You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".



import java.util.ArrayList;
import java.util.HashSet;
import java.util.Iterator;
import java.util.Scanner;

public class codeforces {


	
	public static void main(String[] args) 
	{
		Scanner in = new Scanner(System.in);
		int n=in.nextInt();
		String []  st= new String[n];
		
		int i=0;
		
		for(i=0;i<n;i++)
		{
			st[i]=in.next();
		}
		
		int j=0;
		
		for(i=0;i<n;i++)
		{
			for(j=0;j<n-i-1;j++)
			{
				if(st[j].length()>st[j+1].length())
				{
					String temp = st[j];
					st[j]=st[j+1];
					st[j+1]=temp;
				}
			}
		}
		
		for(i=0;i<n-1;i++)
		{
			if(st[i+1].contains(st[i])==true)
			{
				continue;
			}
			else
			{
				System.out.println("NO");
				System.exit(0);
			}
		}

		System.out.println("YES");
		
		for(i=0;i<n;i++)
		{
			System.out.println(st[i]);
		}
		
		
	}

}

