You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".

import java.util.*;

/*
_Подстрочная_сортировка
*/
public class B988 {
    
    public static void main(String...args){
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();sc.nextLine();
        String[] ar = new String[n];
        for(int i = 0; i < n; i++){
            String s = sc.nextLine();
            ar[i]=s;
        }
        ar = sortStrArray(ar);
        boolean a = true;
        for(int i = 0; i < n-1; i++){
            if(!ar[i+1].contains(ar[i])){
                a=false;
            }
        }
        if(a){
            System.out.println("YES");
            print(ar);
        }
        else{System.out.println("NO");}
        
    }
    public static void print(String[]arr){
        for(int i = 0; i < arr.length; i++){
            System.out.println(arr[i]);
        }
//        System.out.println("");
    }
    public static String[] sortStrArray(String[] array){
        //sort arrays by length before returning
        Arrays.sort(array, new Comparator<String>() {
        @Override
            public int compare(String a, String b) {
                return Integer.compare(a.length(),b.length());//specifying compare type that is compare with length
            }
        });
        return array;
    }
}
