You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".


import java.util.*;

public class Main {
        public static void main(String[] args){
        Scanner input = new Scanner(System.in);
           int n = input.nextInt();
           if(n==1){
               String ss = input.next();
               System.out.println("YES");
               System.out.println(ss);
           }
           else{
           String [] s = new String[n];
            for (int i = 0; i < n; i++) {
                s[i]= input.next();
            
            }
            Arrays.sort(s, (x,y) -> Integer.compare(x.length(),y.length()));
            Boolean x = false;
            for (int i = 0; i < s.length-1; i++) {
                if(s[i+1].contains(s[i])){
                    x= true;
                }
                else{
                    x = false;
                break;}
            }
            if(x == true){
                System.out.println("YES");
                for (int i = 0; i < s.length; i++) {
                    System.out.println(s[i]);
                }
            }
            else
                System.out.println("NO");
            
            }
        }
}

          
        



