WMIC - bat file menu program
===

I'm trying to write a batch file that will uninstall programs by selecting a number. I don't know how to count how many programs in the operating system and then to assign numbers to all of them in a MENU format. I don't want to have to type in all of the letters to a program.  

Copy and past the below program into notepad and save as GUninstall.bat




    @Echo off
    Echo This is a batch file uninstallation program. 
    Echo Run as administrator WMIC will not work. 
    echo.
    Echo The command [wmic product get name] will run.
    Echo Looking up all installed programs...
    echo. 
    wmic product get name

    echo 1. First program
    echo 2. Second program
    echo 3. Third program
    echo 4. Fourth program
    echo 5. Fifth program
    echo.
    @echo Pick a number: 
    echo. 
    choice /c:12345 

    if "%errorlevel%"=="1" wmic product where name="First program" call uninstall
    if "%errorlevel%"=="2" wmic product where name="Second program" call uninstall
    if "%errorlevel%"=="3" wmic product where name="Third program" call uninstall
    if "%errorlevel%"=="4" wmic product where name="Fourth program" call uninstall
    if "%errorlevel%"=="5" wmic product where name="Fifth program" call uninstall

    Echo.
    Echo.

    @echo First method is done. I'll go into the alternate method. 

    pause
    Echo Get user input - program name?
    Echo.
    Echo This is an alternate method 
    :input
    set INPUT=
    set /P INPUT=Uninstall which program?: %=%
    if "%INPUT%"=="" goto input
    echo Your input was: %INPUT%

    echo.
    echo.
    Echo Uninstalling... 

    echo The command [wmic product where name="%INPUT%" call uninstall] will run. 


    wmic product where name="%INPUT%" call uninstall

    @echo If there is "no instance" errors, then the program %INPUT% was uninstalled.

    pause