You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
//package com.company;
import java.util.Scanner;
import java.util.*;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

import static java.lang.Math.*;

public class Main {

    static class FastScanner {
        StringTokenizer tok = new StringTokenizer("");
        BufferedReader in;

        FastScanner()  {
            in = new BufferedReader(new InputStreamReader(System.in));
        }

        String next() throws IOException {
            while (!tok.hasMoreElements())
                tok = new StringTokenizer(in.readLine());
            return tok.nextToken();
        }

        int nextInt() throws IOException {
            return Integer.parseInt(next());
        }


    }

    public static void main(String[] args) throws IOException {

        FastScanner input = new FastScanner();
        Scanner in = new Scanner(System.in);

        int n = input.nextInt();
        String[] s = new String[n];
        for( int i = 0 ; i < n ; i++ ){
            s[i] = input.next();
        }
        Arrays.sort(s,(s1,s2)->{return s1.length()-s2.length();});

        boolean ok = true;

        for( int i = 0 ; i < n -1 ; i++ ){

            if( s[i+1].indexOf(s[i])==-1){
                ok = false;
                break;
            }
        }

        if( ok == false ) {
            System.out.println( "NO" );
        }
        else{
            System.out.println("YES");
            for(String it : s){
                System.out.println(it);
            }
        }



    }


}