You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
import java.util.*;

public class SubstribgSort_285C {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		String s[] = new String[n];
		for(int i = 0; i<n; i++) {
			s[i] = sc.next();
		}
		int N = n;
		while(N-->0) {
			for(int i = 0; i<n-1; i++) {
				int a = s[i].length();
				int b = s[i+1].length();
				if(a<=b) {
					continue;
				}
				else {
					String temp = s[i];
					s[i] = s[i+1];
					s[i+1] = temp;
				}
			}
		}

		boolean c = true;
		loop1:for(int i = 0; i<n-1; i++) {
			String q = s[i];
			for(int j = i+1; j<n; j++) {
				if(s[j].contains(q)) {
					continue;
				}
				else {
					c = false;
					break loop1;
				}
			}
		}
		if(c) {
			System.out.println("YES");
			for(int i = 0; i<n; i++) {
			System.out.println(s[i]);
		}
			
		}
		else {
			System.out.println("NO");
		}

	}

}