Given a non-negative decimal integer $x$, convert it to binary representation $b$ of 32 bits. Then, print the result of the following operations to $b$ respecitvely.

* Inversion: change the state of each bit to the opposite state
* Logical left shift: shift left by 1
* Logical right shift: shift right by 1

Constraints

* $0 \leq x \leq 2^{32} - 1$

Input

The input is given in the following format.


$x$


Output

Print the given bits, results of inversion, left shift and right shift in a line respectively.

Examples

Input

8


Output

00000000000000000000000000001000
11111111111111111111111111110111
00000000000000000000000000010000
00000000000000000000000000000100


Input

13


Output

00000000000000000000000000001101
11111111111111111111111111110010
00000000000000000000000000011010
00000000000000000000000000000110
#include <iostream>
#include <string>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <utility>
#include <stack>
#include <numeric>
#include <algorithm>
#include <stdio.h>
#include <bitset>
#include <limits.h>
#include <complex>
#include <iomanip>
#include <sstream>
using namespace std;
#define MM 1000000000
#define MOD MM+7
#define pi pair<int32,int32>
#define pl pair<int64,int64>
#define chmax(a,b) (a<b ? a=b:0)
#define chmin(a,b) (a>b ? a=b:0)
#define en cout << endl //セミコロンつけろ
const long double PI = acos(-1);
const long long INF = 1e15;
int dx[8] = {-1,0,1,0,-1,-1,1,1};
int dy[8] = {0,-1,0,1,-1,1,1,-1};
template<typename T>
T GCD(T u,T v){
    return v ? GCD(v,u%v) : u;
}
template<typename T>
T LCM(T x,T y){
    T gc = GCD(x,y);
    return x*y/gc;
}



int main(){
    long long n;
    string s,s1,s2,s3; cin >> n;
    stringstream ss;
    ss << bitset<32>(n);
    s = ss.str();
    cout << s << endl;
    for(int i = 0; i < s.size(); i++){
        if (s[i] == '0') s1 += '1';
        else s1 += '0';

        if (i == s.size()-1) s2 += '0';
        else s2 += s[i+1];

        if (i == 0) s3 += "0";
        else s3 += s[i-1];
    }
    cout << s1 << endl << s2 << endl << s3 << endl;
}
  


