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ericsun153
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mathqa_shuffle_question_test

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Rationale
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the ratio of 2 numbers is 2 : 3 and their h . c . f . is 10 . their l . c . m . is ?
"explanation : age of the 18 th student = [ 18 * 18 - ( 14 * 5 + 16 * 9 ) ] = ( 324 - 214 ) = 110 years . answer : c"
a ) 101 , b ) 66 , c ) 110 , d ) 160 , e ) 12
c
subtract(multiply(18, 18), add(multiply(5, 14), multiply(9, 16)))
multiply(n0,n0)|multiply(n2,n3)|multiply(n4,n5)|add(#1,#2)|subtract(#0,#3)|
general
in township k each property is taxed at 12 percent of its assessed value . if the assessed value of a property in township k is increased from $ 20,000 to $ 24,000 , by how much will the property tax increase ?
"sol . 15 % of rs . 34 = rs . ( 15 / 100 x 34 ) = rs . 5.10 answer d"
a ) rs . 3.40 , b ) rs . 3.75 , c ) rs . 4.50 , d ) rs . 5.10 , e ) none
d
divide(multiply(15, add(add(multiply(multiply(add(const_3, const_2), const_2), multiply(multiply(const_3, const_4), const_100)), multiply(multiply(add(const_3, const_4), add(const_3, const_2)), multiply(add(const_3, const_2), const_2))), add(const_3, const_3))), const_100)
add(const_2,const_3)|add(const_3,const_4)|add(const_3,const_3)|multiply(const_3,const_4)|multiply(#0,const_2)|multiply(#3,const_100)|multiply(#1,#0)|multiply(#4,#5)|multiply(#6,#4)|add(#7,#8)|add(#9,#2)|multiply(n0,#10)|divide(#11,const_100)|
gain
an item is being sold for $ 10 each . however , if a customer will “ buy at least 3 ” they have a promo discount of 30 % . also , if a customer will “ buy at least 10 ” items they will deduct an additional 8 % to their “ buy at least 3 ” promo price . if sam buys 10 pcs of that item how much should he pay ?
"d = ( d - r ) / q = ( 123 - 4 ) / 7 = 119 / 7 = 17 c"
a ) 15 , b ) 16 , c ) 17 , d ) 18 , e ) 19
c
floor(divide(123, 7))
divide(n0,n1)|floor(#0)|
general
a train covers a distance of 11 km in 10 min . if it takes 6 sec to pass a telegraph post , then the length of the train is ?
solution : 1 st method : let the original price of tea be rs . x / kg . after reduction the price becomes = x - 10 % of x = 9 x / 10 per kg . now , ( 22500 / ( 9 x / 10 ) ) - 22500 / x = 25 or , 22500 [ 10 / 9 x - 1 / x ] = 25 or , 25 * 9 x = 22500 ; or , x = ( 22500 / 2589 ) = rs . 100 . hence , new price = 90 per kg . thought process method : let the original price be rs . 100 per kg , he get tea = 22500 / 100 = 225 kg . after reduction the price becomes = 90 per kg , he get tea = 22500 / 90 = 250 kg . so , reduction price is rs . 90 per kg as it enables him to buy 25 kg of more tea . answer : option c
a ) rs . 70 , b ) rs . 80 , c ) rs . 90 , d ) rs . 100 , e ) none
c
divide(divide(multiply(22500, subtract(divide(const_100, subtract(const_100, 10)), const_1)), 25), divide(const_100, subtract(const_100, 10)))
subtract(const_100,n0)|divide(const_100,#0)|subtract(#1,const_1)|multiply(n2,#2)|divide(#3,n1)|divide(#4,#1)
gain
if an article is sold at 18 % profit instead of 9 % profit , then the profit would be $ 54 more . what is the cost price ?
"answer : 180 degree answer : e"
a ) 120 ° , b ) 135 ° , c ) 125 ° , d ) 150 ° , e ) 180 °
e
subtract(multiply(multiply(multiply(const_60, 12), const_2), divide(30, const_60)), multiply(divide(divide(multiply(multiply(const_60, 12), const_2), 12), const_4), add(divide(30, const_60), 12)))
divide(n1,const_60)|multiply(n0,const_60)|add(n0,#0)|multiply(#1,const_2)|divide(#3,n0)|multiply(#0,#3)|divide(#4,const_4)|multiply(#2,#6)|subtract(#5,#7)|
physics
what is the max number of rectangular boxes , each measuring 4 inches by 6 inches by 10 inches , that can be packed into a rectangular packing box measuring 16 inches by 18 inches by 30 inches , if all boxes are aligned in the same direction ?
"solution given expression = 896.7 - ( 573.07 + 95.007 ) = 896.7 - 668.077 = 228.623 . answer a"
a ) 228.623 , b ) 224.777 , c ) 233.523 , d ) 414.637 , e ) none of these
a
subtract(896.7, divide(573.07, 95.007))
divide(n1,n2)|subtract(n0,#0)|
general
find large number from below question the difference of two numbers is 1365 . on dividing the larger number by the smaller , we get 6 as quotient and the 15 as remainder
"the dollars earned will be in the same ratio as amount of work done 1 day work of c is 1 / 12 ( or 2 / 24 ) 1 day work of the combined workforce is ( 1 / 6 + 1 / 8 + 1 / 12 ) = 9 / 24 c ' s contribution is 2 / 9 of the combined effort translating effort to $ = 2 / 9 * 2200 = $ 488.9 hence : a"
a ) $ 488.9 , b ) $ 480.9 , c ) $ 588.9 , d ) $ 680.9 , e ) $ 788.9
a
multiply(2200, divide(inverse(8), add(inverse(12), add(inverse(6), inverse(8)))))
inverse(n1)|inverse(n0)|inverse(n2)|add(#1,#0)|add(#3,#2)|divide(#0,#4)|multiply(n3,#5)|
physics
3 men and 7 women can complete a work in 10 days . but 4 men and 6 women need 8 days to complete the same work . in how many days will 10 women complete the same work ?
"1 / ( 1 / 36 + 1 / 45 ) = 180 / 9 = 20 hrs answer : a"
a ) 20 hrs , b ) 22 hrs , c ) 23 hrs , d ) 24 hrs , e ) 21 hrs
a
divide(const_1, add(divide(const_1, 36), divide(const_1, 45)))
divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|divide(const_1,#2)|
physics
what quantity of water should be added to reduce 20 liters of 80 % acidic liquid to 20 % acidic liquid ?
"let p be the number of progressives in the country as a whole . in each province , the number of traditionalists is p / 18 the total number of traditionalists is 6 p / 18 = p / 3 . the total population is p + p / 3 = 4 p / 3 p / ( 4 p / 3 ) = 3 / 4 the answer is e ."
a ) 1 / 5 , b ) 1 / 3 , c ) 1 / 2 , d ) 2 / 3 , e ) 3 / 4
e
subtract(1, divide(divide(6, 18), add(divide(6, 18), 1)))
divide(n0,n2)|add(n1,#0)|divide(#0,#1)|subtract(n1,#2)|
general
the cost of 2 chairs and 3 tables is rs . 1500 . the cost of 3 chairs and 2 tables is rs . 1200 . the cost of each table is more than that of each chair by ?
"m = 6.5 s = 1.5 ds = 8 us = 4 as = ( 2 * 8 * 4 ) / 12 = 5.33 answer : a"
a ) 5.33 kmph , b ) 6.00 kmph , c ) 5.00 kmph , d ) 6.00 kmph , e ) 4.00 kmph
a
divide(add(6.5, subtract(6.5, 1.5)), const_2)
subtract(n0,n1)|add(n0,#0)|divide(#1,const_2)|
general
an article with cost price of 245 is sold at 34 % profit . what is the selling price ?
"to obtain rs . 10 , investment = rs . 210 . to obtain rs . 1250 , investment = = rs . 26250 . answer : b"
a ) 5363 , b ) 26250 , c ) 28678 , d ) 29002 , e ) 2732
b
multiply(divide(210, 10), 1250)
divide(n2,n1)|multiply(n0,#0)|
gain
suzie ’ s discount footwear sells all pairs of shoes for one price and all pairs of boots for another price . on monday the store sold 22 pairs of shoes and 16 pairs of boots for $ 540 . on tuesday the store sold 8 pairs of shoes and 32 pairs of boots for $ 720 . how much more do pairs of boots cost than pairs of shoes at suzie ’ s discount footwear ?
"solution area of the floor = ( 5.5 x 3.75 ) m ² = 20.635 m ² cost of paying = rs . ( 400 x 20.625 ) = rs . 8,250 . answer b"
a ) rs . 15,000 , b ) rs . 8,250 , c ) rs . 15,600 , d ) rs . 16,500 , e ) none
b
multiply(400, multiply(5.5, 3.75))
multiply(n0,n1)|multiply(n2,#0)|
physics
rs . 850 becomes rs . 956 in 3 years at a certain rate of simple interest . if the rate of interest is increased by 4 % , what amount will rs . 850 become in 3 years ?
"solution sum of decimals places = ( 2 + 2 ) = 4 . therefore , = 2.68 × . 74 = 1.9632 answer a"
a ) 1.9632 , b ) 1.0025 , c ) 1.5693 , d ) 1.0266 , e ) none
a
multiply(divide(268, const_100), divide(74, const_100))
divide(n0,const_100)|divide(n1,const_100)|multiply(#0,#1)|
general
a factory that employs 1000 assembly line workers pays each of these workers $ 5 per hour for the first 40 hours worked during a week and 1 ½ times that rate for hours worked in excess of 40 . what was the total payroll for the assembly - line workers for a week in which 30 percent of them worked 15 hours , 50 percent worked 40 hours , and the rest worked 50 hours ?
xc 1 * ( x - 1 ) c 1 = 56 x ^ 2 - x - 56 = 0 ( x - 8 ) ( x + 7 ) = 0 x = 8 , - 7 - 7 ca n ' t possible . hence 8 should be the answer b
a ) 7 , b ) 8 , c ) 9 , d ) 10 , e ) 11
b
divide(add(const_1, sqrt(add(multiply(const_4, 56), power(negate(const_1), const_2)))), const_2)
multiply(n0,const_4)|negate(const_1)|power(#1,const_2)|add(#0,#2)|sqrt(#3)|add(#4,const_1)|divide(#5,const_2)
other
the original price of a suit is $ 100 . the price increased 20 % , and after this increase , the store published a 20 % off coupon for a one - day sale . given that the consumers who used the coupon on sale day were getting 20 % off the increased price , how much did these consumers pay for the suit ?
( x - 26,800 ) / 11 - x / 12 = 1,200 x = 480,000 x / 12 = 40,000 answer : c .
a ) $ 29000 , b ) $ 33500 , c ) $ 40000 , d ) $ 41000 , e ) $ 42300
c
add(26800, multiply(const_12, 1200))
multiply(n1,const_12)|add(n0,#0)
general
the cost price of a radio is rs . 1500 and it was sold for rs . 1230 , find the loss % ?
let , total work unit = 160 units a can finish in 16 days = 160 unit work i . e . a can finish in 1 days = 10 unit work i . e . b can finish in 1 days = 10 + ( 60 / 100 ) * 10 = 16 unit work days in which b will complete the work alone = 160 / 16 = 10 days answer : option e
a ) 6 , b ) 6.25 , c ) 7 , d ) 7.5 , e ) 10
e
divide(multiply(16, 60), const_100)
multiply(n0,n1)|divide(#0,const_100)
gain
of the 14,210 employees of the anvil factory , 3 / 7 are journeymen . if half of the journeymen were laid off , what percentage of the total remaining employees would be journeymen ?
"total number of fruits shopkeeper bought = 600 + 400 = 1000 number of rotten oranges = 15 % of 600 = 15 / 100 × 600 = 9000 / 100 = 90 number of rotten bananas = 7 % of 400 = 28 therefore , total number of rotten fruits = 90 + 28 = 118 therefore number of fruits in good condition = 1000 - 118 = 882 therefore percentage of fruits in good condition = ( 882 / 1000 × 100 ) % = ( 88200 / 1000 ) % = 88.2 % answer : b"
a ) 92.5 % , b ) 88.2 % , c ) 85.2 % , d ) 96.8 % , e ) 78.9 %
b
multiply(divide(subtract(add(600, 400), add(multiply(600, divide(15, const_100)), multiply(400, divide(7, const_100)))), add(600, 400)), const_100)
add(n0,n1)|divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#1)|multiply(n1,#2)|add(#3,#4)|subtract(#0,#5)|divide(#6,#0)|multiply(#7,const_100)|
gain
5359 x 51 = ?
"let the money sandy took for shopping be x . 0.7 x = 231 x = 330 the answer is d ."
a ) $ 270 , b ) $ 290 , c ) $ 310 , d ) $ 330 , e ) $ 350
d
divide(231, divide(subtract(const_100, 30), const_100))
subtract(const_100,n1)|divide(#0,const_100)|divide(n0,#1)|
gain
the average age of 15 students of a class is 16 years . out of these , the average age of 5 students is 14 years and that of the other 9 students is 16 years . the age of the 15 th student is ?
"3 pumps take 16 hrs total ( 8 hrs a day ) if 1 pump will be working then , it will need 16 * 3 = 48 hrs 1 pump need 48 hrs if i contribute 12 pumps then 48 / 12 = 4 hrs . answer : a"
a ) 4 , b ) 10 , c ) 11 , d ) 12 , e ) 13
a
divide(multiply(multiply(3, 8), 2), 12)
multiply(n0,n1)|multiply(n2,#0)|divide(#1,n3)|
physics
find the value of ( 20 c 18 ) * ( 20 c 20 )
"let the price of tea and coffee be x per kg in june . price of tea in july = 1.2 x price of coffee in july = 0.8 x . in july the price of 1 / 2 kg ( 700 gm ) of tea and 1 / 2 kg ( 700 gm ) of coffee ( equal quantities ) = 70 1.2 x ( 1 / 2 ) + 0.8 x ( 1 / 2 ) = 70 = > x = 70 thus proved . . . option a ."
a ) 70 , b ) 60 , c ) 80 , d ) 100 , e ) 120
a
divide(70, multiply(subtract(const_1, divide(20, const_100)), add(divide(20, const_100), const_1)))
divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|divide(n2,#4)|
general
a train 300 m long is running at a speed of 45 km / hr . in what time will it pass a bridge 150 m long ?
let the amounts be x , y , z in ascending order of value . as the interest rate and interest accrued are same for 2 years 6 years and 11 years i . e . 2 x = 6 y = 11 z = k . l . c . m . of 2 , 611 = 66 so x : y : z : = 33000 : 11000 : 6000 the amount deposited for 11 years = 6000 answer : e
a ) 6500 , b ) 2000 , c ) 4500 , d ) 3000 , e ) 6000
e
multiply(multiply(6, const_10), const_100)
multiply(n2,const_10)|multiply(#0,const_100)
general
in an examination , the percentage of students qualified to the students appeared from school ' p ' is 70 % . in school ' q ' , the number of students appeared is 30 % more than the students appeared from school ' p ' and the number of students qualified from school ' q ' is 50 % more than the students qualified from school ' p ' . what is the % of students qualified to the number of students appeared from school ' q ' ?
"in 100 consecutive numbers , number of multiples of 5 = 100 / 5 = 20 ( ignore decimals ) in 100 consecutive numbers , number of multiples of 6 = 100 / 6 = 16 number of multiples of 5 * 6 i . e . 30 = 100 / 30 = 3 number of integers from 1 to 100 that are divisible by neither 5 nor by 6 = 100 - ( 29 + 16 - 3 ) { using the concept of sets here ) = 58 answer is c"
a ) 35 , b ) 47 , c ) 58 , d ) 26 , e ) 34
c
subtract(100, subtract(add(divide(100, 5), divide(100, 6)), divide(100, multiply(5, 6))))
divide(n1,n2)|divide(n1,n3)|multiply(n2,n3)|add(#0,#1)|divide(n1,#2)|subtract(#3,#4)|subtract(n1,#5)|
other
on a sum of money , the simple interest for 2 years is rs . 324 , while the compound interest is rs . 340 , the rate of interest being the same in both the cases . the rate of interest is
looking at the ratio we can take total number of people = 20 . . ans 5 / 20 or 25 % c
a ) 50 % , b ) 40 % , c ) 25 % , d ) 20 % , e ) 10 %
c
multiply(divide(subtract(multiply(2, divide(add(3, 1), add(3, 2))), subtract(3, multiply(3, divide(add(3, 1), add(3, 2))))), add(3, 1)), const_100)
add(n0,n1)|add(n0,n3)|divide(#0,#1)|multiply(n3,#2)|multiply(n0,#2)|subtract(n0,#4)|subtract(#3,#5)|divide(#6,#0)|multiply(#7,const_100)
general
if x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year , the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $ 38 . if $ 2,000 is the total amount invested , how much is invested at 8 percent ?
"answer is c . x / x + 36 = 1 / 5 x = 9 16 - 9 = 7"
a ) 3 , b ) 6 , c ) 7 , d ) 7.8 , e ) 9
c
multiply(divide(20, const_100), 20)
divide(n2,const_100)|multiply(n2,#0)|
gain
what least number should be added to 1022 , so that the sum is completely divisible by 25 ?
total age of 20 men = 15.6 x 20 = 312 now , total age of 25 men = 364 . total age of five men added later = 364 - 312 = 52 . hence , the total average of five men = 52 / 5 = 10.4 answer : d
a ) 15.5 , b ) 15.4 , c ) 15.25 , d ) 10.4 , e ) 15.6
d
divide(subtract(multiply(add(20, 5), 14.56), multiply(20, 15.6)), 5)
add(n0,n2)|multiply(n0,n1)|multiply(n3,#0)|subtract(#2,#1)|divide(#3,n2)
general
a is 30 % more efficient than b . how much time they will working together take to complete a job which a alone could have done in 23 days ?
"let the numbers be x , x + 1 and x + 2 x 2 + ( x + 1 ) 2 + ( x + 2 ) 2 = 2030 3 x 2 + 6 x - 2025 = 0 ( x + 27 ) ( x - 25 ) = 0 x = 25 the middle number is 26 answer b 26"
a ) 25 , b ) 26 , c ) 27 , d ) 28 , e ) 29
b
divide(subtract(sqrt(add(multiply(subtract(2030, const_1), const_4), const_1)), const_1), const_2)
subtract(n0,const_1)|multiply(#0,const_4)|add(#1,const_1)|sqrt(#2)|subtract(#3,const_1)|divide(#4,const_2)|
physics
if ( 4 - x ) / ( 5 + x ) = x , what is the value of x ^ 2 + 6 x - 4 ?
"d = 130 m + 120 m = 250 m * 1 / 1000 = 0.25 kms rs = 60 + 60 = 120 kmph t = ( 0.25 / 120 ) * 3600 = 7.5 sec answer : e"
a ) 6.9 sec , b ) 7.1 sec , c ) 7.2 sec , d ) 7.4 sec , e ) 7.5 sec
e
divide(add(60, 60), multiply(add(130, 130), const_0_2778))
add(n0,n0)|add(n1,n1)|multiply(#1,const_0_2778)|divide(#0,#2)|
physics
50 percent of the members of a study group are women , and 30 percent of those women are lawyers . if one member of the study group is to be selected at random , what is the probability that the member selected is a woman lawyer ?
"explanation : increase in the population in 10 years = 2 , 62,500 - 1 , 75,000 = 87500 % ncrease in the population in 10 years = ( 87500 / 175000 ) × 100 = 8750 / 175 = 50 % average % increase of population per year = 50 % / 10 = 5 % answer : option c"
a ) 4 % , b ) 6 % , c ) 5 % , d ) 50 % , e ) none of these
c
add(multiply(divide(subtract(divide(subtract(subtract(subtract(multiply(multiply(const_10, const_1000), const_10), const_1000), const_1000), multiply(add(2, const_3), const_100)), multiply(add(multiply(add(const_3, const_4), const_10), add(2, const_3)), const_1000)), 1), const_10), const_100), const_4)
add(n2,const_3)|add(const_3,const_4)|multiply(const_10,const_1000)|multiply(#2,const_10)|multiply(#0,const_100)|multiply(#1,const_10)|add(#0,#5)|subtract(#3,const_1000)|multiply(#6,const_1000)|subtract(#7,const_1000)|subtract(#9,#4)|divide(#10,#8)|subtract(#11,n0)|divide(#12,const_10)|multiply(#13,const_100)|add(#14,const_4)|
general
what is the smallest positive integer x , such that 1,152 x is a perfect cube ?
"age of the 15 th student = [ 15 * 15 - ( 14 * 5 + 16 * 9 ) ] = ( 225 - 214 ) = 11 years . answer : a"
a ) 11 years , b ) 17 years , c ) 67 years , d ) 14 years , e ) 12 years
a
subtract(multiply(15, 15), add(multiply(5, 14), multiply(9, 16)))
multiply(n0,n0)|multiply(n2,n3)|multiply(n4,n5)|add(#1,#2)|subtract(#0,#3)|
general
the area of a parallelogram is 72 sq m and its altitude is twice the corresponding base . then the length of the base is ?
458 - 435 = 23 . answer is c .
a ) 9 , b ) 17 , c ) 23 , d ) 45 , e ) 12
c
subtract(458, 435)
subtract(n1,n0)
physics
what least value must be given to * so that the number 451 * 603 is exactly divisible by 9 ?
"b 5 1 / 4 â € “ 1 / 20 = 1 / 5 = > 5"
a ) 11 , b ) 5 , c ) 6 , d ) 8 , e ) 25
b
add(inverse(subtract(divide(const_1, 4), divide(const_1, 20))), divide(const_2, add(const_2, const_3)))
add(const_2,const_3)|divide(const_1,n0)|divide(const_1,n1)|divide(const_2,#0)|subtract(#1,#2)|inverse(#4)|add(#3,#5)|
physics
a certain lab experiments with white and brown mice only . in one experiment , 2 / 3 of the mice are white . if there are 15 brown mice in the experiment , how many mice in total are in the experiment ?
let x be the value of the item . 0.07 * ( x - 1000 ) = 109.90 x = 2570 the answer is d .
a ) $ 1940 , b ) $ 2150 , c ) $ 2360 , d ) $ 2570 , e ) $ 2780
d
add(1000, divide(109.9, divide(7, const_100)))
divide(n0,const_100)|divide(n2,#0)|add(n1,#1)
general
a special municipal payroll tax charges not tax on a payroll less than $ 200,000 and only 0.2 % on a company ’ s payroll above $ 200,000 . if belfried industries paid $ 200 in this special municipal payroll tax , then they must have had a payroll of ?
"speed = 54 * 5 / 18 = 15 m / sec . length of the train = 15 * 20 = 300 m . let the length of the platform be x m . then , ( x + 300 ) / 34 = 15 = > x = 210 m . answer : e"
a ) 228 , b ) 240 , c ) 887 , d ) 166 , e ) 210
e
multiply(20, multiply(54, const_0_2778))
multiply(n2,const_0_2778)|multiply(n1,#0)|
physics
a hiker walked for 3 days . she walked 18 miles on the first day , walking 3 miles per hour . on the second day she walked for one less hour but she walked one mile per hour , faster than on the first day . on the third day she walked at 7 miles per hour for 2 hours . how many miles in total did she walk ?
diameter = 11 meter . radius = diameter / 2 . = 11 / 2 . = 5.5 meter . area of a circle = ï € r 2 . here , pi ( ï € ) = 3.14 meter , radius ( r ) = 5.5 . area of a circle = 3.14 ã — 5.5 ã — 5.5 . . = 3.14 ã — 30.25 . = 95.07 square meter answer : b
['a ) 113.00 square meter', 'b ) 95.07 square meter', 'c ) 93.08 square meter', 'd ) 93.24 square meter', 'e ) 113.43 square meter']
b
circle_area(divide(11, const_2))
divide(n0,const_2)|circle_area(#0)
physics
at a wedding reception , 125 guests ate chicken and 75 guests ate beef . if exactly 100 guests ate only one of the two types of meat , how many guests ate both types of meat ?
when positive integer n is divided by 3 , the remainder is 1 i . e . , n = 3 x + 1 values of n can be one of { 1 , 4 , 7 , 10 , 13 , 16 , 19 , 22 . . . . . . . . . . . . . . 49 , 52 , 59 . . . . . . . . . . . . . . . . . . } similarly , when n is divided by 5 , the remainder is 5 . . i . e . , n = 5 y + 4 values of n can be one of { 4 , 9 , 14 , 19 , . . . } combining both the sets we get n = { 4,19 , 52 , . . . . . . . . . . . } what is the smallest positive integer p , such that ( n + p ) is a multiple of 11 or 11 x in case of n = 4 p = 7 so for min value of p , we take min value of n . d is the answer .
a ) 1 , b ) 2 , c ) 5 , d ) 7 , e ) 20
d
subtract(11, reminder(4, 5))
reminder(n3,n2)|subtract(n4,#0)
general
on a certain transatlantic crossing , 40 percent of a ship ’ s passengers held round - trip tickets and also took their cars abroad the ship . if 20 percent of the passengers with round - trip tickets did not take their cars abroad the ship , what percent of the ship ’ s passengers held round - trip tickets ?
"6300 : 4200 : 10500 3 : 2 : 5 3 / 10 * 12400 = 3720 . answer : c"
a ) 3630 , b ) 2881 , c ) 3720 , d ) 9977 , e ) 2212
c
multiply(divide(6300, add(add(6300, 4200), 10500)), 12400)
add(n0,n1)|add(n2,#0)|divide(n0,#1)|multiply(n3,#2)|
gain
john had a stock of 1000 books in his bookshop . he sold 75 on monday , 50 on tuesday , 64 on wednesday , 78 on thursday and 135 on friday . what percentage of the books were not sold ?
sol . speed of the first train = [ 100 / 10 ] m / sec = 10 m / sec . speed of the second train = [ 100 / 15 ] m / sec = 6.7 m / sec . relative speed = ( 10 + 6.7 ) = m / sec = 16.7 m / sec . ∴ required time = ( 100 + 100 ) / 16.7 secc = 11.9 sec . answer b
a ) 12 , b ) 11.9 , c ) 16 , d ) 20 , e ) 18
b
divide(add(100, 100), add(divide(100, 15), divide(100, 10)))
add(n2,n2)|divide(n2,n1)|divide(n2,n0)|add(#1,#2)|divide(#0,#3)
physics
in the class of 50 students , 30 speak tamil and 40 speak telugu . what is the lowest possible number of students who speak both the languages ?
"40 % of ( x - y ) = 20 % of ( x + y ) 40 / 100 ( x - y ) = 20 / 100 ( x + y ) x = 3 y required percentage = y / x * 100 = y / 3 y * 100 = 33.3 % answer is d"
a ) 50.5 % , b ) 44.4 % , c ) 22.2 % , d ) 33.3 % , e ) 25 %
d
multiply(divide(subtract(40, 20), add(40, 20)), const_100)
add(n0,n1)|subtract(n0,n1)|divide(#1,#0)|multiply(#2,const_100)|
general
speed of a boat in standing water is 10 kmph and speed of the stream is 2.5 kmph . a man can rows to a place at a distance of 105 km and comes back to the starting point . the total time taken by him is ?
"to reach the winning post a will have to cover a distance of ( 500 - 170 ) m , i . e . , 330 m . while a covers 3 m , b covers 4 m . while a covers 330 m , b covers 4 x 330 / 3 m = 440 m . thus , when a reaches the winning post , b covers 440 m and therefore remains 60 m behind . a wins by 60 m . answer : a"
a ) 60 m , b ) 20 m , c ) 43 m , d ) 20 m , e ) 23 m
a
subtract(500, divide(multiply(subtract(500, 170), 4), 3))
subtract(n0,n3)|multiply(n2,#0)|divide(#1,n1)|subtract(n0,#2)|
physics
shruti purchased several number of 3 articles p , q and r in the proportion 3 : 2 : 3 . if the unit costs of the articles p , q and r are 200 , rs . 90 and rs . 60 respectively , how many articles of q must have been purchased in the total purchases of rs . 4800 ?
p ( club ) = 1 / 4 p ( red king ) = 1 / 26 p ( club then a red king ) = 1 / 4 * 1 / 26 = 1 / 104 the answer is e .
a ) 1 / 13 , b ) 1 / 15 , c ) 1 / 26 , d ) 1 / 52 , e ) 1 / 104
e
multiply(divide(add(multiply(const_3, const_4), const_1), const_52), divide(const_2, const_52))
divide(const_2,const_52)|multiply(const_3,const_4)|add(#1,const_1)|divide(#2,const_52)|multiply(#3,#0)
probability
two carpenters , working in the same pace , can build 2 desks in two hours and a half . how many desks can 4 carpenters build in 1 hours ?
the mini - cubes with 2 painted sides are all on the edge of the cube , in the ` ` middle ' ' of the edge . there are 4 in front , 4 in back and 4 more on the ` ` strip ' ' that runs around the left / top / right / bottom of the cube . 4 + 4 + 4 = 12 . answer a
['a ) 12', 'b ) 8', 'c ) 6', 'd ) 10', 'e ) 16']
a
multiply(const_4, power(27, divide(const_1, const_3)))
divide(const_1,const_3)|power(n0,#0)|multiply(#1,const_4)
geometry
a 6 litre sol is 40 % alcohol . how many litres of pure alcohol must be added to produce a sol that is 50 % alcohol ?
"total fish = x percentage of second catch = ( 2 / 40 ) * 100 = 5 % so , x * 5 % = 50 x = 1000 ans . a"
a ) 1000 , b ) 625 , c ) 1,250 , d ) 2,500 , e ) 10,000
a
divide(40, divide(2, 40))
divide(n2,n1)|divide(n0,#0)|
gain
the profit earned by selling an article for $ 832 is equal to the loss incurred when the same article is sold for $ 448 . what should be the sale price for making 35 % profit ?
"explanation : in this type of question , where we have one person work and together work done . then we can easily get the other person work just by subtracting them . as son ' s one day work = ( 1 / 3 − 1 / 6 ) = ( 6 − 3 ) / 18 = 1 / 6 so son will do whole work in 6 days answer : b"
a ) 7 days , b ) 6 days , c ) 5 days , d ) 4 days , e ) none of these
b
divide(multiply(6, 3), subtract(6, 3))
multiply(n0,n1)|subtract(n0,n1)|divide(#0,#1)|
physics
the sector of a circle has radius of 14 cm and its perimeter 50 cm . find its central angel ?
"1 - 9 = > 1 * 9 digits 10 - 99 = > 2 * 90 = 180 ( numbers between 10 - 99 is 90 where each has 2 digits ) 100 - 999 = > 3 * 900 = 2700 1000 - 9999 = > 4 * 9000 = 36,000 10000 - 59999 = > 5 * 50,000 = 250,000 the answer is 288,889 the answer is c ."
a ) 248,889 , b ) 268,889 , c ) 288,889 , d ) 308,889 , e ) 328,889
c
add(add(add(subtract(const_10, 1), multiply(subtract(const_100, const_10), const_2)), multiply(subtract(const_100, const_10), const_3)), multiply(subtract(const_100, const_10), const_4))
subtract(const_100,const_10)|subtract(const_10,n0)|multiply(#0,const_2)|multiply(#0,const_3)|multiply(#0,const_4)|add(#2,#1)|add(#5,#3)|add(#6,#4)|
general
how many of the integers between 20 and 80 are even ?
"3 < x < 6 < y < 9 ; 3 < x y < 9 3 + y < x + 9 y - x < 6 . positive integer difference is 5 ( for example y = 8.5 and x = 3.5 ) answer : c ."
a ) 3 , b ) 4 , c ) 5 , d ) 6 , e ) 7
c
subtract(subtract(9, 3), const_1)
subtract(n2,n0)|subtract(#0,const_1)|
general
the average age of students of a class is 15.8 years . the average age of boys in the class is 16.3 years and that of the girls is 15.4 years . the ration of the number of boys to the number of girls in the class is ?
"imo answer should be 350 . . . consider j = 10 , then k = 50 , l = 150 and m = 350 . . . . 20 % of 350 , comes out to be 70 . . . . 150 % of 10 is 15 . . . . ( 70 * 100 ) / 15 = 466.66 . . . . ans : b"
a ) 0.35 , b ) 466 , c ) 35 , d ) 350 , e ) 3500
b
multiply(divide(multiply(divide(multiply(multiply(125, 150), 175), multiply(multiply(25, 50), 75)), 20), 150), const_100)
multiply(n0,n2)|multiply(n1,n3)|multiply(n4,#0)|multiply(n5,#1)|divide(#2,#3)|multiply(n6,#4)|divide(#5,n7)|multiply(#6,const_100)|
gain
consider a lady took a loan from a bank at the rate of 12 % p . a . simple interest . after 3 years she had to pay rs . 9900 interest only for the period . the principal amount borrowed by her was
"explanation : suppose he bought 5 kg and 3 kg of tea . cost price = rs . ( 5 x 18 + 3 x 20 ) = rs . 150 . selling price = rs . ( 8 x 22 ) = rs . 176 . profit = 176 - 150 = 26 so , profit % = ( 26 / 150 ) * 100 = 17 % option e"
a ) 12 % , b ) 13 % , c ) 14 % , d ) 15 % , e ) 17 %
e
divide(multiply(subtract(multiply(22, add(5, 3)), add(multiply(5, 18), multiply(3, 20))), const_100), add(multiply(5, 18), multiply(3, 20)))
add(n2,n3)|multiply(n0,n2)|multiply(n1,n3)|add(#1,#2)|multiply(n4,#0)|subtract(#4,#3)|multiply(#5,const_100)|divide(#6,#3)|
gain
if a mixture is 5 ⁄ 9 alcohol by volume and 4 ⁄ 9 water by volume , what is the ratio of the volume of alcohol to the volume of water in this mixture ?
"explanation : let the cost price of one article = rs . 1 cp of x articles = rs . x cp of 20 articles = 20 selling price of x articles = 20 profit = 25 % [ given ] ⇒ ( sp − cp / cp ) = 25 / 100 = 1 / 4 ⇒ ( 20 − x ) / x = 1 / 4 ⇒ 80 − 4 x = x ⇒ 5 x = 80 option d ⇒ x = 805 = 16"
a ) 13 , b ) 14 , c ) 15 , d ) 16 , e ) 17
d
divide(multiply(20, const_4), add(const_4, const_1))
add(const_1,const_4)|multiply(n0,const_4)|divide(#1,#0)|
gain
j is 25 % less than p and 20 % less than t . t is x % less than p . what is the value of x ?
"19 / 36 m / s = 19 / 36 * 18 / 5 = 19 / 10 = 1.9 kmph . answer : e"
a ) 1.7 , b ) 1.5 , c ) 1.3 , d ) 1.1 , e ) 1.9
e
multiply(const_3_6, divide(19, 36))
divide(n0,n1)|multiply(#0,const_3_6)|
physics
in what time will a train 110 m long cross an electric pole , it its speed be 128 km / hr ?
"percentage error in calculated area = ( 5 + 5 + ( 5 ã — 5 ) / 100 ) % = 10.25 % answer : d"
a ) 4.05 % , b ) 4.02 % , c ) 4 % , d ) 10.28 % , e ) 2 %
d
divide(multiply(subtract(square_area(add(const_100, 5)), square_area(const_100)), const_100), square_area(const_100))
add(n0,const_100)|square_area(const_100)|square_area(#0)|subtract(#2,#1)|multiply(#3,const_100)|divide(#4,#1)|
gain
a merchant marks his goods up by 30 % and then offers a discount of 20 % on the marked price . what % profit does the merchant make after the discount ?
"from 9 : 00 in the morning to 6 : 00 in the afternoon , inclusive there are 9 * 10 = 90 five - minute intervals , thus total of 54 * 30 tickets were sold . say x student and 2 x regular tickets were sold , then x + 2 x = 90 * 30 - - > x = 30 * 30 and 2 x = 2 * ( 30 * 30 ) = 30 * 60 . therefore , the total revenue from ticket sales that day was 30 * 30 * 6 + 30 * 60 * 10 = $ 23,400 . answer : a ."
a ) $ 23400 , b ) $ 25920 , c ) $ 28080 , d ) $ 28500 , e ) $ 29160
a
add(multiply(multiply(divide(multiply(multiply(add(subtract(add(const_12, 6), 9), const_1), const_12), 30), add(const_3.0, const_1)), 2), 10), multiply(divide(multiply(multiply(add(subtract(add(const_12, 6), 9), const_1), const_12), 30), add(2, const_1)), 6))
add(const_12,n4)|add(const_3.0,const_1)|subtract(#0,n2)|add(#2,const_1)|multiply(#3,const_12)|multiply(n0,#4)|divide(#5,#1)|multiply(n8,#6)|multiply(n7,#6)|multiply(n6,#7)|add(#9,#8)|
general
a rectangular photograph is surrounded by a border that is 1 inch wide on each side . the total area of the photograph and the border is m square inches . if the border had been 4 inches wide on each side , the total area would have been ( m + 108 ) square inches . what is the perimeter of the photograph , in inches ?
"explanation : a runs 1000 meters while b runs 900 meters and c runs 830 meters . therefore , b runs 900 meters while c runs 830 meters . so , the number of meters that c runs when b runs 1000 meters = ( 1000 x 830 ) / 900 = 922.22 meters thus , b can give c ( 1000 - 922.22 ) = 77.77 meters start answer : c"
a ) 11.77 meters , b ) 55.77 meters , c ) 77.77 meters , d ) 113.77 meters , e ) none of these
c
subtract(multiply(const_100, const_10), divide(multiply(multiply(const_100, const_10), subtract(multiply(const_100, const_10), 170)), subtract(multiply(const_100, const_10), 100)))
multiply(const_10,const_100)|subtract(#0,n1)|subtract(#0,n0)|multiply(#0,#1)|divide(#3,#2)|subtract(#0,#4)|
physics
uncle bruce is baking chocolate chip cookies . he has 36 ounces of dough ( with no chocolate ) and 10 ounces of chocolate . how much chocolate is left over if he uses all the dough but only wants the cookies to consist of 20 % chocolate ?
# of basic stereos was 2 / 3 of total and # of deluxe stereos was 1 / 3 of total , let ' s assume total = 15 , then basic = 10 and deluxe = 5 . now , if time needed to produce one deluxe stereo is 1 unit than time needed to produce one basic stereo would be 7 / 5 units . total time for basic would be 10 * 1 = 10 and total time for deluxe would be 5 * 7 / 5 = 7 - - > total time for both of them would be 10 + 7 = 17 - - > deluxe / total = 7 / 17 . b
a ) 5 / 17 , b ) 7 / 17 , c ) 4 / 17 , d ) 3 / 17 , e ) 5
b
divide(multiply(5, divide(7, 5)), add(multiply(multiply(2, 5), const_1), multiply(5, divide(7, 5))))
divide(n2,n3)|multiply(n0,n3)|multiply(n3,#0)|multiply(#1,const_1)|add(#3,#2)|divide(#2,#4)
general
what is the probability that when a hand o f 6 cards is drawn from a well shuffled deck of 52 cards , it contains 2 queen ?
"volume of the block = 10 * 20 * 30 = 6000 cm ^ 3 side of the largest cube = h . c . f of 10 , 20,30 = 10 cm volume of the cube = 10 * 10 * 10 = 1000 cm ^ 3 number of cubes = 6000 / 1000 = 6 answer is a"
a ) 6 , b ) 10 , c ) 15 , d ) 40 , e ) 22
a
divide(add(subtract(divide(rectangle_area(const_360, const_1000), const_10), multiply(const_1000, multiply(const_3, const_2))), add(multiply(const_3, const_1000), multiply(30, const_10))), divide(add(subtract(divide(rectangle_area(const_360, const_1000), const_10), multiply(const_1000, multiply(const_3, const_2))), add(multiply(const_3, const_1000), multiply(30, const_10))), const_10))
multiply(const_1000,const_3)|multiply(n2,const_10)|multiply(const_2,const_3)|rectangle_area(const_1000,const_360)|add(#0,#1)|divide(#3,const_10)|multiply(#2,const_1000)|subtract(#5,#6)|add(#4,#7)|divide(#8,const_10)|divide(#8,#9)|
geometry
if 20 liters of chemical x are added to 80 liters of a mixture that is 5 % chemical x and 95 % chemical y , then what percentage of the resulting mixture is chemical x ?
oa is definitely wrong . the answer should be e .
a ) $ 0.50 , b ) $ 1.00 , c ) $ 1.25 , d ) $ 1.50 , e ) $ 1.75
e
add(multiply(0.25, subtract(5, 1)), 0.25)
subtract(n1,n0)|multiply(n3,#0)|add(n3,#1)|
general
50 men shake hands with each other . maximum no of handshakes without cyclic handshakes .
"sp = 800 profit = 25 % cp = ( sp ) * [ 100 / ( 100 + p ) ] = 800 * [ 100 / 125 ] = 640 loss = 45 % = 45 % of 640 = rs . 288 sp = cp - loss = 640 - 288 = rs . 352 answer : b"
a ) s . 429 , b ) s . 352 , c ) s . 429 , d ) s . 128 , e ) s . 419
b
subtract(divide(multiply(800, const_100), add(25, const_100)), divide(multiply(divide(multiply(800, const_100), add(25, const_100)), 45), const_100))
add(n1,const_100)|multiply(n0,const_100)|divide(#1,#0)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)|
gain
rs . 2500 is divided into two parts such that if one part be put out at 5 % simple interest and the other at 6 % , the yearly annual income may be rs . 125 . how much was lent at 5 % ?
"i get b . this question seems too straightforward for 600 + . am i missing something ? 100 first - time visits - - > 100 ( 10 ) = $ 1000 30 + 10 = 40 subsequent visits - - > 40 ( 5 ) = $ 200 total revenue : 1000 + 200 = $ 1200 the answer is b ."
a ) $ 1220 , b ) $ 1200 , c ) $ 1300 , d ) $ 1340 , e ) $ 1880
b
add(multiply(add(10, 5), 30), multiply(subtract(100, 30), 10))
add(n0,n1)|subtract(n2,n3)|multiply(n3,#0)|multiply(n0,#1)|add(#2,#3)|
physics
population of a city in 20004 was 1000000 . if in 2005 there isan increment of 15 % , in 2006 there is a decrements of 35 % and in 2007 there is an increment of 45 % , then find the population of city atthe end of the year 2007
"70 all u do is do 2 : 1 : 6 = > 2 x + x + 6 x = 126 = > x = 14 28 : 14 : 84 84 - 14 = 70 answer d"
a ) 18 , b ) 36 , c ) 72 , d ) 70 , e ) 108
d
subtract(divide(126, add(add(1, divide(1, 3)), divide(1, multiply(3, const_2)))), divide(divide(126, add(add(1, divide(1, 3)), divide(1, multiply(3, const_2)))), multiply(3, const_2)))
divide(n1,n2)|multiply(n2,const_2)|add(n1,#0)|divide(n1,#1)|add(#2,#3)|divide(n0,#4)|divide(#5,#1)|subtract(#5,#6)|
general
chocolate bars are sold in packages of 4 or 9 only . if mark bought 97 chocolate bars exactly , what could be the number of large packs mark bought ?
"the triangle with sides 52 cm , 48 cm and 20 cm is right angled , where the hypotenuse is 52 cm . area of the triangle = 1 / 2 * 48 * 20 = 480 cm 2 answer : a"
a ) 480 cm 2 , b ) 580 cm 2 , c ) 380 cm 2 , d ) 180 cm 2 , e ) 280 cm 2
a
multiply(divide(48, const_2), 20)
divide(n1,const_2)|multiply(n2,#0)|
geometry
one fourth of a solution that was 10 % salt by weight was replaced by a second solution resulting in a solution that was 16 percent sugar by weight . the second solution was what percent salt by weight ?
"there are 7 ! ways to make codes starting with 12 . there are 7 ! ways to make codes starting with 24 . there are 7 ! ways to make codes starting with 36 . there are 7 ! ways to make codes starting with 48 . the number of codes is 4 * 7 ! = 20,160 . the answer is d ."
a ) 14,720 , b ) 16,240 , c ) 18,320 , d ) 20,160 , e ) 22,480
d
multiply(multiply(2, 3), 2)
multiply(n3,n4)|multiply(n3,#0)|
general
excluding stoppages , the speed of a bus is 84 kmph and including stoppages , it is 70 kmph . for how many minutes does the bus stop per hour ?
let the persons be a , b , c . hours worked : a = 2 * 144 / 12 = 24 hours b = 4 * 144 / 12 = 48 hours c = 6 * 144 / 12 = 72 hours c is the hardest worker and a worked for the least number of hours . so the difference is 72 - 24 = 48 hours . answer : c
a ) 47 hours , b ) 45 hours , c ) 48 hours , d ) 49 hours , e ) 50 hours
c
subtract(multiply(divide(144, add(add(2, 4), 6)), 6), multiply(divide(144, add(add(2, 4), 6)), 2))
add(n0,n1)|add(n2,#0)|divide(n3,#1)|multiply(n2,#2)|multiply(n0,#2)|subtract(#3,#4)
physics
a can give b 100 meters start and c 170 meters start in a kilometer race . how much start can b give c in a kilometer race ?
"take the multiples of 7 and add 5 0 x 7 + 5 = 5 . . . . 6 x 7 + 5 = 47 there are 7 numbers answer b"
a ) 3 , b ) 7 , c ) 4 , d ) 5 , e ) 6
b
divide(factorial(subtract(add(const_4, 5), const_1)), multiply(factorial(5), factorial(subtract(const_4, const_1))))
add(n1,const_4)|factorial(n1)|subtract(const_4,const_1)|factorial(#2)|subtract(#0,const_1)|factorial(#4)|multiply(#1,#3)|divide(#5,#6)|
general
two trains leave the train station at the same time . one train , on the blue line , heads east - while the other , on the red line , heads west . if the train on the blue line averages 40 km / hr and the other train averages 40 km / hr - how long will it take for the trains to be 100 km apart ?
"explanation : cash price = $ 24 000 deposit = 10 % ã — $ 24 000 = $ 2400 loan amount = $ 24000 â ˆ ’ $ 2400 number of payments = 60 = $ 21600 i = p * r * t / 100 i = 12960 total amount = 21600 + 12960 = $ 34560 regular payment = total amount / number of payments = 576 answer : d"
a ) $ 503 , b ) $ 504 , c ) $ 555 , d ) $ 576 , e ) $ 587
d
add(divide(multiply(multiply(24, const_1000), subtract(const_1, divide(10, const_100))), 60), multiply(divide(divide(12, const_100), 12), multiply(multiply(24, const_1000), subtract(const_1, divide(10, const_100)))))
divide(n2,const_100)|divide(n4,const_100)|multiply(n0,const_1000)|divide(#1,n4)|subtract(const_1,#0)|multiply(#2,#4)|divide(#5,n3)|multiply(#3,#5)|add(#6,#7)|
gain
an error 5 % in excess is made while measuring the side of a square . what is the percentage of error in the calculated area of the square ?
"explanation : speed of the truck = distance / time = 550 / 1 = 550 meters / minute speed of the train = distance / time = 33 / 45 km / minute = 33000 / 45 meters / minut speed of the truck / speed of the train = 550 / ( 33000 / 45 ) = ( 550 × 45 ) / 33000 = ( 55 × 45 ) / 3300 = ( 11 × 45 ) / 660 = ( 11 × 9 ) / 132 = 9 / 12 = 34 hence , speed of the truck : speed of the train = 3 : 4 answer : option d"
a ) 3 : 7 , b ) 4 : 7 , c ) 1 : 4 , d ) 3 : 4 , e ) 2 : 5
d
divide(550, multiply(divide(33, 45), const_1000))
divide(n2,n3)|multiply(#0,const_1000)|divide(n0,#1)|
physics
albert is 2 times mary ’ s age and 4 times as old as betty . mary is 12 years younger than albert . how old is betty ?
"let the shares of a , b , c , d are 6 x , 4 x , 8 x , 5 x 8 x - 5 x = 3000 3 x = 3000 , x = 1000 b ' s share = 4 x = $ 4000 answer is d"
a ) $ 2000 , b ) $ 6000 , c ) $ 1000 , d ) $ 4000 , e ) $ 5000
d
divide(multiply(divide(multiply(add(3000, 3000), 5), 8), 4), 5)
add(n4,n4)|multiply(n3,#0)|divide(#1,n2)|multiply(n1,#2)|divide(#3,n3)|
general
if x ¤ y = ( x + y ) ^ 2 - ( x - y ) ^ 2 . then √ 7 ¤ √ 7 =
"explanation : let the number of children in the school be x . since each child gets 2 bananas , total number of bananas = 2 x . 2 x / ( x - 380 ) = 2 + 2 ( extra ) = > 2 x - 760 = x = > x = 760 . answer : c"
a ) 237 , b ) 287 , c ) 760 , d ) 287 , e ) 720
c
multiply(380, const_2)
multiply(n0,const_2)|
general
how long does a train 110 m long running at the speed of 72 km / hr takes to cross a bridge 132 m length ?
"the percent of the population who are employed females is 70 - 42 = 28 % the percent of employed people who are female is 28 % / 70 % = 40 % . the answer is d ."
a ) 25 % , b ) 30 % , c ) 35 % , d ) 40 % , e ) 45 %
d
multiply(divide(subtract(70, 42), 70), const_100)
subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)|
gain
the maximum number of students among them 848 pens and 630 pencils can be distributed in such a way that each student get the same number of pens and same number of pencils ?
"initial no of students + 3 * ( 1 + no of possible 3 minute intervals between 15 : 03 and 15 : 44 ) - 8 * ( 1 + no of possible 10 minute intervals between 15 : 10 and 15 : 44 ) 20 + 3 * 14 - 8 * 4 = 25 c"
a ) 7 , b ) 14 , c ) 25 , d ) 27 , e ) 30
c
add(subtract(add(multiply(floor(divide(44, 03)), 03), 20), multiply(floor(divide(44, 9)), 9)), 03)
divide(n10,n4)|divide(n10,n8)|floor(#0)|floor(#1)|multiply(n4,#2)|multiply(n8,#3)|add(n2,#4)|subtract(#6,#5)|add(n4,#7)|
physics
if c and t are positive integers , ct + c + t can not be
"option # 1 : $ 0.75 / crossing . . . . cross twice a day = $ 1.5 / day option # 2 : $ 0.30 / crossing . . . . cross twice a day = $ 0.6 / day + $ 13 one time charge . if we go down the list of possible answers , you can quickly see that 14 days will not be worth purchasing the sticker . 1.5 x 14 ( 21 ) is cheaper than 0.6 x 14 + 13 ( 21.4 ) . . . it ' s pretty close so let ' s see if one more day will make it worth it . . . if we raise the number of days to 15 , the sticker option looks like a better deal . . . 1.5 x 15 ( 22.5 ) vs 0.6 x 15 + 13 ( 22 ) . answer : c"
a ) 14 , b ) 15 , c ) 16 , d ) 28 , e ) 29
c
add(multiply(divide(multiply(divide(13.00, multiply(subtract(0.65, 0.30), const_2)), const_2), const_10), const_2), multiply(divide(13.00, multiply(subtract(0.65, 0.30), const_2)), const_2))
subtract(n0,n2)|multiply(#0,const_2)|divide(n1,#1)|multiply(#2,const_2)|divide(#3,const_10)|multiply(#4,const_2)|add(#5,#3)|
general
the average age of 22 students in a group is 12 years . when teacher ' s age is included to it , the average increases by one . what is the teacher ' s age in years ?
"the volume of water in the tank is h * l * b = 75 cubic feet . since h = 3 , then l * b = 25 and l = b = 5 . since the tank is cubical , the capacity of the tank is 5 * 5 * 5 = 125 . the ratio of the water in the tank to the capacity is 75 / 125 = 3 / 5 the answer is e ."
a ) 1 / 2 , b ) 2 / 3 , c ) 3 / 4 , d ) 2 / 5 , e ) 3 / 5
e
divide(3, divide(75, const_10))
divide(n1,const_10)|divide(n0,#0)|
physics
in the coordinate plane , a circle centered on point ( - 3 , 4 ) passes through point ( 1 , 1 ) . what is the area of the circle ?
"135 - 74 + 1 = 62 ' b ' is the answer"
a ) 53 , b ) 62 , c ) 51 , d ) 50 , e ) 49
b
add(subtract(135, 74), const_1)
subtract(n1,n0)|add(#0,const_1)|
general
in a renowned city , the average birth rate is 9 people every two seconds and the death rate is 3 people every two seconds . estimate the size of the population net increase that occurs in one day .
"answer is 9 , move the decimal forward three places for both numerator and denominator or just multiply both by a thousand . the result is 9009 / 1001 = 9 answer d"
a ) 0.009 , b ) 0.09 , c ) 0.9 , d ) 9 , e ) 90
d
multiply(divide(9.009, 1.001), const_100)
divide(n0,n1)|multiply(#0,const_100)|
general
a man can do a piece of work in 5 days , but with the help of his son , he can finish it in 3 days . in what time can the son do it alone ?
"formula = total = 100 % , increase = ` ` + ' ' decrease = ` ` - ' ' a number means = 100 % that same number increased by 25 % = 125 % 125 % - - - - - - - > 520 ( 120 ã — 4.16 = 520 ) 100 % - - - - - - - > 416 ( 100 ã — 4.16 = 416 ) option ' e '"
a ) 216 , b ) 316 , c ) 616 , d ) 516 , e ) 416
e
divide(520, add(const_1, divide(25, const_100)))
divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)|
gain
if n is an integer and 101 n ^ 2 is less than or equal to 10000 , what is the greatest possible value of n ?
"x / 14 + x / 30 + x / 40 = 1 x = 7.7 days answer : b"
a ) 7.6 days , b ) 7.7 days , c ) 6.7 days , d ) 5.7 days , e ) 8.7 days
b
add(subtract(subtract(14, subtract(40, 30)), 4), const_1)
subtract(n2,n1)|subtract(n0,#0)|subtract(#1,n3)|add(#2,const_1)|
physics
the weight of a glass of jar is 30 % of the weight of the jar filled with coffee beans . after some of the beans have been removed , the weight of the jar and the remaining beans is 60 % of the original total weight . what fraction part of the beans remain in the jar ?
"t 1 = 240 / 60 = 4 hours t 2 = 120 / 40 = 3 hours t = t 1 + t 2 = 7 hours avg speed = total distance / t = 360 / 7 = 51 mph = b"
a ) 42 , b ) 51 , c ) 50 , d ) 54 , e ) 56
b
divide(add(240, 120), add(divide(240, 60), divide(120, 40)))
add(n0,n2)|divide(n0,n1)|divide(n2,n3)|add(#1,#2)|divide(#0,#3)|
physics
the price of an item is discounted 4 percent on day 1 of a sale . on day 2 , the item is discounted another 4 percent , and on day 3 , it is discounted an additional 10 percent . the price of the item on day 3 is what percentage of the sale price on day 1 ?
"the fastest way in an ap is to find the average and multiply with total integers . . between 38 and 127 , the smallest multiple of 4 is 40 and largest = 124 . . average = ( 40 + 124 ) / 2 = 164 / 2 = 82 . . total numbers = ( 124 - 40 ) / 4 + 1 = = 84 / 4 + 1 = 27 + 1 = 22 . . sum = 82 * 22 = 1804 ans a"
a ) 1804 , b ) 1816 , c ) 1824 , d ) 1828 , e ) 1832
a
multiply(divide(add(subtract(127, const_3), add(38, const_2)), const_2), add(divide(subtract(subtract(127, const_3), add(38, const_2)), 4), const_1))
add(n1,const_2)|subtract(n2,const_3)|add(#0,#1)|subtract(#1,#0)|divide(#3,n0)|divide(#2,const_2)|add(#4,const_1)|multiply(#6,#5)|
general
in what time will a train 180 m long cross an electric pole , it its speed be 144 km / hr ?
"ans is d given d _ ab = 2 * d _ bc let d _ ab = d and d _ bc = x so d = 2 x for average miles per gallon = ( d + x ) / ( ( d / 10 ) + ( x / 18 ) ) = 14.5 ( formula avg speed = total distance / total time )"
a ) 13 , b ) 13.5 , c ) 14 , d ) 14.5 , e ) 15
d
divide(add(multiply(18, const_10), divide(multiply(18, const_10), const_2)), add(divide(multiply(18, const_10), 10), divide(divide(multiply(18, const_10), const_2), 18)))
multiply(n1,const_10)|divide(#0,const_2)|divide(#0,n0)|add(#1,#0)|divide(#1,n1)|add(#2,#4)|divide(#3,#5)|
general
find the ratio of the curved surfaces of two cylinders of same heights if their radii are in the ratio 1 : 2 ?
"speed of train relative to man = 30 + 6 = 36 km / hr . = 36 * 5 / 18 = 10 m / sec . time taken to pass the men = 110 / 10 = 11 sec . answer : d"
a ) 7 sec , b ) 6 sec , c ) 8 sec , d ) 11 sec , e ) 2 sec
d
divide(110, multiply(add(30, 6), const_0_2778))
add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)|
physics
if the average of r , b , c , 14 and 15 is 12 . what is the average value of r , b , c and 29
here one boy is excluded and final average of the group decreases . ∴ change in average is ( – ) ve = – 0.1 kg . using the formula sum of the quantities excluded = ( changein no . ofquantities × origina laverage ) + ( changeinaverage × final no . ofquantities ) ⇒ weight of the boy who left = ( 1 × 45 ) – ( – 0.1 × 49 ) = 49.9 kg answer c
a ) 40.9 kg , b ) 42.9 kg , c ) 49.9 kg , d ) 39.9 kg , e ) none of these
c
add(45, divide(multiply(subtract(50, const_1), 100), const_1000))
subtract(n0,const_1)|multiply(n2,#0)|divide(#1,const_1000)|add(n1,#2)
general
how many odd prime numbers are there less than 100 ?
"1 h - - - - - 5 ? - - - - - - 60 12 h rs = 20 + 21 = 41 t = 12 d = 41 * 12 = 492 answer : b"
a ) 288 , b ) 492 , c ) 877 , d ) 278 , e ) 178
b
add(multiply(divide(60, subtract(21, 20)), 20), multiply(divide(60, subtract(21, 20)), 21))
subtract(n1,n0)|divide(n2,#0)|multiply(n0,#1)|multiply(n1,#1)|add(#2,#3)|
physics
the measure of the side of a square is multiplied by 7 . if x represents the perimeter of the original square , what is the value of the new perimeter ?
from here , it might be easier to go up in bounds of 60 , so we know that 61 - 120 gives 10 more numbers . 121 - 180 and 181 - 240 as well . this brings us up to 240 with 40 numbers . a cursory glance at the answer choices should confirm that it must be 42 , as all the other choices are very far away . answer choice a is correct here .
a ) 40 , b ) 31 , c ) 42 , d ) 53 , e ) 64
a
divide(factorial(subtract(add(const_4, 4), const_1)), multiply(factorial(4), factorial(subtract(const_4, const_1))))
add(n1,const_4)|factorial(n1)|subtract(const_4,const_1)|factorial(#2)|subtract(#0,const_1)|factorial(#4)|multiply(#1,#3)|divide(#5,#6)|
general
machine a and machine b are each used to manufacture 550 sprockets . it takes machine a 10 hours longer to produce 550 sprockets than machine b . machine b produces 10 percent more sprockets per hour than machine a . how many sprockets per hour does machine a produces ?
"w / x = 1 / 3 = > x = 3 w and w / y = 4 / 15 = > y = 15 / 4 w ( x + y ) / y = ( 3 w + 15 / 4 w ) / ( 15 / 4 w ) = ( 27 / 4 w ) / ( 15 / 4 w ) = 9 / 5 correct option : e"
a ) 4 / 5 , b ) 6 / 5 , c ) 7 / 5 , d ) 8 / 5 , e ) 9 / 5
e
add(divide(divide(4, 1), divide(15, 3)), const_1)
divide(n2,n0)|divide(n3,n1)|divide(#0,#1)|add(#2,const_1)|
general
if annual decrease in the population of a town is 5 % and the present number of people is 40000 what will the population be in 2 years ?
"price of 1 ticket = 20 $ revenue generated from sales of first 10 tickets = 10 * ( 60 / 100 * 20 ) = 10 * 12 = 120 revenue generated from sales of next 20 tickets = 20 * ( 85 / 100 * 20 ) = 20 * 17 = 340 revenue generated from sales of last 22 tickets = 20 * 22 = 440 revenue generated from sales of 52 tickets = 120 + 340 + 440 = 900 $ answer d"
a ) $ 600 , b ) $ 740 , c ) $ 850 , d ) $ 900 , e ) $ 1,140
d
multiply(add(add(subtract(subtract(52, 20), 10), multiply(subtract(const_1, divide(40, const_100)), 10)), multiply(subtract(const_1, divide(15, const_100)), 20)), 20)
divide(n2,const_100)|divide(n4,const_100)|subtract(n5,n0)|subtract(const_1,#0)|subtract(#2,n1)|subtract(const_1,#1)|multiply(n1,#3)|multiply(n0,#5)|add(#6,#4)|add(#8,#7)|multiply(n0,#9)|
gain
out of 400 students of a school , 325 play football , 175 play cricket and 50 neither play football nor cricket . how many students play both football and cricket ?
"lets say x ounces of p is mixed with q . = > 64 - x ounces of q is present in the mixture ( as the total = 64 ounces ) given total almond weight = 14 ounces ( 20 x / 100 ) + ( 25 / 100 ) ( 64 - x ) = 14 = > x = 40 = > 64 - 40 = 14 ounces of q is present in the mixture . answer is a ."
a ) 14 , b ) 20 , c ) 32 , d ) 44 , e ) 48
a
divide(subtract(14, multiply(divide(20, const_100), 64)), subtract(divide(25, const_100), divide(20, const_100)))
divide(n0,const_100)|divide(n1,const_100)|multiply(n2,#0)|subtract(#1,#0)|subtract(n3,#2)|divide(#4,#3)|
general
the list price of an article is rs . 65 . a customer pays rs . 56.16 for it . he was given two successive discounts , one of them being 10 % . the other discount is ?
"explanation : solution : relative speed = ( 9 - 8 ) = 1 km / hr . distance covered in 3 minutes = ( 1 * 3 / 60 ) km = 1 / 20 km = 50 m . . ' . distance between the criminal and policeman = ( 265 - 50 ) m = 215 m . answer : e"
a ) 100 m , b ) 120 m , c ) 130 m , d ) 150 m , e ) none of these
e
subtract(265, multiply(divide(3, const_60), const_1000))
divide(n3,const_60)|multiply(#0,const_1000)|subtract(n0,#1)|
physics
125 liters of a mixture of milk and water contains in the ratio 3 : 2 . how much water should now be added so that the ratio of milk and water becomes 3 : 4 ?
6 flavours * 6 choices = 6 c 1 * 6 c 1 = 6 * 6 = 36 = d
a ) 4 , b ) 8 , c ) 12 , d ) 36 , e ) 32
d
multiply(6, 6)
multiply(n0,n0)
general
what is the sum of all the odd numbers between 24 and 50 , inclusive ?
"let the numbers be 3 x , 3 x + 3 and 3 x + 6 . then , 3 x + ( 3 x + 3 ) + ( 3 x + 6 ) = 117 9 x = 108 x = 12 largest number = 3 x + 6 = 42 answer : d"
a ) 45 , b ) 48 , c ) 51 , d ) 42 , e ) 54
d
add(add(power(add(add(divide(subtract(subtract(3, const_10), const_2), const_4), const_2), const_2), const_2), power(add(add(add(divide(subtract(subtract(3, const_10), const_2), const_4), const_2), const_2), const_2), const_2)), add(power(divide(subtract(subtract(3, const_10), const_2), const_4), const_2), power(add(divide(subtract(subtract(3, const_10), const_2), const_4), const_2), const_2)))
subtract(n0,const_10)|subtract(#0,const_2)|divide(#1,const_4)|add(#2,const_2)|power(#2,const_2)|add(#3,const_2)|power(#3,const_2)|add(#5,const_2)|add(#4,#6)|power(#5,const_2)|power(#7,const_2)|add(#9,#10)|add(#11,#8)|
general
if a speaks the truth 30 % of the times , b speaks the truth 40 % of the times . what is the probability that at least one will tell the truth
one short cut to solve the problem is c : p = 1 : 3 c increased to 5 = > 1 : 3 = 5 : x = > x = 15 = > p increased by 12 b is the answer
a ) 2 , b ) 12 , c ) 5 , d ) 10 , e ) 15
b
subtract(multiply(4, 4), const_4)
multiply(n0,n0)|subtract(#0,const_4)
other
a factory that employs 1000 assembly line workers pays each of these workers $ 5 per hour for the first 40 hours worked during a week and 1 ½ times that rate for hours worked in excess of 40 . what was the total payroll for the assembly - line workers for a week in which 30 percent of them worked 15 hours , 50 percent worked 40 hours , and the rest worked 50 hours ?
"d = 72 * 5 / 18 = 50 = 1000 â € “ 250 = 750 m answer : d"
a ) 150 m , b ) 200 m , c ) 250 m , d ) 750 m , e ) 300 m
d
subtract(multiply(50, multiply(72, const_0_2778)), 250)
multiply(n1,const_0_2778)|multiply(n2,#0)|subtract(#1,n0)|
physics
a train running at the speed of 60 km / hr crosses a pole in 30 seconds . what is the length of the train ?
"3 multiples are . . . 6,9 , 12,15 , 18,21 , 24,27 , 30,33 , 36,39 , 42,45 , 48,51 , 54,57 , . . . , the answer is = 18 answer is c"
a ) 16 , b ) 22 , c ) 18 , d ) 11 , e ) 9
c
add(divide(subtract(59, 5), 3), const_1)
subtract(n2,n1)|divide(#0,n0)|add(#1,const_1)|
general
if 36 men can do a piece of work in 25 hours , in how mwny hours will 15 men do it ?
"given that milk / water = 4 x / x and 4 x + x = 45 - - > x = 9 . thus milk = 4 x = 36 liters and water = x = 9 liters . new ratio = 36 / ( 9 + 12 ) = 36 / 21 = 12 / 7 . answer : a ."
a ) 12 / 7 , b ) 4 / 1 , c ) 2 / 3 , d ) 3 / 4 , e ) 3 / 2
a
divide(subtract(45, divide(45, add(4, 1))), add(divide(45, add(4, 1)), 12))
add(n1,n2)|divide(n0,#0)|add(n3,#1)|subtract(n0,#1)|divide(#3,#2)|
general
what is the probability that when a hand o f 6 cards is drawn from a well shuffled deck of 52 cards , it contains 2 queen ?
"number of passengers using kennedy airport = 32 / 3 = ~ 10.67 passengers using miami airport = 10.67 / 2 = ~ 5.34 passengers using logan airport = 5.34 / 4 = ~ 1.33 so d"
a ) 18.6 , b ) 9.3 , c ) 6.2 , d ) 1.33 , e ) 1.6
d
divide(divide(32.3, 3), multiply(4, 2))
divide(n3,n2)|multiply(n5,n6)|divide(#0,#1)|
general
15 lts are taken of from a container full of liquid a and replaced with liquid b . again 15 more lts of the mixture is taken and replaced with liquid b . after this process , if the container contains liquid a and b in the ratio 9 : 16 , what is the capacity of the container h ?
"let the greater and the smaller number be g and s respectively . gs = 2496 g + s exceeds g - s by 64 i . e . , g + s - ( g - s ) = 64 i . e . , 2 s = 64 = > s = 32 . g = 2496 / s = 78 . answer : d"
a ) a ) 96 , b ) b ) 108 , c ) c ) 110 , d ) d ) 78 , e ) of these
d
divide(2496, multiply(power(const_2, const_4), const_2))
power(const_2,const_4)|multiply(#0,const_2)|divide(n0,#1)|
general
find compound interest on rs . 7500 at 4 % per year for 2 years , compounded annually .
"a + b + c = 6490 4 a = 6 b = 2 c = x a : b : c = 1 / 4 : 1 / 6 : 1 / 2 = 3 : 2 : 6 3 / 11 * 6490 = rs 1770 answer : e"
a ) s 6490 , b ) s 1880 , c ) s 1660 , d ) s 1550 , e ) s 1770
e
multiply(4, divide(6490, add(add(4, 2), const_3)))
add(n1,n2)|add(#0,const_3)|divide(n0,#1)|multiply(n1,#2)|
general
a horse is tethered to one corner of a rectangular grassy field 36 m by 20 m with a rope 12 m long . over how much area of the field can it graze ?
of the goose eggs laid at a certain pond , 2 / 3 hatched and 3 / 4 of the geese that hatched from those eggs survived the first month : 2 / 3 * 3 / 4 = 1 / 2 survived the first month . of the geese that survived the first month , 3 / 5 did not survive the first year : ( 1 - 3 / 5 ) * 1 / 2 = 1 / 5 survived the first year . 120 geese survived the first year : 1 / 5 * ( total ) = 125 - - > ( total ) = 625 . answer : d .
a ) 280 , b ) 400 , c ) 540 , d ) 625 , e ) 840
d
divide(divide(divide(125, subtract(const_1, divide(3, 5))), divide(3, 4)), divide(const_2, const_3))
divide(n1,n5)|divide(n1,n3)|divide(const_2,const_3)|subtract(const_1,#0)|divide(n6,#3)|divide(#4,#1)|divide(#5,#2)
general
a pair of articles was bought for $ 1000 at a discount of 10 % . what must be the marked price of each of the article ?
explanation : salary of the manager = ( 56 * 8800 - 55 * 8500 ) = 25300 answer : d
a ) 10000 , b ) 12000 , c ) 23000 , d ) 25300 , e ) 45000
d
subtract(multiply(add(55, const_1), 8800), multiply(55, 8500))
add(n0,const_1)|multiply(n0,n1)|multiply(n2,#0)|subtract(#2,#1)
general
a 750 m long train crosses a platform in 39 sec while it crosses a signal pole in 18 sec . what is the length of the platform ?
"let x be the number of roses . then the number of birches is 24 − x , and the number of boys is 3 × ( 24 − x ) . if each girl planted 3 roses , there are x 3 girls in the class . we know that there are 24 students in the class . therefore x 3 + 3 ( 24 − x ) = 24 x + 9 ( 24 − x ) = 3 ⋅ 24 x + 216 − 9 x = 72 216 − 72 = 8 x 1448 = x 1 x = 18 so , students planted 18 roses and 24 - x = 24 - 18 = 6 birches . correct answer is d ) 6"
a ) 2 , b ) 5 , c ) 8 , d ) 6 , e ) 4
d
divide(subtract(multiply(3, 24), 24), subtract(multiply(3, 3), 1))
multiply(n0,n1)|multiply(n1,n1)|subtract(#0,n0)|subtract(#1,n2)|divide(#2,#3)|
physics
a dishonest person wants to make a profit on the selling of milk . he would like to mix water ( costing nothing ) with milk costing 33 $ per litre so as to make a profit of 50 % on cost when he sells the resulting milk and water mixture for 36 $ . in what ratio should he mix the water and milk ?
"factors of 12 - 1 , 2 , 3 , 4 , 6 , and 12 factors of 16 - 1 , 2 , 4 , 8 and 16 comparing both , we have three common factors of 45,16 - 3 answer c"
a ) 1 , b ) 2 , c ) 3 , d ) 4 , e ) 5
c
divide(16, 10)
divide(n1,n0)|
other
andy solves problems 74 to 135 inclusive in a math exercise . how many problems does he solve ?
here n ( s ) = ( 6 * 6 ) = 36 let e = event of getting a total more than 7 = { ( 2,6 ) , ( 3,5 ) , ( 3,6 ) , ( 4,4 ) , ( 4,5 ) , ( 4,6 ) , ( 5,3 ) , ( 5,4 ) , ( 5,5 ) , ( 5,6 ) , ( 6,2 ) , ( 6,3 ) , ( 6,4 ) , ( 6,5 ) , ( 6,6 ) } p ( e ) = n ( e ) / n ( s ) = 15 / 36 = 5 / 12 option c
a ) 5 / 7 , b ) 4 / 7 , c ) 5 / 12 , d ) 4 / 7 , e ) 1 / 6
c
divide(add(add(7, const_4), const_4), multiply(add(const_4, const_2), add(const_4, const_2)))
add(n0,const_4)|add(const_2,const_4)|add(#0,const_4)|multiply(#1,#1)|divide(#2,#3)
general
a total of 520 players participated in a single tennis knock out tournament . what is the total number of matches played in the tournament ? ( knockout means if a player loses , he is out of the tournament ) . no match ends in a tie .
"largest 4 digit number is 999999 after doing 999999 ÷ 96 we get remainder 55 hence largest 4 digit number exactly divisible by 88 = 9999 - 55 = 9944 answer : d"
a ) 999991 , b ) 999965 , c ) 999912 , d ) 999936 , e ) 999930
d
multiply(add(const_100, const_2), 99)
add(const_100,const_2)|multiply(n1,#0)|
general