Let's call a string good if and only if it consists of only two types of letters — 'a' and 'b' and every two consecutive letters are distinct. For example "baba" and "aba" are good strings and "abb" is a bad string.

You have a strings "a", b strings "b" and c strings "ab". You want to choose some subset of these strings and concatenate them in any arbitrarily order.

What is the length of the longest good string you can obtain this way?

Input

The first line contains three positive integers a, b, c (1 ≤ a, b, c ≤ 10^9) — the number of strings "a", "b" and "ab" respectively.

Output

Print a single number — the maximum possible length of the good string you can obtain.

Examples

Input


1 1 1


Output


4


Input


2 1 2


Output


7


Input


3 5 2


Output


11


Input


2 2 1


Output


6


Input


1000000000 1000000000 1000000000


Output


4000000000

Note

In the first example the optimal string is "baba".

In the second example the optimal string is "abababa".

In the third example the optimal string is "bababababab".

In the fourth example the optimal string is "ababab".
import java.util.*;
import java.io.*;
public class AnotherOneBitesTheDust  {
    static long mod = (long) Math.pow(10, 9) + 7;
    public static void main(String[] args) {
        FastScanner f = new FastScanner(System.in);
            long a = f.nextLong();
            long b = f.nextLong();
            long c = f.nextLong();
            long ans = (a == b) ? (a + b + 2 * c) : (2 * c + 2 * Math.min(a , b) + 1);
            pn(ans);
    }
        
/******************************END OF MAIN PROGRAM*******************************************/
    // Fast Scanner Alternative of Scanner 
    // Uses Implementation of BufferedReader Class
    public static class FastScanner {
        BufferedReader br;
        StringTokenizer st;
        FastScanner(InputStream stream) {
            try {
                br = new BufferedReader(new
                    InputStreamReader(stream));
            } catch (Exception e) {
                e.printStackTrace();
            }
        }
        String next() {
            while (st == null || !st.hasMoreTokens()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
            return st.nextToken();
        }
        int nextInt() {
            return Integer.parseInt(next());
        }
        long nextLong() {
            return Long.parseLong(next());
        }
        double nextDouble() {
            return Double.parseDouble(next());
        }
    }
    
    // Print in console
    static void pn(Object o){System.out.println(o);}
    static void p(Object o){System.out.print(o);}
    static void pni(Object o){System.out.println(o);System.out.flush();}

    //GCD of two integers
    static int gcd(int a, int b) {
        if(b == 0) return a;
        else {
            return gcd(b, a % b);
        }
    }

    // GCD of a array of integers
    static int gcdarray(int a[]) {
        int res = a[0];
        for(int i = 1; i < a.length; i++) {
            res = gcd(a[i] , res);
        }
        return res;
    }
    
    // Return boolean sieve of first n prime nos.
    static boolean[] sieve(int n) {
        boolean isprime[] = new boolean[n + 1];
        for(int i = 0; i <= n;++i) {
            isprime[i] = true;
        }
        isprime[0] = false;
        isprime[1] = false;
        for(int i = 2; i * i <= n; ++i) {
             if(isprime[i] == true) {               
                 for(int j = i * i; j <= n;j += i)
                     isprime[j] = false;
            }
        }
        return isprime;
    }

    // Return HashSet of factors of a number
    static HashSet<Long> factors(long n) {
        HashSet<Long> hs = new HashSet<Long>();
        for(long i = 1; i <= (long)Math.sqrt(n); i++) {
            if(n % i == 0) {
                hs.add(i);
                hs.add(n / i);
            }
        }
        return hs;
    }

    //Is n prime ?
    static boolean isPrime(int n) {
        if(n == 1) return false;
        int i = 2;
        while((i * i) <= n) {
            if(n % i == 0) return false;
            i += 1;
        }
        return true;
    }

    // Gives next (Lexicographical) permutation of String
    public static String nextPermutation(String s) {
        StringBuffer sb = new StringBuffer(s);
        String ans = "No Successor";
        int ii = -1 , jj = -1;
        for(int i = 0; i < s.length() - 1; i++) {
            if((int)s.charAt(i) < (int)s.charAt(i + 1))
                ii = i;
        }
        for(int j = ii + 1; j < s.length() && j != 0; j++) {
            if((int)s.charAt(j) > (int)s.charAt(ii))
                jj = j;
        }
        if(ii == -1)
            return ans;
        else {
        char tempi = s.charAt(ii);
        char tempj = s.charAt(jj);
        sb.setCharAt(jj , tempi);
        sb.setCharAt(ii , tempj);
        StringBuffer sub = new StringBuffer(sb.substring(ii + 1));
        sub.reverse();
        int v = sub.length();
        while(v-- > 0) {
            sb.deleteCharAt(sb.length() - 1);
        }
        sb.append(sub);
        ans = sb.toString();
        return ans;
        }
    }
}