You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;
import java.util.Scanner;

public class SubstringsSort {

	public static void main(String[] args) {

		Scanner sc = new Scanner(System.in);

		int n = sc.nextInt();

		List<String > list = new ArrayList<String>();
		for (int i = 0; i <= n; i++) {
			list.add(sc.nextLine());
		}
		list.remove(0);
		
		Comparator<String> c = (a,b) -> a.length() - b.length();
		Collections.sort(list, c);
		
		boolean result = true;
		
		for(int i=0;i<list.size()-1;i++) {
			String two = list.get(i+1);
			String one = list.get(i);
			
			if(!two.contains(one)) {
				result = false;
				break;
			}
		}
		
		if(result) {
			System.out.println("YES");
			for(String s : list) {
				System.out.println(s);
			}
		}else {
			System.out.println("NO");
		}

	}

}