new int[n + 1][];
            int from[] = new int[m];
            int to[] = new int[m];
            int count[] = new int[n + 1];
            int cost[] = new int[n + 1];
            for (int i = 0; i < m; i++) {
                from[i] = ni();
                to[i] = ni();
                cost[i] = ni();
                count[from[i]]++;
                count[to[i]]++;
            }
            for (int i = 0; i <= n; i++) {
                adja[i] = new int[count[i]];
                weight[i] = new int[count[i]];
            }
            for (int i = 0; i < m; i++) {
                adja[from[i]][count[from[i]] - 1] = to[i];
                adja[to[i]][count[to[i]] - 1] = from[i];
                weight[from[i]][count[from[i]] - 1] = cost[i];
                weight[to[i]][count[to[i]] - 1] = cost[i];
                count[from[i]]--;
                count[to[i]]--;
            }
            return new int[][][] { adja, weight };
        }

        public int[][] gtree(int n) throws IOException {
            int adja[][] = new int[n + 1][];
            int from[] = new int[n - 1];
            int to[] = new int[n - 1];
            int count[] = new int[n + 1];
            for (int i = 0; i < n - 1; i++) {
                from[i] = i + 1;
                to[i] = ni();
                count[from[i]]++;
                count[to[i]]++;
            }
            for (int i = 0; i <= n; i++) {
                adja[i] = new int[count[i]];
            }
            for (int i = 0; i < n - 1; i++) {
                adja[from[i]][--count[from[i]]] = to[i];
                adja[to[i]][--count[to[i]]] = from[i];
            }
            return adja;
        }

        public int[][] gg(int n, int m) throws IOException {
            int adja[][] = new int[n + 1][];
            int from[] = new int[m];
            int to[] = new int[m];
            int count[] = new int[n + 1];
            for (int i = 0; i < m; i++) {
                from[i] = ni();
                to[i] = ni();
                count[from[i]]++;
                count[to[i]]++;
            }
            for (int i = 0; i <= n; i++) {
                adja[i] = new int[count[i]];
            }
            for (int i = 0; i < m; i++) {
                adja[from[i]][--count[from[i]]] = to[i];
                adja[to[i]][--count[to[i]]] = from[i];
            }
            return adja;
        }

        public void print(String s) throws IOException {
            bw.write(s);
        }

        public void println(String s) throws IOException {
            bw.write(s);
            bw.newLine();
        }

        public void print(int s) throws IOException {
            bw.write(s + "");
        }

        public void println(int s) throws IOException {
            bw.write(s + "");
            bw.newLine();
        }

        public void print(long s) throws IOException {
            bw.write(s + "");
        }

        public void println(long s) throws IOException {
            bw.write(s + "");
            bw.newLine();
        }

        public void print(double s) throws IOException {
            bw.write(s + "");
        }

        public void println(double s) throws IOException {
            bw.write(s + "");
            bw.newLine();
        }

        private String nextToken() throws IndexOutOfBoundsException, IOException {
            if (index == s.length) {
                s = br.readLine().split(" ");
                index = 0;
            }
            return s[index++];
        }

        private void validate(int n, int start, int end) {
            if (start < 0 || end >= n) {
                throw new IllegalArgumentException();
            }
        }
    }
}
