Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
m,d=map(int,input().split())
kalendar=[[0 for i in range(7)] for j in range(6)]
D=1
if m==1 or m==3 or m==5 or m==7 or m==8 or m==10 or m==12:
    for i in range(6):
        for j in range(7):
            if d==0:
                kalendar[i][j]=D
                D+=1
            else:
                d-=1
            if D==31:
                print(i+1)
                exit()
elif (m==4 or m==6) or (m==9 or m==11):
    for i in range(6):
        for j in range(7):
            if d==0:
                kalendar[i][j]=D
                D+=1
            else:
                d-=1
            if D==30:
                print(i+1)
                exit()
else:
    for i in range(6):
        for j in range(7):
            if d==0:
                kalendar[i][j]=D
                D+=1
            else:
                d-=1
            if D==28:
                print(i+1)
                exit()