Andrey received a postcard from Irina. It contained only the words "Hello, Andrey!", and a strange string consisting of lowercase Latin letters, snowflakes and candy canes. Andrey thought that this string is an encrypted message, and decided to decrypt it.

Andrey noticed that snowflakes and candy canes always stand after the letters, so he supposed that the message was encrypted as follows. Candy cane means that the letter before it can be removed, or can be left. A snowflake means that the letter before it can be removed, left, or repeated several times.

For example, consider the following string: 

<image>

This string can encode the message «happynewyear». For this, candy canes and snowflakes should be used as follows: 

  * candy cane 1: remove the letter w, 
  * snowflake 1: repeat the letter p twice, 
  * candy cane 2: leave the letter n, 
  * snowflake 2: remove the letter w, 
  * snowflake 3: leave the letter e. 

<image>

Please note that the same string can encode different messages. For example, the string above can encode «hayewyar», «happpppynewwwwwyear», and other messages.

Andrey knows that messages from Irina usually have a length of k letters. Help him to find out if a given string can encode a message of k letters, and if so, give an example of such a message.

Input

The first line contains the string received in the postcard. The string consists only of lowercase Latin letters, as well as the characters «*» and «?», meaning snowflake and candy cone, respectively. These characters can only appear immediately after the letter. The length of the string does not exceed 200.

The second line contains an integer number k (1 ≤ k ≤ 200), the required message length.

Output

Print any message of length k that the given string can encode, or «Impossible» if such a message does not exist.

Examples

Input


hw?ap*yn?eww*ye*ar
12


Output


happynewyear


Input


ab?a
2


Output


aa

Input


ab?a
3


Output


aba

Input


ababb
5


Output


ababb

Input


ab?a
1


Output


Impossible
import java.io.*;
import java.util.*;
import java.lang.Math;

public class Main{
	static BufferedReader reader;
	static StringTokenizer tokenizer;
	static PrintWriter writer;

	static int nextInt() throws IOException {
		return Integer.parseInt(nextToken());
	}

	static long nextLong() throws IOException {
		return Long.parseLong(nextToken());
	}

	static double nextDouble() throws IOException {
		return Double.parseDouble(nextToken());
	}

	static String nextToken() throws IOException {
		while (tokenizer == null || !tokenizer.hasMoreTokens()) {
			tokenizer = new StringTokenizer(reader.readLine());
		}
		return tokenizer.nextToken();
	}
	static String nexts() throws IOException {
	  	  tokenizer = new StringTokenizer(reader.readLine());
	   	 String s="";
	   	 while (tokenizer.hasMoreTokens()) {
			s+=tokenizer.nextElement()+" ";
		}
		return s;
	}
	public static int gcd(int x, int y){
		if (y == 0) return x; else return gcd(y, x % y);
	}

	public static boolean isPrime(int nn) 
	    { 
	         if(nn<=1){
		 return false; }
	        if(nn<=3){
		 return true; }
	      if (nn%2==0||nn%3==0){
		 return false; }
	        for (int i=5;i*i<=nn;i=i+6){ 
	            if(nn%i==0||nn%(i+2)==0){
	            	return false;  }
	            }
	         return true; 
	    } 

	public static void shuffle(int[] A) {
		for (int i = 0; i < A.length; i++) {
			int j = (int)(i * Math.random());
			int tmp = A[i];
			A[i] = A[j];
			A[j] = tmp;
		}
	}
	public static void shufflel(Long[] A) {
		for (int i = 0; i < A.length; i++) {
			int j = (int)(i * Math.random());
			long tmp = A[i];
			A[i] = A[j];
			A[j] = tmp;
		}
	}

	public static String reverse(String input)
 	   {
	        StringBuilder input2=new StringBuilder();
	        input2.append(input);
	        input2 = input2.reverse();
	        return input2.toString();
	    }


	 public static long power(int x, long n)
	{
	//    long mod = 1000000007;
		if (n == 0) {
			return 1;
		}

		long pow = power(x, n / 2);

		if ((n & 1) == 1) {
			return (x * pow * pow);
		}
		return (pow * pow);
	}
	public static long power(long x, long y, long p)     //x^y%p
	    { 
  	       long res = 1; 
	       x = x % p; 
  	       while (y > 0) { 
 	 	 if (y % 2 == 1) {
      	        	        res = (res * x) % p; 
		 }
  		 y = y >> 1; // y = y/2 
     	     	 x = (x * x) % p; 
     	         } 
  	         return res; 
    	} 

	 static long ncr(int n, int k)  
   	 { 
           		 long res = 1; 
  		   // Since C(n, k) = C(n, n-k)  
 		       if (k > n - k) { 
     		       k = n - k; 
      		  } 
  		  // Calculate value of [n*(n-1)*---*(n-k+1)] / [k*(k-1)*---*1]  
     		   for (int i = 0; i < k; ++i) { 
        		    res *= (n - i); 
         		   res /= (i + 1); 
     		   } 
  		  return res; 
 	   }
	public static int inv(int a, int m)     //Returns modulo inverse of a with respect to m using extended euclid algorithm
	    { 
	        int m0=m,t,q; 
	        int x0=0,x1=1; 
      	        if(m==1){
	                return 0; }
                 	         while(a>1) 
     	        {  
   	                q=a/m; 
    	                t=m; 
                                 m=a%m;a=t; 
    	                t=x0; 
     	                x0=x1-q*x0; 
      	                x1=t; } 
    	          if(x1<0){
 	   	 x1+=m0; }
   	           return x1; 
	    } 

	static int modInverse(int n, int p) 
  	{ 
    	          return (int)power((long)n, (long)(p - 2),(long)p); 
	 } 
	static int ncrmod(int n, int r, int p) 
   	 { 
	        if (r == 0)        // Base case 
	            return 1; 
  	        int[] fac = new int[n + 1];         // Fill factorial array so that we can find all factorial of r, n and n-r 
	        fac[0] = 1; 
	        for (int i = 1; i <= n; i++) 
                                     fac[i] = fac[i - 1] * i % p; 
   	         return (fac[n] * modInverse(fac[r], p) % p * modInverse(fac[n - r], p) % p) % p;     //IMPORTANT
    	}	 

	static int upper(int a[], int x)   //Returns rightest index of x in sorted arr else -1
  	  {                                                //If not present returns index of just smaller element
  	            int n=a.length;
    	        int l=0;
                int r=n-1;
                int ans=-1;
                while(l<=r){
                    int m=(r-l)/2+l;
                    if(a[m]<=x){
                        ans=m;
                        l=m+1;
                    }
                    else{
                        r=m-1;
                    }
                }
                 return ans;  
                } 
	static int lower(int a[], int x)     //Returns leftest index of x in sorted arr else n
 	   {                                                  //If not present returns index of just greater element
 	            int n=a.length;
   	            int l=0;
                int r=n-1;
                int ans=n;
                while(l<=r){
                    int m=(r-l)/2+l;
                    if(a[m]>=x){
                        ans=m;
                        r=m-1;
                    }
                    else{
                         l=m+1;
                    }
                }
                 return ans; 
                 } 

	public static long stringtoint(String s){ // Convert bit string to number
		long a = 1;
		long ans = 0;
		StringBuilder sb = new StringBuilder();
		sb.append(s);  
		sb.reverse();
		s=sb.toString();
		for(int i=0;i<s.length();i++){
			ans = ans + a*(s.charAt(i)-'0');
			a = a*2;
		}
		return ans;
	}
 
	String inttostring(long a,long m){        // a is number and m is length of string required
		String res = "";                     // Convert a number in bit string representation
		for(int i=0;i<(int)m;i++){
			if((a&(1<<i))==1){
				res+='1';
			}else
				res+='0';
		}
		StringBuilder sb = new StringBuilder();
		sb.append(res);  
		sb.reverse();
		res=sb.toString();
		return res;
    }
	
	 static class R implements Comparable<R>{
	        int x, y;
	        public  R(int x, int y) {           //a[i]=new R(x,y);
	            this.x = x;
	            this.y = y;
	        }
	        public int compareTo(R o) {
            		return x-o.x;     //Increasing order(Which is usually required)
        		}
	    }   
/*   FUNCTION TO SORT HASHMAP ACCORDING TO VALUE
//USE IT AS FOLLOW	

//Make a new list
List<Map.Entry<Integer, Integer> > list = 
               new LinkedList<Map.Entry<Integer, Integer> >(h.entrySet()); 
  
        // Sort the list 
        Collections.sort(list, new Comparator<Map.Entry<Integer, Integer> >() { 
            public int compare(Map.Entry<Integer, Integer> o1,  
                               Map.Entry<Integer, Integer> o2) 
            { 
                return (o1.getValue()).compareTo(o2.getValue());     //This is used to sort string stored as VALUE, use below function here accordingly
            } 
        }); 
          
        // put data from sorted list to new hashmap  
        HashMap<String, Integer> temp = new LinkedHashMap<String, Integer>(); 
        for (Map.Entry<String, Integer> aa : list) { 
            temp.put(aa.getKey(), aa.getValue()); 
        } 
        return temp;   //Now temp is our new sorted hashmap
OR
	for(int i = 0;i<h.size();i++)  //accessing elements from the list made
		{
			int count = list.get(i).getValue();    //Value
			while(count >= 0)
			{
					int key=list.get(i).getKey();  //key
					count -- ;
			}
		}

////////////////////////////////////////////////////////////////////////////////////////
public int compare(Entry<Integer, Integer> o1, Entry<Integer, Integer> o2) 
	{
		if(o1.getValue() != o2.getValue())
			return o1.getValue() > o2.getValue()?1:-1;  //Sorts Value in increasing order
		else if(o1.getValue() == o2.getValue()){
			return o1.getKey() > o2.getKey() ? 1:-1;  //If value equal, then sorts key in increasing order
		}
		
		return Integer.MIN_VALUE;
	}
*/
//Check if palindrome string - System.out.print(A.equals(new StringBuilder(A).reverse().toString())?"Yes":"No");
	public static void main(String[] args) throws IOException {
		reader = new BufferedReader(new InputStreamReader(System.in));
		tokenizer = null;
		writer = new PrintWriter(System.out);
		solve();
		reader.close();
		writer.close();
	}
	
	private static void solve() throws IOException {
	//	int t = nextInt();
	//	while(t-->0){
			//String s= nextToken();
			//String[] s = str.split("\\s+");
			//ArrayList<Integer> ar=new ArrayList<Integer>();
			//HashSet<Integer> set=new HashSet<Integer>();
			//HashMap<Integer,String> h=new HashMap<Integer,String>();
			//R[] a1=new R[n];
		    char[] c=nextToken().toCharArray();
			//PriorityQueue<Integer> pq=new PriorityQueue<Integer>(Collections.reverseOrder());
			//NavigableSet<Integer> pq=new TreeSet<>();
			int n = c.length;
			int k = nextInt();
			//long n = nextLong();
			
			//int[] a=new int[n];
			//long[] a=new long[n];
			int l=0;
			int u=0;
			for(int i=0;i<n;i++){
				if(c[i]=='*'||c[i]=='?'){
				    l++;
				}
				if(c[i]=='*')u=1;
			}
			//shuffle(a);
			//shufflel(a);
			//Arrays.sort(a);
			int nn=n-l;
			//StringBuilder ans=new StringBuilder();
			if(k>nn&&u==0){
			    writer.println("Impossible");
			    return;
			}
			if(k<nn&&(nn-k)>l){
			    writer.println("Impossible");
			    return;
			}
			String s="";
			int d=k-nn;
			for(int i=0;i<n;i++){
			    if(d>0){
			        if(c[i]!='*'&&c[i]!='?'){
    				    s+=c[i];
    				}
    				if(c[i]=='*'){
    				    char m=c[i-1];
    				    while(d-->0)s+=m;
    				    if(d!=0)d=0;
    				}
			    }
			    else if(d<0){
			        if(c[i]!='*'&&c[i]!='?'){
    				    s+=c[i];
    				}
    				else{
    				    d++;
    				    int ll=s.length();
    				    s=s.substring(0,ll-1);
    				}
			    }
			    else {
			        if(c[i]!='*'&&c[i]!='?'){
    				    s+=c[i];
    				}
			    }
			}
            writer.println(s);
            
			
		 }
//	}
}