HTML page not getting value from data base using php scrip
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I am getting data from mysql data base using php script problem is that in table there is data but when i fetch returen NO only

it shows following error 


    Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/content/i/h/u/ihus235/html/cs/emrapp/surveyDescription.php on line 73
[]


HTML CODE



      <html<body>
       <INPUT TYPE = "Text" VALUE ="user_id" NAME = "user_id"> This form allows you to connect to the server.<br>
       <form action="surveyDescription.php" method="post" enctype="multipart/form-data"><br>

       Type (or select) Filename: 
        <input type="submit" value="submit">
        </html>



PHP CODE


       <?php 
       $host = "surveyipad.db.6420177.hostedresource.com"; 
       $user = "surveyipad"; 
       $pass = "Jackson12"; 
       $database = "surveyipad"; 

       $linkID = mysql_connect($host, $user, $pass) or die("Could not connect to host."); 
mysql_select_db($database, $linkID) or die("Could not find database."); 

      if (!function_exists('json_encode'))
      {
       function json_encode($a=false)
      {
      if (is_null($a)) return 'null';
      if ($a === false) return 'false';
      if ($a === true) return 'true';
      if (is_scalar($a))
       {
        if (is_float($a))
        {
        // Always use "." for floats.
        return floatval(str_replace(",", ".", strval($a)));
        }

        if (is_string($a))
        {
        static $jsonReplaces = array(array("\\", "/", "\n", "\t", "\r", "\b", "\f", '"'), array('\\\\', '\\/', '\\n', '\\t', '\\r', '\\b', '\\f', '\"'));
        return '"' . str_replace($jsonReplaces[0], $jsonReplaces[1], $a) . '"';
        }
        else
        return $a;
        }
        $isList = true;
        for ($i = 0, reset($a); $i < count($a); $i++, next($a))
        {
        if (key($a) !== $i)
        {
         $isList = false;
         break;
         }
         }
         $result = array();
         if ($isList)
         {
         foreach ($a as $v) $result[] = json_encode($v);
         return '[' . join(',', $result) . ']';
         }
         else
         {
         foreach ($a as $k => $v) $result[] = json_encode($k).':'.json_encode($v);
         return '{' . join(',', $result) . '}';
         }
         }
         }



       $user_id=$_POST['user_id'];
       $query = mysql_query("SELECT s.*, u.user_id FROM survey_master AS s
JOIN user_profile AS u on u.user_id = s.user_id where s.user_id=$user_id");

       $rows = array();
     while($row = mysql_fetch_assoc($query)) {
     $rows[] = $row;
     }
    echo json_encode($rows);

      ?> 

   

    




