Write LINQ to parse aspx page using HtmlAgilityPack
===

I have looked at the following and similar links on SO and google to parse aspx page using HTMLAgilityPack

http://stackoverflow.com/questions/7758792/parse-html-document-using-htmlagilitypack

But I don't know how to write LINQ statement such that I could identify Button and Label Control Names in my aspx page. 

Here is my aspx page.

    <%@ Page Language="C#" AutoEventWireup="true" CodeBehind="WebForm4.aspx.cs" Inherits="WebApplication1.WebForm4" %>
    
    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
    
    <html xmlns="http://www.w3.org/1999/xhtml">
    <head runat="server">
        <title></title>
    </head>
    <body>
        <form id="form1" runat="server">
        <div>
        
                <asp:Button ID="Button1" runat="server" Text="Button on page4" />
            <br />
            <br />
            <asp:Label ID="Label1" runat="server" Text="Label on page 4"></asp:Label>
            <br />
                        <br />
            <asp:Button ID="Button2" runat="server" Text="second button page 4" />
            
                            <br />
            <asp:Button ID="Button3" runat="server" Text="second button page 4" />
    
    
    
        </div>
        </form>
    </body>
    </html>


I want to write LINQ using HTML Agility pack such that I could list the following output:

**Controls on this page are Button1, Label1, Button2, Button3**

I am having trouble writing LINQ for parsing the aspx page. Please help. 

Here is what I have written so far and its not working. 

       HtmlAgilityPack.HtmlDocument htmlDoc = new HtmlAgilityPack.HtmlDocument();

        htmlDoc.OptionFixNestedTags = true;

        string filePath = @"C:\WebApplication1\webform4.aspx";


        htmlDoc.Load(filePath);

        var ItemsAndPrices = new Dictionary<string, string>();

        var findItemPrices = from links in htmlDoc.DocumentNode.Descendants("div")
                             select links;

