You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
import java.util.*;

public class Main {

    public static void main(String[] args)
    {
        Scanner scanner=new Scanner(System.in);
         int n=scanner.nextInt();
         String s[]=new String[n];
        for (int i = 0; i <n ; i++) {
            s[i]=scanner.next();
        }
        String temp;
        for (int i = 0; i <n; i++) {
            for (int j = n - 1; j > i; j--) {
                if (s[i].length() > s[j].length()) {
                    temp = s[i];
                    s[i] = s[j];
                    s[j] = temp;
                }
            }
        }
        int i=0;
        for (; i <n-1 ; i++) {
            if (!s[i+1].contains(s[i])) {
                break;

            }
        }
        if (i==n-1)
        {
            System.out.println("YES");
            for (int j = 0; j <n ; j++) {
                System.out.println(s[j]);
            }
        }
        else
        {
            System.out.println("NO");
        }
	}
}
