Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
a,b=map(int,input().split())
x=1
if a==1 or a==3 or a==5 or a==7 or a==8 or a==10 or a==12:
	m=31-(abs(b-8))
	if m%7>=1:
		print(x+m//7+1)
	else:
		print(x+m//7)
if a==4 or a==6 or a==9 or a==11:
	m=30-(abs(b-8))
	if m%7>=1:
		print(x+m//7+1)
	else:
		print(x+m//7)
if a==2:
	m=28-(abs(b-8))
	if m%7>=1:
		print(x+m//7+1)
	else:
		print(x+m//7)
