Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
#include <bits/stdc++.h>
using namespace std;
int main() {
  int a, b, l;
  while (cin >> a >> b) {
    if (b == 7) {
      l = 6;
    }
    if (b == 6) {
      l = 5;
    }
    if (b == 5) {
      l = 4;
    }
    if (b == 4) {
      l = 3;
    }
    if (b == 3) {
      l = 2;
    }
    if (b == 2) {
      l = 1;
    }
    if (b == 1) {
      l = 0;
    }
    if (a == 1 || a == 3 || a == 5 || a == 7 || a == 8 || a == 10 || a == 12) {
      int k = 31 + l;
      if (k > 35) {
        cout << "6" << endl;
      } else {
        cout << "5" << endl;
      }
    } else if (a == 2) {
      int k = l + 28;
      if (k > 28) {
        cout << "5" << endl;
      } else {
        cout << "4" << endl;
      }
    } else {
      int k = 30 + l;
      if (k > 35) {
        cout << "6" << endl;
      } else {
        cout << "5" << endl;
      }
    }
  }
  return 0;
}
