You are given a string q. A sequence of k strings s1, s2, ..., sk is called beautiful, if the concatenation of these strings is string q (formally, s1 + s2 + ... + sk = q) and the first characters of these strings are distinct.

Find any beautiful sequence of strings or determine that the beautiful sequence doesn't exist.

Input

The first line contains a positive integer k (1 ≤ k ≤ 26) — the number of strings that should be in a beautiful sequence. 

The second line contains string q, consisting of lowercase Latin letters. The length of the string is within range from 1 to 100, inclusive.

Output

If such sequence doesn't exist, then print in a single line "NO" (without the quotes). Otherwise, print in the first line "YES" (without the quotes) and in the next k lines print the beautiful sequence of strings s1, s2, ..., sk.

If there are multiple possible answers, print any of them.

Examples

Input

1
abca


Output

YES
abca


Input

2
aaacas


Output

YES
aaa
cas


Input

4
abc


Output

NO

Note

In the second sample there are two possible answers: {"aaaca", "s"} and {"aaa", "cas"}.
#include <bits/stdc++.h>
using namespace std;
int main() {
  long long k, j = 1;
  string q, b;
  char a;
  cin >> k >> q;
  if (k > q.size()) {
    cout << "NO";
  } else {
    vector<char> r;
    r.push_back(q[0]);
    vector<string> t;
    for (int i = 0; i < q.size(); i++) {
      for (int j = 0; j < r.size(); j++) {
        if (q[i] == r[j]) {
          break;
        } else if (j == r.size() - 1) {
          r.push_back(q[i]);
          t.push_back(b);
          b.clear();
        }
      }
      b += q[i];
    }
    t.push_back(b);
    if (t.size() >= k) {
      cout << "YES" << endl;
      if (t.size() == k) {
        for (int i = 0; i < t.size(); i++) {
          cout << t[i] << endl;
        }
      } else {
        for (int i = 0; i < t.size() - k + 1; i++) {
          cout << t[i];
        }
        cout << endl;
        for (int i = t.size() - k + 1; i < t.size(); i++) {
          cout << t[i] << endl;
        }
      }
    } else {
      cout << "NO";
    }
  }
  return 0;
}
