You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
import java.util.*;

public class Main {
  public static void main(String[] args) {
    Scanner sc = new Scanner(System.in);
    int n = sc.nextInt();
    String arr[] = new String[n];
    for(int i = 0; i < n; i++){
      arr[i] = sc.next();
    }
    Arrays.sort(arr, new Comparator<String>() {

        @Override
        public int compare(String o1, String o2) {
            return o1.length()-o2.length();
        }
    });
    boolean flag = true;
    for(int i = 1; i < n; i++){
      for(int j =0; j < i; j++){
        if(!arr[i].contains(arr[j])){
          flag = false;
          break;
        }
      }
    }
    if(!flag){
      System.out.println("NO");
    } else {
      System.out.println("YES");
      for(int i = 0; i < n; i++){
        System.out.println(arr[i]);
      }
    }
  }
}