You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
import java.util.*;

public class Main {

    public static void main(String[] args) {
        Scanner scanner = new Scanner (System.in);
        int n =  scanner.nextInt();
        scanner.nextLine();
        ArrayList<String> arrayList = new ArrayList<>();
        for (int i = 0; i < n ; i++){
            arrayList.add(scanner.nextLine());
        }
        Collections.sort(arrayList, new Comparator<String>() {
            @Override
            public int compare(String o1, String o2) {
                if (o1.length() != o2.length()) return o1.length() - o2.length();
                else return o1.compareTo(o2);
            }
        });
        for (int i = 0 ; i <n-1 ; i++){
            String str1 = arrayList.get(i);
            String str2 = arrayList.get(i+1);
            if (!str2.contains(str1)){
                System.out.println("NO");
                return;
            }
        }
        System.out.println("YES");
        for(String str : arrayList){
            System.out.println(str);
        }
    }
}
