You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
import sys
class word :
    word =""
    counter = 0

index_list = []
my_list = []
for i in range (101):
    my_word = word()
    my_list.append(my_word)
tedad = int(input())
#print(tedad) # yoloooooo
for i in range(tedad):
    a = input()

    if (my_list[len(a)].counter == 0):
        my_list[len(a)].word = a

        my_list[len(a)].counter += 1
        index_list.append(len(a))
    else:
        if (my_list[len(a)].word != a):
            print("NO")
            sys.exit()
        else:
            my_list[len(a)].counter += 1

index_list.sort()

for i in range (len(index_list)-1):
    if (my_list[index_list[i]].word in my_list[index_list[i+1]].word):
        continue
    else:
        print("NO")
        sys.exit()
print("YES")
for i in range(len(index_list)):
    for j in range(my_list[index_list[i]].counter):
        print(my_list[index_list[i]].word)

