Polycarp wants to assemble his own keyboard. Layouts with multiple rows are too complicated for him — his keyboard will consist of only one row, where all 26 lowercase Latin letters will be arranged in some order.

Polycarp uses the same password s on all websites where he is registered (it is bad, but he doesn't care). He wants to assemble a keyboard that will allow to type this password very easily. He doesn't like to move his fingers while typing the password, so, for each pair of adjacent characters in s, they should be adjacent on the keyboard. For example, if the password is abacaba, then the layout cabdefghi... is perfect, since characters a and c are adjacent on the keyboard, and a and b are adjacent on the keyboard. It is guaranteed that there are no two adjacent equal characters in s, so, for example, the password cannot be password (two characters s are adjacent).

Can you help Polycarp with choosing the perfect layout of the keyboard, if it is possible?

Input

The first line contains one integer T (1 ≤ T ≤ 1000) — the number of test cases.

Then T lines follow, each containing one string s (1 ≤ |s| ≤ 200) representing the test case. s consists of lowercase Latin letters only. There are no two adjacent equal characters in s.

Output

For each test case, do the following:

  * if it is impossible to assemble a perfect keyboard, print NO (in upper case, it matters in this problem); 
  * otherwise, print YES (in upper case), and then a string consisting of 26 lowercase Latin letters — the perfect layout. Each Latin letter should appear in this string exactly once. If there are multiple answers, print any of them. 

Example

Input


5
ababa
codedoca
abcda
zxzytyz
abcdefghijklmnopqrstuvwxyza


Output


YES
bacdefghijklmnopqrstuvwxyz
YES
edocabfghijklmnpqrstuvwxyz
NO
YES
xzytabcdefghijklmnopqrsuvw
NO
/*	/ ﾌﾌ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ム
	/ )\⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀  Y
	(⠀⠀| ( ͡° ͜ʖ ͡°）⠀⌒(⠀ ノ
	(⠀ ﾉ⌒ Y ⌒ヽ-く __／
	| _⠀｡ノ| ノ｡ |/
	(⠀ー '_人`ー ﾉ
	⠀|\ ￣ _人'彡ﾉ
	⠀ )\⠀⠀ ｡⠀⠀ /
	⠀⠀(\⠀ #⠀ /
	⠀/⠀⠀⠀/ὣ====================D-
	/⠀⠀⠀/⠀ \ \⠀⠀\
	( (⠀)⠀⠀⠀⠀ ) ).⠀)
	(⠀⠀)⠀⠀⠀⠀⠀( | /
	|⠀ /⠀⠀⠀⠀⠀⠀ | /
	[_] ⠀⠀⠀⠀⠀[___]                     */
// Main Code at the Bottom
import java.util.*;
import java.lang.*;
import java.io.*;
import java.math.BigInteger; 
public class Main {
	//Fast IO class
    static class FastReader {
        BufferedReader br; 
        StringTokenizer st; 
        public FastReader() {
        	boolean env=System.getProperty("ONLINE_JUDGE") != null;
        	if(!env) {
        		try {
					br=new BufferedReader(new FileReader("src\\input.txt"));
				} catch (FileNotFoundException e) {
					e.printStackTrace();
				}
        	}
        	else br = new BufferedReader(new InputStreamReader(System.in)); 
        } 
        String next() {
            while (st == null || !st.hasMoreElements()) {
                try {
                    st = new StringTokenizer(br.readLine()); 
                } 
                catch (IOException  e) {
                    e.printStackTrace(); 
                } 
            } 
            return st.nextToken(); 
        } 
        int nextInt() {
            return Integer.parseInt(next()); 
        } 
        long nextLong() {
            return Long.parseLong(next()); 
        } 
        double nextDouble() {
            return Double.parseDouble(next()); 
        } 
        String nextLine() {
            String str = ""; 
            try {
                str = br.readLine(); 
            } 
            catch (IOException e) {
                e.printStackTrace(); 
            } 
            return str; 
        } 
    }     
    static long MOD=1000000000+7;
    //Euclidean Algorithm
    static long gcd(long A,long B){
    	return (B==0)?A:gcd(B,A%B);
    }
    //Modular Exponentiation
    static long fastExpo(long x,long n){
        if(n==0) return 1;
        if((n&1)==0) return fastExpo((x*x)%MOD,n/2)%MOD;
        return ((x%MOD)*fastExpo((x*x)%MOD,(n-1)/2))%MOD;
    }
    //Modular Inverse
    static long inverse(long x) {
    	return fastExpo(x,MOD-2);
    }
    //Prime Number Algorithm
    static boolean isPrime(long n){
        if(n<=1) return false;
        if(n<=3) return true;
        if(n%2==0 || n%3==0) return false;
        for(int i=5;i*i<=n;i+=6) if(n%i==0 || n%(i+2)==0) return false;
        return true;
    }
    //Reverse an array
    static void reverse(int arr[],int l,int r){
    	while(l<r) {
    		int tmp=arr[l];
    		arr[l++]=arr[r];
    		arr[r++]=tmp;
    	}
    }
    //Print array
    static void print1d(int arr[]) {
    	out.println(Arrays.toString(arr));
    }
    static void print2d(int arr[][]) {
    	for(int a[]: arr) out.println(Arrays.toString(a));
    }
    // Pair
    static class pair{
    	int x,y;
    	pair(int a,int b){
    		this.x=a;
    		this.y=b;
    	}
    	public boolean equals(Object obj) {
    		if(obj == null || obj.getClass()!= this.getClass()) return false;
            pair p = (pair) obj;
            return (this.x==p.x && this.y==p.y);
        }
    	public int hashCode() {
            return Objects.hash(x,y);
        }
    }
    static FastReader sc=new FastReader();
    static PrintWriter out=new PrintWriter(System.out);  
    //Main function(The main code starts from here)
    static int V,visited[];
    static ArrayList<Integer> graph[];
    static void init(int n){
        V=n;
        graph=new ArrayList[V];
        visited=new int[n];
        for(int i=0;i<V;i++) graph[i]=new ArrayList<>();
    }
    static void addEdge(int src,int dest){
        graph[src].add(dest);
        graph[dest].add(src);
    }
    static ArrayList<Integer> ans;
    static void dfs(int s) {
    	if(visited[s]==1) return;
    	ans.add(s);
    	visited[s]=1;
    	for(Integer x: graph[s]) dfs(x);
    }
    public static void main (String[] args) throws java.lang.Exception {
    	int test=sc.nextInt();
        while(test-->0) {
        	char s[]=sc.nextLine().toCharArray();
        	int n=s.length;
        	if(n==1) {
        		out.println("YES");
        		for(char i='a';i<='z';i++) out.print(i);
        		out.println();
        		continue;
        	}
        	init(26);
        	int map[][]=new int[26][26];
        	ans=new ArrayList<>();
        	for(int i=0;i<n-1;i++) {
        		if(map[s[i]-'a'][s[i+1]-'a']==1) continue;
        		addEdge(s[i]-'a',s[i+1]-'a');
        		map[s[i]-'a'][s[i+1]-'a']=1;
        		map[s[i+1]-'a'][s[i]-'a']=1;
        	}
        	int flag=0,cnt=0,idx=-1;
        	//for(int i=0;i<26;i++) out.println(graph[i]);
        	for(int i=0;i<26;i++) {
        		int x=graph[i].size();
        		if(x>2) {
        			flag=1;
        			break;
        		}
        		if(x==1) {
        			idx=i;
        			cnt++;
        		}
        	}
        	if(n>=2 && cnt!=2) flag=1;
        	if(flag==1) {
        		out.println("NO");
        		continue;
        	}
        	dfs(idx);
        	out.println("YES");
        	//out.println(ans);
        	for(Integer i: ans) out.print((char)(i+'a'));
        	for(int i=0;i<26;i++) if(visited[i]==0) out.print((char)(i+'a'));
        	out.println();
        } 	
        out.flush();
        out.close();
    }
}