Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

<image>

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.

Input

The only line contain two integers m and d (1 ≤ m ≤ 12, 1 ≤ d ≤ 7) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month (1 is Monday, 7 is Sunday).

Output

Print single integer: the number of columns the table should have.

Examples

Input

1 7


Output

6


Input

1 1


Output

5


Input

11 6


Output

5

Note

The first example corresponds to the January 2017 shown on the picture in the statements.

In the second example 1-st January is Monday, so the whole month fits into 5 columns.

In the third example 1-st November is Saturday and 5 columns is enough.
import java.util.Scanner;

public class Petr_And_A_Calendar {

	private static final Scanner INPUT = new Scanner(System.in);

	public static void main(String[] args) {
		int month = INPUT.nextInt();
		int date = INPUT.nextInt();
		int days = 0;

		if(month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12)
			days = 30 + date;
		else if(month == 4 || month == 6 || month == 9 || month == 11)
			days = 29 + date;
		else
			days = 27 + date;

		int week = 0;

		if(days % 7 != 0)
			week = days / 7 + 1;
		else
			week = days / 7;

		System.out.printf("%d", week);
	}
}

