You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.

String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".

Input

The first line contains an integer n (1 ≤ n ≤ 100) — the number of strings.

The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.

Some strings might be equal.

Output

If it is impossible to reorder n given strings in required order, print "NO" (without quotes).

Otherwise print "YES" (without quotes) and n given strings in required order.

Examples

Input

5
a
aba
abacaba
ba
aba


Output

YES
a
ba
aba
aba
abacaba


Input

5
a
abacaba
ba
aba
abab


Output

NO


Input

3
qwerty
qwerty
qwerty


Output

YES
qwerty
qwerty
qwerty

Note

In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
import java.util.*;
public class DiverseTeam {
public static void main(String[] args) {
	Scanner sc=new Scanner (System.in);
	int n=sc.nextInt();
	String array[]=new String[n];
	for(int i=0;i<n;i++){
		array[i]=sc.next();
	}
	
	
        
        for (int i=1; i<n; ++i)
        {
            int key = array[i].length();
            String keyy=array[i];
            int j = i-1;
            while (j>=0 && array[j].length() > key)
            {
                array[j+1] = array[j];
                j = j-1;
            }
            array[j+1] = keyy;
        }
        int count=1;
        for(int i=1;i<array.length;i++){
        	if(array[i].contains(array[i-1])){
        		count++;
        	}
        }
        if(count==array.length){
        	System.out.println("YES");
        	for(int i=0;i<n;i++){
        		System.out.println(array[i]);
        	}
        }
        else {
        	System.out.println("NO");
        }
    
}
}
