Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
a = raw_input()
b = a.split(" ")
m = int(b[0])
d = int(b[1])
if (m == 1) or (m ==3) or (m ==5) or (m ==7) or (m ==8) or (m ==10) or (m ==12):
    n = 31
elif (m == 4) or (m ==6) or (m ==9) or (m ==11):
    n = 30
else:
    n = 28

e = int(n +d -8)%7
c = int((n +d -8)/7)
if e != 0:
    c = c +2
else:
    c = c +1
print c
	 	 		  	    			  	   			  			