An army of n droids is lined up in one row. Each droid is described by m integers a1, a2, ..., am, where ai is the number of details of the i-th type in this droid's mechanism. R2-D2 wants to destroy the sequence of consecutive droids of maximum length. He has m weapons, the i-th weapon can affect all the droids in the army by destroying one detail of the i-th type (if the droid doesn't have details of this type, nothing happens to it). 

A droid is considered to be destroyed when all of its details are destroyed. R2-D2 can make at most k shots. How many shots from the weapon of what type should R2-D2 make to destroy the sequence of consecutive droids of maximum length?

Input

The first line contains three integers n, m, k (1 ≤ n ≤ 105, 1 ≤ m ≤ 5, 0 ≤ k ≤ 109) — the number of droids, the number of detail types and the number of available shots, respectively.

Next n lines follow describing the droids. Each line contains m integers a1, a2, ..., am (0 ≤ ai ≤ 108), where ai is the number of details of the i-th type for the respective robot.

Output

Print m space-separated integers, where the i-th number is the number of shots from the weapon of the i-th type that the robot should make to destroy the subsequence of consecutive droids of the maximum length.

If there are multiple optimal solutions, print any of them. 

It is not necessary to make exactly k shots, the number of shots can be less.

Examples

Input

5 2 4
4 0
1 2
2 1
0 2
1 3


Output

2 2


Input

3 2 4
1 2
1 3
2 2


Output

1 3

Note

In the first test the second, third and fourth droids will be destroyed. 

In the second test the first and second droids will be destroyed.
#include <bits/stdc++.h>
using namespace std;
const double PI = acos(-1);
const double eps = 1e-9;
const int inf = 2000000000;
const long long infLL = 9000000000000000000;
inline bool checkBit(long long n, int i) { return n & (1LL << i); }
inline long long setBit(long long n, int i) { return n | (1LL << i); }
inline long long resetBit(long long n, int i) { return n & (~(1LL << i)); }
int dx4[] = {0, 0, +1, -1};
int dy4[] = {+1, -1, 0, 0};
int dx8[] = {+1, 0, -1, 0, +1, +1, -1, -1};
int dy8[] = {0, +1, 0, -1, +1, -1, +1, -1};
inline bool EQ(double a, double b) { return fabs(a - b) < 1e-9; }
inline bool isLeapYear(long long year) {
  return (year % 400 == 0) || (year % 4 == 0 && year % 100 != 0);
}
inline bool isIntege(double num) { return (num == (int)num); }
inline bool collinear(int x1, int y1, int x2, int y2, int x3, int y3) {
  return (y1 - y2) * (x1 - x3) == (y1 - y3) * (x1 - x2);
}
inline double coDist(double x1, double y1, double x2, double y2) {
  return sqrt(((x1 - x2) * (x1 - x2)) + ((y1 - y2) * (y1 - y2)));
}
inline double TriangleAreaWithSide(double a, double b, double c) {
  double s = (a + b + c) / 2;
  double area = sqrt(s * (s - a) * (s - b) * (s - c));
  return area;
}
inline double area3(double x1, double y1, double x2, double y2, double x3,
                    double y3) {
  double A = abs((x1 * y2 + x2 * y3 + x3 * y1) - (y1 * x2 + y2 * x3 + y3 * x1));
  A /= 2.0;
  return A;
}
inline long double degreetoradian(long double x) {
  long double val = PI * x;
  val /= (180.0);
  return val;
}
inline void normal(long long &a) {
  a %= 1000000007;
  (a < 0) && (a += 1000000007);
}
template <typename T>
inline T gcd(T a, T b) {
  T c;
  while (b) {
    c = b;
    b = a % b;
    a = c;
  }
  return a;
}
inline long long modMul(long long a, long long b) {
  a %= 1000000007, b %= 1000000007;
  normal(a), normal(b);
  return (a * b) % 1000000007;
}
inline long long modAdd(long long a, long long b) {
  a %= 1000000007, b %= 1000000007;
  normal(a), normal(b);
  return (a + b) % 1000000007;
}
inline long long modSub(long long a, long long b) {
  a %= 1000000007, b %= 1000000007;
  normal(a), normal(b);
  a -= b;
  normal(a);
  return a;
}
inline long long modPow(long long b, long long p) {
  long long r = 1;
  while (p) {
    if (p & 1) r = modMul(r, b);
    b = modMul(b, b);
    p >>= 1;
  }
  return r;
}
inline long long modInverse(long long a) { return modPow(a, 1000000007 - 2); }
inline long long modDiv(long long a, long long b) {
  return modMul(a, modInverse(b));
}
inline bool equalTo(double a, double b) {
  if (fabs(a - b) <= eps)
    return true;
  else
    return false;
}
inline bool notEqual(double a, double b) {
  if (fabs(a - b) > eps)
    return true;
  else
    return false;
}
inline bool lessThan(double a, double b) {
  if (a + eps < b)
    return true;
  else
    return false;
}
inline bool lessThanEqual(double a, double b) {
  if (a < b + eps)
    return true;
  else
    return false;
}
inline bool greaterThan(double a, double b) {
  if (a > b + eps)
    return true;
  else
    return false;
}
inline bool greaterThanEqual(double a, double b) {
  if (a + eps > b)
    return true;
  else
    return false;
}
inline string to_s(int t) {
  stringstream ss;
  ss << t;
  return ss.str();
}
struct edge {
  int p, q, w;
};
bool cmp(edge &a, edge &b) { return a.w < b.w; }
template <typename first, typename second>
ostream &operator<<(ostream &os, const pair<first, second> &p) {
  return os << "(" << p.first << ", " << p.second << ")";
}
template <typename T>
ostream &operator<<(ostream &os, const vector<T> &v) {
  os << "{";
  for (auto it = v.begin(); it != v.end(); ++it) {
    if (it != v.begin()) os << ", ";
    os << *it;
  }
  return os << "}";
}
template <typename T>
ostream &operator<<(ostream &os, const set<T> &v) {
  os << "[";
  for (auto it = v.begin(); it != v.end(); ++it) {
    if (it != v.begin()) os << ", ";
    os << *it;
  }
  return os << "]";
}
template <typename T>
ostream &operator<<(ostream &os, const multiset<T> &v) {
  os << "[";
  for (auto it = v.begin(); it != v.end(); ++it) {
    if (it != v.begin()) os << ", ";
    os << *it;
  }
  return os << "]";
}
template <typename first, typename second>
ostream &operator<<(ostream &os, const map<first, second> &v) {
  os << "[";
  for (auto it = v.begin(); it != v.end(); ++it) {
    if (it != v.begin()) os << ", ";
    os << it->first << " = " << it->second;
  }
  return os << "]";
}
clock_t tStart = clock();
void faltu() { cerr << '\n'; }
template <typename T>
void faltu(T a[], int n) {
  for (int i = 0; i < n; ++i) cerr << a[i] << ' ';
  cerr << '\n';
}
template <typename T, typename... hello>
void faltu(T arg, const hello &...rest) {
  cerr << arg << ' ';
  faltu(rest...);
}
const int mx = 1e5 + 3;
int a[mx][7];
int n, m, k;
int maxi[mx][21][7], par[mx][21];
vector<int> ans;
int hi = 0;
void sptable() {
  for (int j = 1; j <= 19; j++) {
    for (int i = 1; i <= n; i++) {
      if (par[i][j - 1] != -1) {
        par[i][j] = par[par[i][j - 1]][j - 1];
      }
      for (int k = 1; k <= m; k++) {
        if (par[i][j - 1] != -1) {
          maxi[i][j][k] = max(maxi[i][j - 1][k], maxi[par[i][j - 1]][j - 1][k]);
        }
      }
    }
  }
}
void quary(int id) {
  vector<int> v;
  int x = id;
  int ar[10];
  memset(ar, 0, sizeof(ar));
  for (int j = 19; j >= 0; j--) {
    if (par[id][j] != -1) {
      int sum = 0;
      for (int i = 1; i <= m; i++) {
        sum += max(ar[i], maxi[id][j][i]);
      }
      if (sum <= k) {
        for (int i = 1; i <= m; i++) {
          ar[i] = max(ar[i], maxi[id][j][i]);
        }
        id = par[id][j];
      }
    }
  }
  if (id - x + 1 > hi) {
    ans.clear();
    hi = id - x + 1;
    for (int i = 1; i <= m; i++) ans.emplace_back(ar[i]);
  }
}
int main() {
  ios_base::sync_with_stdio(0);
  cin.tie(0);
  cout.tie(0);
  ;
  cin >> n >> m >> k;
  for (int i = 1; i <= n; i++) {
    for (int j = 1; j <= m; j++) {
      cin >> a[i][j];
    }
  }
  memset(par, -1, sizeof(par));
  for (int i = 1; i < n; i++) {
    for (int j = 1; j <= m; j++) {
      maxi[i][0][j] = max(a[i][j], a[i + 1][j]);
    }
    par[i][0] = i + 1;
  }
  sptable();
  for (int i = 1; i < n; i++) {
    quary(i);
  }
  if (ans.size() == 0) {
    for (int i = 1; i <= n; i++) {
      int sum = 0;
      for (int j = 1; j <= m; j++) {
        sum += a[i][j];
        ans.emplace_back(a[i][j]);
      }
      if (sum <= k)
        break;
      else
        ans.clear();
    }
    if (ans.size() == 0)
      for (int i = 1; i <= m; i++) ans.emplace_back(0);
  }
  for (int i = 0; i < ans.size(); i++) cout << ans[i] << " ";
}
