Write a program which computes the area of a shape represented by the following three lines:

$y = x^2$
$y = 0$
$x = 600$



It is clear that the area is $72000000$, if you use an integral you learn in high school. On the other hand, we can obtain an approximative area of the shape by adding up areas of many rectangles in the shape as shown in the following figure:

<image>
$f(x) = x^2$



The approximative area $s$ where the width of the rectangles is $d$ is:

area of rectangle where its width is $d$ and height is $f(d)$ $+$
area of rectangle where its width is $d$ and height is $f(2d)$ $+$
area of rectangle where its width is $d$ and height is $f(3d)$ $+$
...
area of rectangle where its width is $d$ and height is $f(600 - d)$


The more we decrease $d$, the higer-precision value which is close to $72000000$ we could obtain. Your program should read the integer $d$ which is a divisor of $600$, and print the area $s$.



Input

The input consists of several datasets. Each dataset consists of an integer $d$ in a line. The number of datasets is less than or equal to 20.

Output

For each dataset, print the area $s$ in a line.

Example

Input

20
10


Output

68440000
70210000
import java.io.*;
import java.util.*;
import static java.lang.System.*;

public class Main {
	static FastScanner sc = new FastScanner(System.in);
	public static void main(String[] args) {
		int d;
		while (sc.hasNext()) {
			d = sc.nextInt();
			int ans = 0;
			for (int i=1; i<600/d; i++) {
				ans += (i*i)*(d*d)*d;
			}
			out.println(ans);
		}
	}
}



class FastScanner implements Closeable {
	private final InputStream in;
	private final byte[] buffer = new byte[1024];
	private int ptr = 0;
	private int buflen = 0;
	public FastScanner(InputStream in) {this.in = in;}
	private boolean hasNextByte() {
		if (ptr < buflen) {return true;}
		else{
			ptr = 0;
			try {buflen = in.read(buffer);}
			catch (IOException e) {e.printStackTrace();}
			if (buflen <= 0) {return false;}
		}
		return true;
	}
	private int readByte() { if (hasNextByte()) return buffer[ptr++]; else return -1;}
	private static boolean isPrintableChar(int c) { return 33 <= c && c <= 126;}
	public boolean hasNext() { while(hasNextByte() && !isPrintableChar(buffer[ptr])) ptr++; return hasNextByte();}
	public String next() {
		if (!hasNext()) throw new NoSuchElementException();
		StringBuilder sb = new StringBuilder();
		int b = readByte();
		while(isPrintableChar(b)) {
			sb.appendCodePoint(b);
			b = readByte();
		}
		return sb.toString();
	}
	public long nextLong() {
		if (!hasNext()) throw new NoSuchElementException();
		long n = 0;
		boolean minus = false;
		int b = readByte();
		if (b == '-') {
			minus = true;
			b = readByte();
		}
		if (b < '0' || '9' < b) {throw new NumberFormatException();}
		while(true){
			if ('0' <= b && b <= '9') {
				n *= 10;
				n += b - '0';
			}else if(b == -1 || !isPrintableChar(b)){return minus ? -n : n;}
			else{throw new NumberFormatException();}
			b = readByte();
		}
	}
	public int nextInt() {
		long nl = nextLong();
		if (nl < Integer.MIN_VALUE || nl > Integer.MAX_VALUE) throw new NumberFormatException();
		return (int) nl;
	}
	public double nextDouble() { return Double.parseDouble(next());}
	public void close() {
		try {in.close();}
		catch (IOException e) {}
	}
}
