You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
import java.util.Arrays;
import java.util.Scanner;

public class CF988_B {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);

        int n = in.nextInt();
        String[] arr = new String[n];

        for (int i = 0; i < n; i++) {
            arr[i] = in.next();
        }

        Arrays.sort(arr, (o1, o2) -> {
            if (o1.contains(o2)) {
                return 1;
            } else if (o2.contains(o1)) {
                return -1;
            } else {
                return 0;
            }
        });


        boolean ok = true;
        for (int i = arr.length - 1; i >= 1; i--) {
            if (!arr[i].contains(arr[i-1])) {
                ok = false;
                break;
            }
        }

        if (ok) {
            System.out.println("YES");
            for (String a: arr) {
                System.out.println(a);
            }
        } else {
            System.out.println("NO");
        }

    }
}