Alfi asked Roy to go for shopping with her. Witty Roy came up with a condition. He said, for each product of MRP (Maximum Retail Price) R, she'll have to pay minimum of all the prime factors of R and he himself will pay rest of the amount. Without giving it a second thought Alfi agreed. 

Now they bought N number of products. You're to find how much money did Roy had to pay for each product.

Input:

First line will contain integer N, number of products they bought.

Next N lines each will contain R, MRP of each product.

Output:

Print single integer in a new line, the amount of money Roy had to pay for each product.

Constraints:

2 ≤ N,R ≤ 1000000

Warning:
Large I/O. Be careful with certain languages.

SAMPLE INPUT
2
5
10

SAMPLE OUTPUT
0
8

Explanation

Test Case #1: Only 1 prime factor of 5 is 5 itself, so Alfi will pay all the money and hence Roy has to pay 0.

Test Case #2: Prime Factors of 10 are 2 and 5, minimum of these is 2, so Alfi pays 2 and hence Roy has to pay the rest, which is 8.
from sys import stdin
N = 1000001
prime = [0]*N
lpf = [0]*N
prime[0] = 1
prime[1] = 1
def lpf_sieve():
    for i in xrange(N):
        lpf[i] = i
    i = 2
    while i*i <= N:
        j = 2*i
        if prime[i] != 1: 
            while j < N:
                if lpf[j] > i:
                    lpf[j] = i
                prime[j] = 1
                j += i
        i += 1
def abcd():
    data = (line for line in stdin.read().splitlines())
    #T = input()
    T = int(next(data))
    lpf_sieve()
    for i in xrange(T):
        #R = input()
        R = int(next(data))
        print R-lpf[R]
abcd()