Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.io.BufferedReader;
import java.io.InputStreamReader;

public class PetrAndACalendar {

	public static void main(String[] args) {
		try
		{
			   BufferedReader inp = new BufferedReader (new InputStreamReader(System.in));
			   
			   String in = inp.readLine();
			   String inpu[] = in.split(" ");
			   
			   int m = Integer.parseInt(inpu[0]);
			   int d = Integer.parseInt(inpu[1]);
			   
			   int days[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

			   int ans =1;
			   m--;d--;
			   for(int i=0; i< days[m] -1 ;i++)
			   {
				   d = (d+1) % 7;
				   if(d ==0)
				   {
					  ans++;
				   }
			   }
			   System.out.println(ans);
			   
			
		}
		catch(Exception e)
		{
			e.printStackTrace();
		}

	}

}
