Skier rides on a snowy field. Its movements can be described by a string of characters 'S', 'N', 'W', 'E' (which correspond to 1 meter movement in the south, north, west or east direction respectively).

It is known that if he moves along a previously unvisited segment of a path (i.e. this segment of the path is visited the first time), then the time of such movement is 5 seconds. If he rolls along previously visited segment of a path (i.e., this segment of the path has been covered by his path before), then it takes 1 second.

Find the skier's time to roll all the path.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each set is given by one nonempty string of the characters 'S', 'N', 'W', 'E'. The length of the string does not exceed 10^5 characters.

The sum of the lengths of t given lines over all test cases in the input does not exceed 10^5.

Output

For each test case, print the desired path time in seconds.

Example

Input


5
NNN
NS
WWEN
WWEE
NWNWS


Output


15
6
16
12
25
from functools import reduce
import os
import sys
from math import *
from collections import *
from fractions import *
from bisect import *
from heapq import*
from io import BytesIO, IOBase

input = lambda: sys.stdin.readline().rstrip("\r\n")
def value():return tuple(map(int,input().split()))
def arr():return [int(i) for i in input().split()]
def sarr():return [int(i) for i in input()]
def starr():return [str(x) for x in input().split()]
def inn():return int(input())
def svalue():return tuple(map(str,input().split()))
mo=1000000007
#----------------------------CODE------------------------------#
for _ in range(inn()):
    d=defaultdict(int)
    s=input()
    x=0
    y=0
    lx,ly=0,0
    ans=0
    #d[(0,0)]+=1
    for i in s:
        lx,ly=x,y
        if(i=='N'):
            y+=1
        if(i=='S'):
            y-=1
        if(i=='E'):
            x+=1
        if(i=='W'):
            x-=1
        if((x,y,lx,ly) not in d):
            d[(x, y,lx,ly)] += 1
            d[(lx,ly,x,y)]+=1
            ans += 5
        else:
            ans+=1
        #print(x,y)
    #print(d)
    print(ans)




