Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet.

Input

The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes).

Output

Output the decoded ternary number. It can have leading zeroes.

Examples

Input

.-.--


Output

012

Input

--.


Output

20

Input

-..-.--


Output

1012
n = list(str(input()))

x = "" 
finalarray = []

def isInteger(value):
    try:
        value = int(value)
        return True 
    except ValueError: 
        pass
        return False
for i in range(0, len(n)): 
    if n[i] == "-": 
        n[i] = "a"
    else: 
        n[i] = "b"


for k in range(1, len(n)): 
    if (n[k] == n[k-1] == "a"):
        n[k-1] = "2" 
        n[k] = ""  
    if ((n[k-1] == "a") and (n[k] == "b")  ) :    
        n[k-1] = "1" 
        n[k] = ""

for i in range(0,len(n)):
    if (n[i] == "b"):
        n[i] = "0" 
        
for i in range(0, len(n)):         
    if (isInteger(n[i]) == True):
        finalarray.append(n[i])

for i in range(0, len(finalarray)): 
    x += finalarray[i]

print(x) 
