You are given a string s, consisting only of characters '0' or '1'. Let |s| be the length of s.

You are asked to choose some integer k (k > 0) and find a sequence a of length k such that: 

  * 1 ≤ a_1 < a_2 < ... < a_k ≤ |s|; 
  * a_{i-1} + 1 < a_i for all i from 2 to k. 



The characters at positions a_1, a_2, ..., a_k are removed, the remaining characters are concatenated without changing the order. So, in other words, the positions in the sequence a should not be adjacent.

Let the resulting string be s'. s' is called sorted if for all i from 2 to |s'| s'_{i-1} ≤ s'_i.

Does there exist such a sequence a that the resulting string s' is sorted?

Input

The first line contains a single integer t (1 ≤ t ≤ 1000) — the number of testcases.

Then the descriptions of t testcases follow.

The only line of each testcase contains a string s (2 ≤ |s| ≤ 100). Each character is either '0' or '1'.

Output

For each testcase print "YES" if there exists a sequence a such that removing the characters at positions a_1, a_2, ..., a_k and concatenating the parts without changing the order produces a sorted string.

Otherwise, print "NO".

You may print every letter in any case you want (so, for example, the strings yEs, yes, Yes and YES are all recognized as positive answer).

Example

Input


5
10101011011
0000
11111
110
1100


Output


YES
YES
YES
YES
NO

Note

In the first testcase you can choose a sequence a=[1,3,6,9]. Removing the underlined letters from "10101011011" will produce a string "0011111", which is sorted.

In the second and the third testcases the sequences are already sorted.

In the fourth testcase you can choose a sequence a=[3]. s'= "11", which is sorted.

In the fifth testcase there is no way to choose a sequence a such that s' is sorted.
#------------------Important Modules------------------#
from sys import stdin,stdout
from bisect import bisect_left as bl
from bisect import bisect_right as br
from heapq import *
from random import *
input=stdin.readline
prin=stdout.write
from random import sample
from collections import Counter,deque
from fractions import *
from math import sqrt,ceil,log2,gcd
#dist=[0]*(n+1)
mod=10**9+7
"""
class DisjSet: 
    def __init__(self, n): 
        
        self.rank = [1] * n 
        self.parent = [i for i in range(n)] 
    def find(self, x): 
        if (self.parent[x] != x): 
              
             
            self.parent[x] = self.find(self.parent[x]) 
              
            
        return self.parent[x] 
  
  
    
    def union(self, x, y): 
          
         
        xset = self.find(x) 
        yset = self.find(y) 
  
        if xset == yset: 
            return
  
        if self.rank[xset] < self.rank[yset]: 
            self.parent[xset] = yset 
  
        elif self.rank[xset] > self.rank[yset]: 
            self.parent[yset] = xset 
  
        else: 
            self.parent[yset] = xset 
            self.rank[xset] = self.rank[xset] + 1
  

"""

def f(arr,i,j,d,dist):
    if i==j:
        return 
    nn=max(arr[i:j])
    for tl in range(i,j):
        if arr[tl]==nn:
            dist[tl]=d
            #print(tl,dist[tl])
            f(arr,i,tl,d+1,dist)
            f(arr,tl+1,j,d+1,dist)
    #return dist
            
        
def ps(n):
    cp=0;lk=0;arr={}
    #print(n)
    #cc=0;
    while n%2==0:
        n=n//2
        #arr.append(n);arr.append(2**(lk+1))
        lk+=1
    
    
    
        
    for ps in range(3,ceil(sqrt(n))+1,2):
        lk=0
        cc=0
        while n%ps==0:
            n=n//ps
            #cc=1
            #arr.append(n);arr.append(ps**(lk+1))
            lk+=1
        
            
            
    if n!=1:
        #lk+=1
        #arr[n]=1
        #ans*=n;
        lk+=1
        return False
        #return arr
    
    #print(arr)
    
    return True


#count=0
#dp=[[0 for i in range(m)] for j in range(n)]
#[int(x) for x in input().strip().split()]
def gcd(x, y): 
      
    while(y): 
        x, y = y, x % y 
      
    return x 
          
# Driver Code         
def factorials(n,r):
    #This calculates ncr mod 10**9+7
    slr=n;dpr=r
    qlr=1;qs=1
    mod=10**9+7
    
    for ip in range(n-r+1,n+1):
        qlr=(qlr*ip)%mod
    for ij in range(1,r+1):
        qs=(qs*ij)%mod
    #print(qlr,qs)
    ans=(qlr*modInverse(qs))%mod
    return ans

        
        
def modInverse(b):
    qr=10**9+7
    return pow(b, qr - 2,qr)

#===============================================================================================
### START ITERATE RECURSION ###
from types import GeneratorType
def iterative(f, stack=[]):
  def wrapped_func(*args, **kwargs):
    if stack: return f(*args, **kwargs)
    to = f(*args, **kwargs)
    while True:
      if type(to) is GeneratorType:
        stack.append(to)
        to = next(to)
        continue
      stack.pop()
      if not stack: break
      to = stack[-1].send(to)
    return to
  return wrapped_func
def power(arr):
  listrep = arr
  subsets = []
  for i in range(2**len(listrep)):
    subset = []
    for k in range(len(listrep)):            
      if i & 1<<k:
        subset.append(listrep[k])
    subsets.append(subset)        
  return subsets
def pda(n) :
    list = [] 
    for i in range(1, int(sqrt(n) + 1)) :
         if (n % i == 0) :
            if (n // i == i) :
                list.append(i)
            else :
                list.append(n//i);list.append(i)
                 
    # The list will be printed in reverse    
    return list
def dis(xa,ya,xb,yb):
    return sqrt((xa-xb)**2+(ya-yb)**2)
#### END ITERATE RECURSION ####
 
#===============================================================================================
#----------Input functions--------------------#
def ii():
    return int(input())
def ilist():
    return [int(x) for x in input().strip().split()]
def islist():
    return list(map(str,input().split().rstrip()))
def inp():
    return input().strip()
def google(test,ans):
    return "Case #"+str(test)+": "+str(ans);
def overlap(x1,y1,x2,y2):
    if x2>y1:
        return y1-x2
    if y1>y2:
        return y2-x2
    return y1-x2;


###-------------------------CODE STARTS HERE--------------------------------###########
#########################################################################################
t=int(input())
#t=1
for p in range(t):
    s=input()
    n=len(s)
    one=0;zero=0
    cc=1;
    for i in range(1,n):
        if s[i]==s[i-1]:
            if s[i]=='1':
                one=1
            elif one==1:
                cc=0
                break
            else:
                zero=1;
    if cc:
        print("YES")
    else:
        print("NO")
                
            
            
            
        
                    
            
            
    
        
    
    
            
        
    
    
            
    
        
    
            
                
    
        
    
        
        
        
        
        
                
                
        
        
    
            
        
    
        
        
    
    
            
            
        
    
            
            
                
                
                
            
    
    
            
                
        
                
        
    
    
    
            
            
            
        
            
        
        
        
    
    
        
        
                
            
        
        
        
                
                
                
        
    
        
                
            
                
            
        
        
        
    
    
                
                
        
    
        
        
    
        
    
    
    
    
    
        
                
    
            
            
    
    





















    
