You have a fraction <image>. You need to find the first occurrence of digit c into decimal notation of the fraction after decimal point.

Input

The first contains three single positive integers a, b, c (1 ≤ a < b ≤ 105, 0 ≤ c ≤ 9).

Output

Print position of the first occurrence of digit c into the fraction. Positions are numbered from 1 after decimal point. It there is no such position, print -1.

Examples

Input

1 2 0


Output

2

Input

2 3 7


Output

-1

Note

The fraction in the first example has the following decimal notation: <image>. The first zero stands on second position.

The fraction in the second example has the following decimal notation: <image>. There is no digit 7 in decimal notation of the fraction. 
import java.math.BigDecimal;
import java.util.Scanner;

public class code900B {
	public static void main(String[] args) {
		Scanner s = new Scanner(System.in);
		int a = s.nextInt();
		int b = s.nextInt();
		int cc = s.nextInt();
		char c = (char)(cc+48);
		
		a = a % b;
		if(a==0){
			if(cc==0){
				System.out.println("1");
				return;
			}else{
				System.out.println("-1");
				return;
			}
		}
		
		StringBuilder sb = new StringBuilder();
		//div (a<b)
		for(int i=0;i<500;i++){
			a *= 10;
			int r = a%b;
			int q = a/b;
			sb.append(q);
			if(r==0){
				// fill 0 return
				String str = sb.toString();
				int re = str.indexOf(c);
				if(re == -1){
					if(cc==0){
						System.out.println(str.length()+1);
					}else{
						System.out.println("-1");
					}
					return;
				}else{
					System.out.println(re+1);
					return;
				}
			}else{
				a = r;				
			}
		}
		String str = sb.toString();
		int re = str.indexOf(c);
		if(re == -1){
			System.out.println("-1");
			return;
		}else{
			System.out.println(re+1);
			return;
		}	
	}	
}
