Vasya has got n books, numbered from 1 to n, arranged in a stack. The topmost book has number a_1, the next one — a_2, and so on. The book at the bottom of the stack has number a_n. All numbers are distinct.

Vasya wants to move all the books to his backpack in n steps. During i-th step he wants to move the book number b_i into his backpack. If the book with number b_i is in the stack, he takes this book and all the books above the book b_i, and puts them into the backpack; otherwise he does nothing and begins the next step. For example, if books are arranged in the order [1, 2, 3] (book 1 is the topmost), and Vasya moves the books in the order [2, 1, 3], then during the first step he will move two books (1 and 2), during the second step he will do nothing (since book 1 is already in the backpack), and during the third step — one book (the book number 3). Note that b_1, b_2, ..., b_n are distinct.

Help Vasya! Tell him the number of books he will put into his backpack during each step.

Input

The first line contains one integer n~(1 ≤ n ≤ 2 ⋅ 10^5) — the number of books in the stack.

The second line contains n integers a_1, a_2, ..., a_n~(1 ≤ a_i ≤ n) denoting the stack of books.

The third line contains n integers b_1, b_2, ..., b_n~(1 ≤ b_i ≤ n) denoting the steps Vasya is going to perform.

All numbers a_1 ... a_n are distinct, the same goes for b_1 ... b_n.

Output

Print n integers. The i-th of them should be equal to the number of books Vasya moves to his backpack during the i-th step.

Examples

Input

3
1 2 3
2 1 3


Output

2 0 1 


Input

5
3 1 4 2 5
4 5 1 3 2


Output

3 2 0 0 0 


Input

6
6 5 4 3 2 1
6 5 3 4 2 1


Output

1 1 2 0 1 1 

Note

The first example is described in the statement.

In the second example, during the first step Vasya will move the books [3, 1, 4]. After that only books 2 and 5 remain in the stack (2 is above 5). During the second step Vasya will take the books 2 and 5. After that the stack becomes empty, so during next steps Vasya won't move any books.
import sys


def solve(io):
    N = io.read_int()
    A = io.read_int_array(N)
    B = io.read_int_array(N)

    done = [False] * (N + 1)
    p = 0
    cnt = []
    for b in B:
        if done[b]:
            cnt.append(0)
            continue
        sofar = 1
        while A[p] != b:
            done[A[p]] = True
            sofar += 1
            p += 1
        done[b] = True
        p += 1
        cnt.append(sofar)
    io.println_array(cnt)

# +---------------------+
# | TEMPLATE CODE BELOW |
# |    DO NOT MODIFY    |
# +---------------------+


class IO:
	in_stream = None
	out_stream = None
	raw = ""
	buf = []
	pos = 0

	def __init__(self, input_stream, output_stream):
		self.in_stream = input_stream
		self.out_stream = output_stream

	def read_to_buffer(self):
		self.raw = self.in_stream.readline().rstrip('\n')
		self.buf = self.raw.split()
		self.pos = 0

	def read_string(self):
		while self.pos == len(self.buf):
			self.read_to_buffer()
		ans = self.buf[self.pos]
		self.pos += 1
		return ans

	def read_int(self):
		return int(self.read_string())

	def read_float(self):
		return float(self.read_string())

	def read_string_array(self, N, offset=0):
		arr = [None] * offset
		for _ in range(0, N):
			arr.append(self.read_string())
		return arr

	def read_int_array(self, N, offset=0):
		arr = [None] * offset
		for _ in range(0, N):
			arr.append(self.read_int())
		return arr

	def read_float_array(self, N, offset=0):
		arr = [None] * offset
		for _ in range(0, N):
			arr.append(self.read_float())
		return arr

	def read_line(self):
		while self.pos == len(self.buf):
			self.read_to_buffer()
		if self.pos > 0:
			raise ValueError("Cannot call read_line in the middle of a line.")
		return self.raw

	def print(self, s):
		self.out_stream.write(str(s))

	def println(self, s):
		self.print(s)
		self.print('\n')

	def println_array(self, arr, sep=' '):
		self.println(sep.join(str(x) for x in arr))

	def flush_output(self):
		self.out_stream.flush()


pythonIO = IO(sys.stdin, sys.stdout)
solve(pythonIO)
pythonIO.flush_output()
