Skier rides on a snowy field. Its movements can be described by a string of characters 'S', 'N', 'W', 'E' (which correspond to 1 meter movement in the south, north, west or east direction respectively).

It is known that if he moves along a previously unvisited segment of a path (i.e. this segment of the path is visited the first time), then the time of such movement is 5 seconds. If he rolls along previously visited segment of a path (i.e., this segment of the path has been covered by his path before), then it takes 1 second.

Find the skier's time to roll all the path.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each set is given by one nonempty string of the characters 'S', 'N', 'W', 'E'. The length of the string does not exceed 10^5 characters.

The sum of the lengths of t given lines over all test cases in the input does not exceed 10^5.

Output

For each test case, print the desired path time in seconds.

Example

Input


5
NNN
NS
WWEN
WWEE
NWNWS


Output


15
6
16
12
25
#include <bits/stdc++.h>
using namespace std;
int main() {
  ios_base::sync_with_stdio(false);
  cin.tie(NULL);
  cout.tie(NULL);
  int T;
  cin >> T;
  while (T--) {
    set<pair<pair<int, int>, pair<int, int>>> m;
    pair<int, int> p = {0, 0};
    string s;
    cin >> s;
    int t = 0;
    for (int i = 0; i < s.size(); i++) {
      pair<int, int> c = p;
      if (s[i] == 'N') {
        c.second--;
      }
      if (s[i] == 'S') {
        c.second++;
      }
      if (s[i] == 'W') {
        c.first--;
      }
      if (s[i] == 'E') {
        c.first++;
      }
      if (m.emplace(min(c, p), max(c, p)).second) {
        t += 5;
      } else {
        t += 1;
      }
      p = c;
    }
    cout << t << '\n';
  }
}
