Vasya has got n books, numbered from 1 to n, arranged in a stack. The topmost book has number a_1, the next one — a_2, and so on. The book at the bottom of the stack has number a_n. All numbers are distinct.

Vasya wants to move all the books to his backpack in n steps. During i-th step he wants to move the book number b_i into his backpack. If the book with number b_i is in the stack, he takes this book and all the books above the book b_i, and puts them into the backpack; otherwise he does nothing and begins the next step. For example, if books are arranged in the order [1, 2, 3] (book 1 is the topmost), and Vasya moves the books in the order [2, 1, 3], then during the first step he will move two books (1 and 2), during the second step he will do nothing (since book 1 is already in the backpack), and during the third step — one book (the book number 3). Note that b_1, b_2, ..., b_n are distinct.

Help Vasya! Tell him the number of books he will put into his backpack during each step.

Input

The first line contains one integer n~(1 ≤ n ≤ 2 ⋅ 10^5) — the number of books in the stack.

The second line contains n integers a_1, a_2, ..., a_n~(1 ≤ a_i ≤ n) denoting the stack of books.

The third line contains n integers b_1, b_2, ..., b_n~(1 ≤ b_i ≤ n) denoting the steps Vasya is going to perform.

All numbers a_1 ... a_n are distinct, the same goes for b_1 ... b_n.

Output

Print n integers. The i-th of them should be equal to the number of books Vasya moves to his backpack during the i-th step.

Examples

Input

3
1 2 3
2 1 3


Output

2 0 1 


Input

5
3 1 4 2 5
4 5 1 3 2


Output

3 2 0 0 0 


Input

6
6 5 4 3 2 1
6 5 3 4 2 1


Output

1 1 2 0 1 1 

Note

The first example is described in the statement.

In the second example, during the first step Vasya will move the books [3, 1, 4]. After that only books 2 and 5 remain in the stack (2 is above 5). During the second step Vasya will take the books 2 and 5. After that the stack becomes empty, so during next steps Vasya won't move any books.
import java.util.*;
import java.io.*;
import java.math.BigInteger;
public class Bedu53{
public static long mod = 1000000007;
public static int dx[] = {-1,0,1,0,-1,-1,1,1,-1};//primero ady, despues esq
public static int dy[] = {0,1,0,-1,1,1,-1,-1};
public static void main(String args[]) throws IOException{
StringBuilder sb = new StringBuilder("");
BufferedReader lector = new BufferedReader(new InputStreamReader(System.in));
//String tmp[] = lector.readLine().split(" ");
int cas = Integer.parseInt(lector.readLine());
String t[] = lector.readLine().split(" ");
String tt[] = lector.readLine().split(" ");
int a[] = new int[cas];
int b[] = new int[cas];
int c[] = new int[cas+1];
int lastin = -1;
for(int n =0;n<cas;n++){
a[n]=Integer.parseInt(t[n]);
c[a[n]]=n;
b[n]=Integer.parseInt(tt[n]);
}
for(int n = 0;n<cas;n++){
int newin = c[b[n]];
if(newin>=lastin){
sb.append((newin-lastin)+" ");
lastin = newin;
}else{
sb.append("0 ");
}
}
System.out.println(sb.substring(0,sb.length()-1));
}

}
class p implements Comparable{
public int a;
public p(int a){
this.a = a;
}
public String toString(){
return "";
}
public int compareTo(Object o){
p pp = (p)o;
return (int)Math.signum(a-pp.a);
}
}
//sergio1
