Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
# your code goes here# cook your code here
s=raw_input()
arr=s.split(" ")
arr=map(int,arr)
i=arr[0]
j=arr[1]
if(i==2 ):
    if j==1:
	print 4
    else:
    	print 5
elif(i==1 or i==3 or i==5 or i==7 or i==8 or i==10 or i==12):
    if(j<=5):
        print 5
    else:
        print 6
else:
    if(j!=7):
        print 5
    else:
        print 6