Chegg Guided Solutions for Chemistry The Molecular Nature of Matter and Change 6th Edition: Chapter 16

Chapter: Problem:
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    Plan: Add the two equations, canceling substances that appear on both sides of the arrow. The rate law for each step follows the format of rate = k[reactants]. An initial reactant that appears as a product in a subsequent step is a catalyst; a product that appears as a reactant in a subsequent step is an intermediate (produced in one step and consumed in a subsequent step).

    a) Add the two equations:

    Rate laws:

    Step 1 Rate1 = k1[X][O3]

    Step 2 Rate2 = k2[XO][O]

    b) X acts as a catalyst; it is a reactant in step 1 and a product in step 2. XO acts as an intermediate; it was produced in step 1 and consumed in step 2.

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