Find places where a string P is found within a text T. Print all indices of T where P found. The indices of T start with 0.

Constraints

* 1 ≤ length of T ≤ 1000000
* 1 ≤ length of P ≤ 10000
* The input consists of alphabetical characters and digits

Input

In the first line, a text T is given. In the second line, a string P is given.

Output

Print an index of T where P found in a line. Print the indices in ascending order.

Examples

Input

aabaaa
aa


Output

0
3
4


Input

xyzz
yz


Output

1


Input

abc
xyz


Output
#!usr/bin/env python3
from collections import defaultdict, deque
from heapq import heappush, heappop
from itertools import permutations, accumulate
import sys
import math
import bisect
def LI(): return [int(x) for x in sys.stdin.buffer.readline().split()]
def I(): return int(sys.stdin.buffer.readline())
def LS():return [list(x) for x in sys.stdin.readline().split()]
def S():
    res = list(sys.stdin.readline())
    if res[-1] == "\n":
        return res[:-1]
    return res
def IR(n):
    return [I() for i in range(n)]
def LIR(n):
    return [LI() for i in range(n)]
def SR(n):
    return [S() for i in range(n)]
def LSR(n):
    return [LS() for i in range(n)]

sys.setrecursionlimit(1000000)
mod = 1000000007

def solve():
    def Z_algorithm(s):
        n = len(s)
        z = [0]*n
        z[0] = n
        c = 1
        for i in range(1,n):
            if i+z[i-c] < c+z[c]:
                z[i] = z[i-c]
            else:
                j = max(0,c+z[c]-i)
                while i+j < n and s[j] == s[i+j]:
                    j += 1
                z[i] = j
                c = i
        return z
    s = input()
    t = input()
    z = Z_algorithm(t+s)[len(t):]
    for i in range(len(s)):
        if z[i] >= len(t):
            print(i)
    return

#Solve
if __name__ == "__main__":
    solve()

