Let's define the cost of a string s as the number of index pairs i and j (1 ≤ i < j < |s|) such that s_i = s_j and s_{i+1} = s_{j+1}.

You are given two positive integers n and k. Among all strings with length n that contain only the first k characters of the Latin alphabet, find a string with minimum possible cost. If there are multiple such strings with minimum cost — find any of them.

Input

The only line contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 26).

Output

Print the string s such that it consists of n characters, each its character is one of the k first Latin letters, and it has the minimum possible cost among all these strings. If there are multiple such strings — print any of them.

Examples

Input


9 4


Output


aabacadbb


Input


5 1


Output


aaaaa

Input


10 26


Output


codeforces
import java.util.*;
import java.io.*;
/**
 *
 * @author alanl
 */
public class Solve {

    /**
     * @param args the command line arguments
     */
    static BufferedReader input = new BufferedReader(new InputStreamReader(System.in));
    static StringTokenizer st;
    static PrintWriter pr = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));
    public static void main(String[] args) throws IOException {
        int n = readInt(), k = readInt(), cnt = 0, cur = 0, val = 0;
        StringBuilder sb = new StringBuilder();
        while(sb.length()<n){
            sb.append((char)(cnt+'a'));
            sb.append((char)(cur+'a'));
            cnt++;
            if(cnt==k){
                cur++;
                cnt = cur;
                sb.deleteCharAt(sb.length()-1);
            }
            if(cur==k){
                cur = 0;
                cnt = 0;
            }
        }
        if(sb.length()==n)println(sb.toString());
        else{
            sb.deleteCharAt(sb.length()-1);
            //sb.deleteCharAt(sb.length()-1);
            //sb.deleteCharAt(sb.length()-1);
            
            println(sb.toString());
        }
        //println(sb.length());
    }
    static String next () throws IOException {
        while (st == null || !st.hasMoreTokens())
                st = new StringTokenizer(input.readLine().trim());
        return st.nextToken();
    }
    static long readLong () throws IOException {
        return Long.parseLong(next());
    }
    static int readInt () throws IOException {
        return Integer.parseInt(next());
    }
    static double readDouble () throws IOException {
        return Double.parseDouble(next());
    }
    static char readChar () throws IOException {
        return next().charAt(0);
    }
    static String readLine () throws IOException {
        return input.readLine().trim();
    }
    static void print(Object b) {
        System.out.print(b);
    }
    static void println(Object b) {
        System.out.println(b);
    }
    static void println() {
        System.out.println();
    }
}
