Skier rides on a snowy field. Its movements can be described by a string of characters 'S', 'N', 'W', 'E' (which correspond to 1 meter movement in the south, north, west or east direction respectively).

It is known that if he moves along a previously unvisited segment of a path (i.e. this segment of the path is visited the first time), then the time of such movement is 5 seconds. If he rolls along previously visited segment of a path (i.e., this segment of the path has been covered by his path before), then it takes 1 second.

Find the skier's time to roll all the path.

Input

The first line contains an integer t (1 ≤ t ≤ 10^4) — the number of test cases in the input. Then t test cases follow.

Each set is given by one nonempty string of the characters 'S', 'N', 'W', 'E'. The length of the string does not exceed 10^5 characters.

The sum of the lengths of t given lines over all test cases in the input does not exceed 10^5.

Output

For each test case, print the desired path time in seconds.

Example

Input


5
NNN
NS
WWEN
WWEE
NWNWS


Output


15
6
16
12
25
import collections
import heapq
from bisect import bisect_right

import math


def create(a, b, c):
    if (a, b) in dic:
        if c not in dic[(a, b)]:
            dic[(a, b)].append(c)
    else:
        dic.update({(x, y): [c]})


t = int(input())
for w in range(t):
    s = input()
    x = 0
    y = 0
    count = 0
    dic = {}
    for j in s:
        if (x, y) in dic:
            if j in dic[(x, y)]:
                count += 1
                if j == 'N':
                    y += 1
                elif j == 'S':
                    y -= 1
                elif j == 'E':
                    x += 1
                elif j == 'W':
                    x -= 1
            else:
                count += 5
                create(x, y, j)
                if j == 'N':
                    y += 1
                    create(x, y, 'S')
                elif j == 'S':
                    y -= 1
                    create(x, y, 'N')
                elif j == 'E':
                    x += 1
                    create(x, y, 'W')
                elif j == 'W':
                    x -= 1
                    create(x, y, 'E')
        else:
            count += 5
            create(x, y, j)
            if j == 'N':
                y += 1
                create(x, y, 'S')
            elif j == 'S':
                y -= 1
                create(x, y, 'N')
            elif j == 'E':
                x += 1
                create(x, y, 'W')
            elif j == 'W':
                x -= 1
                create(x, y, 'E')
    print(count)





