You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".

import java.util.Scanner;
import java.io.BufferedReader;
import java.io.InputStreamReader;
public class azzama {
	public static boolean issubstring(String s,String x) {
		for (int i=0;i<x.length();i++) {
			for (int j=i+1;j<=x.length();j++) {
				if (s.equals(x.substring(i,j))) return true;
			}
		}
		return false;
		
	}
	public static void sort(String[] a) {
		for (int i=0;i<a.length;i++) {
			for (int j=0;j<a.length-1;j++) {
				if (a[j].length()>a[j+1].length()) {
					String tmp=a[j];
					a[j]=a[j+1];
					a[j+1]=tmp;
				}
					
			}
		}
	}
	public static void display(String [] a) {
		for (int i=0;i<a.length;i++) {
			System.out.println(a[i]);
		}
	}
	public static boolean done (String [] a) {
		sort(a);
		for(int i=0;i<a.length-1;i++) {
			if (!issubstring(a[i],a[i+1]))
				return false;
		}
		return true;
	}
	public static void main(String [] args) {
		Scanner sc =new Scanner (System.in);
		BufferedReader r = new BufferedReader(new InputStreamReader(System.in));
		int n=sc.nextInt();
		sc.nextLine();
		String []a=new String [n];
		for (int i=0;i<n;i++) {
			a[i]= sc.nextLine();
		}
		if (done(a))
		{
			System.out.println("YES");
			display(a);
		}
		else 
			System.out.println("NO");

		

		
	}
}