Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.

import java.util.*;



public class checker {
	
	
	
	
    public static void main(String args[] ) {
       Scanner in = new Scanner(System.in);
     int m  = in.nextInt();
     int d = in.nextInt();
     
     int[] month = new int[12];
     month[0] = 31; month[2] = 31; month[4] = 31; month[6] = 31;
     month[7] = 31; month[9] = 31;month[11] = 31;
     month[1] = 28;month[3] = 30;month[5] = 30;month[8] = 30;month[10] = 30;
     
     m = m-1;
     
     int days = month[m]; int count = 1;
     days -= 7-d+1;
     count += days/7;
     if(days%7!=0) count++;
     System.out.println(count);
    }
}
