Like post/print result with ajax
===

I've created a like button for my users posts. I'm trying to print out the amount of likes. At the moment when I click the LIKE button nothing shows beside the like button unless I refresh the page then it shows the amount of like clicks the post has (4).

The problem I face is I have a LIKE_DO.php page that collects the data then sends it to a function which is in another page called function_user.php. Is there anyway I can use Ajax to grab the printed value of likes and how would I go about it? I would really like to just build ontop of the ajax I already have, to insert the data and make a call for the printed likes to save confusion and having to re-write all my code again. 

Like Button 

    echo "<div class='stream_option'><a id='likecontext_".$streamitem_data['streamitem_id']."' style='cursor:pointer;' onClick=\"likestatus(".$streamitem_data['streamitem_id'].",this.id);\">";

CURRENT AJAX

    function likestatus(postid,contextid){
    var obj = document.getElementById(contextid);
    if(obj.innerHTML=="Like"){
    obj.innerHTML="Unlike";
    }else{
    obj.innerHTML="Like";
    }
    $.post("../include/like_do.php", { streamitem_id: postid} );
    }

LIKE_DO.PHP

    <?php
    session_start();
    require"rawfeeds_load.php";
    if(isset($_POST['streamitem_id'])){
    
    $check = user_core::check_liked($_SESSION['id'],$_POST['streamitem_id'],1);
    
    user_core::do_like($_SESSION['id'],$_POST['streamitem_id'],1);
    if($check==0){?>
    <?php }else{ ?>
    <?php }
    }else{
    echo "<script>alert('Error liking post');</script>";
    }
    ?>

USER_CORE - (With my printed likes that I need to get with ajax)

    	function print_like_count($streamid){
			$check		=	"SELECT feedback_id FROM streamdata_feedback WHERE feedback_streamid='$streamid' AND feedback_rating=1";
			$check1		=	 mysql_query($check);
			$check2		=	 mysql_num_rows($check1);
			if($check2>0){
			return "(".$check2.")";
			}
	}