You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
import java.util.*;
public class B_01_06_2018 {

	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		
		int n = sc.nextInt();
		ArrayList<String> s = new ArrayList<String>();
		ArrayList<String> ss = new ArrayList<String>();
		ArrayList<Integer> l = new ArrayList<Integer>();
		
		for(int i=0;i<n;i++) {
			s.add(sc.next());
			l.add(s.get(i).length());
		}
		
		if(n == 1) {
			System.out.println("YES");
			System.out.println(s.get(0));
			System.exit(0);
		}
		
		for(int i=0;i<n;i++) {
			int x = l.indexOf(Collections.min(l));
			ss.add(s.get(x));
			l.remove(x);
			s.remove(x);
		}
		//System.out.println(ss);////////////////////////
		
		for(int i=1;i<n;i++) {
			if(ss.get(i) != ss.get(i-1) & !ss.get(i).contains(ss.get(i-1))) {
				System.out.println("NO");
				System.exit(0);
			}
		}
		
		System.out.println("YES");
		for(int i=0;i<n;i++) System.out.println(ss.get(i));
		
		sc.close();

	}

}
