You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".

import java.util.*;

public class training {

    static class cl implements Comparator<String> {

        public int compare(String o1, String o2) {
            return (o1.length() - o2.length());
        }
    }

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int n = in.nextInt();
        String[] t = new String[n];
        for (int i = 0; i < n; i++) {
            t[i] = in.next();
        }
        int i = 1;
        Arrays.sort(t, new cl());
        /*for (int j = 0; j < n; j++) {
            System.out.println(t[j]);
        }*/
        boolean v = true;
        while (i < n && v) {
            v = t[i].contains(t[i - 1]);
            i++;
        }
        if (v) {
            System.out.println("YES");
            for (String ti : t) {
                System.out.println(ti);
            }
        } else {
            System.out.println("NO");
        }
    }
}
