def getx5(self, g11, g12, g13):
        A1 = (((745.0 * g13) /(g11*g12))**2 + 0.169*1.0e08)**0.5
        g21 = (A1 / (1100.0*0.1) )**(1.0/3.0)
        g22 = (1.93 * g13 * g13 * g13 / (g11 * g12))**0.25
        g23 = 2.9

        x05 = max(g21, g22, g23)
        return x05


#   optimize  x[6] ..............
dataset/ETHPy150Open OpenMDAO/OpenMDAO-Framework/openmdao.lib/src/openmdao/lib/drivers/test/test_opt_golinski.py/GolinskiTestCase.getx5/original