Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
''' Read input from STDIN. Print your output to STDOUT '''


# Use input() to read input from STDIN and use print to write your output to STDOUT

def main():
    #m = int(input())
    #d = int(input())
    dim = list(map(int,input().split()))
    if dim[0] == 2:
        if dim[1] > 1:
            print(5, end="")
        else:
            print(4, end="")
        return
    else:
        if dim[0] in [1, 3, 5, 7, 8, 10, 12]:
            if dim[1] <= 5:
                print(5, end="")
            else:
                print(6, end="")
            return
        else:
            if dim[1] <= 6:
                print(5, end="")
            else:
                print(6, end="")
            return


main()

