The sum of the first n terms of an arithmetic progression is given by $S_n = 6n^2 - 2n$. What is the value of n for which $S_n = 1320$?
A. 12
B. 13
C. 14
D. 15
Answer:C
The sum of the first n terms of an arithmetic progression is given by $S_n = 6n^2 - 2n$. What is the value of n for which $S_n = 1320$?
A. 12 B. 13 C. 14 D. 15