Skier rides on a snowy field. Its movements can be described by a string of characters 'S', 'N', 'W', 'E' (which correspond to 1 meter movement in the south, north, west or east direction respectively).

It is known that if he moves along a previously unvisited segment of a path (i.e. this segment of the path is visited the first time), then the time of such movement is 5 seconds. If he rolls along previously visited segment of a path (i.e., this segment of the path has been covered by his path before), then it takes 1 second.

Find the skier's time to roll all the path.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each set is given by one nonempty string of the characters 'S', 'N', 'W', 'E'. The length of the string does not exceed 10^5 characters.

The sum of the lengths of t given lines over all test cases in the input does not exceed 10^5.

Output

For each test case, print the desired path time in seconds.

Example

Input


5
NNN
NS
WWEN
WWEE
NWNWS


Output


15
6
16
12
25
#include <bits/stdc++.h>
using namespace std;
long long po(long long a, long long b) {
  long long res = 1;
  while (b) {
    if (b & 1) {
      res = ((res) % 1000000007 * a) % 1000000007;
    }
    a = (a * a) % 1000000007;
    b = b / 2;
  }
  return res % 1000000007;
}
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  int t;
  cin >> t;
  while (t--) {
    string s;
    cin >> s;
    map<pair<long long, long long>, long long> vis;
    long long sum = 0, x, y;
    x = y = 0;
    for (long long i = 0; i < s.size(); i++) {
      long long a, b;
      a = x;
      b = y;
      if (s[i] == 'N') x--;
      if (s[i] == 'S') x++;
      if (s[i] == 'W') y--;
      if (s[i] == 'E') y++;
      if (vis[{a + x, y + b}] == 1)
        sum += 1;
      else {
        sum += 5;
        vis[{a + x, y + b}] = 1;
      }
    }
    cout << sum << "\n";
  }
  return 0;
}
