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ericsun153
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mathqa_question_token_drop_test

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Rationale
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annotated_formula
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linear_formula
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company green imported?
"answer a . we are told that 10 % of all imported widgets are made of brass and of those , 20 % are red and 40 % are blue . since we know that there are only three colors , the remaining 40 % must be green . 40 % blue of 10 % brass widgets leads to 4 % green brass widgets out of the total 10,550 widgets . 10,500 / 100 * 4 = 420 . answer d ."
a ) 480 , b ) 840 , c ) 1050 , d ) 420 , e ) 2100
d
multiply(multiply(multiply(multiply(divide(10, const_100), divide(40, const_100)), divide(add(10, const_2), 10)), const_100), const_100)
add(n1,const_2)|divide(n1,const_100)|divide(n3,const_100)|divide(#0,n1)|multiply(#1,#2)|multiply(#3,#4)|multiply(#5,const_100)|multiply(#6,const_100)|
gain
a at is :
"speed of the train relative to man = 250 / 20 m / sec = 25 / 2 m / sec . = 25 / 2 x 18 / 5 km / hr = 45 km / hr . let the speed of the train be x km / hr . then , relative speed = ( x - 10 ) km / hr . x - 10 = 45 = 55 km / hr . answer : c"
a ) 100 , b ) 60 , c ) 55 , d ) 50 , e ) 45
c
divide(divide(subtract(250, multiply(multiply(10, const_0_2778), 10)), 10), const_0_2778)
multiply(n1,const_0_2778)|multiply(n1,#0)|subtract(n0,#1)|divide(#2,n1)|divide(#3,const_0_2778)|
physics
you'end?
"solution start with 17 baseball cards . maria takes half of one more than the number of baseball cards you have . so maria takes half of 17 + 1 which is 9 , so you ' re left with 17 - 9 = 8 . peter takes 1 baseball card from you : 8 - 1 = 7 baseball cards . paul triples the number of baseball cards you have : 7 ã — 3 = 21 baseball cards . so you have 21 at the end . correct answer : e"
a ) 17 , b ) 18 , c ) 19 , d ) 20 , e ) 21
e
multiply(subtract(subtract(subtract(17, const_4), const_4), 1), const_3)
subtract(n0,const_4)|subtract(#0,const_4)|subtract(#1,n1)|multiply(#2,const_3)|
general
a annual employees?
average = 2 ( 19000 ) + ( 21000 ) + 3 ( 22000 ) / 6 = $ 20,833 the answer is c .
a ) $ 20,200 , b ) $ 20,500 , c ) $ 20,800 , d ) $ 21,000 , e ) $ 21,400
c
divide(divide(add(multiply(22000, 3), add(multiply(19000, 2), 21000)), const_1000), 6)
multiply(n1,n2)|multiply(n5,n6)|add(n3,#0)|add(#2,#1)|divide(#3,const_1000)|divide(#4,n0)
general
if23 days?
"total number of days of stay = 23 charge of staying in first week = 18 * 7 = 126 $ charge of staying for additional days = ( 23 - 7 ) * 15 = 16 * 15 = 240 $ total charge = 126 + 240 = 366 $ answer a"
a ) $ 336 , b ) $ 289 , c ) $ 282 , d ) $ 274 , e ) $ 286
a
add(multiply(18.00, add(const_3, const_4)), multiply(15.00, subtract(23, add(const_3, const_4))))
add(const_3,const_4)|multiply(n0,#0)|subtract(n2,#0)|multiply(n1,#2)|add(#1,#3)|
general
oneals field.
"other side = ( ( 17 ) 2 - ( 15 ) 2 ) ( 1 / 2 ) = ( 289 - 225 ) ( 1 / 2 ) = ( 64 ) ( 1 / 2 ) = 8 m . area = ( 15 x 8 ) m 2 = 120 m 2 . ans : a"
a ) 120 , b ) 147 , c ) 251 , d ) 451 , e ) 258
a
rectangle_area(15, sqrt(subtract(power(17, const_2), power(15, const_2))))
power(n1,const_2)|power(n0,const_2)|subtract(#0,#1)|sqrt(#2)|rectangle_area(n0,#3)|
geometry
a water storm?
after the reservoir is filled to 75 gallons the amount of water is at 37.5 % - which means that 62.5 % of the reservoir is empty . to figure out what that 62.5 % is approximate : 75 gallons / 37.5 percent = x gallons / 62.5 percent , therefore , x = 125 gallons , answer choices a , b , c , d are below 125 . we know that the reservoir must be short more than 125 gallons , therefore , the only possible choice is e .
a ) 90 , b ) 114 , c ) 124 , d ) 120 , e ) 127
e
divide(divide(multiply(75, const_100), 37.5), const_2)
multiply(n1,const_100)|divide(#0,n2)|divide(#1,const_2)|
general
a s scale?
first , we have to understand what linearly means . it ' s not a straight ratio ( since 6 : 30 does not equal 24 : 60 ) . we need to look at the increases in each measurement to see what the scalar actually is . from 6 to 24 we have an increase of 18 . from 30 to 60 we have an increase of 30 . therefore , the increase ratio is 18 : 30 or 3 : 5 . in other words , for every 3 that t increases , s increases by 5 . we know that s is 100 . to get from 60 to 100 , we went up by 40 , or 8 jumps of 5 ; therefore , t will go up by 8 jumps of 3 . 24 + 8 ( 3 ) = 24 + 24 = 48 = c
a ) 20 , b ) 36 , c ) 48 , d ) 60 , e ) 84
c
add(multiply(subtract(24, 6), divide(subtract(100, 60), subtract(60, 30))), 24)
subtract(n4,n3)|subtract(n3,n2)|subtract(n1,n0)|divide(#0,#1)|multiply(#3,#2)|add(n1,#4)
general
the. number.
let the numbers be x and ( 184 - x ) . then , ( x / 3 ) - ( 184 - x ) / 7 = 8 7 x - 3 ( 184 - x ) = 168 10 x = 720 , x = 72 . hence the correct answer is option a ) 72 .
a ) 72 , b ) 64 , c ) 84 , d ) 12 , e ) 92
a
divide(add(multiply(184, const_3), multiply(multiply(add(const_3, const_4), const_3), 8)), add(add(const_3, const_4), const_3))
add(const_3,const_4)|multiply(n0,const_3)|add(#0,const_3)|multiply(#0,const_3)|multiply(n1,#3)|add(#1,#4)|divide(#5,#2)
general
the even inclusive?
"my solution is : first 50 even integers : 2 4 6 8 < . . . > integers from 102 to 200 102 104 106 108 < . . . > we notice that each integer from the second set is 100 more than the respective integer in the first set . since we have 50 even integers from 102 to 200 , then : q = 2550 + ( 100 * 50 ) = 7550 . b"
a ) 5100 , b ) 7550 , c ) 10100 , d ) 15500 , e ) 20100
b
multiply(divide(add(200, 102), const_2), add(divide(subtract(200, 102), const_2), const_1))
add(n2,n3)|subtract(n3,n2)|divide(#1,const_2)|divide(#0,const_2)|add(#2,const_1)|multiply(#4,#3)|
general
how are % solution
explanation : question of this type looks a bit typical , but it is too simple , as below . . . it will be 15 * 20 / 100 = 3 answer : option d
a ) 4 , b ) 5 , c ) 2 , d ) 3 , e ) 1
d
multiply(divide(20, const_100), 15)
divide(n1,const_100)|multiply(n0,#0)|
gain
rs among share?
let y gets rs x . then we can say x gets rs ( x + 20 ) and y gets rs ( x + 35 ) . x + 20 + x + x + 35 = 385 3 x = 330 x = 110 . r ’ s share = rs ( 110 + 35 ) = rs . 145 b
a ) rs . 130 , b ) rs . 145 , c ) rs . 154 , d ) rs . 160 , e ) rs . 164
b
add(15, add(divide(subtract(385, add(15, add(20, 20))), const_3), 20))
add(n1,n1)|add(n2,#0)|subtract(n0,#1)|divide(#2,const_3)|add(n1,#3)|add(n2,#4)
general
when3 16
case 1 n = 5,8 , 11,14 , 17,20 case 2 m = 5 , 9,13 , 17,21 therefore n = 17 remainder of 17 / 16 will be 1 a
a ) 1 , b ) 3 , c ) 4 , d ) 5 , e ) 2
a
floor(divide(add(add(const_12, const_3), add(const_2, const_4)), 16))
add(const_12,const_3)|add(const_2,const_4)|add(#0,#1)|divide(#2,n4)|floor(#3)
general
a the men?
"original number of men = 8 * 28 / ( 28 - 20 ) = 28 answer is b"
a ) 60 , b ) 28 , c ) 40 , d ) 50 , e ) 25
b
divide(multiply(8, 28), subtract(28, 20))
multiply(n1,n2)|subtract(n2,n0)|divide(#0,#1)|
physics
three covered wallpaper?
"280 - 180 = 100 sq m of the wallpaper overlaps ( in either two layers or three layers ) if 36 sq m has two layers , 100 - 36 = 64 sq m of the wallpaper overlaps in three layers . 64 sq m makes two extra layers hence the area over which it makes two extra layers is 32 sq m . answer ( b ) ."
a ) 5 square meters , b ) 32 square meters , c ) 42 square meters , d ) 83.3 square meters , e ) 120 square meters
b
divide(subtract(subtract(280, 180), 36), const_2)
subtract(n0,n1)|subtract(#0,n2)|divide(#1,const_2)|
geometry
mr by6 is
explanation : numbers from 1 to 60 , which are divisible by 6 are : 6 , 1218 , 24 , 30 , 3642 , 48 , 54 , 60 . there are 10 such numbers . numbers from 1 to 60 , the sum of whose digits is 6 are : 6 , 15 , 24 , 33 , 42 , 51 , 60 . there are 7 such numbers of which 4 are common to the above ones . so , there are 3 such uncommon numbers . numbers from 1 to 60 , which have 6 as one of the digits are 6 , 16 , 26 , 36 , 46 , 56 , 60 . clearly , there are 4 such uncommon numbers . so , numbers ' not connected with 6 ' = 60 - ( 10 + 3 + 4 ) = 43 . answer : d
a ) 18 , b ) 22 , c ) 42 , d ) 43 , e ) 45
d
subtract(60, add(add(const_10, const_3), const_4))
add(const_10,const_3)|add(#0,const_4)|subtract(n6,#1)
general
a45 individually?
"cost of kit = $ 67.50 if filters are purchased individually - $ 7.45 * 2 + $ 10.05 * 2 + $ 14.50 = $ 49.50 amount saved = $ 67.50 - $ 49.50 = $ 18 required % age = ( $ 18 / $ 67.50 ) * 100 = 26.66 % so , the correct answer is b ."
a ) 25.66 % , b ) 26.66 % , c ) 27.66 % , d ) 28.66 % , e ) 29.66 %
b
divide(multiply(subtract(67.50, add(14.50, add(multiply(2, 7.45), multiply(2, 10.05)))), const_100), 67.50)
multiply(n2,n3)|multiply(n2,n5)|add(#0,#1)|add(n7,#2)|subtract(n1,#3)|multiply(#4,const_100)|divide(#5,n1)|
general
the is?
"largest 4 - digit number = 9999 90 ) 9999 ( 111 9990 - - - - - - - - - - - - largest number divisible by 90 is 9990 answer : e"
a ) 9935 , b ) 9939 , c ) 9944 , d ) 9954 , e ) 9990
e
square_area(const_pi)
square_area(const_pi)|
general
if the?.
20 ! = 1 * 2 * 3 * 4 * 5 . . . * 19 * 20 ( this is 20 factorial written as 20 ! ) n = 1 * 2 * 3 * 4 * 5 * 6 * 7 . . . . . * 19 * 20 how many 2 s are there in n ? one 2 from 2 two 2 s from 4 one two from 6 three 2 s from 8 and so on . . . when you count them all , you get 18 . answer : d
a ) 10 , b ) 12 , c ) 15 , d ) 18 , e ) 20
d
add(add(add(divide(20, 2), divide(20, power(2, const_2))), floor(divide(20, power(power(2, const_2), 2)))), floor(divide(20, power(2, const_3))))
divide(n1,n2)|power(n2,const_2)|power(n2,const_3)|divide(n1,#1)|divide(n1,#2)|power(#1,n2)|add(#0,#3)|divide(n1,#5)|floor(#4)|floor(#7)|add(#6,#9)|add(#10,#8)
general
a rail journey is
"explanation : let the journey be x km then , 1 x / 2 + 1 x / 4 + 4 = x 3 x + 16 = 4 x x = 16 km answer : option b"
a ) 18 km , b ) 16 km , c ) 12 km , d ) 24 km , e ) 25 km
b
multiply(4, 4)
multiply(n3,n4)|
general
what a5?
"explanation : since every third number starting from 10 will be divisible by 3 , so total number of numbers divisible by 3 are 90 / 3 = 30 numbers which are divisible by 3 and 5 both are numbers which are multiple of 15 . for the range 10 to 99 , 15 is the first number divisible by 15 and 90 is the last number . so total number of numbers divisible by 15 are : ( 90 - 15 ) / 15 + 1 = 5 + 1 = 6 number of numbers which are divisible by 3 are 30 and number of numbers which are divisible by 3 and 5 both are 6 . so number of numbers divisible by 3 and not by 5 are : 30 - 6 = 24 so total probability = 24 / 90 = 4 / 15 answer : c"
a ) 1 / 15 , b ) 2 / 15 , c ) 4 / 15 , d ) 7 / 15 , e ) none of these
c
divide(subtract(multiply(multiply(5, const_2), 3), multiply(3, const_2)), multiply(multiply(5, const_2), multiply(3, 3)))
multiply(n1,const_2)|multiply(n0,const_2)|multiply(n0,n0)|multiply(n0,#0)|multiply(#0,#2)|subtract(#3,#1)|divide(#5,#4)|
probability
b. rent?
"given 30 % ( income ) = 300 ⇒ ⇒ income = 1000 after having spent rs . 300 on petrol , he left with rs . 700 . his spending on house rent = 21 % ( 700 ) = rs . 147 answer : e"
a ) 2287 , b ) 140 , c ) 128 , d ) 797 , e ) 147
e
multiply(subtract(divide(300, divide(30, const_100)), 300), divide(21, const_100))
divide(n1,const_100)|divide(n0,const_100)|divide(n2,#1)|subtract(#2,n2)|multiply(#0,#3)|
gain
45 should hours?
"45 workers * 8 hours / 30 meters = x * 6 / 35 x = 70 total workers 70 - 45 = 30 new workers the answer is c ."
a ) 10 , b ) 20 , c ) 30 , d ) 40 , e ) 50
c
subtract(multiply(multiply(45, divide(8, 6)), divide(35, 30)), 45)
divide(n3,n2)|divide(n1,n4)|multiply(n0,#1)|multiply(#0,#2)|subtract(#3,n0)|
physics
one equal to :
"lots of ways to tackle this . 25 % of 180 = 45 1 / 3 of 45 = 15 so , 1 / 3 less than 45 is equal to 45 - 15 = 30 answer : b"
a ) 15 , b ) 30 , c ) 35 , d ) 40 , e ) 45
b
subtract(multiply(divide(25, const_100), 180), multiply(divide(const_1, const_3), multiply(divide(25, const_100), 180)))
divide(n0,const_100)|divide(const_1,const_3)|multiply(n1,#0)|multiply(#1,#2)|subtract(#2,#3)|
general
if five minutes?
"if an object travels at 8 feet per second it covers 8 x 60 feet in one minute , and 8 x 60 x 45 feet in forty five minutes . answer = 21600 answer : c"
a ) 18000 , b ) 24000 , c ) 21600 , d ) 18000 , e ) 22000
c
multiply(multiply(const_3, const_60), const_60)
multiply(const_3,const_60)|multiply(#0,const_60)|
physics
in sun?
explanation : let arun ’ s weight by x kg . according to arun , 65 < x < 72 according to arun ’ s brother , 60 < x < 70 . according to arun ’ s mother , x < = 68 the values satisfying all the above conditions are 66 , 67 and 68 . required average = [ 66 + 67 + 68 / 3 ] = [ 201 / 3 ] = 67 kg answer b
a ) 66 kg , b ) 67 kg , c ) 68 kg , d ) 69 kg , e ) none of these
b
divide(add(add(subtract(68, const_1), subtract(subtract(68, const_1), const_1)), 68), const_3)
subtract(n4,const_1)|subtract(#0,const_1)|add(#0,#1)|add(n4,#2)|divide(#3,const_3)
general
there paperback?
approach 1 at - least 1 paper back = total - no paper back 8 c 4 - 5 c 4 = 65 approach 2 at - least 1 paper back = 1 paper back , 3 hard back or 2 paper back 2 hard back = 3 c 1 * 5 c 3 + 3 c 2 * 5 c 2 + 3 c 3 * 5 c 1 = 65 answer is e
a ) a ) 40 , b ) b ) 45 , c ) c ) 50 , d ) d ) 55 , e ) e ) 65
e
subtract(choose(8, 4), choose(5, 4))
choose(n0,n3)|choose(n2,n3)|subtract(#0,#1)
probability
ro and salary is
"sol . saving = [ 100 - ( 40 + 20 + 10 + 10 ] % = 20 % . let the monthly salary be rs . x . then , 20 % of x = 500 â ‡ ” 20 / 100 x = 500 â ‡ ” x = 500 ã — 5 = 2500 . answer a"
a ) rs . 2500 , b ) rs . 3500 , c ) rs . 1500 , d ) rs . 500 , e ) rs . 2000
a
multiply(500, add(const_4, const_1))
add(const_1,const_4)|multiply(n4,#0)|
gain
there many hospital?
"given , the ratio of the doctors to the nurses is 8 : 11 number of nurses = 11 / 19 x 418 = 242 answer : c"
a ) 152 , b ) 209 , c ) 242 , d ) 171 , e ) 181
c
multiply(multiply(8, subtract(11, 8)), 11)
subtract(n2,n1)|multiply(n1,#0)|multiply(n2,#1)|
other
rovt robert?
"total salary = rs . 15000 / - borrowed money = 7280 / - balance salary = 15000 - 7280 = 7720 paid amount = 18500 / - incentive amount = 18500 - 7720 = 10780 / - answer is c"
a ) 9500 , b ) 12500 , c ) 10780 , d ) 10500 , e ) 8600
c
subtract(18500, 7280)
subtract(n2,n1)|
general
what to400?
"3 : 4 = x : 200 4 x = 3 * 400 x = 300 answer : d"
a ) 130 , b ) 100 , c ) 200 , d ) 300 , e ) 120
d
multiply(400, 3)
multiply(n0,n2)|
other
the days last?
one man can consume the same food in 40 * 20 = 800 days . 10 more men join , the total number of men = 50 the number of days the food will last = 800 / 50 = 16 days . answer : d
a ) 22 days , b ) 30 days , c ) 23 days , d ) 16 days , e ) 17 days
d
divide(multiply(40, 20), add(40, 10))
add(n0,n2)|multiply(n0,n1)|divide(#1,#0)
physics
a30 price?
"original price = 100 cp = 70 s = 70 * ( 150 / 100 ) = 105 100 - 105 = 5 % answer : e"
a ) 7 % , b ) 62 % , c ) 12 % , d ) 19 % , e ) 5 %
e
multiply(subtract(divide(divide(multiply(subtract(const_100, 30), add(const_100, 50)), const_100), const_100), const_1), const_100)
add(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|divide(#2,const_100)|divide(#3,const_100)|subtract(#4,const_1)|multiply(#5,const_100)|
gain
how be cm edge
"explanation : number of cubes = ( 20 x 20 x 20 ) / ( 5 x 5 x 5 ) = 64 answer : b"
a ) 36 , b ) 64 , c ) 216 , d ) 484 , e ) none of these
b
divide(volume_cube(20), volume_cube(divide(5, const_100)))
divide(n0,const_100)|volume_cube(n1)|volume_cube(#0)|divide(#1,#2)|
probability
in'lift?
"this problem is a general word translation . we first define variables and then set up equations . we can define the following variables : f = the weight of the first lift s = the weight of the second lift we are given that the total weight of joe ' s two lifts was 450 pounds . we sum the two variables to obtain : f + s = 450 we are also given that twice the weight of his first lift was 300 pounds more than the weight of his second lift . we express this as : 2 f = 300 + s 2 f – 300 = s we can now plug in ( 2 f – 300 ) for s into the first equation , so we have : f + 2 f – 300 = 450 3 f = 750 f = 250 answer is a ."
a ) 250 , b ) 275 , c ) 325 , d ) 350 , e ) 400
a
divide(add(450, 300), const_3)
add(n0,n1)|divide(#0,const_3)|
general
a month month?
"the total number of books is 150 . let x be the number of books which were loaned out . 65 % of books that were loaned out are returned . 35 % of books that were loaned out are not returned . now , there are 108 books , thus the number of un - returned books is 150 - 108 = 42 books . 0.35 x = 42 x = 120 the answer is e ."
a ) 40 , b ) 60 , c ) 80 , d ) 100 , e ) 120
e
divide(subtract(150, 108), subtract(const_1, divide(65, const_100)))
divide(n1,const_100)|subtract(n0,n2)|subtract(const_1,#0)|divide(#1,#2)|
gain
ram speed ).
distance travelled by ramu = 45 * 4 = 180 km somu travelled the same distance in 6 hours . his speed = 180 / 6 = 30 km / hr hence in the conditional case , ramu ' s speed = 45 - 9 = 36 km / hr and somu ' s speed = 30 + 10 = 40 km / hr . therefore travel time of ramu and somu would be 5 hours and 4.5 hours respectively . hence difference in the time taken = 0.5 hours = 30 minutes . answer : b
a ) 23 minutes , b ) 30 minutes , c ) 43 minutes , d ) 23 minutes , e ) 33 minutes
b
multiply(subtract(divide(multiply(45, 4), subtract(45, 9)), divide(multiply(45, 4), add(divide(multiply(45, 4), 6), 10))), const_60)
multiply(n0,n1)|subtract(n0,n3)|divide(#0,#1)|divide(#0,n2)|add(n4,#3)|divide(#0,#4)|subtract(#2,#5)|multiply(#6,const_60)
general
if œ =?
"explanation : given : 240 * 80 / 60 + 40 / 10 = ? substituting the coded symbols for mathematical operations , we get , 240 / 80 - 60 * 40 - 10 = ? 3 - 2400 - 10 = - 2407 answer : b"
a ) - 2305 , b ) - 2407 , c ) 2509 , d ) - 2101 , e ) none of these
b
add(multiply(divide(60, 40), divide(240, 80)), 10)
divide(n2,n3)|divide(n0,n1)|multiply(#0,#1)|add(n4,#2)|
general
el $ purchase?
"4 x + 2.8 y = 42 - - > multiply by 2.5 ( to get the integers ) - - > 10 x + 7 y = 105 - - > only one positive integers solutions x = 6 and y = 5 ( how to solve : 7 y must have the last digit of 5 in order the last digit of the sum to be 5 ) . answer : c ."
a ) 4 , b ) 5 , c ) 6 , d ) 7 , e ) 8
c
subtract(multiply(const_4.0, 12), 42.00)
multiply(const_4.0,n2)|subtract(#0,n3)|
general
the. is :
"let the numbers be 2 x and 3 x . then , their l . c . m = 6 x . so , 6 x = 48 or x = 8 . the numbers are 16 and 24 . hence , required sum = ( 16 + 24 ) = 40 . answer : c"
a ) 28 , b ) 30 , c ) 40 , d ) 50 , e ) 60
c
divide(multiply(2, 48), 3)
multiply(n0,n1)|divide(#0,n2)|
other
in square formed?
let the side of the square be x m . ∴ perimeter of the square = 48 × 2 = 4 x ∴ x = 24 m ∴ area = ( 24 ) 2 = 576 m 2 answer d
['a ) 133 cm 2', 'b ) 276 cm 2', 'c ) 2500 cm 2', 'd ) 576 cm 2', 'e ) none of these']
d
square_area(divide(48, 2))
divide(n0,n1)|square_area(#0)
physics
find paralle cm?
area of a parallelogram = base * height = 20 * 10 = 200 cm 2 answer : e
['a ) 290 cm 2', 'b ) 380 cm 2', 'c ) 270 cm 2', 'd ) 280 cm 2', 'e ) 200 cm 2']
e
multiply(20, 10)
multiply(n0,n1)
geometry
a type b?
"in 84 liters of drink a , there are 48 liters of milk and 36 liters of juice . with 48 liters of milk , we need a total of 64 liters of juice to make drink b . we need to add 28 liters of juice . the answer is b ."
a ) 24 , b ) 28 , c ) 32 , d ) 36 , e ) 40
b
subtract(divide(multiply(multiply(divide(4, add(4, 3)), 84), 4), 3), multiply(divide(3, add(4, 3)), 84))
add(n0,n1)|divide(n0,#0)|divide(n1,#0)|multiply(n4,#1)|multiply(n4,#2)|multiply(n0,#3)|divide(#5,n1)|subtract(#6,#4)|
general
which possible65 cm
"explanation : convert first all terms into cm . i . e . 1265 cm , 1525 cm , 1065 cm . now whenever we need to calculate this type of question , we need to find the hcf . hcf of above terms is 5 . option b"
a ) 45 cm , b ) 5 cm , c ) 4 cm , d ) 15 cm , e ) 50 cm
b
floor(divide(add(multiply(12, const_100), 65), add(multiply(15, const_100), 25)))
multiply(n0,const_100)|multiply(n2,const_100)|add(n1,#0)|add(n3,#1)|divide(#2,#3)|floor(#4)|
physics
in players m?
"we have equation 2 n + 5 m = 50 we have factor 2 in first number and we have factor 5 in second number . lcm ( 2 , 5 ) = 10 so we can try some numbers and we should start from 5 because it will be less list than for 2 2 * 5 = 10 and n should be equal 20 4 * 5 = 20 and n should be equal 15 6 * 5 = 30 and n should be equal 10 8 * 5 = 40 and n should be equal 5 10 * 5 = 50 and n should be equal 0 third variant give us the mininal difference n - m = 10 - 6 = 4 and there is some mistake in my way of thinking because we do n ' t have such answer ) if we change the task and will seek for difference between m and n than minimal result r will be 8 - 5 = 3 and answer b"
a ) 1 , b ) 3 , c ) 5 , d ) 7 , e ) 9
b
subtract(5, 2)
subtract(n1,n0)|
general
in the school is
"sol . let the number of grils be x . then , number of boys = ( 620 - x ) . then , ( 11 3 / 4 × 620 ) ⇔ 11 x + 12 ( 620 - x ) ⇔ x = 7440 - 7285 ⇔ 155 . answer c"
a ) 150 , b ) 200 , c ) 155 , d ) 350 , e ) none
c
subtract(multiply(12, 620), multiply(add(11, divide(9, 12)), 620))
divide(n4,n1)|multiply(n0,n1)|add(n2,#0)|multiply(n0,#2)|subtract(#1,#3)|
general
two cross - seconds
"relative speed = 60 + 90 = 150 km / hr ( since both trains are moving in opposite directions ) total distance = 1.1 + . 9 = 2 km time = 2 / 150 hr = 1 / / 75 hr = 3600 / 75 seconds = 1200 / 25 = 240 / 5 = 48 seconds answer is e ."
a ) 40 , b ) 42 , c ) 44 , d ) 46 , e ) 48
e
multiply(divide(add(1.10, 0.9), add(60, 90)), const_3600)
add(n2,n3)|add(n0,n1)|divide(#0,#1)|multiply(#2,const_3600)|
physics
the0 in?
clearly , the two will meet when they are 1000 m apart to be 20 + 14 = 34 km apart , they take 1 hour to be 1000 m apart , they take 34 * 1000 / 1000 = 34 min . answer is c
a ) 50 min , b ) 40 min , c ) 34 min , d ) 25 min , e ) 20 min
c
add(20, 14)
add(n1,n2)
general
the simple is :
"sol . sum = s . i . * t . d . / ( s . i ) - ( t . d . ) = 90 * 80 / ( 90 - 80 ) = rs . 720 . answer c"
a ) 1360 , b ) 1450 , c ) 720 , d ) 1800 , e ) none
c
divide(multiply(90, 80), subtract(90, 80))
multiply(n0,n1)|subtract(n0,n1)|divide(#0,#1)|
gain
find m20.
"explanation : 2 x 3 x 5 x 2 x 2 = 120 answer : option c"
a ) 140 , b ) 160 , c ) 120 , d ) 150 , e ) 250
c
multiply(multiply(power(const_3, const_3), multiply(power(const_2, const_3), power(add(const_4, const_1), const_2))), divide(divide(divide(divide(divide(24, const_2), const_2), const_3), add(const_4, const_1)), add(const_4, const_1)))
add(const_1,const_4)|divide(n2,const_2)|power(const_2,const_3)|power(const_3,const_3)|divide(#1,const_2)|power(#0,const_2)|divide(#4,const_3)|multiply(#2,#5)|divide(#6,#0)|multiply(#7,#3)|divide(#8,#0)|multiply(#10,#9)|
physics
if of house?
speed = 4.5 * 5 / 18 = 1.25 m / sec time taken = 750 / 1.25 = 600 sec ie . 10 mins . answer : c
a ) 5 , b ) 30 , c ) 10 , d ) 12 , e ) 15
c
multiply(divide(divide(750, const_1000), 4.5), const_60)
divide(n1,const_1000)|divide(#0,n0)|multiply(#1,const_60)
physics
if x =
x ^ 2 + 2 x - 24 = ( x + 6 ) ( x - 4 ) = 0 then x = - 6 or x = 4 . x ^ 2 - 5 x + 4 = ( x - 4 ) ( x - 1 ) = 0 then x = 4 or x = 1 . thus x = 4 . the answer is a .
a ) 4 , b ) - 4 , c ) - 3 , d ) - 6 , e ) 1
a
divide(add(4, 24), add(2, 5))
add(n2,n6)|add(n0,n5)|divide(#0,#1)
general
a the sunday is
sol . since the month begins with a sunday , so there will be five sundays in the month . ∴ required average = [ 510 x 5 + 240 x 25 / 30 ] = 8550 / 30 = 285 answer d
a ) 250 , b ) 276 , c ) 280 , d ) 285 , e ) none
d
divide(add(multiply(add(const_4, const_1), 510), multiply(multiply(add(const_4, const_1), add(const_4, const_1)), 240)), 30)
add(const_1,const_4)|multiply(n0,#0)|multiply(#0,#0)|multiply(n1,#2)|add(#1,#3)|divide(#4,n2)
general
a. pony?
pony take 20 hours and horse take 12 hours . . . then distance chased by them is 320 * 12 . so speed of pony is ( 320 * 12 ) / 20 = 192 kmph . answer is b
a ) 182 kmph , b ) 192 kmph , c ) 193 kmph , d ) 196 kmph , e ) 190 kmph
b
divide(multiply(12, 320), add(12, 8))
add(n0,n1)|multiply(n1,n2)|divide(#1,#0)
physics
a0 b.
"ratio of the capitals of a , b and c = 10000 ã — 6 + 5000 ã — 6 : 10000 ã — 6 + 6000 ã — 6 : 10000 ã — 6 + 16000 ã — 6 = 90000 : 96000 : 156000 = 90 : 96 : 156 b â € ™ s share = ( 34200 ã — 96 ⠁ „ 342 ) = 9600 answer a"
a ) 9,600 , b ) 21,200 , c ) 28,200 , d ) 20,500 , e ) none of these
a
divide(add(multiply(subtract(const_12, 6), 4000), multiply(multiply(const_2, multiply(const_100, const_100)), 6)), multiply(const_100, const_10))
multiply(const_100,const_100)|multiply(const_10,const_100)|subtract(const_12,n1)|multiply(n3,#2)|multiply(#0,const_2)|multiply(n1,#4)|add(#3,#5)|divide(#6,#1)|
gain
a. cost?
"let x is the cost of the food 1.07 x is the gross bill after including sales tax 1.15 * 1.10 x = 50 x = 39.52 hence , the correct option is a"
a ) 39.52 $ , b ) 40.63 $ , c ) 41.63 $ , d ) 42.15 $ , e ) 41.15 $
a
divide(50, add(divide(add(10, 15), const_100), const_1))
add(n1,n2)|divide(#0,const_100)|add(#1,const_1)|divide(n0,#2)|
general
an of of :
"explanation : distance = ( 300 x 6 ) = 1800 km . speed = distance / time speed = 1800 / ( 5 / 3 ) km / hr . [ we can write 1 2 / 3 hours as 5 / 3 hours ] required speed = 1800 x 3 / 5 km / hr = 1080 km / hr . answer : option c"
a ) 1008 kmph , b ) 760 kmph , c ) 1080 kmph , d ) 1070 kmph , e ) none
c
divide(divide(multiply(300, 6), add(const_1, divide(const_2, const_3))), const_2)
divide(const_2,const_3)|multiply(n0,n1)|add(#0,const_1)|divide(#1,#2)|divide(#3,const_2)|
physics
what and150?
"surprisingly no one answered this easy one . property of a set of consecutive integerz . mean = median = ( first element + last element ) / 2 = ( second element + last but one element ) / 2 = ( third element + third last element ) / 2 etc . etc . so mean = median = 150 / 2 = 75 answer is d"
a ) 10 , b ) 25 , c ) 50 , d ) 75 , e ) 100
d
divide(150, const_2)
divide(n0,const_2)|
general
two trains is?
"let the speeds of the two trains be x m / sec and y m / sec respectively . then , length of the first train = 27 x meters , and length of the second train = 17 y meters . ( 27 x + 17 y ) / ( x + y ) = 25 = = > 27 x + 17 y = 25 x + 25 y = = > 2 x = 8 y = = > x / y = 4 / 1 . answer : b"
a ) 3 / 1 , b ) 4 / 1 , c ) 3 / 3 , d ) 3 / 5 , e ) 5 / 2
b
divide(subtract(27, 25), subtract(25, 17))
subtract(n0,n2)|subtract(n2,n1)|divide(#0,#1)|
physics
a of x?
"concentration of salt in pure solution = 0 concentration of salt in salt solution = 60 % concentration of salt in the mixed solution = 15 % the pure solution and the salt solution is mixed in the ratio of - - > ( 60 - 15 ) / ( 15 - 0 ) = 3 / 1 1 / x = 3 / 1 x = 1 / 3 answer : b"
a ) 1 / 4 , b ) 1 / 3 , c ) 1 / 2 , d ) 1 , e ) 3
b
divide(15, subtract(60, 15))
subtract(n0,n1)|divide(n1,#0)|
gain
a. highway?
"4 miles on the highway = 4 / 32 gallons ; 4 miles in the city = 4 / 20 gallons ; total = 4 / 32 + 4 / 20 = 13 / 40 gallons . 8 miles on the highway = 8 / 30 gallons . the % change = ( 13 / 40 - 8 / 32 ) / ( 8 / 32 ) = 0.30 . answer : e ."
a ) 15 % , b ) 20 % , c ) 22.5 % , d ) 25 % , e ) 30 %
e
multiply(divide(subtract(add(multiply(divide(const_1, 20), 4), multiply(4, divide(const_1, 32))), multiply(8, divide(const_1, 32))), multiply(8, divide(const_1, 32))), const_100)
divide(const_1,n1)|divide(const_1,n0)|multiply(n2,#0)|multiply(n2,#1)|multiply(n4,#1)|add(#2,#3)|subtract(#5,#4)|divide(#6,#4)|multiply(#7,const_100)|
general
a of profit?
let p be the original price paid by the retailer . 1.25 * p = 100 p = 80 the profit is $ 20 . the answer is c .
a ) $ 10 , b ) $ 16 , c ) $ 20 , d ) $ 24 , e ) $ 25
c
subtract(100, multiply(divide(const_1, add(divide(25, 100), const_1)), 100))
divide(n1,n0)|add(#0,const_1)|divide(const_1,#1)|multiply(n0,#2)|subtract(n0,#3)
gain
24 x?
easy way to solve this question is start from the answer and then conform the information provided in the question . we can start from option d i . e 20 . . . as a quantity of juice p in x because it is the only one option that gets divided by 4 is 20 . . . since in the x the juice p to t ratio is 4 : 1 this gives us that quantity of juice p in x = 20 therefore quantity of juice t will be 5 . . . hence ratio = 4 : 1 this will lead to quantity of juice p in x = 4 and quantity of juice t = 20 . . . hence ratio 1 : 5 if we calculate total juice p = 24 and total of juice v = 25 it fits because totals are same as what mentioned in the question . . . thus ans is d
a ) 5 , b ) 10 , c ) 15 , d ) 20 , e ) 25
d
subtract(24, divide(subtract(multiply(4, 25), 24), subtract(multiply(4, 5), 1)))
multiply(n1,n2)|multiply(n2,n5)|subtract(#0,n0)|subtract(#1,n3)|divide(#2,#3)|subtract(n0,#4)
other
if, correctly?
{ total } = { first correctly } + { second correctly } - { both correctly } + { neither correctly } 100 = 85 + 75 - { both correctly } + 15 { both correctly } = 75 . answer : d .
a ) 60 % , b ) 65 % , c ) 70 % , d ) 75 % , e ) 80 %
d
subtract(add(add(85, 75), 15), const_100)
add(n0,n1)|add(n2,#0)|subtract(#1,const_100)
other
the of class?
"let the number of students in class a be = x 1 + x 2 + . . . . . . + a 1 ( where a 1 = remaining students ) now the remaining avg of the students be a 1 / t = 60 a 1 = 60 t ( we are not sure on the number of students , assuming it as t ) . a = x 1 + x 2 + . . . . . . + a 1 ( first set of students + remaining students ) . one third of a students avg is 60 . a / 3 = 69 = > a = 207 . now x 1 + x 2 + . . . . . . + a 1 = 207 . x 1 + x 2 + . . . . . . = 207 - 60 t . we are not sure about the number of students in the remaining class + whole class and without that we ca n ' t solve this . answer : e is correct option ."
a ) 61 . , b ) 63 . , c ) 65 , d ) 67 , e ) it depends how many people are there in the class .
e
add(multiply(divide(60, const_3), const_2), divide(69, const_3))
divide(n0,const_3)|divide(n1,const_3)|multiply(#1,const_2)|add(#0,#2)|
general
find complete itself?
"4 years answer : d"
a ) 6 years , b ) 9 years , c ) 5 years , d ) 4 years , e ) 6 years
d
floor(add(divide(log(const_2), log(add(const_1, divide(25, const_100)))), const_1))
divide(n0,const_100)|log(const_2)|add(#0,const_1)|log(#2)|divide(#1,#3)|add(#4,const_1)|floor(#5)|
general
m has correctly?
"total number of enrolled students = 29 number of students who did not take test = 5 hence , number of students who took test = 29 - 5 = 24 number of students who answered q 2 correctly = 24 , therefore , all students who took test answered q 2 correctly . so , number of students who answered q 1 correctly , also answered q 2 correctly = 22 . number of students who answered both q 1 & q 2 correctly = 22 . answer : c"
a ) 18 , b ) 19 , c ) 22 , d ) 20 , e ) 19
c
subtract(add(add(24, 22), 5), 29)
add(n1,n3)|add(n5,#0)|subtract(#1,n0)|
other
7 then to?
7 m - 20 = 2 m so , 5 m = 20 so , m + 7 = 11 answer : c
a ) 9 , b ) 10 , c ) 11 , d ) 12 , e ) 13
c
add(divide(20, subtract(7, 2)), 7)
subtract(n0,n2)|divide(n1,#0)|add(n0,#1)
general
which than 16
"66 greater than 16 . answer : b"
a ) 1.6 , b ) 66 , c ) 6 , d ) - 6 , e ) 6.1
b
divide(divide(divide(divide(divide(divide(16, const_4), const_3), const_4), const_3), const_2), const_2)
divide(n0,const_4)|divide(#0,const_3)|divide(#1,const_4)|divide(#2,const_3)|divide(#3,const_2)|divide(#4,const_2)|
general
the n number is
"sol . = ( 2 × 1 + 1 ) = 3 , = ( 2 × 3 + 1 ) = 7 , = ( 2 × 4 + 1 ) = 9 , which is not prime . therefore n = 4 . answer b"
a ) 3 , b ) 4 , c ) 5 , d ) 6 , e ) 7
b
add(2, 2)
add(n0,n0)|
general
two multiples odd?
two hundred multiples of seven will have 100 even and 100 odd numbers 300 multiples of eight will have all even ( being multiple of 8 ) probability of number selected being odd = total odd numbers / total available numbers probability = 100 / 500 = 0.2 = 20 % answer : option a
a ) 20 % , b ) 25 % , c ) 40 % , d ) 50 % , e ) 80 %
a
multiply(divide(100, 500), const_100)
divide(n0,n4)|multiply(#0,const_100)
general
in a city?
"whole trip = distance by foot + distance by bus + distance by car x = 1 / 2 x + 3 / 5 x + 5 x - 1 / 2 x - 3 / 5 x = 5 x = 12 km option : e"
a ) 13 , b ) 17 , c ) 42 , d ) 15 , e ) 12
e
multiply(5, inverse(subtract(1, add(divide(1, 3), divide(1, 4)))))
divide(n0,n1)|divide(n2,n3)|add(#0,#1)|subtract(n0,#2)|inverse(#3)|multiply(n4,#4)|
physics
the its perimeter?
"perimeter of the sector = length of the arc + 2 ( radius ) = ( 108 / 360 * 2 * 22 / 7 * 14 ) + 2 ( 14 ) = 26.4 + 28 = 54.4 cm answer : b"
a ) 52 cm , b ) 54.4 cm , c ) 60 cm , d ) 65 cm , e ) 70 cm
b
multiply(multiply(const_2, divide(multiply(subtract(14, const_3), const_2), add(const_4, const_3))), 14)
add(const_3,const_4)|subtract(n0,const_3)|multiply(#1,const_2)|divide(#2,#0)|multiply(#3,const_2)|multiply(n0,#4)|
physics
tabby her?
( 1 mph + 10 mph ) / 2 = 5.5 mph correct option is : b
a ) 8 mph , b ) 5.5 mph , c ) 3.5 mph , d ) 4 mph , e ) 0.5 mph
b
divide(add(1, 10), const_2)
add(n0,n1)|divide(#0,const_2)
physics
j. x?
"let , p = 400 then j = ( 75 / 100 ) * 400 = 300 also j = ( 80 / 100 ) * t i . e . t = 300 * 100 / 80 = 375 and t = [ 1 - ( x / 100 ) ] * p i . e . 100 - x = 100 * t / p = 100 * 375 / 400 = 93.75 i . e . x = 6.25 answer : option d"
a ) 93.5 , b ) 90 , c ) 6.75 , d ) 6.25 , e ) 2
d
divide(multiply(25, 25), const_100)
multiply(n0,n0)|divide(#0,const_100)|
general
den is combination.
when trying the first time the probability denise does n ' t pick the correct combination = 3999 / 4000 second time , as the total number of possible combinations reduced by one , not picking the right one would be 3998 / 3999 . third time 3997 / 3998 . . . and the same 75 times . so we get : 3999 / 4000 ∗ 3998 / 3999 ∗ . . . ∗ 3925 / 39263999 / 4000 ∗ 3998 / 3999 ∗ . . . ∗ 3925 / 3926 every denominator but the first will cancel out and every nominator but the last will cancel out as well . we ' ll get 3925 / 4000 = 157 / 160 . answer : c .
a ) 1 , b ) 159 / 160 , c ) 157 / 160 , d ) 4 3 / 160 , e ) 0
c
divide(subtract(4000, 75), 4000)
subtract(n0,n1)|divide(#0,n0)
probability
what percentpees?
"12 rupees = 1200 paisa ' s 36 / 1200 × 100 = 3 / 12 12 / 3 = 3 % b"
a ) 2 % , b ) 3 % , c ) 4 % , d ) 5 % , e ) 6 %
b
multiply(divide(36, 12), const_100)
divide(n0,n1)|multiply(#0,const_100)|
gain
in100. ]
"main thing to remember is answer is asked in cents , however when we calculate , it comes up as 0.44 $ just multiply by 100 , answer q = 44 . d"
a ) 0.33 , b ) 0.44 , c ) 0.55 , d ) 44 , e ) 55
d
multiply(divide(divide(8, divide(const_1, const_2)), const_12), multiply(0.33, 100))
divide(const_1,const_2)|multiply(n1,n2)|divide(n0,#0)|divide(#2,const_12)|multiply(#3,#1)|
general
two4 ratio?
sphere volume ( v ) = 4 / 3 π r ( power 3 ) : 4 / 3 π r ( power 3 ) = 4 ( power 3 ) : 3 ( power 3 ) = 64 : 27 answer is d .
['a ) 64 : 13', 'b ) 13 : 64', 'c ) 27 : 64', 'd ) 64 : 27', 'e ) none of them']
d
divide(volume_sphere(4), volume_sphere(3))
volume_sphere(n0)|volume_sphere(n1)|divide(#0,#1)
other
a it direction?
"time taken to cross a moving person = length of train / relative speed time taken = 420 / ( ( 45 - 9 ) ( 5 / 18 ) = 420 / 36 * ( 5 / 18 ) = 420 / 10 = 42 sec answer : b"
a ) 56 sec , b ) 42 sec , c ) 36 sec , d ) 29 sec . , e ) 19 sec .
b
divide(420, subtract(divide(45, const_3_6), divide(divide(9, const_2), const_3_6)))
divide(n1,const_3_6)|divide(n2,const_2)|divide(#1,const_3_6)|subtract(#0,#2)|divide(n0,#3)|
physics
d of box?
"lets suppose length = l , breadth = b , depth = d front face area = l * w = 1 / 2 w * d ( l = 1 / 2 d or d = 2 l ) top face area = w * d side face area = w * d = 1.5 d * l ( w = 1.5 l ) volume = l * w * d = 1536 l * 1.5 l * 2 l = 1536 l = 8 side face area = l * d = l * 2 l = 8 * 2 * 8 = 128 e is the answer"
a ) 34 , b ) 65 , c ) 88 , d ) 90 , e ) 128
e
divide(power(multiply(const_3, power(1536, const_2)), divide(const_1, const_3)), 1.5)
divide(const_1,const_3)|power(n1,const_2)|multiply(#1,const_3)|power(#2,#0)|divide(#3,n0)|
geometry
sum products sum?
"( a + b + c ) 2 = a 2 + b 2 + c 2 + 2 ( ab + bc + ca ) = 276 + 2 * 150 a + b + c = â ˆ š 576 = 24 answer d"
a ) 22 , b ) 18 , c ) 26 , d ) 24 , e ) 32
d
sqrt(add(276, multiply(150, const_2)))
multiply(n2,const_2)|add(n1,#0)|sqrt(#1)|
general
z questions correctly?
i got two equations : 3 x - 2 y = 25 x + y = 14 3 x - 2 ( 14 - x ) = 25 3 x - 28 + 2 x = 25 5 x = 53 x = 10.6 or between 10 and 11 . ( ans e )
a ) 6 , b ) 7 , c ) 8 , d ) 9 , e ) 10
e
divide(add(subtract(multiply(2, subtract(14, 2)), multiply(3, 2)), 31), add(3, 2))
add(n0,n2)|multiply(n0,n2)|subtract(n1,n2)|multiply(n2,#2)|subtract(#3,#1)|add(n3,#4)|divide(#5,#0)
general
b thean?
let the distance travelled be x km . total time = ( x / 2 ) / 40 + ( x / 2 ) / 10 = 15 = > x / 80 + x / 20 = 15 = > ( x + 4 x ) / 80 = 15 = > x = 240 km answer : a
a ) 240 , b ) 230 , c ) 260 , d ) 220 , e ) 340
a
multiply(divide(15, add(divide(multiply(const_2, 40), const_10), divide(multiply(const_2, 10), const_10))), multiply(multiply(divide(multiply(const_2, 40), const_10), divide(multiply(const_2, 10), const_10)), const_10))
multiply(n1,const_2)|multiply(n2,const_2)|divide(#0,const_10)|divide(#1,const_10)|add(#2,#3)|multiply(#2,#3)|divide(n0,#4)|multiply(#5,const_10)|multiply(#6,#7)
physics
in jobs?
fathers without full - time jobs are 1 / 4 * 3 / 5 = 3 / 20 of all the parents surveyed . mothers without full - time jobs are 1 / 8 * 2 / 5 = 1 / 20 of all the parents surveyed . the percent of parents without full - time jobs is 3 / 20 + 1 / 20 = 1 / 5 = 20 % the answer is a .
a ) 20 % , b ) 23 % , c ) 15 % , d ) 18 % , e ) 16 %
a
add(subtract(subtract(const_100, 40), multiply(divide(3, 4), subtract(const_100, 40))), subtract(40, multiply(divide(7, 8), 40)))
divide(n2,n3)|divide(n0,n1)|subtract(const_100,n4)|multiply(#0,#2)|multiply(n4,#1)|subtract(#2,#3)|subtract(n4,#4)|add(#5,#6)
general
three pipes in.
the part of the tank filled by three pipes in one hour = 1 / 8 = > the part of the tank filled by two pipes in 1 hour = 2 / 3 * 1 / 8 = 1 / 12 . the tank can be filled in 12 hours . answer : b
a ) 11 hours , b ) 12 hours , c ) 15 hours , d ) 16 hours , e ) 17 hours
b
inverse(multiply(divide(const_2, const_3), divide(const_1, 8)))
divide(const_2,const_3)|divide(const_1,n0)|multiply(#0,#1)|inverse(#2)
physics
each,55?
"the # of factors 220 has is 12 ; so out of 12 factors only three are multiples of 55 : 55 , 110 and 220 , itself ; so , the probability is 3 / 12 = 1 / 4 . answer : e ."
a ) 1 / 16 , b ) 5 / 42 , c ) 1 / 8 , d ) 3 / 16 , e ) 1 / 4
e
divide(divide(choose(55, const_1), 55), power(const_3, const_2))
choose(n1,const_1)|power(const_3,const_2)|divide(#0,n1)|divide(#2,#1)|
other
john the increase?
"increase = ( 30 / 40 ) * 100 = ( 3 / 4 ) * 100 = 75 % . e"
a ) 16 % , b ) 16.66 % , c ) 76.69 % , d ) 76.98 % , e ) 75 %
e
multiply(divide(subtract(70, 40), 40), const_100)
subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)|
gain
an of cast?
"total number of members = 1260 number of members that cast votes = 525 since , winning candidate received 72 percent of the votes cast number of votes for winning candidate = ( 72 / 100 ) * 525 = 378 percent of total membership that voted for winning candidate = ( 378 / 1260 ) * 100 = 30 % answer c"
a ) 75 % , b ) 58 % , c ) 30 % , d ) 34 % , e ) 25 %
c
multiply(divide(multiply(divide(72, const_100), 525), multiply(const_100, power(const_4, const_2))), const_100)
divide(n2,const_100)|power(const_4,const_2)|multiply(n1,#0)|multiply(#1,const_100)|divide(#2,#3)|multiply(#4,const_100)|
gain
a20?
"let the sale in the sixth month = x then ( 6435 + 6927 + 6855 + 7230 + 6562 + x ) / 6 = 6500 = > 6435 + 6927 + 6855 + 7230 + 6562 + x = 6 × 6500 = > 34009 + x = 39000 = > x = 39000 − 34009 = 4991 answer is c ."
a ) 4551 , b ) 4771 , c ) 4991 , d ) 4881 , e ) 4661
c
subtract(multiply(add(5, const_1), 6500), add(add(add(add(6435, 6927), 6855), 7230), 6562))
add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)|
general
one two number?
"explanation : x / 2 – x / 3 = 4 = > x = 24 2 + 4 = 6 a"
a ) 6 , b ) 9 , c ) 11 , d ) 12 , e ) 15
a
add(reminder(multiply(4, const_4), const_10), const_1)
multiply(n0,const_4)|reminder(#0,const_10)|add(#1,const_1)|
general
calculate m mortar?
explanation : let the number of bricks be ' n ' 10 x 4 / 100 x 6 x 90 / 100 = 25 / 100 x 15 / 100 x 8 / 100 x n 10 x 4 x 6 x 90 = 15 x 2 x n = > n = 720 . answer is a
a ) 720 , b ) 600 , c ) 660 , d ) 6000 , e ) none of these
a
divide(multiply(multiply(multiply(10, divide(4, const_100)), 6), subtract(const_1, divide(10, const_100))), multiply(multiply(divide(25, const_100), divide(15, const_100)), divide(8, const_100)))
divide(n4,const_100)|divide(n3,const_100)|divide(n2,const_100)|divide(n0,const_100)|divide(n1,const_100)|multiply(n3,#0)|multiply(#3,#4)|subtract(const_1,#1)|multiply(n5,#5)|multiply(#2,#6)|multiply(#8,#7)|divide(#10,#9)
physics
if length a?
"let x be the side length of square a . then the area of square a is x ^ 2 . the area of square b is ( 3 x ) ^ 2 = 9 x ^ 2 . the answer is a ."
a ) 9 , b ) 8 , c ) 6 , d ) 3 , e ) 2
a
multiply(const_4, const_4)
multiply(const_4,const_4)|
geometry
thecf other?
hcf x lcm = product of numbers 8 x 48 = 24 x the other number other number = ( 8 x 48 ) / 24 other number = 16 answer : d
a ) 12 , b ) 14 , c ) 15 , d ) 16 , e ) 20
d
divide(multiply(8, 48), 24)
multiply(n0,n1)|divide(#0,n2)
physics
one the conditioned?
the rooms which were not rented is 2 / 5 the ac rooms which were not rented is ( 1 / 3 ) * ( 3 / 5 ) = 1 / 5 the percentage of unrented rooms which were ac rooms is ( 1 / 5 ) / ( 2 / 5 ) = 1 / 2 = 50 % the answer is a .
a ) 50 % , b ) 55 % , c ) 60 % , d ) 65 % , e ) 70 %
a
multiply(divide(multiply(subtract(const_1, divide(2, 3)), multiply(divide(3, 5), const_100)), subtract(const_100, multiply(divide(3, 5), const_100))), const_100)
divide(n0,n1)|divide(n2,n0)|multiply(#0,const_100)|subtract(const_1,#1)|multiply(#2,#3)|subtract(const_100,#2)|divide(#4,#5)|multiply(#6,const_100)
gain
in km hr?
"speed = 144 * 5 / 18 = 40 m / sec time taken = 180 / 40 = 4.5 sec . answer : d"
a ) 2.5 sec , b ) 1.9 sec , c ) 8.9 sec , d ) 4.5 sec , e ) 2.9 sec
d
divide(180, multiply(144, const_0_2778))
multiply(n1,const_0_2778)|divide(n0,#0)|
physics
how a1.
"take the task of building palindromes and break it intostages . stage 1 : select the 7 th digit we can choose 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , or 9 so , we can complete stage 1 in 9 ways stage 2 : select the 6 th digit we can choose 0 , 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , or 9 so , we can complete stage 2 in 10 ways stage 3 : select the 5 th digit we can choose 0 , 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , or 9 so , we can complete stage 3 in 10 ways stage 4 : select the 5 th digit we can choose 0 , 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , or 9 so , we can complete stage 4 in 10 ways important : at this point , the remaining digits are alreadylocked in . stage 5 : select the hundreds digit this digit must be the same as the thousands digit ( which we already chose in stage 2 ) so , we can complete this stage in 1 way . stage 6 : select the tens digit this digit must be the same as the thousands digit ( which we already chose in stage 2 ) so , we can complete this stage in 1 way . stage 7 : select the units digit this digit must be the same as the ten - thousands digit ( which we already chose in stage 1 ) so , we can complete this stage in 1 way . by thefundamental counting principle ( fcp ) , we can complete all 5 stages ( and thus build a 7 - digit palindrome ) in ( 9 ) ( 10 ) ( 10 ) ( 10 ) ( 1 ) ( 1 ) ( 1 ) ways ( = 9000 ways ) answer : d"
a ) 100 , b ) 610 , c ) 729 , d ) 9000 , e ) 1000
d
multiply(multiply(multiply(multiply(7, const_10), const_10), const_10), const_10)
multiply(n0,const_10)|multiply(#0,const_10)|multiply(#1,const_10)|multiply(#2,const_10)|
general
the is salary?
"manager ' s monthly salary = rs . ( 2700 * 26 - 2500 * 25 ) = rs . 7700 answer : a"
a ) rs . 7700 , b ) rs . 3618 , c ) rs . 3600 , d ) rs . 3619 , e ) rs . 3610
a
subtract(multiply(add(2500, 200), add(25, const_1)), multiply(2500, 25))
add(n1,n2)|add(n0,const_1)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2)|
general
the number?
"let consecutive number be x , x + 1 therefore sum of the consecutive number is x + x + 1 = 49 2 x + 1 = 49 2 x = 48 x = 24 therefore larger number is x + 1 = 25 answer : c"
a ) 42 , b ) 43 , c ) 25 , d ) 45 , e ) 46
c
add(add(power(add(add(divide(subtract(subtract(49, const_10), const_2), const_4), const_2), const_2), const_2), power(add(add(add(divide(subtract(subtract(49, const_10), const_2), const_4), const_2), const_2), const_2), const_2)), add(power(divide(subtract(subtract(49, const_10), const_2), const_4), const_2), power(add(divide(subtract(subtract(49, const_10), const_2), const_4), const_2), const_2)))
subtract(n0,const_10)|subtract(#0,const_2)|divide(#1,const_4)|add(#2,const_2)|power(#2,const_2)|add(#3,const_2)|power(#3,const_2)|add(#5,const_2)|add(#4,#6)|power(#5,const_2)|power(#7,const_2)|add(#9,#10)|add(#11,#8)|
physics
we % with?
"let x be the amount of money we started with . 0.7 x = 1400 x = 2000 the answer is a ."
a ) $ 2000 , b ) $ 2100 , c ) $ 2200 , d ) $ 2300 , e ) $ 2400
a
divide(1400, subtract(const_1, divide(30, const_100)))
divide(n1,const_100)|subtract(const_1,#0)|divide(n0,#1)|
gain