Let's define the cost of a string s as the number of index pairs i and j (1 ≤ i < j < |s|) such that s_i = s_j and s_{i+1} = s_{j+1}.

You are given two positive integers n and k. Among all strings with length n that contain only the first k characters of the Latin alphabet, find a string with minimum possible cost. If there are multiple such strings with minimum cost — find any of them.

Input

The only line contains two integers n and k (1 ≤ n ≤ 2 ⋅ 10^5; 1 ≤ k ≤ 26).

Output

Print the string s such that it consists of n characters, each its character is one of the k first Latin letters, and it has the minimum possible cost among all these strings. If there are multiple such strings — print any of them.

Examples

Input


9 4


Output


aabacadbb


Input


5 1


Output


aaaaa

Input


10 26


Output


codeforces
import java.util.*;
import java.lang.*;
import java.io.*;
import java.math.BigInteger;


public class CF {
	private static FS sc = new FS();
	
	private static class FS {
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		StringTokenizer st = new StringTokenizer("");
		String next() {
			while (!st.hasMoreTokens())
				try {
					st=new StringTokenizer(br.readLine());				               
	            } catch (IOException e) {}
			return st.nextToken();
		}
		
		int nextInt() {
			return Integer.parseInt(next());
		}
		long nextLong() {
			return Long.parseLong(next());
		}
	}
	
	private static class extra {
		
		static int[] intArr(int size) {
			int[] a = new int[size];
			for(int i = 0; i < size; i++) a[i] = sc.nextInt();
			return a;
		}
		
		static long[] longArr(int size) {
			long[] a = new long[size];
			for(int i = 0; i < size; i++) a[i] = sc.nextLong();
			return a;
		}
		
		static long intSum(int[] a) {
			long sum = 0; 
			for(int i = 0; i < a.length; i++) {
				sum += a[i];
			}
			return sum;
		}
		
		static long longSum(long[] a) {
			long sum = 0; 
			for(int i = 0; i < a.length; i++) {
				sum += a[i];
			}
			return sum;
		}
		
	}
	
	static int mod = (int) (Math.pow(10, 9) + 7);
	
	public static void main(String[] args) {	
//		int t = sc.nextInt();
		int t = 1;
		StringBuilder ret = new StringBuilder();
		while(t-- > 0) {
			int n = sc.nextInt();
			int k = sc.nextInt();
			int s = 'a';
			StringBuilder str = new StringBuilder();
			int ini = s;
			while(s != ini+k) {
				str.append((char)s);
				for(int i = s+1; i < ini+k; i++) {
					str.append((char)s);
					str.append((char)(i));
				}
				s++;
			}
			StringBuilder ans = new StringBuilder();
			while(n >= str.length()) {
				int min = Math.min(str.length(), n);
				ans.append(str.substring(0, min));
				n -= str.length();
			}
			ans.append(str.substring(0, n));
			ret.append(ans + "\n");
		}
		System.out.println(ret);
	}
	
}

