You are given two integers n and m. Calculate the number of pairs of arrays (a, b) such that:

  * the length of both arrays is equal to m; 
  * each element of each array is an integer between 1 and n (inclusive); 
  * a_i ≤ b_i for any index i from 1 to m; 
  * array a is sorted in non-descending order; 
  * array b is sorted in non-ascending order. 



As the result can be very large, you should print it modulo 10^9+7.

Input

The only line contains two integers n and m (1 ≤ n ≤ 1000, 1 ≤ m ≤ 10).

Output

Print one integer – the number of arrays a and b satisfying the conditions described above modulo 10^9+7.

Examples

Input


2 2


Output


5


Input


10 1


Output


55


Input


723 9


Output


157557417

Note

In the first test there are 5 suitable arrays: 

  * a = [1, 1], b = [2, 2]; 
  * a = [1, 2], b = [2, 2]; 
  * a = [2, 2], b = [2, 2]; 
  * a = [1, 1], b = [2, 1]; 
  * a = [1, 1], b = [1, 1]. 
def mod_inverse(n, mod=10**9+7):
    return pow(n, mod-2, mod)


def combination(n, k, mod=10**9+7):
    numer = denom = 1
    for i in range(k):
        numer = (numer * (n-i)) % mod
        denom = (denom * (i+1)) % mod
    return (numer * mod_inverse(denom, mod)) % mod


mod = 10**9+7
n, m = map(int, input().split())
ans = 0

for k in range(1, n+1):
    ans += combination(m+k-2, k-1) * combination(m+n-k, n-k)
    ans %= mod
print(ans)
