Little X has met the following problem recently. 

Let's define f(x) as the sum of digits in decimal representation of number x (for example, f(1234) = 1 + 2 + 3 + 4). You are to calculate <image>

Of course Little X has solved this problem quickly, has locked it, and then has tried to hack others. He has seen the following C++ code: 
    
    
      
        ans = solve(l, r) % a;  
        if (ans <= 0)  
          ans += a;  
      
    

This code will fail only on the test with <image>. You are given number a, help Little X to find a proper test for hack.

Input

The first line contains a single integer a (1 ≤ a ≤ 1018).

Output

Print two integers: l, r (1 ≤ l ≤ r < 10200) — the required test data. Leading zeros aren't allowed. It's guaranteed that the solution exists.

Examples

Input

46


Output

1 10


Input

126444381000032


Output

2333333 2333333333333
import java.io.*;
import java.util.*;
import java.math.*;

public class Main {
  // main
  public static void main(String [] args) throws IOException {
    // makes the reader and writer
    BufferedReader f = new BufferedReader(new InputStreamReader(System.in));
    PrintWriter out = new PrintWriter(new BufferedOutputStream(System.out));
    
    // read in a
    BigInteger a = new BigInteger(f.readLine());
    
    // solve
    BigInteger l = a.subtract((BigInteger.TEN.pow(19).multiply(new BigInteger("900"))).mod(a));
    BigInteger r = l.add(BigInteger.TEN.pow(20).subtract(BigInteger.ONE));

    // write to out
    out.println(l.toString()+" "+r.toString());
    
    // cleanup
    out.close();
    System.exit(0);
  }
}