Polycarp is practicing his problem solving skill. He has a list of n problems with difficulties a_1, a_2, ..., a_n, respectively. His plan is to practice for exactly k days. Each day he has to solve at least one problem from his list. Polycarp solves the problems in the order they are given in his list, he cannot skip any problem from his list. He has to solve all n problems in exactly k days.

Thus, each day Polycarp solves a contiguous sequence of (consecutive) problems from the start of the list. He can't skip problems or solve them multiple times. As a result, in k days he will solve all the n problems.

The profit of the j-th day of Polycarp's practice is the maximum among all the difficulties of problems Polycarp solves during the j-th day (i.e. if he solves problems with indices from l to r during a day, then the profit of the day is max_{l ≤ i ≤ r}a_i). The total profit of his practice is the sum of the profits over all k days of his practice.

You want to help Polycarp to get the maximum possible total profit over all valid ways to solve problems. Your task is to distribute all n problems between k days satisfying the conditions above in such a way, that the total profit is maximum.

For example, if n = 8, k = 3 and a = [5, 4, 2, 6, 5, 1, 9, 2], one of the possible distributions with maximum total profit is: [5, 4, 2], [6, 5], [1, 9, 2]. Here the total profit equals 5 + 6 + 9 = 20.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 2000) — the number of problems and the number of days, respectively.

The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 2000) — difficulties of problems in Polycarp's list, in the order they are placed in the list (i.e. in the order Polycarp will solve them).

Output

In the first line of the output print the maximum possible total profit.

In the second line print exactly k positive integers t_1, t_2, ..., t_k (t_1 + t_2 + ... + t_k must equal n), where t_j means the number of problems Polycarp will solve during the j-th day in order to achieve the maximum possible total profit of his practice.

If there are many possible answers, you may print any of them.

Examples

Input

8 3
5 4 2 6 5 1 9 2


Output

20
3 2 3

Input

5 1
1 1 1 1 1


Output

1
5


Input

4 2
1 2000 2000 2


Output

4000
2 2

Note

The first example is described in the problem statement.

In the second example there is only one possible distribution.

In the third example the best answer is to distribute problems in the following way: [1, 2000], [2000, 2]. The total profit of this distribution is 2000 + 2000 = 4000.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Random;
import java.util.StringTokenizer;


public class Main {

	static boolean visited[] ; 
	static boolean ends[] ;
	static long mod = 1000000007 ;
	static int lens[] ; 
	static int seeds[] ; 
	static char a[] ;
	static double total ; 
	public static ArrayList adj[] ; 
	public static long x,y ;
	public static ArrayList<Integer> xx ;	
	public static double dp[][][] ;
	public static void main(String[] args) throws IOException, InterruptedException {
		Scanner sc =  new Scanner(System.in) ;


		int n = sc.nextInt() ; 
		int k = sc.nextInt() ; 

		int b[] = new int[n];
		int a[] = new int[n] ;
		for (int i = 0; i <n; i++)
		{
			int x =sc.nextInt() ; 
			b[i]=x ;
			a[i]=x ;
		}


		Arrays.sort(a);
		if(k==1)
		{

			System.out.println(a[n-1]);
			System.out.println(n);
			return ;
		}

		int s=0 ;
		int c[] = new int[k];
		for (int i = a.length-1, j=0; i>=0 && k>0 ; i--)
		{
			s += a[i];
			k--;
			c[j++]=a[i];
		}

		ArrayList<Integer> xx = new ArrayList<Integer>() ; 

		for (int i = 0; i < b.length; i++)
		{
			for (int j = 0; j < c.length; j++)
			{
				if(b[i]==c[j])
				{
					xx.add(i); 
					c[j]=-1;
					break ;
				}
			}
		}


		System.out.println(s);
		System.out.print((xx.get(0)+1)+" ");
		for (int i = 1; i < xx.size()-1; i++)
		{
			System.out.print(xx.get(i)-xx.get(i-1)+" ");
		}
		System.out.print(n-xx.get(xx.size()-2)-1);


	}

	static void generate(int n)
	{
		if(n>=10000000)
			return ; 

		xx.add(n) ; 
		generate(Integer.parseInt("4"+n)) ;
		generate(Integer.parseInt("7"+n)) ;

	}


	static long pow(long base, int exp) {
		long res = 1;
		while(exp > 0) {
			if(exp % 2 == 1) {
				res = (res * base);
			}

			base = (base * base) ;
			exp /= 2;
		}

		return res;
	}
































	public static void dfss(int root , int len)
	{
		visited[root]=true ; 
		if(ends[root] && root!=0) lens[root] = len ; 

		for (int i = 0; i < adj[root].size(); i++)
		{
			int c= (int) adj[root].get(i) ; 
			if(visited[c]==false)
				dfss(c, len+1);
		}
	}

	public static void pr(int root ,  int seed){
		visited[root] = true ;
		int dv = adj[root].size()-1 ; 
		if(root==0) dv++ ;

		for (int i = 0; i < adj[root].size(); i++)
		{
			int c = (int)adj[root].get(i) ; 
			seeds[c]=dv*seed ;
		}

		for (int i = 0; i < adj[root].size() ; i++)
		{
			int c = (int)adj[root].get(i) ; 
			if(visited[c]==false)
				pr(c , seeds[c]);

		}

	}



	static class Scanner {
		StringTokenizer st;
		BufferedReader br;

		public Scanner(InputStream s) {
			br = new BufferedReader(new InputStreamReader(s));
		}

		public String next() throws IOException {
			while (st == null || !st.hasMoreTokens())
				st = new StringTokenizer(br.readLine());
			return st.nextToken();
		}

		public int nextInt() throws IOException {
			return Integer.parseInt(next());
		}

		public long nextLong() throws IOException {
			return Long.parseLong(next());
		}

		public String nextLine() throws IOException {
			return br.readLine();
		}

		public double nextDouble() throws IOException {
			return Double.parseDouble(next());
		}

		public boolean ready() throws IOException {
			return br.ready();
		}

		public int[] nextIntArray(int n) throws IOException {
			int arr[] = new int[n];
			for (int i = 0; i <n ; i++)
			{
				arr[i] = Integer.parseInt(next());
			}
			return arr;
		}
		public long[] nextLongArray(int n) throws IOException {
			long arr[] = new long[n];
			for (int i = 0; i <n ; i++)
			{
				arr[i] = Long.valueOf(next());
			}
			return arr;
		}
	}


	public static long getGCD(long n1, long n2) {
		if (n2 == 0) {
			return n1;
		}
		return getGCD(n2, n1 % n2);
	}


	public static void shuffle(ArrayList<Integer> ss){
		if(ss.size()==1)
			return ; 
		for (int i = 0; i < ss.size(); i++)
		{
			Random rand = new Random();

			int  n = rand.nextInt(ss.size()-1) + 0;

			int tmp = ss.get(n);
			ss.remove(n);
			ss.add(tmp);
		}
	}
	//	public static int binary(ArrayList<pair> arr, int l, int r, long x)   /// begin by 0 and n-1
	//	{
	//		if (r>=l)
	//		{
	//			int mid = l + (r - l)/2;
	//			if (arr.get(mid).x== x)
	//				return mid;
	//			if (arr.get(mid).x> x)
	//				return binary(arr, l, mid-1, x);
	//			return binary(arr, mid+1, r, x);
	//		}
	//		return -1;
	//	}

	/// searching for the index of first elment greater than x
	public static int binary1(int[]arr , int x) {
		int low = 0, high = arr.length; // numElems is the size of the array i.e arr.size() 
		while (low != high) {
			int mid = (low + high) / 2; // Or a fancy way to avoid int overflow
			if (arr[mid] <= x) {
				/* This index, and everything below it, must not be the first element
				 * greater than what we're looking for because this element is no greater
				 * than the element.
				 */
				low = mid + 1;
			}
			else {
				/* This element is at least as large as the element, so anything after it can't
				 * be the first element that's at least as large.
				 */
				high = mid;
			}
		}
		return low ; // return high ; 
	}


	////// searching for last element less than X 
	//	public static int binary2(pair[]arr , int x) {
	//		int low = 0, high = arr.length; // numElems is the size of the array i.e arr.size() 
	//		while (low != high) {
	//			int mid = (low + high) / 2; // Or a fancy way to avoid int overflow
	//			if (arr[mid].x >= x) {
	//				/* This index, and everything below it, must not be the first element
	//				 * greater than what we're looking for because this element is no greater
	//				 * than the element.
	//				 */
	//				high=mid;
	//			}
	//			else {
	//				/* This element is at least as large as the element, so anything after it can't
	//				 * be the first element that's at least as large.
	//				 */
	//				low = mid+1 ; 
	//			}
	//		}
	//		return low ; // return high ; 
	//	}







	public static int binary(long []arr , long target , int low , long shift) {
		int high = arr.length; 
		while (low != high) {
			int mid = (low + high) / 2; 
			if (arr[mid]-shift <= target) {
				low = mid + 1;
			}
			else {
				high = mid;
			}
		}
		return low ; // return high ; 
	}
	public static boolean isLetter(char x){
		if(x+0 <=122 && x+0 >=97 )
			return true ;
		else if (x+0 <=90 && x+0 >=65 )
			return true ; 
		else return false; 
	}
	public static long getPrimes(long x ){
		if(x==2 || x==3 || x==1)
			return 2 ;
		if(isPrime(x))
			return 5 ;
		for (int i = 2; i*i<=x; i++)
		{
			if(x%i==0 && isPrime(i))
				return getPrimes(x/i) ;
		}
		return -1;
	}







	public static int lis( int[]a , int n){
		int lis[] = new int[n] ; 
		Arrays.fill(lis,1) ; 

		for(int i=1;i<n;i++)
			for(int j=0 ; j<i; j++)
				if (a[i]>a[j] &&  lis[i] < lis[j]+1)   
					lis[i] = lis[j] + 1;           

		int max = lis[0];

		for(int i=1; i<n ; i++)
			if (max < lis[i])
				max = lis[i] ;
		return (max);

		//			ArrayList<Integer> s = new ArrayList<Integer>() ;
		//			for (int i = n-1; i >=0; i--)
		//			{
		//				if(lis[i]==max)
		//				{
		//					s.add(a[i].z);
		//					max --; 
		//				}
		//			}
		//
		//			for (int i = s.size()-1 ; i>=0 ;  i--)
		//			{
		//				System.out.print(s.get(i)+" ");
		//			}
		//
	}
	public static int calcDepth(Vertix node){
		if(node.depth>0) return node.depth; 
		// meaning it has been updated before;
		if(node.parent != null)
			return 1+ calcDepth(node.parent);
		else
			return -1;
	}

	public static boolean isPrime (long num){
		if (num < 2) return false;
		if (num == 2) return true;
		if (num % 2 == 0) return false;
		for (int i = 3; i * i <= num; i += 2)
			if (num % i == 0) return false;
		return true;
	}


	public static ArrayList<Long> getDiv(Long n)
	{
		ArrayList<Long>  f = new ArrayList<Long>() ; 

		while (n%2==0)
		{
			if(!f.contains(2))f.add((long) 2) ;
			n /= 2;
		}

		// n must be odd at this point.  So we can
		// skip one element (Note i = i +2)
		for (long i = 3; i <= Math.sqrt(n); i+= 2)
		{
			// While i divides n, print i and divide n
			while (n%i == 0)
			{
				if(!f.contains(i))f.add(i);
				n /= i;
			}
		}

		// This condition is to handle the case whien
		// n is a prime number greater than 2
		if (n > 2)
			if(!f.contains(n))f.add(n);


		return f ;



	}

	//		public static boolean dfs(Vertix v , int target){
	//			try{
	//				visited[v.i]= true ;
	//			} catch (NullPointerException e)
	//			{
	//				System.out.println(v.i);
	//			}
	//			if(v.i == target)
	//
	//				return true ;
	//			for (int i =0 ; i< v.neighbours.size() ; i++)
	//			{ 
	//
	//				Vertix child = v.neighbours.get(i) ;
	//				if(child.i == target){
	//					found = true  ; 
	//				}
	//				if(visited[child.i]==false){
	//					found |= dfs(child, target) ;
	//				}
	//			}
	//			return found; 
	//		}









	public static class Vertix{
		long i ; 
		int depth ;
		ArrayList<Vertix> neighbours ; 
		Vertix parent ; 
		Vertix child ; 


		public Vertix(long i){
			this.i = i ;
			this.neighbours = new ArrayList<Vertix> () ;
			this.parent = null ;
			depth =-1;
			this.child = null ;
		}
	}

	public static class pair implements Comparable<pair> {
		int x ; 
		int y ; 




		public pair(int x, int y ){

			this.x=x ; 
			this.y =y ;


		}


		@Override
		public int compareTo(pair p) {
			if(this.y-this.x > p.y-p.x)
				return 1 ; 
			else if (this.y-this.x == p.y-p.x) 
				return 0 ; 
			else 
				return -1 ;
		}




	}

	public static class pair2 implements Comparable<pair2>{
		int i ; 
		int j ;
		int plus ;

		public pair2(int i , int j , int plus){
			this.i =i ;
			this.j = j ; 
			this.plus = plus ;
		}

		@Override
		public int compareTo(pair2 p) {
			if(this.j > p.j)
				return 1 ; 
			else if (this.j == p.j) return 0 ;
			else 
				return -1 ;
		}


	}
	public static class point implements  Comparable<point>
	{
		int x, y ; 
		public point(int x,int y){
			this.x=x ; this.y=y;
		}
		@Override
		public boolean equals(Object o) {

			// If the object is compared with itself then return true  
			if (o == this) {
				return true;
			}

			/* Check if o is an instance of Complex or not
	          "null instanceof [type]" also returns false */
			if (!(o instanceof point)) {
				return false;
			}

			// typecast o to Complex so that we can compare data members 
			point c = (point) o;

			// Compare the data members and return accordingly 
			return Integer.compare(x, c.x) == 0
					&& Integer.compare(y, c.y) == 0;
		}
		@Override
		public int compareTo(point p) {
			if(this.x == p.x && this.y ==p.y)
				return 0 ; 
			else
				return -1 ; 
		}

		@Override
		public int hashCode()
		{
			return 15+x+(y%2) ;
		}



	}


}