You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
import java.util.Scanner;

public class sortirovka988B {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();
        String resultArray[]=new String[n];
        String array[]=new String[n];
        boolean check=true;
        for (int i = 0; i <n; i++) {
            array[i]=sc.next();
        }
        for (int i = 1; i <array.length; i++) {
            for (int j = 0; j <array.length-i ; j++) {
                if (array[j].contains(array[j+1])){
                    String temp=array[j];
                    array[j]=array[j+1];
                    array[j+1]=temp;
                }
            }
        }
        for (int i = 1; i <array.length; i++) {
            for (int j = 0; j <array.length-i ; j++) {
                if (!array[j+1].contains(array[j])){
                    check=false;
                }
            }
        }
        if (check) {
            System.out.println("YES");
            for (int i = 0; i < array.length; i++) {
                System.out.println(array[i]);
            }
        }
        else {
            System.out.println("NO");
        }
    }
}
