Bash: Can an array hold the name of another array?
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I am writing a program and trying to break up data, which is stored in an array, in order to make it run faster. 
I am attempting to go about it this way:

        data_to_analyze=(1 2 3 4 5 6 7 8 9 10)
        #original array size
        dataSize=(${#data_to_analyze[@]})
        
        #half of that size
        let samSmall="$dataSize/2"
        
        #the other half
        let samSmall2="$dataSize - $samSmall -1)"
        
        #the first half
        smallArray=("${data_to_analyze[@]:0:$samSmall}")
        
        #the rest
        smallArray2=("${data_to_analyze[@]:$samSmall:$samSmall2}")
        
        #an array of names(which correspond to arrays)
        combArray=($smallArray smallArray2)
        sizeComb=(${#combArray[@]})
        
        #for the length of the new array
        for ((i=0; i<= $sizeComb ; i++)); do
        #through first set of data and then loop back around for the second arrays data? 
        for sample_name in ${combArray[i]}; do
        command
        wait
        command
        wait
        done
What I imagine this does is gives only the first array of data to the for loop at first. When the first array is done it should go through again with the second array set. 

That leaves me with two questions. Is combArray really passing the two smaller arrays? And is there a better way? 