package com.fishercoder.solutions;

import java.util.Stack;

/**
 * 735. Asteroid Collision
 *
 * We are given an array asteroids of integers representing asteroids in a row.
 * For each asteroid, the absolute value represents its size, and the sign represents its direction
 * (positive meaning right, negative meaning left). Each asteroid moves at the same speed.
 * Find out the state of the asteroids after all collisions.
 * If two asteroids meet, the smaller one will explode. If both are the same size, both will explode. Two asteroids moving in the same direction will never meet.

 Example 1:
 Input:
 asteroids = [5, 10, -5]
 Output: [5, 10]
 Explanation:
 The 10 and -5 collide resulting in 10.  The 5 and 10 never collide.

 Example 2:
 Input:
 asteroids = [8, -8]
 Output: []
 Explanation:
 The 8 and -8 collide exploding each other.

 Example 3:
 Input:
 asteroids = [10, 2, -5]
 Output: [10]
 Explanation:
 The 2 and -5 collide resulting in -5.  The 10 and -5 collide resulting in 10.

 Example 4:
 Input:
 asteroids = [-2, -1, 1, 2]
 Output: [-2, -1, 1, 2]
 Explanation:
 The -2 and -1 are moving left, while the 1 and 2 are moving right.
 Asteroids moving the same direction never meet, so no asteroids will meet each other.

 Note:
 The length of asteroids will be at most 10000.
 Each asteroid will be a non-zero integer in the range [-1000, 1000]..

 */
public class _735 {
    public static class Solution1 {
        public int[] asteroidCollision(int[] asteroids) {
            Stack<Integer> stack = new Stack();
            for (int i = 0; i < asteroids.length; i++) {
                if (!stack.isEmpty() && stack.peek() > 0 && asteroids[i] < 0) {
                    if (Math.abs(stack.peek()) < Math.abs(asteroids[i])) {
                        stack.pop();
                        stack.push(asteroids[i]);
                        collide(stack);
                    } else if (Math.abs(stack.peek()) == Math.abs(asteroids[i])) {
                        stack.pop();
                    }
                } else {
                    stack.push(asteroids[i]);
                }
            }
            int[] result = new int[stack.size()];
            int i = stack.size();
            while (!stack.isEmpty()) {
                result[--i] = stack.pop();
            }
            return result;
        }

        private void collide(Stack<Integer> stack) {
            do {
                Integer top = stack.pop();
                if (!stack.isEmpty() && stack.peek() * top < 0) {
                    if (stack.peek() < Math.abs(top)) {
                        stack.pop();
                        stack.push(top);
                    } else if (stack.peek() == Math.abs(top)) {
                        stack.pop();
                        break;
                    } else {
                        break;
                    }
                } else if (stack.isEmpty() || stack.peek() * top > 0) {
                    stack.push(top);
                    break;
                }
            } while (!stack.isEmpty());
        }
    }
}

@@ -58,1321 +58,8 @@
 k;%0A%0A
-/**%0A * 735. Asteroid Collision%0A *%0A * We are given an array asteroids of integers representing asteroids in a row.%0A * For each asteroid, the absolute value represents its size, and the sign represents its direction%0A * (positive meaning right, negative meaning left). Each asteroid moves at the same speed.%0A * Find out the state of the asteroids after all collisions.%0A * If two asteroids meet, the smaller one will explode. If both are the same size, both will explode. Two asteroids moving in the same direction will never meet.%0A%0A Example 1:%0A Input:%0A asteroids = %5B5, 10, -5%5D%0A Output: %5B5, 10%5D%0A Explanation:%0A The 10 and -5 collide resulting in 10.  The 5 and 10 never collide.%0A%0A Example 2:%0A Input:%0A asteroids = %5B8, -8%5D%0A Output: %5B%5D%0A Explanation:%0A The 8 and -8 collide exploding each other.%0A%0A Example 3:%0A Input:%0A asteroids = %5B10, 2, -5%5D%0A Output: %5B10%5D%0A Explanation:%0A The 2 and -5 collide resulting in -5.  The 10 and -5 collide resulting in 10.%0A%0A Example 4:%0A Input:%0A asteroids = %5B-2, -1, 1, 2%5D%0A Output: %5B-2, -1, 1, 2%5D%0A Explanation:%0A The -2 and -1 are moving left, while the 1 and 2 are moving right.%0A Asteroids moving the same direction never meet, so no asteroids will meet each other.%0A%0A Note:%0A The length of asteroids will be at most 10000.%0A Each asteroid will be a non-zero integer in the range %5B-1000, 1000%5D..%0A%0A */%0A
 publ

refactor 735