You are given a string q. A sequence of k strings s1, s2, ..., sk is called beautiful, if the concatenation of these strings is string q (formally, s1 + s2 + ... + sk = q) and the first characters of these strings are distinct.

Find any beautiful sequence of strings or determine that the beautiful sequence doesn't exist.

Input

The first line contains a positive integer k (1 ≤ k ≤ 26) — the number of strings that should be in a beautiful sequence. 

The second line contains string q, consisting of lowercase Latin letters. The length of the string is within range from 1 to 100, inclusive.

Output

If such sequence doesn't exist, then print in a single line "NO" (without the quotes). Otherwise, print in the first line "YES" (without the quotes) and in the next k lines print the beautiful sequence of strings s1, s2, ..., sk.

If there are multiple possible answers, print any of them.

Examples

Input

1
abca


Output

YES
abca


Input

2
aaacas


Output

YES
aaa
cas


Input

4
abc


Output

NO

Note

In the second sample there are two possible answers: {"aaaca", "s"} and {"aaa", "cas"}.
#include <bits/stdc++.h>
using namespace std;
bool book[26];
char a[105];
int main() {
  int k;
  cin >> k;
  cin >> a;
  for (int i = 0; a[i]; i++) book[a[i] - 'a'] = 1;
  int cnt = 0;
  for (int i = 0; i < 26; i++) cnt += book[i];
  if (cnt < k) {
    cout << "NO";
    return 0;
  }
  cout << "YES" << endl;
  for (int i = 0; a[i];) {
    if (book[a[i] - 'a']) {
      cout << a[i];
      book[a[i] - 'a'] = 0;
      i++;
      while (!book[a[i] - 'a'] && a[i]) cout << a[i++];
      k--;
      if (!k) {
        while (a[i]) cout << a[i++];
      }
      cout << endl;
    }
  }
  return 0;
}
