Try guessing the statement from this picture <http://tiny.cc/ogyoiz>.

You are given two integers A and B, calculate the number of pairs (a, b) such that 1 ≤ a ≤ A, 1 ≤ b ≤ B, and the equation a ⋅ b + a + b = conc(a, b) is true; conc(a, b) is the concatenation of a and b (for example, conc(12, 23) = 1223, conc(100, 11) = 10011). a and b should not contain leading zeroes.

Input

The first line contains t (1 ≤ t ≤ 100) — the number of test cases.

Each test case contains two integers A and B (1 ≤ A, B ≤ 10^9).

Output

Print one integer — the number of pairs (a, b) such that 1 ≤ a ≤ A, 1 ≤ b ≤ B, and the equation a ⋅ b + a + b = conc(a, b) is true.

Example

Input


3
1 11
4 2
191 31415926


Output


1
0
1337

Note

There is only one suitable pair in the first test case: a = 1, b = 9 (1 + 9 + 1 ⋅ 9 = 19).
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
public class codeforces1288B
{ 
	static class FastReader 
	{ 
		BufferedReader br; 
		StringTokenizer st; 
		public FastReader() 
		{ 
			br = new BufferedReader(new InputStreamReader(System.in)); 
		} 

		String next() 
		{ 
			while (st == null || !st.hasMoreElements()) 
			{ 
				try
				{ 
					st = new StringTokenizer(br.readLine()); 
				} 
				catch (IOException e) 
				{ 
					e.printStackTrace(); 
				} 
			} 
			return st.nextToken(); 
		} 

		int nextInt() 
		{
			return Integer.parseInt(next());
		}
		long nextLong() 
		{
			return Long.parseLong(next()); 
		}
		double nextDouble() 
		{
			return Double.parseDouble(next()); 
		}
		String nextLine() 
		{ 
			String str = ""; 
			try
			{ 
				str = br.readLine(); 
			} 
			catch (IOException e) 
			{ 
				e.printStackTrace(); 
			} 
			return str; 
		} 
	} 

	public static void main(String[] args) 
	{ 
        FastReader s=new FastReader();
        StringBuilder sb=new StringBuilder();
		int t=s.nextInt();
		while(t-->0)
		{
            long A =s.nextLong(),B=s.nextLong(),x;
            String st =Long.toString(B),k="";
            int i=st.length();
            while(i-->0)
            k=k+'9';
            if(Long.parseLong(k)!=B)
            x=A*(k.length()-1);
            else
            x=A*(k.length());
            sb.append(x);
			sb.append("\n");
		}
		System.out.print(sb);
    }
}