Drazil is playing a math game with Varda.

Let's define <image> for positive integer x as a product of factorials of its digits. For example, <image>.

First, they choose a decimal number a consisting of n digits that contains at least one digit larger than 1. This number may possibly start with leading zeroes. Then they should find maximum positive number x satisfying following two conditions:

1. x doesn't contain neither digit 0 nor digit 1.

2. <image> = <image>.

Help friends find such number.

Input

The first line contains an integer n (1 ≤ n ≤ 15) — the number of digits in a.

The second line contains n digits of a. There is at least one digit in a that is larger than 1. Number a may possibly contain leading zeroes.

Output

Output a maximum possible integer satisfying the conditions above. There should be no zeroes and ones in this number decimal representation.

Examples

Input

4
1234


Output

33222


Input

3
555


Output

555

Note

In the first case, <image>
n = int(input())
s = str(input())


myList = []
flag = False
for c in s:
    if not c=='0':
        flag = True
    if flag:
        myList.append(c)

a = int(''.join(myList))


import math


def fac(n):
    prod = 1
    for i in range(1,n+1):
        prod *= i
    return prod


def F(n):
    res = 1
    while n > 0:
        res *= fac(n%10)
        n = n // 10
    return res
        

def fun(x):
    d = {"0":"",
         "1":"",
         "2":"2",
         "3":"3",
         "4":"223",
         "5":"5",
         "6":"53",
         "7":"7",
         "8":"7222",
         "9":"7332"
         }
    return d[x]


def answer(num):
    s = str(num)
    myList = []
    for c in s:
        val = fun(c)
        for v in val:
            myList.append(v)
    myList.sort()
    myList = myList[::-1]
    return ''.join(myList)


def check(a):
    return F(int(answer(a))) == F(a)

'''
0 -> ""
1 -> ""
2 -> 2
3 -> 3
4 -> 2!2!3!     
5 -> 5
6 -> 2*3*4*5*6 = 5! * 2 * 3 = 5!3! 
7 -> 7
8 -> 8 = 2*3*4*5*6*7*8 = 7!2!2!2!
9 -> 9 = 2*3*4*5*6*7*8*9 = 7!*(2*2*2)*(3*3) = 7!3!3!2
'''

print(answer(a))
