def long_to_bytes(n, blocksize=0):
    """long_to_bytes(n:long, blocksize:int) : string
    Convert a long integer to a byte string.

    If optional blocksize is given and greater than zero, pad the front of the
    byte string with binary zeros so that the length is a multiple of
    blocksize.
    """
    # after much testing, this algorithm was deemed to be the fastest
    s = b('')
    n = long(n)
    pack = struct.pack
    while n > 0:
        s = pack('>I', n & 0xffffffffL) + s
        n = n >> 32
    # strip off leading zeros
    for i in range(len(s)):
        if s[i] != b('\000')[0]:
            break
    else:
        # only happens when n == 0
        s = b('\000')
        i = 0
    s = s[i:]
    # add back some pad bytes.  this could be done more efficiently w.r.t. the
    # de-padding being done above, but sigh...
    if blocksize > 0 and len(s) % blocksize:
        s = (len(s) % blocksize - blocksize) * b('\000') + s
    return s
dataset/ETHPy150Open cloudera/hue/desktop/core/ext-py/pycrypto-2.6.1/lib/Crypto/Util/number.py/long_to_bytes/swapped operands of `-`