You are given a string q. A sequence of k strings s1, s2, ..., sk is called beautiful, if the concatenation of these strings is string q (formally, s1 + s2 + ... + sk = q) and the first characters of these strings are distinct.

Find any beautiful sequence of strings or determine that the beautiful sequence doesn't exist.

Input

The first line contains a positive integer k (1 ≤ k ≤ 26) — the number of strings that should be in a beautiful sequence. 

The second line contains string q, consisting of lowercase Latin letters. The length of the string is within range from 1 to 100, inclusive.

Output

If such sequence doesn't exist, then print in a single line "NO" (without the quotes). Otherwise, print in the first line "YES" (without the quotes) and in the next k lines print the beautiful sequence of strings s1, s2, ..., sk.

If there are multiple possible answers, print any of them.

Examples

Input

1
abca


Output

YES
abca


Input

2
aaacas


Output

YES
aaa
cas


Input

4
abc


Output

NO

Note

In the second sample there are two possible answers: {"aaaca", "s"} and {"aaa", "cas"}.
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.List;
import java.util.StringTokenizer;

public class SetOfStrings {
	public static BufferedReader f = new BufferedReader(new InputStreamReader(System.in));
	public static StringTokenizer st;
	
	public static void main(String[] args) throws IOException {
		int k = nextInt();
		String s = nextString();
		
		List<Integer> list = new ArrayList<Integer>(); 
		boolean[] b = new boolean[26];
		for (int i = 0; i < s.length(); i++) {
			int index = s.charAt(i)-'a';
			if (!b[index]) {
				list.add(i);
				if (list.size() == k) {
					System.out.println("YES");
					list.add(s.length());
					for (int j = 0; j < k; j++)
						System.out.println(s.substring(list.get(j), list.get(j+1)));
					return;
				}
			}
			
			b[index] = true;
		}
		
		System.out.println("NO");
	}
	
	public static String nextLine() throws IOException {
		return f.readLine();
	}
	
	public static String nextString() throws IOException {
		while (st == null || !st.hasMoreTokens())
			st = new StringTokenizer(f.readLine());
		return st.nextToken();
	}
	
	public static int nextInt() throws IOException {
		return Integer.parseInt(nextString());
	}
	
	public static long nextLong() throws IOException {
		return Long.parseLong(nextString());
	}
	
	public static int[] intArray(int n) throws IOException {
		int[] a = new int[n];
		for (int i = 0; i < n; i++)
			a[i] = nextInt();
		return a;
	}
	
	public static long[] longArray(int n) throws IOException {
		long[] a = new long[n];
		for (int i = 0; i < n; i++)
			a[i] = nextLong();
		return a;
	}
}