Vasiliy is fond of solving different tasks. Today he found one he wasn't able to solve himself, so he asks you to help.

Vasiliy is given n strings consisting of lowercase English letters. He wants them to be sorted in lexicographical order (as in the dictionary), but he is not allowed to swap any of them. The only operation he is allowed to do is to reverse any of them (first character becomes last, second becomes one before last and so on).

To reverse the i-th string Vasiliy has to spent ci units of energy. He is interested in the minimum amount of energy he has to spent in order to have strings sorted in lexicographical order.

String A is lexicographically smaller than string B if it is shorter than B (|A| < |B|) and is its prefix, or if none of them is a prefix of the other and at the first position where they differ character in A is smaller than the character in B.

For the purpose of this problem, two equal strings nearby do not break the condition of sequence being sorted lexicographically.

Input

The first line of the input contains a single integer n (2 ≤ n ≤ 100 000) — the number of strings.

The second line contains n integers ci (0 ≤ ci ≤ 109), the i-th of them is equal to the amount of energy Vasiliy has to spent in order to reverse the i-th string. 

Then follow n lines, each containing a string consisting of lowercase English letters. The total length of these strings doesn't exceed 100 000.

Output

If it is impossible to reverse some of the strings such that they will be located in lexicographical order, print  - 1. Otherwise, print the minimum total amount of energy Vasiliy has to spent.

Examples

Input

2
1 2
ba
ac


Output

1


Input

3
1 3 1
aa
ba
ac


Output

1


Input

2
5 5
bbb
aaa


Output

-1


Input

2
3 3
aaa
aa


Output

-1

Note

In the second sample one has to reverse string 2 or string 3. To amount of energy required to reverse the string 3 is smaller.

In the third sample, both strings do not change after reverse and they go in the wrong order, so the answer is  - 1.

In the fourth sample, both strings consists of characters 'a' only, but in the sorted order string "aa" should go before string "aaa", thus the answer is  - 1.
import java.io.IOException;
import java.io.InputStream;
import java.io.PrintWriter;
import java.math.BigInteger;
import java.util.*;

public class TestClass {
	private static InputStream stream;
	private static byte[] buf = new byte[1024];
	private static int curChar;
	private static int numChars;
	private static SpaceCharFilter filter;
	private static PrintWriter pw;
	
	public static class Queue{
		private class node{
			int val;
			node next;
			node(int a){
				val = a;
				next = null;
			}
		}
		node head,tail;
		Queue(){
			head = null;
			tail = null;
		}
		public void EnQueue(int a){
			if(head==null){
				node p = new node(a);
				head = p;
				tail = p;
			}
			else{
				node p = new node(a);
				tail.next = p;
				tail = p;
			}
		}
		public int DeQueue(){
			int a = head.val;
			head = head.next;
			return a;
		}
		public boolean isEmpty(){
			return head==null;
		}
	}
	public static long pow(long x,long y,long m){
		if(y==0)
    		return 1;
    	long k = pow(x,y/2,m);
    	if(y%2==0)
    		return (k*k)%m;
    	else
    		return (((k*k)%m)*x)%m;
    }
	static long Inversex = 0,Inversey = 0;
	public static void InverseModulo(long a,long m){
		if(m==0){
			Inversex = 1;
			Inversey = 0;
		}
		else{
    		InverseModulo(m,a%m);
    		long temp = Inversex;
    		Inversex = Inversey;
    		Inversey = temp+ - (a/m)*Inversey;
    	}
    }
    static long mod1 = 1000000007;
    static long mod2 = 1000000009;
	public static long gcd(long a,long b){
		if(a%b==0)
			return b;
		return gcd(b,a%b);
	}
	public static boolean isPrime(long a){
		if(a==1)
			return false;
		else if(a==2||a==3)
			return true;
		for(long i=2;i<=Math.sqrt(a);i++)
			if(a%i==0)
				return false;
		return true;
	}
	public static double distance(int a,int b,int x,int y){
		return Math.sqrt(((long)(a-x)*(long)(a-x))+((long)(b-y)*(long)(b-y)));
	}
	public static class Pair implements Comparable<Pair> {
		long u;
		long v;
		BigInteger bi;
		public Pair(long u, long v) {
			this.u = u;
			this.v = v;
		}
		public int hashCode() {
			int hu = (int) (u ^ (u >>> 32));
			int hv = (int) (v ^ (v >>> 32));
			return 31 * hu + hv;
		}
		public boolean equals(Object o) {
			Pair other = (Pair) o;
			return u == other.u && v == other.v;
		}
		public int compareTo(Pair other) {
			return Long.compare(u, other.u) != 0 ? Long.compare(u, other.u) : Long.compare(v, other.v);
		}
		public String toString() {
			return "[u=" + u + ", v=" + v + "]";
		}
	}
	public static int seive(int a[],boolean b[],TreeSet<Integer> c){
		int count = 0;
		for(int i=2;i<a.length;i++){
			if(!b[i]){
				for(int j=i*i;j<a.length&&j>0;j=j+i)
					b[j] = true;
				c.add(i);
				a[count++] = i;
			}
		}
		return count;
	}
	public static void MatrixMultiplication(int a[][],int b[][],int c[][]){
		for(int i=0;i<a.length;i++){
			for(int j=0;j<b[0].length;j++){
				c[i][j] = 0;
				for(int k=0;k<b.length;k++)
					c[i][j]=(int)((c[i][j]+((a[i][k]*(long)b[k][j])%mod1))%mod1);
			}
		}
	}
	public static void Equal(int arr[][],int temp[][]){
		for(int i=0;i<arr.length;i++){
			for(int j=0;j<arr.length;j++)
				temp[i][j] = arr[i][j];
		}
	}
	public static int bs(int arr[],int k,int x,int y){
		if(x>=y)
			return x;
		int mid = (x+y)/2;
		if(arr[mid]>k)
			return bs(arr,k,x,mid-1);
		else
			return bs(arr,k,mid+1,y);
	}
	private static void soln(){
		int n = nI();
		int arr[] = new int[n+1];
		for(int i=0;i<n;i++)
			arr[i+1] = nI();
		String a[] = new String[n+1];
		for(int i=1;i<=n;i++)
			a[i] = nLi();
		long dp[][] = new long[n+1][2];
		for(int i=0;i<=n;i++){
			dp[i][0] = Long.MAX_VALUE;
			dp[i][1] = Long.MAX_VALUE;
		}
		dp[1][1] = arr[1];
		dp[1][0] = 0;
		String p = a[1];
		char b[] = new char[p.length()];
		p.getChars(0, p.length(), b, 0);
		for(int i=0;i<p.length()/2;i++){
			char ch = b[i];
			b[i] = b[p.length()-(i+1)];
			b[p.length()-(i+1)] = ch;
		}
		String q = new String(b);
		for(int i=2;i<=n;i++){
			String x = q;
			char y[] = new char[a[i].length()];
			a[i].getChars(0, a[i].length(), y, 0);
			for(int j=0;j<a[i].length()/2;j++){
				char ch = y[j];
				y[j] = y[a[i].length()-(j+1)];
				y[a[i].length()-(j+1)] = ch;
			}
			String z = new String(y);
			q = z;
			if(a[i].compareTo(a[i-1])>=0)
				dp[i][0] = Math.min(dp[i][0], dp[i-1][0]);
			if(a[i].compareTo(x)>=0)
				dp[i][0] = Math.min(dp[i][0], dp[i-1][1]);
			if(z.compareTo(a[i-1])>=0)
				dp[i][1] = Math.min(dp[i][1], dp[i-1][0]);
			if(z.compareTo(x)>=0)
				dp[i][1] = Math.min(dp[i][1], dp[i-1][1]);
			if(dp[i][1]!=Long.MAX_VALUE)
				dp[i][1]+=arr[i];
		}
		long pi = Math.min(dp[n][0], dp[n][1]);
		if(pi==Long.MAX_VALUE)
			pw.println("-1");
		else
			pw.println(pi);
	}
	public static void main(String[] args) {
		InputReader(System.in);
		pw = new PrintWriter(System.out);
		soln();
		pw.close();
	}
	// To Get Input
	// Some Buffer Methods
	public static void InputReader(InputStream stream1) {
		stream = stream1;
	}
	private static boolean isWhitespace(int c) {
		return c == ' ' || c == '\n' || c == '\r' || c == '\t' || c == -1;
	}
	private static boolean isEndOfLine(int c) {
		return c == '\n' || c == '\r' || c == -1;
	}
	private static int read() {
		if (numChars == -1)
			throw new InputMismatchException();
		if (curChar >= numChars) {
			curChar = 0;
			try {
				numChars = stream.read(buf);
			} catch (IOException e) {
				throw new InputMismatchException();
			}
			if (numChars <= 0)
				return -1;
		}
		return buf[curChar++];
	}
	private static int nI() {
		int c = read();
		while (isSpaceChar(c))
			c = read();
		int sgn = 1;
		if (c == '-') {
			sgn = -1;
			c = read();
		}
		int res = 0;
		do {
			if (c < '0' || c > '9')
				throw new InputMismatchException();
			res *= 10;
			res += c - '0';
			c = read();
		} while (!isSpaceChar(c));
		return res * sgn;
	}
	private static long nL() {
		int c = read();
		while (isSpaceChar(c))
			c = read();
		int sgn = 1;
		if (c == '-') {
			sgn = -1;
			c = read();
		}
		long res = 0;
		do {
			if (c < '0' || c > '9')
				throw new InputMismatchException();
			res *= 10;
			res += c - '0';
			c = read();
		} while (!isSpaceChar(c));
		return res * sgn;
	}
	private static String nextToken() {
		int c = read();
		while (isSpaceChar(c))
			c = read();
		StringBuilder res = new StringBuilder();
		do {
			res.appendCodePoint(c);
			c = read();
		} while (!isSpaceChar(c));
		return res.toString();
	}
	private static String nLi() {
		int c = read();
		while (isSpaceChar(c))
			c = read();
		StringBuilder res = new StringBuilder();
		do {
			res.appendCodePoint(c);
			c = read();
		} while (!isEndOfLine(c));
		return res.toString();
	}
	private static int[] nIA(int n) {
		int[] arr = new int[n];
		for (int i = 0; i < n; i++)
			arr[i] = nI();
		return arr;
	}
	private static long[] nLA(int n) {
		long[] arr = new long[n];
		for (int i = 0; i < n; i++)
			arr[i] = nL();
		return arr;
	}
	private static void pArray(int[] arr) {
		for (int i = 0; i < arr.length; i++)
			pw.print(arr[i] + " ");
		pw.println();
		return;
	}
	private static void pArray(long[] arr) {
		for (int i = 0; i < arr.length; i++)
			pw.print(arr[i] + " ");
		pw.println();
		return;
	}
	private static boolean isSpaceChar(int c) {
		if (filter != null)
			return filter.isSpaceChar(c);
		return isWhitespace(c);
	}
	private interface SpaceCharFilter {
		public boolean isSpaceChar(int ch);
	}
}