You are given a non-empty string s consisting of lowercase English letters. You have to pick exactly one non-empty substring of s and shift all its letters 'z' <image> 'y' <image> 'x' <image> 'b' <image> 'a' <image> 'z'. In other words, each character is replaced with the previous character of English alphabet and 'a' is replaced with 'z'.

What is the lexicographically minimum string that can be obtained from s by performing this shift exactly once?

Input

The only line of the input contains the string s (1 ≤ |s| ≤ 100 000) consisting of lowercase English letters.

Output

Print the lexicographically minimum string that can be obtained from s by shifting letters of exactly one non-empty substring.

Examples

Input

codeforces


Output

bncdenqbdr


Input

abacaba


Output

aaacaba

Note

String s is lexicographically smaller than some other string t of the same length if there exists some 1 ≤ i ≤ |s|, such that s1 = t1, s2 = t2, ..., si - 1 = ti - 1, and si < ti.
import java.io.*;
import java.lang.*;
import java.text.DecimalFormat;
import java.util.*;
import java.math.*;

// Sachin_2961 submission //
public class CodeforcesA {

    public void solve() {
        char[]str = fs.n().toCharArray();
        int n = str.length;
        boolean ok = false;
        for(int i=0;i<n;i++){
            if(ok && str[i] == 'a')break;
            if( str[i] > 'a'){
                str[i] = (char)(str[i]-1);
                ok = true;
            }
        }
        if(!ok)
            str[n-1] = 'z';
        for(char c:str)
            out.print(c);
    }

    static boolean multipleTestCase = false; static FastScanner fs; static PrintWriter out;
    public void run(){
        fs = new FastScanner();
        out = new PrintWriter(System.out);
        int tc = (multipleTestCase)?fs.nInt():1;
        while (tc-->0)solve();
        out.flush();
        out.close();
    }
    static long max(long a,long b){ return Math.max(a,b);}
    static long min(long a,long b){ return Math.min(a,b);}
    static long abs(long a){return Math.abs(a);}
    public static void main(String[]args){
        try{
            new CodeforcesA().run();
        }catch (Exception e){
            e.printStackTrace();
        }

    }
    static class FastScanner {
        BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st=new StringTokenizer("");
        String n() {
            while (!st.hasMoreTokens())
                try {
                    st=new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            return st.nextToken();
        }
        String Line()
        {
            String str = "";
            try
            {
                str = br.readLine();
            }catch (IOException e)
            {
                e.printStackTrace();
            }
            return str;
        }
        int nInt() {return Integer.parseInt(n()); }
        long nLong() {return Long.parseLong(n());}
        int[]aI(int n){
            int[]ar = new int[n];
            for(int i=0;i<n;i++)
                ar[i] = nInt();
            return ar;
        }
    }
}