You are given a string q. A sequence of k strings s1, s2, ..., sk is called beautiful, if the concatenation of these strings is string q (formally, s1 + s2 + ... + sk = q) and the first characters of these strings are distinct.

Find any beautiful sequence of strings or determine that the beautiful sequence doesn't exist.

Input

The first line contains a positive integer k (1 ≤ k ≤ 26) — the number of strings that should be in a beautiful sequence. 

The second line contains string q, consisting of lowercase Latin letters. The length of the string is within range from 1 to 100, inclusive.

Output

If such sequence doesn't exist, then print in a single line "NO" (without the quotes). Otherwise, print in the first line "YES" (without the quotes) and in the next k lines print the beautiful sequence of strings s1, s2, ..., sk.

If there are multiple possible answers, print any of them.

Examples

Input

1
abca


Output

YES
abca


Input

2
aaacas


Output

YES
aaa
cas


Input

4
abc


Output

NO

Note

In the second sample there are two possible answers: {"aaaca", "s"} and {"aaa", "cas"}.
from collections import defaultdict
def cutter(a, cuts):
    
    if cuts == 1:
        return [a]
    comparador = set([a[0]])
    aux = a[0]
    ans = []
    flag = True
    for i in range(1, len(a)):
        # print(a[i])
        if a[i] not in comparador:
            ans.append(aux)
            aux = a[i]
            comparador = comparador.union(set([a[i]]))
        else:
            aux += a[i]
        # print(comparador)
        # print(aux)
        
        if len(ans) == cuts - 1 :
            ans.append(a[i:])
            break
    return ans
        
def isBeautiful(a):
    mapa = defaultdict(int)
    
    for i in a:
        mapa[i[0]] += 1
        
        if mapa[i[0]] > 1:
            return False
    return True

def func():
    n = int(input())
    p = input()
    
    if len(p) < n:
        print('NO')
        return
    
    lista =  cutter(p, n)
    # print(lista)
    if len(lista) < n:
        print('NO')
        return
    
    if isBeautiful(lista):
        print('YES')
        for i in lista:
            print(i)
    else:
        print('NO')
        return
    
func()