Allen has a LOT of money. He has n dollars in the bank. For security reasons, he wants to withdraw it in cash (we will not disclose the reasons here). The denominations for dollar bills are 1, 5, 10, 20, 100. What is the minimum number of bills Allen could receive after withdrawing his entire balance?

Input

The first and only line of input contains a single integer n (1 ≤ n ≤ 10^9).

Output

Output the minimum number of bills that Allen could receive.

Examples

Input

125


Output

3


Input

43


Output

5


Input

1000000000


Output

10000000

Note

In the first sample case, Allen can withdraw this with a 100 dollar bill, a 20 dollar bill, and a 5 dollar bill. There is no way for Allen to receive 125 dollars in one or two bills.

In the second sample case, Allen can withdraw two 20 dollar bills and three 1 dollar bills.

In the third sample case, Allen can withdraw 100000000 (ten million!) 100 dollar bills.
#import modules here
import math,sys,os
#from itertools import permutations, combinations
from collections import defaultdict,deque,OrderedDict,Counter
import bisect as bi
#import heapq
from io import BytesIO, IOBase
mod=10**9+7

# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
    newlines = 0
 
    def __init__(self, file):
        self._fd = file.fileno()
        self.buffer = BytesIO()
        self.writable = "x" in file.mode or "r" not in file.mode
        self.write = self.buffer.write if self.writable else None
 
    def read(self):
        while True:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            if not b:
                break
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines = 0
        return self.buffer.read()
 
    def readline(self):
        while self.newlines == 0:
            b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
            self.newlines = b.count(b"\n") + (not b)
            ptr = self.buffer.tell()
            self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
        self.newlines -= 1
        return self.buffer.readline()
 
    def flush(self):
        if self.writable:
            os.write(self._fd, self.buffer.getvalue())
            self.buffer.truncate(0), self.buffer.seek(0)
 
 
class IOWrapper(IOBase):
    def __init__(self, file):
        self.buffer = FastIO(file)
        self.flush = self.buffer.flush
        self.writable = self.buffer.writable
        self.write = lambda s: self.buffer.write(s.encode("ascii"))
        self.read = lambda: self.buffer.read().decode("ascii")
        self.readline = lambda: self.buffer.readline().decode("ascii")
        
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")

#input functions
def minp(): return map(int, sys.stdin.readline().rstrip().split())
def linp(): return list(map(int, sys.stdin.readline().rstrip().split()))
def inp(): return int(input())
def print_list(l):
    print(' '.join(map(str,l)))

#functions
def BinarySearch(a,x): 
    i=bi.bisect_left(a, x) 
    if i != len(a) and a[i] == x: 
        return i 
    else: 
        return -1
        
def gcd(a,b):
    return math.gcd(a,b)
    
def is_prime(n):
    """returns True if n is prime else False"""
    if n < 5 or n & 1 == 0 or n % 3 == 0:
        return 2 <= n <= 3
    s = ((n - 1) & (1 - n)).bit_length() - 1
    d = n >> s
    for a in [2, 325, 9375, 28178, 450775, 9780504, 1795265022]:
        p = pow(a, d, n)
        if p == 1 or p == n - 1 or a % n == 0:
            continue
        for _ in range(s):
            p = (p * p) % n
            if p == n - 1:
                break
        else:
            return False
    return True
    
def mulinverse(a):
    return pow(a,mod-2,mod)

####################Let's Go Baby########################
n=inp()
a=[100, 20, 10, 5, 1]
ans = 0
for c in a:
    if n >= c:
        ans += n//c
        n = n % c
print(ans)