Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.util.Scanner;

public class Main {
    public static void main(String[] args)  {
        Scanner read = new Scanner(System.in);
       int a=read.nextInt();
       int b=read.nextInt();
       if (a==2){
           if (b>1)
           System.out.println(5);
           else {
               System.out.println(4);
           }
       }
       else if (a==1 || a==3 || a==1 || a==5 || a==7 || a==8 || a==10 || a==12){
           if (b>5){
               System.out.println(6);
           }else {
               System.out.println(5);
           }
       }else {
           if (b>6){
               System.out.println(6);
           }else {
               System.out.println(5);
           }
       }
    }
}
