Skier rides on a snowy field. Its movements can be described by a string of characters 'S', 'N', 'W', 'E' (which correspond to 1 meter movement in the south, north, west or east direction respectively).

It is known that if he moves along a previously unvisited segment of a path (i.e. this segment of the path is visited the first time), then the time of such movement is 5 seconds. If he rolls along previously visited segment of a path (i.e., this segment of the path has been covered by his path before), then it takes 1 second.

Find the skier's time to roll all the path.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each set is given by one nonempty string of the characters 'S', 'N', 'W', 'E'. The length of the string does not exceed 10^5 characters.

The sum of the lengths of t given lines over all test cases in the input does not exceed 10^5.

Output

For each test case, print the desired path time in seconds.

Example

Input


5
NNN
NS
WWEN
WWEE
NWNWS


Output


15
6
16
12
25
import sys
n = int(sys.stdin.readline())

tests = sys.stdin.readlines()

def solve(testcase):
    x = 0
    y = 0
    typeA = 0
    typeB = 0
    visitedNS = set()
    visitedEW = set()
    for c in testcase:
        if c == 'N':
            if (x, y) in visitedNS:
                typeB += 1
            else:
                typeA += 1
                visitedNS.add((x, y))
            y += 1
        if c == 'S':
            if (x, y - 1) in visitedNS:
                typeB += 1
            else:
                typeA += 1
                visitedNS.add((x, y - 1))
            y -= 1
        if c == 'W':
            if (x, y) in visitedEW:
                typeB += 1
            else:
                typeA += 1
                visitedEW.add((x, y))
            x += 1
        if c == 'E':
            if (x - 1, y) in visitedEW:
                typeB += 1
            else:
                typeA += 1
                visitedEW.add((x - 1, y))
            x -= 1
    print(typeA * 5 + typeB)


for testcase in tests:
    solve(testcase)
