You are given a string q. A sequence of k strings s1, s2, ..., sk is called beautiful, if the concatenation of these strings is string q (formally, s1 + s2 + ... + sk = q) and the first characters of these strings are distinct.

Find any beautiful sequence of strings or determine that the beautiful sequence doesn't exist.

Input

The first line contains a positive integer k (1 ≤ k ≤ 26) — the number of strings that should be in a beautiful sequence. 

The second line contains string q, consisting of lowercase Latin letters. The length of the string is within range from 1 to 100, inclusive.

Output

If such sequence doesn't exist, then print in a single line "NO" (without the quotes). Otherwise, print in the first line "YES" (without the quotes) and in the next k lines print the beautiful sequence of strings s1, s2, ..., sk.

If there are multiple possible answers, print any of them.

Examples

Input

1
abca


Output

YES
abca


Input

2
aaacas


Output

YES
aaa
cas


Input

4
abc


Output

NO

Note

In the second sample there are two possible answers: {"aaaca", "s"} and {"aaa", "cas"}.
from collections import OrderedDict
count = int(input())
line  = input()

uniq = "".join(OrderedDict.fromkeys(line).keys())

if count > len(uniq):
	print("NO")
else:
	print("YES")
	if count == len(uniq):
		while len(line) != 0:
			first_uniq = 0
			uniq = uniq[1:]
			if len(uniq) == 0:
				print(line)
				break
			last_uniq = line.find(uniq[0])
			print(line[first_uniq:last_uniq])
			line = line[last_uniq:]
	else:
		while count != 1:
			first_uniq = 0
			uniq = uniq[1:]
			last_uniq = line.find(uniq[0])
			print(line[first_uniq:last_uniq])
			line = line[last_uniq:]
			count -= 1
		print(line)