Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
# Petr and a calendar _ 760A
from math import ceil

m,wd= input().split()
m= int(m); wd= int(wd)

if (m == 1) or (m == 3) or (m == 5) or (m == 7) or (m == 8) or (m == 10) or (m == 12):  
    l=list(range(1, 32))
    for i in range(1,wd):
        l.insert(0,0)
    print(ceil(len(l)/7))

elif (m == 4) or (m == 6) or (m == 9) or (m == 11):
    l=list(range(1, 31))
    for i in range(1,wd):
        l.insert(0,0)
    print(ceil(len(l)/7))

else:
    l=list(range(1, 29))
    for i in range(1,wd):
        l.insert(0,0)
    print(ceil(len(l)/7))    