Skier rides on a snowy field. Its movements can be described by a string of characters 'S', 'N', 'W', 'E' (which correspond to 1 meter movement in the south, north, west or east direction respectively).

It is known that if he moves along a previously unvisited segment of a path (i.e. this segment of the path is visited the first time), then the time of such movement is 5 seconds. If he rolls along previously visited segment of a path (i.e., this segment of the path has been covered by his path before), then it takes 1 second.

Find the skier's time to roll all the path.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each set is given by one nonempty string of the characters 'S', 'N', 'W', 'E'. The length of the string does not exceed 10^5 characters.

The sum of the lengths of t given lines over all test cases in the input does not exceed 10^5.

Output

For each test case, print the desired path time in seconds.

Example

Input


5
NNN
NS
WWEN
WWEE
NWNWS


Output


15
6
16
12
25
import sys
#sys.stdin=open("skier",'r')
def oppDirc(c):
    if(c=='b'):
        return 'u'
    elif(c=='u'):
        return 'b'
    elif(c=='l'):
        return 'r'
    else:
        return 'l'

t=int(input())
for i in range(t):
    s=input()
    ans=0
    last=[0,0]
    vis=dict()
    vis[tuple(last)]=set()
    for si in s:
        prev=last.copy()
        dirn=None
        if(si=='N'):
            last[1]+=1
            dirn='b'
        elif(si=='E'):
            last[0]+=1
            dirn='l'
        elif(si=='W'):
            last[0]-=1
            dirn='r'
        else:
            last[1]-=1
            dirn='u'

        tl=tuple(last)
        tp=tuple(prev)
        if tl not in vis:
            ans+=5
            #print("a")
            vis[tl]=set([dirn])
            vis[tp].add(oppDirc(dirn))
        else:
            if (dirn in vis[tl]):
                ans+=1
                #print("b")
            else:
                vis[tl].add(dirn)
                vis[tp].add(oppDirc(dirn))
                ans+=5
                #print("c")
        #print(last)
        #print(ans)
    #print(vis)
    print(ans)

            








    


