You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
//package Div3;

import java.util.Arrays;
import java.util.Comparator;
import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		Scanner sc =new Scanner(System.in);
		int n=sc.nextInt();
		
		String s[]=new String[n];
		for(int i=0;i<n;i++)
		{
			s[i]=sc.next();
			
		}
		//System.out.println(Arrays.toString(s));
		Arrays.sort(s,new Comparator<String>() {

			@Override
			public int compare(String o1, String o2) {
				// TODO Auto-generated method stub
				return o1.length()-o2.length();
			}
			
		});
		String ans="YES";
		for(int i=0;i<n;i++)
		{
			for(int j=i+1;j<n;j++)
			{
				if(s[j].indexOf(s[i])==-1)
				{
					ans="NO";
					break;
				}
			}
		}
		if(ans=="YES")
		{
			System.out.println("YES");
			for(int i=0;i<n;i++)
			{
				System.out.println(s[i]);
			}
			//System.out.println();
		}
		else
		{
			System.out.println("NO");
		}
		

	}

}
