A: IP Address (Internet Protocol Address)

problem

Since one number string is given, find the number of valid delimiters for IPv4 IP addresses. However, the effective delimiters for IPv4 IP addresses are as follows.

* The sequence of numbers is divided into four, and each of the separated columns satisfies all of the following.
* Not an empty string.
* When read as a decimal number, it is an integer between 0 and 255.
* If the number is 0, then the column is `0` (` 00` etc. are not allowed).
* If the number is non-zero, the first digit is not `0` (`01` etc. are not allowed).



Input format


S

Constraint

* 4 \ leq | S | \ leq 12
* S contains only numbers.



Output format

Output the number on one line according to the valid delimiter.

Input example 1


123456789

Output example 1


1

There is one valid delimiter, `123.45.67.89`.

Input example 2


768426

Output example 2


6





Example

Input

123456789


Output

1
import java.util.*;
import java.util.stream.*;
import java.io.*;
import java.math.*;

public class Main {

	static void solve (FastScanner in, PrintWriter out, Methods ms) {
		
		String s = in.next();
		int length = s.length();
		int ans = 0;
		
		for (int i=1; i<length-2; i++) {
			for (int j=i+1; j<length-1; j++) {
				loop : for (int k=j+1; k<length; k++) {
					
					String[] a = {s.substring(0,i), s.substring(i,j), s.substring(j,k), s.substring(k,length)};
					
					for (int x=0; x<4; x++) {
						if (a[x].length() != String.valueOf(Integer.parseInt(a[x])).length()) {
							continue loop;
						}
					}
					
					int[] b = {Integer.parseInt(a[0]), Integer.parseInt(a[1]), Integer.parseInt(a[2]), Integer.parseInt(a[3])};
					if (b[0]<=255 && b[1]<=255 && b[2]<=255 && b[3]<=255) ans++;
					
				}
			}
		}
		
		out.println(ans);
		
	}
	


	public static void main(String[] args) {
		FastScanner in = new FastScanner(System.in);
		PrintWriter out = new PrintWriter(System.out);
		Methods ms = new Methods();
		solve(in, out, ms);
		in.close();
		out.close();
	}

	static class Methods {

		public void print (Object... ar) {System.out.println(Arrays.deepToString(ar));}

		public int max (int... ar) {Arrays.sort(ar); return ar[ar.length-1];}

		public int min (int... ar) {Arrays.sort(ar); return ar[0];}

		public long gcd (long a, long b) {return b>0?gcd(b,a%b):a;}

		public long lcm (long a, long b) {return a/gcd(a,b)*b;}

		public long factorial (int i) {
			if (i==1) return 1;
			else return i*factorial(i-1);
		}

		public int manhat (int x1, int y1, int x2, int y2) {
			return Math.abs(x1-x2)+Math.abs(y1-y2);
		}

		public double euclid (double x1, double y1, double x2, double y2) {
			return Math.sqrt((x2-x1)*(x2-x1)+(y2-y1)*(y2-y1));
		}

		public boolean isPrime (int n) {
			if (n==2) return true;
			if (n<2 || n%2==0) return false;
			for (int i=3; i<=Math.sqrt(n); i+=2) if(n%i==0) return false;
			return true;
		}

	}

	static class FastScanner {

		private InputStream in;
		private byte[] buffer = new byte[1024];
		private  int length = 0, p = 0;

		public FastScanner (InputStream stream) {
			in = stream;
		}

		public boolean hasNextByte () {
			if (p < length) return true;
			else {
				p = 0;
				try {length = in.read(buffer);}
				catch (Exception e) {e.printStackTrace();}
				if (length <= 0) return false;
			}
			return true;
		}

		public int readByte () {
			if (hasNextByte() == true) return buffer[p++];
			return -1;
		}

		public boolean isPrintable (int n) {return 33<=n&&n<=126;}

		public void skip () {
			while (hasNextByte() && !isPrintable(buffer[p])) p++;
		}

		public boolean hasNext () {skip(); return hasNextByte();}

		public String next () {
			if (!hasNext()) throw new NoSuchElementException();
			StringBuilder sb = new StringBuilder();
			int t = readByte();
			while (isPrintable(t)) {
				sb.appendCodePoint(t);
				t = readByte();
			}
			return sb.toString();
		}

		public String[] nextArray (int n) {
			String[] ar = new String[n];
			for (int i=0; i<n; i++) ar[i] = next();
			return ar;
		}

		public int nextInt () {return Math.toIntExact(nextLong());}

		public int[] nextIntArray (int n) {
			int[] ar = new int[n];
			for (int i=0; i<n; i++) ar[i] = nextInt();
			return ar;
		}

		public long nextLong () {
			if (!hasNext()) throw new NoSuchElementException();
			boolean minus = false;
			int temp = readByte();
			if (temp == '-') {
				minus = true;
				temp = readByte();
			}
			if (temp<'0' || '9'<temp) throw new NumberFormatException();
			long n = 0;
			while (isPrintable(temp)) {
				if ('0'<=temp && temp<='9') {
					n *= 10;
					n += temp - '0';
				}
				else throw new NumberFormatException();
				temp = readByte();
			}
			return minus? -n : n;
		}

		public long[] nextLongArray (int n) {
			long[] ar = new long[n];
			for (int i=0; i<n; i++) ar[i] = nextLong();
			return ar;
		}

		public double nextDouble () {
			return Double.parseDouble(next());
		}

		public double[] nextDoubleArray (int n) {
			double[] ar = new double[n];
			for (int i=0; i<n; i++) ar[i] = nextDouble();
			return ar;
		}

		public void close () {
			try {in.close();}
			catch(Exception e){}
		}

	}

}
