You are given a string q. A sequence of k strings s1, s2, ..., sk is called beautiful, if the concatenation of these strings is string q (formally, s1 + s2 + ... + sk = q) and the first characters of these strings are distinct.

Find any beautiful sequence of strings or determine that the beautiful sequence doesn't exist.

Input

The first line contains a positive integer k (1 ≤ k ≤ 26) — the number of strings that should be in a beautiful sequence. 

The second line contains string q, consisting of lowercase Latin letters. The length of the string is within range from 1 to 100, inclusive.

Output

If such sequence doesn't exist, then print in a single line "NO" (without the quotes). Otherwise, print in the first line "YES" (without the quotes) and in the next k lines print the beautiful sequence of strings s1, s2, ..., sk.

If there are multiple possible answers, print any of them.

Examples

Input

1
abca


Output

YES
abca


Input

2
aaacas


Output

YES
aaa
cas


Input

4
abc


Output

NO

Note

In the second sample there are two possible answers: {"aaaca", "s"} and {"aaa", "cas"}.
#include <bits/stdc++.h>
using namespace std;
bool a[26];
int sum;
int k;
string s;
int main() {
  cin >> k;
  cin >> s;
  for (int i = 0; i < s.size(); ++i) {
    a[s[i] - 'a'] = 1;
  }
  for (int i = 0; i < 26; ++i)
    if (a[i]) sum++;
  if (sum < k)
    puts("NO");
  else {
    printf("YES");
    memset(a, 0, sizeof a);
    int ss = k;
    for (int i = 0; i < s.size(); ++i) {
      if (ss == 0) {
        for (int j = i; j < s.size(); ++j) cout << s[j];
        return 0;
      }
      if (a[s[i] - 'a'] == 0) {
        cout << endl;
        --ss;
      }
      a[s[i] - 'a'] = 1;
      cout << s[i];
    }
  }
  return 0;
}
