Ternary numeric notation is quite popular in Berland. To telegraph the ternary number the Borze alphabet is used. Digit 0 is transmitted as «.», 1 as «-.» and 2 as «--». You are to decode the Borze code, i.e. to find out the ternary number given its representation in Borze alphabet.

Input

The first line contains a number in Borze code. The length of the string is between 1 and 200 characters. It's guaranteed that the given string is a valid Borze code of some ternary number (this number can have leading zeroes).

Output

Output the decoded ternary number. It can have leading zeroes.

Examples

Input

.-.--


Output

012

Input

--.


Output

20

Input

-..-.--


Output

1012
# https://codeforces.com/problemset/problem/32/B

"""
Ternary notation in Berland is as follows:
    * . is 0
    * -. is 1
    * -- is 3
"""

import sys

t_number = sys.stdin.readline().strip()
n = len(t_number)
number = ''

flag = 0
for i in range(n):
    # Character has already been considered so skip
    if flag == 1:
        flag = 0
        continue

    # Performing the parse
    if t_number[i] == '.':
        number += '0'
    elif t_number[i] == '-':
        flag = 1  # We have already considered the next character
        if t_number[i+1] == '.':
            number += '1'
        elif t_number[i+1] == '-':
            number += '2'

sys.stdout.write(number)