You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
import java.util.Scanner;

public class Substring_Sort {

	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		int x = Integer.parseInt(in.nextLine());
		String arr[] = new String[x];
		for(int i = 0; i < x; i++) {
			arr[i] = in.nextLine();
		}
		
		for(int i = 0; i < x; i++) {
			for(int j = 0; j < x; j++) {
				if(arr[j].contains(arr[i])) {
					String temp = arr[i];
					arr[i] = arr[j];
					arr[j] = temp;					
				}
			}
		}
		
		String ans = "YES";
		boolean cont = true;
		for(int i = 0; i < arr.length-1; i++) {
			if(arr[i+1].contains(arr[i]) == false) {
				cont = false;
				ans = "NO";
				break;
			}
		}
		System.out.println(ans);
		if(cont) {
			for(int i = 0; i < arr.length; i++) {
				System.out.println(arr[i]);
			}
		}

	}

}
