You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".

def main():
    n = int(input())
    strings = {}
    strings1 = {}
    S = []
    for i in range(n):
        s = input()
        strings[s] = 0
        if s in strings1:
            strings1[s] += 1
        else: strings1[s] = 1
        S.append(s)

    for s1 in S:
        for s2 in S:
            if s1.find(s2) == -1 and s2.find(s1) == -1:
                print("NO")
                return

    for cur_string in strings:
        for another_string in S:
            if cur_string != another_string and another_string.find(cur_string) != -1:
                strings[cur_string] += 1
    
    q = 0
    for s in strings:
        if strings[s] == 0:
            q += 1
            if q >= 2:
                break
    if q >= 2:
        print("NO")
        return
    
    print("YES")

    for x in sorted(strings.items(), key = lambda kv: (kv[1], kv[0]), reverse=True):
        for i in range(strings1[x[0]]):
            print(x[0])


main()